12级概率A卷
12级原理课( A 卷)试题
12级原理课( A 卷)试题一、单项选择题(30小题,每小题1分,共30分;每小题只有一个正确答案。
)1、作为中国共产党和社会主义事业指导思想的马克思主义,是指()A、从广义上理解的马克思主义B、从狭义上理解的马克思主义C、马克思、恩格斯所创立的理论体系D、马克思、恩格斯、列宁的理论体系2、马克思主义理论体系的基础部分是()A、科学社会主义B、马克思主义哲学C、马克思主义政治经济学D、马克思主义社会学3、恩格斯第一次明确指出:全部哲学,特别是近代哲学的重大的基本问题是()A、人与客观世界的关系问题B、思维与存在的关系问题C、思维与实践的关系问题D、人与社会的关系问题4、列宁对辩证唯物主义物质范畴的定义是通过()A、物质与意识的关系界定的B、个别与一般的关系界定的C、哲学与具体科学的关系界定的D、认识与实践的关系界定的5、古诗云:“风定花犹落,鸟鸣山更幽”,它反映的哲学观点是()A、物质运动的具体形式是复杂多样的B、运动的绝对性和静止的相对性C、空间的无限性D、时间的无限性6、中国古代哲学家张载提出“凡可状皆有也,凡有皆象也,凡象皆气也”。
这是()A、形面上学的观点B、古代朴素唯物主义的观点C、主观唯心主义的观点D、辩证唯物主义的观点7、下列成语中体现质量互变规律的是()A、晕而风,础润而雨B、有无相生,前后相随C、千里之堤,溃于蚁穴D、将欲取之,必先予之8、唯物辩证法的实质和核心是()规律A、联系与发展B、质量互变C、否定之否定D、对立统一9、感性认识和理性认识是辩证统一的,统一的基础是()A、认识B、事实C、世界D、实践10、主体和客体的关系,从根本上说是()A、认识关系和实践关系B、认识和被认识的关系C、改造和被改造的关系D、价值关系和审美关系11、1978年关于真理标准大讨论是一场新的思想解放运动,实践之所以成为检验真理的唯一标准是由()A、真理的主观性和实践的客观性所要求的B、真理的本性和实践的特点所决定的C、真理的属性和实践的功能所规定的D、真理的相对性和实践的决定性所规定的12、实用主义鼓吹“有用就是真理”,把“有用”与“真理”完全等同起来,从根本上否定了()A、相对性B、价值性C、客观性D、实践性13、认识运动过程的第一次飞跃是()A、感性认识到理性认识的飞跃B、理性认识到实践的飞跃C、真理向价值的飞跃D、谬误向真理的飞跃14、价值评价的对象本质是()A、价值主体的需要B、价值客体的属性和功能C、主体和客体之间的价值关系D、主体和客体之间的事实关系15、人类社会历史发展的决定力量是()A、生产方式B、地理条件C、社会意识D、人口因素16、历史上杰出人物的产生()A、纯粹偶然的B、纯粹必然的C、偶然与必然的统一D、有的是偶然有的是必然17、“英雄造时势”与“时势造英雄”这两种观点()A、两者都是英雄史观的命题B、前者是唯物史观,后者是唯心史观C、前者是唯心史观,后者是唯物史观D、两者都是唯物史观的命题18、在同一劳动时间内,由于劳动生产率的提高,生产出的商品数量和单位价值量都发生了变化,这种变化表现为()A、商品数量增加,单位商品价值量减少B、商品数量减少,单位商品价值量增大C、商品数量增加,单位商品价值量不变D、商品数量减少,单位商品价值量不变19、私有制商品经济的基本矛盾是()A、简单劳动和复杂劳动的矛盾B、必要劳动和剩余劳动的矛盾C、具体劳动和抽象劳动的矛盾D、私人劳动与社会劳动的矛盾20、“我们从小麦的滋味中根本无法判断他是封建农民生产的,还是资本主义制度下农业工人生产的。
天津城建大学12级土木及地下专业基础工程试卷-A-参考答案(1)(最新整理)
加载阶段、卸载阶段、 动力固结阶段 。 6. 计算地下水位以下的土、水压力,有 水土合算 和 水土分算 两种方法。 7. 从重力式挡土墙墙背受力情况分析, 仰斜 式主动土压力最小, 俯斜 式主
动土压力最大。
8. 基坑工程包括了围护体系的设置和 土方开挖 两个方面。 9. 土工合成材料的在工程中应用十分广泛,按其功能划分包括反滤、 排水 、防 渗、
5. 减轻不均匀沉降危害的建筑措施有哪些?
3. 什么是群桩效应?什么是群桩效应系数?
答:由两根以上的桩组成的桩基础称为群桩基础(1 分),在竖向荷载作用下,由于承台、 桩、土相互作用,群桩基础中的一根桩单独受荷时的承载力和沉降形状,往往与相同地质条 件和设置方法的同样独立单桩有显著区别,这种现象称为群桩效应(1 分),因此群桩基础的
承载力(Qg)常不等于其中各根单桩的承载力之和( Qi ),通常用群桩效应系数 Qg Qi
来衡量群桩基础中各根单桩的平均承载力比独立单桩降低(η<1)或提高(η>1)的幅度(3 分)。
答:(1)建筑物的体型应力求简单,体型简单的建筑物,其整体刚度大,抵抗变形的能 力强;(1 分)
(2)控制建筑物的长高比及合理布置墙体,长高比大的砌体承重房屋,其整体刚度差, 纵墙很容易因挠曲而开裂;(1 分)
A 加大基础埋深,减小基础底面积 B 减小基础埋深,加大基础底面积
C 加大基础埋深,加大基础底面积 D 减小基础埋深,减小基础底面积
3、浅埋基础设计时,属于正常使用极限状态验算的是( B ) 。
A 持力层承载力
B 地基变形
C 软弱下卧层承载力
D 地基稳定性
2021年12月大学英语CET四级预测押题卷一和答案解析
2021年12月四级考试预测押题卷(一)Part I Writing(30minutes)Directions:For this part,you are allowed30minutes to write a letter to offer your suggestions to your cousin who sought your advice on how to make his resume distinctive.You should write at least120words but no more than 180words.Part II Listening Comprehension(25minutes)Section ADirections:In this section,you will hear three news reports.At the end of each conversation,you will hear four questions.Both the news report and the questions will be spoken only once.After you hear a question,you must choose the best answer from the four choices marked A),B),C)and D).Then mark the corresponding letter on Answer Sheet1with a single line through the centre.Questions1and2are based on the news report you have just heard.1.A)Two.B)Three.C)Four.D)Five.2.A)He called the police after the accident.B)He broke his arm in the accident.C)He was caught taking drugs.D)He was arrested by the police.Questions3and4are based on the news report you have just heard.3.A)A cure to brain cancer.B)A new surgical instrument.C)A pen that can identify cancerous tissue.D)A new drug that can eliminate cancerous tissue.4.A)Finding the border between the cancerous and normal tissue.B)Identifying the accuracy rate of the new device.C)Improving their speed of removing a tumour.D)Using the new device in brain surgery.Questions5to7are based on the news report you have just heard.5.A)To collect scientific data on it.C)To take photos of the storm on it.B)To monitor the storm on it.D)To investigate its environment.6.A)It has lasted for nearly350years.B)It has lasted for more that350months.C)It seems to be getting smaller.D)It seems to be getting larger.7.A)What initially caused the storm.C)What is the impact of the storm.B)What is underneath the storm.D)What makes the storm last for so long.Section BDirections:In this section,you will hear two long conversations.At the end of each conversation,you will hear four questions.Both the conversation and the questions will be spoken only once.After you hear a question,you must choose the best answer from the four choices marked A),B),C),and D).Then mark the corresponding letter on Answer Sheet1with a single line through the centre.Questions8to11are based on the conversation you have just heard.8.A)It’s for disabled adults.B)It’s in a sports centre.C)It’s rewarding and challenging.D)It’s compulsive in her community.9.A)The skills they need.B)The products they have.C)The market they target.D)The language they require.10.A)Diversify markets and sales strategies.B)Reduce costs and jobs.C)Learn from other companies.D)Listen to the opinions of experts.11.A)The salary and the workload.B)The office hour and the penalty system.C)The welfare and the holiday system.D)The ethical policy and the carbon footprint.Questions12to15are based on the conversation you have just heard.12.A)Double-decker buses.B)The traffic in London.C)Bus routes.D)Travels in Britain.13.A)It has no windows.B)People get onto it at the front.C)It has two carriages.D)It is open at the back.14.A)Uncomfortable.B)Noisy.C)Dangerous.D)Shabby.15.A)Bendy buses can help reduce the traffic jam.B)Bendy buses are more environmentally friendly.C)Bendy buses are convenient for people in wheelchairs.D)Bendy buses are more popular among tourists.Section CDirections:In this section,you will hear three passages.At the end of each passage,you will hear some questions. Both the passage and the questions will be spoken only once.After you hear a question,you must choose the best answer from the four choices marked A),B),C)and D).Then mark the corresponding letter on Answer Sheet1 with a single line through the centre.Questions16to18are based on the passage you have just heard.16.A)They had four toes.B)They were not as big as dogs.C)They lived in South America.D)They lived in thick forests.17.A)They had long legs and a long tail.B)They were smaller and had front eyes.C)They began to eat grass as well as fruit.D)They were bigger and had long legs.18.A)They evolved into donkeys in Asia and Africa.B)They used their long legs to run south to South Africa.C)They began to eat apples on the North American plains.D)They preferred grass to fruit and vegetables.Questions19to21are based on the passage you have just heard.19.A)Being rejected by friends and teachers.B)Staying away from his native land.C)Adapting to new study expectations.D)Keeping a balance between study and job.20.A)Talking with older brothers or sisters.C)Starting a conversation with close friends.B)Having a casual talk with a college student.D)Playing with friends on the same sports team.21.A)Follow traditions of with a college student.C)Respect the customs of different colleges.B)Take part in as many activities as possible.D)Take others’advice as reference only.Questions22to25are based on the passage you have just heard.22.A)They tend to harm wildlife.C)They are thrown away everywhere.B)They are hardly recyclable.D)They are made from useless materials.23.A)It is fatal.B)It is weird.C)It is very serious.D)It is complicated.24.A)The sea creatures that have taken in then are consumed by humans.B)The ocean’s ecology has been polluted and affected humans.C)Humans eat the seabirds that have swallowed plastic particles.D)Humans consume the fish that have eaten sea creatures with them.25.A)Its use has been drastically reduced.C)Most products use natural materials.B)It is still an indispensable material.D)The use of plastic items will be charged.PartⅢReading Comprehension(40minutes)Section ADirections:In this section,there is a passage with ten blanks.You are required to select one word for each blank from a list of choices given in a word bank following the passage.Read the passage through carefully before making your choices.Each choice in the bank is identified by a letter.Please mark the corresponding letter for each item on Answer Sheet2with a single line through the centre.You may not use any of the words in the bank more than once.Questions26to35are based on the following passage.A third of the planet’s land is severely degraded and fertile soil is being lost at the rate of24bn tonnes a year, according to a new United Nations-backed study that calls for a shift away from destructively intensive agriculture, The alarming____26____,which is forecast to continue as demand for food and productive land increases,will ass to the risks of conflicts unless____27____actions are implemented,warns the institution behind the report.