2013学年第一学期徐汇区学习能力诊断卷(理科)
上海市徐汇区2013届高三上学期期末教学质量调研数学理试题
2012学年第一学期徐汇区高三年级数学学科学习能力诊断卷 (理)(考试时间:120分钟,满分150分) 2013.1一.填空题(本大题满分56分)本大题共有14题,考生应在答题纸相应编号的空格内直接填写结果,每个空格填对得4分,否则一律得零分.1.方程组2132x y x y -=⎧⎨+=-⎩的增广矩阵是__________________.【答案】211132-⎛⎫⎪-⎝⎭【Ks5U 解析】根据增广矩阵的定义可知方程组的增广矩阵为211132-⎛⎫⎪-⎝⎭。
2. 已知幂函数()f x 的图像过点18,2⎛⎫ ⎪⎝⎭,则此幂函数的解析式是()f x =_____________.【答案】13x-【Ks5U 解析】设幂函数为()f x x α=,则由1(8)2f =得182α=,即3122α-=,所以31α=-,13α=-,所以13()f x x -=。
3.(理)若θ为第四象限角,且4sin()25πθ+=,则sin 2θ=___________. 【答案】2425-【Ks5U 解析】由4sin()25πθ+=得4cos 5θ=,因为θ为第四象限角,所以3sin 5θ=-,所以3424sin 22sin cos 2()5525θθθ==⨯-⨯=-。
4.若抛物线22(0)y px p =>的焦点与双曲线221610x y -=的右焦点重合,则实数p 的值是 . 【答案】8【Ks5U 解析】抛物线的焦点坐标为(,0)2p,在双曲线中22610a b ==,,所以22216c a b =+=,所以4c =,即双曲线的右焦点为(4,0),所以482pp ==,。
5.函数()sin()(0,0,||)2f x A x A πωϕωϕ=+>><的部分图像如右图所示,则()f x = _________.【答案】()2sin4f x x π=【Ks5U 解析】由图象可知26242TA ==-=,,即周期8T =,由28T πω==得,4πω=,所以()2s i n ()4f x x πϕ=+,有(2)2f =得,(2)2s i n (2)24f πϕ=⨯+=,即s i n ()12πϕ+=,所以22k k Z ππϕπ+=+∈,,所以k k Z ϕπ=∈,,因为2πϕ<,所以0ϕ=,所以()2sin 4f x x π=。
上海市徐汇区2013—2014学年第一学期期末学习能力诊断卷 初三物理学科
6.将一个重10牛的容器放置在水平地面上,再向容器中注入20牛的水(水不溢出),则注水后容器对水平地面的压力
A.一定为20牛B.一定为30牛C.可能为25牛D.可能大于30牛
7.用铝、铁、铜和铅(已知ρ铅>ρ铜>ρ铁>ρ铝)分别制成体积相等的实心物块,其中质量最大的是
A.铝块B.铁块C.铜块D.铅块
8.自动电压力锅当锅内压强过大或温度过高时,发热器都会停止工作,压强过大时电键S过压自动断开,温度过高时电键S过热自动断开。图1中反映了压力锅内部电路的是
9. 在图2所示的电路中,电源电压保持不变,电键S闭合后,有一个电表的指针没有发生偏转。移动滑动变阻器的滑片,此时观察到只有一个电表指针的位置在改变,则一定是
A.变阻器R1短路
B.变阻器R1断路
C.电阻R2短路
D.电阻R2断路
10.如图3所示,放在水平地面上的均匀实心正方体甲、乙对地面的压强相等。现将两物体均沿水平方向切去一部分,则
A.若切去相等质量,甲被切去的厚度一定小于乙
B.若切去相等质量,甲被切去的厚度可能小于乙
C.若切去相等体积,甲对地面的压强一定小于乙
(12)。
③小汇将重物放在一块长薄板上,观察到图19(a)所示的现象,将薄板的一端抬高,使支持面倾斜,观察到图19(b)所示的现象。根据上述实验现象,可初步判断:物体对支持面的压力大小可能与支持面的倾角(13)(选填“有关”或“无关”)。
④在进一步的实验探究中,小汇测出了斜面的倾角θ(注:倾斜的支持面称为斜面),如图19(c)所示,并改变θ继续实验,同时用力传感器测出相应的压力大小,实验数据记录在表二中。
①甲的质量。
②水对容器底部的压强。
历年上海一模、二模专题汇编:矩阵与行列式【S】
高中数学上海市重点高中辅导讲义汇编学科:数学专题:矩阵行列式版本:学生用书姓名:年级:高二上海市各区县2016届高三上学期期末考试数学理试题汇编矩阵与行列式1、(宝山区2016届高三上学期期末)已知矩阵A =⎪⎪⎭⎫ ⎝⎛421y ,B =⎪⎪⎭⎫ ⎝⎛876x ,AB =⎪⎪⎭⎫⎝⎛50432219, 则x+y = .2、(崇明县2016届高三上学期期末)函数sin 2()1x f x =- cosx 的最小正周期是 .3、(宝山区2016届高三上学期期末)已知,0,>t ω函数xx x f ωωcos 1sin 3)(=的最小正周期为π2,将)(x f 的图像向左平移t 个单位,所得图像对应的函数为偶函数,则t 的最小值为 .4、(虹口区2016届高三上学期期末)行列式12cos()tan 25cos cot()x x x x ππ+-的最大值为______.5、(黄浦区2016届高三上学期期末)直线321x y=的一个方向向量可以是 .6、(嘉定区2016届高三上学期期末)已知31cos 75sin sin 75cos =︒-︒αα,则=+︒)230cos(α_______.7、(金山区2016届高三上学期期末)若线性方程组的增广矩阵为⎪⎪⎭⎫ ⎝⎛212332c c ,解为⎩⎨⎧==12y x , 则c 1–c 2= .8、(金山区2016届高三上学期期末)行列式dc b a (a 、b 、c 、d ∈{–1,1,2})所有可能的值中,最小值为 .9、(闵行区2016届高三上学期期末)函数()cos()sin sin()cos x xf x x xπ-=π+的最小正周期T = .10、(浦东新区2016届高三上学期期末)若复数z 满足1012ii z=-(i 为虚数单位),则z = . 11、(青浦区2016届高三上学期期末)方程组35604370x y x y ++=⎧⎨--=⎩的增广矩阵是____________.12、(松江区2016届高三上学期期末)行列式cos 20sin 20︒︒ sin 40cos 40︒︒的值是 .13、(徐汇区2016届高三上学期期末)若三条直线03=++y ax ,02=++y x 和012=+-y x 相交于一点,则行列式11221131-a的值为__________.14、(杨浦区2016届高三上学期期末)已知矩阵1012A ⎛⎫= ⎪-⎝⎭,2413B ⎛⎫= ⎪-⎝⎭,则=+B A _____________.15、(长宁区2016届高三上学期期末)关于x 的不等式的解集为.(1)求实数a ,b 的值; (2)若为纯虚数,求tan α的值.【例题解析】1. 【上海市十三校2013年高三调研考数学试卷(文科)】已知二元一次方程组的增广矩阵是421m m mm +⎛⎫⎪⎝⎭,若该方程组无解,则实数m 的值为___________.2. 【2013学年第一学期徐汇区学习能力诊断卷高三年级数学学科(文科)】计算:122423432⎛⎫⎛⎫⋅+ ⎪ ⎪⎝⎭⎝⎭= .3. 【黄浦区2013—2014学年度第一学期高三年级学业质量调研数学试卷(文科)】三阶行列式45sin 2cos 610sin ---x x x ()R x ∈中元素4的代数余子式的值记为()x f ,则函数()x f 的最小值为4. 【黄浦区2013—2014学年度第一学期高三年级学业质量调研数学试卷(文科)】各项都为正数的无穷等比数列{}na ,满足,,42t a m a ==且⎩⎨⎧==ty m x 是增广矩阵⎪⎪⎭⎫⎝⎛-2221103的线性方程组⎩⎨⎧=+=+2222111211c y a x a c y a x a 的解,则无穷等比数列{}na 各项和的数值是 _________.5. 【上海市杨浦区2013—2014学年度第一学期高三年级学业质量调研数学试卷(文科)】若行列式124012x -=,则x = .2014年高三二模汇编——矩阵、行列式1、(2014宝山四区文理1). 二阶行列式ii i ++-1101的值是 . (其中i 为虚数单位)2、(2014长宁二模文理7)对于任意),1()1,0(∞+∈ a ,函数)1(log 111)(--=x x f a 的反函数)(1x f -的图像经过的定点的坐标是______________.3、(2014奉贤二模理10)、已知函数cos ()sin x f x x=, 则方程()021cos =+⋅x x f 的解是________.4、(2014奉贤二模文10)、将函数cos ()sin x f x x=的图像向左平移m 个单位(0)m >,若所得图像对应的函数为偶函数, 则m 的最小值是________.5、(2014虹口二模5文6)、复数z 满足11z ii i=+,则复数z 的模等于_______________.7、(2014浦东二模文理3). 函数()31cos 4sin xx x f =的最大值为 .8、(2014松江三区二模文理7).函数()()sin cos cos 2sin cos sin x x x f x xx xπ+-=-的最小正周期T =____________.【课堂练习】1. 【上海市黄浦区2014届高三上学期期末考试(即一模)数学(理)试题】三阶行列式45sin 2cos 61sin ---xx x ()R x ∈中元素4的代数余子式的值记为()x f ,则函数()x f 的最小值为2. 【上海市十三校2013年高三调研考数学试卷(理科)】已知二元一次方程组的增广矩阵是421m m m m +⎛⎫⎪⎝⎭,若该方程组无解,则实数m 的值为___________.3. 【2013学年第一学期徐汇区学习能力诊断卷高三年级数学学科(理科)】计算:122423432⎛⎫⎛⎫⋅+ ⎪ ⎪⎝⎭⎝⎭= .4. 【上海市杨浦区2013—2014学年度第一学期高三年级学业质量调研数学试卷(理科)】若行列式124012x -=,则x = .5. 【上海市黄浦区2014届高三上学期期末考试(即一模)数学(理)试题】各项都为正数的无穷等比数列{}na ,满足,,42t a m a ==且⎩⎨⎧==ty mx 是增广矩阵⎪⎪⎭⎫⎝⎛-2221103的线性方程组⎩⎨⎧=+=+2222111211c y a x a c y a x a 的解,则无穷等比数列{}na 各项和的数值是 _________.上海市各区县2015届高三上学期期末考试数学理试题分类汇编矩阵与行列式一、填空题1、(宝山区20152、(宝山区2015届高三上期末)设矩阵241A x ⎛⎫= ⎪⎝⎭,2211B -⎛⎫= ⎪-⎝⎭,若BA =2412⎛⎫⎪--⎝⎭, 则x =3、(崇明县2015届高三上期末)已知线性方程组的增广矩阵为103210⎛⎫⎪⎝⎭,则其对应的方程组解为4、(奉贤区2015届高三上期末)已知⎪⎪⎭⎫⎝⎛-βαcos 200sin 为单位矩阵,且,2παβπ⎡⎤∈⎢⎥⎣⎦、,则tan()αβ+= 5、(虹口区2015届高三上期末)行列式()3sin tan 4cos tan()2x x x x ππ-+的最小值为6、(嘉定区2015届高三上期末)将函数xx x f 2sin 12cos 3)(=的图像向左平移m (0>m )个单位,所得图像对应的函数为偶函数,则m 的最小值为____________7、(金山区2015届高三上期末)当a >0,b >0且a+b =2时,行列式ba 11的值的最大值是8、(浦东区2015届高三上期末)已知一个关于y x ,的二元线性方程组的增广矩阵是⎪⎪⎭⎫ ⎝⎛-210211,则y x +=9、(松江区2015届高三上期末)若复数z 满足014=-zz ,则z 的值为10、(徐汇区2015届高三上期末)若全集U R =,不等式11111x x+≥-的解集为A ,则U A C =11、(杨浦区2015届高三上期末)设△ABC 的内角A ,B ,C 所对的边长分别为a ,b ,c ,若30a b c a ba b c ++=+-,则角C =_______12、(黄浦区2015届高三上期末)若三阶行列式1302124121n m mn -+---中第1行第2列的元素3的代数余子式的值是15-,则|i |n m +(其中i 是虚数单位,R m n ∈、)的值是二、选择题 1、(浦东区2015届高三上期末)已知数列{}n a 的通项公式2,n a n n N *=∈,则5231234201220134345620142015a a a a a a a a a a a a a a a a ++++= ( )()A 16096-()B 16104- ()C 16112-()D 16120-。
