三相交流电抗器设计单

Core loss
1.3133
78.3411
0.001055401 Ω Eddy current
770.9619 A 8.3076 %
Base frquency 50 HZ Switching frequen 3500 HZ
Remark
Base current 770 A Switching current 38.5 A
0.795609726
mΩ
Conductor weight Gm
13.27292375
KG
Insulating paper P Length 14414.6646 Width
460
mm
A
Insulating paper wW'T
0.776
KG
206.82
Inductance&gap accurately calculated.
Ar
B(G)
W/kg
W
75% 1434.920229 82.88%
50
770.00
9400.000
0.502
29.970
50% 650.7991702 88.35%
3500
38.50
376.058
0.811
48.371
30% 243.6886306 92.73%
0
0.00
0.000
0.000
0.000
7 Leakage
Ls=0.4*π*ρs*N^2*Ss/hm*10^-5
15.05 ) 37.838 cm2 δ0
Dm UNIT
/
28.4938 4.19135 0.0185
cm mH
1.273
5.084
cm
ρs=1-2*(Dm+δo)/(π*hm)
Rockwell ρs 0.90904916
8 Inductance L=0.4*π*N^2*Sc/(lg+lc/μ) 1.257 * 20016 / 4.193
②
①
125
②
②
135
①
645
UNIT: mm
15 SUM GAP core 14 41.9 mm gap
尺寸比
X = 1.08
25
Y = 0.2 Z = 3.76
2.98%
Item ①
② Unit
Width 125 125 mm
Length 645 28.5 mm
Stack 48.5 1091.25 mm
3-phase AC reactor design report Revision
A
Specification
0.06mH/770A
Page page 3 of 3
Performance calculations
Core loss(Fundamental & harmonic)
Efficiency
/
TURNS
S.Qty Stack Layers T 0 × 0 = 0
1 1 23
23 Layers Sum 23
Winding insulation I
Material Nomex － 0.13
Turns 29
TURNS
Winding thickness δn
30.91
mm
142.82
145
45
a' = sc ÷ y
31.30 ÷ 0.20 × 10
125 mm y 0.20 1 ~ 2 Width factor
a1 =
H ÷ Kh
3 Core width
a2 = ( L - P ) ÷ Kl （
*
÷ 8.00
* - 0 ） ÷ 7.00
* mm kh 8.00 4.0~ 7.0 H/W factor * mm Kl 7.00 6.0~7.0 L/W factor
hm= 470.0 － 25 ＝ 445 Winding width hm
hm = c - k ( k = 25 ~ 80 )
Left
0
mm
Right
0
10 1 0
0
10 1 0
0
P.Qty P.wide may turn 23 × 1 = 23
B
1 430 1 L 0 × 0 = 0
40.91
Winding layout D
Item Splint/bobbin
Core
Winding
Conductor Material M Narrowa 1 Section Qty Total.secti Density A/mm2 Front
0
10 1 10 1
Broad b 430 430
1
430 1.793
Back
0
10 1 10 1
433.1 / 15.0000
28.874 mm
44.5
4 Diffraction W ε=δ/π*ln((H+δ)/δ) 2.50 / 3.14 * ln ( 13 ) 2.01408 mm
5 Gap flux area Se=Sc+2ε(a+b+2ε) 30.3 + 0.5 * (
6 Final gap lg"=1.78*I*W*Se/(Bc*Sc) 1.78 * ##### * 38
7 Core Gap Lg=1.78 * ( I e*W/ Bm )*10^- 1.78 × ( 770 × 23 ÷ 0.94 ) 3.3536 cm Kg 1 0.8~1.2 Total gap
Design：Renquan.xiao
Check：
Date：2014/1/2
3-phase AC reactor design report Revision
0.06001 mH
9 Check gap
lg=L/Le*lg"
0.0785 /
0.06 * 4.19 5.48395 cm
Ss=1/3*Dm*lm+ (a+δ0)*(b+δ0)
Leakage areaSs
136.20566
Design：Renquan.xiao
Check：
Date：2014/1/2
23
TURNS Toltal Air-duct * 4
7 2 EA
Current density j Conductor sectio q
2 j = 0.75 × Pm / Z × Gm
385.4809496
A/mm2 mm2
Manual adjustment air-duct
Aluminum foil
Turns
23 TS Effective gap 4.19135 cm KN=8.4*δ^2*W*B
B= 1.78*I*W/Lg; W=0.677*10^-3*f^1.656*B*^1.857(0.4291,^1.68,^1.86)
Formula Δτ=(0.55*(((Ws+0.05246)/(5.13*10^-12))^0.25-318)+0.45*(Ws/(2.7*10^-4))^0.8333)/2
a = ( a1 ＋ a2 ) ÷ 2 （ * ＋ * ） ÷ 2
