新GRE数学模拟练习题(2)
新GRE数学11道练习题及答案解析
新GRE数学11道练习题及答案解析导读：本文新GRE数学11道练习题及答案解析，仅供参考，如果觉得很不错，欢迎点评和分享。
1：还有数列题：a1=2，a2=6，an=an-1/an-2，求a150.解答: an=an-1/an-2,所以an-1=an-2/an-3,带入前式得an=1/an-3,然后再拆一遍得到an=an-6,也就是说,这个数列是以6为周期的,则a150=a144=...=a6,利用a1,a2可以计算出a6=1/3.如果实在想不到这个方法,可以写几项看看很快就会发现a150=a144,大胆推测该数列是以6为周期得,然后写出a1-a13(也就是写到你能看出来规律),不难发现a6=a12,a7=a13,然后那,稍微数数,就可以知道a150=a6了,同样计算得1/3.2：问摄氏升高30度华氏升高的度数与62比大小.key:F=30*9/5=543：那道费波拉契数列的题:已知,a1=1 a2=1 an=an-1+an-2 ，问a1,a2,a3,a6四项的平均数和a1,a3,a4,a5四项的平均数大小比较。
解答:费波契那数列就是第三项是前两项的和,依此类推得到a1-a6为:1 123 5 8 13 21 a1+a2+a3+a6=12, a1+a3+a4+a5=11,所以为大于.4：满足x^2+y^2key: 按照X的可能情况顺序写出:X= Y=1 1-92 1-93 1-94 1-95 1-86 1-87 1-78 1-9 1-4 =>Myanswer:加起来=695：24，36，90，100四个数中,该数除以它的所有的质因子，最后的结果是质数的是那个：Key:906:0.123456789101112….，这个小数无限不循环地把所有整数都列出来.请问小数点后第100位的数字是多少?Key: 位数0 1 2 3 4 5 6 7 8 9 1010 11 12 ………………………19 2020 21……………………………29 2030………………………………39 2040………………………………49 2050 51 52 53 54 55 56 ――――――第101位=5??7：2904x=y2(y的平方)，x、y都是正整数，求x的最小值。
GRE数学模拟题目
GRE数学模拟题目近年来，GRE数学部分在考题的设计上越来越注重考察考生的逻辑推理能力和问题解决能力。
下面将为大家提供一些模拟GRE数学题目，并对这些题目进行详细的解析。
题目一：某公司的年度销售额从1997年的50万美元增加到2000年的80万美元。
如果假设年销售额以4%的年增长率递增，那么请推算出该公司在1997年的年度销售额是多少？解析：假设1997年的年销售额为x万美元。
根据题意，该公司的年销售额从1997年到2000年增长了80 - 50 = 30 万美元。
根据题设，年增长率为4%，可得以下等式：x * (1 + 0.04)^3 = x + 30化简得：1.04^3 * x = x + 301.1259 * x = x + 300.1259 * x = 30x = 30 / 0.1259 ≈ 238.39因此，该公司在1997年的年度销售额约为238.39 万美元。
题目二：将一个名为A的集合中的元素逐个地添加到一个名为B的集合中，每次添加时，元素个数增加的量以等比数列递增，首项为1，公比为2。
如果操作6次后，集合B中的元素个数为121个，请问集合A原本有多少个元素？解析：设集合A原本有n个元素。
根据题设，我们可以列出公式：1 +2 + 2^2 + 2^3 + 2^4 + 2^5 = n + 1212^6 - 1 = n + 12164 - 1 = n + 12163 = n + 121n = 63 - 121 = -58由于集合中元素个数不能为负数，所以集合A原本的元素个数不能为-58。
因此，这道题目是不符合实际情况的，解不存在。
题目三：已知一组数据为 {2，4，6，8，10}，若要将该组数据的每个元素都除以相同的正整数x，使得得到的结果仍然构成一个等差数列，求x的最小值。
解析：首先计算原数据元素间的差值为2。
如果要将这组数据除以x得到一个等差数列，那么除数x应该满足以下条件：2 / x = 4 / x - 2 / x = 6 / x - 4 / x = 8 / x - 6 / x = 10 / x - 8 / x化简得：2 / x = 2 / x = 2 / x = 2 / x = 2 / x由此可得x的最小值为2。
gre考试数学真题试卷
gre考试数学真题试卷GRE考试数学真题试卷一、选择题（每题1分，共20分）1. If the function f(x) = 3x^2 - 2x + 1, what is the value of f(1)?A. 0B. 2C. 3D. 4E. 52. What is the derivative of the function g(x) = 4x^3 - x^2 + 7?A. 12x^2 - 2xB. 12x^2 + 2xC. 12x^3 - 2xD. 12x^3 + 2xE. 12x^3 - 2x^23. The area under the curve of y = x^2 from x = 0 to x = 2 is:A. 2B. 4C. 8D. 10E. 124. If a and b are the roots of the quadratic equation x^2 +5x + 6 = 0, what is the value of a + b?A. -3B. -2C. -1D. 0E. 15. The slope of the line passing through the points (2, 3) and (4, 7) is:A. 1B. 2C. 3D. 4E. 56. What is the value of sin(30°)?A. 1/2B. √2/2C. √3/2D. 2/√3E. 1/√27. The integral of the function h(x) = 3x + 2 is:A. x^3 + 2x + CB. x^3 + 2x^2 + CC. x^2 + 2x + CD. 3x^2 + 2x + CE. 3x^2 + 2x^3 + C8. The equation of a circle with center (3, 4) and radius 5 is:A. (x - 3)^2 + (y - 4)^2 = 25B. (x - 3)^2 + (y - 4)^2 = 1C. (x - 3)^2 + (y - 4)^2 = 100D. (x - 3)^2 + (y - 4)^2 = 625E. (x - 3)^2 + (y - 4)^2 = 09. The volume of a sphere with radius 4 is:A. 256πB. 512πC. 1024πD. 2048πE. 4096π10. If the sequence 2, 6, 18, 54, ... is a geometric sequence, what is the common ratio?A. 2B. 3C. 4D. 5E. 6二、填空题（每题2分，共20分）11. If the sum of the first n terms of an arithmetic sequence is given by S_n = n^2, then the 5th term of the sequence is__________.12. The equation of the line perpendicular to y = 2x - 1 and passing through the point (1, 3) is __________.13. The value of the definite integral ∫(0 to 1) x^2 dx is__________.14. If the function f(x) = sin(x) + cos(x), then f''(x) is__________.15. The area of a triangle with vertices at (0,0), (3,0), and (0,4) is __________.16. The limit of the function (1 + 1/n)^n as n approaches infinity is __________.17. The value of e^(iπ) is __________.18. The standard deviation of the data set {2, 4, 6, 8, 10} is __________.19. If a fair coin is tossed 5 times, the probability of getting exactly 3 heads is __________.20. The value of the binomial coefficient C(n, k) when。
2018-2019-GRE几何数学的备考练习题-推荐word版 (2页)
2018-2019-GRE几何数学的备考练习题-推荐word版
本文部分内容来自网络整理，本司不为其真实性负责，如有异议或侵权请及时联系，本司将立即删除！
== 本文为word格式，下载后可方便编辑和修改！ ==
GRE几何数学的备考练习题
1 两条直线比斜率:
一条x轴intercede 3,y轴intercede 4, 和一条x轴intercede 4,一个y轴intercede 3 解：slope1=/=-4/3 slop2=/=-3/4
注意由于两条直线的斜率是负数, 后者斜率大一些.
