商师《土力学与基础工程》第三版(赵明华)课后习题答案武汉理工大学出版社

2 1
500.0= 0i s/mm 5−01 5 = k =Q v Q ba s/mm 01 5 = k
2−
2
m1
3
2
h 2 ba b.a 53. 2 71< p I < 01 2 1 1 m02 01.2
i m 02. 32 m05.32
52.0<80. 0= L I <0 80.0 =
pI 6 .2 1 = = LI 4.53 − 4.63 pw − w
e rs = s dw ⇒
s
%001
w
v v = rs v
2
d
w
e +1 = d
s d
s w
v = m
1
)w + 1( s d = wm + sm = m
w s
w
s
dw = smw = wm
%001
w
sm =w m
d=
w
s s
v d = sm
wp 1
s
sv = sd m
e + 1 = vv + sv = v
e = vv
v
sv =e v
1 = sv
e +1 n = = rs ) 3( w s )n − 1( S dw r d + wre rs
) 2(
w
e +1 =d d
s
1 2.2
2
3
%6.6= %001 * mc / g 997.1 =
sm 5.121 sm = %001 * s = %001 * w = w )1( m−m 5.121 − 5.921 m
6.21 = 4.53 − 84 = pw − Lw = p I
7
% 01
639.1= xam d 188.1=
067.1= d
880.0 + 1 =d 30.2
639.1= d 529.1= d 328. 1= d
857.1 =
d
271.0 + 1 w + 1 = = 60.2
s
d
po w
56.2= 61.2 2.21 01.2 2.51
081= 1wm + sm
%81=% 001 *
s
m m
1w
= 1w Q % 52 = 2w
%81 = 1w
8
5 m/Nk052
5
7
4
3 0
3
m / Nk5.71 = 23.3 3.3
4
apk8.122 = )0.2 + 2.4 ( wr + 8.951 =
2.3 2.3
13.3 apk8.951= 0. 2* 6.9 + 6.041 = 4h ' r + 6.041 =
%3. 49 = %001∗
18.0 e = = rs 86.2 ∗ 582.0 s dw
w
18.0 = 1 −
9.1 = 1− 1 ∗ )582.0 + 1( ∗ 86.2
)w + 1( s d %05
=e
2
% 9.68=%5.73+% 0. 12+%6.81+%4.9 41=N m3
mm570.0
2c
202.0 =
1c
b 1= z b 1= z 2=
1z
b 1= :liem l b 5. 2 = :jqme l A 021.0 =
b l
4c
B =
2c
a pk 811=002
021.0+571.0
2= b z
2=
:
1c
mcde : 1= 4 b l fgda
hgcm bmhf bmea A ) a(
1 4 3 2 1
5.31 570.0<
5.73 570.0 2.0
0 52.0
12 5.0
6.81 5. 0 2
4.9 2>
% mm
, 86.2 = s d
, 3m /Nk91=r
,%5.82=w % 2 . 9 =% 0 0 1 *
8.2
sd 96.2 = =w 26.0 ∗ 04.0 e rs
2c
2 33.1 76.0 0 )cfea( b/z 6 4 2 0 )m(Z
6 4 2 0 ) m( Z
5- 5 7 6 5 4
(2 =
z
25.62 67.83 78.96 5.721
) apk ( 0p 1c 4 =
z
250.0 670.0 731.0 052.0
1c
7- 4 3 2 1 0
3- 0 apk 5.721 = 5.71 − 541 = − p = 0p
3
w
)w + 1( s d
=e
e
164.0 =
nim
e
76.2 = s d
mc / g 77.1 =
r
D 76.2
e %8.9
3
3 4 9. 0 , 3 mc / g77.1
164. 0 6.2
m /N k 9 1 = 0 1 *
68.0 + 1 e +1 = gw =r ∴ )w + 1( s d 2 3 . 0 + 1 × 86.2
n im
p
apk542=
3 A W 2 ∗2 4 + = + = 001 08 + 006 M G + F
xam
p
3 6 6 6 = =2 2 = lb = w 4 8 1 2 1 nK 08=1 2 2 02=dAgr =G
5.3
m 0. 2 = z m ⋅ Nk 001 = M Nk 006 = F
2
72 = 54 − 27 = sv − v = vv
54 =
sd 7.2 = = sv ⇒ 5.121 sm
w sv = sd m s
5
%4.53= Pw
%84= Lw
%4.63= w ) 2(
L
I
P
I
)1( 9.2 41=N 4 3
.%4.53= Pw
%84= Lw
%4. 63= w 51 N <01
v 78.0 v = %001 * w v 78.0 s
%001 = %001 *
e = rs dw
g 75.3 = wm + sm = m g 78.0 = 0.1 * 07.2 * 223.0 =
w s
dw = wm
s
g07.2=0.1 * 07.2 =
3
w
d = sm
mc 78.1 = 78.0 + 1 = e + 1 = v
3
mc 78.0= 07.2 * 223.0 = s dw = wv
3
mc 78.0 = e = v v
78.0 = 1 −
19.1 = 1− 0.1)223.0 + 1(07.2
w
)w + 1( s d
=e
4
656.0= 1 − 349.0 =
xam
77.1 = 1− )890.0 + 1( ∗ 76.2 %8.9=w
3
4zc
m / Nk6.9 = 01 − 6.91 = wr − tasr = ' r
3zc
a p k 6 . 0 4 1 = 2 . 4 * 791.8 + 2.601 = 3h ' r + 2.601 = m /Nk791.8=
3
