(第四周)每日一练
青岛版三年级下册数学每周一练三下周周清 (2)
三年级班第一周姓名:估一估:718÷9 478÷6 567÷8 463÷92、算一算:756÷9= 436÷4= 750÷5=3、脱式计算:258+348÷4 900-379+539 630÷5÷71、三位数除以一位数,商是()位数或()位数。
2、一个数除以7,商是137,余数是5。
这个数是()3、一头大象相当于7匹马的体重,一头牛相当于3匹马的体重,一头牛重300千克,一头大象重()千克。
4、510÷5的商是()位数。
9□6÷3商的中间有0,□里最大填()。
5、最大的三位数除以最大的一位数商是()位数。
1、5千克鲜鱼能晒成1千克鱼干,445千克鲜鱼能晒成多少千克鱼干?要求能晒成多少千克鱼干?列式是:445÷5,为什么用除法计算?()2、一辆汽车7小时行驶了518千米,求这辆汽车的速度。
列式是:()说一说为什么这样列式?()。
3、每盒巧克力有9包,每包有4块,要购买432块巧克力。
需要买多少盒?要求需要买多少盒?可以先算(),再算(),列综合算式:()也可以先算(),再算(),列综合算式:()。
1、包装车间要把960瓶酒包装起来,每盒装2瓶酒,每箱装4盒。
一共能装多少箱?2、一架飞机7秒钟飞行952千米,平均每秒飞行多少千米?3、一堆煤300吨,先用载重12吨的汽车运一次,余下的用载重6吨的汽车运,还需要几次?三年级班第二周姓名:1、直接写得数:480÷6= 360÷3= 640÷8= 208÷2= 416÷2=505÷5= 304×3= 24×5= 324÷3= 125×8=2、脱式计算:142-125÷5 804÷(730-724) 980-643+279= = =1、305÷3的商中间有()个0.2、要使872÷□商的中间出现0,□内应填()。
2019广东中考英语短文填空每日一练第四周(有答案)
2019广东中考英语短文填空每日一练第四周(有答案)第一天I love fashion. In the past, I only wore American brands. And in my1 , the most popular student was always the one who wore the latest pair of Jordans.At that time, I paid 2 attention to Chinese brands like Li-Ning, because l thought they were not in fashion. And I thought that Chinese clothes couldn't be as comfortable as American ones. But later, I found I was3 . More and more basketball players are wearing Li-Ning shoes. A few pairs of Li-Ning shoes4 on eBay are even over $ 1, 000!However, in the past, a few China-made products were not so 5 . In 2011, for example, some Chinese toys were found to have heavy metals which were bad for kids' 6 . And in 2018, China's largest provider of milk powder (奶粉) had to recall 700 tons of milk powder after one child died and more than 50 others had health 7 .Nowadays, the Chinese government and companies have 8 this serious problem. They pay more attention to China-made products. They want to9 more things as good as American ones. Now some Chinese brands have become stronger in the American market, 10 it's time to change our opinion about China-made products. We should support products that are made in China.第二天In some provinces of Canada, people celebrate Family Day on the second Monday of February. It is a holiday that gives families the chance to __1__ together.On Family Day, many people plan and take part in activities such as visiting artmuseums watching movies, playing games and holding parties, with their families. Some communities plan special public __2__ too.__3__ the weather is usually very cold in February, some people __4__ choose to stay at home. Hot chocolate and freshly made cookies are the most popular snacks for __5__. Other people use the long weekend as a chance to take a short winter break, or to travel to visit friends.On Family Day, most people have a day off work or school. Many stores and supermarkets are __6__,but post offices may be open. Buses run __7__ to their usual timetables .Family Day was first __8__ in Alberta, Canada in 1990. It was held to show the importance of family and home that were important to people in Alberta. Later, Family Day was __9__ to other provinces, such as Ontario and Saskatchewan. British Columbia celebrated Family Day as a(n) __10__ for the first time in 2013. One of the reasons for introducing Family Day was that there were no holidays from New Year's Day to Good Friday (受难节). It was such a long time.第三天People once went hungry. A rich man who made bread and cakes sent for twenty of the __1__ children in the town, and told them to take a loaf(条)of bread from a __2__ every day till the hard days passed.The hunger children came together __3__,and argued for the bread, because each wished to have the largest one. Finally they went away without even thanking the good gentleman.But Gretchen, a poorly-dressed little girl, did not argue or __4__ with the rest, but remained standing quietly far away from them. __5__ the bad-mannered girls left, she took the smallest bread, which alone was left in the basket, kissed the gentleman's hand, and went home.The next day the children were as bad-mannered as before, and poor, shy Gretchen __6__ a loaf hardly the size of the one she got the first day. When she came home, her mother cut the loaf open. Many new shining pieces of __7__ fellout of it.H er mother was very surprised and worried, and said, “Take the money back to the good gentleman at once, for it must have got into the dough(生面团) __8__ mistake. Be quick, Gretchen! Be quick!”But when the little girl gave the rich man her mother's __9__,h e said, “No, no, my child, it was no mistake. I had the silver pieces put into the smallest loaf to give you. Always be as satisfied, quiet, and __10__ as you now are. Go home now, and tell your mother that the money is your own. ”第四天1 Sunday morning, I usually get up very late. I wash my face and then go out to do morning exercises. After I have2 , I often go to a supermarket with my mother. The supermarket is3 my home, so we4 walk there. It takes us about 105 to get there on foot. The supermarket has a good __6 . It’s called Hao You Duo. It’s new and big.7 are many things there, such as TVs, fridges, computers, clothes, shoes, food and drinks. Of course there are many people there. They are men and women, old and8 . Parents must look9 their children 10 the supermarket is so big that young children may get lost in it. The supermarket is open from 9:00 am to 9:00 pm every day. The shopkeepers are very nice and friendly. The things in it are usually good and cheap. If you come here, I can take you to have a look.第五天Jenny was my grandmother’s sister and she was an amazing woman. She was born in 1901 and 1 in 2000. It was a pity that she didn’t live to celebrate(庆祝)her 100th birthday, 2 she had a good, long life.She had already been a professional 3 before many women had jobs. She taught in Africa for many years. Then she moved to Malaysia and taught English there for a few years. At that time, people didn’t travel 4 a plane, so she had to travel there by ship. It took her three months 5 from England to Malaysia in those days.In 1947,she traveled by plane for the first time. This made traveling 6 easier and quicker. She continued to teach around the world until she was 75 years old.Jenny really loved teaching and she was also good at telling stories. I always loved to hear her 7 about her stories. They were 8 interesting that I would like to listen to her when I was free. It was 9 that she could remember everything even though she was so old. I think it was because she never stopped 10 and thinking .My grandmother’s sister was really an amazing woman.