初一下第六单元练习题
人教版初一下册英语各单元基础检测题
人教版初一下册英语各单元基础检测题第一单元练习题1.Lucy can play the guitar but she can’t play it .A. well B good C nice D fine2.Bill can play piano. He can also play soccer.A the ;theB the ;/C /; the3.—Can I help you??A. Yes ,pleaseB. No, I can’tC. Yes, I canD. you are welcome .4. Miss 'Read is good music. A. for B. with C. at D in5. He wants to join the club. He can chess.A. chess's; play theB. chess; playC. chessing; playD. chess; plays the6.一Dad, we can sports at school one hour a day.A. to doB. doesC. doD. doing7. 一What can you do, Lin Tao?A.I like sports B I want to join the music clubC.I am wellD. I can do Chinese Kong fu.8、She wants to go to Beijing her father in 2013.A for B. with C of D before9.If you want to know that, please call 622-6033.A. byB. at C for D on10. Let’s go and play __ping-pong. I don’t want to play __violin.A. a, theB. the, aC. /, the D the, the11. Who wants ______ the singing club?A. to joinsB. joinC. to join D joining12.I always help my sister_______ her history.A. toB. withC. for D of13.Maybe he can ______ in their basketball team.A. isB. beC. are D am14. -- Can you play the violin? --- .But I can sing.A. Yes, I doB. No ,I don’tC. Yes, I canD. No, I can’t15.My friend Lisa is good at _____.A. singB. to singC. singing D sings16.He is funny. He likes____ stories.A. talkingB. sayingC. telling D speaking17. A:Can you swim or play chess? B:___________.A. Yes, I amB. Yes, I canC. I can swimD.I don’t know18. Are you good ____ children? A. with B. at C. for D. to19. A: _ _ do you join the club? B: I like music.A. WhatB. WhereC. Why D How20. Can you ____ Chinese? A. say B. talk C. speak D. tell21. Tom can play the drums very well.(改为否定句)Tom the drums very well.22.I can speak English well.(改为一般疑问句)speak English well?23. Her sister can join the swimming club ( 就画线部分提问)can her sister join?24. My brother can play the guitar。
冀教版七年级英语下册Unit 6单元检测卷(附答案)
学校汛前准备情况汇报尊敬的领导、老师们:根据学校防汛工作部署,我校已经全面展开了汛前准备工作,确保学校师生的生命财产安全。
现将学校汛前准备情况进行汇报如下:一、加强汛期安全教育。
为了增强师生的防汛意识,学校开展了一系列的汛期安全教育活动。
通过班会、主题班会、安全教育课等形式,向师生宣传防汛知识,教育他们如何在汛期保护自己,避免发生意外事故。
同时,学校还利用校园广播、电子屏等宣传媒介,不断提醒师生关注天气预警信息,增强自我保护意识。
二、检查校园设施和设备。
为了确保校园设施和设备的安全可靠,学校成立了专门的检查小组,对校园内的电力设施、排水系统、楼宇结构等进行了全面检查和维护。
对于存在安全隐患的地方,学校及时进行了修缮和加固,确保在汛期能够正常使用。
三、加强校园巡查和警戒。
学校加强了校园巡查和警戒工作,每天都有专门的工作人员对校园内的池塘、河道、排水沟等进行巡视,及时发现并处理存在的安全隐患。
同时,学校还配备了专门的安全巡逻队,24小时轮流值班,确保在汛期能够第一时间应对突发情况。
四、制定应急预案和演练。
学校制定了汛期应急预案,并组织了应急演练活动。
通过模拟汛期突发事件,检验学校的应急处置能力,提高师生在突发事件中的应对能力。
同时,学校还加强了与当地政府和相关部门的沟通联系,确保在汛期能够及时得到支持和帮助。
五、加强师生安全检查。
学校组织了全校师生的安全检查活动,对校园内的安全隐患进行了全面排查和整改。
同时,学校还加强了学生的安全教育,教育他们在汛期要远离危险区域,不随意涉水,避免发生意外。
六、加强社会宣传和联防联控。
学校积极响应政府的号召,加强了与社区、家长的沟通和协作。
通过社会宣传活动,提高了社会公众对汛期安全的重视程度,形成了社会共同防汛的氛围。
同时,学校还与社区、家长建立了联防联控机制,共同保障师生的安全。
以上就是我校汛前准备情况的汇报,学校将继续密切关注天气变化,加强防汛工作,确保师生的安全。
人教版英语七年级下册Unit6练习题及答案解析
七下Unit 6 I’m watching TV.第1课时一、根据中文或首字母提示填写单词。
1. Can I __________(使用)your phone for a while?2. Tony is __________(只有)3 years old, but he can dress himself.3. My father reads __________(报纸)for half an hour every morning.4. Wolf Warrior II(《战狼2》)is one of my favorite __________(电影).5. I like chicken __________(汤)because it tastes good.二、用括号内所给单词的适当形式填空。
6. Tom's clothes get dirty after one day's work. He __________ (wash) them now.7. It's 7:20. Jane and her father __________ (take)a walk in the park.8. My mother __________ (make) soup for us every day.9. --- Is Ben __________ (write) a letter now? --- Yes, he is.10. The boys like __________ (run). Look! They __________ (run) in the playground now.11. Going to the movies is one of my favorite activities on __________.12. --- Where's Lisa? --- She __________ to music in her bedroom.13. We need __________ every day to keep healthy.14. Look! Some students __________ the classroom now.15. The teacher teaches the children how __________ the dictionary.四、根据中文意思完成句子,每空一词。
(必考题)初中七年级数学下册第六单元《实数》经典练习题(答案解析)
一、选择题1.给出下列各数①0.32,②227,③π,⑤0.2060060006(每两个6之间依次多个0), ) A .②④⑤B .①③⑥C .④⑤⑥D .③④⑤D解析:D【分析】无理数就是无限不循环小数.初中范围内学习的无理数有:π,开方开不尽的数,以及像0.1010010001…,等有这样规律的数.由此逐一判断即可得答案.【详解】①0.32是有限小数,是有理数, ②227是分数,是有理数, ③π是无限循环小数,是无理数,⑤0.2060060006(每两个6之间依次多个0)是无限循环小数,是无理数,,是整数,是有理数,综上所述:无理数是③④⑤,故选:D .【点睛】此题主要考查了无理数的定义,初中范围内学习的无理数有:π,2π等;开方开不尽的数;以及像0.1010010001…,等有这样规律的数;熟练掌握定义是解题关键.2 )A .8B .±8C .D . C解析:C【分析】【详解】,8的算术平方根是,.故选择:C .【点睛】本题考查一个数的算术平方根的算术平方根,掌握求算式的平方根,一定要把算式化简得到结果后再求是解题关键.3.观察下列运算:81=8,82=64,83=512,84=4 096,85=32 768,86=262 144,…,则81+82+83+84+…+82 017的和的个位数字是()A.2 B.4 C.6 D.8D解析:D【分析】根据规律可得底数为8的幂的个位数字依次为8,4,2,6,以4个为周期,个位数字相加为0. 2017除以4余数是1,故得到和的个位数字是8.【详解】解:2017÷4=504…1,循环了504次,还有1个个位数字为8,所以81+82+83+84+…+82017的和的个位数字是504×0+8=8.故选:D.【点睛】本题主要考查了数字的变化类,尾数的特征,得到底数为8的幂的个位数字的循环规律是解决本题的突破点.4.下列实数220.0100100017;; (相邻两个1之依次多一个0);2,其中无理数有( )A.2个B.3个C.4个D.5个B解析:B【分析】根据无理数、有理数的定义即可判定选择项.【详解】4=-,是有理数;3.14是有限小数,是有理数;227是分数,是有理数;,0.010010001(相邻两个1之依次多一个0)2,是无理数,共3个,故选:B.【点睛】本题考查了无理数的定义,注意无理数的三种形式:①开方开不尽的数,②无限不循环小数,③含有π的数.5.1的值()A.在7和8之间B.在6和7之间C.在5和6之间D.在4和5之间C解析:C【分析】利用36<48<49得到6<7−1进行估算.【详解】解:∵36<48<49,∴6<7,∴5-1<6.故选:C .【点睛】本题考查了估算无理数的大小:估算无理数大小要用逼近法.6.,则571.34的平方根约为( )A .239.03B .±75.587C .23.903D .±23.903D 解析:D【分析】根据被开方数小数点向右移动两位,其算术平方根向右移动一位及平方根的定义求解即可.【详解】解:∵,∴,故选:D .【点睛】本题主要考查算术平方根与平方根,解题的关键是掌握被开方数小数点向右移动两位,其算术平方根向右移动一位和平方根的定义.7.下列说法中,错误的有( )①符号相反的数与为相反数;②当0a ≠时,0a >;③如果a b >,那么22a b >;④数轴上表示两个有理数的点,较大的数表示的点离原点较远;⑤数轴上的点不都表示有理数.A .0个B .1个C .2个D .3个D解析:D【分析】根据相反数、绝对值、数轴表示数以及有理数的乘法运算等知识综合进行判断即可.【详解】解:符号相反,但绝对值不等的两个数就不是相反数,例如5和-3,因此①不正确; a≠0,即a >0或a <0,也就是a 是正数或负数,因此|a|>0,所以②正确;例如-1>-3,而(-1)2<(-3)2,因此③不正确;例如-5表示的点到原点的距离比1表示的点到原点的距离远,但-5<1,因此④不正确; 数轴上的点与实数一一对应,而实数包括有理数和无理数,因此⑤正确;综上所述,错误的结论有:①③④,故选:D .【点睛】本题考查相反数、绝对值、数轴表示数,对每个选项进行判断是得出正确答案的前提. 8.关于x 的多项式32711159x mx x --+与多项式22257x nx --相加后不含x 的二次和一次项,则()mn n -+平方根为( )A .3B .3-C .3±D .解析:C【分析】将两个多项式相加,根据相加后不含x 的二次和一次项,求得m 、n 的值,再进行计算.【详解】 32711159x mx x --++22257x nx --=()()32722111552x m x n x +--++ 由题意知,2211=0m -, 155=0n +,∴=2m ,=3n -,∴()()=323=9mn n -+--⨯-,9的平方根是3±,∴()mn n -+平方根为3±,故选:C .【点睛】此题考查了整式的加减−化简求值,熟练掌握运算法则是解本题的关键,同时考查了平方根的定义,熟练掌握正数有两个平方根,0的平方根是0,负数没有平方根.9.估计50的立方根在哪两个整数之间( )A .2与3B .3与4C .4与5D .5与6B 解析:B【分析】,可得答案.【详解】,得34,所以,50的立方根在3与4之间故选:B .【点睛】本题考查了估算无理数的大小,利用了正数的被开方数越大立方根越大的关系. 10.下列各数中是无理数的是( )A .227B .1.2012001C .2πD 解析:C【分析】无理数就是无限不循环小数.理解无理数的概念,一定要同时理解有理数的概念,有理数是整数与分数的统称.即有限小数和无限循环小数是有理数,而无限不循环小数是无理数.由此即可判定选择项.【详解】解:A 、227分数,是有理数,选项不符合题意; B 、1.2012001是有理数,选项不符合题意; C 、2π是无理数,选项符合题意;D ,9是整数是有理数,,选项不符合题意.