2020年1月学考选考浙江省嘉兴市2019学年第一学期高三期末教学质量检测语文试题参考答案

合集下载

浙江省嘉兴市19-20学年高三上学期期末数学试卷 (有解析)

浙江省嘉兴市19-20学年高三上学期期末数学试卷 (有解析)

浙江省嘉兴市19-20学年高三上学期期末数学试卷一、选择题(本大题共10小题,共40.0分)1. 设全集U =R ,A ={x|x 2−2x >0},B ={x|y =√x −1},则A ∪∁U B =( )A. (2,+∞)B. (−∞,0)∪(2,+∞)C. (−∞,1)∪(2,+∞)D. (−∞,0)2. 已知i 是虚数单位,z =4(1+i)4−3i ,则|z|=( )A. 10B. √10C. 5D. √53. 设曲线y =x+3x−1在点(2,5)处的切线与直线ax +y −1=0平行,则a =( )A. −4B. −14 C. 14 D. 44. 函数f(x)=x 2+log 2x ,则满足x 0∈(1,4],且f(x 0)为整数的实数x 0的个数为( )A. 3B. 4C. 17D. 185. 设a ,b ∈R ,则“a >b ”是“a >|b|”的( )A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件6. 已知实数x ,y 满足{x −2y +2≥0x +3y −3≤0x +y −3≤0,则z =x +2y 的最大值为( )A. 2B. 3C. 143 D. 57. 已知正三棱锥V −ABC 的正视图、侧视图和俯视图如图所示,则该正三棱锥侧视图的面积是()A. √39B. 6√3C. 8√3D. 68. 已知数列{a n }满足:a 1=−1,a n+1=a n +1,则a 100=( )A. 100B. 99C. 98D. 979. 设动直线x =m 与函数f(x)=e x ,g(x)=lnx 的图象分别交于点M ,N ,则|MN |最小值所在的区间为( ) A. (12,1) B. (1,2) C. (2,52) D. (52,3) 10. 在△ABC 中AC =6,AC 的垂直平分线交AB 边所在直线于N 点,则AC⃗⃗⃗⃗⃗ ⋅CN ⃗⃗⃗⃗⃗⃗ 的( ) A. −6√3 B. −15√2 C. −9 D. −18二、填空题(本大题共7小题,共36.0分)11. 已知角α的终边上一点的坐标为(sin 3π4,cos 3π4),则角α的最小正值为______ .12. 已知箱中装有10个不同的小球,其中2个红球、3个黑球和5个白球,现从该箱中有放回地依次取出3个小球,则3个小球颜色互不相同的概率是 ;若变量ξ为取出3个球中红球的个数,则ξ的方差D(ξ)=________.13. 已知(3x 2+1x)n的展开式中的各二项式系数的和比各项系数的和小240,则n =________;展开式中的系数最大的项是________.14. 在△ABC 中,点M ,N 满足AM⃗⃗⃗⃗⃗⃗ =MC ⃗⃗⃗⃗⃗⃗ ,BN ⃗⃗⃗⃗⃗⃗ =2NC ⃗⃗⃗⃗⃗⃗ .若MN ⃗⃗⃗⃗⃗⃗⃗ =x AB ⃗⃗⃗⃗⃗ +y AC ⃗⃗⃗⃗⃗ ,则x +y =______. 15. 已知f(x)=a x −1a x +1(a >1),实数x 1,x 2满足f(x 1)+f(x 2)=1,则f(x 1+x 2)的最小值为________. 16. 已知点P(√3,1)和圆O :x 2+y 2=16,过点P 的动直线与圆O 交于M ,N ,则弦MN 的中点Q的轨迹方程为______.17. 如图所示,正方体ABCD −A 1B 1C 1D 1的棱长为2,E ,F 为AA 1,AB 的中点,M 点是正方形ABB 1A 1内的动点,若C 1M//平面CD 1E ,则M 点的轨迹长度为______.三、解答题(本大题共5小题,共74.0分)18. 设函数f(x)=sinxcosx −cos 2(x +π4).(1)求函数f(x)在区间[−π8,π2]上的最值;(2)在△ABC 中,若f(A 2)=0,a =1,b =c ,求△ABC 的面积.19.在如图的几何体中,平面CDEF为正方形,平面ABCD为等腰梯形,AB//CD,AB=2BC,∠ABC=60°,AC⊥FB.(1)求证:AC⊥平面FBC;(2)求直线BF与平面ADE所成角的正弦值.20.已知数列{a n}的前n项和为S n,且2S n=3a n−3.(Ⅰ)求数列{a n}的通项公式;(Ⅱ)设b n=log3a2n−1,数列{1b n⋅b n+1}的前n项和为T n,求证:13≤T n<12.21.已知点A,B的坐标分别是(−1,0),(1,0),直线AM,BM相交于点M,且直线BM的斜率与直线AM的斜率的差是2.(1)求点M的轨迹方程C;(2)若直线l:x−y=0与曲线C交于P,Q两点,求ΔAPQ的面积.22.已知函数f(x)=ln(1+x)−x.1+x(1)求f(x)的极小值;(2)若a、b>0,求证:lna−lnb≥1−b.a-------- 答案与解析 --------1.答案:C解析:解:A ={x|x <0,或x >2},B ={x|x ≥1};∴∁U B ={x|x <1};∴A ∪∁U B ={x|x <1,或x >2}=(−∞,1)∪(2,+∞).故选:C .可解出A ={x|x <0,或x >2},B ={x|x ≥1},然后进行并集、补集的运算即可.考查一元二次不等式的解法,描述法、区间表示集合的概念,以及并集和补集的运算.2.答案:B解析:本题主要考查复数模的求法,属基础题.化简z ,即可得|z |的值.解:由z =4(1+i)4−3i ,则z =44i 2−3i=−1−3i ,∴|z|=√(−1)2+(−3)2=√10.故选B . 3.答案:D解析:解:由y =x+3x−1,得y′=x−1−x−3(x−1)2=−4(x−1)2, ∴y′|x=2=−4,又曲线y =x+3x−1在点(2,5)处的切线与直线ax +y −1=0平行,∴−a =−4,即a =4.故选:D .求出原函数的导函数,得到函数在x =2时的导数,再由两直线平行与斜率的关系求得a 值.本题考查利用导数研究过曲线上某点处的切线方程,考查两直线平行与斜率的关系,是中档题.4.答案:C解析:本题考查了函数定义域与值域,考查学生灵活解决问题的能力,属于基础题.根据函数的是连续函数,在区间(1,4]上是单调增函数,可得函数的值域为(1,18],即可判断出函数值中整数的个数.解:由于函数f(x)=x2+log2x的是连续函数,在区间(1,4]上是单调增函数,故函数的值域为(1,18],即满足x0∈(1,4],且f(x0)为整数的实数x0的个数为17个,故选C.5.答案:B解析:本题主要考查充分条件和必要条件的判断,根据不等式的关系结合充分条件和必要条件的定义是解决本题的关键.根据充分条件和必要条件的定义进行判断即可.解:当a=1,b=−2时,满足a>b,但a>|b|不成立,即充分性不成立,若a>|b|,当b≥0,满足a>b,当b<0时,a>|b|>b,成立,即必要性成立,故“a>b”是“a>|b|”必要不充分条件,故选B.6.答案:C解析:本题考查了简单的线性规划,考查了数形结合的解题思想方法,是中档题.由约束条件作出可行域,化目标函数为直线方程的斜截式,数形结合得到最优解,把最优解的坐标代入目标函数得答案.解:作出不等式组对应的可行域,如图三角形区域:化目标函数z=x+2y为y=−x2+z2,由图可知,当直线y=−x2+z2过A(43,53)时,直线在y轴上的截距最大,z有最大值为43+2×53=143.故选C.7.答案:D解析:解:如图,根据三视图间的关系可得BC=2√3,∴侧视图中VA=√42−(23×√32×2√3)2=2√3,∴三棱锥侧视图面积S△ABC=12×2√3×2√3=6,故选:D.求出侧视图的底边边长和高,代入三角形面积公式,可得答案.本题考查了简单几何体的三视图,空间几何体的直观图,考查了学生的空间想象力及三视图中量的相等关系,属于基础题.8.答案:C解析:本题主要考察数列的递推关系以及等差数列的通项公式,属于基础题.解:∵a n+1=a n+1,∴a n+1−a n=1,所以这是一个公差为1的等差数列,又a1=−1,所以a n=a1+(n−1)·d=−1+(n−1)·1=n−2,所以a100=100−2=98.故选C.9.答案:C解析:由题意得|MN|=e m−lnm,构造函数,确定函数的单调性,即可求出|AB|的最小值,问题得以解决.解:由题意得|MN|=e m−lnm,令ℎ(m)=e m−lnm,∴ℎ′(m)=e m−1m,∵ℎ′(0.5)=e 0.5−2<0,ℎ′(0.6)>0,∴∃m 0∈(0.5,0.6),使得ℎ′(m 0)=0,即e m 0=1m 0,m 0=1e m 0, 且m ∈(0,m 0)时,ℎ(m)单调递减,m ∈(m 0,+∞)时,ℎ(m)单调递增,∴ℎ(m)min =ℎ(m 0)=e m 0−lnm 0=e m 0+m 0∈(2,2.5),故选C .10.答案:D解析:解:如图,设AC 垂直平分线交AC 于M ,则:AC⃗⃗⃗⃗⃗ ⋅CN ⃗⃗⃗⃗⃗⃗ =AC ⃗⃗⃗⃗⃗ ⋅(CM ⃗⃗⃗⃗⃗⃗ +MN ⃗⃗⃗⃗⃗⃗⃗ ) =AC ⃗⃗⃗⃗⃗ ⋅(−12AC ⃗⃗⃗⃗⃗ +MN ⃗⃗⃗⃗⃗⃗⃗ ) =−12AC ⃗⃗⃗⃗⃗ 2+AC ⃗⃗⃗⃗⃗ ⋅MN ⃗⃗⃗⃗⃗⃗⃗ =−18+0=−18.故选:D .先根据条件画出图形,并设AC 的垂直平分线交AC 于M ,从而得出AC ⃗⃗⃗⃗⃗ ⋅CN ⃗⃗⃗⃗⃗⃗ =AC ⃗⃗⃗⃗⃗ ⋅(−12AC ⃗⃗⃗⃗⃗ +MN ⃗⃗⃗⃗⃗⃗⃗ ),这样进行数量积的运算便可求出AC ⃗⃗⃗⃗⃗ ⋅CN⃗⃗⃗⃗⃗⃗ 的值. 考查线段垂直平分线的定义,向量垂直的充要条件,向量加法的几何意义,向量数乘的几何意义,以及向量数量积的运算.11.答案:7π4解析:解:角α的终边上一点的坐标为M(sin3π4,cos 3π4),即M(√22,−√22),故点M 在第四象限,且tanα=−√22√22=−1,则角α的最小正值为7π4,故答案为:7π4.根据角α的终边经过点M ,且点M 在第四象限,tanα═−1,从而求得角α的最小正值.本题主要考查任意角的三角函数的定义,属于基础题. 12.答案:950;1225解析:本题考查考查相互独立事件同时发生的概率,离散型随机变量的期望与方差,考查运算求解能力,是中档题.从该箱中有放回地依次取出3个小球,利用相互独立事件概率乘法公式能求出3个小球颜色互不相同的概率;变量ξ为取出3个球中红球的个数,则ξ~B(3,15),由此能求出ξ的方差D(ξ). 解:箱中装有10个不同的小球,其中2个红球、3个黑球和5个白球,现从该箱中有放回地依次取出3个小球.则3个小球颜色互不相同的概率是:P =A 33×210×310×510=950.变量ξ为取出3个球中红球的个数,则ξ~B(3,15),∴ξ的方差D(ξ)=3×15×(1−15)=1225.故答案为950;1225. 13.答案:4;108x 5;解析:本题考查了二项式定理的应用问题,也考查了运算求解能力,是基础题.由题意列方程求出n 的值,再计算展开式中系数最大的项.解:(3x 2+1x )n 展开式中,各二项式系数的和比各项系数的和小240,即2n −(3+1)n =−240,化简得22n −2n −240=0,解得2n =16或2n =−15(不合题意,舍去);所以n =4;所以(3x 2+1x )4=81x 8+4×27x 5+6×9x 2+4×3⋅1x +1x 4; 其展开式中的系数最大的项是108x 5.