2.直线y+x=4, 与x^2+y=4交点的距离?
解：meykey:根号2。
4-x=4-x2
3.有一个题目觉得很有意思，就是问y=xx+1和y=x-1的图是下列哪一个?
比较简单。
选的是D。
4.一直线在X轴截距为a，Y轴上截距为b，问斜率是多少。
解：两点式：列出两点,k=/=-b/a
5.圆里头最长的线段是哪条?
就是直径
6.图中一三角形,X,,Z分别为两个角的外角,Y为第三个内角,问X+Z与
180+Y的大小?
解： Y++=180
可退出Y+180= X+Z 所以相等
7.钝角三角形，两短边为6，8，问其面积与24的大小。
解：
8.三角形三边为8,5,6,问5,6 夹角于90谁大?。
新GRE数学代数模拟考试练习题
新GRE数学代数模拟考试练习题1.正整数x，下面哪个选项不和3x相等我选的是E：7-x(sure)2.X~3 * y = 10 ~6 (y > 1), 问X 与 10~2比大小解：x=10~2/y~1/3y>1则y~1/3>1 所以还是10~2大选B3.数列：a1=3, a2=6, a(n)= a(n-1)/a(n-2)，问：a(150)=?解：3, 6, 2, 1/3, 1/6, 1/2, 3, 6, (每6次一个循环，答案应该是1/2吧)另一版本：前人几经有误,我的是：a1=2, a2=6, an=a(n-1)/a(n-2), 求a1502, 6, 3, 1/2, 1/6, 1/3 , 2, 6, 3, …所以我的答案是1/3 (大家看清楚A1的值，自己判断吧)4. 125w+25x+5y+z=264,x,y,z,w,are nonnegative integrate,and no more than 5,what is w+x+y+z?解：用短除法把256写成五进制就是2024，则得到x+y+z+w=2+0+2+4=85.a * x平方+B*X+k=0(a和b已知，k未知)，给出一个X的值，问另一个。
简单，解出K后，再解出X26.a,b,c,-5,-10的平均数和a,b,c,5,10的平均数之差是多少?解：在考场遇到时看清楚谁在前。
答案是-6 ，也许是6。
7. F(X)=2的2X-1方，求F(3+X)F(3-X)解：2的10次方8.-7<=x<=5-5<=y<=3问x^2-y^2的值?(转载自http://，请保留此信息。
)解：当X= -7 ，Y= 0 时，49。
9.有个公式很重要。
求M到N之间是Q的倍数的数有多少个?公式是： [(该范围内Q的倍数-该范围内Q的最小倍数)/Q ] +1今天我碰到两个这样的题，多亏有这个公式，要不然就费劲了10.一个数，被9整除得x1+x2+x3,被12整除得x2+x3,则这个数至少为?能被x1整除?答案：369(x1+x2+x3)=12(x2+x3) x1=3(x2+x3)……..11.数列a1,a2,...a10.除了第一项外的各项都是其前一项的1/2。
英语证书考试美国研究生入学考试(GRE)2022年模拟题2
英语证书考试美国研究生入学考试（GRE）2022年模拟题2(总分：170.00，做题时间：180分钟)一、数值比较题(总题数：7，分数：56.00)1.n is a positive integerQuantity A: (-1)n-1Quantity B: 0（分数：8.00）A.Quantity A is greater.B.Quantity B is greater.C.The two quantities are equal.D.The relationship cannot be determined from the information given. √解析：n如果为1，那么Quantity A为1，大于Quantity B。
n如果为大于1的奇数，那么Quantity A 为1，大于Quantity B。
n如果为大于1的偶数，那么Quantity A为-1，小于Quantity B。
所以选择D 无法比较。
2.n is a positive integer greater than 1Quantity A: the greatest common divisor of n+4 and n+5Quantity B: 1（分数：8.00）A.Quantity A is greater.B.Quantity B is greater.C.The two quantities are equal. √D.The relationship cannot be determined from the information given.解析：既然n是大于1的整数，那么n+4，n+5必然是两个连续的正整数，它们互质，那么它们的最大公约数为1，所以选择C。
3.(a+b)2=a2+b2, and a=1Quantity A: aQuantity B: b（分数：8.00）A.Quantity A is greater. √B.Quantity B is greater.C.The two quantities are equal.D.The relationship cannot be determined from the information given.解析：(a+b)2=a2+b2+2ab，现在已知(a+b)2=a2+b2，因此2ab=0，因为a=1，所以b=0，选择A。
GRE数学机经200题答案及解析(第二版)-2018年6月更新
持续更更新，欢迎关注
淘宝店铺：点睛英语
持续更更新，欢迎关注
淘宝店铺：点睛英语
持续更更新，欢迎关注
淘宝店铺：点睛英语
持续更更新，欢迎关注
淘宝店铺：点睛英语
解析题17：x的15次方方=x的3次方方的5次方方，x的3次方方个位数又又等 于3，所以等于是求一一个个位数是3的数字的五次方方的个位数是多 少。根据我们上课所讲的规律律，当指数是4n+1（n是零或正整 数）的形式时，3的4n+1次方方的个位数一一定是3，所以答案选B。
16答案E
解析：根据题意可以知道，丢失的总工作周数=(5200*48.5)/40=6305,选E
17答案E
解析：可以把x=4代入ABCDE中进行检验，y应该等于0，可以发现BE符合。又因
为二次曲线过(0，-60)这个点，所以排除B，选E
18答案E
解析：因为是正方形内接于大正方形中，所以每一个小三角形的斜边都是y，
以选D
13答案A
持续更更新，欢迎关注
淘宝店铺：点睛英语
解析：题目问Q与R的表面积和与P的表面积的差值。可以这样想：如果把Q与R 堆在一起，那么就是与P的表面积一样。但是Q与R堆在一起会抵消掉两个底面 （就像把双手合十以后两只手就只有两个面了，本来有四个），所以Q与R的表
面积和与R的表面积差值为2ab
大
5答案B
解析：A式为y/(xz2),B式为y2/(x2z2),即比较y/x与（y/x）2的大小，因为y/x >1,所
以选B
持续更更新，欢迎关注
淘宝店铺：点睛英语
6答案B
解析：已知x<y-2,在不等式两边分别加y，可得x+y<2y-2，再在不等式两边同时
gre练习题
gre练习题GRE（Graduate Record Examinations）是一项广泛用于研究生院入学申请的标准化考试，它包括了数学、阅读和写作三个部分。
以下是一些模拟练习题，可以帮助你准备GRE考试。
# 数学部分练习题1. 整数问题如果一个整数除以4余1，除以5余1，那么这个整数加1后一定是5的倍数。
这种说法正确吗？为什么？2. 百分比问题如果一个商品打8折后的价格是原价的80%，那么原价与打折后价格的差额占原价的百分比是多少？3. 几何问题一个圆的半径是10厘米，求这个圆的面积。
4. 代数问题如果方程 \( ax^2 + bx + c = 0 \) 有两个实数根，且 \( a \), \( b \), \( c \) 都是正数，那么 \( b^2 - 4ac \) 必须大于、等于还是小于0？5. 概率问题一个袋子里有5个红球和3个蓝球。
如果随机抽取2个球，至少有一个是红球的概率是多少？# 阅读部分练习题1. 主旨大意题阅读以下段落，并概括其主旨大意："In recent years, the debate over the role of technologyin education has intensified. Advocates argue that incorporating technology into the classroom can enhance learning experiences and prepare students for the digital age. Critics, on the other hand, contend that an over-reliance on technology can detract from critical thinking andinterpersonal skills."2. 推断题根据上述段落，推断作者可能对技术在教育中的作用持什么态度？3. 词汇题段落中提到的“enhance”一词，最接近的同义词是什么？4. 细节理解题根据段落，哪些论点是支持者提出的？哪些是批评者提出的？5. 逻辑关系题段落中提到的两种观点之间存在什么逻辑关系？# 写作部分练习题1. 论证有效性分析阅读以下论证：“由于越来越多的人选择在线购物，实体店铺将很快消失。
GRE数学的模拟试题
GRE数学的模拟试题GRE数学的模拟试题1. x+y=5&2x+2y=8之间最短距离与1比较<12 .3/0.0001 与 3/0.000099 比大小?(答案：<)3. 在一个图表题里考到了median。
这题比较不好做，还是罗马数字题。
是有关选民选举的比例，两块饼饼统计图，一饼是参选人x,y的支持率，另一块是选民们的收入income (?)。
从图中收入少于3000的选民有58% ，所以说选民收入median在收入少于3000的里面。
