包九中高一月考试卷及答案
内蒙古包头市第九中学2015-2016学年高一10月月考语文试卷 Word版含答案
资料概述与简介 包九中2015-2016学年度高一年级月考考试 语文命题人: 本试卷分第Ⅰ卷和第Ⅱ卷两部分,共8页。
满分150分。
考试用时150分钟。
考试结束后,请将答题卡交回。
注意事项:答卷前,考生务必用黑色签字笔将自己的姓名、座号、考生号填写在答题卡和试卷规定的位置上。
第Ⅰ卷阅读题 一、现代文阅读(9分,每小题3分) 阅读下面的文字,完成1~3题。
同其他林木相比,竹子颇有一些独特之处,如虚心、有节、清拔凌云、不畏霜雪、随处而安等等。
这些特点,很自然地与历史上某些审美趣味、伦理道德意识发生契合,进而被引入社会伦理美学范畴,成为君子贤人等理想人格的化身,并对中国传统文化的发展产生深刻的影响。
不仅春风得意的封建宠儿常常以竹来互相吹捧或以竹自诩,那些落泊荒野的书生和隐居“南山”、待价而沽的名士,也普遍寓情于竹、引竹自况。
在这种独特的文化氛围中,有关竹子的诗词歌赋层出不穷,画竹成为中国绘画艺术中一个重要门类,封建士大夫在私园、庭院中种竹养竹以助风雅,亦成为普遍风气。
最早赋予竹以人的品格,把它引入社会伦理范畴的,要算《礼记》了。
《礼记·祀器》中说:“……其在人也,如竹箭之有筠也,如松柏之有心也。
二者居天下之大端矣,故贯四时而不改柯易叶。
”魏晋时期政治局势反复无常,文人士子意气消沉,以阮籍、嵇康为代表的一批失意文人,为逃避现实,不与当权者合作,遁隐竹林,借竹之高标、清姿佐己之风流,在当时社会引起很大震动,对后代封建文人的行止也产生了莫大影响,可以说,敬竹崇竹、寓情于竹、引竹自况,竹林七贤乃是“始作俑者”。
自此以后,中国的文人士大夫便与竹子结下了不解之缘。
晋室东渡之后,文人士子大量南逃,南方秀丽的山水将他们从对现实的迷惘、懑闷中解脱出来,他们纵情山水、远离尘嚣,与大自然融为一体,广袤的竹林正是他们托身、浪迹之所,竹子清丽俊逸、挺拔凌云的姿质令风流名士们沉醉痴迷。
一时间,闻有好竹即远涉造访而不通名姓者有之,种竹十顷栖居林中者有之,对竹啸吟终日不辍者亦有之,王徽之、张廌、翟庄、袁粲等,是其中风流最著者;王徽之乃至声称:不可一日无此君!这一时期,文人雅士赋竹、赞竹,为竹作谱,蔚成风气,世界上最早的一部植物专谱——戴凯之的《竹谱》正是在这种风气下以韵文的形式诞生的。
内蒙古包头九中2015-2016学年高一上学期12月月考数学试卷 含解析
2015-2016学年内蒙古包头九中高一(上)12月月考数学试卷一、选择题(本大题共17个小题,1—14每小题5分,15-17每题4分共计82分,在每小题给出的四个选项中,只有一项是符合题目要求的)1.cos390°=()A.﹣B.﹣ C. D.2.已知cosθ•tanθ<0,那么角θ是()A.第一或第二象限角B.第二或第三象限角C.第三或第四象限角D.第一或第四象限角3.集合M={α|}与N={α|}之间的关系是( )A.M⊆N B.N⊆M C.M=N D.M∩N=∅4.设,则()A.a>b>c B.c>a>b C.b>a>c D.b>c>a 5.集合{α|kπ+≤α≤kπ+,k∈Z}中的角所表示的范围(阴影部分)是()A.B. C.D.6.若,则不等式f(x)>f(8x﹣16)的解集是( )A.(0,+∞) B.(0,2] C.[2,+∞) D.[2,)7.函数f(x)=2x|log0。
5x|﹣1的零点个数为()A.1 B.2 C.3 D.48.若f(x)和g(x)都是奇函数,且F(x)=f(x)+g (x)+2在(0,+∞)上有最大值8,则在(﹣∞,0)上F(x)有()A.最小值﹣8 B.最大值﹣8 C.最小值﹣6D.最小值﹣49.已知f(lnx)=x,则f(1)=()A.e B.1 C.e2D.010.已知函数f(x)是R上的增函数,A(0,﹣1),B(3,1)是其图象上的两点,那么|f(x+1)|<1的解集的补集是()A.(﹣1,2)B.(1,4)C.(﹣∞,﹣1)∪[4,+∞)D.(﹣∞,﹣1]∪[2,+∞)11.在y=2x,y=log2x,y=x2,这三个函数中,当0<x1<x2<1时,使f()<恒成立的函数的个数是()A.0个B.1个 C.2个 D.3个12.函数y=2x﹣x2的图象大致是()A.B.C.D.13.函数的值域为R,则实数a的取值范围是()A.(﹣∞,0]B.(﹣∞,1] C.[0,+∞) D.[1,+∞)14.一个半径为R的扇形,它的周长为4R,则这个扇形所含弓形的面积为()A.B.C.D.R2﹣sin1•cos1•R215.函数f(x)=log a(6﹣ax)在[0,2]上为减函数,则a 的取值范围是( )A.(0,1) B.(1,3)C.(1,3] D.[3,+∞) 16.设函数f(x)=|log a x|(0<a<1)的定义域为[m,n](m<n),值域为[0,1],若n﹣m的最小值为,则实数a的值为( )A.B.或C. D.或17.已知函数f(x)=ax2+bx+c(a>0)的零点为x1,x2(x1<x2),函数f(x)的最小值为y0,且y0∈[x1,x2),则函数y=f(f(x))的零点个数是( )A.3 B.4 C.3或4 D.2或3二、填空题:本大题共5小题,每小题5分,共20分,把答案填在答题卷的横线上..18.已知函数f(x)在(0,+∞)上有定义,且对于任意正实数x、y,都有f(xy)=f(x)+f(y),则f(1)= .19.计算的结果是.20.定义运算min{x,y}=,已知函数g(x)=min{()x,2x+1},则g(x)的最大值为.21.下列说法正确的是.(只填正确说法的序号)①若集合A={y|y=x﹣1},B={y|y=x2﹣1},则A∩B={(0,﹣1),(1,0)};②函数y=log(x2﹣2x﹣3)的单调增区间是(﹣∞,﹣1);③若函数f(x)在(﹣∞,0),[0,+∞)都是单调增函数,则f(x)在(﹣∞,+∞)上也是增函数;④函数y=是偶函数.22.已知函数,若f(﹣1)≈1。
内蒙古包头市第九中学高一6月月考化学试题含答案.doc
【全国百强校】内蒙古包头市第九中学2015-2016学年高一6月月考化学试題相对原子质量 C 12 N 14 O 16 Na 23 Al 27 Cl 35.5 K 39Ca 40-、选择题(每小题只有一个正确选项,1〜15题每小题2分,16〜20题每小题3分,共 45分) 1、下列关于节能与可再生能源表述不正确的是A. “低碳”意指更低的二氧化碳气体的排放B. 太阳能、水能、风能都属于可再生能源C. 太阳能电池的工作原理是光能与化学能的转换D. 利用燃气轮机进行天然气发电不属于可再生能源利用2、下列对应的表达方式错误的是3、X 、Y 是短周期元素,二者能形成化合物X 2Y 3O 若已知X 的原子序数为n,则Y 的原子叙 述不可能是A. n+11B. n-5C. n+3D. n+44、甲、乙、丙、丁为四种短周期元素,在周期表中,甲与乙、丙、丁在周期表中的位置关 系如下图所示(原子序数:乙〉丙)。
丁的原子序数与乙、丙原子序数之和相等,4种 元素原子的最外层电子数之和为24。
下列判断正确的是 甲A. 元素甲的简单气态氢化物稳定性比乙的强B. 元素乙在周期表中的位置为第2周期,VIA 族C. 元素丙和元素丁的最高价氧化物对应的水化物均为强酸D. 4种元素的简单阴离子半径从大到小顺序为:丁〉乙>丙> 甲5、X 、Y 、Z 、M 是元素周期表中前20号元素,其原子序数依次增大,且X 、Y 、Z 相邻。
X的核电荷数是Y 核外电子数的一半,Y 与M 可形成化合物M 2Y O 下列说法止确的是A. C 「的结构示意图 C. 碳一12原子B.氯化氢分子的电子式:H 駅诃D. HCIO 的结构式H —O —CIA.还原性:X的氢化物>Y的氢化物>Z的氢化物B.简单离子的半径:Y的离子>Z的离子>“的离子〉X的离子C.YX2> M2Y都含有极性键D.Z元素的最高价氧化物的水化物的化学式为H2ZO46、意大利罗马大学的Fulvio Cacace等人获得了极具理论研究意义的N4分子。
内蒙古包头市第九中学高一6月月考物理试题 含答案
一、单项选择题(共10小题,每小题3分,共30分) 1、下列关于做功的说法正确的是A 、力对物体做功越多,说明物体的位移一定越大B 、滑动摩擦力可能做正功也可能做负功,静摩擦力一定不做功C 、若作用力做正功,则反作用力一定做负功D 、一个质点受到一对平衡力做功的代数和一定为零2、一物体置于光滑水平面上,受互相垂直的水平力12F F 、作用,经过一段位移1F 做功为3J ,克服2F 做功为4J ,则12F F 、的合力做功为 A 、7J B 、-1J C 、1J D 、5J3、如图,质量相同两物块分别在力作用下,沿同一水平面做匀速直线运动,两力与水平面的夹角相同,两物块经过的位移相同,设此过程中,1F 对M 做的功为1W ,2F 对m 做的功为2W ,则A 、无论水平面光滑与否,都有12W W =B 、若水平面光滑,则12W W >C 、若水平面粗糙,则12W W <D 、若水平面粗糙,则12W W =4、一质量为m 的物体以某一速度从固定斜面底端冲上倾角α=30°的斜面,其加速度为34g ,如图所示,着物体在斜面上上升的最大高度为h ,则此过程中正确的是A 、动能减小了34mgh B 、重力势能减少了mgh C 、机械能损失了12mghD 、物体克服摩擦力做功14mgh 5、如图所示,在外力作用下某质点运动的v-t 图像为正弦曲线,从图中可知判断A 、在10~t 时间内,外力做负功B 、在10~t 时间内,外力的功率逐渐增大C 、在2t 时刻,外力的功率最大D 、在13~t t 时间内,外力做的总功为零6、在平直的公路上,汽车由静止开始做匀加速运动,当速度达到m V ,立即关闭发动机而滑行直到停止,v-t 图线如图所示,汽车的牵引力大小为1F ,摩擦力大小为2F ,全过程中,牵引力做功为1W ,克服摩擦力做功为2W ,则A 、1:1:3F F =B 、1:3:1F F =C 、12:1:1W W =D 、12:1:3W W =7、如图所示,电梯与水平地面成θ角,一人站在电梯上,电梯从静止开始匀加速上升,到达一定速度后再匀速上升,若以N F 表示水平梯板对人的支持力,G 为人受到的重力,f F 为电梯对人的静摩擦力,则下列结论正确的是A 、加速过程中0f F ≠,N F 、f F 、G 都做功B 、加速过程中0f F ≠,N F 不做功C 、加速过程中0f F =,N F 、G 都做功D 、匀速过程中0f F =,N F 、G 都不做功8、如图所示,在高1.5m 的光滑平台上有一个质量为2kg 的小球被一细线栓在墙上,球与墙之间有一根被压缩的轻质弹簧,当烧断细线时,小球被弹出,小球落地的速度方向与水平方向成30°角,则弹簧被压缩时具有的弹性势能为(210/g m s =)A 、10JB 、15JC 、90JD 、100J9、如图所示,一很长,不可伸长的柔软轻绳跨过光滑定滑轮,绳两端各系一小球a 和b ,a 球质量为m ,静置于地面;b 球质量为2m ,用手托住,高度为h ,此时轻绳刚好拉紧,从静止开始释放b 后,a 可能达到的最大高度为A 、23h B 、h C 、43h D 、53h 10、如图所示,细线的一端固定于O 点,另一端系一小球,在水平拉力作用下,小球以恒定速率在竖直平面内由A 点运动到B 点,在此过程中拉力的瞬时功率变化情况是A 、逐渐增大B 、逐渐减小C 、先增大,后减小D 、先减小后增大 二、多项选择题(共5小题,每小题4分,共20分)11、轻质弹簧竖直放在地面上,物块P 的质量为m ,与弹簧连在一起保持静止,现用竖直向上的恒力F 使P 向上加速运动一小段距离L 时速度为v ,则A 、重力做功是-mgLB 、合外力做的功是212mv mgL - C 、合外力做的功是FL mgL - D 、弹簧弹力做的功是212mgL FL mv -+12、一物体从高h 处自由下落,落至某一位置时其动能与重力势能恰好相等(取地面为零势能面)A 、此时物体所处的高度为14h B 、此时物体的速度为gh C 、这段下落的时间为h gD 、此时机械能可能小于mgh13、如图所示,水平路面上有一辆质量为M 的汽车,车厢中有一个质量为m 的人正用恒力F 向前推车厢,在车以加速度a 向前加速行驶距离L 的过程中,下列说法正确的是A 、人对车的推力F 不做功B 、人对车做的功为maLC 、车对人的做用力大小为22m a g + D 、车对人的摩擦力做的功为(F+ma )L14、质量为m 的物体静止在光滑水平面上,从t=0时刻开始受到水平力的作用,力的大小F 与时间t 的关系如图所示,力的方向保持不变,则A 、03t 时刻的瞬时功率为20015F t mB 、03t 时刻的瞬时功率为20010F t mC 、在t=0到03t 这段时间内,水平力的平均功率为200234F t mD 、在t=0到03t 这段时间内,水平力的平均功率为200254F t m15、如图所示,劲度系数为k 的轻质弹簧,一端系在竖直放置、半径为R 的光滑圆环顶点P ,另一端连接一套在圆环上且质量为m 的小球,开始时小球位于A 点,此时弹簧处于原长且与竖直方向的夹角为45°,之后小球由静止沿圆环下滑,小球运动到最低点B 时速率为v ,此时小球与圆环之间压力恰好为零,下列分子正确的是A 、小球过B 点时,弹簧的弹力大小为2v mg m RB 、从A 到B 的过程中,小球的机械能守恒C 、从A 到B 的过程中,小球的重力势能转化为小球的动能和弹簧的弹性势能D 、从A 到B 的过程中,重力对小球做的功大于小球克服弹簧弹力做的功 三、实验题16、在利用重锤下落验证机械能守恒定律的实验中:(1)实验中动能的增加量略小于重力势能的减少量,其主要原因是_____ A 、重物下落的实际距离大于测量值 B 、重物下落的实际距离小于测量值 C 、重物下落受到阻力D 、重物的实际末速度大于计算值(2)甲、乙、丙三位同学分别得到A 、B 、C 三条纸带,他们的前两个点间的距离分别是1.0mm 、1.9mm 、4.0mm ,那么应该选用___同学的纸带最为理想,一定存在操作误差的同学是_________,可能的错误原因是_______.(3)如图所示,有一条纸带,各点距A 点的距离分别为1d ,2d ,3d ,……,各相邻点间的时间间隔为T ,当地重力加速度为g ,要用它来验证物体从B 到G 处的机械能是否守恒,则B 点的速度表达式为B v =_____,(4)若B 点和G 点的速度B v 、G v 以及BG 间的距离h 均为已知量,则当满足_____时,物体的机械能守恒。
内蒙古包头市第九中学2015-2016学年高一下学期第一次月考语文试题 含答案
一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1—3题道在瓦甓①朱以撒自立风标的古代书法家,历千年审美迭变而不被磨洗,着实很让人敬畏。
如果不是倚仗书法资料的越发丰富,往往会觉得史上大书家都是凌空蹈虚、破坚发奇之人。
事实上,书风再新颖奇谲也都吸收了前人的书法精华,并以此作为根柢。
正是这些根柢使一个学习者有了基础,最后总而成之,使之更为典型.在北朝书法资料没有广泛传播时,我们对于这个时段的创作风貌几乎茫然,不知其对后世的影响.直到后来,这些民间之作才忽地涌到眼前,令人应接不暇.让人很清楚地看到大唐楷书完全可以从北朝那里寻到根源。
尤其是到了北齐、北周,许多书法作品已经开启了唐人楷书的先河,如用笔、间架、章法等.只不过民间之作缺乏创作链、传播机遇,终是底层之物。
到了唐官僚文人手里就大不一样了,譬如颜真卿,就是很明显地受到北齐、北周书风的熏染,只是在效法过程中,用笔更为细致准确,结构更为堂正庄重,模式更为稳定,于是更典型、更突出.他不断地创作,有所递进,使模式更为牢固、强大.天下人尽知颜真卿,却不详其出处何在,以为书法大家可以无中生有,是天纵之才.树必有根,水必有源,这是很常识的理。
再有天赋、才情的书法家,也不能向壁虚造。
学文学艺,就是掌握其法。
法是传承的,文人雅士需要,民间书手也需要,否则,就难以言说书写。
民间有民间的法,民间与上层建筑离得很远,法也就有一定的界限。
尽管无名姓,书写也无从看出秩序,形成不了一个人完整的创作程序,但法在每件作品里,可以为后世效仿。
初唐欧、虞、褚、薛四家之作,在北朝墓志、造像记中可以找到和他们极其相似的用笔和结体。
譬如《元景略妻兰将墓志》就颇似褚遂良的书迹,《高归彦造像记》又似虞世南的笔调,欧阳询、薛稷的坚硬、瘦劲、决断之神态,更是能轻易地在北朝书法中察觉。
可是,究竟他们在多大程度上效仿过民间书法呢?他们自己都没有提及,后人凡提及,也都归于取法王羲之,如宋《宣和书谱》称:“询喜字,学王羲之书,后险劲瘦硬,自成一家。
包头市第九中学2019~2020年高一第一学期10月月考 word含部分答案