故答案为4;108x 5. 14.答案:解析:解:∵MN ⃗⃗⃗⃗⃗⃗⃗ =AN ⃗⃗⃗⃗⃗⃗ −AM ⃗⃗⃗⃗⃗⃗ =AB ⃗⃗⃗⃗⃗ +BN ⃗⃗⃗⃗⃗⃗ −12AC ⃗⃗⃗⃗⃗ =AB ⃗⃗⃗⃗⃗ +23BC ⃗⃗⃗⃗⃗ −12AC ⃗⃗⃗⃗⃗ =AB ⃗⃗⃗⃗⃗ +23(AC ⃗⃗⃗⃗⃗ −AB ⃗⃗⃗⃗⃗ )−12AC ⃗⃗⃗⃗⃗ =13AB ⃗⃗⃗⃗⃗ +16AC ⃗⃗⃗⃗⃗ , 根据平面向量基本定理可得:x =13,y =16,∴x +y =13+16=2+16=12. 故答案为:12.根据向量加减法的运算法则以及平面向量的基本定理可得. 本题考查了平面向量的基本定理,属基础题. 15.答案:45解析:本题考查函数最值的求法,考查换元思想及运算能力,属于中档题. 设t =a x ,由已知结合基本不等式可得t 1t 2≥9,再化简f(x 1+x 2)分离常数后即可得出答案.解:设t =a x ,则t 1−1t 1+1+t 2−1t 2+1=1, 化简得t 1t 2=t 1+t 2+3≥2√t 1t 2+3,故t 1t 2≥9,当且仅当“t 1=t 2”时取等号,∴f(x 1+x 2)=t 1t 2−1t 1t 2+1=1−2t 1t 2+1≥1−15=45. 故答案为45.16.答案:(x −√32)2+(y −12)2=1解析:本题考查轨迹方程的求法,圆的方程的求法,属于中档题. 由题意可得点Q 在以OP 为直径的圆上,进一步求出轨迹方程即可.解:点P(√3,1)和圆O :x 2+y 2=16,过点P 的动直线与圆O 交于M ,N ,Q 为MN 的中点, 则OQ ⊥MN ,点Q 在以OP 为直径的圆上, 则圆心坐标为(√32,12),直径为2,所以点Q 的轨迹方程为:(x −√32)2+(y −12)2=1.故答案为:(x −√32)2+(y −12)2=1.17.答案:√2解析:本题考查了面面平行的判定定理与性质定理、勾股定理,考查了推理能力与计算能力,属于中档题. 如图所示,取A 1B 1的中点H ,B 1B 的中点G ,可得:四边形EGC 1D 1是平行四边形,可得C 1G//D 1E .同理可得:C 1H//CF.可得面面平行,进而得出M 点轨迹.解:如图所示,取A 1B 1的中点H ,B 1B 的中点G ,连接GH ,C 1H ,C 1G ,EG ,HF .可得:四边形EGC 1D 1是平行四边形,∴C 1G//D 1E . 同理可得:C 1H//CF . ∵C 1H ∩C 1G =C 1. ∴平面C 1GH//平面CD 1E ,∵M 点是正方形ABB 1A 1内的动点,若C 1M//平面CD 1E . ∴点M 在线段GH 上.∴M 点的轨迹长度=GH =√12+12=√2. 故答案为:√2.18.答案:(1)由题意知f(x)=sin2x 2−1+cos(2x+π2)2=sin2x 2−1−sin2x2=sin2x −12. 令t =2x ,则t ∈[−π4,π],g(t)=sint −12,所以g(t)的最大值为12,最小值为−√2+12;所以f(x)的最大值为12,最小值为−√2+12;(2)由f(A2)=sinA−12=0,得sinA=12,∵A∈(0,π),∴A=π6或A=5π6,当A=π6时,a2=b2+c2−2bccosA,b=c得bc=2+√3,S=12bcsinA=2+√34;当A=5π6时,a2=b2+c2−2bccosA,b=c得bc=2−√3,S=12bcsinA=2−√34.解析:(1)化简,换元法,求最值即可;(2)求出A,分两种情况讨论,求出面积.本题考查三角形的解法,正弦定理以及余弦定理的应用,考查计算能力19.答案:(1)证明1:因为AB=2BC,∠ABC=60°,在△ABC中,由余弦定理得:AC2=(2BC)2+BC2−2×2BC⋅BC⋅cos60°,即AC=√3BC.所以AC2+BC2=AB2.所以AC⊥BC.因为AC⊥FB,BF∩BC=B,BF、BC⊂平面FBC,所以AC⊥平面FBC.证明2:因为∠ABC=60°,设∠BAC=α(0°<α<120°),则∠ACB=120°−α.在△ABC中,由正弦定理,得BCsinα=ABsin(120∘−α).因为AB=2BC,所以sin(120°−α)=2sinα.整理得tanα=√33,所以α=30°.所以AC⊥BC.因为AC⊥FB,BF∩BC=B,BF、BC⊂平面FBC,所以AC⊥平面FBC.(2)解法1:由(1)知,AC⊥平面FBC,FC⊂平面FBC,所以AC⊥FC.因为平面CDEF为正方形,所以CD⊥FC.因为AC∩CD=C,所以FC⊥平面ABCD.取AB的中点M,连结MD,ME,因为ABCD是等腰梯形,且AB=2BC,∠DAM=60°,所以MD =MA =AD.所以△MAD 是等边三角形,且ME//BF . 取AD 的中点N ,连结MN ,NE ,则MN ⊥AD . 因为MN ⊂平面ABCD ,ED//FC ,所以ED ⊥MN . 因为AD ∩ED =D ,所以MN ⊥平面ADE. 所以∠MEN 为直线BF 与平面ADE 所成角. 因为NE ⊂平面ADE ,所以MN ⊥NE .因为MN =√32AD ,ME =√MD 2+DE 2=√2AD ,在Rt △MNE 中,sin∠MEN =MN ME=√64. 所以直线BF 与平面ADE 所成角的正弦值为√64.解法2:由(1)知,AC ⊥平面FBC ,FC ⊂平面FBC , 所以AC ⊥FC .因为平面CDEF 为正方形,所以CD ⊥FC . 因为AC ∩CD =C ,所以FC ⊥平面ABCD . 所以CA ,CB ,CF 两两互相垂直, 建立如图的空间直角坐标系C −xyz .因为ABCD 是等腰梯形,且AB =2BC ,∠ABC =60° 所以CB =CD =CF .不妨设BC =1,则B(0,1,0),F(0,0,1),A(√3,0,0),D(√32,−12,0),E(√32,−12,1),所以BF ⃗⃗⃗⃗⃗ =(0,−1,1),DA ⃗⃗⃗⃗⃗=(√32,12,0), DE⃗⃗⃗⃗⃗⃗ =(0,0,1). 设平面ADE 的法向量为n⃗ =(x,y ,z), 则有{n ⃗ ⋅DA ⃗⃗⃗⃗⃗ =0n⃗ ⋅DE ⃗⃗⃗⃗⃗⃗ =0.即{√32x +y 2=0z =0. 取x =1,得n ⃗ =(1,−√3,0)是平面ADE 的一个法向量. 设直线BF 与平面ADE 所成的角为θ, 则sinθ=|cos〈BF ⃗⃗⃗⃗⃗ ,n ⃗ >|=|BF ⃗⃗⃗⃗⃗ ⋅n ⃗⃗|BF ⃗⃗⃗⃗⃗ |⋅|n ⃗⃗ ||=|√3,0)√2⋅2|=√64.所以直线BF 与平面ADE 所成角的正弦值为√64.解析:(1)证明1:由余弦定理得AC =√3BC ,所以AC ⊥BC ,由此能够证明AC ⊥平面FBC . 证明2:设∠BAC =α,∠ACB =120°−α.由正弦定理能推出AC ⊥BC ,由此能证明AC ⊥平面FBC . (2)解法1:由(1)结合已知条件推导出AC ⊥FC.由平面CDEF 为正方形,得到CD ⊥FC ,由此入手能求出直线BF 与平面ADE 所成角的正弦值.解法2:由题设条件推导出CA ,CB ,CF 两两互相垂直,建立空间直角坐标系利用向量法能求出直线BF 与平面ADE 所成角的正弦值.本题考查直线与平面垂直的证明,考查直线与平面所成角的正弦值,解题时要注意向量法的合理运用,注意空间思维能力的培养.20.答案:解:(Ⅰ)2S n =3a n −3,可得2a 1=2S 1=3a 1−3,解得a 1=3,n ≥2时,2S n−1=3a n−1−3,相减可得2a n =2S n −2S n−1=3a n −3−3a n−1+3, 化为a n =3a n−1,则ana n−1=3,故数列{a n }为公比为3的等比数列,经验证,n =1也符合, 可得a n =3⋅3n−1=3n ; 故a n =3n(Ⅱ)证明:b n =log 3a 2n−1=log 332n−1=2n −1, 可得1bn b n+1=1(2n−1)(2n+1)=12(12n−1−12n+1),即前n 项和为T n =12(1−13+13−15+⋯+12n−1−12n+1) =12−12(2n+1),由{T n }为递增数列,可得T n ≥T 1=13,且T n <12, 可得13≤T n <12.解析:本题考查数列的通项公式的求法,注意运用数列的递推式的运用,考查数列的裂项相消求和和数列的单调性,考查运算能力,属于中档题.(Ⅰ)求得首项,n ≥2时,a n =S n −S n−1,结合等比数列的定义和通项公式,即可得到所求; (Ⅱ)求得b n =log 332n−1=2n −1,可得1b n b n+1=1(2n−1)(2n+1)=12(12n−1−12n+1),由数列的裂项相消求和和数列的单调性,即可得证.21.答案:解:(1)设M(x,y),则k AM =yx+1,k BM =yx−1, 所以yx−1−y x+1=2,所以轨迹方程为y =x 2−1(y ≠0或x ≠±1);(2)方法一:设P(x 1,y 1),Q(x 2,y 2)联立方程{y =x 2−1x −y =0,得x 2−x −1=0,所以{x 1+x 2=1x 1x 2=−1,所以|PQ|=√1+12√(x 1+x 2)2−4x 1x 2=√10,A 到直线的距离为d =√12+12=√2, 所以S △APQ =12⋅d ⋅|PQ|=√52.方法二:设P(x 1,y 1),Q(x 2,y 2)联立方程{y =x 2−1x −y =0,得x 2−x −1=0,所以{x 1+x 2=1x 1x 2=−1,S △APQ =12⋅|AO|⋅|y 1−y 2|=12⋅|AO|⋅|x 1−x 2|=12√(x 1+x 2)2−4x 1x 2,所以S △APQ =√52.解析:定理,结合S △APQ =12⋅|AO|⋅|y 1−y 2|转化求解即可.本题考查直线与抛物线的位置关系的综合应用,轨迹方程的求法,考查转化思想以及计算能力,是中档题.(1)设M(x,y),求出直线的斜率,然后求解轨迹方程即可.(2)方法一:设P(x 1,y 1),Q(x 2,y 2)联立方程{y =x 2−1x −y =0,得x 2−x −1=0,利用韦达定理以及弦长公式结合三角形的面积求解即可.方法二:设P(x 1,y 1),Q(x 2,y 2)联立方程{y =x 2−1x −y =0,得x 2−x −1=0,利用韦达22.答案:解:(1)f′(x)=11+x −1(1+x)2=x(1+x)2,x >−1当−1<x <0时,f′(x)<0,f(x)在(−1,0)上单调递减, 当x =0时,f′(x)=0,当x>1时,f′(x)>0,f(x)在(1,+∞)上单调递增,所以x=1是f(x)的极小值点也是最小值点,所以f(x)的极小值=f(0)=0;(2)由(1),f(x)≥f(0)=0,从而ln(1+x)≥x1+x在定义域(−1,+∞)上恒成立.要证lna−lnb≥1−ba 成立.即证ln ab≥1−ba成立.令1+x=ab ,则x1+x=1−1x+1=1−ba,于是ln ab≥1−ba,不等式成立.解析:(1)先求出函数的导数,得到单调区间,求出极值点,从而求出函数的极小值;(2)由(1)f(x)≥f(0)=0,从而ln(1+x)≥x1+x 在定义域(−1,+∞)上恒成立.经分析,令1+x=ab,则上述不等式即为ln ab ≥1−ba成立.本题考查函数极值求解,函数性质的得出与应用,考查构造,分析解决问题能力,由特殊到一般的数学思想.。

