补充练习三
语言学补充练习(1-3)
第一章语言学入门知识:I. 名词解释1.cultural transmission (as a defining property of language)Answer: While human capacity for language has a genetic basis, the details of any language system are not genetically transmitted, but instead have to be taught and learned. An English speaker and a Chinese speaker are both able to use a language, but they are not mutually intelligible. This shows that language is culturally transmitted. It is passed on from one generation to the next through teaching and learning, rather than by instinct. In contrast, animal call systems are genetically transmitted. They are born with the capacity to produce the set of calls peculiar to their species.2.descriptive linguistics vs. prescriptive linguisticsAnswer: A linguistic study is descriptive if it describes and analyses facts observed; it is prescriptive if it tries to lay down rules for "correct" behavior. Linguistic studies before the 204 century are largely prescriptive whereas modem linguistic is mostly descriptive.II. 判断正误(T for True and F for False)1. When language is used to get information, it serves an informative function.Answer: F (It serves an interrogative function).2.Most animal communication systems lack the primary level of articulation.Answer: F (The primary units in these systems cannot be further divided into elements. So what they lack is the secondary level of articulation.) 3.Descriptive linguistics are concerned with how languages work, not with how they can be improved.Answer: TIII. 填空题1.By saying that "language is arbitrary", we mean that there is no logical connection between meaning and _______.Answer: sounds2.The distinction between langue and parole is made by the Swiss linguist E de Saussure. The distinction between competence and performance is made by the American linguist__________.Answer: Noam Chomsky3.An approach to linguistic study which attempts to lay down rules of correctness as to how language should be used is _______.Answer: prescriptiveIV. 选择题1.Unlike animal communication system, human language is ______.A. stimulus freeB. stimulus boundC. under immediate stimulus controlD. stimulated by some occurrence of communal interestAnswer:A2. ____ has been widely accepted as the forefather of modem linguistics.a. Chomskyb. Saussurec. Bloomfieldd. John LyonAnswer: bV. 问答题l. Is language productive or not? Why?Answer: Firstly, Language is productive or creative. This means that language users can understand and produce sentences they have never heard before. Secondly, Productivity is unique to human language. Most animal communication systems have a limited repertoire, which is rapidly exhausted, making any novelty impossible. Thirdly, The productivity or creativity of human language originates from its duality. Because of duality, the speaker can combine the basiclinguistic units to form an infinite set of sentences. The productivity of language also means its potential to create endless sentences. This is made possible by the recursive nature of language.2. Comment on the f ollowing statement: “In linguistics, ‘language’ onlymeans what a person says or said in a given situation”.Answer: This statement is incorrect. In linguistics, "language" has several layers of meaning: firstly, the whole of a person’s language, e.g. Sha kespeare’s language; secondly, a particular variety or level of speech or writing, e.g. scientific language, literary language, colloquial language; thirdly, an abstract system underlying the totality of the speech/writing behavior of a