第六天Friendship, which you think may have lost, will come back amazingly. I had a best friend __1__ the age of 7. Two years later, her family moved to England. Before she left, she gave me a similar bracelet(手镯) to __2__. She said it was like our friendship. She also told me to be __3__ with it and remember our friendship. She __4__ that she would be back to visit me one day.Years passed, __5__ I never saw her. I took the bracelet off, because I thought she might have forgotten me.Guess what! All these years, our parents __6__ kept in touch(保持联系). One day, they decided to see each other at the city where we lived, without telling us. Later that night, when we met, we were both __7__,and of course, very pleased to see each other again. Then we talked about the things that __8__ to us all these years. In the conversation, she found I wasn't __9__ the bracelet she gave me, so she asked why. I explained the __10__ with patience. Then she said, “I promised you that I would come back, so here I am today. I always remember our friendship. I will do everything I can to keep my promise. ”第七天The universe is really mystical ( 神秘的). Scientists have done lots of study about it but there is still much they haven't discovered.Scientists think that there __1__ life on the earth for many years. However, we haven't found life on any other planets __2__.There are eight planets going around the sun. The earth is one of them. There are humans, animals, plants and many other kinds of life on the earth. There is water and air, too. And compared to the other planets, the earth is not too __3__ or too cold. None of seven other planets has an environment like that of the earth.The sun and its planets are called the solar system, and our solar system is a small part of a __4__ larger group of stars and planets, called the Galaxy or the Milky Way. There are billions __5__ stars in the Galaxy, and our sun is only one of them.Scientists have also discovered many other galaxies in the universe. Their light has to travel for many years to reach us. So how _6__ is the universe?It is impossible to imagine.Scientists have sent spaceships to the planet Mars to__7__ photos. They have even sent spaceships to travel outside __8__ solar system. However, no spaceship has travelled __9__ enough to reach other stars in our Galaxy.When we see stars twinkling ( 闪耀) in the sky at night, we may think a lot:__10__ so many stars in the universe, is there life out there in space? If there is life on other planets, what life will be like there? What transports do they use to travel? Why don't they visit us?We do not know the answers...参考答案第一天.1. school 2.little 3.wrong 4. sold 5. good6.health7. problems8. Realized9. produce 10. so第二天1.stay 2.events 3. Because 4.just 5.them6. closed7.to8. held9. introduced 10.holiday第三天1.poorest 2. basket 3. excitedly 4. fight 5. When6.received7. silver8. by9. message 10. thankful第四天1.On2.breakfast3.near4.always5. D.minutes7.There8.young9.after 10..because第五天1.died 2. but 3. teacher 4. by 5..to sail6. much7.talk8.so9. amazing 10.working第六天1. at 2. hers 3. careful 4. promised 5. but7.still 7. surprised 8. happened 9. wearing 10. reason 第七天1.has been 2.yet 3. hot 4.much 5.of6. large7. take8. the9. far 10. with。
专升本英语每日一练·第四周
每日一练第一天1.The___you start,the___you'll finish the work.A.early……soonB.earlier……soonerC.early……soonerD.earlier……soon2.If you are worried___the problem,you should do something about it.A for B.about C.with D.on3.英译汉:have an effect on4.英译汉:identify with5.英译汉:The main idea of the passage……答案:1.B the more,the more的句型,越…就越…。
early的比较级为earlier.soon的比较级为sooner.译文:你开始得越早,就能越快完成工作。
2.B be worried about固定短语,担心3.对…有影响4.认为…等同于5.这段话的中心思想/主旨大意是......第二天1.Your nose is bleeding.___you'd better lie down immediately.A.SoB.orC.whatD.when2.jack speaks a little Chinese,___he can’t write in it.A.ButB.howC.andD.otherwise3.英译汉:What does the passage imply about......4.英译汉:The reason why......5.英译汉:According to......答案:1.A你的鼻子流血了,所以你最好立刻躺在床上。
so表因果。
2.A杰克会说一点汉语,但是他不会写。
But,前后表示转折。
3.这段话主要是关于……4.......的原因是.....5.根据……第三天1.I prefer to live in the country rather than___in a city.A.to liveB.loveC.lovingD.loved2.Mr.Brown's monthly income has increased___100dollars.A.inB.atC.byD.on3.英译汉:What can we know about......4.英译汉:From the passage we know...5.英译汉:Which of the following statements is TRUE?答案:1.B固定搭配prefer to rather than do,宁愿....也不.....2.C increase by增长了increase to增长到3.我们可以了解到....4.从这段话我们知道……5.下列那句话是正确的?第四天1.It was between1830and1835___the modern newspaper was born. when B.that C.which D.because2.英译汉:Positive/negative3.英译汉:Change one’s mind4.英译汉:According to the last paragraph......5.英译汉:The first paragraph tells us that......答案:1.B it is/was……that强调句2.积极地/消极的3.改变主意4.根据最后一段....5.第一段告诉我们……第五天1.英译汉:In the third paragraph,……2.The Customs officer didn't bother to___our luggage.A.controlB.checkC.askD.glance3.翻译:mean to do/mean doing4.翻译:It is+adj+for sb.+to do sth5.翻译:In private/be strict with sb.答案:1.在第三段中.....2.B check luggage检查行李3.打算干...../意味着.....4.对某人来说做....怎么样5.私下的/对某人很严格。
青岛版五年级数学下册周周清每日一练五年级下册每周一练每日一练周周清
五年级下册第二周周周清分数的意义和性质班级 姓名一、 基础部分: 课本原题:把30吨小麦分4次运完,平均每次运这些小麦的( ),每次运( )吨。
练习:1.把一根6米长的铁丝平均截成7段,每段长( )米,每段长是这根铁丝的( )。
2.把一根5米长的铁丝平均截成7段,每段长( )米,每段长是这根铁丝的( )。
3.把一根10米长的铁丝平均截成6段,每段长是这根铁丝的( ),每段长( )米。
2. 把10块糖平均分成5个小朋友,每人分得这些糖的( )( ),3人分得这些糖的( )( ) ,这个分数的分数单位是( ),单位“1”是( )。
3.学校新购进7个篮球,10个排球。
篮球的个数是排球的( )( ),这是把( )看作单位“1”;排球的个数是篮球个数的( )( ),这是把( )看作单位“1”。
4.把一根3米长的彩带平均分成5段,每段是全长的( )( ) ,每段长( )( )米。
二、拓展应用。
1. 买来5箱打印纸,共35包,平均分给8个部门。
(1)每个部门分得多少包?(2)每个部门分得多少箱?(3)每个部门分得这些打印纸的几分之几?五下2.小红家住5楼,她每次从一楼走到家中大概要2分钟。
(1)小红平均走一楼用的时间是她从一楼到家中时间的几分之几?(2)小红平均走一层楼用多少分钟?3. 把3块同样的饼干平均分给4个小朋友,每人分得( )( )块。
它是1块饼干的( )( ) ,是3块饼干的( )( )。
53块是1块的( )( ) ,是3块的( )( ) 。
65块是1块的( )( ) ,是( )块的61。
三、相信你最棒。
1.将一根8米长的圆木锯了4次,得到同样长的每小段,每段是全长的( ),每段长( )米。
2.三个笔筒,第一个露出1枝铅笔,占筒内铅笔数的51;第二个露出2枝铅笔,也占筒内铅笔数的51,第三个露出3枝铅笔,也占筒内铅笔数的51。
三个笔筒内各有多少枝铅笔?3.把一根2米长的绳子对折两次,这时每段绳子占全长的几分之几,每段绳子长多少米?第三周周周清分数的意义和在数轴上表示数 班级 姓名一、基础部分。
小学四年级数学暑假每日一练(第四周)
第1题一个物体从高空落下;已知第一秒下落的距离是5米;以后每秒落下的距离都比前一秒多10米;10秒末物体离地。
则物体最初距离地面的高度为多少米?【答案】500米【解析】5+15+25+……+95=(5+95)*10÷2=500米第2题甲乙两人从相距2400米的AB两地同时出发;相向而行;甲每分钟走30米;乙每分钟走50米;那么相遇时;乙比甲多走多少米?答案:600米解析:相遇的时间:2400÷(30+50)=30分钟乙比甲多走:50*30-30*30=600米第3题四年级三个班的同学们参加植树活动;共植树220棵;一班植的是二班的2倍;二班比三班多植20棵。
三个班各值多少棵树?解答:二班:(220+20)÷(2+1+1)=60(棵)一班:60×2=120(棵)三班:60-20=40(棵)答:一班植树120棵;二班植树60棵;三班植树40棵。
