python利用7z批量解压rar

python利⽤7z批量解压rar
⼀开始我使⽤了rarfile这个库，奈何对于含有密码的压缩包⽀持不好，在linux上不抛出异常；之后有⼜尝试了unrar。

⽐rarfile还费劲。

所以⽤了调⽤系统命令的⽅法，⽤7z来解压
通过apt可以安装上7z-full和7z的rar插件
有⼀个地⽅要注意 -o 和-p与后⾯的⽬录、密码之间没有空格！！
同样可以⽤这个代码暴⼒破解压缩包密码
# coding:utf-8
import os
import zipfile
import traceback
import time
import shutil
import sys,getopt
succeedpath=""
unsucceedpath=""
psds={"2018","123456"}
opts,args=getopt.getopt(sys.argv[1:],"p:")
path=args[0]
for psd in args[1:]:
psds.add(psd)
#for op,value in opts:
# if op in ("-p","--password"):
# psds.add(value)
def mkdirs(dirpath):
global succeedpath,unsucceedpath
succeedpath=os.path.join(dirpath,"0.succeed")
unsucceedpath=os.path.join(dirpath,"0.unsucceed")
if(not os.path.exists(succeedpath)):
os.makedirs(succeedpath)
if(not os.path.exists(unsucceedpath)):
os.makedirs(unsucceedpath)
def extractdir(path):
for filename in os.listdir(path):
filepath=os.path.join(path,filename)
if(os.path.isfile(filepath)):
extractfile(filepath)
def extractfile(path):
(dirpath,filen)=os.path.split(path)
print("解压"+filen+" ing...")
try:
if(filen.endswith(".rar") or filen.endswith(".zip")):
path=os.path.abspath(path)
dirpath=os.path.abspath(dirpath)
cmd="7z x "+path+" -o"+dirpath+" -y "+" -p"
state=False
if(os.system(cmd)==0):
state=True
else:
for psd in psds:
cmdp="7z x "+path+" -p"+psd+" -y "+" -o"+dirpath
if(os.system(cmdp)==0):
state=True
break
else:
return
if (state):
shutil.move(path,succeedpath)
else:
shutil.move(path,unsucceedpath)
with open(os.path.join(dirpath,"errorinfo.txt"),"a+") as errorinfo:
errorinfo.write("time:"+str(time.time())+"\n")
errorinfo.write("解压出错！\n可能是密码错误！\n")
except :
with open(os.path.join(dirpath,"errorinfo.txt"),"a+") as errorinfo:
errorinfo.write("time:"+str(time.time())+"\n")
errorinfo.write("解压出错！\n")
traceback.print_exc(file=errorinfo) shutil.move(path,unsucceedpath)
if(os.path.isdir(path)):
dirpath=path
mkdirs(dirpath)
extractdir(dirpath)
elif(os.path.isfile(path)):
filepath=path
(dirpath,filename)=os.path.split(path) mkdirs(dirpath)
extractfile(path)
else:
print("输⼊错误！请重新输⼊！")。