包九中2019~2020学年高一第一学期10月月考第一部分阅读理解(共两节,40分)第一节(15*2,共30分)AMore perhaps than any other European nation, the Swiss have got used to looking after foreign travelers. As early as the 18th century, wealthy French, Germans and Italians were treating the country as an amusement center while, in the 19th century, it became the major holiday playground for the British nobles. Today, it attracts visitors from all over the world.The Swiss are clear about the importance of tourism to their economy, which makes up about eight percent of the Gross Domestic Product, and helps industry greatly. Managers of hotels from all over the world go to Switzerland to learn how to do the job, and a high standard can be expected from the great majority of the country's hotels, most of which are small and pride themselves on personalized service. Public transport is the best in Europe. Both the Swiss Federal railways and the private railways are fully electric-powered, and the total network consists of about 5,000 kilometers of track.Under the Fly Baggage system passengers can check luggage in at 116 railway stations and have it automatically transferred to their flight. The national highway system is equally well planned, and the mountain roads offer views of some of the country's most breathtaking scenery. Also serving the mountains is an effective system of railways and cable ways, while more than 160 passenger cars cross the lakes and rivers. Hiking in the mountains is equally popular with Swiss nationals and foreign visitors. For those who want to view the country from a great height without having to climb the mountain themselves, it is always possible to take in the view from a balloon.1. Compared with other European countries, Switzerland _____.A. places more importance on entertainmentB. thinks more about foreign travelersC. has more convenient public transportD. has more five-star hotels2. According to the passage, Switzerland is now visited by _____.A. wealthy French peopleB. rich Germans and ItaliansC. British noblesD. people from various countries3. According to the passage we learn that _____.A. most of the hotels in Switzerland are bigB. all the hotels in Switzerland offer exactly the same serviceC. most of the hotels in Switzerland offer first class serviceD. the hotels in Switzerland are accustomed to learning from the rest of the world4. The passage mainly tells us about _____.A. scenery in SwitzerlandB. the life in SwitzerlandC. tourism in SwitzerlandD. the transportation in SwitzerlandBDo you want to get home from work knowing you have made a real difference in someone’s life ? If yes, don’t care about sex or age !Come and join us, then you’ll make it !Position: Volunteer Social Care Assistant(No Pay with Free Meals)Place: ManchesterHours: Part TimeWe are now looking for volunteers to support people with learning disabilities to live active lives!Only 4 days left. Don"t miss the chance of lending your warm hands to help others!Role:You will provide people with learning disabilities with all aspects of their daily lives. You will help them to develop new skills. You will help them to protect their rights and their safety. But your primary concern is to let them know they are valued.Skills and Experience Required:You will have the right values and great listening skills. You will be honest and patient. You will have the ability to drive a car and to communicate in fluent written and spoken English since you"ll have to help those people with different learning disabilities. Previous care-related experience will be a great advantage for you.1. The text is meant to ______ .A.leave a note B.send an invitation C.present a document D.carry advertisement2. What does the underlined part mean?A.You"ll make others" lives more meaningful with this job.B.You"ll arrive home just in time from this job.C.You"ll earn a good salary from this job.D.You"ll succeed in getting this job.3. Which of the following can first be chosen as a volunteer?A. The one who can drive a carB. The one who has done similar work before.C.The one who has patience to listen to others. D. The one who can use English to communicate.C How I Turned to be optimistic (乐观的)I beg an to grow up that winter night when my parents and I were returning from my aunt’s house, and my mother said that we might soon be leaving for America. We were on the bus then. I was crying, and some people on the bus were turning around to look at me. I remember that I could not bear the thought of never hearing again the radio program for school children to which I listened every morning.I do not remember myself crying for this reason again. In fact, I think I cried very little when Iwas saying goodbye to my friends and relatives. When we were leaving I thought about all the places I was going to see-the strange and magical places I had known only from books and pictures. The country I was leaving never to come back was hardly in my head then.The four years that followed taught me the importance of optimism (乐观主义), but the idea didnot come to me at once. For the first two years in New York I was really lost-having to study inthree schools as a result of family moves. I did not quite know what I was or what I should be. Mother remarried, and things became even more complex for me. Some time passed before my stepfather and I got used to each other. I was often sad, and saw no end to "the hard times."My responsibilities in the family increased a lot since I knew English better than everyone else athome. I wrote letters, filled out forms, translated at interviews with immigration officers, took my grandparents to the doctor and translated there, and even discussed telephone bills with company representatives.From my experiences I have learned one important rule: Almost all common troubles eventually go away! Something good is certain to happen in the end when you do not give up, and just wait a little! I believe that my life will turn out all right, even though it will not be that easy.1. How did the author get to know America?A. From her relativesB. From her motherC. From books and pictureD. From radio programs2. Upon leaving for America the author felt______.A. confusedB. excitedC. worriedD. sad3.For the first two years in New York, the author .A. often lost her wayB. did not think about her futureC. studied in three different schoolsD. got on well with her stepfather4. The author believes that ______.A. her future will be free from troublesB. it is difficult to learn to become patientC. there are more good things than bad thingsD. good things will happen if one keeps tryingDIf you want to learn anything at school, you need to listen to your teachers. Unfortunately, millions声)-filled classrooms that make hearing difficult.Children with hearing impairments(损伤)suffer most from noisy classrooms. They sometimescan’t hear questions that other students ask in class. Compared with kids with healthy hearin g, they have a harder time picking up new vocabulary words by hearing them in talking.Even kids with normal hearing have a harder time in the classroom when there’s too much noise.Younger children in particular have trouble separating important sounds –like a teacher’s voice –from background noise. Kids with learning disabilities and speech impediments(障碍)and kidsfor whom English is a second language also have a harder time learning in noisy situations.In recent years, scientists who study sound have been asking schools to reduce background noise, which may include loud air-conditioners and pipes. They’re also targeting outdoor noises, such as highway traffic. Noise reduction is a big deal. Why? Because quieter classrooms might make you smarter by letting you hear your lessons better.