第4题小米做一道整数减法题时;把减数个位上的1看成7;把减数十位上的7看成1;结果得出差是111.问正确答案应是几?【答案解析】分析:小米错把减数个位上1看成7;使差减少7-1=6;而把十位上的7看成1;使差增加70-10=60.因此这道题归结为某数减6;加60得111;求某数是几的问题.解:111-(70-10)+(7-1)=57答:正确的答案是57.第5题有四个数;其中每三个数的和分别是45;46;49;52;那么这四个数中最小的一个数是多少?解析:把4个数全加起来就是每个数都加了3遍;所以;这四个数的和等于(45+46+49+52)÷3=64。
用总数减去最大的三数之和;就是这四个数中的最小数;即64-52=12。
第6题静水中;甲船速度是每小时22千米;乙船速度是每小时18千米;乙船先从某港开出顺水航行;2小时后甲船同方向开出;若水流速度为每小时4千米;求甲船几小时可以追上乙船?答案与解析:甲船顺水速度:22+4=26(千米/小时);乙船顺水速度:18+4=22(千米/小时);乙船先行路程:22×2=44(千米);甲船追上乙船时间:44÷(26-22)=11(小时)。
【强烈推荐】小学四年级数学暑假每日一练(第四周)
第1题一个物体从高空落下,已知第一秒下落的距离是5米,以后每秒落下的距离都比前一秒多10米,10秒末物体离地。
则物体最初距离地面的高度为多少米?【答案】500米【解析】5+15+25+……+95=(5+95)*10÷2=500米第2题甲乙两人从相距2400米的AB两地同时出发,相向而行,甲每分钟走30米,乙每分钟走50米,那么相遇时,乙比甲多走多少米?答案:600米解析:相遇的时间:2400÷(30+50)=30分钟乙比甲多走:50*30-30*30=600米第3题四年级三个班的同学们参加植树活动,共植树220棵,一班植的是二班的2倍,二班比三班多植20棵。
三个班各值多少棵树?解答:二班:(220+20)÷(2+1+1)=60(棵)一班:60×2=120(棵)三班:60-20=40(棵)答:一班植树120棵,二班植树60棵,三班植树40棵。
第4题小米做一道整数减法题时,把减数个位上的1看成7,把减数十位上的7看成1,结果得出差是111.问正确答案应是几?【答案解析】分析:小米错把减数个位上1看成7,使差减少7-1=6,而把十位上的7看成1,使差增加70-10=60.因此这道题归结为某数减6,加60得111,求某数是几的问题.解:111-(70-10)+(7-1)=57答:正确的答案是57.第5题有四个数,其中每三个数的和分别是45,46,49,52,那么这四个数中最小的一个数是多少?解析:把4个数全加起来就是每个数都加了3遍,所以,这四个数的和等于(45+46+49+52)÷3=64。
用总数减去最大的三数之和,就是这四个数中的最小数,即64-52=12。
第6题静水中,甲船速度是每小时22千米,乙船速度是每小时18千米,乙船先从某港开出顺水航行,2小时后甲船同方向开出,若水流速度为每小时4千米,求甲船几小时可以追上乙船?答案与解析:甲船顺水速度:22+4=26(千米/小时),乙船顺水速度:18+4=22(千米/小时),乙船先行路程:22×2=44(千米),甲船追上乙船时间:44÷(26-22)=11(小时)。
高中数学每日一练 第四周
第四周[周一]1.(2022·菏泽模拟)在①3a cos A +B 2=c sin A ;②3a =3c cos B +b sin C ;③cos 2A -cos 2C =sin 2B -sin A sin B ,这三个条件中任选一个,补充在下面问题中,并给出解答.问题:已知△ABC 的内角A ,B ,C 的对边分别是a ,b ,c ,c =3,________,求a +2b 的最大值.注:如果选择多个条件分别解答,按第一个解答计分.解 若选①:3a cos A +B 2=c sin A , ∵A +B +C =π,∴由已知条件得3sin A sin C 2=sin C sin A , 由sin A ≠0, 得3sin C 2=2sin C 2cos C 2, 由sin C 2≠0,得cos C 2=32, ∵C ∈(0,π), ∴C 2=π6,即C =π3, 在△ABC 中,由正弦定理得a sin A =b sin B =c sin C=2, ∴a =2sin A ,b =2sin B ,∴a +2b =2sin A +4sin B=2sin A +4sin ⎝⎛⎭⎫A +π3 =2sin A +4⎝⎛⎭⎫12sin A +32cos A =4sin A +23cos A=27sin(A +φ)⎝ ⎛⎭⎪⎫其中sin φ=37,cos φ=27, ∵A ∈⎝⎛⎭⎫0,2π3, ∴存在A ,使得A +φ=π2, 此时a +2b 取得最大值为27.若选②:3sin A =3sin C cos B +sin B sin C ,∵A +B +C =π, ∴3sin(B +C )=3sin C cos B +sin B sin C ,即3(sin B cos C +cos B sin C )=3sin C cos B +sin B sin C , 化简得3sin B cos C =sin B sin C ,由sin B ≠0,得tan C =3,∵C ∈(0,π),∴C =π3. 下同①.若选③:cos 2A -cos 2C =sin 2B -sin A sin B ,即1-sin 2A -(1-sin 2C )=sin 2B -sin A sin B ,即sin 2C -sin 2A =sin 2B -sin A sin B ,由正弦定理得c 2-a 2=b 2-ab ,∴由余弦定理得cos C =a 2+b 2-c 22ab =12, ∵C ∈(0,π),∴C =π3. 下同①.[周二]2.已知数列{a n }满足a n +a n +2=2a n +1,n ∈N *,且a 1=1,a 5+a 7=22.(1)求数列{a n }的通项公式;(2)记在区间(3m ,3m +1)(m ∈N *)上,{a n }的项数为b m ,求数列{b m }的前m 项和.解 (1)由题意知a n +2-a n +1=a n +1-a n ,则{a n }为等差数列,设其公差为d ,由a 5+a 7=22,得a 1+4d +a 1+6d =22,又a 1=1,∴d =2,则a n =2n -1.(2)由题意得,b m =3m +1-3m2-1=3m -1, ∴b 1+b 2+…+b m=(31-1)+(32-1)+…+(3m -1)=31+32+…+3m -m=3×1-3m1-3-m =3m +12-m -32. [周三]3.(2022·临沂模拟)在正方体ABCD -A 1B 1C 1D 1中,E 为A 1D 1的中点,过AB 1E 的平面截此正方体,得到如图所示的多面体,F 为棱CC 1上的动点.(1)点H 在棱BC 上,当CH =14CB 时,FH ∥平面AEB 1,试确定动点F 在棱CC 1上的位置,并说明理由;(2)若AB =2,求点D 到平面AEF 的最大距离.解 (1)设平面BCC 1B 1与平面AEB 1的交线为l ,因为FH ∥平面AEB 1,平面BCC 1B 1∩平面AEB 1=l ,FH ⊂平面BCC 1B 1,所以FH ∥l .由正方体ABCD -A 1B 1C 1D 1知,平面ADD 1E ∥平面BCC 1B 1,又因为平面ADD 1E ∩平面AEB 1=AE ,所以AE ∥l ,所以AE ∥FH ,如图,取BC 的中点G ,连接C 1G ,易知AE ∥GC 1,所以GC 1∥FH ,又因为H 为CG 的中点,所以F 为CC 1的中点.(2)如图,以点D 为原点,DA →,DC →,DD 1——→分别为x 轴、y 轴、z 轴的正方向,建立空间直角坐标系,则有D (0,0,0),A (2,0,0),E (1,0,2),设F (0,2,t ),t ∈[0,2],AE →=(-1,0,2),AF →=(-2,2,t ),DA →=(2,0,0),设平面AEF 的法向量为n =(x ,y ,z ),则有⎩⎪⎨⎪⎧ n ·AE →=0,n ·AF →=0,即⎩⎪⎨⎪⎧-x +2z =0,-2x +2y +tz =0, 不妨取x =2,则n =⎝⎛⎭⎫2,2-t 2,1, 所以点D 到平面AEF 的距离d =|DA →·n ||n |=45+⎝⎛⎭⎫2-t 22=414(t -4)2+5≤263, 当t =2,即点F 与点C 1重合时,取等号.所以点D 到平面AEF 的最大距离为263.[周四]4.已知抛物线C :x 2=2py (p >0)与圆O :x 2+y 2=12相交于A ,B 两点,且点A 的横坐标为2 2.F 是抛物线C 的焦点,过焦点的直线l 与抛物线C 相交于不同的两点M ,N .(1)求抛物线C 的方程; (2)过点M ,N 作抛物线C 的切线l 1,l 2,P (x 0,y 0)是l 1,l 2的交点,求证:点P 在定直线上.(1)解 因为点A 的横坐标为22,且点A 在圆O 上,所以点A 的坐标为A (22,2),代入抛物线方程得p =2,所以抛物线的方程为x 2=4y .(2)证明 抛物线C :y =x 24,则y ′=x 2, 设M (x 1,y 1),N (x 2,y 2),所以切线PM 的方程为y -y 1=x 12(x -x 1), 即y =x 12·x -x 214, 同理切线PN 的方程为y =x 22·x -x 224, 联立解得点P ⎝ ⎛⎭⎪⎫x 1+x 22,x 1x 24, 设直线MN 的方程为y =kx +1,代入x 2=4y ,得x 2-4kx -4=0,所以x 1x 2=-4,所以点P 在定直线y =-1上,结论得证.[周五]5.(2022·福州模拟)某超市开展购物抽奖送积分活动,每位顾客可以参加n (n ∈N *,且n ≥2)次抽奖,每次中奖的概率为13,不中奖的概率为23,且各次抽奖相互独立.规定第1次抽奖时,若中奖则得10分,否则得5分.第2次抽奖,从以下两个方案中任选一个:方案①:若中奖则得30分,否则得0分;方案②:若中奖则获得上一次抽奖得分的两倍,否则得5分.第3次开始执行第2次抽奖所选方案,直到抽奖结束.(1)如果n =2,以抽奖的累计积分的期望值为决策依据,顾客甲应该选择哪一个方案?并说明理由;(2)记顾客甲第i 次获得的分数为X i (i =1,2,…,n ),并且选择方案②.请直接写出E (X i +1)与E (X i )的递推关系式,并求E (X 8)的值.(精确到0.1,参考数据:⎝⎛⎭⎫237≈0.059.)解 (1)若甲第2次抽奖选方案①,两次抽奖累计积分为ξ,则ξ的可能取值为40,35,10,5.P (ξ=40)=13×13=19, P (ξ=35)=23×13=29, P (ξ=10)=13×23=29,P (ξ=5)=23×23=49, 所以E (ξ)=40×19+35×29+10×29+5×49=1509=503. 若甲第2次抽奖选方案②,两次抽奖累计积分为η,则η的可能取值为30,15,10,则P (η=30)=13×13=19, P (η=15)=23×13+13×23=49, P (η=10)=23×23=49, E (η)=30×19+15×49+10×49=1309, 因为E (ξ)>E (η),所以应选择方案①.(2)依题意得E (X i +1)=5×23+2E (X i )·13=23E (X i )+103, X 1的可能取值为10,5,其分布列为所以E (X 1)=203, 则E (X 1)-10=-103, 由E (X i +1)=23E (X i )+103得 E (X i +1)-10=23[E (X i )-10], 所以{E (X i )-10}为等比数列.其中首项为-103,公比为23. 则E (X i )-10=-103×⎝⎛⎭⎫23i -1, 所以E (X 8)-10=-103×⎝⎛⎭⎫237,故E (X 8)=-103×⎝⎛⎭⎫237+10≈9.8. [周六]6.(2022·江门模拟)已知函数f (x )=ln x ,g (x )=ax +2x-5. (1)证明:f (x )<x ;(2)若函数f (x )的图象与g (x )的图象有两个不同的公共点,求实数a 的取值范围.(1)证明 要证f (x )<x ,即证当x ∈(0,+∞)时,不等式ln x -x <0恒成立.令F (x )=ln x -x ,则F ′(x )=1x -12x =2-x 2x, 故当0<x <4时,F ′(x )>0,F (x )单调递增;当x >4时,F ′(x )<0,F (x )单调递减.则F (x )max =F (4)=ln 4-2<0,故f (x )<x .(2)解 由f (x )=g (x )可得a =ln x x +5x -2x2 =x ln x +5x -2x 2, 构造函数h (x )=5+ln x x -2x2,其中x >0, 则h ′(x )=1x ·x -(5+ln x )x 2+4x3 =4-4x -x ln x x 3, 当0<x <1时,4-4x >0,ln x <0,则h ′(x )>0,此时函数h (x )单调递增,当x >1时,4-4x <0,ln x >0,则h ′(x )<0,此时函数h (x )单调递减,所以h (x )max =h (1)=3,令φ(x )=x ln x +5x -2,则当x >1时,φ(x )>5x -2>0,当0<x <25时,φ(x )<5x -2<0,故存在x 0∈⎝⎛⎭⎫25,1,使得φ(x 0)=0,即h (x 0)=0,作出函数h (x )与y =a 的图象如图所示,由图可知,当0<a <3时,函数h (x )与y =a 的图象有2个交点, 因此,实数a 的取值范围是(0,3).。
最新完整版:七年级数学思维训练题
初一数学思维训练题(第一周)班级______________ 姓名_____________ 一、选择题:1.a 为任意自然数,包括a 在内的三个连续的自然数,可以表示为 ( )A .a -2,a -1,aB .a -3,a -2,a -1C .a ,a +1,a +2D .不同于A 、B 、C 的形式二、计算题:(动动脑筋,可能会有简便的解题方法!)1.____________________56875=⨯2.____________2006200420022000...12108642=+-+-+-+-+- 3.__________________8567785667855678=+++4.()()__________888...6428002...888488868888=++++-++++ 5.______________125.01712517125625.05.0171251753=⨯-⨯+⨯+ 6.______________12346123451234512345=÷7._________________31313131=-+-8._______________99163135115131=++++ 9._____________20042004...200432004220041=++++10._____________90197218561742163015201412136121=++++++++三、应用与创新:1.有一高楼,每上一层需要3分钟,每下一层需要1分30秒。
