Discrete-Time System Analysis in the z-Domain

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Y (z) ay[1]z bz z z a z a z 1
ay[1]z
bz2
z a (z a)(z 1)
(5.6)
Expanding
bz2
1 ab /(a 1) b /(a 1)
(z a)(z 1) z z Hale Waihona Puke Baidua
The system given by (5.1) has no initial energy at time n=0 if y[–1] =0, in which case (5.3) reduces to
4
Y (z) bz X (z)
(5.4)
za
Defining (5.4) becomes
Y (z) a{z1Y (z) y[1]} bX (z)
(5.2)
where Y(z) is the z-transform of the output response y[n] and X(z) is the z-transform of the input x[n]. Solving (5.2) for Y(z) yields
2
First-order Case
Consider the linear time-invariant discrete-time system given by the first-order input/output difference equation
y[n]+ay[n–1] = bx[n]
1
§5-1 Transfer Function Representation
In this section the transfer function representation is generated for the class of causal linear time-invariant discrete-time systems. The development begins with discrete-time systems defined by an input/output difference equation. Systems given by a first-order input/output difference equation are considered first.
z 1
(5.7)
and taking the inverse z-transform of both sides of (5.6) gives
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y[n] ay[1](a)n b [a(a)n (1)n ] a 1
ay[1](a)n b [(a)n1 1] a 1
3
Y (z) ay[1]z bz X (z)
(5.3)
za za
Equation (5.3) is the z-domain representation of the discretetime system defined by the input/output difference equation (5.1). The first term on the right-hand side of (5.3) is the ztransform of the part of the output response resulting from the initial condition y[–1], and the second term on the right-hand side of (5.3) is the z-transform of the part of the output response resulting from the input x[n] applied for n=0, 1, 2, ….
Chapter 5 Discrete-Time System Analysis in the z-Domain
§5-1 Transfer Function Representation §5-2 Transform of the Input/output Convolution Sum §5-3 Stability of Discrete-time Systems §5-4 Frequency Response of Discrete-Time Systems Problems
5
Example 5.1 Step response
For the system given by (5.1), suppose that a0 and x[n] is equal to the unit-step function u[n n]. Then X(z)=z/(z–1), and from (5.3) the z-transform of the output response is
(5.1)
where a and b are real numbers, y[n] is the output, and x[n] is the input. Taking the z-transform of both sides of (5.1) and using the right-shift property gives
H(z) bz za
Y(z) H(z)X(z)
(5.5)
The function H(z) is called the transfer function of the system since it specifies the transfer from the input to output in the zdomain assuming no initial energy (y[–1] =0). Equation (5.5) is the transfer function representation of the system.
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