浙江省嘉兴市2019—2020学年第一学期期末检测高三语文试卷与答案

浙江省嘉兴市2019—2020学年第一学期期末检测高三语文试卷与答案

嘉兴市2019—2020学年第一学期期末检测高三语文试卷(2020.1)一、语言文字运用(共20分)1.下列各句中,没有错别字且加点字的注音全都正确的一项是(3分)A.倏(shū)然觉得,冬天像一个穿着灰色长袍的青衿,面容清癯却胸襟坦荡,神情严肃而心地诚笃,来时硬朗,让人觉得踏实与豁(huò)亮,去时又淡然,让人有了怀念和希冀。

B.阳光从篱笆边的丝瓜、扁豆藤蔓(wàn)上掠过,落在巷子的苔藓上,那扇被蛀得千疮(chuāng)百孔的木门呈现着幸福的嫩黄色,门里桌边脸色腊黄的孩子,也似乎带着某种幸福。

C.面对打上门来的贸易战,我们坚持“不愿打、不怕打”的原则立场,戮(lù)力同心众志成诚,沉着应对,坚决抵御美国霸凌主义行径(jìn)的冲击,捍卫民族的核心利益。

D.成龙动作电影探索出与好莱坞(wū)“硬动作”电影截然不同的道路,通过柔性表达塑造了一系列有血有肉的贫民英雄形象,向世界弘扬惩恶扬善、扶危济(jì)困的情怀。

阅读下面的文字,完成2-3题。

[甲]古人云:诗言志,歌咏言。

诗歌是中国文化在语言文字使用中的浓缩精华,寥寥数语,却做到了写实性与抒情性、艺术性与思想性的统一。

[乙]中国曾被称为“诗的国度”,所谓“不学诗,无以言。

”祭拜祖先需要唱诗,登高望远需要题诗,好友分别需要赠诗,入仕为官需要考诗……在中国历史上,诗歌与社会生活息息相关....是中国文化的有力表达。

[丙]中华民族五千年来的历史经验、哲学思想文化传统是中华儿女文化自信的底气,深刻影响着中国人的社会实践与人生哲学价值观。

中华优秀思想长期浸润..中国文学,久而久之转化为诗意,以诗歌等形式影响和塑造着民众的人生观、世界观与价值观。

凭借着优美的语言与凝练的旋律,诗歌将中华文明的精神内涵外化为口耳相传的继承与发展,又内化为潜移默化....的心灵认知。

多少名诗佳句依旧在中国人嘴边吟诵,因而..在他们心间缓缓流淌。

2020年1月学考选考浙江省嘉兴市2019学年第一学期高三期末教学质量检测数学试题参考答案

2020年1月学考选考浙江省嘉兴市2019学年第一学期高三期末教学质量检测数学试题参考答案

sin 2x 3(1 cos 2x) sin(2x ) 3
2
2
32
当 x [0, ] 时, 2x [ , 2 ] .
2
3 33
当 2x [ , 2 ] ,即 x [5 , ] 时, f ( x) 是增函数.
3 23
12 2
高三数学 参考答案 第 1 页 共 6 页
考 选 考 学 省 江 浙
AB
sin
A
1
sin
2 3
21 .
BC
7
14
19.(本题满分 15 分)如图,在四棱柱 ABCD ABCD 中,底面 ABCD 为等腰梯形,
DA AB BC 1 , DC 2 . 平面 DCC D 平面 ABCD ,四边形 DCCD 为菱形,
DDC 60 . (Ⅰ)求证: DA BC ; (Ⅱ)求 DA 与平面 BCC B 所成角的正弦值.
3 , 1 ,0) (0,1,
3) (
33 ,,
3) ,
22
22
BC ( 3 , 1 ,0) , 22
∴ DA BC 3 3 0 0 ,∴ DA BC . 44
(Ⅱ) CC DD (0, 1, 3 ) ,设平面 BCC B 的法向量为 m ( x, y, z) DAB
BD BA
1 , tan OAB
OB BA
1 2

∴ tan DAO
1 1 2
1 ,∴ sin DAO
10 .
1 1 1 3
10
2
∴ DA 与平面 BCC B 所成角的正弦值为 10 . 10
方法二、
z D
A
C B
D
O
C
y

浙江省嘉兴市2019-2020学年高一上学期期末语文试题(解析版)

浙江省嘉兴市2019-2020学年高一上学期期末语文试题(解析版)

嘉兴市2019~2020学年第一学期期末检测高一语文试题卷(2020.1)试卷满分150分考试时间150分钟一、语言基础与运用(共20分)1.下列各句中,没有错别字且加点字的注音全都正确的一项是A. 网络专题片《一片叶子的扶贫故事》从小切口入手,聚焦大主题,充分总结了在全面打赢脱贫攻艰战道路上的典型.(xíng)经验。

B. 区块链技术已开始用于民生服务领域,区块链分布式账本不可篡.(zuàn)改的特性,解决了长三角地区地铁的跨区域交通结算问题。

C. 在货运行业竞相降价的畸.(jī)形竞争中,要有效解决超限超载问题,让货车司机在运输市场博弈中摆脱弱势地位显得尤为重要。

D. 中秋,父母们忙着在密不透风的玉米地里掰.(bān)玉米,而不知疲倦的孩子们在月光下忙着追赶萤火虫、摸知了、捉谜藏……【答案】C【解析】【详解】本题考查对字音、字形的识记能力。

字音题考查对形近音同(或音异)、形异音同(或音异)、多音多义的汉字读音的辨识。

注意“多音读次音,形声莫套读,方言要纠错”的原则。

字形题通过分析形声字的形旁来推导这个字的含意,再放到这个词语中去判定是否相符。

对于独体字或形声字中的形旁已失去表意功能的形声字,可以通过分析词语的语法结构来确定它是不是别字,还可以通过对整个词语的理解,来寻找不合语境的别字。

本题中,A项,脱贫攻艰——脱贫攻坚。

B项,篡(zuàn)改——cuàn。

D项,掰(bān)玉米——bāi;捉谜藏——捉迷藏。

故选C。

【点睛】据义别形,形随义定,是汉字的基本特点,要辨析字形正误,应当从字的意义考虑。

在这里,我想提供两个据义别形的技巧:①字形结构分析法。

汉字当中,有若干是形声字、会意字、指事字等,它们的表意性很强。

剖析字形特点,或者说是剖析汉字的造字方法,推知汉字的意义,从而为我们辨析别字提供了有利的条件。

②词语结构分析法。

现代汉语中有不少联合式的词语,对这类词,可根据前后位置的关系,推知相对应的字词的词义,从而帮助我们辨析字形。

2019-2020学年嘉兴市第一中学高三英语上学期期末考试试卷及答案

2019-2020学年嘉兴市第一中学高三英语上学期期末考试试卷及答案

2019-2020学年嘉兴市第一中学高三英语上学期期末考试试卷及答案第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AWhen the sun shines brightly, it provides a great chance to get outdoor things done. Like making hay! At least, that is what farmers from the past would say. ―Make hay while the sun shines.This idiom is very old, dating back to Medieval times. Rain would often ruin the process of making hay. So, farmers had no choice but to make hay when the sun was shining.Today, we all use this expression, not just farmers. When conditions are perfect to get something done, we can say, ―It’s a good idea to make hay while the sun shines.In other words, you are taking advantage of a good situation or of good conditions. You are making the most of your opportunities. These all mean ―making hay while the sun shines.And sometimes we use this expression to mean we beat someone to the punch, or we got ahead of someone else. And other times you make hay while the sun shines to make good use of the chance to do something while it lasts. You are being opportunistic – taking advantage of a good opportunity. For example, my friend Ozzy was sick for a week and could not go to work. So, his co-worker Sarah -- who doesn’t like him -- took advantage of his illness and stole his project! Talk about making hay while the sun shines.Sometimes when you make hay while the sun shines you are staying ahead of a problem – like in this example:Hey, do you want to go hiking with me and my friends this weekend? The weather is going to be beautiful! I wish I could. But I have to finish my taxes. It’s the last weekend before they’re due.Oh, that’s too bad.Wait. What about your taxes?My taxes are done. I was off from work a couple of weeks ago and made hay while the sun shined. I got all of it done!I wish I would have taken advantage of my time off last week___1___All I did was lay around thehouse.And that’s all the time we have for these Words and Their Stories. But join us again next week. You can listen while you’re making dinner or riding to work. Yeah, make hay while the sun shines.1.Which of the following best matches ―make hay whilethe sun shines in paragraph 2?A.Sow nothing, reap nothing.B.Sharp tools make good work.C.Strike while the iron is hot.D.One swallow doesn’t make a summer.2.According to the underlined sentence, what feeling does the speaker express?A.AdmirableB.RegretfulC.AnnoyedD.Indifferent3.Where is the passage probably taken from?A.A radio programB.A magazineC.A brochureD.A novelBEvery racehorse has different abilities.Like humans,some are short- distance runners,while others are marathoners.Figuring out which is which and how to pace them can be the difference between failure in the finish and taking the award home.Jockeys(赛马骑师)and trainers have traditionally relied on centuries of experience and data from previous races to plan their races.Amandine Aftalion,a mathematician in Paris,thought she could add to that.Since 2013,she has been analyzing the performances of world champion runners like Usain Bolt.She has found that short-distance runners tend to win when they start strong and gradually slow down toward the finish line.Butin medium-distance races,runners perform better when they start strong,settle down,and finish with a burst of speed.Her model shows how those winning strategies maximize the energy output of muscles reliant on two different pathways:powerful aerobic(有氧的)ones that require oxygen,which can be in limited supply during a race,and anaerobic ones,which don't need oxygen but build up waste products that lead to tiredness.Aftalion wondered which strategy would be best for horses.So she and Quentin Mercier,anothermathematician,took advantage of a new GPS tracking tool inserted in French racing saddles(马鞍).The two studied patterns in many races at the Chantilly racetracks north of Paris and developed a model that accounted for winning strategies for three different races:a short one(1,300 meters),a medium one (1,900 meters),and a slightly longer one (2,100 meters),all with different starting points on the same track.The model takes into account not just different race distances,but also the size or friction fromthe track surface.The results might surprise jockeys who hold horses back early for bursts of energy in the last finish.Instead,a strong start leads to a better finish,the team found.“That doesn't mean those jockeys are wrong,though.If the start is too strong,it can bedevastatingas well,leaving the horse tired by the end,” Aftalion says.4. What should a runner do to get an award according to the text?A. Make a good start.B. Plan for the race early.C. Run slowly on the starting line.D. Try runningquickly all the time.5. What formed the basis for Aftalion's studying horse race?A The experience and data from previous horse races.B. The benefit of knowing horses' different abilities.C. The success in studying runners' winning strategies.D. The performance of horses on different race distances.6. What does the underlined word“devastating”in the last paragraph mean?A. Boring.B. Damaging.C. Astonishing.D. Puzling.7. What can we infer from the text?A. Runners have the same energy output of muscles.B. Aftalion's findings may help horses to win the race.C. What Jockeys and trainers do makes no sense to horses.D. World champion runners made a contribution to the study.CThe race skywards began inAmerica. In the late1800s, industrialization had driven urban populations and land prices up, making tall buildings increasingly cost-effective, according to Carol Willis, director of theSkyscraperMuseuminNew York, “The very first tall buildings were office buildings that concentrated a work force, piled one on top of the other in order to make business very efficient, ”she says.Like all major changes in architecture, the trend wasunderpinnedby engineering. The development of steel framework, which could be used instead of load-bearing stones, made it easier and cheaper to build tall. The coming of the elevator, meanwhile, made living on higher floors far more convenient.Though similar in shape, today's skyscrapers (摩天大楼) look little like those built in the first half of the 20thcentury. This is mostly thanks to architecture's next major technological shift:the curtain wall.Postwar developments in manufacturing meant that huge panes of glass could be produced quickly and uniformly, and glass windows soon became the front of choice for high-rises. As well as allowing for greater floor space and more natural light, glass exteriors (外部) help. buildings resist greater windloads.There are now 191 completed skyscrapers that are at least 300 meters tall. But that doesn't mean our cities will grow taller indefinitely. While each additional story adds sellable floor space, construction costs also rise. All buildings reach a point where adding an extra floor will cost more money than it brings.“Every city wants to have this landmark that gives that sense of distinct culture, ”but it also needs places for people to live and work in urban settings“without the city sprawling (无序扩张), ”explains Hong Kong architect Simon Chan.The next big challenge facing architects goes beyond height:At a time when buildings and their construction account for more than a third of the world's energy consumption and contribute about 40% of greenhouse gas emissions(排放), there are new costs to consider.Whether it's employing more energy-efficient materials, encouraging natural air or using buildings themselves to generate solar or wind energy, reducing carbon emissions is the new frontier for many skyscraper architects.8. What does the underlined word“underpinned” in paragraph 2 probably mean?A. Created.B. Prepared.C. Suggested.D. Supported.9. What made living on higher floors much more convenient?A. The development of steel framework.B. Load-bearing stones.C. The use of the elevator.D. The curtain wall.10. What can we know from paragraph 5?A. Our cities will grow taller definitely.B. All skyscrapers are at least 300 meters tall.C. Construction cost rises as the stories increase.D. The profit for builders will be greater as the building becomes higher.11. What's the next big challenge facing architects?A. How to build the greenest building.B. How to build the strongest building.C. How to build the tallest building in the world.D. How to build the most comfortable building.DJake Oldershaw and his daughter Mollie from Birmingham, Britain have asthma (哮喘). Mollie, 11, has required hospital treatment several times while Jake Says he always finds breathing more difficult when there is heavy traffic. Air quality has an enormous impact on their lives and both noticed a marked improvement during the spring lockdown because of the epidemic (疫情). Jake said, “During lockdown there was a noticeabledifference in air quality. I didn't suffer any asthmatic attacks during that period. These days you can feel the effects.”However, under current COVID-19 restrictions in the UK this winter, many people probably will have to work from home. The Energy and Climate Intelligence Unit (ECIU) says while emissions (排放) have dropped this year because we've been travelling less and doing less, the expected use ofgas boilers to provide heating and hot water could rise by more than half.Heating accounts for nearly 37% of the UK's total carbon emissions. Modelling by the ECIU suggests a 56% increase in boiler usage this winter resulting in a 12% increase in emissions of carbon. The ECIU says that's enough to offset the last two years' worth of progress on reducing traffic emissions.Jess Ralston, author of the analysis for the ECIU, said, “Working from home and having increased gas use in the home could be really critical for air pollution and also climate change. The way we heat our homes needs to change if we are to get to net zero by 2050.”Jess Ralston said, “The increase in pollution from gas boilers expected this winter provides a graphic illustration (图解) of their forgotten role in air pollution. And it is a role set to continue without practical policies to decarbonize home heating. ”The government is set to publish its Heat and Buildings Decarbonisation Strategy in a few weeks which is expected to give details on plans to try to switch British homes to cleaner sources of heat.12. How did the spring lockdown in the UK affect Jake?A. He was cured of his asthma.B. He had to go to hospital for retreatment.C. He suffered a noticeable difficulty in study.D. He didn't suffer any asthmatic attacks during that period.13. What is concerning the Energy and Climate Intelligence Unit?A. The epidemic will become worse.B. Air pollution will get worse this winter.C. People may have to work from home longer.D. There is less energy for gas boilers in winter.14. What would Jess Ralston agree with?A. People prefer to work from home in winter.B. The government failed to protect the environment.C. People tend to ignore the harmful effect of home heating.D. The climate has suffered a lot from the epidemic this year.15. How to improve air quality during winter according to Jess Ralston?A. A warmer winter season.B. Less and less gas boilers.C. Practical plans from the government.D. Improved awareness of cutting down pollution.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年嘉兴市第一中学高三语文期末考试试卷及参考答案

