2015柳州二模 广西省柳州市2015届高中毕业班3月份模拟(梧州二模)考试理综试卷 扫描版含答案

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2015年广西柳州市二中高三语文上学期第二次模拟(文科)试卷

2015年广西柳州市二中高三语文上学期第二次模拟(文科)试卷

2015年广西柳州市二中高三语文上学期第二次模拟(文科)试卷语文2.7本试卷,150分。

考试时长120分钟。

考生务必将答案答在答题卡上,在试卷上作答无效。

考试结束后,将本试卷和答题卡一并交回。

一、选择题共8小题,每小题5分,共40分。

在每小题列出的四个选项中,选出符合题目要求的一项。

1.下列各句中,没有语病的一句是()A、作为一名杰出的政治家和诗人,于谦为人正直,不畏强暴,他短暂而壮烈的一生,是他那四句自勉诗的真实写照。

B、我们可以在街头随处可见各类商店出售不同档次的商品,而且卖得很火。

C、神舟5号宇宙飞船载着杨利伟胜利返回地球,这是我们国家自行研制的,每一个中国人不能不为它骄傲。

D、在市场经济发展的初期,许多发达国家曾为此付出过社会伦理道德几乎崩溃的惨重代价。

2. 下列语句表达没有歧义的一句是A.他身为副总经理,经常在董事长面前说总经理搞行贿,是为了能向上爬,这完全是一派胡言。

B.近来有些学生出现呕吐、腹泻的症状,有些学生又出现头昏、失眠的症状,究其原因是多方面的,而主要的是不注意饮食卫生。

C.人非圣贤,孰能无过?年轻人经验不足,在实际工作中难免不犯一些错误。

D.这支来访的利兹联队给我们绿城队的年轻队员们上了很好的一课,恐怕他们终生都不会忘记这次比赛。

3.下列句子没有语病、句意明确的一句是A、一对夫妇特意赶在结婚纪念日这天来到捐助中心,一人捐了1000元钱。

B、老人在80岁的时候,还清楚地记得哥哥参加学生运动时对自己的评价:一个温情主义者。

C、针对中国新一代家用电脑发展趋势,一贯以技术领先、功能创新闻名的恒利科技电脑公司计划在近期率先推出具有国际先进水准的新一代家用电脑产品。

D、为了给村民们讨一个说法,从前年冬天开始,年近花甲的老村长就带他和两个弟弟踏上了这漫长而艰辛的告状之路。

4.下列各句中,没有语病的一句是A.建议有关部门能否考虑设立租房介绍所,使动迁居民能租到临时房屋。

B..如果有了正确的道德观和健康的审美感,那么阅读中就能正确理解文章的含义。

中考二模 广西梧州市2015年初中毕业升学考试抽样调研测试卷(二)英语试题(含听力)及答案

中考二模 广西梧州市2015年初中毕业升学考试抽样调研测试卷(二)英语试题(含听力)及答案

2015年梧州市初中毕业升学考试抽样调研测试卷(二)英语说明:1.本试卷共10页(试题卷8页,答题卡2页),满分120分,考试时间120分钟。

2.答题前,请将准考证号、姓名、座位号写在答题卡指定位置,答案写在答题卡相应的区域内,在试题卷上答题无效.........。

第Ⅰ卷(选择题,共85分)一、听力测试(共30分)(一)听句子,选画面(每小题1分,共5分)请你根据所听到的5个句子,选出意思相符的图画选项。

每个句子读一遍。

A B C D E1.__________2. __________3. __________4. __________5. __________(二)听句子,选答语(每小题1分,共5分)请你根据所听到的5个句子,选出最恰当的答语。

每个句子读一遍。

6. A. Not at all. B. That sounds good. C. Yes, we are.7. A. He likes eggs. B. He is eleven. C. He is tall.8. A. P.E. B. The big one. C. Size eight.9. A. No, thanks. B. Here you are. C. Certainly.10. A. Since last week. B. Once a week. C. A week ago.(三)对话理解(每小题1分,共10分)你将听到10段小对话,请根据对话内容和所提出的问题,选择最佳答案。

每段对话读两遍。

11. A. Green. B. Red. C. Blue.12. A. In July. B. In June. C. In August.13. A. Go swimming. B. Go for a picnic. C. Play football.14. A. Canada. B. England. C. Australia.15. A.$50. B.$35. C.$70.16. A. Cindy. B. Helen. C. Grace.六堡茶17. A. A sweater. B. A T-shirt. C. A skirt.18. A. Have a party. B. Have a test. C. Have dinner.19. A. Take singing lessons. B. Take acting lessons. C. Write stories.20. A. Six. B. Five. C. Four.(四)短文理解(每小题2分,共10分)你将听到一篇短文,请根据短文内容和所提出的问题,选择最佳答案。

广西梧州市2015届高三第三次模拟数学(理)试卷 (Word版含答案)

广西梧州市2015届高三第三次模拟数学(理)试卷 (Word版含答案)

梧州市2015届高三第三次模拟试卷理科数学(考试时间:120分钟 满分:150分)注意:1.本套试卷分第I 卷(选择题)和第Ⅱ卷(非选择题)两部分,所有答案写在答卷上,否则答题无效。

2.答卷前,考生务必将密封线内的项目填写清楚,密封线内不要答题。

3.选择题,请用2B 铅笔,把答题卡上对应题目选项的信息点涂黑。

非选择题,请用 0. 5mm 黑色字迹签字笔在答题卡指定位置作答。

第I 卷(选择题,共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每个小题给出的四个选项中,只有一项是符合题目要求的.1.设集合 {}{}(2)|ln(2),|21,x x A x N y x B x A B -=∈=-=≤=A . {}|1x x ≥B . {}|12x x ≤<C . {}1D . {}0,12.已知复数z 满足方程 z i zi +=(i 为虚数单位),则复数 z 对应点在第几象限 A.第一象限 B.第二象限 C.第三象限 D .第四象限3.已知正数组成的等比数列 {}n a ,若 120100a a ⋅=,那么 318a a + 的最小值为 A.20 B .25 C. 50 D .不存在4.已知向量 2(1,2),(,4)a b m =--=,那么“ //a b ”是“ m =A.充分不必要条件 B .必要不充贫条件C.充分必要条件 D .既不充分也不必兽名仳5.如右图,当输入的实数 []2,30x ∈时,执行如图所示的程序框图,则输出的 x 不小于111的概率是 A.813 B.1728 C.23 D.18296.正四面体ABCD 中,E 、F 分别是棱BC 、AD 的中点,则直线DE 与平面BCF 所成角的正弦值为A.B .C.D7.在△ABC 中,A=60,若a,b,c 成等比数列,则sin b Bc= A.12 B .C.D .8.已知函数2,(0),()0x x f x x ⎧≤⎪=>.则1()f x dx -=A.123π- B . 123π+ C. 143π+ D . 143π- 9.设函数 1()cos()2f x x ωϕ=+对任意的 x R ∈,都有 ()()66f x f x ππ-=+,若函数()3sin()2g x x ωϕ=+-,则 ()6g π的值是A. 1 B . -5或3 C. -2 D . 1210.点 (,)M x y 在直线x+y-10=0上,且x ,y 满足 55x y -≤-≤,则围是A.⎡⎢⎣⎦ B .0,⎡⎣C. ⎡⎢⎣⎦ D .⎡⎢⎣⎦11.过双曲线 22221(0,0)x y a b a b-=>>的左焦点 (,0)(0)F c c ->,作圆 2224a x y +=的切线,切点为E ,延长FE 交双曲线右支于点P ,若 2OF OE OP =-,则双曲线的离心率为 A.B .5 C.2D .12.直线y=m 分别与曲线y=2x+3, ln y x x =+交于A ,B ,则 AB 的最小值为A. 3 B . 2 C.4D . 32第Ⅱ卷(非选择题,共90分)本卷包括必考题和选考题两部分.第13~21题为必考题,每个试题考生都必须作答.第22~24题为选考题,考生根据要求作答.二、填空题:本大题共4小题,每小题5分,共20分. 13.在 ∆ABC 中,若 31,32AB AC AB AC ==⋅=,则 ABC S ∆为_________。

广西省柳州市高三数学毕业班3月份模拟(梧州二模)考试试卷 理(扫描版)

广西省柳州市高三数学毕业班3月份模拟(梧州二模)考试试卷 理(扫描版)

广西省柳州市2015届高三数学毕业班3月份模拟(梧州二模)考试试卷理(扫描版)柳州市2015届高中毕业班3月份模拟考试题 理科数学参考答案4.C 【解析】当α⊥β,m ∥α时,有m ⊥β,m ∥β,m ⊆β等多种可能情况,所以①不正确;当m ∥α,n ∥β,且m ∥n 时,α∥β或α,β相交,所以④不正确,故选C.6.B 【解析】由正切函数y =tan x 的一个对称中心是⎝⎛⎭⎫k π2,0,k ∈Z ,由函数y =tan ωx ()ω∈N*的一个对称中心是⎝⎛⎭⎫π6,0,所以πω6=k π2(k ∈Z),因此ω=3k(k ∈Z),故ω的最小值为3.7.C 【解析】由题设,a1+a2+a3+…+a10=5(a1+a10)=5(a5+a6)=30所以a5+a6=6,又因为等差数列{an}各项都为正数,所以a5a6≤⎝⎛⎭⎫a5+a622=9, 当且仅当a5=a6=3时等号成立,所以a5·a6的最大值等于9,故选C. 8.A 【解析】P(AB)=323=38,P(A)=1-123=78,所以P(B |A )=P (AB )P (A )=37.10.C 【解析】由||a +b =||c ,得||a +b 2=||c 2,即a2+b2+2a·b =||c 2,又因为||a =||b =||c ,所以a·b =-||a 22=||a ||b cos 〈a ,b 〉,所以cos 〈a ,b 〉=-12,故〈a ,b 〉=2π3. 11.B 【解析】因为函数y =ex 与y =ln x 互为反函数,所以他们的函数图象关于直线y =x 对称,要使||PQ 最小,则必有P ,Q 两点的切线斜率和y =x 的斜率相等,对于曲线y =ln x ,令y′=1x =1,得x =1,故Q(1,0).同理,对于曲线y =ex ,令y′=ex =1,得x =0,所以P 点坐标为(0,1),综上,|PQ|最小值为1+1=2,选B.12.C 【解析】双曲线的左焦点F1(-c ,0),右焦点F2(c ,0),渐近线l1:y =ba x ,l2:y =-ba x ,因为点P 在第一象限内且在l1上,所以设P(x0,y0),x0>0,因为l2⊥PF1,l2∥PF2,所以PF1⊥PF2,即||OP =12||F1F2=c ,即x20+y20=c2,又y0=b a x0,代入得x20+⎝⎛⎭⎫b a x02=c2,解得x0=a ,y0=b ,即P(a ,b).所以kPF1=b a +c ,l2的斜率为-b a ,因为l2⊥PF1,所以b a +c ·⎝⎛⎭⎫-b a =-1,即b2=a ()a +c =a2+ac =c2-a2,所以c2-ac -2a2=0,所以e2-e -2=0,解得e =2,所以双曲线的离心率e =2,故选C.二、填空题 13.614.99 【解析】an =1n +1+n=n +1-n ,可得前n 项和Sn =a1+a2+a3+…+an =2-1+3-2+4-3+…+n +1-n =n +1-1,所以n +1-1=9,则n =99. 15.42 16.19π3【解析】由题意知正三棱柱底边长为2,高为1,则根据球的性质可得:R2=⎝⎛⎭⎫122+⎝⎛⎭⎫2sin 60°×232=14+⎝ ⎛⎭⎪⎫2332=1912,球的表面积S =4πR2=4π×1912=193π. 三、解答题 17.【解析】(1)甲公司员工A 投递快递件数的平均数为36,众数为33.2分 (2)设a 为乙公司员工B 投递件数,则当a =34时,X =136元,当a≥35时,X =35×4+(a -35)×7元, X 的可能取值为136,147,154,189,203.4分 X 的分布列为:E(X)=136×110+147×310+154×210+189×310+203×110=165.5(元).10分(3)根据图中数据,可估算甲公司被抽取员工该月收入4 860元,乙公司被抽取员工该月收入4 965元.12分18.【解析】(1)由sin C cos C =sin A +sin Bcos A +cos B 得,sin Ccos A +sin Ccos B =cos Csin A +cos Csin B ,即sin (C -A)=sin(B -C),所以C -A =B -C ,即2C =B +A ,得C =π3.6分 (2)由C =π3,可设A =π3-α,B =π3+α其中-π3<α<π3. 所以a2+b2=(2Rsin A)2+(2Rsin B)2=4(sin2A +sin2B),则: a2+b2=4⎝⎛⎭⎫1-cos 2A 2+1-cos 2B 2=4-2⎣⎡⎦⎤cos ⎝⎛⎭⎫2π3+2α+cos ⎝⎛⎭⎫2π3-2α=4+2cos 2α.由-π3<α<π3得-2π3<2α<2π3,所以-12<cos 2α≤1,所以3<a2+b2≤6. 故a2+b2的取值范围是(]3,6.12分19.【解析】(1)过C 作CE ∥AB 且CE =AB ,连BE ,PE.∵AC2+AB2=BC2,∴AC ⊥AB ,所以四边形ABEC 是矩形. 又AC ⊥CE ,PC ⊥AC ,∴AC ⊥面PEC ,所以∠PCE 是二面角P -AC -B 的平面角,∴∠PCE =60°. ∵PC =CE =4,∴△PCE 为正三角形. ∵BE ∥AC ,∴BE ⊥面PEC ,∴BE ⊥PE ,∴PB =PE2+BE2=5=BC.而H 是PC 的中点,∴BH ⊥PC ,∵G 、H 是△PAC 的中位线,∴GH ⊥PC , ∵GH ∩BH =H ,∴PC ⊥平面BGH.7分(2)以CE 的中点O 为坐标原点,建立如图所示的空间直角坐标系, 则A(3,-2,0),P(0,0,23),C(0,-2,0). 易求得面PAB 的法向量为n =(23,0,3), 而平面BGH 的法向量为PC →=(0,-2,-23), 所以||cos 〈n ,PC →〉=3714.故二面角P -BG -H 的余弦值是3714.12分20.【解析】(1)依题意有c =2,c a =63,可得a2=6,b2=2.所以所求椭圆的方程为x26+y22=1.4分(2)直线l 的方程为y =k(x -2).联立方程组⎩⎪⎨⎪⎧y =k (x -2),x26+y22=1.消去y 并整理得(3k2+1)x2-12k2x+12k2-6=0.设A(x1,y1),B(x2,y2),得x1+x2=12k23k2+1,x1x2=12k2-63k2+1,所以|AB|=1+k2|x1-x2|=26(k2+1)3k2+1.设AB 的中点M(x0,y0),得x0=6k23k2+1,y0=-2k 3k2+1.得直线MP 的斜率为-1k ,又xP =3,所以|MP|=1+1k2·|x0-xP|=k2+1k2·3(k2+1)(3k2+1).当△ABP 为正三角形时,|MP|=32|AB|,即k2+1k2·3(k2+1)(3k2+1)=32·26(k2+1)3k2+1.解得k =±1.即直线l 的方程为x -y -2=0或x +y -2=0.12分21.【解析】(1)若f(x)≤-1对定义域内的x 恒成立,则f(x)max ≤-1.于是f(1)+1=-a -a +1+1≤0⇒a ≥1.当a≥1时,f′(x)=-(ax +a -1)(x -1)x2=0⇒x =1,x =-1+1a .因为x =-1+1a ≤0,则当x ∈(0,1)时,f′(x)>0,故f(x)在(0,1)上单调递增, 当x ∈(1,+∞)时,f′(x)<0,故f(x)在(1,+∞)上单调递减, 则f(x)max =f(1)=1-2a≤-1,即f(x)≤-1恒成立. 故实数a 的取值范围为[)1,+∞.5分 (2)由(1)知,实数a 的取值范围为[)1,+∞.f(1+sin θ)-f(1-sin θ)=ln(1+sin θ)-a(1+sin θ)-a -11+sin θ-⎣⎢⎡⎦⎥⎤ln (1-sin θ)-a (1-sin θ)-a -11-sin θ=ln(1+sin θ)-ln(1-sin θ)-2asin θ-(a -1)⎣⎡⎦⎤11+sin θ-11-sin θ=ln(1+sin θ)-ln(1-sin θ)-2asin θ+2(a -1)sin θcos2θ=ln(1+sinθ)-ln(1-sin θ)-2asin θ⎝⎛⎭⎫1-1cos2θ-2sin θcos2θ=ln(1+sin θ)-ln(1-sin θ)+2asin3θcos2θ-2sin θcos2θ≥ln(1+sin θ)-ln(1-sin θ)+2sin3θcos2θ-2sin θcos2θ=ln(1+sin θ)-ln(1-sin θ)+2sin θcos2θ(sin2θ-1)=ln(1+sin θ)-ln(1-sin θ)-2sin θ. 令h(x)=ln(1+x)-ln(1-x)-2x(0≤x<1),则h ′(x)=11+x +11-x -2=21-x2-2≥2-2=0,∴h(x)在区间[0,1)上单调递增,∴h(x)≥h(0)=0.由题意知,sin θ∈[0,1),于是ln(1+sin θ)-ln(1-sin θ)-2sin θ≥0, ∴f(1+sin θ)≥f(1-sin θ).故对任意的θ∈⎣⎡⎭⎫0,π2,f(1-sin θ)≤f(1+sin θ)成立.12分22.【解析】(1)解:由A ,B ,C ,D 四点共圆,得∠CDE =∠ABE , 又∠DEC =∠BEA ,∴△ABE ∽△CDE ,于是AB CD =BE DE =AECE .① 设DE =a ,CE =b ,则由BE DE =AE CE ,得3b2=2a2,即b =23a代入①,得AB CD =3ba = 6.5分(2)证明:由EF ∥CD ,得∠AEF =∠CDE.∵∠CDE =∠ABE ,∴∠AEF =∠EBF.又∠BFE =∠EFA ,∴△BEF ∽△EAF ,于是FA FE =FEFB ,故FA ,FE ,FB 成等比数列.10分 23.【解析】(1)由曲线C :ρ2cos 2θ=ρ2(cos2θ-sin2θ)=1, 得x2-y2=1 ①5分(2)把直线参数方程化为标准参数方程得:⎩⎪⎨⎪⎧x =2+12ty =32t(t 为参数) ② 把②代入①得: ⎝⎛⎭⎫2+12t 2-⎝ ⎛⎭⎪⎫32t 2=1 整理,得t2-4t -6=0设其两根为t1,t2,则t1+t2=4,t1·t2=-68分从而弦长为|t1-t2|=(t1+t2)2-4t1t2=42-4(-6)=40=210.10分 24.【解析】(1)当a =4时,|2x +1|-|x -1|≤2, x<-12时,-x -2≤2,得-4≤x<-12 -12≤x ≤1时,3x≤2,得-12≤x ≤233分 x>1时,x≤0,此时x 不存在∴不等式的解集为⎩⎨⎧⎭⎬⎫x|-4≤x≤235分(2)设f(x)=|2x +1|-|x -1|=⎩⎨⎧-x -2,x<-123x ,-12≤x≤1x +2,x>1故f(x)∈⎣⎡⎭⎫-32,+∞,即f(x)的最小值为-328分故a≥2410分。

广西柳州市高三第二次模拟考试(理综).doc

广西柳州市高三第二次模拟考试(理综).doc

广西柳州市高三第二次模拟考试(理综)相对原子质量:H 1 C 12 N 14 O 16一.选择题(本题共13个小题,每小题6分.在每小题给出的四个选项中,只有一项是符合题目要求的)1、艾弗里等人的肺炎双球菌转化实验和赫尔希与蔡斯的噬菌体侵染细菌实验都证明了DNA是遗传物质。

这两个实验在设计思路上的共同点是:A、重组DNA片段,研究其表型效应B、诱发DNA突变,研究其表型效应C、设法把DNA与蛋白质分开,研究各自的效应D、应用同位素示踪技术,研究DNA在亲代与子代之间的传递2、下列有关神经兴奋的叙述,正确的是A、静息状态时神经元的细胞膜内外没有离子进出B、组织液中Na+浓度增大,则神经元的静息电位减小C、突触间隙中的神经递质经主动运输穿过突触后膜而传递兴奋D、神经纤维接受刺激产生的兴奋以电信号的形式传递3、下列关于哺乳动物胚胎发育和细胞工程的叙述,正确的是A、卵裂期胚胎中细胞数目和有机物总量在不断增加B、胚胎分割时需将原肠胚的细胞团均等分割C、胚胎干细胞具有细胞核大、核仁小和蛋白质合成旺盛等特点D、胚胎干细胞是一类未分化细胞,可从早期胚胎中分离获取4、地球上现有的生物有万种,其中只进行无性生殖种类的原始种类只占1~2%,而进行有性生殖的种类占绝对优势。

