必修二第一单元练习题汇编
语文:第一单元测试(新人教必修2)
必修二第一单元一、基础题1.下列词语中加点的字,注音完全都正确的一项是()A.踱.步(dù)袅.娜(niǎo )峭楞楞..郁郁(wěng)..(léng)蓊蓊B.颤.动(zhàn)落蕊.(ruǐ)潭柘.寺(zhè)脉脉..含情(mò)C.涸辙.(hé)蕈菌.(sùn)廿.四桥(niàn)揠.苗助长(yàn)D..漪.澜(yī)深邃.(suì)黑.(xū)混混沌沌..(dùn)2.下列词语中没有错别字的一项是()A.寂寞幽辟弥望缕缕清香B.缈茫宛然歧韵平平仄仄C.嘻游瞥见镶嵌急不暇择D.嫩绿攀缘峻峭恍然大悟3.下列各句标点符号使用正确的一项是()A.这一片天地好像是我的,我也像超出了平常的自己,到了另一世界里。
我爱热闹,也爱冷静,爱群居,也爱独处。
B.秋之于人,何尝有别?更何尝有人种阶级之分呢?C.绿色是多宝贵的啊!它是生命,它是希望,它是慰安,它是快乐。
我怀念着绿色把我的心等焦了。
D.“行啊,”小王停了一会儿说:“叫我干什么我就干什么。
”4.下列各句空格处应填入的词语正确的一项是()①沿着荷塘,是一条曲折的小煤屑路。
这是一条的路;白天也少人走,夜晚更加寂寞。
②秋的味,秋的色,秋的意境与姿态,总是看不饱,尝不透,不到十足。
③我为了这永远向着阳光生长的植物不快,因为它损害了我的自尊心。
可是我囚系住它,仍旧让的枝叶垂在我的案前。
A.幽静品尝软弱B.幽僻品尝柔弱C.幽僻赏玩柔弱D.幽静赏玩软弱5.对下列词句的理解,错误的一项是()A.许多人都曾经被譬为瓦尔登湖,但只有少数几个人能受之无愧。
在作者看来,瓦尔登湖是纯洁、深刻、博大、富有生命力的象征,人类社会中,许多人受物质利益的诱惑,能像瓦尔登湖的贤者少之又少。
B.微风过处,送来缕缕清香,仿佛远处高楼上渺茫的歌声似的。
作者运用通感的手法,表现荷香的似有似无,时断时续的特点,启发读者丰富的联想和想像。
人教版高中英语必修二Unit1CulturalRelics单元练习
高中英语学习材料madeofjingetieji高中英语人教新课标必修2Unit1 Cultural Relics单元练习一、听力(听力)(共20小题;共20分)第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话。每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。每段对话仅读一遍。1. Where does the woman live now?A. In New York.B. In Chicago.C. In Boston.2. What do we know from the conversation?A. Both of them got good marks in the exam.B. One of them spilt the milk.C. Either of them got low marks in the exam.3. What was the climate like where the old couple lived?A. It was very rainy.B. It was very warm.C. It was very snowy.4. Why won't the woman order dessert?A. She thinks the dessert is too expensive.B. She doesn't want to gain weight.C. She is afraid of dropping the dessert on her clothes.5. Why did the woman get a new job in another country?A. Because she hated to work with the man here.B. Because she didn't like the culture here.C. Because she wanted to experience a new culture.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白,每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。每段对话或独白读两遍。听第6段材料,回答第6至8题。6. How does the man feel about David's way of sleeping?A. It's effective.B. It's strange.C. It's the best.7. How many hours does David sleep a day?A. Four.B. Six.C. Seven.8. What does the woman suggest at the end of the talk?A. People should develop a habit like David's.B. People need longer hours of sleep.C. People have different sleeping habits.听第7段材料,回答第9至11题。9. What is the woman going to do?A. Attend a party.B. Take a holiday.C. Go on a business trip.10. When does the woman plan to arrive?A. Late Friday.B. Midday Saturday.C. Saturday night.11. What is the weather like in the town during the day?A. Cold.B. Wet.C. Warm.听第8段材料,回答第12、13题。12. Why does the man thank the woman?A. She has helped him with his problems.B. She has invited him for coffee.C. She has agreed to see him on Monday.13. When does the conversation take place?A. Before class.B. After class.C. During class. 听第9段材料,回答第14至16题。14. What will the man do next morning?A. Meet Mr Cooper.B. Visit the national lab.C. Meet Bill Lyons.15. How will the man spend his Saturday?A. He will do some paperwork.B. He will take some rest.C. He will meet some visitors.16. What do we know about the woman?A. She's the man's wife.B. She's a business manager.C. She's a company secretary.听第10段材料,回答第17至20题。17. Where did the fire probably start?A. On the first floor.B. On the second floor.C. On the third floor.18. When was the building built?A. In 1718.B. In 1782.C. In 1930.19. What was the building used as at the time of the fire?A. A hotel.B. An old people's home.C. A history museum.20. Who is Andrew Bond?A. A newspaper reporter.B. The owner of the building.C. The head of the fire department.二、单词拼写(单句首字母填空)(共15小题;共15分)21. To my great surprise, he somehow managed to s the earthquake.22. My brother is the first student in our class to be s to take part in the English oral competition.23. The magazine will appear in a new d next month.24. On Christmas Eve, the whole family helped to d the house.25. There is no d about his honesty.26. The car is w at least 100,000 yuan.27. The bomb was timed to e during the rush-hour.28. She was Titanic, a ship which was said never to s .29. R the dishes from the table, please.30. His teacher gave him much v advice on his study.31. Up to now, there has been no e to prove that he has something to do with the theft.32. The two sides had a fierce d before they reached an agreement.33. Children have different s of learning: some learn by seeing, some by hearing, some by doing.34. Mary and Jane are sisters. The f is a singer; the latter is a dancer.35. The government holds an official r (接待) to welcome the foreign visitors.