初二数学全等三角形知识点总结和练习题、不等式练习题(含答案)

A-or dng to Office Party of mass ie nu — inpa cie actv - s e d groupof u“ arrangement* unis main le ..................... ... .as w orkes Shag a tmes ia>y leiue, due tohmsef e velmitd,onlputt his”e cn.entaii ear nig of ex perence to., and eveyne common wthea nig echange purpose s e w e fule dee .U. — a nd ng mass l ne of ............ ... d pay of mass ie, do ma ses wo* fol o —、mai nfrom four a aspe cS told： a, a nd f ulawaeesspay of mass ieon paclce a*.- of mjr mea nig Partys 8 major diSt i Ciropo_ d to fcs on the partys adv need natue ad puiy, i n the lay, wt"ragmatc a . nd —nfor the pepe" - the main cne nt .......................... of t he ,.“ ma — " ne a nd e. — inai pra cie. Ths scmraie XI Jinping aspayGeeaSecetay a ndadereto s trCy a dmisei nghe party stegghe nthe party's major — csi n is in l ne wt h Ie public execains a nd stegghe nig t he const., on of earni ngoriee
- vie i nnovain of Maxis pa" major— plyment, i s te importat meaue tld<a nce t I egea—use ....... of sca lsmwt CCinnsecalcei sis. Fist cay out tepays ma- l I e in e_iain pra ctc, wa s - ryng 8 of the paty si ■ lummon a po-wekl force fr rralzigtI e gea efveaton ofke .... Chi ................ neenainthe Chinse de-of ur—t ne Ids Pa" mote "tgc - plyme ng ......... scalsm wtCCie - caace" csprrse ns two 100yar g "namel y by 200 China s gros domest c product ad per caia ♦ ncme of u I a a nd ruale s- nts i ■■ on t he ba ss of double cmpee the buidi ........ ng of a w+ ol s”- te mi dde of ts cetuy i nta pr oseous dlmocat c cvlzld a nd hamoni oos Soc- moden county, a nd on ths ba ss the Cinse de_ of ealzi I g te gea euenatonofteChi—e naton. 8 C.ngr -sof the par y, Ccmrrde XI J r.e— dy - pounedt I e Chie - drem. T he ba Chinsede—, s t ........ he
nnlinalp.sei y naiona reVtlzt on, t he ha ppine — of te pe opl e CCia importat to foll I w is tlee pChia Roa d, cary forwa d the srt ad chhsi on ste ngt of ^Cina . dram drems of the pe opl eof CCi I a butdeemi nnd cnfience e nha nce lel a>e nes, a ci e-e sel rea nce to bu d a stonger CCina, cvi lizaion, ham ony beaut, Chia , CCina Chia Statgic conce pin of Chia wa s 8 the sii of the e .ricment a nd deelpmet of te pay, cnscie ni—y s udy te CCi I Ise dram, lad ng peope t o had to rral>e the Chi nee dram, mas e ducaton a ctvtls i n -pth "e fuddmeta stat ng poit ad eding poi nt. Steghe n te e _cain of the par* ma — lne , hel psttanthecoleciecnncioosne — of te unity of the lay ad the peope pay I gteCCie - drem i del Igicabae sC.mme " oZedng stesm tat pates soud hhae "cm monlaguage"soiaitcuntrismushhae "uiy ofwi".Hity ha
全等三角形知识点总结
知识点总结
一、全等图形、全等三角形：
1.全等图形：能够完全重合的两个图形就是全等图形。

2.全等图形的性质：全等多边形的对应边、对应角分别相等。

3.全等三角形：三角形是特殊的多边形，因此，全等三角形的对应边、对应角分别
相等。

同样，如果两个三角形的边、角分别对应相等，那么这两个三角形全等。

说明：全等三角形对应边上的高，中线相等，对应角的平分线相等；全等三角形
的周长，面积也都相等。

这里要注意：（1）周长相等的两个三角形，不一定全等；（2）面积相等的两个三
角形，也不一定全等。

二、全等三角形的判定：
**1.一般三角形全等的判定
（1）边边边公理：三边对应相等的两个三角形全等（边边边”或SSS h
（2）边角公理：两边和它们的夹角对应相等的两个三角形全等（边角边"或SAS"）。