“As the ready supply of healthy and productive land dries up and the population grows,competition is ___28___for land within countries and globally,”said executive secretary of the UN Convention to Combat Desertification(UNCCD)at the launch of the Global Land Outlook.“To___29____the losses,the outlook suggests it is in all our interests to step back and rethink how we are managing the pressures and the competition.”The Global Land Outlook is____30____as the most comprehensive study of its type,mapping the interlinked impacts of urbanization,climate change,erosion and forest loss.But the biggest factor is the___31___of industrial farming.Heavy tilling,multiple harvests ans___32____use of agrochemicals have increased yields at the____33____of long-term sustainability.If the past20years,agricultural production has increased threefold and the amount of irrigated land has doubled,notes a paper in the outlook by the Joint Research Centre(JRC)of the European commission.Over time,however,this___34___fertility and can lead to abandonment of land and ___35___desertification.A)absorb I)limitedB)abundant J)minimizeC)billed K)occasionallyD)decline L)optimizesE)diminishes M)rateF)expansion N)remedialG)expense O)ultimatelyH)intensifyingSection BDirections:In this section,you are going to read a passage with ten statements attached to it.Each statement contains information given in one of the paragraphs.Identify the paragraph from which the information is derived. You may choose a paragraph more than once.Each paragraph is marked with a letter.Answer the questions by marking the corresponding letter on Answer Sheet2.Take Naps at Work.Apologize to No One[A]In the past two weeks I’ve taken three naps at work,a total of an hour or so of shut-eye while on the clock.And I have no shame or uncertainty about doing it.I couldn’t feel better about it,and my productivity reflects it,too.[B]Sleeping on the job is one of those workplace taboos-like leaving your desk for lunch or taking an afternoon walk-that we’re taught to look down on.If someone naps at2p.m.while the rest of us furiously write memos and respond to emails,surely it must mean they’re slacking off(偷懒).Or so the assumption goes.[C]Restfulness and recharging can take a back seat to the perception and appearance of productivity.It’s easier to stay on a virtual hamster(仓鼠)wheel of activity by immediately responding to every email than it is to measure aggregate productivity over a greater period of time.But a growing field of occupational and psychological research is building the case for restfulness in pursuit of greater productivity.[D]Companies are suffering from tremendous productivity problems because people are stressed out and not recovering from the workday,said Josh Bersin,Principal and Founder of Bersin by Deloitte.“They’re beginning to realize that this is their problem,and they can’t just say to people,‘Here’s a work-life balance course,go teach yourself how to manage your inbox,’”Mr.Bersin said.“It’s way more complicated than that.”[E]To be sure,the ability to nap at work is far from widespread,experts said.Few among us have the luxury of being able to step away for a half-hour snoozefest.But lunch hours and coffee breaks can be great times to duck out,and your increased productivity and alertness will be all the evidence you need to make your case to inquiring bosses.[F]In an ideal world,we’d all solve this problem by unplugging early and getting a good night’s sleep. Here’s our guide on how to do just that.But the next best thing is stealing away for a quick power nap when you’re dragging after lunch.[G]In a study published in Nature Neuroscience,researchers tested subjects on their perceptual performance four times throughout the day.Performance deteriorated with each test,but subjects who took a30-minute nap between tests stopped the deterioration in performance,and those who took a60-minute nap even reversed it.[H]“Naps had the same magnitude of benefits as full nights of sleep if they had a quality of nap.”said Sara Mednick,a co-author of the study and associate professor of psychology at the University of California,Riverside.[I]Dr.Mednick,a sleep researcher and the author of Take a Nap!Change Your Life,said daytime napping can have many of the benefits of overnight sleep,and different types of naps offer specific benefits.[J]For example,Dr.Mednick said a20-to60-minute nap might help with memorization and learning specific bits of information.It’s just long enough to enter stage-two sleep,or non-rapid eye movement(R.E.M.)sleep.[K]After60minutes,you start getting into R.E.M.sleep,most often associated with that deep,dreaming state we all enjoy at night R.E.M.sleep can improve creativity,perceptual processing and highly associativethinking,which allows you to make connections between disparate ideas,Dr.Mednick said.Beyond that,your best bet is a90-minute nap,which will give you a full sleep cycle.[L]Any nap,however,can help with alertness and perception and cut through the general fog that creeps in during the day,experts said.[M]So how did we even arrive at this point where aptitude is inextricably tied(紧密相连)to working long, concentrated hours?Blame technology,but think broader than smartphones and laptops;the real issue is that tech has enabled us to be available at all times.[N]“We went through a period where people were in denial and business leaders were ignoring it,”Mr. Bersin said.“They were assuming that if we give people more tools,more emails,more Slack,more chatter,and we’ll just assume they can figure out how to deal with it all.And I think they’ve woken up to the fact that this is a big problem,and it is affecting productivity,engagement,health,safety,wellness and all sorts of things.”[O]It isn’t just office workers who can benefit from an afternoon siesta(午睡).A2015study published in Current Biology looked at the at the sleeping habits of three hunter-gatherer preindustrial societies in Tanzania, Namibia and Bolivia.[P]“They’re active in the morning,then they get in the shade under the trees and have a sort of quiet time, but they’re not generally napping,”said Jerome Siegel,professor of psychiatry and biobehavioral sciences,and director of the U.C.L.A.Center for Sleep Research,a co-author of the study.“Then they do some work and go to sleep,and they sleep through the night.”[Q]Still,Mr.Siegel said,“the only genuine way to solve daytime sleepiness and fatigue starts the night before with a solid night’s sleep.”The real Holy Grail of restfulness is a regular sleep schedule with ideally seven or eight hours of sleep each night,which experts say is optimal.[R]“Daytime napping certainly does increase alertness,”Mr.Siegel said.“But it’s not as simple as going to the gas station and filling the tank.”[S]He also advises avoiding caffeine late in the day and waking around the same time every morning,even if you can’t get to sleep at the same time every night,This helps acclimate(使适应)your body to your regular wake-up time,regardless of how much sleep you got the night before.[T]So if you’ve made it this far and you’re interested in giving workday naps a try(or just starting to nod off),here’s a quick guide to the perfect nap;Find a quiet,unoccupied space where you won’t be disturbed.Try to make your area as dim as possible(or invest in a sleep mask you can keep in the office).Earplugs might help.too.Aim for around20minutes.Any longer than that and you’re likely to wake up with sleep inertia(睡眠惰性),which will leave you even groggier(头脑昏沉的)than before.36.Participants’perceptual performance became better after sleeping one hour between tests in an article inNature Neuroscience.37.Jerome Siegel found that only by sleeping soundly through the previous night could people tackle theirweariness during the day.38.Our talent is closely bound to working with concentration for long periods of time because technologymakes us accessible24/7.39.Taking a nap at work is normally regarded as laziness that should be held in contempt and avoided inworkplace.40.Between20to60minutes,people can get into non-REM sleep which may improve memory and learningability according to Dr.Mednick.41.People can doze off at lunch and coffee breaks and defended themselves by saying their improvedproductivity and alertness when bosses investigated their whereabouts.42.The author’s tips on taking a perfect nap involve sleeping place,environment and duration.43.The author believes business leaders are aware that availability at any time due to technology has negativeeffects on every aspect of people’s life.44.The optimal length of a nap was an hour and a half so that