修改答案

30
n=stlen[aa]; / c=aa[i];
n=strlen(aa); / ch=aa[i];
31
k++ / if(m=k)
k++; / if(m==k)
32
(char s,char t) / t[2*d-1]=’\0’
(char *s,char *t) / t[2*d]=’\0’
33
(i=2;i<m;i++) / y+=1/(i*i)
return sp;
25
void fun / elseIf(m>a[mid])
fun / else if(m>a[mid])
26
(long s,lont t) / while(s<0)
(long s,lont* t) / while(s>0)
序号
错误
正确答案
27
fun(double a , double x0)/
For / c[t]=”\0”;
for / c[t]=’\0’;
51
(int n,int xx[][]) / printf(“%4f’,xx[i][j]);
(int n,int xx[][M]) / printf(“%4 d”,xx[i][j]);
52
fun(n) / if(n=1)
int fun(int n) / if(n==1)
68
for(i=1;i<y;i++) / t=t/1000;
for(i=1;i<=y;i++) / t=t%1000;
69
k=n; / c=k/10;
k=i; / c=k%10;
70
d=0;s=1; / s=s/10;
d=1;s=0; / d=d/10;
71
int i,j,k,sum; / if(sum%4=2)/return j;
t+=1.0/i; / return t;
66
void fun(int a) / a[j]=a[j+1];
void fun(int *a) / a[j]=a[j-1];
67
for(i=0;i<3;i++) / if(k>=1 && k<=6)
for(i=1;i<3;i++) / if(k>=0 && k<=6)
13
long s=0,t=1; / t=t%10;
long s=0,t=0; / t=t/10;
14
a2=k%10; / return k;
a2=k/10; / return i;
15
voidfun(char a) / printf(“%c” *a)
void fun(char *a) / printf(“%c” ,*a)
(i=2;i<=m;i++) / y+=1.0/(i*i)
34
(i%2&&s[i]%2==0) / t[i]=’\0’;
(i%2||s[i]%2==0) / t[j]=’\0’;
35
if(P==n) / a[i+1]=a[i];
if(p==n) / a[i]=a[i+1];
36
*r=t; /填空
r=t; / r=t；
if(fabs(x1-x0)<0.00001)
double fun(double a , double x0)/
if(fabs(x1-x0)>=0.00001)
28
p=j / p=j；
p=j；/ p=i；
29
FU(m,n) ((m/n))/return(Value)
FU(m,n) (m)/(n)/return(value)
16
n=*p-‘o’; / n=n*7+*p-‘0’;
n=*p-‘0’; / n=n*8+*p-‘0’;
17
(d%2=0) / s\=10;
(d%2==0) / s/=10;
18
while((high>=2)&&n<10) / yes=0,break
while((high>=2)&&n<10)) / yes=0, break;
63
result*=--n; / return ;
result*=n--; / return result;
64
if(p==’ ’) / *(p-1)=toupper(*(p-1))
if(*p==’ ’) / *(p-1)=toupper(*(p-1));
65
t+=1.0/k; /return i;
19
s[j]=s[i] / s[i]=’\0’
s[j++]=s[i] / s[j]=’\0’
20
(long s,lont t) / s1=s1*100
(long s,lont* t) / s1=s1*10
21
f(double x) / result s
double f(double x) / return s;
22
fun(int x,y,z)/return i;
fun(int x,int y,int z)/return j;
23
while( r)/{*a=*r;a++;r++ }
while( *r)/{*a=*r;a++;r++; }
24
fun(char (*sq)[N])/
return sq;
char *fun(char (*sq)[M])/
int i,j=0,k,sum; / if(sum%4==2) / return j++;
72
if(t=0) / zero=count;
if(t==0=0; / d=i-a;
y=1; / d= a-i;
74
return 1; / return 3;
return 3; / return 1;
void fun/num[k]=0; / switch(*s)
81
(char *s,int a,int b) / a++; / b++;
(char *s,int *a,int *b) / *a++; / ++(*b)
82
sum=1; / scanf(“%d”,a[i][j];)
sum=0; / scanf(“%d”,&a[i][j];)
75
c=c-32; / c=c-5;
c=c+32; / c=c+5;
76
p=(NODE) / return p;
p=(NODE*) / return h;
77
double fun(int m) / for(i=2,i<=m;, ++)
double fun(int m) / for(i=2;i<=m;i++)
37
while(fabs(t)>=num)/ t=s%n;
while(t >=num)/t=s/n;
38
while(*s!=@) / (*s)++;
while(*s!=’\0’) / s++;
39
s[j]=s[i]; / s[j]=”\0”;
s[j++]=s[i]; / s[j]=’\0’;
40
int sum=0.0; / sum\=c
78
int fun(int n)/ for(i=2;i<n;i++)
float fun(int n)/ for(i=2;i<=n;i++)
79
voidupfst(char p)
#include “stdiio.h” / void upfst(char *p)
80
fun/num[i]=0; / switch(s)
a[j][k]＝k*j;
void fun(int a[][M], int m) /
a[j][k]=(k+1)*(j+1);
91
(i=2;i<m;i++) / y-=1/(i*i)
(i=2;i<=m;i++) / y-=1.0/(i*i)
92
(i%k!=0) / if(k<i)
(i%k==0) / if(k>=i)
7
b[k]=p/ b[k]=” ”;
b[k]=*p/ b[k++]=’ ‘;
8
if(‘a’<=tt[i])||(tt[i]<=’z’)) / tt[i]+=32
if(‘a’<=tt[i])&&(tt[i]<=’z’)) / tt[i]-=32
9
for( , , )/ *(pstr+i)=pstr+j;
47
if n==0 / result*=n--
if(n==0) / result*=n--;
48
s=s+(n+1)/n; / return s;
s=s+(double)(n+1)/n; / return t;
49
sun / if(i+1%5==0)
sum=0.0 / if((i+1)%5==0)