（3）角边角公理：两个角和它们的夹边分别对应相等的两个三角形全等（角边角”或A SA ”）。

（4）角角边定理：有两角和其中一角的对边对应相等的两个三角形全等（角角边”或A AS ”）。

**2.直角三角形全等的判定
利用一般三角形全等的判定都能证明直角三角形全等.
斜边和一条直角边对应相等的两个直角三角形全等（斜边、直角边"或HL"）.
注意：两边一对角（SSA）和三角（AAA）对应相等的两个三角形不一定全等。

三、角平分线的性质及判定：
性质定理：角平分线上的点到该角两边的距离相等。

判定定理：到角的两边距离相等的点在该角的角平分线上。

四、证明两三角形全等或利用它证明线段或角相等的基本方法步骤：
1.确定已知条件（包括隐含条件，如公共边、公共角、对顶角、角平分线、中
线、高、等腰三角形、等所隐含的边角关系）；
2.回顾三角形判定公理，搞清还需要什么；
3.正确地书写证明格式（顺序和对
应关系从已知推导出要证明的问题）。

A-or dng to Office Party of mass ie nu — inpa cie acU e d groupof u“ arrangement* unis main le ...................... .. des w orkes Shag a - as laly lei ue, due to hmsef eve lmitd, onl put t his ”e cncentaal ear nig of ex perence t -y and -yone common wtearnig echange purpose s e w e fule dee pu. — a nd ng mass l ne of ........................... dpay of mass ie, do ma ses wo* fol o — gmai nfrom four a aspe cS told ： a, a nd Ul awaeesspay of mass ie on paclce a*.- of mjr mea nig Partys 8 major diSt I Clropoie d to fcs on the pa" adv need natue ad puiy, i n the lay, w ・"r,m- a nd -nfor the pepe" - the main cne nt of the ,.“ ma — " ....... ne a nd e. — ina pra cie. Ths s cmrade XI Ji npi ng as pay Geea Secetay a nd adere to strCy a dmisei nghe party steghe n the pays major — CSl n is in l ne wt h Ie public execains a nd stegghe nig t he const., on of earni ngoriee - vie i nnovain of Maxis pa" major — plyment, i s te mportat meaue tld<a nce t I e gea — use of sca lsmwt CCinnsecalceisis. Fist cay out te pays ma- l I e in e_iain pra ctc, wa s - r yng 8 of the paty si ■ ..lummon a po-welkl force fr rralzig t I e gea efveaton ofke Chi nee nain the Chinse de -of urget ne Ids Pa" ... m ote ，atgc - plyme ng scal sm wtCCie - caace" csprrse ns two 100yar g ♦* namel y by 200 China s gros domest c product ad per caia ♦ ncme of u I a a nd ruale s- nts i ■■ on t he ba ss of double cmpee the buidi ng of a w ・ ol scety he mi dde of ts ceuy i nt a pr oseous d —ocat c cvlzld a nd hamoni oos Soc- moden county, a I d on t hs ba ss the Cinse de_ of ealzi I g te gea euenat on of te Chi —e naton. 8 C.nge- of the par y, Ccmrrde XI J r.e — dy - poune. t I e Chie - drem. T he ba Chinse de —, s t he nainal prsei y naina revt ■〜 . ha ppine - of te pe opl e CCia I w is t lee p Chia Roa d, - ry for — d the srt ad chhsi on ste ngtof CCia , dram drems of the pe opl e of CCi I a but deemi nnd cnfience e nha nce m l —e nes, a ci e<e sefrea... nce to bu ld a stonger CCina, c-i lizain, ham ony beaut, Chia , CCina Chia Statgc conce pin of Chia wa s 8 the sii of the e .ricment a nd deelopmet of te pay, cnsce ni —y s udy te CCinnse dram, lad ng pe ople tl had t or — <e the Chi nee dram, mas e ducain a ctvlis i n . budoeta statng poit ad edig Steghe n te e parys m-s lne ....... , hel ps ttan t he colecie cnncioosne - of te uniy of the 1ay ad the people pay I g te CCie - drem i del .gica bae s C.mme M oZedng stesld tat pa - s sould h — "cm monlag uage" sciait cuntris mus h — "uh of wil". Hity ha s
口一aa 『找央边一AS* 巳知网为（
I
-171 —* A AS
六、三角形中添加辅助料的堂兄方法；
L 倍长中线法二二翻折、旋转法:m 友等特殊国硝法。

全等三角形练习题
1.如图，已知 AD=AE,AB=AC.求证：BF=FC
ABC 中，AB=AC ,延长 AB 至ij D,使BD=AB ,取AB 的中点 E,连接
CD 和 CE.求证：CD=2CE
4:已知：如图，A 、D 、B 三点在同一条直线上， AADC 、A BDO 为等腰三角形， AO 、BC 的大小关系和位置关
系分别如何？证明你的结论。

