JavaSpaces- An Affordable Technology For The Simple Implementation Of Reusable Parallel Evo
java的用途英语作文
java的用途英语作文Java, a programming language that revolutionized the software industry, has emerged as a leading force intoday's digital world. Its widespread adoption and adaptability across various platforms and applications are testament to its versatility and reliability. From desktop applications to web development, mobile computing, and beyond, Java's impact is felt across the technological spectrum.**Desktop Applications**Java's early foray into the computing world was through desktop applications. Its "Write Once, Run Anywhere" mantra allowed developers to create cross-platform softwarewithout the need for separate codebases for each operating system. This eliminated the complexity and cost associated with maintaining multiple versions of the same application. Java-based desktop applications are still widely used today, ranging from productivity tools to gaming platforms.**Web Development**With the advent of the internet, Java found a new home in web development. Servlets and JavaServer Pages (JSP) revolutionized web application development by providing a platform-independent, scalable, and secure way to create dynamic web content. Java-based web frameworks like Spring and Struts have further simplified the development process, making it easier for developers to build robust and scalable web applications.**Mobile Computing**As mobile computing gained popularity, Java made its way into the mobile space with the launch of Java ME (Micro Edition) for mobile devices. This allowed developers to create applications that could run on a wide range of mobile phones, regardless of their hardware or operating system. Although Java's market share in mobile development has been overshadowed by other languages like Swift and Kotlin, it still holds a significant presence inenterprise-level mobile solutions.**Big Data and Cloud Computing**In recent years, Java has emerged as a key player in big data and cloud computing. Its scalability, performance,and robust security features make it an ideal choice for handling massive amounts of data in distributed environments. Hadoop, a popular open-source framework for processing large datasets, is written in Java. Additionally, Java-based platforms like Apache Spark and Kafka provide powerful tools for real-time data processing and streaming analytics.**Enterprise Solutions**Java's strength in enterprise solutions lies in its ability to handle complex, mission-critical applications. Enterprises worldwide rely on Java-based systems for their enterprise resource planning (ERP), customer relationship management (CRM), and supply chain management (SCM) needs. The language's robust security features, scalability, and support for distributed computing make it a natural fit for these demanding enterprise environments.**The Future of Java**As the technological landscape continues to evolve,Java remains a relevant and influential force. With the advent of new frameworks, libraries, and tools, Java developers are constantly innovating and pushing theboundaries of what's possible with the language. From machine learning and artificial intelligence to the Internet of Things (IoT) and beyond, Java's future looks bright as it continues to power the digital world.**Java的用途:技术之旅**Java,一种改变了软件行业的编程语言,如今已成为当今数字世界中的领先力量。
Java程序设计_北京大学中国大学mooc课后章节答案期末考试题库2023年
Java程序设计_北京大学中国大学mooc课后章节答案期末考试题库2023年1.Java不直接使用指针。
答案:正确2.可以使用jar来打包程序。
答案:正确3.字符串连接运算符其实是用append来实现的。
答案:正确4.break及continue后面可以跟一个语句标号。
答案:正确5.增强的for语句可以方便地遍历数组。
答案:正确6.数组元素都会隐式初始化。
答案:正确7.如果没有定义任何构造方法,系统会自动产生一个构造方法。
答案:正确8.方法重载是多态(polymorphism)的一种方式。
答案:正确9.Java中的继承是通过extends关键字来实现的。
答案:正确10.如果没有extends子句,则该类默认为ng.Object的子类。
答案:正确11.使用super访问父类的域和方法。
答案:正确12.在构造方法中,使用super()时,必须放在第一句。
答案:正确13.子类对象实例可以被视为其父类的一个对象。
答案:正确14.同一包中的各个类,默认情况下可互相访问。
答案:正确15.final所修饰的变量,是只读量。
答案:正确16.在定义final局部变量时,也必须且只能赋值一次。
答案:正确17.在接口中定义的常量具有public, static, final的属性。
答案:正确18.虚方法调用是由对象实例的类型来动态决定的。
答案:正确19.在构造方法中,如果没有this及super,则编译器自动加上super()。
答案:正确20.实例初始化,先于构造方法{}中的语句执行。
答案:正确21.getCause()可以得到异常的内部原因。
答案:正确22.JavaSE的源代码是开放的,我们可以阅读。
答案:正确23.任何类都可以覆盖toString()方法。
答案:正确24.字符串的+运算,实际表示StringBuffer、StringBuiler的append运算。
答案:正确25.SimpleDateFormat类可以用来解析日期字符串。
JAVA试题英文版(答案)
一.Which two demonstrate an “is a” relationship? (Choose Two)A. public interface Person { }//语法错了public class Employee extends Person { }B. public interface Shape { }//语法错了public class Employee extends Sha pe { }C. public interface Color { }//语法错了public class Employee extends Color { }D. public class Species { }public class Animal{private Species species;}E. interface Component { }Class Container implements Component (Private Component[ ] children;二.which statement is true?A. An anonymous inner class may be declared as finalB. An anonymous inner class can be declared as privateC. An anonymous inner class can implement mutiple interfacesD. An anonymous inner class can access final variables in any enclosing scope (不能)E. Construction of an instance of a static inner class requires an instance of the encloing outer class构造一个静态的内部类对象需要构造包含它的外部类的对象三. Given:1. package foo;2.3. public class Outer (4. public static class Inner (5. )6. )Which statement is true?A. An instance of the Inner class can be constructed with “new Outer.Inner ()”B. An instance of the inner class cannot be constructed outside of package foo他们都是public的,只要在外部import就行C. An instance of the inner class can only be constructed from within the outer classD. From within the package bar, an instance of the inner class can be constructed with “new inner()”四.Exhibit(展览、陈列):1 public class enclosinggone{2 public class insideone{}3 }4 public class inertest{5 public static void main (String[] args){6 enclosingone eo = new enclosingone();7 //insert code here8 }}Which statement at line 7 constructs an instance of the inner class?A. InsideOne ei = eo.new InsideOne(); 写程序试出来B. Eo.InsideOne ei = eo.new InsideOne();C InsideOne ei = EnclosingOne.new InsideOne();D.EnclosingOne InsideOne ei = eo.new InsideOne();五.1) interface Foo{2) int k=0;3) }4) public class Test implements Foo{5) public static void main(String args[]){6) int i;7) Test test =new Test();8) i=test.k;9) i=Test.k;10) i=Foo.k;11) }12) }What is the result?A. Compilation succeeds.B. An error at line 2 causes compilation to fail.C. An error at line 9 causes compilation to fail.D. An error at line 10 causes compilation to fail.E. An error at line 11 causes compilation to fail.六.//point Xpublic class Foo{public static void main(String[] args){PrintWriter out=new PrintWriter(new java.io.OutputStreamWriter(System.out),true); out.println("Hello");}}which statement at point X on line 1 allows this code to compile and run?在point X这个位置要填入什么代码才能使程序运行A.import java.io.PrintWriterB.include java.io.PrintWriterC.import java.io.OutputStreamWriterD.include java.io.OutputStreamWriterE.No statement is needed本来两个都要import,但是后者OutputStreamWriter指定了包结构java.io.OutputStreamWriter七.what is reserved words in java? 保留字而非关键字A. runB.defaultC. implementD. import八. which three are valid declaraction of a float?(float作为整数是可以的,其余几个都是double)A. float foo=-1;B. float foo=1.0;C. float foo=42e1;D. float foo=2.02f;E. float foo=3.03d;F. float foo=0x0123;九. Given:8. int index = 1;9. boolean[] test = new boolean[3]; (数组作为对象缺省初始化为false)10. boolean foo= test [index];What is the result?A. foo has the value of 0B. foo has the value of nullC. foo has the value of trueD. foo has the value of falseE. an exception is thrownF. the code will not compile十. Given:1. public class test(2. public static void main(String[]args){3. String foo = args [1];4. String foo = args [2];5. String foo = args [3];6. }7. }And the command line invocation:Java TestWhat is the result?A. baz has the value of “”B. baz has the value of nullC. baz has the value of “red”D. baz has the value of “blue”E. bax has the value of “green”F. the code does not compileG. the program throws an exception(此题题目出错了,重复定义了变量foo,如果没有重复的话,应选G,因为只传递了0-2三个数组元素,而题目中需要访问args [3],所以会抛出数组越界异常)十一.int index=1;int foo[]=new int[3];int bar=foo[index]; //bar=0int baz=bar+index; //baz=1what is the result?A. baz has a value of 0B. baz has value of 1C. baz has value of 2D. an exception is thrownE. the code will not compile十二.1)public class Foo{2)public static void main(String args[]){3)String s;4)System.out.println("s="+s);5)}6)}what is the result?A. The code compiles and “s=” is printed.B. The code compiles and “s=null” is printed.C. The code does not compile because string s is not initialized.D. The code does not compile because string s cannot be referenced.E. The code compiles, but a NullPointerException is thrown when toString is called.十三. Which will declare a method that forces a subclass to implement it?(谁声明了一个方法,子类必须实现它)A. public double methoda();B. static void methoda (double d1) {}C. public native double methoda();D. abstract public void methoda();E. protected void methoda (double d1){}十四.You want subclasses in any package to have access to members of a superclass. Which is the most restrictive access modifier that will accomplish this objective?(你希望子类在任何包里都能访问父类,为完成这个目的,下列哪个是最严格的访问权限)A. PublicB. PrivateC. ProtectedD. TransientE. No access modifier is qualified十五. Given:1. abstract class abstrctIt {2. abstract float getFloat ();3. )4. public class AbstractTest extends AbstractIt {5. private float f1= 1.0f;6. private float getFloat () {return f1;}7. }What is the result?A. Compilation is successful.B. An error on line 6 causes a runtime failure.(抛出实时异常)C. An error at line 6 causes compilation to fail.D. An error at line 2 causes compilation to fail.(子类覆盖父类方法的时候,不能比父类方法具有更严格的访问权限)十六. Click the exhibit button:1. public class test{2. public int aMethod(){3. static int i=0;4. i++;5. return I;6. }7. public static void main (String args[]){8. test test = new test();9. test.aMethod();10. int j = test.aMethod();11. System.out.printIn(j);12. }13. }(局部变量不能声明为静态)What is the result?A. Compilation will fail.B. Compilation will succeed and the program will print “0”.C. Compilation will succeed and the program will print “1”.D. Compilation will succeed and the program will print “2”.十七.1) class Super{2) public float getNum(){return 3.0f;}3) }4)5) public class Sub extends Super{7) }which method, placed at line 6, will cause a compiler error?A. public float getNum(){return 4.0f;}B. public void getNum(){} 返回值类型不同不足以构成方法的重载C. public void getNum(double d){}D. public double getNum(float d){return 4.0d;}十八. Which declaration prevents creating a subclass of an outer class?A.static class FooBar{}B.pivate class Foobar{}C.abstract class FooBar{}D.final public class FooBar{}E.final abstract class FooBar{} 抽象类不能声明为final十九. byte[] array1,array2[]byte array3[][]byte[][] array4if each has been initialized, which statement will cause a compile error?A. array2 = array1;B. array2 = array3;C. array2 = array4;D. both A and BE. both A and CF. both B and C(一维数组和二维数组的区别)二十.class Super{public int i=0;public Super(String text){i=1;}public class Sub extends Super{public Sub(String text){i=2;}public static void main(String args[]){Sub sub=new Sub("Hello");System.out.println(sub.i);}}what is the result?A. compile will failB. compile success and print "0"C. compile success and print "1"D. compile success and print "2"子类总要去调用父类的构造函数,有两种调用方式,自动调用(无参构造函数),主动调用带参构造函数。