故选:C .【点睛】此题主要考查了无理数的定义,其中初中范围内学习的无理数有:π,2π等;开方开不尽的数;以及像0.1010010001…,等有这样规律的数.二、填空题11.求满足条件的x 值:(1)()23112x -=(2)235x -=(1);(2)【分析】(1)方程两边同除以3再运用直接开平方法求解即可;(2)方程移项后再运用直接开平方法求解即可【详解】解:(1)解得;(2)∴∴【点睛】本题考查了平方根的应用解决本题的关键是熟记解析:(1)13x =,21x =-;(2)1x =2x =-【分析】(1)方程两边同除以3,再运用直接开平方法求解即可;(2)方程移项后,再运用直接开平方法求解即可.【详解】解:(1)()23112x -= ()214x -=12x -=±解得,13x =,21x =-;(2)235x -=28x = ∴x =±∴1x =2x =-【点睛】本题考查了平方根的应用,解决本题的关键是熟记平方根的定义.12.初一年级某同学在学习完第二章《有理数》后,对运算产生了浓厚的兴趣.他借助有理数的运算,定义了一种新运算“⊕”,规则如下:21a b a ab ⊕=--.求()23-⊕的值.1【分析】根据新运算的运算法则计算即可【详解】解:【点睛】本题考查新定义下的有理数运算通过阅读材料掌握新运算的运算法则是解题关键 解析:1【分析】根据新运算的运算法则计算即可.【详解】解:()()()2322231-⊕=⨯---⨯-()4614611=----=-+-=.【点睛】本题考查新定义下的有理数运算,通过阅读材料掌握新运算的运算法则是解题关键. 13.计算.(1)3218433⎛⎫-⨯-+- ⎪⎝⎭(2)178(4)4(5)-÷-+⨯-(3163⎫-⎪⎪⎭(4)22323223⎡⎤⎛⎫-⨯-⨯--⎢⎥ ⎪⎝⎭⎢⎥⎣⎦(1);(2)-1;(3);(4)9【分析】(1)运用乘法分配律去括号再进行乘法运算最后进行加减运算即可得到答案;(2)原式首先计算乘除法选辑减去息怒可;(3)原式首先化简算术平方根和立方根再进行加解析:(1)354;(2)-1;(3)1-;(4)9. 【分析】(1)运用乘法分配律去括号,再进行乘法运算,最后进行加减运算即可得到答案; (2)原式首先计算乘除法选辑减去息怒可;(3)原式首先化简算术平方根和立方根,再进行加减运算即可得到答案;(4)首先计算乘方运算,再计算括号内,最后算乘法即可得到答案.【详解】解:(1)3218433⎛⎫-⨯-+- ⎪⎝⎭ =33231(8)()()()44343-⨯-+-⨯+-⨯-=11624-+ =354; (2)178(4)4(5)-÷-+⨯-=17+2-20=-1;(3163⎫-⎪⎪⎭=115+()633-+-=5+0-6=-1;(4)22323223⎡⎤⎛⎫-⨯-⨯--⎢⎥ ⎪⎝⎭⎢⎥⎣⎦ =34(92)29-⨯-⨯- =3(42)2-⨯-- =3(6)2-⨯-=9. 【点睛】此题主要考查了实数的混合运算,熟练掌握运算法则是解答此题的关键.14.规定一种新的定义:a ★b -a 2,若a =3,b =49,则(a ★b )★b =_________.【分析】根据题中给到的新运算先计算a ★b 然后直接代入数据计算(a ★b)★b 即可【详解】因为a ★b =-a2=所以(a ★b)★b==7-4=3故答案为:3【点睛】本题考查定义新运算解题关键在于熟练掌握运解析:3【分析】根据题中给到的新运算,先计算a ★b 然后直接代入数据计算(a ★b )★b 即可.【详解】因为a ★b -a 2,=23792=-=-所以 (a ★b )★b=2(2)- =7-4=3故答案为:3.【点睛】本题考查定义新运算,解题关键在于熟练掌握运算法则.15. ________0.5.(填“>”“<”或“=”)<【分析】将05变形为将两数作差后借助<2即可得出﹣05<0进而即可得出<05【详解】解:∵05=∴﹣05=∵()2=322=43<4∴<2∴<0∴﹣05<0即<05故答案为:<【点睛】本题考查了实解析:<【分析】将0.5变形为12<2﹣0.5<0,进而即可得出<0.5. 【详解】解:∵0.5=12,∴﹣0.5 ∵2=3,22=4,3<4, ∴2,∴22<0,∴﹣0.5<0,<0.5. 故答案为:<.【点睛】﹣0.5<0是解题的关键.16.<x 的所有整数x 的和是_____.2【分析】首先通过对和大小的估算可得满足﹣<x <的所有整数进而对其求和可得答案【详解】解:∵﹣2<﹣<﹣12<<3∴满足﹣<x <的所有整数有﹣1012∴﹣1+0+1+2=2故答案为:2【点睛】本题主解析:2【分析】x 的所有整数,进而对其求和可得答案.【详解】解:∵﹣21,2 <3,∴<x 的所有整数有﹣1,0,1,2,∴﹣1+0+1+2=2,故答案为:2.【点睛】本题主要考查无理数大小的估算,比较简单,正确理解是解题的关键.17.比较大小:12π-________1【分析】利用估值比较法再利用不等式的性质3不等式两边都乘以-1不等式方向改变最后利用不等式性质1不等式两边都加1不等号方向不变即可确定大小【详解】∵∴∴∴故答案为:【点睛】本题考查无理数的比较大小问解析:<【分析】利用估值比较法322π>>,再利用不等式的性质3,不等式两边都乘以-1,不等式方向改变2π-<,最后利用不等式性质1,不等式两边都加1,不等号方向不变即可确定大小. 【详解】∵322π>32<,∴2π>,∴2π-<, ∴12π-<1. 故答案为:<.【点睛】本题考查无理数的比较大小问题,掌握不等式的性质,会用不等式的性质比较大小,用估值法比较大小是解题关键.18的相反数是________的数是________【分析】直接利用相反数的定义以及绝对值的性质分析得出答案【详解】的相反数是;绝对值等于的数是故答案为:;【点睛】本题主要考查了绝对值以及相反数正确掌握相关定义是解题关键【分析】直接利用相反数的定义以及绝对值的性质分析得出答案.【详解】;【点睛】本题主要考查了绝对值以及相反数,正确掌握相关定义是解题关键.19.阅读下列信息材料信息1:因为尤理数是无限不循环小数,因此无理数的小数部分我们不可能全部地写出来比如:π“……”或者“≈”的表示方法都不够百分百准确;信息2:2.5的整数部分是2,小数部分是0.5,可以看成2.52-得来的;信息3:任何一个无理数,都可以夹在两个相邻的整数之间,如23<<,是因为<;根据上述信息,回答下列问题:(1___________,小数部分是______________;(2)若2122a <<,则a 的整数部分是___________;小数部分可以表示为_______;(3)10+10a b <则a b +=______;(43x y =+,其中x 是整数,且01y <<,请求x y -的相反数.(1)3;;(2)21;;(3)23;(4)【分析】(1)先找到可找到即可找出的整数部分与小数部分(2)根据因为即可找出的整数部分与小数部分(3)找到在哪两个整数之间再加10即可(4)先确定找到由是解析:(1)33;(2)21;21a -;(3)23;(47.【分析】(1)先找到91316<<,可找到34<< (2)根据因为2122a <<,即可找出a 的整数部分与小数部分(3)找到12<<在哪两个整数之间,再加10即可.(4)先确定56<<,找到233<<,由01y <<,x 是整数,即可确定x=2,5,再求7x y -=,即可求出【详解】(1)91316<<∴34<<33故答案为:33;(2)因为2122a <<,故则a 的整数部分是21,a 的小数部分可以表示为21a -. 故答案为:21;21a -;(3)因为12<<, ∴10110102+<+<+,即111012<+<,所以=11a ,=12b ,故23a b +=,故答案为:23;(4)5306<<,23033<<,∵01y <<,x 是整数,∴x=2, ∴325-=,∴)257x y -=-=,∴x y -7.【点睛】本题考查的是无理数的整数部分与小数部分,掌握估值法确定无理数的范围,即无限不循环小数知识的拓展延伸,理解题意,按照题目所给的表示方法去解答是关键.20_____;16的平方根为_____;()34-的立方根是_____.【分析】分别根据算术平方根相反数平方根和立方根的概念直接计算即可求解【详解】解:=所以的相反数是;16的平方根为;的立方根是故答案为:;±4;-4【点睛】本题考查了算术平方根平方根和立方根的概念进行解析:- 4± 4-【分析】分别根据算术平方根、相反数、平方根和立方根的概念直接计算即可求解.【详解】-;16的平方根为4±;()34-的立方根是4-.故答案为:—±4;-4【点睛】本题考查了算术平方根、平方根和立方根的概念进行求解即可.注意一个正数有两个平方根,它们互为相反数,正的平方根即为它的算术平方根.立方根的性质:一个正数的立方根是正数,一个负数的立方根是负数,0的立方根是0.三、解答题21.计算:2(3)2--解析:1【分析】先计算乘方、算术平方根,然后计算乘法和减法,即可得到答案.【详解】解:2(3)2--924=-⨯98=-1=.【点睛】本题考查了算术平方根、乘方、有理数的加减乘除混合运算,解题的关键是掌握运算法则进行计算.22.求下列各式中的x :(1)29(1)25x -=(2)3548x +=解析:(1)x=83或x=-23;(2)x =32-. 【分析】 (1)根据平方根的定义解答即可;(2)根据立方根的定义解答即可.【详解】解:(1)∵9(x-1)2=25∴x-1=±53, 即x-1=53或x-1=-53, 解得x=83或x=-23; (2)3548x += 3548x =- 3278x =-x =32-.【点睛】本题主要考查了求一个数的平方根与立方根,熟记定义是解答本题的关键.23.对数运算是高中常用的一种重要运算,它的定义为:如果a x=N(a>0,且a≠1),那么数x叫做以a为底N的对数,记作:x=log a N,例如:32=9,则log39=2,其中a=10的对数叫做常用对数,此时log10N可记为lgN.当a>0,且a≠1,M>0,N>0时,log a (M•N)=log a M+log a N.(1)解方程:log x4=2;(2)求值:log48;(3)计算:(lg2)2+lg2•1g5+1g5﹣2018解析:(1)x=2;(2)32;(3)-2017【分析】(I)根据对数的定义,得出x2=4,求解即可;(Ⅱ)根据对数的定义求解即可;(Ⅲ)根据log a(M•N)=log a M+log a N求解即可.【详解】解:(I)解:∵log x4=2,∴x2=4,∴x=2或x=-2(舍去)(II)解法一:log48=log4(4×2)=log44+log42=1+12=32;解法二:设log48=x,则4x=8,∴22x=32,∴2x=3,x=32,即log48=32;(Ⅲ)解:(lg2)2+lg2•1g5+1g5﹣2018= lg2•( lg2+1g5) +1g5﹣2018= lg2 +1g5﹣2018=1-2018=-2017故答案为-2017.【点睛】本题主要考查同底数幂的乘法,有理数的乘方,是一道关于新定义运算的题目,解答本题的关键是理解给出的对数的定义和运算法则.24.(1)小明解方程2x1x a332-+=-去分母时,方程右边的−3忘记乘6,因而求出的解为x=2,则原方程正确的解为多少?(2)设x ,y 是有理数,且x ,y 满足等式2x 2y 17++=-x-y 的值. 解析:(1)x =−13;(2)(2)x-y 的值为9或-1.【分析】(1)将错就错把x =2代入计算求出a 的值,即可确定出正确的解;(2)根据题意可以求得x 、y 的值,从而可以求得x−y 的值.【详解】(1)把x =2代入2(2x−1)=3(x +a )−3中得:6=6+3a−3,解得:a =1, 代入方程得:2x 1x 1332-+=-, 去分母得:4x−2=3x +3−18,解得:x =−13;(2)∵x 、y 是有理数,且 x ,y 满足等式2x 2y 17++=-∴22174x y y ⎧+=⎨=-⎩, 解得,54x y =⎧⎨=-⎩或54x y =-⎧⎨=-⎩, ∴当x =5,y =−4时,x−y =5−(−4)=9,当x =−5,y =−4时,原式=−5−(−4)=−1.故x-y 的值为9或-1.【点睛】此题考查了解一元一次方程,熟练掌握运算法则是解本题的关键.也考查了实数. 25.计算:(12(2)22(2)8x -=解析:(1)1;(2)124,0x x ==【分析】(1)实数的混合运算,利用算术平方根和立方根的概念逐个进行化简计算;(2)直接用平方根的概念求解.【详解】解:(12=4(2)23----=4+223--=1(2)22(2)8x -=2(2)4x -=22x -=±22x =±∴124,0x x ==.【点睛】本题考查实数的混合运算及利用平方根解方程,掌握相关概念和性质正确计算是解题关键.26.111111133557792017201920192021++++⋯+⨯⨯⨯⨯⨯⨯ 解析:10102021【分析】利用裂项法计算即可.【详解】 原式1111111233520192021⎛⎫=⨯-+-+⋯+- ⎪⎝⎭ 11122021⎛⎫=⨯- ⎪⎝⎭ 1202022021=⨯ 10102021=. 【点睛】 本题考查了利用裂项法进行分数的加法计算,熟练掌握裂项法是解题的关键.27.把下列各数的序号填入相应的括号内①-3,②π,,④-3.14,,⑥0,⑦227,⑧-1,⑨1.3,⑩1.8080080008…(两个“8”之间依次多一个“0”). 整数集合{ …},负分数集合{ …},正有理数集合{ …},无理数集合{ …}.解析:见解析.【分析】先求出立方根,再根据整数、负分数、正有理数、无理数的定义即可得.【详解】3=-,28.计算:(1)2019(1)|2|-(2)[(x ﹣2y )2+(x ﹣2y )(x +2y )﹣2x (2x ﹣y )]÷2x解析:(1)1--2)y x --【分析】(1)先根据正整数指数幂、立方根、平方根、去绝对值化简各项,再进行加减运算即可; (2)先去括号,根据完全平方公式和平方差公式计算后合并同类项,再计算除法即可求解.【详解】(1)原式= 1242-+-+1=-(2)原式=22222444422x xy y x y x xy x ⎡⎤-++-⎣⎦÷-+ ()2222xy x x =-÷-y x =--.【点睛】本题主要考查整式的混合运算,解题的关键是掌握立方根、平方根、绝对值及多项式与单项式的除法法则.。
2020-2021学年部编版语文七年级下册第六单元名著导读《海底两万里》知识点+训练【含答案】
七下《海底两万里》【阅读技法】快速阅读【作者简介】儒勒·凡尔纳(1828一1905)法国科幻和探险小说家,一生创作了六十多部长篇科幻小说,其中的科学幻想如今大部分已变成现实,因此被人们誉为“科学时代的预言家”和“现代科学幻想小说之父”。