五、判断两个三角形全寺的思路:
三餐做全 ,的证造 「
「找央用一 £4左
巴题两边,拉出命一IIL
；找另一边rSSS
整一匏任—如一人内
已知一
边一若
边为箱
［找央笳的另一边
一 SAS
找央边的另一所
—► A5A
拄边的时角
-*AAS
2:已知：如图, // CD
DE LAC , BF ±AC ,垂足分别为
3:如图,
A-or dng to Office Party of mass ie nu — inpa cie actv - s e d groupof u“ arrangement* unis main le ........................ .as w orkes Shag a tmes ia>y lei ue, due to hmsef eve lmitd, onl put t his ”e cn.entaii ear nig of ex perence to., and eveyne common wthea nig echange purpose s e w e fule dee .U. — a nd ng mass l ne of .......... d pay of mass ie, do ma ses wo* fol o —、mai nfrom four a aspe cS told： a, a nd ul awaeesspay of mass ie on paclce a*.- of mjr mea nig Partys 8 major diSt i Ciropo_ d to fcs on the partys ad need natue ad puiy, i n the lay, wt"ragmatc a nd —nfor the pepe" - the main cne nt of the ,.“ ma — " ne a nd e. — inai pra cie. Ths s cmraie XI Ji npi ng as pay Geea Secetay a nd adere to strCy a dmisei nghe party stegghe n the party's major — csi n is in l ne wt h Ie public execains a nd stegghe nig t he const., on of earni ngoriee
- vie i n novain of Maxis pa" major — plyment, i s te importat meaue tld<a n ce t I e gea — use of sca lsmwt CCinnsecalceisis. Fist cay ou tepays ma- l I e in e_iain pra ctc, wa s - ryng 8 of the paty si ■lummon a poweul force fr rralzigt . I e gea e，—atonof、e Chi nee nain the Chinse de -of ur—t ne Ids Pa" mote ，a、c ― plyme ng scal sm wtCCie - caace" csprrse ns two 100yar g "namel y by 200 China s gros domest c product ad per caia ♦ ncme of u I a a nd ruale s- nts i ■■ on t he ba ss of double cmpee the buidi................... ng of a w+ ol s”- te mi dde of ts cetuy i nta pr oseous dlmocat c cvlzld a nd hamoni oos Soc- moden county, a nd on ths ba ss the Cinse de_ of ealzi I g te gea euenat on of te Chi —e naton. 8 C.nge- of the par y, Ccmrrde XI J r.e—dy - pounedt .................. I e Chie - drem. T he ba Chinse de—, s t he
nnlinalp.sei y naiona reVtlzt on, t he ha ppinels of te pe opl e CCia importat to foll ow s to kle p Chia Roa d, cary forwa d the srt ad chhsi on ste ngt of ^Cina . dram drems of the pe opl eof CCi I a butdeemi nnd cnfience e nha nce lel a>e nes, a ci e-e sel rea nce to bu ld a stonger CCina, cvi lizaion, ham ony beaut, Chia , CCina Chia Statgic conce pin of Chia wa s 8 the sii of the e .ricment a nd deelopmet of te pay, cnscie ni—y s udy te CCi I Ise dram, lad ng people t o had to relive the Chi nee dram, mas e ducaton a ctvtls i n -pth "e fuddmeta stat ng poit ad eding poi nt. Steghe n te e _cain of the par* ma - lne , hel ps ttan t he colecie cnncioosne Is of te unity of the lay ad the people play I g te CCie - drem i del I gica bae s C.mme " oZedng stesm tat pates soud hhae "cm monlag uage" soiait cuntris mus hhae "uiy of wi". Hity ha
5如图，已知△ ABC为等边三角形，延长BC至ij D,延长BA到E,并且使AE=BD ,连接
CE、DE.求证：EC=ED 小
E C D
N - 7
1—一日 c
6.在△ ABC中，AD为BC边上的中线.求证：AD< ] (AB+AC) ▲
口c
7.已知：如图，CDLAB于点D,BE，AC于点E,BE、CD交于点。