下列关于这一事实的叙述中,不正确的是:A、有性生殖提高了物种的变异性B、有性生殖大大加快了生物进化的步伐C、有性生殖形成合子,丰富了子代的遗传信息D、有性生殖出现在真核细胞起源之前5、下列有关哺乳动物体内三大营养物质代谢的叙述,错误的是A、用15N标记的苯丙氨酸饲喂小鼠后,在体内检测不到15N标记的酪氨酸B、当体内脂肪的分解速度加快时,意味着糖类的供应不足C、肝脏中的内质网的功能出现障碍,脂蛋白的合成受阻D、肝糖元和肌糖元去路的差异,与所在细胞功能密切相关6.下列说法中正确的是()①只有一种元素组成的物质,一定是纯净物;②所有酸性氧化物都是非金属氧化物;③硝酸和氢硫酸均既有氧化性又有还原性;④化学反应的实质就是旧化学键断裂、新化学键形成的过程。

广西柳州市2015届高三第三次模拟考试

广西柳州市2015届高三第三次模拟考试

广西柳州市2015届高三第三次模拟考试高三2010-05-05 20:41广西柳州市2015届高三第三次模拟考试(语文)第Ⅰ卷(选择题共30分)一、(12分,每小题3分)1.下列各组词语中,书写全都正确的一组是()A.稻杆协奏曲侯门如海运筹帷幄B.摇憾一幅画挑拨事非宴安鸩毒C.原委一炷香瓦釜雷鸣恍如隔世D.人材红朴朴横度长江绝代佳人2.下列各句中,加点的成语使用最恰当的一句是()A.老舍先生的《北京的春节》介绍了北京的春节习俗,文章描写细腻生动,结构清晰完整,语言简洁通俗,平易近人。

B.他的成功之路非常曲折,能取得今天的成绩至当不易。

C.中央电视台“对话”栏目,既有财经名流的高谈阔论,又有普通观众的对话交流,雅俗共赏,广受观众喜爱。

D.在女子短道速滑1500米决赛中,周洋以2分16秒的好成绩夺得冠军,并打破奥运会纪录,韩国选手只能望其项背,眼睁睁地看着冠军旁落。

3.下列句子中,没有语病的一项是()A.在市政府的帮助下,这群农民工终于在今年春节前向施工单位讨回了工资和利息两万多元,高高兴兴地回家过年去了。

B.日本丰田汽车公司由于产品质量问题,遭到来自消费者、媒体及业界的猛烈抨击,这家全球最大的汽车制造商因此陷入四面楚歌的境地。

C.人们或许会把托尔斯泰“随着岁月增长,我的生命越来越精神化了”的自述解释为衰老的征兆,但即使在老年时,他也比许多年轻人,甚至比所有的同龄人,更充满生命力。

D.要顺利完成防止经济增长由偏快转为过热,防止价格由结构性上涨演变为明显的通货膨胀,我们还有许多工作要做。

4.依次填入下列句后横线上的语句,顺序妥当的一项是()我爱小池,也爱溪流,是因为爱它们的“清”和“远”。

,像一位开朗的小伙、活泼的姑娘,唱着欢快的歌儿,踏着轻快的脚步,走出群山去迎接太阳和大海。

①各种颜色的小鱼穿行其间,历历可数。

②溪流蜿蜒,如一条银蛇③小池清澈见底,汪汪一碧,宛如一块温润的玉④时隐时现,游向远方⑤绿油油的水草在水底晃动A.②④⑤③① B.②④①③⑤ C.③①⑤④② D.③⑤①②④二、(9分,每小题3分)阅读下面的文章,完成5—7题。

广西柳州市高三语文毕业班3月份模拟(梧州二模)考试试卷(扫描版)

广西柳州市高三语文毕业班3月份模拟(梧州二模)考试试卷(扫描版)

广西柳州市2015届高三语文毕业班3月份模拟(梧州二模)考试试卷(扫描版)柳州市2015届高中毕业班3月份模拟考试题语文参考答案1.A(人类不可能参与、影响硅化木的形成过程,A项所述的“无字的天书”“大自然的秘密”,都不属于人类的“文化印记”。

)2.B(“就是松花石”太过绝对,原文是“很可能是松化石”。

)3.B(“‘一夕’和‘忽’则均属谬误”的说法太绝对。

硅化木的形成,既包含突变,也包含渐变,杜绾的说法,也有不少合理因素。

)4.A(贼,在句中是阴毒的意思。

)5.B6.B(“从不做坏事”不对,原文有“其阴贼著于心,卒发于睚眦如故云”;“受到广大群众仰慕”,文中无此表述,只有“少年慕其行”。

)7.(1)恰好有上天保佑,在危急中常常能摆脱出来,就像是犯法遇到了赦免。

(2)洛阳人有相互结仇的,城中有十几个贤人豪杰从中调解,两方面始终不听劝解。

8.动静结合。

(2分)“波上马嘶看棹去”写水上马在嘶叫,船在缓缓而行,是动态描写;“柳边人歇待船归”写柳树下人在歇息,等待船归,是静态描写。

一动一静,动静结合,描绘了一幅静中有动、充满情思的立体画面。

(3分)9.诗人触景生情,偶然兴起了欲学范蠡急流勇退、放浪江湖的愿望,(2分)表达了自己淡泊遗世,忘却机心的归隐之志。

(2分)同时,“独忘机”三字流露出了无人理会的失意、无奈之情。

(2分)10.(1)浊酒一杯家万里燕然未勒归无计(2)黄发垂髫并怡然自乐(3)黑云压城城欲摧甲光向日金鳞开11.(1)D、E(D.老于“自感寒碜”不准确,且文中说他谈文学是要“配得上这气氛和这气氛中的女市长”。

E.“直接批评了……脱离群众”过于牵强,文中的项副市长并非“目中无人”,也不能直接看出她“脱离群众”这一点。

)(2)运用了对比和白描的手法,展现了老于既自尊又自卑的矛盾心理,将物质困顿而精神充足的底层知识分子刻画得非常形象到位。

(2分)一方面,他带着妻女的期望,被逼无奈,来向项副市长提出请求;另一方面,他又试图通过谈论文学等来掩盖自己有求于人的目的。

2015年广西柳州市柳江县中考英语二模试卷(解析版)

2015年广西柳州市柳江县中考英语二模试卷(解析版)

