玉田二中第二学期阶段考试A卷试题

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2018-2019年第二学期河北唐山市玉田县八年级地理考试试卷(A)

2018-2019年第二学期河北唐山市玉田县八年级地理考试试卷(A)

2018-2019年度第二学期唐山市玉田县八年级地理考试试卷(A)【湘教版:第5-7章】考生注意:1.本卷共4页,总分50分,考试时间35分钟。

2.答题前请将密封线左侧的项目填写清楚。

3.答案请用蓝、黑色钢笔或圆珠笔填写。

题号一二总分21 22得分一、选择题(共20道小题,每小题只有一个正确答案,每小题1分,共20分)读我国四大地理区域划分图,完成1-3题1.下列叙述正确的是()A.甲地主要种植水稻、甘蔗、柑橘B.乙地区农作物的熟制为一年一熟或两年三熟C.丙地区为半湿润地区D.丁地区的自然特征是高和寒2.品尝糌粑最好到()A.甲地区B.乙地区C.丙地区D.丁地区3.图中甲、乙、丙、丁四地民风民俗对应关系,正确的是()A.甲─端午赛龙舟B.乙─那达慕大会C.丙─迎送宾客献哈达D.丁─冬季滑雪运动2009年12月26日,武汉至广州高铁开通运营。

请读图完成4-5题4.有关武广高铁沿线的自然地理特征的叙述正确的是()A.主要经过了温带季风气候区B.连接了湖北、江西、广东三省C.缓解了京九铁路的压力。

D.武广高铁联系了长江水系和黄河水系。

5.武广高铁沿线最有可能看到的景观是()A.成群的牦牛B.一望无际的苹果林C.风吹草低见牛羊D.一片片的稻田读下图,回答6-8题。

6.图中甲所在的地形区是()A.塔里木盆地B.四川盆地C.华北平原D.云贵高原7.图中①----②----③降水量逐渐减少,形成这种差异的主要因素是()A.地形因素B.纬度因素C.海陆位置D.人类活动8.下列图片所示的传统民居中属于该地区的是()9.关于图中阴影区域的叙述正确的是()A.图中阴影区域是三江源地区B.被誉为“中华水塔”,取之不尽,用之不竭C.是长江、黄河、雅鲁藏布江上游最主要的水源涵养区D.该地区光照强烈,气温日较差小10.下列与东北地区相关的叙述,错误的是()A.城市密集,多沿交通干线分布B.“汽车工业的摇篮”长春C.地形以高原为主D.中部和南部平原地区人口多读“东北三省主要矿产资源、工业中心和交通”图,完成11-12题。

河北省唐山市玉田县高二数学下学期期中试卷文(含解析)

河北省唐山市玉田县高二数学下学期期中试卷文(含解析)

2016-2017学年河北省唐山市玉田县高二(下)期中数学试卷(文科)一、选择题(共12小题,每小题5分,满分60分)1.在如图所示的知识结构图中:“求简单函数的导数”的“上位"要素有()A.1个B.2个C.3个D.4个2.下列类比推理命题(其中Q为有理数集,R为实数集,C为复数集):①“若a,b∈R,则a﹣b=0⇒a=b"类比推出“若a,b∈C,则a﹣b=0⇒a=b”;②“若a,b,c,d∈R,则复数a+bi=c+di⇒a=c,b=d”类比推出“若a,b,c,d∈Q,则a+b⇒a=c,b=d”;③“若a,b∈R,则a﹣b>0⇒a>b”类比推出“若a,b∈C,则a﹣b>0⇒a>b”.其中类比结论正确的个数是( )A.0 B.1 C.2 D.33.下列求导运算正确的是()A.(log2x)′=B.()′=C.(10x)′=10x lge D.(x+)′=1﹣4.下面几种推理中是演绎推理的为()A.科学家利用鱼的沉浮原理制造潜艇B.猜想数列,,,…的通项公式为a n=(n∈N+)C.半径为r的圆的面积S=πr2,则单位圆的面积S=πD.由平面直角坐标系中圆的方程为(x﹣a)2+(y﹣b)2=r2,推测空间直角坐标系中球的方程为(x﹣a)2+(y﹣b)2+(z﹣c)2=r25.设a,b大于0,则a+,b+的值()A.都大于2 B.至少有一个不大于2C.都小于2 D.至少有一个不小于26.函数y=xcosx﹣sinx在下面哪个区间内是增函数( )A.(,)B.(π,2π)C.(,)D.(2π,3π)7.要证:a2+b2﹣1﹣a2b2≤0,只要证明()A.2ab﹣1﹣a2b2≤0 B.a2+b2﹣1﹣≤0C.﹣1﹣a2b2≤0 D.(a2﹣1)(b2﹣1)≥08.如图所给的程序运行结果为S=35,那么判断框中应填入的关于k的条件是()A.k=7 B.k≤6 C.k<6 D.k>69.复数z满足(1+i)z=|﹣i|,则=()A.1+i B.1﹣i C.﹣1﹣i D.﹣1+i10.已知函数f(x)=x3﹣3x+m只有一个零点,则实数m的取值范围是( )A.B.(﹣∞,﹣2)∪(2,+∞) C.(﹣2,2)D.(﹣∞,﹣2]∪时,恒有mt﹣f(x)<1成立,求实数t的取值范围.2016-2017学年河北省唐山市玉田县高二(下)期中数学试卷(文科)参考答案与试题解析一、选择题(共12小题,每小题5分,满分60分)1.在如图所示的知识结构图中:“求简单函数的导数"的“上位”要素有()A.1个B.2个C.3个D.4个【考点】EJ:结构图.【分析】先对所画结构的每一部分有一个深刻的理解,从头到尾抓住主要脉络进行分解;再将每一部分进行归纳与提炼,形成一个个知识点并逐一写在矩形框内;最后按其内在的逻辑顺序将它们排列起来并用线段相连,从而形成知识结构图.“求简单函数的导数”是建立在熟练掌握“基本求导公式”,“函数四则运算求导法则”和“复合函数求导法则”基础上的,故三者均为其上位.【解答】解:根据知识结构图得,“求简单函数的导数”是建立在熟练掌握“基本求导公式”,“函数四则运算求导法则”和“复合函数求导法则”基础上的,故“基本求导公式”,“函数四则运算求导法则”和“复合函数求导法则”均为“求简单函数的导数"的“上位”要素,共有3个.故选:C.【点评】本题主要考查了结构图的组成与应用问题,是基础题目.2.下列类比推理命题(其中Q为有理数集,R为实数集,C为复数集):①“若a,b∈R,则a﹣b=0⇒a=b”类比推出“若a,b∈C,则a﹣b=0⇒a=b”;②“若a,b,c,d∈R,则复数a+bi=c+di⇒a=c,b=d”类比推出“若a,b,c,d∈Q,则a+b⇒a=c,b=d”;③“若a,b∈R,则a﹣b>0⇒a>b"类比推出“若a,b∈C,则a﹣b>0⇒a>b”.其中类比结论正确的个数是( )A.0 B.1 C.2 D.3【考点】F1:归纳推理.【分析】在数集的扩展过程中,有些性质是可以传递的,但有些性质不能传递,因此,要判断类比的结果是否正确,关键是要在新的数集里进行论证,当然要想证明一个结论是错误的,也可直接举一个反例,要想得到本题的正确答案,可对3个结论逐一进行分析,不难解答.【解答】解:①在复数集C中,若两个复数满足a﹣b=0,则它们的实部和虚部均相等,则a,b相等.故①正确;②在有理数集Q中,若,则(a﹣c)+(b﹣d)=0,易得:a=c,b=d.故②正确;③若a,b∈C,当a=1+i,b=i时,a﹣b=1>0,但a,b 是两个虚数,不能比较大小.故③错误故3个结论中,有两个是正确的.故选C【点评】类比推理的一般步骤是:(1)找出两类事物之间的相似性或一致性;(2)用一类事物的性质去推测另一类事物的性质,得出一个明确的命题(猜想).但类比推理的结论不一定正确,还需要经过证明.3.下列求导运算正确的是( )A.(log2x)′=B.()′=C.(10x)′=10x lge D.(x+)′=1﹣【考点】63:导数的运算.【分析】根据导数的求导法则,分别计算,即可求得答案.【解答】解:由求导公式可知(log2x)′=,故A正确,对于B:()′==,故B错误,对于C:(10x)′=10x ln10,故C错误;对于D:(x+)′=1+,故D错误,故选A.【点评】本题考查常见函数的求导公式,导数的运算法则,考查计算能力,属于基础题.4.下面几种推理中是演绎推理的为( )A.科学家利用鱼的沉浮原理制造潜艇B.猜想数列,,,…的通项公式为a n=(n∈N+) C.半径为r的圆的面积S=πr2,则单位圆的面积S=πD.由平面直角坐标系中圆的方程为(x﹣a)2+(y﹣b)2=r2,推测空间直角坐标系中球的方程为(x﹣a)2+(y﹣b)2+(z﹣c)2=r2【考点】F5:演绎推理的意义.【分析】本题考查的是演绎推理的定义,判断一个推理过程是否是演绎推理关键是看他是否符合演绎推理的定义,能否从推理过程中找出“三段论”的三个组成部分.【解答】解:选项B是由特殊到一般的推理过程,为归纳推理;选项C:半径为r圆的面积S=πr2,因为单位圆的半径为1,则单位圆的面积S=π中,半径为r圆的面积S=πr2,是大前提单位圆的半径为1,是小前提单位圆的面积S=π为结论;选项A,D是由特殊到与它类似的另一个特殊的推理过程,是类比推理,故选:C.【点评】判断一个推理过程是否是归纳推理关键是看它是否符合归纳推理的定义,即是否是由特殊到一般的推理过程.判断一个推理过程是否是类比推理关键是看它是否符合类比推理的定义,即是否是由特殊到与它类似的另一个特殊的推理过程.判断一个推理过程是否是演绎推理关键是看它是否符合演绎推理的定义,能否从推理过程中找出“三段论"的三个组成部分.5.设a,b大于0,则a+,b+的值( )A.都大于2 B.至少有一个不大于2C.都小于2 D.至少有一个不小于2【考点】7F:基本不等式.【分析】利用反证法:假设a+,b+都小于2,再利用基本不等式的性质得出矛盾【解答】解:假设a+,b+都小于2,∴a++b+<4∵a,b大于0,∴a++b+=(a+)+(b+)≥2+2=4,这与假设相矛盾,故假设不成立,故则a+,b+的值至少有一个不小于2,故选:D.【点评】本题考查了反证法、基本不等式的性质,考查了推理能力与计算能力,属于中档题.6.函数y=xcosx﹣sinx在下面哪个区间内是增函数()A.(,)B.(π,2π)C.(,) D.(2π,3π)【考点】HA:余弦函数的单调性;3E:函数单调性的判断与证明;H5:正弦函数的单调性.【分析】分析知函数的单调性用三角函数的相关性质不易判断,易用求其导数的方法来判断其在那个区间上是减函数.【解答】解:y'=cosx﹣xsinx﹣cosx=﹣xsinx欲使导数为正,只需x与sinx符号总相反,分析四个选项知,B选项符合条件,故应选B.【点评】考查判断函数单调性的方法.一般可以用定义法,导数法,其中导数法判断函数的单调性是比较简捷的方法.7.要证:a2+b2﹣1﹣a2b2≤0,只要证明()A.2ab﹣1﹣a2b2≤0 B.a2+b2﹣1﹣≤0C.﹣1﹣a2b2≤0 D.(a2﹣1)(b2﹣1)≥0【考点】R8:综合法与分析法(选修).【分析】将左边因式分解,即可得出结论.【解答】解:要证:a2+b2﹣1﹣a2b2≤0,只要证明(a2﹣1)(1﹣b2)≤0,只要证明(a2﹣1)(b2﹣1)≥0.故选:D.【点评】综合法(由因导果)证明不等式、分析法(执果索因)证明不等式.8.如图所给的程序运行结果为S=35,那么判断框中应填入的关于k的条件是()A.k=7 B.k≤6 C.k<6 D.k>6【考点】EF:程序框图.【分析】根据程序,依次进行运行得到当S=35时,满足的条件,即可得到结论.【解答】解:当k=10时,S=1+10=11,k=9,当k=9时,S=11+9=20,k=8,当k=8时,S=20+8=28,k=7,当k=7时,S=28+7=35,k=6,此时不满足条件输出,∴判断框中应填入的关于k的条件是k>6,故选:D.【点评】本题主要考查程序框图的识别和判断,依次将按照程序依次进行运行即可.9.复数z满足(1+i)z=|﹣i|,则=( )A.1+i B.1﹣i C.﹣1﹣i D.﹣1+i【考点】A8:复数求模.【分析】设出z=a+bi,得到关于a,b的方程组,求出z的共轭复数即可.【解答】解:设z=a+bi,则(1+i)z=(1+i)(a+bi)=(a﹣b)+(a+b)i,∴,解得:a=1,b=﹣1,故=1+i,故选:A.【点评】本题考查了复数求模问题,考查共轭复数,是一道基础题.10.已知函数f(x)=x3﹣3x+m只有一个零点,则实数m的取值范围是()A.B.(﹣∞,﹣2)∪(2,+∞)C.(﹣2,2)D.(﹣∞,﹣2]∪min=f(ln2)=2﹣2ln2>0,∴g’(x)=f(x)>0,故g(x)在R上单调递增,因此,当x>0时,g(x)>g(0)=1>0,即e x>x2.(Ⅲ)由题意知,,∵F(x)在(1,3)上单调递减,∴F'(x)=x2+2mx﹣2≤0在(1,3)恒成立,∴F′(x)图象过点(0,﹣2),∴,,所以满足实数m的取值范围为(﹣∞,﹣).【点评】本题考查了导函数与函数单调性、最值之间的关系,本题难度适中,属于中档题.20.(12分)(2017春•玉田县期中)如表提供了甲产品的产量x(吨)与利润y(万元)的几组对照数据.x3456y2。