community, e.g. the English language, the Chinese language; lastly, there is an even more abstract sense of "language", referring to the common features of all human languages that distinguish them from animal communication systems or any artificial language.3. Point out three ways in which linguistics differs from traditional grammar.Answer: Firstly, most linguistic analyses today focus on speech rather than writing. Secondly, modem linguistics is mostly descriptive while traditional grammar is largely prescriptive. Thirdly, a third difference is the priority of synchronic description over the traditional diachronic studies.4. What is the major difference between Saussure' s distinction between langue and parole and Chomsky's distinction between competence and performance?Answer: Saussure’s langue is social product, a set of conventions for a speech community. Chomsky regards competence as a property of themind of each individual. Saussure studies language more from a sociological point of view while Chomsky studies it more from a psychological point of view.第二章语音学和音位学I. 名词解释1.narrow transcriptionAnswer: There are two ways to transcribe speech sounds. One is the “broad transcription”----the transcription with letter-symbols only, and the other is “narrow transcription”---the transcription with letter-symbols accompanied by the diacritics which can help bring out the finer distinctions than the letters alone may possibly do.2. Illustrate the term “allophone” with at least one appropriate example. Answer: Allophones are the different members of a phoneme, sounds which are phonetically different but do not make one word different from another in meaning. For example, in English, the phoneme /l/ is pronounced differently in "let", "play" and "tell". The first /l/ is made by raising the front of the tongue to the hard palate, while the vocal cords are vibrating; the second /l/ is made with the same tongue position as the first, but the vocal cords are not vibrating; and the third /l/ is made by raisingnot only the front by also the back of the tongue while the vocal cords are vibrating.II 判断正误(T for True and F for False)1. /o/ is a mid-high front rounded vowel.Answer: F. (/o/ is a mid-high BACK rounded vowel.)2. A phoneme in one language or one dialect may be an allophone in another language or dialect.Answer: T.III. 填空题:1. The three cavities in the articulatory apparatus are _____, _______, and _____.Answer: pharynx, the nasal cavity, the oral cavity2. By the position of the ____ part of the tongue, vowels and classified as front vowels, central vowels and back vowels.Answer: highest.3. ____refers to the change of a sound as a result of the influence of an adjacent sound.Answer: Assimilation.4. You are required to fill in the blanks below abiding by the instancegiven beforehand.Example: /p/: voiced bilabial stop/s/: ________________/g/:_______________/tʃ/:______________/t/: _______________/f /: _______________Answer:/s/: voiceless alveolar fricative/g/: voiced velar stop/tʃ/: voiceless alveo-palatal/post-alveolar affricate/ t /: voiced dental fricative/f /: voiceless labiodental fricative5. Which of the following words would be treated as minimal pairs and minimal sets?pat, pen more, heat, tape, bun, fat, ban, chain, tale, bell, far, meal, vote, bet, heel, ten, men, pit, main, hit, eat, manAnswer:pat, fat; pat, pit; pit, hit;pen, ten; ten, men;heat, eat; heat, heel;tape, tale;bun, ban;chain, main;bell, bet;meal, heel;man, men, main.IV. 