2013学年徐汇区初中学业考试能力诊断理化答案
2013学年徐汇区初中学业考试能力诊断理化试卷答案六、选择题七、填空题(共20分)47.(Ⅰ)CH 4 CaCO (Ⅱ)碳酸根 40% (Ⅲ)相对分子质量48.(Ⅰ)过滤 搅拌与引流 (Ⅱ)除去炭粉(Ⅲ)蒸发浓缩 冷却结晶 NH 4Cl NH 4Cl ZnCl 249.(Ⅰ)长颈漏斗 锥形瓶 (Ⅱ)C F G (Ⅲ)与同体积同浓度的稀硫酸反应,含杂质的锌比纯锌反应速率要快 (Ⅳ)a 和c (Ⅴ)温度(或锌粒形状大小),取质量相等的锌粒分别放入两只试管中,然后分别加入温度不同,体积和溶质质量分数相同的稀硫酸,测量收集等体积的氢气所需要的时间。
3’八、简答题(共20分)50.(Ⅰ) 0.05 1’ (Ⅱ)解:设10片钙片中CaCO 3的物质的量x mol 。
2HCl+CaCO 3→CaCl 2+H 2O+CO 2↑ 1’ 1 1x 0.05x = 0.05(mol) 1’m(CaCO 3)= 100×0.05=5(g ) 1’ 答:略。
(Ⅲ)偏大 1’51.(Ⅰ)Na 2CO 3+CaCl 2→CaCO 3↓+2NaCl 与碳酸钠充分反应大于 不洗涤碳酸钙表面可能会附着一层可溶性物质使沉淀物质量增加,所以使得计算出的碳酸钠的质量增大(Ⅱ)①二氧化碳(空气)② 黄 白色固体变蓝色③ C52.(Ⅰ)CO+CuOCu+CO 2 (Ⅱ) Ca(OH)2+CO 2→CaCO 3↓+H 2O 黑色固体变红色 吸收水分(干燥) 没有进行尾气处理(Ⅲ)Cu+2Ag(NO 3)2→2Ag+Cu(NO 3)2(Ⅳ)Cu 有+1、+2价,与CuO 反应的CO 不足量时,可能会生成氧化亚铜。
题号 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 答案 BC B CD A D C B D C A D B C A B D C C。
2013学年徐汇区初中学业考试能力诊断理化试卷
2013学年徐汇区初中学业考试能力诊断理化试卷(满分150分,考试时间100分钟)化学部分 (满分60分)可能用到的相对原子质量:H-1 C-12 N-14 O-16 S-32 Cl-35.5 Na-23 Mg-24 Al-27 K-39 Ca-40 Fe-56 Cu-64 Zn-65六、选择题(共20分)27.属于“空气污染指数”需要监测的污染物是A.二氧化碳B.可吸入颗粒物C.稀有气体D. 氮气28.常见的物质变化中,属于化学变化的是A.石蜡熔化 B.瓷碗破碎 C.铁锅生锈 D.车胎爆炸29.对应括号内的化学式书写错误的是A.氧化镁(MgO) B.氯化铝(AlCl) C.硫酸亚铁(FeSO4) D.氧化钠(Na2O) 30.生活中的下列物质属于溶液的是A.果汁 B.冰水 C.食盐水 D.豆浆31.化肥对农作物有举足轻重的作用,以下化肥属于氮肥是A. Ca(H2PO4)2B. K2CO3C.KClD.NH4NO332.根据物质分类知识判断属于化合物的是A.干冰B.石油C.液态氧D.碘酒33.下列图示实验操作正确的是A.给液体加热 B.闻气体气味 C.过滤 D.蒸发34.能在空气中燃烧,且产生大量白烟的物质是A.木炭B.硫粉C.红磷D.铁丝35.对于化学式“H20”的各种表述错误的是A.表示水这种物质B.表示水分子由氢元素和氧元素组成C.表示1个水分子D.表示1个水分子由2个氢原子和1个氧原子构成36.X是一种重要的阻燃剂,制备X的化学方程式为:Sb2O3+2H2O2→X+2H2O。
则X的化学式为 A.SbO2 B.H3SbO4 C.HSbO3 D. Sb2O537.实验室用电解水的方法测定水的组成,化学方程式为:2H2O2H2↑+ O2↑该反应的基本类型是A.复分解反应 B.置换反应 C.分解反应 D.化合反应38. 实验室用I2O5测定空气受CO污染的程度,其化学方程式如下:I2O5+5CO→I2+5CO2,该反应中属于氧化剂的物质是A.I2O5 B.CO C.CO2D.I239.鉴别氢氧化钠溶液和澄清的石灰水的四组方案,一定能达到实验目的的是盐酸氯化铜溶液石蕊试液碳酸钠溶液40.物质的性质与所对应的用途没有直接关系的是A.甲烷具有可燃性——可用做燃料B.氧化钙受热不分解——可用作干燥剂C.石墨能导电——可作电极 D.熟石灰具有碱性——可用于改良酸性土壤41. 燃烧是人类最早利用的化学反应之一,下列叙述中正确的是A.在化学反应中只有燃烧才能放出热量B.物质与氧气发生的反应都是燃烧C.煤、石油、天然气燃烧都放出大量的热,都是重要的燃料D.只要达到燃烧所需的最低温度,可燃物就能燃烧42.镁与盐酸反应,生成0.1molH2,则0.1mol H2分子的个数为A. 6.02×1022B. 1.204×1023C.3.01×1023D. 6.02×102343. 20℃时,NaCl溶解于水的实验数据如下表:A.②中所得溶液是饱和溶液 B.20℃时,NaCl的溶解度为36g/100g水C.所得溶液的溶质质量分数④>③ D.①所得溶液的溶质质量分数为20%44.右图是稀HCl和NaOH溶液反应的pH变化曲线,以下说法正确的是A.A点溶液的溶质为NaOH和NaClB.B点溶液的溶质只有NaClC.a是NaOH溶液质量,b是稀HCl质量D.该反应是NaOH溶液滴入稀HCl中45.右图所示微观变化的化学反应类型,与下列反应的反应类型一致的是A.2Mg + CO22MgO+ CB.2HCl + CuO → CuCl2 + H2OC.2HI +Cl2 → 2HCl +I2D.2HCl+Fe→ FeCl2+H2↑46.某物质中可能含有碳酸钙、炭粉、氧化铜、氧化铁中的一种或几种。
2013年上海市徐汇区初中化学一模卷试题及答案(2013年1月,即是2012-2013学年第一学期期末测试题)
2012学年第一学期徐汇区初三化学学习能力诊断试卷(90分钟完成满分100分)2013.1相对原子质量:H-1 O-16 C-12 N-14 Si-28 Cl-35.5 Na-23 K-39 Ca-40 一、选择题(只有一个正确答案)(共30分)1.酸雨危害大,酸雨的形成与排放某种气体有关,该气体是() A.CO2 B.SO2 C.O3 D.CO2.C3N4是一种新型材料,它的硬度比金刚石还高,可做切割工具。
在C3N4中,C的化合价为+4,则N的化合价是() A.+5 B.+3 C.-4 D.-33.能使带火星的木条复燃的气体是 ( )A.空气B.二氧化碳C.氧气D.水蒸气4.常见物质中,属于纯净物的是 ( ) A.洁净的空气 B.海水 C.可口可乐 D.冰水共存物5.物质的命名与化学式一致的是 ( )A.氯化钙 CaCl2B. 硫酸钠 Na2SO3C.氧化铁 FeOD. 氢氧化钡 BaOH6.矿泉水中含有钙、镁、钾、钠,这里的钙、镁、钾、钠指()A.单质 B.原子 C.元素 D.分子7. 探究物质的变化是学习化学的重要内容。
下列变化中属于化学变化的是()A. B. C. D.8.生命离不开空气。
关于空气的叙述错误的是()A.空气中二氧化碳的含量是始终不变的B.空气中含量最多的气体是氮气C.空气是多种单质和多种化合物组成的混合物D.空气是一种重要的化工原料9.过氧乙酸(C2H4O3)溶液可用作公用场所的消毒。
过氧乙酸属于()A.混合物B.氧化物C.化合物D.单质10. 一些食品的近似pH如下:番茄4.0~4.4;苹果2.9~3.3;牛奶6.3~6.6;鸡蛋清7.6~8.0。
则下列说法中错误的是 ( )A.胃酸过多的人应少吃苹果 B.番茄汁属酸性食品C.牛奶和鸡蛋清均为碱性食品 D.苹果汁酸性比牛奶强11. 把下列气体通入紫色石蕊试液中,紫色石蕊试液变成红色的是()A.氧气B.氢气C.一氧化碳D.二氧化碳12.常温下,碳的化学性质不活泼。
上海市徐汇区2013届高三上学期期末教学质量调研政治试题.pdf
情就是开心的;如果从悲观的角度去看,所看到的事情就是悲观的。”这句话说明
A.意识是客观存在的主观映像
B.人能够能动地改造客观世界
C.改变命运取决于人的努力
D.实践对认识具有决定作用
23.庖丁解牛,游刃有余;揠苗助长,苗枯田荒。这些成语给我们的哲学启示是
① 规律是不以人的意志为转移的
A.执行交换媒介和支付手段
B.计价单位和货币符号
C.执行交换媒介和计价单位
D.支付手段和世界货币
5.下表是近年来我国经济发展的主要数据,根据数据可以推论出我国
① 城乡居民收入不断增长
② 财政促进人民生活水平的提高
③ 需要完善收入分配政策
④ GDP增长速度降低意味经济发展质量下降
;20-40为富裕水平;20以下为极度富裕。根据下表推断小张家的消费水平已经达到
项目支出吃穿用其他总计金额(元)150050015001003600A、温饱水平
B、小康水平
C、富裕水平
D、极度富裕
8.2012年国家安排财政资金亿元,在开展家电产品“以旧换新”,按新家电销售价格的10%给予补贴家电产品
A. 科学性是马克思主义哲学的一个基本特点
B. 实践性是马克思主义哲学的一个基本特点
C. 马克思主义哲学正确阐明了整个世界发展的最普遍规律
D. 马克思主义哲学给人们提供了正确认识客观事物及其规律的观点和方法
`22. “其实命运就跟生活一样,它是一件很简单的事情,看你怎么去看。如果你从开心的角度去看,所看到的事
② 必须取消家庭承包经营搞合作规模生产
③ 必须发展高产、优质、高效、生态、安全农业
④ 必须促进农业科技的进步和创新
A. ①②
B. ②③
2014届上海市徐汇区高三上学期期末学习能力诊断理科数学试题(含答案详解)word精校版
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已知函数 f ( x) = x −1 , g ( x) = −x2 + 6x − 5 . (1)若 g ( x) ≥ f ( x) ,求实数 x 的取值范围; (2)求 g ( x) − f ( x) 的最大值.