三、单词拼写(根据中文提示拼写单词)(共15小题;共15分)36. Why didn't you (选择) a better subject for your composition?37. My children, please r (除去) the snow from your shoes before coming in.38. He saw some (令人惊异的) sights at the zoo.39. I (怀疑) if there's anything more we can do tonight.40. I held my breath and (下沉) under the water.41. There is a heated (争论) on these issues.42. You have bought a new flat. Now have you decided how to design and (装饰) it?43. It is said that a (贵重的) diamond will be on show here soon.44. The (设计) of the Amber Room was in the style still popular today.45. He has developed his own (风格) of writing.46. China is a country (属于) to the developing ones.47. That house is very expensive, but I think it's (值) the money.48. The bomb was timed to (爆炸) during the rush hour.49. There is a lot of (证据) that stress is partly responsible for disease.50. A(n) (非正式的) party will be held next Sunday in his home.四、翻译(根据中文提示完成句子)(共15小题;共30分)51. 父亲是老师的那个女孩被北京大学录取了。
高一化学必修二第一章测试题含参考答案
第一章 物质结构 元素周期律一、选择题1.某粒子含有6个电子、7个中子,呈电中性,则它的化学符号可能是( )A .13AlB .13AlC .13CD .13C2.下列粒子半径最小的是( )A .Na +B .NaC .ClD .Cl -3.下列各组中属于同位素关系的是( )A .K 4019与Ca 4020B .T 2O 与H 2OC .K 4019与K 3919D .金刚石与石墨4.在元素周期表中位于金属元素和非金属元素交界处最容易找到的材料是( )A .制催化剂的材料B .耐高温、耐腐蚀的合金材料C .制农药的材料D .半导体材料5.下列递变规律不正确的是( )A .Na 、Mg 、Al 还原性依次减弱B .I 2、Br 2、Cl 2氧化性依次增强C .C 、N 、O 原子半径依次增大D .P 、S 、Cl 最高正价依次升高6.下列各组微粒具有相同的质子数和电子数的是( )A .OH -、H 2O 、F -B .NH 3、NH +4、NH -2C .H 3O +、NH +4、NH -2 D .HCl 、F 2、H 2S 7.X 元素的阳离子和Y 元素的阴离子具有相同的核外电子结构,下列叙述正确的是( )A .原子序数X <YB .原子半径X <YC .离子半径X >YD .原子最外层电子数X <Y8.下列各组中化合物的性质比较,不正确的是( )A .酸性:HClO 4>HBrO 4>HIO 4B .碱性:NaOH >Mg (OH )2>Al (O H )3C .稳定性:PH 3>H 2S >HClD .非金属性:F >O >S9.同周期的X 、Y 、Z 三种元素,已知其高价氧化物对应的水化物的酸性强弱顺序是:HXO 4>H 2YO 4>H 3ZO 4,则下列各判断中正确的是( )A .原子半径:X >Y >ZB .单质的非金属性:X >Y >ZC .气态氢化物稳定性:X <Y <ZD .原子序数:X <Y <Z10.铊是超导材料的组成元素之一,铊在周期表中位于第六周期,与铝是同族元素,元素符号是Tl,以下对铊的性质的推断不正确的是()A.铊是易导电的银白色金属B.能生成+3价离子化合物C.Tl(OH)3是两性氢氧化物D.Tl3+的氧化能力比Al3+弱11.下列说法错误的是()A.含有共价键的化合物一定是共价化合物B.在共价化合物中一定含有共价键C.含有离子键的化合物一定是离子化合物D.双原子单质分子中的共价健一定是非极性键12.下列说法中正确的是()A.非金属元素呈现的最高化合价不超过该元素原子的最外层电子数B.非金属元素呈现的最低化合价,其绝对值等于该元素原子的最外层电子数C.最外层有2个电子的原子都是金属原子D.最外层有5个电子的原子都是非金属原子13.某主族元素R的最高正价与最低负化合价的代数和为4,由此可以判断() A.R一定是第四周期元素B.R一定是ⅣA族元素C.R的气态氢化物比同族其他元素气态氢化物稳定D.R气态氢化物化学式为H2R 14.无机化学命名委员会(国际组织)在1989年作出决定,把长式周期表原先的主副族序号取消,由左到右按原顺序编为18列,稀有气体为第18列,按这个规定,下列说法正确的是A.第三列所含元素最多B.从上到下第一列元素单质熔点逐渐降低,而第17列元素单质熔点逐渐升高C.从上到下第一列元素单质密度逐渐升高,而第17列元素单质密度逐渐降低D.第18列最外层电子数均为8,化学性质十分稳定15.若短周期的两元素可形成原子个数比为2∶3的化合物,则这两种元素的序数之差不可能是()A.1B.3C.5D.616.a X n-和b Y m+为两主族元素的离子,它们的电子层结构相同,下列判断错误的是()A.原子半径X<Y B.a+n=b-mC.Y最高价氧化物的化学式为YO m D.X的氢化物的化学式为H n X17.右表为元素周期表前四周期的一部分,下列有关R、W、X、Y、Z五种元素的叙述中,正确的是()A.常压下五种元素的单质中,Z单质的沸点最高Array B.Y、Z的阴离子电子层结构都与R原子的相同C.Y的氢化物的沸点比H2O的沸点高D.Y元素的非金属性比W元素的非金属性强18.A、B、C、D、E是同一周期的五种主族元素,A和B的最高价氧化物对应的水化物均呈碱性,且碱性B>A,C和D的气态氢化物的稳定性C>D;E是这五种元素中原子半径最小的元素,则它们的原子序数由小到大的顺序是()A.A、B、C、D、E B.E、C、D、B、AC.B、A、D、C、E D.C、D、A、B、E二、填空题19.有下列物质:①Cl2②Na2O2③NaOH④HCl⑤H2O2⑥MgF2⑦NH4Cl(1)只由离子键构成的物质是________;(2)只由极性键构成的物质是________;(3)只由非极性键构成的物质是____;(4)只由非金属元素组成的离子化合物是____;(5)由极性键和非极性键构成的物质是______________;(6)由离子键和极性键构成的物质是_____________;(7)由离子键和非极性键构成的物质是________________。
必修二第一单元测试题
第一单元古代中国经济的基本结构与特点一、选择题1. 下列农具或农耕技术出现的先后顺序是()①青铜农具②在耕犁上安装犁壁③铁犁④曲辕犁A. ①②③④B. ②①④③C. ①③②④D. ①③④②2. 《吕氏春秋》载:“公作则迟,有所匿其力也;分地则速,无所匿其力也。
”这句话的实质问题是( )A. 封建生产方式比井田制进步B. 私田开垦越来越多C. 国君承认了私田主人的土地所有权D. 铁农具和牛耕出现,生产效率提高3. 鲁国的初税亩和商鞅变法“为田开阡陌封疆”的相似作用在于()A. 都以法律形式确立了封建土地所有制B. 都加强了奴隶主贵族对土地的控制权C. 都有利于井田制的瓦解和封建土地所有制的形成D. 都有利于鲁国和秦朝的税收额增加4. 下列能反映秦汉时期已经出现租佃关系的是()A. “为田开阡陌封疆”B. “耕豪民之田,见税十五”C. “田制不立”“不抑兼并”D.“上米贸银,别以下中者抵租”5. 汉高祖曾经令贾(商)人不得衣丝乘车,并用重税抑制他们。
孝惠、高后时,仍不准市井之子仕宦为吏。
这说明西汉初年实行()A. 休养生息政策B. 禁止经商政策C. 歧视商人政策D. 打击商业政策6. 下列表述能正确反映六朝时期经济发展特点的是()A. 全国经济重心南移B. 寺院经济衰落C. 城市中出现了柜坊D. 南北经济趋向平衡7. 北魏、隋唐实施均田制,政府向农民所授的土地是()A. 荒地和部分官田B. 地主的部分土地C. 官僚地主多占的土地D. 军队屯种的部分土地8. 下列关于我国坊市与城镇演变的叙述不正确的是()A.宋朝时市坊分开,交易活动不受官府直接管理B. 城市的职能主要是政治中心、军事重镇C. 宋代以前实行整齐划一的坊市制D. 明清时期城市的商业性、生产性增强9. 官营手工业和民营手工业的主要区别有()①资金来源②生产规模③对生产效益的重视程度④生产服务的对象A. ①②B. ③④C. ①②③D. ①②③④10. 据清代史料记载,台湾“百货皆取资于内地”;乾隆五十年浙江杭、嘉、湖三府歉收,“招商贩运闽省台湾仓谷,以资粜济”(粜指卖出粮食)。
(完整版)高中数学必修二第一章同步练习(含答案).docx
(完整版)高中数学必修二第一章同步练习(含答案).docx.1.1.1 柱、锥、台、球的的结构特征练习一一、选择题1、下列命题中,正确命题的个数是()(1 )桌面是平面;( 2)一个平面长 2 米,宽 3 米;( 3)用平行四边形表示平面,只能画出平面的一部分;(4)空间图形是由空间的点、线、面所构成。
A 、 1B、2C、3D、42、下列说法正确的是()A、水平放置的平面是大小确定的平行四边形B、平面ABCD就是四边形ABCD 的四条边围来的部分C、100 个平面重叠在一起比10 个平面重叠在一起厚D、平面是光滑的,向四周无限延展的面3、下列说法中表示平面的是()A、水面B、屏面C、版面D、铅垂面4、下列说法中正确的是()A、棱柱的面中,至少有两个面互相平行B、棱柱的两个互相平行的平面一定是棱柱的底面C、棱柱的一条侧棱的长叫做棱柱的高D、棱柱的侧面是平行四边形,但它的底面一定不是平行四边形5、长方体的三条棱长分别是AA /=1 , AB=2 ,AD=4 ,则从 A 点出发,沿长方体的表面到C/的最短距离是()A、5C、29D、376、若正棱锥的底面边长与侧棱长相等,则该棱锥一定不是()A、三棱锥B、四棱锥C、五棱锥D、六棱锥]7、过球面上两点可能作出球的大圆()A、0 个或 1 个B、有且仅有 1 个C、无数个D、一个或无数个8、一个圆柱的母线长为 5 ,底面半径为2,则圆柱的轴截面的面积为()A、10B、20二、填空题9、用一个平面去截一个正方体,截面边数最多是----------------条。
10、正三棱台的上、下底面边长及高分别为1、 2、 2,则它的斜高是------------。
11、一个圆柱的轴截面面积为Q,则它的侧面面积是----------------。
12、若圆锥的侧面面积是其底面面积的2 倍,则这个圆锥的母线与底面所成的角为----------------,圆锥的侧面展开图扇形的圆心角为----------------。
数学必修二第一章练习题及答案