选择题1. All syllables contain a(n) _______.a. nucleusb. codac. onsetAnswer: a2. _____is one of the supersegmental features.a. Stopb. Voicingc. Deletiond. ToneAnswer: d3. Which of the following consonants does not exist in English?a. dental stopb. bilabial stopc. alveolar stopd. velar stopAnswer: a4. _____is not an English consonant.a. Labiodental plosiveb. Alveolar nasalc. Velar stopd. Dental fricativeAnswer: aV. 辨音选择1. What are the distinctive features that group the following sounds in these sets?1) /f, v ,s/2) /p, f, b/3) /g, z, b/4) /k, g, w/5) /m, n, ŋ/Answer: 1) fricative 2) obstruent 3) voiced 4) velar5) nasal2. There is one segment that does not belong to the natural class in each of the following groups of speech sounds. You are required to identify that segment and label the natural class, using a descriptive term asspecific as possible.a) /m/, /n/, /w/, / ŋ /b) /v/, /w/, /z/, /t/c) /n/, /f/, /l/, /s/, /t/, /d/, /z/Answer:1) /w/ is a semi-vowel, and the others are all nasals.2) /t/ is voiceless, and the others are voiced.3) /f/ is labiodental, and the rest are alveolarVI. 问答题1.Circle the words that contain a sound as required:1) a low vowel: pipe, gather, article, leave, cook2) a bilabial consonant: cool, lad, leap, bomb, push3) an approximant: luck, boots, word, once, table4) a front vowel: god, neat, pit, lush, cook5) a velar: god, fast, chat, lake, quick2.Exemplify the relationship between phone, phoneme and allophone. Answer: Firstly, a “phone” is a phonetic unit or segment. The speech sounds we hear and produce during linguistic communication are all phones. Phones may or may not distinguish meaning. Secondly, a "phoneme" is a phonological unit that is of distinctive value. As an abstract unit, a phoneme is not any particular sound. It is represented orrealized by a certain phone in a certain phonetic context. Thirdly, the phones representing a phoneme are called its "allophones". How a phoneme is represented by a phone, or which allophone is to be used, is determined by the phonetic context in which it occurs. But the choice of an allophone is not random but rule-governed in most cases.3.When we are pronouncing the following phrases, how do we actually articulate the "n" sound in the word "ten"? Do we still pronounce it as /n/?1) ten houses 2) ten teachers 3) ten colleges 4) ten pupils 5) ten buildings 6) ten classesAnswer: 1) /n/2) /n/3) / ŋ /4) /m/5) /m/6) / ŋ /4.How many functions do the vocal cords have in the production of speech sounds?Answer: They have three functions: to make a glottal stop, to produce a voiced sound and to produce a voiceless sound.第三章形态学I. 名词解释1.morphemeAnswer: The morpheme is the smallest unit in terms of relationship between expression and content, a unit which cannot be divided without destroying or drastically altering its meaning, whether it is lexical or grammatical. For instance, the word "barks" in "The dog barks" consists of two morphemes ― "bark" and "-s", neither of which can be further divided into other smaller meaningful units.2.lexemeAnswer: The term "lexeme" is postulated to reduce the ambiguity of the term "word". It is the abstract unit underlying the smallest unit in the lexical system of a language, which appears in different grammatical contexts. For example, "write" is the lexeme of the following set of words: "writes", "wrote", "writing", "written".3.inflectional morphemesAnswer: Inflectional morphemes are also called inflectional affixes. They manifest various grammatical relations or grammatical categories such as number, tense, degree and case. In English, all inflectional morphemes are suffixes, e.g. -(e)s, -ing, -(e)d, -est.II. 