4. 有一题问下面这个数里能找出的最2的最大次方的factor 是多少?(2^5)(12^10)(18^6)，指数可能不是这个了，不过意思是这个意思。
5.1-10中选出两个数，可重复，问是都是偶数的概率。
(答案：3/4)6.以40miles/hour速度经过一1.5miles的路，若超速则罚款fine=50+(速度-40)*10，现一人用108秒通过此路，问她的'fine=?(key 150 )7.xyz togather finish the task for 9 hour, xy togather need 12 hour,z alone needs ? hour. key 368. 直线l.在X轴截距是3，在Y轴截距是4。
直线m.在X轴截距是4，在X轴截距是3。
比两个直线的sloop. 注意都为负 m19. 从一堆6个什么东东(blesket?不认识的单词)里取4个共会有15种不同的可能，如果从8个里面取4个会比从6个里面取多多少种可能?我选的是55.这题有点怪，不知为什么它还要把15说出来。
难道是我理解有误?10. 一个表3分钟慢一秒钟，问慢3分钟要过多少分种?(答案：540分钟 )。
gre考试模拟试题及答案
gre考试模拟试题及答案GRE考试模拟试题及答案一、词汇部分1. The scientist's innovations in the field of genetics have been pioneering.- A. Traditional- B. Conservative- C. Revolutionary- D. Outdated答案: C2. Despite the dire predictions, the explorer was undaunted and continued his journey.- A. Optimistic- B. Alarming- C. Encouraging- D. Neutral答案: B二、阅读部分Passage 1:In the modern era, the role of technology in education has become increasingly significant. The integration of digitaltools in classrooms has revolutionized the way students learn and interact with educational content.Question 1: What is the main idea of the passage?- A. The history of technology in education.- B. The negative impact of digital tools on students.- C. The positive influence of technology on educational methods.- D. The resistance to the integration of technology in classrooms.答案: CQuestion 2: What is a possible title for this passage?- A. "The Decline of Traditional Education"- B. "The Digital Revolution in Classrooms"- C. "The Challenges of Modern Education"- D. "The Future of Technology-Free Learning"答案: B三、数学部分1. If the sum of three consecutive integers is 69, what is the middle integer?- A. 22- B. 23- C. 24- D. 25解答: 设三个连续整数分别为 \( n-1 \), \( n \), \( n+1 \)。
GRE数学模拟的练习题
GRE数学模拟的练习题
GRE数学模拟的练习题
GRE数学模拟的练习题
1、n个数从小到大排列，求/4，设商为i，余数为j，则可求得1st Quartile为：/4+j/4
2、4个，2个?的排列方式 15
3、 5双袜子，同时去2只，刚好配对的概率。
4、40人说French,60人说Russian,80人说Italy,说两种语言的有50人,说三种语言的有10人. 共有125人,问不说这些语言的`有几人. Key:125-=15
5、等腰直角三角形边长2加2倍根号2，求面积。
6、某种溶液浓度为125gram per liter, 转换成 ounce per gallon,求表达式。
已知 1 ounce=28.xxx gram and 1 gallon=3.875 liter
7、x,y,z 均方差为d, 求x+10,y+10,z+10的均方差
8、1的概率是0.8,2的概率是0,6,问是1或是2或是both的概率,1-0.60.8=0.92.
9、还有一组测量数据中,12.1比mean低1.5个标准差,17.5比mean高3.0个标准方差.问mean是多少.13.9
10、图表题,1992年总和是50,96年是60,每年至少增长1,问最大的年增长:7.0。
gre模拟考试题及答案
gre模拟考试题及答案GRE模拟考试题及答案一、词汇题（每题1分，共10分）1. The scientist's discovery was _______ and had the potential to revolutionize the field.A. innovativeB. traditionalC. redundantD. mundane答案：A2. Despite the _______ weather, the hikers continued their journey with determination.A. inclementB. clementC. sereneD. temperate答案：A3. The politician's speech was filled with _______ promises that appealed to the masses.A. hollowB. genuineC. superficialD. profound答案：A4. The artist's work was _______ in its complexity, requiringa deep understanding to appreciate fully.A. simplisticB. intricateC. rudimentaryD. elementary答案：B5. The _______ of the old building was a testament to its historical significance.A. preservationB. demolitionC. renovationD. destruction答案：A6. The _______ of the new policy was met with mixed reactions from the public.A. implementationB. abandonmentC. rejectionD. endorsement答案：A7. The _______ of the ancient ruins provided valuableinsights into the past civilization.A. excavationB. concealmentC. obliterationD. preservation答案：A8. The _______ of the novel was its ability to captivate the reader's imagination.A. allureB. tediumC. mediocrityD. monotony答案：A9. The _______ of the evidence led to the suspect's acquittal.A. absenceB. presenceC. abundanceD. scarcity答案：A10. The _______ of the argument was flawed, leading to an unsatisfactory conclusion.A. logicB. fallacyC. coherenceD. inconsistency答案：B二、阅读理解题（每题2分，共20分）阅读以下短文，回答后面的问题。
新GRE数学模拟练习题(2)
新GRE数学模拟练习题（2）下面是新GRE数学模拟练习题，参加GRE考试的考生能够好好的练习一下这些GRE模拟题。
GRE考试中，虽说考生在GRE数学部分有着很大的优势，但对于复习也不能轻视，要把这个优势发挥的作用，提升GRE成绩，下面是GRE 数学模拟练习题。