他的作品想象丰富,文笔细腻,构思奇巧,既引人入胜,又很有教育意义,适合各个年龄阶段的读者。
代表作有《地心游记》《气球上的五星期》《环游世界八十天》等。
其中,《格兰特船长的儿女》《海底两万里》《神秘岛》被称为“海洋三部曲”。
【创作背景】波兰人民反对沙皇独裁统治的起义遭到残酷镇压是凡尔纳创作《海底两万里》的一个导火索。
他在小说中塑造了尼摩船长这个反对沙皇专制统治的高大形象,赋予其强烈的社会责任感和人道主义精神,以此来表达对现实的批判。
【作品梗概】《海底两万里》是凡尔纳“海洋三部曲”中的第二部,叙述了法国生物学家阿龙纳斯在海洋深处旅行的故事。
故事发生在1866年,当时海上发现了一只被断定为独角鲸的大怪物,阿龙纳斯接受邀请参加追捕,在追捕过程中不幸落水,泅到怪物的脊背上。
其实这怪物并非独角鲸,而是一位叫尼摩的船长自己设计制造的潜水艇“诺第留斯号”。
尼摩船长邀请阿龙纳斯作海底旅行。
他们从太平洋出发,经过珊瑚岛、印度洋、红海、地中海,进入大西洋,还到达了南极,一路饱览了许多罕见的海生动植物和海底的奇异景象,又经历了搁浅、土著人围攻、同鲨鱼搏斗、冰山封路、章鱼袭击等险情。
最后,当潜水艇到达挪威海岸时,阿龙纳斯不辞而别,并将他所知道的海底秘密公布于世。
小说设想了潜水艇的强大功能,描绘了奇幻美妙的海底世界,体现了人类自古以来渴望上天下海、自由翱翔的梦想,也显示了作者非凡的想象力。
反对殖民压迫也是这部小说的重要主题。
主人公尼摩船长不仅是献身科学的探索者,同时也是英勇顽强、反对一切压迫和殖民主义的战士。
在他的身上,体现了作者对科学、社会正义和人类平等的不懈追求。
【主要人物】01尼摩船长本书主人公。
历下区第三中学七年级数学下册第六章二元一次方程组6.1二元一次方程组单元练习1新版冀教版9
二元一次方程组一、判断题(每小题1分,共5分)下列各题正确的画“√”,错误的画“×”。
1、11x y =⎧⎨=⎩不是二元一次方程组。
( ) 2、解二元一次方程组的基本方法有代入消元法、加减消元法等。
( ) 3、某一个二元一次方程组的解一定是组成这个方程组的各个方程的解。
( )4、一次函数y=x 的图像与一次函数y=2x 的图像不相交。
( )5、若方程组⎩⎨⎧=-=-a y ax y x 535 有惟一解,则a≠35 。
( )二、选择题(每小题3分,共30分)下列每小题都给出了四个答案,其中只有一个是正确的,请把正确答案的代号填在题后括号内。
1、如果3x2-k=y 是二元一次方程,那么k 的值是( ) (A ) 2 (B ) 3 (C ) 1 (D ) 02、下列方程组中是二元一次方程组的是( )(A )23x y xy -=⎧⎨=⎩ (B )0x y x y =⎧⎨+=⎩ (C )2101x x x y ⎧--=⎨=+⎩ (D )1231xx y ⎧=⎪⎨⎪+=⎩3、已知x=-2 是方程2x+m -4=0的一个根,则m 的值是( ) (A ) 8 (B ) -8 (C ) 0 (D ) 24、以⎩⎨⎧==32y x 为解的二元一次方程组是( )(A )⎩⎨⎧=-=+15y x y x (B )⎩⎨⎧==y x y x 2332(C )⎪⎪⎩⎪⎪⎨⎧=+=+65213123121y x y x (D )⎪⎪⎩⎪⎪⎨⎧=--+=-++32)(2)(22)(2)(y x y x y x y x5、已知|x+y -1|+(x -y+3)2=0,则(x+y)2002的值是( )(A ) 22002 (B ) -1 (C ) 1 (D ) -220026、6年前,A 的年龄是B 的3倍,现在A 的年龄是B 的2倍,A 现在的年龄是( ) (A ) 12 (B ) 18 (C ) 24 (D ) 307、函数y=x 的图像与函数y=2x+1的图像的交点坐标是( )(A ) (1,1) (B )(0,0) (C )(13,13) (D )(-13,-13)8、8个连续整数的和是28,则紧接这8个连续整数后的8个连续整数的和等于( ) (A ) 36 (B ) 44 (C ) 56 (D ) 929、若方程组431(1)3x y ax a y +=⎧⎨+-=⎩的解x 与y 相等,则a 的值是( )(A ) 4 (B ) 10 (C ) 11 (D )1210、有大小两种笔记本,3个大的2个小的共售10.5元,2个大的4个小的共售11元,大小笔记本售价各是( )(A ) 2.5 元,1.5 元 (B ) 2元,1元 (C ) 1.5元,1元 (D ) 1元,0.5元 三、填空题(每空2分,共 20分)1、在二元一次方程3(x-1)+y=2(y-2)中,当x=2时,y=_________。
初一英语试卷习题
第一单元练习题一、根据句意和首字母提示填空。
1.Your family name is Moore, and what’s your f name?2.Can you fill in your own ID c ?3.Tony wants to ask you three q .4.L ! That’s an English book.5.This is a boy. H name is Bruce.6.Your telephone n is 422-2785.7.There are s days in a week.8.You can know the time by your watch or c .9.Eleven g students are in the classroom. There are no boys. 10.What’s your a?二、根据句意用括号内所给单词的适当形式填空。
1.I’m a singer and _________(I) name’s Dale.2.Is _________(she) book new?3.It’s nice __________(meet) you.4.Let _________(we)learn and read English.5.What’s the __________(boy) name?6.His __________(one) name is Jones.7.Six and eight ___________(be) fourteen.8.In the small village(村子), there are only nine __________(family) now. 9.How are ____________(your)?10.Can you ____________(answer) the question.三、单项选择。
人教版七年级下册数学单元练习题卷:第六章 实数
第六章实数一、填空题1.已知a+2与2a﹣5都是m的平方根,则m的值是 92.1的平方根为_____±1___,立方根为_____1____,算术平方根为_____1____.3.在数轴上,-2对应的点为A,点B与点A的距离为,则点B表示的数为__7- _______.2--或72+4.矩形ABCD的面积是16,它的长与宽的比为4:1,则该矩形的宽为 25.已知一个有理数的平方根和立方根相同,则这个数是______0______.6.有一个数值转换器,原理如图所示:当输入的x为256时,输出的y是__2______.二、选择题7. 下列说法不正确的是( C )A. -是2的平方根B. 是2的平方根C. 2的平方根是D. 2的平方根是±8.下列说法正确的是( C )A.立方根是它本身的数只能是0和1B.立方根与平方根相等的数只能是0和1C.算术平方根是它本身的数只能是0和1D.平方根是它本身的数只能是0和19.下列对实数的说法其中错误的是( C )A.实数与数轴上的点一一对应B.两个无理数的和不一定是无理数C.负数没有平方根也没有立方根D.算术平方根等于它本身的数只有0或110.估算的值在( C )A.1与2之间B.2与3之间C.3与4之间D.5与6之间11. 运算结果是( D )A.B.C.8 D.412.估计的值在( C )A.1和2之间B.2和3之间C.3和4之间D.4和5之间13.一个正数的两个平方根分别是与,则a的值为(B)A. 1B.C. 2D.14. 若5x+19的立方根是4,则2x+7的平方根是( D )A. 25B. -5C. 5D. ±515.实数a在数轴上的位置如图所示,则+化简后为(A )A.7B.﹣7C.2a﹣15D.无法确定16.下列说法中:①每个正数都有两个立方根;②平方根是它本身的数有1,0;③立方根是它本身的数有±1,0;④如果一个数的平方根等于它的立方根,那么这个数是1或0;⑤没有平方根的数也没有立方根;⑥算术平方根是它本身的数有1,0.其中正确的有( A )A.2个 B.3个 C.4个 D.5个三、解答题17. 已知a=,b=|-2|,c=,求a2+b-4c的值.【答案】由题意知:a=,b=|-2|=2,c=,将其代入a2+b-4c,得:原式=()2+2-4×=3+2-2=3.18.计算:(1) .解:=-=4-4=0.(2)3(x-2)3=24【答案】x=419.【答案】 2.20.已知5a+2的立方根是3,3a+b-1的算术平方根是4,c是的整数部分,求3a-b+c的平方根.解:∵5a+2的立方根是3, 3a+b-1的算术平方根是4,∴5a+2=27, 3a+b-1=16---∴a=5,b=2--∵c是的整数部分∴c=3-∴3a-b+c=163a-b+c的平方根是±4;21.现有一个体积为125cm3的木块,将它锯成同样大小的8块小正方体,求每个小正方体木块的表面积.=cm,6×()2=37.5cm2.22.下列实数-7.5,15,4,3-27,-π,813中,有a个整数,b个无理数,求a-b的平方根和立方根.解:由题意得a-3,b=2.∴a-b=1.∴±a-b=±1=±1,3a-b=31=1.即a-b的平方根为±1,立方根为1.23.小明买了一箱苹果,装苹果的纸箱的尺寸为2×3×9(长度单位为分米),现小明要将这箱苹果分装在两个大小一样的正方体纸箱内,要求两个纸箱都装满,且恰好把苹果分完. 问这两个正方体纸箱的棱长为多少分米?设这两个正方体纸箱的棱长为x分米,根据题意得,所以,所以.因此,这两个正方体纸箱的棱长为3分米.24.如图,实数、在数轴上的位置,化简.解:由图可知: ,,∴.∴原式===.。
初一下第六章《整式的乘除》单元习题归类
《整式的乘除》单元习题归类冶基中学王大勇Ⅱ、知识点归纳与典型例题分析一、幂的运算性质(一)同底数幂的乘法公式:a m·a n=a m +n同底数幂的乘法公式推广:a m·a n·a p=a m +n+p应用举例:(x+y ) 3m·(x+y) 2n·(x+y) n= (x+y) 3m+3n典型例题分析1.(x-y) 2·(y-x) 3·(x-y)= __________答案提示:-(y-x)6或-(x-y)62.已知4x=8,4y=2,求x+y的值答案提示:∵4x×4y=8×2∴4x+y=16∴4x+y=42∴x+y=23.已知2a=5,2b=10,2c=50,那么a、b、c之间满足的等量关系是___________. 答案提示:∵2a=5,2b=10,∴2a×2b=2a+b=5×10=50,∵2c=50,∴2a+b =2c∴a+b=c.故答案为:a+b=c.4.若2×3×9m=2×311,则m=_____________答案提示:∵9m=32m,∴2×3×9m=2×3×32m =2×32m+1=2×311,∴2m+1=11,解得m=5.5。
已知:3×9m×27m=321,求m的值。
答案提示:∵3×9m×27m =3×32m×33 m=35m+1=321,∴5m+1=21,解得:m=4.故答案为:4.6.若a,b都为正整数,且2a×2b=23,求a,b的值答案提示:∵2a×2b=23∴2a+b=23∴a+b=3∵a,b都为正整数,∴a,b 的值分别为1,2或2,1.7.当为偶数时,(a-b)m·(b-a)n与(a-b)m +n的关系是()A.相等B.不相等C.互为相反数D.以上说法都不对答案提示:当n也为偶数时相等;当n为奇数时互为相反数故选D.以上说法都不对对应巩固练习:1.如果82a+3×8b-2=810,求2a+b的值2.若642×83=2n,则n= 。
七年级最新英语单元测试题初一英语章节练习题带图文答案解析全部100篇全国统一英语下学期期中试卷
初一英语下学期期中试卷(答题时间:70分钟满分:100分)Ⅰ. 单项选择(每小题1分,共15分)()1. My mother is a nurse and is good _______ kids.A. inB. forC. withD. at()2. My teacher helps us _______ swimming.A. onB. inC. forD. with()3. It’s an English class. Please don’t _________ Chinese.A. sayB. talkC. tellD. speak()4. Jie Min usually gets up _______.A. at six thirtyB. at thirty sixC. on six thirtyD. on thirty six()5. It’s ten o’clock. I must go ____.A. to homeB. homeC. my homeD. his home()6. —______ is it from your home to school?—Three miles.A. How farB. How muchC. How soonD. How long()7. Don’t forget________ me this evening.A. to callB. callC. callsD. calling()8. Lily and Amy often leave _____ school _____ half past seven.A. from; toB. for; inC. to; fromD. for; at()9. I have ______ rules in my home. We have ______homework to do today.A. too many; too muchB. too much; many tooC. too many; much tooD. much too; many too()10. It takes us about a week ________ the work.A. to doB. doC. doingD. for doing()11. It’s raining all day, so I ______ stay at home.A. mustB. have toC. must toD. can()12. “No______!” says the sign.A. smokeB. smokingC. smokesD. to smoke()13.Tigers are i n great ______, though they’re ______.A. danger; dangerB. dangerous; dangerousC. danger; dangerousD. dangerous; danger()14. —What _____ he _____ now?