java选择题题库
选择题第一章java语言概述1在下列概念中, Java语言只保留了 B .A.运算符重载B.方法重载C.指针`D.结构和联合2下列关于Java语言特性的描述中,错误的是___D_.A.支持多线程操作B. JA V A程序与平台无关C. JA V A程序可以直接访问Internet上的对象D. 支持单继承和多继承3下列关于JavaApplication程序在结构上特点的描述中,错误的是 CA. Java程序是由一个或多个类组成的B. 组成Java程序的若干个类可以放在一个文件中,也可以放在多个文件中C. Java程序的文件名要与某个类名相同D. 组成Java程序的多个类中,有且仅有一个主类.4Java 程序经过编译后生成的文件的后缀是 CA. .objB. .exeC. .classD. .java5下列关于运行字节码文件的命令行参数的描述中,正确的是 AA.第一个命令行参数被存放在args[0]中B.第一个命令行参数被存放在args[1]中C.命令行的命令字被存放在args[0]中D.数组args[]的大小与命令行参数的个数无关。
6下列关于java语言面向对象特性描述中,错误的是___C___A.具有封装性B. 支持多态性,允许方法重载C. 支持单继承和多继承D. 支持多接口7下列关于java语言与C++语言异同点的描述中,错误的是______DA. java语言取消了goto语句|B. java语言中取消了指针C. java 语言不支持运算符重载D. java 语言仍保留了结构和联合8列关于JavaApplication程序特点的描述中,错误的是 AA. 该程序只能是一个名字与主类名相同的文件组成B. 该程序中仅有一个主方法,并被包含在某个类中C. 该程序中没有不属于某个类的方法D. 该程序实际上是一个类串9使用Java语言编写的源程序保存时的文件扩展名是( B )。
A.classB.javaC.cppD.txt10Java源文件和编译后的文件扩展名分别为( B )(A) .class和.java (B).java和.class(C).class和 .class (D) .java和.java11Java语言使用的字符码集是( D )(A) ASCII (B) BCD(C) DCB (D) Unicode12下面关于main方法说明正确的是( B )(A) public main(String args[ ])(B) public static void main(String args[ ])(C) private static void main(String args[ ])(D) void main()13Java application中的主类需包含main方法以下哪项是main方法的正确形参( B )A、String argsB、String args[]C、Char argD、StringBuffer args[]14下列关于Java语言和C++语言之间差别的描述中,不正确的一项是( A )A. Java虽然提供了安全机制,但是还是没有C++安全B. Java的内存管理优于C++的内存管理C. Java没有全局变量,但是C++有全局变量D. Java没有指针,但是C++的指针最灵活15关于Java语言的内存回收机制,下列选项中最正确的一项是(C )A. Java程序要求用户必须手工创建一个线程来释放内存B. Java程序允许用户使用指针来释放内存C. 内存回收线程负责释放无用内存D. 内存回收线程不能释放内存对象16下列关于Java语言和C++语言之间差别的描述中,不正确的一项是(A )A. Java虽然提供了安全机制,但是还是没有C++安全B. Java的内存管理优于C++的内存管理C. Java没有全局变量,但是C++有全局变量D. Java没有指针,但是C++的指针最灵活17Java语言是一种(D)A. 面向机器的编程语言B. 面向过程的编译型编程语言C. 面向问题的解释型编程语言D. 面向对象的解释型编程语言18下面的说法正确的是( C )。
java第七版课后答案——第二章
//******************************************************************** // AverageOfThree.java Author: Lewis/Loftus//// Solution to Programming Project 2.2//******************************************************************** import java.util.Scanner;public class AverageOfThree{//----------------------------------------------------------------- // Reads three integers from the user and prints their average.//----------------------------------------------------------------- public static void main (String[] args){int num1, num2, num3;double average;Scanner scan = new Scanner (System.in);System.out.print ("Enter the first number: ");num1 = scan.nextInt();System.out.print ("Enter the second number: ");num2 = scan.nextInt();System.out.print ("Enter the third number: ");num3 = scan.nextInt();average = (double) (num1+num2+num3) / 3;System.out.println ("The average is: " + average);}}//******************************************************************** // AverageOfThree2.java Author: Lewis/Loftus//// Alternate solution to Programming Project 2.2//******************************************************************** import java.util.Scanner;public class AverageOfThree2{//----------------------------------------------------------------- // Reads three integers from the user and prints their average.//----------------------------------------------------------------- public static void main (String[] args){int num1, num2, num3;double average;Scanner scan = new Scanner (System.in);System.out.print ("Enter three numbers: ");num1 = scan.nextInt();num2 = scan.nextInt();num3 = scan.nextInt();average = (double) (num1+num2+num3) / 3;System.out.println ("The average is: " + average);}}//******************************************************************** // Balloons.java Author: Lewis/Loftus//// Solution to Programming Project 2.17//********************************************************************import javax.swing.JApplet;import java.awt.*;public class Balloons extends JApplet{//----------------------------------------------------------------- // Draws a set of balloons on strings.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.white);// draw the stringspage.setColor (Color.black);page.drawLine (45, 95, 100, 300);page.drawLine (90, 100, 100, 300);page.drawLine (60, 100, 100, 300);page.drawLine (122, 85, 100, 300);page.drawLine (145, 115, 100, 300);// draw the balloonspage.setColor (Color.blue);page.fillOval (20, 30, 50, 65);page.setColor (Color.yellow);page.fillOval (70, 40, 40, 60);page.setColor (Color.red);page.fillOval (40, 50, 40, 55);page.setColor (Color.green);page.fillOval (100, 30, 45, 55);page.setColor (Color.cyan);page.fillOval (120, 55, 50, 60);}}//******************************************************************** // BigDipper.java Author: Lewis/Loftus//// Solution to Programming Project 2.16//********************************************************************import javax.swing.JApplet;import java.awt.*;public class BigDipper extends JApplet{//----------------------------------------------------------------- // Draws the Big Dipper constellation and some other stars.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.black);page.setColor (Color.white);page.drawLine (100, 80, 110, 120);page.drawLine (110, 120, 165, 115);page.drawLine (165, 115, 175, 70);page.drawLine (100, 80, 175, 70);page.drawLine (175, 70, 245, 20);page.drawLine (245, 20, 280, 30);// Draw some extra starspage.fillOval (50, 50, 4, 4);page.fillOval (70, 150, 3, 3);page.fillOval (90, 30, 3, 3);page.fillOval (220, 140, 4, 4);page.fillOval (280, 170, 3, 3);page.fillOval (310, 100, 4, 4);page.fillOval (360, 20, 3, 3);}}//******************************************************************** // BusinessCard.java Author: Lewis/Loftus//// Solution to Programming Project 2.20//********************************************************************import javax.swing.JApplet;import java.awt.*;public class BusinessCard extends JApplet{//----------------------------------------------------------------- // Draws a business card.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.yellow);page.setColor (Color.red);page.fillOval (10, 20, 60, 60);page.setColor (Color.cyan);page.fillRect (25, 35, 130, 25);page.setColor (Color.black);page.drawString ("James C. Kerplunk", 35, 50);page.drawString ("President and CEO", 85, 80);page.drawString ("Origin Software, Inc.", 85, 100);page.drawLine (225, 20, 225, 80);page.drawLine (195, 50, 255, 50);page.setColor (Color.blue);page.drawString ("where it all begins...", 115, 135);}}//******************************************************************** // ChangeCounter.java Author: Lewis/Loftus//// Solution to Programming Project 2.10//******************************************************************** import java.util.Scanner;public class ChangeCounter{//----------------------------------------------------------------- // Computes the total value of a collection of coins.//----------------------------------------------------------------- public static void main (String[] args){int quarters, dimes, nickels, pennies;int total, dollars, cents;Scanner scan = new Scanner(System.in);System.out.print ("Enter the number of quarters: ");quarters = scan.nextInt();System.out.print ("Enter the number of dimes: ");dimes = scan.nextInt();System.out.print ("Enter the number of nickels: ");nickels = scan.nextInt();System.out.print ("Enter the number of pennies: ");pennies = scan.nextInt();total = quarters * 25 + dimes * 10 + nickels * 5 + pennies;dollars = total / 100;cents = total % 100;System.out.println ("Total value: " + dollars + " dollars and " + cents + " cents.");}}//******************************************************************** // DrawName.java Author: Lewis/Loftus//// Solution to Programming Project 2.15//********************************************************************import javax.swing.JApplet;import java.awt.*;public class DrawName extends JApplet{//----------------------------------------------------------------- // Draws a name.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.cyan);page.setColor (Color.black);page.drawString ("John A. Lewis", 50, 50);}}//******************************************************************** // FloatCalculations.java Author: Lewis/Loftus//// Solution to Programming Project 2.4//******************************************************************** import java.util.Scanner;public class FloatCalculations{//----------------------------------------------------------------- // Reads two floating point numbers and prints their sum,// difference, and product.//----------------------------------------------------------------- public static void main (String[] args){float num1, num2;Scanner scan = new Scanner (System.in);System.out.print ("Enter the first number: ");num1 = scan.nextFloat();System.out.print ("Enter the second number: ");num2 = scan.nextFloat();System.out.println ("Their sum is: " + (num1+num2));System.out.println ("Their difference is: " + (num1-num2));System.out.println ("Their product is: " + (num1*num2));}}//******************************************************************** // Fraction.java Author: Lewis/Loftus//// Solution to Programming Project 2.13//******************************************************************** import java.util.Scanner;public class Fraction{//----------------------------------------------------------------- // Computes the floating point equivalent of a fraction.