* mm K2 0.9 0.8~1.3 Width factor
4 Core stack b = Sc ÷ a
31.3 ÷ 125 × 100
25 mm P 0 10~200
Splint
h1 = a × z 5 Window higth
20% 113.5287965 94.92%
0
0.00
0.000
0.000
0.000
10% 32.29925302 97.11%
Loss &
0
0.00
0.000
0.000
0.000
5%
10.0333402 98.20%
Efficienc
0
0.00
0.000
0.000
0.000
CEC
EURO
y
0
0.00
A
Specification
0.06mH/770A
Page page 1 of 3
Saturated inductance
0.050
mH
Switching frequency
3500
HZ
Switching current
38.5
A
Test condition
AC
V
Performance comparison
t/v
Item
B/A Actual L/R Actual Unit
Winding voltage U
14.51415781
V Available space * 40 73.2 20 mm
Winding current I
770.9618992
A
Set height 10 10
10 10 mm
Winding turns N
*
142.82
mm
Height H
*
790
mm
Cost
Materials Each Wire 17.5 Core 19.6
Insulation 360
Weight 39.8 59.7 2.328
Total weight 107.9 kg
Total cost 3515 Chs
Results OK
Core calculation
h2 = H - BASE - el
125.0 × 3.760 * - 70 - 125.0 × 2
470 mm z 3.76 2 ~ 4 * mm BASE 70 20 ~ 200
Z factor Base
6 Window widthc = a × x
125.0 × 1.0800
135 mm x 1.08 0.6 ~ 1.28 X factor
harmonic 3 Current 0
5 0
7 0
9 11 13 15 17 19 21 HZ 0 0 0 0 0 0 0 Arms
Load
LoadW Efficiencyη
Frequency Current
Flux
Unit core loss Loss
100% 2430.7589 78.25%
HZ
Setp Item
Formula
Process
Result
Evolution MFL width
1
Line
ε%=Lg/Lc*100%
3.3536 / 94.16666667
3.56%
2 No.gap
NO.=nLg/ single gap
33.5 / 2.5
14.00 EA
hm
3
Hm
Hm=C/No.gap
720 470 28.5
Technical conditions
Base frequency 50 HZ Rated inductance 0.06 mH
Rated current 770 A Saturation curren 1155 A
3-phase AC reactor design report Revision
A A"mold a side 20 + 125 = 145
L
R
Around the mold
mm
B A'mold b side 20
+ 25 =
45
30.91
Average turn length Lm
497.0574
mm
Wire length Ln
11432.3202
mm
DC Resistance DCR
Flux 0.94 T Core loss 1.3133 W Saturated flux 1.128 T
Total gap 41.9134663 mm Magnetic density H~
0.1454 A/cm Magnetic permeability
64649.24347
Step Item
Formula
Item
Spec Design Test Unit
voltage 14.5142 11.617
V
Load loss 33527.7 2431
W来自百度文库
Temperature rise 200 188
K
Dimensions
Item
Spec Design Actual
Unit
Length L
*
727
mm
Depth D
0.000
0.000
0.000
0
0.00
0.000
0.000
0.000
Coil loss
0 0
0.00
0.000
0.000
0.000
0.00
0.000
0.000
0.000
Coil loss
2352.417813 W
0
0.00
0.000
0.000
0.000 Dc resistance Rdc Winding current Ie
Calculation
Results
Factor
Remark
1 Power Pva = Ux × I
14.5141578 ×
770
11175.9 VA REF 0.61 64.2635 Power fator
2 Core section Sc = Kb × Pva
0.296 ×
11175.90152 31.3 cm2 Kb 0.30 0.7~1 Section factor
Weight 29.9139 29.74 kg
Remark L of magnetic
direction Core type 30Z120
Core properties
Core section 30.3125 cm Magnetic length 94.1667 cm
Single gap 2.50 mm
A
Specification
0.06mH/770A
Page page 2 of 3
Coil calculation
Power
S
Uint turns T/V
11175.90152
1.564233794
Bm 0.95
T/V=10000 / (4.44 * f * Bm* Sc )
VA
Air-duct space calculation