—He _____ a book.A. is; doing; watchingB. does; do; are readingC. is; doing; is readingD. do; doing; reading()15. He has four children. One lives in Nanjing, _____ live in Beijing.A. otherB. the otherC. othersD. the othersⅡ. 完形填空(每小题1分,共10分)Peter is a waiter. He 1 in a restaurant. He is very busy, so he gets 2 very late every night. He doesn’t stay at home 3 the day. Peter has a parrot(鹦鹉)at home. Its nameis Dora. It is a beautiful 4 . Every morning Peter likes to 5 to it after he gets up.“Good morning, Dora!” Peter says.“Good morning, Peter!” Dora says.6 the parrot flies in the room, Peter often says, “What are you doing?” The parrot is7 . It can say “What are you doing?” too.One day, Peter isn’t at home. He is at work. A 8 comes into his house. He sees a 9 on the table. He thinks it must be expensive. So he takes it. When he is going, the parrot says, “What are you doing?” The thief is very10 . There is a man in the house! He drops it and runs away.()1. A. sleeps B. learns C. works D. walks()2. A. school B. home C. office D. station()3. A. on B. in C. with D. at()4. A. bird B. girl C. toy D. boy()5. A. tell B. speak C. wash D. play()6. A. When B. Before C. After D. Because()7. A. small B. shy C. clever D. quiet()8. A. worker B. thief C. reporter D. doctor()9. A. bike B. notebook C. computer D. magazine()10. A. dangerous B. excited C. ugly D. afraidⅢ. 阅读理解(每小题2分,共30分)APeople travel to work in different ways. Some people go to work on foot because they live near their work places. Some people go to work by bike because they live farther away, or they like riding bikes. They think it’s good for their health. Today more people have private(私人的)cars, so they can go to work in their cars. In the south of China, many people even go to work by boat because water is around their houses. Will people go to work by plane? I think so, if necessary(如果必要的话).根据短文内容,判断下面各题的正(T)误(F)。
广东2023-2024第二学期学年人教版七年级下册Unit6达标训练(含答案)
广东2023-2024第二学期学年人教版七年级下册Unit6达标训练S ection A一、单项选择。
( ) 1. Cindy ______TV now.A. is watching B. are watching C. watched D. watch( )2. Look!The students _____their homework.A. is doingB. are doingC. didD. does( ) 3. It's six o'clock in the afternoon. Mr. and Mrs. Green ______ dinner.A. are eatingB. is eatingC. ateD. eats( ) 4. My grandfather often _____newspapers in the afternoon.A. watchesB. seesC. readsD. looks at( ) 5. They ____English.A. are readingB. is readingC. readingD. reads( )6. Tom _____his bed every morning.A. makeB. makingC. makesD. is making( ) 7. My mother _____ cooking for us.A. amB. isC. beD. are( ) 8. Look! Mr. Brown _____you r father.A. talks toB. talking withC. is talking withD. talks with( ) 9. —What is Jenny doing?—She’s _____ something.A. look atB. look likeC. looking forD. looking ( ) 10. Who _____over there now?A. singingB. singC. is singingD. are singing二、根据汉语意思,完成下列句子。
【3套打包】承德市人教版初中数学七年级下册第六章《实数》单元综合练习题(含答案)
人教版七年级下册单元检测卷:第六章 实数一.选择题(共10小题) 1.2的平方根是( )A B .C .D .42.若a 2=4,b 2=9,且ab<0,则a-b 的值为( ) A .-2B .±5C .5D .-53的平方根是则a 的值为( ) A .2B .-2C .5D .-54.下列说法正确的是( ) A .-3是-9的平方根 B .1的立方根是±1 C .a 是2a 的算术平方根 D .4的负的平方根是-25.下列各式中正确的是( )A 3B =xC 3D =-x6.如果-b 是a 的立方根,则下列结论正确的是( ) A .3b -=aB .-b=3aC .b=3aD .3b =a7.小明在作业本上做了4;②=4=9=-6,他做对的题有( ) A .1道B .2道C .3道D .4道8.下列实数是无理数的是( )A .227B .C .πD .09.实数a 、b 在数轴上的对应点的位置如图所示,则正确的结论是( ) A .b>-2B .-b<0C .-a>bD .a>-b10.如图,数轴上的点A,B,C,D,E 对应的数分别为-1,0,1,2,3,那么与实数112-对应的点在( )A .线段AB 上B .线段BC 上C .线段CD 上D .线段DE 上二.填空题(共6小题)11.有一个数值转换器,原理如图:当输入的x=4时,输出的y 等于 .12.如果某数的一个平方根是-5,那么这个数是 . 13.若3a =-8,则a= .14.已知=2,ab<0,的值为 .15.现在规定一种新运算:对于任意实数对(a,b),满足a ※b=a 2-b-5,若45※m=1,则m= .16.实数a 、b 在数轴上的位置如图所示,则化简|a+2b|-|a-b|的结果为 .三.解答题(共7小题)17.将-2,12-在数轴上表示,并将原数用“<”连接.1819.已知5a+2的立方根是3,4a+2b+1的平方根是±5,求a-2b 的平方根.20.解下列方程: (1)(x-2)2-25=0(2)x3-1=21521.已知一个正方体的体积是1000cm3,现要在它的8个角上分别截去1个大小相同的小正方体,截去后余下部分的体积是488cm3.(1)截去的每个小正方体的棱长是多少?(2)截完余下部分的表面积是多少?22.阅读完成问题:数轴上,已知点A、B、C.其中,C为线段AB的中点:(1)如图,点A表示的数为-1,点B表示的数为3,则线段AB的长为,C点表示的数为;(2)若点A表示的数为-1,C点表示的数为2,则点B表示的数为;(3)若点A表示的数为t,点B表示的为t+2,则线段AB的长为,若C点表示的数为2,则t=,(4)点A表示的数为1,x点B表示的为2x人教版七年级下册数学第6章实数培优试题一.选择题(共10小题)1.289的平方根是±17的数学表达式是()A=17 B=±17 C.=±17 D.=172则这个数的立方是()A.8 B.64 C.8或-8 D.64或-64 3.一个数的算术平方根是0.01,则这个数是()A.0.1 B.0.01 C.0.001 D.0.0001 4.下列各式中正确的是()A±4 B=-9 C D=3 25.如果-b是a的立方根,则下列结论正确的是()A.3b-=a B.-b=3a C.b=3a D.3b=a 6.已知正方体的体积为64,则这个正方体的棱长为()A.4 B.8 C.D.7.已知一个正数的两个平方根分别为3a-1和-5-a,则这个正数的立方根是()A.-2 B.2 C.3 D.48.在这四个数中,最小的数是()A.-2 B.0 C.1 D9)A.线段AB上B.线段BC上C.线段CD上D.线段DE上10.下列说法正确的是()A,则a>0B.若a与b也互为相反数C2,则a=bD.若a>b>0,b>二.填空题(共6小题)11.已知2x-1的平方根是±3,则5x+2的立方根是.12.若一个数的算术平方根与它的立方根相等,那么这个数是13.如图,某计算机中有、、三个按键,以下是这三个按键的功能.(1):将荧幕显示的数变成它的算术平方根,例如:荧幕显示的数为49时,按下后会变成7.(2):将荧幕显示的数变成它的倒数,例如:荧幕显示的数为25时,按下后会变成0.04.(3):将荧幕显示的数变成它的平方,例如:荧幕显示的数为6时,按下后会变成36.若荧幕显示的数为100时,小刘第一下按,第二下按,第三下按,之后以、、的顺序轮流按,则当他按了第2018下后荧幕显示的数是25x=4,则x的值为.14.对于正实数a,b作新定义:a⊙若215.已知实数a、b都是比2小的数,其中a是整数,b是无理数,请根据要求,分别写出一个a、b的值:a= ,b= .16.如图,长方形内有两个相邻的正方形,面积分别为4和3,那么阴影部分的面积为.三.解答题(共8小题)17.求x的值:(1)(x+1)2=64(2)8x3+27=0.1819.已知a+1的算术平方根是1,-27的立方根是b-12,c-3的平方根是±2,求a+b+c的平方根.20.如图所示的圆柱形容器的容积为81升,它的底面直径是高的2倍.(π取3)(1)这个圆柱形容器的底面直径为多少分米?(2)若这个圆柱形容器的两个底面与侧面都是用铁皮制作的,则制作这个圆柱形容器需要铁皮多少平方分米?(不计损耗)21.对于实数a、b定义运算"#"a#b=ab-a-1.(1)求(-2)#3的值;(2)通过计算比较3#(-2)与(-2)#3的大小关系;(3)若x#(-4)=9,求x的值.22.已知表示a,b两个实数的点在数轴上的位置如图所示,化简|a-b|+|a+b|.23.右图是一个无理数筛选器的工作流程图.(1)当x为16时,y值为(2)是否存在输入有意义的x值后,却始终输不出y值?如果存在,写出所有满足要求的x 值;如果不存在,请说明理由;(3)如果输入x 值后,筛选器的屏幕显示“该操作无法运行”,请你分析输入的x 值可能是什么情况;(4)当输出的y 时,判断输入的x 值是否人教版七年级数学下册第六章实数章末综合测试卷一.选择题(共10小题)1.下列式子,表示4的平方根的是( ) A . 4B .42C .-4D .±42.若a 是无理数,则a 的值可以是( )A .14B .1C .2D .93.已知实数a ,b 在数轴上对应的点如图所示,则下列式子正确的是( ) A .-a<-b B .a+b<0 C .|a|<|b| D .a-b>04.实数3的大小在下列哪两个整数之间,正确的是( ) A .0和1 B .1和2 C .2和3 D .3和45.若一个正方形的面积为7,它的周长介于两个相邻整数之间,这两个相邻整数是( ) A .9,10 B .10,11 C .11,12 D .12,13 6.在-3、0、6、4这四个数中,最大的数是( ) A .-3 B .0 C . 6 D .47.下列说法正确的是( )A .立方根等于它本身的实数只有0和1B .平方根等于它本身的实数是0C .1的算术平方根是±1D .绝对值等于它本身的实数是正数8.已知a ,b 为两个连续整数,且a< 13<b,则a+b 的值为( ) A .9 B .8 C .7 D .6 9.如果一个实数的平方根与它的立方根相等,则这个数是( ) A .0 B .正实数 C .0和1 D .1 10.有下列说法:①实数与数轴上的点一一对应; ②2- 7的相反数是7-2;③在1和3之间的无理数有且只有2, 3,5,7这4个;④2+3x-4x 2是三次三项式; ⑤绝对值等于本身的数是正数; 其中错误的个数为( ) A .1 B .2 C .3 D .4二.