判断正误1.A root is not always a free form.Answer: T (There are such bound roots as “-ceive”.)III. 填空题1.Polymorphemic words other than compounds have two parts: the roots and the ____.Answer: affixes2.On, before and together are_____words ― they are words which do not take inflectional endings.Answer: grammatical (functional/form)IV.选择题1."Radar" is a/an____.a. acronymb. blendingc. coinaged. clippingAnswer: a2.Compound words consist of______ morphemes.a. boundb. freec. both bound and freeAnswer: bV. 匹配题Match each expression under A with the one statement under B that characterizes it.A B1. a noisy crow a. compound noun2. eat crow b. root morpheme plus derivational prefix3. scarecrow c. phrase consisting of an adjective plus noun4. the crow d. root morpheme plus inflection affix5. crowlike e. root morpheme plus derivational suffix6. crows f. grammatical morpheme followed by lexical morphemeg. idiomAnswer: 1. c 2. g 3. a 4. f 5. e 6. dVI. 问答题1. Divide the following words into Roots, IA (inflectional affix) and/or DA (derivational affix).1) transformations 2) looseleaves3) destructive 4) geese 5) misledAnswer:1) trans- (DA) form (Root) -ation (DA) s (IA)2) loose (Root) leave (Root) s (IA)3) de- (DA) struct (Root) -ive (DA)4) geese (IA)5) mis- (DA) led (IA)2. Label the morphological category of the morphemes underlined in each of the English expressions.a) I' ve been here.b) transformc) oxend) recurAnswer: a) bound morpheme b) derivational prefix c) inflectional suffix d) bound root3. Each of the following Persian words is poly-morphemic. You are required to match each of the notions given below with a morpheme in Persian. (Note that xar means "buy" and -id designates the past tense). xaridiYou (singular) bought.naxaridamI did not buy.namixaridandThey were not buying.xaridHe bought.naxaridimWe did not buy.mixaridHe was buying.mixarididYou (plural) were buying.xaridamI bought.Match each of the notions given below with a morpheme in Persian:a) Ib) you (singular)c) notd) was/were V-ing (continuous)Answer: a) amb) ic) nad) miVid4.It is a fact that morphological processes may be sensitive to certain phonological context. The English data given below illustrate this fact. You are required to state the phonological contexts where the addition of -en is possible.a bwhiten *bluenmadden *stupidenredden *greenenFatten *fartheren quicken *slowendeafen *difficultenLiven *abstractenharden *shallowensoften *angryendeepen *vividenAnswer: The suffix -en, which attaches to adjectives to form verbs, can only attach to monosyllabic bases ending in oral stops or fricatives.VerbAdjective-en if Adjective ends in an obstruent (oral stop or fricative).- <Φ> if Adjective ends in a sonorant (nasal, approximant, vowel) Meaning: to make (more) Adjectives5.The word uneasiness may be analyzed in either of the two ways below. You are required to find an argument to support one of the two analyses.a)NPrefixNoununAdjectiveSuffixeasinessb)NAdjectiveSuffixPrefixAdjectivenessuneasiAnswer: b) is the correct analysis, because un- only attaches to adjectivesto form other adjectives. Un- cannot be attached to a noun.。
2013翻译转译法
英译汉翻译技巧:转换法转换法指翻译过程中为了使译文符合目标语的表述方式、方法和习惯而对原句中的词类、句型和语态等进行转换。
具体的说,就是在词性方面,把名词转换为代词、形容词、动词;把动词转换成名词、形容词、副词、介词;把形容词转换成副词和短语。
在句子成分方面,把主语变成状语、定语、宾语、表语;把谓语变成主语、定语、表语;把定语变成状语、主语;把宾语变成主语。
在句型方面,把并列句变成复合句,把复合句变成并列句,把状语从句变成定语从句。
在语态方面,可以把主动语态变为被动语态。
(一)转译成动词1. 名词转译为动词The very sight of it makes me nervous一看到他,我就感到紧张。