//----------------------------------------------------------------- public static void main (String[] args){int numerator, denominator;float value;Scanner scan = new Scanner(System.in);System.out.print ("Enter the numerator: ");numerator = scan.nextInt();System.out.print ("Enter the denominator: ");denominator = scan.nextInt();value = (float) numerator / denominator;System.out.println ("Floating point equivalent: " + value);}}//******************************************************************** // HousePicture.java Author: Lewis/Loftus//// Solution to Programming Project 2.19//********************************************************************import javax.swing.JApplet;import java.awt.*;public class HousePicture extends JApplet{//----------------------------------------------------------------- // Draws a house scene.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.cyan);page.setColor (Color.gray);page.fillRect (0, 200, 400, 50); // groundpage.setColor (Color.blue);page.fillRect (50, 125, 300, 100); // housepage.setColor (Color.green);page.fillRect (180, 175, 40, 50); // doorpage.setColor (Color.yellow);page.fillRect (100, 155, 40, 25); // windowpage.fillRect (260, 155, 40, 25); // windowpage.setColor (Color.black);page.fillRect (40, 100, 320, 40); // roofpage.fillOval (210, 200, 6, 6); // doorknobpage.setColor (Color.red);page.fillRect (80, 80, 20, 40); // chimneypage.setColor (Color.darkGray);page.fillOval (80, 60, 20, 20); // smokepage.fillOval (85, 50, 15, 25); // smokepage.fillOval (90, 45, 15, 20); // smokepage.setColor (Color.white);page.fillOval (200, 30, 80, 40); // cloudpage.fillOval (230, 40, 80, 40); // cloud}}//******************************************************************** // InfoParagraph.java Author: Lewis/Loftus//// Solution to Programming Project 2.3//********************************************************************import java.util.Scanner;public class InfoParagraph{//----------------------------------------------------------------- // Reads information about a person and incorporates it into an// output paragraph.//----------------------------------------------------------------- public static void main (String[] args){String name, age, college, pet;Scanner scan = new Scanner (System.in);System.out.print ("What is your name? ");name = scan.nextLine();System.out.print ("How old are you? ");age = scan.nextLine();System.out.print ("What college do you attend? ");college = scan.nextLine();System.out.print ("What is your pet's name? ");pet = scan.nextLine();System.out.println ();System.out.print ("Hello, my name is " + name + " and I am ");System.out.print (age + " years\nold. I'm enjoying my time at "); System.out.print (college + ", though\nI miss my pet " + pet);System.out.println (" very much!");System.out.println ();}}//******************************************************************** // Lincoln4.java Author: Lewis/Loftus//// Solution to Programming Project 2.1//********************************************************************public class Lincoln4{//----------------------------------------------------------------- // Prints a quote from Abraham Lincoln, including quotation// marks.//----------------------------------------------------------------- public static void main (String[] args){System.out.println ("A quote by Abraham Lincoln:");System.out.println ("\"Whatever you are, be a good one.\"");}}//******************************************************************** // MilesToKilometers.java Author: Lewis/Loftus//// Solution to Programming Project 2.6//******************************************************************** import java.util.Scanner;public class MilesToKilometers{//----------------------------------------------------------------- // Converts miles into kilometers. The value for miles is read// from the user.//----------------------------------------------------------------- public static void main (String[] args){final double MILES_PER_KILOMETER = 1.60935;double miles, kilometers;Scanner scan = new Scanner(System.in);System.out.print ("Enter the distance in miles: ");miles = scan.nextDouble();kilometers = MILES_PER_KILOMETER * miles;System.out.println ("That distance in kilometers is: " +kilometers);}}//******************************************************************** // MoneyConversion.java Author: Lewis/Loftus//// Solution to Programming Project 2.11//******************************************************************** import java.util.Scanner;public class MoneyConversion{//----------------------------------------------------------------- // Reads a monetary amount and computes the equivalent in bills// and coins.//----------------------------------------------------------------- public static void main (String[] args){double total;int tens, fives, ones, quarters, dimes, nickels;int remainingCents;Scanner scan = new Scanner(System.in);System.out.print ("Enter monetary amount: ");total = scan.nextDouble();remainingCents = (int) (total * 100);tens = remainingCents / 1000;remainingCents %= 1000;fives = remainingCents / 500;remainingCents %= 500;ones = remainingCents / 100;remainingCents %= 100;quarters = remainingCents / 25;remainingCents %= 25;dimes = remainingCents / 10;remainingCents %= 10;nickels = remainingCents / 5;remainingCents %= 5;System.out.println ("That's equivalent to:");System.out.println (tens + " ten dollar bills");System.out.println (fives + " five dollar bills");System.out.println (ones + " one dollar bills");System.out.println (quarters + " quarters");System.out.println (dimes + " dimes");System.out.println (nickels + " nickels");System.out.println (remainingCents + " pennies");}}//******************************************************************** // OlympicRings.java Author: Lewis/Loftus//// Solution to Programming Project 2.18//********************************************************************import javax.swing.JApplet;import java.awt.*;public class OlympicRings extends JApplet{//----------------------------------------------------------------- // Draws the olympic logo.//----------------------------------------------------------------- public void paint (Graphics page){final int DIAMETER = 50;setBackground (Color.lightGray);page.setColor (Color.blue);page.drawOval (30, 40, DIAMETER, DIAMETER);page.setColor (Color.yellow);page.drawOval (60, 70, DIAMETER, DIAMETER);page.setColor (Color.black);page.drawOval (90, 40, DIAMETER, DIAMETER);page.setColor (Color.green);page.drawOval (120, 70, DIAMETER, DIAMETER);page.setColor (Color.red);page.drawOval (150, 40, DIAMETER, DIAMETER);}}//******************************************************************** // PieChart.java Author: Lewis/Loftus//// Solution to Programming Project 2.22//******************************************************************** import javax.swing.JApplet;import java.awt.*;public class PieChart extends JApplet{//----------------------------------------------------------------- // Draws the pie chart with equal sections.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.lightGray);page.setColor (Color.blue);page.fillArc (70, 25, 100, 100, 0, 45);page.setColor (Color.yellow);page.fillArc (70, 25, 100, 100, 45, 45);page.setColor (Color.black);page.fillArc (70, 25, 100, 100, 90, 45);page.setColor (Color.green);page.fillArc (70, 25, 100, 100, 135, 45);page.setColor (Color.red);page.fillArc (70, 25, 100, 100, 180, 45);page.setColor (Color.magenta);page.fillArc (70, 25, 100, 100, 225, 45);page.setColor (Color.cyan);page.fillArc (70, 25, 100, 100, 270, 45);page.setColor (Color.orange);page.fillArc (70, 25, 100, 100, 315, 45);}}//******************************************************************** // Seconds.java Author: Lewis/Loftus//// Solution to Programming Project 2.8//******************************************************************** import java.util.Scanner;public class Seconds{//----------------------------------------------------------------- // Computes the total number of seconds for a given number of// hours, minutes, and seconds.//-----------------------------------------------------------------public static void main (String[] args){final int SECONDS_PER_HOUR = 3600;final int SECONDS_PER_MINUTE = 60;int seconds, minutes, hours, totalSeconds;Scanner scan = new Scanner(System.in);System.out.print ("Enter the number of hours: ");hours = scan.nextInt();System.out.print ("Enter the number of minutes: ");minutes = scan.nextInt();System.out.print ("Enter the number of seconds: ");seconds = scan.nextInt();totalSeconds = hours * SECONDS_PER_HOUR +minutes * SECONDS_PER_MINUTE +seconds;System.out.println ();System.out.println ("Total seconds: " + totalSeconds);}}//******************************************************************** // Seconds2.java Author: Lewis/Loftus//// Solution to Programming Project 2.9//******************************************************************** import java.util.Scanner;public class Seconds2{//----------------------------------------------------------------- // Computes the number of hours, minutes, and seconds that are// equivalent to the number of seconds entered by the user.//----------------------------------------------------------------- public static void main (String[] args){final int SECONDS_PER_HOUR = 3600;final int SECONDS_PER_MINUTE = 60;int seconds, minutes, hours;Scanner scan = new Scanner(System.in);System.out.print ("Enter the number of seconds: ");seconds = scan.nextInt();hours = seconds / SECONDS_PER_HOUR;seconds = seconds % SECONDS_PER_HOUR; // remaining secondsminutes = seconds / SECONDS_PER_MINUTE;seconds = seconds % SECONDS_PER_MINUTE; // remaining secondsSystem.out.println ();System.out.println ("Hours: " + hours);System.out.println ("Minutes: " + minutes);System.out.println ("Seconds: " + seconds);}}//******************************************************************** // ShadowName.java Author: Lewis/Loftus//// Solution to Programming Project 2.21//********************************************************************import javax.swing.JApplet;import java.awt.*;public class ShadowName extends JApplet{//----------------------------------------------------------------- // Draws a name with a slightly offset shadow.