填空题(共6小题)11.4的算术平方根是 ,-64的立方根是 .12.若m 为整数,且5<m< 10,则m=13.某个正数的平方根是x 与y,3x-y 的立方根是2,则这个正数是 .14.已知实数a 、b 都是比2小的数,其中a 是整数,b 是无理数,请根据要求,分别写出一个a 、b 的值:a= ,b= . 15.如图,在数轴上点A ,B 表示的数分别是1,- 2,若点B ,C 到点A 的距离相等,则点C所表示的数是 .16.如图,长方形内有两个相邻的正方形,面积分别为4和3,那么阴影部分的面积为 .三.解答题(共7小题)17.求x 的值: (1)2x 2-32=0; (2)(x-1)3=2718.计算:49-| 3-64|+(-3)2- 31252719.已知2的平方等于a,2b-1是27的立方根,± c-2表示3的平方根. (1)求a,b,c 的值;(2)化简关于x 的多项式:|x-a|-2(x+b)-c,其中x <4.20.正数x 的两个平方根分别为3-a 和2a+7. (1)求a 的值;(2)求44-x 这个数的立方根.21.定义新运算:对任意实数a 、b ,都有a △b=a 2-b 2,例如:(3△2)=32-22=5,求(1△2)△4的值.22.如图甲,这是由8个同样大小的立方体组成的魔方,总体积为64cm 3. (1)这个魔方的棱长为cm;(2)图甲中阴影部分是一个正方形ABCD,求这个正方形的边长;(3)把正方形ABCD 放置在数轴上,如图乙所示,使得点A 与数1重合,则D 在数轴上表示的数为.23.有两个大小完全一样的长方形OABC 和EFGH 重合放在一起,边OA 、EF 在数轴上,O 为数轴原点(如图1),长方形OABC 的边长OA 的长为6个坐标单位. (1)数轴上点A 表示的数为.(2)将长方形EFGH 沿数轴所在直线水平移动①若移动后的长方形EFGH 与长方形OABC 重叠部分的面积恰好等于长方形OABC 面积的13,则移动后点F 在数轴上表示的数为.②若出行EFGH 向左水平移动后,D 为线段AF 的中点,求当长方形EFGH 移动距离x 为何值时,D 、E 两点在数轴上表示的数是互为相反数?答案: 1.D 2.C 3.C 4.B 5.B 6.D 7.B 8.C 9.A 10.C 11.2,-4 12.3 13.4 14.1,15.2+ 16.2-3 17. 解:(1)∵2x 2-32=0, ∴2x 2=32, 则x 2=16, 所以x=±4;(2)∵(x-1)3=27, ∴x-1=3, 则x=4. 18.解:原式=23-4+3- 53=-2.19. 解:(1)由题意知a=22=4, 2b-1=3,b=2; c-2=3,c=5; (2)∵x <4, ∴|x-a|-2(x+b )-c =|x-4|-2(x+2)-5 =4-x-2x-4-5 =-3x-5. 20. 解:(1)∵正数x 的两个平方根是3-a 和2a+7, ∴3-a+(2a+7)=0, 解得:a=-10(2)∵a=-10,∴3-a=13,2a+7=-13.∴这个正数的两个平方根是±13,∴这个正数是169.44-x=44-169=-125,-125的立方根是-5.21. 解:(1△2)△4=(12-22)△4=(-3)。
人教版初一七年级英语(下)第六单元Unit6知识点、语法+练习题、测试
Unit 6 I'm watching TV.一、重点单词:mall _______________ pool _______________TV show _______________ cleaning _______________ reading _______________ shopping _______________ swimming _______________playing _______________watching TV _______________ doing homework _______________ eating dinner _______________ talking on the phone _______________二、重点短语:_______________ 看电视read a newspaper _______________ ___________________ 通过电话交谈_______________ 听音乐use the computer _______________ make soup_______________wash the dishes ______________________________ 有点儿go to the movies _______________ eat out _______________ host family _______________any other ______________________________ 做晚饭_______________ 喝茶swim in a pool _______________ live with sb. in ... _______________ make zongzi _______________a picture of ______________________________ 访谈节目watch…on TV _______________三、核心句型:1. —Why are you doing?—I’m watching TV.2. —What’s she doing?—She’s washing her clothes.3. —What are they doing?—They’re listening to a CD.4. —Are you doing your homework?—Yes, I am. / No, I’m not. I’m cleaning my room.5. Zhu Hui misses his family and wishes to have his mom’s delicious zongzi.四、重点语法:现在进行时:①定义:现在进行时态主要用于表示现在正在进行的动作,有时也可表示现阶段正在进行的动作。
人教版七年级英语下册UNIT 6 达标检测卷含答案
人教版七年级英语下册UNIT 6 达标检测卷第一部分听力(四大题,20分)一、短对话理解(共5小题;每小题1分,满分5分)()1. What's Rick doing now?()2. Where are the boy and the girl going after school?()3. What does the boy think of the movie?A. Relaxing.B. Interesting.C. Exciting.()4. Who is studying in the United States?A. Helen.B. Jack.C. Lisa.()5. When does Eric usually wash his clothes?A. On Saturday morning.B. On Saturday afternoon.C. On Sunday morning.二、长对话理解(共5小题;每小题1分,满分5分)听下面一段对话,回答第6、7小题。
()6. Who does Frank want to visit?A. His teachers.B. His friends.C. His grandparents.()7. What's Frank's favorite subject?A. Chinese.B. English.C. Math.听下面一段对话,回答第8至10小题。
()8. What is Clark doing?A. Watching TV.B. Exercising.C. Washing his clothes.()9. What does Clark ask Kate to do?A. Go shopping.B. Go out for dinner.C. Meet his friend.()10. What time will Clark and Kate meet?A. At 5: 30.B. At 6: 20.C. At 6: 30.三、短文理解(共5小题;每小题1分,满分5分)()11. How does Jane go to the park?A. By bus.B. By subway.C. By bike.()12. Where are two old people playing chess?A. Under a tree.B. By the river.C. On the bridge.()13. What are the five girls doing?A. Swimming.B. Playing games.C. Listening to music.()14. How many boys are playing basketball?A. Eight.B. Nine.C. Ten.()15. Who is drawing a picture?A. Kate.B. Lily.C. Jane.四、信息转换(共5小题;每小题1分,满分5分)第二部分语言知识运用(三大题,35分) 五、单项填空(共10小题;每小题1分,满分10分)()21. —Eric, is your penfriend ____ American girl?—Yes. She is from New York, ____ USA.A. an; 不填B. an; theC. a; 不填D. a; the()22. —How many ____ does Mrs Green have?—Four. Two daughters and two sons.A. childrenB. womenC. studentsD. musicians()23. My shoes are dirty. Can you help me to ____ them, Mom?A. sellB. findC. wearD. wash()24. —People like the hamburgers in the food store.—Yeah! They're very ____.A. difficultB. deliciousC. beautifulD. terrible()25. It's 11: 00 pm. Steve Brown is ____ doing his homework.A. justB. oftenC. stillD. then()26. —What is your uncle doing there?—He is talking ____ the phone.A. onB. inC. ofD. to()27. My aunt often ____ on Saturday. Now she ____ in the store.A. shops; shopsB. is shopping; is shoppingC. is shopping; shopsD. shops; is shopping()28. Lisa has ____ pictures of pandas, but she doesn't have ____ pictures of tigers.A. any; someB. some; anyC. some; someD. any; any()29. —Let's ____ to celebrate the New Year.—OK. I know a new restaurant.A. come trueB. get lostC. eat outD. get dressed()30. —What are you doing now?—________. I'm just listening to music.A. Not muchB. Good luckC. Come onD. Excuse me六、完形填空(共20小题;每小题1分,满分20分)AI have a happy family. There are __31__ people in myfamily—my parents and I. My father is a bank clerk(银行职员),and he works in a bank. He thinks it's a boring __32__. He wants tobe a police officer. My mother is a teacher. She __33__ English in amiddle school. She thinks her job is very interesting. She works hard and often comes back home very late, so my father and I often __34__ the dishes. In her free(空闲的) time, she enjoys(喜欢) __35__ newspapers. I study at a middle school. I like __36__. I want to be a singer. I wish my dream would __37__ one day.Now we're at home. My father is __38__ TV on the sofa. My mother is in the kitchen. What am I doing? I am making a card __39__ my cousin in my bedroom. Next Sunday is his birthday. I wish to give a beautiful gift(礼物) to him. I have a cat in my home. Her name is Mimi. Where is she? Oh! She is __40__ milk in her room. Howhappy she looks!