(数学2必修)第一章空间几何体[基础训练A组]一、选择题1.有一个几何体得三视图如下图所示,这个几何体应就是一个( )A、棱台B、棱锥C、棱柱D、都不对主视图左视图俯视图2.棱长都就是得三棱锥得表面积为( )A、B、C、D、3.长方体得一个顶点上三条棱长分别就是,且它得个顶点都在同一球面上,则这个球得表面积就是( )A. B. C. D.都不对4.正方体得内切球与外接球得半径之比为()A. B. C. D.5.在△ABC中,,若使之绕直线旋转一周,则所形成得几何体得体积就是( )A、B、C、D、6.底面就是菱形得棱柱其侧棱垂直于底面,且侧棱长为,它得对角线得长分别就是与,则这个棱柱得侧面积就是( )A. B. C. D.二、填空题1.一个棱柱至少有_____个面,面数最少得一个棱锥有________个顶点,顶点最少得一个棱台有________条侧棱。
2.若三个球得表面积之比就是,则它们得体积之比就是_____________。
3.正方体中,就是上底面中心,若正方体得棱长为,则三棱锥得体积为_____________。
4.如图,分别为正方体得面、面得中心,则四边形在该正方体得面上得射影可能就是____________。
5.已知一个长方体共一顶点得三个面得面积分别就是、、,这个长方体得对角线长就是___________;若长方体得共顶点得三个侧面面积分别为,则它得体积为___________、三、解答题1.养路处建造圆锥形仓库用于贮藏食盐(供融化高速公路上得积雪之用),已建得仓库得底面直径为,高,养路处拟建一个更大得圆锥形仓库,以存放更多食盐,现有两种方案:一就是新建得仓库得底面直径比原来大(高不变);二就是高度增加(底面直径不变)。
ABDC E F(1) 分别计算按这两种方案所建得仓库得体积; (2) 分别计算按这两种方案所建得仓库得表面积; (3) 哪个方案更经济些?2.将圆心角为,面积为得扇形,作为圆锥得侧面,求圆锥得表面积与体积、(数学2必修)第一章 空间几何体 [综合训练B 组]一、选择题1.如果一个水平放置得图形得斜二测直观图就是一个底面为, 腰与上底均为得等腰梯形,那么原平面图形得面积就是( ) A. B. C. D.2.半径为得半圆卷成一个圆锥,则它得体积为( ) A. B. C. D.3.一个正方体得顶点都在球面上,它得棱长为, 则球得表面积就是( )A. B.C. D.4.圆台得一个底面周长就是另一个底面周长得倍,母线长为,圆台得侧面积为,则圆台较小底面得半径为( ) A. B. C. D.5.棱台上、下底面面积之比为,则棱台得中截面分棱台成两部分得体积之比就是( )A. B. C. D.6.如图,在多面体中,已知平面就是边长为得正方形,,,且与平面得距离为,则该多面体得体积为( ) A. B. C. D.二、填空题1.圆台得较小底面半径为,母线长为,一条母线与底面得一条半径有交点且成,则圆台得侧面积为____________。
(人教版最新)高中英语必修第二册 Unit 1单元测试01
Unit 1 单元测试一、阅读理解(共两节,满分35分)第一节(共10小题,每小题2.5分,满分25分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。
AFrom early times, man has been interested in art. People have often worked together to collect and save the world’s art treasures. Fine art treasures from many countries are kept in an art museum called the Louvre in Paris, France. The works of art have been collected by the people of France over many centuries. It is one of the biggest art museums in the world.The Louvre has not always been a museum. The first building was a fort(堡垒). In 1190, it was the king’s castle with high walls and a round tower. It had a moat(护城河)to keep out the enemies. Over the years, the number of buildings around the castle grew. By 1350, the castle no longer needed a fort. The Louvre became a palace home for French kings and queens.During the time of peace, new treasures were brought in. During the days of war, many treasures were stolen, and the buildings were damaged.When Francis I became the King of France in 1515, he brought in many artists from other countries. One of the artists was Leonardo da Vinci from Italy. Da Vinci’s Mona Lisa is the best known painting in the museum today.In 1793, the Louvre became a public museum. It is a place where art treasures are kept for everyone to enjoy. Every year millions of people from all over the world come to the Louvre to see the masterpieces.1. Most of works of art in the Louvre have been collected probably by ________.A. the French peopleB. Francis IC. Leonardo da VinciD. people of the world2. Why is it good for the works of art to be kept in public museums?A. The works of art will not be stolen.B. The works of art will not be damaged.C. Artists can study the works of art.D. Everyone has a chance to enjoy the works of art.3. According to the passage, which of the following statements is TRUE?A. The Louvre is always a museum since it was built.B. All the art treasures in the Louvre have been destroyed in the war.C. The Louvre was once the king’s castle in history.D. There is still a fort near the Louvre now.BWhat killed King Tut? Historians and scientists have long believed that ancient Egypt’smost famous king was probably murdered. But a recent scientific study claims to have found adifferent answer to this more than 3,300-year-old mystery. A team of researchers now say thatKing Tut, the boy ruler, died of complications (并发症)from a broken leg.Tut’s full name was Tutankhamun. He was just 9 years old when he became the ruler ofEgypt in 1333 BC. His treasure-filled tomb was discovered almost a century ago. It was filled with royal riches, including a solid-gold coffin, a gold mask, and piles of jewelry.Unfortunately Tut died at the age of 19. Many experts have thought that Tut was killed by one of his advisers, named Ay, who wanted to be king. But thanks to a major modern science project, it seems Ay is innocent.Researchers set out to solve the mystery of King Tut’s death by using the tools of science, including DNA tests and electronic scans of his mummy(木乃伊). Scientist Carsten Pusch carried out the tests on Tut for the new study. He thinks a broken leg led to the young king’s death. More than 100 walking sticks were found in King Tut’s tomb. This supports the team’s findings. But how could a person die from a simple broken leg?Pusch also found DNA evidence in Tut’s body that shows he had malaria, a disease carried by mosquitoes. Malaria seriously weakens the immune system(免疫系统).Pusch and his fellow researchers believe the malaria and the bone disease together caused the king’s fracture (骨折)to become deadly. Finally, the young king was just too weak