21. (本题满分 14 分,第(1)小题 5 分,第(2)小题 9 分)
某种海洋生物身体的长度 f (t ) (单位:米)与生长年限 t(单位:年)
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三. 解答题:(本大题共 5 题,满分 74 分) 19. (本题满分 12 分)
在△ABC 中,BC=a,AC=b,a、b 是方程 x2 − 2 3x + 2 = 0 的两个根,且 A + B = 120o ,
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2013学年上海市徐汇区九年级第一学期学习能力诊断卷
2013学年第一学期徐汇区学习能力诊断卷初三年级语文学科(考试时间100分钟满分150分) 2014.1 请注意:本卷共有四题。
请将所有答案写在答题纸上,写在试卷上不计分。
(一)文言文(共42分)默写(18分)1.浮云游子意,。
(李白《送友人》)2.,雪尽马蹄轻。
(王维《观猎》)3.昨夜雨疏风骤,。
(李清照《如梦令》)4.人生自古谁无死,。
(文天祥《过零丁洋》)5.至若春和景明,,上下天光……(范仲淹《岳阳楼记》)6.,往来而不绝者,滁人游也。
(欧阳修《醉翁亭记》)(二)阅读下面的诗,完成7-8题(4分)卖炭翁(唐白居易)卖炭翁,伐薪烧炭南山中。
满面尘灰烟火色,两鬓苍苍十指黑。
卖炭得钱何所营?身上衣裳口中食。
可怜身上衣正单,心忧炭贱愿天寒。
夜来城外一尺雪,晓驾炭车辗冰辙。
牛困人饥日已高,市南门外泥中歇。
翩翩两骑来是谁?黄衣使者白衫儿。
手把文书口称敕,回车叱牛牵向北。
一车炭,千余斤,宫使驱将惜不得。
半匹红绡一丈绫,系向牛头充炭直。
7.诗中的“驱将”的意思是。
(2分)8.下列选项中不正确的一项是(2分)A.“满面尘灰烟火色”体现卖炭翁劳作的辛苦。
B.“心忧炭贱愿天寒”突显卖炭翁内心的忧伤。
C.诗歌揭露了宫使们巧取豪夺百姓物品的行径。
D.诗歌表达了对受“宫市”之苦的人民的同情。
(三)阅读下文,完成9-11题(8分)金溪民方仲永,世隶耕。
仲永生五年,未尝识书具,忽啼求之。
父异焉,借旁近与之,即书诗四句,并自为其名。
其诗以养父母、收族为意,传一乡秀才观之。
自是指物作诗立就,其文理皆有可观者。
邑人奇之,稍稍宾客其父,或以钱币乞之。
父利其然也,日扳仲永环谒于邑人,不使学。
余闻之也久。
明道中,从先人还家,于舅家见之,十二三矣。
令作诗,不能称前时之闻。
又七年,还自扬州,复到舅家问焉。
曰:“泯然众人矣。
”9.本文的作者是的(人名)。
(2分)10.用现代汉语翻译下面的句子,注意加点词的含义。
父异焉,借旁近与之.(3分)11.从全文来看,仲永“泯然众人矣”的最根本原因是___(3分)A.“邑人”纷纷用钱财讨取仲永的诗作。
上海第期高三名校数学理试题分省分项汇编 专题 数列数学归纳法与极限解析含解析
一.基础题组1. 【上海市黄浦区2014届高三上学期期末考试(即一模)数学(理)试题】已知数列{}n a 是公差为2的等差数列,若6a 是7a 和8a 的等比中项,则n a =________.2. 【上海市嘉定区2014届高三上学期期末质量调研(一模)数学(理)试卷】已知数列}{n a 的前n 项和2n S n =(*N ∈n ),则8a 的值是__________.3. 【上海市嘉定区2014届高三上学期期末质量调研(一模)数学(理)试卷】若nn r r ⎪⎭⎫ ⎝⎛+∞→12lim 存在,则实数r 的取值范围是_____________.4. 【虹口区2013学年度第一学期高三年级数学学科期终教学质量监控测试题】在n n n C B A ∆中,记角n A 、n B 、n C 所对的边分别为n a 、n b 、n c ,且这三角形的三边长是公差为1的等差数列,若最小边1+=n a n ,则=∞→n n C lim ( )..A 2π .B 3π .C 4π .D 6π5. 【上海市浦东新区2013—2014学年度第一学期期末质量抽测高三数学试卷(理卷)】221lim 2n n n n→∞+=-___________.6. 【上海市普陀区2014届高三上学期12月质量调研数学(理)试题】若圆1)1(22=-+y x 的圆心到直线:n l 0=+ny x (*N n ∈)的距离为n d ,则=∞→n n d lim .【答案】1 【解析】试题分析:圆心为(0,1),21nd n =+,22limlim1111n n n n→∞→∞==++. 考点:点到直线距离公式,极限.7.【2013学年第一学期十二校联考高三数学(理)考试试卷】计算:2(1)(13)lim(2)(1)n n n n n n →∞+-=-++________.8. 【上海市浦东新区2013—2014学年度第一学期期末质量抽测高三数学试卷(理卷)】已知数列{}n a 中,11a =,*13,(2,)n n a a n n N -=+≥∈,则n a =___________.9. 【2013学年第一学期十二校联考高三数学(理)考试试卷】设正项数列}{n a 的前n 项和是n S ,若}{n a 和}{n S 都是等差数列,且公差相等,则1a =_______________. 【答案】14【解析】试题分析:等差数列}{n a 的公差为d ,则21()22n d dS n a n =+-,21()22n d dS n a n =+-,数列}{n S 是等差数列,则n S 是关于n 的一次函数(或者是常函数),则102da -=,2n d S n =,从而数列}{n S 的公差是2d ,那么有2d d =,0d =(舍去)或12d =,114a =. 考点:等差数列的通项公式.10. 【上海市十三校2013年高三调研考数学试卷(理科)】计算:2211lim[()]12n n n n n →+∞--++=_________.11. 【上海市十三校2013年高三调研考数学试卷(理科)】设正数数列{}n a 的前n 项和是n S ,若{}n a 和{n S }都是等差数列,且公差相等,则=+d a 1__ _.12. 【2013学年第一学期徐汇区学习能力诊断卷高三年级数学学科(理科)】计算:210lim323xnn→∞++=.【答案】23【解析】试题分析:这属于“∞∞”型极限问题,求极限的方法是分子分母同时除以n(n的最高次幂),化为一般可求极限型,即210lim323xnn→∞++1022lim2333nnn→∞+==+.考点:“∞∞”型极限13.【2013学年第一学期徐汇区学习能力诊断卷高三年级数学学科(理科)】如果()1111112312nf nn n=++++++++L L(*n N∈)那么()()1f k f k+-共有项.14.【上海市杨浦区2013—2014学年度第一学期高三年级学业质量调研数学试卷(理科)】计算:=+∞→133limnnn.15.【上海市长宁区2013—2014第一学期高三教学质量检测数学试卷(理科)】已知数列{}{}n n b a ,都是公差为1的等差数列,其首项分别为11,b a ,且,511=+b a,,11N b a ∈设),(N n a c n b n ∈=则数列{}n c 的前10项和等于______.【答案】85 【解析】试题分析:数列{}n c 到底是什么暂时不知,因此我们试着把其前10项的和10S 表示出来,1210b b S a a =++L10b a +11121[(1)][(1)][(1)]n a b a b a b =+-++-+++-L 1121010()10a b b b =++++-L =111091010102a b ⨯++-1110()451085a b =++-=. 考点:等差数列的通项公式与前n 和公式.二.能力题组1. 【上海市黄浦区2014届高三上学期期末考试(即一模)数学(理)试题】已知数列{}na 满足()()*+∈=-+N n n a a n nn ,11,则数列{}na 的前2016项的和2016S 的值是___________.可行,由此我们可得2016S =12344342414()()k k k k a a a a a a a a ---+++++++++L L 20132014(a a ++2015a + 2016)a +(222)(226)(22(42))(222014)k =+⨯++⨯+++⨯-+++⨯L L 25044(13=⨯+⨯++5+L 1007)+=1017072.考点:分组求和.2. 【上海市嘉定区2014届高三上学期期末质量调研(一模)数学(理)试卷】某种平面分形图如下图所示,一级分形图是一个边长为1的等边三角形(图(1));二级分形图是将一级分形图的每条线段三等分,并以中间的那一条线段为一底边向形外作等边三角形,然后去掉底边(图(2));将二级分形图的每条线段三等边,重复上述的作图方法,得到三级分形图(图(3));…;重复上述作图方法,依次得到四级、五级、…、n 级分形图.则n 级分形图的周长为__________.3. 【虹口区2013学年度第一学期高三年级数学学科期终教学质量监控测试题】已知函数2sin)(2πn n n f =,且)1()(++=n f n f a n ,则=++++2014321a a a a Λ . 【答案】4032- 【解析】试题分析:考虑到sin2n π是呈周期性的数列,依次取值1,0,1,0,-L ,故在122014a a a +++L 时要分组求和,又由n a 的定义,知1352013a a a a ++++L (1)(2)(3)(4)(2013)(2014)f f f f f f =++++++L2222221357200920112013=-+-++-+L 1(53)(53)(97)(97)=+-++-++L (20132011)+-⋅(20132011)+12(357920112013)=+++++++L 110062016=+⨯,242014a a a +++L(2)(3)(4)f f f =+++(5)(2014)(2015)f f f +++L 22223520132015=-+++-L 22(352013)2015=+++-L 2100620062015=⨯-,从而122014a a a +++L 1210062016=+⨯⨯图(1)图(2)图(3)……22015-4032=-.考点:周期数列,分组求和.4. 【虹口区2013学年度第一学期高三年级数学学科期终教学质量监控测试题】已知{}n a 是各项均为正数的等比数列,且1a 与5a 的等比中项为2,则42a a +的最小值等于 .5. 【上海市长宁区2013—2014第一学期高三教学质量检测数学试卷(理科)】数列{}n a 满足*,5221...2121221N n n a a a n n ∈+=+++,则=n a .6. 【上海市浦东新区2013—2014学年度第一学期期末质量抽测高三数学试卷(理卷)】已知函数,1)(22+=x x x f 则 ()()()111112(2013)20142320132014f f f f f f f f ⎛⎫⎛⎫⎛⎫⎛⎫+++++++++= ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭⎝⎭K L ( )(A) 201021 (B) 201121 (C) 201221 (D) 2013217. 【上海市普陀区2014届高三上学期12月质量调研数学(理)试题】数列}{n a 中,若11=a ,n n n a a 211=++(*N n ∈),则=+++∞→)(lim 221n n a a a Λ .8. 