()31. A. five B. twoC. threeD. four()32. A. work B. jobC. studyD. host()33. A. does B. wantsC. studiesD. teaches()34. A. wash B. brushC. sweepD. keep()35. A. see B. seeingC. readingD. read()36. A. dancing B. singingC. writingD. studying()37. A. come on B. go outC. come trueD. get lost()38. A. watches B. watchingC. watchD. to watch()39. A. by B. withC. toD. for()40. A. drinking B. usingC. shoppingD. eatingBIt's ten o'clock now. What is Tom doing? Oh, he is __41__ a model plane with his friend Jack in his bedroom. Tom is good at it. When they __42__ it, Jack asks, “Can you give it to me?” Tom says, “No. ”But Jack wants the model plane very much. After some minutes, they begin to __43__. Mr White comes to the __44__ and asks, “Why are you fighting?”“Jack __45__ my model plane, but I don't want to give it to him. It's __46__,” says Tom.“Uncle Tony, Tom's model plane looks so __47__. I really like it,” Jack says.“Ah, I see. But Jack, that model plane is Tom's and he also __48__ it,” Mr White says. “Ah, I have an idea! But please wait a minute. ”“Tom, come to the ‘QUIET ROOM’ with me,” says Mr White. “Tom, you can protect your things, but I don't think it is a good idea to fight with your friend. You should learn to share. ”“Daddy, you are __49__. I will say sorry to Jack,” Tom says. “And Jack doe sn't do well in making model planes. I __50__ I can teach him. ”“That's my boy,” says Mr White.()41. A. looking B. makingC. playingD. selling()42. A. show B. watchC. knowD. finish()43. A. sleep B. crossC. fightD. spell()44. A. pool B. roomC. hallD. kitchen()45. A. wants B. knowsC. meetsD. tells()46. A. yours B. hersC. mineD. his()47. A. small B. longC. oldD. nice()48. A. sings B. readsC. likesD. takes()49. A. late B. rightC. easyD. cute()50. A. think B. forgetC. studyD. leave七、补全对话(有两项多余)(共5小题;每小题1分,满分5分)A: Excuse me, madam. 51. ________B: Yes, little boy. What's up?A: 52. ________B: Oh, I'm sorry to hear that but don't worry!I can help you find them. A: Thank you.B: 53. ________A: Well, my father is wearing a blue sweater.B: Is there a hat on his head?A: Yes,there is. 54. ________B: What about your mother?A: She is wearing a red sweater and blue trousers.B: Now I know where they are. They are in the reading room. 55. ________ A: OK.第三部分阅读(共两节,40分)八、阅读理解(共20小题;每小题2分,满分40分)第一节:Aloves animals.The Brown family: Jeremy is a tidy boy and often helps with housework onweekends. He is cleaning the house now. His parents are washing clothes in the bathroom(浴室).The Black family: Peter is doing his homework in his bedroom. His father isreading a book to his brother Dave in the living room. His mother is there, too.The Green family: Julie loves cooking. Her mother is teaching her how tocook in the kitchen. Her brother Steve is reading newspapers with their fatherin the living room.()56. Why is Lucy very happy most probably?A. Because she can get up late.B. Because she can see animals.C. Because she can learn to cook.D. Because she can watch TV at home.()57. Where is Julie now?()58. Which is TRUE?A. Jeremy usually cleans his room on Friday.B. There are four people in the Brown family.C. Steve has a sister and her name is Lucy.D. Two people in the Green family are reading newspapers.BThere are five people in Mr. Li's family. Mr Li is a teacher. He always drives the car to work. But now a doctor is talking to him. He doesn't feel well. Mrs. Li is sittingon the bed. She is watching TV. She is a nurse. Mr. and Mrs. Li have two sons and one daughter. Li Gang is in his bedroom. He is writing a letter. Li Wei is at the desk. He is doing his homework. Li Gang and Li Wei are the students in No. 7 Middle School. They like playing football. Li Yan is their sister. She is only four.What is Li Yan doing? Oh, she is playing with her cat.()59. How many people are there in Mr. Li's family?A. Four.B. Five.C. Six.D. Seven.()60. Who is probably (可能) Li Wei's father?()61. Which of the following is NOT true?A. Mrs. Li is watching TV.B. Li Yan is doing homework.C. Li Gang is writing a letter.D. Li Wei likes playing football.()62. What's Li Yan doing?A. She's playing with her toy.B. She's playing with her ball.C. She's playing with her cat.D. She is playing football.CIt's ten in the morning. Mrs. Brown and her children are in the zoo. Look! They arelooking at the monkeys. The monkeys are on a small man-made (人造的)hill. The monkeys are climbing up and down the hill. But one monkey is sleeping. It is ill. It needs to see a doctor.Where are the children now? The children are standing next to a small cage. What's in the small cage? There is a fox. What is the fox doing? The fox is walking in the cage. It's looking for something to eat. It wants to go out of the cage to play and walk.After they see the lovely pandas, giraffes, elephants, tigers. . . the children come to see the wolf. Is the wolf sleeping? No, it isn't. The wolf is eating. What is the wolf eating? It is eating meat. There is a bone(骨头) in its mouth.They have a good time in the zoo. It's time for them to go home. The children wish they could come again.()63. What does the underlined word “ill” mean?A. 生病的B. 恐惧的C. 懒惰的D. 贪玩的()64. The last animal that the children see is ____.A. the monkeyB. the foxC. the wolfD. the elephant()65. Which is the best title for the passage?A. One Day in the ZooB. We Love AnimalsC. What Is Your Favorite AnimalD. Animals Are Our Best FriendsDThis is Mrs. White. Now she is teaching math. She works in a middle school. She lives in London. Mrs. White and Mr. White have three children. They all love animals and they have a big dog and a cute cat.Mrs. White is Sophie's aunt. Sophie lives and studies in Liverpool, but now she is in London. She is on her holiday here. She wants to do some shopping with her aunt.Mrs. White's son Arnold doesn't like shopping, but he loves going out with friends.He usually goes to a park to play soccer or basketball in the afternoon. Today, Arnold isn't playing soccer or basketball. He is swimming now.Mr. White works for a company (公司). He isn't working today, because he isn't feeling well. He is in a hospital now.()66. Mrs. White is a ____.A. farmerB. teacherC. doctorD. musician()67. What is Arnold doing now?A. Running.B. Swimming.C. Playing soccer.D. Playing basketball.()68. Where is Mr. White now?A. In a school.B. In a supermarket.C. In a store.D. In a hospital.