2019-2020学年嘉兴市第一中学高三语文期末考试试卷及参考答案

2019-2020学年嘉兴市第一中学高三语文期末考试试卷及参考答案一、现代文阅读(36分)(一)现代文阅读I(9分)阅读下面的文字,完成下面小题。

“乡土美术”是当代中国主题性美术创作领域一个极其重要的思潮与现象。

五四新文化运动以来,尤其是“左翼”美术运动及革命美术诞生以来,乡土美术一直以视觉图像的方式紧随现代中国的社会变革与实践。

党的十八大以来,随着“五位一体”总体布局和“四个全面”战略布局的提出,中国当代主题性美术创作乡土叙事也随之出现一种“生态转向”现象:乡村、城市、工业、环境等题材的图像叙事,呈现出更为强烈的生态观念意识。

对环境问题的批判,是“生态转向”的主线。

随着生态环境出现不同程度的污染与恶化,中国艺术家敏锐地察觉到这种现象,并将其表现在艺术创作中。

对动物权利的确立与保护,也是“生态转向”的重要内容。

大量艺术作品都反映出中国当代美术创作对人与动物关系的反思与重构。

占山的“众生”系列,延续着中国传统文化“众生平等”“万物一体”的伦理学立场。

雕塑家曹晖“揭开你”系列作品,以牛、猪、羊等动物为对象,通过超级写实性的雕塑语言,精细而逼真地揭开动物作为“他者”的表皮。

对消费欲望的克制,是“生态转向”的精神指向。

抑制过度消费的欲望,倡导人与自然的和谐共生,成为中国当代生态美术的重要艺术倾向。

魏怀亮以中国传统绘画为切入点,将高速公路、交通标识等现代生活元素符号用到中国传统水墨图像中,重点表现现代城市与交通设施占用自然环境的飞速扩张所引发的社会现象,从而引导人们思考现代社会发展对自然生态带来的创伤。

如果说占山、王家增、余明等将忧虑的目光转向了大地干旱、工业废墟、生产与生活垃圾,那么,尚扬的“大风景”系列和“董其昌计划”系列则进一步从人类中心主义和西方中心主义的文化立场中退却出来,试图遏制现代人过度生产与消费的疯狂欲望。

对人与自然和谐关系的重建,是“生态转向”的主旨所在。

德国当代思想家尤尔根·哈贝马斯曾提出,“我们不把自然当作开采对象,而试图把它看作(生存)伙伴”。

浙江省嘉兴市2020届高三第一学期期末检测数学试题(含答案)

浙江省嘉兴市2020届高三第一学期期末检测数学试题(含答案)

DDC 60 . (Ⅰ)求证: DA BC ; (Ⅱ)求 DA 与平面 BCC B 所成角的正弦值.
D A
C B
19.方法一、
D
H
C
(Ⅰ)连接 DB 、BA ,取 DC 中点 H ,连接 DH 、HB .
A
B
∵等腰梯形 ABCD 中, DA AB BC 1 , DC 2 .
3 , 1 ,0) (0,1,
3) (
33 ,,
3) ,
22
22
BC ( 3 , 1 ,0) , 22
∴ DA BC 3 3 0 0 ,∴ DA BC . 44
(Ⅱ) CC DD (0, 1, 3 ) ,设平面 BCC B 的法向量为 m ( x, y, z) ,则
嘉兴市 2019—2020 学年第一学期期末检测(2020.1)
高三数学 参考答案
一、选择题(本大题共 10 小题,每小题 4 分,共 40 分)
1.A;
2.A;
3.B;
4.C;
5.C;
6.B;
7.D;
8.C;
9.D;
10.D.
10.提示:连接 AD .
PA
BC

( PD

DA)
1 1 2
1 ,∴ sin DAO
10 .
1 1 1 3
10
2
∴ DA 与平面 BCC B 所成角的正弦值为 10 . 10
方法二、
z D
A
C B
D
O
C
y
A
B
x
(Ⅰ)取 DC 中点 O ,连接 OD .
∵四边形 DCCD 为菱形, DDC 60 ,∴ OD CD .

2019-2020学年嘉兴市第一中学高三英语期末考试试卷及参考答案

2019-2020学年嘉兴市第一中学高三英语期末考试试卷及参考答案

2019-2020学年嘉兴市第一中学高三英语期末考试试卷及参考答案第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项ADesign a science holiday to win a science holidayIs there a scientific holiday,tour,vacation or experience in your list that you dream of making a reality? We might just be able to help with that! We are the crowd sourcing thoughts and suggestions onnew tours,and the winner will receive two free places on their tour when it's launched.Starting entries 1st May 2020Deadline 31st August 2020ENTER NOW---Write a brief description of your ideal science holiday,tour,vacation or experience.---No matter how big or small,we are looking for brilliant, unique thoughts.It can be a complex multi-location overseas holiday tour,a weekend away deep-diving,or a simple walking tour(and everything in between).---Our current tours are mainly individual-focused but we would love to hear ideas for families and schools.---Creations that have environmentally friendly themes and a low carbon impact are also welcome.---Your entry can be as simple as a great title but writing more specifies will improve the possibility of walking off with the prize.---The competition doesn't close by September,2020,so plenty of time to brainstorm your entry.---We will launch the best idea in late 2020 or at the beginning of 2021. The winner will receive the award once the result is published.If you want to submit more than 3,999 words,include photos/maps with your entry, or submit multiple entries then send it to tours @ . The competition guidelines and other related information are available at .1. When will the winner probably be announced?A. In August,2020.B. In September,2020.C. In January,2021.D. In May,2021.2. What kind of entries might be more likely to win?A. Those producing a low carbon impact.B. Those with a long and unique title.C. Those providing detailed information.D. Those for individual-focused tours.3. What is the purpose of this text?A. To give guidance on a competition.B. To advertise a science holiday.C. To inspire creativity in teenagers.D. To collect the ideas for tours.BPeggy Whitson's job demands a daily two­hour workout in a gym where weight has no meaning and the view changes at 17,000 miles an hour.Whitson makes it look easy. At 57, she is the oldest woman to fly in space, breaking the record last November, 2016, when she began her third long­term stay at the International Space Station. After returning home in September, 2017, the NASA astronaut feltmatter­-of­-factabout the age milestone.“It wasn't a record I was seeking for,” Whitson said. “I was 42 and 48 for my first two space flights. I feel lucky that I was able to get to do another one in my 50s. I don't think people should let age discourage them, even on those jobs that require some amount of physical fitness. The oldest man is John Glenn (at 77), and we've had male astronauts in their 60s before, so it's just a matter of time before women start flying in space at this age”.On the earth, she stays fit by weightlifting, biking, playing basketball and water skiing. She shared what it's like to live in microgravity: “It's like you're in a swimming pool, but you don't have to worry about breathing. If I push off from one side, I'm going to float to the other side. Every direction feels exactly the same, which is really hard for your brain to grasp, but it's amazing how fast you adapt.It's a big shock for the body to come back to Earth—everything is so heavy. We spend a lot of time getting used to being back in gravity again. Back pain was really the most dramatic for me this time. For me, coming home is harder than going up into space.”4. How long did Peggy Whitson spend for her third stay in the International Space Station?A. About 300 days.B. About 708 days.C. About 107 days.D. About57 days.5. What does the underlined word probably mean in the passage?A. Amazing.B. Not surprising.C. Enthusiastic.D. Unbelievable.6. According to the passage, which of the following is true?A. Peggy Whitson likes swimming most.B. Peggy Whitson is the oldest person to fly in space.C. Peggy Whitson had been in space in 2002 and 2008.D. There had been female astronauts over 60s flying in space before.7. Which of the following will Peggy Whitson probably say?A. You can still be successful and do physical things when old.B. I spent quite a lot of time getting used to the life in space.C. The moment we reached the earth, we felt so relaxed.D. I feel lucky that I am physically well after the whole journey.CWhat will people die of 100 years from now? If you think that is a simple question,you have not been paying attention to the revolution that is taking place in bio-­technology(生物技术). With the help of new medicine,the human body will last a very long time. Death will come mainly from accidents,murder and war. Today’s leading killers,such as heart disease,cancer,and aging itself,will become distant memories.In discussion of technological changes,the Internet gets most of the attention these days. But the change in medicine can be the real technological event of our times. How long can humans live? Human brains were known to decide the final death. Cells(细胞)are the basic units of all living things,and until recently,scientists were sure that the life of cells could not go much beyond 120 years because the basic materials of cells,such as those of brain cells,would not last forever. But the upper limits will be broken by new medicine. Sometime between 2050 and 2100,medicine will have advanced to the point at which every 10 years or so,people will beable to take medicine to repair their organs(器官). The medicine,made up of the basic building materials of life,will build new brain cells,heart cells,and so on-in much the same way our bodies make new skin cells to take the place of old ones.It is exciting to imagine that the advance in technology may be changing the most basic condition of human existence,but many technical problems still must be cleared up on the way to this wonderful future.8. According to the passage,human death is now mainly caused by ________.A. diseases and agingB. accidents and warC. accidents and agingD. heart disease and war9. In the author’s opinion,today’s most important advance in technology lies in(在于)________.A. the InternetB. medicineC. brain cellsD. human organs10. Humans may live longer in the future because ________.A. heart disease will be far away from usB. human brains can decide the final deathC. the basic materials of cells will last foreverD. human organs can be repaired by new medicine11. How long can humans live in the future according to the passage?A. Over 100 years.B. More than 120 years.C. About 150 years.D. The passage doesn’t tell us.DRemember when your mom told you not to eat too many candy bars or sweets because they can cause tooth decay (蛀牙)? However, it turns out that chocolate can be moresalutaryto your teeth than you might expect. Recent studies show that chocolate can effectively fight against tooth decay, as if we need another excuse to eat chocolate.Chocolate offers protection like fluoride, a main ingredient in most household toothpastes. Not only does chocolate protect our teeth, but it can do so very effectively. Studies show that chocolate has compounds that provide strong protection for teeth. One of the compounds in chocolate, CBH, is shown to protect even more effectively than fluoride.Tooth decay happens when bacteria work to turn sugar into acids in our mouth. This is why eating foods with high sugar content can lead to more tooth decay. The compounds in chocolate, however, are anti-bacteria and can fight against bacteria in your mouth. The CBH compound in particular also works to strengthen tooth enamel (牙釉质), andprotects against tooth decay.Does this mean you can cat as much chocolate as you want without worrying about your teeth? It depends on the types of chocolate that you like. The protective effect of chocolate is most effective when you chew on cocoa beans. Of course, this option is not very appealing to; most people. A more tasty option is to choose dark chocolate with little sugar content, ideally no more than 6 to 8 grams per serving. For other types of chocolate with higher sugar content, the effect will be lessened. However, because of the protective compounds, it is stillbetter for your teeth than other sweets and desserts containing the same amount of sugar.12. The word “salutary” in paragraph 1 means?A. Beneficial.B. Harmful.C. Familiar.D. Useless.13. What can we know about the compound CBH in chocolate?A. It can help chocolate cure tooth decay.B. It can effectively stop teeth from decaying.C. It may protect teeth better than toothpastes do.D. It may soon replace most household toothpastes.14. How does chocolate fight tooth decay?A. By breaking down acids.B. By building up compounds.C. By fixing up tooth enamel.D. By fighting against bacteria.15. What's the main idea of the text?A. Chocolate plays the role of toothpaste.B. Chocolate protects against tooth decay.C. Chocolate is the best choice for teeth protection.D. Chocolate is healthier to teeth than other sweets.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

2019-2020学年浙江省嘉兴市高三(上)月考语文试卷(1月份)(有答案解析)

2019-2020学年浙江省嘉兴市高三(上)月考语文试卷(1月份)(有答案解析)

2019-2020学年浙江省嘉兴市高三(上)月考语文试卷(1月份)一、单选题(本大题共2小题,共6.0分)1.下列各句中,没有错别字且加点字的注音全都正确的一项是()A. 想三年前,身处耄耋之年的武侠小说巨擘.(bò)金庸本该怡养天年,却因作品被侵权,状告某出版公司,尽管该公司辩称旗下作品为非营利性项目,金庸粉丝们早已按捺.(nà)不住,唇枪舌剑对准了这家公司。

B. 在那个直言贾.(gǔ)祸的年代,真的是人心惟危,即便是底层百姓,如果在言语上稍有差.(chā)迟,也立即会招致灭顶之灾,言论自由在那时是一种可望而不可即的奢望。

C. 嘉庆对内政的整饬.(chì)是从诛和珅着手的。

在清除飞扬拔扈、贪赃营私的和珅后,嘉庆即以此为契机,打出“咸与维新”的旗号,诏求直言,广开言路,祛.(qū)邪扶正。

D. 两会代表们一致认为,我们不仅要大力践行“八荣八耻”的社会主义荣辱观,更要继续对一切徇.(xún)私舞弊、敢冒天下之大不韪.(wěi)的贪污腐败分子严惩不怠,让美丽中国梦真正美丽纯净。

2.下列各句中,没有语病的一项是()A. 截至2019年2月,由阿里巴巴支撑的网商银行绿色信贷余额1.9万亿元,占全部信贷比重的5.1%左右,实现了阿里承诺的绿色信贷规模的持续增长。