“It’s so obvious that we should have quiet rooms that allow for access to the lesson,” says Dan Ostergren, a hearing scientist. “Sometimes it surprises me that we spend so much time discussing this topic. I just want to go. Why is this hard for anyone to grasp?”1. Then underlined part “goofing off ” in the first paragraph can be replaced by “”.A. lazyB. intelligentC. sleepyD. foolish2. Who is most affected by noisy classrooms?A. Children with learning disabilities.B. Children with hearing impairments.C. Children with speech impediments.D. Children with normal hearing.3. Why should noise be reduced in classrooms ?A. Quiet classrooms are suitable for kids to have discussions.B. Quiet classrooms help kids recover from hearing impairments.C. Kids can’t separate sounds of air-conditioners and pipes.D. Kids can become smarter after hearing lessons better.4. What would be the best title for the passage?A. Noisy classroomsB. Classroom designC. The sense of hearingD. Disabled kids第二节七选五Every day can be a fresh, new beginning—this is very important if you had a difficult day before. By starting with some preparations, you can face the problems of the day in a good mood(心情). 1Exercise. Exercising is one of the best methods to start your day for your mind as well as the body. __2__ In addition, it also reduces stress and improves your metabolism (新陈代谢). So go for a walk, go for a bike ride, or go to the gym in the morning.Organize yourself. __3__ Make a to-do list and make an effort to follow it. It will keep you organized and make your day easier. However, make sure that your to-do list is manageable. There are only so many things you can do in a day.Smile. Starting your day by acting the way you want to feel can help you be more positive. __4__ The easiest thing to do is smile. Just smile because you are alive and you can. Watch or listen to something humorous so you can laugh. It makes you feel positive and really good about yourself and the world that surrounds you.Keep important items in the same place. To make mornings less busy, start a habit—keeping your important items in one easily accessible place. __5__ This way, you are never looking for that lost item when you a re running behind.A.Write down the tasks for the day.B.Try other actions to get yours elf to feel happier.C.Try some of the following tips to start your day right.D.Put your keys, wallet, purse, and other important items there.E.Instead of rushing through the morning, go slow and take your time.F.It increases brain function, which can help you get a jump-start on the day.G.If you feel annoyed or tired, do something physical to make yourself feel happy.第三部分英语知识运用第一节完形填空I was late for the school bus and rushing to get ready, My dog, Tippy, got to the front door and lay down in front of it—his way of asking to be petted. I 1 his begging for affection (喜爱), hurdled(跨) over him and ran for the waiting bus.___2___, that afternoon, when I came home, Mom said to me___3___, “Honey, I have some___4__news that I need to tell you. This morning, while you were at school, Tippy was hit by a car and___5__. I’m so sorry.”“No! It’s not true!” I was___6__. I couldn’t believe her. “Tippy, come here! Come on, boy!” I called and c alled for him. I waited. He didn’t come. Feeling___7___, I wandered into the living room. I didn’t cry that night. I still couldn’t believe that he was___8_.petted him when I left. 11 could I have known that was my last chance? I cried until I felt empty inside.Time passed, and against my will, I started to__12__some things. I realized what little control any of us have over what happens ___13__ a dog. We can do everything right, but___14___things can still happen. But good things can happen too. That’ 15 . The best way to deal with the hard times is to___16___what you need to do to get through them when they come, and to remember that hard times always___17___.I now deeply understand the “circle of life”. Everyone is born, everyone__18__, and that’s the way it is. If dogs never died, there would be no___19__for others like Belle – my new dog.Best of all, I realized that Tippy___20__all of my good memories of him. And they come to me every time I call!1. A.met B.ignored C.promised D.preferred2. A.However B.Besides C.so D.Finally3. A.excitedly B.quickly C.nervously D.seriously4. A.good B.sad C.dull D.happy5. A.escaped B.wounded C.killed D.knocked6. A.in disagreement B.in anger C.in silence D.in surprise7. A.upset B.sleepy C.spellbound D.uncertain8. A.gone B.disappeared C.hidden D.stolen9. A.noise B.quarrel C.silence D.sound10. A.waiting B.crying C.thinking D.expecting11. A.Why B.What C.Which D.How12. A.forget B.recall C.understand D.change13. A.to B.about C.out D.into14. A.surprising B.bad C.amazing D.amusing15. A.nature B.human C.life D.rule16. A.figure out B.picked out C.try out D.put out17. A.disappear B.overcome C.help D.pass18. A.grows B.lives C.suffers D.dies19. A.chance B.room C.possibility D.doubt20. A.thought of B.brought up C.left behind D.picked up第二节单句语法填空1. When________(cook) the meal, she was burnt by the hot oil.2. With the development of science and technology, I think ____ very important to learn English well.3. I wonder ____ he could go to the party the next day.4. The man looked at he plane as it _____(gradual) disappeared into the clouds.5. It was because of the bad weather _____ the sports meeting was put off.6. You can’t imagine what trouble I had _____ (settle) the problem.7. Go _____(straight) down the road until you come to the English language school.8. It was the first time that the man _______(be) late for work.9. American English is loosely based ____ British English.10. _______(actual), he is an honest and reliable person, whom you can depend on.11. Visitors are requested _______(smoke) here.12. I am glad to hear that he is recovering _____the serious illness.13. The ____(express) on her face suggested that she was more than angry.14. These ____(curtain) are very dirty and they need to be washed.15. You failed the job interview again and you _____(make) full preparations.第三节单词拼写1. They d_____ with each other, so they didn’t reach an a greement.2. Susan looks very _____(沮丧的), so I should do something to make her happy.3. The old man went through many difficulties and s______ a lot from then.4. More and more people are c______ about the traffic safety now.5. He was __________(辨认出) by his fans though he wore a pair of sunglasses.6. It is so warm that many students are taking exercise _______ (在户外) now.7. Of the two songs we heard, I like the l_______ one better.8. Liu Yan’s English is so good that you will think she is a n_____ speaker.9. The man’s heavy _______(口音) shows that he comes from the South.10. The _______ (身份)of the murdered woman has not yet been established.短文改错One day, I went to the railway station to buy a ticket to my aunt. When I got there, I told that the ticket had all been sold out . Just then a man came up and said with a strongly Zhejiang accent that he had a spare ticket. I didn’t know that whether I could believe him or not . After hesitate for while , I decided to take it. So as soon as the man left, I began to regret. If he was not honest , what shall I do ? On a third day, I went to the station to see my aunt away. As I was waving goodbye to her, I saw the man sitting next to my aunt , smiling at me.书面表达:假设你是李华,你的好朋友Susan 前不久随父母去了美国,她写信告诉你她很不适应美国的校园生活,感到很孤独。