2015年广西柳州市柳江县中考英语二模试卷一、听力(共16小题,满分30分)1.(4分)2.(1分)A.Nice to meet you,too.B.Goodbye,Tom.C.Thank you.3.(1分)A.It's blue.B.I'm fine,thanks.C.You're welcome.4.(1分)A.Yes,of course.B.It's a pen.C.It's D ﹣E﹣S﹣K.5.(1分)A.No,it isn't.B.Happy New Year!C.Good idea!6.(1分)A.It's mine.B.Good morning.C.I'm Lingling.7.(1分)A.Congratulations.B.What a pity.C.That's all right.8.(1分)What does Tom often have for breakfast?A.Some cakes.B.Some fish.C.Some noodles.9.(1分)Who might the man be?A.A doctor.B.A farmer.C.A worker.10.(1分)Which lesson is Jenny going to have tomorrow?A.English.B.Piano.C.Football.11.(1分)Whose bag is it?A.It's Jack's.B.It's Betty's.C.It's Tony's.12.(1分)How old is the woman?A.Two.B.Twelve.C.Twenty.13.(3分)听第一段长对话,回答第16至18小题.16.Where are they talking?A.In a book shop.B.In a restaurant.C.In a cloth shop.17.What does the woman want to drink?A.Orange juice.B.Water.C.Milk.18.What food can't the woman order?A.Tomato soup.B.Chicken.C.Apple pie.14.(3分)听第二段长对话,回答第19至21小题.19.Who is Tony talking to?A.Betty.B.Linda.C.Kate.20.What's the film about?A.Animals.B.Friendship.C.Sports.21.When will the film start?A.At 8 o'clock.B.At 7:30.C.At 9 o'clock.15.(4分)听第三段长对话,回答第22至25小题.22.How does Daming talk to Sara?A.By letter.B.By QQ.C.On the phone.23.What day is it today?A.Tuesday.B.Saturday.C.Friday.24.Where is Daming now?A.In New York.B.In Washington.C.In Beijing.25.What's the time in Beijing now?A.6 am.B.8 am.C.10 am.16.(5分)第四节语篇理解听一篇短文,根据短文内容选择正确答案.短文读三遍.26.Jim wanted to choose a sport to.A.keep fit B.relax C.spend time27.At first he joined.A.the swimming club B.the running club C.the climbing club 28.Jim didn't want to run because it was.A.expensive B.popular C.boring29.Once Jim hurt his badly when he went walking in the mountain.A.foot B.leg C.hand30.Jim thinks that walking in the mountains is a bit.A.popular B.dangerous C.boring.二、单项选择(本大题共15小题.每小题1分,共15分)从A、B、C三个选项中,选出最佳选项.17.(1分)Tony is ________ honest boy,we all like him.()A.a B.an C.the18.(1分)﹣Where ________ your teacher from?﹣Australia.()A.am B.is C.are19.(1分)﹣Would you like something to eat?﹣No,thanks.I'd like some tea ________milk.()A.with B.in C.for20.(1分)﹣Good morning,madam.Can I help you?﹣Sure,I'd like ________ for cooking vegetables.()A.one bowl of dumplings B.three pieces of breadC.five kilos of oil21.(1分)My teacher is a friend of _________.()A.mother's of Jim B.Jim mother'sC.Jim's mother's22.(1分)Our teacher often uses the Internet ________ he often sends emails.()A.or B.and C.but23.(1分)﹣Must I come before 7:00tomorrow?﹣No,you ________.()A.needn't B.mustn't C.couldn't24.(1分)I don't think he can read the new words so well,__________?()A.can he B.can't he C.do you25.(1分)All of us find __________ difficult to do the exercise.()A.this B.it C.that26.(1分)About __________ of my classmates in my class were born in 2000.()A.two third B.four fifthC.three fourths27.(1分)I always give my friends __________ to eat when they come to my home.()A.something delicious B.delicious nothingC.anything delicious28.(1分)People in this area ________ to leave because there is not enough water for them.()A.told B.was told C.were told29.(1分)He asks ________ we can help protect the environment.()A.how B.what C.that30.(1分)If you do all these other things instead of your homework,you _______ time to study.()A.didn't have B.don't have C.won't have31.(1分)You can never imagine the great difficulty I had ___________ her QQ number.()A.A.to get B.getting C.got三、完形填空(本大题共1小题.每小题10分,共10分)阅读下面短文,选择最佳的答案.32.(10分)Do you often smile?Do you like a smiling face?Smile is very(46).It is like a spring wind.It lets us feel warm in our (47).It is like the sunshine and it makes us (48)in our eyes.Smile is very important (49)our lives.When you are sad,make a big smile,and it can make you happy again.When you (50)worried,make a big smile,and it can help(51)keep cool again.When you aren't successful,make a big smile,and it can help you try again and (52)harder.Smile is very easy,(53)it is very useful.So let's learn to smile.Everyone (54)smiles.When we give others a smile,we can feel happy,too.When you see(55)smiling faces,you can feel warm.Let's smile every day.Don't you think so?46.A.nice B.sad C.hungry47.A.eyes B.hearts C.mouths48.A.bright B.beautiful C.brave49.A.under B.on C.in50.A.am B.is C.are51.A.I B.you C.he52.A.smile B.rain C.work53.A.but B.because C.or54.A.needs B.sees C.does55.A.the other's B.others'C.another's.四、阅读理解(本大题共4小题.56-70小题每小题5分,71-75小题每小题5分,共25分)33.(5分)Peter is in his first grade this year.He likes to play football and watch football matches.Now he is having lunch.He is listening to music,too.He is very happy because there is going to be a great football match on TV at four thisafternoon.He wants to watch it very much.But he is going to have his math and art lessons.He thinks hard and finds an idea."Hello,Mrs Black,"Peter says to his teacher on the telephone."Peter is ill in bed.He wants to ask for a half a day's leave.""Oh,I'm sorry to hear that,says Mrs Black."But who is that?""It's my father,Mrs Black."根据短文内容判断正误,正确的在括号内填A,错误的在括号内填B.56.Peter is in Grade One this year.57.Now Peter is having lunch.58.Peter doesn't have lessons this afternoon.59.Mrs Black is Peter's teacher.60.Peter's father told Mrs Black that Peter was ill in bed..34.(5分)Most children like watching TV.It's very interesting.By watching TV they can see and learn a lot and know many things about their country and the world.Of course,they can also learn over the radio.But they can learn better and more easily with TV.Why?Because they can hear and watch at the same time.But they can't see anything over the radio.TV helps to open children's eyes.TV helps to open their minds(智力),too.They learn newer and better ways of doing things.They may find the world is now smaller than before.Many children watch TV only on Saturday or Sunday evening.They are always busy with their lessons.But a few children watch TV every night.They go to bed very late.They can't have a good rest.How about you and your friends?61.Children like watching TV because it's.A.interestingB.boringC.exciting62.Children can't see anything.A.on TVB.on the radioC.on the computer63.TV helps to open children's.A.eyesB.mindsC.eyes and minds64.Many children watch TV only.A.every dayB.on MondayC.on Saturday or Sunday evening65.From the passage we can guess the writer thinks.A.it's bad for children to watch TVB.it's good for children to watch TVC.listening to radio is not useful for learning.35.(5分)Welcome to My Restaurant根据表格信息,选择正确答案.66.There are kinds of drinks in the restaurant.A.3B.4C.567.If you want to buy a sandwich and a glass of juice,you must pay.A.7.50B.5.00C.2.5068.The most expensive thing on the menu is.A.PizzaB.CokeC.Ice cream69.The restaurant isn't open on.A.Children's DayB.New Year's DayC.Christmas Day70.The restaurant is open at in the morning.A.8:00amB.9:00amC.11:00pm.36.(10分)Most mobile phone companies design(设计)models especially for children.But parents are usually the ones buying the phones,and paying the phones.According to a study,56% of parents of children aged 8 to 12 have given their children a mobile phone.Most children get their first mobile phone at the age of 12.Many parents think it's necessary for children to have a mobile phone because it helps children stay in touch with their friends and families.They believe that mobile phones are an important tool when something happens suddenly.Children can stay connected with their parents at all times.Some people think mobile phones help teach children to be responsible.But other people are worried about the health and safety of children's mobile phones.They believe that sending messages while doing homework is bad forchildren's concentration(注意力).They say that children are spending too much time sending messages instead of talking to each other.But we do need to communicate face to face.Also,the radiation(辐射)that the mobile phones give off can be harmful to young people.What do you think?If you have any idea about it,please tell me.根据短文内容,选择正确答案.71.According to the passage,most children got their first mobile phone.A.at the age of 12B.at the age of 10C.at the age of 872.Many parents think it's necessary for children to have a mobile because.A.it's cheaper than beforeB.it helps children stay in touch with their friends and familiesC.it's a great birthday present73.When something happens suddenly,mobile phones are to stay touch with others.A.a useful languageB.an important toolC.a different way74.The underline word"responsible"means""in Chinese.A.负责任的B.乐于助人的C.尊重人的75.Which is NOT TRUE according to this passage?A.Some especial mobile phones are designed for children.B.Some people think that sending messages while doing homework is a bad habit.C.56% of children aged 8to 12paid for their mobile phones.五、口语运用(本大题共1小题.每小题10分,共10分)根据以下对话内容,从对应的方框中的六个选项中选出五个合适的句子补全对话,请将句子的字母标号填写在答题卡对应的横线上.37.(10分)A:Hi,Tony!B:(76)A:Where are you now?B:(77)A:What are you doing?B:(78)A:Do you like your trip to China?B:(79)A:How about your friends?B:They are having a good time,too.A:(80)B:Next Monday.A:OK,see you then.A.Yes,I do.B.I am fine,thanks.C.Hi,Dad.D.When will you go back home?E.I am on the Great Wall.F.I am taking photos.六、综合填空(本大题共5小题.每小题1分,共10分)A.单词拼写:根据句子意思及所给的中文提示完成单词,并将完整的单词填写在答题卡对应的横线上.每空只能填一词.38.(1分)Three and(六)is nine.39.(1分)The girl's(名字)is Linda.40.(1分)The students will have a lot of(空闲的)time.41.(1分)Our city needs better(公共的)services.42.(1分)His aunt is a(秘书)in a big company.B.选词填空:根据短文内容,从方框中选择恰当的单词完成句子,并填写在答题卡对应的横线上.所有单词在填入前不需进行词形转换,每个单词只能用一次,每空只能写一词.43.(5分)I want to go on a trip with my(86)in the summer holiday,but I do not think we will agree on where to go.I think that we should go to the beach but Mum and Dad say they want to go to the countryside.Danny is sure that the beach and the countryside (87)boring.He wants to go to a(88)city and do sightseeing.Milly doesn't think that sightseeing is interesting.She wants to stay at home and(89)TV or go swimming.I tell my family that(90)have to decide soon because the holiday starts next week!七、句子翻译(本大题共5小题,每小题l分,共5分)根据中文意思完成句子,并将答案填写在答题卡对应的横线上.每空词数不限.44.(1分)我早上七点起床.I at seven in the morning.45.(1分)起初他没有注意我.He didn't notice me.46.(1分)柳州非常值得游览.Liuzhou is well.47.(1分)足球比赛已经开始大约有20分钟了.The football match for about twenty minutes.48.(1分)如果时间再多一些,我将能做地更好.If more time,I will do it better.八、书面表达(本大题共15分)49.(15分)目前柳州正在争创全国文明城市,作为一个中学生,我们应该积极参与这件有意义的事.请你根据以下的内容提示,写一篇80词左右的短文.参考词汇:尊敬(respect),长辈(elders),礼貌的(polite),遵守交规(obey the traffic rules),闯红灯(go across the streets when the traffic lights are red),斑马线(the zebra crossing),保护(protect),到处(everywhere),无烟学校(a smokeless school)要求:1.短文中请勿使用真实姓名、地点或所在学校名称.=.短文要包含所给的提示信息,可适当发挥.3.短文开头与结尾已为你写好,字数不计入总数.Liuzhou is now making its effort to become a national civilized city.As students,what should we do?Liuzhou is our hometown.Let's try our best to make it a civilized city.2015年广西柳州市柳江县中考英语二模试卷参考答案与试题解析一、听力(共16小题,满分30分)1.(4分)【解答】略2.(1分)A.Nice to meet you,too.B.Goodbye,Tom.C.Thank you.【解答】略3.(1分)A.It's blue.B.I'm fine,thanks.C.You're welcome.【解答】略4.(1分)A.Yes,of course.B.It's a pen.C.It's D ﹣E﹣S﹣K.【解答】略5.(1分)A.No,it isn't.B.Happy New Year!C.Good idea!【解答】略6.(1分)A.It's mine.B.Good morning.C.I'm Lingling.【解答】略7.(1分)A.Congratulations.B.What a pity.C.That's all right.【解答】略8.(1分)What does Tom often have for breakfast?A.Some cakes.B.Some fish.C.Some noodles.【解答】略9.(1分)Who might the man be?A.A doctor.B.A farmer.C.A worker.【解答】略10.(1分)Which lesson is Jenny going to have tomorrow?A.English.B.Piano.C.Football.【解答】略11.(1分)Whose bag is it?A.It's Jack's.B.It's Betty's.C.It's Tony's.【解答】略12.(1分)How old is the woman?A.Two.B.Twelve.C.Twenty.【解答】略13.(3分)听第一段长对话,回答第16至18小题.16.Where are they talking?A.In a book shop.B.In a restaurant.C.In a cloth shop.17.What does the woman want to drink?A.Orange juice.B.Water.C.Milk.18.What food can't the woman order?A.Tomato soup.B.Chicken.C.Apple pie.【解答】略14.(3分)听第二段长对话,回答第19至21小题.19.Who is Tony talking to?A.Betty.B.Linda.C.Kate.20.What's the film about?A.Animals.B.Friendship.C.Sports.21.When will the film start?A.At 8 o'clock.B.At 7:30.C.At 9 o'clock.【解答】略15.(4分)听第三段长对话,回答第22至25小题.22.How does Daming talk to Sara?A.By letter.B.By QQ.C.On the phone.23.What day is it today?A.Tuesday.B.Saturday.C.Friday.24.Where is Daming now?A.In New York.B.In Washington.C.In Beijing.25.What's the time in Beijing now?A.6 am.B.8 am.C.10 am.【解答】略16.(5分)第四节语篇理解听一篇短文,根据短文内容选择正确答案.短文读三遍.26.Jim wanted to choose a sport to略.A.keep fit B.relax C.spend time27.At first he joined略.A.the swimming club B.the running club C.the climbing club 28.Jim didn't want to run because it was略.A.expensive B.popular C.boring29.Once Jim hurt his略badly when he went walking in the mountain.A.foot B.leg C.hand30.Jim thinks that walking in the mountains is a bit略.A.popular B.dangerous C.boring.【解答】略二、单项选择(本大题共15小题.每小题1分,共15分)从A、B、C三个选项中,选出最佳选项.17.(1分)Tony is ________ honest boy,we all like him.()A.a B.an C.the【解答】答案:B.用a还是用an一般说来,在辅音因素开头的词前用a,而在元音音素开头的词前用an.注意:有些以辅音字母开头的单词,由于第一个音素不是辅音而是元音,其前用an;根据题干Tony is ________ honest boy,we all like him托尼是一个诚实的男孩,表泛指."一个诚实的男孩"中honest读音是以元音音素开头,应用冠词an;故选B.18.(1分)﹣Where ________ your teacher from?﹣Australia.()A.am B.is C.are【解答】答案:B.根据Where ________ your teacher from?可知你老师来自哪儿?be from是"来自…"句子的主语your teacher 是单数;故选B.19.(1分)﹣Would you like something to eat?﹣No,thanks.I'd like some tea ________milk.()A.with B.in C.for【解答】答案:A.with作为介词表示有,具有,带有;in 作为介词表示在什么里;for 作为介词表示为什么,根据句意,此处应该是有,具有,带有,故选A.20.(1分)﹣Good morning,madam.Can I help you?﹣Sure,I'd like ________ for cooking vegetables.()A.one bowl of dumplings B.three pieces of breadC.five kilos of oil【解答】答案:C 根据for cooking vegetables,可知此人需要的是烹饪蔬菜的用品.A为一碗水饺;B为三片面包;C为5公斤油.故选C.21.(1分)My teacher is a friend of _________.()A.mother's of Jim B.Jim mother'sC.Jim's mother's【解答】答案:C.考点:名词所有格.在名词所有格的其中一项规则中是双重所有格,是有…of…构成;"吉姆的妈妈的…"是Jim′s mother′s;故选C.22.(1分)Our teacher often uses the Internet ________ he often sends emails.()A.or B.and C.but【解答】答案:B此题考查连词词意.选项A:或者,表选择关系;选项B:和、又,表并列关系;选项C:但是、而,表转折关系.根据题干"Our teacher often uses the Internet"(我们的老师经常使用网络)与"he often sends emails"(他经常发送邮件)之间为并列关系,故选C.23.(1分)﹣Must I come before 7:00tomorrow?﹣No,you ________.()A.needn't B.mustn't C.couldn't【解答】答案:A.根据Must I come before 7:00tomorrow,可知这里考查了must引导的一般疑问句,must 表必须时,引导的一般疑问句,否定回答用needn't,表不必.故选:A.24.(1分)I don't think he can read the new words so well,__________?()A.can he B.can't he C.do you【解答】答案:A.含有think,believe,suppose,imagine,expect等表示主语主观意愿的词后接宾语从句构成的主从复合句在构成反意疑问句时,当主句的主语为第一人称时,其后的简短问句应与从句相一致.并且当这些动词后接的宾语从句的否定转移到主句时,其仍属否定句,故其后的简短问句应用肯定式,而非否定式.因此用can he,选A25.(1分)All of us find __________ difficult to do the exercise.()A.this B.it C.that【解答】答案B 根据find…difficult to do the exercise可知句子的真正的宾语是to do the exercise,可知所填代词it在句子中作形式宾语,为固定用法,this和that 没有这种用法,故答案选B.26.(1分)About __________ of my classmates in my class were born in 2000.()A.two third B.four fifthC.three fourths【解答】答案:C.在分数的表达法中,分子用基数词,分母用序数词;当分子大于一时,分母加s;题干里About __________ of my classmates in my class were born in 2000.在我班里大约有四分之三的同学们在2000年出生的.故选C.27.(1分)I always give my friends __________ to eat when they come to my home.()A.something delicious B.delicious nothingC.anything delicious【解答】答案为A.本题主要考察不定代词与形容词的位置关系.something"某物,某事",用于肯定句;nothing"没有东西",本身表示否定;anything"任何东西",用于否定句或问句中;不定代词+形容词;本题的题干为肯定句;由以上条件可用直接法,选A.28.(1分)People in this area ________ to leave because there is not enough water for them.()A.told B.was told C.were told【解答】答案:C 根据People in this area ________ to leave,可知这句话的主语是People,是动作的承受着,和动词told构成被动系,应该用被动语态,故排除A答案.一般过去时的被动语态的构成:was/were+及物动词的过去分词.根据句意和下文there is not enough water for them.可知主语people是复数,故选:C.29.(1分)He asks ________ we can help protect the environment.()A.how B.what C.that【解答】答案为A. A how 怎么样,具体询问方式 B what 什么,具体询问的对象具体内容,C that 用作关系代词,引导限制性定语从句,先行词可人可物.句子是属于复合句,需要一个疑问词做宾语从句的连接词,表怎么样做,因为文中提到怎么样做才能保护环境,故how这一词符合题意,故答案为A.30.(1分)If you do all these other things instead of your homework,you _______ time to study.()A.didn't have B.don't have C.won't have【解答】答案为C.if引导的条件状语从句.if 意为"如果",引导条件状语从句时,表示假如有从句的动作发生就(不)会有主句的动作发生.if引导的条件状语从句,时态应该遵循主将从现,就是说主句用一般将来时,而从句用一般现在时表示将来.从句"If you do all these other things instead of your homework"用了一般现在时,故句子的主句要用将来时,故答案为C.31.(1分)You can never imagine the great difficulty I had ___________ her QQ number.()A.A.to get B.getting C.got【解答】答案:B.根据You can never imagine the great difficulty I had ___________ her QQ number.你根本想不到我获得她的QQ号有多困难;此题是考查"做某事有困难",其英语表达是have difficulty doing sth,句中I had作he great difficulty 的定语,故选B.三、完形填空(本大题共1小题.每小题10分,共10分)阅读下面短文,选择最佳的答案.32.(10分)Do you often smile?Do you like a smiling face?Smile is very(46)A.It is like a spring wind.It lets us feel warm in our (47)B.It is like the sunshine and it makes us (48)A in our eyes.Smile is very important (49)C our lives.When you are sad,make a big smile,and it can make you happy again.When you (50)C worried,make a big smile,and it can help(51)B keep cool again.When you aren't successful,make a big smile,and it can help you try again and (52)C harder.Smile is very easy,(53)A it is very useful.So let's learn to smile.Everyone (54)A smiles.When we give others a smile,we can feel happy,too.When you see(55)B smiling faces,you can feel warm.Let's smile every day.Don't you think so?46.A.nice B.sad C.hungry47.A.eyes B.hearts C.mouths48.A.bright B.beautiful C.brave49.A.under B.on C.in50.A.am B.is C.are51.A.I B.you C.he52.A.smile B.rain C.work53.A.but B.because C.or54.A.needs B.sees C.does55.A.the other's B.others'C.another's.【解答】46.A 考查形容词辨析.A表示不错的;B表示伤心的;C表示饿的.由It is like a spring wind可知描述的是微笑是不错的,选A.47.B 考查名词辨析.A表示眼睛;B表示心;C表示嘴.结合语境可知此处表示它让我们心中觉得温暖(微笑的作用),选B.48.A 考查形容词辨析.A表示明亮的;B表示漂亮的;C表示勇敢的.由It is like the sunshine的sunshine可知此处表示它使我们的眼神明亮,选A.49.C 考查介词辨析.A表示在…下;B表示在…上;C表示在…里.in one's life 表示在某人的生活中,此处表示微笑在我们的生活中很重要,选C.50.C 考查be动词.A是be动词的单数形式,用于主语为I时;B是be动词的第三人称单数形式;C是be动词的复数形式.此处的主语you是第二人称单数或复数,be动词要用are.51.B 考查代词辨析.A表示我;B表示你,你们;C表示他.此句的主语是you,所以句意为它可以帮助你再次保持酷酷的,选B.52.C 考查动词辨析.A表示微笑;B表示下雨;C表示工作.由When you aren't successful,make a big smile和help you try again可推测此处表示更加的努力工作,选C.53.A 考查连词辨析.A表示但是;B表示因为;C表示否则.Smile is very easy 与it is very useful是转折关系,选A.54.A 考查动词辨析.A表示需要;B表示看见;C表示做.由When we give othersa smile,we can feel happy,too可知此处表示每个人都需要微笑,选A.55.B 考查不定代词.A表示特指的其他人或事物的;B表示其他人或事物的;C表示三者及以上的另一个的.此处表示当你看见别人的笑脸,此处没有特指,选B.四、阅读理解(本大题共4小题.56-70小题每小题5分,71-75小题每小题5分,共25分)33.(5分)Peter is in his first grade this year.He likes to play football and watch football matches.Now he is having lunch.He is listening to music,too.He is very happy because there is going to be a great football match on TV at four this afternoon.He wants to watch it very much.But he is going to have his math and art lessons.He thinks hard and finds an idea."Hello,Mrs Black,"Peter says to his teacher on the telephone."Peter is ill in bed.He wants to ask for a half a day's leave.""Oh,I'm sorry to hear that,says Mrs Black."But who is that?""It's my father,Mrs Black."根据短文内容判断正误,正确的在括号内填A,错误的在括号内填B.56.Peter is in Grade One this year.A57.Now Peter is having lunch.A58.Peter doesn't have lessons this afternoon.B59.Mrs Black is Peter's teacher.A60.Peter's father told Mrs Black that Peter was ill in bed.B.【解答】试题分析:这篇文章讲述了一名中学生,他非常喜欢足球,今天下午有一场足球赛,所以他假装是自己的爸爸给老师打电话想请假看足球赛.56.A 细节理解题.根据Peter is in his first grade this year.可知,彼得今年上一年级.故选A.57.A 细节理解题.根据Now he is having lunch.可知现在彼得正在吃午饭.故选A.58.B 细节理解题.根据But he is going to have his math and art lessons.可知今下午彼得有数学和美术课.故选B.59.A 细节理解题.根据"Hello,Mrs Black,"Peter says to his teacher on the telephone.可知布莱克夫人是彼得的老师.故选A.60.B 综合理解题.根据It's my father,Mrs Black并结合全文可知是彼得假装是爸爸给老师打的电话.故选B.34.(5分)Most children like watching TV.It's very interesting.By watching TV they can see and learn a lot and know many things about their country and the world.Of course,they can also learn over the radio.But they can learn better and more easily with TV.Why?Because they can hear and watch at the same time.But they can't see anything over the radio.TV helps to open children's eyes.TV helps to open their minds(智力),too.They learn newer and better ways of doing things.They may find the world is now smaller than before.Many children watch TV only on Saturday or Sunday evening.They are always busy with their lessons.But a few children watch TV every night.They go to bed very late.They can't have a good rest.How about you and your friends?61.Children like watching TV because it's A.A.interestingB.boringC.exciting62.Children can't see anything B.A.on TVB.on the radioC.on the computer63.TV helps to open children's C.A.eyesB.mindsC.eyes and minds64.Many children watch TV only C.A.every dayB.on MondayC.on Saturday or Sunday evening65.From the passage we can guess the writer thinks B.A.it's bad for children to watch TVB.it's good for children to watch TVC.listening to radio is not useful for learning.【解答】答案:61.A 细节理解题.根据Most children like watching TV.It's very interesting.大多数孩子喜欢看电视,这是非常有趣的.可知孩子们喜欢看电视因为是有趣的.故选A.62.B 细节理解题.根据But they can't see anything over the radio.但他们不能看到任何东西在收音机.可知孩子们不能看到任何东西在收音机.故选B.63.C 细节理解题.根据TV helps to open children's eyes.TV helps to open their minds(智力),too.电视有助于打开孩子的眼界.电视也有助于开发他们的智力.可知电视可以打开孩子眼界和开发智力.故选C.64.C 细节理解题.根据Many children watch TV only on Saturday or Sunday evening.许多孩子只在星期六或星期日晚上看电视.可知孩子只能在星期六或星期日晚上看电视.故选C.65.B 主旨归纳题.根据整篇文章内容及其句子By watching TV they can see and learn a lot and know many things about their country and the world.通过看电视,他们可以看到和学到有关他们国家和世界的很多事情.TV helps to open children's eyes.TV helps to open their minds(智力),too.电视有助于打开孩子的眼界.电视也有助于开发他们的智力.可知作者认为看电视对孩子有好处.故选B.35.(5分)Welcome to My Restaurant根据表格信息,选择正确答案.66.There are B kinds of drinks in the restaurant.A.3B.4C.567.If you want to buy a sandwich and a glass of juice,you must pay A.A.7.50B.5.00C.2.5068.The most expensive thing on the menu is A.A.PizzaB.CokeC.Ice cream69.The restaurant isn't open on C.A.Children's DayB.New Year's DayC.Christmas Day70.The restaurant is open at B in the morning.A.8:00amB.9:00amC.11:00pm.【解答】66.B细节理解题.根据drinks一栏可知有果汁,可乐,咖啡,牛奶4种饮料,故选B.67.A细节理解题.根据Sandwich 5.00dollars;Juice 2.50dollars可知要一个三明治和一杯果汁一共7.5元,故选A.68.A细节理解题.根据表格中的价格Pizza 12.00dollars可知披萨是最贵的,每个12元,故选A.69.C细节理解题.根据We're closed on Christmas Day.可知这个店在圣诞节是不营业的,故选C.70.B细节理解题.根据We're open every day from 9:00am to 10:00pm.可知这个店在上午9点开门,故选B.36.(10分)Most mobile phone companies design(设计)models especially for children.But parents are usually the ones buying the phones,and paying the phones.According to a study,56% of parents of children aged 8 to 12 have given their children a mobile phone.Most children get their first mobile phone at the age of 12.Many parents think it's necessary for children to have a mobile phone because it helps children stay in touch with their friends and families.They believe that mobile phones are an important tool when something happens suddenly.Children can stay connected with their parents at all times.Some people think mobile phones help teach children to be responsible.But other people are worried about the health and safety of children's mobile phones.They believe that sending messages while doing homework is bad for children's concentration(注意力).They say that children are spending too much time sending messages instead of talking to each other.But we do need to communicate face to face.Also,the radiation(辐射)that the mobile phones give off can be harmful to young people.What do you think?If you have any idea about it,please tell me.根据短文内容,选择正确答案.71.According to the passage,most children got their first mobile phone A.A.at the age of 12B.at the age of 10C.at the age of 872.Many parents think it's necessary for children to have a mobile because B.A.it's cheaper than beforeB.it helps children stay in touch with their friends and familiesC.it's a great birthday present73.When something happens suddenly,mobile phones are B to stay touch with others.A.a useful languageB.an important toolC.a different way74.The underline word"responsible"means"A"in Chinese.A.负责任的B.乐于助人的C.尊重人的75.Which is NOT TRUE according to this passage?CA.Some especial mobile phones are designed for children.B.Some people think that sending messages while doing homework is a bad habit.C.56% of children aged 8to 12paid for their mobile phones.【解答】答案:71.A 细节理解题.根据第一段第二行句子Most children get their first mobile phone at the age of 12.大多数孩子在12岁时得到了自己的第一个手机.故选A.72.B 细节理解题.根据第二段第一行句子Many parents think it's necessary for children to have a mobile phone because it helps children stay in touch with their friends and families.许多家长认为孩子有手机是很必要的因为它可以帮助孩子们和他们的朋友和家庭联系.可知家长认为孩子有手机可以和家人朋友联系.故选B.73.B 细节理解题.根据第二段第一二行句子They believe that mobile phones are an important tool when something happens suddenly.他们认为当事情突然发生的时候,手机是一个重要的工具.故选B.74.A 词义猜测题.根据第二段第二行句子Children can stay connected with their parents at all times.Some people think mobile phones help teach children to be responsible.孩子们可以在任何时候与父母联系.有些人认为手机帮助教孩子成为负责任的人.这里responsible是负责任的意思.故选A.75.C 细节理解题.根据第一段第一行句子According to a study,56% of parents of children aged 8 to 12 have given their children a mobile phone.根据一项研究,56%的8到12岁孩子的父母给他们的孩子手机.而不是这些孩子自己付钱买的.所以C不正确.故选C.五、口语运用(本大题共1小题.每小题10分,共10分)根据以下对话内容,从对应的方框中的六个选项中选出五个合适的句子补全对话,请将句子的字母标号填写在答题卡对应的横线上.37.(10分)A:Hi,Tony!B:(76)CA:Where are you now?B:(77)EA:What are you doing?B:(78)FA:Do you like your trip to China?B:(79)AA:How about your friends?B:They are having a good time,too.A:(80)DB:Next Monday.A:OK,see you then.A.Yes,I do.B.I am fine,thanks.C.Hi,Dad.D.When will you go back home?E.I am on the Great Wall.F.I am taking photos.【解答】76:C此处考查日常交际用语,根据"Hi,Tony!"可知,此处的回答也为"Hi",故答案为C.Hi,Dad.77:E根据"Where are you now?"可知,此处的回答应为他们在哪儿,故答案为E.I am on the Great Wall.78:F根据"What are you doing?"可知,此处的回答应为他们现在正在干什么,故答案为F.I am taking photos.79:A根据"They are having a good time,too."中的"too"可知,儿子在中国也玩得很开心,所以他应该喜欢他的中国之旅,故此处应为肯定回答,答案为A.Yes,I do.80:D根据"Next Monday."可知,此处为询问他什么时候回来,故答案为D.When will you go back home?六、综合填空(本大题共5小题.每小题1分,共10分)A.单词拼写:根据句子意思及所给的中文提示完成单词,并将完整的单词填写在答题卡对应的横线上.每空只能填一词.38.(1分)Three and six(六)is nine.【解答】答案:six 根据题干Three and____(六)is nine.结合提示,可知:三加六是九.六,基数词,six.故填:six.39.(1分)The girl's name(名字)is Linda.【解答】答案:name 根据题干The girl's____(名字)is Linda.结合提示,可知:这个女孩的名字叫Linda.名字,name,名词.根据The girl's,可知是这一个女孩的,应该用单数,故填:name.。

广西柳州二中2015届上学期高三第一次月考试题语文

广西柳州二中2015届上学期高三第一次月考试题语文

广西柳州二中2015届上学期高三第一次月考试题语文高三2011-09-16 12:01广西柳州二中2015届上学期高三第一次月考试题语文第Ⅰ卷(选择题,共30分)一、(12分,每小题3分)1.下列词语中,划线的字读音全都正确的一组是()A.绚(xuàn)丽丰腴(yú)倩(qiàn)影乳臭(chîu)未干B.赦(shâ)免嗜(shì)好逡(qūn)巡弱不禁(jīn)风C.游说(shuì)愤懑(mân)逶迤(yí)不见经传(chuán)D.泅(qiú)渡坍圮(pǐ)恐吓(xià) 否(pǐ)极泰来2.下列各句中,划线的成语使用恰当的一句是()A.司机张师傅冒着生命危险解救乘客的事迹,一经新闻媒体报道,就被传得满城风雨,感动了无数市民。

B.近年来,在种种灾害面前,各级政府防患未然,及时启动应急预案,力争把人民的生命财产损失降到最低限度。

C.这些“环保老人”利用晨练的机会,将游客丢弃在景点的垃圾信手拈来,集中带到山下,分类处理。

D.“生命的价值在于厚度而不在于长度,在于奉献而不在于获取……”院士的一番话入木三分,让我们深受教育。

3.下列各句中,没有语病的一句是()A.曹操的性格具有双重性,他的雄才大略与奸诈凶狠对于任何一个扮演他的演员来说都具有挑战性,也是个难得的表演机会。

B .我国计划在2011年向太空发射目标飞行器“天宫一号”的实验,这一消息引起世界各国极大关注,被全球各大媒体争相报道。

C.尽管作为欧盟成员国的希腊经济总量有限,其债务危机不足以使美国经济受到直接冲击,但是仍然会间接影响美国经济的复苏进程。

D.灾后重建三年目标任务两年基本完成的原因:一是十八个对口援建省市支援的结果,二是灾区干部群众自力更生所取得的成绩。

4.依次填入下面一段文字横线处的语句,衔接最恰当的一组是()在21世纪的今天,正确对待任何大自然的关系比以往任何时候都重要。

2015年广西柳州市柳江县中考数学二模试卷(解析版)

2015年广西柳州市柳江县中考数学二模试卷(解析版)