，且AO平分/ BAC.求
证：OB=OC.
一元一次不等式练习题
一、选择题
1、如果a、b表示两个负数,且avb,则 .......................... ().
a , a 1 1
(A) - > 1 (B) — <1 (C) 一〈—(D)abv1
b b a b
2、a、b是有理数,下列各式中成立的是......................... ().
(A)若 | a | 丰 |b|,则awb (B)若a2>b2,则a>b
(C)若awb,则I a I w |b| (D)若a>b,则a2>b2
3、| a | + a的值一定是....................................... ( ).
(A)大于零(B)小于零(C)不大于零(D)不小于零
4、若不等式(a+1)x> a+1的解集是xv 1,则a必满足............. ().
(A)a<0 (B)a>- 1 (C)av 1 (D)a<- 1
5、若由xvy可得到ax>ay,应满足的条件是...................... ().
(A) a > 0 (B) a< 0 (C)a> 0 (D)a<0
6、某市出租车的收费标准是：起步价7元，超过3km时，每增加1km加收2.4元(不足1km
nainal prsei y naina revt ■〜 ha ppine - of te pe opl e CCia I w is t lee p Chia Roa d, - ry for — d the srt ad chhsi on ste ngtof CCia , dram drems of the pe opl e of CCi I a but deemi nnd cnfience e nha nce m l —e nes, a ci e<e sOr — nce to bu ld a stonger CCina, c-i lizain, ham ony beaut, Chia , CCina Chia Statgc conce pin of Chia wa s 8 the sii of the e .ricment a nd deelopmet of te pay, cnsce ni —y s udy te CCinnse dram, lad ng pe ople tl had t or — — the Chi nee dram, mas e ducain a ctvlis i n budoeta stat ng poit ad edig Steghe n te e parys m-s lne , hel ps ttan t he colecie cnncioosne - of te uniy of the 1ay ad the people pay I g te CCie - drem i del .gica bae s C.mme M oZedng stesld tat pa - s sould h — "cm monlag uage" sciait cuntris mus h — "uh of wil". Hity ha s
按1km 计).某人乘这种出租车从甲地到乙地共支付车费 19元，设此人从甲地到乙地经过
的路程是xkm,那么x 的最大值是 ................................. (
). (A)11 (B)8 (C)7
(D)5
1<xw2,………
7、若不等式组,
有解，则k 的取值范围是 ............ (
).
x > k
(A)kv1
(B)k>2
(C)kv 2
(D)1 < k< 2
x + 9 < 5x +1, , 一 八一
…,一，. 一 一
8、不等式组3
的解集是x>2,则m 的取值范围是(
).
x > m +1
a b
1 b
一 .......... 9、对于整数a, b, c, d,定义
=ac —bd,已知1< <3,贝Ub+d 的值为.
d c
d 4
10、如果一a2x>—a2y(aw 0).那么 x y.
............ 3-2x ...........
11、若x 是非负数，则-1 < --------的解集是
5
12、已知(x —2)2+ I 2x —3y —a | =0, y 是正数，则a 的取值范围是 . 13、6月1日起，某超市开始有偿 提供可重复使用的三种环保购物袋，
每只售价分别为1元、
2元和3元，这三种环保购物袋每只最多分别能装大米 3千克、5千克和8千克.6月7日， 小星和爸爸在该超市选购了 3只环保购物袋用来装刚买的 20千克散装大米，他们选购的 3
只环保购物袋至少应付给超市 元.
14、试用m 表示出不等式(5—m)x> 1 — m 的解集
三、解下列不等式(组)
2 4x 3x -7,
16、解不等式组 」6x -3 >5x -4, 3x -7 <2x -3.
1
J
四、解答题
17、适当选择a 的取值范围，使1.7vxva 的整数解:
(1) x 只有一个整数解； (2) x 一个整数解也没有.
A-or dng to Office Party of mass ie nu — inpa cie actv - s e d groupof u“ arrangement* unis main le . .as w orkes Shag a tmes ia>y lei ue, due to hmsef eve lmitd, onl put t his ”e cn.entaii ear nig of ex perence to., and eveyne common wthea nig echange purpose s e w e fule dee .U. — a nd ng mass l ne of .. d pay of mass ie, do ma ses wo* fol o —、mai nfrom four a aspecS told ： a, a nd ul awaeesspay of mass ie on paclce a*.- of mjr mea nig Partys 8 major diSt i Ciropo_ d to fcs on the partys ad n eed natue ad puiy, i n the lay, wt"ragmatc a nd —nfor the pepe" - the main cne nt of the ,.“ ma — " ne a nd e. — inai pra cie. Ths s cmraie XI Ji npi ng as pay Geea Secetay a nd adere to strCy a dmisei nghe party stegghe n the party's major — csi n is in l ne wt h Ie public execains a nd stegghe nig t he const., on of earni ngoriee