玉田二中第二学期阶段考试a卷试题

玉田二中第二学期阶段考试a卷试题

玉田二中第二学期阶段考试(高二英语)A套试卷第一节单项选择题(25分)1.The couple died but their child ____ after the earthquake .A.lived onB. lived up toC.lived throughD. lived by2.But by no means ___ with my progress .A. the teacher is not satisfiedB. is the teacher not satisfiedC. the teacher is satisfiedD. is the teacher satisfied3 It is not immediately clear ___ the financial crisis will soon be overA. since B what C when D whether4. A good idea ___ him when he was asked to solve the problemA. struke toB. occurred toC. happened toD. stuck to5. ___ we will hold a party in the open air tomorrow depends on the weatherA. whetherB. if C.whatD.which6.The word “media” basically refers to ___ we commonly call newspapers , m agazines, radios and televisionsA. whichB. thatC. whatD.where7.The man has a good sense of humor and we all find it great fun to ___ with him .A. team upB. make upC. catch upD. keep up8.To travel to the United States , you must first apply __ the American embassy __ your visaA. for; toB. to; forC. for; forD.to ;to9. His hard work _____and he made great progress in his EnglishA.paid offB.paid backC.paid forD. paid on10 Many college students _____by the failure to find workA. was much cast downB. were much cast downC. much cast downD. were cast off11 His girlfriend is trying her best to reduce the young man’s fear ___he would die of the disease soonA whenB why C. that D. of which12.Do you have any idea ___TV plays such an important part in our daily life nowadays ?A. why is it thatB. how it is thatC. why was itD. when it was that13.The tsunami ___fear ___the people’s hearts of the tsunami-hit countriesA struck; into B. struck; on C .struck; by D. struck; at14. The young man ___in his first play and became famous overnightA .distinguished himself B. enjoyed himselfC. betrayed himselfD. dressed himself15.____with his brother , the little boy is not clever at all. A. comparing B. comparedC. to compareD. to be compared16. only if a teacher has given permission ___to enter this roomA. a student is allowedB. is allowed a studentC. is a student allowedD. a student allowed17.Such effective measures ___ much earlier , the river would not be polluted so seriouslyA. if we had takenB.had we takenC.takenD. taking18.He goes through the whole performance of checking the oil and water ___ he drives the carA. every timeB. in timeC. whileD. on time19. ___ to nuclear radiation , even for a short time , may produce variants(变体) sf genes in human bodiesA .Being exposed B. Having exposedC. ExposedD. After being exposed20.He ___before he answered because he didn’t know what to sayA. paused B ceased C. hesitated D. stopped21. Their suggestions are of not much ____A. valuableB. valueC. goodD. better22.The emperor traveled ____ in order not to be recognizedA.in the disguise ofB. in disguiseC. without disguise D with disguise23. I remember her face but I can’t ___ where I met herA. recallB. remarkC. remindD. retell24. His accent at once betrayed ____he was a foreignerA which B. that C. what D. with that25. ___, the nutrition in them will be destroyedA. If vegetables are cooked too longB. Cooked too longC. If cooked too longD. If being cooked too long第二节完形填空(20小题每小题1.5分共30分)As she walked round the large shop, Edith realized how difficult it was to choose a suitable Christmas 26 for her father.She 27 that he were as easy to please as her mother, who was 28 satisfied with perfume(香水).29 , shopping at this time of the year was a most 30 job. People 31 on your feet, pushed you with their shoulders and almost 32 you over in their hurry in order to 33 something cheap ahead of you.Partly to have a rest, Edith paused in front of a counter, where some beautiful ties were on 34 . "They are 35 silk," the shop assistant told her with a smile trying to 36 her to buy one. But Edith knew from past 37 that her choice of ties hardly ever pleased her father.She moved on slowly and then, quite by chance, 38 where a small crowd of men had gathered round a counter. She found some fine pipes on sale and the 39 were very beautiful. Edith did not hesitate for long, although her father 40 smoked a pipe once in a while, she believed this was 41 to please him. When she got home, with her small but 42 present hidden in her handbag, it was time for supper and her parents were already43 table. Her mother was in great 44 . "Your father has at last decided to stop smoking," she told her daughter happily. Edith was so 45 that she could not say a single word.26. A. suit B. card C. thing D. gift27. A. believed B. wished C. hoped D. supposed28. A. never B. seldom C. always D. scarcely29. A. Therefore B. Fortunately C. Besides D. Finally30. A. unhappy B. careful C. exciting D. tiring31. A. walked B. stepped C. lifted D. stood32. A. turned B. hit C. brought D. knocked33. A. watch B. find C. grasp D. sell34. A. time B. show C. board D. duty35. A. real B. cheap C. poor D. exact36. A. hope B. ask C. force D. persuade37. A. experience B. things C. books D. school38. A. stopped B. saw C. asked D. found39. A. money B. cigarette C. shapes D. shop40. A. always B. nearly C. only D. never41. A. hardly B. impossibly C. possibly D. certainly42. A. cheap B. well-chosen C. expensive D. ready-made43. A. on B. by C. beside D. at44. A. excitement B. anger C. sadness D. disappointment45. A. glad B. happy C. surprised D. excited第三部分:阅读理解(共20小题,每题2分,满分40分)阅读下列短文,从每题所给的A、B、C、D四个选项中,选出最佳答案.AWASHINGTON -Tofu(豆腐)and Soyaburgers (豆饼) may be coming to American school lunch menus. What will the kids say?“Terrible,” said Greg Dudzinski, 17, of Ripon High School in Wisconsin, as he toured the US capital. “The regular hamburgers are bad enough, so soyaburgers would be a lot worse, offered Zach Richey, 13, of Scottsboro Junior High in Alabama, another tourist.But the United States government – hoping to reduce the amount of fat that children are eating –has approved the use of soy as a meat substitute in meals for schools and day-care centers.Not all kids dislike the change. Mariel Spano, 17, of sandy Greek High School in New York, also visiting the capital, said she likes soyaburgers:“There is less fat, and they are better for you… They taste the same, and they are just as good.”The government tried to make soy a meat substitute nearly 20 years ago, but later dropped the ideA.At the time, the plan was intended as a cost-cutting move. US Agriculture Department officials say that their purpose now is only to make meals healthier.Schools are likely to increase the amount of soy that is mixed with hamburgers and other foods already on their menus, and they will also be looking for food companies to develop new soy products that children will like. “ I can’t see putting tofu on a student’s plate and having a good acceptance. I can see taking a product that is familiar to the students and adding a large amount of soy to it and having it to be acceptable,” said Jill Benza, director of food services for the Mesa, Arizona schools.46.What is the newspaper report mainly about?A.The difficulty in using soy products for US schools.B.Various opinions on soy products for US schools.C.The plan that is made by the US government for school lunch.D.Healthy foods for students in US schools.47.Where did the interviews most probably take place?A.In food companies. B.In schools.C.In Washington. D.In some other states.48.We may learn from the text that _________________________.A.soyaburgers taste better than hamburgers.B.hamburgers are healthier than soyaburgers.C.soyaburgers cost less than hamburgers.D.hamburgers cost less than soyaburgers.49.What Jill Benza said shows that ___________________________.A.students have not yet been used to soy products.B.it is hardly possible to make soy products popular.C.he does not like the change in meals for students.D.schools are unwilling to change the lunch menus.BCutsBleeding can usually be stopped by applying pressure to the cut for 2 or 3 minutes. The cut can then be carefully inspected. If it has bled freely any germs will normally have been washed away by the blood.Apply a plaster dressing firmly, bringing the edges of the cut together so that it knits quickly. Keep dry for 1 to 2 days.If the cut is deep and the edges cannot be pulled together with a dressing consult the doctor or the practice nurse. A tetanus (破伤风) injection may be needed.GrazesDirt will often enter a graze caused by falling on a hard or rough surface. It must be cleaned out carefully with an antiseptic solution. (消毒液)After cleaning, leave the graze uncovered. Exposure to the air will cause a scab to form. This will gradually fry and fall off.It is not a good idea to apply a dressing. This may stick to the graze or make it complete wet and infected.BruisesBruises are very common in children. They normally get better in 7 to 10 days Parents sometimes worry that a bone may be broken, but if in doubt consult the doctor. If a child gets up at once after a fall and moves about normally, it is unlikely that a bone has been broken.Severe bruising can be treated by:Rest for 24 to 48 hours .In the case of a badly bruised leg, the limb should be raised. Lying in bed is the easiest way to do this.A bad compress may ease a bad bruise if applied at once. This is made by leaving some material in water and applying it to the bruise.Insect bitesThese are common in th e summer .They look like spots about 1/4’’across .They are very itchy (痒) and usually appear on exposed parts, e.g. arms and legs.The itching can be relieved by calamine lotion (护肤药水).Burns and scaldsMinor burns and scalds cause redness of the skin. Immediate treatment by pouring cold water over a burn is often helpful. If burns cause the skin severe hot or break the skin, the doctor should be turned to.Sunburns should, if possible, be prevented by avoiding long exposure and covering exposed areas as much as needed. It may be treated by calamine lotion to relieve the pain.50.The purpose of the booklet is _____A.to tell us what to do until a doctor arrives.B.to explain what cause minor illnesses.C.to show that it is unnecessary to call a doctor.D.to help us to treat minor illnesses at home51.When treating a minor cut ,we are first told to _____.A.clean out the wound. B.press down on the wound.C.wash the blood away. D.close up the wound. 52.The injury which we are told how to avoid is _____.A.sunburn. B.insect bites. C.scalds. D.cuts.53.Patients with badly bruised legs are advised to go to bed so that ______.A.they can rest completely. B.their injured leg can be lifted up.C.they can leave their leg in water. D.a cold compress can be appliedCA man was tired of living in his old house in the country and wanted to sell it and buy a better one. He tried to sell it for a long time,but was not successful,so at last he decided to solve the problem by using as real estate agent.(房地产代理人)The agent decided at once to advertise the house,and a few days later,the owner saw a very attractive photograph of it,with a wonderful description of its gardens,in an expensive magazine. After the house owner had read the advertisement through,he hurriedly telephoned the real estate agent and said to him,“I'm sorry,Mr. Jones,but I've decided not to sell my house after all. After reading your advertisement in that magazine,I can see that it's just the kind of house I've wanted to live in all my life.”54.What problem did the man have?A.He couldn't find his houseB.He was unsuccessful at selling his houseC.He was unsuccessful at buying a houseD.He was unsuccessful at finding a real estate agent55.It's easier to sell house through agents because ______.A.they have a magazineB.they are better at writing articlesC.they are good at better advertisingD.they are better looking56.Which of the following best states the main idea?A.You don't know what you have until you have lost it.B.It's hard to sell a houseC.No one likes to live in the country.D.There is no place like home.57.In the passage the word“attractive”most nearly means ______.A.perfectpleteC.modernD.pleasant to look atDHave you ever seen any students whose trousers hang so low you can see their underwear?What do you think of that?Fashionable?Some of today's teenagers are big fans of such a look. But recently this trend has been at the center of an argument in Italian middle schools. The headmaster of a school in central Italy has asked students to stop wearing low-rise jeans that expose underwear and parts of the body. His request came after a class trip,when he saw one boy's baggy trousers slide to his feet. He pointed out that this way of dressing is not suitable for school. But in Italy,a nation that takes fashion very seriously,the suggestion caused a debate among parents,teachers and students. The issue is whether the headmaster's request will limit students' freedom— or whether dress in Italianschools is too casual. A parents' group praised the move in favor of good taste,while others advised schools to stop worrying about fashion and fix up old school buildings.“We do not want to kick fashion out,” the headmaster explained,“but extrems (极端)of fashion like this are not right in school.” Many other schools have now requested that their students also stop wearing such trousers. Most students have simply ignored the request. Ludovica Gaudio,14,wore extremely low trousers exposing orange underwear in class. It was cold,so she wore a matching orange scarf. Another 14-year-old said she would probably respect the request,simply for practical reasons. “I don't really feel comfortable in those sort of jeans,” said Sarah Lattanzi,“in winter,when dressed like that,it's quite cold and I am afraid my stomach will ache.”58. What led to the argument in Italian middle schools?A. Students' craze for fashions.B. Clothes that are too exposing.C. Students' ignoring dress codes(着装规则)D. Students' underwear.59. Which of the following supports the headmaster's request?A. Fashion should be taken seriously.B. Fashion should not be followed in school.C. Students should have their freedom in choosing what they wear.D. Students should be encouraged to have good taste in clothes.60. The argument against the headmaster's request is that ________.A. schools should pay attention to things more important than students' clothesB. fashion should not be followed in schoolC. dress in Italian schools is too casualD. low-rise jeans can do harm to youngster's health61.The purpose of this story is to ________A. show Chinese students that wearing very fashionable clothes in school is under attack in othercountries,too.B. show that dress code is necessary even in a country like ItalyC. tell us that a debate started in Italian middle schools over the way students dress in schoolD. let us see that Italian students react differently to schools' requests.EA year ago, I paid no attention to English idioms, though my teacher emphasized the importance again and again. But soon, the importance of English idioms was shown in an amusing experience.One day, I happened to meet an Englishman on the road, and soon we began totalk. As I was talking about how I was studying English, the foreigner seemed to be astonished gently shaking his head, shrugging his shoulders, saying, “You don’t say!”“You don’t say!” I was puzzled. I thought, perhaps this is not an appropriate topic. “Well, I’d better change the topic. ”So I said to him, “well, shall we talk about the Great Wall?” By the way, have you ever been there? “Certainly, every one back home will laugh at me if I leave China without seeing it. It was magnificent.” He was deep in thought when I began to talk like a tourist guide, “The Great Wall is one of the wonders in the world. We are proud of it.” Soon I was interrupted again by his order “You don’t say!” I couldn’t help asking .I said, “Didn’t you say you don’t say?” Hearing this, the Englishman laughed to tears. He began to explain, “You don’t say actually means really? It is an expression of surprise. Perhaps you don’t pay a ttention to English idioms.” Only then did I had made a fool of myself. Since then I have been more careful with idiomatic expression.62.A year ago, I paid no attention to English idioms because .A.English idioms were too difficult to masterB.I had no interest in English learingC.my teacher didn’t emphasize the importanceD.I cared little about the teacher’s instruction63.When I first heard “You don’t say!” I thought .A.the Englishman was not interested in my EnglishB.the Englishman was only interested in the Great WallC.I had talked too muchD.I had to stop talking at once64.Which of the following is true?A.The Englishman was leaving China without seeing the Great Wall.B.The Englishman wanted to see the Great Wall after I talked about it.C.The Englishman wanted me to act as his guide.D.The Englishman visited the Great Wall and thought it worth visiting65.After the Englishman explained the idiom, .A.the Englishman made me a foolB.the Englishman made a fool of himselfC.I felt very sillyD.I felt proud of my understanding高二英语 卷II (共55分)单词拼写(5分)1.I’d like to come, too, if you have no ___________(反对).2. They were so much alike that we could hardly ____________(区分)one from the other.3.Everything _________(表明) that the day’s work is over.4.The __________(积累的) evidence showed that a puma had escaped from the zoo.5.They occupy a very __________(较高)position in local society. 完成句子(10分)1. 我突然想起今晚我该拜访汤姆。