1. A,B,C,D,E,F排在1,2,3,4,5,6六个位置上,问A不在1, B不在2, C不在3的情况下,共有多少种排法?(A) 720(B) 450(C) 180(D) 216(E) 3202. 一直线L过点A(5,0), B(0,2), 坐标原点为O, 点P(X,Y)为三角形OAB中一点, 问：Y(A) 1/4(B) 3/8(C) 1/2(D) 5/8(E) 3/43. In an insurance company, each policy has a paper record and an electric record. For those policies having incorrect paper record, 60% also having incorrect electricrecord; For policies having incorrect electric record, 75% also having incorrect paper record. 3% of all policies have both incorrect paper and incorrect electric records. If we randomly pick out one policy,what’s the probability that the one having both correct paper and correct electric records?(A) 0.80(B) 0.94(C) 0.75(D) 0.88(E) 0.924. If Bob can do a job in 20 days and Jane can do the job in 30 days, they work together to do this job and in this period, Bob stop work for 2.5 days and Jane stop work for x days, and the job be finished for 14 days, what is x?(A) 1.6(B) 3.2(C) 1.5(D) 1.25(E) 1.155. The probability of A is 60% and the probability of Bis 50%, what is the most possible probability that neither A nor B would happen?(A) 0.80(B) 0.40(C) 0.75(D) 0.55(E) 0.686. There are 1200 respondents to a poll, each favoringtheir preference for candidates A,B, and C. 54% favored A, 48% favored B, and 42% favored C, and there is 30% favored both A and B. what’s the largest possible number of respondents favoring C, but not C&B, nor C&A?(A) 25%(B) 30%(C) 28%(D) 38%(E) 40%参考答案：1.解：首先考虑总的可能性为，再考虑A在1，B在2，C在3的可能性分别为，中重复计算了三者交集，分别为AB在1，2，AC在1，3，BC在2，3，所需将三种情况加回，即，但考虑这三种加回的交集又重复计算了ABC在1，2，3的情况，所以应减去P332.解：在平面直角坐标系中，T3.解：设总数为x，设incorrect paper record有y, incorrect electric record有z，则：x·y·60%=3%·x y=5%x·z·75%=3%·x z=4%则，两者至少有一个错误的百分比为5%+4%-3%=6%，所准确答案为94%4.解：1/20(14-2.5)+1/30(14-x)=1，得出x=1.255.解：划出图表来能够一目了然：A， B均不发生的概率为40%，最小概率为0.6.解：A和B的并集为：54%+48%-30%=72%，所C为28%.以上就是小编给大家整理的新GRE数学模拟练习题资料，参加GRE 考试的考生，能够来看看这些GRE模拟题，在此小编预祝广大考生能够在GRE考试中考出好成绩。
GRE_OG_数学精选
1.y=2x2+7x – 3x y本体答案不确定。
我开始做的时候被题目放了烟雾弹，以为要经过什么特别处理，像配方啥的。
但配着配着就感觉不对劲，x与y只有函数关系，没有绝对的大小关系嘛。
汗2.The figure above shows the graph of a function f, defined by f(x)=|2x|+4for all numbers x. For which of the following functions g defined for allnumbers x does the graph of g intersect the graph of f ?A g(x)=x–2B g(x)=x+3C g(x)=2x – 2D g(x)=2x+3E g(x)=3x – 2这个题就是问两个函数图象相交的问题，根据观察，要与这个折线相交的直线的斜率满足的条件是要么是正斜率比2大，要么是负斜率比-2小，因此只能选E了。
3.Each employee of a certain company is in either Department X orDepartment Y, and there are more than twice as many employees inDepartment X as in Department Y. The average (arithmetic mean) salaryis $25,000 for the employees in Department X and is $35,000 for theemployees in Department Y. Which of the following amounts could bethe average salary for all of the employees in the company?Indicate all such amounts.A $26,000B $28,000C $29,000D $30,000E $31,000F $32,000G $34,000本题我们要注意到题目中的more than twice的字眼，我们当做twice算的时候，结果是（25000*2+35000）/3约等于28333，因为有more than，所以选的答案要么是比前面这个数大，要么小，又由于more的是X部门的，那么肯定会将平均工资给拉低了，因此，选比前面那个数小的答案，AB都可以了。
GRE2002年6月数学题库(2)2
GRE2002年6月数学题库（2）20.01inch/min, 问圆柱体底面半径。
Lee:1000/0.01=100000平方inch---------------------------------------------------------------------------61. 出现日期：17两个square,其中共用一个定点，则x+y的角度（360－90－90）。
（烂仔：不完整，后来者补充）-----------------------------------------------------------------------------62. 出现日期：17在一条Y轴截距为+5，X轴截距为+10的直线与两坐标轴围成的三角形内部随意取点，取到x y的点的概率是多少。
（烂仔：2/3）----------------------------------------------------------------------------63. 出现日期：20有圆x+y=49上两点，A(4,a),B(0,b);a为positive，b为negative，问AB的长度和12的大小，选大于（烂仔：答案确认）-----------------------------------------------------------------------------64. 出现日期：20一个▲ABC，面积28，底边上的高AD为7，两个底角为x(B)和x+1(C)度，问CD的长度与4的大小。
（烂仔：小于。
当两底角相同时，CD=4,当B-----------------------------------------------------------------------------65. 出现日期：20直线l: x+y=10,一个集合M={-4/3,-1/3,-1,0,1/2,2}另一条直线y=mx+5,m是M中的一个数，与直线l交于点（a,b）问使得a b的m有几个？（key：4,分别是-1/3,0,1/2,2）（烂仔：答案正确）----------------------------------------------------------------------------66. 出现日期：20圆A内切于一面积为18的正方形，圆B外接于一面积为9的正方形。
GRE(QUANTITATIVE)综合模拟试卷2(题后含答案及解析)