to recover. So effects of the disease combined with the bad luck of a broken bone —not a jealous adviser —are likely the real, causes of King Tut’s death.4. It has long been believed by historians and scientists that ________.A. King Tut was the youngest ruler in the world historyB. King Tut was the richest ruler in the history of EgyptC. King Tut was murdered by one of his advisersD. King Tut was poisoned by one of his servants.5. With the help of modern technology, the new study discovered that the king ________.A. died directly of a disease called malariaB. died of complications from a broken legC. died of a simple cut in the broken legD. was bitten to death by deadly mosquitoes6. Researchers uncovered the mystery of King Tut’s death by ________.A. testing the King’s immune systemB. studying the walking sticks found in the tombC. performing experiments on mosquitoesD. applying DNA tests and electronic scan technology7. The passage mainly tells us about ________.A. a different answer to King Tut’s deathB. a famous boy king in ancient EgyptC. a treasure-filled tomb discovered in EgyptD. a team of researchers studying ancient tombsCIn the 1960s, while studying the volcanic history of Yellowstone National Park, Bob Christiansen became puzzled about something that, oddly, had not troubled anyone before: he couldn’t find the park’s volcano. It had been known for a long time that Yellowstone was volcanic in nature —that’s what accounted for all its hot springs and other steamy features. But Christiansen couldn’t find the Yellowstone volcano anywhere.Most of us, when we talk about volcanoes, think of the classic cone(圆锥体)shapes of a Fuji or Kilimanjaro, which are created when erupting magma(岩浆)piles up. These can form remarkably quickly. In 1943, a Mexican farmer was surprised to see smoke rising from a small part of his land. In one week he was the confused owner of acone five hundred feet high. Within two years it had topped out at almost fourteen hundred feet and was more than half a mile across. Altogether there are some ten thousand of these volcanoes on Earth, all but a few hundred of them extinct. There is, however, a second less known type of volcano that doesn’t involve mountain building. These are volcanoes so explosive that they burst open in a single big crack, leaving behind a vast hole, the caldera. Yellowstone obviously was of this second type, but Christiansen couldn’t find the caldera anywhere.Just at this time NASA decided to test some new high-altitude cameras by taking photographs of Yellowstone.A thoughtful official passed on some of the copies to the park authorities on the assumption that they might make a nice blow-up for one of the visitors’ centers. As soon as Christiansen saw the photos, he realized why he had failed to spot the caldera: almost the whole park —2.2 million acres —was caldera. The explosion had left a hole more than forty miles across —much too huge to be seen from anywhere at ground level. At some time in the past Yellowstone must have blown up with a violence far beyond the scale of anything known to humans.8. What puzzled Christiansen when he was studying Yellowstone?A. Its complicated geographical features.B. Its ever-lasting influence on tourism.C. The mysterious history of the park.D. The exact location of the volcano.9. What does the second paragraph mainly talk about?A. The shapes of volcanoes.B. The impacts of volcanoes.C. The activities of volcanoes.D. The heights of volcanoes.10. What does the underlined word “blow-up” in the last paragraph most probably mean?A. Hot-air balloon.B. Digital camera.C. Big photograph.D. Bird’s view.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
人教版高中英语必修第二册 Unit 1 单元测试题(含答案)
人教版高中英语必修第二册 Unit 1 单元测试题(含答案)(考试时间:90分钟满分:120分)第一部分阅读理解(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、B、C、D四个选项中,选出最佳选项。
AJourney Back in Time with ScholarsClassical Provence(13 days)Journey through the beautiful countryside of Provence, France, with Prof. Ori Z. Soltes. We will visit some of the best-preserved Roman monuments in the world. Our tour also includes a chance to walk in the footsteps of Van Gogh and Gauguin. Fields of flowers, tile-roofed(瓦屋顶) villages and tasty meals enrich this wonderful experience.Southern Spain(15 days)Spain has lovely white towns and the scent(芳香) of oranges, but it is also a treasury of ancient remains including the cities left by the Greeks, Romans and Arabs. As we travel south from Madrid with Prof. Ronald Messier to historic Toledo, Roman Mérida and into Andalucia, we explore historical monuments and architecture. China's Sacred Landscapes(21 days)Discover the China of "past ages," its walled cities, temples and mountain scenery with Prof. Robert Thorp. Highlights(精彩之处) include China's most sacred