玉田县第二中学校2018-2019学年高二上学期第二次月考试卷数学

玉田县第二中学校2018-2019学年高二上学期第二次月考试卷数学

玉田县第二中学校2018-2019学年高二上学期第二次月考试卷数学班级__________ 姓名__________ 分数__________一、选择题1. 设曲线y=ax 2在点(1,a )处的切线与直线2x ﹣y ﹣6=0平行,则a=( )A .1B .C .D .﹣12. 若函数)1(+=x f y 是偶函数,则函数)(x f y =的图象的对称轴方程是( )] A .1=x B .1-=x C .2=x D .2-=x 3. 阅读如下所示的程序框图,若运行相应的程序,则输出的S 的值是( )A .39B .21C .81D .1024. 函数()2cos()f x x ωϕ=+(0ω>,0ϕ-π<<)的部分图象如图所示,则 f (0)的值为( )A.32-B.1-C.D.【命题意图】本题考查诱导公式,三角函数的图象和性质,数形结合思想的灵活应用.5. 已知全集U={0,1,2,3,4},集合M={2,3,4},N={0,1,4},则集合{0,1}可以表示为( ) A .M ∪N B .(∁U M )∩N C .M ∩(∁U N ) D .(∁U M )∩(∁U N ) 6. 设集合P={3,log 2a},Q={a ,b},若P ∩Q={0},则P ∪Q=( ) A .{3,0}B .{3,0,1}C .{3,0,2}D .{3,0,1,2}7. 阅读右图所示的程序框图,若8,10m n ==,则输出的S 的值等于( ) A .28 B .36 C .45 D .1208. 已知正方体的不在同一表面的两个顶点A (﹣1,2,﹣1),B (3,﹣2,3),则正方体的棱长等于( )A .4B .2C .D .29. 已知函数f (x )=⎩⎪⎨⎪⎧log 2(a -x ),x <12x ,x ≥1若f (-6)+f (log 26)=9,则a 的值为( )A .4B .3C .2D .110.若抛物线y 2=2px 的焦点与双曲线﹣=1的右焦点重合,则p 的值为( )A .﹣2B .2C .﹣4D .411.下列命题中正确的是( )A .复数a+bi 与c+di 相等的充要条件是a=c 且b=dB .任何复数都不能比较大小C .若=,则z 1=z 2D .若|z 1|=|z 2|,则z 1=z 2或z 1=12.在△ABC 中,内角A ,B ,C 所对的边分别为a ,b ,c ,若sinB=2sinC ,a 2﹣c 2=3bc ,则A 等于( ) A .30° B .60° C .120° D .150°二、填空题13.定义在(﹣∞,+∞)上的偶函数f (x )满足f (x+1)=﹣f (x ),且f (x )在[﹣1,0]上是增函数,下面五个关于f (x )的命题中: ①f (x )是周期函数;②f (x ) 的图象关于x=1对称; ③f (x )在[0,1]上是增函数; ④f (x )在[1,2]上为减函数; ⑤f (2)=f (0). 正确命题的个数是 .14.设x∈(0,π),则f(x)=cos2x+sinx的最大值是.15.对于|q|<1(q为公比)的无穷等比数列{a n}(即项数是无穷项),我们定义S n(其中S n是数列{a n}的前n项的和)为它的各项的和,记为S,即S=S n=,则循环小数0.的分数形式是.16.长方体ABCD﹣A1B1C1D1的棱AB=AD=4cm,AA1=2cm,则点A1到平面AB1D1的距离等于cm.17.已知圆C1:(x﹣2)2+(y﹣3)2=1,圆C2:(x﹣3)2+(y﹣4)2=9,M,N分别是圆C1,C2上的动点,P为x轴上的动点,则|PM|+|PN|的最小值.18.当a>0,a≠1时,函数f(x)=log a(x﹣1)+1的图象恒过定点A,若点A在直线mx﹣y+n=0上,则4m+2n 的最小值是.三、解答题19.已知等差数列{a n},等比数列{b n}满足:a1=b1=1,a2=b2,2a3﹣b3=1.(Ⅰ)求数列{a n},{b n}的通项公式;(Ⅱ)记c n=a n b n,求数列{c n}的前n项和S n.20.已知函数f(x)=log a(1﹣x)+log a(x+3),其中0<a<1.(1)求函数f(x)的定义域;(2)若函数f(x)的最小值为﹣4,求a的值.21.已知函数f(x)=e x(ax+b)+x2+2x,曲线y=f(x)经过点P(0,1),且在点P处的切线为l:y=4x+1.(I)求a,b的值;(Ⅱ)若存在实数k,使得x∈[﹣2,﹣1]时f(x)≥x2+2(k+1)x+k恒成立,求k的取值范围.22.如图,在四棱锥O﹣ABCD中,底面ABCD四边长为1的菱形,∠ABC=,OA⊥底面ABCD,OA=2,M为OA的中点,N为BC的中点.(Ⅰ)证明:直线MN∥平面OCD;(Ⅱ)求异面直线AB与MD所成角的大小;(Ⅲ)求点B到平面OCD的距离.23.已知﹣2≤x≤2,﹣2≤y≤2,点P的坐标为(x,y)(1)求当x,y∈Z时,点P满足(x﹣2)2+(y﹣2)2≤4的概率;(2)求当x,y∈R时,点P满足(x﹣2)2+(y﹣2)2≤4的概率.24.已知f(x)=|﹣x|﹣|+x|(Ⅰ)关于x的不等式f(x)≥a2﹣3a恒成立,求实数a的取值范围;(Ⅱ)若f(m)+f(n)=4,且m<n,求m+n的取值范围.玉田县第二中学校2018-2019学年高二上学期第二次月考试卷数学(参考答案)一、选择题1. 【答案】A【解析】解:y'=2ax , 于是切线的斜率k=y'|x=1=2a ,∵切线与直线2x ﹣y ﹣6=0平行∴有2a=2 ∴a=1 故选:A【点评】本题考查导数的几何意义:曲线在切点处的导数值是切线的斜率.2. 【答案】A 【解析】试题分析:∵函数)1(+=x f y 向右平移个单位得出)(x f y =的图象,又)1(+=x f y 是偶函数,对称轴方程为0=x ,∴)(x f y =的对称轴方程为1=x .故选A . 考点:函数的对称性. 3. 【答案】] 【解析】试题分析:第一次循环:2,3==n S ;第二次循环:3,21==n S ;第三次循环:4,102==n S .结束循环,输出102=S .故选D. 1 考点:算法初步. 4. 【答案】D【解析】易知周期112()1212T π5π=-=π,∴22T ωπ==.由52212k ϕπ⨯+=π(k ∈Z ),得526k ϕπ=-+π(k Z ∈),可得56ϕπ=-,所以5()2cos(2)6f x x π=-,则5(0)2cos()6f π=-=,故选D. 5. 【答案】B【解析】解:全集U={0,1,2,3,4},集合M={2,3,4},N={0,1,4}, ∴∁U M={0,1}, ∴N ∩(∁U M )={0,1}, 故选:B .【点评】本题主要考查集合的子交并补运算,属于基础题.6. 【答案】B【解析】解:∵P ∩Q={0}, ∴log 2a=0 ∴a=1从而b=0,P ∪Q={3,0,1}, 故选B .【点评】此题是个基础题.考查集合的交集和并集及其运算,注意集合元素的互异性,以及对数恒等式和真数是正数等基础知识的应用.7. 【答案】C【解析】解析:本题考查程序框图中的循环结构.121123mn n n n n m S C m---+=⋅⋅⋅⋅=,当8,10m n ==时,82101045m n C C C ===,选C .8. 【答案】A【解析】解:∵正方体中不在同一表面上两顶点A (﹣1,2,﹣1),B (3,﹣2,3),∴AB 是正方体的体对角线,AB=,设正方体的棱长为x ,则,解得x=4.∴正方体的棱长为4,故选:A .【点评】本题主要考查了空间两点的距离公式,以及正方体的体积的有关知识,属于基础题.9. 【答案】【解析】选C.由题意得log 2(a +6)+2log 26=9. 即log 2(a +6)=3,∴a +6=23=8,∴a =2,故选C. 10.【答案】D【解析】解:双曲线﹣=1的右焦点为(2,0),即抛物线y 2=2px 的焦点为(2,0), ∴=2, ∴p=4. 故选D .【点评】本题考查双曲线、抛物线的性质,考查学生的计算能力,属于基础题.11.【答案】C【解析】解:A.未注明a,b,c,d∈R.B.实数是复数,实数能比较大小.C.∵=,则z1=z2,正确;D.z1与z2的模相等,符合条件的z1,z2有无数多个,如单位圆上的点对应的复数的模都是1,因此不正确.故选:C.12.【答案】C【解析】解:由sinB=2sinC,由正弦定理可知:b=2c,代入a2﹣c2=3bc,可得a2=7c2,所以cosA===﹣,∵0<A<180°,∴A=120°.故选:C.【点评】本题考查正弦定理以及余弦定理在解三角形中的应用,考查了转化思想,属于基本知识的考查.二、填空题13.【答案】3个.【解析】解:∵定义在(﹣∞,+∞)上的偶函数f(x),∴f(x)=f(﹣x);∵f(x+1)=﹣f(x),∴f(x+1)=﹣f(x),∴f(x+2)=﹣f(x+1)=f(x),f(﹣x+1)=﹣f(x)即f(x+2)=f(x),f(﹣x+1)=f(x+1),周期为2,对称轴为x=1所以①②⑤正确,故答案为:3个14.【答案】.【解析】解:∵f(x)=cos2x+sinx=1﹣sin2x+sinx=﹣+,故当sinx=时,函数f(x)取得最大值为,故答案为:.【点评】本题主要考查三角函数的最值,二次函数的性质,属于基础题.15.【答案】.【解析】解:0.=++…+==,故答案为:.【点评】本题考查数列的极限,考查学生的计算能力,比较基础.16.【答案】【解析】解:由题意可得三棱锥B1﹣AA1D1的体积是=,三角形ABD1的面积为4,设点A1到平面AB1D1的距离等于h,则,1则h=故点A1到平面AB1D1的距离为.故答案为:.17.【答案】5﹣4.【解析】解:如图,圆C1关于x轴的对称圆的圆心坐标A(2,﹣3),半径为1,圆C2的圆心坐标(3,4),半径为3,|PM|+|PN|的最小值为圆A与圆C2的圆心距减去两个圆的半径和,即:﹣4=5﹣4.故答案为:5﹣4.【点评】本题考查圆的对称圆的方程的求法,考查两个圆的位置关系,两点距离公式的应用,考查转化思想与计算能力,考查数形结合的数学思想,属于中档题.18.【答案】2.【解析】解:整理函数解析式得f(x)﹣1=log a(x﹣1),故可知函数f(x)的图象恒过(2,1)即A(2,1),故2m+n=1.∴4m+2n≥2=2=2.当且仅当4m=2n,即2m=n,即n=,m=时取等号.∴4m+2n的最小值为2.故答案为:2三、解答题19.【答案】【解析】解:(I)设等差数列{a n}的公差为d,等比数列{b n}的公比为q:∵a1=b1=1,a2=b2,2a3﹣b3=1.∴1+d=q,2(1+2d)﹣q2=1,解得或.∴a n=1,b n=1;或a n=1+2(n﹣1)=2n﹣1,b n=3n﹣1.(II)当时,c n=a n b n=1,S n=n.当时,c n=a n b n=(2n﹣1)3n﹣1,∴S n=1+3×3+5×32+…+(2n﹣1)3n﹣1,3S n=3+3×32+…+(2n﹣3)3n﹣1+(2n﹣1)3n,∴﹣2S n=1+2(3+32+…+3n﹣1)﹣(2n﹣1)3n=﹣1﹣(2n﹣1)3n=(2﹣2n)3n﹣2,∴S n=(n﹣1)3n+1.【点评】本题考查了等差数列与等比数列的通项公式及其前n项和公式、“错位相减法”,考查了推理能力与计算能力,属于中档题.20.【答案】【解析】解:(1)要使函数有意义:则有,解得﹣3<x<1,所以函数f(x)的定义域为(﹣3,1).(2)f(x)=log a(1﹣x)+log a(x+3)=log a(1﹣x)(x+3)==,∵﹣3<x<1,∴0<﹣(x+1)2+4≤4,∵0<a<1,∴≥log a4,即f(x)min=log a4;由log a4=﹣4,得a﹣4=4,∴a==.【点评】本题考查对数函数的图象及性质,考查二次函数的最值求解,考查学生分析问题解决问题的能力.21.【答案】【解析】解:(I)f'(x)=e x(ax+a+b)+2x+2…依题意,,即,解得.…(II)由f(x)≥x2+2(k+1)x+k得:e x(x+1)≥k(2x+1).∵x∈[﹣2,﹣1]时,2x+1<0,∴f(x)≥x2+2(k+1)x+k即e x(x+1)≥k(2x+1)恒成立,当且仅当…设,由g'(x)=0得…当;当∴上的最大值为:…所以常数k的取值范围为…【点评】本题考查函数的导数的综合应用,切线方程,闭区间是函数的最值的求法,构造法的应用,难度比较大,是高考常考题型.22.【答案】【解析】解:方法一(综合法)(1)取OB中点E,连接ME,NE∵ME∥AB,AB∥CD,∴ME∥CD又∵NE∥OC,∴平面MNE∥平面OCD∴MN∥平面OCD(2)∵CD∥AB,∴∠MDC为异面直线AB与MD所成的角(或其补角)作AP⊥CD于P,连接MP∵OA⊥平面ABCD,∴CD⊥MP∵,∴,,∴所以AB与MD所成角的大小为.(3)∵AB∥平面OCD,∴点A和点B到平面OCD的距离相等,连接OP,过点A作AQ⊥OP于点Q,∵AP⊥CD,OA⊥CD,∴CD⊥平面OAP,∴AQ⊥CD.又∵AQ⊥OP,∴AQ⊥平面OCD,线段AQ的长就是点A到平面OCD的距离,∵,,∴,所以点B到平面OCD的距离为.方法二(向量法)作AP ⊥CD 于点P ,如图,分别以AB ,AP ,AO 所在直线为x ,y ,z 轴建立坐标系: A (0,0,0),B (1,0,0),,,O (0,0,2),M (0,0,1),(1),,设平面OCD 的法向量为n=(x ,y ,z ),则•=0,•=0即取,解得∵•=(,,﹣1)•(0,4,)=0,∴MN ∥平面OCD .(2)设AB 与MD 所成的角为θ,∵∴,∴,AB 与MD 所成角的大小为.(3)设点B 到平面OCD 的距离为d ,则d 为在向量=(0,4,)上的投影的绝对值,由,得d==所以点B 到平面OCD 的距离为.【点评】培养学生利用多种方法解决数学问题的能力,考查学生利用空间向量求直线间的夹角和距离的能力.23.【答案】【解析】解:如图,点P所在的区域为长方形ABCD的内部(含边界),满足(x﹣2)2+(y﹣2)2≤4的点的区域为以(2,2)为圆心,2为半径的圆面(含边界).(1)当x,y∈Z时,满足﹣2≤x≤2,﹣2≤y≤2的点有25个,满足x,y∈Z,且(x﹣2)2+(y﹣2)2≤4的点有6个,依次为(2,0)、(2,1)、(2,2)、(1,1)、(1,2)、(0,2);∴所求的概率P=.(2)当x,y∈R时,满足﹣2≤x≤2,﹣2≤y≤2的面积为:4×4=16,满足(x﹣2)2+(y﹣2)2≤4,且﹣2≤x≤2,﹣2≤y≤2的面积为:=π,∴所求的概率P==.【点评】本题考查的知识点是几何概型概率计算公式,计算出满足条件和所有基本事件对应的几何量,是解答的关键,难度中档.24.【答案】【解析】解:(Ⅰ)关于x的不等式f(x)≥a2﹣3a恒成立,即|﹣x|﹣|+x|≥a2﹣3a恒成立.由于f(x)=|﹣x|﹣|+x|=,故f(x)的最小值为﹣2,∴﹣2≥a2﹣3a,求得1≤a≤2.(Ⅱ)由于f(x)的最大值为2,∴f(m)≤2,f(n)≤2,若f(m)+f(n)=4,∴m<n≤﹣,∴m+n<﹣5.【点评】本题主要考查分段函数的应用,求函数的最值,函数的恒成立问题,属于中档题.。

河北省唐山市玉田县高二数学下学期期中试题 理(扫描版)

河北省唐山市玉田县高二数学下学期期中试题 理(扫描版)

参考答案一、选择题: ADBCA BCCBB DD二、填空题: 13.(3,4) 14.2. 15.21, 16. (20,6)- 三、解答题:解:(1)当1n =时,11a =,-------1分当2n ≥时,112[2(1)]n n n n n a S S a n a n --=-=---- 即:121n n a a -=+,-------3分 ∴当2n ≥时,111122211n n n n a a a a ---++==++∴数列{1}na +是首项为2,公比为2的等比数列 。

-------5分(2)由(1)知:21n n a =- -------6分假设存在不同的三项,,(,,*)m n p a a a m n p m n p N >>∈且成等差数列, ----7分则:112222222222221n m pn m p n m p n p m p a a a ++--=+⇒⨯-=+-⇒=+⇒=+因为1,10,02n pm n p n p m p +->>∴+->->∴为偶数,21m p -+为奇数,产生矛盾所以假设错误,原命题成立。

-------------10分 18.解:(1)96444=A ; ……………………4分 (2)4822223=⨯⨯⨯⨯; ……………………8分(3)16800)(5537222527=+A C A C C . ……………………12分 19.解:(Ⅰ)设221(6)u k x x -=-∵售价为10元时,年销量为233万件; ∴2321(10060)3k -=-,解得13k = 212213u x x =-++ ……4分 ∴23211(6)(221)(6)49126(6)33y u x x x x x x x x =-=-++-=-++->……6分(Ⅱ)289(1)(9)y x x x x '=-++=-+- ……8分显然,当(6,9)x ∈时,0y '>,当(9,+)x ∈∞时,0y '<, ∴函数321491263y x x x =-++-在(6,9)上是关于x 的增函数; 在(9,)+∞上是关于x 的减函数。

河北省玉田县第二学期期末考试八年级物理试卷(含解析)

河北省玉田县第二学期期末考试八年级物理试卷(含解析)