()69. What can we know about the Whites?A. They have some pets.B. They live in Liverpool.C. They like going out on weekends.D. There are four people in the family.EMr. Green is sixty-five years old. He stays(待) at home and he doesn't work. These days he always stays with his cute bird, Jill. He's teaching Jill to speak,“Hell o,what are you doing now?”Jill is very clever and she can speak it very well. When she sees some people, she asks,“ Hello, what are you doing now?”Today is Sunday. In the evening,Mr. Green goes to the movies with his familyafter dinner. Jill is at home. A thief(贼) sees that Mr. Green's home is dark and he goes into it. He wants to steal some things in Mr. Green's home.“Hello,what are you doing now?”Jill sees the thief and says to him.“What? Is there anyone in his home?I must leave,” the thief thinks.The thief is very afraid, so he runs out of Mr. Green's home quickly.()70. What can we know about Jill?A. She's fat.B. She's fine.C. She's smart.D. She's lazy.()71. Which of the following can Jill speak?A. Hello.B. Sorry.C. Thanks.D. Goodbye.()72. The underlined word“steal”means “____”in Chinese.A. 藏B. 抢C. 用D. 偷第二节:阅读下面的短文,并用英语回答问题(请注意每小题的词数要求)。
2020-2021初一数学有理数及其运算单元综合练习题(附答案)
2020-2021初一数学有理数及其运算单元综合训练题(附答案) 一、单选题 1.计算2–(–3)×4的结果是( )A .10B .–20C .–10D .14 2.计算216()22÷-⨯的结果是( )A .-12B .-48C .48D .12 3.计算-113÷(-3)×(-13)的值为( ) A .-113 B .113C .-427D .427 4.定义一种新的运算:a •b =2a b a +,如2•1=2212+⨯=2,则(2•3)•1=( ) A .52B .32C .94D .1985.字母a 、b 、c 分别表示一个有理数,它们在数轴上的位置如图所示,则下列结论正确的是( )A .0a b +>B .0c a -<C .0bc >D .a b -> 6.使得算式()()24123311⎡⎤-⨯--⎣⎦的值最大,则“□”里应填入的运算符号为( ) A .+ B .- C .⨯ D .÷7.如图所示,是一个数值转换机,当输入3-时,输出的结果是( )A .1-B .1C .3-D .3二、解答题8.把下列各数分别填入相应的集合里:3--,1.525525552,0,34⎛⎫-- ⎪⎝⎭,3.14,()6--,3π- (1)负数集合:{ };(2)非负整数集合:{ };(3)无理数集合:{}. 9.计算:(1)2125824(3)3-+-+÷-⨯;(2)20171313[2()24]5(1)2864-+-⨯÷⨯-. 10.计算:(1)2304124()(2)3-⨯+---; (2)422311(1){[()0.4(1)](2)}532---+⨯-÷-.11.已知a ,b 互为相反数,c ,d 互为倒数,m 的绝对值等于3,求m 2+(cd +a +b )×m +(cd )2018的值.12.对于四个数“6-,2-,1,4”及四种运算“+,-,⨯,÷”,列算式回答: (1)求这四个数的和;(2)在这四个数中选出两个数,填入下列□中,使得: ①“□-□”的结果最小; ②“□⨯□”的结果最大;(3)在这四个数中选出三个数,组成一个算式,使运算结果等于没选的那个数.请写出这个算式.13.某商贩每日要到小龙虾基地购进500千克小龙虾,下表是该商贩记录的本周小龙虾购进价格(单位:元)浮动情况:注:正号表示价格比前一天上涨,负号表示价格比前一天下降.已知小龙虾上周末的进价为每千克23元,这周四的进价为每千克24元.(1)m =______.(2)这周购进小龙虾的最高价是每千克多少元?最低价是每千克多少元?(3)若该商贩周五将购进的小龙虾以每千克25元全部售出,且出售时小龙虾有4%的损耗,那么该商贩在本周星期五的收益情况如何?14.观察下列三组数: 第一组:1-,4-,9-,16-,25-,…;第二组:1,8,27,64,125,…;第三组:2-,16-,54-,128-,250-,….(1)分别写出三组数中的第7个数.(直接写结果)(2)取每组数的第10个数,计算这三个数的和.(列式计算)15.已知a 的相反数是5,9b =,且0a b +<,求2a b +的值.16.已知下列等式:1×12 =1- 12;1123⨯= 1231-;1134⨯ =1341-;1145⨯ =1145-. (1)按照这个规律,请你写出第5个等式;(2)按照这个规律,请你写出第n 个等式;(3)计算:111145566778+++⨯⨯⨯⨯. 17.如图,数a ,b ,c 对应的点在数轴上,且|a |=|b |.(1)a +b ________0,c -b ________0,a -c ________0;(2)|a |=2,|c |=4,求a -b +(-c )的值;(3)化简:|a -c |-|c -b |.18.己知5a =,3b =,且a b a b +=+,求a b -的值.19.某出租车驾驶员从公司出发,在南北向的人民路上连续接送5批客人,行驶路程记录如下(规定向南为正,向北为负,单位:km ):第1批第2批 第3批 第4批 第5批 5km 2km ﹣4km ﹣3km 10km(1)接送完第5批客人后,该驾驶员在公司什么方向,距离公司多少千米?(2)若该出租车每千米耗油0.2升,那么在这过程中共耗油多少升?(3)若该出租车的计价标准为:行驶路程不超过3km 收费10元,超过3km 的部分按每千米加1.8元收费,在这过程中该驾驶员共收到车费多少元?20.某校想要为参加校园艺术节演出的72名同学每人购买一套服装,负责采购的老师现有A 、B 两家服装厂备选,两厂每套服装出货价都是100元,但A 厂的优惠是:每套服装打9折;B 厂给出的优惠是:前50套不优惠,超出的部分打8折;已知参加演出的男生数量比女生的2倍少18人.(1)参加演出的男生有多少人?(2)如果您是采购老师,从省钱的角度,会选择哪个厂家购买?请说明理由.(3)购买服装后,厂里指派甲、乙两车间用1天时间,完成为每件上衣刺绣出校方指定图案的任务,假设两车间的工人原计划每人每天刺绣件数相同,而最终甲车间加工总件数比计划每人每天加工件数的4倍多2套,乙车间加工总件数比计划每人每天加工件数的5倍少11套,若甲车间人数比乙车间人数的一半还少1人,那么该厂乙车间一共有几名工人?21.体育课上全班女生进行了百米测验,达标成绩为18秒,第一小组8名女生的测试成绩记录如下表:其中“+”表示成绩大于18秒,“-”表示成绩小于18秒,“0”表示刚好达标.(1)这个小组女生最快的成绩是______秒,最慢的成绩与最快的成绩相差______秒; (2)求这个小组8名女生百米测试的平均成绩.22.有一种“24”点游戏,其游戏规则是:任取一副扑克牌,我们约定A 为1,J 、Q 、K 分别为11、12、13,并规定方块、红桃牌为正,黑桃、梅花牌为负.任取4张牌,将这4张牌的牌面所表示的数进行加、减、乘、除运算(使用括号).每个数用且只用一次,使其结果等于24.如:抽出4张牌黑桃4、梅花2、方块4、红桃3,可做运算:(4)(2)4324-÷-⨯⨯=.(1)若抽出黑桃3,梅花1,方块5,红桃3,请写出1种算式,并写出计算过程,验证结果为24.(2)若抽出黑桃3、梅花K 、方块8、红桃Q ,请写出2种不同的算式,并写出计算过程,验证结果为24(3)若抽出黑桃4、梅花7、方块2、红桃3,请设计1种含“乘方”的混合运算的算式,并写出计算过程,验证结果为24.23.请观察下列算式,找出规律并填空.111122=-⨯,1112323=-⨯,1113434=-⨯,1114545=-⨯. 则第10个算式是________,第n 个算式是________.根据以上规律解读以下两题:(1)求111112233420192020++++⨯⨯⨯⨯的值; (2)若有理数a ,b 满足|2||4|0a b -+-=,试求:1111(2)(2)(4)(4)(2016)(2016)ab a b a b a b ++++++++++的值.三、填空题 24.若|2||4|0a b ++-=,则a b -=______.25.将数4.5983按精确到百分位取近似值,所得的结果是__________.26.用四舍五入法把5.3476精确到百分位,取得的近似数是______.27.计算()2021202011-+-的值是______.28.在数学小组探究活动中,小月请同学想一个数,然后将这个数按以下步骤操作:小月就能说出同学最初想的那个数,如果小红想了一个数,并告诉小月操作后的结果是6,那么小红所想的数是______.29.根据如图的程序,计算当输入4x =时,输出的结果y =______.参考答案1.D【解析】【分析】原式先计算乘法运算,再计算加减运算即可得到结果.【详解】解:原式=2+12=14,故选D .【点睛】此题考查了有理数的混合运算,熟练掌握运算法则是解题关键.2.C【解析】 原式162642484=÷⨯=⨯⨯=.故选C . 3.C【解析】-113÷(-3)×(-13)=411433327-⨯⨯=-,选C. 4.B【解析】【分析】 根据2a b a b a +⋅=,可以求得所求式子的值,本题得以解决. 【详解】 解:∵2a b a b a+⋅=, ∴(2•3)•1 2232+⨯=•1 =4•14421+⨯= 32=, 故选B .【点睛】本题考查有理数的混合运算,解答本题的关键是明确有理数混合运算的计算方法. 5.D【解析】【分析】根据数轴可得a <c <0,b >0,|a|>|b|>|c|,据此可逐项进行判断即可得到答案.【详解】解:根据数轴可得a <c <0,b >0,|a|>|b|>|c|,∴a+b <0,故选项A 错误;c-a >0,故选项B 错误;bc <0,故选项C 错误;a b ->,正确,故选:D .【点睛】本题考查的是数轴的特点,熟知“数轴上数轴右边的数总比左边的数大”是解答此题的关键. 6.D【解析】【分析】将各项的运算符号填入,先分别根据有理数的乘方、加减乘除运算求出结果,再比较大小即可得.【详解】A 、()()24123311⎡⎤-+⨯--⎣⎦, ()1163911=-+⨯-, 61611=--, 61611=-; B 、()()24123311⎡⎤--⨯--⎣⎦, ()1163911=--⨯-,61611=-+, 51511=-; C 、()()24123311⎡⎤-⨯⨯--⎣⎦, ()1163911=-⨯⨯-, ()116611=-⨯⨯-, 9611=; D 、()()24123311⎡⎤-÷⨯--⎣⎦, ()1163911=-÷⨯-, ()16116=-⨯⨯-,1056=; 因为659616151056111111-<-<<, 所以应填入的运算符号为÷, 故选:D .【点睛】本题考查了含乘方的有理数混合运算、有理数的大小比较法则,熟练掌握有理数的运算法则是解题关键.7.B【解析】【分析】按照转换机的要求列式:()()()3331-+-÷--⎡⎤⎣⎦,再按照有理数的混合运算的运算法则与运算顺序进行计算即可得到答案.【详解】解:由题意得:()()()()()333163121 1.-+-÷--=-÷--=-=⎡⎤⎣⎦故选B .【点睛】本题考查的是列式计算,掌握有理数的混合运算的法则与顺序是解题的关键.8.(1)|3|,3π---;(2)()0,6--;(3)1.525525552,3π-. 【解析】【分析】(1)由实数可分为:正实数,0,负实数,从而可得答案; (2)由非负整数分为正整数与0,从而可得答案; (3)由无理数的定义:无限不循环小数,从而可得答案.【详解】解:(1)负数集合:|3|,3π⎧⎫---⎨⎬⎩⎭; (2)非负整数集合:(){}0,6--; (3)无理数集合: 1.525525552,3π⎧⎫-⎨⎬⎩⎭ 故答案为:|3|,3π---;()0,6--;1.525525552,3π-.【点睛】 本题考查的是实数的分类,无理数的定义,掌握按不同的分类依据将实数分类是解题的关键. 9.(1)−113(2)−32 【解析】(1)()212582433-+-+÷-⨯ =−4+3+(−8)×13=−1−83=−113. (2)()20171313224512864⎡⎤⎛⎫-+-⨯÷⨯- ⎪⎢⎥⎝⎭⎣⎦()131312242424128645⎡⎤=-⨯-⨯+⨯⨯⨯-⎢⎥⎣⎦()519418125⎡⎤=--+⨯⨯-⎢⎥⎣⎦ ()515125⎡⎤=+⨯⨯-⎢⎥⎣⎦ ()51151255⎡⎤=⨯+⨯⨯-⎢⎥⎣⎦ ()1112⎡⎤=+⨯-⎢⎥⎣⎦=32×(−1) =−32. 10.(1)1;(2)518. 【解析】【分析】(1)结合负整数指数幂、零指数幂的概念进行求解即可(2)先算乘方,再算乘除,最后算加减,有括号,要先做括号内的运算.【详解】(1)2304124()(2)3-⨯+--- =3141164⨯+- 24116=+-16116=+-1=.(2)422311(1){[()0.4(1)](2)}532---+⨯-÷- 3121{[()]4}59523=--+⨯-÷ 31311[()]5954=---⨯3221=-+⨯1()54545411=1()-+9090651=-90131=-185=.18【点睛】此题考查有理数的混合运算,解题关键在于掌握负整数指数幂,零指数幂的运算法则11.7或13.【解析】【分析】首先根据a、b互为相反数,可得a+b=0;再根据c、d互为倒数,可得cd=1;再根据m是绝对值等于3的负数,可得m=-3;然后应用代入法,求出m2+(cd+a+b)×m+(cd)2018的值是多少即可.