2015-2016学年内蒙古包头九中高一12月月考语文(解析版)
2015-2016学年内蒙古包头九中高一12月月考语文1.下列各句横线处的成语,正确的一项是()A.他不愿说出实情,闪烁其词地遮掩过去了。
B.这一特大洪灾发生后,全市各机关和广大人民群众,积极捐款捐物,奉献爱心,我们也要响应号召,鼎力相助。
C.董事长的一席话起到了抛砖引玉的作用,引出了员工们许多提升产品品牌影响力的好建议。
D.目前学术界存在大量不端行为,抄袭、剽窃、造假已经蔚然成风,这与无原则宽容的学术环境是分不开的。
2.下列各句中,没有语病的一句是()A.城关中学的学生在老师的带领下,为山区百姓义务投递邮件,几年来没有丢失一封信,推动了村民之间的联系,弥补了当地交通发展的局限。
B.馨园社区居委会在展示的普法板报中,用通俗易懂的语言剖析了生动典型的案例现实,让读者在轻松的阅读中领略到法律精神的独特魅力。
C.粮食不同于其他产品,其生产环节明显的季节性决定了它不能像工业产品流通一样可以零库存周转,因而储备粮食以备不时之需十分重要。
D.为了露出琉璃瓦深蓝色的瓦体,去年盖的办公楼没有在屋檐外设墙体遮挡,这是成为楼顶覆冰融化时容易整体滑落砸到过路人的原因之一。
3.将下列语句依次填入文中的括号处,使上下文语意连贯。
只填序号。
()明式家具,崇尚简约、天然之美,,,,牢固结实;不过多地进行装饰,不过多地渲染技艺,不过多地雕琢,,,。
①结构全不用钉②以木材天然纹理和色泽为美③加工工艺精密④简洁而典雅⑤用榫铆接合得天衣天缝⑥符合中国“道法自然”的传统审美情趣A.③①⑤②④⑥ B.⑥④②③①⑤C.③⑤①④②⑥ D.⑥②④③①⑤阅读下面文字完成文后各题。
书院教育,是宋元明时期最具特色的教育组织形式。
“书院”一词,最早出现于唐代。
不过,那时的书院主要还只是编书、藏书以及读书的场所。
作为具有一定规模的教育场所的书院,是到宋代才出现的。
当时,刚刚经历五代十国战乱,文化教育亟待振兴,一些思想家也需要自己的宣传阵地,以私人讲学为核心的书院教育,就顺应这种时代需要而出现了。
2020-2021学年内蒙古包头九中高一10月月考物理卷(解析版).doc
2020-2021学年内蒙古包头九中高一10月月考物理卷(解析版)姓名:_____________ 年级:____________ 学号:______________题型选择题填空题解答题判断题计算题附加题总分得分1. (知识点:时间与时刻)一列长50m的队伍,以1.5m/s速度经过一座全长为100m的桥,当队伍的第一个人踏上桥到队尾最后一人离开桥时,总共需要的时间是多少?【答案】T=100s【解析】试题分析:从队伍的第一个人踏上桥到队伍最后一个人离开桥,队伍一共行走的路程为根据速度公式:,当队伍全部穿过大桥所需要的时间为。
答:总共需要的时间是。
考点:匀速直线运动【名师点睛】本题考查时间的计算,关键是速度公式及其变形的灵活运用,难点在于路程的确定。
当队伍全部通过大桥时,队伍经过的距离为队伍的长度与大桥长度之和,行进速度已知,根据速度公式的导出公式求所需的时间。
汽车在平直公路上以10m/s的速度做匀速直线运动,发现前面有情况而刹车,若获得的加速度大小为2m/s2,则经过6s汽车的速度有多大?【答案】【解析】试题分析:汽车从刹车到静止所用的时间为:所以汽车在末速度为0;即经过汽车的速度为零。
评卷人得分考点:匀变速直线运动的速度与时间的关系。
【名师点睛】掌握匀变速直线运动的速度时间关系是正确解题的关键,本题注意汽车刹车后的加速度取值以及停车时间的注意。
在“用打点计时器测速度”的实验中,小车拖着纸带运动,打出的纸带如图所示。
选出A、B、C、D、E共5个计数点,每相邻两点间还有四个计时点(图中未画出),以A点为起点量出的到各点的位移已标在图上。
由此可求得打下B点时小车运动的速度约为vB=_______m/s;打下D点时小车运动的速度约为vD=_______m/s.(结果保留二位有效数字)【答案】0.170.21【解析】试题分析:由于每相邻两个计数点间还有4个点没有画出,所以相邻的计数点间的时间间隔,根据匀变速直线运动中时间中点的速度等于该过程中的平均速度,,。
2020-2021学年10高一月考英语试卷+答案
包九中2020 ~ 2021学年高一年级10月月考英语试题第一部分听力 (共两节,满分20分)第一节(共5小题,每小题1分;满分5分)听下面5段对话,每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置;听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What does Jim do?A. A teacher.B. An officer.C. A student.2. What time did Suzy leave home?A. 4:30.B. 5:00.C. 5:15.3. What is the man's suggestion?A. Going to the concert.B. Going to see a show.C. Just walking around.4. How long has the rain lasted?A. 5 days.B. 6 days.C. 7 days.5. What opinion do they hold on their chemistry course?A. It's well organized.B. It is satisfactory.C.It is unsatisfactory. 第二节(共15小题;每小题1分,满分15分) 听下面5段对话或独白。
每段对话或独白后有几个小题,从每题所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听第6段材料,回答第6、7题。
6. Where does this conversation take place? A. In a library. B. In a school. C. In a bookstore. 7. Why is William Shakespeare mentioned (提及) in the conversation? A. He gave gifts to millions of people. B. He was a very wealthy man in his times. C. His signature (签名) is worth a lot of money. 听第7段材料,回答第8至11题。
内蒙古包头市第九中学高一6月月考英语试题含答案.doc
包头九中2016-2017学年度第二学期高一年级英语月考试卷第I卷(选择题共90分)第一部分听力(共两节,满分20分)第一节(共5小题;每小题1分,满分5分)听下而5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都冇10秒钟的时间來回答冇关小题和阅读下一小题。
每段对话仅读一遍。
1・ What did the man read?A.English short stories B・ English novels C・ English advertisements2. What will the weather be like in Beijing tomorrow?A.Sunny B・ Rainy C. Snowy3・ What is the man,s advice probably?A.To buy a new house B・ To earn enough money first C・ To buyan old house4. How long does BBC news 1ast?A・ One and a half hours B. Half an hour C. One hour 5・ Why odes the man come to the woman?A・ To hand in his application B・ To get an answer from her C・ Toget his application back第二节(共15小题;每小题1分,满分15分)听下血5段对话或独白。
每段対话或独白后有儿个小题,从题中所给A、B、C三个选项中选出最佳选项,并标在试卷的相应位直。
听每段对话或独口前,你都有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒蚀的作答吋间。
每段对■话或独口读两遍。
听下而一段材料,回答第6至第7两个小题。
内蒙古包头九中高一物理上学期12月月考试卷(含解析)
内蒙古包头九中2015-2016学年高一(上)月考物理试卷(12月份)一、选择题(本题共14小题,共56分.1-10题为单选,11-14题为多选.全部选对的得4分,选对但不全的得2分,有选错的得0分)1.关于伽利略对自由落体运动的研究,下列叙述错误的是()A.伽利略采用了斜面实验,“冲淡”了重力的作用,便于运动时间的测量B.伽利略把实验和逻辑推理和谐地结合起来,从而发展了人类的科学思维方式和科学研究方法C.伽利略认为,如果没有空气阻力,重物与轻物应该下落同样快D.伽利略用实验直接证实了自由落体运动是初速度为零的匀加速直线运动2.下列说法中正确的是()A.出租车是按位移的大小来计费的B.3秒时指的是第3秒末时C.任意相等时间内通过的位移都相同的运动一定是匀速直线运动D.初速度为零的匀加速直线运动,第一个s、第二个s、第三个s…所用的时间之比为tⅠ、tⅡ、t Ⅲ:…:t N=1:(﹣1):(﹣)…:(﹣)3.在2008北京奥运会中,牙买加选手博尔特(如图)是一公认的世界飞人,在男子100m决赛和男子200m决赛中分别以9.69s和19.30s的成绩破两项世界纪录,获得两枚金牌.关于他在这两次决赛中的运动情况,下列说法正确的是()A.200m决赛中的位移是100m决赛的两倍B.100m决赛中的平均速度约为10.32m/sC.200m决赛中的平均速度约为10.36m/sD.100m决赛中的最大速度约为20.64m/s4.做匀加速直线运动的质点在0﹣3s内的平均速度比它在6﹣9s内的平均速度小9m/s,则质点的加速度大小为()A.a=1m/s2B.a=1.5m/s2C.a=2m/s2D.a=2.5m/s25.物体甲的x﹣t图象和物体乙的v﹣t图象分别如图所示,则这两物体的运动情况是()A.甲在整个t=6s时间内运动方向一直不变,它通过的总位移大小为6mB.甲在整个t=6s时间内有来回运动,它通过的总位移为零C.乙在整个t=6s时间内有来回运动,它通过的总位移为零D.乙在整个t=6s时间内运动方向一直不变,它通过的总位移大小为4m6.如图所示,质量为10kg的物体静止在水平桌面上,物体与桌面间的动摩擦因数为0.2,现对其施加水平向左的拉力F,(已知重力加速度g=10m/s2,最大静摩擦力等于滑动摩擦力)以下说法正确的是()A.物体对桌面的压力就是木块所受的重力,施力物体是地球B.物体对桌面的压力是弹力,是由于桌面发生形变而产生的C.若拉力F=12N,物体受到的摩擦力大小为20N,方向向右D.若拉力F=22N,物体受到的摩擦力大小为20N,方向向右7.如图所示,用一根细绳和一根轻直杆组成三角支架,绳的一端绕在手指上,杆的一端顶在掌心,当A处挂上重物时,绳与杆对手指和手掌均有作用,对这两个作用力的方向判断完全正确的是的()A.B. C.D.8.如图,用两根等长轻绳将木板悬挂在竖直木桩上等高的两点,制成一简易秋千,某次维修时将两轻绳各剪去一小段,但仍能保持等长且悬挂点不变,木板静止时,F1表示木板所受合力的大小,F2表示单根轻绳对木板拉力的大小,则维修后()A.F1不变,F2变大B.F1变大,F2变小C.F1变大,F2变大D.F1变小,F2变小9.两个力的合力F为50N,其中一个力F1为30N,那么另一个力F2的大小可能是()A.10N B.15N C.80N D.85N10.已知两个共点力的合力为50N,分力F1的方向与合力F的方向成30°角,分力F2的大小为30N.则()A.F1的大小是唯一的 B.F2的方向是唯一的C.F2有两个可能的方向D.F2可取任意方向11.水平皮带传输装置如图所示.O1为主动轮,O2为从动轮.当主动轮顺时针匀速转动时,物体被轻轻地放在A端皮带上,开始时物体在皮带上滑动,当它到达位置C后滑动停止,之后就随皮带一起匀速运动,直至传送到目的地B端.在传送过程中,若皮带与轮不打滑,则物体受到的摩擦力和图中皮带上P、Q两处(在O1、O2连线上)所受摩擦力情况是()A.在AC段物体受水平向左的滑动摩擦力,P处受向上的滑动摩擦力B.在AC段物体受水平向右的滑动摩擦力,P处受向下的静摩擦力C.在CB段物体不受静摩擦力,Q处受向下的静摩擦力D.在CB段物体受水平向右的静摩擦力,P、Q两处始终受向下的静摩擦力12.两个力F1和F2间的夹角为θ,两个力的合力为F.以下说法正确的是()A.若F1和F2大小不变,θ角越小,合力F就越大B.合力F总比分力中的任何一个力都大C.如果夹角不变,F1大小不变,只要F2增大,合力F就必然增大D.合力F可能比分力中的任何一个力都小13.如图,一个重为10N的大砝码,用细线悬挂在O点,现在用力F拉砝码,使悬线偏离竖直方向θ=60°时处于静止状态,此时所用拉力F的值可能为()A.5.0N B.5N C.10N D.10.0N14.一辆汽车沿着一条平直的公路行驶,公路旁边与公路平行有一行电线杆,相邻电线杆间的间隔均为50m,取汽车驶过某一根电线杆的时刻为零时刻,此电线杆作为第1根电线杆,此时刻汽车行驶的速度为5m/s,若汽车的运动为匀变速直线运动,在10s末汽车恰好经过第3根电线杆,则下列说法中正确的是()A.汽车的加速度为1m/s2B.汽车继续行驶,经过第7根电线杆时瞬时速度大小为25m/sC.汽车在第3根至第7根间运动所需要的时间为20sD.汽车在第3根至第7根间的平均速度为20m/s二、实验题(共12分,每空2分)15.在“探究弹力和弹簧伸长的关系”时,某同学把两根弹簧如图1连接起来进行探究:(1)某次测量如图2所示,指针示数为cm;(2)在弹性限度内,将50g的钩码逐个挂在弹簧下端,得到指针A、B的示数L A和L B如表所示.用下表数据计算弹簧Ⅰ的劲度系数为N/m(重力加速度g取10m/s2,结果保留三位有效数字),由表Ⅰ数据(选填“能”或“不能”)计算出弹簧Ⅱ的劲度16.在做“验证力的平行四边形定则”的实验时,其中A为固定橡皮筋的图钉,O为橡皮筋与细绳的结点,OB和OC为细绳,图乙是在白纸上根据实验数据画出的图.(1)本实验主要采用的科学方法是A.理想实验法 B.等效替代法C.控制变量法 D.建立物理模型法(2)在本实验的操作中,下列说法中正确的是A.同一次实验中,O点位置不允许变动B.实验中,只需记录弹簧测力计的读数和O点的位置C.实验中,把橡皮条的另一端拉到O点时,两个弹簧测力计之间的夹角必须取90°D.实验中,要始终将其中一个弹簧测力计沿某一方向拉到最大量程,然后调节另一弹簧测(3)图乙做出的F与F′两力中,方向一定沿AO方向的是.三、计算题(32分)17.一辆汽车以72km/h的速度正在匀速行驶,现因故紧急刹车并最终停止运动,已知汽车刹车过程加速度大小为4m/s2,则:(1)从开始刹车到停止运动所需时间;(2)汽车刹车4s末的速度;(3)汽车从开始刹车经过6s通过的位移.18.滑板运动是一项非常刺激的水上运动,研究表明,在进行滑板运动时,水对滑板的作用力F x垂直于板面,大小为kv2,其中v为滑板速率(水可视为静止).某次运动中,在水平牵引力作用下,当滑板和水面的夹角θ=37°时,滑板做匀速直线运动,相应的k=54kg/m,人和滑板的总质量为108kg,试求(g取10m/s2,sin 37°=0.6,忽略空气阻力):(1)水平牵引力的大小;(2)滑板的速率;(3)水平牵引力的功率.19.如图所示,质量为m的物体在与水平面成θ角的斜向上推力F作用下,沿水平天花板向右匀速运动,则物体与天花板间的动摩擦因数应为多少?20.如图所示,物体A、B叠放在倾角a=37°的斜面上,并通过细线跨过光滑滑轮相连,细线与斜面平行.