GRE（QUANTITATIVE）综合模拟试卷2(题后含答案及解析) 题型有：1. 2. 3.1．正确答案：A解析：In this question you are given that machine R, working alone at its constant rate, produces x units of a product in 30 minutes. Since it is easy to see that 3 hours is 6 times 30 minutes, you can conclude that Quantity A is 6x. You can compare 6x with Quantity B in two ways. One: In the additional information centered above the quantities, you are given that machine S, working alone at its constant rate, produces x units of the product in 48 minutes, so you can conclude that machine S can produce 6x units of the product in(6)(48)minutes, or 4.8 hours. So in 4 hours, machine S produces less than 6x units, and Quantity B is less than 6x. Two: First, convert 48 minutes to 4/5 hour, then find the number of 48-minute periods there are in 4 hours by computing= 5. Thus, Quantity B is 5x. Either way, Quantity A is greater than Quantity B, and the correct answer is Choice A.2．正确答案：B解析：In this problem you are asked to compare the average with the median of the 120 numbers in list Z. Since list Z consists of the numbers in lists X and Y combined, it is reasonable to try to use the information about lists X and Y to calculate the average and the median of the numbers in list Z. To determine the average of the 120 numbers in list Z, you can use the information given about the individual averages of the numbers in lists X and Y. Because lists X and Y each contain 60 numbers, the average of the numbers in list Z is the average of the individual averages of the numbers in lists X and Y. Thus, the average of the numbers in list Z is, or 4.9. To determine the median of the 120 numbers in list Z, first note that list Z contains an even number of numbers, so the median of the numbers in list Z is the average of the middle two numbers when the numbers are listed in increasing order. If you look at the numbers in the two lists, you will see that the 60 numbers in list X are all less than or equal to 5, and the 60 numbers in list Y are all greater than or equal to 6. Thus, the two middle numbers in list Z are 5 and 6, and the average of these numbers is, or 5.5. Therefore, the median of the numbers in list Z is 5.5, and this is greater than the average of 4.9. The correct answer is Choice B.3．正确答案：D解析：You are given that the circle has a diameter of 10, and from the figure you can assume that points A, B, C, and D lie on the circle in the order shown. However, because figures are not necessarily drawn to scale, you cannot assume anything else about the positions of points A, B, C, and D on the circle. Therefore, to get an idea of how various possible positions of these four points could affect the area of quadrilateral ABCD, it is a good idea to see how the figure can vary but still have points A, B, C, and D in the same order as in the figure above. One way that you might vary the figure is to evenly space the four points along the circle, as shown below. Another way is to draw points A and C opposite each other, with points B and D close to point C, as shown below. From these figures you can draw some basic conclusions about the area of ABCD. If points A and C are opposite each other, with points B and D very close to point C, the area of quadrilateral ABCD is very close to 0. Clearly, the area can be less than 40(Quantity B). If points A, B, C, and D are evenly spaced, the area is not close to 0. How does the area compare with 40? To calculate the area of ABCD, draw the diameters AC and BD in the figure. The two diameters are perpendicular bisectors of each other, so they divide ABCD into four right triangles, as shown. The area of each of the right triangles is(1/2)(5)(5), or 12.5. Thus, the area ofABCD is(4)(12.5), or 50. Since the area of the quadrilateral in the first figure is less than 40 and the area of the quadrilateral in the second figure is greater than 40, the relationship cannot be determined from the information given. The correct answer is Choice D.4．正确答案：B解析：You are given that x2y > 0, which means that the product of the two numbers x2 and y is positive. Recall that the product of two numbers is positive only if both numbers are positive or both numbers are negative. The square of a number is always greater than or equal to 0. In this case, x2 cannot equal 0 because the product x2y is not 0. Thus, x2 is positive and it follows that y is also positive. You are also given that xy2 0, which of the following is equivalent to?A．x2B．x3C．x4D．x5E．