people could go through a complete sleep cycle.45.Josh Bersin mentioned the cause of companies’big productivity problems and the solution which needsmore that just employees’efforts.Section CDirections:There are2passages in this section.Each passage is followed by some questions or unfinished statements.For each of them there are four choices marked A),B),C)and D).You should decide on the best choice and mark the corresponding letter on Answer Sheet2with a single line through the centre.Passage OneQuestions46to50are based on the following passage.Every office worker hates meetings.But it’s a strange sort of hate,similar to the hatred of Londoners for the Northern Line,or New Yorkers for tourists who walk too slowly:the dislike is real,yet if the despised thing were to vanish,it’d be like surrendering a piece of your soul.When researchers probed into why people put up with the strain that meetings place on their time and sanity, they found something-those who resent and dread meetings the moat also defend them as a“necessary evil”, sometimes with great passion.True,research suggests that meetings take up vastly more of the average manager’s time than they used to.True,done badly,they’re associated with lower levels of innovation and employee wellbeing(幸福).But that’s just office life,right?It’s not supposed to be fun.That’s why they call it work.Underlying(引起)this attitude is an assumption that’s drummed into us not just as workers but as children, parents and romantic partners;that more communication is always a good thing.So suggestions abound for(大量存在)communicating better in meetings-for example,hold them standing up,so speakers will come to the point more quickly.But even when some companies consider abolishing meetings entirely,the principle that more communication is better isn’t questioned.If anything,it’s reinforced when such firms introduce“flat”management structures,with bosses always available to everyone,plus plenty of electronic distraction.In fact,constant connectivity is disastrous for both job satisfaction and the bottom line.And anyway,once you give it three seconds’thought,isn’t it cleat that more communication frequently isn’t a good thing?Often,the difference between a successful marriage and a second-rate one consists of leaving about three or four things a day unsaid.At work,it’s surely many more than four,though for a different reason;office communication comes at the cost of precisely the kind of focus that’s essential to good work.Yet we’re so accustomed to seeing talking as a source of solutions-for resolving conflicts or finding new ideas-that it’s hard to see when it is the problem.46.What does the author say about meetings?A)Londoners hate them as well as the Northern Line.B)They can help to keep workers’physical and spiritual health.C)Workers might be reluctant to give up them completely.D)New Yorkers dislike meetings more than Londoners.47.What did researchers find about people’s attitude towards meeting?A.Their attitude and behavior are paradoxical.B)People who hate meetings the most are senior insane.C)Those who like meetings might be considered insane.D)More meetings are regarded as a sign of less innovation.48.Why do people think that more communication is always a good thing?A)Because the concept is firmly believed by workers.B)Because everyone loves to communicate with others.C)Because the idea has been instilled into people’s mind.D)Because communication is vital for building relationships.49.What does the author think of the“flat”management structure?A)It forces bosses to frequently contact their employees.B)It helps to soften employees’bottom line of work.C)It is definitely a disaster to employees’job satisfaction.D)It strengthens people’s deeply-rooted notion of communication.50.What is the author’s argument about office communication?A)It is an effective way to solve office conflicts.B)It affects work efficiency in a negative way.C)It should come to a halt at intervals.D)It is useful for workers to find new ideas.Passage TwoQuestions51to55are based on the following passage.The Internet has enabled the spread of information at lightning speed.This information revolution has created tremendous business opportunities for online publishers,but not all of them maintain proper quality-control mechanisms to ensure that only good information is being shared.Instead,many publishers aim simply to make money by whatever means possible,with no regard for the implications for society at large.When selfish publishers set up shops online,the primary goal is to publish as much as possible,often at the cost of quality.In this respect,many publishers start numerous online journals focused on overlapping(重叠的)disciplines—to increase their total number of published papers—and hire young business managers who do not have any experience in either science or publishing.In some cases,online publishers even give up peer review, while still presenting themselves as scientific journals—deception designed to take advantage of scientists who simply want to share their research.If publishers structure their business to make more revenue,it often does harm to their products.When publishers start journals with overlapping domains,in combination with the pressure to publish more studies,this could promote the publication of marginal or even questionable articles.Moreover,publishers with multiple overlapping journals and journals with very narrow specialties(专业)increase the demands on the time and efforts of willing reviewers.With the fact that reviewers are generally not compensated for their time and effort,journal editors are often unable to find enough reviewers to keep up with the increased publication rate.To improve the situation and increase the trust in scientific community,the pressure to publish must be reduced.Funding and promotion decisions should not be based on the number of publications,but on the quality of those publications and a researcher’s long-term productivity and instructions.And that’s just the start.We need additional mechanisms,such as Beall’s list of predatory(掠夺的)publishers, to alert scientists to fake journals and fake articles.In addition,the price for online publication must be controlled and a mechanism must be put in place to honor and reward hard-working reviewers.51.What does the author think of online publishers?A)A small proportion of them can guarantee their publishing quality.B)They have lots of opportunities to renovate their business models.C)Many of them tend to try every means to make a buck.D)Social impact is their first priority when publishing books.52.It can be inferred from the second paragraph that______.A)peer review generally is a criterion to identify academic journalsB)researchers focus their research on the combination of disciplinesC)scientists care about their publications rather than researchD)young business managers are willing to face new challenges53.Why can’t publishers find enough reviewers to review papers?A)Reviewers are pressed for time when reviewing articles.B)Reviewers’gains can’t make up for what they have done.C)Publishers may compel reviewers to accept marginal articles.D)Publishers urge reviewers to increase publication rate rapidly.54.What is the author’s suggestion for online publication?A)More weight should be put on the quantity of publications.B)It is worthwhile to reward diligent reviewers for their effort.C)Fake journals should be reported to a regulatory organization.D)The price of online publication should be lowered greatly.55.What is the main idea of this passage?A)Online publishers should take measures to fight against fake scientific journals.B)Online publishers are pursuing their work efficiency at the cost of quality.C)Online publishers business models are quite likely to harm their publications.D)Online publishers are sacrificing the quality of research articles to make money.PartⅣTranslation(30minutes)Directions:For this part,you are allowed30minutes to translate a passage from Chinese intoEnglish.You should write your answer on Answer Sheet2.春节是中国的传统节日,相当于美国的圣诞节。
12级一年级大专试卷A
2011-2012学年度第一学期宿迁经贸学院期末考试2012级大专班数学期末试题(A )(共三大题21小题,满分100分,考试时间90分钟)2013年1月一、选择题(只有一项答案符合题意,共10题,每题4分,共40分) 1、N 是自然数集,Z 是整数集,则下列表述正确的是( )。
A. N=ZB. N ∈ZC. N ∉ZD. N ⊆Z2、如果a>b ,下列不等式不一定成立的是( )(c ≠0) A. b <a B. a +c >b +cC. ac 2>bcD. ac 2 bc 23、a 32-用根式表示为( )。
A. -32a; B. -a3; C.321a ; D.a314、不等式| x |<2的解集为( )。
A. (-2,2)B. (-∞,-2)∪ (2,+∞)C. (-∞,-2)D. (2,+∞)5、lg5+lg2=( )。
A. 25B.32;C.10;D. 16、lg N=-2改写成指数形式是( )。
A.N =12- ;B.12-=N;C. N =102-;D. 210-=N7、下列函数是偶函数的是( )。
A. y =x +2B. y =x 2C. y = 2xD. y =2x8、已知二次函数f (x )=x 2+2x -3,则f (2)=( )。