A careful study of the original text will give you a better translation.仔细研究原文,你会翻译得更好。
He is a good singer.他唱歌唱得好。
Too much exposure to TV programs will do great harm to the eyesight of children. 孩子们看电视过多会大大地损坏视力。
(名词转动词)Too little brushing and too many sweets can cause tooth decay, sometimes very seriously.极少刷牙和吃太多的糖果会导致蛀牙,有时会非常严重。
2. 形容词转译成动词常见的有:与思维和知觉相关的形容词:aware, conscious, certain, sure, ignorant(无知的), alert等;与情感相关的形容词:glad, pleased, cautious, careful, angry, happy, excited, confident, thankful, grateful, concerned, eager, afraid, doubtful, sorry等;I am anxious about his health.我担心他的身体健康。
三角形重心、外心、垂心、内心的向量表示及其性质
a P A
b
P B
c P0C,
则
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点
为
三角Leabharlann 形的()
A
外心
B
内心
C
重心
D
垂心
2
CB
2
CP,则P点轨迹一定通
6.在三角形ABC中,动点P满足:CA
2 AB
过
△
ABC
的
:
(
)
A
外心
B
内心
C
重心
D
垂心
7.已知非 零向 量AB与AC满足
AB
AC
BC
0,且AB
AC
1, 则
AB
AC
AB
AC
2
ABC为
A.三边均不相等的三角形
HB AC
0
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同理HC
AB,HA
BC .故H是ABC的垂心.(反之亦然(证略))
3、P是△ABC所在平面上一点,若PA PB
PB PC
PC
PA,则P是△ABC的
垂心.
由PA PB
PB PC,得PB (PA
PC ) 0,即PB CA
0,所以PB⊥CA.同理
可证PC⊥AB,PA⊥BC.
∴P是△ABC的垂心.如图1.
OC,则O是ABC
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B.外 心
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关于“欧拉定理”的一些问题:
著名的“欧拉定理”讲的是锐角三角形的“三心”——外心、重心、垂心的位置关系:
(1)三角形的外心、重心、垂心三点共线——“欧拉线”;
(2)三角形的重心在“欧拉线”上,且为外——垂连线的第一个三分点,即重心到垂心的距离是重心到外心距离的2倍。
现代汉语补充练习答案
《现代汉语》(增订四版)课后补充练习答案现代汉语》第五章语法(一)语法补充练习答案一为什么要学习语法?有人说:不学语法,也能说话写文章。
你认为这种说法对吗?为什么?人从孩提时代就学会了说话,也学会了理解别人所说的话,也就是说已经学到了感性的语法知识,不自觉地运用语法规律了。
因而才有“不学语法,也能说话写文章”的论调。
其实这种说法是很片面的。
因为你所说的不学语法,也能说话写文章的现象是建立在语法知识的感性阶段上的,只有对语法提高到理性认识的高度,自觉地运用它,才能把话说得更好,把文章写得更好。
随着我国对外开放和交往的发展,学习汉语的外国人越来越多,为了适应这种迅速发展的新形势,我们也应该学好自己的母语语法。
尤其是 21 世纪是一个电子计算机在社会生活中发挥巨大作用的时代,为了提高工作效率,使计算机真正做到处理汉语的程序化、自动化,就必须深入研究汉语的语法规则,使之有效地为汉语的计算机处理服务。
而且学会了汉语语法,还可以有效地提高语言教学的效果,在学习其它语言时,还可以自觉地进行对照和比较,较快地学会一门或几门外语。
学会了分析语法的方法,对训练科学的思维方法也是大有益处的。
(二)语法补充练习答案二1.指出下面各组内的词的词性,并说明它们在功能上的区别。
(1)组:“高级”是形容词,“初级”是区别词。
在功能上的区别是:“高级”可“说“非常高级”;“初级”不行。
尽管它们都能修饰名词。
(2)组:“一概”是副词,“一致”是形容词。
“一概”“一致”虽然都能修饰、限制动词,但“一致” 可以受程度副词的修饰,可以作谓语、定语,“一概”不行。
(3)组:“家务”是名词,“医务”是区别词。
“家务”可作主语、宾语,(家务繁重/操持家务)“医务”只能修饰名词(医务人员、医务部门),否定时用“非”(非医务人员)。
(4)组:“常常”是时间副词,“往常”是时间名词。
“常常”修饰、限制动词(常常出去),“往常” 可以用在介词的后面(因为有事,所以比往常回来得晚。
电磁感应复习练习三
高二物理补充练习三 姓名:________1.一个矩形线圈在匀强磁场中转动,产生的感应电动势e =2202sin100πt ,则( )A .交流电的频率是100πB .t =0时,线圈位于中性面C .交流电的周期是0.02sD .t =0.05s 时,e 有最大值2.一只低压教学电源输出的交变电压瞬时U=102sin314t(V),关于该电源的规格和使用,以下说法正确的是( )A. 这只电源可以使"10V 2W"的灯泡正常发光B. 这只电源的交变电压的周期是314sC. 这只电源在t=0.01s 时电压达到最大值D. “10V 2μF”电容器不能接在这只电源上3.有一交变电流如图所示,则由此图象可知( )A .它的周期是0.8 sB .它的峰值是4 AC .它的有效值是2 2 AD .它的频率是0.8 Hz4.一台小型发电机产生的电动势随时间变化的正弦规律图象如图甲所示。
已知发电机线圈内阻为5.0 Ω, 现外接一只电阻为95.0 Ω的灯泡,如图乙所示,则( )A. 电压表V 的示数为220 VB. 电路中的电流方向每秒钟改变50次C. 灯泡实际消耗的功率为484 WD. 发电机线圈内阻每秒钟产生的焦耳热为24.2 J5.如下图所示,甲、乙是规格相同的灯泡,接线柱a 、b 接电压为U 的直流电源时,无论电源的正极与哪一个接线柱相连,甲灯均能正常发光,乙灯完全不亮.当a 、b 接电压的有效值为U 的交流电源时,甲灯发出微弱的光,乙灯能正常发光,则下列判断正确的是( )A .与甲灯串联的元件x 是电容器,与乙灯串联的元件y 是电感线圈B .与甲灯串联的元件x 是电感线圈,与乙灯串联的元件y 是电容器C .与甲灯串联的元件x 是二极管,与乙灯串联的元件y 是电容器D .与甲灯串联的元件x 是电感线圈,与乙灯串联的元件y 是二极管6.两只相同的白炽灯L 1、L 2接到如图所示的电路中,灯L 1与电容器串联,灯L 2与电感器串联,当a 、b 处接电压 最大值为U m 、频率为f 的正弦交流电源时,两灯都发光,且亮度相同。
练习三补充练习
5.李阿姨在网站上八折购买了4台打印机,每台 1600元,如果在实体店按原价购买,那么用同样 的钱最多可以购买多少台?
7.李阿姨进了60箱香梨,第一天卖出后还剩20箱, 第一天卖出后大约还剩这批香梨的百分之几?
①60+10=70cm
②60+10=70cm
①甲、乙合修的工效: ②乙、丙合修的工效: ③剩下的部分三人又合修了5天才完成,可求出三人合作一天的工作效率。
④再分别求出甲、乙、丙的工作效率
⑤再分别求出甲、乙、丙的量
⑥再分别求出甲、乙、丙的劳务费:
练习四
小数 分数
百分 62.5% 数
0.375
1.75 0.5%
1.一种铁矿石含铁30%-32%,至少多少吨这样定价24元,甲书店八折,乙店 六折,在甲店购买比乙店多付多少元?
3.一筐桃,大猴取走总数的40%多3个,小猴取走总 数的45%。两只猴取走的桃正好一样多,这筐桃一共 多少个?
11.一条不足10cm的线段,从一端量起5cm处记点A, 从另一端量起5cm处记点B,AB之间的长度正好是这 条线段的20%,这根线段长几厘米?