【上海市普陀区2014届高三上学期12月质量调研数学(理)试题】数列}{n a 的前n 项和为n S ,若2cos 1πn n a n +=(*N n ∈),则=2014S . 【答案】1006 【解析】试题分析:组成本题数列的通项公式中,有式子cos2n π,它是呈周期性的,周期为4,因此在求和2014S 时,想象应该分组,依次4个为一组,12341(12)1(14)a a a a +++=+-+++6=,56781(16)1(18)6a a a a +++=+-+++=,43424141[1(42)]1(14)k k k k a a a a k k ---+++=+--+++6=,最后还剩下20131a =,2014120142013a =-=-,所以20146503120131006S =⨯+-=.考点:分组求和.9. 【2013学年第一学期十二校联考高三数学(理)考试试卷】若数列{}n a 满足:111,2()n n a a a n N *+==∈,则前6项的和6S= .(用数字作答)10. 【上海市十三校2013年高三调研考数学试卷(理科)】等差数列{}n a 中,1102,15a S ==,记2482n n B a a a a =++++L ,则当n =____时,n B 取得最大值.11. 【上海市十三校2013年高三调研考数学试卷(理科)】已知函数()(2318,3133,3x tx x f x t x x ⎧-+≤⎪=⎨-->⎪⎩,记()()*n a f n n N =∈,若{}n a 是递减数列,则实数t 的取值范围是______________.12. 【上海市十三校2013年高三调研考数学试卷(理科)】已知无穷数列{}n a 具有如下性质:①1a 为正整数;②对于任意的正整数n ,当n a 为偶数时,12nn a a +=;当n a 为奇数时,112n n a a ++=.在数列{}n a 中,若当n k ≥时,1n a =,当1n k ≤<时,1n a >(2k ≥,*k N ∈),则首项1a 可取数值的个数为 (用k 表示)三.拔高题组1. 【虹口区2013学年度第一学期高三年级数学学科期终教学质量监控测试题】数列{}n a 是递增的等差数列,且661-=+a a ,843=⋅a a . (1)求数列{}n a 的通项公式;(2)求数列{}n a 的前n 项和n S 的最小值; (3)求数列{}n a 的前n 项和n T .【答案】(1) 210n a n =-;(2)20-;(3)229,15,*,940,6,*,n n n n n N T n n n n N ⎧-+≤≤∈⎪=⎨-+≥∈⎪⎩.【解析】2.【上海市普陀区2014届高三上学期12月质量调研数学(理)试题】已知数列{}a中,n13a =,132n n n a a ++=⋅,*n N ∈.(1)证明数列{}2n n a -是等比数列,并求数列{}n a 的通项公式;(2)在数列{}n a 中,是否存在连续三项成等差数列?若存在,求出所有符合条件的项;若不存在,请说明理由;(3)若1r s <<且r ,*s N ∈,求证:使得1a ,r a ,s a 成等差数列的点列(),r s 在某一直线上.(2)假设在数列{}n a 中存在连续三项成等差数列,不妨设连续的三项依次为1k a -,k a ,1k a +(2k ≥,*k N ∈),由题意得,112+-+=k k k a a a ,将1)1(2--+=k k k a ,211)1(2----+=k k k a ,kk k a )1(211-+=++代入上式得……7分])1(2[])1(2[])1(2[21211k k k k k k -++-+=-++---………………8分化简得,21)1(42---⋅=-k k ,即11)1(42---⋅=k k ,得4)2(1=--k ,解得3=k所以,存在满足条件的连续三项为2a ,3a ,4a 成等比数列。
2013届徐汇区高三数学二模试卷理科含答案
2012学年第二学期徐汇区高三年级数学学科学习能力诊断卷 (理科试卷)(考试时间:120分钟,满分150分) 2013.4一.填空题(本大题满分56分)本大题共有14题,考生应在答题纸相应编号的空格内直接填写结果,每个空格填对得4分,否则一律得零分.1.若函数()(0,1)x f x a a a =>≠的反函数图像过点(2,1)-,则a = . 2.已知函数[]13(),8,64f x x x =∈的值域为A ,集合43|01x x B x x⎧-⎫=<⎨⎬⎩⎭,则A B = . 3.已知(,0)2πα∈-,且4cos 5α=,则tan 2α=___________.4.已知圆锥的母线长为5,侧面积为π15,则此圆锥的体积为__________(结果保留π).5.已知32i x =--(i 为虚数单位)是一元二次方程20x ax b ++= (,a b 均为实数)的一个根,则a b +=__________.6.如图给出的是计算1111352013++++ 的值的一个程序框图,图中空白执行框内应填入i = .7. 在极坐标系中,过圆6cos ρθ=的圆心,且垂直于极轴的直线的极坐标方程是__________.8.将参数方程212cos x y θθ⎧=⎪⎨=+⎪⎩(θ为参数,R θ∈)化为普通方程,所得方程是_____ _____.9. 在二项式63()()ax a R x+∈的展开式中,常数项的值是20-,则23lim()n n a a a a →∞++++ = .10.一质地均匀的正方体三个面标有数字0,另外三个面标有数字1.将此正方体连续抛掷两次,若用随机变量ξ表示两次抛掷后向上面所标有的数字之积,则数学期望ξE =___________.11.已知椭圆2212516x y +=内有两点()()1,3,3,0,A B P 为椭圆上一点,则PA PB +的最大值为 .12.如图,O 为直线02013A A 外一点,若0123452013,,,,,,,A A A A A A A 中任意相邻两点的距离相第6题图2013等,设02013,OA a OA b == ,用,a b表示0122013OA OA OA OA ++++uuu r uuu r uuu r uuuuu r L L ,其结果为 .13.设函数()f x x x =,将()f x 向左平移a (0)a >个单位得到函数()g x ,将()f x 向上平移a (0)a >个单位得到函数()h x ,若()g x 的图像恒在()h x 的图像的上方,则正数a 的取值范围为 .14.如图,现将一张正方形纸片进行如下操作:第一步,将纸片以D 为顶点,任意向上翻折,折痕与BC 交于点1E ,然后复原,记11CDE α∠=;第二步,将纸片以D 为顶点向下翻折,使AD 与1E D 重合,得到折痕2E D ,然后复原,记22ADE α∠=;第三步,将纸片以D 为顶点向上翻折,使CD 与2E D 重合,得到折痕3E D ,然后复原,记33CDE α∠=;按此折法从第二步起重复以上步骤……,得到12,,,,n ααα ,则lim n n α→∞=.二.选择题(本大题满分20分)本大题共有4题,每题有且只有一个正确答案,考生应在答题纸的相应编号上,将代表答案的小方格涂黑,选对得5分,否则一律得零分.15.已知,a b 为实数,命题甲:2ab b >,命题乙:110b a<<,则甲是乙的( )A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件16.已知函数()1,00,01,0x f x x x >⎧⎪==⎨⎪-<⎩,设2()()F x x f x =⋅,则()F x 是 ( )A.奇函数,在(,)-∞+∞上单调递减B.奇函数,在(,)-∞+∞上单调递增C.偶函数,在(),0-∞上递减,在()0,+∞上递增D.偶函数,在(),0-∞上递增,在()0,+∞上递减17.气象意义上从春季进入夏季的标志为:“连续5天的日平均温度均不低于22 (0C)”.现有甲、乙、丙三地连续5天的日平均温度的记录数据(记录数据都是正整数):①甲地:5个数据的中位数为24,众数为22; ②乙地:5个数据的中位数为27,总体均值为24;③丙地:5个数据中有一个数据是32,总体均值为26,总体方差为10.8;则肯定进入夏季的地区有 ( ) A. 0个 B. 1个 C. 2个 D. 3个18. 如图所示,向量BC 的模是向量AB 的模的t 倍,AB BC 与的夹角为θ,那么我们称向量AB经过一次(),t θ变换得到向量BC .在直角坐标平面内,设起始向量()14,0OA =,向量1OA 经过1n -次12,23π⎛⎫⎪⎝⎭变换得到的向量为()1*,1n n A A n N n -∈> ,其中*12,,()i i i A A A i N ++∈为逆时针排列,记i A 坐标为()(),*i i a b i N ∈,则下列命题中不正确...的是( )A. 2b =3130k k b b +-=()*k N ∈ C. 31310k k a a +--=()*k N ∈D. ()()43180k k k k a a a a +++-+-=()*k N ∈三.解答题(本大题满分74分)本大题共有5题,解答下列各题必须在答题纸相应编号的规定区域内写出必要的步骤.19.(本题满分12分)在ABC ∆中,,,a b c 分别是角,,A B C 的对边,且sin cos cos sin A C A C +=,若b =ABC ∆的面积ABC S ∆=a c +的值. 20.(本题满分14分) 本题共有2个小题,第1小题满分6分,第2小题满分8分.某轮船公司的一艘轮船每小时花费的燃料费与轮船航行速度的平方成正比,比例系数为k .轮船的最大速度为15海里/小时.当船速为10海里/小时,它的燃料费是每小时96元,其余航行运作费用(不论速度如何)总计是每小时150元.假定运行过程中轮船以速度v 匀速航行.(1)求k 的值;(2)求该轮船航行100海里的总费用W (燃料费+航行运作费用)的最小值.21.(本题满分14分) 本题共有2个小题,第1小题满分6分, 第2小题满分8分.如图,已知111ABC A B C -是正三棱柱,它的底面边长和侧棱长都是2,D 为侧棱1CC 的中点.(1)求异面直线1A D 与BC 所成角的大小(结果用反三角函数值表示); (2)求直线11A B 到平面DAB 的距离.DBCAB 1C 1A 1第21题图22.(本题满分16分) 本题共有3个小题,第1小题满分4分,第2小题满分6分,第3小题满分6分.已知数列{}*()n a n N ∈的前n 项和为n S ,数列n S n ⎧⎫⎨⎬⎩⎭是首项为0,公差为12的等差数列. (1)求数列{}n a 的通项公式; (2)设()*42()15n an b n N =⋅-∈,对任意的正整数k ,将集合{}21221,,k k k b b b -+中的三个元素排成一个递增的等差数列,其公差为k d ,求证:数列{}k d 为等比数列; (3)对(2)题中的k d ,求集合{}1,k k x d x d x Z +<<∈的元素个数.23.(本题满分18分) 本题共有3个小题,第1小题满分4分,第2小题满分6分,第3小题有三个问题情形,每位考生只能选择一个作答,若多答,只对所答情形中最前面的一个记分,情形一、二、三满分依次为5分、6分、8分.已知双曲线C 的中心在原点,()1,0D 是它的一个顶点,d =是它的一条渐近线的一个方向向量.