peaks at Mount Tai and Hangzhou's rolling hills, waterways and peaceful temples. We will wander in traditional small towns and end our tour with an exceptional museum in Shanghai.Tunisia(17 days)Join Prof. Pedar Foss on our in-depth Tunisian tour. Tour highlights include the Roman city of Dougga, the underground Numidian capital at Bulla Regia, Roman Sbeitla and the remote areas around Tataouine and Matmata, unique for underground cities. Our journey takes us to picturesque Berber villages and lovely beaches.1.What can visitors see in both Classical Provence and Southern Spain?A.Historical monuments.B.Fields of flowers.C.Van Gogh's paintings.D.Greek buildings.2.Which country is Prof. Thorp most knowledgeable about?A.France.B.Spain.C.China.D.Tunisia.3.Which of the following highlights the Tunisian tour?A.White towns.B.Underground cities.C.Tile-roofed villages.D.Rolling hills.BRome can be pricey for travelers, which is why many choose to stay in a hostel (旅社). The hostels in Rome offer a bed in a dorm room for around $25 a night, and for that, you’ll often get to stay in a central location (位置) with security and comfort. Yellow HostelIf I had to make just one recommendation for where to stay in Rome, it would be Yellow Hostel. It’s one of the best-rated hostels in the city, and for good reason. It’s affordable, and it’s got a fun atmosphere without being too noisy. As an added bonus, it’s close to the main train station.Hostel Alessandro PalaceIf you love social hostels, this is the best hostel for you in Rome. Hostel Alessandro Palace is fun. Staff members hold plenty of bar events for guests like free shots, bar crawls and karaoke. There’s also an area on the rooftop for hanging out with other travelers during the summer.Youth Station HostelIf you’re looking for cleanliness and a modern hostel, look no further than Youth Station. It offers beautiful furnishings and beds. There are plenty of other benefits, too; it doesn’t charge city tax; it has both air conditioning and a heater for the rooms; it also has free Wi-Fi in every room.Hotel and Hostel Des ArtistesHotel and Hostel Des Artistes is located just a 10-minute walk from the central city station and it’s close to all of the city’s main attractions. The staff is friendly and helpful, providing you with a map of the city when you arrive, and offering advice if you require some. However, you need to pay 2 euros a day for Wi-Fi.4.What is probably the major concern of travelers who choose to stay in a hostel?fort.B.Security.C.Price.D.Location.5.Which hotel best suits people who enjoy an active social life?A.Yellow Hostel.B.Hostel Alessandro Palace.C.Youth Station Hostel.D.Hotel and Hostel Des Artistes.6.What is the disadvantage of Hotel and Hostel Des Artistes?A.It gets noisy at night.B.Its staff is too talkative.C.It charges for Wi-Fi.D.It’s inconveniently located.CYears ago, I could not stick to exercising until I bought a CD called I Enjoy Exercise.I listened to it every day. I bought the CD because I wanted to run in a race and hopefully win!I had promised my 10-year-old son Todd that I would run in a race with him. Unfortunately, however, when that race came about, his left leg was hurt in a car accident. Without him running with me, although I took part in that race, yet I didn’t do quite well in it.While Todd couldn’t run together with me because of h is injury, he never forgot the promise I made for him. He was always asking me whether I would keep my promise when he recovered in the future. So I decided I was going to train and go all out to win the next race. What I needed was motivation (动力). It happened that one of my friends mentioned the CD which he liked very much, saying that he got a lot from the music in it when feeling down. So I bought it and listened to it while exercising every day.It was amazing what happened to my thinking as I listened to it daily. I started to think about the repeated words on the CD—“I enjoy exercise”. Instead of dreading exercise, I was thinking, “I enjoy exercise.”I found out how important words are that we play in our minds every day. I went from a person who seldom exercised to someone who started to exercise daily. Just think how our lives will improve if we reflect on the uplifting and motivating words of the famous works. I have found the positive messages have greatly improved my thinking and then changed my life.How did I do in that race, you might be thinking? I actually won the gold medal in my age group.7.Why did the author take part in the race by herself?A. She would like to win the race.B. She had a good talent for running.C. Her son got injured in a car accident.D. Her son was unwilling to run with her.8.How did the author get the motivation for training?A. By recalling some inspiring