(解析版)河北省玉田县第二学期期末考试八年级物理试卷一、选择题(本题共14个小题,每小题3分,共42分.在每小题给出四个选项中,只有一个选项符合题意)1.(3分)生活中物理随处可见,以下说法正确是()①在空中飞行飞机只具有动能②汽车在平直公路上匀速直线行驶时没有受到平衡力作用③在火车站或地铁站候车人必须站在安全线以外区域候车是防止人身体前后压力差把人推向列车④汽车突然启动时乘客会向后倾倒,是因为乘客具有惯性⑤山间公路往往环绕山坡,盘山而上,这样可以使上山汽车提高功率.A.①③B.②③C.③④D.④⑤考点:物理常识.专题:其他综合题.分析:本题根据对初中物理基础知识认识找出相对应正确答案.解答:解:①在空中飞行飞机具有速度和高度,所以具有重力势能和动能,说法错误;②汽车在平直公路上匀速直线行驶时受到平衡力作用,说法错误;③在火车站或地铁站候车人必须站在安全线以外区域候车是防止人身体前后压力差把人推向列车,说法正确;④汽车突然启动时乘客会向后倾倒,是因为乘客具有惯性,说法正确;⑤山间公路往往环绕山坡,盘山而上,这样可以使上山汽车减小阻力,说法错误.故选C.点评:本题考查知识点比较多,主要考查学生对所学物理知识综合应用能力.2.(3分)(2013•滨海县二模)如图所示,所使用杠杆属于费力杠杆是()A.钓鱼竿B.开瓶器C.灭火器压把D.钢丝钳考点:杠杆分类.专题:应用题;简单机械.分析:结合图片和生活经验,判断杠杆在使用过程中,动力臂和阻力臂大小关系,再判断它是属于哪种类型杠杆.解答:解:A、钓鱼竿在使用过程中,动力臂小于阻力臂,是费力杠杆;B、开瓶器在使用过程中,动力臂大于阻力臂,是省力杠杆;C、灭火器压把在使用过程中,动力臂大于阻力臂,是省力杠杆;D、钢丝钳在使用过程中,动力臂大于阻力臂,是省力杠杆.故选A.点评:此题考查是杠杆分类和特点,主要包括以下几种:①省力杠杆,动力臂大于阻力臂;②费力杠杆,动力臂小于阻力臂;③等臂杠杆,动力臂等于阻力臂.3.(3分)图所示四种情景中,人对物体做功是()A.静止不动B.从地上搬到车上C.静止不动D.小静背着书包在等车考点:力是否做功判断.专题:功、功率、机械效率.分析:判断人是否做功依据就是看在这个过程中,是否同时具备做功两个必要因素:①作用在物体上力,②物体在力方向上通过了距离.解答:解:A、举着杠铃静止不动,尽管施加了力,但是没有移动距离,因此不做功;B、把货物从地上搬到车上,人对货物施加了力,并且在力方向上移动了距离,因此做功;C、用力推轮胎,施加了一个力,但没有移动距离,因此不做功;D、背着书包原地不动,对书包施加了力,但没有移动距离,因此不做功.故选B.点评:明确三种情况不做功:一是有力无距离(例如:推而未动),二是有距离无力(靠惯性运动),三是力方向与运动方向垂直.4.(3分)如图所示是使用简单机械匀速提升同一物体四种方式(不计机械自重和摩擦),其中所需动力最小是()A.B.C.D.考点:动滑轮拉力计算;滑轮组绳子拉力计算;杠杆平衡条件.专题:比较思想.分析:理想状况下:①斜面上拉力F=,②滑轮组绳子末端拉力F=×G,③根据杠杆平衡条件F1L1=F2L2可知动力:F1=,由图可知L1:L2=(1m+3m):1m=4:1,F1=.解答:解:不计机械自重和摩擦说明不考虑机械效率问题,即指是理想状况下:A、F1===G;B、F2=G=G;C、F4=G=G;D、F3=G=G.四个选项中,提起是同一物体.故选B.点评:此题主要是考查各种简单机械省力情况及省力原理.5.(3分)对物理量估测,是一种良好学习习惯,也是学好物理基本功之一,下面是小宇同学对所学物理量估测,下列数据明显不合理是()A.1个鸡蛋漂浮在盐水中静止时所受浮力大约是0.5NB.跑百米运动员具有动能大约为3000JC.一个中学生空手从一楼走到三楼,大约做功为3000JD.珠穆朗玛峰山脚今天大气压约1.5×105Pa考大气压强与高度关系;浮力大小计算;功计算.点:专题:估算综合应用题.分析:不同物理量估算,有需要凭借生活经验,有需要简单计算,有要进行单位换算,最后判断最符合实际是哪一个.解答:解:A、1个鸡蛋漂浮在盐水中静止时所受浮力大约是0.5N,数据合理;故A正确,不符合题意;B、跑百米运动员具有动能大约为3000J,数据合理;故B正确,不符合题意;C、一个中学生空手从一楼走到三楼,大约做功为3000J,数据合理;故C正确,不符合题意;D、珠穆朗玛峰在高原地区气压一定低于1标准大气压,数据不合理.故D错误,符合题意.故选D.点评:物理学中,对各种物理量估算能力,是我们应该加强锻炼重要能力之一,这种能力提高,对我们生活同样具有很大现实意义.6.(3分)下列关于功和功率,机械效率说法正确是()A.有力作用在物体上,力﹣定对物体做功B.物体做功越快,功率越大C.有用功越多,机械效率越大D.力对物体做功越多,功率就越大考点:功率概念.专题:功、功率、机械效率.分析:根据功、功率、机械效率关系分析.功率是单位时间内做功多少,是表示做功快慢物理量;机械效率是有用功与总功比值.解答:解:A、有力作用在物体上,物体在力方向上通过距离,力才会对物体做功,故A错误;B、物体做功越快,功率越大,故B正确;C、机械效率是有用功与总功比值,比值越大,机械效率越大,故C错误;D、单位时间内,力对物体做功越多,功率就越大,故D错误.故选B.点评:本题考查了功、功率、机械效率关系.功率由功和时间共同决定,机械效率由有用功和总功共同决定.7.(3分)(2002•广州)如图所示,作用在杠杆一端且始终与杠杆垂直力F,将杠杆缓慢地由位置A拉至位置B,力F在这个过程中()A.变大B.变小C.不变D.先变大后变小考点:杠杆动态平衡分析.分析:解答此题,首先要判断杠杆五要素中,有哪些要素发生了变化,然后再利用杠杆平衡条件进行分析.解答:解:在杠杆缓慢由A到B过程中,动力臂OA长度没有变化,阻力G 大小没有变化,而阻力臂L却逐渐增大;由杠杆平衡条件知:F•OA=G•L,当OA、G不变时,L越大,那么F 越大;因此拉力F在这个过程中逐渐变大.故选A.点评:在分析杠杆动态平衡时,一般是动中取静,依据杠杆平衡条件进行分析,最后得到结论.8.(3分)下面四幅图中属于动能转化为重力势能是()A.小刚用弹弓上形变橡皮条将“子弹”弹射出去B.小明脚踩滑板从高处滑下C.轻轨列车无动力滑上站台D.蹦床运动员从高空下落至蹦床上考点:动能和势能转化与守恒.专题:简单机械.分析:动能转化为重力势能,必然是动能是逐渐减少,重力势能是逐渐增加.动能变化一般都体现在速度变化上,重力势能变化一般都体现在高度变化上.解答:解:动能转化为重力势能必然是动能减小而重力势能增大.A、橡皮条射“子弹”时:橡皮条弹性形变程度逐渐减小,弹性势能增加;子弹由静止变为运动,动能增大.弹性势能转化为动能.B、小明踩滑板从高处滑下:高度减小,重力势能减小;速度增大,动能增大.重力势能转化为动能.C、列车无动力滑上站台:速度减小,动能减小;高度增大,重力势能增大.动能转化为重力势能.D、蹦床运动员从高空下落至蹦床:速度增大,动能增大;高度减小,重力势能减小.重力势能转化为动能.故选C.点评:在做能量转化这种题时,我们要注意分析哪种能量增加了,哪种能量减少,因为总是减少这种能量转化为增加那种能量.9.(3分)平直公路上甲、乙两辆汽车,在相同牵引力作用下匀速行驶,如果在相同时间内通过路程之比为3:2,则甲与乙()A.牵引力做功之比为2:3 B.牵引力做功率之比为2:3 C.汽车所受阻力之比为3:2 D.牵引力功率之比为3:2考点:功率计算;二力平衡条件应用;功计算.分析:已知牵引力相等,路程之比已知,利用W=Fs可求做功之比;又知道做功时间相同,利用P=可求功率之比;已知两车都做匀速运动,根据二力平衡原则可知牵引力等于阻力,从而可求阻力之比.解答:解:A、牵引力做功之比:===,故A错;B、牵引力做功功率之比:===,故B错、D正确;C、因为汽车匀速行驶,所以汽车受到阻力等于牵引力,所以汽车受到阻力之比f1:f2=F1:F2=1:1,故C错;故选D.点评:本题考查了学生对功公式、功率公式、二力平衡条件掌握和运用,要求功、功率、阻力大小之比,要求细心,防止因颠倒而出错.10.(3分)将重为40N,体积为5×10﹣3m3铁球,将它没入水中,铁球静止时()A.漂浮,F浮=50N B.悬浮,F浮=50NC.漂浮,F浮=40N D.沉在水底,F浮=40N考点:物体浮沉条件及其应用.专题:浮沉应用.分析:掌握物体浮沉条件:上浮:F浮>G;悬浮:F浮=G;下沉:F浮<G;或ρ物<ρ液,上浮;ρ物=ρ液,悬浮;ρ物>ρ液,下沉;计算出铁球完全浸没时浮力,将其浮力与物体重力比较判断出其浮沉状态.解答:解:当铁球完全浸没时,铁球受到浮力:F浮=ρ水gV排=1.0×103kg/m3×10N/kg×5×10﹣3m3=50N;因为F浮>G,所以铁球将上浮,最后漂浮在水面上,此时浮力等于重力等于40N.故选C .点评:研究物体浮沉时,物体应浸没于液体中(V排=V物),然后比较此时物体受到浮力与重力关系.如果被研究物体平均密度可以知道,则物体浮沉条件可变成以下形式:①ρ物<ρ液,上浮②ρ物=ρ液,悬浮③ρ物>ρ液,下沉.11.(3分)下面对于物理知识总结中连线正确是()A .B.C.D.考点:物理常识.专题:其他综合题.分析:,在解题时应认真分析每一个选择项.解答:解:A、力单位是牛顿;功单位是焦耳,功率单位是瓦特,故A错误;B、掷实心球时,球离开手还要继续飞行,是因为具有惯性原因;注射器抽取药液时利用就是大气压作用,热气球升空利用是浮力原理,故B正确;C、头球攻门说明力可以改变物体运动方向;用吸管吸饮料应用是大气压原理;切肉磨刀为是减小受力面积,增大压强,故C错误;D、自行车车把应用了轮轴;茶壶应用是连通器原理;旗杆顶上滑轮,应用是定滑轮,故D错误.故选B.点评:此题考查知识点比较多,需要同学们对于各种物理现象和知识有一定了解,需要逐个去分析.出题意图是为了让同学了解各种基本物理知识.12.(3分)(2012•无锡)学习了功率知识后,小明和几位同学准备开展“比一比谁功率大”活动,他们设计了三套方案:①测量出各自体重、爬楼用时间和爬楼高度,算出爬楼功率并进行比较;②控制爬楼时间相同,测量出各自体重、爬楼高度,算出爬楼做功并进行比较;③控制爬楼高度相同,测量出各自体重、爬楼时间,算出体重和时间比值并进行比较,可行是()A.只有①B.只有①②C.只有②③D.①②③都可以考点:功率测量实验.专题:应用题;实验题;压轴题.分要比较功率大小,有三种方法:析:①做功时间一定,比较做功多少,做功多,功率大;②做功多少一定,做功时间短,功率大;③分别测出功率,进行比较.比较功率不一定必须测出功率.解答:解:爬楼是克服自身重力做功,功率P===,①测出各自体重、爬楼时间和爬楼高度,根据P=求出功率,直接比较功率大小;②制爬楼时间相同,测出各自体重m和爬楼高度h,若mgh越大,功率就越大;③控制爬楼高度相同,测出各自体重m和爬楼时间t,若比值越大,功率就越大;所以三种方法都是可以.故选D.点评:功率公式是这一实验原理,因此要从公式入手,找出需要测量量,同时要注意不变量和对应比较功率方法.13.(3分)如图甲所示,长方体金属块在细绳竖直向上拉力作用下从水中开始一直竖直向上做匀速直线运动,上升到离水面一定高度处.图乙是绳子拉力F随时间t变化图象,取g=10N/Kg.根据图象信息,下列判断正确是()A.该金属块重力大小为34NB.浸没在水中金属块受到浮力大小是20NC.在t1至t2时间段金属块在水中受到浮力逐渐增大D.该金属块密度是3.4×103Kg/m3考点:重力计算;密度计算;阿基米德原理;浮力大小计算.专题:计算题;压轴题;图析法.分析:分析绳子拉力随时间t变化图象,当金属块从水中一直竖直向上做匀速直线运动,但未露出液面,此时金属块排开水体积不变,由阿基米德原理可知,此时浮力不变,绳子拉力也不变,即为图中AB段.当金属块完全露出液面,没有浸入水中时,金属块不受浮力,此时拉力等于重力,即为图中CD段,据此求出金属块重.来判断A是否符合题意.当金属块未露出液面时,拉力等于重力减去浮力,据此求金属块受到浮力,再根据阿基米德原理求金属块排开水体积(金属块体积),知道金属块重,利用重力公式求金属块质量,最后利用密度公式求金属块密度.来判断B、D是否符合题意.首先判断拉力在t1至t2时间段内变化,再利用公式F浮=G﹣F拉判断浮力变化.来判断C是否符合题意.解解:当金属块完全露出液面,没有浸入水中时,金属块不受浮力,此答:时拉力等于重力,即为图中CD段,从图可知,该金属块重力为:G=F拉=54N,故A说法错误,不符合题意.当金属块未露出液面时,即为图中AB段,从图可知,此时绳子拉力为34N,则金属块受到浮力大小为:F浮=G﹣F拉=54N﹣34N=20N.故B说法正确,符合题意.∵F浮=ρ水v排g,∴金属块排开水体积(金属块体积):V金=V排===0.002m3,∵G=mg,∴金属块质量为:m===5.4kg,金属块密度为:ρ金===2.7×103kg/m3.故D说法错误,不符合题意.从图可知,绳子拉力在t1至t2时间段内逐渐变大,则由公式F浮=G﹣F拉可知,金属块重力不变,而拉力逐渐变大,所以浮力逐渐变小.故C说法错误,不符合题意.故选B.点评:本题考查了重力、浮力、质量、密度计算,以及阿基米德原理,关键是公式和公式变形应用,难点是通过图乙确定金属块重力及绳子受到拉力、会用称重法计算出金属块受到浮力.14.(3分)(2008•达州)在不计绳重和摩擦情况下,利用右图所示甲、乙两装置,分别用力把相同物体匀速提升相同高度.若用η甲、η乙表示甲、乙两装置机械效率,W甲、W乙表示拉力所做功.下列正确是()A.η甲=η乙,W甲=W乙 B.η甲>η乙,W甲>W乙C.η甲<η乙,W甲<W乙D.η甲>η乙,W甲<W乙考点:功计算;有用功和额外功;滑轮(组)机械效率.专题:应用题;压轴题.分析:已知物体升高高度和物体重力大小,根据公式W=Gh可求所做有用功;已知两滑轮组动滑轮上绳子段数和物体重力,可求拉力大小,根据公式W=FS可求总功,有用功与总功比值就是滑轮组机械效率.解答:解:物体升高高度和物体重力都相同,根据公式W=Gh可知做有用功相同;动滑轮上绳子段数都是4段,所以拉力大小都为物体重力,所以拉力相同;因为升高高度相同,动滑轮上绳子段数相同,所以绳子自由端移动距离相同,根据公式W=FS可知做总功相同;所以两滑轮组机械效率相同.故选A.点评:本题考查有用功和总功、机械效率计算,关键是公式应用,难点是对动滑轮上绳子段数判断.二、填空题(请将正确答案填写在横线上,每空1分,共15分)15.(3分)教材中有许多实验与生活应用插图,请观察下面三幅图,将下列表述填写完整.图甲实验说明液体压强随深度增加而增大(或液体压强与深度有关);图乙说明自行车刹车时,是通过增大压力来增大摩擦;图丙是一个动滑轮,它作用是可以省力.考点:液体压强特点;增大或减小摩擦方法;动滑轮及其工作特点.专题:重力、弹力、摩擦力;压强、液体压强;简单机械.分析:三幅图分别对应了不同物理知识运用:图甲从液体压强特点角度进行解答;图乙从增大摩擦力方法角度进行解答;图丙从动滑轮应用角度进行解答.解答:解:图甲中,不同高度小孔喷出水距离不同,越低处喷得越远,说明液体压强随深度增加而增大(或液体压强与深度有关);图乙中,自行车刹车时用力捏闸,是通过增大压力来增大摩擦力;图丙中,是一个可以随重物一起移动动滑轮,它作用是可以省力.故答案为:液体压强随深度增加而增大(或液体压强与深度有关);增大压力;动;可以省力.点评:三幅教材中插图,考查了三个不同知识点:液体压强规律、增大摩擦方法、动滑轮特点等,有一定综合性,但难度不大,是我们学习教材时必须引起重视.16.(3分)2013年6月11日17时38分神舟十号飞船搭载三位航天员飞向太空,并进入近地点200公里,远地点329.8公里预定轨道,在轨飞行15天后已于26日8时许安全返回地面.飞船在轨运行过程中机械能守恒,在近地点时,动能最大,飞船从近地点向远地点运动过程中,动能转化为重力势能(选填“动”或“重力势”).在20日上午成功举行了首次太空授课活动,其中有一实验聂海胜表演了“悬空打坐”,而后又被“太空教师﹣﹣王亚平”用一指推开,请针对以上情景和力学知识提出一个问题并回答,问题:在太空中为什么能很容易表演“悬空打坐”?回答:在太空中处于失重状态.考点:动能和势能大小变化.专题:机械能及其转化.分析:(1)飞船运行过程中,要经历两个过程:①从远地点向近地点运行下降过程;②从近地点向远地点运行上升过程.根据题目中提到物理过程,结合动势能转化来分析其能量变化.(2)利用从聂海胜表演“悬空打坐”,及被“太空教师﹣﹣王亚平”用一指推开情景,并结合地球上情况提出物理问题.解答:解:(1)飞船在真空中飞行,不受摩擦阻力,机械能是守恒.飞船从远地点到近地点运动过程中,重力势能减小,动能增大,重力势能转化为动能,在近地点时,动能最大.飞船从近地点向远地点运动过程中,动能减小,重力势能增大,动能转化为重力势能,在远地点,重力势能最大.(2)①根据聂海胜表演“悬空打坐”,可提出问题:在太空中为什么能很容易表演“悬空打坐”?回答:太空中没有重力,处于失重状态.②根据“太空教师﹣﹣王亚平”用一指将“悬空打坐”聂海胜推开,可提出问题:为什么聂海胜被推后运动起来?回答:力是改变物体运动原因.故答案为:动能;动能;重力势能;在太空中为什么能很容易表演“悬空打坐”;在太空中处于失重状态.点评:①飞船运行过程中远地点、近地点中远近,可以理解为高低.这样就会比较容易理解飞船运行这两个过程.②要会根据物理情景提出问题,并做出回答.17.(3分)如图所示,是我国科学院海洋仪器仪表研究所自主研制“海洋气候监测浮标”,其技术处于国际领先水平.2012年伦敦奥委会正与中方洽谈,准备引进这种浮标.浮标质量达2.06×103kg,漂浮在海面,可测量风速、风向、气温、海流等数据,准确地提供海洋、气象、水文信息,确保了奥帆赛顺利进行.那么,浮标受到浮力是 2.06×104 N,它浸入海水体积是2m3.(ρ海水取1.03×103kg/m3,g取10N/kg)考点:物体浮沉条件及其应用;阿基米德原理.专题:应用题.分析:①浮标漂浮在水面上,知道浮标质量,利用重力公式求浮标重,再利用物体漂浮条件求浮标受到浮力;②求出了浮标受到浮力,根据公式F浮=ρgV排可求排开海水体积.排开海水体积即为它浸入海水体积.解答:解:浮标受到浮力是F浮=G=mg=2.06×103kg×10N/kg=2.06×104N.它浸入海水体积是V排===2m3.故答案为:2.06×104;2.点评:本题考查浮力和排开水体积计算,关键是公式及其变形应用,还要知道物体漂浮时浮力等于物体自身重力.18.(3分)如图甲所示滑轮组,每个滑轮等重.不计绳重和摩擦,物体重G1从200N开始逐渐增加,直到绳子被拉断.每次均匀速拉动绳子将物体提升同样高度.图乙记录了在此过程中滑轮组机械效率随物体重力增加而变化图象.(1)每个动滑轮重100牛,(2)绳子能承受最大拉力是500牛,(3)当滑轮组机械效率为80%时,物体重800牛.(4)拉N重物时不省力也不费力.考点:滑轮组绳子拉力计算;滑轮(组)机械效率.专题:计算题;图析法.分析:根据图判断绳子段数n=4,然后对每小题分析:(1)根据公式η==变形公式就可以求得动滑轮重力;(2)由图可知物体在1800N时绳子断了,此时最大拉力可用公式F=来计算;(3)在动滑轮重力已经计算出情况下,利用公式η=变形公式可以求得物体重力;(4)当拉力和物体重力时,既不省力也不费力,根据省力公式F=变形就可以求出物体重力.解答:解:(1)由图可知:当物体重200N时,机械效率为50%,由公式η=变形可得:G动=﹣G物=﹣200N=200N;由图可知动滑轮为两个,所以每个滑轮重100N.故答案为:100.(2)当绳子要被拉断时拉力最大,由图可知物体在1800N时绳子断了,则F===500N;故答案为:500.(3)根据滑轮组机械效率计算公式η=变形得:G物===800N故答案为:800N.(4)既不省力也不费力,说明拉力F=G物,即G物=,将G动=200N,n=4代入得:G物=N;故答案为:.点评:本题考查了滑轮组省力公式以及机械效率公式变形及应用,计算量比较大,解题时要特别注意.三、作图和实验探究:(除特殊说明外,每空1.5分,共30分)19.(2分)物体M在杠杆AOBC作用下如图位置静止,试在A点作出使杠杆在如图位置平衡时最小力(O为支点).考点:杠杆中最小力问题.专题:作图题.分本题主要考查两个知识点:(1)对力臂概念理解:力臂是指从支点到析:力作用线距离.(2)对杠杆平衡条件(F1l1=F2l2)理解与运用:在阻力跟阻力臂乘积一定时,动力臂越长动力越小.解答:解:由杠杆平衡条件F1l1=F2l2可知在阻力跟阻力臂乘积一定时,动力臂越长动力越小.由图可知当力方向跟杠杆OA垂直向上时动力臂最长.如下图所示:点评:本题解题关键是通过杠杆平衡条件得出:在阻力跟阻力臂乘积一定时,动力臂越长动力越小结论.20.(8分)语哲同学用一个弹簧测力计、一个金属块、两个相同烧杯(分别装有一定量水和煤油),对浸在液体中物体所受浮力进行了探究.图表示探究过程及有关数据.(1)分析图A、B、C、D,说明浮力大小跟排开液体体积有关.(2)分析图A、D、E,说明浮力大小跟液体密度有关.(3)物体完全浸没在煤油中所受浮力是 2.4N.(4)语哲还想探究浮力大小与物体形状是否有关,他找来一小团橡皮泥、烧杯和水进行实验.实验步骤如下:步骤一:将橡皮泥团放入盛有适量水烧杯中,橡皮泥团下沉至杯底.步骤二:将橡皮泥团捏成“碗状”再放入水中,它漂浮在水面上.(a)语哲通过分析得出结论:由于第一次橡皮泥团受到浮力小于第二次呈“碗状”时受到浮力(选填“大于”、“等于”或“小于”),所以物体受到浮力与其形状有关.(b)同组小彤不同意语哲得出结论,她指出语哲实验有一处错误,所以才会得出错误结论结论,错误原因是:他只关注了橡皮泥形状改变,没有控制物体都要排开相同体积液体.考点:探究浮力大小实验.专题:简答题;实验探究题;控制变量法.分析:本题目是考查学生对探究影响浮力大小因素实验掌握程度,看学生能否灵活利用控制变量法,根据题干已知求得想要物理量,并且为了了解学生对控制变量法掌握,设计实验让学生找错误原因.解答:解:(1)分析图B,C,D,浮力逐渐增大,在其他物理量均不变情况下,只有排开液体体积不断变化,所以浮力大小跟排开液体体积有关;(2)要看浮力大小跟液体密度关系,应保证在其他物理量不变情况下,只有密度变化而引起浮力变化.只有D、E这组合式;。