x6正确答案：D解析：To simplify, it can be helpful to write(x2)3 as(x2)(x2)(x2)in the given expression; that is,. Because x0, both numerator and denominator can be divided by x2, and the expression simplifies to x(x2)(x2), which, by the rules of exponents, is equal to x5. Another way to simplify the expression using the rules of exponentsdirectly is as follows.The correct answer is Choice D.7．The figure above shows the graph of the function f in the xy-plane. What is the value of f(f(-1))?A．-2B．-1C．0D．1E．2正确答案：D解析：Note that to find f(f(-l)), you must apply the function f twice, first to find the value of f(-1)and then to find the value of f(f(-l)). To find the value of f(-l), find the point on the graph of the function f whose x-coordinate is x =-1. This point has y-coordinate y = 2. Therefore, the value of f(-1)is 2, and f(f(-1))= f(2). Next you need to find the value of f(2). To find the value of f(2), find the point on the graph whose x-coordinate is x = 2. This point has y-coordinate y = 1. Therefore, f(2)= 1, and because f(f(-1))= f(2), you can conclude that f(f(-l))= 1. The correct answer is Choice D.8．If= 1, which of the following statements describes d in terms of n ?A．d is 4 less than n.B．d is 4 more than n.C．d is 3/7 of n.D．d is 2 times n.E．d is 5 times n.正确答案：E解析：To describe d in terms of n, you need to solve the equation[*]= 1 for d. To simplify the equation, you can begin by multiplying both sides by 7n - d and then proceed as follows.[*]d - 3n = 7n —d d=10n-d 2d= 10n d = 5n The correct answer is Choice E.9．By weight, liquid A makes up 8 percent of solution R and 18 percent of solution S. If 3 grams of solution R are mixed with 7 grams of solution S, then liquid A accounts for what percent of the weight of the resulting solution?A．10%B．13%C．15%D．19%E．26%正确答案：C解析：Liquid A makes up 8 percent of the weight of solution R and 18 percent of the weight of solution S. Therefore, 3 grams of solution R contain(0.08)(3), or 0.24 gram of liquid A, and 7 grams of solution S contain(0.18)(7), or 1.26 grams of liquid A. When the two solutions are mixed, the resulting solution weighs 3 + 7, or 10 gramsand contains 0.24 + 1.26, or 1.5 grams of liquid A. This means that liquid A makes up1.5/10, or15/100, or 15 percent of the weight of the resulting solution. The correct answer is Choice C.10．Of the 700 members of a certain organization, 120 are lawyers. Two members of the organization will be selected at random. Which of the following is closest to the probability that neither of the members selected will be a lawyer?A．0.5B．0.6C．0.7D．0.8E．0.9正确答案：C解析：The probability that neither of the members selected will be a lawyer is equal to the fractionthe number of ways 2 members who are not lawyers can be selected the number of ways 2 members can be selectedwhere the order of selection does not matter. Since there are 120 members who are lawyers, there must be 700 - 120, or 580 members who are not lawyers. There are 580 ways of selecting a first member who is not a lawyer and 579 ways of selecting a second member who is not a lawyer. Multiplying these two numbers gives the number of ways to select 2 members who are not lawyers. However, in the(580)(579)ways, each group of 2 members who are not lawyers is counted twice. You can see this by considering 2 members, A and B. The 2 members can be chosen in 2 ways: A first, followed by B, and B first, followed by A. To adjust for double counting, you need to divide(580)(579)by 2. Similarly, the number of ways 2 members can be selected from among the 700 members is(700)(699)divided by 2. Thus, the desired probability isSince the answer choices are all tenths, you need to approximate the value of this fraction to the nearest tenth. There are several ways to do this approximation. One way is to use your calculator to convert the fraction to a decimal and round the decimal to the nearest tenth. Another way is to approximate the value of the fraction as follows. Either way, the answer choice that is closest to the value of the fraction is 0.7.The correct answer is Choice C. Another approach to this problem is to consider the random selections as two separate but successive events. The probability of selecting a first member who is not a lawyer is =580/700, because there are 580 members out of the 700 members who are not lawyers. For the second selection, there are only 699 members left to select from, because one member has already been selected. If the first member selected is not a lawyer, then there are only 579 members left who are not lawyers. So the probability of selecting a second member who is not a lawyer, given the condition that the first member selected was not a lawyer, is 579/699. The probability that both members selected will not be lawyers is the product of the two probabilities, or(580/700)(579/699), which is approximated above as 0.72. The correct answer is Choice C.11．