stories.B. By listening to the CD while running.C. By getting timely help from his friend.D. By forcing herself into keeping running.9.What does the underlined word “dreading” in paragraph 4 mean?A. Fearing.B. Improving.C. Preferring.D. Taking.10.What message does the author intend to deliver to us?A. It’s important to avoid injury while running.B. The motivating words make a difference to us.C. Parents should get along well with children.D. We can build up our bodies by regular exercise.DLocal officials in Beijing promised to further protect the city's cultural heritage, in particular the narrow streets known as hutongs.Hutongs are commonly found in the cities of North China, but they are at risk. Beijing is currently believed to have fewer than 1,000 hutongs, most of which are near the Imperial Palace. Only 60 years ago, the number was 3,250. In the old districts of Dongcheng and Xicheng, which cover 62 square kilometers, some people will be asked to move out from hutong houses to avoid further damage to the ancient architecture."On average more than 100,000 people visit the Imperial Palace during the National Day holiday. The visitors put pressure on the protection of cultural relics," said Huang Yan, director of the Beijing Municipal Commission of Urban Planning, adding that hutongs should be protected from human damage.The government focused on how the protection plans were carried out and how the management of the cultural heritage worked. Wang Shaofeng, head of the Xicheng district government, said the area has 182 cultural relics, many of which were built asfar back as the Yuan Dynasty (1271—1368). The district of Xicheng has 1.28 million residents in its 57 square kilometers of land. "The most efficient way is to decrease the local population to reduce the possibility of causing harm to the heritage," Wang said."Each community has been required to report the status of its cultural heritage, especially hutongs, and any action that will damage the heritage will be punished," Wang said.No one knows for sure how many hutongs will be left in the coming 100 years.11.How many hutongs have disappeared in the past sixty years in Beijing?A.Less than 1,000.B.About 2,000.C.More than 3,000.D.Over 4,000.12.According to Huang Yan, what is the main cause of the damage to cultural relics?A.Visitors' activities.B.Residents'attitude.munities' behaviour.D.The government's policy.13.Which of the following is a useful way to protect hutongs?A.To attract more visitors.B.To punish anyone damaging them.C.To increase the local population.D.To forbid everyone getting close to them.14.What will happen to hutongs in the near future?A.Only time will tell.B.No one will remember them.C.The number will be growing.D.Hutongs will disappear completely.第二节(共5小题;每小题2.5分,满分12.5分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
人教版高中英语必修二 Unit 1单元同步练习+答案
人教版高中英语必修二Unit1单元同步练习词句基础巩固练习一、单词拼写1.All of our cultural________(遗产)which is useful should be inherited, but in a critical way.2.Bethune started to________(抗议)but the general waved him to be silent.3.The________(委员会)was composed mainly of teachers and parents, who were likely to ignore the requirement of teenagers.4.Are there any________store(百货公司)around where you live?5.It is a good strategy to try and find time to read the________(文件)before the meeting.6.Reading was the________(入口)into a world which was so fascinating that she couldn’t get enough of it.7.Brazil began importing soybeans(大豆)to________(加工)at home.8.Wukong said a spell(咒语)to call the D________kingofthe Eastern Sea.9.I was impressed that the q________of their work was so high.10.May the friendship between the people of our two countries lastf________.二、单句语法填空1.Nowadays we are following the trend towards mastering strategies to study________(creative).2.It’s strange that he________(promote)in such a short time.3.Keep silent,for I am writing with reference to your job________(apply).4.As a matter of fact,his second novel________(establish)his fame as a writer in spring of1998.5.Geng Shuang said that we Chinese people had made a greater________(contribute)to mankind.6.What astonishes us is that many________(investigate)are conducted by Yuan Longping in such a short period.7.Lisa watched until the train________(disappear)from view.8.An urgent situation is that you need a________(profession)to sort out your finances.9.It was most generous of you________(forgive)me,but I would rather not be forgiven.10.In________(compare)with his brother,Edmund would have nothing to say.三、短语填空用方框内短语的适当形式填空,有两项为多余选项。
必修2 第一章单元测试卷
