软件测试实践报告

软件测试实践报告学号：姓名：指导老师：问题描述：完成一个银行贷款利息计算的程序，具体计算方式如下：贷款利息=贷款金额*利率不同基本点下的利率不同，基本点为13及以上的年利率为5.56%，基本点为13以下的年利率为6.05%基本点具体计算情况如下：输入范围：1、年龄：输入为整数，有效范围为20-992、信用度：输入为整数，有效范围1-103、房产所有情况：有效值只能取“property”（有房产）“nonproperty”(无房产)源代码：import java.util.*;import java.io.*;public class loanFee {public double loanStype(int loanPoint){//根据基本点决定利率double loanRate ;if(loanPoint>=13){loanRate = 0.0556 ;}else{loanRate = 0.0605 ;}return loanRate ;}public int loanPoint(int loanAge,int loanCre,int loanProperty){//计算基本点int loanPoint ;loanPoint = loanAge + loanCre + loanProperty;return loanPoint ;}public int loanAge(int age){//根据年龄判断点数int loanAge ;if(age<20 || age>99){loanAge = -20 ;return loanAge ;}if(age>=20 && age<=32){//年龄20-32基本点为2loanAge = 2 ;}else{if(age>=33 && age<=50){//年龄33-50基本点为6loanAge = 6 ;}else{//年龄在50以上基本点为4loanAge = 4 ;}}return loanAge ;}public int loanCre(Int credit){//根据信用度判断点数int loanCre ;if( credit<1 || credit>10){loanCre = -20 ;return loanCre ;}if(credit>=1 && credit<=5){loanCre = 3 ;}else{loanCre = 5 ;}return loanCre ;}public int loanProperty(String housing){//根据房产所有状况判断点数int loanProperty ;if( !housing.equals("property")&& !housing.equals("nonproperty")){loanProperty = -20 ;return loanProperty ;}if(housing.equals("property")){loanProperty = 5 ;}else{loanProperty = 3 ;}return loanProperty ;}public double finalResult(int age,int credit,String housing, double amount){double result ;int point = loanPoint(loanAge(age), loanCre(credit),loanProperty(housing) ;if(point <-1){System.out.print("Input error!") ;System.exit(0) ;}double stype = loanStype(point) ;result = amount * stype ;//贷款金额*利率return result ;private int age ;private int loanCre ;private String housing ;private double amount ;public static void main(String[] args) throws FileNotFoundException {Scanner in = new Scanner(new File("loanTest.txt")) ;int index ;loanFee fee = new loanFee() ;while(in.hasNextLine()){index = in.nextInt();fee.age = in.nextInt() ;fee.credit = in.next() ;fee.housing = in.next() ;fee.amount = in.nextDouble() ;System.out.println(index + " The Loan fee = " +fee.finalResult(fee.age, fee.credit,fee.housing, fee.amount)) ;}}}测试：1.黑盒测试：考虑到变量之间主要采用物理量以及它们之间的依赖关系，决定采用弱健壮等价类测试以及决策表进行测试。

输入变量等价类划分：有效等价类：年龄：A1={20<=age<=32}A2={33<=age<=50}A3={age>50}信用度：C1={1<=credit<=5}C2={6<=credit<=10}房产所有情况：P1={housing=property}P2={housing=nonproverty}无效等价类：年龄：A4={age<20}A5={age>=100}信用度：C3={credit<1}C4={credit>10}房产所有情况：P3={housing！=规定字符串}1、弱健壮等价类测试：2、基于决策表的测试：基于决策表的用例，由决策表共得7个2、白盒测试：采用DD-路径图和基路径来完成测试1、程序图：（见附表）2、DD-路径图：（见附表）主要代码段：1 public double loanStype(int loanPoint){//根据基本点决定利率double loanRate ;2 if(loanPoint>=13){loanRate = 0.0556 ;}3 else{loanRate = 0.0605 ;}4 return loanRate ;}5 public int loanPoint(int loanAge,int loanCre,int loanProperty,int insuFosterNum){//计算基本点int loanPoint ;6 loanPoint = loanAge + loanCre + loanProperty;7 return loanPoint ;}8 public int loanAge(int age){//根据年龄判断点数int loanAge ;9 if(age<20 || age>99){loanAge = -20 ;return loanAge ;}10 else{11 if(age>=20 && age<=32){//年龄20-32基本点为2loanAge = 2 ;}12 else{13 if(age>=33 && age<=50){//年龄33-50基本点为6loanAge = 6 ;}14 else{//年龄在50以上基本点为4loanAge = 4 ;}}15 return loanAge ;}16 public int loanCre(Int credit){//根据信用度判断点数int loanCre ;17 if( credit<1 || credit>10){loanCre = -20 ;return loanCre ;}18 else{19 if(credit>=1 && credit<=5){loanCre = 3 ;}20 else{loanCre = 5 ;}21 return loanCre ;}22 public int loanProperty(String housing){//根据房产所有状况判断点数int loanProperty ;23 if( !housing.equals("property")&& !housing.equals("nonproperty")){loanProperty = -20 ;return loanProperty ;}24 else{25 if(housing.equals("property")){loanProperty = 5 ;}26 else{loanProperty = 3 ;}27 return loanProperty ;}28 public double finalResult(int age,int credit,String housing,double amount){double result ;29 int point = loanPoint(loanAge(age), loanCre(credit),loanProperty(housing) ;30 if(point <-1){31 System.out.print("Input error!") ;32 System.exit(0) ;}33 double stype = loanStype(point) ;34 result = amount * stype ;//贷款金额*利率35 return result ;}3、基路径可行的基路径共有8条：。