The figure above represents a rectangular garden with a walkway around it.The garden is 18 feet long and 12 feet wide. The walkway is uniformly 3 feet wide, and its edges meet at right angles. What is the area of the walkway?______square feet正确答案：216解析：You can see from the figure that the shaded region is the region between the two rectangles. Looking at the shaded region in this way suggests that the area of the walkway can be calculated as the difference between the area of the larger rectangle and the area of the smaller rectangle. The region represented by the smaller rectangle is the garden. Since the garden is 18 feet long and 12 feet wide, its area is(18)(12), or 216 square feet. The region represented by the larger rectangle is the garden and the walkway combined. The length of the region is the length of the garden plus twice the width of the walkway, or 18 +(2)(3)= 24 feet. The width of the region is the width of the garden plus twice the width of the walkway, or 12 +(2)(3)= 18 feet. Therefore, the area of the region represented by the larger rectangle is(24)(18), or 432 square feet, and the area of the walkway is 432 —216, or 216 square feet. Another way to approach this problem is to think of the walkway as being composed of four rectangles and four squares, as shown in the figure below. Each of the four squares is 3 feet long and 3 feet wide. The two rectangles running along the length of the garden are 18 feet long and 3 feet wide, and the two rectangles running along the width of the garden are 12 feet long and 3 feet wide. Thus, the area of the walkway is 4(3)(3)+ 2(18)(3)+ 2(12)(3)= 36 + 108 + 72 = 216 square feetThe correct answer is 216.12．Line k lies in the xy-plane. The x-intercept of line k is -4, and line k passes through the midpoint of the line segment whose endpoints are(2, 9)and(2,0). What is the slope of line k ?Give your answer as a fraction.正确答案：3/4解析：You can calculate the slope of a line if you know the coordinates of two points on the line. In this question you are given information about two points on line k, namely, the point at which line k crosses the x-axis has x-coordinate -4; the midpoint of the line segment with endpoints at(2, 9)and(2,0)is on line k.The coordinates of the first point are(-4, 0), since the x-coordinate is -4 and the y-coordinate of every point on the x-axis is 0. For the second point, the midpoint of the line segment is halfway between the endpoints(2, 9)and(2, 0).Thus, the midpoint has x-coordinate 2 and y-coordinate 9/2, the number halfway between 9 and 0. Based on the coordinates(-4, 0)and(2,9/2), the slope of line k isThe correct answer is -(or any equivalent fraction).13．If the lengths of two sides of a triangle are 5 and 9, respectively, which of the following could be the length of the third side of the triangle?Indicate all such lengths.A．3B．5C．8D．15正确答案：B，C解析：A good way to approach this problem is to think about how much the length of the third side of a triangle with two fixed side lengths can vary. If you think about it a bit, you will see that the smaller the interior angle between the two sides of the triangle is, the smaller the length of the third side is; and the larger the interior angle between the two sides of the triangle is, the larger the length of the third side is. This suggests drawing two triangles, one in which the angle between the two sides is close to 0 degrees and one in which the angle between the two sides is close to 180 degrees, like the triangles below. In the triangle in which the angle between the sides of length 5 and 9 is small, you can see that the length of the third side is a bit greater than 9 - 5, or 4. If it were equal to 4, the triangle would degenerate into a line segment. In the triangle in which the angle between the sides of length 5 and 9 is large, you can see that the length of the third side is a bit less than 9 + 5, or 14. If it were equal to 14, the triangle would degenerate into a line segment. Therefore, the length of the third side of the triangle must be greater than 4 and less than 14. Furthermore, it is intuitive that any length between these two numbers can be achieved by some triangle. The correct answer consists of Choices B and C.14．