四氧化三铁的化学式分子质量及元素质量比

四氧化三铁的化学式分子质量及元素质量比
（中英文实用版）
英文文档：
Iron(III) oxide, also known as ferric oxide, has the chemical formula Fe3O4.To calculate the molecular weight of Fe3O4, we add up the atomic weights of each element in the formula.The atomic weight of iron (Fe) is approximately 55.845 g/mol, and the atomic weight of oxygen (O) is approximately 16 g/mol.
Molecular weight of Fe3O4 = (3 × atomic weight of Fe) + (4 × atomic weight of O)
Molecular weight of Fe3O4 = (3 × 55.845 g/mol) + (4 × 16 g/mol) Molecular weight of Fe3O4 = 167.535 g/mol + 64 g/mol
Molecular weight of Fe3O4 = 231.535 g/mol
ow let"s discuss the elemental mass ratio in Fe3O4.The elemental mass ratio is the ratio of the mass of one element to the mass of another element in the compound.
Elemental mass ratio of Fe to O in Fe3O4 = (3 × atomic weight of Fe) / (4 × atomic weight of O)
Elemental mass ratio of Fe to O in Fe3O4 = (3 × 55.845 g/mol) / (4 × 16 g/mol)
Elemental mass ratio of Fe to O in Fe3O4 = 167.535 g/mol / 64 g/mol Elemental mass ratio of Fe to O in Fe3O4 ≈ 2.639
中文文档：
四氧化三铁，也称为氧化铁(III)，其化学式为Fe3O4。

要计算Fe3O4的分子量，我们需要将公式中每个元素的原子量相加。

铁（Fe）的原子量约为55.845 g/mol，氧（O）的原子量约为16 g/mol。

Fe3O4的分子量= （3 × 铁的原子量）+ （4 × 氧的原子量）
Fe3O4的分子量= （3 × 55.845 g/mol）+ （4 × 16 g/mol）
Fe3O4的分子量= 167.535 g/mol + 64 g/mol
Fe3O4的分子量= 231.535 g/mol
接下来，让我们讨论Fe3O4中的元素质量比。

元素质量比是一个化合物中一个元素的质量与另一个元素的质量的比值。