2、去掉52%的百分号,这个数就( )。 3、7.5÷37.5%=
Sn=(a1+an)n÷2
12.元旦那天,6位朋友均匀地围坐在圆桌旁共度佳节。圆 桌半径为60cm,每人离圆桌的距离均为10cm,现又来了2 名客人,每人向后挪动了相同的距离,再左右调整位置, 使8人都坐下,并且8人之间的距离与原来6人之间的距离 (即在圆周上两人之间的圆弧的长)相等。每人向后移动 了多少距离?
8.一台音响降价400元后,售价1200元。现价是原 价的百分之几?这台音响是在打几折出售?
职业培训师三级理论知识补充练习题
职业培训师三级理论知识补充练习题(含答案)练习5一.单项选择题:1.企业中()要素是企业经营活动的主体,是其他各要素的支配者。
A.资金B.信息C.人员D.设施2.在企业的各种经营管理要素中,()是基础的、决定性的要素。
A.信息B.资金C.商品D.人员3.企业经营信息中()用于确定企业经营目标,制定经营策略的信息。
A.决策信息B.控制信息C.作业信息D.组织信息4.()是人力资源培训开发的最基础性工作。
A.基本素材台账B.员工基本素质台账C.相关新信息台账D.项目台账5.关于培训计划论述错误的是()A.培训计划是培训工作发展的重要手段B.综合培训计划一般是年度培训计划C.单项培训计划是综合培训计划的基础D.综合培训计划是培训计划中最重要的6.()主要解决培训要达到什么标准的问题A.培训对象B.培训方式C.培训目的D.培训目标7.关于培训计划基本要素论述错误的是()A.技术要求较为专业的培训,其规模都较小B.名人讲座形式的培训可扩大规模C.培训对象主要确定多少人接受培训的问题D.培训教师是培训计划的基本因素8.关于培训方式方法论述错误的是()A.培训方式方法主要是指在职培训还是离职培训B.专业技能培训主要采用边干边学的方式C.高层管理培训常采用分散方式进行D.采用何种培训方式主要由培训目的、对象决定9.企业培训必须服从一定的战略原则,企业的培训战略原则包括两层含义,即服从企业的发展战略和( )。
A.培训工作的效益原则B.从战略角度来开展培训工作C.培训工作的计划原则D.培训工作的系统原则10.目前很多企业的培训工作,经常是培训完了就完了,而没有相应的培训评估和严格的管理,我们称这个现象不符合企业培训的( )原则。
A.投资效益B.严格考核和择优奖励C.主动参与D.长期性11.企业培训的产出不能纯粹以传统的经济核算方式来进行,因为它包括潜在的和发展的因素,另外还有( )。
A.战略的因素B.社会的因素C.企业竞争力的因素 D. 企业员工队伍素质的因素12.培训激励制度是做好培训工作的重要组成部分,所以,在培训激励制度中,需要包括完善的岗位任职资格要求、业绩考核标准、公平竞争的晋升规定和( )等四个方面。
病句的辨析与修改(补充练习)
病句的辨析与修改补充练习一:1、名著不管是不是够格,总是时间和空间筛选。
2、这个地方很特别,一到节假日、星期天,到处冷冷清清。
3、最近省博物馆展出2000多年前新出土的文物。
4、听了这个讲座,使我增长了很多知识。
5、这个神话虽然也反映了部落之间的斗争,但很能说明古代人对我国地形的看法。
6、到了冬天,脚湿病也会暂时静止一下。
7、他跳下池塘,来到池边,很快就游了过去。
8、同学以敬佩的目光注视着和倾听着这位老英雄的报告。
9、《包身工》是剥削制度下是悲惨女工生活的写照。
10、在新长征的路上,我们及时取得了一些成绩但这仅仅是第一步。
11、为了防止类似事故不再发生,交通管理局多次召开会议认真研讨解决。
12、60年代初,第一次发现了世界各地已经灭绝了的动物---黑颈鹤。
13、在老师的帮助下,使我认识到了错误。
14、通过告别网吧的主题班会,使同学们有了很大触动。
15、到处校园里充满了欢歌笑语。
16、我校8个教师的孩子都已解决了就业问题。
17、学校开展地震安全常识教育活动,可以增强同学们的安全自我保护。
18、他的学习成绩不仅在全校是拔尖的,而且在班里也名列前茅。
19、从大量的观测事实中告诉我们:要掌握天气的连续变化,最好每小时都进行观测。
20、复习时,我们要克服没有计划、没有重点。
21、我一直思想着那件事。
22、每天从凌晨5点到下午2点,他在车上摇来晃去的时间。
23、许多附近的老人、青年和孩子都跑来观看。
24、看了电视剧《围城》,使我对那时的生活有了更多的认识。
25、我们要解决并分析问题。
26、我们肩负着建设祖国和保卫祖国。
27、这个学校的共青团员,决心响应团委人人为“希望工程”献爱心。
28、一进会场就看见许多面彩旗和欢乐的歌声。
29、我们一些足球运动员的技术水平没有多大改善。
30、解放军同志奋不顾身地抢救粮食、棉花和人民的生命财产。
31、晴朗的夜空,群星灿烂,汇成一幅星星的世界。
32、有没有良好的思想品德,是评价一个优秀学生的标准之一。
人教版六年级数学上册补充教材练习三
发现:连乘的积都等于 8201。因为任
意3个既不同行又不同列的数连乘
都可以转化为
1 2
2 3
3 5
7 4
6 5
5 8
,
积是 21。
80
×
1
2
3
2
3
5
7
7
7
21
4
8
6
20
6
3
4
18
5
5
5
25
5
5
5
3
8
16
12
8
21 (1 1) = 21 4 3
3 = 28(天)
鸭的孵化期是多少天?