//----------------------------------------------------------------- public void paint (Graphics page){setBackground (Color.yellow);page.setColor (Color.black);page.drawString ("John A. Lewis", 50, 50);page.setColor (Color.red);page.drawString ("John A. Lewis", 49, 49);}}//******************************************************************** // Snowman2.java Author: Lewis/Loftus//// Solution to Programming Project 2.14//********************************************************************import javax.swing.JApplet;import java.awt.*;public class Snowman2 extends JApplet{//----------------------------------------------------------------- // Draws a snowman with added features.//----------------------------------------------------------------- public void paint (Graphics page){final int MID = 130;final int TOP = 50;setBackground (Color.cyan);page.setColor (Color.blue);page.fillRect (0, 175, 300, 50); // groundpage.setColor (Color.yellow);page.fillOval (260, -40, 80, 80); // sunpage.setColor (Color.white);page.fillOval (MID-20, TOP, 40, 40); // headpage.fillOval (MID-35, TOP+35, 70, 50); // upper torsopage.fillOval (MID-50, TOP+80, 100, 60); // lower torsopage.setColor (Color.red);page.fillOval (MID-3, TOP+50, 6, 6); // buttonpage.fillOval (MID-3, TOP+60, 6, 6); // buttonpage.setColor (Color.black);page.fillOval (MID-10, TOP+10, 5, 5); // left eyepage.fillOval (MID+5, TOP+10, 5, 5); // right eyepage.drawArc (MID-10, TOP+20, 20, 10, 10, 160); // frownpage.drawLine (MID-25, TOP+60, MID-50, TOP+40); // left armpage.drawLine (MID+25, TOP+60, MID+55, TOP+60); // right armpage.drawLine (MID-20, TOP+5, MID+20, TOP+5); // brim of hatpage.fillRect (MID-15, TOP-20, 30, 25); // top of hatpage.drawString ("John Lewis", 20, 20); // artist}}//******************************************************************** // SquareCalculations.java Author: Lewis/Loftus//// Solution to Programming Project 2.12//******************************************************************** import java.util.Scanner;public class SquareCalculations{//----------------------------------------------------------------- // Computes a square's perimeter and area given the length of// one side.//----------------------------------------------------------------- public static void main (String[] args){int side, perimeter, area;Scanner scan = new Scanner(System.in);System.out.print ("Enter the length of a square's side: ");side = scan.nextInt();perimeter = side * 4;area = side * side;System.out.println ("Perimeter: " + perimeter);System.out.println ("Area: " + area);}}//********************************************************************// TempConverter2.java Author: Lewis/Loftus//// Solution to Programming Project 2.5//******************************************************************** import java.util.Scanner;public class TempConverter2{//----------------------------------------------------------------- // Computes the Celsius equivalent of a Fahrenheit value read// from the user. Uses the formula C = (5/9)(F - 32).//----------------------------------------------------------------- public static void main (String[] args){final int BASE = 32;final double CONVERSION_FACTOR = 5.0 / 9.0;double celsiusTemp, fahrenheitTemp;Scanner scan = new Scanner(System.in);System.out.print ("Enter a Fahrenheit temperature: ");fahrenheitTemp = scan.nextDouble();celsiusTemp = CONVERSION_FACTOR * (fahrenheitTemp - BASE);System.out.println ("Celsius Equivalent: " + celsiusTemp);}}//******************************************************************** // TravelTime.java Author: Lewis/Loftus//// Solution to Programming Project 2.7//******************************************************************** import java.util.Scanner;public class TravelTime{//----------------------------------------------------------------- // Converts miles into kilometers. The value for miles is read// from the user.//-----------------------------------------------------------------public static void main (String[] args){int speed, distance;double time;Scanner scan = new Scanner(System.in);System.out.print ("Enter the speed: ");speed = scan.nextInt();System.out.print ("Enter the distance traveled: ");distance = scan.nextInt();time = (double) distance / speed;System.out.println ("Time elapsed during trip: " + time); }}。
java期末复习题库及答案
java期末复习题库及答案一、选择题1. Java是一种()。
A. 编译型语言B. 解释型语言C. 标记语言D. 汇编语言答案:B2. Java程序的执行流程是()。
A. 编译 -> 链接 -> 执行B. 编译 -> 执行C. 编译 -> 解释 -> 执行D. 解释 -> 执行答案:C3. 下列哪个是Java的关键字?()A. classB. functionC. includeD. namespace答案:A4. Java中的类是()。
A. 抽象的B. 具体的C. 既是抽象的也是具体的D. 以上都不是答案:A5. Java中,哪个关键字用于定义一个类?()A. publicB. classC. voidD. int答案:B二、填空题1. Java语言的跨平台特性主要得益于______机制。
答案:JVM(Java虚拟机)2. 在Java中,所有的类都是继承自______类。
答案:Object3. Java中的______关键字用于定义一个方法。
答案:void 或者其他返回类型4. 在Java中,______关键字用于定义一个类是公共的。
答案:public5. Java中的______关键字用于定义一个变量是静态的。
答案:static三、简答题1. 简述Java语言的特点。
答案:Java语言具有面向对象、跨平台、健壮性、多线程、安全性、简单性等特点。
2. 什么是Java的垃圾回收机制?答案:Java的垃圾回收机制是指JVM自动检测内存中不再被使用的对象,并释放它们占用的内存资源,以防止内存泄漏。
3. 什么是Java的异常处理机制?答案:Java的异常处理机制是指程序在执行过程中,当出现错误或异常情况时,Java运行时环境提供的一种处理机制,包括try、catch、finally和throw等关键字的使用。
四、编程题1. 编写一个Java程序,实现计算两个整数的和。
JAVA多选题
1.break ,continue ,return 的区别及作用正确的是(ABCD )A.break 跳出现在的循环块,不再执行循环(结束当前的循环体);B.continue 跳出本次循环,继续执行下次循环(结束正在执行的循环进入下一个循环条件);C.return 程序返回,不再执行下面的代码(结束当前的方法直接返回);D.以上说法都正确;2.以下关于final关键字说法错误的是(AC)A.final是java中的修饰符,可以修饰类、接口、抽象类、方法和属性;B.final修饰的类肯定不能被继承;C.final修饰的方法不能被重载;D.final修饰的变量不允许被再次赋值;3.下面哪些不是java的简单数据类型(BC)A.short;B.Boolean;C.Double;D.float;4.以下哪四个能使用throw抛出(ABCD)A.Error;B.Throwable;C.Exception;D.RuntimeException;5.下列关于静态方法描述正确的是( AC )A.非静态方法中可以调用任何成员;B.静态方法中可以使用this和super区分成员;C.静态方法中只能调用静态成员;D.静态方法只能通过对象进行调用;6.下列关于类和接口的关系说法正确的是( ABD )A.Java中的类与类只能单继承, 可以多层继承;B.Java中的类与接口是实现关系, 一个类可以在继承一个类的同时实现多个接口;C.Java中的接口与接口属于实现关系, 只能单实现;D.Java中的接口与接口属于继承关系, 可以单继承, 也可以多继承;7.关于等待唤醒方法描述正确的是(ACD)A.wait方法调用会导致当前线程释放掉锁资源;B.notify和notifyAll方法调用会导致当前线程释放掉锁资源;C.等待和唤醒的方法,都要使用锁对象调用;D.等待和唤醒方法应该使用相同的锁对象调用;8.下列关于数组和集合描述正确的是( CD )A.数组和集合的长度都是可变的;B.数组只能存储基本数据类型,集合只能存储引用数据类型;C.数组的长度固定,集合的长度可变;D.数组可以存储基本数据类型和引用数据类型, 集合只能存储引用数据类型;9.下列关于增强for循环说法正确的是( ABD )A.增强for循环可以遍历数组也可以遍历单列集合;B.增强for循环没有索引;C.增强for遍历集合, 可以通过集合对象修改集合的长度;D.增强for的底层采用的是迭代器;10.下列关于单列集合体系说法正确的是(ABC)A.List和Set都是属于Collection的子接口;B.ArrayList类属于List接口的实现类;C.HashSet类属于Set接口的实现类;D.LinkedHashMap类属于Collection接口的实现类;11.下列属于Collections工具类中的方法有( ACD )A.shuffle() : 对单列集合进行乱序;B.remove() : 删除集合中的元素;C.sort() : 对单列集合进行排序;D.addAll() : 对单列集合批量添加元素;12.下列对于Map集合的特点说法正确的是( BC )A.所有的双列集合都是无序的;B.键不能重复,值可以重复;C.键和值是一一对应的,通过键可以找到对应的值;D.Map集合键可以重复, 但是值是唯一的;13.下列对于Map集合方法描述正确的是( BCD )A.add() : 添加元素;B.remove() : 根据键删除元素;C.keySet() : 获取键集合;D.containKey() : 判断集合是否存在指定的键;14.下列关于自动装箱和拆箱正确的是( ABCD )A.自动装箱指的是基本数据类型自动转成对应的包装类类型;B.自动拆箱指的是包装类类型自动转成对应的基本数据类型;C.Integer i = 10; // 属于自动装箱;D.Int num = new Integer(“100”); // 属于自动拆箱;15.以下哪些是运行时异常(ABCD)ng.lndexOutOfBoundsException;ng.NullPointerException;C.java.util.ConcurrentModificationException;D.java.time.format.DataTimeParseException;16.以下哪些能够保证线程安全(BC)A.单例模式;B.java.util.Hashtable;C.synchronized;D.volatile;17.以下哪些语句可以正常创建Lock对象(ABD)A.Lock lock = new ReentrantLock(true);B.Lock lock = new ReentrantLock();C.Lock lock = new Lock();D.Lock lock = new ReentrantLock(false);18.对下列运算结果,判断正确的是(AD )A.“1az098”.matches("\d[a-z]{2,8}[0-9]+")结果为true;B.“1az098”.matches("\d[a-z]{2,8}[0-9]+")结果为false;C.“张三,李四,王五,马六,”.split("[,]+").length == 1;该表达式结果返回true;D.“张三,李四,王五,马六,”.split("[,]+").length == 4;该表达式结果返回true19.String str = “We are students”; 下面说法正确的是(AC )A.str的长度是15;B.str的长度是14;C.str.indexOf(“a”)返回的结果是3;stIndexOf(“e”)返回的结果是3;20.下列逻辑表达式,值为false的是(BCD)A.“abc,bcd,def,efg,”.split("[,]+").length == 4;B.“1st456”.matches("\d[a-z&&[^et]]{2,8}[0-9]+");C.“abcdefghijklmnopqrstuvwxyz”.substring(5,26).length() == 20;D.“whatisjava”.equals(null);21.在Java语言中,下列说法正确的是:(ABD)A.StringBuffer和StringBuilder的区别在于:StringBuffer是线程安全的而StringBuilder不是;B.String是不可变对象,而StringBuffer中封装的字符串数据是可以动态改变的;C.判断两个StringBuilder对象的字符序列是否相同,可以调用其equlas方法进行比较;D.String的重写了equals方法,重写的逻辑是:字符序列相同的String对象equals方法返回true;22.关于Java8 Optional的说法正确的是(AB)A.Optional的map()方法,允许改变容器中元素类型B.Optional的filter()方法执行过滤,容器中元素不符合条件,会返回一个空容器C.orElse()方法,会创建默认对象替代容器中元素对象D.Optional.ofNullable()方法中传入空引用变量,将抛出异常23.下列关于Stream流中获取功能有哪些( ACD )A.Collection接口中的默认方法stream()生成流;B.Map接口中的默认方法stream()生成流;C.Arrays中的静态方法stream生成流;D. Stream类中of方法生成流;24.下列关于Stream流中中间功能有哪些( ABC )A.filter()方法用于对流中的数据进行过滤;B.sorted()方法将流中元素进行排序;C.limit()方法截取指定参数个数的数据D.collector()方法收集流中的数据;25.下列关于Stream流中终结功能有哪些((ABD )A.forEach()方法对流中的元素遍历;B.count()方法返回此流中的元素数;C.skip()方法跳过指定参数个数的数据;D.collector()方法收集流中的数据;26.按照学生平均成绩(avg_grade) 将students表中的数据检索出来,下面SQL语句正确的是(ACD)A.SELECT * FROM students ORDER BY avg_grade;B.SELECT * FROM students GROUP BY avg_grade ASC;C.SELECT * FROM students ORDER BY avg_grade DESC;D. SELECT * FROM students ORDER by avg_grade asc27.下列索引定义不符合规范的是(CD)A.uniq_order_idB.idx_user_ider_id_order_idD.idx_a_b_c_d_e_f28.下面有关sql 语句中delete、truncate的说法正确的是(AC)A.论清理表数据的速度,truncate一般比delete更快;B.truncate命令可以用来删除部分数据;C.truncate只删除表的数据不删除表的结构;D.delete能够回收高水位(自增ID值);29.在SQL中语法规范中,having子句的使用下面描述正确的是(AC)A.having子句即可包含聚合函数作用的字段也可包括普通的标量字段使用having的同时不能使用where子句;B.having子句必须于group by 子句同时使用,不能单独使用使用having子句的作用是限定分组条件;C.having子句和where子句是等同的;D.having子句后面必须使用聚合函数;30.下列中属于MyBatis全局配置文件中的标签是(ACD)A.settings;B.select;C.plugins;D.properties;31.在MyBatis 动态SQL 中,循环使用的标签名不正确的是(ABD)A.for;B.while;C.foreach;D.do-while;32.关于MyBatis传递数组参数的说法正确的是(ABD)A.在映射文件中取得数组值应该通过< forEach>标签;B.< forEach>标签可以应用于set、List以及数组的取值;C.传递数组的值,和多参数传值一样在映射文件中只能通过< forEach>取值;D.< forEach>标签的open和close属性用于写开始和结束标签;33.对mybatis描述有误的是(CD)A.MyBatis 是一个可以自定义SQL、存储过程和高级映射的持久层框架;B.MyBatis 的缓存分为一级缓存和二级缓存,一级缓存放在session 里面;C.Mybatis是一个全ORM(对象关系映射)框架,它内部封装了JDBC;D.MyBatis 只可以使用XML来配置和映射原生信息;34.Mybatis是如何将sql执行结果封装为目标对象并返回的(BC)A.id;B.< resultMap>标签;C.使用sql列的别名;D.resultType;35.mybaties中模糊查询like语句的写法(AD)A.select * from foo where bar like #{value}B.select * from foo where bar like #{%value%}C.select * from foo where bar like %#{value}%D.select * from foo where bar like “%”${value}"%"36.Mybatis的Xml映射文件中,不同的Xml映射文件,id是否可以重复?选择说法正确的(AB)A.不同的Xml映射文件,如果配置了namespace,那么id可以重复;B.如果没有配置namespace,那么id不能重复C.如果没有配置namespace,id能重复D.