2015年广西柳州市柳江县中考数学二模试卷一、选择题(本大题共12小题,每小题3分,满分36分.在每个小题给出的四个选项中,只有一项是正确的,每小题选对得3分,错选、不选或多选均得0分)1.(3分)下列实数中,最大的是()A.﹣1B.﹣2C.﹣D.﹣2.(3分)计算(2a2)3的结果是()A.2a6B.6a6C.8a6D.8a53.(3分)将6.18×10﹣3化为小数的是()A.0.618B.0.0618C.0.00618D.0.000618 4.(3分)下列四个几何体中,俯视图为四边形的是()A.B.C.D.5.(3分)一次函数y=kx+k(k<0)的图象大致是()A.B.C.D.6.(3分)如图,△ABC中,∠A=90°,点D在AC边上,DE∥BC,若∠1=35°,则∠B的度数为()A.25°B.35°C.55°D.65°7.(3分)不等式组的整数解共有()A.1个B.2个C.3 个D.4个8.(3分)若反比例函数的图象经过点(﹣2,3),则该反比例函数图象一定经过点()A.(2,﹣3)B.(﹣2,﹣3)C.(2,3)D.(﹣1,﹣6)9.(3分)某地为了缓解旱情进行了一场人工降雨,现测得6个面积相等区域的降雨量如下表所示:则这6个区域降雨量的众数和平均数分别为()A.13,13.8B.14,15C.13,14D.14,14.5 10.(3分)如图,菱形ABCD中,对角线AC、BD相交于点O,H为AD边中点,菱形ABCD 的周长为28,则OH的长等于()A.3.5B.4C.7D.1411.(3分)如图,某人站在楼顶观测对面的笔直的旗杆AB.已知观测点C到旗杆的距离CE=8m,测得旗杆的顶部A的仰角∠ECA=30°,旗杆底部B的俯角∠ECB=45°,那么,旗杆AB的高度是()A.(+8)m B.(8+8)m C.(8+)m D.(8+)m 12.(3分)如图,在平面直角坐标系中,⊙M与y轴相切于原点O,平行于x轴的直线交⊙M于P,Q两点,点P在点Q的右方,若点P的坐标是(﹣1,2),则点Q的坐标是()A.(﹣4,2)B.(﹣4.5,2)C.(﹣5,2)D.(﹣5.5,2)二、填空题(本大题共6小题,每小题3分,满分18分.请将答案直接填写在答题卡中相应的横线上,在草稿纸、试卷上答题无效)13.(3分)计算:=.14.(3分)若二次根式是最简二次根式,则最小的正整数a=.15.(3分)一元二次方程2x2﹣3x﹣5=0的两个实数根分别为x1、x2,则x1+x2的值为.16.(3分)袋中有4个红球,x个黄球,从中任摸一个恰为黄球的概率为,则x的值为.17.(3分)如图,在矩形ABCD中,DE⊥AC于点E,AB=12,AC=20,则cos∠ADE=.18.(3分)如图,菱形ABCD的边长为2,∠ADC=120°,弧CD是以点B为圆心BC长为半径的弧.则图中阴影部分的面积为(结果保留π).三、解答题(本大题8分,满分66分.解答应写出必要的文字说明、演算步骤或推理过程.请将写在答题卡中相应的区域内,画图或作辅助线时使用铅笔画出,确定后必须使用黑色字迹的签字笔描黑.在草稿纸、试卷上答题无效)19.(6分)=.20.(6分)化简:.21.(6分)在边长为1的小正方形网格中,△AOB的顶点均在格点上,(1)B点关于y轴的对称点坐标为;(2)将△AOB向左平移3个单位长度得到△A1O1B1,请画出△A1O1B1;(3)在(2)的条件下,A1的坐标为.22.(8分)已知:如图,在平行四边形ABCD中,O为对角线BD的中点,过点O的直线EF分别交AD,BC于E,F两点,连结BE,DF.(1)求证:OE=OF.(2)当∠DOE等于度时,四边形BFDE为菱形.(直接填写答案即可)23.(8分)学校为统筹安排大课间体育活动,在各班随机选取了一部分学生,分成四类活动:“篮球”、“羽毛球”、“乒乓球”、“其他”进行调查,整理收集到的数据,绘制成如下的两幅统计图.(1)学校采用的调查方式是;学校在各班随机选取了名学生;(2)补全统计图中的数据:羽毛球人、乒乓球人、其他人、其他%;(3)该校共有1100名学生,请估计喜欢“篮球”的学生人数.24.(10分)某电器超市销售每台进价分别为200元,170元的A、B联众型号的电风扇,表中是近两周的销售情况:(进价、售价均保持不变,利润=销售收入﹣进货成本)(1)求A、B两种型号的电风扇的销售单价;(2)若超市准备用不多于5400元的金额再采购这两种型号的电风扇共30台,求A种型号的电风扇最多能采购多少台?(3)在(2)的条件下,超市销售完这30台电风扇能否实现利润为1400元的目标?若能,请给出相应的采购方案;若不能,请说明理由.25.(10分)如图,AB是⊙O的直径,点C是⊙O上一点,AD与过点C的切线垂直,垂足为点D,直线DC与AB的延长线相交于点P,弦CE平分∠ACB,交AB点F,连接BE.(1)求证:AC平分∠DAB;(2)求证:PC=PF;(3)若tan∠ABC=,AB=14,求线段PC的长.26.(12分)如图,抛物线y=﹣x2+bx+c与x轴交于点A(﹣1,0),B(5,0)两点,直线y=﹣x+3与y轴交于点C,与x轴交于点D.点P是x轴上方的抛物线上一动点,过点P作PF⊥x轴于点F,交直线CD于点E.设点P的横坐标为m.(1)求抛物线的解析式;(2)若PE=5EF,求m的值;(3)若点E′是点E关于直线PC的对称点,是否存在点P,使点E′落在y轴上?若存在,请直接写出相应的点P的坐标;若不存在,请说明理由.2015年广西柳州市柳江县中考数学二模试卷参考答案与试题解析一、选择题(本大题共12小题,每小题3分,满分36分.在每个小题给出的四个选项中,只有一项是正确的,每小题选对得3分,错选、不选或多选均得0分)1.(3分)下列实数中,最大的是()A.﹣1B.﹣2C.﹣D.﹣【解答】解:∵﹣2<﹣<﹣<﹣1,∴四个实数中,最大的实数是﹣1.故选:A.2.(3分)计算(2a2)3的结果是()A.2a6B.6a6C.8a6D.8a5【解答】解:(2a2)3=8a6.故选:C.3.(3分)将6.18×10﹣3化为小数的是()A.0.618B.0.0618C.0.00618D.0.000618【解答】解:把数据“6.18×10﹣3中6.18的小数点向左移动3位就可以得到为0.00618.故选:C.4.(3分)下列四个几何体中,俯视图为四边形的是()A.B.C.D.【解答】解:A、三棱锥的俯视图是,故此选项错误;B、六棱柱的俯视图是六边形,故此选项错误;C、正方体俯视图是正方形,故此选项正确;D、圆锥的俯视图是有圆心的圆,故此选项错误,5.(3分)一次函数y=kx+k(k<0)的图象大致是()A.B.C.D.【解答】解:∵一次函数y=kx+k(k<0),∴函数的图象经过二、三、四象限,故选:D.6.(3分)如图,△ABC中,∠A=90°,点D在AC边上,DE∥BC,若∠1=35°,则∠B的度数为()A.25°B.35°C.55°D.65°【解答】解:∵DE∥BC,∠1=35°,∴∠C=∠1=35°.∵∠A=90°,∴∠B=90°﹣35°=55°.故选:C.7.(3分)不等式组的整数解共有()A.1个B.2个C.3 个D.4个【解答】解:,解①得,x≥3,解②得,x<5,∴不等式组的解集为:3≤x<5,整数解有3,4.8.(3分)若反比例函数的图象经过点(﹣2,3),则该反比例函数图象一定经过点()A.(2,﹣3)B.(﹣2,﹣3)C.(2,3)D.(﹣1,﹣6)【解答】解:设反比例函数的解析式为:y=,反比例函数的图象经过点(﹣2,3),∴k=﹣6,即解析式为y=﹣,A、满足;B、不满足;C、不满足;D、不满足,故选:A.9.(3分)某地为了缓解旱情进行了一场人工降雨,现测得6个面积相等区域的降雨量如下表所示:则这6个区域降雨量的众数和平均数分别为()A.13,13.8B.14,15C.13,14D.14,14.5【解答】解:数据13出现了2次,出现的次数最多,则众数是13(mm);平均降水量=(14+12+13+13+17+15)=14(mm).则这6个区域降雨量的众数和平均数分别为13,14;故选:C.10.(3分)如图,菱形ABCD中,对角线AC、BD相交于点O,H为AD边中点,菱形ABCD 的周长为28,则OH的长等于()A.3.5B.4C.7D.14【解答】解:∵菱形ABCD的周长为28,∴AB=28÷4=7,OB=OD,∵H为AD边中点,∴OH是△ABD的中位线,∴OH=AB=×7=3.5.故选:A.11.(3分)如图,某人站在楼顶观测对面的笔直的旗杆AB.已知观测点C到旗杆的距离CE=8m,测得旗杆的顶部A的仰角∠ECA=30°,旗杆底部B的俯角∠ECB=45°,那么,旗杆AB的高度是()A.(+8)m B.(8+8)m C.(8+)m D.(8+)m 【解答】解:在△EBC中,有BE=EC×tan45°=8,在△AEC中,有AE=EC×tan30°=,∴AB=8+(米).故选:D.12.(3分)如图,在平面直角坐标系中,⊙M与y轴相切于原点O,平行于x轴的直线交⊙M于P,Q两点,点P在点Q的右方,若点P的坐标是(﹣1,2),则点Q的坐标是()A.(﹣4,2)B.(﹣4.5,2)C.(﹣5,2)D.(﹣5.5,2)【解答】解:∵⊙M与y轴相切于原点O,平行于x轴的直线交⊙M于P,Q两点,点P在点Q的右方,点P的坐标是(﹣1,2)∴点Q的纵坐标是2设PQ=2x,作MA⊥PQ,利用垂径定理可知QA=P A=x,连接MP,则MP=MO=x+1,在Rt△AMP中,MA2+AP2=MP2∴22+x2=(x+1)2∴x=1.5∴PQ=3,Q的横坐标=﹣(1+3)=﹣4∴Q(﹣4,2)故选:A.二、填空题(本大题共6小题,每小题3分,满分18分.请将答案直接填写在答题卡中相应的横线上,在草稿纸、试卷上答题无效)13.(3分)计算:=3.【解答】解:原式===3.故填3.14.(3分)若二次根式是最简二次根式,则最小的正整数a=2.【解答】解:二次根式是最简二次根式,则最小的正整数a=2,故答案为:2.15.(3分)一元二次方程2x2﹣3x﹣5=0的两个实数根分别为x1、x2,则x1+x2的值为.【解答】解:∵一元二次方程x2﹣5x+2=0的两个实数根分别为x1和x2,∴x1+x2=.故答案为:.16.(3分)袋中有4个红球,x个黄球,从中任摸一个恰为黄球的概率为,则x的值为12.【解答】解:设袋中有x个黄球,根据题意得=,解得x=12.故答案为:12.17.(3分)如图,在矩形ABCD中,DE⊥AC于点E,AB=12,AC=20,则cos∠ADE=.【解答】解:∵四边形ABCD是矩形,∴CD=AB=12,∠ADC=90°,∴∠ADE+∠CDE=90°,∵DE⊥AC于E,∴∠DEC=90°,∴∠ACD+∠CDE=90°,∴∠ADE=∠ACD,∴cos∠ADE=cos∠ACD===;故答案为:.18.(3分)如图,菱形ABCD的边长为2,∠ADC=120°,弧CD是以点B为圆心BC长为半径的弧.则图中阴影部分的面积为(结果保留π).【解答】解:∵菱形ABCD的边长为2,∠ADC=120°,∴∠BDC=∠DBC=60°,∴△DBC是等边三角形,∴BD=BC=2,∴图中阴影部分的面积为:=.故答案为:.三、解答题(本大题8分,满分66分.解答应写出必要的文字说明、演算步骤或推理过程.请将写在答题卡中相应的区域内,画图或作辅助线时使用铅笔画出,确定后必须使用黑色字迹的签字笔描黑.在草稿纸、试卷上答题无效)19.(6分)=.【解答】解:方程两边同时乘以2x(x+3)得,x+3=4x,整理得,3x=3,解得x=1,把x=1代入2x(x+3)得,2x(x+3)=8,故x=1是原分式方程的解.20.(6分)化简:.【解答】解:原式=…(4分)=…(4分)=.…(2分)21.(6分)在边长为1的小正方形网格中,△AOB的顶点均在格点上,(1)B点关于y轴的对称点坐标为(﹣3,2);(2)将△AOB向左平移3个单位长度得到△A1O1B1,请画出△A1O1B1;(3)在(2)的条件下,A1的坐标为(﹣2,3).【解答】解:(1)B点关于y轴的对称点坐标为(﹣3,2);(2)△A1O1B1如图所示;(3)A1的坐标为(﹣2,3).故答案为:(1)(﹣3,2);(3)(﹣2,3).22.(8分)已知:如图,在平行四边形ABCD中,O为对角线BD的中点,过点O的直线EF分别交AD,BC于E,F两点,连结BE,DF.(1)求证:OE=OF.(2)当∠DOE等于90度时,四边形BFDE为菱形.(直接填写答案即可)【解答】(1)证明:∵四边形ABCD是平行四边形,O为对角线BD的中点,∴BO=DO,AD∥BC∴∠EDB=∠FBO,在△EOD和△FOB中,∴△DOE≌△BOF(ASA),∴OE=OF;(2)解:当∠DOE=90°时,四边形BFDE为菱形.23.(8分)学校为统筹安排大课间体育活动,在各班随机选取了一部分学生,分成四类活动:“篮球”、“羽毛球”、“乒乓球”、“其他”进行调查,整理收集到的数据,绘制成如下的两幅统计图.(1)学校采用的调查方式是抽样调查;学校在各班随机选取了100名学生;(2)补全统计图中的数据:羽毛球21人、乒乓球18人、其他25人、其他25%;(3)该校共有1100名学生,请估计喜欢“篮球”的学生人数.【解答】解:(1)学校采用的调查方式是抽样调查;由题意可得:喜欢篮球的人数为:36人,所占比例为:36%,所以学校在各班随机选取了学生:36÷36%=100(名);(2)喜欢羽毛球人数为:100×21%=21(人),喜欢乒乓球人数为:100×18%=18(人),其他所占百分比为:1﹣36%﹣21%﹣18%=25%,喜欢其它人数为:100×25%=25(人),如图所示:(3)根据题意得:36%×1100=396,即估计喜欢“篮球”的学生人数为396人.故答案为:(1)抽样调查;100;(2)21,18,25,25.24.(10分)某电器超市销售每台进价分别为200元,170元的A、B联众型号的电风扇,表中是近两周的销售情况:(进价、售价均保持不变,利润=销售收入﹣进货成本)(1)求A、B两种型号的电风扇的销售单价;(2)若超市准备用不多于5400元的金额再采购这两种型号的电风扇共30台,求A种型号的电风扇最多能采购多少台?(3)在(2)的条件下,超市销售完这30台电风扇能否实现利润为1400元的目标?若能,请给出相应的采购方案;若不能,请说明理由.【解答】解:(1)设A、B两种型号电风扇的销售单价分别为x元、y元,依题意得:,解得:,答:A、B两种型号电风扇的销售单价分别为250元、210元;(2)设采购A种型号电风扇a台,则采购B种型号电风扇(30﹣a)台.依题意得:200a+170(30﹣a)≤5400,解得:a≤10.答:超市最多采购A种型号电风扇10台时,采购金额不多于5400元;(3)依题意有:(250﹣200)a+(210﹣170)(30﹣a)=1400,解得:a=20,∵a≤10,∴在(2)的条件下超市不能实现利润1400元的目标.25.(10分)如图,AB是⊙O的直径,点C是⊙O上一点,AD与过点C的切线垂直,垂足为点D,直线DC与AB的延长线相交于点P,弦CE平分∠ACB,交AB点F,连接BE.(1)求证:AC平分∠DAB;(2)求证:PC=PF;(3)若tan∠ABC=,AB=14,求线段PC的长.【解答】(1)证明:∵PD切⊙O于点C,∴OC⊥PD,又∵AD⊥PD,∴OC∥AD,∴∠ACO=∠DAC.∵OC=OA,∴∠ACO=∠CAO,∴∠DAC=∠CAO,即AC平分∠DAB;(2)证明:∵AD⊥PD,∴∠DAC+∠ACD=90°.又∵AB为⊙O的直径,∴∠ACB=90°.∴∠PCB+∠ACD=90°,∴∠DAC=∠PCB.又∵∠DAC=∠CAO,∴∠CAO=∠PCB.∵CE平分∠ACB,∴∠ACF=∠BCF,∴∠CAO+∠ACF=∠PCB+∠BCF,∴∠PFC=∠PCF,∴PC=PF;(3)解:∵∠P AC=∠PCB,∠P=∠P,∴△P AC∽△PCB,∴.又∵tan∠ABC=,∴,∴,设PC=4k,PB=3k,则在Rt△POC中,PO=3k+7,OC=7,∵PC2+OC2=OP2,∴(4k)2+72=(3k+7)2,∴k=6 (k=0不合题意,舍去).∴PC=4k=4×6=24.26.(12分)如图,抛物线y=﹣x2+bx+c与x轴交于点A(﹣1,0),B(5,0)两点,直线y=﹣x+3与y轴交于点C,与x轴交于点D.点P是x轴上方的抛物线上一动点,过点P作PF⊥x轴于点F,交直线CD于点E.设点P的横坐标为m.(1)求抛物线的解析式;(2)若PE=5EF,求m的值;(3)若点E′是点E关于直线PC的对称点,是否存在点P,使点E′落在y轴上?若存在,请直接写出相应的点P的坐标;若不存在,请说明理由.【解答】方法一:解:(1)将点A、B坐标代入抛物线解析式,得:,解得,∴抛物线的解析式为:y=﹣x2+4x+5.(2)∵点P的横坐标为m,∴P(m,﹣m2+4m+5),E(m,﹣m+3),F(m,0).∴PE=|y P﹣y E|=|(﹣m2+4m+5)﹣(﹣m+3)|=|﹣m2+m+2|,EF=|y E﹣y F|=|(﹣m+3)﹣0|=|﹣m+3|.由题意,PE=5EF,即:|﹣m2+m+2|=5|﹣m+3|=|m+15|①若﹣m2+m+2=m+15,整理得:2m2﹣17m+26=0,解得:m=2或m=;②若﹣m2+m+2=﹣(m+15),整理得:m2﹣m﹣17=0,解得:m=或m=.由题意,m的取值范围为:﹣1<m<5,故m=、m=这两个解均舍去.∴m=2或m=.(3)假设存在.作出示意图如下:∵点E、E′关于直线PC对称,∴∠1=∠2,CE=CE′,PE=PE′.∵PE平行于y轴,∴∠1=∠3,∴∠2=∠3,∴PE=CE,∴PE=CE=PE′=CE′,即四边形PECE′是菱形.当四边形PECE′是菱形存在时,由直线CD解析式y=﹣x+3,可得OD=4,OC=3,由勾股定理得CD=5.过点E作EM∥x轴,交y轴于点M,易得△CEM∽△CDO,∴,即,解得CE=|m|,∴PE=CE=|m|,又由(2)可知:PE=|﹣m2+m+2|∴|﹣m2+m+2|=|m|.①若﹣m2+m+2=m,整理得:2m2﹣7m﹣4=0,解得m=4或m=﹣;②若﹣m2+m+2=﹣m,整理得:m2﹣6m﹣2=0,解得m1=3+,m2=3﹣.由题意,m的取值范围为:﹣1<m<5,故m=3+这个解舍去.当四边形PECE′是菱形这一条件不存在时,此时P点横坐标为0,E,C,E'三点重合与y轴上,也符合题意,∴P(0,5)综上所述,存在满足条件的点P,可求得点P坐标为(0,5),(﹣,),(4,5),(3﹣,2﹣3)方法二:(1)略.(2)略.(3)若E(不与C重合时)关于直线PC的对称点E′在y轴上,则直线CD与直线CE′关于PC轴对称.∴点D关于直线PC的对称点D′也在y轴上,∴DD′⊥CP,∵y=﹣x+3,∴D(4,0),CD=5,∵OC=3,∴OD′=8或OD′=2,①当OD′=8时,D′(0,8),设P(t,﹣t2+4t+5),D(4,0),C(0,3),∵PC⊥DD′,∴K PC×K DD′=﹣1,∴,∴2t2﹣7t﹣4=0,∴t1=4,t2=﹣,②当OD′=2时,D′(0,﹣2),设P(t,﹣t2+4t+5),∵PC⊥DD′,∴K PC×K DD′=﹣1,∴=﹣1,∴t1=3+,t2=3﹣,∵点P是x轴上方的抛物线上一动点,∴﹣1<t<5,∴点P的坐标为(﹣,),(4,5),(3﹣,2﹣3).若点E与C重合时,P(0,5)也符合题意.综上所述,存在满足条件的点P,可求得点P坐标为(0,5),(﹣,),(4,5),(3﹣,2﹣3)。

广西柳州市高三文综毕业班3月份模拟(梧州二模)考试试卷(扫描版)

广西柳州市高三文综毕业班3月份模拟(梧州二模)考试试卷(扫描版)

广西柳州市2015届高三文综毕业班3月份模拟(梧州二模)考试试卷(扫描版)文科综合参考答案第页柳州市2015届高中毕业班3月份模拟考试题文科综合参考答案一、选择题(本大题共35小题,每小题4分,共计140分。