(1) 求双曲线C 的方程;(2) 若过点(3,0-)任意作一条直线与双曲线C 交于,A B 两点 (,A B 都不同于点D ),求证:DA DB ⋅为定值;(3) 对于双曲线Γ:22221(0,0,)x y a b a b a b-=>>≠,E 为它的右顶点,,M N 为双曲线Γ上的两点(都不同于点E ),且EM EN ⊥,那么直线MN 是否过定点?若是,请求出此定点的坐标;若不是,说明理由.然后在以下三个情形中选择一个,写出类似结论(不要求书写求解或证明过程).情形一:双曲线22221(0,0,)x y a b a b a b-=>>≠及它的左顶点;情形二:抛物线22(0)y px p =>及它的顶点;情形三:椭圆22221(0)x y a b a b+=>>及它的顶点.(理)参考答案一.填空题:(本题共有14题,每小题4分)1.12 2. [)2,3 3. 247- 4. 12π 5. 19 6.2i +7. cos3ρθ= 8. 23y x =-+(x ≤≤ 9. 14- 10. 14 11.15 12.1007()a b +13.2a > 14.6π二.选择题:(本题共有4小题,每小题5分) 15. B16. B 17. C 18.D 三.解答题 19.(本题12分)解:由条件可得sin()A C +=,……………2分 即sin 2B =,……………4分 1sin 2ABC S ac B ∆=3.ac ∴=………………………………8分 由余弦定理B ac c a b cos 2222-+=,得22()22cos ,b a c ac ac B =+--………………10分于是,217()23(1).2a c =+-⋅+4a c ∴+=. ………………………………………12分 20.(本题14分)本题共有2小题,第(1)小题6分,第(2)小题8分. 解:(1)由题意得燃料费21W kv =,………………………………2分把v =10,196W =代入得0.96k =.………………………………………………6分(2)21001001500.96W v v v ⨯=⋅+,……………………………………9分 =15000962400v v+≥=,………………………11分 其中等号当且仅当1500096v v =时成立,解得12.515v ==<,……………13分 所以,该轮船航行100海里的总费用W 的最小值为2400(元). ……………………………14分21.(本题14分)本题共有2题,第(1)小题6分,第(2)小题8分.解:(1)方法一:以11AB 中点O 为坐标原点,如图建立空间直角坐标系.………1分 由题意得()(()(11,0,0,,1,2,0,A D B C - 则((1,A D BC =-=. .............3分设θ为向量1A D BC与的夹角,则1222,2ABDS ∆=⋅⋅=,.....5分异面直线1A D 与BC所成角的大小为arccos . ...... 6分 方法二:取1B B 中点E ,连结1,A E DE .//DE CB ………………………………….2分1A DE ∴∠(或其补角)为异面直线1A D BC 与所成的角. ……3分由题意得:在11Rt A B E ∆中,1A E =在11Rt AC D ∆中,1A D ……………………4分在等腰三角形1A DE 中,………5分所以异面直线1A D 与BC 所成角的大小为分(2)方法一:由题意可得11//A B ABD 平面,所以,11A B 到平面DAB 的距离即为1A 到平面DAB 的距离,设为h . …………….8分设平面ABD 的法向量为n ,(),,1n x y =r,由()(()1(1,0,0),1,2,0,,1,2,0A A D B -得()((12001AB AD A D =-=--=- ,,,,,,…………………11分 ,即()n =. ……………………………………………………12分所以故直线11A B 到平面DAB …………………………………14分 方法二:由题意可得11//A B ABD 平面,所以,11A B 到平面DAB 的距离即为1A 到平面DAB 的距离,设为h .…………….8分 由题意得12A D AD BD AB ====, 等腰ADB ∆底边AB 2=,则12AA B S ∆=, D BC1A 200000x x AB n x y y AD n ⎧-==⎧⎧⋅=⎪⎪⎪⇒⇒⎨⎨⎨--+==⎪⎪⋅=⎪⎩⎩⎩1n A D h n⋅===112cos DEA DE A D ∠==且D 到平面11ABB A12分 由11A ABD D A AB V V --=得……………………………………………………………13分,则h =所以,直线11A B 到平面DAB……………14分22.(本题满分16分) 本题共有3个小题,第(1)小题满分4分,第(2)小题满分6分, 第(3)小题满分6分. 解:(1)由条件得10(1)2n S n n =+-,即(1)2n nS n =-,…………………………..2分 所以,*1()n a n n N =-∈. ……………………………………………………..4分(2) 由(1)可知1*4(2)()15n n b n N -=⋅-∈ 所以,22222144(2)21515k k k b ---=-=⋅,2121244(2)21515k k k b --=-=-⋅, 222144(2)21515k k k b +=-=⋅,…………………………..7分由212212k k k b b b -+=+及22121k k k b b b -+<<得22121,,k k k b b b -+依次成递增的等差数列, …………………………..8分所以22221214442215155kk k k k k d b b -+-=-=⋅-⋅=,…………………………..9分 满足14k kd d +=为常数,所以数列{}k d 为等比数列. …………………………..10分 (3)①当k 为奇数时,112211223101555(1)4(51)55515555(1)5k k k k k k kk k k k k k k k k k C C d C C C --------+-+--====-+-+--,…………………………..12分同样,可得111122011114(51)15555(1)555k k k k k k kk k k k d C C C ++--++++-===-+-+-+ , 所以,集合{}1,k k x d x d x Z +<<∈的元素个数为111()()155k k d d +--++133(41)55k k k d d ++=-+=;……..13分11133ABD A AB S h S ∆∆⋅⋅=②当k 为偶数时,同理可得集合{}1,k k x d x d x Z +<<∈的元素个数为3(41)5k ⋅-. (16)分23.(本题满分18分) 本题共有3个小题,第1小题满分4分,第2小题满分6分,第3小题有三个问题情形,每位考生只能选择一个作答,若多答,只对所答情形中最前面的一个记分,情形一、二、三满分依次为5分、7分、8分。
上海市徐汇区高三物理一模试卷(含答案)
v2013学年第一学期徐汇区高三年级物理学科学 习 能 力 诊 断 卷(考试时间120分钟,满分150分)2014.11.答第Ⅰ卷前,考生务必在答题卷上用蓝色或黑色的钢笔或圆珠笔清楚填写姓名、考号,并用2B 铅笔在答题卷上正确涂写考号。
2.第Ⅰ卷(1—20题) 由机器阅卷。
考生应将在答题卷上的代表正确答案的小方格用2B 铅笔涂黑。
注意试题题号和答题卷题号一一对应,不能错位。
答案需要更改时,必须将原选项用橡皮擦去,重新选择。
第 Ⅰ 卷(68分)一.单项选择题(共24分,每小题3分。
每小题只有一个正确选项)1.物理学中,运动合成、力的分解、平均速度这三者所体现的共同的科学思维方法是( ) (A )比值定义(B )控制变量(C )等效替代(D )理想模型2.下列物理规律中不能直接通过实验进行验证的是( ) (A )牛顿第一定律 (B )机械能守恒定律 (C )欧姆定律(D )玻意耳定律3.下列关系式中正确的是( ) (A )室外气温:-2℃<-5℃(B )重力对某物体做功:-2J <-12J (C )物体的重力势能:-2 J <-12J(D )电场中某点的电势:-2V <-5V4.一质点做简谐运动,其振动图线如图所示。
由图可知,在t =4s 时,质点的( )(A )速度为正的最大值,加速度为零 (B )速度为负的最大值,加速度为零 (C )速度为零,加速度为正的最大值(D )速度为零,加速度为负的最大值 小水作品5.如图,光滑的水平面上固定着一个半径在逐渐减小的螺旋形光滑水平轨道。
一个小球以一定速度沿轨道切线方向进入轨道,下列物理量中数值将减小的是( ) (A )周期(B )线速度(C )角速度(D )向心加速度6.两个相距较远的分子仅在分子力作用下由静止开始运动,直到不再靠近,在此过程中( ) (A )分子力大小先增大,后一直减小 (B )分子力始终做正功 (C )分子动能先减小,后增大(D )分子势能先减小,后增大7.物块静止在固定的斜面上,分别按图示的方向对物块施加大小相等的力F ,A 中F 垂直于斜面向上,B 中F 垂直于斜面向下,C 中F 竖直向上,D 中F 竖直向下,施力后物块仍然静止,则物块所受的静摩擦力增大的是( )FFFFx O1 23 4t /s(A ) (B ) (C )(D )8.在水平放置的光滑绝缘杆ab 上,挂有两个金属环M 和N ,两环套在一个通电密绕长螺线管的中部。
第一学期徐汇区学习能力诊断卷
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8. x 3 ; 9. (x 3 5 )(x 3 5 ) ; 10. 3 2 ; 11.是;
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16.10 ℅;
17.这个角的平分线(除顶点); 18. 45 或 36 .
注:第 17 题缺“除顶点”不得分;第 18 题错解、漏解都不得分.
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第 4 页 共 11 页
五、(本大题共 2 题,第 26 题 10 分,第 27 题 12 分,满分 22 分)
26.如图 7,点 B(2, n) 是直线 y k1x(k1 0) 上的点,如果直线 y k1x(k1 0) 平分 yOx , BA x 轴于 A , BC y 轴于 C .
(1)求 DCB 的大小; (2)如图 9,点 F 是边 BC 上一点,将 ABF 沿 AF 所在直线翻折,点 B 的对应点是点 H ,
直线 HF AB ,垂足为 G ,如果 AB 2 ,求 BF 的长; ( 3 ) 如 图 10 , 点 E 是 ACD 内 一 点 , 且 AEC 150 , 联 结 DE , 请 判 断 线 段
三、简答题(本大题共 4 题,每题 5 分,满分 20 分)
19.先化简再计算: a b (其中 ab 9 ). a 2b ab 2
20.解方程: (2x 3)2 x(x 5) 6 .
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21.已知:线段 a、b (如图 3).
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(D)不能确定.