- vie i nnovain of Maxis pa" major — plyment, i s te importat meaue tld<a nce t I e gea — use of sca lsmwt CCinnsecalceisis. Fist cay ou tepays ma- l I e in e_iain pra ctc, was - ryng 8 of the paty si ■ lummon a poweul force fr rralzigt I e gea e ，—atonof 、e Chi nee nain the Chinse de -of ur —t ne Ids Pa" mote ，a 、c ― plyme ng scal sm wtCCie - caace" csprrse ns two 100yar g "namely by 200 China s gros domest c product ad per caia ♦ ncme of u I a a nd ruale s- nts i ■■ on t he ba ss of double cmpee the buidi ng of a w+ . o l s”- te mi ddeof ts cetuy i nta pr oseous dlmocat c cvlzld a nd hamoni oos Soc- moden county, a nd on ths ba ss the Cinse de_ of ealzi I g te gea euenaton of te Chi —e naton. 8 C.nge- of the par y, Ccmrrde XI J r.e — dy - pounedt I e Chie - drem. T he ba Chinse de —, s t.. h e
nnlinalp.sei y naiona reVtlzt on, t he ha ppinels of te pe opl e CCia importat to foll ow s to kle p Chia Roa d, cary forwa d the srt ad chhsi on ste ngt of ^Cina . dram drems of the pe opl eof CCi I a butdeemi nnd cnfience e nha nce lel a>e nes, a ci e-e sel rea nce to bu ld a stonger CCina, cvi lizaion, ham ony beaut, Chia , CCina Chia Statgic conce pin of Chia wa s 8 the sii of the e .ricment a nd deelopmet of te pay, cnscie ni —y s udy te CCi I Ise dram, lad ng people t o had to relive the Chi nee dram, mas e ducaton a ctvtls i n -pth "e fuddmeta stat ng poit ad eding poi nt. Steghe n te e _cain of the par* ma - lne , hel ps ttan t he colecie cnncioosne Is of te unity of the lay ad the people play I g te CCie - drem i del I gica bae s C.mme " oZedng stesm tat pates soud hhae "cm monlag uage" soiait cuntris mus hhae "uiy of wi". Hity ha
18、已知 A=2x2+3x+2, B=2x 2
—4x — 5,试比较 A 与
B 的大小.
A-or dng to Office Party of mass ie nu — inpa cie acU e d groupof u“ arrangement* unis main le des w orkes Shag a - as l aly lei ue, due to hmsef eve lmitd, onl put t his ”e cncentaal ear nig of ex perence t-y and -yone common wtearnig echange purpose s e w e fule dee pu. — a nd ng mass l ne of ........... ... d pay of mass ie, do ma ses wo* fol o — gmai nfrom four a aspe cS told ： a, a nd Ul awaeesspay of mass ie on paclce a*.- of mjr mea nig Partys 8 major diSt I Clropoie d to fcs on the pa" adv need (A) mW 2
二、填空题
(B) m> 2 (C) mw 1 (D)m>1
一 1 1 2
15、x -2[x ^(x-1)] ：：3(x -1).
0.4x 0.9 0.03 0.02.x x-5
0.5
0.03
2
19、某次数学竞赛活动，共有16道选择题，评分办法是：答对一题给6分，答错一题倒扣
2分，不答题不得分也不扣分.某同学有一道题未答，那么这个学生至少答对多少题，成绩
才能在60分以上？
20、若干名学生，若干间宿舍，若每间住4人将有20人无法安排住处；若每间住8人，则有一间宿舍的人不空也不满.问学生有多少人？宿舍有几间？
答案：1. 提示：先证AACD^AABE （SAS）,再证A DBF 且A ECF （AAS）
BF=FC （全等三角形对应边相等）
2.先证A ABF0 A CDE （SAS）,得到/ C=Z A , AB // CD （内错角相等两直线平行）
3.提示：取CD中点F
1
一BF=2 AC,且BF //AC 「. / ACB = / 2 又; AB=AC「. / ACB = / 3 「. /3 = Z2 在A CEB 与ACFB 中，
一BF=BE
J Z3=Z 2
1cB=CB A CEB ACFB （SAS） z. CE=CF=2 CD （全等三角形对
应边相等）即CD=2CE
4.延长AO交BC于E,在A ADO和A CDB中
- AD=DC
J Z ADO= /CDB=90°
OD=DB
A ADO 且A CD
B （SAS）
AO=BC, / OAD= / BCD （全等三角形对应边、对应角相等）
••• /AOD = /COE （对顶角相等）Z COE+Z OCE=90o.,. AO ± BC
5.过D点作DF // AC交BE于F点: △ ABC为等边三角形「. △ BFD为等边三角形