不同的Xml映射文件,如果配置了namespace,那么id不可以重复37.Mybatis的mapper接口调用时候的要求正确的是(ABC)A.Mapper接口方法名和Mapper.xml中定义的每个SQL的id相同B.Mapper接口方法的输入参数类型和mapper.xml中定义的每个sqlparameterType类型相同C.Mapper接口方法的输入输出参数类型和mapper.xml中定义的每个sql的resultType的类型相同D.Mapper.xml文件中的namespace,就是接口的名字38.MyBatis内置类型别名有那些(AC)A._int;B.Integer;C.Int;D.String;39.Mybatis动态sql标签有哪些(ABC)A.trim;B.foreach;C.set;D.than40.实体类中的属性名和表中的字段名不一样怎么处理(AC)A.查询的sql语句中定义字段名的别名;B.不用处理;C.通过< resultMap>来映射字段名和实体类属性名;D.通过< resultType>来映射字段名和实体类属性名;41.关于MyBatis参数处理说法正确的是(BC)A.传递单个参数时,MyBatis会自动封装到Map集合中;B.传递单个参数时,MyBatis会自动进行参数的赋值;C.传递多个参数时,MyBatis会自动封装到Map集合中;D.传递多个参数时,MyBatis会自动进行参数的赋值;42.@SpringBootApplication注解是一个组合组件,下面是属于它的有(ACD)A.ConfigurationB.ControllerC.EnableAutoConfigurationpontScan43.以下哪些是SpringBoot默认支持自动装配的(ABC)A.spring-boot-starter-webB.spring-boot-starter-data-redisC.spring-boot-starter-securityD.mybatis-spring-boot-starter44.下面关于SpringBoot启动说明正确的是(BCD)A.SpringBoot项目启动就会加载bootstrap.properties文件B.SpringBoot项目启动会加载所有的在spring.factories中配置的监听器C.SpringBoot项目启动的时候会发布相关事件,从而会触发对应的监听器来完成对应的操作D.SpringBoot项目启动本质上就是Spring的初始化操作45.SpringBoot读取配置相关注解有(ABCD)A.@PropertySourceB.@ValueC.@EnvironmentD.@ConfigurationProperties46.Spring Boot 里面,可以使用以下哪几种方式来加载配置(ABCD)A.properties文件;B.YAML文件;C.系统环境变量;D.命令行参数;47.Dubbo集群提供了哪些负载均衡策略(ABCD)A.Random LoadBalance: 随机选取提供者策略,有利于动态调整提供者权重;B.RoundRobin LoadBalance: 轮循选取提供者策略;C.LeastActive LoadBalance: 最少活跃调用策略;D.ConstantHash LoadBalance: 一致性Hash 策略;48.Dubbo 核心组件有哪些(ABCD)A.Provider:暴露服务的服务提供方;B.Consumer:调用远程服务消费方;C.Registry:服务注册与发现注册中心;D.Monitor:监控中心和访问调用统计;49.下列哪些是SpringBoot数据源的配置项(ABC)A.spring.datasource.url=jdbc:mysqI://127.0.0.1:3306/news?useUnicode=true&characterEncoding=utf8;ername=root;C.spring.datasource.password=pwd;D.spring.datasource.driver-class =com.mysql.jdbc.Drive50.Spring Boot有哪些优点(BCD)A.完全没有代码生成和xml配置文件;B.使用JavaConfig有助于避免使用XML;C.避免大量的Maven导入和各种版本冲突;D.通过提供默认值快速开始开发。
Java基础题库
1.Java属于以下哪种语言?(C)A. 机器语言B. 汇编语言C. 高级语言D. 以上都不对2.下列目录中,哪一个是用来存放JDK核心源代码的?(B)A. lib目录B. src目录C. jre目录D. include目录3.下面命令中,可以用来正确执行HelloWorld案例的是(A)A. java HelloWorldB. java HelloWorld.javaC. javac HelloWorldD. javac HelloWorld.java4.下面关于配置path环境变量作用的说法中,正确的是(A)A. 在任意目录可以使用javac和java命令B. 在任意目录下可以使用class文件C. 在任意目录可以使用记事本D. 在任意目录下可以使用扫雷游戏5.下列选项中,可以正确配置classpath的命令是(A)A. set classpath =C:\Program Files\Java\jdk1.7.0_15\binB. set classpath : C:\Program Files\Java\jdk1.7.0_15\binC. classpath set =C:\Program Files\Java\jdk1.7.0_15\binD. classpath set : C:\Program Files\Java\jdk1.7.0_15\bin6.下面选项中,完全面向对象的编程语言是?(C)A. CB. COBOLC. JAVAD. FORTRAN7.下列关于Java特点的描述中,错误的是?(C)A. Java语言不支持指针B. Java具有自动垃圾回收的机制C. Java只能运行在Window和Linux平台D. Java允许多个线程同时执行8.下列关于JDK、JRE和JVM关系的描述中,正确的是(D)A. JDK中包含了JRE,JVM中包含了JRE。
B. JRE中包含了JDK,JDK中包含了JVM。
(完整版)JAVA试题及答案(50道选择题)
选择题1、JAVA所定义的版本中不包括:( D )A、JAVA2 EEB、JAVA2 CardC、JAVA2 MED、J AVA2 HEE、J AVA2 SE2、下列说法正确的是( A )A、JAVA程序的main方法必须写在类里面B、JAVA程序中可以有多个main方法C、JAVA程序中类名必须与文件名一样D、J AVA程序的main方法中如果只有一条语句,可以不用{}(大括号)括起来3、变量命名规范说法正确的是( B )A、变量由字母、下划线、数字、$符号随意组成;B、变量不能以数字作为开头;C、A和a在java中是同一个变量;D、不同类型的变量,可以起相同的名字;4、下列javaDoc注释正确的是( C )A、/*我爱北京天安门*/B、//我爱北京天安门*/C、/**我爱北京天安门*/D、/*我爱北京天安门**/5、为一个boolean类型变量赋值时,可以使用( B )方式A、boolean = 1;B、boolean a = (9 >= 10);C、boolean a="真”;D、b oolean a = = false;6、以下(C )不是合法的标识符A、STRINGB、x3x;C、voidD、d e$f7、表达式(11+3*8)/4%3的值是( D )A、31B、0C、1D、28、( A )表达式不可以作为循环条件A、i++;B、i>5;C、bEqual = str。
equals("q");D、c ount = = i;9、运算符优先级别排序正确的是(A )A、由高向低分别是:()、!、算术运算符、关系运算符、逻辑运算符、赋值运算符;B、由高向低分别是:()、关系运算符、算术运算符、赋值运算符、!、逻辑运算符;C、由高向低分别是:()、算术运算符、逻辑运算符、关系运算符、!、赋值运算符;D、由高向低分别是:()、!、关系运算符、赋值运算符、算术运算符、逻辑运算符;10、以下程序的运行结果是:( B )public class Increment{public static void main(String args[]) {int a;a = 6;System。
Java语言程序设计课程教学辅导技术资料——第1章 Java2 语言概述(第1部分)
1.1Java语言程序设计课程教学辅导技术资料——第1章 Java2 语言概述(第1部分)【教学目标】让学员了解Java的主要特点,Java的主要应用领域,系统类库的主要版本,Java应用系统的开发方式,Java是如何实现“平台无关”。
1.1.1Java2 语言概述1、Java2的主要技术特点(1)面向对象:以类为编程单元并通过对象来操作使用类中的数据成员(属性)、代码成员(方法)(2)分布式编程模式:功能代码可以分散在客户机、服务器机及其它主机中(3)与平台(CPU、OS类型)无关性一次编程到处执行,Write Once, Run AnyWhere,而传统的计算机应用程序需要针对不同的应用平台进行开发。
2、Java2类库的版本和主要应用领域(1)Java2类库的版本类型J2ME(Java2 Micro Edition),针对嵌入式设备的编程技术。
J2SE(Java2 Standard Edition),针对桌面计算机开发J2EE(Java2 Enterprise Edition),针对企业级的分布式应用,主要涉及JDBC、RMI、EJB、Servlet、JSP以及Web Service、XML等方面的技术(2)Java2主要应用领域嵌入式技术(如嵌入式设备、移动通讯设备、手持式设备、测试仪器等);基于Application/Applet、JavaBean的PC应用;基于动态网站的Servlet、JSP 应用,实现Web应用程序等基于EJB的J2EE企业级分布式应用等,主要是解决企业级异构环境(不同主机、不同的操作系统)下的编程。
3、Java应用编程的开发方式(1)方式一采用标准的JDK,可以从/下载获得,并且设置JDK的环境变量(2)方式二采用第三方的开发工具,目前流行的工具有IDE开发工具:如JCreator()RAD可视化开发工具:Borlandc公司的JBuilder、SyManTec公司的Visual Café、IBM公司的Visual Age for Java4、Java编译、解释执行过程图示1.1.2Java语言基础1、Java中的数据类型(1)数据类型种类基本数据类型(int、float、char、boolean、byte等,但要注意的是:在Java中不直接提供对指针的支持!)复合数据类型(数组、类、接口等)。
java 英文句子拆分短语 -回复
java 英文句子拆分短语-回复1. Java is an object-oriented programming language.2. He wrote his first Java program last night.3. Java was created by James Gosling at Sun Microsystems.4. Java programs can run on any platform that supports the Java Virtual Machine.5. The Java Virtual Machine is responsible for executing compiled Java code.6. The Java Development Kit includes the Java compiler, the Java Virtual Machine, and other tools.7. Java supports multithreading, allowing for concurrent execution of code.8. Unlike C++, Java does not have pointers, which makes it easier to write secure code.9. Java's exception handling mechanism allows for graceful error handling.10. The Java Standard Edition includes APIs for graphics, networking, and I/O operations.11. Java applets were once popular for running in a web browser, but are now considered outdated.12. Java Enterprise Edition provides APIs for developing enterprise-level applications.13. JavaFX is a platform for developing rich, graphical applications using Java.14. JavaBeans are reusable software components used in building Java applications.15. The Java Native Interface allows for integration with code written in other programming languages.16. Java is used extensively in Android app development.17. Java is an interpreted language, which allows for fast development and testing.18. The Java Runtime Environment is required to run Java programs.19. Java supports both primitive and object data types.20. The Java platform is constantly evolving, with new versions and updates being released regularly.。
2022年全国计算机等级考试二级JAVA上机模拟试卷(5)
2022年全国计算机等级考试二级JAVA上机模拟试卷(5)2022年全国计算机等级考试二级JAVA上机模拟试卷(5)一、选择题(每小题1分,共40分)1.为保护本地主机,对Applet安全限制中正确的是()。
[1分]A.Applet可加载本地库或方法B.Applet可读、写本地计算机的文件系统C.Applet可向Applet之外的任何主机建立网络连接D.Applet不能运行任何本地可执行程序2.下面的()关键字通常用来对对象加锁,从而使得对对象的访问是排他的。
[1分]A.serializeB.transientC.synchronizedD.static3.下列叙述中,错误的是()。
[1分]A.JavaApplication与Applet所用编译命令相同B.通常情况下JavaApplication只能有一个main()方法C.JavaApplet必须有HTML文件才能运行D.JavaApplet程序的.class文件可用Java命令运行4.以下程序计算1+1/3+1/5+…+1/(2N+1),直至1/(2N+1)小于0.00001,横线处应补充的程序是()。
public class Sun{public static void main(String args[]){int n=1:double term,sum=1.0:do{n= __ ;term=1.0/n;sum=sum+term;}while(term=0.00001);System.out.println(n);System.out.println(sum);}}[1分]A.2nB.2n+1C.2*nD.2*n+15.阅读下列代码片段class InterestTest——ActionListener{public"void actionPerformed(ActionEvent event){double interest=balance*rate/1 00 ;balance+=interest;NumberFormat format=NumberFormat.getCur-rencyInstance();System.OUt.print]b("balance="+formatter.format(balance));}Private double rate;}在下画线处,应填的正确选项是()。
2022年计算机等级《二级JAVA》考前押密试题
2022年计算机等级《二级JAVA》考前押密试题2022年计算机等级《二级JAVA》考前押密试题1.【单选题】3分| 软件按功能可以分为:应用软件、系统软件和支撑软件(或工具软件),下面属于系统软件的是()。
A 编辑软件B 操作系统C 教务管理系统D 浏览器2.【单选题】3分| 下面的()关键字通常用来对对象加锁,从而使得对对象的访问是排他的。
A serializeB transientC synchronizedD static3.【单选题】3分| 下列方法中,不属于Throwable类的方法是()。
A printMessageB getMessageC toStringD fillStackTrace4.【单选题】3分| 下列选项中为单精度数的是()。
B 5.2C 0.2fD 235.【单选题】3分| 下列选项中,与成员变量共同构成一个类的是()。
A 关键字B 方法C 运算符D 表达式6.【单选题】3分| 下列说法正确的是()。
A 共享数据的所有访问都必须作为临界区B 用synchronized保护的共享数据可以是共有的C Java中对象加锁不具有可重人性D 对象锁不能返回7.【单选题】3分| AWT中用来表示颜色的类是()。
A FontB ColorC PanelD Dialog8.【单选题】3分| 在创建线程时可以显式地指定线程组,此时可供选择的线程构造方法有()种。
B 2C 3D 49.【单选题】3分| 将E—R图转换为关系模式时,实体和联系都可以表示为()。
A 属性B 键C 关系D 域10.【单选题】3分| 下列事件监听器中,无法对TextField对象进行事件监听和处理的是()。
A ActionListenerB FocusListenerC MouseMotionListenerD ChangeListener11.【单选题】3分| Java中的线程模型由三部分组成,与线程模型组无关的是()。
走进JAVA编程知到章节答案智慧树2023年昆明理工大学
走进JAVA编程知到章节测试答案智慧树2023年最新昆明理工大学第一章测试1.下面的方法中,不能实现为Java程序输入数据的是___________。
( )参考答案:直接使用System.in对象的各种方法2.Scanner对象中用于读取一个整数的方法是_________。
( )参考答案:nextInt3.Java既是开发环境,又是应用环境,它代表了一种新的计算模式。
()参考答案:对4.Java是一种严格的面向对象语言,编写的所有代码都限定在类内完成。
()参考答案:对5.JVM的代码格式为压缩的字节码,因而效率较高。
()参考答案:对第二章测试1.有声明语句“final int P=3;int s;”,下列的哪个语句是正确的________。
()参考答案:s=2*P;2.public class Ex49 {public static void main(String args[]) {float a=20.28f,b=5.0F;a%=b;b*=b+2;System.out.println(""a=""+a+"",b=""+b);}}"上面程序的运行结果是________。
()参考答案:a=0.28,b=35.003.基本数据类型的变量在声明时,系统会给它们分配相应的存储空间。
()参考答案:对4.引用型数据类型的变量在声明时,系统不会为它们分配相应的存储空间。
( )参考答案:错5.在Java语言中可以同时使用ASCII码和Unicode码。
( )参考答案:错第三章测试1.else子句总是与和它具有相同缩进格式的if语句配对。
()参考答案:错2.在for循环中,初始化语句可以定义两种不同类型的变量。
()参考答案:错3.在switch语句中的表达式计算结果可以是浮点型。
()参考答案:错4.public class Exa2 {public static void main (String[] args){int grade;grade=Integer.parseInt(args[0]);if(grade>=60)System.out.println(""及格"");else if(grade>=70)System.out.println(""中"");else if(grade>=80)System.out.println(""良"");else if(grade>=90)System.out.println(""优"");elseSystem.out.println(""不及格"");}}仔细阅读上面的程序,选择正确答案________。
java虚拟机规范
Java 虚拟机规范第 3 页/ 共387 页版权声明1. 本翻译工作完全基于个人兴趣爱好以及学术研究目的,不涉及出版或任何其他商业行为。
本次翻译与Oracle 或其他Java 虚拟机厂商无关,译文是非官方的翻译。
2. 译者曾经尝试邮件联系过原文作者,但是一直未获得到回复。
根据我国著作权法第22 条规定,以教学、科研为目的,可以不经著作权人许可翻译其已经发表的作品,不向其支付报酬,但应当指明作者姓名、作品名称,且不得出版发行。
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如果需要进行商业使用,则必须到原作者和译者的授权。
