1照明回路计算

1照明回路计算：

总功率: Pe =0.796KW

取Pe=0.796kW Kd =0.8 cos φ=1.0 tg φ=0 Pc = Pe ×Kd=0.796×0.8=0.6368kW

Qc = Pc ×tg φ=0.6368×0=0kvar Sc =2200.6368+=0.6368kVA

Ic = Sc ÷U=0.6368÷0.22=2.89A

2厨房插座计算:

总功率: Pe =2000W

取Pe=2kW Kd =0.9 cos φ=0.95 tg

φ=0.33 Pc = Pe ×Kd=2×0.9=1.8kW

Qc = Pc ×tg φ=1.8×0.33=1.71kvar Sc =2201.711.8+=2.4828kVA

Ic = Sc ÷U=2.4828÷0.22=11.29A

3卫生间插座计算:

总功率: Pe =1000W

取Pe=1kW Kd =0.9 cos φ=0.95 tg

φ=0.33 Pc = Pe ×Kd=1×0.9=0.9kW

Qc = Pc ×tg φ=1.8×0.33=0.594kvar Sc =220.5940.9+=1.0783kVA

Ic = Sc ÷U=1.0783÷0.22=4.9A

4一般插座:

总功率: Pe =2000W

取Pe=2kW Kd =0.9 cos φ=0.9 tg

φ=0.48 Pc = Pe ×Kd=2×0.9=1.8kW

Qc = Pc ×tg φ=1.8×0.48=0.864kvar Sc =220.8641.8+=1.9975kVA

Ic = Sc ÷U =1.9975÷0.22=9.08A

4一般插座

总功率: Pe =2000W

取Pe=2kW Kd =0.9 cos φ=0.9 tg

φ=0.48

Pc = Pe ×Kd=2×0.9=1.8kW

Qc = Pc ×tg φ=1.8×0.48=0.864kvar Sc =22 1.8641.8+=1.41kVA

Ic = Sc ÷U =1.41÷0.22=6.54A

5壁挂式空调插座

总功率: Pe =2000W

取Pe=2kW Kd =0.5 cos φ=0.9 tg φ=0.48 Pc = Pe ×Kd=2×0.5=1kW

Qc = Pc ×tg φ=1×0.48=0.48kvar Sc =220.481+=1.11kVA

Ic = Sc ÷U=1.11÷0.22=5A

6台式空调插座:

总功率: Pe =2000W

取Pe=2kW Kd =0.5 cos φ=0.9 tg φ=0.48 Pc = Pe ×Kd=2×0.5=1kW

Qc = Pc ×tg φ=1×0.48=0.48kvar Sc =220.481+=1.11kVA

Ic = Sc ÷U=1.11÷0.22=5A

B 户总功率: Pe =9796W

取Pe=9.796kW Kd =0.9 cos φ=0.9 tg φ=0.48 Pc = Pe ×Kd=9.796×0.9=8.8164kW

Qc = Pc ×tg φ=8.8164×0.48=4.23kvar Sc =22 4.238.8164+=9.78kVA

Ic = Sc ÷U=9.78÷0.22=44.46A