每小题列出的四个选项中,只有一项符合题意。

)1.A。

【解析】结合轮廓与经纬度位置可以判断出该地为北欧地区(丹麦),M地纬度高,气候冷湿,适合乳畜业,N地纬度较M地低,气候温和为商品谷物农业。

2.C。

【解析】丹麦是发达国家,农业科技水平高。

3.D。

【解析】图中海拔最高处(图中右上角)为300~330米,最低处(图中左下角)为60~90米,其相对高度为210~270米之间。

4.A。

【解析】①处为瀑布强力侵蚀而形成的深潭;②处地势较低应以沉积为主;③、④在山脊处属于分水线。

5.C。

【解析】根据图中年等降水量线分布可知,该流域南部降水多,北部降水少,在同一条纬线上,西部降水多,东部降水少,即图示区域年降水量由西南向东北递减,所以C正确。

6.B。

【解析】从图中可以看出,马更些河上游源地有3 000m以上的高山,且该流域所处纬度高,年降水量基本在400mm以下,因此该河流应以冰雪融水补给为主;因纬度高,气侯寒冷,冬季漫长,结冰期长;该河含沙量小;该河流总体上由低纬流向高纬,而且结冰期长,所以有明显的凌汛。

所以B正确。

7.D。

【解析】图中甲点位于北极圈上,夏至日日出时地方时为0:00,甲位于西经130°经线上,北京时间为东经120°地方时,故此时北京时间为16时40分。

8.D。

【解析】该产业应市场需求而生。

9.B。

【解析】该产品的时效性强,只有通过电子商务平台及现代物流业的快速直达运送才能使消费者在6小时内顺利地获取产品。

10.B。

【解析】华北由于人口稠密,降水变率大,蒸发旺盛,缺水严重,所以不适合水田。

11.D。

【解析】表中ab两个数据分别表示初与末的数值。

两者之差最大,就表示变化最大。

广西柳州市高三英语毕业班3月份模拟(梧州二模)考试试卷(扫描版)

广西柳州市高三英语毕业班3月份模拟(梧州二模)考试试卷(扫描版)

广西柳州市2015届高三英语毕业班3月份模拟(梧州二模)考试试卷(扫描版)柳州市2015届高中毕业班3月份模拟考试题英语听力材料及参考答案听力材料Text 1M:Hey,Mary. I’m here.W:Oh,hi!I’m sorry I’m late. The car couldn’t start,and it was rather difficult to take a taxi,so I had to come by subway in the end.Text 2W:I’m looking for the nearest post office. Can you help me?M:Yes. Drive down Sesame Street and turn left when you see Moon Bridge to Broadway. Go on driving until you get to Rose Square. You will see it easily there.Text 3M:Excuse me. Has the plane from New York arrived yet?W:I’m sorry,sir. It’s delayed because of the storm. When it arrives,we’ll let you know.Text 4M:Let’s have a break. We have been working for a long time.W:Not a good idea. The boss asked us to finish the report before six.M:Come on. It won’t take a long time to have a drink. The computer needs rest,too.Text 5W:Do you let people know when you are taking pictures of them?M:I try not to. You know any picture of a person who poses for the camera would look dull and unnatural.Text 6M:Hello,Sara,do you have any plans for the weekend?W:Oh,I plan to work on my paper on Saturday. What’s up?M:Well,we’re going to have a picnic this weekend. Would you like to join us?W:Thank you. But I can only spare an afternoon.M:What do you mean?W:I have to go help my uncle on Sunday morning—he opened a bookstore several days ago. Text 7M:Are you watching a movie on your iPad?W:No,it’s a television show. I watched Season 1 and 2 last week. Now I’m watc hing Season 3. M:Are you enjoying it?W:Season 2 was great. So far,Season 3 isn’t as good. But I heard Season 4 is the best.M:Well,I prefer watching music videos on Youku. Television shows take up too much time. Text 8W:Hello,a friend told me that you have dance classes here.M:That’s right.W:Can you give me some information about the days and times?M:Yes,there are 3 classes a day from Monday to Saturday. Nothing on Sunday.W:Oh,I see.M:The first one is from 8:30 to 9:30,the next from 10:00 to 11:00,and there is only one in the afternoon from 2:30 to 3:30.W:Right. I know when I can come since I’m only free in the afternoon.Text 9M:Good afternoon,Madam. What can I do for you?W:I’d like a table for one,please.M:This way,please. Here is the menu.W:Thank you. Which dishes would you recommend?M:How about today’s specials?We have a wonderful tomato soup to start off with. The main course is fish and chips.W:Alright. I’d like the fish and chips.M:Would you like a salad?We have a number of different salads,such as green salad,Greek salad and so on.W:I’d like a green salad.M:Well. Would you like something to drink?Coca Cola or beer?W:Oh,no,some mineral water,please.M:OK. The total cost is $50. And we can give you a ten percent discount today.W:That’s great. Thank you.M:Enjoy your lunch.Text 10Don’t forget to get ready for the Christmas festival!Everyone is invited to attend,and your friends and family are welcome,too. We will need some members to help prepare for our yearly event. Please sign up on the sheet of paper by the door if you can help with anything. The list of things to be done includes:buying food,cooking the dinner,making decorations,and cleaning up after the party. We could use at least five people for each of these activities. Also,please give as much money for the festival as you can,so we can buy all the things we need to make this a great event. If every member here today gives twenty dollars,we should have enough. Remember that the money for the Christmas festival does not come out of our normal membership fees.One more thing,each adult who comes to the party must bring a separate gift for a child. This year,as usual,we will be giving the presents to children who have no parents. If you need ideas,just ask Mark at the back of the room.参考答案1-5.CBABA6-10.ACCAB11-15.CACAC16-20.BACBA21. D。

广西柳州市高三地理高考二模试卷

广西柳州市高三地理高考二模试卷

广西柳州市高三地理高考二模试卷姓名:________ 班级:________ 成绩:________一、单选题 (共5题;共20分)1. (4分) (2015高二上·响水期中) 以下材料是20世纪下半叶我国强沙尘暴发生频率与土地沙化速度统计表,表中显示我国的土地沙化速度在不断加快,其原因可能是()时间50年代60年代70年代80年代90年代强沙尘暴次数58131423土地沙化速度(平方千米/年)156021002460A . 西北干旱地区生态环境的进一步恶化B . 南方北回归线附近地区出现沙化C . 长江中上游地区毁林现象严重D . 华北地区土地盐碱化面积扩大2. (6分) (2019高二上·蚌埠期中) 下图示意某地降水量逐月累计曲线和最热月与各月平均气温差曲线。

读下图,完成下面小题。

(1)该地冬季气候特点是()A . 温和多雨B . 高温多雨C . 寒冷干燥D . 寒冷少雨(2)该地最有可能位于()A . 悉尼B . 上海C . 纽约D . 开普敦3. (2分)在水循环中,海洋水进入陆地上空大气中所通过的环节是()A . 径流输送B . 植物蒸腾C . 降水D . 水汽输送4. (4分) (2019高一下·遵义月考) (2008年高考江苏卷)下图为“我国1990一2007年某城市各区人口密度变化示意图”。

读图回答下列小题。

(1)④区土地利用类型应为()A . 商业用地B . 工业用地C . 政府机关用地D . 居住用地(2)下列关于该城市发展的叙述正确的是()A . 该城市总人口明显减少B . ③区商业服务等级最高、种类最多C . K滨河带适宜建开放式公园D . 高新技术产业区应建在①区5. (4分) (2017高一下·山东期末) 决定下列农业区位选择的主导因素分别是()①长江的双季稻种植②河套平原的粮棉种植③新疆哈密盆地的瓜果生产④成都郊区的乳畜业A . ①热量②水源③光照④市场B . ①水源②地形③热量④市场C . ①地形②国家政策③土壤④科技D . ①土壤②热量③地形④国家政策二、综合题 (共4题;共45分)6. (20分)(2019·定远模拟) 阅读材料,完成下列问题。

广西梧州市中考数学二模试题(含解析)

广西梧州市中考数学二模试题(含解析)

