重庆大学C语言

程序设计技术重点知识点一、C语言的基本概念（数据类型，常量，变量，表达式的书写方法等）典型运算符的使用（++，--,复合赋值等）关系运算和逻辑运算基本控制结构（特别注意++，--运算符的进入条件表达式）*参考例题1、2、3（包括：习题2、一4,5）二、函数的递归调用（进制转换/例题4，最大公约数/例题5e0515等）函数的指针参数（处理实参/例题6 e0504，返回多个值/例题7实验七等）穷举算法的实现（爱因斯坦阶梯/例题8，数字拆分(水仙花数)/例题9，素数/例题10等）宏代换的使用（不带参数/例题11e0525，带参数/例题12e0527）全局变量和局部静态变量（例题13习题5、一7）文件处理简单应用（文件处理模式/例题14，统计文件中的特定数据/例题15，用文件保存数据处理结果）三、数组元素的引用、指针与数组（用指针引用数组元素/例题16习题8 一、5）结构体数组与指针的关系（用指针访问结构体数据成员）（例题17、18习题10，一1、4）字符串处理基础（字符串的拷贝、链接，字符的插入/删除，字符或子串的统计、插入/删除等）例题19、20、、、例题1、#include<stdio.h>#include<math.h>void main(){ int a=1,b=5,c;c=++a||b++;printf("%d,%d,%d\n",a,b,c);c=sqrt(a+b)>2;printf("%d\n",c);for(c=a;c++<b;)printf("c=%d\n",c);while(a!=5&&c<7){ a++;c--;}printf("a=%d,c=%d\n",a,c);if(c%2)printf("c=%d\n",c);}例题2、#include<stdio.h>void main(){ int x=0,y=-1,z=-1;x+=-z---y;printf("%d,%d,%d\n",x,y,z);}//结果：2，-1，-2例题3、#include<stdio.h>void main(){ int x=-3;x+=x-=x*x;printf("x=%d\n",x);}//结果：x=-24例题4#include<stdio.h>void main(){ void transto8(int n);int num;printf("?num: ");scanf("%d",&num);transto8(num);printf("\n");}void transto8(int n){ if(n!=0){ transto8(n/8);printf("%d",n%8);}}例题5#include<stdio.h>void main(){ int Gcd(int m,int n); int num1,num2;printf("请输入两个正整数：");scanf("%d,%d",&num1,&num2) ;if(num1<num2)num1=num1+num2,num2=num1-n um2,num1=num1-num2;printf("%d与%d的最大公约数是：%d\n",num1,num2,Gcd(nu m1,num2));}int Gcd(int m,int n){ int r;if((r=m%n)==0)return n;elsereturn Gcd(n,r);}例题6#include<stdio.h>void main(){ void swap(int *x,int *y); int a=3,b=5;printf("swap函数调用前：a=%d,b=%d\n",a,b);swap(&a,&b);printf("swap函数调用后：a=%d,b=%d\n",a,b);}void swap(int *x,int *y) { int t;t=*x,*x=*y,*y=t;}例题7#include<stdio.h>void main(){ int addmul(int x,int y,int *m);int a=10,b=20,sum,mul; sum=addmul(a,b,&mul);printf("sum=%d,mul=%d\n",s um,mul);}int addmul(int x,int y,int *m){ int s;s=x+y;*m=x*y;return s;}例题8#include<stdio.h>void main(){ int i,j;for(i=0;i<=100;i++)for(j=0;j<=100;j++)if(30*i==7*j+1)printf("输出的结果为：%d\n",7*j);}例题9#include<stdio.h>void main(){ int a,b,c,n;printf("水仙花数：");for(n=100;n<999;n++){ a=n/100;b=n%100/10;c=n%10;if(n==a*a*a+b*b*b+c*c*c)printf("%4d、",n);}printf("\n");}例题10#include<stdio.h>#include<math.h>void main(){ int a,b,num,i,k;printf("Input a & b:"); scanf("%d，%d"，&a，&b); for(num=a;num<=b;num++) { k=(int)sqrt(num); //标准函数库sqrt的返回值是double类型for(i=2;i<=k;i++)//内层循环用来寻找2 sqrt（num）之间能被num整除的数if(num%i==0)break;//如果找到能够被num整除的数，则提前退出内层for循环if(i>k)printf("%d是素数。

\n");}}例题11#include<stdio.h>#define N 2#define M N+2#define MN 2*Mvoid main(){ int x=MN;printf("x=%d\n",x);}例题12#include<stdio.h>#define Min(x,y) (x)<(y)?(x):(y)void main(){ int a=1,b=2,c=3,d=4,t; t=Min(a+b,c+d)*1000;printf("t=%d\n",t);}例题13#include<stdio.h>int a,b,c,d;void main(){ void p(int a,int b);a=b=c=d;printf("%d,%d,%d,%d\n",a,b ,c,d);p(a,b);printf("%d,%d,%d,%d\n",a,b ,c,d);}void p(int a,int b){ static int c;a++,b++;c-=10,d+=5;if(a<3)p(a,b);printf("%d,%d,%d,%d\n",a,b ,c,d);}例题14#include<stdio.h>void main(){ FILE *f1;char c='A';int i;for(i=0;i<10;i++){ f1=fopen("data.txt","w" );fputc(c,f1);fclose(f1);}}例题15#include<stdio.h>void main(){ FILE *fp;int c1,c2,c3,c4;char c;c1=c2=c3=c4=0;if((fp=fopen("mydata.txt","r"))==NULL){ printf("Can't open file.\n");return;}c=fgetc(fp);while(c!=EOF){ c1=c1+1;if(c>='A'&&c<+'Z'||c>='a'& &c<='z')c2=c2+1;else if(c>='0'&&c<='9') c3++;else if(c=='\n')c4++;c=fgetc(fp);}printf("字符：%4d\n字母：%4d\n数字：%4d\n行数：%4d\n",c1,c2,c3,c4);fclose;}例题16#include<stdio.h>#define M 5void f(int *v);void main(){ int b[M][M]={{13,12},{0},{3,5, 8},{5,6}},i,j;f(b[1]);for(i=0,i<M;i++){ for(i=0,j<M;j++)printf("%3d",*(*(b+i)+j)); printf("\n");}}void f(int *v){ int i;for(i=0;i<M*(M-1);i++) *(v+i)+=3;}例题17#include<stdio.h>struct T{ int x;char c;};void main(){ void f(struct T b);struct T a={110,'z'};f(a);printf("%d,%c\n",a.x,a.c); }void f(struct T b){ b.x=20;b.c='y';}例题18#include<stdio.h>void main(){ struct T{ int x;int *y;}*p;int dt[]={10,20,30,40}; struct T d[]={50,&dt[1],70,&dt[2],8 0,&dt[3]};p=d;printf("%d\n",++p->x); printf("%d\n",(++p)->x);printf("%d\n",++(*p->y)); }例题19#include<stdio.h>#include<string.h>void main(){ int countsubstr(char *s,char c);char s1[100],ch,n;gets(s1);ch=getchar();n=countsubstr(s1,ch);printf("n=%d\n",n);}int countsubstr(char *s,char c){ int i=0,counter=0;while(s[i]){ if(s[i]==c)counter++;i++;}return counter;}例题20#include<stdio.h>#include<string.h>void main(){ int countsubstr(char *s,char *t);char s1[100],s2[100],n; gets(s1);gets(s2);n=countsubstr(s1,s2);printf("n=%d\n",n);}int countsubstr(char *s,char *t){ int i=0,counter=0;while(*(s+i)){ if(strncmp(s+i,t,strlen (t))==0)counter++;i++;}return counter;}。