鸡的孵化期21天
鸭的孵化期 比鸡长 1
3
答:鸭的孵化期是28天。
6.磁悬浮列车的运行速度是430千米/时,普通列车
31
比它慢 43 。普通列车的速度是多少? (课本P15 练习三 第6题)
430 (1 31)=120(千米/时)Байду номын сангаас43
R.六年级上册
1
练习三
1.人体血液在主动脉中的流动速度约为20厘米/秒,
在静脉中的流动速度约为主动脉中的 2 ,在毛细血
管中的流动速度大约只有静脉中的
1
5
。血液在毛
160
细血管中每秒约流动多少厘米?(教科书P15 练习三 第1题)
20× 2 × 1 = 1(厘米) 5 160 20
答:血液在毛细血管中每秒约流动 1 厘米。
40× 3 × 2 43
=30 2 3
=2(0 年)
答:海豹的寿命大约是20年。
5
3.芍药的花期是32天,玫瑰的花期是芍药的 8 ,
氮相关高考题及其答案
限时训练11一、氮气【真题一】制备氮化镁的装置示意图如下:回答下列问题:(1)检查装置气密性的方法是_______________________________________________ ,a的名称是 ______________ ,b的名称是;(2)写出NaNO2和(NH4)2SO4反应制备氮气的化学方程式__________________ ;(3)C的作用是“ ____________ ,D的作用是___________________________ ,是否可以把C和D的位置对调并说明理由________________________ ;(4)写出E中发生反应的化学方程式__________________________________ ;(5)请用化学方法确定是否有氮化镁生成,并检验是否含有未反应的镁,写出实验操作及象。
【补充练习一】固态化合物A由两种短周期元素组成,可与水发生复分解反应。
甲组同学用下图装置(夹持装置略)对其进行探究实验。
(1)仪器B的名称是_____________________ 。
(2)实验中,n中的试纸变蓝,w中黑色粉末逐渐变为红色,并有M生成,则m中的试剂为,W中发生反应的化学方程式为 _______________________________________________ , V中的试剂为。
(3)乙组同学进行同样实验,但装置连接顺序为i—m—w—n—v—w,此时n中现象为,原因是__________________________________________________________________ 。
(4)经上述反应,2.5g化合物A理论上可得到0.56L(标准状况)M,则A的化学式为。
【补充练习二】氯离子插层镁铝水滑石[Mg2Al(OH)6cl - xH2O]是以中国新型离子交换材料,其在高温下完全分解为MgO、Al2O3、HCl和水蒸气,现用下图装置进行实验确定其化学式(固定装置略去)。
时间单位换算试
时间单位换算试————————————————————————————————作者:————————————————————————————————日期:《时、分、秒》补充练习一班级: 姓名:1、在50米决赛时,小丽用了11秒,小玉比她快1秒,小玉用了( )秒。
2、老师和同学们去春游,要求大家8:00到校,看一看谁没迟到,在下面画“√ ”。
晚到的同学迟到了( )秒。
丽丽 ( ) ( ) 涛涛出发时刻 经过时间到达时刻 2:052:453、把下表补充完整。