广西梧州市2015届中考数学二模试题一、选择题(本大题共12小题,每小题3分,共36分.在每小题给出的四个选项中,只有一项是正确的,每小题选对得3分,选错、不选或多选均得零分.)1.=()A.2 B.﹣2 C.D.﹣2.计算:3x+2x=()A.5 B.5x C.6x2D.5x23.在直角坐标中,有一点A(1,﹣3),点A的坐标在第几象限()A.第一象限 B.第二象限 C.第三象限 D.第四象限4.在直角坐标系中,反比例函数的图象不经过以下的点是()A.(2,3) B.(﹣1,﹣3) C.(﹣3,﹣1) D.(4,)5.在数据分析的过程中,有人对两个不同城市学生的数学成绩进行了分析,结果发现这两座城市统计的方差值都是10.34,那么下列说法中,正确的是()A.两城市学生的成绩一样B.两城市学生的数学平均分一样C.两城市数学成绩的中位数一样D.两城市学生数学成绩波动情况一样6.如图,在下面的立方体中,它的主视图是()A.B.C.D.7.如图,已知:直线a、b被AB所截,交点分别是点A、B,其中a∥b,∠1=72°,点D是线段AB 上一点,CD=BD.则∠2=()A.72° B.36° C.64° D.56°8.如图,在▱ABCD中,过A点作高,垂足刚好为点C,AC=2,∠B=30°,则▱ABCD的周长是()A.B.C.8 D.49.二次函数y=ax2+bx+c的图象如图所示,则在下列说法中,与此函数的系数相关的一元二次方程ax2+bx+c=0的根的情况,说法正确的是()A.方程有两个相等的实数根B.方程的实数根的积为负数C.方程有两个正的实数根 D.方程没有实数根10.有A、B两个黑色袋子,A袋装有3个黑球、2个白球,B袋装有黑、白两个球,这些球除颜色外,其它一样.在随机抽球中,如果从A袋取一个球,再从B袋取一个球,那么得到两个都是黑球的概率是()A.B.C.D.11.如图,AB是⊙O的直径,它与弦CD交于点E.我们给出下列结论:①AE•BE=CE•DE;②△ADE∽△CBE;③∠A=∠C;④∠AED=∠BEC这些结论中正确的是()A.①②③④ B.①②③C.②③ D.②③④12.如图,将Rt△ABC以直角顶点C为旋转中心顺时针旋转,使点A刚好落在AB上(即:点A′),若∠A=55°,则图中∠1=()A.110°B.102°C.105°D.125°二、填空题(本大题共6小题,每小题3分,共18分.)13.计算:2= .14.分解因式:2x2﹣8= .15.不等式组的解集是.16.如图所示,⊙O的半径是5,它的弦AB=8,OC⊥AB交AB于点D,则CD= .17.如图,在反比例函数图象上有点A(a,1),过点A作y轴的平行线交某直线于点B,已知△AOB的面积是8,则直线OB的解析式为.18.观察下列关于自然数的等式:第1个式子:32﹣4×12=5;第2个式子:52﹣4×22=9;第3个式子:72﹣4×32=13;…根据上述规律请你写出第2015个式子的计算结果:.三、解答题(本大题共8小题,满分66分.)19.先化简,再求值:x2(x﹣1)﹣x(x2+x﹣1),其中x=﹣1.20.今年两会期间,“全民阅读”被再次写进《政府工作报告》,成为社会热词.在第20个世界读书日来临之际,我市某中学为了解本校学生每周课外阅读时间t(单位:小时),采用随机抽样的方法进行问卷调查,调查结果按0≤t<0.5,0.5≤t<1,1≤t<2,2≤t分为四个等级,分别用A、B、C、D表示,并绘制成了两幅不完整的统计图,由图中给出的信息回答下列问题:(1)填空:A等级的百分率是%;B等级的百分率是%;(2)将不完整的条形统计图补充完整;(3)若该校共有学生2400人,试估计每周课外阅读时间量满足t≥1的人数.21.如图,在Rt△ABC中,∠C=90°,以点C为圆心作⊙C,与AB切于点D,过点A、B分别作⊙C 的切线AF、BE,切点为F、E点.求证:AF∥BE.22.如图,阳光下斜坡旁有一棵树AB,它的阴影投在斜坡上为AC=10米,斜坡与平面形成的坡角∠DAC=15°,光线与斜坡形成的∠BCA=75°.求树AB的高度(精确到0.1米)参考数据:sin15°≈0.26,cos15°≈0.97,tan15°≈0.27,≈1.73.23.A地至B地的航线长9750km,一架飞机从A地顺风飞往B地需12.5h,它逆风飞行同样的航线需13h,求飞机无风时的平均速度与风速.24.为对荒山进行改造,政府投资13万元给某村民小组用于购买与种植A、B两种树苗共3000棵.完成这项种植后,剩余的款项作为村民小组的纯收入.已知用160元购买A树苗比购买B树苗多3棵.这两种树苗的单价、成活率及移栽费用见下表:树苗品种A树苗B树苗购买价格(元/棵)a a+12树苗成活率90% 95%移栽费用(元/棵)3 5(1)求表中a的值;(2)设购买A树苗x棵,其它购买的是B树苗,把这些树苗种植完成后,村民小组获得的纯收入为y元,请你写出y与x之间的函数关系式;(3)若要求这批树苗种植后,成活率达到94%以上(包含94%),则最多种植A树苗多少棵?此时,村民小组在这项工作中,所得的纯收入最大值可以是多少元?25.如图,在正方形ABCD中,延长对角线CA到点E,以AE为边作正方形AEFG,连接BG、DE.(1)求证:△ABG≌△ADE;(2)当AB=,AG=3时,求线段BG的长度.26.如图,抛物线y=ax2+bx+4与坐标轴交于A、B、C三点,直线y=x+4与坐标轴交于B、C点,其中点A(4,0).(1)求此抛物线的解析式;(2)在线段AC、BC上分别取点P、Q,使CP=CQ,连接PQ,以PQ为对称轴对折,点C刚好落在抛物线的C′上,求点C′的坐标;(3)连接AB,在抛物线上是否存在点M,使得∠MBA+∠CBO=45°?若存在,请直接写出适合此条件的点M的坐标;若不存在,请说明理由.2015年广西梧州市中考数学二模试卷参考答案与试题解析一、选择题(本大题共12小题,每小题3分,共36分.在每小题给出的四个选项中,只有一项是正确的,每小题选对得3分,选错、不选或多选均得零分.)1.=()A.2 B.﹣2 C.D.﹣【考点】实数的性质.【分析】根据负数的绝对值是它的相反数,可得答案.【解答】解:|﹣|=,故C正确.故选:C.【点评】本题考查了实数的性质,负数的绝对值是它的相反数,零的绝对值是零,正数的绝对值是它本身.2.计算:3x+2x=()A.5 B.5x C.6x2D.5x2【考点】合并同类项.【分析】根据合并同类项的法则:把同类项的系数相加,所得结果作为系数,字母和字母的指数不变作答.【解答】解:3x+2x=(3+2)x=5x.故选B.【点评】本题考查同类项的定义,合并同类项时把系数相加减,字母与字母的指数不变.3.在直角坐标中,有一点A(1,﹣3),点A的坐标在第几象限()A.第一象限 B.第二象限 C.第三象限 D.第四象限【考点】点的坐标.【分析】根据第四象限内点的横坐标大于零,纵坐标小于零,可得答案.【解答】解:A(1,﹣3),点A的坐标在第四象限,故选:D.【点评】本题考查了各象限内点的坐标的符号特征以及解不等式,记住各象限内点的坐标的符号是解决的关键,四个象限的符号特点分别是:第一象限(+,+);第二象限(﹣,+);第三象限(﹣,﹣);第四象限(+,﹣).4.在直角坐标系中,反比例函数的图象不经过以下的点是()A.(2,3) B.(﹣1,﹣3) C.(﹣3,﹣1) D.(4,)【考点】反比例函数图象上点的坐标特征.【分析】只需把所给点的横纵坐标相乘,结果是3的,就在此函数图象上.【解答】解:∵反比例函数中,k=3,∴只需把各点横纵坐标相乘,结果为3的点在函数图象上,四个选项中只有A符合.故选:A.【点评】本题主要考查反比例函数图象上点的坐标特征,所有在反比例函数上的点的横纵坐标的积应等于比例系数.5.在数据分析的过程中,有人对两个不同城市学生的数学成绩进行了分析,结果发现这两座城市统计的方差值都是10.34,那么下列说法中,正确的是()A.两城市学生的成绩一样B.两城市学生的数学平均分一样C.两城市数学成绩的中位数一样D.两城市学生数学成绩波动情况一样【考点】方差.【分析】利用方差的意义回答即可.【解答】解:∵方差是反映数据波动的量,方差越大,波动越大,∴两城市学生数学成绩波动情况一样,故选D.【点评】考查了方差的知识,解题的关键是了解方差是反映数据波动情况的量,方差越大,波动越大.6.如图,在下面的立方体中,它的主视图是()A.B.C.D.【考点】简单组合体的三视图.【分析】找到从正面看所得到的图形即可,注意所有的看到的棱都应表现在主视图中.【解答】解:从正面看易得第一层有5个正方形,第二层左边有2个正方形.故选C.【点评】本题考查了三视图的知识,主视图是从物体的正面看得到的视图.7.如图,已知:直线a、b被AB所截,交点分别是点A、B,其中a∥b,∠1=72°,点D是线段AB 上一点,CD=BD.则∠2=()A.72° B.36° C.64° D.56°【考点】平行线的性质.【分析】先根据平行线的性质求出∠CBD的度数,根据等腰三角形的性质即可得出结论.【解答】解:∵a∥b,∠1=72°,∴∠CBD=∠1=72°.∵CD=BD,∴∠2=180°﹣2∠CBD=180°﹣144°=36°.故选B.【点评】本题考查的是平行线的性质,用到的知识点为:两直线平行,内错角相等.8.如图,在▱ABCD中,过A点作高,垂足刚好为点C,AC=2,∠B=30°,则▱ABCD的周长是()A.B.C.8 D.4【考点】平行四边形的性质.【分析】由AC⊥AD,∠B=30°,AC=2,根据含30°角的直角三角形的性质,可求得AB的长,然后由勾股定理求得BC的长,继而求得答案.【解答】解:∵AC⊥AD,∠B=30°,AC=2,∴AB=2AC=4,∴BC==2,∴▱ABCD的周长是:2(AB+BC)=8+4.故选A.【点评】此题考查了平行四边形的性质、含30°角的直角三角形的性质以及勾股定理.注意平行四边形的对边相等是解题关键.9.二次函数y=ax2+bx+c的图象如图所示,则在下列说法中,与此函数的系数相关的一元二次方程ax2+bx+c=0的根的情况,说法正确的是()A.方程有两个相等的实数根B.方程的实数根的积为负数C.方程有两个正的实数根 D.方程没有实数根【考点】抛物线与x轴的交点.【分析】根据抛物线与x轴交点个数和位置判断一元二次方程ax2+bx+c=0的根的情况即可.【解答】解:根据图象可以看出抛物线与x轴有两个不同的交点,故与此函数的系数相关的一元二次方程ax2+bx+c=0有两个不相等的实数根,由于两交点位于原点的两侧,故一元二次方程ax2+bx+c=0有一正根一负根,故只有B正确;故选:B.【点评】本题考查了抛物线与x轴的交点.根据图象与x轴交点的个数和位置判断一元二次方程根的情况.10.有A、B两个黑色袋子,A袋装有3个黑球、2个白球,B袋装有黑、白两个球,这些球除颜色外,其它一样.在随机抽球中,如果从A袋取一个球,再从B袋取一个球,那么得到两个都是黑球的概率是()A.B.C.D.【考点】列表法与树状图法.【分析】分别求得各自袋子中摸到黑球的概率,然后相乘即可得到两个袋子均为黑球的概率.【解答】解:∵A袋装有3个黑球、2个白球,B袋装有黑、白两个球,∴A袋中摸到黑球的概率为,B袋中摸到黑球的概率为,∴P(两个都是黑球)=×=,故选D.【点评】本题考查了组合概率的求法,解题的关键是了解两个独立事件同时发生的概率等于两个独立事件发生概率的积,难度不大.11.如图,AB是⊙O的直径,它与弦CD交于点E.我们给出下列结论:①AE•BE=CE•DE;②△ADE∽△CBE;③∠A=∠C;④∠AED=∠BEC这些结论中正确的是()A.①②③④ B.①②③C.②③ D.②③④【考点】相似三角形的判定与性质;圆周角定理.【分析】根据圆周角定理得到∠A=∠C,∠D=∠B,由相似三角形的判定定理得到△AED∽△CEB,再根据相似三角形的性质得到AE•BE=CE•DE,由对顶角的性质得到∠AED=∠BEC.【解答】解:∵AB是⊙O的直径,它与弦CD交于点E,∴∠A=∠C,∠D=∠B,∴△AED∽△CEB,∴,∴AE•BE=CE•DE,∵∠AED与∠BEC是对顶角,∴∠AED=∠BEC,∴①②③④都正确.故选A.【点评】本题考查了相似三角形的判定和性质,圆周角定理,对顶角相等,熟练掌握圆周角定理是解题的关键.12.如图,将Rt△ABC以直角顶点C为旋转中心顺时针旋转,使点A刚好落在AB上(即:点A′),若∠A=55°,则图中∠1=()A.110°B.102°C.105°D.125°【考点】旋转的性质.【专题】计算题.【分析】先利用互余计算出∠B=35°,再根据旋转的性质得CA=CA′,∠ACA′=∠BCB′,∠B′=∠B=35°,则利用等腰三角形的性质得∠CA′A=∠CAA′=55°,于是利用三角形内角和可计算出∠ACA′=70°,则∠BCB′=70°,然后根据三角形外角性质计算∠1的度数.【解答】解:在Rt△ABC中,∠B=90°﹣∠A=35°,∵Rt△ABC以直角顶点C为旋转中心顺时针旋转,使点A刚好落在AB上(即:点A′),∴CA=CA′,∠ACA′=∠BCB′,∠B′=∠B=35°,∴∠CA′A=∠CAA′=55°,∴∠ACA′=180°﹣2×55°=70°,∴∠BCB′=70°,∴∠1=∠BCB′+∠B′=70°+35°=105°.故选C.【点评】本题考查了旋转的性质:对应点到旋转中心的距离相等;对应点与旋转中心所连线段的夹角等于旋转角;旋转前、后的图形全等.二、填空题(本大题共6小题,每小题3分,共18分.)13.计算:2= 2 .【考点】二次根式的乘除法.【分析】根据二次根式的乘除法法则计算即可.【解答】解:2=2=2.故答案为:2.【点评】本题考查了二次根式的乘除法法则,熟记法则是解题的关键.14.分解因式:2x2﹣8= 2(x+2)(x﹣2).【考点】因式分解-提公因式法.【分析】观察原式,找到公因式2,提出即可得出答案.【解答】解:2x2﹣8=2(x+2)(x﹣2).【点评】本题考查提公因式法分解因式,是基础题.15.不等式组的解集是x>5 .【考点】解一元一次不等式组.【分析】先求出每个不等式的解集,再根据找不等式组解集的规律找出不等式组的解集即可.【解答】解:∵解不等式①得:x>﹣3,解不等式②得:x>5,∴不等式组的解集为x>5,故答案为:x>5.【点评】本题考查了解一元一次不等式组的应用,解此题的关键是能根据不等式的解集求出不等式组的解集.16.如图所示,⊙O的半径是5,它的弦AB=8,OC⊥AB交AB于点D,则CD= 2 .【考点】垂径定理;勾股定理.【分析】连接OA,先根据垂径定理求出AD的长,再由勾股定理求出OD的长,进而可得出结论.【解答】解:连接OA,∵AB=8,OC⊥AB,OA=5,∴AD=AB=4,∴OD===3,∴CD=OC﹣OD=5﹣3=2.故答案为:2.【点评】本题考查的是垂径定理,熟知平分弦的直径平分这条弦,并且平分弦所对的两条弧是解答此题的关键.17.如图,在反比例函数图象上有点A(a,1),过点A作y轴的平行线交某直线于点B,已知△AOB的面积是8,则直线OB的解析式为y=x .【考点】反比例函数与一次函数的交点问题.【分析】先求得A点坐标,延长BA交x轴于点C,由△AOB的面积可求得AB的长,则可求得B点坐标,利用待定系数法可求得直线OB的解析式.【解答】解:∵A(a,1)在反比例函数图象上,∴a=4,∴A(4,1),如图,延长BA交x轴于点C,则OC=4,AC=1,∴S△AOB=OC•AB=×4AB=2AB=8,∴AB=4,∴B(4,5),设直线OB解析式为y=kx,则5=4k,解得k=,∴直线OB的解析式为y=x.故答案为:y=x.【点评】本题主要考查函数图象上点的坐标特征及待定系数法,利用条件求得B点坐标是解题的关键.18.观察下列关于自然数的等式:第1个式子:32﹣4×12=5;第2个式子:52﹣4×22=9;第3个式子:72﹣4×32=13;…根据上述规律请你写出第2015个式子的计算结果:8061 .【考点】规律型:数字的变化类.【分析】由所给三个等式可得,被减数是从3开始连续奇数的平方,减数是从1开始连续自然数的平方的4倍,计算的结果是被减数的底数的2倍减1,由此规律得出答案即可.【解答】解:32﹣4×12=5 ①52﹣4×22=9 ②72﹣4×32=13 ③…,所以第n个等式为:(2n+1)2﹣4n2=4n+1,∴第2015个式子为:(2×2015+1)2﹣4×20152=4×2015+1=8061,∴第2015个式子的计算结果为8061,故答案为:8061.【点评】本题主要考查数字的变化规律,找出数字之间的运算规律,利用规律解决问题是解答此题的关键.三、解答题(本大题共8小题,满分66分.)19.先化简,再求值:x2(x﹣1)﹣x(x2+x﹣1),其中x=﹣1.【考点】整式的混合运算—化简求值.【分析】根据整式乘法法则展开,然后合并同类项,最后将x=﹣1代入即可.【解答】解:原式=x3﹣x2﹣x3﹣x2+x=﹣2x2+x∵x=﹣1,∴原式=﹣2﹣1=﹣3.【点评】本题考查整式的乘法法则、加减法则,正确利用法则是解题的关键.20.今年两会期间,“全民阅读”被再次写进《政府工作报告》,成为社会热词.在第20个世界读书日来临之际,我市某中学为了解本校学生每周课外阅读时间t(单位:小时),采用随机抽样的方法进行问卷调查,调查结果按0≤t<0.5,0.5≤t<1,1≤t<2,2≤t分为四个等级,分别用A、B、C、D表示,并绘制成了两幅不完整的统计图,由图中给出的信息回答下列问题:(1)填空:A等级的百分率是 5 %;B等级的百分率是15 %;(2)将不完整的条形统计图补充完整;(3)若该校共有学生2400人,试估计每周课外阅读时间量满足t≥1的人数.【考点】条形统计图;用样本估计总体;扇形统计图.【分析】(1)先求出总人数,再求出样本中C等级人数及A等级人数,即可求出A等级的百分率及B等级的百分率,(2)求出C等级人数及A等级人数,补全统计图即可,(3)求出样本中满足t≥1的人数,再求出样本中满足t≥1的百分比,用总人数乘这个百分比即可.【解答】解:(1)样本的总人数:(人),样本中C等级:200×45%=90(人),样本中A等级:200﹣30﹣90﹣70=10(人)A等级的百分率是=5%;B等级的百分率是=15%;故答案为:5,15.(2)样本中A等级:200×5%=10(人),样本中C等级:200×45%=90(人),(3)样本中满足t≥1的人数:90+70=160(人)样本中满足t≥1的百分比为: =80%,该校共有学生2400人,时间量满足t≥1的人数:2400×80%=1920(人).答:该校共有学生2400人,时间量满足t≥1的人数是1920人.【点评】本题主要考查了条形统计图,扇形统计图及用样本估计总体,解题的关键是读懂统计图,从统计图中获得准确的信息.21.如图,在Rt△ABC中,∠C=90°,以点C为圆心作⊙C,与AB切于点D,过点A、B分别作⊙C 的切线AF、BE,切点为F、E点.求证:AF∥BE.【考点】切线的性质.【专题】证明题.【分析】根据切线长定理得到∠1=∠2,∠3=∠4,则利用互余得∠2+∠3=90°,所以∠1+∠2+∠3+∠4=180°,于是可根据平行线的判定得到结论.【解答】证明:∵AF、AD是⊙C的切线,∴∠1=∠2,∵BE、BD是⊙C的切线,∴∠3=∠4,又∵∠C=90°,∴∠2+∠3=90°,∴∠1+∠2+∠3+∠4=180°,即∠FAB+∠EBA=180°,∴AF∥BE.【点评】本题考查了切线的性质:圆的切线垂直于经过切点的半径.也考查了切线长定理和平行线的判定.22.如图,阳光下斜坡旁有一棵树AB,它的阴影投在斜坡上为AC=10米,斜坡与平面形成的坡角∠DAC=15°,光线与斜坡形成的∠BCA=75°.求树AB的高度(精确到0.1米)参考数据:sin15°≈0.26,cos15°≈0.97,tan15°≈0.27,≈1.73.【考点】解直角三角形的应用-坡度坡角问题.【分析】作CE⊥AB于E,根据平行线的性质求出∠ECA的度数,根据三角函数的概念求出AE的长,求出∠B的度数,求出BE的长,得到答案.【解答】解:作CE⊥AB于E,则CE∥AD,∴∠ECA=∠DAC=15°,cos∠ECA=,∴EC=10×0.97=9.7,sin∠ECA=,AE=10×0.26=2.6,∵∠DCA=15°,∴∠BAC=75°,又∠BCA=75°,∴∠ABC=30°,BE=CE=16.78,AB=AE+BE=2.6+16.78=19.38≈19.4.【点评】本题考查的是解直角三角形的应用,掌握锐角三角函数的概念是解题的关键,解答时,要把实际问题转化为解直角三角形的问题.23.A地至B地的航线长9750km,一架飞机从A地顺风飞往B地需12.5h,它逆风飞行同样的航线需13h,求飞机无风时的平均速度与风速.【考点】二元一次方程组的应用.【分析】设飞机的平均速度为x千米/时,风速为y千米/时,根据航行问题的数量关系建立方程组求出其解即可.【解答】解:设飞机的平均速度为x千米/时,风速为y千米/时,由题意,得,解得:.答:飞机的平均速度为765千米/时,风速为15千米/时.【点评】本题考查了二元一次方程组的实际运用,掌握行程问题的顺风速度=静风速度+风速和逆风速度=静风速度﹣风速,由此建立方程组是关键.24.为对荒山进行改造,政府投资13万元给某村民小组用于购买与种植A、B两种树苗共3000棵.完成这项种植后,剩余的款项作为村民小组的纯收入.已知用160元购买A树苗比购买B树苗多3棵.这两种树苗的单价、成活率及移栽费用见下表:树苗品种A树苗B树苗购买价格(元/棵)a a+12树苗成活率90% 95%移栽费用(元/棵)3 5(1)求表中a的值;(2)设购买A树苗x棵,其它购买的是B树苗,把这些树苗种植完成后,村民小组获得的纯收入为y元,请你写出y与x之间的函数关系式;(3)若要求这批树苗种植后,成活率达到94%以上(包含94%),则最多种植A树苗多少棵?此时,村民小组在这项工作中,所得的纯收入最大值可以是多少元?【考点】一次函数的应用;分式方程的应用.【分析】(1)根据题意列出方程解答即可;(2)根据题意列出函数解析式即可;(3)设种植A树苗b棵,列出解析式根据增函数解答即可.【解答】解:(1)根据题意,得:,解得:a1=20,a2=﹣32,经检验,它们都是原方程的解,但a2=﹣32不合题意,舍去,所以a=20;(2)由(1)可知:A树苗购买价格:20元/棵;B树苗购买价格:32元/棵,根据题意,得:y=130000﹣[20x+(3000﹣x)•32+3x+5(3000﹣x)]=14x+19000,即:y与x之间的函数关系式是:y=14x+19000,(3)设种植A树苗b棵,则有:90%b+(3000﹣b)×95%≥94%×3000,解得:b≤600,由(2)可知:y=14x+19000,其中14>0,对于此一次函数,当x取最大值时,纯收入y的值最大.所以有:y最大值=14×600+19000=27400(元),因此:最多种植A树苗600棵,纯收入最大值是27400元.【点评】此题考查一次函数的应用,关键是根据题意列出分式方程和函数解析式进行解答.25.如图,在正方形ABCD中,延长对角线CA到点E,以AE为边作正方形AEFG,连接BG、DE.(1)求证:△ABG≌△ADE;(2)当AB=,AG=3时,求线段BG的长度.【考点】全等三角形的判定与性质;勾股定理;正方形的性质.【分析】(1)由四边形ABCD是正方形,得到AB=AD,∠BAD=90°,根据四边形AEFG是正方形,得到AE=AG,∠EAG=90°,于是得到∠BAD=∠EAG,证得∠BAG=∠DAE,于是得到结论;(2)如图,连接BD交AC于点H,根据四边形ABCD是正方形,于是得到AH=DH,∠AHD=90°,由于,求出AH=DH=1,在Rt△EHD中,由勾股定理得:,又由(1)△ABG≌△ADE得到BG=ED,于是结论可得.【解答】(1)证明:∵四边形ABCD是正方形,∴AB=AD,∠BAD=90°,∵四边形AEFG是正方形,∴AE=AG,∠EAG=90°,∴∠BAD=∠EAG,∴∠BAD+∠DAG=∠EAG+∠DAG,∴∠BAG=∠DAE,在△ABG与△ADE中,,∴△ABG≌△ADE(SAS);(2)解:如图,连接BD交AC于点H,∵四边形ABCD是正方形,∴AH=DH,∠AHD=90°,又∵,∴AH=DH=1,又∵四边形AEFG是正方形,∴AE=AG=3,∴EH=AE+AH=4,在R t△EHD中,由勾股定理,得:,又由(1)△ABG≌△ADE,∴BG=ED,∴.【点评】本题考查了全等三角形的判定和性质,正方形的性质,勾股定理,证得△ABG≌△ADE是解题的关键.26.如图,抛物线y=ax2+bx+4与坐标轴交于A、B、C三点,直线y=x+4与坐标轴交于B、C点,其中点A(4,0).(1)求此抛物线的解析式;(2)在线段AC、BC上分别取点P、Q,使CP=CQ,连接PQ,以PQ为对称轴对折,点C刚好落在抛物线的C′上,求点C′的坐标;(3)连接AB,在抛物线上是否存在点M,使得∠MBA+∠CBO=45°?若存在,请直接写出适合此条件的点M的坐标;若不存在,请说明理由.【考点】二次函数综合题.【分析】(1)首先求出点B的坐标,然后利用待定系数法求出抛物线的解析式即可;(2)设CQ=e,根据题意得到CP=QC′=e,对于直线,当x=0时,y=4,在Rt△BCO中,,过点Q作QK⊥x轴,垂足为点K,则有:QK∥OB,得到△CKQ∽△COB,于是得到比例式,求出,,过点C′作,C′H⊥x轴,垂足为点H,得到KH=QC′=e,C′H=KQ=e,于是得到,求出C′(e﹣3, e),根据题意,点C′为抛物线上的点,得到方程,解得,即可得到结论;(3)满足条件的点M有两种情形,需要分类讨论:设M(x,y),①当BM⊥BC时,如图2所示.由∠ABO=45°,得到∠MBA+∠CBO=45°,故点M满足条件.过点M1作M1E⊥y轴于点E,则M1E=x,OE=﹣y,求得BE=4﹣y.由于tan∠M1BE=tan∠BCO=,得到方程=,求出直线BM1的解析式为y=﹣x+4.联立y=﹣x+4与y=﹣x2+x+4,即可得到结果;②当BM与BC关于y轴对称时,如图3所示.由∠ABO=∠MBA+∠MBO=45°,∠MBO=∠CBO,于是得到∠MBA+∠CBO=45°,故点M满足条件过点M2作M2E⊥y轴于点E,则M2E=x,OE=y,求出BE=4﹣y.根据tan∠M2BE=tan∠CBO=,得到方程=求出直线BM2的解析式为:y=﹣x+4.联立y=﹣x+4与y=﹣x2+x+4得﹣x+4=﹣x2+x+4,即可得到结果.【解答】解:(1)当y=0时,由直线得:,解得:x=﹣3,∴点C(﹣3,0),又∵抛物线y=ax2+bx+4经过点A(4,0),所以有:,解得:,∴抛物线的解析式是:;(2)设CQ=e,则根据题意,得:CP=QC′=e,对于直线,当x=0时,y=4,∴点B(0,4),OB=4,又∵点C(﹣3,0),∴CO=3,在Rt△BCO中,,如图1,过点Q作QK⊥x轴,垂足为点K,则有:QK∥OB,∴△CKQ∽△COB,∴,即:,∴,,如图1,过点C′作,C′H⊥x轴,垂足为点H,则有:KH=QC′=e,C′H=KQ=e,∴,又∵CO=3,∴,∴C′(e﹣3, e),根据题意,点C′为抛物线上的点,则有:,解得:,e2=0(不合题意,舍去),∴当时,有:,,∴点C′的坐标是(2.5,2.75);(3)存在这样的点M的坐标,设M(x,y),①当BM⊥BC时,如图2所示.∵∠ABO=45°,∴∠MBA+∠CBO=45°,故点M满足条件.过点M1作M1E⊥y轴于点E,则M1E=x,OE=﹣y,∴BE=4﹣y.∵tan∠M1BE=tan∠BCO=,∴=,∴直线BM1的解析式为:y=﹣x+4.联立y=﹣x+4与y=﹣x2+x+4,得:﹣ x+4=﹣x2+x+4,解得:x1=0,x2=,∴y1=4,y2=,∴M1(,);②当BM与BC关于y轴对称时,如图3所示.∵∠ABO=∠MBA+∠MBO=45°,∠MBO=∠CBO,∴∠MBA+∠CBO=45°,故点M满足条件.过点M2作M2E⊥y轴于点E,则M2E=x,OE=y,∴BE=4﹣y.∵tan∠M2BE=tan∠CBO=,∴=∴直线BM2的解析式为:y=﹣x+4.联立y=﹣x+4与y=﹣x2+x+4得:﹣ x+4=﹣x2+x+4,解得:x1=0,x2=5,∴y1=4,y2=﹣,∴M2(5,﹣).综上所述,满足条件的点M的坐标为:(,)或(5,﹣).【点评】本题考查了二次函数的图象与性质,待定系数法求函数的解析式,解直角三角形,一次函数的性质,解方程等知识点,正确的作出图形是解题的关键.。

2015年广西柳州市鱼峰区柳北区中考英语二模试卷(解析版)

2015年广西柳州市鱼峰区柳北区中考英语二模试卷(解析版)