A. 5B. -3C. -5D. 39、下列函数在区间(0, +∞)上是减函数的为( )。
A. y =3B. Y=1/xC. Y=x 2D. Y=x10、一元二次不等式x 2-5>0的解集为( )。
班级__________ 姓名___________ 学号___________A. (- 5 , 5 )B. (-∞, - 5 ) ∪( 5 ,+∞)C. (-∞, - 5 )D. ( 5 , +∞)二、填空题(每空2分,共20分)11、已知集合A={1,3,5,7,9}、B={7,9,11},则A∩B=______________,A ∪B______________。
哈理工12级单片机试题A
哈尔滨理工大学 2014-2015 学年第 一 学期考试试题 A 卷 系: 自动化 出题教师: 仲伟峰 系主任:考试科目:单片机原理及应用 考试时间: 100 分钟试卷总分:100分一、单项选择题(每小题1分,共15分) 1、 80C51系列单片机中片内具有8KFlash ROM 的机型是( )。
(A )80C51 (B )87C51 (C )89C52 (D )80C52 2、 80C51单片机复位时,RST 引脚应当接( )。
(A )低电平 (B )高电平 (C )悬空 (D )XTAL1 3、 在80C51单片机的4个I/O 口中,能作为通用I/O 口和数据总线口的是( )。
(A )P0 (B )P1 (C )P2 (D )P3 4、 当优先级的设置相同时,若以下几个中断同时发生,( )中断优先响应。
(A )INT1 (B )T1 (C )串行通信口 (D )T0 5、 指令MOV A, @R0中,R0的取值范围为( )。
(A )00H-1FH (B )00H-7FH (C )00H-FFH (D )80H-FFH 6、 在中断服务程序中,至少应有一条( )。
(A )SJMP 指令 ( B )LJMP 指令 (C )RETI 指令 (D) RET 指令 7、8051单片机复位后,执行PUSH ACC 指令,则栈指针SP 的内容为( )。
(A )08H (B )80H (C )00H (D )07H 8、80C51单片机入栈操作的顺序是( )。
(A )SP-1,然后数据入栈 (B )数据入栈,然后SP-1 (C )SP+1,然后数据入栈 (D )数据入栈,然后SP+1 9、若使定时器T0工作在最长时间的定时方式,则应选择( )。
(A )方式0 (B )方式1 (C )方式2 (D )方式3 10、80C51单片机向外部RAM 输出的指令是( )。
(A )MOV 2000H , A (B )MOV @R0, A (C )MOVX A, @DPTR (D )MOVX @DPTR ,A11、若单片机执行NOP 指令的周期为1us ,则单片机的晶振频率为( )。
12级专科英语卷第二学期A
包头医学院2012~2013学年第二学期2012级专科英语(二)考试试卷(A)Part I Vocabulary & Structure (15%)Directions: Choose the appropriate answer from the four choices marked A, B, C andD.1. As soon as you decide on the _____ of the new building, please let us know.A. locationB. areaC. regionD. situation2. She is always a big star at parties because she has a(n) ________ of her own in clothing.A. styleB. exampleC. fashionD. model3. Of the six people injured in the accident, only two ________.A. killedB. lastedC. damagedD. survived4. He _____ his knowledge of radio just by standing around the radio station.A. picked outB. picked upC. took outD. took up5. The washing machine’s so I have to wash all our clothes by hand.A. broken outB. broken inC. broken upD. broken down6. I wasn’t sure if I could such a powerful car.A. careB. handle C catch D hold7. We fell in love with the house at first _____.A. viewB. sightC. lookD. seeing8. The _ of the book is to provide a complete guide to the university.A. abilityB. directionC. purposeD. possibility9. What’s the most _____ way of building a bridge?A. economicB. economicalC. economyD. economically10. After graduation they kept with each other.A. writingB. contactingC. correspondingD. informing11. A good student must _____ what he reads from books with what he sees around him.A. combineB. contactC. relateD. refer12. She had _____ herself that life was worth living.A. persuadedB. believedC. undertookD. considered13. After a long _____ for the murder weapon, the police found a knife.A. searchB. lookC. studyD. examination14. We were really by the way you treat your classmates.A. informedB. urgedC. connectedD. disturbed15. If you want to operate the machine properly, you’d better look at me carefully and do_____.A. alikeB. likewiseC. likelyD. samePart II Working with Expressions(20%)Directions: Fill in each of the blanks in the following sentences with a suitable preposition or adverb.16. The matter has nothing to do _______ him; he was just doing his job.17. If you are interested in this line______ thinking, please read this book for more details.18. Unfortunately, the hat I had just bought was no longer ________fashion.19. The trend at the moment is ________ a more natural and less made-up look.20. Thanks ________ our medical knowledge, this terrible disease is much less commonnow.21. Will you apply________ the job by letter or in person?22. Our math teacher is very nice, as he never seems tired________ answering ourquestions at any time and at any place.23. Last night the storm was so heavy that the roof of the small house was blown_______.24. Many people believe he died ________ working too hard.25. ________ this day, I still have fresh memories of my life in that small, quiet town.26. I want to go ________ education when I leave college.27. You may need to pay a price ________ making your dream come true.28. When the children grow up, they usually feel most comfortable ________ the kinds offood they had in their own homes.29. It has been hard to adjust________ the idea of being a waitress but now I’m gettingsatisfaction from work.30. The medicine needs to be taken________ a daily basis.31. She was scared to see two strange men wandering ________ near her apartmentbuilding.32. This job can best be described________ boring. I don’t want to do it any more.33. Mothers are well known________ considering the needs of the family more importantthan their own interests.34. All the police officers were equipped ________ guns to defend themselves against thecriminals.35. The factory is faced ________ many problems as a result of years of badmanagement(管理)Part III Cloze (15%)Directions:There are 15 blanks in the following passage. For each blank there are four choices marked a), b), c) and d) on the right side of the paper. You shouldchoose the ONE that best fits into the passage.When I was growing up, I had an old neighbor named Dr Gibbs. He didn’t look like anydoctor I’d 36 known. He never shouted at us for playing in his yard. When Dr Gibbs wasn’t 37 lives, he was planting trees. His house 38 on ten acres(英亩), and his life’s goal was to make it a 39 .The good doctor had some 40 theories about planting trees. He never 41 his new trees. Once I 42 why. He said that watering plants spoiled them, and that 43 you watered them, each successive(继承的) tree generation would grow weaker and weaker.44 , you had to make things 45 for them. He talked about how watering trees made for shallow roots, and how trees that weren’t watered had to grow 46 roots.Dr Gibbs died a couple of years after I left home. Sometimes, I walked by his __47__ and looked at the trees that I’d watched him _48__ twenty-five years ago. They’re very __49__ now.I planted a couple of trees a few years back. I carried water to them for a solid summer. Two years of looking after them had 50 in the fact that the trees expected to be waited on hand and foot. How weak they were!Every night before I go to bed, I check on my two sons. I stand over them and watch their little bodies, the rising and falling of life within. If often pray for them. Mostly I pray that that their lives will be easy. But lately I’ve been thinking that it’s time to change my prayer. There’s always a cold wind blowing somewhere. So I’m changing my prayer because life is tough, whether we want it to be or not.36. a) ever b) never c) always d) often37. a) wasting b) reducing c) saving d) storing38. a) built b) sat c) covered d) shared39. a) lake b) garden c) zoo d) forest40. a) terrible b) puzzling c) interesting d) disappointing41. a) watered b) cared c) fed d) missed42. a) explained b) knew c) understood d) asked43. a) if b) whether c) unless d) though44. a) However b) Therefore c) Anyhow d) Anyway45. a) easy b) comfortable c) rough d) suitable46. a) shallow b) long c) short d) deep47. a) factory b) company c) village d) house48. a) buy b) sell c) plant d) destroy49. a) weak b) strong c) thick d) beautiful50. a) resulted b) led c) called d) madePart IV Reading Comprehension (30%)Directions: After reading the following passages, you will find 10 questions or unfinished statements. For each question or statement there are 4 choices marked A), B), C), or D). You should make the correct choicePassage 1The United States covers a large part of the North American continent. Its neighbors are Canada to the north and Mexico to the south. Although the United States is a big country, it is not the largest in the world. In 2000, its population was over 222 million.When this land first became a nation, after winning its independence from England, it had thirteen states. Each of the states was represented (代表) on the American flag by a star. All these states were in the eastern part of the continent. As the nation grew toward the west, new states were added and new stars appeared on the flag. For a long time, there were 48 stars. In 1959, however, two more stars were added to the flag, representing the new states of Alaska and Hawaii.Indians were the first people of the land which is now the United States. There are still many thousands of Indians now living in all parts of the country. Sometimes it is said that the Indians are “the only real Americans”. Most Americans come from all over the world. Those who came first in greatest numbers to make their homes on the eastern coast of North America were mostly from England. It is for that reason that the language of theUnited States is English and that its culture and customs are more