第一章单元测试卷第Ⅰ卷(选择题,共60分)一、选择题(本大题共12小题,每题5分,共60分)1.下列说法不正确的是()A.圆柱的侧面展开图是一个矩形B.圆锥的过轴的截面是一个等腰三角形C.直角三角形绕它的一条边旋转一周形成的曲面围成的几何体是圆锥D.圆台平行于底面的截面是圆面答案C2.如图所示的直观图的原平面图形是()A.任意三角形C.任意四边形B.直角梯形D.平行四边形答案B3.三视图如图所示的几何体是()A.三棱锥C.四棱台B.四棱锥D.三棱台答案B4.下图中的图形经过折叠不能围成棱柱的是()3 32 3 2 3 3答案 D5.水平放置的正方体的六个面分别用“前面、后面、上面、下面、左面、右面”表示,如图所示,是一个正方体的表面展开图,若图中“2”在正方体的上面,则这个正方体的下面是()A .1C .快B .6D .乐答案 B解析 如图所示,将题图折成正方体,可得 2 的下面是 6.32π6.已知正方体外接球的体积是 ,那么正方体的棱长等于()A .2 24 2 C.B.D.2 3 34 3 3答案 D解析 过正方体的相对侧棱作球的截面,可得正方体的对角线是球的直径.设正方体的棱长为 a ,球的半径为 R ,则有 2R = 3a ,所以 R3a 4π 3a 32π 4 3= ,则 ( )3= ,解得 a = .故选 D.7.一个圆锥的侧面展开图的圆心角为 90°,它的表面积为 a ,则它的底面积为( )522C.6D.34aA.a C.B. D.a3a4答案Aπ解析设圆锥的母线长为l,底面圆半径为r,则2πr=l·,故la=4r,由题意知πrl+πr2=a,所以πr2=.58.在正方体的八个顶点中,有四个顶点恰好是正四面体的顶点,则正方体的表面积与此正四面体的表面积之比为()A.32B.23答案A解析如图,设正方体的棱长为a,则正四面体A-B D C的11所有棱长均为2a.正方体的表面积S=6a2,13正四面体的表面积S=4××(2a)2=23a2.2∴S∶S=6a2∶23a2=3∶1.129.一个长方体去掉一个小长方体,所得几何体的正(主)视图与侧(左)视图分别如下图所示,则该几何体的俯视图为()3 3 33 3 3 3 3答案 C解析 由正(主)视图可知去掉的长方体在正对视线的方向,从侧(左)视图可以看出去掉的长方体在原长方体的左侧,由以上各视图的描述可知 C 选项的俯视图符合,C 正确.10.两个半径为 1 的铁球,熔化成一个大球,则大球的表面积为()A .6π3C .4 4πB .8πD .8 3 2π答案 C4π 8π 4π解析大球的体积是 2× ×13= ,设大球的半径为 R ,则有8π 3 3 3R 3= ,解得 R = 2,所以大球的表面积为 4π( 2)2=4 4π.故选 C.11.一平面截一球得到直径是 6 cm 的圆面,球心到这个平面的距离是 4 cm ,则该球的体积是()100π A. cm 3500π C. cm 3208πB. cm 3416 13πD. cm 33332C.3π2333 33222答案C解析设球的半径为R,则32+42=R2,故R=5.44500π所以球的体积为V=πR3=π×125=(cm3).12.一个四面体的所有棱长都为2,四个顶点在同一球面上,则此球的体积为()πA.2B.πD.3π答案C6262解析解法一:如下图,AD=,AO=AD=,SO=SA2-AO2=3.2233∴R2=(3-R)2+.∴R=.球的体积为π.解法二:构造棱长为1的正方体如上图,则C A BD为棱长为2的正11四面体,正方体的外接球也为正四面体的外接球.此时球的直径为33,因此球的体积为π.第Ⅱ卷(非选择题,共90分)二、填空题(本大题共4小题,每小题5分,共20分)13.设某几何体的三视图如下(尺寸的长度单位为m)6 2 23则该几何体的体积为________ m 3.答案 4解析 这是一个三棱锥,高为 2,底面三角形一边为 4,这边上的高1为 3,体积等于 ×2×4×3=4.614.若一个底面边长为 ,侧棱长为 6的正六棱柱的所有顶点都在一个球的面上,则此球的体积为________.答案 4 3π解析 2R =6( ×2)2+( 6)2=2 3,4∴R= 3,V = πR 3=4 3π. 球15.若干毫升水倒入底面半径为 2 cm 的圆柱形器皿中,量得水面的高度为 6 cm ,若将这些水倒入轴截面是正三角形的倒圆锥形器皿中,则水面的高度是________ cm.答案 616.如图是古希腊数学家阿基米德的墓碑文,墓碑上刻着一个圆柱,圆柱内有一个内切球,这个球的直径恰好与圆柱的高相等.相传这个图形表达了阿基米德最引以自豪的发现.我们来重温这个伟大发现:3 V4 2πR 3S 4πR 2 23 圆柱的体积与球的体积之比和圆柱的表面积与球的表面积之比分别为________,________.答案3 3 2 2解析 设球的半径为 R ,则圆柱的底面半径为 R ,高为 2R ,∴V 圆柱 =πR 2×2R=2πR 3,4π V 2πR 3 3 V = R 3,∴ 圆柱= = .球 球 3∵S圆柱 =2πR×2R +2×πR 2=6πR 2,S =4πR 2,球S 6πR 2 3 ∴ 圆柱= = .球三、解答题(本大题共 6 小题,共 70 分)17.(10 分)一个几何体的三视图及其尺寸如下(单位:cm),求该几何体的表面积和体积.解析 由三视图知道该几何体是圆锥,且母线长为 5 cm ,底面半径是 3 cm ,圆锥的高是 4 cm ,所以其表面积是 S =π×3×(3+5)= 表124π cm 2,其体积 V = π×32×4=12π cm 3.18.(12 分)正方体的每条棱长都增加 1 cm ,它的体积扩大为原来的8 倍,求此正方体的棱长.3 2 3 答案 1 cm分析 利用待定系数法求解.设出正方体的棱长,根据体积扩大为原来的 8 倍列方程,解方程得正方体的棱长.设正方体的棱长为 a cm ,由题意,得(a +1)3=8a 3,解得 a =1,即此正方体的棱长为 1 cm.19.(12 分)如下的三个图中,上面的是一个长方体截去一个角所得多面体的直观图,它的正视图和侧视图在下面画出(单位:cm).(1)在正视图下面,按照画三视图的要求画出该多面体的俯视图;(2)按照给出的尺寸,求该多面体的体积;解析 (1)如下图所示,(2)所求多面体体积V =V-V 长方体正三棱锥1 1 284=4×4×6- ×( ×2×2)×2= (cm 3).20.(12 分)根据三视图想象物体原形,并画出物体的实物草图:(1)三视图甲; (2)三视图乙.2223 3答案21.(12 分)已知六棱锥 P -ABCDEF ,其中底面 ABCDEF 是正六边形,点 P 在底面的投影是正六边形的中心,底面边长为 2 cm ,侧棱长为 3 cm ,求六棱锥 P -ABCDEF 的表面积和体积.解析 先求底面正六边形的面积,S六边形 ABCDEF=△6S OBC 1=6× ×2×2sin60°=6 3(cm 2),S 侧面=6S 1=6× ×2×△PCD CDPC 2-( )2=6 32-12=12 2(cm 2),∴S P -ABCDEF =S 六边形 ABCDEF +S 侧面=(6 3+12 2)(cm 2).在 △R t POC 中,PO = PC 2-OC 2= PC 2-BC 2= 9-4= 5(cm),∴V六棱锥 P -ABCDEF 1 1= Sh = ×6 3× 5=2 15(cm 3).22.(12 分)如图,是从上下底面处在水平状态下的棱长为 a 的正方体 ABCD -A B C D 中分离出来的.1 1 1 13 2 66(1)∠DC D 在图中的度数和它表示的角的真实度数都是 45°,对吗? 1 1(2)∠A C D 的真实度数是 60°,对吗?1 1(3)设 BC =1 cm ,如果用图示中这样一个装置来盛水,那么最多能盛多少体积的水?解析 (1)对;(2)对;(3)由题意知,以平面 B CD 为水平面,可盛最多体积的水,此时 V 1 11 1 1=VC -B D C =VC -B C D = × ×1×1×1= (cm 3). 1 1 1 1 1 11∴最多能盛 cm 3 的水.水。
高中英语人教版(2019)必修第二册Unit 1 单元习题精选(含答案)
Unit 1 单元习题精选一.单句语法填空1.Pictures are scanned into a form of _________(数据的) information that computers can recognize.1.His public ________(形象) is very different from the real person.2.Climbers took cover from the storm in a __________(山洞).3.The museum is open daily ____________(贯穿;从始至终) the year.4.Nowadays people are very concerned about the safety and _________(质量) of food.5.They also hope to _________(进一步地) educate people about the importance of safeguarding historic and cultural relics for future generations to understand and appreciate.6.He represents the __________(观点) of the youth of today.7.I hope our friendship will last __________(永远地).8.Students from different countries are working __________(creative) to protect a temple in China.9.Like so many __________(create) people he was never satisfied.1.digital;2.image;3.cave;4.throughout;5.quality;6.further;7.opinions;8.forever; 9.creatively; 10.creative;二.单句语法填空1.This is the room ________ my grandma used to live.2.The reason ________ he explained at the meeting was not sound. 3.The boy ________ I thought to be honest lied to me.4.This was the reason ________ he took apart the machine.5.My eldest son ________ work takes him all over the world is in New York at the moment.6.Their child is at the stage ________ she can say individual words but not full sentences.7.We have entered into an age ________ dreams have the best chance of coming true.8.The teacher is good because she always tries her best to be the one ________ classes are more active and lively with some stories and examples.9.The watch ________ was a gift from his father was very important to him and he was determined to find it.10.He started out as a basketball prodigy(神童)________ skipped college and took his talents directly to NBA.1.where 2.that/which 3.who/whom/that 4.why 5.whose 6.where7.when8.whose9.which/that10.who/that三.语法填空练习阅读下面短文,在空白处填入1个适当的单词或括号内单词的正确形式。