两物体的质量分别为m A=5kg,m B=10kg,A、B间动摩擦因数为μ1=0.1,B与斜面间的动摩擦因数为μ2=0.3,现对B施一平行于斜面向下的拉力F,使B平行于斜面向下匀速运动(g=10m/s2,sin37°=0.6,cos37°=0.8).求拉力F的大小.2015-2016学年内蒙古包头九中高一(上)月考物理试卷(12月份)参考答案与试题解析一、选择题(本题共14小题,共56分.1-10题为单选,11-14题为多选.全部选对的得4分,选对但不全的得2分,有选错的得0分)1.关于伽利略对自由落体运动的研究,下列叙述错误的是()A.伽利略采用了斜面实验,“冲淡”了重力的作用,便于运动时间的测量B.伽利略把实验和逻辑推理和谐地结合起来,从而发展了人类的科学思维方式和科学研究方法C.伽利略认为,如果没有空气阻力,重物与轻物应该下落同样快D.伽利略用实验直接证实了自由落体运动是初速度为零的匀加速直线运动【考点】伽利略研究自由落体运动的实验和推理方法.【专题】定性思想;推理法;直线运动规律专题.【分析】要了解伽利略“理想斜面实验”的内容、方法、原理以及物理意义,伽利略斜面实验的卓越之处不是实验本身,而是实验所使用的独特的方法在实验的基础上,进行理想化推理.(也称作理想化实验)它标志着物理学的真正开端.【解答】解:A、伽利略采用了斜面实验,“冲淡”了重力的作用,便于运动时间的测量,故A正确.B、伽利略把实验和逻辑推理和谐地结合起来,从而发展了人类的科学思维方式和科学研究方法,故B正确C、伽利略认为,如果没有空气阻力,重物与轻物应该下落得同样快,故C正确D、伽利略猜想自由落体运动是初速度为零的匀加速直线运动,并未直接进行验证,而是在斜面实验的基础上的理想化推理,故D错误.本题选错误的,故选:D【点评】伽利略的“理想斜面实验”是建立在可靠的事实基础之上的,它来源于实践,而又高于实践,它是实践和思维的结晶.2.下列说法中正确的是()A.出租车是按位移的大小来计费的B.3秒时指的是第3秒末时C.任意相等时间内通过的位移都相同的运动一定是匀速直线运动D.初速度为零的匀加速直线运动,第一个s、第二个s、第三个s…所用的时间之比为tⅠ、tⅡ、t Ⅲ:…:t N=1:(﹣1):(﹣)…:(﹣)【考点】匀变速直线运动规律的综合运用;时间与时刻;匀变速直线运动的位移与时间的关系.【专题】直线运动规律专题.【分析】出租车是按路程的大小来计费的.3秒时指的是第3秒末.初速度为零的匀加速直线运动,第一个s、第二个s、第三个s…所用的时间之比为tⅠ、tⅡ、tⅢ:…:t N=1:(﹣1):(﹣)…:(﹣).【解答】解:A、出租车是按路程的大小来计费的,故A错误;B、3秒时指的是第3秒末这一时刻,B正确;C、任意相等时间内通过的位移都相同的运动一定是匀速直线运动一定是匀速直线运动,C正确;D、初速度为零的匀加速直线运动,第一个s、第二个s、第三个s…所用的时间之比为tⅠ、tⅡ、tⅢ:…:t N=1:(﹣1):(﹣)…:(﹣),D正确.故选:BCD.【点评】本题考查了有关运动学部分的基础知识,注意D选项的推导,只要理解了推导的过程就不再认为是难点.3.在2008北京奥运会中,牙买加选手博尔特(如图)是一公认的世界飞人,在男子100m决赛和男子200m决赛中分别以9.69s和19.30s的成绩破两项世界纪录,获得两枚金牌.关于他在这两次决赛中的运动情况,下列说法正确的是()A.200m决赛中的位移是100m决赛的两倍B.100m决赛中的平均速度约为10.32m/sC.200m决赛中的平均速度约为10.36m/sD.100m决赛中的最大速度约为20.64m/s【考点】平均速度;位移与路程.【专题】常规题型.【分析】正确解答本题的关键是:理解应用平均速度的公式求物体的平均速度;理解位移和路程的区别;明确在体育比赛中100比赛是直道,200米是弯道.【解答】解:A、200米比赛为弯道,路程大小是200米(位移不是200m),100米比赛为直道,位移大小为100米,故A错误;B、100米比赛的位移大小为100米,因此其平均速度为: ==10.32m/s,故B正确;C、由于200米比赛为弯道,无法求出其位移大小,故平均速度无法求,故C错误;D、由于100比赛过程中运动员并不是一直匀加速运动,v=不成立,无法求出其最大速度,故D错误.故选:B.【点评】体育运动与物理中的运动学规律有很多的结合点,在平时训练中要加强应用物理知识解决实际问题的能力.4.做匀加速直线运动的质点在0﹣3s内的平均速度比它在6﹣9s内的平均速度小9m/s,则质点的加速度大小为()A.a=1m/s2B.a=1.5m/s2C.a=2m/s2D.a=2.5m/s2【考点】加速度.【专题】定量思想;推理法;直线运动规律专题.【分析】根据某段时间内的平均速度等于中间时刻的瞬时速度,结合速度时间公式求出质点的加速度.【解答】解:0﹣3s内的平均速度等于1.5s末的瞬时速度,6﹣9s内的平均速度等于7.5s末的速度,则质点的加速度a=.故选:B.【点评】解决本题的关键掌握匀变速直线运动的运动学公式和推论,并能灵活运用,有时运用推论求解会使问题更加简捷.5.物体甲的x﹣t图象和物体乙的v﹣t图象分别如图所示,则这两物体的运动情况是()A.甲在整个t=6s时间内运动方向一直不变,它通过的总位移大小为6mB.甲在整个t=6s时间内有来回运动,它通过的总位移为零C.乙在整个t=6s时间内有来回运动,它通过的总位移为零D.乙在整个t=6s时间内运动方向一直不变,它通过的总位移大小为4m【考点】匀变速直线运动的图像.【专题】运动学中的图像专题.【分析】位移﹣时间图象表示物体的位置随时间变化的规律,斜率等于速度,而速度﹣时间图象表示速度随时间变化的规律,图线与时间轴所的面积大小等于位移;由图象的性质可得出物体的运动性质、位移和路程的大小.【解答】解:A、B:位移﹣时间图象的斜率等于速度,可知甲在0时刻由负方向上距原点2m 处向正方向运动,6s时达到正向的2m处,故甲的运动方向不变,总位移为4m,故AB错误;C、D:乙开始时速度为沿负向的匀减速直线运动,位移为:;3s后做正向的匀加速直线运动,图象与时间轴围成的面积为物体通过的位移,位移为:;故总位移为:x=x1+x2=0,总路程为:S=|x1|+x2=6m,故C正确,D错误;故选:C.【点评】本题考查对速度图象和位移的识别和理解能力,抓住各自的数学意义理解其物理意义,即速度图象的“面积”大小等于位移,而位移图象的斜率等于速度,△x表示位移.6.如图所示,质量为10kg的物体静止在水平桌面上,物体与桌面间的动摩擦因数为0.2,现对其施加水平向左的拉力F,(已知重力加速度g=10m/s2,最大静摩擦力等于滑动摩擦力)以下说法正确的是()A.物体对桌面的压力就是木块所受的重力,施力物体是地球B.物体对桌面的压力是弹力,是由于桌面发生形变而产生的C.若拉力F=12N,物体受到的摩擦力大小为20N,方向向右D.若拉力F=22N,物体受到的摩擦力大小为20N,方向向右【考点】滑动摩擦力;物体的弹性和弹力.【专题】摩擦力专题.【分析】木块放在水平桌面上保持静止,木块对桌面的压力大小等于木块受的重力,压力的施力物体是木块,是由于木块发生形变而产生的.压力与支持力是一对作用力与反作用力.并根据静摩擦力与滑动摩擦力区别,来确定求解.【解答】解:A、木块放在水平桌面上保持静止,木块对桌面的压力大小等于木块受的重力,但不能说木块对桌面的压力就是木块受的重力,因为两者产生的原因、施力物体和受力物体等都不同.压力的施力物体是木块.故A错误.B、木块对桌面的压力是弹力,是由于木块发生形变对桌面产生的弹力.故B错误.C、若拉力F=12N,小于最大静摩擦力fmax=μN=0.2×100=20N,物体受到的静摩擦力大小为12N,方向向右;故C错误.D、若拉力F=22N,大于最大静摩擦力,物体受到的滑动摩擦力大小为20N,方向向右;故D 正确.故选:D.【点评】本题考查弹力的形成原因,要注意两物体相互挤压后,由于施力物体发生形变而产生的指向受力物体的力称为弹力,注意静摩擦力与滑动摩擦力大小的计算区别.7.如图所示,用一根细绳和一根轻直杆组成三角支架,绳的一端绕在手指上,杆的一端顶在掌心,当A处挂上重物时,绳与杆对手指和手掌均有作用,对这两个作用力的方向判断完全正确的是的()A.B. C.D.【考点】力的合成与分解的运用;共点力平衡的条件及其应用.【分析】对重物分析,重物受重力及绳子的拉力,因细绳是连续的,故绳子上各点的拉力均等于物体的重力,由此可判断手指的受力方向;对结点进行受力分析,则可知杆对结点的弹力方向,即可判出杆对手掌的作用力的方向.【解答】解:重物受绳子的拉力及物体本身的重力而处于平衡,故绳子的拉力等于物体的重力;而绷紧的绳子各处的拉力相等,故绳子对手指有大小为mg的拉力,方向沿绳的方向背离手指的方向;结点A处受绳子向下的拉力及沿绳向上的拉力,二力的合力应沿杆的方向向里压杆,故杆对手掌有向里的压力;故答案为D.【点评】本题应明确:绷紧的绳子不论是否弯曲,绳子上各点的拉力大小相等,方向指向绳子收缩的方向.8.如图,用两根等长轻绳将木板悬挂在竖直木桩上等高的两点,制成一简易秋千,某次维修时将两轻绳各剪去一小段,但仍能保持等长且悬挂点不变,木板静止时,F1表示木板所受合力的大小,F2表示单根轻绳对木板拉力的大小,则维修后()A.F1不变,F2变大B.F1变大,F2变小C.F1变大,F2变大D.F1变小,F2变小【考点】共点力平衡的条件及其应用;物体的弹性和弹力.【专题】共点力作用下物体平衡专题.【分析】木板静止时,受重力和两个拉力而平衡,根据共点力平衡条件并结合正交分解法列式分析即可.【解答】解:木板静止时,受重力和两个拉力而平衡,故三个力的合力为零,即:F1=0;根据共点力平衡条件,有:2F2cosθ=mg解得:F2=当细线变短时,细线与竖直方向的夹角θ增加,故cosθ减小,拉力F2变大.故选:A.【点评】本题是简单的三力平衡问题,关键是受力分析后运用图示法分析,不难.9.两个力的合力F为50N,其中一个力F1为30N,那么另一个力F2的大小可能是()A.10N B.15N C.80N D.85N【考点】力的合成.【专题】受力分析方法专题.【分析】根据两个分力的合力在两个分力之差与两个分力之和之间,分析另一个分力的大小可能值.【解答】解:有两个共点力的合力大小为50N,若其中一个分为大小为30N,另一个分力的大小应在20N≤F≤80N范围,所以可能为80N.故选C.【点评】本题求解分力的范围与确定两个力的合力范围方法相同.基本题.也可以采用代入法,将各个选项代入题干检验,选择符合题意的.10.已知两个共点力的合力为50N,分力F1的方向与合力F的方向成30°角,分力F2的大小为30N.则()A.F1的大小是唯一的 B.F2的方向是唯一的C.F2有两个可能的方向D.F2可取任意方向【考点】力的合成.【分析】已知合力的大小为50,一个分力F1的方向已知,与F成30°夹角,另一个分力的最小值为Fsin30°=25N,根据三角形定则可知分解的组数.【解答】解:已知一个分力有确定的方向,与F成30°夹角,知另一个分力的最小值为Fsin30°=25N而另一个分力大小大于25N小于30N,所以分解的组数有两组解.如图.故C正确,ABD错误故选C.【点评】解决本题的关键知道合力和分力遵循平行四边形定则,知道平行四边形定则与三角形定则的实质是相同的.11.水平皮带传输装置如图所示.O1为主动轮,O2为从动轮.当主动轮顺时针匀速转动时,物体被轻轻地放在A端皮带上,开始时物体在皮带上滑动,当它到达位置C后滑动停止,之后就随皮带一起匀速运动,直至传送到目的地B端.在传送过程中,若皮带与轮不打滑,则物体受到的摩擦力和图中皮带上P、Q两处(在O1、O2连线上)所受摩擦力情况是()A.在AC段物体受水平向左的滑动摩擦力,P处受向上的滑动摩擦力B.在AC段物体受水平向右的滑动摩擦力,P处受向下的静摩擦力C.在CB段物体不受静摩擦力,Q处受向下的静摩擦力D.在CB段物体受水平向右的静摩擦力,P、Q两处始终受向下的静摩擦力【考点】牛顿第二定律;匀变速直线运动的位移与时间的关系.【专题】传送带专题.【分析】在AC段,物体受滑动摩擦力带动,沿传送带做加速运动,故所受摩擦力方向向右,而CB段时物体与传送带速度相同,都是匀速运动,可知摩擦力的有无P所在的为主动轮,即轮子带着传送带运动,故传送带相对轮子由向后运动的趋势,可知此处摩擦向下;Q所在的为从动轮,即轮子是在传送带的带动下运动的,故可知摩擦力向上【解答】解:A:在AC段,物体受滑动摩擦力带动,沿传送带向右做加速运动,故所受摩擦力方向向右,又P所在的为主动轮,即轮子带着传送带运动,故传送带相对轮子由向后运动的趋势,可知此处摩擦向下,故A错误B:由A的分析知B正确C:CB段时物体与传送带速度相同,都是匀速运动,两者没有相对运动也没有相对运动趋势,故物体再这段不受摩擦力,Q所在的为从动轮,皮带上Q点相对于从动轮有向上运动的趋势,故皮带Q点上受到摩擦力方向向下,故C正确D:由C的分析知D错误故选BC【点评】摩擦力方向判定就是要判定物体间的相对运动,这点在CD另个选项中,涉及到的主动轮和从动轮是个难点,这个要分清主动轮是轮子带动皮带,从动轮是皮带带动轮子,这样就可以判定相对运动,进而确定摩擦力方向.12.两个力F1和F2间的夹角为θ,两个力的合力为F.以下说法正确的是()A.若F1和F2大小不变,θ角越小,合力F就越大B.合力F总比分力中的任何一个力都大C.如果夹角不变,F1大小不变,只要F2增大,合力F就必然增大D.合力F可能比分力中的任何一个力都小【考点】力的合成.【分析】由力的合成方法可知,二力合成时,夹角越大,合力越小,两力合力的范围|F1﹣F2|≤F 合≤F1+F2;一个合力与几个分力共同作用的效果相同,合力可以大于分力,可以小于分力,也可以等于分力.【解答】解:A、若F1和F2大小不变,θ角越小,合力F越大,故A正确;B、由力的合成方法可知,两力合力的范围|F1﹣F2|≤F合≤F1+F2,所以合力有可能大于任一分力,也可能小于任一分力,还可能与两个分力都相等,故B错误;C、如果夹角不变,F1大小不变,只要F2增大,合力F可以减小,也可以增加,故C错误;D、二力平衡时,合力为零,此时合力F比分力中的任何一个力都小,故D正确;故选AD.【点评】本题考查对合力与分力关系的理解能力.合力与分力是等效的,合力的范围在两个分力之差与之和之间.二力合成时,夹角越大,合力越小.13.如图,一个重为10N的大砝码,用细线悬挂在O点,现在用力F拉砝码,使悬线偏离竖直方向θ=60°时处于静止状态,此时所用拉力F的值可能为()A.5.0N B.5N C.10N D.10.0N【考点】共点力平衡的条件及其应用;物体的弹性和弹力.【专题】共点力作用下物体平衡专题.【分析】以物体为研究对象,采用图解法分析什么条件下拉力F最小.再根据平衡条件求解F 的最小值和最大值.【解答】解:以物体为研究对象,根据图解法可知,当拉力F与细线垂直时最小.根据平衡条件得F的最小值为:F min=Gsin60°=10×N=5N,当拉力水平向右时,拉力最大,F=Gtan60°=10N故A错误,BCD正确.故选:BCD.【点评】本题是物体平衡中极值问题,难点在于分析F取得最小值的条件,采用作图法,也可以采用函数法分析确定.14.一辆汽车沿着一条平直的公路行驶,公路旁边与公路平行有一行电线杆,相邻电线杆间的间隔均为50m,取汽车驶过某一根电线杆的时刻为零时刻,此电线杆作为第1根电线杆,此时刻汽车行驶的速度为5m/s,若汽车的运动为匀变速直线运动,在10s末汽车恰好经过第3根电线杆,则下列说法中正确的是()A.汽车的加速度为1m/s2B.汽车继续行驶,经过第7根电线杆时瞬时速度大小为25m/sC.汽车在第3根至第7根间运动所需要的时间为20sD.汽车在第3根至第7根间的平均速度为20m/s【考点】匀变速直线运动规律的综合运用.【专题】定量思想;方程法;直线运动规律专题.【分析】根据匀变速直线运动的位移时间公式求出加速度.根据位移公式得出汽车从第一根到第7根的时间,从而得出第3根到第7根的时间,通过平均速度的定义式求出平均速度的大小,根据速度时间公式求出通过第7根电线杆的速度.【解答】解:A、汽车在10s内的位移是:x13=50×2=100m,由x=v1t+at2,代入数据解得:a=1m/s2.A正确;B、由v2﹣v02=2ax,v22﹣v12=2ax,即:v22﹣52=2×1×6×50,解得:v2=25m/s,B正确;C、汽车从第1根到第7根电线杆的时间是t7,则:x17=6×50m=300m。
内蒙古包头市第九中学最新高一上学期12月月考生物试题
2021-2021年度包九中高一生物月考 12Ⅰ。
选择题(每题1分,共60分)1。
下列事实中,不支持“生命活动离不开细胞"观点的是( )A。
乙肝病毒依赖人体肝细胞生活B.草履虫会逃避有害刺激C.HIV由蛋白质和核酸组成D.父母亲通过精子和卵细胞把遗传物质传给下一代2。
下列关于细胞与生命活动关系的叙述,正确的是( )A.细胞学说解释了细胞的多样性和统一性B。
一切生物都由细胞构成,所以细胞是最基本的生命系统C.草履虫、变形虫等均能完成摄食、运动、生殖等生命活动D.病毒没有细胞结构,在生命系统的层次中属于个体水平3.生长在沙漠中的仙人掌,其肉质茎的细胞中,含量最多的化合物是( )A.蛋白质 B。