like those of England than those of any other country in the world.51. Which of the following is TRUE?A. America is the largest country in the world.B. the United States lies next to Canada and Mexico.C. America covers most part of the North American continent.D. Mexico is to the north of Canada.52. After winning its independence, the United States _______.A. had nothing to do with EnglandB. made India part of its landC. mainly developed westwardD. took over parts of Canada and Mexico53. The United States didn’t have _______ states until________.A. thirteen; 1959B. fifty; 1959C. fifty; this land first became a nationD. fifty; 196454. Why is English the language of America?A. English is the native language of the Indians.B. Most Americans come from all over the world.C. Most of the people who first settled in America were from England.D. Canada is America’s nearest neighbor.55. The best title for the passage is “______________”.A. The States of AmericaB. The Language of AmericaC. The United States of AmericaD. The Culture and Customs of AmericaPassage 2A friend of mine named Paul received an expensive car from his brother as a Christmas present. On Christmas Eve when Paul came out of his office, a street urchin (顽童) was walking around the shining car. “Is this your car, Paul?”he asked.Paul answered, “Yes, my brother gave it to me for Christmas.”The boy was surprised. “You mean your brother gave it to you and it didn’t cost you anything? Boy, I wish .…”He hesitated.Of course Paul knew what he was going to wish for. He was going to wish he had a brother like that. But what the boy said surprised Paul greatly.“I wish,”the boy went on, “that I could be a brother like that.”Paul looked at the boy in surprise, then he said again, “Would you like to take a ride in my car?”“Oh yes, I’d love that.”After a short ride, the boy turned and with his eyes shining, said, “Paul, would you mind driving in front of my house?”Paul smiled a little. He thought he knew what the boy wanted. He wanted to show his neighbors that he could ride home in a big car. But Paul was wrong again. “Will you stop where those two steps are?”the boy asked.He ran up to the steps. Then in a short while Paul heard him coming back, but he was not coming fast. He was carrying his little crippled (残疾) brother. He sat him down on the step and pointed to the car.“There she is, Buddy, just like I told you upstairs. His brother gave it to him for Christmas and it didn’t cost him a cent. And some day I’m going to give you one just like it …then you can see for yourself all the nice things in the Christmas windows that I’ve been trying to tell you about.”Paul got out and lifted the boy to the front seat of his car. The shining-eyed older brother climbed in beside him and the three of them began an unforgettable holiday ride.56. The street urchin was very surprised when ________.A. Paul received an expensive carB. Paul told him about the carC. he saw the shining carD. he was walking around the car57. From the story we can see the urchin ________.A. wished to give his brother a carB. wanted Paul’s brother to give him a carC. wished he could have a brother like Paul’sD. wished Paul could be a brother likethat58. The urchin asked Paul to stop his car in front of his house ________.A. to show his neighbors the big carB. to show he had a rich friendC. to let his brother ride in the carD. to tell his brother about his wish59. We can infer(推断)from the story that ________.A. Paul couldn’t understand the urchinB. the urchin had a deep love for hisbrotherC. the urchin wished to have a rich brotherD. the urchin’s wish came true in theend60. Paul gave the brothers a ride probably because _________.A. he was free during the Christmas holidayB. he thought he should help allcrippled peopleC. he was moved by the older brother’s wishD. he wanted to take them to buyChristmas giftsPassage 3Like most people, I was brought up to look upon life as a process of getting. It was not until in my late thirties that I made this important discovery: giving-away makes life so much more exciting. You need not worry if you lack money. This is how I experimented with giving-away. If an idea for improving the window display of a neighborhood store flashes to me, I step in and make the suggestion to the storekeeper. One discovery I made about giving-away is that it is almost impossible to give away anything in this world without getting something back, though the return often comes in an unexpected form. One Sunday morning the local post office delivered an important special delivery letter to my home, though it was addressed to me at my office. I wrote the postmaster a note of appreciation. More than a year later I needed a post-office box for a new business I was starting. I was told at the window that there were no boxes left, and that my name would have to go on a long waiting list. As I was about to leave, the postmaster appeared in the doorway. He had overheard (无意中听到) our conversation. “Wasn’t it you that wrote us that letter a year ago about delivering a special delivery to your home?”I said yes. “Well, you certainly are going to have a box in this post office if we have to make one for you. You don’t know what a letter like that means to us. We usually get nothing but complaints.”61. From the passage, we understand that ____________.A. the author did not understand the importance of giving until he was in late thirtiesB. the author was like most people who were mostly receivers rather than giversC. the author received the same education as most people during his childhoodD. the author liked most people as they looked upon life as a process of getting62. According to the author, ______________.A. giving means you will have less moneyB. the excitement of giving can bring you moneyC. you don’t have to be rich in order to giveD. when you give away money, you will be rich63. The author would make the suggestion to the storekeeper ______________.A. in writingB. in personC. in the window displayD. about the neighborhood64. When the author needed a post-office box, _______________.A. he had to put his name on a waiting listB. he wrote the postmaster a note of appreciationC. many people had applied for post-office boxes before himD. he asked the postmaster to make one for him65. In reply to the postmaster’s question, the author said _____________.A. it was the special deliveryB. it was the post-office boxC. it was the note of appreciation he wroteD. it was he who wrote him a letter a year agoPart V Translation (10%).66. 房子着火了,里面的人面临着死亡的危险。
(完整版)厦门理工概率论课件信号与系统复习练习题(12级)
一、选择题1、f (5-2t )是如下运算的结果( C )。
A .f (-2t )右移5 B .f (-2t )左移5 C .f (-2t )右移25 D .f (-2t )左移252.已知f (t )的频带宽度为Δω,则f (2t-4)的频带宽度为( A )。
A . 2Δω B . ∆ω/2 C . 2(Δω-4) D . 2(Δω-2)3.已知信号f (t )的频带宽度为Δω,则f (3t-2)的频带宽度为( A )。
A .3Δω B .Δω/3 C .(Δω-2)/3 D .(Δω-6)/6 4.连续周期信号f (t )的频谱F(j ω)的特点是( D )。
A .周期、连续频谱 B .周期、离散频谱 C .连续、非周期频谱 D .离散、非周期频谱5.信号f (t )=Sa (100t ),其最低取样频率fs 为( A )。
A . 100/π B . 200/π C .π/100 D .π/2006.系统函数H (s )与激励信号X (s )之间( B )。
A .是反比关系;B .无关系;C .线性关系;D .不确定。
7.线性时不变系统输出中的自由响应的形式由( A )决定。
A .系统函数极点的位置; B .激励信号的形式; C .系统起始状态; D .以上均不对。
8.线性时不变系统输出中的自由响应的形式由( A )决定。
A .系统的结构参数; B .系统激励信号的形式; C .系统起始状态; D .以上均不对。
9.信号⎪⎭⎫ ⎝⎛+=34cos 3)(πt t x 的周期是( C )。
(A )π2 (B )π (C )2π (D )π210. 设f(t)=0,t<3,则信号f(1-t)+ f(2-t)为0的t 值是( C )。
(A )t>-2或 t>-1 (B )t=1和t=2 (C )t>-1 (D )t>-2 11. 设f(t)=0,t<3,则信号f(1-t)× f(2-t) 为0的t 值是( D )。
2011-2012汽车电工识图 期末考卷A
苏州市电子信息技工学校11-12第二学期期终考试试卷科目:12级汽车电工识图卷型:A型(闭卷)
出卷人:汤彬文审卷人:肖玉梅教研组:电子组班级:姓名:学号:得分:_______
一、填空题
1、写出下列图形符号所表示的元器件的名称或含义。
(58×1=58分)
2、画出正确的图形符号。
动合(常开)触点光敏电阻时钟指示仪表灯
光电二极管电压表传感器尾灯传感器信号发生器
3、写出下列文字符号。
照明灯蓄电池同步发电机电位器交流
电流互感器插头按钮开关电磁离合器电磁阀
4、说明下列文字符号含义。
EH FU1 KM PV GA
AD RV EV MS XJ
5、说明下列项目代号的含义。
⑴、=1-T1
⑵、=2+5-K3:4
⑶、=2+C4-M1
⑷、-XT:7
6、写出下列项目的项目代号。
⑴、1单元位置2中的变压器T2的3号端子
⑵、转数传感器的1号端子
⑶、301室B列1号机柜中的熔断器FU1
⑷、第二个复合项目中的温度传感器ST1
二、综合题。
(10分)
1、识读用连接线表示的单元接线图,并补全用中断线表示的单元接线图。
1)用连接线表示的单元接线图
2)用中断线表示的单元接线图
2、在指定位置将主视图画成剖视图。
(10分)。
2012级《模拟电子技术》期末试题A卷
四川工业管理职业学院2012~2013学年度下期12级电子设备与运行管理专业期末考试《模拟电子技术》试题(A卷)座位号:___(满分100分,120分钟完卷)一、填空题(共25空,每空1分,共25分)1、P型半导体中空穴为载流子,自由电子为载流子。
2、PN结正偏时,反偏时,所以PN结具有单向导电性。
3、反向电流是由载流子形成,其大小与有关,而与外加电压无关。
4、三极管是控制元件,场效应管是控制元件。
5、当温度升高时,三极管的集电极电流I C ,发射结压降U BE。
6、晶体三极管具有放大作用时,发射结,集电结。
7、三极管放大电路共有三种组态、共集电极、放大电路。
8、为了稳定三极管放大电路和静态工作点,采用负反馈,为了减小输出电阻采用负反馈。
9、负反馈放大电路的放大倍数A f= ,对于深度负反馈A f= 。
10、共模信号是大小,极性的两个信号。
11、乙类互补功放存在失真,可以利用类互补功放来克服。
12、要保证振荡电路满足相位平衡条件,必须具有网络。
13、在桥式整流电阻负载中,理想二极管承受最高反压是。
14、稳压二极管是利用二极管的__________特性工作的。
二、选择题(每题2分,共30分)1、PN结加反向电压时,其空间电荷区()A.变窄B.变宽C.不变D.不一定2、测得NPN型三极管上各电极对地电位分别为VE=2.1V,VB=2.8V,VC=4.4V,说明此三极管处在()A.放大区B.饱和区C.截止区D.反向击穿区3、某放大器的中频电压增益为40dB,则在上限频率处的电压放大倍数约为()A.43B.100C.37D.704、把差动放大电路中的发射极公共电阻改为电流源可以()A.增大差模输入电阻B.提高共模增益C.提高差模增益D.提高共模抑制比5、负反馈所能抑制的是()的干扰和噪声。