e +1 1 4 . 0 + 1 47.2 )w + 1( s d = ='r = r)1 − s d ( wr )1 − s d( 2.81)1 − 47.2 ( a pk 2. 601=8.3 *91+0.43= 2h 2r +0. 43= 2 zc apk0.43=0.2 * 71 = 1h1r = 1zc
w
vv = rs v
%0.23 = w
%0.23 86.2
8 6. 2 = s d % 0 0 1 = rs r
'r
d
e 5.2 r
r
tas
r
3
m /N k 9 . 6 1 = 0 1 *
27 v = g s = g d = dr 5.121 m
w s
3
m / nK 6 . 0 1
01 *
27 =g 54 − 5.121
c
a p k 5 . 7 1 = 1 * 5 . 7 1 = d 0r =
apk541 =
A 2 = =p 04 + 052 G + F
;Nk04=1 1
2
02 = dA Gr =G 3.3
01
1 b apk8.821 = 8.01 + 811 =
z
m
2z
apk8.01 = 00 2 ∗ )571.0 − 202.0 ( ∗ 2 = 571.0 =
1.3
13.3
1.3
3
9
82.25
0
502.0
1c
1 b /z 6 4 2 .0 )dfeb( b/z 6 4 2 0 b/ z
c
2 )m(Z 731.0 971.0 922.0 052.0
1c
8
p 1c 2 =
z
86.12 72.62 94.32 0
) apk ( 0p ) 2c −
1c
250.0 670.0 731.0 52,0
sv sv = =eQ w sv s d vv
68. 0=23.0 *86. 2= w s d =
w
w v
w sv s d = vv
w
w v s w
w
s s
v d=
v
v
∴
w
s s
v d = sm ⇒
w sv = sd m s
v
= sm ⇒
m
w
w
sm = v v
v
=%001 *
w
sm =w m
v = wv ⇒ % 0 0 1 =% 0 0 1 *
案答题习后课�华明赵�版三第》程工础基与学力土《
2
3
m c / g 0. 1 =
w
, 3 mc /g19.1= 6 05.2
,% 2.23=w , 07.2 = s d , 1 = sv
'
r
w
r
s
3
3
mc / g 0.1 =
mc / g 19.1 = 1 = sv
%2.23=
07.2= s d 3.2
v = g' = ' r v − sm
w v
6 5 4 3
3
m /Nk 6.02=01 *
3
27 = g 72 + 5.121
v = tasr v + sm
m /Nk 0. 81=01 * 997.1 = g = r
6. 92= %001 *
72 vv = = rs 8 wv
8=
w 1 54 sv = = wv 06.0 = = =e 5.121 − 5.921 wm 7 2 vv
6
%52
2
%81
g081
11.2
m.h / 3m 6−01∗ 8.1 = 1∗ 1∗ 6−01∗ 8.1 = tsv = Q h/m 6− 01 * 8.1 =
s / mm 7− 01 * 5 = s / mm 5− 0 1 * 5 0 . 0 =
2
5 0 0 . 0 - 5 1 0 . 0 * 5−01 * 5 = ) bi − i( k = v 3
5.1 b = 2 z
2=
5.1 b = 3 l
apk001 = 0p )3(
a pk 26.91=001
890.0 =
m * h / 3 m 3− 01 * 7.2 = 6 01 * 1 * 0063 * 4−01 * 5.7 = tsr = Q
s / mm 4− 01 * 5.7 = 510.0 * 2−01 * 5 = ik = v 510.0 = 02 L =i = 02.32 − 05.32 2h − 1h
3
27 v = = 5.921 m
7.2 = s d
g 5.121 = sm , dr
g 5.921=m
3
m c2 7 = v
tas
'r
r
r g5.121
r
s
e g5.921
3
Hale Waihona Puke Baidu
w
3
7.2
mc 27
4.2 8 7 6 5 4 3 2 1
m / Nk1.9 = 01 *
78.0 + 1 e +1 = gw = g' = 'r 1 − 7.2 1 − sd
571.0 = 571.0 =
3c
1=
b z
4.3
m 0. 2 = z
m
3 3.3
4.3
11
z apk 77 =
n im 0
p
apk 722 =
xam 0
p
dc
− p = 0p
dc
a pk 81=1
81 = dor =
a pk 59=
3 4 W A 4 = = 001 08 + 006 M G + F
d
98.1 4.7
30.2 8.8
31.2 0.01
60.2 2.71
)mc/ g(P ) %(w 21.2
s
g7.01=64.72-531.83
g531. 83=45.251 * 52.0 = 2wm ⇒ % 52=%001 * g 64.72= 1wm
m m
2w
= 2m
g45.251= sm ∴ g 081 = 1m
3
m / Nk0.81 = 5.3
m1 = d
m2 = b
z
apk 2.402=24.41+43+26.91+42.631 =
apk24.41= 001 270.0 270. 0= 1c
2=
4z
apk001 = 0p )4(
apk43= 001 071.0
0 71. 0 =
1c
2=
3z
333.1 =
n e = %001 = )n − 1( s dv s dw
w s
w
v v = rs v
n −1 e +1 =e⇒ =n n e
w
%001
v
v =n v
3
e +1 e +1 e +1 = = =g r d + wre rs wr s d + wrw s d wr)w + 1( s d
e +1 v =g =g =r )w + 1( s d m e = rs dw
d w s
026.0 = 1 −
66.1 = 1− 1 ∗ 96.2 ?
d
=e
%04 = rs 96.2 = s d
3
mc / g 66.1 =
d
w 96.2= s d , 3mc /g66.1=
%04 7.2
∴
33.0> rD >76.0 Q
595.0 =
164.0 − 349.0 nime − xame = = rD 656.0 − 349.0 e − xame