河北省唐山市玉田县第二中学2020年高二物理模拟试卷含解析

河北省唐山市玉田县第二中学2020年高二物理模拟试卷含解析

河北省唐山市玉田县第二中学2020年高二物理模拟试卷含解析一、选择题:本题共5小题,每小题3分,共计15分.每小题只有一个选项符合题意1. (多选)如图所示,直角三角形ABC区域中存在一匀强磁场,比荷相同的两个粒子沿AB方向自A 点射入磁场,分别从AC边上的P、Q两点射出,则A.从P射出的粒子速度大B.从Q射出的粒子速度大C.从P射出的粒子,在磁场中运动的时间长D.两粒子在磁场中运动的时间一样长参考答案:BD2. (单选)一物体由静止开始自由下落,一小段时间后突然受一恒定水平向右的风力的影响,但着地前一段时间风突然停止,则其运动的轨迹可能是图中的哪一个?()参考答案:C3. (单选)质量为m的带正电小球A悬挂在绝缘细线上,且处在场强为E的匀强电场中,当小球A 静止时,细线与竖直方向成30°角,已知此电场方向恰使小球受到的电场力最小,则小球所带的电量应为()A.B.C.D.参考答案:B4. (多选)火警报警系统的具体形式有很多,如图所示,M是一小型理想变压器,接线柱a、b接在电压u=311sin314t(V)的正弦交流电源上,变压器右侧部分为一火警报警系统原理图,其中R2为用半导体热敏材料制成的传感器,电流表A2为值班室的显示器,显示通过R1的电流,电压表V2显示加在报警器上的电压(报警器未画出),R3为一定值电阻。

当传感器R2所在处出现火警时,以下说法中正确的是:A.A1的示数不变,A2的示数增大B.V1的示数不变,V2的示数减小C.V1的示数不变,V2的示数增大D.A1的示数增大,A2的示数减小参考答案:BD5. 自由下落的小球,从接触竖直放置的轻弹簧开始,到压缩弹簧有最大形变的过程中,以下说法中正确的是A.小球的动能逐渐减少 B.小球的重力势能逐渐减少C.小球的机械能守恒 D.小球的加速度逐渐增大参考答案:B二、填空题:本题共8小题,每小题2分,共计16分6. (4分)在远距离输电时,若输电功率保持不变,使输电电压升高到原来的n倍,则输电线上因电阻而产生的电能损失将变为原来的____________。

河北省玉田县2013-2014学年高二下学期期中考试语文试题 扫描版含答案

河北省玉田县2013-2014学年高二下学期期中考试语文试题 扫描版含答案

2013--2014高二年级第二学期期中考试语文卷本试卷分选择题和非选择题两部分,满分150分。

考试时间150分钟。

第Ⅰ卷(共35分)一、(17分,5、6、7小题3分,其余每小题2分)1.A叨读‚tāo‛2 .B蓬蒿 3.A.‚信‛译为‚信物‛4.A5.D (A指有些闲人过多地仔细评论女性相貌,也比喻在细节上随便批判B神兽吉光身上的一片毛。

比喻残存的艺术珍品。

C只长了苗而没有开花结实。

比喻人资质虽好,但尚未有所成就即不幸夭折。

或者比喻虚有其表。

D空旷的山谷里听到的人的脚步声。

比喻十分难得,极为可贵的6.C(A项‚雕刻歪歪扭扭的‘某某某到此一游’字形‛搭配不当,可以改为‚歪歪扭扭刻下‘某某某到此一游’‛;B项语序不当。

定语语序不当。

改为:王老师是我校一位有着30多年丰富教学经验的优秀的语文老师。

(定语语序:领属性的词+数量性的词+动词或动词短语+形容词或形容词短语+表性质的名词+中心语)D主语暗中转换,可以在‚提前‛之前加上‚使他们‛。

)7.D 按照游览的空间顺序排列。

先是‚少林景区‛,接下来‚少林寺的门前‛,之后‚走进少林寺‛,后是‚沿着一条甬路往里走‛,是‚天王殿‛,最后‚该殿‛怎么样。

二、(9分)阅读下列文字,完成8—10题。

8.D 不属于对方块字发展历史的表述9.C ‚如果学好端正秀丽的干禄字,就可以参加科举考试谋求仕途发展‛与原文不符10.B‚颜师古创立的干禄字‛不正确三、(9分)阅读下面文言文,完成11—13题。

11.C.‚设下了埋伏拦截攻击‛错误,‚埋伏拦截攻击‛只是图谋计划,还未落实12.A.应为动词意‚依法‛13.B.②表现的是成祖对朱高煦身边人的惩罚。

③是间接表现。

⑥说的并非朱高煦第Ⅱ卷非选择题(共115分)四、(24分)14.(1)仁宗多次用书信警告,(他却)不肯悔改。

(‚数‛、‚书‛、‚悛‛各1分,句意1分)(2)你诚然可以擒获此贼,但朕刚刚即位,小人或许怀有二心,(朕若)不亲征,(便)不能使(小人)的反叛安定。

河北省唐山市玉田县第一中学2024_2025学年高二物理下学期第二次阶段性考试试题含解析

河北省唐山市玉田县第一中学2024_2025学年高二物理下学期第二次阶段性考试试题含解析
C.一摩尔氧气分子的质量是摩尔质量,一摩尔氧气含有阿伏伽德罗常数个分子,已知氧气分子的质量和阿伏伽德罗常数,可以求出氧气的摩尔质量,故C正确;
D.已知氧气分子的体积和氧气分子的质量,求不出氧气的摩尔质量,故D错误.
2.如图所示,三个单摆的摆长为L1=1.5 m,L2=1 m,L3=0.5 m,现用一周期等于2 s的驱动力,使它们做受迫振动,那么当它们的振动稳定时,下列推断中正确的( )
C. 滴入水中的红墨水很快散开
D. 悬浮在水中的花粉做无规则运动
【答案】AB
【解析】
【详解】A.因为液体表面张力的存在,有些小昆虫才能自由自在地在水面上行走自如,故A正确;
B.草叶上的露珠存在表面张力,它表面的水分子表现为引力,从而使它收缩成一个球形,与表面张力有关,故B正确;
C.滴入水中的红墨水很快散开是扩散现象,是液体分子无规则热运动的反映,故C错误;
D. 无法确定
【答案】B
【解析】
【详解】水和水银的初温相同(两球的初温相同),当两液体温度同时缓缓地上升同一值,二者的末温相同,所以内能变更相同,依据热力学第肯定律 ,汲取的热量除了使内能增加相同的量外还要克服液体的压力做功,由于水银的密度比水的密度大,所以乙球汲取的热量较多。
故选B。
【点睛】甲乙两球完全相同,即质量和比热容相同,当温度变更相同时,依据 可知,二者汲取的热量相同,而在水银中压强大,球要膨胀相同的体积,那么在水银中的球要克服的力就大,做功就多,汲取的热量除了使内能增加相同的量外还要克服液体的压力做功,据此分析推断。
A.4瓶B.50瓶C.54瓶D.56瓶
【答案】D
【解析】
【详解】气体的初态
p1=30atm
V1=20L
末态

玉田县第二中学校2018-2019学年上学期高二期中化学模拟题

玉田县第二中学校2018-2019学年上学期高二期中化学模拟题

玉田县第二中学校2018-2019 学年上学期高二期中化学模拟试题班级 __________座号_____姓名__________分数__________一、选择题1.某有机物的构造简式为,以下对其化学性质的判断中,错误的选项是()A.能被银氨溶液氧化B.能使 KMnO 4酸性溶液退色C. 1mol 该有机物只好与1mol Br 2发生加成反响D .1mol 该有机物只好与1mol H 2发生加成反响2.某温度下,体积必定的密闭容器中进行反响:。