B. 视频“万人迷”--抖音视频因不仅涉嫌违反法律法规,而且内容引人不适甚至低俗不堪,自去年底以来不断被广电总局约谈,整改不止。

C. 长生生物多年来能够游走于监管缝隙,穿越法律、政策防线,并不是其本身有多大能量,根源在于职能部门监管的全面失守所致,否则,问题也不至如此严重。

D. 只要主管部门切实履行监管责任,依法加强新兴媒体管理,那么无论什么形式的媒体,无论网上还是网下,无论大屏还是小屏,都没有法外之地、舆论飞地。

二、默写(本大题共1小题,共6.0分)3.补写出下列名篇名句的空缺部分。

(只选3小题)子游对曰:“昔者偃也闻诸夫子曰:‘______ ,______ 。

嘉兴市2019学年第一学期期末测试卷附答案

嘉兴市2019学年第一学期期末测试卷附答案
4.下列文化常识的表述有误的一项是()(2分)
A.我国古代常用皇帝的年号来纪年,如“庆历四年春” “崇祯五年”;也有用干支来 纪年,如“岁在癸丑,暮春之初”。
B.古人常用伯、仲、叔、季来表示兄弟排行的次序,伯是老大,仲是第二,叔是第三, 季是最小的。如孙权在兄弟中排老二,故字仲谋。
C.《论语》中称三十岁为“而立之年”,四十岁为“不惑之年”,五十岁为“花甲之 年”,六十岁为“知天命之年”,七十岁为“古稀之年”。
嘉兴市2019学年第一学期期末测试卷
一、积累(16分)
1.阅读下面的文字,完成后面题目。(4分)
中国梦应是一是一①一(A.幅B.副C.辐)多维度的1仙 图,它需要以更加宽
广的胸怀包容各种文化思潮的交融碰撞,需要弘扬—②_(源头很远,水流很长,比喻历史 悠久)的中华文明,传承优秀cuican的中国文化。
④老鱼头失手了。这是在他的捕鱼生涯中从没有出现过的事情,出去了一整天竟然只逮 到几条小鱼。跟着的村民以为老鱼头昨晚没睡好。可接下来的几天还是这样。老鱼头盯着水 面,除了说一句“这鱼都跑哪里去了",再也没捞起一网满满实实的鱼来。跟着老鱼头捕鱼 的人说,老鱼头都七十多了,大概这眼神不好了,否则怎么会抓不到鱼呢?
B.《儒林外史》是清代吴敬梓的长篇讽刺小说,主要描写封建社会后期知识分子及官 绅的活动和精神面貌。范进、孔乙己、严监生等都是其中的艺术典型。
C.《三顾茅庐》一文,前而写求贤若渴的刘备屡次寻访诸葛亮不遇,为后面诸葛亮的 上场做足了铺垫;而见面后的“隆中对”,则是刘备雄才大略的集中展现。
D.刘姥姥是《红楼梦》里的人物。我们现在常用“刘姥姥进大观园”来揶揄那些见识 短浅、孤陋寡闻的人,也用作自谦或者自嘲。
一直奔向黎明
鱼化石(节选)

浙江省嘉兴市2019-2020学年高三上学期期末考试数学试题及答案

浙江省嘉兴市2019-2020学年高三上学期期末考试数学试题及答案

浙江省嘉兴市2019~2020学年第一学期期末检测高三数学试题卷(2020.1)本试题卷分选择题和非选择题两部分。

全卷共6页,选择题部分1至3页;非选择题部分4至6页。

满分150分,考试时间120分钟。

考生注意:1. 答题前,请务必将自己的姓名、准考证号用黑色字迹的签字笔或钢笔分别填写在试题卷和答题纸规定的位置上。

2. 答题时,请按照答题纸上“注意事项”的要求,在答题纸相应的位置上规范作答,在本试题卷上的作答一律无效。

参考公式:若事件A ,B 互斥,则()()()P A B P A P B +=+ 若事件A ,B 相互独立,则()()()P A B P A P B ⋅=⋅若事件A 在一次试验中发生的概率是p ,则n 次独立重复试验中事件A 恰好发生k 次的概率()()()10,1,2,,n kk kn n P k C p p k n −=−=⋅⋅⋅台体的体积公式()1213V S S h =其中1S ,2S 分别表示台体的上、下底面积,h 表示台体的高. 柱体的体积公式V Sh =其中S 表示柱体的底面积,h 表示柱体的高 锥体的体积公式13V Sh =其中S 表示锥体的底面积,h 表示锥体的高 球的表面积公式24S R π= 球的体积公式343V R π=其中R 表示球的半径选择题部分(共40分)一、选择题:本大题共10小题,每小题4分,共40分。

在每小题给出的四个选项中,只有一项是符合题目要求的。

1. 已知全集U R =,集合{}|11A x x =−<≤,{}1,1B =−,则()U A C B =( )A. {}|1x x ≠−B. {}|1x x ≠C. {}|11x x −<<D. {}|11x x −≤≤2. 已知i 是虚数单位,()122z i i +=−,则z =( ) A. 1B. 2C. iD. 2i3. 设曲线12x y x +=−在点()1,2−处的切线与直线0ax by c ++=垂直,则ab=( ) A.13B. 13− C. 3 D. -34. 函数()22log f x x x =+,则满足(]01,4x ∈,且()0f x 为整数的实数0x 的个数为( ) A. 3B. 4C. 17D. 185. 设,m n R ∈,则“m n >”是“m m n n >”的( ) A. 充分而不必要条件 B. 必要而不充分条件 C. 充要条件D. 既不充分也不必要条件6. 已知x ,y 满足条件2020240x y y x y −−≤⎧⎪−≤⎨⎪+−≥⎩,若z ax y =+的最大值为0,则实数a 的值为( )A. 12−B. -2C.12D. 27. 如图是某三棱锥的正视图和俯视图(单位:cm ),则该三棱锥侧视图面积是( )(单位:2cm )A. 2B.C.32D.8. 等差数列{}n a 满足:10a >,31047a a =.记12n n n n a a a b ++=,当数列{}n b 的前n 项和n S 取最大值时,n =( )A. 17B. 18C. 19D. 209. 已知A ,B 是椭圆C :2213y x +=短轴的两个端点,点O 为坐标原点,点P 是椭圆C 上不同于A ,B 的动点,若直线PA ,PB 分别与直线4x =−交于点M ,N ,则OMN ∆面积的最小值为( )A. B.C. D.10. 如图,ABC ∆中,2AB =,3AC =,BC 边的垂直平分线分别与BC ,AC 交于点D ,E ,若P 是线段DE 上的动点,则PA BC ⋅的值为( )A. 与角A 有关,且与点P 的位置有关B. 与角A 有关,但与点P 的位置无关C. 与角A 无关,但与点P 的位置有关D. 与角A 无关,且与点P 的位置无关非选择题部分(共110分)二、填空题:本大题共7小题,多空题每题6分,单空题每题4分,共36分. 11. 已知55sin,cos 66P ππ⎛⎫⎪⎝⎭是角α的终边上一点,则cos α=______,角α的最小正值是______. 12. 已知箱中装有10个不同的小球,其中2个红球、3个黑球和5个白球,现从该箱中有放回地依次取出3个小球.则3个小球颜色互不相同的概率是______;若变量ξ为取出3个球中红球的个数,则ξ的方差()D ξ=______.13. 已知213nx x ⎛⎫+ ⎪⎝⎭的展开式中的各二项式系数的和比各项系数的和小240,则n =______;展开式中的系数最大的项是______.14. 在ABC ∆中,角A ,B ,C 所对的边分别为4a =,4b =,6c =.I 是ABC ∆内切圆的圆心,若AI xAB yAC =+,则x =______;y =______.15. 已知()()111x x a a a f x −=>+,实数1x ,2x 满足()()121f x f x +=,则()12f x x +的最小值为______.16. 已知两定点1,04P ⎛⎫− ⎪⎝⎭,1,04Q ⎛⎫ ⎪⎝⎭位于动直线l 的同侧,集合{}|,1M l P Q l =点到直线的距离之和等于,()(){},|,,N x y x y l l M =∉∈.则集合N 中的所有点组成的图形面积是______.17. 已知矩形ABCD ,4AB =,2BC =,E 、F 分别为边AB 、CD 的中点.沿直线DE 将ADE ∆翻折成PDE ∆,在点P 从A 至F 的运动过程中,CP 的中点G 的轨迹长度为______.三、解答题:本大题共5小题,共74分。

2019-2020学年嘉兴市第一中学高三英语上学期期末试卷及参考答案

2019-2020学年嘉兴市第一中学高三英语上学期期末试卷及参考答案

2019-2020学年嘉兴市第一中学高三英语上学期期末试卷及参考答案第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AF the Art World competition.Prize -The winner of each type will get the chance to display their artworks in a week-long exhibition inChelsea,New York..Eligibility - Open to artists all over the world..Entry Fee(参赛费)-$24 for a maximum of 3 submitted(提交的)photos..Date of Exhibition - From 25thApril to 2ndMay.F the Art World is an international art competition organized by which is quite unusual, compared to other competitions. The artworks are not judged on the basis of creativity and skill. Instead, they're judged by the depth of the subject matter. The subject this year is “A Competition About Change”, where artists can try and show how they'd like to change humanity in a good way.Notes*For this competition, there are three types for submissions, namely: street art, fine art, and digital art.*Each type will have a winner as chosen by the organizers and all the winners will have the wonderful chance to exhibit their works at the Unarthodox Gallery inNew Yorkin a week-long exhibition.*All the winners will also receive 100% of the sale price when any of their artworks are sold!Winners will also be displayed on the website and the entrants' artworks will also be displayed in the opening ceremony(仪式)as well.1.What is special about F the Art World Competition?AIt is free to attend.B.It lasts for over a week.C.It is open to artists inNew York.D.It centers on the depth of the artworks.2.What will the winners get?A.Prize money.B.A chance to visit an exhibition.C.A written judgement of their artworks.D.Money from the sale of their artworks.3.Where will the entrants' artworks be shown?A.In the street.B.In the opening ceremony.C.On the website.D.At the market.BEvery day, millions of shoppers hit the stores in full force, searching wildly for the perfect gift.Aside from purchasing holiday gifts, most people regularly buy presents for other occasions throughout the year, including weddings, birthdays, anniversaries, and graduations. This frequent experience of gift-giving cancause uncertain feelings in gift-givers. Many enjoy the opportunity to buy presents because gift-giving offers a powerful means to build stronger bonds, while many worry that their purchases will disappoint rather than delight the intended recipients (接受者).Anthropologists describe gift-giving as a positive social process, serving various political, religious, and psychological functions. Economists, however, offer a less favorable view. According to Waldfogel, gift-giving represents an objective wasteof resources. People buy gifts that recipients would not choose to buy on their own, or at least not spend as much money to purchase (a phenomenon referred to as‘‘the deadweight loss of Christmas”).What is surprising is that gift-givers have much experience acting as both gift-givers and gift-recipients, but nevertheless tend to overspend each time they set out to purchase a meaningful gift. In the present research, we propose a unique psychological explanation for this overspending problem — gift-givers link how much they spend with how much recipients will appreciate the gift. Though it seems natural to gift-givers, such an assumption may be unfounded. Indeed, we propose that gift-recipients will be less likely to base their feelings of appreciation on the value of a gift than givers assume.Why do gift-givers assume that gift price is closely linked to gift-recipients’ feelings of appreciation? Perhaps givers believe that more expensive gifts communicate a stronger sense ofthoughtfulness and consideration. According to Camerer and others, gift-giving represents a symbolic ritual (习俗), by which gift-givers attempt to signal their positive attitudes towards the recipient and their willingness to invest resources in a futurerelationship. In this sense, gift-givers may be motivated to spend more money on a gift in order to send a “stronger signal”. As for gift-recipients, they may not interpret smaller and larger gifts as representing smaller and larger signals of thoughtfulness and consideration.The idea of gift-givers and gift-recipients being unable to account for the other party’s viewpoint seems confusing because people slip in and out of these roles every day. Yet, despite the experience as both givers and receivers, people often struggle to apply information gained from one role in another. In theoretical terms, people fail to use information about their own preferences and experiences to produce more efficient outcomes in their exchange relations. In practical terms, people spend hundreds of dollars each year on gifts, but somehow never learn to estimate their gift expense according to personal insight.4. The author uses “the deadweight loss of Christmas” in Paragraph 2 to express ________.A. gift-givers don’t spend much money during holidaysB. gift-givers don’t ask recipients what gifts they preferC. gift-givers buy improper and expensive giftsD. gift-givers have difficulty in choosing gifts5. According to the passage, people buy gifts to ________.A. receive gifts in returnB. enjoy the feeling of shoppingC. help recipients to save moneyD. better relationships with recipients6. What can we learn from the passage?A. People’s high living standards require expensive gifts.B. Gift-givers buy gifts based on their experiences as recipients.C. Anthropologists think gift-giving meets different human needs.D. Recipients judge the depth of friendship according to the gift price.7. Why did the author write this article?A. To criticize people’s gift-buying habits.B. To analyze people’s gift-giving behaviors.C. To offer advice on how to improve relationships.D. To remind people not to overlook others’ preferences.CA teenager in Georgia will no longer have to walk 7 miles to work after school thanks to one woman’s act of kindness.Jayden Sutton, a high school senior, went on foot each day from school to his job at a restaurant and thenback home. Sutton was determined to work and make enough money to eventually buy his own vehicle.Sutton said he’d leave school at 3:30 pm, then walk miles to his job at the restaurant. After his work, which usually lasted six to eight hours, he walked home, sometimes not arriving back until almost midnight.That all changed when Myers saw him walking down the road in the rain in December. “The young man was insistently in a rush walking to work, saying ‘I can’t be late,’” Myers said. “He begged me to give him a ride. I told him I could take him as far as I was going. I began to create small talk along the way. It wasrevealedto me that his name was Jayden, 12th grader, worked 40 hours a week, walked 5 miles to work immediately after school, got off at 10:30 pm at night and walked back home another 5 miles if co-workers didn’t offer a ride.”After dropping Sutton off, Myers said his heart and determination filled her with tears. “He was smiling in good spirits and that’s a child worth blessing,” she told Fox News. So, Myers shared Sutton’s story on the GoFundMe page, which raised more than $ 9, 000 from 186 donors.She surprised Sutton with a new car after she managed to convince the general manager to drop the price of the vehicle to meet the budget.8. Why did Sutton work so hard in his spare time?A. To gain working experience.B. To pay for his education.C. To own a car.D. To support his family.9. What difficulty did Sutton have in his work at the restaurant?A. He worked longer than other workers.B. His work was too tiring.C. His job was much less paid.D. He had to walk to work.10. What does the underlined word “revealed” in paragraph 4 mean?A. Known.B. Attached.C. Believed.D. Limited.11. What do we know about the money donated online?A. It could buy more than a new car.B. It was not enough to buy a new car.C. It was given to Myers to buy herself a new car.D It mainly came from a car sales manager.DThere are 8.8 million blind people in India. In fact, there are 36 million blind people worldwide and a quarter of them are in India; however, many cases of blindness in India are curable. The poor in India have limited access to primary eye healthcare and often do not eat foods rich in micronutrients, like vitamins and minerals, which playan important role in maintaining good eye health.Many people worldwide are not even aware that they may have a vision (视力) problem simply because they do not get their eyes tested every year with a doctor, who tests for the functioning of the eye muscles (肌肉), as well as common diseases like night blindness. This exam is strongly recommended by experts because some changes in vision, which the patient may take longer to notice, can be found easily in this way.Certain simple changes in diet and lifestyle can ensure better eye health for you. These include drinking plenty-of water, not smoking, and eating brightly color1 ed and leafy fruit and vegetables. Wearing sunglasses protects your eyes from the sun, which damages otherwise healthy eyes. Learn about your family's eye disease history, and be on the lookout for any problem about your vision. Make sure that you see a doctor immediately for early intervention(干预) if you see any of these signs of worsening eye health.If you or a loved one needs to cure blindness or other eye diseases, turn to a crowdfunding (众筹) platform. A group of eye health caregivers have fundraised with crowdfunding platform ImpactGuru to raise money to perform operations on the eyes of blind women in south Asia. Running an online fundraiser enables both doctors and patients to find a way out of the dark. If you want eye care to develop, start a fundraiser today.12. Why are there so many blind people in India?A. There is a lack of eye hospitals in India.B. People pay no attention to their eyes at all.C. Poor Indians lack food good for eye health.D. The environment damages their eyes.13. What does the author suggest in Paragraph 2?A. Examining your eyes annually.B. Strengthening muscles every day.C. Raising the awareness of physical health.D. Attaching importance to self-examination.14. Which of the following may do harm to your eyes?A. Smoking a lot.B. Wearing sunglasses.C. Drinking much water.D. Watching brightly-color1 ed pictures.15. What does the author want to show in the last paragraph?A. How to start a fundraiser online.B. The importance of raising money.C. The role of crowdfunding in eye care.D. What should bedone to raise money.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