脂质 C.糖类D.水4。
进行足球比赛时,有的运动员到了下半场会出现抽搐现象,出现这种情况的主要原因是( )A.运动员体力消耗太大,能量供应不足B.运动员体内的水分散失太多,体内的细胞大量失水C.伴随着大量流汗,体内的钙盐流失太多,没有及时补充D.体内的钠盐流失太多,出现了血压下降、心率加快造成的5.下列有关生命系统的叙述正确的是()A.生命系统中各生物体均具有多种组织、器官和系统B。
生物圈是地球上最基本的生命系统和最大的生态系统C.流感病毒不属于生命系统,但其增殖离不开活细胞D。
肌肉细胞里的蛋白质和核酸属于生命系统的分子层次6。
电影《侏罗纪公园》中恐龙是霸主动物,可是恐龙已经灭绝了。
请你推测,在组成恐龙的细胞的各种元素中,含量最多的四种元素是( )A.C、O、Ca、KB.C、H、O、NC.O、C、N、PD.C、H、O、P7。
夏季酷暑十分,在室外作业的人们应多饮用( )A.盐汽水 B.牛奶C.纯净水D.果汁8。
鱼体内的核酸彻底水解后,对水解物判断正确的是( )A.1种五碳糖B.4种脱氧核糖核苷酸C.5种含氮碱基D.8种核苷酸9。
经测定知道某蛋白质的相对分子质量为5646,若已知氨基酸的平均相对分子质量为128,由此推断该蛋白质分子中含有的氨基酸数、肽链数以及至少含有的游离氨基数分别为( )A。
内蒙古包头市第九中学高一10月月考物理试卷 Word版含答案.pdf
2015.10月包九中高一物理月考试卷 时间:60分钟 满分:100分 一、单项选择题(共7小题,每小题5分,共35分。
每个小题只有一个选项符合题目要求) 1.下列关于质点的说法中正确的是( ) A.只要是体积很小的球体就可以视为质点 B.研究一汽车从包头到北京的运动时间时可以将其视为质点 C.因为太阳的体积太大了,所以任何情况下都不可以将其视为质点 D.质量很大的物体无论在任何情况下都不能看成质点 2.下列各组物理量中,都是矢量的是( )A. 加速度、速度的变化量、速度B.速度、速率、加速度C. 位移、时间、速度D.路程、时间、位移 3. 在电视连续剧《西游记》中,常常有孙悟空“腾云驾雾”的镜头,这通常是采用“背景拍摄法”让“孙悟空”站在平台上,做着飞行的动作,在他的背后展现出蓝天和急速飘动的白云,同时加上烟雾效果;摄影师把人物动作和飘动的白云及下面的烟雾等一起摄入镜头放映时,观众就感觉到“孙悟空”在“腾云驾雾”时,观众所选的参考系是( ) A.孙悟空 B.平台 C.白云 D.镜头 A.在某一段时间内物体运动的位移为零,则该物体一定是静止的 B.只要物体做直线运动,位移的大小和路程就一定相等[Z&X&X&K] C.只要物体的加速度不为零,它的速度就在变化 D.平均速率一定等于平均速度的大小 5.一质点始终向着一个方向做直线运动,在前2/3时间内平均速度为v/2,后1/3时间内平均速度为2v,则物体在t时间内平均速度大小是( )A.3v/4B.3v/2C.2v/3.D. v 6.甲、乙两物体的图象如图所示,下列判断正确的是( ) 甲作直线运动,乙作曲线运动B.tl时刻甲乙相遇 C.tl时间内甲的位移大于乙的位移 D.tl时刻甲的速度大于乙的速度关于速度和加速度的关系,下列说法正确的有 A.加速度越大,速度越大 B速度变化量越大,加速度越大 C,则加速度 D.速度变化率越大则加速度越大8.如图所示,是一个圆心为O半径为R的中国古代八卦图,中央S部分是两个半圆,练功人从A点出发沿相关圆弧A→B→C→O→A→D→C进行,最后到达C点。
内蒙古包头市第九中学最新高一10月月考生物试题
包头九中最新度第一学期高一生物月考试题一.选择题(共30小题,每小题2分,共60分)1.从生命系统结构层次分析,下列正确的是( )A.一个细菌只是细胞层次B。
高等动物和高等植物都具有器官和系统C.生物大分子如蛋白质、核酸,不是生命系统的结构层次D。
一个湖泊中的所有动物可以看成是一个群落2。
细胞学说揭示了( )A。
植物细胞与动物细胞的区别B.生物体结构的统一性C.细胞为什么要产生新细胞D.人们对细胞的认识是一个艰难曲折的过程3.HIV、肺炎双球菌和变形虫这三种生物的共同点是( )A .都有细胞结构B.都有细胞器核糖体C .都能独立生活D.都含有遗传物质4.大肠杆菌与草履虫的主要不同之处是前者具有( )A 。
拟核B.核糖体C.细胞核D.遗传物质5.下列组合,在生命系统的层次中依次属于种群、群落、和生态系统的一组是()①一个池塘中的全部生物②一片草地上的全部昆虫③某水库中的全部鲫鱼④一根枯木及枯木上的所有生物A .①②④ B .③①④ C .①②③ D .②③④ 6。
下列各组合中,能体现生命系统由简单到复杂的正确层次的是( )①苹果 ②呼吸道上皮 ③神经元 ④柳树 ⑤细胞内蛋白质、水等化合物 ⑥甲型H1N1病毒⑦某池塘中的所有的鱼 ⑧一片森林中的全部山毛榉 ⑨一片草地 ⑩某片森林中所有的生物 A. ⑤⑥③②①④⑦⑩⑨ B。
③②①④⑦⑧⑩⑨ C. ③②①④⑧⑩⑨D .⑤②①④⑦⑩⑨7。
细胞是生命活动的基本单位,关于细胞结构的叙述,错误的是( ) A.细菌有核糖体,无叶绿体 B . 蓝藻无细胞核,也无核糖体C .水绵有细胞核。
也有叶绿体 D 。
酵母菌有细胞核,无叶绿体 8.下列有关病毒的叙述中,正确的是( ) A 。
病毒和其他生物一样,也具有细胞结构B 。
一种病毒一般可以同时感染动物细胞和植物细胞 C.病毒的繁殖只在宿主的活细胞中进行 D.在人工配制的培养基上就能培养病毒9.下列有关肽键写法中,不正确的是( )A 。
内蒙古包头市第九中学高一下学期第一次月考物理试题含答案.doc
内蒙古包头市第九中学2015-2016学年高一下学期第一次月考物理试题 1、质点仅在恒力F 的作用下,由O 点运动到&点的轨迹如图所示,在人点时速度的方向与 x 轴平行,则恒力F 的方向可能沿( )A 、兀轴正方向B 、x 轴负方向C 、y 轴正方向D 、y 轴负方向2、 关于做平抛运动的物体,正确的说法是() A 、速度始终不变B 、加速度始终不变C 、受力始终与运动方向垂直D 、受力始终与运动方向平行3、 设行星绕恒星运动轨道为圆形,则它运动的周期平方与轨道半径的三次方之比C=K 为 R常数,此常数的大小()A 、 只与恒星质量有关B 、 与恒星质量和行星质量均有关C 、 只与行星质量有关D 、 与恒星和行星的速度有关 4、 如图所示,光滑水平面上,小球〃在拉力F 作用下做匀速圆周运动。
若小球运动到P 点 小球将沿轨迹R?做离心运动关于小球运动情况的说法正确的是(C 、 若拉力突然变大, 小球将沿轨迹Pa 做离心运动D 、 若拉力突然变小, 小球将沿轨迹Pc 运动5、小球将沿轨迹Pa 做离心运动若拉力突然变小,B、如图所示,质量为加的石块从半径为R的半球形碗口下滑到碗的最低点的过程中,如果A、因为速率不变,加以石块的加速度为零B、石块下滑过程中受的合外力越來越大C、石块下滑过程中受的摩擦力大小不变D、石块下滑过程中的加速度大小不变,方向始终指向球心6、加为在水平传送带上被传送的小物体(可视为质点,且相对传送带静止),A为终端皮带轮,如图所示,己知皮带轮半径为厂,传送带与皮带轮间不会打滑。
当加可被水平抛出时,人轮每秒的转速最少是()D7、如图所示,在人点有一个小球,紧靠小球的左方有一个点光源S。
现将小球从A点正对着竖直墙水平抛岀,不计空气阻力,则打到竖直墙之前,小球在点光源照射下的彫子在墙上的运动是()u _____ / 「j1h\ \ 、 \A、匀速直线运动B、自由落体运动C、变加速直线运动D、匀减速直线运动8、在河面上方h = 20^的岸上有人用长绳栓住一条小船,开始时绳与水面的夹角为30°。
2022-2023学年内蒙古自治区包头市第九中学高一上学期10月月考数学试题(解析版)
2022-2023学年内蒙古自治区包头市第九中学高一上学期10月月考数学试题一、单选题1.若集合{}220,{03}A x x x B x x =--<=<<,则A B =( )A .(0,2)B .(2,3)C .(1,0)-D .(1,3)-【答案】A【分析】化简集合,然后利用交集的定义运算即得. 【详解】由题可知(1,2),(0,3)A B =-=, 所以(0,2)A B ⋂=. 故选:A .2.已知a ∈R ,集合{}21,M a =,{},1N a =-,若M N ⋃有三个元素,则M N ⋂=A .{}0,1B .{}0,1-C .{}0D .{}1【答案】C【分析】由M N ⋃有三个元素可判断2a a =,结合集合的互异性排除不合理数值,再求M N ⋂即可【详解】因为集合{}21,M a =,{},1N a =-,若M N ⋃有三个元素,则2a a =且1a ≠±,解得0a =.此时{}0MN =,故选C.【点睛】本题考查根据集合的并集求解参数,进而求解两集合交集问题,解题易错点为忽略集合的互异性3.已知a 、b 、R c ∈,那么下列命题中正确的是( ) A .若a b >,则22ac bc > B .若a bc c>,则a b > C .若33a b >且0ab <,则11a b> D .若22a b >且0ab >,则11a b> 【答案】C【分析】根据不等式的性质,对选项逐一判断即可. 【详解】对于选项A ,当c 为0时不成立; 对于选项B ,当c 为负数是不成立;对于选项C ,由33a b >且0ab <可得0,0a b ><,所以11a b>故C 正确;对于选项D ,若22a b >且0ab >说明,a b 同号,当,a b 为正数时不成立. 故选:C4.如果不等式1x a -<成立的充分不必要条件是1322x <<,则实数a 的取值范围是( )A .1322a <<B .1322a ≤≤C .32a >或12a < D .32a ≥或12a ≤ 【答案】B【分析】先用去绝对值法解出不等式的解集,说明1322x <<包含在不等式的解集中,找出边界的大小关系可得答案.【详解】1,11,11;x a x a a x a -<∴-<-<∴-<<+不等式1x a -<成立的充分不必要条件是1322x <<,说明()13,1,1,22a a ⎛⎫⊂-+ ⎪⎝⎭112312a a ⎧-≤⎪⎪∴⎨⎪+≥⎪⎩不等号不能同时取到,解之:1322a ≤≤,检验一下左右等号命题成立.故选:B 5.不等式组(2)0{1x x x +><的解集为A .{|21}x x -<<-B .{|10}x x -<<C .{|01}x x <<D .{|1}x x >【答案】C【详解】试题分析:(2)020{{01111x x x x x x x +>-∴∴<<<-<<或,所以不等式的解集为{|01}x x <<【解析】不等式解法6.下列四个函数中,与函数y x =是同一个函数的是( ) A .2x y x=B.2y = C.y D.y 【答案】C【分析】从对应关系与定义域两方面同时判断,均相同的即为同一个函数.【详解】A 选项,2x y x=等价于,(0)y x x =≠,与原函数定义域不同,不是同一函数;B选项,2y =等价于,(0)y x x =≥,与原函数定义域不同,不是同一函数;C选项,y 等价于y x =,与原函数是同一函数;D选项,y =y x =,与原函数对应关系不同,不是同一函数. 故选:C.7.若集合{}2|10A x ax ax =-+<为空集,则实数a 的取值范围是( )A .(0,4)B .[0,4)C .(0,4]D .[0,4]【答案】D【分析】题意说明不等式210ax ax -+<无实解,分类讨论0a =和0a ≠两种情况. 【详解】由题意不等式210ax ax -+<无实解,0a =时,不等式为10<,不成立,无实解.0a ≠时,240a a a >⎧⎨∆=-≤⎩,解得04a <≤, 综上,[0,4]a ∈. 故选:D.【点睛】本题考查不等式恒不成立问题,即不等式无实解.注意要对最高次系数分类讨论.8.已知函数()234,1(),1a x a x f x x x ⎧--<=⎨≥⎩是R 上的增函数,则实数a 的取值范围是( ) A .2,35⎛⎫⎪⎝⎭B .2,35⎡⎤⎢⎥⎣⎦C .2,35⎡⎫⎪⎢⎣⎭D .2,35⎛⎤ ⎥⎝⎦【答案】C【分析】根据()f x 是R 上的增函数,列出不等式组,解该不等式组即可得答案.【详解】解:因为函数()234,1(),1a x a x f x x x ⎧--<=⎨≥⎩是R 上的增函数, 所以()230134a a a->⎧⎨≥--⎩,解得235a ≤<,所以实数a 的取值范围是2,35⎡⎫⎪⎢⎣⎭,故选:C.二、多选题9.已知函数228,1()42,1x ax x f x x a x x ⎧-+≤⎪=⎨++>⎪⎩,若()f x 的最小值为(1)f ,则实数a 的值可以是( )A .1B .54C .2D .4【答案】BCD【分析】根据分段函数解析式,结合对勾函数的性质判断1x >上单调性、值域,再讨论1a <、1a ≥结合二次函数的性质判断1x ≤上的单调性和值域,最后根据题设求a 的范围,即可确定正确选项. 【详解】由题设,()()228,1{42,1x a a x f x x a x x-+-≤=++>,根据对勾函数的性质:()f x 在(1,2)上递减且值域为(42,52)a a ++,在(2,)+∞上递增且值域为(42,)a ++∞,当1a <时,()f x 在(,)a -∞上递减且值域为2(8,)a -+∞,在(,1]a 上递增且值域为2(8,92]a a --, ∴此时,(1)92f a =-,显然不是最小值,不合题设; 当1a ≥时,()f x 在(,1]-∞上递减且值域为[92,)a -+∞, ∴此时,要使(1)92f a =-是最小值,则9242a a -≤+,可得54a ≥. ∴B 、C 、D 符合要求. 故选:BCD10.已知不等式20ax bx c ++<的解集为{|1x x <-或3}x >,则下列结论正确的是( ) A .a<0 B .0a b c ++>C .0c >D .20cx bx a -+<的解集为1{|3x x <-或1}x >【答案】ABC【分析】根据题意可得a<0且20ax bx c ++=的根为1,3-,利用韦达定理可得023a b a c a <⎧⎪=-⎨⎪=-⎩,分别代入计算判断正误.【详解】根据二次函数开口与二次不等式之间的关系可知a<0,A 正确; 20ax bx c ++=的根为1,3-,则01313a b a c a ⎧⎪<⎪⎪-+=-⎨⎪⎪-⨯=⎪⎩,即023a b a c a<⎧⎪=-⎨⎪=-⎩∴40a b c a ++=->,B 正确;30c a =->,C 正确;20cx bx a -+<,即2320ax ax a -++<,则23210x x --<,解得113-<<x∴20cx bx a -+<的解集为1|13x x ⎧⎫-<<⎨⎬⎩⎭,D 错误;故选:ABC .三、填空题11.已知1x >,则函数211x x y x ++=-的最小值为__________.【答案】3+【详解】1x > ,则函数213133311x x y x x x ++==-++≥++--,当且仅当1x =时,函数取得最小值,最小值为3+,故答案为3+【易错点晴】利用基本不等式求最值,属于难题.利用基本不等式求最值时,一定要正确理解和掌握“一正,二定,三相等”的内涵:一正是,首先要判断参数是否为正;二定是,其次要看和或积是否为定值(和定积最大,积定和最小);三相等是,最后一定要验证等号能否成立(主要注意两点,一是相等时参数否在定义域内,二是多次用≥或≤时等号能否同时成立).12.若函数()2212f x x x +=-,则()7f =_________.【答案】3【分析】先设21x t +=进行换元,求出()f t 的解析式,再求出()f x 的解析式,即可求出()7f 的值. 【详解】设21x t +=,则1,2t x -=所以22135()(1),2424t t f t t t -⎛⎫=--=-+ ⎪⎝⎭所以235(),424x f x x =-+故()7f =273573424-⨯+=故答案为:313.用篱笆围成一个面积为1002m 的矩形菜园,则最少需要篱笆的长度为___________m . 【答案】40【分析】设出矩形的边长,表示出面积和周长,由基本不等式求出最小值即可.【详解】设矩形菜地的边长为(),0,0>>a b a b ,则100ab =,矩形的周长为()22240C a b ab =+≥⨯=,当且仅当10a b ==时,等号成立,所以最少需要篱笆的长度为40m . 故答案为:40.14.某班共有30名学生,在校运会上有20人报名参加赛跑项目,11人报名参加跳跃项目,两项都没有报名的有4人,则两项都参加的人数为________. 【答案】5【分析】设参加赛跑项目为集合A ,参加跳跃项目为集合B ,根据题意,可得A 、B 、A B ⋃中元素的数目,由集合间元素数目的关系计算可得答案.【详解】根据题意,设参加赛跑项目为集合A ,参加跳跃项目为集合B ,可得()20card A =,card (B )=11,()=30-4=26card A B ⋃, 所以()=card A B card ⋂(A )+card (B )-()=31-26=5card A B ⋃, 所以两项都参加的有5人. 