《时、分、秒》补充练习二班级:姓名:()分()秒=450秒60秒=()分()分=300秒3分= ()秒210秒=()分()秒()分()秒=150秒()秒=1分30秒6分=()秒8分=()秒()秒=7分()分()秒=270秒()秒=4分300秒=()分()秒=4分30秒()分=480秒()分=60秒8:1025分钟30分钟12:00120秒= ()分2分= ()秒120秒=( ) 分270秒=()分()秒()秒=7分()分()秒=330秒60秒= ()分()秒=6分480秒=()分180秒=()分7分30秒=()秒()分=180秒3分30秒=()秒150秒=()分()秒9分= ()秒9分30秒=()秒330秒=()分()秒()秒=5分1分30秒= ()秒1分= ()秒270秒=()分()秒()秒=5分()秒=1分30秒90秒= ()分()秒《时、分、秒》补充练习三班级:姓名:()分=540秒()分=60秒540秒=()分()分=480秒60秒=()分()秒=9分30秒1分=()秒7分30秒=()秒330秒=()分()秒210秒=()分()秒()秒=1分()分=420秒9分=()秒420秒=()分60秒= ()分4分30秒=()秒6分30秒=()秒8分30秒=()秒3分=()秒120秒=()分()秒=1分30秒270秒=()分()秒3分30秒=()秒7分30秒=()秒7分=()秒7分30秒=()秒()分=120秒 360秒=()分480秒=()分420秒=()分2分30秒=()秒5分= ()秒8分=()秒()秒=7分30秒()秒=8分30秒180秒=()分()分=420秒7分=()秒390秒=()分()秒9分30秒=()秒《时、分、秒》补充练习四班级:姓名:1、我们早上8:05开始上第一节课,8:45下课,这节课上了多长时间?2、叔叔早上8时上班,中午11时30分下班午休,下午1时上班,4时下班回家,他一天工作多长时间?3、吴老师加班改作业,预计晚上7:00能完成。
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5.如图,在直角坐标系中,点 O 是圆心,点 A(13,0),Y=kx-3k+4 与⊙O 交与 B、C 点,求弦 BC 的最小值
6.如图,已知 A、B 两点的坐标分别为(2 则点 P 的坐标为____
3 ,0)(0,2),P 是△AOB 外接圆上的一点,且∠AOP=45°,
7.已知:如图,A,B 是半圆 O 上的两点,CD 是⊙O 的直径,∠AOD=80°,B 是 (1)在 CD 上求作一点 P,使得 AP+PB 最短; (2)若 CD=4cm,求 AP+PB 的最小值.
补充练习三:圆的经典试题 1. 已知:如图 2, PAC 30 ,在射线 AC 上顺次截取 AD=3cm,DB=10cm,以 DB 为直径作 ⊙O 交射线 AP 于 E、F 两点,求圆心 O 到 AP 的距离及 EF 的长.
P F E A D O B C
2.已知:如图,M 是弧 AB 的中点,过点 M 的弦 MN 交 AB 于点 C,设⊙O 的半径为 4cm,MN=4 3 cm. (1)求圆心 O 到弦 MN 的距离; (2)求∠ACM 的度数.
的中点.
8.已知 Rt△ABC 中,ACB 90 ,CA CB ,有一个圆心角为 45 ,半径的长等于 CA 的扇形 CEF 绕点 C 旋 转,且直线 CE,CF 分别与直线 AB 交于点 M,N.
2 2 2 (Ⅰ)当扇形 CEF 绕点 C 在 ACB 的内部旋转时,如图①,求证: MN AM BN ;
2 2 2 (Ⅱ) 当扇形 CEF 绕点 C 旋转至图②的位置时, 关系式 MN AM BN 是否仍然成立?若成立, 请证明;
若不成立,请说明理由.
C
C
E A E M N F 图 C
O · D B
N
3.如图,⊙O 是△ABC 的外接圆,且 AB=AC,点 D 在弧 BC 上运动,过点 D 作 DE∥BC,DE 交 AB 的延长线于点
E,连结 AD、BD. (1)求证:∠ADB=∠E (2)当 AB=5,BC=6 时,求⊙O 的半径.
A
B E
O
C D
4.如图,四边形 ABCD 内接于圆,若 AB=AC,且∠ABD=60°.求证:AB=BD+CD。