嘉兴市2019—2020学年第一学期期末检测高三数学试题卷Word版含解析

嘉兴市2019—2020学年第一学期期末检测高三数学试题卷Word版含解析

嘉兴市2019-2020学年第一学期期末检测高三数学试题卷第Ⅰ卷一、选择题(本大题共10小题,每小题4分,共40分.)1. 已知集合,,则A. B.C. D.2. 若复数,为虚数单位,则A. B. C. D.3. 点到直线的距离是A. B. C. 1 D.4. 已知是非零实数,则“”是“”的A. 充分不必要条件B. 必要不充分条件C. 充分必要条件D. 既不充分也不必要条件5. 实数满足,若的最小值为1,则正实数A. 2B. 1C.D.6. 某几何体的三视图如图所示(单位:),则该几何体的表面积(单位:)是A. B. C. D.7. 函数的图象与直线相切,则实数A. B. 1 C. 2 D. 48. 若在内有两个不同的零点,则和A. 都大于1B. 都小于1C. 至少有一个大于1D. 至少有一个小于19. 设点是双曲线与圆在第一象限的交点,是双曲线的两个焦点,且,则双曲线的离心率为A. B. C. 13 D.10. 如图,正方体的棱长为1,分别是棱的中点,过的平面与棱分别交于点.设,.①四边形一定是菱形;②平面;③四边形的面积在区间上具有单调性;④四棱锥的体积为定值.以上结论正确的个数是A. 4B. 3C. 2D. 1第Ⅱ卷二、填空题(本大题共7小题,多空题6分,单空题4分,共36分)11. 各项均为实数的等比数列,若,,则______,公比_____.12. 已知,则项的二项式系数是________;________.13. 已知函数,则的单调递增区间是______;14. 直角中,,为边上的点,且,则______;若,则________.15. 在锐角中,内角所对的边分别是,若,则的取值范围是________.16. 有编号分别为1,2,3,4的4个红球和4个黑球,从中取出3个,则取出的编号互不相同的概率是________.17. 已知实数满足,则的取值范围是_______.三、解答题(本大题共5小题,共74分,解答应写出文字说明、证明过程或演算步骤)18. 已知函数的部分图象如图所示.(Ⅰ)求的解析式;(Ⅱ)设函数,求的值域.19. 已知函数,(为自然对数的底数).(Ⅰ)若是的极值点,求实数的值;(Ⅱ)求的单调递增区间.20. 如图,在矩形中,点在线段上,,,沿直线将翻折成,使点在平面上的射影落在直线上.(Ⅰ)求证:直线平面;(Ⅱ)求二面角的平面角的余弦值.21. 如图,为半圆的直径,点是半圆弧上的两点,,.曲线经过点,且曲线上任意点满足:为定值.(Ⅰ)求曲线的方程;(Ⅱ)设过点的直线与曲线交于不同的两点,求面积最大时的直线的方程.22. 已知数列满足,.(Ⅰ)求数列的通项公式;(Ⅱ)求证:对任意的,都有①;②().嘉兴市2019-2020学年第一学期期末检测高三数学试题卷参考答案第Ⅰ卷一、选择题(本大题共10小题,每小题4分,共40分.)1. 已知集合,,则A. B.C. D.【答案】D【解析】,选D.2. 若复数,为虚数单位,则A. B. C. D.【答案】B【解析】 ,选B.,3. 点到直线的距离是A. B. C. 1 D.【答案】A【解析】点到直线的距离是 ,选A.4. 已知是非零实数,则“”是“”的A. 充分不必要条件B. 必要不充分条件C. 充分必要条件D. 既不充分也不必要条件【答案】D点睛:充分、必要条件的三种判断方法.1.定义法:直接判断“若则”、“若则”的真假.并注意和图示相结合,例如“⇒”为真,则是的充分条件.2.等价法:利用⇒与非⇒非,⇒与非⇒非,⇔与非⇔非的等价关系,对于条件或结论是否定式的命题,一般运用等价法.3.集合法:若⊆,则是的充分条件或是的必要条件;若=,则是的充要条件.5. 实数满足,若的最小值为1,则正实数A. 2B. 1C.D.【答案】C【解析】由 ,舍; 由作可行域,则直线过点A取最小值1,满足题意,所以,选C点睛:线性规划的实质是把代数问题几何化,即数形结合的思想.需要注意的是:一,准确无误地作出可行域;二,画目标函数所对应的直线时,要注意与约束条件中的直线的斜率进行比较,避免出错;三,一般情况下,目标函数的最大或最小值会在可行域的端点或边界上取得.6. 某几何体的三视图如图所示(单位:),则该几何体的表面积(单位:)是A. B. C. D.【答案】B【解析】几何体为一个正方体与一个正四棱台的组合体,所以表面积为,选B点睛:空间几何体表面积的求法(1)以三视图为载体的几何体的表面积问题,关键是分析三视图确定几何体中各元素之间的位置关系及数量.(2)多面体的表面积是各个面的面积之和;组合体的表面积注意衔接部分的处理.(3)旋转体的表面积问题注意其侧面展开图的应用.7. 函数的图象与直线相切,则实数A. B. 1 C. 2 D. 4【答案】C【解析】选C8. 若在内有两个不同的零点,则和A. 都大于1B. 都小于1C. 至少有一个大于1D. 至少有一个小于1【答案】D【解析】+=,因为在内有两个不同的零点,所以+<,即和至少有一个小于1,选D9. 设点是双曲线与圆在第一象限的交点,是双曲线的两个焦点,且,则双曲线的离心率为A. B. C. 13 D.【答案】A【解析】因为,,所以,因为,选A.点睛:解决椭圆和双曲线的离心率的求值及范围问题其关键就是确立一个关于的方程或不等式,再根据的关系消掉得到的关系式,而建立关于的方程或不等式,要充分利用椭圆和双曲线的几何性质、点的坐标的范围等.10. 如图,正方体的棱长为1,分别是棱的中点,过的平面与棱分别交于点.设,.①四边形一定是菱形;②平面;③四边形的面积在区间上具有单调性;④四棱锥的体积为定值.以上结论正确的个数是A. 4B. 3C. 2D. 1【答案】B【解析】因为对面互相平行,所以四边形一定是平行四边形;因为EF垂直平面BDD1B1,所以EF垂直GH,所以四边形一定是菱形;因为AC//EF,所以平面;四边形的面积在区间上先减后增;四棱锥的体积为 ,所以正确的是1,2,4,选B点睛:求体积的两种方法:①割补法:求一些不规则几何体的体积时,常用割补法转化成已知体积公式的几何体进行解决.②等积法:等积法包括等面积法和等体积法.等积法的前提是几何图形(或几何体)的面积(或体积)通过已知条件可以得到第Ⅱ卷二、填空题(本大题共7小题,多空题6分,单空题4分,共36分)11. 各项均为实数的等比数列,若,,则______,公比_____.【答案】 (1). 3 (2).【解析】12. 已知,则项的二项式系数是________;________.【答案】 (1). 15 (2). 64【解析】项的二项式系数是 ,点睛:赋值法研究二项式的系数和问题“赋值法”普遍适用于恒等式,是一种重要的方法,对形如的式子求其展开式的各项系数之和,常用赋值法,只需令即可;对形如的式子求其展开式各项系数之和,只需令即可.13. 已知函数,则的单调递增区间是______;______.【答案】 (1). (2). 3【解析】因为为单调递增函数,所以由得的单调递增区间是;14. 直角中,,为边上的点,且,则______;若,则________.【答案】 (1). 4 (2).【解析】建立直角坐标系,设,所以,由得15. 在锐角中,内角所对的边分别是,若,则的取值范围是________.【答案】..................因为锐角,所以16. 有编号分别为1,2,3,4的4个红球和4个黑球,从中取出3个,则取出的编号互不相同的概率是________.【答案】【解析】8个球,从中取出3个,共有种基本事件其中取出的编号互不相同的有种基本事件,所以概率为17. 已知实数满足,则的取值范围是_______.【答案】【解析】设因此因为,所以,即取值范围是点睛:利用三角函数的性质求范围,先通过变换把函数化为的形式再借助三角函数图象研究性质,解题时注意观察角、函数名、结构等特征.三、解答题(本大题共5小题,共74分,解答应写出文字说明、证明过程或演算步骤)18. 已知函数的部分图象如图所示.(Ⅰ)求的解析式;(Ⅱ)设函数,求的值域.【答案】(1) (2)【解析】试题分析:(1)先根据最高点得振幅,再根据四分之一个周期求,最后代入最值点求(2)先根据二倍角公式以及配角公式将函数化为基本三角函数,再根据正弦函数性质求值域试题解析:(Ⅰ)由图象得周期,所以;又由,得;所以.(Ⅱ),因为,,,所以的值域为.19. 已知函数,(为自然对数的底数).(Ⅰ)若是的极值点,求实数的值;(Ⅱ)求的单调递增区间.【答案】(1) (2)见解析【解析】试题分析:(1)先求导数,再根据,得实数的值;(2)先求导函数零点,再根据两零点大小分类讨论,根据对应导函数符号确定单调增区间试题解析:(Ⅰ)由,得,此时是的极小值点.(Ⅱ)由,得或.①当时,,的单调递增区间是;②当时,,的单调递增区间是;③当时,,的单调递增区间是.20. 如图,在矩形中,点在线段上,,,沿直线将翻折成,使点在平面上的射影落在直线上.(Ⅰ)求证:直线平面;(Ⅱ)求二面角的平面角的余弦值.【答案】(1)见解析(2)【解析】试题分析:(1)根据射影定义得,再根据线面垂直得,最后根据线面垂直判定定理得结论(2)连接交于点.则根据二面角定义得是二面角的平面角的平面角.再通过解三角形得二面角的平面角的余弦值.试题解析:(Ⅰ)证明:在线段上取点,使,连接交于点.正方形中,,翻折后,,,又,平面,又平面,平面平面又平面平面,点在平面上的射影落在直线上,又点在平面上的射影落在直线上,点为直线与的交点,平面即平面,直线平面;(Ⅱ)由(Ⅰ)得是二面角的平面角的平面角.,在矩形中,可求得,.在中,,二面角的平面角的余弦值为.点睛:立体几何中折叠问题,要注重折叠前后垂直关系的变化,不变的垂直关系是解决问题的关键条件.线面角的寻找,主要找射影,即需从线面垂直出发确定射影,进而确定线面角.21. 如图,为半圆的直径,点是半圆弧上的两点,,.曲线经过点,且曲线上任意点满足:为定值.(Ⅰ)求曲线的方程;(Ⅱ)设过点的直线与曲线交于不同的两点,求面积最大时的直线的方程.【答案】(1) (2)或【解析】试题分析:(1)先求P点坐标,再根据两点间距离公式求,最后根据椭圆定义确定a,c,b(2)先设,与椭圆方程联立,结合韦达定理以及弦长公式求EF,根据点到直线距离公式求高,再根据三角形面积公式得面积关于k的函数关系式,最后根据基本不等式求最值,根据等号成立条件确定直线的方程试题解析:(Ⅰ)根据椭圆的定义,曲线是以为焦点的椭圆,其中,.,,,曲线的方程为;(Ⅱ)设过点的直线的斜率为,则.由得,,,又点到直线的距离,的面积.令,则.当且仅当,即时,面积取最大值.此时直线的方程为或.22. 已知数列满足,.(Ⅰ)求数列的通项公式;(Ⅱ)求证:对任意的,都有①;②().【答案】(1) (2)见解析【解析】试题分析:(1)对递推关系式进行变形,转化为一个常数列,即得数列的通项公式;(2)①先对通项进行放缩:,再根据裂项相消法求和,即证得结论②先倒序相加法求和,再利用基本不等式进行放缩求和,最后证明和值与结果大小试题解析:(Ⅰ)当时,,当时,.又,,.(Ⅱ)①证明:当时,成立;当时,②设,则,当时,,,当且仅当时等号成立.当时,,点睛:证明数列不等式,,常用方法为方缩法,经过放缩,将数列化为可求和,最后再比较和值与结果大小即可。