2015年广西柳州市鱼峰区柳北区中考英语二模试卷一、听力1.(4分)1.2.3.4..2.(1分)A.By bike.B.Go to school.C.Once a week.3.(1分)A.Good morning!B.Good afternoon!C.Good evening!4.(1分)A.No,I don't.B.Yes,I can.C.Yes,I did.5.(1分)A.No problem.B.Nice to meet you,too.C.I'm from England.6.(1分)A.A doctor.B.He's forty﹣five.C.He likes reading.7.(1分)A.I'm 14.B.I'm a student.C.I'm in Class 6.8.(1分)How many students are there in Tom's class?A.25.B.40.C.45.9.(1分)Why does Tony like the cartoon Tom and Jerry?A.Because it's boring.B.Because it ends in a happy way.C.Because it's very funny.10.(1分)What time did Alice get to the meeting?A.At 8:50.B.At 9:20.C.At 8:30.11.(1分)How much will the man have to pay in all?A.$10.B.$40.C.$60.12.(1分)Can they take photos in the museum?A.Yes,they can.B.They can't take photos.C.No,they can't.13.(3分)听第一段长对话,回答第16至第18小题.16.What day is it today?A.Saturday.B.Friday.C.Thursday.17.Where will they have lunch?A.In a restaurant near the office building.B.In a restaurant far away form the company.C.In the office building.18.Does Sue like dumplings?A.No,she doesn't.B.Yes,she does.C.I don't know.14.(3分)听第二段长对话,回答第19至第21小题.19.Where does the man want to go?A.To Shanghai Road.B.To Bridge Street.C.To a bank.20.Which bus may the man take?A.No.18.B.No.8.C.No.12.21.Where will the man take the bus from?A.Shanghai Road.B.Bridge Street.C.The bank.15.(4分)听第三段长对话,回答第22至第25小题.22.What sport does Adam like?A.Football.B.Baseball.C.Basketball.23.What does Adam think of basketball?A.It's exciting.B.It's tiring.C.It's difficult.24.What else does Adam like?A.Collecting baseball cards.B.Tennis.C.Table tennis.25.What's the girl's favourite sport?A.Table tennis.B.Tennis.C.Baseball.16.(5分)第四节语篇理解.听一篇短文,根据短文内容选择正确的答案.短文读三遍.26.Beijing will be.A.sunny B.cloudy C.raining27.The temperature will be in Shanghai.A.5℃~9℃B.﹣5℃~5℃C.5℃~8℃28.It'll be in Xi'an.A.cloudy and snowy B.sunny and windy C.cloudy and rainy29.In Guangzhou,there may be.A.some showers B.some clouds C.storms30.Hong Kong will be later.A.cloudy B.7℃~20℃C.stormy.二、单项选择(共15小题,每小题1分,共15分)从A、B、C三个选项中,选出最佳选项,并将其字母标号在答题卡上涂黑.17.(1分)They are __________.()A.boys B.boy C.boy's18.(1分)﹣Where were you born?﹣I ___________ in Guangxi.()A.am born B.were born C.was born19.(1分)﹣Hello,Friendship Helpline.Who's calling,please?﹣Hello.__________.()A.I amB.This is Lingling speakingC.It's me20.(1分)My best friend,____ fifteen﹣year﹣old Tony said,"I enjoy sailing alone."()A.a B.the C./21.(1分)I'm looking forward __________ good marks.()A.to get B.got C.to getting22.(1分)She has breakfast at about 7:00every morning,__________?()A.hasn't she B.doesn't she C.has she23.(1分)The man lives alone,_______ he doesn't feel lonely.()A.and B.but C.or24.(1分)The students in our class are more than _______ in their class.()A.those B.ones C.students25.(1分)Is there ___________ in today's newspaper?()A.anything interesting B.something interestingC.interesting anything26.(1分)September is the _______ month of a year.()A.nine B.nineth C.ninth27.(1分)This is ______________ room.()A.Betty's and Kate's B.Betty's and KateC.Betty and Kate's28.(1分)Can you tell me ___________________to school yesterday?()A.why he did come B.why he didn't comeC.why he didn't comeC29.(1分)﹣Must I come before 6:30tomorrow?﹣_________.()A.No,you needn't B.Yes,you needC.No,you have to30.(1分)Shenzhen will become ___________ Hong Kong.()A.as busier than B.as busy asC.as busier as31.(1分)A pair of shoes ________ to him as a present by his grandma last week.()A.were given B.was given C.gave三、完形填空(共1小题,每小题10分,共10分)阅读下面短文,选择最佳的答案,并将其字母标号在答题卡上涂黑.32.(10分)Many Chinese students find it difficult(46)English,but not Chinese,because Chinese is(47)own language.Actually,Chinese is(48)to learn than English.Still some foreign students can speak Chinese so (49)that if you didn't see them,you would take them for Chinese.What makes them (50)?"For me,conversation is the most helpful.I use every chance to speak(51)Chinese.If you only listen to what others (52),you'll improve your listening ability,but if you talk as much as (53),you'll find you can express yourself much better,"says Ulrike Nootz,a German girl now studying Chinese at Shanghai International Studies University.Though the Chinese language is difficult,she can learn it well.She thinks that to learn a language one must try to know something about the history of the country.Though Chinese is different from English,the experience of success can be (54).Conversation,in English learning,(55)very important.46.A.to learn B.learning C.learn47.A.we B.their C.us48.A.very more difficult B.much difficult C.much more difficult 49.A.well B.good C.better 50.A.success B.succeed C.successful51.A.in B.by C.with52.A.say B.talk C.speak53.A.can B.possible C.may54.A.the same B.same C.the different 55.A.may be B.maybe C.may.四、阅读理解(共4小题,56-70小题每小题5分,71-75小题每小题5分,共25分)A篇:根据短文内容判断正误,正确的在答题卡上涂A,错误的涂B.(5小题,每小题5分,共5分)33.(5分)Li Lei is thirteen now.He began to study in a middle school two years ago.His home is in a small village,and it's nearly five kilometers from his school.He has to get up early in the morning and run to school.He is never late for school.His father thinks Li Lei is too tired.He wants to borrow some money to buy a bike for him.Li Lei doesn't agree because he knows his mother is always ill and the family spends a lot of money on medicine.He keeps running every day.He becomes stronger and stronger.He runs fastest in his class.Last week there was a sports meeting in his school.Li Lei ran faster than any other boy and got the first place in the boys'1,500meters.Now he's famous in the whole school.His classmates and teachers were very proud of him.He was happy,too.He ran home fast to tell his parents about the good news.56.Li Lei is thirteen years old.57.Li Lei runs to school in the morning.58.Li Lei's father bought him a bike.59.Li Lei is often late for school.60.Li Lei got the first place in the boys'1,500meters last week..34.(5分)Eating habits are different in many countries.The Chinese have a saying,"Eat good things for breakfast,eat a big meal for lunch,but eat less at dinner."Many Americans agree that one should start the day with a good breakfast,but their ideas about lunch and dinner are different.Most Americans only give themselves a short time for lunch.So they eat a small meal.After work they will have more time to eat a big dinner.Also a quiet dinner at home with all the family members,talking about their day is a way to rest after a long,hard day of work.Eating at restaurant is also different.In China,people like to talk and laugh while eating.Very often you can hear people talking and laughing loudly,and they are justhaving a good time.In America it is not like this.People want a quiet place where they can eat a good meal far away from the noise of the outside world.If some people are talking too loudly,the manager(经理)may come out and ask them to leave.61.Which is the good way for keeping healthy in China?A.Eating nothing for breakfast.B.Eating less to lose weight.C.Eating less at dinner.62.How long do most Americans only give themselves for lunch?A.The whole noon.B.A long time.C.A short time.63.Talking at table isn't a way to rest in America,is it?A.Yes,it is.B.No,it isn't.C.No.They aren't.64.What do people like doing when we are having a meal in China?A.Talking and laughing.B.Having a rest.C.Only eating quietly.65.What will the manager of the restaurant do if some people are talking too loudly in America?A.Talk with them happily.B.Let them go away.C.Do nothing.35.(5分)Sam's Snack Bar(汤姆的小吃店)OPENING HOURS:11:00am~10:00pm (weekdays)12:00am~8:00pm (weekends)The followings are some of the set meals(套餐)in the bar.Pay only two more yuan to change small fries to large fries!根据表格信息,选择正确答案.66.David wants two cheese burger meals,two vegetable salad meals and a chicken nuggets meal.How much should he pay?A.¥112.B.¥108.C.¥102.67.According to Question 66,how much more does David have to pay if he wants all the meals with large fries?A.¥10.B.¥8.C.¥6.68.Mandy likes chicken very much.How many meals may she like?A.Two.B.Three.C.Four.69.Amanda would like to have more vegetables for her lunch because she is on diet.Which meal should she order(点菜)?A.Meal 2.B.Meal 4.C.Meal 5.70.Which of the following is TRUE?A.The snack bar only opens on weekdays.B.All the set meals have soup.C.The snack bar doesn't open before 11:00am.36.(10分)Whoever you are or wherever you come from,one thing is clear:you know the mosquito(蚊子)very well.Mosquitoes fly everywhere.They can be found almost all over the world,and there are more than 2,500kinds of them.No one loves the mosquito.But the mosquito may decide that she loves you.She?Yes.It is true that only the female(雌性的)mosquito bites because she needs blood to lay eggs.She is always looking for things or people she wants to bite.If she likes what she finds,she bites.But if she doesn't like your blood,she will turn to someone more delicious.Next time a mosquito bites you,just remember that you are chosen.You are different from the others!If the mosquito likes you,she lands on your body without letting you know.She bites you so quickly and quietly that you may not have known anything is happening.After she bites,you will have an itch(发庠)on your body because she puts something from her mouth together with your blood.By the time the itching begins,she has gone.And then what happens?Well,after her delicious dinner,the mosquito feels tired.She just wants to find a place to rest.There,on a leaf or a wall,she begins to lay eggs,hundreds of eggs!71.Why do you know mosquitoes very well?A.Because they can fly.B.Because there are many kinds of them.C.Because they fly everywhere.72.There are over kinds of mosquitoes.A.two hundred and fiftyB.twenty thousand and fiftyC.two thousand and fifty73.If the mosquito bites you,it means.A.she hates youB.she likes your bloodC.she decides to go away74.The mosquito bites you.A.because it doesn't like your bloodB.too quickly to let you knowC.because you have chosen it75.Why do you have an itch after the mosquito bites you?Because.A.she puts something from her mouth together with your bloodB.you don't know what has happenedC.the itching begins only when the mosquito has gone.五、口语运用(共1小题,每小题10分,共10分)根据对话内容,从右边方框中的六个选项中选出五个合适的句子补全对话,并将句子的字母标号在答题卡上涂黑.37.(10分)A:How do you do?B:(76)A:Do you mind if I ask you some questions?B:Of course not.Please ask.A:What's your favourite colour?B:(77)A:What's your hobby?B:(78)A:Have you ever been to Beijing?B:(79)A:Thank you!B:Don't mention it.A:Goodbye!B:(80).六、综合填空(共5小题,每小题1分,共10分)A.单词拼写根据句子意思及所给的中文提示完成单词,并将完整的单词填写在答题卡对应的横线上.每空只能填一词.(5小题,每小题1分,共5分)38.(1分)(我)am from Liuzhou.39.(1分)She hurried towards it,and knocked on the(门).40.(1分)Once or(两次)she looked into her sister's book.41.(1分)It will(可能)be cold and wet.42.(1分)I stood very(不动的).I didn't even turn my head.B.选词填空根据短文内容,从方框中选择恰当的单词完成句子并填写在答题卡对应的横线上.所有单词在填入前不需进行词形转换,每个单词只能用一次,每空只能写一词.(5小题,每小题5分,共5分)43.(5分)It's great to (86)others.When I was a small kid,my family often needed money.Thanks to some kind(87),we didn't live a hard life.Now our life is(88)than before.So it's time to pay back.When we (89)free,my parents and I often do some work in hospitals or the Old People's Home.Wealways try (90)best to help others in need.七、句子翻译(共5小题,每小题1分,共5分)根据中文意思完成句子,并将答案填写在答题卡对应的横线上.每空词数不限.44.(1分)请问您贵姓?What's your,please?45.(1分)我们可以互相学习.We can learn from.46.(1分)我们的数学老师能把枯燥乏味的课讲得生动有趣.Our maths teacher can make lessons interesting.47.(1分)错误是难免的,但你练得越多,你的英语就讲得越好.Nobody can,but the more you practice,the better your spoken English will be.48.(1分)请告诉他们,我一做完作业我就去跟他们一起打篮球.Please tell them I'll go to play basketball with them as soon as my homework.八、书面表达(15分)49.(15分)中秋节是中国最重要的传统节日之一.假设你的美国笔友Mike想了解一下中秋节的情况,请你根据下表所提供的信息写一篇70词左右的英语短文,向他简单介绍中秋节.开头已给出,不计入总词数.提示词:August 15th of the Lunar calendar (阴历八月十五);mooncake(月饼);round(圆的);bean paste(豆馅);egg﹣yolk(蛋黄);nut(果仁);appreciatethe moon(赏月);express(表达);a symbol of reunion(团圆的象征);fortune (财富).2015年广西柳州市鱼峰区柳北区中考英语二模试卷参考答案与试题解析一、听力1.(4分)1.略2.略3.略4.略.【解答】略2.(1分)A.By bike.B.Go to school.C.Once a week.【解答】略3.(1分)A.Good morning!B.Good afternoon!C.Good evening!【解答】A4.(1分)A.No,I don't.B.Yes,I can.C.Yes,I did.【解答】略5.(1分)A.No problem.B.Nice to meet you,too.C.I'm from England.【解答】略6.(1分)A.A doctor.B.He's forty﹣five.C.He likes reading.【解答】略7.(1分)A.I'm 14.B.I'm a student.C.I'm in Class 6.【解答】略8.(1分)How many students are there in Tom's class?A.25.B.40.C.45.【解答】略9.(1分)Why does Tony like the cartoon Tom and Jerry?A.Because it's boring.B.Because it ends in a happy way.C.Because it's very funny.【解答】略10.(1分)What time did Alice get to the meeting?A.At 8:50.B.At 9:20.C.At 8:30.【解答】略11.(1分)How much will the man have to pay in all?A.$10.B.$40.C.$60.【解答】略12.(1分)Can they take photos in the museum?A.Yes,they can.B.They can't take photos.C.No,they can't.【解答】略13.(3分)听第一段长对话,回答第16至第18小题.16.What day is it today?A.Saturday.B.Friday.C.Thursday.17.Where will they have lunch?A.In a restaurant near the office building.B.In a restaurant far away form the company.C.In the office building.18.Does Sue like dumplings?A.No,she doesn't.B.Yes,she does.C.I don't know.【解答】略14.(3分)听第二段长对话,回答第19至第21小题.19.Where does the man want to go?A.To Shanghai Road.B.To Bridge Street.C.To a bank.20.Which bus may the man take?A.No.18.B.No.8.C.No.12.21.Where will the man take the bus from?A.Shanghai Road.B.Bridge Street.C.The bank.【解答】略15.(4分)听第三段长对话,回答第22至第25小题.22.What sport does Adam like?A.Football.B.Baseball.C.Basketball.23.What does Adam think of basketball?A.It's exciting.B.It's tiring.C.It's difficult.24.What else does Adam like?A.Collecting baseball cards.B.Tennis.C.Table tennis.25.What's the girl's favourite sport?A.Table tennis.B.Tennis.C.Baseball.【解答】略16.(5分)第四节语篇理解.听一篇短文,根据短文内容选择正确的答案.短文读三遍.26.Beijing will be略.A.sunny B.cloudy C.raining27.The temperature will be略in Shanghai.A.5℃~9℃B.﹣5℃~5℃C.5℃~8℃28.It'll be略in Xi'an.A.cloudy and snowy B.sunny and windy C.cloudy and rainy29.In Guangzhou,there may be略.A.some showers B.some clouds C.storms30.Hong Kong will be略later.A.cloudy B.7℃~20℃C.stormy.【解答】略二、单项选择(共15小题,每小题1分,共15分)从A、B、C三个选项中,选出最佳选项,并将其字母标号在答题卡上涂黑.17.(1分)They are __________.()A.boys B.boy C.boy's【解答】答案为A,这一题可以用排除法,be动词are 后面的名词要复数,所以可以排除B选项.A男孩们B男孩C男生的they are+名词,表示他们是什么,they are+形容词,表示他们是什么样子的,根据题意得知他们是男孩子们,故答案A比较符合题意,故答案为A.18.(1分)﹣Where were you born?﹣I ___________ in Guangxi.()A.am born B.were born C.was born【解答】答案:C根据be born"出生"通常表达的是过去的事情,故动词be通常只用was或were,结合答语中的主语是I,故搭配was,故选C19.(1分)﹣Hello,Friendship Helpline.Who's calling,please?﹣Hello.__________.()A.I amB.This is Lingling speakingC.It's me【解答】答案:B;该题考查电话用语;用于打电话this/that is sb.speaking表示我/你正在打电话;根据上句Who's calling,please?可知是电话用语,答语应是This is Lingling speaking;故选B.20.(1分)My best friend,____ fifteen﹣year﹣old Tony said,"I enjoy sailing alone."()A.a B.the C./【解答】答案:C 专有名词前一般不加冠词,根据句中Tony是人名,属专有名词,故选C21.(1分)I'm looking forward __________ good marks.()A.to get B.got C.to getting【解答】答案:C.根据I'm looking forward __________ good marks可知我盼望着取的好成绩.句子里有固定短语look forward to doing."期待着,盼望着做某事,结合语境,故选C.22.(1分)She has breakfast at about 7:00every morning,__________?()A.hasn't she B.doesn't she C.has she【解答】答案:B.根据She has breakfast at about 7:00every morning,__________?可知她每天早上大约7点吃早饭,是吗?在反意一般疑问句中,如果陈述句部分是肯定形式,那么附加疑问部分就是否定形式,根据主语是第三人称单数she,谓语动词是实意动词has,故要借助does构成一般疑问句;故选B.23.(1分)The man lives alone,_______ he doesn't feel lonely.()A.and B.but C.or【解答】答案:B此题考查连词词意.选项A:和、又,表示并列关系;选项B:但是,表转折关系;选项C:或者,表选择关系.根据题干"The man lives alone"(这个人独自居住)与"he doesn't feel lonely"(他不觉得孤独)之间为转折关系,故选B.24.(1分)The students in our class are more than _______ in their class.()A.those B.ones C.students【解答】答案:A根据The students in our class are more than _______ in their class.我们班的学生们比他们班的学生多..Ones替代的物或者人前一般没定冠词,而those有;在题干里the students,其前面有定冠词"The";还有Ones一般都带有形容词作定语,不能单独使用,而those可单独使用;故选A.25.(1分)Is there ___________ in today's newspaper?()A.anything interesting B.something interestingC.interesting anything【解答】答案为A.不定代词的用法:something用于肯定句中,anything用于否定句或问句中,本题为一般疑问句,可排除B;由"不定代词+形容词"这一规则可排除C;故答案为A.26.(1分)September is the _______ month of a year.()A.nine B.nineth C.ninth【解答】答案:C.根据September is the _______ month of a year.可知九月是一年中的第九个月.表顺序.在序数词中的其中一条用法是:在序数词前面加定冠词the;B项拼写错误.故选C.27.(1分)This is ______________ room.()A.Betty's and Kate's B.Betty's and KateC.Betty and Kate's【解答】答案:C.考点:名词所有格.在名词所有格的其中一项构成是:两人共同拥有同一物或者人的时候,在最后的名词后面加′s;题干里的房间是"贝蒂和凯特的",是二人共住着一间;故选C.28.(1分)Can you tell me ___________________to school yesterday?()A.why he did come B.why he didn't comeC.why he didn't comeC【解答】答案:B.根据Can you tell me ___________________to school yesterday?你能告诉我昨天他为什么没来学校吗?可知句子是一个宾语从句;宾语从句的语序应为陈述句的语序;结合语境,句子的时间状语是yesterday,从句应用一般过去时;来说明没到校的理由;故选B.29.(1分)﹣Must I come before 6:30tomorrow?﹣_________.()A.No,you needn't B.Yes,you needC.No,you have to【解答】答案:A;以must为首的提问句型,肯定回答用yes,you must.否定回答用no,you need not;根据上述问句Must I come before 6:30tomorrow明天我必须在6:30以前来到吗?结合给出的答案,可知答语应为:No,you needn't,表不必;故选A.30.(1分)Shenzhen will become ___________ Hong Kong.()A.as busier than B.as busy asC.as busier as【解答】答案:B.同级之间的比较用as+形容词或副词的原型+as,结合句意,这里是指一样忙碌.故选B.31.(1分)A pair of shoes ________ to him as a present by his grandma last week.()A.were given B.was given C.gave【解答】答案:B根据句中时间状语为last week可判断句子为一般过去时,主语 a pair of shoes是谓语动词give的承受者二者是被动关系,故用被动语态,所以空处为一般过去时的被动语态,一般过去时的被动语态的结构为was/were+及物动词的过去分词.又根据kind of,pair of,glass of 等表示确定数量的名词短语修饰主语时,谓语与kind,pair,glass等的单复数一致,结合句中pair是单数,动词be为was 故选B三、完形填空(共1小题,每小题10分,共10分)阅读下面短文,选择最佳的答案,并将其字母标号在答题卡上涂黑.32.(10分)Many Chinese students find it difficult(46)A English,but not Chinese,because Chinese is(47)B own language.Actually,Chinese is(48)C to learn than English.Still some foreign students can speak Chinese so (49)A that if you didn't see them,you would take them for Chinese.What makes them (50)C?"For me,conversation is the most helpful.I use every chance to speak(51)A Chinese.If you only listen to what others (52)A,you'll improve your listening ability,but if you talk as much as (53)B,you'll find you can express yourself much better,"says Ulrike Nootz,a German girl now studying Chinese at Shanghai International Studies University.Though the Chinese language is difficult,she can learn it well.She thinks that to learn a language one must try to know something about the history of the country.Though Chinese is different from English,the experience of success can be (54)A.Conversation,in English learning,(55)A very important.46.A.to learn B.learning C.learn47.A.we B.their C.us48.A.very more difficult B.much difficult C.much more difficult 49.A.well B.good C.better 50.A.success B.succeed C.successful51.A.in B.by C.with52.A.say B.talk C.speak53.A.can B.possible C.may54.A.the same B.same C.the different 55.A.may be B.maybe C.may.【解答】46.A 考查固定搭配.find it+形容词to do sth表示发现做某事是…的,it作形式宾语,所以此处要用不定式形式,选A.47.B 考查代词辨析.A表示我们,主格代词,作主语;B表示他们的,形容词性物主代词,作定语;C表示我们,是宾格代词,作宾语.此处作定语修饰名词短语own language,所以选B.48.C 考查形容词的比较级.由than可知此处要用形容词的比较级,A和B是错误的表达,A中的very修饰形容词的原级,不能修饰比较级;B中的much修饰形容词的比较级,不能修饰原级,C正确,表示比…困难得多.49.A 考查词性.A作形容词时表示好的,指身体好,作副词时是good的副词形式,表示某种事物好;B表示好的,是形容词;C表示更好的.由if you didn't see them,you would take them for Chinese可知一些外国学生的中文说得很好,选A,副词修饰动词speak.50.C 考查固定搭配.make sb后接形容词,表示使某人如何.A是名词;B是动词;C是形容词.选C,此处表示是什么使他们成功的.51.A 考查介词辨析.A表示在…里,或表示使用某种语言;B表示通过;C表示有,和,使用某种工具.此处表示用中文说,所以要用in.52.A 考查动词辨析.A表示说,接说的内容;B表示交谈,常与about搭配表示谈论某事或与with搭配表示与某人交谈;C表示说,指说某种语言.此句中的what是作从句的宾语,表示其他人说的内容,选A.53.B 考查固定搭配.as much as possible表示尽可能多的,句意为但如果你尽可能多的谈话,你就会发现你可以更好地表达你自己,选B.54.A 考查形容词辨析.A表示相同的;B表示相同的;C表示不同的.由though 可知此句与上一句间的关系是让步关系,与different相对的是the same,选A.55.A 考查情态动词.A用在句中,表示也许;B用在句首,表示也许;C用在句中,表示也许.此处是在句中,且important是形容词,所以要用may加上be 动词的原形,选A.四、阅读理解(共4小题,56-70小题每小题5分,71-75小题每小题5分,共25分)A篇:根据短文内容判断正误,正确的在答题卡上涂A,错误的涂B.(5小题,每小题5分,共5分)33.(5分)Li Lei is thirteen now.He began to study in a middle school two years ago.His home is in a small village,and it's nearly five kilometers from his school.He has to get up early in the morning and run to school.He is never late for school.His father thinks Li Lei is too tired.He wants to borrow some money to buy a bike for him.Li Lei doesn't agree because he knows his mother is always ill and the family spends a lot of money on medicine.He keeps running every day.He becomes stronger and stronger.He runs fastest in his class.Last week there was a sports meeting in his school.Li Lei ran faster than any other boy and got the first place in the boys'1,500meters.Now he's famous in the whole school.His classmates and teachers were very proud of him.He was happy,too.He ran home fast to tell his parents about the good news.56.Li Lei is thirteen years old.A57.Li Lei runs to school in the morning.A58.Li Lei's father bought him a bike.B59.Li Lei is often late for school.B60.Li Lei got the first place in the boys'1,500meters last week.A.【解答】答案:56.A 细节判断题.根据Li Lei is thirteen now.李磊现在是十三.可知李磊十三岁时正确的.故答案为A.57.A 细节判断题.根据He has to get up early in the morning and run to school.他早上必须起得很早然后跑着上学.可知李磊早上跑着上学是正确的.故答案为A.58.B 细节判断题.根据He wants to borrow some money to buy a bike for him.Li Lei doesn't agree.他想借些钱给他买了一辆自行车.李磊没有同意.可知李磊的爸爸没有买,故答案为B.59.B 细节判断题.根据He is never late for school.他上学从不迟到.可知他经常迟到是错误的.故答案为B.60.A 细节判断题.根据Li Lei ran faster than any other boy and got the first place in the boys'1,500 meters.李磊在男子1500米长跑中比其他任何男孩跑的都快获得了第一名.李磊了上周在男孩的1500米获得第一名是正确的.故答案为A.34.(5分)Eating habits are different in many countries.The Chinese have a saying,"Eat good things for breakfast,eat a big meal for lunch,but eat less at dinner."Many Americans agree that one should start the day with a good breakfast,but their ideas about lunch and dinner are different.Most Americans only give themselves a short time for lunch.So they eat a small meal.After work they will have more time to eat a big dinner.Also a quiet dinner at home with all the family members,talking about their day is a way to rest after a long,hard day of work.Eating at restaurant is also different.In China,people like to talk and laugh while eating.Very often you can hear people talking and laughing loudly,and they are justhaving a good time.In America it is not like this.People want a quiet place where they can eat a good meal far away from the noise of the outside world.If some people are talking too loudly,the manager(经理)may come out and ask them to leave.61.Which is the good way for keeping healthy in China?CA.Eating nothing for breakfast.B.Eating less to lose weight.C.Eating less at dinner.62.How long do most Americans only give themselves for lunch?CA.The whole noon.B.A long time.C.A short time.63.Talking at table isn't a way to rest in America,is it?AA.Yes,it is.B.No,it isn't.C.No.They aren't.64.What do people like doing when we are having a meal in China?A A.Talking and laughing.B.Having a rest.C.Only eating quietly.65.What will the manager of the restaurant do if some people are talking too loudly in America?BA.Talk with them happily.B.Let them go away.C.Do nothing.【解答】61 C 细节理解题.根据第一段The Chinese have a saying,"Eat good things for breakfast,eat a big meal for lunch,but eat less at dinner."中国有句谚语:"早饭要吃得好,午饭要吃得饱,晚饭要吃得少."由此可知,这是中国的养生之道.故选C.62 C 细节理解题.根据第二段Most Americans only give themselves a short time for lunch绝大多数美国人只给自己很短的时间吃午饭.可知应选C.63 A 推理判断题.根据第二段Also a quiet dinner at home with all the family members talking about their day is a way to rest after a long,hard day of work在家里安安静静地吃饭,和家人一起聊聊这一天也是辛苦劳累后的一种休息方式.可知在餐桌上聊天在美国也是一种休息.故选A.64 A 细节理解题.根据第三段In China,people like to talk and laugh while eating.在中国,人们喜欢边吃边聊边笑.故选A.65 B 细节理解题.根据第三段If some people are talking too loudly,the manager (经理)may come out and ask them to leave.如果有人说话声音太响,经理会走出来叫他们离开.可知应选B.35.(5分)Sam's Snack Bar(汤姆的小吃店)OPENING HOURS:11:00am~10:00pm (weekdays)12:00am~8:00pm (weekends)The followings are some of the set meals(套餐)in the bar.Pay only two more yuan to change small fries to large fries!根据表格信息,选择正确答案.66.David wants two cheese burger meals,two vegetable salad meals and a chicken nuggets meal.How much should he pay?AA.¥112.B.¥108.C.¥102.67.According to Question 66,how much more does David have to pay if he wants all the meals with large fries?CA.¥10.B.¥8.C.¥6.68.Mandy likes chicken very much.How many meals may she like?B A.Two.B.Three.C.Four.69.Amanda would like to have more vegetables for her lunch because she is on diet.Which meal should she order(点菜)?CA.Meal 2.B.Meal 4.C.Meal 5.70.Which of the following is TRUE?CA.The snack bar only opens on weekdays.B.All the set meals have soup.C.The snack bar doesn't open before 11:00am.【解答】66.A细节理解题.根据广告中第一个Meal 1:chicken nuggets(鸡块)+small fries(薯条)+drink¥18;及Meal 5:vegetable salad(沙拉)+soup¥24,两个花费48元;Meal 3:cheese burger+small fries+drink¥23,两个花费46元.可知一共花费112元.故选A.67.C细节理解题.根据广告中Pay only two more yuan to change small fries to large fries!可知每个加2元可以换成大的,三个就是加6元.故选C.68.B细节理解题.根据短文中Meal 1:chicken nuggets(鸡块)+small fries(薯条)+drink¥18;Meal 2:chicken burger(汉堡包)+small fries+drink;Meal 4:fried chicken rice+soup 可知喜欢吃鸡肉的话可以吃三种这种饭.故选B.69.C细节理解题.根据广告中Meal 5:vegetable salad(沙拉)+soup可知要多吃蔬菜可以点第五种菜.故选C.70.C细节理解题.根据文中OPENING HOURS:11:00 am~10:00 pm (weekdays);12:00 am~8:00 pm (weekends)可知这个小店在11点之前是不开门的.故选C.36.(10分)Whoever you are or wherever you come from,one thing is clear:you know the mosquito(蚊子)very well.Mosquitoes fly everywhere.They can be found almost all over the world,and there are more than 2,500kinds of them.No one loves the mosquito.But the mosquito may decide that she loves you.She?Yes.It is true that only the female(雌性的)mosquito bites because she needs blood to lay eggs.She is always looking for things or people she wants to bite.If she likes what she finds,she bites.But if she doesn't like your blood,she will turn to someone more delicious.Next time a mosquito bites you,just remember that you are chosen.You are different from the others!If the mosquito likes you,she lands on your body without letting you know.She bites you so quickly and quietly that you may not have known anything is happening.After she bites,you will have an itch(发庠)on your body because she puts something from her mouth together with your blood.By the time the itching begins,she has gone.And then what happens?Well,after her delicious dinner,the mosquito feels tired.She just wants to find a place to rest.There,on a leaf or a wall,she begins to lay eggs,hundreds of eggs!。