小贤于下午6时15分开始从最底层不断地向上走,到了最顶层后便立即往下走,中途没有停留,他在7时36分返回最底层。
这座高楼共有多少层?2.回答下列各题:(1)用1、2、3、4、5、6、7、8可组成多少个没有重复数字的五位数?(2)在15个连续自然数中最多有多少个质数?最少有多少个质数?(3)以下是一个数列,第一项是1,第二项是4,以后每一项是前两项相乘的积。
2022年北师大版五年级数学下册--每日一练第4周
一、选择题1.正方体的棱长扩大到原来的2倍,它的表面积扩大到原来的()倍。
A.2B.4C.8D.122.把一个边长是8dm的正方体切成两个完全一样的长方体,表面积增加了()。
A.64dm²B.128dm²C.32dm²3.一张长方形纸板长80厘米,宽10厘米,把它对折、再对折。
打开后,围成一个高10厘米的长方体纸箱的侧面。
如果要为这个长方体纸箱配一个底面,这个底面的面积是()。
A.200平方厘米B.400平方厘米C.800平方厘米二、填空题4.至少需要(___________)个相同的小正方形可以拼成一个较大的正方形。
5.一个正方形的棱长之和是24厘米,它的表面积是(_______)平方厘米,体积是(_______)立方厘米。
6.一个长方体木块,从上部、下部分别截去高为3厘米、2厘米的长方体后,便成为一个正方体,表面积减少了120平方厘米。
正方形棱长是________厘米。
三、解答题7.学校要粉刷新教室。
已知教室的长是8m,宽是6m,高是3m,扣除门窗的面积是11.4m2。
如果每平方米要花4元涂料费,粉刷这个教室需要花多少元?8.健身中心新建一个游泳池,该游泳池的长是50m,是宽的2倍,深2.5m.现要在池的四周和底面都帖上瓷砖,共需要帖多少平方米的瓷砖?一、选择题1.把三个棱长1厘米的正方体拼成一个长方体,这个长方体的表面积比原来三个正方体的表面积的和减少()。
A.2平方厘米B.3平方厘米C.4平方厘米2.下面图形()不能折成正方体.A.B.C.D.3.正方体的棱长扩大到原数的3倍,表面积扩大到原数的()倍。
A.3B.9C.6二、填空题4.下图是由同样大小的小方块堆积起来的,每个小方块的棱长是1分米,这堆小方块露在外面的面积是(_________)。
5.一根长方形木料(如图),它的表面积是________cm2。
沿着它的横截面把它锯成两段后,表面积增加了________cm2。
一年级语文暑假作业设计方案
一年级语文暑假作业设计方案一、作业目标1. 巩固一年级语文基础知识,提高学生汉字书写能力。
2. 培养学生阅读兴趣,拓展课外阅读量。
3. 提升学生口头表达和写作能力,激发创意思维。
二、作业内容1. 每日一练:汉字书写练习,包括生字、词语、句子等。
要求:书写规范、工整、美观,注重笔画顺序和结构。
2. 阅读理解:每周一篇寓言故事或成语故事,提高阅读理解能力。
要求:阅读后能用自己的话复述故事内容,并总结故事寓意。
3. 诗歌背诵:每周一首古诗,培养学生对古典文化的热爱。
要求:熟练背诵,理解诗意,能简单分析诗歌的修辞手法。
4. 写作训练:每周一篇看图写话或命题作文,锻炼写作能力。
要求:语句通顺,表达清晰,注意运用学过的词语和句式。
5. 口语表达:每周一次家庭分享会,鼓励学生表达自己的观点。
要求:能自信地表达自己的想法,注意语言组织和逻辑性。
三、作业安排1. 作业时间:共计8周,每周一至周五进行作业练习,周六、日休息。
2. 作业量:每日作业量控制在30分钟以内,确保学生轻松完成。
3. 作业提交:每周五将本周作业统一提交给老师,以便及时反馈和指导。
四、作业评价1. 评价方式:采用教师评价、家长评价和学生自评相结合的方式。
2. 评价标准:作业完成情况、书写质量、阅读理解能力、写作水平、口语表达能力等。
3. 奖励措施:对作业完成优秀的学生给予表扬和奖励,提高学生学习积极性。
五、家长配合事项1. 家长督促学生按时完成作业,确保作业质量。
2. 家长鼓励学生阅读课外书籍,共同参与家庭分享会。
3. 家长关注学生的学习进度,与老师保持沟通,共同促进孩子成长。
六、作业辅导1. 老师每周对作业进行一次集中辅导,解答学生疑问。
2. 针对学生个体差异,老师给予个性化指导,提高作业效果。
3. 家长可随时与老师沟通,共同解决孩子在作业过程中遇到的问题。
四、作业具体内容详述1. 每日一练- 生字练习:每天选取10个生字,要求学生按照正确的笔画顺序书写,注意字形的规范和美观。
高考数学大题每日一题规范练(第四周)
高考数学大题每日一题规范练【题目1】 (本小题满分12分)已知向量a =(sin x ,m cos x ),b =(3,-1). (1)若a ∥b ,且m =1,求2sin 2x -3cos 2x 的值;(2)若函数f (x )=a ·b 的图象关于直线x =2π3对称,求函数f (2x )在⎣⎢⎡⎦⎥⎤π8,2π3上的值域.解 (1)当m =1时,a =(sin x ,cos x ),又b =(3,-1), 且a ∥b .∴-sin x -3cos x =0,即tan x =-3,∵2sin 2x -3cos 2x =2sin 2x -3cos 2x sin 2x +cos 2x =2tan 2x -3tan 2x +1=2×(-3)2-3(-3)2+1=32,∴2sin 2x -3cos 2x =32.(2)∵f (x )=a ·b =3sin x -m cos x 的图象关于直线x =2π3对称, ∴f ⎝ ⎛⎭⎪⎫2π3-x =f ⎝ ⎛⎭⎪⎫2π3+x,即f ⎝ ⎛⎭⎪⎫π2=f ⎝ ⎛⎭⎪⎫5π6, 即3=32+32m ,得m =3,则f (x )=23⎝ ⎛⎭⎪⎫32sin x -12cos x =23sin ⎝ ⎛⎭⎪⎫x -π6,∴f (2x )=23sin ⎝⎛⎭⎪⎫2x -π6,∵x ∈⎣⎢⎡⎦⎥⎤π8,2π3,∴2x -π6∈⎣⎢⎡⎦⎥⎤π12,7π6,∴当x =π3时,f (2x )取最大值为23;当x =2π3时,f (2x )取最小值为- 3. 即函数f (2x )在⎣⎢⎡⎦⎥⎤π8,2π3上的值域为[-3,23].星期二 (概率统计) 2018年____月____日【题目2】 (本小题满分12分)某项科研活动共进行了5次试验,其数据如下表所示:(1)从5600的概率;(2)求特征量y 关于x 的线性回归方程y ^=b ^x +a ^:并预测当特征量x 为570时特征量y 的值.(附:回归直线的斜率和截距的最小二乘法估计公式分别为解 (1)从5次特征量y 的试验数据中随机地抽取两个数据,共有C 25=10种方法,都小于600,有C 23=3种方法,∴至少有一个大于600的概率P =1-C 23C 25=1-310=710.-1×1+3×5+(-5)×(-3)+7×(-1)+(-4)×(-2)(-1)2+32+(-5)2+72+(-4)2=0.3,a ^=y-b ^x =600-0.3×556=433.2, 线性回归方程为y ^=0.3x +433.2,当x =570时,y ^=0.3×570+433.2=604.2. 即当特征量x 为570时特征量y 的估计值为604.2.星期三 (数列) 2018年____月____日【题目3】 (本小题满分12分)在数列{a n }中,a 1=1,2+a n +11+a n +1=11+a n +32(n ∈N *).(1)求数列{a n }的通项公式;(2)设b n =1+a 2n (n ∈N *),求数列{2nb n }的前n 项和S n .解 (1)∵2+a n +11+a n +1=11+a n +32,∴11+a n +1=11+a n+12,即11+a n +1-11+a n =12,设c n =1a n +1,由a 1=1得c 1=12,则数列{c n }是一个首项和公差均为12的等差数列, ∴c n =12+12(n -1)=n 2,则a n =2n -1.(2)由(1)得b n =1+a 2n =22n =12n -1,所以2nb n =2n2n -1,则S n =2×1+4×12+6×122+…+2n ×12n -1①,∴12S n =2×12+4×122+6×123+…+2n ×12n ②, ①-②得12S n =2⎝ ⎛⎭⎪⎫1+12+122+123+…+12n -1-2n ×12n ,即12S n =4-2n +42n .得S n =8-n +22n -2⎝⎛⎭⎪⎫或8-4n +82n .星期四 (立体几何) 2018年____月____日【题目4】 (本小题满分12分)如图,三棱柱ABC -A 1B 1C 1中,A 1A ⊥平面ABC ,∠ACB =90°,AC =CB =2,M ,N 分别是AB ,A 1C 的中点.(1)求证:MN ∥平面BB 1C 1C ;(2)若平面CMN ⊥平面B 1MN ,求直线AB 与平面B 1MN 所成角的正弦值. (1)证明 连接AC 1,BC 1,则N ∈AC 1且N 为AC 1的中点,又∵M 为AB 的中点,∴MN ∥BC 1,又BC 1⊂平面BB 1C 1C ,MN ⊄平面BB 1C 1C , 故MN ∥平面BB 1C 1C .(2)解 由A 1A ⊥平面ABC 且CC 1∥A 1A ,得AC ⊥CC 1,BC ⊥CC 1.又∠ACB =90°,则AC ⊥BC ,以C 为原点,分别以CB ,CC 1,CA 所在直线为x 轴、y 轴、z 轴建立如图所示的空间直角坐标系,设CC 1=2λ(λ>0).则M (1,0,1),N (0,λ,1),B 1(2,2λ,0),∴CM →=(1,0,1),MN →=(-1,λ,0),NB 1→=(2,λ,-1). 取平面CMN 的一个法向量为m =(x ,y ,z ), 由CM→·m =0,MN →·m =0. 得⎩⎨⎧x +z =0,-x +λy =0,令y =1,得m =(λ,1,-λ).同理可得平面B 1MN 的一个法向量为n =(λ,1,3λ), ∵平面CMN ⊥平面B 1MN ,∴m ·n =λ2+1-3λ2=0,解得λ=22,得n =⎝ ⎛⎭⎪⎫22,1,322,又AB →=(2,0,-2),设直线AB 与平面B 1MN所成角为θ,则sin θ=|cos 〈n ,AB →〉|=|n ·AB →||n ||AB →|=66.所以,直线AB 与平面B 1MN 所成角的正弦值是66.星期五 (解析几何) 2018年____月____日【题目5】 (本小题满分12分)在平面直角坐标系xOy 中,已知椭圆E :x 2a 2+y 2b 2=1(a >b >0),圆O :x 2+y 2=r 2(0<r <b ),若圆O 的一条切线l :y =kx +m 与椭圆E 相交于A ,B 两点.(1)当k =-12,r =1时,若点A ,B 都在坐标轴的正半轴上,求椭圆E 的方程; (2)若以AB 为直径的圆经过坐标原点O ,探究a ,b ,r 是否满足1a 2+1b 2=1r 2,并说明理由.解 (1)依题意原点O 到切线l :y =-12x +m 的距离为半径1,∴|m |1+14=1,解之得m =±52,又点A ,B 都在坐标轴的正半轴上,则m >0, ∴切线l :y =-12x +52,∴A ⎝⎛⎭⎪⎫0,52,B (5,0),∴B 为椭圆的右顶点,A 为椭圆的上顶点,则a =5,b =52, ∴椭圆E 的方程为:x 25+y 254=1.(2)a ,b ,r 满足1a 2+1b 2=1r 2成立,理由如下:设A (x 1,y 1),B (x 2,y 2),直线l 与圆x 2+y 2=r 2相切,则|m |1+k 2=r ,即m 2=r 2(1+k 2),① 联立⎩⎪⎨⎪⎧y =kx +m ,x 2a 2+y 2b2=1,得(b 2+a 2k 2)x 2+2a 2kmx +a 2m 2-a 2b 2=0. 则x 1+x 2=-2a 2km b 2+a 2k 2,x 1x 2=a 2m 2-a 2b 2b 2+a 2k 2,所以y 1y 2=(kx 1+m )(kx 2+m )=k 2x 1x 2+km (x 1+x 2)+m 2=b 2m 2-a 2b 2k 2b 2+a 2k 2,AB 为直径的圆经过坐标原点O ,则∠AOB =90°, 则OA→·OB →=0, ∴x 1x 2+y 1y 2=a 2m 2-a 2b 2b 2+a 2k 2+b 2m 2-a 2b 2k 2b 2+a 2k 2=(a 2+b 2)m 2-a 2b 2(1+k 2)b 2+a 2k 2=0.则(a 2+b 2)m 2=a 2b 2(1+k 2),②将①代入②,得a 2+b 2a 2b 2=1r 2, ∴1a 2+1b 2=1r 2.星期六 (函数与导数) 2018年____月____日【题目6】 (本小题满分12分)已知函数f (x )=x 2-a ln x (a >0)的最小值是1. (1)求a ;(2)若关于x 的方程f 2(x )e x -6mf (x )+9m e -x =0在区间[1,+∞)有唯一的实根,求m 的取值范围. 解 (1)f ′(x )=2x -ax =2⎝⎛⎭⎪⎫x +a 2⎝ ⎛⎭⎪⎫x -a 2x(x >0).所以,当0<x <a2时,f ′(x )<0,函数f (x )单调递减;当x >a2时,f ′(x )>0,函数f (x )单调递增. 故f (x )min =f ⎝⎛⎭⎪⎫a 2=a 2-a 2ln a 2, 由题意可得:a 2-a 2ln a 2=1,即a 2-a 2ln a2-1=0, 记g (a )=a 2-a 2ln a2-1(a >0),则函数g (a )的零点即为方程a 2-a 2ln a2=1的根; 由于g ′(a )=-12ln a2,故a =2时,g ′(2)=0, 且0<a <2时,g ′(a )>0;a >2时,g ′(a )<0, 所以a =2是函数g (a )的唯一极大值点, 所以g (a )≤g (2),又g (2)=0, 所以a =2.(2)由条件可得f 2(x )e 2x -6mf (x )e x +9m =0, 令g (x )=f (x )e x =(x 2-2ln x )e x , 则g ′(x )=⎝ ⎛⎭⎪⎫x 2+2x -2x -2ln x e x ,令r (x )=x 2+2x -2x -2ln x (x ≥1),则r ′(x )=2x +2+2x 2-2x >2x -2x =2(x 2-1)x≥0,r (x )在区间[1,+∞)内单调递增, ∴g (x )≥g (1)=e ;所以原问题等价于方程t 2-6mt +9m =0在区间[e ,+∞)内有唯一解, 当Δ=0时可得m =0或m =1,经检验m =1满足条件. 当Δ>0时可得m <0或m >1, 所以e 2-6m e +9m ≤0, 解之得m ≥e 26e -9,综上,m的取值范围是⎩⎪⎨⎪⎧⎭⎪⎬⎪⎫m ⎪⎪⎪m =1或m ≥e 26e -9.星期日 (选考内容) 2018年____月____日【题目7】 在下面两题中任选一题作答.注意:只能做所选定的题目.如果多做,则按所做第一个题目计分.1.(本小题满分10分)选修4-4:坐标系与参数方程.在直角坐标系xOy 中,曲线C 的参数方程为⎩⎨⎧x =4t 2,y =4t(t 为参数),以O 为极点,x 轴的正半轴为极轴建立极坐标系,直线l 的极坐标方程为ρ(4cos θ+3sin θ)-m =0(其中m 为常数).(1)若直线l 与曲线C 恰好有一个公共点,求实数m 的值; (2)若m =4,求直线l 被曲线C 截得的弦长.解 (1)直线l 的极坐标方程可化为直角坐标方程:4x +3y -m =0,曲线C 的参数方程可化为普通方程:y 2=4x , 由⎩⎨⎧4x +3y -m =0,y 2=4x可得y 2+3y -m =0, ∵直线l 和曲线C 恰好有一个公共点, ∴Δ=9+4m =0,∴m =-94.(2)当m =4时,直线l :4x +3y -4=0恰好过抛物线的焦点F (1,0),由⎩⎨⎧4x +3y -4=0,y 2=4x可得4x 2-17x +4=0,设直线l 与抛物线C 的两个交点分别为A (x 1,y 1),B (x 2,y 2),则x 1+x 2=174, 故直线l 被抛物线C 所截得的弦长为|AB |=x 1+x 2+2=174+2=254. 2.(本小题满分10分)选修4-5:不等式选讲. 设函数f (x )=⎪⎪⎪⎪⎪⎪12x +1+|x |(x ∈R )的最小值为a .(1)求a ;(2)已知两个正数m ,n 满足m 2+n 2=a ,求1m +1n 的最小值.解 (1)f (x )=⎩⎪⎨⎪⎧-32x -1,x <-2,-12x +1,-2≤x ≤0,32x +1,x >0.当x ∈(-∞,0)时,f (x )单调递减; 当x ∈[0,+∞)时,f (x )单调递增; ∴当x =0时,f (x )的最小值a =1.(2)由(1)知m 2+n 2=1,则m 2+n 2≥2mn ,得1mn ≥2, 由于m >0,n >0, 则1m +1n ≥21mn ≥22,当且仅当m =n =22时取等号.∴1m +1n 的最小值为2 2.。