A.反馈环内B.输入信号所包含C.反馈环外D.不确定6、用集成运放组成模拟信号运算电路时,通常工作在()A.线性区B.非线性区C.饱和区D.截止区7、某迟滞比较器的回差电压为6V,其中一个门限电压为-3V,则另一门限电压为()A.3VB.-9VC.3V或-9VD.9V8、RC桥式振荡电路中,RC串并联网络的作用是()A.选频B.引入正反馈C.稳幅和引入正反馈D.选频和引入正反馈9、功率放大电路的输出功率大是由于()A.电压放大倍数大或电流放大倍数大B.电源电压高且输出电流大C.输出电压变化幅值大且输出电流变化幅值大D.负载电阻小且输出电流大10、若一个乙类双电源互补对称功率放大电路的最大输出功率为4W,则该电路的最大管耗约专业______________班级______________姓名______________学号______________为( )A .0.8WB .4WC .0.4 WD .无法确定11、某简单稳压电路要求稳定电压为8V ,而仅有7.3V 硅稳压管D Z 一只,二极管(硅管)D 一只,可采用D Z 与D 串联接入电路( )A .D 正偏,D Z 反偏B .D 反偏,D Z 反偏C .D 正偏,D Z 正偏 D .D 反偏,D Z 正偏 12、为了获得电压放大,同时又使得输出与输入电压同相,则应选用( )放大电路。
2012级概率论与数理统计课程考试卷A(含参考答案626)
湖南人文科技学院 数学系 数学与应用数学、信息与计算科学专业 2012 级2013---2014学年第二学期概率论与数理统计课程考试试卷A分钟一、单项选择题(本大题共5小题,每小题3分,共15分)在每小题列出的四个备选项中只有一个是符合题目要求的,请将其代码填写在题干的括号内。
多选无分。
1.设B A ,是任意2个事件,则=-)(B A P ( C).(A ))()(B P A P -; (B )()()()P A P B P AB -+;(C ))()(AB P A P -; (D ))()()(AB P B P A P -+.2.设n x x x ,,,21 是来自正态总体),(2σμN (σ未知)的样本,对均值μ考虑如下的检验0100::μμμμ≠=H vs H ,则显著性水平为α的拒绝域是( A )(记t =)A .2{;(1)}W t t t n α=≥- B.{;(1)}W t t t n α=≥-C.1{;(1)}W t t t n α-=≤- D .2{;(1)}W t t t n α=≤-3.设总体X ~2(1,)N σ,12,,,n X X X ⋅⋅⋅是取自总体X 的一个样本, 则为参数2σ的无偏估计量的是( A )(A) 211()1n i i X X n =--∑; (B) 211()ni i X X n =-∑; (C) 211nii X n =∑; (D) 2X4.若随机变量X 和Y 的协方差等于0,则以下结论正确的是( B ).)(A X 和Y 相互独立; )(B )()()(Y D X D Y X D +=+;)(C )()()(Y D X D Y X D -=-; )(D )()()(Y D X D XY D ⋅=.5设随机变量X 与Y 均服从正态分布,)5,(~),4,(~22μμN Y N X ;记},4{1-≤=μX p p }5{2+≥=μY p p ,则有( A).)(A 对任何实数μ,都有21p p =; )(B 对任何实数μ,都有21p p < ;)(C 只对个别μ值,才有21p p =; )(D 对任何实数μ,都有21p p >. 二、填空题(本大题共5小题,每小题 3分,共15分) 1.随机变量X ~)4,(μN ,且5)(2=X E ,则X 2(1)x ±-2.设Y X ,独立且均服从正态分布),0(2σN ,且41)2,2(=-≤≤Y X P ,则=->>)2,2(Y X P 14 . 3.设 ,n X X X ,,,21为独立同分布的随机变量序列,且),2,1( =i X i 服从参数为2的指数分布,则∞→n 当时,∑==n i i n X n Y 121依概率收敛于 12. 4. 设(1521,,,X X X )是来自正态总体()9,0N 的简单随机样本,则统计量 2152122112102221 21X X X X X X Y ++++++= 的概率分布是(10,5)F .(只填F分布得2分.) 5. 设总体n X X X N X ,,,),,(~212⋅⋅⋅σμ是来自X 的一个样本∑==n i i X n X 11,参数2,σμ都是未知的,则2σ的矩估计量为 22211()n n i i i i x x x x n n ==--∑∑或 三、判断题(每小题2分,共12分对的打“√”,错的打“×”) 1.设X ~(,1)N μ,则满足{}{}22P X P X >=≤的参数μ=2 (√ ) 2.设随机变量)1,0(~),1,0(~N Y N X ,则22Y X +服从2χ分布; (× ) 3. 设随机变量X 与Y 相互独立,且),(~1p n B X ,),(~2p n B Y ,则~Y X +)2,(21p n n B +;(× )4. 设A,B,C 是三个事件,如果有 ()()()()()()()()()P AB P A P B P BC P B P C P AC P A P C =⎧⎪=⎨⎪=⎩, 则称A,B,C 相互独立 ( × )5. 设0<P(A)<1,0<P(B)<1,且A 、B 两事件相互独立,则必有A 与B 互斥事件; (× )6. 设总体),(~2σμN X ,2σ未知,X 为样本均值,,)(1122∑=-=n i i n X X n S,)(11122∑=--=ni i X X n S 检验假设00:μμ=H 时采用的统计量是n X Z /0σμ-= ( × )(以下各题要有详细过程,只写结果不给分)。
2023-2024学年第一学期北师大版九年级数学上册第3章复习测试卷附答案
2023-2024学年第一学期九年级数学上册第3章【概率的进一步认识】复习测试卷一.选择题1.某中学初三年级四个班,四个数学老师分别任教不同的班.期末考试时,学校安排统一监考,要求同年级数学老师交换监考,那么安排初三年级数学考试时可选择的监考方案有()种.A.8B.9C.10D.122.经过某十字路口的汽车,可能直行,也可能向左转或向右转,如果这三种可能性大小相同,当三辆汽车经过这个十字路口时,至少有两辆汽车向左转的概率是()A.B.C.D.3.小颖有两顶帽子,分别为红色和黑色,有三条围巾,分别为红色、黑色和白色,她随机拿出一顶帽子和一条围巾戴上,恰好为红色帽子和红色围巾的概率是()A.B.C.D.4.现有4根木棒,长度分别为4cm、6cm、8cm、10cm,从中任取三根木棒,能够组成三角形的概率是()A.B.C.D.5.如图,随机闭合开关S1,S2,S3中的两个,则能让两盏灯泡同时发光的概率为()A.B.C.D.6.从﹣4,﹣1,2,3四个数中随机选取两个不同的数,分别记为a,c,则关于x的方程ax2+4x+c=0有两个不相等的实数根的概率是()A.B.C.D.7.从1,2,3三个数中取出一个数作为点P的横坐标,从4,5,6,7四个数中取出一个数作为点P的纵坐标,则点P落在直线y=﹣x+6上的概率是()A.B.C.D.8.一个盒子里有完全相同的三个小球,球上分别标上数字﹣1、1、2.随机摸出一个小球(不放回)其数字记为p,再随机摸出另一个小球其数字记为q,则满足关于x的方程x2+px+q=0有实数根的概率是()A.B.C.D.9.将一枚六个面编号分别为1、2、3、4、5、6的质地均匀的正方体骰子先后投掷两次,记第一次掷出的点数为a,第二次掷出的点数为c,则使关于x的一元二次方程ax2﹣6x+c=0有实数解的概率为()A.B.C.D.10.在一个不透明的袋子里装有红球,黄球共36个,这些球除颜色外都相同.小明通过多次试验发现,摸出红球的频率稳定在0.25左右,则袋子中红球的个数最有可能是()A.5B.9C.15D.2411.甲、乙两名同学在一次用频率去估计概率的试验中,统计了某一结果出现的频率,并绘出了如下折线统计图,则最有可能符合这一结果的试验的是()A.掷一枚正六面体的骰子,出现1点的概率B.抛一枚硬币,出现正面的概率C.任意写一个整数,它能被3整除的概率D.从一副去掉大小王的扑克牌中,任意抽取一张,抽到黑桃的概率二.填空题12.如图,有A、B、C三类长方形(或正方形)卡片(a>b),其中甲同学持有A、B类卡片各一张,乙同学持有B、C类卡片各一张,丙同学持有A、C类卡片各一张,现随机选取两位同学手中的卡片共四张进行拼图,则能拼成一个正方形的概率是.13.如图所示的电路图中,当随机闭合S1,S2,S3,S4中的两个开关时,能够让灯泡发光的概率为.14.将如图所示的两个转盘(A转盘被分成三等份,B转盘被分成四等份)各转动一次,当转盘停止后,指针所在区域(指针指向区域分界线时,需重新转动转盘)的数字之和为偶数概率是.15.一水库里有鲤鱼、鲫鱼、草鱼共2000尾,小明捕捞了100尾鱼,发现鲫鱼有35尾,估计水库里有尾鲫鱼.16.某养鱼专业户为了估计鱼塘中鱼的总条数,他先从鱼塘中捞出100条,将每条鱼作了记号后放回水中,当它们完全混合于鱼群后,再从鱼塘中捞出100条鱼,发现其中带记号的鱼有10条,估计该鱼塘里约有条鱼.三.解答题17.三人相互传球,由甲开始发球,并作为第一次传球.(1)用列表或画树状图的方法求经过3次传球后,球仍回到甲手中的概率是多少?(2)由(1)进一步探索:经过4次传球后,球仍回到甲手中的不同传球的方法共有多少种?18.某大学为了解大学生对中国共产党党史知识的学习情况,在大学一年级和二年级举行有关党史知识测试活动.现从一、二两个年级中各随机抽取20名学生的测试成绩(满分50分,30分及30分以上为合格;40分及40分以上为优秀)进行整理、描述和分析,给出了下面的部分信息.大学一年级20名学生的测试成绩为:39,50,39,50,49,30,30,49,49,49,43,43,43,37,37,37,43,43,37,25.大学二年级20名学生的测试成绩条形统计图如图所示;两个年级抽取的学生的测试成绩的平均数、众数、中位数、优秀率如下表所示:年级平均数众数中位数优秀率大一a b43m大二39.544c n请你根据上面提供的所有信息,解答下列问题:(1)上表中a=,b=,c=,m=,n;根据样本统计数据,你认为该大学一、二年级中哪个年级学生掌握党史知识较好?并说明理由(写出一条理由即可);(2)已知该大学一、二年级共1240名学生参加了此次测试活动,通过计算,估计参加此次测试活动成绩合格的学生人数能否超过1000人;(3)从样本中测试成绩为满分的一、二年级的学生中随机抽取两名学生,用列举法求两人在同一年级的概率.19.如图,甲、乙两个转盘均被分成3个面积相等的扇形,每个扇形中都标有相应的数字,同时转动两个转盘(当指针指在边界线上时视为无效,需重新转动转盘),当转盘停止后,把甲、乙两个转盘中指针所指数字分别记为x,y.请用树状图或列表法求点(x,y)落在平面直角坐标系第一象限内的概率.20.“共和国勋章”获得者钟南山院士说:按照疫苗保护率达到70%计算,中国的新冠疫苗覆盖率需要达到近80%,才有可能形成群体免疫.本着自愿的原则,18至60周岁符合身体条件的中国公民均可免费接种新冠疫苗.居民甲、乙准备接种疫苗,其居住地及工作单位附近有两个大型医院和两个社区卫生服务中心均可免费接种疫苗,提供疫苗种类如下表:接种地点疫苗种类医院A新冠病毒灭活疫苗B重组新冠病毒疫苗(CHO细胞)社区卫生服务中心C新冠病毒灭活疫苗D重组新冠病毒疫苗(CHO细胞)若居民甲、乙均在A、B、C、D中随机独立选取一个接种点接种疫苗,且选择每个接种点的机会均等.(提示:用A、B、C、D表示选取结果)(1)求居民甲接种的是新冠病毒灭活疫苗的概率;(2)请用列表或画树状图的方法求居民甲、乙接种的是相同种类疫苗的概率.21.现有分别标有1,2,3,4的四张扑克:(1)同时从中任取两张,猜测两数和为奇数的机会;(2)先从中任取一张,放回后搅匀再取一张,猜测两数和为奇数的机会.小明说(1)(2)中和为奇数的机会均等;小刚说(1)(2)中和为奇数的机会不均等,你认为他们俩谁的判断正确?请用画树状图或列表的方法说理.22.小杰和小明玩扑克牌游戏,各出一张牌比输赢.游戏的规则是:谁的牌数字大谁赢,同样大就平:A 遇2就输,遇其他牌(除A外)都赢.目前小杰手中A、K、J,小明手中有2、Q、J.(1)求出小明抽到的牌恰好是“2”的概率;(2)小杰、小明两人谁获胜的机会大?画出树状图,通过计算说明理由.23.将5个完全相同的小球分别装在甲、乙两个不透明的口袋中.甲袋中有3个球,分别标有数字2、3、4;乙袋中有2个球,分别标有2、4.从甲、乙两个口袋中各随机摸出一个球.用列表法或画树状图法,求摸出的两个球上数字之和为5的概率.24.在一个不透明的箱子中装有2个红球、n个白球和1个黄球,这些球除颜色外无其他差别.(1)若每次摸球前先将箱子里的球摇匀,任意摸出一个球记下颜色后再放回箱子里,通过大量重复摸球实验后发现,摸到红球的频率稳定在25%,那么估计箱子里白球的个数n为;(2)如果箱子里白球的个数n为1,小亮随机从箱子里摸出1个球不放回,再随机摸出1个球,请用画树状图或列表法求两次均摸到红球的概率.25.在一个不透明的口袋里装有只有颜色不同的黑、白两种颜色的球共30只,某小组做摸球实验,将球搅匀后从中随机摸出一个球记下颜色,再把它放回袋中,不断重复.下表是活动进行中的一组统计数据:摸球的次数n1001502005008001000…摸到白球的次数m5896116295484601…摸到白球的频率0.580.640.580.590.6050.601…(1)请估计:当n很大时,摸到白球的频率将会接近;(2)假如你去摸一次,你摸到白球的概率是,摸到黑球的概率是;(3)试估算口袋中黑、白两种颜色的球各有多少只?26.一个不透明的箱子里装有3个红色小球和若干个白色小球,每个小球除颜色外其他完全相同,每次把箱子里的小球摇匀后随机摸出一个小球,记下颜色后再放回箱子里,通过大量重复试验后,发现摸到红色小球的频率稳定于0.75左右.(1)请你估计箱子里白色小球的个数;(2)现从该箱子里摸出1个小球,记下颜色后放回箱子里,摇匀后,再摸出1个小球,求两次摸出的小球颜色恰好不同的概率(用画树状图或列表的方法).参考答案一.选择题1.解:设4个班级分别为A、B、C、D,相对应的4个老师分别为a,b,c,d.由图中可以看出,共有9种情况.故选:B.2.解:根据题意画图如下:一共有27种等可能的情况;至少有两辆车向左转的有7种,则至少有两辆车向左转的概率为:.故选:D.3.解:画树状图如图:,共有6个等可能的结果,恰好取到红色帽子和红色围巾的结果有1个,∴恰好取到红色帽子和红色围巾的概率为,故选:C.4.解:从中任取三根木棒所有可能的情况为(4、6、8),(4、6、10),(6、8、10),(4、8、10)4种情况,其中(4、6、8),(6、8、10),(4、8、10)这3种能构成三角形,所以能够构成三角形的概率是,故选:C.5.解:根据题意画图如下:∵共有6种等可能的结果,能让两盏灯泡同时发光的有2种情况,∴能让两盏灯泡同时发光的概率为:P==.故选:C.6.解:画树状图如图:共有12个等可能的结果,关于x的方程ax2+4x+c=0有两个不相等的实数根(16﹣4ac>0,即ac<4)的结果有8个,∴关于x的方程ax2+4x+c=0有两个不相等的实数根的概率为=,故选:D.7.解:根据题意画图如下:共有12种等可能的情况数,其中点P落在直线y=﹣x+6上的有2种,则点P落在直线y=﹣x+6上的概率是=.故选:D.8.解:画树状图得:∵x2+px+q=0有实数根,∴Δ=b2﹣4ac=p2﹣4q≥0,∵共有6种等可能的结果,满足关于x的方程x2+px+q=0有实数根的有(1,﹣1),(2,﹣1),(2,1)共3种情况,∴满足关于x的方程x2+px+q=0有实数根的概率是:=.故选:A.9.解:列表得:∴一共有36种情况,∵b=﹣6,当b2﹣4ac≥0时,有实根,即36﹣4ac≥0有实根,∴ac≤9,∴方程有实数根的有17种情况,∴方程有实数根的概率=,故选:D.10.解:设袋子中红球有x个,根据题意,得:=0.25,解得x=9,∴袋子中红球的个数最有可能是9个,故选:B.11.解:A、掷一枚正六面体的骰子,出现1点的概率为,故此选项不符合题意;B、掷一枚硬币,出现正面朝上的概率为,故此选项不符合题意;C、任意写一个整数,它能被3整除的概率为,故此选项符合题意;D、从一副去掉大小王的扑克牌中,任意抽取一张,抽到黑桃的概率,故此选项不符合题意;故选:C.二.填空题12.解:由题可得,随机选取两位同学,可能的结果如下:甲乙、甲丙、乙丙,∵a2+2ab+b2=(a+b)2,∴选择乙丙手中的卡片共四张进行拼图,则能拼成一个边长为(a+b)的正方形,∴能拼成一个正方形的概率为,故答案为:.13.解:设S1、S2、S3、S4分别用1、2、3、4表示,画树状图得:∵共有12种等可能的结果,能够让灯泡发光的有6种结果,∴能够让灯泡发光的概率为:=,故答案为:.14.解:根据题意画图如下:共有12个等可能的结果,指针所在区域(指针指向区域分界线时,需重新转动转盘)的数字之和为3的倍数偶数的结果有6个,则指针所在区域(指针指向区域分界线时,需重新转动转盘)的数字之和为偶数的概率为=.故答案为:.15.解:由题意可得,2000×=700(尾),即估计水库里有700尾鲫鱼,故答案为:700.16.解:∵100条鱼,带记号的鱼有10条,∴估计鱼塘中带记号的鱼的概率==,而鱼塘中带记号的鱼有100条,∴估计该鱼塘里约有鱼的条数=100÷=1000.故答案为1000.三.解答题17.解:(1)画树状图得:∵共有8种等可能的结果,经过3次传球后,球仍回到甲手中的有2种情况,∴经过3次传球后,球仍回到甲手中的概率是:=;(2)画树状图得:则经过4次传球后,球仍回到甲手中的不同传球的方法共有6种.18.解:(1)将一年级20名同学成绩整理如下表:成绩25303739434950人数1242542∴a=(25×1+30×2+37×4+39×2+43×5+49×4+50×2)=41.1,b=43,c==42.5,m=(5+4+2)÷20×100%=55%,n=(3+5+2+3)÷20×100%=65%,故答案为:41.1,43,42.5,55%,=65%;从表中优秀率看,二年级样本优秀率达到65%高于一年级的55%,因此估计二年级学生的优秀率高,所以用优秀率评价,估计二年级学生掌握党史知识较好.(2)∵样本合格率为:=92.5%,∴估计总体的合格率大约为92.5%,∴估计参加测试的两个年级合格学生约为:1240×92.5%=1147(人),∴估计参加此次测试活动成绩合格的学生人数能超过1000人;(3)一年级满分有2人,记为A,B,二年级满分有3人,记为C,D,E,画树状图如图:共有20种等可能的结果,两人在同一年级的结果有8种,∴两人在同一年级的概率为=.19.解:画树状图如图:共有9种等可能的结果,点(x,y)落在平面直角坐标系第一象限内的结果有4种,∴点(x,y)落在平面直角坐标系第一象限内的概率为.20.解:(1)居民甲接种的是新冠病毒灭活疫苗的概率为=;(2)画树状图如图:共有16种等可能的结果,居民甲、乙接种的是相同种类疫苗的结果有8种,∴居民甲、乙接种的是相同种类疫苗的概率为=.21.解:小刚的判断正确.(1)列表如下:第一张第二张12341(2,1)(3,1)(4,1)2(1,2)(3,2)(4,2)3(1,3)(2,3)(4,3)4(1,4)(2,4)(3,4)由上表可知,共有12种结果,每种结果出现的可能性相同,其中两数和为奇数的结果有8种.∴P(和为奇数)=;(2)列表如下:第一次第二次12341(1,1)(2,1)(3,1)(4,1)2(1,2)(2,2)(3,2)(4,2)3(1,3)(2,3)(3,3)(4,3)4(1,4)(2,4)(3,4)(4,4)由上表可知,其16种结果,每种结果出现的可能性相同,其中两数和为奇数的结果共有8种.∴P(和为奇数)=,∵,∴小刚的判断正确.22.解:(1)小明抽到的牌恰好是“2”的概率=;(2)他们获胜的机会一样大.理由如下:画树状图为:共有9种等可能的结果,其中小杰获胜的结果数为4,小明获胜的结果数为4,所以小杰获胜的概率=;小明获胜的概率=,而=,所以小杰、小明两人获胜的机会一样大.23.解:画图如下:共有6种等可能的结果数,其中摸出的两个球上数字之和为5的有1种,则摸出的两个球上数字之和为5的概率为.故答案为:.24.解:(1)根据题意知,=0.25,解得:n=5,经检验n=5是分式方程的解,即估计箱子里白球的个数n为5,故答案为:5;(2)列表得红1红2白黄红1(红2,红1)(白,红1)(黄,红1)红2(红1,红2)(白,红2)(黄,红2)白(红1,白)(红2,白)(黄,白)黄(红1,黄)(红2,黄)(白,黄)摸球的结果共有12种等可能结果,其中两次均摸到红球的有2种结果,∴P(两次均摸到红球)==.25.答:(1)根据题意可得当n很大时,摸到白球的频率将会接近0.60;(2)因为当n很大时,摸到白球的频率将会接近0.60;所以摸到白球的概率是0.6;摸到黑球的概率是0.4;(3)因为摸到白球的概率是0.6,摸到黑球的概率是0.4,所以口袋中黑、白两种颜色的球有白球是30×0.6=18个,黑球是30×0.4=12个;故答案为:(1)0.60;(2)0.6,0.4;26.解:(1)∵通过多次摸球试验后发现,摸到红球的频率稳定在0.75左右,∴估计摸到红球的概率为0.75,设白球有x个,根据题意,得:=0.75,解得x=1,经检验x=1是分式方程的解,∴估计箱子里白色小球的个数为1;(2)画树状图为:共有16种等可能的结果数,其中两次摸出的球恰好颜色不同的结果数为6,∴两次摸出的小球颜色恰好不同的概率为=.。