附原文版权声明如下:Specification: JSR-000924 Java™ Virtual Machine Specification ("Specification") Version: 7Status: Final ReleaseRelease: July 2011Copyright 2011 Oracle America, Inc. and/or its affiliates. All rights reserved.500 Oracle Parkway M/S 5op7, California 94065, U.S.ALIMITED LICENSE GRANTS1. License for Evaluation Purposes. Oracle hereby grants you a fully-paid,non-exclusive,non-transferable, worldwide, limited license (without the right to sublicense), under Oracle's applicable intellectual property rights to view, download, use and reproduce the Specification only for the purpose of internal evaluation. 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With respect to any patent claims covered by the license granted under subparagraph2 above that would be nfringed by all technically feasible implementations of the Specification, such license is conditioned upon your offering on fair, reasonable and non-discriminatory terms, to any party seeking it from You, a perpetual, non-exclusive, non-transferable, worldwide license under Your patent rights which are or would be infringed by all technically feasible implementations of the Specification to develop, distribute and use a CompliantImplementation.b With respect to any patent claims owned by Oracle and covered by the license granted under subparagraph 2, whether or not their infringement can be avoided in a technically feasible manner when implementing the Specification, such license shall terminate with respectto such claims if You initiate a claim against Oracle that it has, in the course of performing its responsibilities as the Specification Lead, induced any other entity to infringe Your patent rights.c Also with respect to any patent claims owned by Oracle and covered by the license granted第 5 页/ 共387 页under subparagraph 2 above, where the infringement of such claims can be avoided in a technically feasible manner when implementing the Specification such license, with respect to such claims, shall terminate if You initiate a claim against Oracle that its making, having made, using, offering to sell, selling or importing a Compliant Implementation infringes Your patent rights.5. 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No modification to this Agreement will be binding, unless in writing and signed by an authorized representative of each party.第7 页/ 共387 页目录译者序 (2)版权声明 (4)目录 (8)前言 (14)第二版说明 (15)Java SE 7 版说明 (15)第1 章引言 (18)1.1 简史 (18)1.2 Java 虚拟机 (18)1.3 各章节提要 (19)1.4 说明 (20)第2 章Java 虚拟机结构 (21)2.1 Class 文件格式 (21)2.2 数据类型 (22)2.3 原始类型与值 (22)2.3.1 整型类型与整型值 (23)2.3.2 浮点类型、取值集合及浮点值 (24)2.3.3 returnAddress 类型和值 (26)2.3.4 boolean 类型 (26)2.4 引用类型与值 (27)2.5 运行时数据区 (27)2.5.1 PC 寄存器 (28)2.5.2 Java 虚拟机栈 (28)2.5.3 Java 堆 (29)2.5.4 方法区 (29)第8 页/ 共387 页2.5.5 运行时常量池 (30)2.5.6 本地方法栈 (30)2.6 栈帧 (31)2.6.1 局部变量表 (32)2.6.2 操作数栈 (33)2.6.3 动态链接 (34)2.6.4 方法正常调用完成 (34)2.6.5 方法异常调用完成 (34)2.7 对象的表示 (35)2.8 浮点算法 (35)2.8.1 Java 虚拟机和IEEE 754 中的浮点算法 (35)2.8.2 浮点模式 (36)2.8.3 数值集合转换 (37)2.9 初始化方法的特殊命名 (38)2.10 异常 (38)2.11 字节码指令集简介 (40)2.11.1 数据类型与Java 虚拟机 (41)2.11.2 加载和存储指令 (44)2.11.3 运算指令 (45)2.11.4 类型转换指令 (46)2.11.5 对象创建与操作 (47)2.11.6 操作数栈管理指令 (48)2.11.7 控制转移指令 (48)2.11.8 方法调用和返回指令 (49)2.11.9 抛出异常 (49)2.11.10 同步 (49)2.12 类库 (50)2.13 公有设计,私有实现 (51)第3 章为JAVA 虚拟机编译 (53)第9 页/ 共387 页3.1 示例的格式说明 (53)3.2 常量、局部变量的使用和控制结构 (54)3.3 算术运算 (58)3.4 访问运行时常量池 (59)3.5 更多的控制结构示例 (61)3.6 接收参数 (64)3.7 方法调用 (64)3.8 使用类实例 (67)3.9 数组 (69)3.10 编译switch 语句 (71)3.11 使用操作数栈 (73)3.12 抛出异常和处理异常 (74)3.13 编译finally 语句块 (78)3.14 同步 (81)3.15 注解 (82)第4 章Class 文件格式 (84)4.1 ClassFile 结构 (85)4.2 各种内部表示名称 (90)4.2.1 类和接口的二进制名称 (90)4.2.2 非全限定名 (90)4.3 描述符和签名 (91)4.3.1 语法符号 (91)4.3.2 字段描述符 (92)4.3.3 方法描述符 (93)4.3.4 签名 (94)4.4 常量池 (97)4.4.1 CONSTANT_Class_info 结构 (98)4.4.2 CONSTANT_Fieldref_info,CONSTANT_Methodref_info 和CONSTANT_InterfaceMethodref_info 结构 (99)第10 页/ 共387 页4.4.3 CONSTANT_String_info 结构 (100)4.4.4 CONSTANT_Integer_info 和CONSTANT_Float_info 结构 (101)4.4.5 CONSTANT_Long_info 和CONSTANT_Double_info 结构 (102)4.4.6 CONSTANT_NameAndType_info 结构 (103)4.4.7 CONSTANT_Utf8_info 结构 (104)4.4.8 CONSTANT_MethodHandle_info 结构 (106)4.4.9 CONSTANT_MethodType_info 结构 (107)4.4.10 CONSTANT_InvokeDynamic_info 结构 (107)4.5 字段 (108)4.6 方法 (110)4.7 属性 (113)4.7.1 自定义和命名新的属性 (115)4.7.2 ConstantValue 属性 (116)4.7.3 Code 属性 (117)4.7.4 StackMapTable 属性 (120)4.7.5 Exceptions 属性 (126)4.7.6 InnerClasses 属性 (128)4.7.7 EnclosingMethod 属性 (130)4.7.8 Synthetic 属性 (131)4.7.9 Signature 属性 (132)4.7.10 SourceFile 属性 (132)4.7.11 SourceDebugExtension 属性 (133)4.7.12 LineNumberTable 属性 (134)4.7.13 LocalVariableTable 属性 (135)4.7.14 LocalVariableTypeTable 属性 (137)4.7.15 Deprecated 属性 (139)4.7.16 RuntimeVisibleAnnotations 属性 (139)4.7.16.1 element_value 结构 (141)4.7.17 RuntimeInvisibleAnnotations 属性 (143)第11 页/ 共387 页4.7.18 RuntimeVisibleParameterAnnotations 属性 (144)4.7.19 RuntimeInvisibleParameterAnnotations 属性 (146)4.7.20 AnnotationDefault 属性 (147)4.7.21 BootstrapMethods 属性 (148)4.8 格式检查 (150)4.9 Java 虚拟机代码约束 (150)4.9.1 静态约束 (150)4.9.2 结构化约束 (153)4.10 Class 文件校验 (156)4.10.1 类型检查验证 (157)4.10.2 类型推导验证 (158)4.10.2.1 类型推断的验证过程 (158)4.10.2.2 字节码验证器 (158)4.10.2.3 long 和double 类型的值 (161)4.10.2.4 实例初始化方法与创建对象 (162)4.10.2.5 异常和finally (163)4.11 Java 虚拟机限制 (165)第5 章加载、链接与初始化 (167)5.1 运行时常量池 (167)5.2 虚拟机启动 (170)5.3 创建和加载 (170)5.3.1 使用引导类加载器来加载类型 (172)5.3.2 使用用户自定义类加载器来加载类型 (172)5.3.3 创建数组类 (173)5.3.4 加载限制 (174)5.3.5 从Class 文件中获取类 (175)5.4 链接 (176)5.4.1 验证 (176)5.4.2 准备 (177)第12 页/ 共387 页5.4.3 解析 (178)5.4.3.1 类与接口解析 (179)5.4.3.2 字段解析 (179)5.4.3.3 普通方法解析 (180)5.4.3.4 接口方法解析 (181)5.4.3.5 方法类型与方法句柄解析 (182)5.4.3.6 调用点限定符解析 (185)5.4.3 访问控制 (185)5.4.5 方法覆盖 (186)5.5 初始化 (187)5.6 绑定本地方法实现 (189)5.7 Java 虚拟机退出 (189)第6 章Java 虚拟机指令集 (190)6.1 设定:“必须”的含义 (190)6.2 保留操作码 (190)6.3 虚拟机错误 (191)6.4 指令描述格式 (191)6.5 指令集描述 (193)第7 章操作码助记符 (379)第13 页/ 共387 页前言《Java 虚拟机规范》是一份完整的描述Java 虚拟机是如何设计的规范文档。
关于JavaSpace和Jini系统
一.摘要随着网络技术的发展,分布式计算越来越显示出巨大的优势。
只有具备跨平台、动态、健壮、安全、方便灵活等特性的分布式平台才是用户所急需的。
文中讨论了一种全新的基于Java 技术的分布式计算平台Jini,主要介绍了其与传统的分布式系统相比所具有的优势,以及其基本原理和关键概念,Jini系统的三个组成部分:基础设施、编程模式和协议,和提供的服务和服务过程。
最后讨论了Jini技术在数字家庭网络中的应用关于JavaSpace的应用方面Jini提供了在分散式环境中寻找(look-up)、注册(registration)、租借(leasing)等功能。
而JavaSpaces则负责管理分散式物件的处理程序(processing)、分享(sharing)、以及流通(migration )等。
因此Jini 与JavaSpaces 彼此存在著相互合作的关系。
以军队作比喻,Jini扮演的是军官的角色,负责分派许多武器装备给军队。
JavaSpaces则扮演军队的角色,负则使用那些被分派的武器以执行命令。
简单的说,JavaSpaces就好像网路上的一个市场,它提供一个简单、快速、统一的介面,让网路上分散的资源可以被分享、协调与流通。
JavaSpaces是用Java所发展的技术,并且以RMI实作其网路通讯的功能,一般应用在n-tiers 架构的中间层(middle tiers)。
JavaSpaces虽然能提供求者与供应者之间查询与沟通的机制,但它并不是资料库,而是以简单的messaging system为基础,进而提供更强大的功能。
Jini 代表着计算技术的深刻变化,在联合用户组和对分布式资源的高效处理的基础上,将网络变成一个灵活的、易管理的工具, 通过它用户或任何可计算实体均能发现对其有用的资源,从而完成各种分布式计算。
资源可以是硬件设备、软件或两者的结合。
同时系统使得网络是一个动态的实体, 该实体具有灵活地增加和删除服务的能力,很好地反映了工作组的动态特性。
java选择题
java选择题1、Java属于以下哪种语言?()A、机器语言B、汇编语言C、高级语言D、以上都不对2、在JDK安装目录下,用于存放可执行程序的文件夹是?A、binB、jreC、libD、db3、下列Java命令中,哪一个可以编译HelloWorld.java文件?A、java HelloWorldB、java HelloWorld.javaC、javac HelloWorldD、javac HelloWorld.java4、以下关于java命令作用的描述中,正确的是A、它专门负责解析由Java编译器生成的.class文件B、它可以将编写好的Java文件编译成.class文件C、可以把文件压缩D、可以把数据打包5、下面关于配置path环境变量作用的说法中,正确的是()A、在任意目录可以使用javac和java命令B、在任意目录下可以使用class文件C、在任意目录可以使用记事本D、在任意目录下可以使用扫雷游戏6、下面关于path和classpath的说法中,错误的是()A、path用来指定java 虚拟机(JVM) 所在的目录B、classpath用来指定我们自己所写的或要用到的类文件(.jar文件) 所在的目录C、在dos命令行中,classpath和path环境变量的查看与配置的方式不相同D、只要设置了classpath 这个环境变量系统就不会再在当前目录下查询某个类7、下面关于classpath的说法中,错误的是()。
A、classpath和path环境变量的查看与配置的方式完全相同。
B、为了让Java虚拟机能找到所需的class文件,就需要对classpath环境变量进行设置。
C、从JDK5.0开始,如果classpath环境变量没有进行设置,Java虚拟机会自动将其设置为“.”,也就是当前目录。
D、在命令行窗口中配置了classpath后,重新打开新命令行窗口依然生效8、下面哪种类型的文件可以在Java虚拟机中运行?()A、.javaB、.jreC、.exeD、.class9、阅读下段代码片段,选择正确的运行结果public static void main(String[] args) {int a = 1;System.out.print(a);}{int a = 2;System.out.print(a);}int a = 3;System.out.print(a);}A、123B、111C、121D、编译不通过10、下面选项中,哪个是短路与运算符()A、&B、&&C、|D、||11、关于表达式1234/1000 * 1000的运算结果,下列哪个选项是正确的()A、1234B、1000C、1234.0D、以上都不对12、下面的运算符中,用于执行除法运算是哪个?A、/B、\C、%D、*13、以下哪个选项可以正确创建一个长度为3的二维数组()A、new int [2][3];B、new int[3][];C、new int[][3];D、以上答案都不对14、下列选项中,不属于比较运算符的是A、=B、==C、<D、<=15、下列选项中,用于引入包的关键字是A、classB、importC、package16、下列选项中,哪一个不能通过编译()A、byte a=1;B、short b=100;C、int c='a';D、long d=8888888888;17、下列选项中,哪一个是多行注释符号?()A、//* *//B、/* /*C、/ /D、/* */18、为了能让外界访问私有属性,需要提供一些使用()关键字修饰的公有方法。
智慧树答案基于创业思维的软件开发技术(JAVA)知到课后答案章节测试2022年
第一章1.编译Java Application源文件将产生相应的字节码文件,扩展名是什么()答案:class2.Java语言具有许多优点和特点,下列选项中,哪个反映了Java中“一次编译,随处运行”的特点。
()答案:平台无关性3.Java语言具有许多优点和特点,下列选项中,哪个反映了Java中并行机制的特点。
()答案:多线程4.一个Java源文件中最多只能有多少个public类。
()答案:1个5.下面哪一个不是Java语言所具有的特点。
()答案:没有全局变量,在类的定义外部没有任何的变量定义;第二章1.若有定义 int a=9,b=6; 那么a>b的值是:()答案:true2.执行完以下代码int[ ] x = new int[25];后,以下说明正确的是:()答案:x[24]为03.设 x = 1 , y = 2 , z = 3,则表达式 y+=z--/++x 的值是()答案:34.执行System.out.println(5/4),这条代码的输出结果是()答案:15.下列语句有错误的是:()答案:int c[]=new int[];第三章1.下列关于变量的叙述哪个是错的?()答案:实例变量用关键字static声明。
2.在Java语言中,下列哪个包是编译器自动导入的?()答案:ng3.不允许作为类及类成员的访问控制符的是()答案:static4.为AB类的一个无形式参数无返回值的方法method书写方法头,使得使用类名AB作为前缀就可以调用它,该方法头的形式为()答案:static voidmethod( )5.Java提供的许多类在不同的包中,使用下面哪个语句可以引入包中的类。
()答案:import第四章1.以下关于abstract的说法,正确的是()答案:abstarct方法所在的类必须用abstract修饰2.下列哪种说法是正确的()答案:私有方法不能被子类覆盖。
3.以下关于继承的叙述正确的是()答案:在Java中类只允许单一继承4.子类对象能否直接向其父类赋值?父类对象能否向其子类赋值?()答案:能,不能5.如果局部变量和成员变量同名,如何在局部变量作用域内引用成员变量?()答案:在成员变量前加this,使用this访问该成员变量1.Java中用于定义接口的关键字是()答案:interface2.关于类继承的说法,正确的是()答案:Java接口允许多继承3.关于抽象类,正确的是()答案:某个非抽象类的父类是抽象类,则这个子类必须重载父类的所有抽象方法4.以下关于抽象类和接口的说法错误的是()答案:接口中的方法都必须加上public关键字。
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JavaSpaces-An Affordable Technology For The Simple Implementation Of Reusable Parallel EvolutionaryAlgorithmsChristian Setzkorn,Ray C.PatonDepartment of Computer Science,University of Liverpool,UKAbstract.Parallel evolutionary algorithms are often used to alleviate the largecomputational demands of standard evolutionary algorithms.Unfortunately,im-plementations of parallel evolutionary algorithms can be complicated and oftenrequire specific hardware and software settings.This frequently results in veryproblem-specific parallel evolutionary algorithms with little scope for reuse.Thispaper investigates the JavaSpaces technology to help to overcome these prob-lems.This technology is free of charge,simplifies the implementation of paral-lel/distributed applications,and is independent of hardware and software speci-fications.Several approaches for the implementation of different parallel evolu-tionary algorithms using JavaSpaces are proposed and successfully tested.1IntroductionIt is well known that evolutionary algorithms require large amounts of computational re-sources,especially when the problems to be tackled become complicated and/or when the evaluation of the candidate solutions is computationally expensive[3].This can hamper their practicality.For these reasons,many researchers have proposed paradigms to execute evolutionary algorithms in parallel.This has given rise to Parallel Evolution-ary Algorithms(PEAs).Several proposed PEAs are reviewed in[3,17].Unfortunately, implementations of PEAs can be complicated,and often require specific hardware and software specification.This frequently results in very problem-specific applications with little scope for reuse.This paper investigates the utility of the JavaSpaces technology1for the implemen-tation of a synchronous master-slave PEA[10]and a coarse-grained PEA.The proposed frameworks can be used to tackle different problems concurrently with evolutionary al-gorithms.The JavaSpaces technology has many advantages:it is free of charge,known to simplify the implementation of parallel/distributed applications and is independent of hardware and software settings.It can therefore be used to harvest the computational power of a number of different computers within institutions.The computers can have different hardware and software specifications.To our knowledge JavaSpaces itself has not been used to implement PEAs.Atienza et al.