一年级上册每日一题
一年级上册每日一题第一周星期一数一数,并圈出正确的数。
(2 5 10)只手(2 5 10)双鞋第一周星期二( )比( )多 ( )比( )多( )比( )少 ( )比( )少( ) >( ) ( )<( )第一周星期三读一读,想一想,再在()里填出她们的名字。
小敏住在小英楼下,小英住在小兰楼下,()住在一楼()在最下面,()住在二楼()在最上面。
()住在三楼(1)下楼的小朋友是靠()边走,上楼的小朋友是靠()边走.(2)上楼、下楼和在路上行走我们都应靠()边走.第一周星期五有两种走法:(1)可以先往()走,再往()走,就到了火车站。
(2)还可以先往()走,再往()走,再往()走,就到了火车站。
第二周星期二(1)跑在最前面的是(),最后面的是()。
(2)丽丽的前面有()个小朋友,她的后面有()个小朋友。
第二周星期三上面是一群小动物在一起休息。
从左数起小马是第()位,从右数起小象是第()位。
小鹿的右边有()个,左边有()个,一共有()个小动物。
1. 在的上面画上一个。
在的左面画上一个。
2. 在的右面画上一个。
在的下面画上一个。
3. 在的左边写上5。
在的上面写上8。
4. 在的下面写上6。
在的下面写上9。
用“上”“下”“前”“后”这四个方位词说一说家中或者教室里物品的位置。
第二周星期五哪一块地的面积大?在里画。
第三周星期一括号里能填几?(1)5>()(2)()<3第三周星期二找一找家中或身体上数量是1~5的物品,并和爸爸妈妈说一说。
5名消防员叔叔练习正步走,王刚叔叔排第2.教练发令:“向后转。
”这时王刚叔叔排第()。
第三周星期四同学们报数,从左数,小明排第3,从右数,小明排第2,这一队一共有多少个同学?第三周星期五2 3 42 33第四周星期一想一想,填一填5 4 3 31 2 4第一个鱼缸有4条鱼,第二个鱼缸有2条鱼。
能使两个鱼缸的鱼同样多的方法可以是:(1)从左边鱼缸里拿走()条鱼。
(2)往右边鱼缸里放入()条鱼。
[VIP专享]三年级数学每日一题
三年级数学每日一题第一周1、□□÷4=12……□□□÷4=12……□□□÷4=12……□2、□□÷□=15 (4)3、你能写几道?□□÷3=23……□4、你能写几道?□□÷□=21 (1)第二周1、小方买6枝钢笔,小华买3枝,小方比小华多付24元,每枝钢笔几元?2、明明买6本练习本,东东买4本,东东比明明少付2元。
每本练习本几元?第三周1、89÷4()76÷7()90÷2()55÷4()2、83÷4 二十多94÷472÷3 三十多78÷23、三(1)班64人,大船每条最多坐4人,小船每条最多坐3人。
(1)你想怎样租船?(2)大船每条6元,小船每条5元,你的方法要花多少元?4、有两位老师带同学去划船,男生33人,女生21人,每条船最多坐6人,至少要几条船?第四周1、3597,3598,3599,(),(),()2、3597,3596,(),3594,(),()3、3597,3697,3797,(),()4、3597,3497,3397,(),(),()第五周1、用8、9、7、5、0组成四位数:(1)最大的是()(2)最小的是()(3)最接近9000的是()(4)比7000大的是()2、算筹这样表示数字:这里的“ ”表示(),“ ”表示()。
用算筹表示73(),表示3608()3、40□6>4056,□里可以填()4、8□91<8991,□里可以填()第七周你最多能写几道?1、42+3□=7□2、42+3□=8□3、一桶油连桶重12千克,倒掉一半油后连桶重7千克。
原来油重多少千克?桶重多少千克?4、一桶油连油带桶重200千克,倒掉一半油后连桶还重110千克。
原来油重多少千克?第八周画出线段图解决问题1、红花有36朵,黄花的朵数是红花的3倍,两种花一共有多少朵?2、合唱队有男生58人,男生人数比女生人数多46人,合唱队一共有多少人?3、两筐水果共重124千克,第一筐比第二筐多8千克,两筐水果各重多少千克?4、鸡和兔共有34只,鸡比兔的2倍多4只。
2021-2022年度部编版七年级上册语文教学工作计划及教学进度表(全国通用)
2021-2022年度部编版七年级上册语文教学工作计划及教学进度表(全国通用)七年级上册语文教学工作计划及教学进度表为了顺利完成本学期的语文教学任务,特结合新版部编教材制定本教学计划。
本教学工作以语文新课程标准为指导,以学校的工作计划为依据,旨在提高教师的业务知识水平和教育教学能力,落实常规工作,扎实基础。
同时,对于七年级学生,我们将坚持识字写字的教学,增加课外阅读量,有的放矢地进行写作训练,全面提高学生的语文素养,使他们的现代文阅读能力、写作能力和口语交际能力得到提高,具有初步的文学鉴赏能力和阅读课外文言文的能力。
我们还将教授语文研究的基本方法,培养学生自学语文的惯。
教材的编排意图更加注重学生的人文体验,特别是对于阅读的编排体现了“三位一体”的理念,也就是教读课文、自读课文和课外阅读三者既有区别,又有联系,互为补充,力求构建完整的阅读体系,同时培养的阅读能力,体现语文的“工具性”。
本册教材共分为六个单元,共计22课,各种文体混合编排,注重对学生研究惯的培养,而且体现了梯度。
比如,每个单元要求学生掌握的研究目标都有明确规定,既有练,呈螺旋式上升,又有侧重。
第一单元:本单元展示了大自然的美丽多彩,启发学生品味语言,欣赏修辞手法的表达效果,研究细致观察景物和抓住景物特点进行描写的方法。
同时,学生也可以从中感受到大自然的神奇和美好,培养对自然的热爱和保护意识。
第二单元:本单元以亲情为主题,选取了多样化的题材、体裁和风格的文章,让学生深刻体会亲情的真挚和美好。
通过阅读这些文章,学生可以感受到生命的力量和情感的共鸣,增强自己的情感认知和表达能力。
第三单元:本单元选取了反映青少年研究生活的文章,让学生了解不同时代、不同国度的孩子们的研究生活,引领学生树立理想,实现理想,为漫长的人生打下精神的底色。
同时,学生也可以从中了解到自己的研究生活和成长,提高自我认知和人生规划能力。
第四单元:本单元的课文主要以作者对于人生的憧憬、体验和思考为主题,让学生深入思考生命的意义和价值。
小学四年级语文暑假一天一练(第四周)
第1题第2题选词填空。
A.严格B.严密C.严肃D.严峻1、我们要经得起____的考验。
2、这篇文章的结构很____。
3、老师一向对我们的要求非常____。
4、父亲的表情是那么的____。
答案:DBAC【严格】严肃而认真;用于执行制度或掌握标准时:严格要求|严格执行各项规定。
【严密】周到;没有疏漏。
“严密”“严密”指不疏漏;如严密地封锁消息;严密注视形势的发展;也指事物结合紧密没有空隙等;如文章结构很严密;罐头盖得很严密等。
【严肃】①(神情、气氛等)使人感到敬畏。
②(作风、态度等)认真。
“严肃”可形容神情或气氛等;如会场上气氛很严肃;表情过于严肃;也可指认真;如处理问题很严肃。
【严峻】严肃;严厉。
“严峻”;严肃;常形容神情等;如脸色严峻;又可指事物;如严峻的形势;严峻的考验等;还可形容山林的高大和森严;如严峻的山林。
第3题下列句子语言表达得体的一项是()A.会议开始前;主持人特别提醒:"为了保持会场安静;请各位关闭手机;否则后果自负!"B.有人从公交车上往外扔香蕉皮;一位乘客冲着他说:"老兄;你太过分了!积点德吧!"C.酒店经理对员工们说:"大家要用心做好服务工作;让客人有宾至如归的感觉。
" D.提到自己的父亲;老刘动情的说:"令尊经常告诫我们;做人要清清白白。
"答案:C第4题下列给广告词“消毒”;恢复原貌。
例:消炎药广告词:快治人口——(脍炙人口)A.热水器广告词:随心所浴——()B.止咳药广告词——咳不容缓()C.摩托车广告词:骑乐无穷——()D.营养液广告词——口蜜腹健()答案:A.欲B.刻C.其 D.剑。
【答案解析】1.随心所欲【解释】:随:任凭;欲:想要。
随着自己的意思;想要干什么就干什么。
【出自】:《论语·为政》:“七十而从心所欲;不逾矩。
”【示例】:我们二人并坐;~的漫谈。
◎臧克家《老舍永在》2.刻不容缓【解释】:刻:指短暂的时间;缓:延迟。
浙江省杭州市外国语学校2013年高考英语集训阅读理解每日一练31
杭州外国语学校2013年高考英语集训阅读理解每日一练31倒数第四周星期一AHave you ever gone to work to find that one of your coworkers is coughing and sneezing all day long? You do your best to keep a safe distance and wonder: Why did he or she come to work when they were ill? The reality for many Americans is that they do not have enough paid sick time each year to afford them the luxury of staying home because they don’t feel well.This problem doesn’t just affect the working employees who are sick,though. In an article by James Warren for Bloomberg Business Week, a second-grade school teacher, Stilli Klikizos shares about the sick children that must stay in school all day long because their parents can’t get off work to come and get them. In the past school year, she had several children who were unable to be picked up at school who were later diagnosed with H1N1.There is a movement called the Healthy Families Act in Congress that would change this situation for many Americans. The Healthy Family Act would require employers with 15 or more employees to provide 7 paid sick days a year for their workers. These days could be used not only for days when the worker is sick, but the time can also be used when caring for others, or going to routine doctor’s appointments.Those who are against the Act argue that many businesses are struggling to make ends meet owing to recession (经济衰退), and point out that this is the wrong time to force employers to add an additional expense.Those who support the Healthy Families Act say that our nation can’t afford to not take these measures. When an individual goes to work sick, they are possibly infecting their coworkers, clients and customers.According to a report by Katie Couric on the CBS evening news, three fourths of low wage earners get docked when they are sick. Those individuals include daycare workers and restaurant workers, whose health can affect the health of many.41. Why do many Americans still come to w ork when they are sick?A. They often ignore the illness if not serious.B. They work in high spirits.C. The cost of staying home is great.D. The cost of medical treatment is high.42. In the article mentioned in this passage, James Warren intends to say ______.A. children need more thoughtful and considerate