浙江省嘉兴市2019—2020学年高三上学期期末检测语文试题

浙江省嘉兴市2019—2020学年高三上学期期末检测语文试题

嘉兴市2019—2020学年第一学期期末检测高三语文试卷(2020.1)一、语言文字运用(共20分)1.下列各句中,没有错别字且加点字的注音全都正确的一项是A. 倏.(shū)然觉得,冬天像一个穿着灰色长袍的青衿,面容清癯却胸襟坦荡,神情严肃而心地诚笃,来时硬朗,让人觉得踏实与豁.(huò)亮,去时又淡然,让人有了怀念和希冀。

B. 阳光从篱笆边的丝瓜、扁豆藤蔓.(wàn)上掠过,落在巷子的苔藓上,那扇被蛀得千疮.(chuāng)百孔的木门呈现着幸福的嫩黄色,门里桌边脸色腊黄的孩子,也似乎带着某种幸福。

C. 面对打上门来的贸易战,我们坚持“不愿打、不怕打”的原则立场,戮.(lù)力同心众志成诚,沉着应对,坚决抵御美国霸凌主义行径.(jìn)的冲击,捍卫民族的核心利益。

D. 成龙动作电影探索出与好莱坞.(wū)“硬动作”电影截然不同的道路,通过柔性表达塑造了一系列有血有肉的贫民英雄形象,向世界弘扬惩恶扬善、扶危济.(jì)困的情怀。

阅读下面的文字,完成下面小题。

[甲]古人云:诗言志,歌咏言。

诗歌是中国文化在语言文字使用中的浓缩精华,寥寥数语,却做到了写实性与抒情性、艺术性与思想性的统一。

[乙]中国曾被称为“诗的国度”,所谓“不学诗,无以言。

”祭拜祖先需要唱诗,登高望远需要题诗,好友分别需要赠诗,入仕为官需要考诗……在中国历史上,诗歌与社会生活息息相关....是中国文化的有力表达。

[丙]中华民族五千年来的历史经验、哲学思想文化传统是中华儿女文化自信的底气,深刻影响着中国人的社会实践与人生哲学价值观。

中华优秀思想长期浸润..中国文学,久而久之转化为诗意,以诗歌等形式影响和塑造着民众的人生观、世界观与价值观。

凭借着优美的语言与凝练的旋律,诗歌将中华文明的精神内涵外化为口耳相传的继承与发展,又内化为潜移默化....的心灵认知。

多少名诗佳句依旧在中国人嘴边吟诵,因而..在他们心间缓缓流淌。

2019-2020学年嘉兴市第一中学高三英语上学期期末考试试卷及参考答案

2019-2020学年嘉兴市第一中学高三英语上学期期末考试试卷及参考答案

2019-2020学年嘉兴市第一中学高三英语上学期期末考试试卷及参考答案第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AIn the 1994 filmForrest Gump, there’s a famous saying, “Life is like a box of chocolates; you never know what you’re gonna get.” The surprise is part of the fun. Now blind box toys are bringing the magic of surprise to online shopping.A blind box toy is hidden inside uniform packaging but invisible from the outside. You don’t know what will be inside, although the toys typically come from pop culture, ranging from movies to comics and cartoons.Blind boxes have caught on since they were first introduced fromJapantoChinain 2014. According to a 2019 Tmall report, the mini-series of Labubu blind box, designed byHong Kong-born Kasing Lung, was named Champion of Unit Sales with 55,000 sold in just 9 seconds during the Singles Day shopping event. Most customers for blind boxes are young people aged 18 to 35.According to The Paper, blind box toys are popular in part because of their cute appearances. The typically cute cartoon figurines come in miniature sizes, making them suitable for display almost anywhere.Even if blind boxes are not their top choice for decorations, the mystery and uncertainty of the process also attracts people. It’s the main reason why people buy blind boxes one after another.“Fear of the unknown is always a part of the box-opening process,” said Miss Cao, 24, who lives and works inShenyang. Speaking to Sina News, she said: “Until you open all the boxes, you cannot know what it is inside.”Opening a blind box is a delightful little surprise for our mundane daily lives, something small but fun to wait for each day, week or month. When people open this simple little box, they may be disappointed, but the uncertainty is part of the fun. People will open more blind boxes and hope for a better outcome.When someone re-makesForrest Gump, don't be surprised if he says, “Life is like a blind box...”1. Why is the famous saying in the filmForrest Gumpquoted at the beginning?A. To arouse the readers’ interest.B. To present the writer’s view.C. To introduce the topic.D. To highlight the fun of blind boxes.2. Which of the following is the main feature that makes blind box so popular?A. Miniature sizes.B. Cute appearances.C. Fear of the unknown.D. Mystery and uncertainty.3. What can we learn from the passage?A. Blind box became popular in 2019 after being first introduced fromJapantoChina.B. Blind box toys typically originated in pop culture, varying from movies to cartoons.C. Blind box toys was designed and named by Hong Kong-born Kasing Lung.D. When people open this simple little box, they will feel disappointed.BPut your hand over your heart and sit very still. You may notice that the sound of your heartbeat is similar to the beat of a drum. Your heart starts beating before you are born and continues throughout your life. For this reason, the beating of a drum stands for the rhythm of life for many people around the world.InGhana, a country inAfrica, many schools use drums instead of bells to show the beginning and ending of class. Through the drum, the children ofGhanaalso learn about their history and culture. They hear old stories passed on through the music of the drum. The stories of the drum also teach children games, rules and lessons about behavior.For thousands of years inAfrica, drums have been used to tell stories of daily life and history. Drums told the coming of a king, the start of a war, or the birth of a child. They also allowed people to share messages. But how does a drum tell a story?InWest Africa, the most common drum used for communication is called a “talking drum”. By making higher orlower drum sounds, the drummer can make the drum “talk”.In many African languages, words go up and down in pitch (高音) when they are spoken, almost like a song. Depending on the pitch or tone (音调), the same sound can have many different meanings. For example, when spoken with two low tones, the African word “ilu” means “drum”. When spoken with one high and one low tone, “ilu” means “town”.Drum language works in the same way. Just as in spoken language, the word “ilu” has different meanings depending on how it’s drummed. When “ilu” is drummed with two beats using low tones, the word means “drum”. When “ilu” is drummed with two beats using one high and one low tone, it means “town”.Drummers create “words” to build ideas, sentences and stories. The next time you hear a song, listen for the heartbeat within the music. Can you hear the story of the drum?4. The first paragraph mainly tells us________.A. drums beat like our heartsB. drums have a long historyC. drums are widely used in the worldD. drums are important for many people worldwide5. From the text, we learn that inGhanadrums________.A. are not as useful as beforeB. teach children a lot of thingsC. help bring the war to an endD. are used in class by teachers6. The example of the African word “ilu” is used to show________.A. how a word can have different soundsB. how to speak African languagesC. how a drum tells storiesD. how to beat a drum7. What would be the best title for the text?A. Know the history of the drumB. Listen to the story of the drumC. Beat the drum of lifeD. Love me, love my drumCA cheap printed sensor could transmit wildfire warnings. Wildfires have recently destroyed regions across the world, and theirgravityis increasing. Hoping to reduce harm, researchersled by Yapei Wang, a Chinese chemist ofRenminUniversity, say they have developed an inexpensive sensor to detect such fires earlier with less effort.Current detection methods rely heavily on human watchfulness, which can delay an effective response. Most wildfires are reported by the general public, and other alerts come from routine foot patrols and watchtower observers. Passing planes and satellites also occasionally spot something, but “the fire first appears on the ground," Wang says. “ When you see the fire from the sky, it is too late. ”The team says its new sensor can be placed near tree trunks' bases and send a wireless signal to a nearby receiver if there is a dramatic temperature increase. That heat also powers the sensor itself, without replacing batteries. The team printed the substances onto ordinary paper to create a sensor for just $ 0.40.But improving coordination among the different agencies involved in firefighting is even more crucial to address, says Graham Kent, an earthquake expert at theUniversityofNevada,Reno, who was not part of the study.Kentis director of ALERTWildfire, a network that uses cameras and crowd sourcing to watch for fires inCalifornia,NevadaandOregon. “The whole way that you respond to a fire until it's put out is like a ballet," he says. “You'd have to choreograph (设计) it just so, with resources precisely used at the right time and place and in theright order from detection to confirmation to assignment to extinguishment (熄灭).Fire detection is just step one.Wang says his team's next steps are to extend the device'ssignal range beyond the current 100 meters, which can limit practical use, and to develop a protective shield for it. The transmitter's effectiveness, he notes, will also need to be examined in the field ahead.8. What does the underlined word “gravity” in paragraph 1 probably mean?A. Pull.B. Extinction.C. Popularity.D. Severity.9. What do we know about the sensor?A. Its price remains high.B. Its batteries are replaceable.C. It can detect fires earlier and easier.D. It can reduce firefighters' pain.10. What doesKentmean in paragraph 4?A. Firefighting is easy but crucial.B. Fire detection resources are rich.C. Putting out a fire is an orderly activity.D. Technology is the key to extinguishing a fire.11. What's the plan for the new sensor according to Wang?A. Improving and testing it.B. Limiting its use and transmission.C. Examing and reducing its signal range.D. Getting it on the market ahead of time.DChancellor of the Exchequer George Osborne said yesterday he would use the autumn spending review to increase Britain’s£12bn-a-year aid budget towards humanitarian(人道主义的) causes in the wake of the European refugee(难民) crisis.Britainpromised to spend 0.7 percent of state general product on aid, meaning the budget could rise sharply by the end of the decade as the economy grows.Mr Osborne also said more of the aid budget could be given to help local government with housing costs for incomers, without breaking international guidelines.“We will use the foreign aid budget to help with the costs of these refugees. People ask about the pressure on public services; we’ll have extra money to help with that.”The government was unable to give a figure for how much aid money could be handed to local authorities: it would depend on how many refugees are accepted.David Cameron, Prime Minister, will set out his position on aid for refugees today. It is reported thatBritainwill accept at least 10,000 extra people from camps on theSyriaborder. He will use a statement in the House of Commons to flesh out plans — announced inMadridon Friday — to take more people.A report inThe Sunday Timesthat the UK would take 15,000 Syrians, not far from the 18,000 figure demanded by the EU, was described by “Downing Street” as a “guess”.TheUKwill offer to resettle Syrians directly from refugee camps inJordan,LebanonandTurkey— but not those who have already reached the EU.12. What is the main idea of the passage?A. Britain tried to help refugees.B. People doubtBritain’s kindness.C. Britain tried to explain its behavior.D. Refugees like to live inBritain.13. What can we infer from the first two paragraphs?A. Britain’s economy grows rapidly.B. Britain will use little of its money to help refugees.C. Most countries are not willing to help refugees.D.Britainwill use more money to help refugees.14. Which of the following statements is TRUE?A. Britain will use foreign money to help refugees.B. Britain helps refugees following international guidelines.C. Britain will use foreign money to develop themselves.D. People ask to use public service money to help refugees.15. What can we know from the passage?A. Britain can hold 10,000 refugees at most.B. The number of refugees to be received is uncertain.C. House of Commons declare a general plan.D.Britaincan hold 15,000 refugees at most.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

浙江省嘉兴市第一学期期末检测高三数学试卷及答案解析[推荐].doc

浙江省嘉兴市第一学期期末检测高三数学试卷及答案解析[推荐].doc

嘉兴市2019-2020学年第一学期期末检测高三数学试题卷第Ⅰ卷一、选择题:本大题共10个小题,每小题4分,共40分.1.已知集合,,则A. B. C. D.【答案】D【解析】【分析】根据题干可知集合A,B,由集合的交集的概念得到结果.【详解】集合,,则.故答案为:D.【点睛】这个题目考查了集合的交集的求法,属于基础题.2.已知复数,(是虚数单位),则A. B. C. D.【答案】C【解析】【分析】根据复数的乘法运算得到结果.【详解】复数,, 则=4+3i.故答案为:C.【点睛】本题考查了复数的乘法运算,是基础题.3.双曲线的离心率是A. B. C. D.【答案】B【解析】【分析】根据双曲线方程得到参数a,b,c的值,进而得到离心率.【详解】双曲线,.故答案为:B.【点睛】这个题目考查了双曲线的方程的应用,属于基础题。

