java中用键盘输入数据

import java.io.*;

public class HelloAl {

public static void main(String[] args) throws IOException { InputStreamReader reader = new InputStreamReader(System.in); BufferedReader input = new BufferedReader(reader); System.out.print("Enter your name: ");

String name = input.readLine();

System.out.println("Hello, " + name + "!");

}

}

我想继续问一下:

如果我想输入的字符是int型的.

也就是说我想read 出来的还是int型,我应该怎么办>

我记得BufferedReader类.没有readInt的方法吧!

是不是可以用别的类实现输入!

还是需要再调用一个stringToInt的方法呀!

import java.io.*;

public class YearOfBirth {

public static void main(String[] args) throws IOException { InputStreamReader reader = new InputStreamReader(System.in); BufferedReader input = new BufferedReader(reader); System.out.print("Enter your age: ");

String text = input.readLine();

int age = new Integer(text).intValue();

System.out.println("You are " + age + " years old, now,");

int year = 2003 - age;

System.out.println("so you were probably born in " + year);

}

}

定一一个int型数组，怎样从键盘输入为数组赋值？

int[] a = new int[10];

String inform;

BufferedReader bf = new BufferedReader( newInputStreamReader(System.in)

);

for(int i=0;i<10;i++)

{

inform = bf.readLine();

a[i] = count + Integer.parseFloat(inform);

}

importjava.util.Scanner;

public class CountNumberDemo {

public static void main(String[] args) {

int sum = 0;

int [] arr = new int [10];

Scanner s = new Scanner(System.in);

for(int i= 0; i<10;i++){

System.out.println("第" + (i+1) + "个数字：");

arr[i] = s.nextInt();

sum += arr[i];

}

System.out.println("你输入的数字是:");

for(int a : arr){

System.out.print(a + "\t");

}

System.out.println("\n他们的和是:" + sum);

}

}