careB. teachers are responsible for taking good care of children at schoolC. parents shouldn’t leave the sick children at schoolD. adults’ not having enough paid sick time may be bad for children43. According to the Healthy Families Act, ______.A. all the employers are required to provide 7 paid sick days a year for theirworkersB. the employees can use the paid sick days to take care of their sick childrenC. the employees could demand their companies pay for their medical billsD. the employees can use the paid sick days to take a trip so as to relax themselves.44. Why are some people against the Healthy Families Act?A. Many companies’ financial situations are not so good due to the recession.B. Companies have no such duty to provide paid sick time.C. The nation can’t afford to do as the Act requires.D. Usually one’s illness won’t infect his coworkers and customers.45. The term "get docked" (Para 6) probably means"______ ".A. get firedB. get paidC. lose their healthD. lose part of wagesBIf it is not only possible but even easy to predict which ten-year-old boys are at greatest risk of growing up to be persistent offenders (惯犯), what are we doing with the information? The last thing that we should do is to wait until their troubles have increased in adolescence and then attack them with the new Criminal Justice Bill.If this bill becomes law, more young people will be drawn into prisons and all the evidence shows that this worsens rather than improves their future. The introduction of short sharp punishment will simply give more young peopl e a taste of something else they don’t need and if you want to train someone to be anti-society, "I can’t think of a better way to do it" says the writer of this report.The Cambridge Institute of Criminology comes up with five key factors that are likely to make for adolescence crimes: a low income family, a large family, parents regarded by social workers to be bad at raising children, parents who themselves have a criminal record, and low intelligence in the child. Of the 63 boys in the sample who had at least three of them when they were ten, half became criminals—compared with only a fifth of the sample as a whole.Three more factors make the prediction more accurate: being judged troublesome by teachers at the age of ten, having a father with at least two criminal records and having another member of the family with a criminal record. Of the 35 men who had at least two of these factors in their background, 18 became persistent offenders and 8 more were in trouble with the law.The role of the schools is recognized as extremely important. The most reliable prediction of all on the futures of boys came from teachers’ ratings of how troublesome they were at the age of ten. If the information is there in the classroom, there must be a response that brings more attention to those troublesome children: a search for things to give them praise r ather than academic achievement, a refusal to allow them to go on playing truant, and a promoting of ambition and opportunitywhich should start early in their school careers.46. According to the author, adolescence crimes should be dealt ______.A. before they become adolescentsB. when they are put into prisonC. when they are in the period of adolescenceD. when the problem becomes serious47. The number of young offenders could be reduced by the way of ______.A. setting new legal systemB. helping with their academic performanceC. applying brief periods of severe punishmentD. knowing about their backgrounds48. Ten-year-old children likely to become offenders are usually______.A. spoilt children from small fa miliesB. bright children in a poor familyC. slow children with many brothers and sistersD. children whose parents gain wealth dishonestly49. The writer concludes that potential offenders could be helped by ______.A. making less trouble through self disciplineB. being given more encouragement at schoolC. being permitted to leave school as they likeD. stricter treatment from teachersCI am beginning to wonder whether my grandmother isn’t right when she complains, as she frequently does, that children nowadays aren’t as well-behaved as they used to be. Whenever she gets the opportunity, she recounts in detail how she used to be told to respect the elders and betters. She was taught to speak only when she was spoken to, and when she went out on her own, she was reminded to say 'please' and 'thank you'. Children in her day, she continues, were expected to be seen and not heard, but these days you are lucky if you ever hear parents telling their children to mind their p’s and q’s.If you give her the chance, she then takes out of her drawer t he old photograph album which she keeps there, and which she never tires of displaying. Of course when you look at pictures of her parents, you feel sure that, with a father as stern-looking as that, you too would have been "seen and not heard". He had a lot of neatly cut hair, long side-whiskers and a big moustache. In the photographs, he is always clutching (抓住) his coat with one hand, while in the other he holds a thin walking stick. Beside him sits his wife, with their children around her: Granny and her elder brothers. It always occurs to me that perhaps those long, stiff, black clothes were so clumsy to a little girl, that she hadn’t enough breath left to be talkative, let alone mischievous (淘气的). It must have been a dull and lonely lifetoo, for she stayed mainly at home during her childhood, while her brothers were sent away to school from an early age. Despite thei r long black shorts and their serious expressions in the photographs, I always suspect that their lives were considerably more enjoyable than hers. One can imagine them telling each other to shut up or mind their own business, as soon as their parents were out of sight.Going to see Granny on Sundays used to be a terrible experience. We would always be warned in advance to be on our best behavior, since my mother made a great effort to show how well brought up we were, in spite of our old, comfortable clothes, our incomprehensible (to Granny) slang, and our noisy games in the garden. We had to change into what Granny described as our "Sundays best" for lunch, when we would sit uncomfortably, kicking each other under the table. We were continually being ordered to sit up straight, to take our elbows off the table, to wait till everybody had been served, not to wolf down our food, nor