4.某几何体的三视图如图所示(单位:),则该几何体的体积(单位:)是A. B. 54 C. D. 108【答案】A【解析】【分析】根据三视图得到原图,再由四棱锥体积公式得到结果.【详解】根据三视图得到原图是如上图的一个四棱锥反转之后的图,正确的图应是三角形VAD为底面,是底边为6,高为的等腰三角形,点V朝外,底面ABCD是竖直的,位于里面边长为6的正方形,且垂直于底面VAD.该几何体是四棱锥,体积为故答案为:A.【点睛】这个题目考查了由三视图还原几何体的应用,考查了四棱锥的体积的求法,思考三视图还原空间几何体首先应深刻理解三视图之间的关系,遵循“长对正,高平齐,宽相等”的基本原则,其内涵为正视图的高是几何体的高,长是几何体的长;俯视图的长是几何体的长,宽是几何体的宽;侧视图的高是几何体的高,宽是几何体的宽.由三视图画出直观图的步骤和思考方法:1、首先看俯视图,根据俯视图画出几何体地面的直观图;2、观察正视图和侧视图找到几何体前、后、左、右的高度;3、画出整体,然后再根据三视图进行调整.5.已知等比数列的各项均为正,且,,成等差数列,则数列的公比是A. B. 2 C. D.【答案】C【解析】【分析】根据题意得到由数列各项是正数,可得到首项和公比均为正,进而化简为,求解即可.【详解】根据,,成等差数列得到=,再根据数列是等比数列得到,因为等比数列的各项均为正,故得到解得或-2(舍去),故得到公比为.故答案为C.【点睛】解决等差数列与等比数列的综合问题,关键是理清两个数列的关系:①如果同一数列中部分项成等差数列,部分项成等比数列,则要把成等差数列和成等比数列的项分别抽出,研究这些项与序号之间的关系;②如果两个数列是通过运算综合在一起的,就要从分析运算入手,把两个数列分割开,再根据两个数列各自的特征进行求解.6.函数的大致图象是A. B. C. D.【答案】B【解析】【分析】根据函数解析式,可代入特殊点,进行排除.【详解】根据函数表达式,当x>2时,函数值大于0,可排除A选项,当x<-1时,函数值小于0 故可排除C和D选项,进而得到B正确。

相关主题
  1. 1、下载文档前请自行甄别文档内容的完整性,平台不提供额外的编辑、内容补充、找答案等附加服务。
  2. 2、"仅部分预览"的文档,不可在线预览部分如存在完整性等问题,可反馈申请退款(可完整预览的文档不适用该条件!)。
  3. 3、如文档侵犯您的权益,请联系客服反馈,我们会尽快为您处理(人工客服工作时间:9:00-18:30)。

嘉兴市2019~2020学年第一学期期末检测高三语文参考答案(2020.1)本卷共9个选择题,其中第3小题2分,其余每小题均为3分,答案如下1.A(B项,藤蔓(wàn),蜡黄。

C项,行径(jìng),众志成城。

D项,好莱坞(wù),平民)2.D(“因而”表达因果关系,语境强调的是名诗佳句仍旧在心间流淌,此句和上句不存在因果关系,此处可用“依然”)3.B(“不学诗,无以言。

”中的句号放在引号后面)4.C(A项,并列不当,“场地”属于“资源”的一种。

B项,语序不当,应为“不仅集中检阅五年来美术界的最新创作成果,更体现出时代新风尚”。

D项,成分残缺,缺少“拓宽”的宾语)5.(3分)因本人疏忽,在“经典阅读读书马拉松”活动宣传海报上,我将原本“11月18日”举行的读书活动的日期误写成了“11月8日”,给大家造成了不便,我感到十分抱歉!请大家于1月18日18点30分,再聚此地,共读经典。

(陈述事件原由1分,道歉1分,邀请1分)6.(6分)(1)高校新生体测整体薄弱(有待提升),部分项目成绩堪忧(2分)(2)①从提升体测成绩的平均分和合格率考虑,高中学校应加大宣传与引导工作,积极利用体育课等时间提升训练效率,加强训练力度。

②从提升项目成绩的均衡性考虑,高中学校的师生都应重视加强薄弱项目如引体向上、仰卧起坐等的训练。

③从提升体测工作的有效性考虑,高中学校应该建立健全一套符合本校学情的体测工作考核制度,如将体测成绩与师生各类考核如评优评先等相关联。

④从提升体测工作的硬件配备角度考虑高中学校应加大相应体测设备与器材的有效投入。

(意思相近即可,写出1点得1分,2点得2分,3点得4分)7.D(A项,无中生有,“随意变形”限定错误。

项,强加因果,“因为所以的前后内容关系不成立,逻辑错误。

C 项,张冠李戴,“手价格”应为“屏幕价格”,对象错误8.B(曲解文意,专家认为不会带来新的换机潮有“贵”这一因素以及消费者并不会因为出现了一个全新的技术而抛弃原来还能使用的产品)9.(4分)(1)在硬件上,还需要突破频闪伤眼、内折等问题。

(2)在价格上,降低柔性屏的制作成本从而降低价格。

(3)在软件上,还需要开发更多彰显柔性屏特点的游戏、电子书等。

(4)在应用上,折叠屏手机、可穿戴设备、艺术表演等领域可以进行更深入的探索与实践。

(5)在技术上,打破外国垄断,走自主研发创新之路。

(每写出一点,得1分)10.(4分)(1)自然界的实实在在的风。

(2)内执着理想的强大动力。

(每点2分)11.(6分)(1)多用拟声词,给读者以身临其境之感如“啊啊啊”形象地描出弟弟奔跑时的快乐心情,以“呼呼”形象地写出了风的强劲有力,用“呼哧呼哧”生动地展现出弟弟迎风奔跑时气喘吁吁的特点。

(2)运用想象的手法,丰富文章内容。

作者由风的呼呼声想象风扯拽弟弟双脚的情态,凸显风的阻挠性;由弟弟的喘气声想象弟弟此时脸红却又追赶不上的状态,表现了弟弟奋力奔跑的形象。

(3)运用拟人的修辞,生动自然。

将风当作人来写,形象地表现了我和弟弟奋力前行时遇到的阻力。

(每点2分)12.(4分)(1)内容上,以沙蓬草的经历喻指人一生的经历。

(2)结构上,通过对沙蓬草随风流浪状态的猜想等引出下文对弟弟和村庄的怀念。

(每点2分)13.(6分)(1)以对过往的回忆,表达对曾经快乐生活的追忆。

(2)以当下生活的失落,表达对人生不可预知的感伤。

(3)以追忆过往、慨叹当下和想象回归,表达对生命成长过程的认知,即要珍惜生命中曾经拥有的美好。

(应有分析,有提炼,每点2分)14.B(:灾祸)15.C(项,之:取消句子独立性。

A项,而:表转折;表承接。

B项,于:介词,引出动作的对象:介词,表示比较。

D项,也:句中语气词,表停顿;句末语气词,表判断)16.A(“范文子胆小无能”表述错误,原文为“范文子疑若儒而无谋者矣”,另外导致晋国大乱的是“陵之功”,不是范文子)17.(3分)天欲亡之/则以美利诱之以得志/使之有功以骄士/玩于寇仇/而侮其人民/至于亡国杀身而不悟者/天绝之也(断对两处得1分,但断错一处需扣1分,扣完为止)18.(4分)(1)不贪求一时的功劳,用仁德爱护君主,保全国君的宗族后代,这就是能够顾全大局且使国家长治久安的良臣。

(“求”“全”和判断句式各1分,整体句意1分)(4分)(2)所以说战争的胜负,不足以成为国家强弱的依据,却足以成为国家是否安定的先兆。

(“兵”“治乱”“兆”各1分,整体句意1分)19.(2分)纤歌凝而白云遏(写错一字不得分)20.(6分)(1)动作描写,“偷泪”写出暗自垂泪的情态,揭示内心的痛苦。

(2)运用多种修辞手法。

如对比,将“满头”“满面”与“一”对比,写出在表面繁华富贵的背后孤独无助之痛苦;如比喻,将“泪珠”比作“珍珠”使痛苦可“”可感;夸张,以“百万”更显愁苦之多。

(3)联想想象,如果能将泪珠“串”起来,当会有百万之数来表现感伤的内心。

(每点2分)21.(2分)要守礼、要谦逊(如果“守礼”答成“有礼貌”不给分) 22.(4分)“修”指修养自己,做到以义为根本,按照礼的标准来实践,使自己具有谦逊、诚信等高尚品德,这是君子立身处世的关键所在。

(2分)“修己”的目的不仅在于提升自己,更在于为他人、为天下着想。

(2分) 23.(6分)(1)发愤忘食不知老之将至云尔(2)内无应门五尺之僮茕茕独立(3)哀斯墓之徒有其石也匹夫之有重于社稷也(4)冰泉冷涩弦凝绝别有幽愁暗恨生(5)疏影横斜水清浅暗香浮动月黄昏24.(60分)立意参考:从本题来看,表面上是有四种不同的回答来告诉我们成功”应该具备的条件,如果学生只从“信仰”“兴趣”“认真”“精确”的任意一点来回答,这样的文章算三类文章。

如果从杰出人物与普通人的角度来分析,不同的人群对待“成功”有不同的理解。

杰出人物更侧重于有远大的理想,取得不俗的贡献,而普通人更侧重于做好自己的本职工作。

“成就”有大小,“成功”义相同。

可记入二类文。

如果站位于“高中生”来看,他们虽然每个人的职业不同,但是在“崭新的时代”中每个人都有着自己的使命,他们都将自己的所作所为与时代紧密相连,那他更有机会取得“成功”。

也可讲到“理性的规范”固然可做得更好,但是“感性的追求”可让人走得更远。

此类文章如果文笔俱佳,可记入一类文。

参考译文估计敌方势力强弱,就知道军队的胜负,这是将帅的能力。

不贪求一时的功劳,用仁德爱护君主,保全国君的宗族后代,这就是能够顾全大局且使国家长治久安的良臣。

鄢陵之战,楚军早晨逼近晋军布阵。

各位将士请求出征迎战,唯独范文子不答应与楚军作战。

晋国的士兵打败了楚国。

楚共王被晋军射中眼睛,楚国司马子反丧命。

范文子在这场战争中看来好像胆小懦弱,没有谋略一样。

但是不到一年,三却被杀,晋厉公被杀,胥童被杀,栾书、中行偃几乎也不能免于祸乱,整个晋国大乱。

鄢陵之战的功劳,实在是造成晋国大乱的原因。

有了异于寻常的人,这样之后就有异于寻常的功勋、成绩。

而面对异于寻常的功勋、成绩,圣人会感到很惊异的。

夜光珠、明月璧,对于这些突如其来的财利,平常人也知道按剑警惕,更何况那些异于寻常的功勋、成绩呢!所以圣人面对非常之功必定反省自问:这是老天爷特别优待我还是祸害我呀?所以即使有大功劳,也不忘戒备警惕。

具有中等资质、不慧不痴的君主,急于创造功业,疏忽了老天的告诫,天天攻伐战争、残害人民以显示他们的威风志气,老天爷若要保全他,那就必定会在他的思想行为刚一冒头之时就折断它,打掉它的锋芒锐气,使他知道悔过老天爷若要灭亡他,就用美色、利益诱惑他让他志得意满,使他因为功劳而对下级骄横无礼,忽视仇敌的存在,而欺侮压迫他的百姓,到了亡国杀身的地步还不悔悟的,老天爷是要灭掉他。

唉,普通人家,一朝之间突然获得大量钱财,不是有大福,必定有大祸临头,为什么呢!那个获得的人,整天勤恳劳作,不过微薄的收入罢了。

收入微薄,所以需要花费应用的范围狭小。

无缘无故得到了大量钱财,岂不是让他骄傲而丢失了他原来惯守的生活原则。

因此,夺得天下当上皇帝的人,如果天下得来艰难,那么丧失也不容易,如果得来容易,那么丧失也会很容易。

汉高皇帝刘邦得到天下,亲自冒着箭石和秦、楚作战,转战五年,都未能称王天下。

等到平定天下之后,又发生了平城之围,所以一生都不扩大对外的侵略战争,老百姓也没有征战之苦。

后来的汉文帝、汉景帝也不提倡攻伐战争。

唐太宗举兵晋阳大破窦建德军,虏获王世充,所过之处,势如破竹。

但是天下刚刚安定,就对外斥逐周围的少数民族,出兵高昌,攻打突厥,终身都没有放弃过军事战争,国家多次处于战乱之中,是因为他亲眼目睹取得天下很容易。

所以说战争的胜负,不足以成为国家的强弱的依据,却足以成为国家安定是否的先兆。

因为有的国家因为打仗胜利而灭亡,也有的国家因为打仗失败而兴盛。

越王勾践为吴王夫差所败,栖于会稽,成为横行江淮的霸主。

黄池会盟,吴国之后连吃败仗亡国都是有原因使他们变成这样的。

以前虢公在桑田击败少数民族戎,晋国的ト偃预测其必亡,说:“这是老天爷有意夺他的镜子(使他看不到自己的危险之处)而加剧他的隐患。

”晋国果然灭掉虢。

这也是范文子不得不劝告厉公的原因。

劝告了却不被接纳,厉公又打了仗,范文子能逃得了必死的下场吗?假使他不死,那么厉公得志,必定先下手谋杀范文子,从赵盾一事中就可以知道了。

赵盾最终虽然免于一死,但是免不了弑君的恶名。

范文子的智慧,远远超过赵盾。

相关文档
最新文档