On the number line shown above, the tick marks are equally spaced. Which of the following statements about the numbers x, y, and z must be true?Indicate all such statements.A．xyz<0B．x + z =yC．z(y-x)>0正确答案：A，B，C解析：You can see from their positions on the number line that x is less than 0 and both y and z are greater than 0. Because the tick marks are equally spaced, you can also see that x = -y and z = 2y. You need to evaluate each answer choice separately to determine whether it must be true. Choice A says that the product of the three numbers x, y, and z is less than 0. Recall that the product of three numbers is negative under either of the following two conditions. All three numbers are negative. One of the numbers is negative and the other two numbers are positive. Choice A must be true, since x is negative and y and z are positive. Choice B is the equation x + z = y. To see whether the equation must be true, it is a good idea to express two of the variables in terms of the third(that is, to “get rid of” two of the variables). The equations x = —y and z = 2y give x and z in terms of y, so the equation x + z =y can be rewritten, substituting —y for x and 2y for z, as —y + 2y =y. In this form you can quickly conclude that the equation must be true. ChoiceC says that the product of the two numbers z and y - x is greater than 0. Recall that the product of two numbers is positive under either of the following two conditions. Both numbers are positive. Both numbers are negative. Since you already know that z is positive, you can conclude that the product z(y - x)will be positive if y - x is positive. By adding x to both sides of the inequality y - x > 0, you can see that it is equivalent to the inequality y > x, which is clearly true from the number line. Since y —x is positive, the product z(y - x)must be positive. Therefore, the correct answer consists of Choices A, B, and C.。
- 1、下载文档前请自行甄别文档内容的完整性，平台不提供额外的编辑、内容补充、找答案等附加服务。
- 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
- 3、如文档侵犯您的权益，请联系客服反馈,我们会尽快为您处理(人工客服工作时间：9:00-18:30)。
新GRE数学模拟练习题（2）
GRE考试中，中国考生在GRE数学部分有着很大的优势，但对于复习也不能轻视。
以下是环球北美考试院为大家带来的GRE数学模拟练习题，希望对考生有所帮助。
1. 从1,2,3,4,5,6,7,8,9中选出三个数字组成一个三位数,这个三位数的digits中有两个相同,另一个digit与其它两个都不同,问共有多少个这样的三位数?
(A) 72
(B) 144
(C) 180
(D) 216
(E) 54
2. 符合X^2+Y^2<=100的整数解共有多少对?
3. A box contains 100 balls, numbered from 1 to 100. If three balls are selected at random and with replacement from the box,what is the probability that the sum of the three numbers on the balls selected from the box will be odd?
(A) 1/4
(B) 3/8
(C) 1/2
(D) 5/8
(E) 3/4
4. Right triangle PQR is to be constructed in the xy-plane so that the right angle is at P and PR is parrallel to the x-axis. The x-and y-coordinates of P,Q,and Rare to be integers that satisfy the inequalities -4<=x<=5,6<=y<=16,how many different triangles with these properties could be constructed?
(A) 110
(B) 1100
(C) 9900
(D) 10000
(E) 12100
5. (0-9) 要组成三位电话号码,第一位不能是0或1,三位数中相邻两位不能为同一数. (e.g. 227 not acceptable, but 272 acceptable),求可以组成多少个这样的电话号码?
参考答案：
1.解：因为三个数中两个数相同，所以从9个数中取出两个的可能性为，三个数中那个不同的数和可能位置为3个，取出的两个数哪个做不同的数的可能性为两种
2.解：本题的意为一个半径为10的圆中的整数对有多少对。
首先，(0，0)是一种特殊情况，另四个坐标轴上各有10对解，共41对，对1至7之间的数字而言，任一对均满足条件，则对，对于8，满足条件的有1，2，3，4，5，6六个数，则：
6×2×4=48对解
对于9，满足条件的有1，2，3，4四个数，则：
4×2×4=32
所以总数为41+196+48+32=317对解。
3.解：本题因为奇数和偶数个数相同，和也只有两种方式，所以三个数的和为奇数的可能性为1/2。
也可以考虑从这100个数中任取三个数的奇偶，可能性为：
奇奇奇，奇偶偶，奇奇偶和偶偶偶，其中奇奇奇和奇偶偶两种情况的和为奇数，所以也得到可能性为1/2
4.解：本题首先应考虑赵有三条形的构成，对于-4<=X<=5 10个数而言，须取两个点构成直角边，且有顺序问题，因为直角可在两边，则应为;对于6<=6<=16，也应取两个点构成另一直角边，也存在顺序问题
5.解：
第一位只能选2-9，有8个可能性
第二位只能选不是第一位的数，有9个可能性
第三位只能选不是第二位的数，有9个可能性
因此共有8×9×9=648种方法。