以下剖析正确的是A. 均衡后加入,该反响的增大B. 均衡后高升温度,均衡常数K 变大C. 均衡后再充入,达到新均衡时,的百分含量变大D. 若反响前充入的与物质的量相等,达均衡时的转变率比的高3.以下说法正确的选项是A .某有机物焚烧只生成CO2O,且二者物质的量相等,则此有机物的构成为C H和 H2n 2nB .乙醛和丙烯醛()不是同系物,它们与氢气充足反响后产物也不是同系物C.CH3 COOCH 2CH 3与 CH3CH2COOCH 3互为同分异构体,1H —NMR 谱显示二者均有三种不一样的氢原子且三种氢原子的比率同样,故不可以用1H— NMR 来鉴识D.植物油不停滴加到溴水中,溴水渐渐变浅直至退色4.以下离子方程式正确的选项是A .NaHSO4溶液中加入 Ba( OH )2溶液至积淀完整: SO42﹣ + H ++ Ba2++ OH ﹣═ BaSO4↓+ H2 OB .NaHCO 3溶液中加入过度石灰水:2HCO 3﹣+ Ca2++ 2OH ﹣═ CaCO3↓+ 2H 2O + CO 32﹣C.NaAlO 2溶液中通入少许 CO2: AlO 2﹣ + CO 2 + 2H 2O ═ Al (OH )3↓+ HCO 3﹣D .Na2CO3溶液与醋酸溶液混淆: 2H +2+ CO 3﹣═ CO2↑+H2O5.以下对反响热的描绘中,正确的选项是()A .甲烷的焚烧热△ H =- 890.3 kJ mol·-1,则甲烷焚烧的热化学方程式可表示为:CH 4( g)+2O 2( g)=CO 2( g)+2H 2O( g)△H =- 890.3 kJ mol·-1B .必定条件下,将0.5molN 2和 1.5molH 2置于密闭容器中充足反响生成NH 3放热 akJ,其热化学方程式为:N 2( g) +3H 2(g)2NH 3( g)△H =- 2a kJ mol·-1C.在 101kPa 时, 2gH2完整焚烧生成液态水,放出285.8kJ 热量,则水分解的热化学方程式表示为:2H2O( l )=2H-12(g ) +O 2( g )△H =+571.6 kJ mol · D .HCl 和 NaOH 反响中和热△ H =- 57.3 kJ ·mol -1 ,则 CH 3COOH 和 NaOH 反响生成 1mol 水时放出的热量为57.3kJ6. 某温度下反响的均衡常数,现向此温度下的真空容器中充入、及,则以下说法中正确的选项是A. 反响正好达均衡B. 反响向逆反响方向进行C. 反响向某方向进行一段时间后D.反响向某方向进行一段时间后7. 某高分子化合物 R 的构造简式如图,以下相关R 的说法正确的选项是A .R 的单体之一的分子式为C 9H 10O 2B .R 完整水解后生成物均为小分子有机物C .碱性条件下, 1 mol R 完整水解耗费 NaOH 的物质的量为 2 molD .经过加聚反响和缩聚反响能够生成 R8. 以下离子方程式中,正确的选项是A .石灰石与盐酸反响: CO 322HCO 2 H 2 O B .铜和硝酸银溶液反响:Cu AgCu 2AgC . 向NaHSO 4 溶液中滴加Ba OH 2 溶 液 至SO 4 2 离子恰巧积淀完 全 :Ba 22OH 2H SO 42BaSO 42H 2 OD . NH 4HCO 3 溶液与过度 HCl 溶液混淆:HCO 3HCO 2 H 2O9. 向 2l 恒温恒容容器中加入 2molMgSO 4 并充入 2molCO ,发生反响: MgSO 4( s ) + CO ( g ) MgO( s ) + CO 2( g )+SO 2 (g )△H > 0 。

河北省玉田县高二下学期期中考试物理试题(扫描版).pdf

河北省玉田县高二下学期期中考试物理试题(扫描版).pdf

高二物理参考答案 13解析:(1)为便于调节,滑动变阻器的阻值不能太大,选择D比较合适. (2)由于没有电压表,给定的电流表G可与定值电阻R3串联作电压表使用,实验电路如图甲所示. (3)依据所测数据,在坐标纸上描点,所画I1和I2的关系图线如图乙所示. (4)由图可知=1.48 mA=1.48×10-3 A 所以E=1.48×(R3+Rg)×10-3 V=1.48 V 图线的斜率k===0.82×10-3 利用闭合电路欧姆定律及串并联特点近似得到=k=0.82×10-3,所以r=0.82 ω.答案:(1)D (2)见解析 (3)见解析 (4)1.48(1.47~1.49) 0.82(0.70~0.90) 线圈运动到位置3时速度最小,设为从位置3到位置4,线圈只受重力=2.83m/s (3) 线圈运动到位置3时速度最小,安培力最小,所以加速度最小=4.1m/s2 15(1)粒子从s1到达s2的过程中,根据动能定理得 ① 解得粒子进入磁场时速度的大小 (2)粒子进入磁场后在洛伦兹力作用下做匀速圆周运动,有 ② 由① ②得加速电压U与轨迹半径r的关系为 当粒子打在收集板D的中点时,粒子在磁场中运动的半径r0=R 对应电压 (3)M、N间的电压越大,粒子进入磁场时的速度越大,粒子在极板间经历的时间越短,同时在磁场中运动轨迹的半径越大,在磁场中运动的时间也会越短,出磁场后匀速运动的时间也越短,所以当粒子打在收集板D的右端时,对应时间t最短。

根据几何关系可以求得粒子在磁场中运动的半径r=R 由 ② 得粒子进入磁场时速度的大小 粒子在电场中经历的时间 粒子在磁场中经历的时间 粒子出磁场后做匀速直线运动经历的时间 粒子从s1到打在收集板D上经历的最短时间为 t=t1+ t2+ t3= 高考学习网: 高考学习网:。

河北省唐山市玉田县第二中学2021年高三语文月考试卷含解析

河北省唐山市玉田县第二中学2021年高三语文月考试卷含解析

河北省唐山市玉田县第二中学2021年高三语文月考试卷含解析一、现代文阅读(35分,共3题)1. 阅读下面的文字,完成13—15题。

给蚂蚁打伞(1)那是个闷热的傍晚,天阴着,没有风,知了的叫声此起彼伏。

他站在一株枝繁叶茂的泡桐树下,心里面像有一堆蚂蚁在没头绪地四处爬行,抓不到,撵不走,躁得不得了。

(2)他是进城务工的农民。

这一点,从他的衣着打扮就可以判断出来。

他在等一个孩子。

(3)当然,那不是他的孩子,他的孩子在两千里之外的乡下,每年春节才能和他见一面。

他真疼那个虎头虎脑的小子,他自己的人生从来没有规划过,但儿子一出生,他的心里就有了一幅宏伟的蓝图,他要让他读书,上大学,做个风刮不着雨淋不着的城里人。

只要想起这幅蓝图,即便身子累散了架,他都能在梦里笑出声。

(4)他经常梦到儿子。

那个夏天,梦到的次数尤其多。

(5)他实在是太想儿子了,便到离工地不远的这个小区看孩子们玩耍。

小区绿化得不错,有一片宽阔的休闲区,休闲区里植满泡桐和月季,还有一座滑梯和两架秋千。

放学之后,这里就成了孩子们小小的游乐场。

那里边还真有个男孩跟他的儿子长得很像。

后来他得知这个孩子名叫童童。

(6)他很想跟童童说话,很想牵着他的小手走一走,他甚至还专门给童童买了一块巧克力,但一直没有机会送给他,他怕被接送童童的老太太看见。

(7)这一天,这个闷热的傍晚,他的机会终于来了。

(8)还是在滑梯旁,童童还是赖着不走。

老太太像往常一样嫌童童淘气,只是,说话间,哈欠连天,她说:“我回家睡一会儿,不许跑远啊!”童童听话地点头,老太太走了。

临走前,拜托一个大点的孩子照顾童童,还将一把雨伞放在了滑梯旁边,叮嘱童童下雨了就打着伞回家。

(9)他在泡桐树后面听得清清楚楚。

过了几分钟,抬头再看,那老太太的脑袋果然没有像往常一样出现在阳台上。

他的心里一阵欢喜。

然而,当他走到滑梯旁,那个大点的孩子一直用警惕的眼光打量他,打量得他心里直发毛。

(10)他想了几分钟,决定去再买一块巧克力来收买这个大点的孩子。

河北省玉田县高二下学期期中考试数学(理)试题.pdf

河北省玉田县高二下学期期中考试数学(理)试题.pdf

玉田县2012-2013学年度高二第二学期期中考试 理科数学参考答案 18.【考点定位】本小题主要考查利用导数研究曲线上某点切线方程、函数的最值及其几何意义,两条直线平行的判定等基础知识,考查运算求解能力.解:(1)因,故 …………2分由于曲线在点处的切线垂直于轴,故该切线斜率为0,即,………………分从而,解得 ……分(2)由(1)知, ……………8分令,解得(因不在定义域内,舍去),当时,,故在上为减函数;当时,,故在上为增函数;故在处取得极小值. ………1分 20.本小题主要考查函数、导数等基础知识,考查运算求解能力、应用意识,考查函数与方程思想、数形结合思想、化归与转化思想,满分12分。

解:(I)因为x=5时,y=11,所以 …………4分(II)由(I)可知,该商品每日的销售量所以商场每日销售该商品所获得的利润 …………6分 从而, 于是,当x变化时,的变化情况如下表: (3,4)4(4,6)+0-单调递增极大值42单调递减由上表可得,x=4是函数在区间(3,6)内的极大值点,也是最大值点; 所以,当x=4时,函数取得最大值,且最大值等于42。

…………11分 答:当销售价格为4元/千克时,商场每日销售该商品所获得的利润最大。

…………12分 21.(12分)解:(1)容易求得: ,----------------------(1分) 故可以猜想, 下面利用数学归纳法加以证明:显然当时,结论成立,-----------------(2分) 假设当;时(也可以),结论也成立,即 ,--------------------------(3分) 那么当时,由题设与归纳假设可知: -----------(5分) 即当时,结论也成立,综上,对,成立。

----(6分) (2)(8分) 所以 ------(10分) 所以只需要证明 (显然成立) 所以对任意的自然数,都有-------(12分) (Ⅱ) ①当时, 即 当时, 在上是减函数,在上是增函数,则函数在区间[-2,0]上的最小值为 …………9分②当时,即 当时, 在上是增函数,则函数在区间[-2,0]上的最小值为综上: 当时, 在区间[-2,0]上最小值为当时, 在区间[-2,0]上最小值为 …………2分。

精品解析:河北省唐山市玉田县2018-2019学年度第二学期八年级历史考试试卷(A)(原卷版)

精品解析:河北省唐山市玉田县2018-2019学年度第二学期八年级历史考试试卷(A)(原卷版)
A.抗日战争取得伟大胜利
B.中央人民政府正式成立
C.联合国合法席位的恢复
D.十一届三中全会的召开
2.1951年,西藏地方政府派出以阿沛·阿旺晋美为首席代表的代表团抵达北京,与中央人民政府谈判,双方达成了和平解放西藏的协议,西藏获得和平解放。这标志着( )
A. 祖国获得了统一B. 祖国大陆获得了统一
C. 西藏自治区成立D. 西藏确立社会主义制度
(1)据材料一,概括新中国成立前夕农民的现状。
(2)据材料二并结合所学知识,指出抗美援朝战争胜利的影响。
(3)根据上述材料及问题指出材料探究的主题是什么?
22.阅读材料,回答问题。
材料一:我们唱着《东方红》,当家做主站起来,我们讲着《春天的故事》改革开放富起来。
——歌曲《走进新时代》歌词
(1)材料一中实行改革开放的伟大历史决策是在哪次会议提出的?这次会议的召开有什么重大意义
7.解放前,上海水泥厂的最高产量达不到设计能力的90%,1957年,还是原有的设备,该厂的产量却超出了设计能力的40%,这一时期产量变化的关键原因是( )
A. 市场需求增大了
B. 该厂的工人人数增加了
C. 打开了国外市场
D. 实行了公私合营
8.十一届三中全会指出:“党中央在理论战线上的崇高任务,就是领导教育全党和全国人民历史地、科学地认识毛泽东同志的伟大功绩,把马列主义、毛泽东思想的普遍原理同社会主义现代化建设的具体实践结合起来,并在新的历史条件下加以发展。”可见,十一届三中全会实现了( )
A. 政治路线的拨乱反正
B. 组织路线的拨乱反正
C. 思想路线的拨乱反正
D. 启动了农村改革的新进程
9.某网站征集“中华人民共和国足迹”专栏的解说词:以简练的语言概括中华人民共和国建立至今每一年发生的重大历史事件产生的影响,以回顾历史,启示后人。其中,“1978年的足迹”的解说词应当是( )