[2]has used the Jini technology to implement PEAs.JavaSpace builds upon Jini,but Jini is harder to use.The scalability of the implemented approaches is evaluated on a particular machine-learning problem;the induction of classifiers from data.Evolutionary algorithms havebeen used successfully for this task in the past.In fact,they sometimes produce better classifiers then deterministic approaches because they perform a global search,and can cope better with attribute interactions[5,8].Unfortunately,evolutionary approaches are often too slow to be used for large real-world data sets.This is due to the fact that each individual has to be evaluated on a large number of data samples to determine its fitness[1].The implemented approach induces fuzzy classification rules systems from data using a multi-objective evolutionary approach,building upon the work of Zitzler et al.[19]and Ishibuchi et al.[12].This type of classifier was chosen due to its potential high comprehensibility[15].A general introduction to the problem of fuzzy classifica-tion rule induction can be found in[13].Cord´o n et al.[4]provide an introduction to the construction of fuzzy classification rule systems utilising evolutionary algorithms.This paper is structured as follows.Section2provides some details about the JavaS-paces technology.The implemented approaches are explained in section3and their scalability is investigated in section4.Section5contains the conclusions,and suggests avenues for future research.2JavaSpaces-A Brief IntroductionSUN Microsystems Inc.proposed the JavaSpaces specification in1999.It was inspired by the concept of Linda[9].Linda’s core idea is that an object storage can greatly sim-plify the implementation of parallel and distributed applications.This is because it can be accessed by several processes using a small number of operations.The object stor-age is referred to as‘tuple space’[9],hence the name JavaSpaces.SUN Microsystems Inc.offers an implementation of the JavaSpaces specification,which utilises technolo-gies such as Jini,RMI[14,18]and the programming language JA V A[11].Therefore a JavaSpace can be executed on many different computer platforms due to JA V A’s plat-form independence.Processes that run within a network of computers,can access the JavaSpace in a concurrent manner.This allows them to communicate and coordinate their actions by writing and reading objects to and from the JavaSpace.Objects are entities that are defined in terms of data and behaviours.They can represent numbers,strings or ar-rays,and executable programs(evolutionary algorithm individuals).The JavaSpace it-self handles the concurrent access,and hence frees the programmer from problems such as race conditions.Objects can be exchanged using the operations write,read,and take. Transactions[7]can be used to make the operations secure because there are many po-tential sources of failure within a network.For example,objects can get lost on the way between a writing/reading process and a JavaSpace.Processes can register their interest for a particular type of object with the space.If the specific object is written into the JavaSpace,it notifies the processes via a Remo-teEvent[16].Therefore,many different applications(evolutionary algorithms)could use a JavaSpace at the same time.In summary,the JavaSpaces technology provides a shared,persistent,and securely accessible opportunity to exchange objects for processes in a computer network.Thisallows the simple implementation of parallel and distributed applications.For an in-depth introduction to the JavaSpace technology see for example[7,6].3The Implemented Approaches3.1The Synchronous Master-Slave Parallel Evolutionary AlgorithmFigure1depicts the structure of the JavaSpaces based synchronous master-slave PEA implementation.The synchronous master-slave PEA wasfirst proposed by Grefenstette in1981[10].The JavaSpaces implementation was inspired by the compute-server ap-proach proposed by Freeman et al.[7].Fig.1.Structure of the JavaSpaces based synchronous master-slave PEA implementation.The master executes the evolutionary algorithm.During thefitness evaluation copies of individuals are written into the JavaSpace.When the master creates a copy of an individual,it attaches a unique identifier and a web server address(URL)to it.Workers (slave computers)take individuals from the space(one at the time)and evaluate them. If data is required during the evaluation,it is downloaded from the web server indicated by the URL attached to each individual.This is only done if the worker has not already downloaded the necessary data.A worker does not return the evaluated individual into the space but rather a‘result object’consisting of the individual’s objective values and its unique identifier.The master removes these result objects from the space,and uses the unique identifier to update the objective values of a particular individual.The master carries on with other evolutionary processes as soon as it has updated the objective values of all individuals.This approach has many advantages,which are listed and explained now.o It is easy to implement and does not change the dynamics of the underlying evolu-tionary processo It implements automatic load balancing.Workers that represent more powerful computers,or those that receive simpler individuals can evaluate more of them as they can access the space concurrently.o Workers can be added and removed whilst the evolutionary process is running.o Workers can be executed on many different hardware and software platforms be-cause they are implemented in JA V A,which is a platform independent language. o Workers do not steal any computational resources as long as no individuals are written into the space.They could therefore run/sleep on all the computers of an in-stitution at all times.A policy could be established that individuals are only written into the space outside normal working times.In this manner all the computer power of an institution could be harvested with virtually no cost,since the computers are often not switched off and JavaSpaces is free of charge.o The programming language JA V A also offers what is known as dynamic class downloading[18],which enables workers to evaluate individuals originating from different EAs that are tackling different problems.As long as the object(a par-ticular individual)implements a specific interface(e.g.SpaceIndividualInterface),a slave computer is capable of downloading the necessary classfiles from a webserver in order to evaluate(execute)this individual.This means that such a parallel evolutionary algorithm can be reused(without shut-down)or could even be used by several users,running different evolutionary algorithms at the same time.However,the presented approach has one disadvantage.It does not fully exploit the power of the utilised computers.This is due to the idle times of the master and the work-ers.The master has to wait until all the workers have returned the evaluated individuals and the workers are idle until the master initiates thefitness evaluation again.Asyn-chronous master-slave and coarse-grained PEAs can be used to overcome these prob-lems.The implemented of these PEAs using the JavaSpaces technology is explained in the next sections.3.2The Asynchronous Master-Slave Parallel Evolutionary AlgorithmThe asynchronous master-slave PEA has the same structure as the synchronous master-slave PEA and was also put forward by Grefenstette in1981[10].In order to tackle the afore-mentioned‘idle time problem’of the synchronous master-slave PEA,a non-generational EA is executed on the master.Individuals are written into the space as soon as they require evaluation(e.g.after mutation).Therefore workers are constantly supplied with individuals and the master can proceed with other evolutionary processes as soon as a sufficient number of individuals have been taken from the space2.This results in lower idle-times for both workers and the master.3.3The Coarse-Grained Parallel Evolutionary AlgorithmThe coarse-grained PEA has the same structure as the synchronous master slave ap-proach.However each worker runs an evolutionary algorithm instead of just evaluating individuals.The workers have to be startedfirst.When a worker has started,it writes an object containing its IP-address into the space.After all workers have started,the mas-ter is started.It removes all objects from the space.The master then writes an object containing all the accumulated IP-addresses back in the space.Each worker reads this object from the space.This makes the workers aware of each other.The master now initialises a population of individuals and writes them into the space.Each of these individuals contains an IP-address and,if necessary,the web server address of the data.An IP-address is chosen with a uniform probability from the previ-ously accumulated IP-addresses.A worker reads those individuals from the space that contain its IP-address.Each individual also contains a counter.Each time an individual passes through the evolutionary algorithm this counter is increased.If counter reaches a maximum value (number of generations),an indicator is added to the individual and it is written in the space.This indicator makes it impossible for a worker to take such an individual from the space again.The master can only take an individual from the space if it contains this indicator.This enables the master to accumulate thefinal population.If an individual’s