整式之积的多项式系数和问题(初一)

整式之积的展开多项式系数之和问题---原创

1.

2()__________________;a b +=

2(1)__________________;x +=

若22210(1),x a x a x a +=++

则210_____,a a a ++=210______,a a a -+=

1___,a =20___;a a +=

2()__________________;a b -=

2(1)__________________;x -=

若22210(1),x a x a x a -=++

则210_____,a a a ++=210______,a a a -+=

1___,a =20___;a a +=

2.

3()______________________;a b +=

3(1)______________________;x +=

若3323210(1),x a x a x a x a +=+++

则3210___,a a a a +++=3210_____,a a a a -+-+=31___,a a +=20___;a a +=

3()______________________;a b -=

3(1)______________________;x -=

若3323210(1),x a x a x a x a -=+++

则3210___,a a a a +++=3210_____,a a a a -+-+=31___,a a +=20___;a a +=

3.

22(1)_______________________;x x ++=

若2243243210(1),x x a x a x a x a x a ++=++++

则43210___,a a a a a ++++=43210_____,a a a a a -+-+=

31___,a a +=420___;a a a ++=

22(1)_______________________;x x -+=

若2243243210(1),x x a x a x a x a x a -+=++++

则43210___,a a a a a ++++=43210_____,a a a a a -+-+=

31___,a a +=420___;a a a ++=

若261211102121110210(1),x x a x a x a x a x a x a -+=+++鬃

?++ 求121110210a a a a a a +++鬃

?++的值．

编辑目的：这类题目很多重点初中平时考试会考到的，但是这里用到的技巧学生在小学阶段往往并没有受到过训练，而且这些技巧在高中阶段学习二项式定理时可能会较多地用到。鉴于此，为了达到强化赋值法的训练目的，特编辑这样几个小问题，希望能引发小朋友的思考，引起他们对代数的兴趣。