ANSYS结构分析软件课程设计

[任务一]计算图示结构的内力，应力和变形，并根据强度理论做出强度判断，其中1668.333N =p F 、截面直径0.050275m =d 。

解：取F 点的竖向位移∆为基本未知量。

则每个杆件的轴力

i i

Ni l EAu F =

其中每个杆件的伸长量i i u αsin ∆= 考虑节点F 的平衡

∑===∑5

1sin ,0i P

i i N y F F F α

所以∑

==∆5

12sin i P i i F l EA

α

解得m 6

1065957.4-⨯=∆

N l EAu F F N N 430.1931

1

51===

N l EAu F F N N 040.3712

2

42==

=

N l EAu F N 168.5373

3

3==

Pa 97438.40851

51==

=A F N σσ .7913Pa 8134812

42===A F N σσ

.5840Pa 7066023

3==

A

F N σ

现根据强度理论进行强度判断，由HRB335的强度设计值是300000000Pa ，且

Pa Pa 0,.5840706602321===σσσ

第一强度理论：Pa f Pa r 300000000.584070660

21=≤=σ 第二强度理论：Pa f P r 300000000a .584070660

2)(3212=≤=--=σσνσσ 第三强度理论： Pa f P r 300000000a .5840706602312=≤=-=σσσ 第四强度理论：

[]

Pa f P r 300000000a .5840706602)()()(212

2312322214

=≤=⎭

⎬⎫

⎩⎨⎧-+-+-=σσσσσσσ电算结果如图所示：

命令流

/NOPR ! Suppress printing of UNDO process

/PMACRO ! Echo following commands to log

FINISH ! Make sure we are at BEGIN level /CLEAR,NOSTART ! Clear model since no SAVE found

! WE SUGGEST YOU REMOVE THIS LINE AND THE FOLLOWING STARTUP LINES

!*

!*

/NOPR

/PMETH,OFF,0

KEYW,PR_SET,1 KEYW,PR_STRUC,1 KEYW,PR_THERM,0

KEYW,PR_FLUID,0

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KEYW,MAGNOD,0

KEYW,MAGEDG,0

KEYW,MAGHFE,0

KEYW,MAGELC,0

KEYW,PR_MULTI,0

KEYW,PR_CFD,0

/GO

!*

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/PREP7

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ET,1,LINK1

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R,1,0.1984e-4, ,

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!*

MPTEMP,,,,,,,,

MPTEMP,1,0

MPDATA,EX,1,,2.0e11

MPDATA,PRXY,1,,0.3

K,1,0,0,,

K,2,2,0,,

K,3,4,0,,

K,4,6,0,,

K,5,8,0,,

K,6,4,-3,,

LSTR, 1,

6

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FLST,5,5,4,ORDE,2

FITEM,5,1

FITEM,5,-5

CM,_Y,LINE

LSEL, , , ,P51X CM,_Y1,LINE CMSEL,,_Y

!*

LESIZE,_Y1, , ,1, , , , ,1

!*

FLST,2,5,4,ORDE,2 FITEM,2,1 FITEM,2,-5 LMESH,P51X

FINISH

/SOL

FLST,2,5,1,ORDE,3 FITEM,2,1 FITEM,2,3 FITEM,2,-6

!*

/GO

D,P51X, , , , , ,ALL,

, , , ,

FLST,2,1,3,ORDE,1

FITEM,2,6

!*

/GO

FK,P51X,FY,-1668.3

/STATUS,SOLU

SOLVE

FINISH

/POST1

AVPRIN,0, ,

ETABLE,fxi,SMISC, 1

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ETABLE,,ERASE,1

AVPRIN,0, ,

ETABLE,mforce,SMISC, 1

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AVPRIN,0, ,

ETABLE,mstress,LS, 1

!*

!*

PLLS,MFORCE,MFORCE,1,

)/GOP ! Resume

printing after UNDO

process

)! We suggest a save at

this point

[任务二]计算图示结构的内力图，并对其应力和变形进行分析。

解：利用结构对称性，取1/2结构解题，其基本体系如下图示，