玉田县第二中学2018-2019学年高二上学期第二次月考试卷数学

玉田县第二中学2018-2019学年高二上学期第二次月考试卷数学

玉田县第二中学2018-2019学年高二上学期第二次月考试卷数学 班级__________ 姓名__________ 分数__________一、选择题1. 函数f (x )=Asin (ωx+φ)(A >0,ω>0,)的部分图象如图所示,则函数y=f (x )对应的解析式为( )A. B. C. D.2. 已知||=||=1,与夹角是90°,=2+3,=k ﹣4,与垂直,k 的值为( )A .﹣6B .6C .3D .﹣33. 在ABC ∆中,内角A ,B ,C 所对的边分别是,,,已知85b c =,2C B =,则cos C =( )A .725B .725- C. 725± D .24254. 下列给出的几个关系中:①{}{},a b ∅⊆;②(){}{},,a b a b =;③{}{},,a b b a ⊆;④{}0∅⊆,正确的有( )个A.个B.个C.个D.个 5. 若{}n a 为等差数列,n S 为其前项和,若10a >,0d <,48S S =,则0n S >成立的最大自 然数为( )A .11B .12C .13D .14 6. 已知实数x ,y 满足a x <a y (0<a <1),则下列关系式恒成立的是( ) A.B .ln (x 2+1)>ln (y 2+1)C .x 3>y 3D .sinx >siny7. 设a >0,b >0,若是5a 与5b的等比中项,则+的最小值为( )A .8B .4C .1D .8. 设1m >,在约束条件,,1.y x y mx x y ≥⎧⎪≤⎨⎪+≤⎩下,目标函数z x my =+的最大值小于2,则m 的取值范围为( )A .(1,1+B .(1)+∞ C. (1,3) D .(3,)+∞ 9. 已知 m 、n 是两条不重合的直线,α、β、γ是三个互不重合的平面,则下列命题中 正确的是( ) A .若 m ∥α,n ∥α,则 m ∥n B .若α⊥γ,β⊥γ,则 α∥βC .若m ⊥α,n ⊥α,则 m ∥nD .若 m ∥α,m ∥β,则 α∥β10.一个椭圆的半焦距为2,离心率e=,则它的短轴长是( )A .3B .C .2D .611.下列命题中正确的是( ) (A )若p q ∨为真命题,则p q ∧为真命题( B ) “0a >,0b >”是“2b aa b+≥”的充分必要条件 (C ) 命题“若2320x x -+=,则1x =或2x =”的逆否命题为“若1x ≠或2x ≠,则2320x x -+≠”(D ) 命题:p 0R x ∃∈,使得20010x x +-<,则:p ⌝R x ∀∈,使得210x x +-≥12.某中学有高中生3500人,初中生1500人,为了解学生的学习情况,用分层抽样的方法从该校学生中抽取一个容量为n 的样本,已知从高中生中抽取70人,则n 为( ) A .100 B .150 C .200 D .250二、填空题13.如图所示是y=f (x )的导函数的图象,有下列四个命题: ①f (x )在(﹣3,1)上是增函数; ②x=﹣1是f (x )的极小值点;③f (x )在(2,4)上是减函数,在(﹣1,2)上是增函数; ④x=2是f (x )的极小值点.其中真命题为 (填写所有真命题的序号).14.设集合 {}{}22|27150,|0A x x x B x x ax b =+-<=++≤,满足A B =∅,{}|52A B x x =-<≤,求实数a =__________.15.用“<”或“>”号填空:30.8 30.7.16.图中的三个直角三角形是一个体积为20的几何体的三视图,则h =__________.17.已知直线5x+12y+m=0与圆x 2﹣2x+y 2=0相切,则m= .18.81()x x-的展开式中,常数项为___________.(用数字作答) 【命题意图】本题考查用二项式定理求指定项,基础题.三、解答题19.(本小题满分12分)如图所示,已知⊥AB 平面ACD ,⊥DE 平面ACD ,ACD ∆为等边 三角形,AB DE AD 2==,F 为CD 的中点. (1)求证://AF 平面BCE ; (2)平面⊥BCE 平面CDE .20.已知奇函数f (x )=(c ∈R ).(Ⅰ)求c 的值;(Ⅱ)当x∈[2,+∞)时,求f(x)的最小值.21.某民营企业生产A,B两种产品,根据市场调查和预测,A产品的利润与投资成正比,其关系如图1,B 产品的利润与投资的算术平方根成正比,其关系如图2(注:利润与投资单位是万元)(1)分别将A,B两种产品的利润表示为投资的函数,并写出它们的函数关系式.(2)该企业已筹集到10万元资金,并全部投入A,B两种产品的生产,问:怎样分配这10万元投资,才能使企业获得最大利润,其最大利润约为多少万元.(精确到1万元).22.如图在长方形ABCD中,是CD的中点,M是线段AB上的点,.(1)若M是AB的中点,求证:与共线;(2)在线段AB上是否存在点M,使得与垂直?若不存在请说明理由,若存在请求出M点的位置;(3)若动点P在长方形ABCD上运动,试求的最大值及取得最大值时P点的位置.23.某志愿者到某山区小学支教,为了解留守儿童的幸福感,该志愿者对某班40名学生进行了一 次幸福指数的调查问卷,并用茎叶图表示如图(注:图中幸福指数低于70,说明孩子幸福感弱;幸福指 数不低于70,说明孩子幸福感强).(1)根据茎叶图中的数据完成22⨯列联表,并判断能否有95%的把握认为孩子的幸福感强与是否是留幸福感强 幸福感弱 总计 留守儿童 非留守儿童 总计1111](2)从5人中随机抽取2人进行家访, 求这2个学生中恰有一人幸福感强的概率.参考公式:22()()()()()n ad bc K a b c d a c b d -=++++附表:20()P K k ≥0.050 0.01024.已知二次函数f(x)的图象过点(0,4),对任意x满足f(3﹣x)=f(x),且有最小值是.(1)求f(x)的解析式;(2)求函数h(x)=f(x)﹣(2t﹣3)x在区间[0,1]上的最小值,其中t∈R;(3)在区间[﹣1,3]上,y=f(x)的图象恒在函数y=2x+m的图象上方,试确定实数m的范围.玉田县第二中学2018-2019学年高二上学期第二次月考试卷数学(参考答案)一、选择题1. 【答案】A【解析】解:由函数的图象可得A=1, =•=﹣,解得ω=2,再把点(,1)代入函数的解析式可得 sin (2×+φ)=1,结合,可得φ=,故有,故选:A .2. 【答案】B【解析】解:∵ =(2+3)(k ﹣4)=2k +(3k ﹣8)﹣12=0,又∵=0.∴2k ﹣12=0,k=6.故选B【点评】用一组向量来表示一个向量,是以后解题过程中常见到的,向量的加减运算是用向量解决问题的基础,要学好运算,才能用向量解决立体几何问题,三角函数问题,好多问题都是以向量为载体的3. 【答案】A 【解析】考点:正弦定理及二倍角公式.【思路点晴】本题中用到了正弦定理实现三角形中边与角的互化,同角三角函数间的基本关系及二倍角公式,如θθθθθ2222sin cos 2cos ,1cos sin -==+,这要求学生对基本公式要熟练掌握解三角形时常借助于正弦定理R CcB b A 2sin sin sin a ===,余弦定理A bc c b a cos 2222-+=, 实现边与角的互相转化. 4. 【答案】C 【解析】试题分析:由题意得,根据集合之间的关系可知:{}{},,a b b a ⊆和{}0∅⊆是正确的,故选C. 考点:集合间的关系. 5. 【答案】A 【解析】考点:得出数列的性质及前项和.【方法点晴】本题主要考查了等差出数列的性质及前项和问题的应用,其中解答中涉及到等差数列的性质,等差数列的前项和等公式的灵活应用的知识点的综合考查,着重考查了学生分析问题和解答问题的能力,以及推理与运算能力,属于中档题,本题的解答中,由“10a >,0d <”判断前项和的符号问题是解答的关键.6. 【答案】C【解析】解:∵实数x 、y 满足a x <a y(1>a >0),∴y <x .对于A .取x=1,y=0,不成立,因此不正确;对于B .取y=﹣2,x=﹣1,ln (x 2+1)>ln (y 2+1)不成立; 对于C .利用y=x 3在R 上单调递增,可得x 3>y 3,正确;对于D .取y=﹣π,x=,但是sinx=,siny=,sinx >siny 不成立,不正确.故选:C .【点评】本题考查了函数的单调性、不等式的性质,考查了推理能力,属于基础题.7. 【答案】B 【解析】解:∵是5a 与5b的等比中项, ∴5a •5b=()2=5,即5a+b =5, 则a+b=1,则+=(+)(a+b)=1+1++≥2+2=2+2=4,当且仅当=,即a=b=时,取等号,即+的最小值为4,故选:B【点评】本题主要考查等比数列性质的应用,以及利用基本不等式求最值问题,注意1的代换.8.【答案】A【解析】考点:线性规划.【方法点晴】本题是一道关于线性规划求最值的题目,采用线性规划的知识进行求解;关键是弄清楚的几何意义直线z x my =+截距为zm,作0my x :L =+,向可行域内平移,越向上,则的值越大,从而可得当直线直线z x my =+过点A 时取最大值,⎩⎨⎧==+00001mx y y x 可求得点A 的坐标可求的最大值,然后由z 2,>解不等式可求m的范围. 9. 【答案】C【解析】解:对于A ,若 m ∥α,n ∥α,则 m 与n 相交、平行或者异面;故A 错误; 对于B ,若α⊥γ,β⊥γ,则 α与β可能相交,如墙角;故B 错误; 对于C ,若m ⊥α,n ⊥α,根据线面垂直的性质定理得到 m ∥n ;故C 正确; 对于D ,若 m ∥α,m ∥β,则 α与β可能相交;故D 错误; 故选C .【点评】本题考查了空间线线关系.面面关系的判断;熟练的运用相关的定理是关键.10.【答案】C【解析】解:∵椭圆的半焦距为2,离心率e=,∴c=2,a=3,∴b=∴2b=2. 故选:C .【点评】本题主要考查了椭圆的简单性质.属基础题.11.【答案】D【解析】对选项A ,因为p q ∨为真命题,所以,p q 中至少有一个真命题,若一真一假,则p q ∧为假命题,故选项A 错误;对于选项B ,2b aab+≥的充分必要条件是,a b 同号,故选项B 错误;命题“若2320x x -+=,则1x =或2x =”的逆否命题为“若1x ≠且2x ≠,则2320x x -+≠”,故选项C 错误;故选D .12.【答案】A【解析】解:分层抽样的抽取比例为=,总体个数为3500+1500=5000,∴样本容量n=5000×=100.故选:A.二、填空题13.【答案】①【解析】解:由图象得:f(x)在(1,3)上递减,在(﹣3,1),(3,+∞)递增,∴①f(x)在(﹣3,1)上是增函数,正确,x=3是f(x)的极小值点,②④不正确;③f(x)在(2,4)上是减函数,在(﹣1,2)上是增函数,不正确,故答案为:①.14.【答案】7,32a b=-=【解析】考点:一元二次不等式的解法;集合的运算.【方法点晴】本题主要考查了集合的综合运算问题,其中解答中涉及到一元二次不等式的解法、集合的交集和集合的并集的运算、以及一元二次方程中韦达定理的应用,试题有一定的难度,属于中档试题,着重考查了学生分析问题和解答问题的能力,同时考查了转化与化归思想的应用,其中一元二次不等式的求解是解答的关键. 15.【答案】>【解析】解:∵y=3x是增函数,又0.8>0.7,∴30.8>30.7.故答案为:>【点评】本题考查对数函数、指数函数的性质和应用,是基础题.16.【答案】 【解析】试题分析:由三视图可知该几何体为三棱锥,其中侧棱VA ⊥底面ABC ,且ABC ∆为直角三角形,且5,,6AB VA h AC ===,所以三棱锥的体积为115652032V h h =⨯⨯⨯==,解得4h =.考点:几何体的三视图与体积. 17.【答案】8或﹣18【解析】【分析】根据直线与圆相切的性质可知圆心直线的距离为半径,先把圆的方程整理的标准方程求得圆心和半径,在利用点到直线的距离求得圆心到直线的距离为半径,求得答案.【解答】解:整理圆的方程为(x ﹣1)2++y 2=1 故圆的圆心为(1,0),半径为1 直线与圆相切∴圆心到直线的距离为半径即=1,求得m=8或﹣18故答案为:8或﹣18 18.【答案】70【解析】81()x x -的展开式通项为8821881()(1)r rr r r r r T C x C x x--+=-=-,所以当4r =时,常数项为448(1)70C -=.三、解答题19.【答案】(1)证明见解析;(2)证明见解析. 【解析】试题分析:(1)推导出BC AC ⊥,1CC AC ⊥,从而⊥AC 平面11B BCC ,连接11,NA CA ,则N A B ,,1三点共线,推导出MN CN BA CN ⊥⊥,1,由线面垂直的判定定理得⊥CN 平面BNM ;(2)连接1AC 交1CA 于点H ,推导出1BA AH ⊥,1BA HQ ⊥,则AQH ∠是二面角C BA A --1的平面角.由此能求出二面角1B BN C --的余弦值.试题解析:(1)如图,取CE 的中点G ,连接BG FG ,. ∵F 为CD 的中点,∴DE GF //且DE GF 21=. ∵⊥AB 平面ACD ,⊥DE 平面ACD , ∴DE AB //, ∴AB GF //.又DE AB 21=,∴AB GF =. ∴四边形GFAB 为平行四边形,则BG AF //. (4分) ∵⊄AF 平面BCE ,⊂BG 平面BCE , ∴//AF 平面BCE (6分)考点:直线与平面平行和垂直的判定.20.【答案】【解析】解:(Ⅰ)∵f (x )是奇函数,∴f (﹣x )=﹣f (x ),∴=﹣=,比较系数得:c=﹣c ,∴c=0,∴f (x )==x+;(Ⅱ)∵f (x )=x+,∴f ′(x )=1﹣,当x ∈[2,+∞)时,1﹣>0,∴函数f (x )在[2,+∞)上单调递增,∴f (x )min =f (2)=.【点评】本题考查了函数的奇偶性问题,考查了函数的单调性、最值问题,是一道中档题.21.【答案】【解析】解:(1)投资为x万元,A产品的利润为f(x)万元,B产品的利润为g(x)万元,由题设f(x)=kx,g(x)=k2,(k1,k2≠0;x≥0)由图知f(1)=,∴k1=又g(4)=,∴k2=从而f(x)=,g(x)=(x≥0)(2)设A产品投入x万元,则B产品投入10﹣x万元,设企业的利润为y万元y=f(x)+g(10﹣x)=,(0≤x≤10),令,∴(0≤t≤)当t=,y max≈4,此时x=3.75∴当A产品投入3.75万元,B产品投入6.25万元时,企业获得最大利润约为4万元.【点评】本题考查利用待定系数法求函数的解析式、考查将实际问题的最值问题转化为函数的最值问题.解题的关键是换元,利用二次函数的求最值的方法求解.22.【答案】【解析】(1)证明:如图,以AB所在直线为x轴,AD所在直线为y轴建立平面直角坐标系,当M是AB的中点时,A(0,0),N(1,1),C(2,1),M(1,0),,由,可得与共线;(2)解:假设线段AB上是否存在点M,使得与垂直,设M(t,0)(0≤t≤2),则B(2,0),D(0,1),M(t,0),,由=﹣2(t﹣2)﹣1=0,解得t=,∴线段AB上存在点,使得与垂直;(3)解:由图看出,当P在线段BC上时,在上的投影最大,则有最大值为4.【点评】本题考查平面向量的数量积运算,考查了向量在向量方向上的投影,体现了数形结合的解题思想方法,是中档题.23.【答案】(1)有95%的把握认为孩子的幸福感强与是否留守儿童有关;(2)35. 【解析】∴240(67918)4 3.84115252416K ⨯⨯-⨯==>⨯⨯⨯. ∴有95%的把握认为孩子的幸福感强与是否留守儿童有关.(2)按分层抽样的方法可抽出幸福感强的孩子2人,记作:1a ,2a ;幸福感强的孩子3人,记作:1b ,2b ,3b .“抽取2人”包含的基本事件有12(,)a a ,11(,)a b ,12(,)a b ,13(,)a b ,21(,)a b ,22(,)a b ,23(,)a b ,12(,)b b ,13(,)b b ,23(,)b b 共10个.事件A :“恰有一人幸福感强”包含的基本事件有11(,)a b ,12(,)a b ,13(,)a b ,21(,)a b ,22(,)a b ,23(,)a b 共6个. 故63()105P A ==. 考点:1、 茎叶图及独立性检验的应用;2、古典概型概率公式. 24.【答案】【解析】解:(1)二次函数f(x)图象经过点(0,4),任意x满足f(3﹣x)=f(x)则对称轴x=,f(x)存在最小值,则二次项系数a>0设f(x)=a(x﹣)2+.将点(0,4)代入得:f(0)=,解得:a=1∴f(x)=(x﹣)2+=x2﹣3x+4.(2)h(x)=f(x)﹣(2t﹣3)x=x2﹣2tx+4=(x﹣t)2+4﹣t2,x∈[0,1].当对称轴x=t≤0时,h(x)在x=0处取得最小值h(0)=4;当对称轴0<x=t<1时,h(x)在x=t处取得最小值h(t)=4﹣t2;当对称轴x=t≥1时,h(x)在x=1处取得最小值h(1)=1﹣2t+4=﹣2t+5.综上所述:当t≤0时,最小值4;当0<t<1时,最小值4﹣t2;当t≥1时,最小值﹣2t+5.∴.(3)由已知:f(x)>2x+m对于x∈[﹣1,3]恒成立,∴m<x2﹣5x+4对x∈[﹣1,3]恒成立,∵g(x)=x2﹣5x+4在x∈[﹣1,3]上的最小值为,∴m<.。

河北省玉田县高二数学下学期期中试题 文(扫描版)新人教A版

河北省玉田县高二数学下学期期中试题 文(扫描版)新人教A版

2013---2014学年度第二学期期中考试高二文科数学参考答案三、解答题:17. (10分)设,则=为纯虚数,所以,…………4分因为,所以;又。

…………7分解得…………8分所以…………10分主食蔬菜主食肉类合计50岁以下 4 8 1250岁以上16 2 18合计20 10 30……6分(2)K2=12×18×20×1030(8-128)2=12×18×20×1030×120×120=10>6.635,有99%的把握认为亲属的饮食习惯与年龄有关.…………12分 19. 解:(1)由的图象经过P (0,2),知d=2,所以由在处的切线方程是知故所求的解析式是 …………6分(2)解得当当故内是增函数,在内是减函数,在内是增函数. …………12分20. 解:∵0°<B<180°,∴B =60°. ∴A +C =2B =120°. ∴A 、B 、C 成等差数列. …………12分21. (1)当x =40(千米/时)时,汽车从甲地到乙地行驶了40100=2.5(小时).要耗油×40+83×11 2.5=17.5(升).所以当汽车以40千米/时的速度匀速行驶时,从甲地到乙地耗油17.5升.…………4分(2)当速度为x 千米/时,汽车从甲地到乙地行驶了x 100小时,设耗油量为h(x)升,依题意得h(x)=x +83·x 100=1 2801x2+x 800-415(0<x ≤120).h ′(x)=640x -x2800=640x2x3-803(0<x ≤120),令h ′(x)=0,得x =80,当x ∈(0,80)时,h ′(x)<0,h(x)是减函数;当x ∈(80,120]时,h ′(x)>0,h(x)是增函数.∴当x =80时,h(x)取得极小值h(80)=11.25.因此h(x)在(0,120]上只有一个极值,也是它的最小值.所以,当汽车以80千米/时的速度匀速行驶时,从甲地到乙地耗油最少,最少为11.25升.…………12分。