counter has not yet reached its maximum value,a process within the worker decides whether or not a particular individual is sent(migrated)to another worker or whether it remains with the worker.An individual only migrates with a specific probability(migration probability).To migrate an individual the original IP-address is removed from it.After this,another worker’s IP-address is attached to it be-fore it is written into the space.This IP-Address is sampled with a uniform probability from the other workers IP-addresses.An interesting property of this implementation of a coarse grained PEA approach is that its behaviour only depends on two parameters:the migration probability and the number of workers.The approach is also topologically independent because all workers are virtually interconnected via the space3.This makes this implementation much easier when compared to other approaches.The migration probability controls the communication costs.If a low migration probability is choosen,the approach can be expected to be faster than the synchronous master-slave approach.4Methodology And ResultsTo investigate the scalability of the synchronous master-slave PEA(parallel implemen-tation),it isfirst compared against a serial implementation,which performs thefitness evaluation locally.After this,several parallel implementations are compared,which utilise different numbers of workers.The master and the serial implementation were executed on a PC with the operating system Windows2000,a single Intel Pentium42.6GHz processor,and1GB memory. The workers were executed on PCs with the operating system Windows2000,a single Intel Celeron2GHz processor,and256MB memory.The JavaSpace and the web server ran on one PC running the operating system Linux(RedHat9.0).This machine had a single AMD Athlon1.3GHz processor and512MB memory.The latest JavaSpaces version that comes with Jini2.0was used4.All machines were connected via a100 Mbit switched network.For thefirst experiments several synthetic data sets were created,each containing between1000to10000samples.A population of one hundred individuals was evaluated ten times on each data set.The average evaluation time and standard deviations were computed.Figure2depicts the results of thefirst experiment.parison between the serial implementation(dotted line)and the JavaSpace implemen-tation(solid line)utilisingfive slave computers.It can clearly be seen that the parallel implementation outperforms the serial im-plementation for data containing more than1000samples.Data sets of this size arenot uncommon nowadays.Figure3compares several synchronous master-slave PEAs, which utilise different numbers of workers.parisons between several parallel implementation utilising different numbers of work-ers(4workers-solid line,eight workers-dashed line,sixteen workers-dotted line).A data set can contain between10000to200000samples.It can clearly be seen that the utilisation of more workers results in a faster evaluation time for these data sets. Figure4depicts the achieved ratios of the decrease in evaluation time.The‘four work-ers’parallel implementation is compared with the‘eight workers’and‘sixteen workers’parallel implementation,whereas the‘eight workers’parallel implementation is com-pared with the‘sixteen workers’implementation.Ratios of the decrease in evaluation time of two,four,and two are expected.Figure4shows that the deployment of eight workers results in a decrease in evalu-ation time by a factor of two.One would expect the same when eight instead of sixteen workers are deployed.Unfortunately,this is not the case.The reason for this might be extra communication costs due to the existence of a larger number of workers.This is also emphasised by the fact that the deployment of sixteen workers instead of four workers only results in a speedup of about three and a half.Three experiments were performed to compare the three PEAs.For each experi-ment a PEA was run one hundred times.For each run a data set containing N rows was produced.The value for N was determined randomly through uniform sampling from the interval.An EA run terminated after the selection process generated1000individuals.This termination criterion enabled a comparison of gener-ational and non-generational approaches.This termination criterion also works for the00.20.40.60.81 1.2 1.4 1.6 1.82x 10511.522.533.54Number of rowsR a t i o o f d e c r e a s e i n e v a l u a t i o n t i m e Fig.4.Ratios of the decrease in evaluation time (8vs 16workers -dotted line,4vs 8workers -solid line,4vs 16workers -dashed line).coarse-grained PEA,although it has several selection processes.As each individual is equipped with a counter,it enables one to measure how many individuals all selection processes have produced globally.The individuals had a fixed size to keep the communication costs constant.A mi-gration probability of 0.1was used for the coarse-grained PEA.This means that (on average)every tenth individual is migrated to another EA.The three experiments utilised the following hardware and software settings.All workers (EAs in the case of the coarse-grained PEA)were executed on PCs with the operating system Linux,a single AMD Athlon 1.3GHz processor and 512MB mem-ory.The master implementations were executed on a PC with the operation system Windows 2000,and a single AMD Athlon 850MHz processor and 256MB memory.The JavaSpace was executed on a machine with the same specification as that of the workers.The JavaSpace implementation that comes with Jini 1.4was used.The utilised web server was a HP RP 2400machine,with one PA 8500RISC 440MHz proces-sor,630MB memory,and Apache 1.3.6and the HP-UX 11.00operating system.All computers were connected via a 100Mbit switched network.It is important to note that other users have used the machines,except the master,while the experiments were performed.Therefore the results show that the approach can be used in a multi-user environment.As stated above,an experiment consisted of one hundred pairs of independent val-ues (number of cases)and dependent values (execution time in seconds).In order tocompare experiments visually the statistical package SAS5was used.For each exper-iment a regression line wasfitted through the data.A ninety-nine percent confidence interval was computed for the mean predicted values for each experiment.Figure5 shows the results when twenty workers are deployed.parsion between different PEAs(Group1:20-worker synchronous master-slave PEA, Group2:20-worker asynchronous master-slave PEA,Group3:20-worker coarse-grained PEA).It can clearly be seen that the coarse-grained PEA outperforms the synchronous master-slave PEA for more than three thousand rows.The coarse-grained PEA outper-forms the asynchronous master-slave PEA for more than one hundred thousand rows. However,the spread of data points also indicates that the execution time of the coarse-grained PEA can vary.5Conclusions And Future WorkThis paper has shown that the JavaSpaces technology can be used to improve the per-formance of evolutionary algorithms in a simple and affordable manner.Several ap-proaches for the implementation of different parallel evolutionary algorithms were pro-posed and successfully tested using this technology.It was also shown that the PEAimplementations perform well in multi-user heterogeneous computer networks.As ex-pected,the coarse-grained PEA outperformed the synchronous and asynchronous mas-ter slave PEAs.This is most probably due to its low communication costs.Although the coarse-grained PEA is capable of evolving the same amount of individuals in a shorter period of time,in comparison to the other PEAs,it remains an open question whether or not these individuals perform as well as the individuals that were evolved by the other PEAs.Further studies are required to investigate this issue.References1. D.L.A.Araujo,H.S.Lopes,and A.A.Freitas.Rule Discovery with a Parallel Genetic Algo-rithm.In Proceedings of the Genetic and Evolutionary Computation Conference Workshop Program2000,pages89–92,Las Vegas,USA,July2000.2.J.Atienza,M.Garcia,J.Gonz´a lez,and J.J.Merelo.Jinetic:a distributed,fine-grained,asyn-chronous evolutionary algorithm using jini,2000.3. E.Cant´a-Paz.A survey of parallel genetic algorithms.Calculateurs Paralleles,Reseaux etSystems Repartis,10(2):141–171,1998.4.O.Cord´o n,F.Herrera,F.Hoffmann,and L.Magdalena.Genetic Fuzzy Systems.WorldScientific,2001.5.V.Dhar,D.Chou,and F.J.Provost.Discovering interesting patterns for investment decisionmaking with glower-a genetic learner overlaid with entropy reduction.Data Mining and Knowledge Discovery,4(4):251–280,2000.6.R.Flenner.Jini and JavaSpaces Application Development.Sams,2001.7. E.Freeman,S.Hupfer,and K.Arnold.JavaSpaces(TM)Principles,Patterns and Practice.Addison-Wesley Longman Ltd.,1999.8. A.A.Freitas.A survey of evolutionary algorithms for data mining and knowledge discovery.In A.Ghosh and S.Tsutsui,editors,Advances in Evolutionary Computation,pages819–845.Springer-Verlag,2002.9. D.Gelernter.Generative communication in linda.ACM Transactions on ProgrammingLanguages and Systems,7(1):80–112,1985.10.J.J.Grefenstette.Parallel adaptive algorithms for function optimization.Technical ReportCS-81-19,1981.Vanderbilt University,Computer Science Department,Nashville.11.J.Hunt.Java and Object Orientation.Springer,1998.12.H.Ishibuchi,T.Nakashima,and T.Murata.Three-Objective Genetics-Based Machine Learn-ing for Linguistic Rule rmation Sciences,136:109–133,2001.13.L.I.Kuncheva.Fuzzy Classifier Design.Heidelberg:Physica-Verlag,2000.14.S.Li.Professional Jini.Wrox,2000.15. D.Michie.Learning concepts from data.Expert System with Applications,15:193–204,1998.16.Sun Microsystems.Java distributed event specification,1998.17.M.Nowostawski and R.Poli.Parallel genetic algorithm taxonomy.In Proceedings of thethird international conference on knowledge-based intelligent information engineering sys-tems(KES’99),pages88–92.IEEE Press,1999.18. E.Pitt and K.McNiff.Java.RMI.Addison-Wesley Longman Ltd.,2001.19. E.Zitzler,umanns,and L.Thiele.SPEA2:Improving the Strength Pareto Evolution-ary Algorithm.In EUROGEN2001-Evolutionary Methods for Design,Optimisation and Control with Applications to Industrial Problems,2001.。