故答案为:5.15.若关于x 的一元二次方程210x ax ++=有两个不相等的负实根,则实数a 的取值范围是__________. 【答案】()2,+∞【分析】由根与系数的关系列方程组,即可解得.【详解】不妨设一元二次方程210x ax ++=有两个不相等的负实根12,x x , 所以21212Δ40010a x x a x x ⎧=->⎪+=-<⎨⎪=>⎩,解得:2a >.所以实数a 的取值范围是()2,+∞. 故答案为:()2,+∞16.函数()21(31)f x x x x =--≤<的值域为__________.【答案】174,8⎡⎤-⎢⎥⎣⎦【分析】设1t x =-,可知20t ≥>,将问题转化为关于t 的二次函数值域的求解问题,根据二次函数性质可求得结果.【详解】函数()21f x x x =+-,31x -≤<,410x ≥-> 令t 1x =-,则20t ≥>,且21x t =-, 得22117222()48y t t t =-+=--+,20t ≥>,当14t =时,函数有最大值178, 当2t =时,函数有最小值4- 所以值域为174,8⎡⎤-⎢⎥⎣⎦. 故答案为:174,8⎡⎤-⎢⎥⎣⎦17.设偶函数()f x 的定义域为[]5,5-,若当[]0,5x ∈时,()f x 的图象如图所示,则不等式()0f x <的解集是__________.【答案】[)(]5,22,5--【分析】根据偶函数性质,将()0f x <转化为()0f x <,再根据图象,写出x 的范围,进而求出解集即可. 【详解】解:由题知()f x 为偶函数, ()()()f x f x f x ∴=-=,()0f x <,即()0f x <,由[]0,5x ∈时,()f x 的图象可知,若()0f x <,即25x <≤,即x 到原点的距离大于2小于等于5的数, 故解得:[)(]5,22,5x ∈--.故答案为:[)(]5,22,5--18.若函数y = f (x )为偶函数,且在(0, + ∞)上是减函数,又f (1) = 0,则()()2f x f x x+-<的解集为_______【答案】()()101-⋃+∞,, 【分析】根据题意作出函数的图象,如图,利用函数的奇偶性将不等式化简,结合图象即可求出不等式的解集.【详解】由题意知,作出符合条件的函数图象,如图,由函数()y f x =为偶函数,得()()()002f x f x f x x x+-<⇒<,即()0xf x <,结合图象可知, 当x >0,时,f (x )<0,则x >1; 当x <0时,f (x )>0,则-1<x <0, 所以()()02f x f x x+-<的解集为()1)01(-+∞,,. 故答案为:()1)01(-+∞,,四、解答题19.已知集合{}()(){}1,2,|10A B x x x a =-=+-=. (1)若3a =,求A B ⋂;(2)若A B A ⋃=,求实数a 的取值集合. 【答案】(1){}1- (2){}1,2-【分析】(1)根据交集的知识求得正确答案.(2)根据A B A ⋃=对a 进行分类讨论,从而求得a 的取值范围. 【详解】(1)依题意1,2A,当3a =时,()(){}{}|1301,3B x x x =+-==-, 所以{}1A B ⋂=-.(2)由()()10x x a +-=解得11x =-,2x a =, 若1a =-,则{}1B =-,A B A ⋃=,符合题意. 若1a ≠-,由于A B A ⋃=,所以2a =. 综上所述,实数a 的取值集合为{}1,2-.20.已知123a b <<<<,求,,2,,aa b a b a b ab b+--各自的取值范围.【答案】35a b <+<,20a b -<-<,522a b -<-<-,26ab <<,113ab <<.【分析】根据不等式的性质可求,,2,,aa b a b a b ab b+--的范围.【详解】因为123a b <<<<,故35a b <+<. 而32b -<-<-,故20a b -<-<, 但a b <,故0a b -<,故20a b -<-<.而624b -<-<-,故522a b -<-<-,但22a b a b b b -=--<-<-, 故522a b -<-<-.又26ab <<,而11132b <<,故113a b <<.21.已知2210ax ax ++≥恒成立. (1)求a 的取值范围;(2)解关于x 的不等式220x x a a --+<.【答案】(1)[0,1]; (2)答案见解析.【分析】(1)根据二次项系数是否为零,结合二次函数的性质分类讨论进行求解即可; (2)根据一元二次方程220x x a a --+=两根的大小分类讨论进行求解即可. 【详解】(1)因为2210ax ax ++≥恒成立, ①当0a =时,10≥恒成立;②当0a ≠时,要使2210ax ax ++≥恒成立.则0a >且0∆≤,即20440a a a >⎧⎨-≤⎩,解得:01a <≤.综上,a 的取值范围为:[0,1];(2)由220x x a a --+<,得()()10x a x a ---<⎡⎤⎣⎦. 因为:01a ≤≤, ①当1a a ->,即102a ≤<时,则1a x a <<-; ②当1a a -=,即12a =时,2102a ⎛⎫-< ⎪⎝⎭,不等式无解; ③当1a a -<,即112a <≤时,则1a x a -<<. 综上所述,当102a ≤<时,解集为{}1x a x a <<-; 当12a =时,解集为∅;当112a <≤时,解集为{}1x a x a -<<. 22.已知函数2()1mx nf x x +=+是定义在[1,1]-上的奇函数,且(1)1f =. (1)求m ,n 的值;判断函数()f x 的单调性并用定义加以证明; (2)求使2(1)(1)0f a f a -+-<成立的实数a 的取值范围.【答案】(1)20m n =⎧⎨=⎩,为增函数,证明见解析;(2)[0,1).【解析】(1)利用()()f x f x -=-和()11f =可求出2m =,0n =,然后利用单调性的定义可得()f x 的单调性;(2)利用()f x 的奇偶性可将不等式2(1)(1)0f a f a -+-<化为()()211f a f a -<-,然后利用其单调性去掉f 即可解出答案.【详解】(1)()f x 是定义在[1,1]-上的奇函数,则()()f x f x -=-, 即2211mx n mx n x x -+--=++,则0n =, 所以()21mx f x x =+,又因为()11f =,得2m =,所以2m =,0n =. 设12,[1,1]x x ∀∈-且12x x <,则()()22121221211212222222121212222(1)2(1)2()(1)11(1)(1)(1)(1)x x x x x x x x x x f x f x x x x x x x +-+---=-==++++++1211x x -≤<≤ ,222112120,10,(1)(1)0x x x x x x ∴->-<++>()()120f x f x ∴-<,()()12f x f x ∴<,f x 在[1,1]-上是增函数 (2)由(1)知()221x f x x =+,()f x 在[1,1]-上是增函数, 又因为()f x 是定义在[1,1]-上的奇函数,由()()2110f a f a -+-<,得()()211f a f a -<-,2211111111a a a a -≤-≤⎧⎪∴-≤-≤⎨⎪-<-⎩,即2020221a a a ≤≤⎧⎪≤≤⎨⎪-<<⎩,解得01a ≤<.故实数a 的取值范围是[0,1).23.为保护环境,某单位采用新工艺,把二氧化碳转化为一种可利用的化工产品.已知该单位每月的处理量最多不超过300吨,月处理成本y (元)与月处理量x (吨)之间的函数关系式可近似的表示为:220040000y x x =-+,且每处理一吨二氧化碳得到可利用的化工产品价值为300元.(1)该单位每月处理量为多少吨时,才能使每吨的平均处理成本最低?(2)要保证该单位每月不亏损,则每月处理量应控制在什么范围?【答案】(1)200x =时,才能使每吨的平均处理成本最低;(2)当100300x ≤≤时,该单位每月不亏损.【分析】(1) 二氧化碳的每吨平均处理成本为40000200,y x x x=+-,由均值不等式求得结果;(2)2500400000S x x =-+-≥结合二次函数的性质以及题意得到结果.【详解】(1)由题意可知,二氧化碳的每吨平均处理成本为(]40000200,0,300y x x x x=+-∈因为40000200200200x x +-≥=,当且仅当40000x x =,即200x =时,才能使每吨的平均处理成本最低;(2)设该单位每月获利为S (元),则()2230030020040000500400000S x y x x x x x =-=--+=-+-≥即100400x ≤≤ ,由题意可知0300x <≤,所以当100300x ≤≤时,该单位每月不亏损.【点睛】本题考查函数模型的构建,考查学生的阅读能力,考查解不等式,同时考查基本不等式的运用,建立函数模型是关键.。
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高考复习试题(一)第一部分:听力(略)第二部分:阅读理解(共两节,满分40分)第一节:(共15小题:每小题2分,满分30分)从A、B、C、D四个选项中,选出可以填入空白处的最佳选项。
AThere is an old Chinese tale about a woman whose only son died. Sadly, she went to the holy man and asked, “What magical things do you have to bring my son back to life?”Instead of sending her away or reasoning with her, he said to her, “Fetch me a mustard (芥菜) seed from a home that has never known sadness. We will use it to drive the sadness out of your life.” The woman happily went off at once in search of that magical mustard seed.She first came to a splendid house, knocked at the door and said, “I am looking for a home that has never known sadness. Is it such a place? It is very important to me.”They told her “You’ve certainly come to the wrong place” and began to describe all the tragic things that had happened to them recently.The woman said to herself, “I have had misfortune of my own. Who is able to help these poor, unfortunate people?” She stayed to comfort them, and then went on in search of a home that had never known sadness. But wherever she went, she found one tale after another of sadness and misfortune.She became so involved in other people’s sorrow that finally she forgot about her search for the magical mustard seed, never realizing that it had, in fact, driven the sadness out of her life. 21.Leaving the holy man, the woman ___________ .A.was full of hope B.was filled with sadnessC.was determined to try again D.became discouraged22.The “magical seed” refers to_________A. a cure for sorrowB.being open to othersC.showing respect to othersD.a home that has never known sorrow23.We can learn from the passage that______A. the holy man was playing a trick on the womanB. the women didn’t go to the right place for the seedC. a mustard seed would bring the woman’s son back to lifeD. the woman was curing herself of sorrow while looking for the seedBWhat if you had only three minutes to grab whatever you could take from your home and the rest would be lost forever? What would you take?As the disasters in Japan changed from the earthquakes and tsunamis (海啸) to nuclear radiati on (核辐射), many people that have been forced to leave their homes are facing the fact that they may not be able to return for a long time.With this in mind, let‟s discuss the value of a Bug Out Bag. This bag is a collection of goods that you would need to survive (生存) if you have to escape from your home with no shelter, food or water during the unexpected situations.A good B.O.B. should include things that are needed for life:● A sleeping bag, or at least a blanket.● Drinking water.● High-calorie, no-cook foods like protein bars, peanut butter, etc.● First-aid supplies.● Fire-starting methods, and a small pot to boil water or cook.● A few basic tools like a knife, some rope, etc.● Flashlight with extra batteries.● Cash.