4.如果 y 关于 x 的函数 y (k 2 1)x 是正比例函数,那么 k 的取值范围是………(
2013学年第一学期徐汇区高三期末试卷资料
2013学年第一学期徐汇区学习能力诊断卷高三地理学科2014.1(120分钟完卷满分为150分)全卷包括两大题,第一大题为选择题,第二大题为综合分析题。
一、选择题(共60分,每小题2分,每小题只有一个正确答案)(一)2013年12月2日(农历十月三十)凌晨,“嫦娥三号”搭乘长征三号在西昌卫星发射中心成功发射。
1.“嫦娥三号”发射之时,月相接近A.望B.朔C.上弦月D.下弦月2.“嫦娥三号”按计划在月球的正面虹湾区着陆,月球的正面是指A.发亮的半个月球B.表面起伏较小的半个月球C.始终面对地球的半个月球D.昼夜温差相对较小的半个月球3.独特的月面环境给探月仪器的研制带来了诸多技术难题,下列匹配正确的是①月球中午气温高达127℃,物体易自燃——探测器难以利用降落伞软着陆②月球晚上气温低至-180℃,且黑夜持续长达约14天——探测器能在月夜生存③月球重力仅地球六分之一,表面崎岖且月壤松软——探月车克服翻车④月球基本无大气,带电粒子可直达其表面——探测器抗辐射要求高A.①②③B.①②④C.①③④D.②③④4.下列有关右图所示地区地形地势的叙述,正确的是①以山地为主,山脉走向为西北-东南向②丙地高于丁地,相对高度约为400米③地形类型多样,分布错综复杂④地势中部低,东北、西南高A.②③B.②④C.①④D.③④5.下列表示地形部位的位置,正确的是A.甲—山峰B.乙—鞍部C.丙—山脊D.丁—悬崖6.若图示为我国江西省某地,在开发中可能出现的生态环境问题是①土壤盐渍化②水土流失③洪涝灾害④地质灾害A.①②③B.②③④C.①③④D.①②④(三)右图为太阳系公转轨道相邻的三大行星相对位置示意图,读图回答 7.我们平时用肉眼可以看见的太阳光亮表面是 A .光球 B .色球C .日冕D .太阳风8.图示时段,下列现象如期出现的是 A .地球处于远日点附近,公转速度较慢 B .南极地区恰值科学考察的黄金季节 C .北印度洋洋流呈逆时针方向流动 D .潮汐的年变化为一年中的高值区9.与①、②行星相比,地球具备生命存在的条件之一是 A .强烈的地震和火山活动 B .适宜的大气厚度和大气成份 C .强烈的太阳辐射和充足的水汽D .复杂的地形和岩石圈(四)2013年的世界气候变化大会在华沙召开,此次会议聚焦温室气体减排。
徐汇区2013学年第一学期期末试题 - 答案
2013学年第一学期徐汇区学习能力诊断卷答案高三年级政治学科 2014.1一、单项选择题(共90分,每小题3分,每题只能选一个选项,选对得3分,错选或不选均不得分。
)1.D 2.A 3.C 4.C 5.C 6.A 7.B 8.C 9.B 10.B 11.D 12.D 13.C 14.C 15.C 16.D 17.A 18.D 19.B 20.B 21.C 22.A 23.C 24.D 25.A 26.D 27.C 28.B 29.B 30.C二、简答题:(共32分,31题为10分,32、34题各8分,33题6分。
)三、分析说明题:(12分)35.答案示例:(1)事物的矛盾是既对立又统一的关系。
矛盾双方相互排斥又相互依存,在一定条件下又相互转化。
我们要用对立统一的观点,全面分析问题。
(3分)(2)在同一个交易行为中,保护消费者的利益与保护商家的利益之间,具有对立的一面,如退换货的增加将使商家承担更多的费用。
该律师的说法看到了保护消费者的利益或许会损害商家利益,是看到了矛盾双方存在对立性,这是正确的。
该律师的说法强调了矛盾双方对立的一面,忽视了两者统一的一面。
(4分)(3)但是消费者和经营者之间利益又是相互依存的,在一定条件下相互转化。
消费者的维权行为使得违反诚信、违法经营的企业被淘汰出局,这有利于市场经济的健康发展,有利于尊重消费者权益的商家获得合理回报,是双赢的。
(4分)(4)该律师的理由不能充分支持其观点。
(1分)评分说明:(1)阐述相关的哲学原理;(2)用哲学知识分析评价该律师所述理由的合理性;(3)用哲学知识分析评价该律师所述理由的不合理性;(4)分析指出无理由退货对消费者和经营者是否平等的准确看法;(5)得出评价结论。
四、论述题(16分)36.答案示例:必须毫不动摇巩固和发展公有制经济,必须毫不动摇鼓励、支持、引导非公有制经济发展,国家依法保护公有制经济和非公有制经济合法利益、公平参与市场竞争。
13年1月徐汇一模
第一学期徐汇区学习能力诊断卷初三(满分150分,考试时间100分钟) 2013年1月考生注意:1、本试卷含四个大题,共25题;2、答题时,考生务必按答题要求在答题纸规定的位置上作答,在草稿纸、本试卷上答题一律无效;3、除第一、二大题外,其余各题如无特别说明,都必须在答题纸的相应位置上写出证明或计算的主要步骤。
一、选择题(本大题共6题,每题4分,满分24分)1、在Rt △ABC 中,∠C =90°,AC =5,AB =13,那么tan A 等于( )A 、513 B 、512 C 、125 D 、1352、将抛物线2y x =沿y 轴向上平移1个单位后所得到的抛物线的解析式是( )A 、21y x =-B 、21y x =+C 、2(1)y x =-D 、2(1)y x =+ 3、坡比等于1:3的斜坡的坡角等于( )A 、30°B 、45°C 、50°D 、60° 4、关于二次函数2(2)y x =+的图像,下列说法正确的是( )A 、开口向下B 、最低点是(2,0)C 、对称轴是直线x =2D 、对称轴的右侧部分是上升的 5、如图1,AC 、BD 相交与点O ,下列条件中能判定CD ∥AB 的是( )A 、AO BO DO CO =B 、AO AB CO CD =C 、BO CO DO AO =D 、AO BOAC BD =6、如图2,在Rt △ABC 中,∠ACB =90°,CD ⊥AB 垂足为D ,那么下列结论中错误的是( )A 、22AC BD BC AD ⋅=⋅B 、22BC BD CD AB ⋅=⋅A BCDO图1ABCD图2C 、AD BC AC CD ⋅=⋅ D 、CD BC AC BD ⋅=⋅二、填空题(本大题共12小题,每题4分,满分48分) 7、计算:2sin 60tan 45︒⋅︒=_______________。
2013年上海市徐汇区初中物理一模试卷及答案.doc
2012学年第一学期徐汇区初三年级物理学科学习能力诊断卷(考试时间:90分钟满分100分) 2013.1注意:所有题目请回答在答题卷上相应位置。
一、单项选择题(共20分〉两电阻串联后总电阻大于其中任一电阻,是因为串联的结果相当于使导体A. 横截而积增大B.横截而积减小C.长度增大D.长度减小用1()牛的水平力把重2牛的正方体木块紧压在竖直的墙壁上,则木块对墙壁的压力为A. 12 牛B. 10 牛C. 8 牛D. 2 牛6. 己知空气的密度为1.29千克/米\下列物体质量与你所在教室中空气质量最接近的是7. 浸没在水中的铝球和铜球(已知它们所受浮力的大小关系为A.铜球大B.铝球大C.大小相等D.无法确定在图1所示的电路中,电源电压不变,当电键S 由断开到闭合时,电压表A. %示数减小,V 2示数减小B. V 1示数增大,乂2示数增大C. Vi 示数减小,乂2示数增大D. V,示数增大,乂2示数减小两个相同的圆柱形容器放在水平桌而上,分别盛有质量相等的洒精和水。
把甲、乙两个金 属球分别浸没于酒精和水中(己知液体不溢出,此时,液体对容器底的压强 相等,界器对水平鉴别物质的方法之一是测定它的 A.密度 B.体积C.质量D. 电阻注射器针尖做得尖锐的目的是为了A.减小压力B.增大压力C.减小压强D. 增大压强物理学中一些单位常以科学家的名字命名, 电功率的单位是A.焦耳B.瓦特C.欧姆D. 库仑1.2. 3. 4. 5. A. 一个人B. 一个苹果C. 一本书D. —张A4纸8.桌面的压强也相等。
以下说法正确的是B. 甲球质量小于乙球质量 D.甲球密度小于乙球密度;10. 如图2所示,左右两柱形玻璃管形状、大小均相同,分别注入水和煤汕,放在水平桌而上。
水和煤油对玻璃管底部的压强相等。
两管距离底部相同《度的地方通过水平细管相连,细 管中的阀门位于水平管中央,将水和煤汕隔离,两管中的液而水平。
当阀门打开瞬间,细 管中的液体A.向左流动B.向右流动C.不动 D.水向右流动,煤油向左流动二、填空题(共26分)11. 教室里的电灯与投影仪之间是 (1) 连接(选填“并联”或“串联”)。
上海市徐汇区2013届高三英语一模试卷(含答案)
2012学年第一学期徐汇区高三年级英语学科学习能力诊断卷(考试时间120分钟,满分150分) 2013.1第一卷I. Listening ComprehensionSection ADirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversation and the question will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. At the booking office. B. In a Hong Kong hotel.C. On a busy street.D. At an airport.2. A. The bag. B. The sofa. C. The table. D. The lamp.3. A. Ask the man for help. B. Have the refrigerator fixed.C. Wait until tomorrow.D. Send the fax right away.4. A. The watch is on the television. B. The program will be over soon.C. The woman should leave the television on.D. The woman shouldn‘t stand in the way.5. A. The man lent the tools to other people. B. The man couldn‘t find the boo kshelf.C. The tools the man borrowed are missing.D. The tools have already been returned.6. A. Because Susan doesn‘t like football. B. Because Susan invited him to amovie.C. Because he wanted to watch the movie.D. Because he didn‘t know about the game.7. A. Give his ankle a good rest. B. Treat his injury immediately.C. Continue his regular activities.D. Go to the doctor for help.8. A. The man missed the way to the class.B. The woman will bring the man the news everyday.C. The woman will help the man make up the lessons.D. The man is always worried about his lessons.9. A. The woman will go to China this weekend.B. The woman will treat the man dinner tonight.C. The man will join her for dinner this weekend.D. The woman refuses to join the man for dinner.10. A. Spending money puts him in a good mood.B. He has just earned a big sum of money.C. He is pleased with his new purchase.D. He paid a high price for his new cell phone.Section BDirections: In Section B, you will hear two short passages, and you will be asked three questions on each of the passages. The passages will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions11through 13 are based on the following passage.11. A. Planting some trees in the greenhouse. B. Writing a want ad to a local newspaper.C. Putting up a going out of business sign.D. Helping a customer select some purchases.12. A. Opening an office in the new office park.B. Keeping better relations with her company.C. Developing fresh business opportunities.D. Building a big greenhouse of his own.13. A. Owning the greenhouse one day. B. Securing a job at the office park.C. Cultivating more potted plants.D. Finding customers out of town.Questions14through 16are based on the following passage.14. A. She had run a long way. B. She felt weak and tired in the subway.C. She had done a 1ot of work.D. She had given blood the night before.15. A. By lifting her to the platform to get others‘ help.B. By moving her with the help of his girlfriend.C. By holding her arm and pulling her along the ground.D. By waking her up and dragging her away from the edge.16. A. Danger in the subway. B. A subway rescue.C. How to save people.D. A traffic accident.Section CDirections: In Section C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with the information you have heard. Write your answers on your answer sheet.Blanks17through20are based on the following conversation.Complete the form. Write ONE WORD for each answer.Blanks 21 through 24 are based on the following conversation.Complete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and VocabularySection ADirections: Beneath each of the following sentences there are four choices marked A, B. C andD. Choose the one answer that best completes the sentence.25. Books are the most important records we keep man‘s thought, ideas and feelings.A. upB. toC. ofD. on26. Knowledge begins to increase as soon as one individual communicates his ideas to _______by means of speech.A. otherB. anotherC. the otherD. some other27. ---I hope you will be ready to leave on time.---Don‘t worry. I‘ll be ready by the time the taxi _______.A. arrivedB. arrivesC. will arriveD. will have arrived28. ---Are you pleased with what he has done?---It couldn‘t be _______. Why didn‘t he put more effort into his work?A. any worseB. much betterC. so badD. the best29. Almost every one of the graduates wants to deliver the keynote speech at the graduationceremony, because for the speaker, _______is an honour.A. invitedB. being invitedC. be invitedD. inviting30. ---My e-dictionary is nowhere to be found. Who have taken it?---I don‘t know. But keep looking and you will find it.A. shouldB. couldC. needD. shall31. I hope to achieve this objective by calling on the smokers ________ good judgment andshow concern for others rather than by regulation.A. to usingB. usingC. useD. to use32. John was so disappointed when Susan turned down his proposal ________ he decided tostay single for the rest of his life.A. thatB. asC. whereD. since33. ________ his own boss for such a long time, he found it hard to accept orders from another.A. BeingB. To beC. Having beenD. Been34. ---I don‘t think our coach knows the real reason for our losing the match.---Well, surprisingly, he does. Our team leader has been called in and now.A. has been questionedB. is being questionedC. is questioningD. has questioned35. The Nobel Prize in literature has been awarded annually to an author from any country_________ has produced "in the field of literature the most outstanding work in an idealdirection".A. whichB. whoC. whereD. as36. Though ______ of danger, sightseers have been flocking to the site where the world‘s bigge stterrorist Bin Laden lived.A. warnedB. warningC. being warnedD. having warned37. Owing to the level of the damage to factories and infrastructure, it will be weeks or evenmonths ________ the country‘s supply chain returns to nor mal.A. thatB. beforeC. whenD. since38. ________ she was at the time of the murder was of major concern to the police that areinvestigating the case.A. WhenB. WhyC. WhetherD. Where39. So _________ that even the people in the next room could hear him.A. loudly he spokeB. he spoke loudlyC. loudly did he speakD. loudly spoke did he40. People may forget what you said or what you did, but they will never forget _______ youmade them feel.A. whyB. howC. whatD. thatSection BDirections: Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.The Man Booker Prize for Fiction is awarded every year for a novel written by a writer from the Commonwealth or the Republic of Ireland and it aims to ___(41)___ the very best in contemporary fiction. The prize was ___(42)___ called the Booker-McConnell Prize, which was the name of the company that ___(43)___ it, though it was better-known as simply the ‗Booker Prize‘. In 2002, the Man Group became the sponsor and they chose the new name, keeping‗Booker‘.Publishers can submit(提交) books for ___(44)___ for the prize, but the judges can also ask for books to be submitted they think should be ___(45)___. Firstly, the Advisory Committee give advice if there have been any changes to the rules for the prize and selects the people who willjudge the books. The judging panel(评审团)changes every year and usually a person is only a judge once.Great efforts are made to ensure that the judging panel is ___(46)___ in terms of gender and professions within the industry, so that a writer, a critic, an editor and an academic are chosen along with a well-known person from wider society. However, when the panel of judges has been ___(47)___, they are left to make their own decisions without any further ___(48)___ orinterference from the prize sponsor.The Man Booker judges include critics, writers and academics to maintain the consistent(始终如一的) quality of the prize and its influence is such that the winner will almost certainly see the sales ___(49)___ considerably, in addition to the £50,000 that comes with the prize.