数据结构复习题及答案(12级)
一、选择题。
(每小题2分,共40分)(1) 计算机识别.存储和加工处理的对象被统称为____A____。
A.数据B.数据元素C.数据结构D.数据类型(2) 数据结构通常是研究数据的____ A _____及它们之间的联系。
A.存储和逻辑结构B.存储和抽象C.理想和抽象D.理想与逻辑(3) 不是数据的逻辑结构是____ A ______。
A.散列结构B.线性结构C.树结构D.图结构(4) 数据结构被形式地定义为<D,R>,其中D是____ B _____的有限集,R是____ C _____的有限集。
A.算法B.数据元素C.数据操作D.逻辑结构(5) 组成数据的基本单位是____ A ______。
A.数据项B.数据类型C.数据元素D.数据变量(6) 设数据结构A=(D,R),其中D={1,2,3,4},R={r},r={<1,2>,<2,3>,<3,4>,<4,1>},则数据结构A是____ A ______。
A.线性结构B.树型结构C.图型结构D.集合(7) 数据在计算机存储器内表示时,物理地址与逻辑地址相同并且是连续的,称之为___ C ____。
A.存储结构B.逻辑结构C.顺序存储结构D.链式存储结构(8) 在数据结构的讨论中把数据结构从逻辑上分为___ A ____。
A.内部结构与外部结构B.静态结构与动态结构C.线性结构与非线性结构D.紧凑结构与非紧凑结构(9) 对一个算法的评价,不包括如下____ B _____方面的内容。
A.健壮性和可读性B.并行性C.正确性D.时空复杂度(10) 算法分析的两个方面是__ A ____。
A.空间复杂性和时间复杂性B.正确性和简明性C.可读性和文档性D.数据复杂性和程序复杂性(11) 线性表是具有n个___ C _____的有限序列(n≠0)。
A.表元素B.字符C.数据元素D.数据项(12) 线性表的存储结构是一种____ B ____的存储结构。
保险学[12级金融学(金融学、会计学业余班)期末A卷
****学院继续教育学院《保险学》课程期末考试试卷( A ) 卷2013 —— 2014 学年第二学期闭卷系、专业、班级学号姓名一、单项选择题(每小题1分,共40分))。
A.行为风险因素B.客观风险因素C.道德风险因素D.有形风险因素2、保险方法最适用于对付哪种风险?()A.损失频率低,损失程度小B.损失频率高,损失程度小C.损失频率低,损失程度大D.损失频率高,损失程度大3、权利人因义务人不能履行诺言而遭受经济损失的风险是()A.财产风险 B.人身风险C.责任风险D.信用风险4、代表投保方的利益,与保险人洽谈签订保险合同,并向保险人收取佣金的是()A、保险代理人B、保险经纪人C、保险公司员工D、保险公估人5、纯粹风险是指( )。
A. 既有损失机会,又有获利可能的风险 B.只有获利可能而无损失机会的风险C.只有损失可能而无获利机会的风险 D.有导致重大损失可能的风险6、责任保险的保险标的是( )。
A.造成损害应负的一切责任 B.造成损害应负的民事赔偿责任或特别约定的合同责任C.造成损害应负的刑事责任 D.造成损害应负的行政责任7、下列属于保险合同当事人的是( )。
A.受益人B.保险代理人 C.投保人D.保险经纪人8、保险利益的载体是( )。
A.保险标的B.保险价值 C.保险金额D.被保险人9、保险承担赔偿或给付保险金的最高限额是( )。
A.保险金额B.保险价值 C.保险费 D.保险价格10、货物运输保险合同所承保的标的是一种流动标的,在不同的地方,其价值不一致,为此采用()方式。
A、定额保险B、定值保险C、不定值保险D、超额保险11、在人身保险合同中,投保人指定或变更受益人需经()同意。
A、保险人B、被保险人C、受益人D、继承人12、人寿保险的被保险人或受益人对保险人请求给付保险金的权利,自其知道保险事故发生之日起()内不行使而灭失。
A、半年B、1年C、2年D、5年13、在抵押贷款的财产保险时,银行以抵押权人名义对抵押品房屋投保,如果银行贷款10万元,房屋价值12万元,保险金额为12万元,当房子发生全损时则保险人对被保险人的赔偿金额为()。
2014概率论与数理统计 试卷(A)(1)
分
四、(12分)设随机变量 的概率密度函数为 ,求(1) 的分布函数 ;(2) ; (3) .
得
分
五、(12分)已知二维离散型随机变量 的联合概率分布如下:
X
0
1001来自(1)求 的边缘概率分布;(2)验证 的独立性;(3)求 的概率分布.
得
分
六、(10分)设随机变量 的联合概率密度函数为
求随机变量 的概率密度.
4.设 是相互独立的随机变量,且它们都服从参数为 的指数分布,记 ,利用中心极限定理计算得 .
(A) (B) (C) (D)
5.设 为总体 的一个样本, 为样本均值,则下列结论中正确的是
.
(A) (B)
(C) (D)
得
分
三、(12分)有甲、乙两个盒子,甲盒装有4个白球1个黑球,乙盒装有3个白球2个黑球.从甲盒中任取1个球,放入乙盒中,再从乙盒中任取2个球. (1)求从乙盒中取出的是2个黑球的概率; (2)已知从乙盒中取出的是2个黑球,求从甲盒中取出的是白球的概率.
得
分
七、(12分)设总体 服从参数为 的泊松分布:
,
为取自总体 的样本,求未知参数 的矩估计和极大似然估计.
得
分
八、(12分)
某工厂生产一批滚珠,其直径 服从正态分布 ,现从某天的产品中随机抽取9件,测得直径并计算出平均值 ,方差及标准差为 (1)求 的置信概率为0.95的置信区间;(2)当显著性水平 时,能否认为这批钢珠直径的标准差 .
得
分
二、单项选择题(每小题3分,共15分)
1.掷一颗骰子,观察出现的点数, 表示“出现2点”, 表示“出现奇数点”,则正确的是.
(A) (B) (C) (D)
西安财经学院12级统计学习题(1)
西安财经学院12级统计学习题(1)三章综合指标(⼀)某⼚14年A种车资料如下:计算A种车平均每辆成本。
(⼆)某车间第⼀批产品的废品率为1%,第⼆批废品率为1.5%,第三批废品为2%,第⼀批产品数量占总数的35%,第⼆批占40%。
试计算平均废品率。
计算该车间⼯⼈平均每⼈⽇产量。
(四)某⼚从不同地区购进三批相同材料资料如下:计算该⼚购进该种材料的平均每公⽄价格。
试计算⼯⼈平均⽇产量。
(六)2015年5⽉甲、⼄两市场商品价格、销售量和销售额资料如下:试分别计算商品在两个市场平均每件的销售价格。
(七)某⼚某车间⼯⼈产量分组资料如下:要求:计算该车间⼯⼈平均每⼈⽇产量、标准差。
答案(⼀)=fX xf∑∑=210×0.4+230×0.45+250×0.15=225(元/辆)(⼆)χ = ∑x∑ff=1%×35%+1.5%×40%+2%×25%= 1.45%(三)χ=∑∑f fχ=(5×10+6×28+7×35+8×31+9×16)÷(10+28+35+31+16) =855/120=7.125(件)(四)380004000022000=10()3800040000220009.51011m X m x ∑++==∑++元/公⽄(10分)(五)2002036021201?+?+?=?∑??∑=X =)/(5.1200/300⼈件=(六)(元/件)(元/件)(七)=(25×10﹢35×70﹢45×90﹢55×30)/(10﹢70﹢90﹢30) =42(公⽄)标准差=7.81(公⽄)四章动态数列(⼀) 某企业2015年⼆季度商品库存如下:(⼆)某商场2014年某些⽉分库存⽪鞋资料如下:计算该商场2009年⽪鞋⽉平均库存量。
(三)某企业2014年⼯业总产值为250万元,若平均每年的发展速度为110%,那么到2019年该企业的⼯业总产值可达多少万元?(四)根据动态指标间的关系,推算出表中空格数值,并填⼊表中。
2022-2023学年四川省成都市锦江区九年级(上)期末数学试卷(一诊)+答案解析(附后)
2022-2023学年四川省成都市锦江区九年级(上)期末数学试卷(一诊)1. 如图,是一个由长方体截去一部分后得到的几何体,其主视图是( )A.B.C.D.2. 下列函数中,y是x的反比例函数的是( )A. B. C. D.3. 若关于x的一元二次方程有一个解为,则另一个解为( )A. 1B.C. 3D. 44. 如图所示的两个四边形相似,则下列结论不正确的是( )A. B. C. D.5. 如图,已知在平面直角坐标系中,四边形ABCD是菱形,其中点B的坐标是,点D的坐标是,点A在x轴上,则点C的坐标是( )A.B.C.D.6. 一个不透明的箱子里装有m个球,其中红球3个,这些球除颜色不同其余都相同,每次搅拌均匀后,任意摸出一个球记下颜色后再放回,大量重复试验发现,摸到红球的频率稳定在附近,则可以估算出m的值为( )A. 10B. 15C. 20D. 257. 如图,在方格纸上,以点O为位似中心,把线段AB缩小到原来的,则点A的对应点为( )A. 点D或点GB. 点E或点FC. 点D或点FD. 点E或点G8. 如图,在矩形ABCD中,,对角线AC,BD相交于点点E,F分别是AO,AD的中点,连接EF,则的周长为( )A. 6B. 7C. 8D. 99. 若,则______ .10. 关于x的一元二次方程有两个不相等的实数根,则a的取值范围是______ .11. 已知点,都在反比例函数的图象上,且,和的大小关系为______ .12. 小颖将能够活动的菱形学具活动成为图1所示形状,接着,她又将这个学具活动成为并测得,,图2所示正方形,此时的长为______ .13. 如图,在中,,按以下步骤作图:①以点C为圆心,以适当的长为半径作弧.交CB于点D,交CA于点E,连接DE;②以点B为圆心,以CD长为半径作弧,交BA于点F;③以点F为圆心,以DE的长为半径作弧,在内与前一条弧相交于点G;④连接BG并延长交AC于点若H恰好为AC的中点,则AC的长为______ .14. 计算:;解方程:15. 中国共产党第二十次全国代表大会于10月16日至22日在北京举行,这是一次具有里程碑意义的大会,必将对中国和世界产生深远影响,某校积极组织学生学习二十大相关会议精神,并组织了二十大知识问答赛,将比赛结果分为A,B,C,D四个等级,根据如下不完整的统计图解答下列问题:求该校参加知识问答赛的学生人数;求扇形统计图中C级所对应的圆心角的度数;现准备从结果为A级的4人两男两女中随机抽取两名同学参加二十大宣讲,请用列表或画树状图的方法,求恰好抽到一名男生和一名女生参加宣讲活动的概率.16. 【学科融合】如图1,在反射现象中,反射光线,入射光线和法线都在同一个平面内;反射光线和入射光线分别位于法线两侧;反射角r等于入射角这就是光的反射定律.【同题解决】如图小红同学正在使用手电筒进行物理光学实验,地面上从左往右依次是墙、木板和平面镜,手电筒的灯泡在点G处,手电筒的光从平面镜上点B处反射后,恰好经过木板的边缘点F,落在墙上的点E处,点E到地面的高度,点F到地面的高度,灯泡到木板的水平距离,本板到墙的水平距离为图中点A,B,C,D在同一条直线上.求BC的长;求灯泡到地面的高度17. 如图1,▱ABCD的各内角的平分线分别相交于点E,F,G,求证:四边形EFGH为矩形;如图2,当▱ABCD为矩形时.①求证:四边形EFGH为正方形;②若,四边形EFGH的面积为8,求AB的长.18. 如图1,已知反比例函数的图象与一次函数的图象相交于,B两点.求反比例函数的表达式及A,B两点的坐标;是x轴上一点,N是y轴上一点,若以A,B,M,N为顶点的四边形是以AB为边的平行四边形,求点M的坐标;如图2,反比例函数的图象上有P,Q两点,点P的横坐标为,点Q的横坐标与点P的横坐标互为相反数,连接AP,AQ,BP,若的面积是的面积的3倍,求m的值.19. 已知一元二次方程的两个根为,,则的值为______ .20. 如图,矩形ABCD的对角线AC,BD相交于点O,过点O作,交AD于点E,若,则的大小为______ .21.如图,在平面直角坐标系xOy中,的顶点A在函数的图象上,顶点B在x轴正半轴上,边AO,AB分别交函数,的图象于点M,连接MN,若轴,则的面积为______ .22. 如图,在矩形ABCD中,,点P是DC上一点,且,点E,F分别是AD,BC上的动点,连接EF,AP,始终满足连接AF,PF,PE,记四边形AEPF的面积为,记的面积为,记的面积为,记的面积为______ .23. 如图,在平面直角坐标系xOy中,正方形ABCD的顶点A,C的坐标分别为,已知线段MN的端点M,N的坐标分别为,,平移线段MN,使得平移后的线段的两个端点均落在正方形ABCD的边上,此时正方形ABCD被该线段分为两部分,其中三角形部分的面积为______ ;已知线段PQ的端点坐标分别为,,且,,平移线段PQ,使得平移后的线段的两个端点均落在正方形ABCD的边上,且线段将正方形的ABCD面积分为6:19部分,取的中点H,连接OH,则OH的长为______ .24. 电影《长津湖》是一部讲述抗美援朝题材影片,该片以朝鲜长津湖战役为背景,讲述一个志愿军连队在极寒严酷环境下坚守阵地奋勇杀敌、为战役胜利作出重要贡献的故事,2022年清明节来临之际,某电影院开展“清明祭英烈,共铸中华魂”系列活动,对团体购买该电影票实行优惠,决定在原定零售票价基础上每张降价16元,这样按原定零售票价需花费2000元购买的门票,现在只花费了1200元.求每张电影票的原定零售票价;为了弘扬爱国主义精神,该影院决定对网上购票的个人也采取优惠,原定零售票价经过连续两次降价后票价为每张元,求平均每次降价的百分率.25. 已知在平面直角坐标系xOy中,点,在反比例函数的图象上.求k的值;将反比例函数的图象中x轴下方部分沿x轴翻折,其余部分保持不变,得到新的函数图象如图1所示,新函数记为函数①如图2,直线与函数F的图象交于A,B两点,点A横坐标为,点B横坐标为,且,,点P在y轴上,连接AP,当最小时.求点P的坐标;②已知一次函数的图象与函数F的图象有三个不同的交点,直接写出n的取值范围.26. 【问题背景】如图1,在矩形ABCD中,点M,N分别在边BC,AD上.且,连接BN,点P在BN上,连接PM并延长至点Q,使,连接【尝试初探】求证:;【深入探究】若,,点P为BN中点,连接NC,NQ,求证:;【拓展延伸】如图2,在正方形ABCD中,点P为对角线BD上一点,连接PC并延长至点使,连接若,求的值用含n的代数式表示答案和解析1.【答案】C【解析】解:从正面看,可得选项C的图形,故选:根据从正面看得到的图形是主视图,可得答案.本题考查了简单组合体的三视图,掌握从正面看得到的图形是主视图是关键.2.【答案】A【解析】解:A、是反比例函数,,故A选项符合题意;B 、是一次函数,不是反比例函数,故B选项不符合题意;C、是正比例函数,故C选项不符合题意;D、是二次函数,不是反比例函数,故D选项不符合题意,故选:根据形如为常数,的函数称为反比例函数,即可判断.本题考查了反比例函数的定义,熟练掌握反比例函数的定义是解题的关键.3.【答案】C【解析】解:设方程的另一个解为,根据题意得:,解得:故选:设方程的另一个解为,根据两根之和等于,即可得出关于的一元一次方程,解之即可得出结论.本题考查了根与系数的关系以及一元二次方程的解,牢记两根之和等于、两根之积等于是解题的关键.4.【答案】B【解析】解:两个四边形相似,相似比为:2::2,::::2,解得:,,,则,综上所述:只有选项B符合题意.故选:根据相似图形的对应角相等,对应边的比相等得到答案.本题考查了相似多边形的性质,牢记相似多边形的对应角相等,对应边的比也相等.5.【答案】C【解析】解:连接AC,BD相交于点E,四边形ABCD是菱形,,,,点A在x轴上,点B的坐标为,点D的坐标为,,,,,点C的坐标为:故选:首先连接AC,BD相交于点E,由在菱形ABCD中,点A在x轴上,点B的坐标为,点D 的坐标为,可求得点E的坐标,继而求得答案.此题考查了菱形的性质以及坐标与图形的性质.注意菱形的对角线互相平分且垂直.6.【答案】B【解析】解:由题意知,m的值约为,故选:用红球的个数除以红球频率的稳定值即可.本题主要考查利用频率估计概率,大量重复实验时,事件发生的频率在某个固定位置左右摆动,并且摆动的幅度越来越小,根据这个频率稳定性定理,可以用频率的集中趋势来估计概率,这个固定的近似值就是这个事件的概率.7.【答案】A【解析】解:作射线AO,,射线AO经过点D和点G,且,,点A的对应点为点D或点G,故选:作射线AO,根据位似中心的概念、线段的位似比解答即可.本题考查位似变换,正确记忆位似图形的特征是解题关键.8.【答案】D【解析】解:四边形ABCD是矩形,,,,在中,,,分别是AO,AD中点,,,,的周长为9,故选:因为四边形ABCD是矩形,所以,,,在中,可得,推出,因为分别是中点,根据三角形中位线定理即可得到结论.本题考查三角形中位线定理、矩形的性质等知识,解题的关键是灵活运用所学知识解决问题,属于基础题,中考常考题型.9.【答案】【解析】解:,,故答案为:根据已知条件得出,再代入要求的式子进行计算,即可得出答案.此题考查了比例的性质,解题的关键是用a表示出10.【答案】【解析】解:整理方程得,关于x的一元二次方程有两个不相等的实数根,,解得故答案为:先将一元二次方程整理成一般形式,然后根据一元二次方程的定义和判别式的意义得到,然后求出两个不等式的公共部分即可.本题考查了根的判别式:一元二次方程的根与有如下关系:当时,方程有两个不相等的实数根;当时,方程有两个相等的实数根;当时,方程无实数根.11.【答案】【解析】解:反比例函数中,函数图象的两个分支分别位于一、三象限,且在每一象限内,y随x的增大而减小.,、B都在第三象限,故答案为:先根据反比例函数的解析式判断出函数图象所在的象限,再根据即可得出结论.本题考查的是反比例函数性质,当,双曲线的两支分别位于第一、第三象限,在每一象限内y随x的增大而减小;当,双曲线的两支分别位于第二、第四象限,在每一象限内y随x的增大而增大.12.【答案】【解析】解:四边形ABCD是菱形,,,是等边三角形,,,,四边形为正方形,,由旋转的性质得出,,故答案为:根据菱形的性质得出,求出是等边三角形,根据等边三角形的性质得出,根据旋转的性质得出,再根据勾股定理求出即可.本题考查了菱形的性质,正方形的性质,旋转的性质等知识点,能熟记菱形和正方形的性质是接此题的关键.13.【答案】【解析】解:如图,连接FG,由题意得,,≌,,又,∽,,是AC的中点,,,,,故答案为:连接FG,先证明≌得到,进一步证明∽得到,再由H是AC中点,得到,即可得到答案.本题考察了全等三角形的性质与判定,相似三角形的性质与判定,证明三角形全等以及三角形相似是解题关键.14.