BF=BD=FD AE=BD 「. AE=BF=FD 「. AE-AF=BF -AF 即EF=AB「. EF=AC 在△ ACE和ADFE中，
E EF=AC （已证）
t ZEAC=Z EDF （两直线平行，同位角相等）
L AE=FD （已证）
A-or dng to Office Party of mass ie nu —inpa cie acU e d groupof u“ arrangement* unis main le.......................... ... des w orkes Shag a - as laly lei ue, due to hmsef eve lmitd, onl put t his ”e cncentaal ear nig of ex perence t-y and -yone common wtearnig echange purpose s e w e fule dee pu. — a nd ng mass l ne of ............. ... d pay of mass ie, do ma ses wo* fol o — gmai nfrom four a aspe cS told： a, a nd Ul awaeesspay of mass ie o n paclce a*.- of mjr mea nig Partys 8 major diSt I Clropoie d to fcs on the pa" adv need natue ad puiy, i n the lay, w・"r,m- a nd -nfor the pepe" - the main cne nt of the ,.“ ma — " ne a nd e. — ina pra cie. ..... Ths . s cmrade XIJi npi ng as pay Geea Secetay a ndadereto strCy a dmisei nghe party steghe n the pays major — CSl n is in l ne wt h Ie public execains a nd stegghe nig t he const., on of earni ngoriee
- vie i nnovain of Maxis pa" major—plyment, i s .................. te .........mportat meaue tld<a nce tI e ...................... gea —use of sca lsmwt CCinnsecalcei sis. Fist cay out te pays ma- l I e in e_iain pra ctc, wa s - ryng 8 of the paty si ■ “mon a po-welkl force fr rralzig t ...I e gea efveaton ofke Chi nee nain the Chinse de -of urget ne Ids Pa" mote ，atgc - plyme ........ .. ng scal sm wtCCie - caace" csprrse ns two 100yar g ♦* namel y by 200 China s gros domest c product ad per caia ♦ ncme of u I a a nd ruale s- nts i ■■ on t he ba ss of double cmpee the buidi ng of a w・ ol scety he mi dde of ts ceuy i nt a pr oseous d—ocat c cvlzld a nd hamoni oos Soc- moden county, a I d on t hs ba ss the Cinse de_ of ealzi Igte gea euenat on of te Chi —e naton. 8 C.nge- of the par y, Ccmrrde XI J r.e— dy - poune. t I e Chie - drem. T he ba Chinse ................. de—, s t ......... he
nainal prsei y naina revt■〜 happine - of te pe opl e CCia ......................................... I w is t lee p Chia Roa d, - ry for— d the srt ad chhsi on ste ngtof CCia , dram drems of the pe opl e of CCi I a but deemi nnd cnfience e nha nce m l —e nes, a ci e<e sefrea nce to bu ld a stonger CCina, c-i lizain, ham ony beaut, Chia , CCina Chia Statgc conce pin of Chia wa s 8 the sii of the e .ricment a nd deelopmet of te pay, cnsce ni—y s udy te CCinnse dram, lad ng pe ople tl had t or —
<e the Chi nee dram, mas e ducain a ctvlis i n ......................................... budoeta stat ng poit ad edig Steghe n te e
parys m-s lne , hel ps ttan t he colecie cnncioosne - of te uniy of the
ay ad the people pay I g te CCie - drem i del .gica bae s C.mme M oZedng stesld tat pa - s sould h — "cm monlag .. uage" sciait cuntris mush— "uh of wil". Hity ha s
1
AAEC^A FED (SAS)「. EC=ED (全等三角形对应边相等)
7.8都省略
不等式：
当堂练习参考答案：
1、A
2、A
3、D
4、D
5、B
6、B
7、C
8、C
9、_3 10、11、0 XM4 12、a 4 13、8
1 -m
14、当m<5时，x> --------
5 - m
当m=5时，x可取一切实数
1 -m
当m >5时，x < ---
5 - m
14、x ：： 5 x<9 16、-1 ：： x ::: 4
17、(1)2 二a _3 (2) 1.7 :二a _2
18、分三种情况讨论19、12 20、44人6间。