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases markedA, B, C and D. Fill in each blank with the word or phrase that best fits the context.Auditing(旁听)classes at university is an ideal way of learning or trying out new areas of study without committing yourself. You can study alongside fellow students without any ___(50)___ to participate in formal assessments or gain credits for your degree.The trend of auditing university classes has ___(51)___ across universities. Recently, Fudan Postgraduate, a publication by Fudan University, even ___(52)___ a map guide on its campus. Altogether, it features 25 courses, including details of lectures, venues, times and recommendations. Students can design their own auditing ___(53)___ based on a handy map. Zhu, editor of the guide, said that she has ___(54)___ from the trend herself – she successfully moved from a bachelor‘s degree in biochemistry to her current one after auditing classes. ―Visiting classes helped me a lot. The teachers of outstanding courses seldom teach strictly according to textbooks, which is attractive to students. Their tutoring methods have ___(55)___ my mind,‖ Zhu said.Other students audit purely out of ___(56)___. Shi Shuai, 22, a senior majoring in administration management at Shantou University, attended courses in economics and finance for one year. ―It is a great way to explore professional knowledge outside your ___(57)___,‖ said Shi, who acquired the basics of accounting and finance management.Despite the ___(58)___ of learning in an open environment, university administrators remind us that there are still rules to follow. Not all classes accept outsiders, especially minority language classes and science modules. These are often taught in small groups to ensure the ___(59)___of learning, or require special equipment and individual instruction, which is only ___(60)___ to registered students who pay tuition fees.Regulations vary across departments and universities. According to Huang Xiaoxiong, a journalism teacher at Fudan University, students need to ensure that auditing a class is permitted. ―It is about basic manners. You need to let the teacher know about your ___(61)___,‖ he explained. ―It‘s polite to greet the teacher when attending a course. Participate in discussions, bu t do not distract (使分心) others,‖ Huang added. ―It‘s okay to hand in homework assigned by the teacher, but expect general advice rather than careful correction.‖Auditing classes ___(62)___ or beyond one‘s ability can be a waste of time, warns Xu Jun, 27, H R manager at Guangzhou Automobile Industry Group. ―It‘s good to audit some classes. But you have to manage your time well, as you can‘t get any academic credit or formal ___(63)___ for these courses,‖ Xu suggested.―Even though your interests are important, your ___(64)___ is the first thing to consider at university.‖50. A. limitation B. hesitation C. obligation D. tendency51. A. swept B. split C. smashed D. survived52. A. imposed B. inserted C. extended D. released53. A. habit B. route C. data D. rule54. A. benefited B. transferred C. suffered D. managed55. A. kept B. burdened C. expanded D. changed56. A. kindness B. interest C. pressure D. instinct57. A. major B. campus C. control D. potential58. A. instructions B. advantages C. possibilities D. qualifications59. A. effectiveness B. uniqueness C. consciousness D. seriousness60. A. affordable B. portable C. adaptable D. available61. A. preference B. existence C. expectation D. performance62. A. regularly B. purposefully C. moderately D. aimlessly63. A. education B. investigation C. recognition D. comment64. A. decision B. diligence C. devotion D. degreeSection BDirections: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)Marlon Brando is widely considered the greatest movie actor of all time. He was born in Omaha Nebraska in 1924. He was named after hisfather, a salesman. His mother, Dorothy, was an actress in the local theater.Marlon Brando moved to New York City when he was 19 years old in 1943. He took acting classes at the New School for Social Research. One of his teachers was Stella Adler, who taught the "Method" style of realistic acting. The Method teaches actors how to use their own memories and emotions to identify with the characters they are playing.Marlon Brando learned the Method style quickly and easily. Critics said he was probably the greatest Method actor ever. One famous actress commented on his natural ability for it. She said teaching Marlon Brando the Method was like sending a tiger to jungle school.Marlon Brando appeared in several plays. He got his first major part in a Broadway play in 1947, at the age of 23. He received great praise for his powerful performance at Stanley Kowalski in Tennessee Williams' play, A Streetcar Named Desire. His fame grew when he acted the same part in the movie version, released in 1951.Marlon Brando won the Best Actor Oscar for The God Father, but he rejected it. He sent a woman named Sasheen Littlefeather to speak for him at the Academy Awards ceremony. She said that Brando could not accept the award because of the way the American film industry treated Native Americans. The people at the Academy Awards ceremony did not like the speech. But some experts think the action helped change the way American Indians were shown in movies.Marlon Brando acted in about forty movies. He was nominated for a total of eight Academy Awards. But he earned a "bad boy" reputation for his public outbursts and unusual behaviours. According to Los Angeles magazine, "Brando was rock and roll before anybody knew what rock and roll was". His later life was marked with family tragedies. His son Christian went to prison for killing his daughter Cheyene‘s boyfriend. Cheyene later committed suicide. Brando became lonely. He worked occasionally for the money. But, in his prime, Marlon Brando was an actor other actors could only hope to become.65. According to the passage, the "Method" ______.A. requires actors to use their imagination in actingB. made Marlon Brando a great and famous actorC. wasn't very difficult for Marlon BrandoD. can be most effectively learned in a jungle66. The speech at the Academy Awards ceremony ______ at the time.A. made Sasheen Littlefeather well-knownB. was well-received by Native AmericansC. changed people's attitude to American IndiansD. received both positive and negative responses67. Which of the following is NOT true according to the passage?A. Marlon Brando‘s later life was troubled and unhappy.B. A Streetcar Named Desire was later adapted into a movie.C. Marlon Brando was the first rock star in USA.D. As an actor, Brando‘s talent was unparalleled.68. The purpose of this passage is to ______.A. inform us of Marlon Brando's attitude to civil rights movementB. introduce Marlon Brando as one of the greatest actorsC. help us understand Marlon Brando's secret to successD. instruct us how to become a great actor like Marlon Brando(B)what is called a "homestay"69. From the passage we can conclude that ―Learning English Video Project‖ is most probably________.A. an online language learning courseB. audio documents on language learningC. a series of short video programsD. a set of films on English-speaking countries70. If someone is interested in the comparison between English and other languages, he might beinterested to watch __________.A. Encounters in the UKB. Stories from MoroccoC. Thoughts from BrazilD. Insights from China71. What can we know about English learning in Sao Paulo, Brazil?A. Classroom teaching is more interactive and communicative.B. Homestay arrangement provides positive experience for learners.C. The Internet and games plays a major role in language learning.D. The principle of learning by doing is widely accepted by learners.(C)It is found that American students spend les s than 15% of their time in school. While there‘s no doubt that school is important, a number of recent studies reminds us that parents are even more so. A study published earlier this month by researchers at North Carolina State University, for example, finds that parental involvement — checking homework, attending school meetings and events, discussing school activities at home —has a more powerful influence on students‘ academic performance than anything about the school the students attend. Another study, published in the Review of Economics and Statistics, reports that the effort put forth by parents (reading stories aloud, meeting with teachers) has a bigger impact on their children‘s educational achievement than the effort devoted by either teachers or the students themselves. And a third study concludes that schools would have to increase their spending by more than $1,000 per pupil in order to achieve the same results that are gained with parental involvement.So parents matter. But it is also revea led in researches that parents, of all backgrounds, don‘t need to buy expensive educational toys or digital devices for their kids in order to give them an advantage. They don‘t need to drive their offspring to enrichment classes or test-preparation courses. What they need to do with their children is much simpler: talk.But not just any talk. Recent research has indicated exactly what kinds of talk at home encourage children‘s success at school. For example, a study conducted by researchers at the UCLA School of Public Health and published in the journal Pediatrics found that two-way adult-child conversations were six times as potent in promoting language development as the ones in which the adult did all the talking. Engaging in this reciprocal(双向的) back-and-forth gives children a chance to try out language for themselves, and also gives them the sense that their