生物高考模拟卷-高三生物试题及答案-柳州市2015届高中毕业班3月份模拟考理科综合

生物高考模拟卷-高三生物试题及答案-柳州市2015届高中毕业班3月份模拟考理科综合

柳州市2015届高中毕业班3月份模拟考试题理科综合(考试时间:150分钟;满分:300分)第I卷选择题(共126分)一、选择题:本题共13小题,每小题6分,在每小题给出的四个选项中,只有一项是符合题目要求的。

1.下列关于物质运输的叙述,错误的是A.协助扩散过程中,需要载体蛋白协助,但不需要ATP供能B.人的红细胞吸收葡萄糖的过程,需要载体蛋白和ATP供能C.质壁分离复原过程中,水分子内流导致细胞内渗透压降低D.胰岛素分泌过程中,囊泡膜经融合成为细胞膜的一部分1.B 【解析】协助扩散是物质从高浓度一侧运输到低浓度一侧,需要载体蛋白的协助,但是顺浓度梯度进行,不需要消耗细胞内化学反应所释放的能量。

人体红细胞吸收葡萄糖是协助扩散。

质壁分离复原过程中,水分子内流导致细胞内溶剂相对增多,渗透压降低。

胰岛素分泌过程属于胞吐,高尔基体产生的囊泡到达细胞膜时,囊泡膜与细胞膜融合,成为细胞膜的一部分。

2.右图是基因型为Aabb的某生物细胞。

关于该细胞的叙述,错误的是A.该细胞具有中心体⑨,可以判断该细胞一定不是高等植物细胞B.④是一个染色体,包含两个染色单体①、③,并含有两个双链DNAC.细胞中有两对同源染色体,一对是④和⑦,另一对是⑤和⑥D.若④上有一对基因A与A,则⑦上的基因一定是a与a2.D 【解析】高等植物细胞没有中心体,A项对;④是已经复制过的一条染色体,含有两条姐妹染色单体,每条姐妹染色单体中各有一个DNA分子,B项对;该细胞具有两对同源染色体,分别是④和⑦、⑤和⑥,C项对;若④上有一对基因A与A,则⑦上的基因可能是a与a,也可能由于基因突变而成为A与a甚至是A与A,D项错。

3.真核生物基因中编码蛋白质的序列被一些不编码蛋白质的序列隔开,每一个不编码蛋白质的序列称为一个内含子。

某同学获取了某基因的双链DNA片段及其mRNA,并通过加热使DNA双链分开成单链后,与mRNA按照碱基配对原则形成双链分子,如下图所示。

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柳州市2015届高中毕业班3月份模拟考试题理科综合参考答案1.B 【解析】协助扩散是物质从高浓度一侧运输到低浓度一侧,需要载体蛋白的协助,但是顺浓度梯度进行,不需要消耗细胞内化学反应所释放的能量。

人体红细胞吸收葡萄糖是协助扩散。

质壁分离复原过程中,水分子内流导致细胞内溶剂相对增多,渗透压降低。

胰岛素分泌过程属于胞吐,高尔基体产生的囊泡到达细胞膜时,囊泡膜与细胞膜融合,成为细胞膜的一部分。

2.D 【解析】高等植物细胞没有中心体,A 项对;④是已经复制过的一条染色体,含有两条姐妹染色单体,每条姐妹染色单体中各有一个DNA 分子,B 项对;该细胞具有两对同源染色体,分别是④和⑦、⑤和⑥,C 项对;若④上有一对基因A 与A ,则⑦上的基因可能是a 与a ,也可能由于基因突变而成为A 与a 甚至是A 与A ,D 项错。

3.C 【解析】DNA 中有四种碱基AGCT, mRNA 有四种AGCU ,配对类型有三种,分别是A —U 、T —A 、C —G ,故A 错;由于该基因中出现了7个配对环,说明该基因中存在7个内含子,是真核基因,真核基因只能在细胞核内转录、细胞质中翻译,故B 错、C 对;逆转录过程中,mRNA 上的每一个核糖核苷酸与脱氧核苷酸是一一互补配对的,不能出现配对环,故D 错。

4.B 【解析】血糖平衡调节存在A →B →C →D →E 过程,属于神经—体液调节,还存在A →C →D →E 过程,属于体液调节。

5.A 【解析】“个体在生活空间中的位臵或布局”是在种群水平上的描述;“在同一地段上呈镶嵌分布”、“ 不同物种通过种间关系形成有机整体”、“ 物种数目的多少称为丰富度”都是在群落水平上描述。

6.D 【解析】减数第一次分裂有一对同源染色体未分开或是减数第二次分裂有一对姐妹染色单体未分开,而是移向了同一极,这样形成的异常配子和正常减数分裂形成的配子结合成的受精卵,都可发育而成三体。

基因型DDd 个体产生配子的比例为Dd ∶D ∶DD ∶d =2∶2∶1∶1,与基因型为dd 的个体杂交,后代基因型比例DDd ∶dd ∶Ddd ∶Dd =1∶1∶2∶2,故正常叶型∶马铃薯叶型=5∶1。

7.A 【解析】硅酸钠的水溶液俗称水玻璃,硅酸钠不能燃烧,不易挥发,能用作木材防火剂,故A 正确;无磷洗涤剂是在洗涤剂的成分中去掉了导致水污染的磷元素,它不会降低碳排放,故B 错误;铁、铜和海水构成了原电池,较活泼的金属铁作负极,铜作正极,负极上易失电子被腐蚀,所以加铜后能加快铁的腐蚀,故C 错误;汽油不完全燃烧的生成物是CO ,氮的氧化物与汽油是否完全燃烧无关系,故D 错误。

8.C 【解析】因为氯代烃和醇都可以发生消去反应,ClH 6C 3-有以下几种结构: CH 3CH 2CHCl 、CH 3CHClCH 2、CH 2ClCH 2CH 2、CCH 3ClCH 3、CH 3CHCH 2Cl5种;—C 2H 5O 有以下结构:-CH 2CH 2OH 、CHOHCH 3、—OCH 2CH 3、 —CH 2—O —CH 3,4种,两种基团连接苯环的对位,故有4×5=20种,故答案选C 。

9.B 【解析】一个苯乙烯分子中只含一个碳碳双键,苯环中并不含碳碳双键,A 项错误;加热条件下,4.6 g 金属Na 与足量O 2反应生成0.1 mol Na 2O 2,Na 2O 2中的阴离子是O 2-2,故产物中阴离子的数目为0.1N A ,B 项正确;盐类水解促进水的电离,CH 3COONa 溶液中的OH -完全来自于水的电离,故室温条件下,pH =9、体积为1 L 的CH 3COONa 溶液中,发生电离的水分子数为1.0×10-5N A ,C 项错误;铁与水蒸气反应生成Fe 3O 4,Fe 元素化合价可看作从0升高至+83,故转移电子的物质的量为16.8 g/(56 g·mol -1)×83=0.8 mol ,D 项错误。

10.D 【解析】Ba(OH)2与NaHSO 4按物质的量之比1∶2反应,正确的离子方程式为:Ba 2++2OH -+SO 2-4+2H +===BaSO 4↓+2H 2O ,故A 错误;硫离子水解只写第一步:S 2-+H 2OHS -+OH -,故B 错误;当二氧化硫少量时,产物是亚硫酸根离子和HCO -3,故C 错误;D 、氧化亚铁溶于稀硝酸发生氧化还原反应,合理且满足守恒关系,故D 正确。

11.D 【解析】乙烧杯中亚铁离子变铁离子发生氧化反应,A 错;甲烧杯中高锰酸根离子在酸性介质中,转化成锰离子和水,消耗氢离子,pH 增大,B 有误;电池工作时,乙杯中因亚铁离子变铁离子,负电荷减少,正电荷增多,故硫酸根离子会移向乙烧杯,C 错。

12.C 【解析】A.加热时,①上部汇集了固体NH 4Cl ,是由于加热时氯化铵分解生成氨气和氯化氢,氨气和氯化氢在试管的顶部反应生成氯化铵,不是NH 4Cl 的热稳定性比较好,故A 错误;B.加热时氨气逸出,②中颜色为无色,冷却后氨气溶解,②中为红色,加热时,③溶液变红,冷却后又变为无色,故B 错误;C.2NO 2(g)N 2O 4(g) ΔH =-92.4 kJ/mol ,正反应为放热反应,升高温度,平衡向逆反应方向移动,则颜色变深,④中浸泡在热水中的容器内气体颜色变深,浸泡在冰水中的容器内气体颜色变浅,故C 正确;D.氯化铵受热分解,与氨气和氯化氢反应生成氯化铵都不是可逆反应,因前者须加热,后者只要在常温下就可发生,故D 错误。

13.A 【解析】AgCl 浊液中滴加氨水后可得到澄清溶液的事实证明B 结论成立;浊液中有AgCl(s),必有AgCl(s)Ag +(aq)+Cl -(aq),C 正确;加入浓硝酸后,Ag ++2NH 3〃H 2O[Ag(NH 3)2]++2H 2O 逆向移动,导致AgCl(s)Ag +(aq)+Cl -(aq)逆向移动,D 成立。

14.D 【解析】 测出引力常量的是卡文迪许,A 错。

伽利略的理想实验只证明了力不是使物体运动的原因,B 错。

法拉第通过对变化的电流、变化的磁场、运动的恒定电流、运动的磁铁、磁场中的运动导体等进行归类,得到了电磁感应的产生条件,C 错。

库仑用相同的金属球平分电荷得到了库仑定律,D 对。

15.D 【解析】甲做竖直上抛运动,对应高度为h 1=10 m ;乙做自由落体运动,对应高度为h 2=20 m 。

故高度差为10 m 。

16.D 【解析】由G Mm r 2=m v 2r =m ⎝⎛⎭⎫2πT 2r =ma 有A 、B 、C 错。

由E k =12m v 2=GMm 2r 得D 对。

17.B 【解析】对系统有a 1=mg -f M +m,a 2=mg -f M ,所以a 2>a 1;F 1=mg -ma ,F 2=mg ,所以F 2>F 1,故选B 。

18.C 【解析】根据粒子a 、b 动能相同,12m a v 2a =12m b v 2b ;a 粒子在磁场中运动的轨迹半径r a =d 3,b 粒子在磁场中运的动轨迹半径r b =d ,粒子a 在磁场中运动轨迹所对的圆心角为120°,轨迹弧长为s a =2πr a 3=2πd 33,运动时间t a =s a v a ;b 粒子在磁场中运动轨迹所对的圆心角为60°,轨迹弧长为s b =πr b 3=πd 3,运动时间t b =s b v b=t a ;联立解得为a 、b 两粒子的质量之比为m a ∶m b =3∶4,选项C 正确。

19.ABC 【解析】由原线圈u 的表达式可得A 对。

由变压比可得副线圈上电压为U 2=1101 100×100 V =10 V ,故R 中电流为I 2=U 2R=0.1 A ,B 错。

由能量守恒得功率为P =I 2U 2=1 W ,C 对。

由E m =nΔΦm Δt , 有ΔΦm Δt =E m n =E m1n 1=E m2n 2,∴ΔΦm Δt=112110 Wb/s =210 Wb/s ,D 错。

20.BD 【解析】因电子的电势能在减小,故电场力做正功,电子逆着电场线运动,故C 错,D 对。

由F 电x =ΔE k =-ΔE p ,F 电为定值,F 电=Ee ,E 为定值,A 错,B 对。

21.AD 【解析】速度选择器是通过电场力与洛伦兹力平衡来实现,A 正确。

因打在β处的粒子不带电,B 错。

由y =12〃qE m〃t 2可知C 错,D 对。

22.(6分)(1)2.30(2分) (2)mgs AB =12(M +m )⎣⎡⎦⎤⎝⎛⎭⎫d Δt 22-⎝⎛⎭⎫d Δt 12(2分) (3)AD(2分)【解析】(1)由图乙知第6条刻度线与主尺刻度线对齐,d =2 mm +6×0.05 mm =2.30 mm 。

(2)钩码的重力势能减少了mgs AB ,系统的动能增加了12(M +m )v 22-12(M +m )v 21,滑块通过光电门的速度v =d Δt ,可知验证本系统机械能守恒的表达式为mgs AB =12(M +m )⎣⎡⎦⎤⎝⎛⎭⎫d Δt 22-⎝⎛⎭⎫d Δt 12。

(3)本实验中验证系统的机械能守恒不需要满足M ≫m ,气垫导轨未调水平、两光电门间距过小、遮光条宽度太大等会增大实验误差。

23.(9分)(1)不明显(1分) (2)串联R 0相当于电源内阻大了,能起到保护电源和减小实验误差的作用(1分)(3)R 1(2分) (4)如右图所示(2分)(5)r =U 2-U 1I 1-I 2-R 0(2分) (6)尽可能多测几组U 、I 值,分别求出每组的E 、r 值,最后求平均值(或作U -I 图象利用图线在坐标轴上截距求出E 、r )(1分)24.(12分)【解析】(1)根据题述传感器A 显示的示数为660 N ,可知轿厢地板对乘客的支持力为F =660 N ,对乘客,由牛顿第二定律知:F -mg =ma (1分)解得轿厢上升的加速度a =1 m/s 2方向竖直向上。

设F 1、F 2分别为牵引钢丝对轿厢和牵引钢丝对对重的拉力大小根据题述,F 1=13 200 N ,F 2=9 000 N设轿厢质量为M ,对轿厢和乘客整体,根据牛顿第二定律得F 1-(M +m )g =(M +m )g (1分)解得M =1 140 kg(1分)设对重质量为m 0,根据牛顿第二定律得m 0g -F 2=m 0a (1分)解得m 0=1 000 kg 。

(1分)(2)方法1:轿厢上升2 s ,上升高度h =12at 2=2 m 。

(2分) 速度v =at =2 m/s(2分)对重下降高度为h ′=h =2 m ,对重速度v ′=v =2 m/s对重减小的机械能ΔE =m 0gh ′-12m 0v ′2(2分) ΔE =1 000×10×2 J -12×1 000×22 J =18 kJ 。

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