● A digital backup (备份) of all your important documents and family treasures.You could keep a B.O.B. by the front door, or even have several bags at home, at the office a nd in your car. This might seem like more than needed to some of you, but just imagine what a diff erence this kind of preparation would have made to the people of Japan. Then think of the differen ce a B.O.B. will make if those disasters happen to you.24. The author asks the questions in the first paragraph to_____.A. test the readers‟ common senseB. show the importance of a B.O.BC. attract the readers‟ interestD. encourage the readers to ask questions25. What is the main purpose of preparing a B.O.B?A. To find out the causes of disasters.B. To help people protect their treasures.C. To prevent disasters from happening.D. To help people survive unexpected disasters.26. It can be inferred from the passage that______.A. aB.O.B. should be as light as possible B. we can prepare more than one B.O.BC. a B.O.B. is only necessary for the JapaneseD.a B.O.B. should contain all the valuable things27. Which of the following could be the best title of the passage?A. What aB.O.B. is B. How to escape from disastersC. Preparations for outdoor lifeD. Dangerous disasters on the earthCJim suffered heart problems. In conversation he expressed little joy and it seemed that his life was drawing to a close.When his heart problems led to operation, Jim went through it successfully, and a full recovery was expected. Within days, however, his heart was not beating properly. Jim was rushed back to o peration, but nothing was found to explain the cause of his illness. He died on the operating table o n the day before his 48th birthday.Dr. Bruce Smaller, a psychologist (心理学家), had had many conversations with him, and the more he learned, the stranger he realized Jim’s case was. When Jim was a child, his father,a teacher, suffered a heart attack and stayed home to recover. One morning Jim asked his father to look over his homework, promising to come home from school at noon to pick it up. His father agr eed, but when Jim returned his father had died. Jim’s father was 48.“I think all his life Jim believed he killed his father,” Dr. Smoller says.“He felt that if he had not asked him to, too. at his homework,his father would have lived. Jim had been troubled by the idea. The operation was the trial(判决) he had expected for forty years.” Smoller believes that Jim willed himself not to live to the age of 48.Jim’s case shows the powerful role that attitude plays m physical health, and that childhood experiences produce far-reaching effect on the health of grown-ups. Although most cases are lessdirect than Jim’s, studies show that childhood events, besides genes(基因), may well cause such midlife diseases as cancer, heart disease and mental illness.28. Jim was sent back to operation because__________.A. his heart didn’t work wellB. he expected a full recoveryC. his life was drawing to a closeD. the first one wasn’t well performed29. What made Dr. Smaller feel strange about Jim’s case?A. Jim died at a young age.B. Jim died on the operating table.C. Both Jim and his father died of the same disease.D. Jim’s death is closely connected with his father’s.30. From Smoller’s words, we can infer that__________.A. Jim’s father cared little about his studyB. Smoller agreed that Jim did kill his fatherC. Jim thought he would be punished some dayD. Smoller believed Jim woul dn’t live to the age of 4831.Which of the following could have strong effect on one’s physical health according to the text?a. One’s genes.b. One’s life in childhood.c. One’s physical education.d. The date of one’s birthday.e. The opinions one has about something.A. a, b, dB. a, b, eC. a, c, e D b, c, dDCoca-Cola has created a publicity stunt (作秀) in Singapore — a vending machine (自动售货机) which gives out free cans of Coke in return for hugs. The whacky idea is part of the company’s Open Happiness campaign designed to attract young people in Singapore.Students at the National University of Singapore were surprised to find that the soft drinks co mpany had placed the machine in the schoolyard. But instead of the drinks brand’s logo (标志), the words “Hug Me” are written across its red-and-white logo. Instead of paying money, custo mers have to hug the drinks machine to receive a free can of Coke.Public displays of affection are uncommon and have long been discouraged in Singapore, but are on the rise among young people. The move is part of a campaign created by the advertising fir m Ogilvy & Mather, intended to let the youth to see the brand as a non-threatening friend.Leonardo O’Grady, leader of the campaign, said, “Happiness is contagious (传染的). The Coca-Cola Hug Machine is a simple idea to spread some happiness. We want to spread happiness in an unexpected, creative way to attract not only the people present, but the audience at large.”He hopes that it will encourage consumers to bring positivity, optimism and fun into their live s and to open a Coke, sharing a little happiness.The machines have been such a success that there are plans to roll them out across Asia. Mr. O’Grady added, “The reaction was amazing — at one point we had four to five people hugging th e machine at the same time as well as each other! In fact, there was a long line of people looking t o give hugs.”32. The underlined word “whacky” in Paragraph1 can be replaced by “__ ”.A. freeB. strangeC. uncertainD. traditional33. What was the purpose of the campaign?A. To help sell more Coca-Cola drinks.B. To display the famous logo of Coca-Cola.C. To tell the young Coca-Cola is their friend.D. To show Coca-Cola is especially generous.34. Leonardo O’Grady thinks that_____ .A. the Coca-Cola Hug Machine is the best advertisementB. the Coca-Cola Hug Machine can spread happinessC. the Coca-Cola Hug Machine should be open only to the studentsD. people who enjoy the campaign would buy more Coca-Cola drinks35. What can we infer from the passage?A. The campaign has achieved good results.B. The campaign has cost Coca-Cola much money.C. The Coca-Cola Hug Machines will be seen worldwide.D. Coca-Cola concentrates more on sharing happiness than on sales.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项,选项中有两项多余选项Taking good notes is a time-saving skill that will help you to become a better student in several ways. __36___ Second, your notes are excellent materials to refer to when you are studying for a test. Third, note-taking offers variety to your study time and helps you to hold your interest.You will want to take notes during classroom discussions and while reading a textbook or doing research for a report. __37__ whenever or however you take notes, keep in mind that note-taking is a selective process. ___38__The following methods may work best for you.●Read the text quickly to find the main facts and ideas in it.●Carefully read the text and watch for words that can show main points and supporting facts.●Write your notes in your own words.●__39__●Note any questions or ideas you may have about what was said or written.As you take notes, you may want to use your own shorthand (速记). When you do, be sure that you understand your symbols and that you use them all the time. ___40__A. Use words, not complete sentences.B. There are three practical note-taking methods.C. You must write your notes on separate paper.D. Otherwise, you may not be able to read your notes later.E. You will also want to develop your own method for taking notes.F. That means you must first decide what is important enough to include in your notes.G. First, the simple act of writing something down makes it easier for you to understand and remember it.第三部分英语知识运用(共两节,满分45分)第一节:完形填空(共20小题;每小题1.5分,满分30分)阅读下面短文,从短文后各题所给的四个选项(A,B,C和D)中,选出可以填入空白处的最佳选项,并在答题卡上将该选项涂黑。