thoughts and opinions matter.The content of parents‘ conversations with kids matters, too. Children who hear talk about counting and numbers at home start school with much more extensive mathematical knowledge, report researchers from the University of Chicago. While the conversations parents have with their children change as kids grow older, the effect of these exchanges on academic achievement r emains strong. Research finds that parents play an important role in what is called ―academic socialization‖ —setting expectations and making connections between current behavior and future goals. Engaging in these sorts of conversations has a greater impact on educational accomplishment.72. Parents are even more important than schools in that ______.A. parental involvement makes up for what schools are not able to doB. teachers and students themselves do not put in enough effortC. parental involvement saves money for schools and the local governmentD. students may well make greater achievements with parents' attention73. It can be inferred from the 2nd paragraph that ______.A. educational toys are unaffordable nowadaysB. digital devices can give children an advantageC. some parents believe in enrichment classesD. talking with children is a very simple task74. The word "potent" is closest in meaning to ______.A. powerfulB. difficultC. necessaryD. resistant75. Which of the following will more encourage children's success at school according to thepassage?A. Parents order their children to stop playing video games.B. Parents discuss with their children the possible future career.C. Parents lecture their children on getting too low marks on tests.D. Parents introduce colleges around the US to their children.Section CDirections: Read the following text and choose the most suitable heading from A-F for each paragraph. There is one extra heading which you do not need.Starting Your Own BusinessStart with an idea. This doesn't have to be a brand new invention or new product. In fact, many successful small businesses have found a way to deliver an existing service more efficiently or economically or have customized an existing product or service. Evaluate your competitors - how many competitors, how strong are they, where are they, how will you compete. State what is required to enter this market, barriers to entry such as high fixed costs (factories, restaurants) and government regulations that must be met.This doesn't mean build a big factory or a fancy office. It simply means keep accurate customer records, a clean set of updated books and a technology foundation, if necessary. One of the downfalls of many small businesses is that they don't know if they're making or losing money (i.e. the need for a clean set of books). Another downfall is when small business owners try to sell their company years later but lack accurate customer history and customer information.Once you know you can be profitable take the leap and get started. Besides getting business supplies or advertising, plan ahead by establishing some new business clients ahead of time. If your business is unlike a restaurant, that physically needs to wait for customers to walk into itsdoors, establish accounts ahead of time. In this way, you will have pre-planned future receivables to look forward to.Use every technology available that will give your business a competitive advantage. The internet is a customers‘ research tool. Help future customers learn more about you and the details about what you sell and why your products or services are different and better for them than other competitors.Carrying cash can be risky. Therefore, most people choose to carry Visa, Mastercard, American Express and Discover. All these credit cards are part of our everyday life when it comes to making purchases. Debit cards are especially popular. So, along with having a sales counter cash register, get set up to accept credit cards for your business. To do this, also purchase a new credit machine.Section DDirections: Read the passage carefully. Then answer the questions or complete the statements in the fewest possible words.If yo u need another reason to give thanks at the dinner table on Thanksgiving Day, how‘s this: people who maintain an ―attitude of gratitude‖ tend to be happier and healthier than those who don‘t, according to an instructive article this week in the Wall Street Journal.The WSJ‘s Melinda Beck reports that adults who feel grateful have ―more energy, more optimism, more social connections and more happiness than those who do not, according to studies conducted over the past decade. Now a new study conducted by researchers at Hofstra University — the results of which are set to be published in an upcoming issue of the Journal of Happiness Studies — finds similar benefits of gratitude for adolescents as well.Dr. Jeffrey J. Froh, assistant professor of psychology and lead researcher of the new study, surveyed 1,035 students aged from 14 to 19 and found that grateful students reported higher grades, more life satisfaction, better social integration and less envy and depression than their peers who were less thankful and more materialistic. Additionally, feelings of gratitude had a more powerful impact on the students‘ lives overall than materialism.What the majority of the research suggests is that gratitude should be chronic(长期的) in order to make a lasting difference in well-being. Dr. Robert Emmons, professor of psychology at the University of California, Davis, and a pioneer in gratitude research, told the WSJ that in order to reap(收获)all of its benefits, feeling gratitude must be rooted into your personality, and you must frequently acknowledge and be thankful for the role other people play in your happiness:―The key is not to leave it on the Thanksgiving table,‖ he said.For older children and adults, one simple way to cultivate gratitude is to literally count your blessings. Keep a journal and regularly record whatever you are grateful for that day. Be specific. Listing ―my friends, my school, my dog‖ day after day means that ―gratitude tiredness‖ has set in, Dr. Froh says. Writing ―my dog licked my face when I was sad‖ keeps it fresher. The real benefit comes in changing how you experience the world. Look for things to be grateful for, and you‘ll start seeing them.Studies show that using negative, insulting words — even as you talk to yourself — can darken your mood, as well. Fill your head with positive thoughts, express thanks and encouragement aloud and look for something to be grateful for, not criticize, in those around you, especially loved ones.(Note: Answer the questions or complete the statements in NO MORE THAN TEN WORDS.)81. According to the article in the Wall Street Journal, people who don‘t maintain an ―attitude of gratitude‖ tend to be ______________.82. What are the major findings of the new study at Hofstra University about?83. Acco rding to the passage, how can people probably avoid ―gratitude tiredness‖?84. In order not to darken our moods, we‘d better stop ________________.第II卷(共45分)I . TranslationDirections: Translate the following sentences into English, using the words given in the brackets.1. 每个市民都应自觉遵守交通法规。
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2013学年第一学期徐汇区学习能力诊断卷
高三年级数学学科(理科)2014.1
一. 填空题:(本题满分56分,每小题4分)
1. 计算:210lim 323
x n n →∞++= . 2. 函数x x y 2cos 2sin =的最小正周期是 .
3. 计算:122423432⎛⎫⎛⎫⋅+ ⎪ ⎪⎝⎭⎝⎭
= . 4. 已知3sin 5x =,,2x ππ⎛⎫∈ ⎪⎝⎭,则x = .(结果用反三角函数表示) 5. 直线()1:330l a x y ++-=与直线()2:5340l x a y +-+=,若1l 的方向向量是2l 的法向量,则实数a = .
6. 如果()1111112312
n f n n n =++++++++ (*n N ∈)那么()()1f k f k +-共有 项. 7. 若函数()f x 的图像经过(0,1)点,则函数()3f x +的反函数的图像必经过点 .
8. 某小组有10人,其中血型为A 型有3人,B 型4人,AB 型3人,现任选2人,则此2人是同一血型的概率为 .(结论用数值表示)
9. 双曲线22
1mx y +=的虚轴长是实轴长的2倍,则m = . 10. 在平面直角坐标系中,动点P 和点M (-2,0)、N (2,0)满足0MN MP MN NP ⋅+⋅= ,则动点P (x ,y )的轨迹方
程为 .
11. 某人5次上班途中所花的时间(单位:分钟)分别为x ,y ,10,11,9.已知这组数据的平均数为10,方差为2,则x y -的值为 .
12. 如图所示,已知点G 是△ABC 的重心,过G 作直线与AB 、AC 两边分别交于M 、N 两点,且,AM xAB AN yAC == ,则xy x y
+的值为 . N M G C
B A
13. 一个五位数abcde 满足,,,a b b c d d e <>><且,a d b e >>(如37201,45412),则称这个五位数符合“正弦规律”.那么,共有 个五位数符合“正弦规律”.
14. 定义区间(),c d 、[),c d 、(],c d 、[],c d 的长度均为()d c d c ->.已知实数(),a b a b >.则满足111x a x b
+≥--的x 构成的区间的长度之和为 . 二. 选择题:(本题满分20分,每小题5分)
15. 直线()0,0bx ay ab a b +=<<的倾斜角是------------------------------------------------------------------------( )
(A) arctan a b π- (B) arctan b a π- (C) arctan a b ⎛⎫- ⎪⎝⎭ (D) arctan b a ⎛⎫- ⎪⎝⎭
16. 为了得到函数2sin ,36x y x R π⎛⎫=+∈ ⎪⎝⎭
的图像,只需把函数2sin ,y x x R =∈的图像上所有的点--------------------------------------------------------------------------------------------------------------------------------------( )
(A) 向右平移
6
π个单位长度,再把所得各点的横坐标伸长到原来的3倍(纵坐标不变) (B) 向左平移6
π个单位长度,再把所得各点的横坐标伸长到原来的3倍(纵坐标不变) (C) 向右平移6π个单位长度,再把所得各点的横坐标缩短到原来的13
倍(纵坐标不变) (D) 向左平移6π个单位长度,再把所得各点的横坐标缩短到原来的13倍(纵坐标不变) 17. 函数()f x x x a b =++是奇函数的充要条件是------------------------------------------------------------------( )
(A) 0ab = (B) 0a b += (C) 220a b += (D) a b =
18. 已知集合()(){},M x y y f x ==,若对于任意()11,x y M ∈,存在()22,x y M ∈,使得12120x x y y +=成立,则称集合M 是“垂直对点集”.给出下列四个集合:
①()1,M x y y x ⎧
⎫==⎨⎬⎩⎭
; ②(){},sin 1M x y y x ==+; ③(){}2,log M x y y x ==; ④(){}
,2x
M x y y e ==-. 其中是“垂直对点集”的序号是---------------------------------------------------------------------------------------( )
(A) ①② (B) ②③ (C) ①④ (D) ②④
三. 解答题:(本大题共5题,满分74分)
19. (本题满分12分)
在△ABC 中,BC =a ,AC =b ,a 、b 是方程22320x x -+=的两个根,且120A B +=
,求△ABC 的面积及AB 的长.
20. (本题满分14分,第(1)小题7分,第(2)小题7分)
已知函数()()21,65f x x g x x x =-=-+-. (1)若()()g x f x ≥,求实数x 的取值范围;
(2)求()()g x f x -的最大值.
21. (本题满分14分,第(1)小题5分,第(2)小题9分)
某种海洋生物身体的长度()f t (单位:米)与生长年限t (单位:年)
满足如下的函数关系:()41012
t f t -+=+.(设该生物出生时t =0) (1)需经过多少时间,该生物的身长超过8米;
(2)设出生后第0t 年,该生物长得最快,求()00*t t N ∈的值.
22. (本题满分16分,第(1)小题4分,第(2)小题5分,第(3)小题7分) 给定椭圆()22
22:10x y C a b a b
+=>>,称圆心在坐标原点O ,半径为22a b +的圆是椭圆C 的“伴随圆”,已知椭圆C 的两个焦点分别是()()
122,0,2,0F F -. (1)若椭圆C 上一动点1M 满足11124M F M F += ,求椭圆C 及其“伴随圆”的方程;
(2)在(1)的条件下,过点()()0,0P t t <作直线l 与椭圆C 只有一个交点,且截椭圆C 的“伴随圆”所得弦长为23,求P 点的坐标;
(3)已知()()cos 3,,0,sin sin m n mn m n θθπθθ
+=-=-≠∈,是否存在a ,b ,使椭圆C 的“伴随圆”上的点到过两点()()22,,,m m n n 的直线的最短距离22min d a b b =+-.若存在,求出a ,b 的值;若不存在,请说明
理由.
23. (本题满分18分,第(1)小题4分,第(2)小题5分,第(3)小题9分)
称满足以下两个条件的有穷数列12,,,n a a a 为()2,3,4,n n = 阶“期待数列”:
①1230n a a a a ++++= ;②1231n a a a a ++++= .
(1)若等比数列{}n a 为()2*k k N ∈阶“期待数列”,求公比q 及{}n a 的通项公式;
(2)若一个等差数列{}n a 既是()2*k k N ∈阶“期待数列”又是递增数列,求该数列的通项公式;
(3)记n 阶“期待数列”{}i a 的前k 项和为()1,2,3,,k S k n = :
(i )求证:12
k S ≤; (ii )若存在{}1,2,3,,m n ∈ 使12m S =
,试问数列{}k S 能否为n 阶“期待数列”?若能,求出所有这样的数列;若不能,请说明理由.。