to talk with our mouths full. At length we would be told to ask to be excused from the table and ordered to find quiet occupations for the rest of the day. We were always very bad-tempered by the evening, and would complain angrily all the way home.Yet though we hated the Sunday visit, we never questioned the rules of good manners themselves. I remember being greatly shocked as a child to hear one of my friends telling her father to shut up. I knew I could never have spoken like that to my father and it would never have occurred to me to do so.However, my childhood was much freer than Granny’s. I went to school with my brother and I played football with him and his friends. We all spoke a common language, and we got up to the same mischief. I would have died if I had had to stay indoors, wear a tight dress, and sew.But I do sometimes look wistfully (惆怅地) at an old sampler which hangs in the hall, which was embroidered (刺绣) by an even more distant relative—my great-great-aunt, of whom, regrettably, no photograph remains. It was done as an example of her progress in learning. The alphabet is carefully sewn in large colored childish letters from A to Z, and below it a small verse reads:Mary Saunders is my name,And with my needle I worked the same,That by it you may plainly seeWhat care my parents have for me.It must have taken that little five-year-old months and months of laborious sewing, but, in a circle in a bottom corner of the sampler, there is a line: "Be Ever Happy".50. The writer’s grandmother will complain that ______.A. children used to be mischievousB. children behave worse than they did in the pastC. children are often reminded of what to doD. childre n are very badly behaved51.Visiting Granny on Sundays was a terrible experience because ______.A. the writer was not so well raised as she was required to pretendB. Granny continually warned the writer to be on her best behaviorC. Granny was always describing the writer’s "Sunday best"D. the writer was always blamed for not behaving well52. From Paragraph 4, we can infer that the writer ______.A. seldom spoke to her father in the way her friend didB. was never questioned about the rules of good mannersC. never doubted the value of the strict rules at that timeD. was worried that her friend’s fath er would be shocked53. The writer looked wistfully at the sampler, because______.A. it was embroidered by a relative.B. she wished she could sew herself.C. it called to mind the values of good old days.D. she had no photographs of Mary Saunders.54. By sewing "Be Ever Happy" in the sampler, Mary Saunders ______.A. suggested she was unhappy thenB. indicated happiness was hard to gainC. expected we would find happiness in sewingD. hoped happiness would be everlastingDIn golf, we talk about handicaps. The lower the handicap, the better the golfer.A golfer with a handicap of 12 tends to play better than one with a handicap of20.It means that for a golf course that normally takes a professional 72 strokes (击球) over 18 holes to play, a 12-handicap golfer would complete his full game with a score of 84 strokes.When it comes to creative thinking, is there such a handicap system? Can we describe a person as a 12-handicap in his creative thinking ability?Fortunately or unfortunately, there is no such system yet for creative thinking. But we all suffer from a handicap when it comes to creative thinking. Some of us are better players at such an activity, with ideas flowing freely. Some of us are average or green hands at such thinking, failing often and feeling very frustrated.But don’t fear. Creative thinkers can be like golfers striving to reduce their handicaps. It takes learning and practice, and re-learning and re-practice until you become better at it.How do you learn to be a creative thinker? Just like the game of golf, you need to have an interest. Is your interest purely social, business or personal? Do you have a desire to improve?Most golfers challenge themselves to reduce their handicaps for personalsatisfaction and enjoyment, so do you have this burning desire to be a better creative thinker?Next comes the learning process. Some golfers are self-taught. They learn from watching golf tour naments live or on TV. They watch videotapes of golf professionals. They read golf books.To self-teach yourself in creative thinking, you can buy books on the subject or borrow books from community and university libraries. Some creative books list a bibliography (书目) of other useful reference books on the same subject. If you are resourceful, you can visit as many schools, colleges, universities, or community libraries as possible.You need to think about what you read. Study the different creative thinking processes and methods, and experiment with them on your own or among friends. Practice makes you remember better. Practice also makes perfect, as the saying goes.Many golfers take up lessons from teaching professionals rather than learning from friends who might not teach correctly. If you can, sign up for creative-thinking lessons offered by famous companies.Don’t just atten d the creative-thinking courses. Be a committed student, always following up on what you have learned and exploring more. Although I train teams in creativity and innovation, I am still reading widely on the subject, reflecting on my company’s methods, improving on the teaching of methods, and experimenting with and adapting to new techniques.The greatest handicap is yourself, your own mind. If you have been brought up to believe that you are not creative and you keep telling yourself or people that you are not creative, then you are not helping yourself. A golfer who has a negative self-image is also ruining himself and his game.Cancel the negative self-image from your mind. Each time the negative thought flashes in your mind, replace it with a positive self-image, such as "I have the capacity to be very creative. I can be a creative thinker." Then affirm (肯定) this new image daily, several times a day. It might help if you write down such affirmative statements and paste them in places to remind you several times each day.Focus on this creative image of yourself daily. Twice a day if possible, even if it is only 10 minutes each time. Focus and imagine yourself being creative in your studies, work, meetings, at home, and in different situations.Then train yourself to succeed as you have imagined. It means actually thinking and experimenting with