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第一单元练习题一、单选题(共12小题,每小题5.0分,共60分)1.随着碱金属原子序数的增大,其单质物理性质变化规律正确的是()A.熔点依次升高 B.熔点依次降低C.密度依次减小 D.密度依次增大2.下列事实中,能说明氯元素的非金属性比硫元素的非金属性强的是()①盐酸的酸性比氢硫酸的酸性强②氯化氢的稳定性比硫化氢强③相同条件下,氯气与铁反应生成氯化铁,而硫与铁反应生成硫化亚铁④氯气能与硫化氢反应生成单质硫⑤酸性强弱:硫酸<高氯酸A.①②③④ B.②③ C.①②③④⑤ D.②③④⑤3.某原子的原子结构示意图,该元素在周期表中的位置为()A.第三周期,ⅤA B.第五周期,ⅢB族C.第三周期,ⅤB族 D.第五周期,ⅢA族4.下列叙述中,不正确的是()A.共价化合物中不可能含有离子键B.硫酸分子中有H+和SO两种离子C.某元素原子的最外层只有一个电子,它跟卤素可能形成离子键,也可能形成共价键D.共价键存在于非金属元素形成的化合物或单质中5.A、B、C都为短周期元素,它们在周期表中的位置如下图所示:已知A、B两元素原子序数之和等于C元素的原子序数,下列说法正确的是()A.元素A的原子序数7 B.元素B位于第ⅥA族C.元素C位于第四周期 D.元素C原子最外层有5个电子6.下列说法能够说明氮的非金属性比磷强的是()A.硝酸比磷酸更稳定 B.硝酸的氧化性比磷酸强C.硝酸的酸性比磷酸强 D.硝酸比磷酸容易挥发7.下列微粒的结构示意图中,表示氟离子的是()A. B. C. D.8.有X、Y、Z、W四种元素,它们的原子序数分别为6、10、11、17,下列判断错误的是()A. X和W能形成共价化合物 B. Z和W能形成离子化合物C. Y和Z不能形成化合物 D. Y分子中存在共价键9.不具有放射性的同位素称之为稳定同位素,稳定同位素分析法近20年来在植物生理学、生态学和环境科学研究中获得广泛应用。
如在陆地生态系统研究中,2H、13C、15N、18O、34S等常用作环境分析指示物。
下列有关说法正确的是()A.34S原子核内中子数为16 B.1H O和1H O的相对分子质量不同C.13C和15N原子核内的质子数相差2 D.2H+结合OH-的能力比1H+的更强10.下列叙述正确的是()A.同一元素的各种同位素的性质相同B.所有主族元素的原子,形成简单离子时,化合价和它的族序数相等C.同一周期中的第ⅡA族和第ⅢA族元素的原子序数相差1或11或25D.因为酸性:HCl>H2S,所以非金属性:Cl>S11.下列说法中正确的是()A.在钠、磷、氯、氩四种元素中,最高正化合价数值最大的是磷B.在氮、氟、镁、氯四种元素中,原子半径最小的是镁C.原子序数从3~10的元素,随核电荷数的递增,原子最外层电子数递增D.硅烷(SiH4)比甲烷(CH4)稳定12.关于碱金属单质的下列叙述中不正确的是()A.都是活泼金属 B.都具有强还原性C.在空气中都能稳定存在 D.都能与水发生置换反应二、填空题13.某元素的原子结构示意图为,该元素的原子核内有____________个质子,核外共有________个电子层,最外电子层上有________个电子,该元素是________。
14.下面是同学们熟悉的物质:①氧气②金刚石③溴化钠④硫酸⑤碳酸钠⑥氯化铵⑦硫酸氢钠⑧单质氖⑨过氧化钠⑩氢氧化钠。
(1)这些物质中,只含有共价键的是________;只含有离子键的是________;既含有共价键又含有离子键的是________;不存在化学键的是________。
(2)属于共价化合物的是________;属于离子化合物的是________。
(3)将硫酸氢钠溶于水,破坏了硫酸氢钠中的________,写出其电离方程式_______________;硫酸氢钠在熔融状态下电离,破坏了________,写出其电离方程式____________________。
三、推断题(共2小题,每小题10.0分,共20分)15. X、Y、Z、M、N为短周期的五种主族元素,其中X、Z同主族,Y、Z同周期,M与X,Y既不同族,也不同周期。
X原子最外层电子数是核外电子层数的三倍,Y的最高化合价与其最低化合价的代数和等于6。
N是短周期主族元素中原子半径最大的非金属元素。
(1)请写出下列元素的元素符号:X________,Y________,M________。
(2)请写出下列反应的离子方程式:①N的氧化物与氢氧化钠溶液反应________________________。
②Y的单质与水反应______________________。
(3)Y与Z相比,非金属性较强的元素是________,可以证明该结论的实验是(用离子方程式表示)__________________________。
16.已知X、Y、Z都是短周期元素,它们的原子序数依次递增,X原子的电子层数与它的核外电子总数相同,而Z原子的最外层电子数是次外层电子数的三倍,Y和Z可以形成两种以上气态化合物。
(1)X是________(填名称,下同),Y是________,Z是________。
(2)由Y和Z组成,且Y和Z质量比为7∶20的化合物的化学式(分子式)是________。
(3)由X、Y、Z中的两种元素组成,且与X2Z分子具有相同电子数的两种离子是________和________。
(4)X、Y、Z可以形成一种盐,此盐中X、Y、Z元素的原子个数比为4∶2∶3,该盐的化学式是________。
答案解析1.【答案】B【解析】碱金属元素随着原子序数的增大,其单质的熔点、沸点依次降低,密度依次增大(但钾反常)。
2.【答案】D【解析】氯气能从硫化氢中置换出单质硫、最高价氧化物的水化物高氯酸的酸性比硫酸强、气态氢化物氯化氢的稳定性比硫化氢强,都能说明氯元素的非金属性比硫元素的非金属性强;相同条件下,氯气可将铁氧化为+3价,硫将铁氧化为+2价,氯气的氧化性比硫强,即氯元素的非金属性比硫强强;盐酸的酸性比氢硫酸的酸性强,不能说明氯元素的非金属性比硫强。
3.【答案】A【解析】由原子结构示意图可知,该原子有三个电子层(位于第三周期),最外层有5个电子(位于第Ⅴ三A族)。
4.【答案】B【解析】A项正确。
分子中没有离子,B项错。
最外层只有一个电子的可能是H,也可能是碱金属元素,所以它们与卤素可能形成共价键,也可能形成离子键,C项正确、D项正确。
5.【答案】A【解析】由图可知,A和B位于第二周期,C位于第三周期。
设A的原子序数为x,则B的原子序数为(x+2),C的原子序数为(x+1+8)=x+9,则x+(x+2)=x+9,x=7。
所以A、B、C的原子序数分别为7、9、16,对应的元素分别为氮、氟、硫。
6.【答案】C【解析】比较判断元素非金属性强弱的依据:其单质与氢气反应的难易程度、生成氢化物的稳定性强弱、最高价氧化物水化物的酸性强弱、对应阴离子的还原性强弱、单质间的置换反应、与变价金属反应后金属化合价的高低。
氮、磷元素的最高价含氧酸的稳定性、氧化性、挥发性等都不能说明它们非金属性的强弱。
7.【答案】A【解析】氟的原子核内有9个质子,氟离子核外共有10个电子。
8.【答案】D【解析】根据原子序数可得X、Y、Z、W分别为C、Ne、Na、Cl;C和Cl可形成共价化合物CCl4;Na和Cl能形成离子化合物NaCl;Na和Ne不能形成化合物;Ne为稀有气体,分子中不存在共价键。
9.【答案】B【解析】34S为硫元素的一种核素,其质子数为16,中子数为34-16=18;1H O的相对原子质量为18,1H O的相对原子质量为20;13C的质子数为6,15N质子数为7,它们的质子数相差1;2H+与1H+都为氢离子,它们与氢氧根离子的结合能力相同。
10.【答案】C【解析】同一元素同位素的化学性质相同同,物理性质不同;主族元素形成的简单阴离子的化合价与族序数不相等(如硫离子、氯离子等);ⅡA族、ⅢA族元素原子序数可相差1(二、三周期)、11 (四、五周期)、25(六、七周期);氢化物水溶液(不是最高价氧化物的水化物)的酸性强弱,不能比较元素非金属性的强弱。
11.【答案】C【解析】最高正价:钠(+1价)、磷(+5价)、氯(+7价)、氩(常为0价),氯元素最高正价数值最大;在氮、氟、镁、氯四种元素中,原子半径Mg>N>F,Mg>Cl>F,原子半径最小的是氟;碳和硅位于同一主族,碳的非金属性比硅强,甲烷比硅烷稳定。
12.【答案】C【解析】碱金属的原子在化学反应中都易失去最外层上的一个电子,其单质都具有强还原性,在空气中都易被氧化,都能与水发生置换反应生成强碱和氢气。
13.【答案】1636硫【解析】该元素的核电荷数为16,为硫元素,其原子核外共有3个电子层,最外电子层上有6个电子。
14.【答案】(1)①②④③⑤⑥⑦⑨⑩⑧(2)④③⑤⑥⑦⑨⑩(3)离子键和共价键NaHSO4===Na++H++SO离子键NaHSO4===Na++HSO【解析】氧气、金刚石等单质中只含有共价键;硫酸是共价化合物,含有共价键;溴化钠是离子化合物,只含有离子键;碳酸钠、氯化铵、硫酸氢钠、过氧化钠、氢氧化钠等都是离子化合物,含有离子键和共价键;稀有气体单质氖是单原子分子,不存在化学键。
硫酸氢钠溶于水电离时,Na+与HSO之间的离子键被破坏,HSO中H+与SO之间的共价键也被破坏;而在熔融状态电离时只断裂离子键。
15.【答案】(1)O;Cl;H(2)①SiO2+2OH-===SiO+H2O②Cl2+H2O鸠馠++Cl-+HClO (3)Cl(或氯)Cl2+S2-===2Cl-+S↓【解析】X原子最外层电子数是核外电子层数的三倍,则X为氧,X、Z同主族,Z为硫;Y的最高化合价与其最低化合价的代数和等于6,则Y为氯;M与X,Y既不同族,也不同周期,则M 为氢;N是短周期主族元素中原子半径最大的非金属元素,则N为硅。
二氧化硅与氢氧化钠溶液反应生成硅酸钠和水;氯气与水反应的生成盐酸和次氯酸。
氯气能从硫化钠溶液置换出单质硫,说明氯元素的非金属性比硫强。
16.【答案】(1)氢氮氧 (2)N2O5 (3)NH OH-(4)NH4NO3【解析】原子的电子层数与其核外电子总数相同的短周期元素X为氢元素,原子最外层电子数是次外层电子数的三倍的元素Z为氧元素,能与Z(氧元素)形成两种以上气态化合物的元素Y为氮元素。