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玉田二中第二学期阶段考试(高二英语)A套试卷第一节单项选择题(25分)1.The couple died but their child ____ after the earthquake .A.lived onB. lived up toC.lived throughD. lived by2.But by no means ___ with my progress .A. the teacher is not satisfiedB. is the teacher not satisfiedC. the teacher is satisfiedD. is the teacher satisfied3 It is not immediately clear ___ the financial crisis will soon be overA. since B what C when D whether4. A good idea ___ him when he was asked to solve the problemA. struke toB. occurred toC. happened toD. stuck to5. ___ we will hold a party in the open air tomorrow depends on the weatherA. whetherB. if C.whatD.which6.The word ―media‖ basically refers to ___ we commonly call newspapers , magazines, radios and televisionsA. whichB. thatC. whatD.where7.The man has a good sense of humor and we all find it great fun to ___ with him .A. team upB. make upC. catch upD. keep up8.To travel to the United States , you must first apply __ the American embassy __ your visaA. for; toB. to; forC. for; forD.to ;to9. His hard work _____and he made great progress in his EnglishA.paid offB.paid backC.paid forD. paid on10 Many college students _____by the failure to find workA. was much cast downB. were much cast downC. much cast downD. were cast off11 His girlfriend is trying her best to reduce t he young man’s fear ___he would die of the disease soonA whenB why C. that D. of which12.Do you have any idea ___TV plays such an important part in our daily life nowadays ?A. why is it thatB. how it is thatC. why was itD. when it was that13.The tsunami ___fear ___the people’s hearts of the tsunami-hit countriesA struck; into B. struck; on C .struck; by D. struck; at14. The young man ___in his first play and became famous overnightA .distinguished himself B. enjoyed himselfC. betrayed himselfD. dressed himself15.____with his brother , the little boy is not clever at all.A. comparingB. comparedC. to compareD. to be compared16. only if a teacher has given permission ___to enter this roomA. a student is allowedB. is allowed a studentC. is a student allowedD. a student allowed17.Such effective measures ___ much earlier , the river would not be polluted so seriouslyA. if we had takenB.had we takenC.takenD. taking18.He goes through the whole performance of checking the oil and water ___ he drives the carA. every timeB. in timeC. whileD. on time19. ___ to nuclear radiation , even for a short time , may produce variants(变体) sf genes in human bodiesA .Being exposed B. Having exposedC. ExposedD. After being exposed20.He ___before he answered because he didn’t know what to sayA. paused B ceased C. hesitated D. stopped21. Their suggestions are of not much ____A. valuableB. valueC. goodD. better22.The emperor traveled ____ in order not to be recognizedA.in the disguise ofB. in disguiseC. without disguise D with disguise23. I remember her face but I can’t ___ where I met herA. recallB. remarkC. remindD. retell24. His accent at once betrayed ____he was a foreignerA which B. that C. what D. with that25. ___, the nutrition in them will be destroyedA. If vegetables are cooked too longB. Cooked too longC. If cooked too longD. If being cooked too long第二节完形填空(20小题每小题1.5分共30分)As she walked round the large shop, Edith realized how difficult it was to choose a suitable Christmas 26 for her father.She 27 that he were as easy to please as her mother, who was 28 satisfied with perfume(香水).29 , shopping at this time of the year was a most 30 job. People 31 on your feet, pushed you with their shoulders and almost 32 you over in their hurry in order to 33 something cheap ahead of you. Partly to have a rest, Edith paused in front of a counter, where some beautiful ties were on 34 . "They are 35 silk," the shop assistant told her with a smile trying to 36 her to buy one. But Edith knewfrom past 37 that her choice of ties hardly ever pleased her father.She moved on slowly and then, quite by chance, 38 where a small crowd of men had gathered round a counter. She found some fine pipes on sale and the 39 were very beautiful. Edith did not hesitate for long, although her father 40 smoked a pipe once in a while, she believed this was 41 to please him. When she got home, with her small but 42 present hidden in her handbag, it was time for supper and her parents were already43 table. Her mother was in great 44 . "Your father has at last decided to stop smoking," she told her daughter happily. Edith was so 45 that she could not say a single word.26. A. suit B. card C. thing D. gift27. A. believed B. wished C. hoped D. supposed28. A. never B. seldom C. always D. scarcely29. A. Therefore B. Fortunately C. Besides D. Finally30. A. unhappy B. careful C. exciting D. tiring31. A. walked B. stepped C. lifted D. stood32. A. turned B. hit C. brought D. knocked33. A. watch B. find C. grasp D. sell34. A. time B. show C. board D. duty35. A. real B. cheap C. poor D. exact36. A. hope B. ask C. force D. persuade37. A. experience B. things C. books D. school38. A. stopped B. saw C. asked D. found39. A. money B. cigarette C. shapes D. shop40. A. always B. nearly C. only D. never41. A. hardly B. impossibly C. possibly D. certainly42. A. cheap B. well-chosen C. expensive D. ready-made43. A. on B. by C. beside D. at44. A. excitement B. anger C. sadness D. disappointment45. A. glad B. happy C. surprised D. excited第三部分:阅读理解(共20小题,每题2分,满分40分)阅读下列短文,从每题所给的A、B、C、D四个选项中,选出最佳答案.AWASHINGTON -Tofu(豆腐)and Soyaburgers (豆饼) may be coming to American school lunch menus. What will the kids say?―Terrible,‖ said Greg Dudzinski, 17, of Ripon High School in Wisconsi n, as he toured the US capital. ―The regular hamburgers are bad enough, so soyaburgers would be a lot worse, offered Zach Richey, 13, of Scottsboro Junior High in Alabama, another tourist.But the United States government – hoping to reduce the amount of fat that children are eating –has approved the use of soy as a meat substitute in meals for schools and day-care centers. Not all kids dislike the change. Mariel Spano, 17, of sandy Greek High School in New York, also visiting the capital, said she likes soyaburgers:―There is less fat, and they are better for you… They taste the same, and they are just as good.‖The government tried to make soy a meat substitute nearly 20 years ago, but later dropped the ideA.At the time, the plan was intended as a cost-cutting move. US Agriculture Department officials say that their purpose now is only to make meals healthier.Schools are likely to increase the amount of soy that is mixed with hamburgers and other foods already on their menus, and they will also be looking for food companies to develop new soy products that children will like. ― I can’t see putting tofu on a student’s plate and having a good acceptance. I can see taking a product that is familiar to the students and adding a large amount of soy to it and having it to be acceptable,‖ said Jill Benza, director of food services for the Mesa, Arizona schools.46.What is the newspaper report mainly about?A.The difficulty in using soy products for US schools.B.Various opinions on soy products for US schools.C.The plan that is made by the US government for school lunch.D.Healthy foods for students in US schools.47.Where did the interviews most probably take place?A.In food companies. B.In schools.C.In Washington. D.In some other states.48.We may learn from the text that _________________________.A.soyaburgers taste better than hamburgers.B.hamburgers are healthier than soyaburgers.C.soyaburgers cost less than hamburgers.D.hamburgers cost less than soyaburgers.49.What Jill Benza said shows that ___________________________.A.students have not yet been used to soy products.B.it is hardly possible to make soy products popular.C.he does not like the change in meals for students.D.schools are unwilling to change the lunch menus.BCutsBleeding can usually be stopped by applying pressure to the cut for 2 or 3 minutes. The cut can then be carefully inspected. If it has bled freely any germs will normally have been washed away by the blood. Apply a plaster dressing firmly, bringing the edges of the cut together so that it knits quickly. Keep dry for 1 to 2 days.If the cut is deep and the edges cannot be pulled together with a dressing consult the doctor or the practice nurse. A tetanus (破伤风) injection may be needed.GrazesDirt will often enter a graze caused by falling on a hard or rough surface. It must be cleaned out carefully with an antiseptic solution. (消毒液)After cleaning, leave the graze uncovered. Exposure to the air will cause a scab to form. This will gradually fry and fall off.It is not a good idea to apply a dressing. This may stick to the graze or make it complete wet and infected.BruisesBruises are very common in children. They normally get better in 7 to 10 days Parents sometimes worry that a bone may be broken, but if in doubt consult the doctor. If a child gets up at once after a fall and moves about normally, it is unlikely that a bone has been broken.Severe bruising can be treated by:Rest for 24 to 48 hours .In the case of a badly bruised leg, the limb should be raised. Lying in bed is the easiest way to do this.A bad compress may ease a bad bruise if applied at once. This is made by leaving some material in water and applying it to the bruise.Insect bitesThese are common in the summer .They look like spots about 1/4’’across .They are very itchy (痒) and usually appear on exposed parts, e.g. arms and legs.The itching can be relieved by calamine lotion (护肤药水).Burns and scaldsMinor burns and scalds cause redness of the skin. Immediate treatment by pouring cold water over a burn is often helpful. If burns cause the skin severe hot or break the skin, the doctor should be turned to.Sunburns should, if possible, be prevented by avoiding long exposure and covering exposed areas as much as needed. It may be treated by calamine lotion to relieve the pain.50.The purpose of the booklet is _____A.to tell us what to do until a doctor arrives.B.to explain what cause minor illnesses.C.to show that it is unnecessary to call a doctor.D.to help us to treat minor illnesses at home51.When treating a minor cut ,we are first told to _____.A.clean out the wound. B.press down on the wound.C.wash the blood away. D.close up the wound.52.The injury which we are told how to avoid is _____.A.sunburn. B.insect bites. C.scalds. D.cuts.53.Patients with badly bruised legs are advised to go to bed so that ______.A.they can rest completely. B.their injured leg can be lifted up.C.they can leave their leg in water. D.a cold compress can be appliedCA man was tired of living in his old house in the country and wanted to sell it and buy a better one. He tried to sell it for a long time,but was not successful,so at last he decided to solve the problem by using as real estate agent.(房地产代理人)The agent decided at once to advertise the house,and a few days later,the owner saw a very attractive photograph of it,with a wonderful description of its gardens,in an expensive magazine. After the house owner had read the advertisement through,he hurriedly telephoned the real estate agent and said to him,―I'm sorry,Mr. Jones,but I've decided not to sell my house after all. After reading your advertisement in that magazine,I can see that it's just the kind of house I've wanted to live in all my life.‖54.What problem did the man have?A.He couldn't find his houseB.He was unsuccessful at selling his houseC.He was unsuccessful at buying a houseD.He was unsuccessful at finding a real estate agent55.It's easier to sell house through agents because ______.A.they have a magazineB.they are better at writing articlesC.they are good at better advertisingD.they are better looking56.Which of the following best states the main idea?A.You don't know what you have until you have lost it.B.It's hard to sell a houseC.No one likes to live in the country.D.There is no place like home.57.In the passage the word―attractive‖most nearly means ______.A.perfectpleteC.modernD.pleasant to look atDHave you ever seen any students whose trousers hang so low you can see their underwear?What do you think of that?Fashionable?Some of today's teenagers are big fans of such a look. But recently this trend has been at the center of an argument in Italian middle schools. The headmaster of a school in central Italy has asked students to stop wearing low-rise jeans that expose underwear and parts of the body. His request came after a class trip,when he saw one boy's baggy trousers slide to his feet. He pointed out that this way of dressing is not suitable for school. But in Italy,a nation that takes fashion very seriously,the suggestion caused a debate among parents,teachers and students. The issue is whether the headmaster's request will limit students' freedom— or whether dress in Italian schools is too casual. A parents' group praised the move in favor of good taste,while others advised schools to stop worrying about fashion and fix up old school buildi ngs.―We do not want to kick fashion out,‖ the headmaster explained,―but extrems (极端)of fashion like this are not right in school.‖ Many other schools have now requested that their students also stop wearing such trousers. Most students have simply ignored the request. Ludovica Gaudio,14,wore extremely low trousers exposing orange underwear in class. It was cold,so she wore a matching orange scarf. Another14-year-old said she would probably respect the request,simply for practical reasons. ―I don't re ally feel comfortable in those sort of jeans,‖ said Sarah Lattanzi,―in winter,when dressed like that,it's quite cold and I am afraid my stomach will ache.‖58. What led to the argument in Italian middle schools?A. Students' craze for fashions.B. Clothes that are too exposing.C. Students' ignoring dress codes(着装规则)D. Students' underwear.59. Which of the following supports the headmaster's request?A. Fashion should be taken seriously.B. Fashion should not be followed in school.C. Students should have their freedom in choosing what they wear.D. Students should be encouraged to have good taste in clothes.60. The argument against the headmaster's request is that ________.A. schools should pay attention to things more important than students' clothesB. fashion should not be followed in schoolC. dress in Italian schools is too casualD. low-rise jeans can do harm to youngster's health61.The purpose of this story is to ________A. show Chinese students that wearing very fashionable clothes in school is under attack in othercountries,too.B. show that dress code is necessary even in a country like ItalyC. tell us that a debate started in Italian middle schools over the way students dress in schoolD. let us see that Italian students react differently to schools' requests.EA year ago, I paid no attention to English idioms, though my teacher emphasized the importance again and again. But soon, the importance of English idioms was shown in an amusing experience.One day, I happened to meet an Englishman on the road, and soon we began totalk. As I was talking about how I was studying English, the foreigner seemed to be astonished gently shaking his head, shrugging his shoulders, saying, ―You don’t s ay!‖―You don’t say!‖ I was puzzled. I thought, perhaps this is not an appropriate topic. ―Well, I’d better change the topic. ‖So I said to him, ―well, shall we talk about the Great Wall?‖ By the way, have you ever been there? ―Certainly, everyone back home will laugh at me if I leave China without seeing it. It was magnificent.‖ He was deep in thought when I began to talk like a tourist guide, ―The Great Wall is one of the wonders in the world. We are proud of it.‖ Soon I was interrupted again by his order ―You don’t say!‖ I couldn’t help asking .I said, ―Didn’t you say you don’t say?‖ Hearing this, the Englishman laughed to tears. He began to explain, ―You don’t say actually means really? It is an expression of surprise. Perhaps you don’t pay attention to E nglish idioms.‖ Only then did I had made a fool of myself. Since then I have been more careful with idiomatic expression. 62.A year ago, I paid no attention to English idioms because .A.English idioms were too difficult to masterB.I had no interest in English learingC.my teacher didn’t emphasize the importanceD.I cared little about the teacher’s instruction63.When I first heard ―You don’t say!‖ I thought .A.the Englishman was not interested in my EnglishB.the Englishman was only interested in the Great WallC.I had talked too muchD.I had to stop talking at once64.Which of the following is true?A.The Englishman was leaving China without seeing the Great Wall.B.The Englishman wanted to see the Great Wall after I talked about it.C.The Englishman wanted me to act as his guide.D.The Englishman visited the Great Wall and thought it worth visiting 65.After the Englishman explained the idiom, .A.the Englishman made me a foolB.the Englishman made a fool of himselfC.I felt very sillyD.I felt proud of my understanding高二英语 卷II (共55分)单词拼写(5分)1.I’d like to come, too, if you have no ___________(反对).2. They were so much alike that we could hardly ____________(区分)one from the other.3.Everything _________(表明) that the day’s work is over.4.The __________(积累的) evidence showed that a puma had escaped from the zoo.5.They occupy a very __________(较高)position in local society. 完成句子(10分)1. 我突然想起今晚我该拜访汤姆。

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