【答案】解:原式;,,,或,,【解析】原式第一项化为最简二次根式,第二项利用利用负指数幂法则计算,第三项利用绝对值的代数意义化简,第四项计算乘方,即可得到结果;方程利用因式分解法即可求出解.此题考查了解一元二次方程-因式分解法,以及实数的运算,熟练掌握解一元二次方程的几种常用方法:直接开平方法、因式分解法、公式法、配方法,结合方程的特点选择合适、简便的方法是解题的关键.15.【答案】解:该校参加知识问答赛的学生人数为人;等级人数为人,扇形统计图中C级所对应的圆心角的度数为;由题意可得,树状图如图所示,由树状图知,共有12种等可能结果,其中恰好抽到一名男生和一名女生参加宣讲活动的有8种结果,所以恰好抽到一名男生和一名女生参加宣讲活动的概率为【解析】由A等级人数及其所占百分比可得总人数;先求出C等级人数,再用乘以C等级人数所占比例即可;画树状图得出所有等可能结果,从种找到符合条件的结果数,再根据概率公式求解即可.本题考查了列表法与树状图法:利用列表法或树状图法展示所有等可能的结果n,再从中选出符合事件A或B的结果数目m,然后利用概率公式计算事件A或事件B的概率.也考查了统计图.16.【答案】解:由题意可得:,则∽BED,,即,解得:,答:BC的长为3m;,,光在镜面反射中的反射角等于入射角,,又,∽,,,解得:,答:灯泡到地面的高度AG为【解析】直接利用相似三角形的判定与性质得出BC的长;根据相似三角形的性质列方程进而求出AG的长.此题主要考查了相似三角形的应用,正确得出相似三角形是解题关键.17.【答案】证明:平分,HB平分,,,在▱ABCD中,,,,即,同理可得,,,四边形EFGH是矩形;①证明:如图2,四边形ABCD为矩形,,,,矩形ABCD的各内角的平分线分别相交于点E,F,G,H,,,,,≌,≌,,,,四边形EFGH是菱形,,四边形EFGH为正方形;②解:四边形EFGH为正方形,四边形EFGH的面积为8,,是等腰直角三角形,,,,是等腰直角三角形,的长为【解析】根据角平分线的定义以及平行四边形的性质,即可得出,,,进而判定四边形EFGH是矩形;①根据矩形的性质证明≌,≌,可得,,所以,可得四边形EFGH是菱形,结合即可得四边形EFGH为正方形;②根据四边形EFGH为面积是8的正方形,可得,然后利用等腰直角三角形的性质即可解决问题.本题属于四边形的综合题,主要考查了平行四边形的性质,矩形的判定与性质,全等三角形的判定与性质,菱形的判定与性质,正方形的判定与性质,证明四边形EFGH为正方形是解题的关键.18.【答案】解:将点A的坐标代入一次函数表达式得:,即点,将点A的坐标代入反比例函数表达式得:,解得:,即反比例函数的表达式为:,联立一次函数和上式得:,解得:舍去或,故点;设点,当AB是边时,将B向右平移3个单位向上平移3个单位得到点A,同样向右平移3个单位向上平移3个单位得到,则,解得:或,故点M的坐标为或;设点,则点,设直线AB交y轴于点R,过点P作直线交y轴于点M,过点Q作直线交y轴于点N,的面积是的面积的3倍,,直线AB的表达式为:,则直线m的表达式为:,则点,同理可得:点,,即,解得:舍去负值,即【解析】用待定系数法即可求解;将B向右平移3个单位向上平移3个单位得到点A,同样向右平移3个单位向上平移3个单位得到,进而求解;设直线AB交y轴于点R,过点P作直线交y轴于点M,过点Q作直线交y轴于点N,由的面积是的面积的3倍,得到,进而求解.本题考查的是反比例函数综合运用,涉及到一次函数的基本性质、平行线的性质、平行四边形的基本性质等,其中,要注意分类求解,避免遗漏.19.【答案】【解析】解:,是方程的两个实数根,,,故答案为:利用根与系数的关系,可得出,,将其代入中,即可求出结论.本题考查了根与系数的关系,牢记“,是一元二次方程的两根时,,”是解题的关键.20.【答案】【解析】解:四边形ABCD是矩形,,,,,,,,,,,,故答案为:根据矩形的性质,等腰三角形的判定和性质以及平行线的性质即可得到结论.本题考查了矩形的性质,等腰三角形的性质,熟练掌握矩形的性质是解题的关键.21.【答案】6【解析】解:如图,作轴于D,轴于E,则,∽,,,::4,::2,是OA的中点,设,则,,轴,是AB的中点,,故答案为:作轴于D,轴于E,根据,得∽,因为,,所以::4,所以OM::2,可得M是OA的中点,设,则,,所以,即可求出答案.本题考查了反比例函数系数k的几何意义和反比例函数图象上点的坐标特征,在反比例函数图象中任取一点,过这一个点向x轴和y轴分别作垂线,与坐标轴围成的矩形的面积是定值,在反比例函数的图象上任意一点向坐标轴作垂线,这一点和垂足以及坐标原点所构成的三角形的面积是,且保持不变.也考查了相似三角形的判定与性质.22.【答案】【解析】解:作F作于H,FH交AP于G,设EF交AP于M,如图:四边形ABCD是矩形,,四边形ABFH是矩形,,,,,,,∽,,,,,,,设,则,,,,,,,,故答案为:作F作于H,FH交AP于G,设EF交AP于M,证明∽,可得,,设,即有,,,,从而,即可得到答案.本题考查矩形的性质,三角形的面积,涉及相似三角形的判定与性质,解题的关键是用含字母的代数式表示,,23.【答案】【解析】解:如图1,作轴,作,MN平移后对应FG,,,,,,如图2,不妨设,,,,,,的面积为:,由题意得,,,,,,,,,故答案为:,作轴,作,MN平移后对应FG,可求得,,进而求得三角形部分的面积;不妨设,,,可得,从而求得x,y进而得出H点坐标,进一步得出OH的长.本题考查了正方形性质,勾股定理,平移的性质等知识,解决问题的关键是弄清数量关系列出方程组.24.【答案】解:设每张电影票的原定零售票价是x元,则降价后的零售票价是元,根据题意得:,解得:,经检验,是所列方程的解,且符合题意.答:每张电影票的原定零售票价是40元;设平均每次降价的百分率为y,根据题意得:,解得:,不符合题意,舍去答:平均每次降价的百分率为【解析】设每张电影票的原定零售票价是x元,则降价后的零售票价是元,利用数量=总价单价,可得出关于x的分式方程,解之经检验后,即可得出结论;设平均每次降价的百分率为y,利用经过两次降价后的价格=原价平均每次降价的百分率,可得出关于y的一元二次方程,解之取其符合题意的值,即可得出结论.本题考查了分式方程的应用以及一元二次方程的应用,解题的关键是:找准等量关系,正确列出分式方程;找准等量关系,正确列出一元二次方程.25.【答案】解:点,在反比例函数的图象上,,解得:,则;①由知,反比例函数的表达式为:,则将反比例函数的图象中x轴下方部分沿x轴翻折,则翻折后函数的表达式为:,联立和并整理得:,则,即,解得:,则,即点A、B的坐标分别为、,作点B关于y轴的对称点,连接AC交x轴于点P,则此时最小,理由:为最小,设直线AC的表达式为:,则,解得:,则直线AC的表达式为:,当时,,即点;②,则该一次函数过点,如图:当时,如图:l:,直线l和y轴左侧函数有2个交点时,必然和y轴右侧的函数有一个交点,符合题设条件,联立和,整理得:,则,解得:或,,或;当时,直线虚线和y轴右侧函数有2个交点时,必然和y轴左侧的函数有一个交点,符合题设条件,联立和,整理得:,则,解得:n为任意实数,即;综上,且或【解析】用待定系数法即可求解;①联立和并整理得:,则,求出,得到点A、B的坐标分别为、,作点B关于y轴的对称点,连接AC交x轴于点P,则此时最小,进而求解;②当时,直线l和y轴左侧函数有2个交点时,必然和y轴右侧的函数有一个交点,符合题设条件,进而求解;当时,直线虚线和y轴右侧函数有2个交点时,必然和y轴左侧的函数有一个交点,符合题设条件,进而求解.本题考查的是反比例函数综合运用,涉及到一次函数基本性质、根和系数关系、点的对称性、图象过定点、图形的翻折、解不等式等,其中,分类求解和数形结合是本题解题的关键.26.【答案】证明:,,∽,,;如图1,连接MN,作于E,四边形ABCD是矩形,,,,四边形ABMN是平行四边形,,▱ABMN是矩形,,矩形ABMN是正方形,,点P是BN的中点,,,由知:,∽,,,,,四边形PQEN是矩形,,,;解:如图2,延长AD,BC,作于F,连接DE,BE交DQ于E,四边形ABCD是正方形,,,,由上可知:,,,,,,,,,,,,,,设,,则,,,,,,,即:【解析】证明∽,从而,进而得出结论;连接MN,作于E,可证明四边形ABMN是正方形,四边形PQEN是矩形,结合,进一步得出结论;延长AD,BC,作于F,连接DE,BE交DQ于E,根据可得出,从而,可推出,是等腰直角三角形,设,,则,,从而,结合,进一步得出结果.本题考查了矩形的性质和判定,正方形的性质和判定,相似三角形的判定和性质,勾股定理的逆定理等知识,解决问题的关键是作辅助线,构造相似三角形.。
2012级《大学物理II》期中考试试卷-A卷_2013_11_6_
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西北工业大学期中考试试题(卷)
2013~2014学年第一学期
开课学院理学院课程大学物理II 学时60
考试日期2013年11月6日考试时间 2.0 小时考试形式(闭)(A)卷
班级学号姓名
重要提示:
1.本试卷含“单选题”、“填空题1”和“填空题2”三部分,总分为100分;2.在机读答题卡上答题。
数字用钢笔填写,涂点用2B铅笔填涂。
填空题答案栏左对齐填入数字,每一格填写1位数字,小数点单独占1格,按题目中的要求取位,4舍5入进位;
3.在答题卡上填涂班号时,RJ =14;学号只填入后6位;
4.题中所涉π一律取3.14 计算;
5.草稿纸不再另发,将试题的背面作为草稿纸。
一、单选题(每小题3分,共45分)
1.如图所示,真空中有一带电导体球,球外P点
的场强大小为E P、电势为U P。
现用一个有一定
厚度的不带电金属球壳把P点包围起来,球壳与导体球同心,此时P点场强大小和电势分别以E'P和U'P表示,则:
A.E P =E'P,U P=U'P;B.E P=E'P,U P≠U'P;C.E P≠E'P,U P=U'P;D.E P≠E'P,U P≠U'P。
O 第1题图
P。
12级 大学物理A2 练习题(马文蔚5版下:振、波、光、气、热、相、量)
一、填空题机械振动1.一作简谐振动的系统,振子质量为2 kg ,系统振动频率为1000 Hz ,振幅为0.5 cm ,则其振动能量为_________.2. 用40N 的力拉一轻弹簧,可使其伸长20cm ,此弹簧下应挂 kg 的物体,才能使弹簧振子作简谐振动的周期T=0.2πs.3. 一质点作谐振动,振动方程为x =6cos(8πt +π/5) cm ,则t =2秒时的相位为____________,质点第一次回到平衡位置所需要的时间为____________. 4. 如图为以余弦函数表示的振动曲线,则其初相ϕ=_____,P 时刻的相位为_____. 5. 一质点作简谐振动的圆频率为ω、振幅为A ,当t =0时质点位于x=A /2处且朝x轴正方向运动,试画出此振动的旋转矢量图.6. 两个同方向的简谐振动曲线如图所示,合振动的振幅为 ,合振动的振动方程为 .7. 用40N 的力拉一轻弹簧,可使其伸长20cm ,此弹簧下应挂kg 的物体,才能使弹簧振子作简谐振动的周期T=0.2πs .8. 一质点沿x 轴以 x = 0 为平衡位置作简谐振动,频率为 0.25 Hz .t = 0时x = -0.37 cm 而速度等于零,则振幅是_________,振动方程为_______________________。
9. 一质点同时参与了两个同方向的简谐振动,它们的振动方程分别为x 1=0.05cos(ωt+π/4) (SI),x 2=0.08cos(ωt +5π/4) (SI),其合成运动的运动方程为x = .10. 一质点同时参与两个同方向同频率的谐振动,已知其中一个分振动的方程为:x 1=4cos(3t ) cm ,其合振动的方程为:x =4cos(3t +π/3) cm ,则另一个分振动的振幅为A 2= ,初相ϕ2=___________. 11. 一质点同时参与了三个简谐振动,它们的振动方程分别为x 1=A cos(ωt +π/3),x 2=A cos(ω t +5π/3),x 3=Acos(ω t +π),其合成运动的运动方程为x =_________________12. 一弹簧振子作简谐振动,其振动曲线如图所示。
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7、 1
0, 其他;
5 11、0, 1
3
12、3
6
同理 ( X ,Y ) 关于Y 的边缘概率密度为 fY ( y)
2 2y,0 y 1
f (x, y)dx 0,其他。
14、0.15
3、解:(1)总体期望为
E( X ) 1x dx ,由矩估计法,令 x 。
0
1
1
1---5 BBDAD 6---10 BBBCD 11---15 ADBCA 三、计算题
2
B x (n 1)s 2 2
x C n
s2 2
x D n
(n 1)s 2 2
10.设总体 X
~
N (, 2 ), X1, X 2 , X 3 是来自 X
的样本,则当常数
为何值时,
^
1 3
X
1
X 2
1 6
X 3 是未知
参数 的无偏估计
(
)
A0
B1
C1
D1
3
2
11.在假设检验问题中,显著性水平 的意义是
1y
D
2
fX
() 2
(
)
1
A dx f (x, y)dy
B dx f (x, y)dy
1
C f (x, y)dx
D f (x, y)dx
1
1
7.设 X ~ N(1,2),Y ~ N(1,3)且X与Y相互独立,则 X Y ~
(
)
A N (1,8)
B N (0,5)
C N (1,22)
D N (1,20)
, , 方差为
2 令
1 n 则对任意
Z n n i1 X i ,
正数 , 有 lim p n
Zn
11.设 x1, x2,xn是来自U(1,1)的样本,则 E(x)
, D(x)
12.设总体 X
~
N (,
2
),x1 ,
x2
,
x3 ,
x
为来自总体
4
X的样本,x
1 4
4 i1
x
,则
C p(3.5 X 4.5)
D p(4.5 X 5.5)
击中一次的概率为
3.设 A、B 是两个随机变量, p(A) 0.8, p( AB) 0.3, 则 p(AB)
4.从1,2,3,4,5 中任取 3 个数字,则这三个数字中不含1的概率是
5.设 X 为连续型随机变量, c 是一个常数,则 p( X c)
i
1 2
4 (xi x)2 服从自由度
i 1
为
的 2 分布
13.已知 x 15.4,标准差为0.1,则置信度为 0.95的置信区间为( u1 1.96 ) 2
14.设某个假设检验问题的拒绝域为W ,且当原假设 H0 成立时,样本 (x1 , x2 ,, xn ) 落入W
的概率为 0.15,则犯第一类错误的概率为
二、单项选择题(每题 2 分,共 30 分)
1.设 A、B 为随机事件,则 (A B)A
(
)
9.总体 X ~ U (, 2 ), 其中, 2 已知, x1,, xn (n 3) 为来自总体的样本, x 为样本均值, s 2 为样本方差,
则下列统计量中服从 t 分布的是
(
)
A
x
(n 1)s 2
6.设随机变量 X ~ N(0,1) , (x) 为其分布函数,则 (x) (x)
7.设随机变量 X、Y 相互独立,且 p( X 1) 1 , p(Y 1) 1 ,则p( X 1,Y 1)
2
3
8.已知 X ~ P(2),则 D(X )
9.若二维随机变量 ( X ,Y )
~
N
(
1
,
(
)
A 在 H 0 成立的条件下,经检验 H 0 被拒绝的概率
本试卷共 4 页,此页为 1 卷第 1、2 页
班级
………………………………………装……………………………订……………………………线………………………………………
学号
B 在 H 0 成立的条件下,经检验 H 0 被接受的概率
C 在 H 0 不成立的条件下,经检验 H 0 被拒绝的概率
2
2.设 ( X ,Y ) 服从 D 上的均匀分布,其中 D 为 x 轴、 y 轴与 y 2x 1围成的三角形区域,求 ( X ,Y ) 的
边缘概率密度。
姓名
班级
本试卷共 4 页,此页为 2 卷第 3、4 页
继续教育学院
2013 ~2014 学年 第 1 学期
A卷当x来自1 2时,fX
(x)
0;
当 x 0时,f X (x) 0;
当
1 2
x
0时,f
X
(x)
f (x, y)dy
2 x1
4dy 8x 4;
0
专业
一、填空题 1、 1 2
8、2
2、0.58 9、0
13、[15.3347,15.4653] 二、单项选择题
3、0.5 10、1
课程期末试卷标准答案(即评分标准)
即
fX
(x)
8x
4,
1 2
x
0,
4、 2
5、0 6、1
1、解:记 A=“第一次取到白球”, B =“第二次取到白球”则
^
解之得 的矩估计为 1
x
1 x
p(A) 5 , p(A) 3 , p(B A) 4 , p(B A) 5
8
8
7
7
由全概率公式,得
n
(2)似然函数为 L( ) (xi 1 ) i 1
取对数得
p(B) p(A) p(B A) p(A) p(B A) 5 4 3 5 5 87 87 8
E ( 1 ), (i 2
1,) ,则当 n 充分大时,随机变量 Z n
1 n
n i 1
Xi
的概率分布近似服从
(
)
A N (2,4)
B N (2, 4) n
C N(1 , 1 ) 2 4n
D N (2n,4n)
14.设 ( X ,Y ) 为二维连续型随机变量,则 X 与 Y 不相关的充分必要条件是
2
;
2 1
,
2
2
;
)
,且
X与Y
相互独立,则
5.已知随机变量的概率密度为 f X (x),令 Y 2X ,则 Y 的概率密度 fY ( y) 为
(
)
A 2 f X (2 y)
B
fX
(
y 2
)
1y
C
2
fX ( 2 )
6.设二维随机变量 (X、Y ) 的概率密度为 f (x, y), 则 pX 1
8.设随机变量 X ~ E(0.5) ,则下列各项中正确的是
(
)
A E(X ) 0.5, D(X ) 0.25
B E(X ) 2, D(X ) 4
C E(X ) 0.5, D(X ) 4
D E(X ) 2, D(X ) 0.25
10.设随机变量 X1, X 2 , X n,相互独立且同分布,它们的期望为
)
A A1 A2 A3
B A1 A2 A2 A3 A1 A3
C A1 A2 A3 A1A2 A3 A1 A2 A3
D A1 A2 A3
3.设 A、B 为两个随机事件,且 p( AB) 0 ,则 P(A AB)
(
)
学号
姓名
一、填空题(每空 2 分,共 30 分)
A p(B)
B p( AB)
3.设总体
X
的概率密度为
f
(x)
x 1,0
0,
其他
x
1(;
0),
^
^
试求:(1) 的矩估计 1 ;(2) 的极大似然估计 2 。
4.某型号元件的尺寸 X 服从正态分布,且均值为 3.278cm ,标准差为 0.002cm ,现用一种新工艺生产此 类元件,从中随机取 9 个元件,测量其尺寸,算得均值 x 3.2795cm, 问用新工艺生产的元件尺寸均值与以 往有无显著差异。(显著性水平 0.05)( u1 1.96,u 1.645 )
统计量
U
x
3.2795 3.278 0.002
2.25 U10.05
1.96
2
n
9
因而拒绝原假设 H 0 ,即有显著差异。
本试卷答案共 页,此页为第 页
C p(A B)
D1
1 掷一颗质地均匀的骰子,出现奇数点的概率是
4.设随机变量 X ~ U (2,4), 则 p(3 X 4)
(
)
2.甲、乙两门高射炮彼此独立地向一架飞机各发一炮,甲、乙击中飞机的概率分别为 0.3、0.4,则飞机至少被
A p(2.25 X 3.25) B p(1.5 X 2.5)
(
)
A X 与 Y 相互独立
B E(X Y ) E(X ) E(Y )
C E(XY) E(X )E(Y )
D
(X ,Y )
~
N (1,2 ;
2 1
,
22;)
15.将两封信随机地投入四个邮筒中,则未向前两个邮筒中投信的概率为
(
)
22 A 42
B
C
1 2
C
2 4
2!
C
A 42
2!
D
4!
三、计算题(每题 10 分,共 40 分) 1.盒中有 5 个白球 3 个黑球,连续不放回地从中取两次球,每次取一个,求第二次取球取到白球的概率。