different creative techniques on practical cases. It also means reading to enrich your mind daily, even if it is but half an hour a day. Keep on learning, practicing, reviewing, re-learning and re-practicing, and I am confident that you can bring down your creative thinking handicap.55. Creative thinking is different from golf in that ______.A. creative thinkers suffer from no handicapB. there is no handicap system for creative thinkingC. creative thinkers have to deal with more obstaclesD. creative thinking has nothing to do with personal satisfaction56. The underlined word "handicap" (Para. 4) can best be replaced by ______.A. uncertaintyB. disadvantageC. inconvenienceD. discomfort57. According to the passage, ______ is the greatest barrier for creative thinking.A. lack of self-confidenceB. lack of the interest in exploring moreC. not attending the creative thinking courseD. having no interest in reading books on creativity58. To cancel the negative self-image from your mind, you have to ______.A. borrow books every dayB. attend courses on creativityC. assure yourself that you are creativeD. experiment with different techniques on practical cases59. What kind of writing technique is employed by the author to make his point clear?A. Comparison.B. Definition.C. Description.D. Explanation.60. The article is writte n to ______.A. provide informationB. share a storyC. express feelingsD. encourage people参考答案41-45 CDBAD 46-49 ADCB 50-54 BACCD55-60 BBACAD。
小学六年级上册数学每日一练(第四周).docx
01足球门票 15 元一张,降价后观众增加一倍,收入增加 1/5 ,问一张门票降价多少元?【答案】初看似乎缺少观众人数这个条件,实际上观众人数于答案无关,我们可以随便假设一个观众数.为了方便,假设原来只有一个观众,收入为 15 元,那么降价后有两个观众,收入为 15 ×(1+1/5)=18元,则降价后每张票价为18÷2=9元,每张票降价 15 -9=6 元.即:15 - 15 ×(1+1/5)÷2=6(元)答:每张票降价 6 元.说明:如果设原来有 a 名观众,则每张票降价:15 - 15a ×( 1+1/5)÷2a=6(元)02小明和小亮各有一些玻璃球,小明说:“你有球的个数比我少 1/4 !”小亮说:“你要是能给我你的 1/6 ,我就比你多 2 个了.”小明原有玻璃球多少个?【答案】小明说:“你有球的个数比我少 1/4则想成小明的球的个数为 4 份,则小亮的球的个数为3 份 4×1/6 =2/3(小明要给小亮!” ,2/3份玻璃球)小明还剩:4-2/3= 3又 1/3(份)小亮现有:3+2/3= 3又 2/3(份)这多出来的 1/3份对应的量为 2,则一份里有:3×2=6(个)小明原有 4 份玻璃球,又知每份玻璃球为 6 个,则小明原有玻璃球 4×6=24(个)03水泥厂原计划12 天完成一项任务,由于每天多生产水泥 4.8 吨,结果 10 天就完成了任务,原计划每天生产水泥多少吨?【解析】想:由题意知,实际10天比原计划 10 天多生产水泥( 4.8 ×10 )吨,而多生产的这些水泥按原计划还需用(12-10 )天才能完成,也就是说原计划(12-10)天能生产水泥( 4.8 ×10 )吨 .【解答】解: 4.8 ×10 ÷(12-10) =24(吨)答:原计划每天生产水泥24吨 .04某商店将进货单价为 90 元的某商品按 100 元售出后,能卖出 500 个.已知这种商品每个涨价 1 元,其销售量就减少 10 个.为了能赚得更多利润,售价应定为每个 ______ 元 .【答案】120元.【解析】因为按每个 100元出售,能卖出500个,每个涨价1元,其销量减少 10 个,所以,这种商品按单价 90 元进货,共进了 600个.现把 600个商品按每份10个,可分成60份.因每个涨价 1 元,销量就减少 1 份(即 10 个);相反,每个减价 1 元,销量就增加 1 份.所以,每个涨价的钱数与销售的份数之和是不变的(为 60),根据等周长长方形面积最大原理可知,当把 60 分为两个 30 时,即每个涨价 30 元,卖出 30 份,此时有最大的利润.因此,每个售价应定为 90 +30=120(元)时,这一天能获得最大利润.05大货车和小轿车从同一地点出发沿同一公路行驶,大货车先走 1.5 小时,小轿车出发后 4 小时后追上了大货车.如果小轿车每小时多行 5 千米,那么出发后 3 小时就追上了大货车.问:小轿车实际上每小时行多少千米?【答案】小轿车实际上每小时行 55 千米.【解析】大货车的速度是小轿车速度的:4 :( 1.5+4)=8/11,小轿车实际每小时行:5×3÷(1-8/11)=55(千米/小时)06王师傅要加工一批零件,若每小时多加工12 个零件,则所用的时间比原计划少1/9 ;若每小时少加工 16 个,则所用的时间比原来多 3/5 小时.这批零件有多少个?解析:工作时间少 1/9 ,说明工作效率提高了 1÷(1-1/9 )-1=1/8 ,说明原来计划每小时加工 12 ÷1/8 =96 个.每小时如果少加工 16 个,工作效率就是原来的(96-16 )÷96 =5/6 ,时间就要增加 1÷5/6 -1=1/5.所以原计划的工作时间是 3/5 ÷1/5 =3 小时.因此这批零件 96 ×3=288个.07小明家离火车站很近,他每天都可以根据车站大楼的钟声起床.车站大楼的钟,每敲响一下延时 3 秒,间隔 1 秒后再敲第二下.假如从第一下钟声响起,小明就醒了,那么到小明确切判断出已是清晨 6 点,前后共经过了几秒钟?分析与解:从第一下钟声响起,到敲响第 6 下共有 5 个“延时”、5 个“间隔”,共计(3+1 )×5=20秒.当第 6 下敲响后,小明要判断是否清晨 6 点,他一定要等到“ 延时 3 秒”和“间隔 1 秒”都结束后而没有第 7 下敲响,才能判断出确是清晨 6 点.因此,答案应是:(3+1)×6=24(秒).08王飞同学 2006 年元旦把积攒的 200 元零花钱存入银行,存整存整取一年.准备到期后把税后利息捐赠给“希望工程”,支援贫困地区的失学儿童.如果年利率按2.25%计算,到期时他可以捐赠给“希望工程”()元.【答案】 4.28【解析】试题分析:利息=本金×年利率×时间,由此代入数据求出利息;再把这个利息看成单位“1”,税后利息是总利息的 15% ,用乘法就可以求出税后利息,解:200 ×2.25%×1×(1-5%)=200×0.0225×1×0.95=4.5×0.95≈4.28(元)答:到期时小红可以捐赠 4.28元.故答案为:4.28. 这种类型属于利息问题,有固定的计算方法,利息=本金×利率×时间(注意时间和利率的对应),利息税=利息×税率.09甲乙两人在河边钓鱼,甲钓了三条,乙钓了两条,正准备吃,有一个人请求跟他们一起吃,于是三人将五条鱼平分了,为了表示感谢,过路人留下 10 元,甲、乙怎么分?【答案】甲收 8 元,乙收 2元.【解析】“三人将五条鱼平分,客人拿出 10 元”,可以理解为五条鱼总价值为 30 元,那么每条鱼价值 6 元.3*6= 18元,“乙钓了两条”,又因为“甲钓了三条”,相当于甲吃之前已经出资相当于乙吃之前已经出资2*6 =12 元.而甲乙两人吃了的价值都是10 元,所以甲还可以收回 18-10 =8 元乙还可以收回 12-10 =2 元刚好就是客人出的钱.10修一条水渠,单独修,甲队需要 20 天完成,乙队需要 30 天完成.如果两队合作,由于彼此施工有影响,他们的工作效率就要降低,甲队的工作效率是原来的五分之四,乙队工作效率只有原来的十分之九 .现在计划 16 天修完这条水渠,且要求两队合作的天数尽可能少,那么两队要合作几天?【解析】解:由题意得,甲的工效为 1/20,乙的工效为1/30,甲乙的合作工效为1/20*4/5+1/30*9/10=7/100,可知甲乙合作工效>甲的工效>乙的工效.又因为,要求“两队合作的天数尽可能少”,所以应该让做的快的甲多做,16天内实在来不及的才应该让甲乙合作完成.只有这样才能“两队合作的天数尽可能少”.设合作时间为 x 天,则甲独做时间为( 16-x )天1/20* ( 16-x) +7/100*x= 1x = 10答:甲乙最短合作 10天。
学考精练英语七年级上册
学考精练英语七年级上册一、本学期的指导思想:1、整体设计目标,体现灵活开放,目标设计以学生技能,语言知识,情感态度,学习策略和文化意识的发展为基础。
2、必须面向全体学生,高度关注每个学生的情感,唤起他们自学英语的兴趣,协助他们创建自学的成就感和自信心,培育技术创新精神。
3、突出学生主体,尊重个体差异。
4、使用活动途径,提倡体验参予,即为使用任务型的教学模式,使学生在老师的指导下通过认知、体验、课堂教学、参予和合作等方式,同时实现任务的目标,体会顺利。
二、所教班级学生基本情况分析:本届七年级新生和以往初一学生有著非常大的差异,即为他们曾在小学研习过一,二年英语。
但由于在小学英语课并未受足够多的注重,他们在写下的技能方面基本上没获得过训练,字母还无法规范的书写,更别提什么单词,句子。
大二,说道方面,语音也存有不少须要制止的地方,由于各小学讲课,英语基础也高弁不齐。
三、奋斗目标:钻研新课标,提升自己的教学水平,真正努力做到教学相长,不懈努力达至学校规定的教学指标。
四、具体措施:1、每天背诵课文中的对话。
目的:建议学生诵读并口诀,培育语感。
2、每天记5个生词,2个常用句子或习语。
实施:利用“互测及教师抽查”及时检查,保证效果并坚持下去。
3、认真贯彻独秀峰制度:规定独秀峰内容,加强监督,确保独秀峰效果。
4、坚持日测、周测、月测的形成性评价制度:对英语学习实行量化制度,每日、每周、每月都要给学生检验自己努力成果的机会,让进步的同学体会到成就感,让落后的同学找出差距,感受压力。
由此在班里形成浓厚的学习氛围,培养学生健康向上的人格和竞争意识。
5、对后进生展开专门辅导,布置单独的作业,使他们在小进步,大转型中体味自学的欢乐,践行自学的自信心,尽快蜕变出来。
6、关注学生的`情感,营造宽松、民主、和谐的教学氛围。
7、强化对学生学习策略的指导,为他们终身自学打下基础。
8、要充分利用现代教育技术,利用计算机和多媒体教学软件,探索新的教学模式,开发英语教学资源,拓宽学生学习渠道,改进学生学习方式,提高教学效果。
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2021年 1 月11 日(周一)
简便计算:连乘——乘法交换律的应用(乘法交换律 b c a c b a ⋅⋅=⋅⋅)
1)
1474135⨯⨯ 2)56153⨯⨯ 3)266831413⨯⨯
简便计算:乘法分配律的应用(乘法分配律 bc ac c b a ±=⨯±)()
例题:1)27)27498
(⨯+ 2)4)41101(⨯+ 3)16)2143(⨯+
简便计算:(脱式计算,能简算的要简算)
191952013⨯⨯ 24165-3787÷+)( 75.08743÷⨯ 253-10125
3⨯
——————————————————————————————————————————————— 2021 年 1 月 12日(周二)
一、简便计算:(脱式计算,能简算的要简算)
1)
759575⨯- 2)9216792⨯- 3)23233117233114+⨯+⨯
4)16317⨯
5)19718⨯ 6)316967⨯
二、解方程
x -20%x =6.4 87-2x=51
6535x 3=÷ 42%50x 32=+x
2021 年 1 月 13 日(周三)
一、简便计算:(脱式计算,能简算的要简算)
1)4161725
⨯ 2)351213⨯ 3)135127⨯
4)
247174249175⨯+⨯ 5)1981361961311⨯+⨯ 6)138
1137138137139⨯+⨯
——————————————————————————————————————— 2021 年 1 月 14日(周四)
一、分数乘法和分数除法的简便计算:
1) 1159251197⨯+÷ 2)6.0352444533533-÷+⨯+÷
(3) 59 × 34 +59 × 14 (4) 46×45
44 (5)( 34 +58 )×32
二、化简下面各比并求比值。
45∶30
57 :34 0.875∶0.125 34 千克∶300克
2021 年1 月15日(周五)
一、分数乘法和分数除法的简便计算:
1 5+
2
9
×
3
10
44-72×
5
12
2
3
+(
4
7
+
1
2
)×
7
25
二、解方程
3 4x + x= 1
4 2
3
x ÷1
4
= 128
21
x=153
8
x + 0.3x= 14
———————————————————————————————————————2021 年 1 月16 日(周六)
一、计算下题,能简算的要简算。
4 7÷ (5
8
− 1
4
) ( 1
3
−1
4
+1
6
)×12 2
7
×21
25
÷(3
4
−1
8
) 2008×
2006
2007
8
7
7
4
8
7
7
3
÷
+
÷
9
1
9
2
9
1
9
7
÷
-
÷
二、把下面各题化成最简单的整数比。
52:36
6
1
4
1
: 0.8:1.2 20cm:1m。