【详解】∵a,b互为相反数,c,d互为倒数,m的绝对值等于3,∴a+b=0,cd=1,|m|=3,当m=–3时,m2+(cd+a+b)×m+(cd)2018=(–3)2+(1+0)×(–3)+12018=9+1×(–3)+1=9+(–3)+1=7;当m=3时,∴m2+(cd+a+b)×m+(cd)2018=13.【点睛】此题考查代数式求值,掌握运算法则是解题关键12.(1)3-;(2)①6-,4;②6-,2-;(3)[](2)(6)14---÷=(答案不唯一)【解析】【分析】(1)求这四个数的和,需要列式并计算即可,(2)两个数 “□−−□”的结果最小,使减数选最大数,被减数取最小数;两个数 “□×□”的结果最大,要求两数为同号,在同号中取绝对值较大的两数即可,(3)四个数中选出三个数剩一,组成一个等式,三数运算的结果为剩下的数,选取-6,-2,1结果为4,由于1比较特殊,用乘除法不影响运算,只要-6,与-2用减法即可得到4即可.【详解】(1)-6+(-2)+1+4=-8+5=-3,(2)-6<-2<1<4, ①“(-6)−4的结果最小, ②“(-6)×(-2)”的结果最大, (3)选取-6,-2,1计算结果为4,算式为:[(-2)-(-6)]÷1,等式为:[(-2)-(-6)]÷1=4. 【点睛】本题考查有理数的限定运算,关键掌握大小比较,求和运算,差最小,积最大,三数运算结果为第四个数等知识.13.(1)1.5;(2)25,21;(3)1500.【解析】【分析】通过题意和图中的表格,可以计算出每天小龙虾的进价,即可求出m 和本周内购进小龙虾的最高价和最低价,也可算出周五购进的小龙虾的价格,根据题意列出关系式即可算出最终收益情况.【详解】(1)由题意可知:星期一的小龙虾每千克进价为:23122-=(元); 星期二的小龙虾每千克进价为:22 2.524.5+=(元); 星期三的小龙虾每千克进价为:24.5222.5-=(元);星期四的小龙虾每千克进价为:24元;星期五的小龙虾每千克进价为:24321-=(元); 星期六的小龙虾每千克进价为:21223+=(元);星期日的小龙虾每千克进价为:23225+=(元),22.524m +=解得: 1.5m =.故答案为:1.5.(2)由(1)可知:212222.5232424.525<<<<<<,这周购进小龙虾的最高价是每千克25元;最低价是每千克21元;(3)由(1)可知:星期五的小龙虾每千克进价为21元,()50014%255002112000105001500⨯-⨯-⨯=-=(元)答:该商贩在本周星期五的收益情况是赚钱1500元.【点睛】本题考查了正数和负数,解题的关键是根据题意列出关系式.14.(1)49-,343,686-;(2)1100.-【解析】【分析】(1)第一组的数是正整数的平方的相反数,第二组的数是正整数的立方,第三组的数是第二组数的2倍的相反数,从而可得每组的第7个数;(2)由(1)中的规律分别写出第10个数,再把它们相加即可得到答案.【详解】解:(1)第一组的数可依次记为:222221,2,3,4,5,-----所以第7个数为:2749,-=-第二组的数可依次记为:333331,2,34,5,, 所以第7个数为:37343,=第三组的数可依次记为:3333321,22,23,24,25,-⨯-⨯-⨯-⨯-⨯所以第7个数为:327686,-⨯=-(2)由(1)得:三组数的第10个数分别为:23310,10,210,--⨯ 所以:233101021010010001100.-+-⨯=--=-【点睛】本题考查的是探究数字的规律,列代数式,有理数的加减运算,有理数的乘方运算,掌握由具体到一般的探究规律的方法是解题的关键.15.-19【解析】【分析】根据相反数的定义、绝对值的意义进行分析计算.【详解】∵ a 的相反数是5,9b =,∴a =-5,b =±9, ∵0a b +<,∴ a =-5,b =-9,当a =-5,b =-9时,2a b +=-19.【点睛】本题考查相反数的定义、绝对值的意义,熟练掌握基础知识是关键.16.(1)11115656⨯=-;(2)111111n n n n ⨯=-++;(3)18【解析】【分析】(1)根据已知等式的规律即可写出结论;(2)根据已知等式的规律即可写出结论;(3)根据(2)的公式变形,然后求和即可.解:(1)第5个等式为:1111 5656⨯=-;(2)第n个等式为:111111 n n n n⨯=-++;(3)原式=11111111 45566778 -+-+-+-=1148 -18=【点睛】此题考查的是有理数的运算,找出运算规律是解决此题的关键.17.(1)=;<;>;(2)8;(3)a-b【解析】【分析】(1)根据数轴可得a>0,c<b<0,从而得出c-b<0,a-c>0,再根据绝对值的性质可得a与b互为相反数,从而求出a+b=0;(2)根据绝对值的定义和相反数的定义即可求出a、b、c,从而求出结论;(3)根据绝对值的性质化简即可.【详解】解:(1)由数轴可知:a>0,c<b<0∴c-b<0,a-c>0∵|a|=|b|∴a与b互为相反数∴a+b=0故答案为:=;<;>;(2)∵|a|=2,|c|=4,a+b=0,∴a=2,c=-4,b=-2,则a-b+(-c)=a-b-c=2+2+4=8;(3)∵a-c>0,c-b<0,∴|a-c|-|c-b|=a-c-[-(c-b)]=a-c-c+b=a-b.此题考查的是利用数轴比较大小、相反数和化简绝对值,掌握利用数轴比较大小、相反数的定义和绝对值的性质是解决此题的关键.18.2或8.【解析】【分析】 由5a =, 3b =可得,5a =±,3b =±,再由a b a b +=+可得,5a =,3b =或5a =,3b =-,代入计算即可.【详解】 ∵5a =,3b =, ∴5a =±,3b =±, ∵a b a b +=+,∴0a b +>,∴5a =,3b =或5a =,3b =-,当5a =,3b =时,2a b -=,当5=,3b =-时,8a b -=.【点睛】本题考查了绝对值,有理数的加减法,此题主要用了分类讨论的方法,各种情况都有考虑,不能遗漏.19.(1)驾驶员在公司的南边10千米处;(2)在这个过程中共耗油4.8升;(3)驾驶员共收到车费68元【解析】【分析】(1)根据有理数加法即可求出答案;(2)根据题意列出算式即可求出答案;(3)根据题意列出算式即可求出答案.【详解】解:(1)5+2+(﹣4)+(﹣3)+10=10(km ),答:接送完第五批客人后,该驾驶员在公司的南边10千米处;(2)(5+2+|﹣4|+|﹣3|+10)×0.2=24×0.2=4.8(升),答:在这个过程中共耗油4.8升;(3)[10+(5﹣3)×1.8]+10+[10+(4﹣3)×1.8]+10+[10+(10﹣3)×1.8]=68(元), 答:在这个过程中该驾驶员共收到车费68元.【点睛】本题考查有理数的加法运算的实际应用,解题的关键是掌握有理数的加法法则,并且能够根据题意列出算式.20.(1)参加演出的男生有42人;(2)选择A 厂家省钱,见解析;(3)乙车间一共有6名工人【解析】【分析】(1)先求出女生人数,进而可求男生人数;(2)分别求出A 、B 两家服装厂需付的钱数,比较即可;(3)设原计划每人每天刺绣件数为a 件,求出a 的值,再求出甲乙两车间的总人数,进而根据甲车间人数比乙车间人数的一半还少1人可求出乙车间的人数.【详解】解:(1)()()27318120÷+=+(人),723042-=(人),答:参加演出的男生有42人.(2) :7210090%6480A ⨯⨯=(元), () :725010080%501006760B -⨯⨯+⨯=(元),64806760<,答:选择A 厂家省钱.(3)设原计划每人每天刺绣件数为a 件,4251172a a ++-=,解得9a =,甲、乙车间共有:8972=÷(人),乙车间有:()181162⎛⎫+÷+= ⎪⎝⎭(人), 答:乙车间一共有6名工人.【点睛】本题考查了有理数混合运算的应用,根据题意正确列出算式是解答本题的关键.21.(1)17.4,1.4;(2)18秒.【解析】【分析】(1)利用成绩记录表中的最小数加上18即可得最快的成绩;利用成绩记录表中最大数减去最小数即可得出答案;(2)先利用平均数公式求出成绩记录表中数据的平均数,再加上18即可得.【详解】(1)这个小组女生最快的成绩是0.61817.4-+=(秒),最慢的成绩与最快的成绩相差0.8(0.6) 1.4--=(秒),故答案为:17.4,1.4;(2)平均成绩为0.60.800.20.30.10.70.518180188-++--++-+=+=(秒), 答:这个小组8名女生百米测试的平均成绩为18秒.【点睛】本题考查了正数和负数在实际生活中的应用、有理数的加减法与除法运算的应用,理解题意,正确列出运算式子是解题关键.22.(1)()()()315324-⨯-⨯+=;(2)()()38131224-⨯⨯-+=;(){}12313824⎡⎤⨯----=⎣⎦;(3)()()324724⎡⎤⨯---=⎣⎦ 【解析】【分析】(1)根据所给的数是-3、-1、5、3,应用有理数混合运算的运算方法,凑成24即可; (2)根据所给的数是-3、-13、8、12,应用有理数混合运算的运算方法,凑成24即可; (3)根据所给的数是-4、-7、2、3,应用有理数混合运算的运算方法,凑成24即可.【详解】(1)()()()31533824-⨯-⨯+=⨯=;(2)()()()38131224124-⨯⨯-+=-⨯-=;(){}()1231381210812224⎡⎤⨯----=⨯-=⨯=⎣⎦;(3)()()32478324⎡⎤⨯---=⨯=⎣⎦. 【点睛】本题考查了有理数的混合运算,熟练掌握运算法则是解本题的关键.23.111=10111011-⨯,()111=11n n n n -++;(1)20192020;(2)10094040 【解析】【分析】归纳总结得到一般性规律,写出第10个等式及第n 个等式即可; (1)原式变形后,计算即可得到结果;(2)利用非负数的性质求出a 与b 的值,代入原式计算即可得到结果.【详解】解:第10个算式是111=10111011-⨯, 第n 个算式是()111=11n n n n -++; (1)1111 (12233420192020)++++⨯⨯⨯⨯ =111111 (22320192020)-+-++- =112020- =20192020; (2)∵|2||4|0a b -+-=,∴a-2=0,b-4=0,∴a=2,b=4, ∴1111(2)(2)(4)(4)(2016)(2016)ab a b a b a b ++++++++++ =111124466820182020++++⨯⨯⨯⨯ =1111111...2244620182020⎛⎫-+-++- ⎪⎝⎭=111222020⎛⎫- ⎪⎝⎭=10094040【点睛】此题考查了有理数的混合运算,熟练掌握运算法则是解本题的关键.24.6-.【解析】【分析】由|2||4|0a b ++-=可得:2040a b +=⎧⎨-=⎩,再求解,a b 的值,从而可得答案. 【详解】解:|2||4|0a b ++-=,2040a b +=⎧∴⎨-=⎩24a b =-⎧∴⎨=⎩ 24 6.a b ∴-=--=-故答案为: 6.-【点睛】本题考查的是两个非负数之和为0的性质,有理数的减法运算,二元一次方程组的解法,掌握非负数的性质是解题的关键.25.4.60【解析】4.5983精确到百分位取近似值,千分位上是8,应该向前一位进1,所以应为4.60, 故答案为4.60.26.5.35【解析】【分析】用四舍五入法可以将5.3476精确到百分位,本题得以解决.解:5.3476≈5.35(精确到百分位),故答案为:5.35.【点睛】本题考查近似数和有效数字,解答本题的关键是明确题意,利用四舍五入法解答. 27.-2【解析】【分析】根据有理数的乘方,可以解答本题.【详解】解:202020211(1)-+-1(1)=-+-2=-,故答案为:-2.【点睛】本题考查了有理数的混合运算,解答本题的关键是明确有理数乘方放入符号规律. 28.4【解析】【分析】根据流程图从后面逆推即可得出结果.【详解】解:()622844-⨯+÷=⎡⎤⎣⎦,故答案为:4【点睛】本题主要考查的是有理数的混合运算,正确的计算出结果是解题的关键.29.1【解析】【分析】根据运算进行的限制条件,选择相应运算程序进行即可.解:∵x=4>1∴y=-4+5=1故答案为:1【点睛】本题考查了有理数的计算,解答关键是根据x取值范围的限定选择相应的计算程序.。
七下英语创新练习2022第六单元第四课时第三大题答案
七下英语创新练习2022第六单元第四课时第三大题答案1、Yesterday I _______ a book.It was very interesting. [单选题] *A. lookedB. read(正确答案)C. watchedD. saw2、Tony can _______ the guitar.Now he _______ the guitar. [单选题] *A. play; plays(正确答案)B. playing; playingC. plays; is playingD. play; is playing3、Mike and his friend are going to the _______ to see the new action movie tonight. [单选题] *A. book shopB. restaurantC. concertD. cinema(正确答案)4、—It’s too noisy outside. I can’t fall asleep.—I can’t, either. We have to ______ new ways to solve the problem.()[单选题] *A. come up with(正确答案)B. get on withC. make up withD. catch up with5、Medicines are to be taken according to the doctor’s advice. [单选题] *A. 发放B. 提取C. 配方D. 服用(正确答案)6、The beautiful sweater _______ me 30 dollars. [单选题] *A. spentB. paidC. cost(正确答案)D. took7、A?pen _______ writing. [单选题] *A. is used toB. used toC. is used for(正确答案)D. used for8、He spoke too fast, and we cannot follow him. [单选题] *A. 追赶B. 听懂(正确答案)C. 抓住D. 模仿9、One effective()of learning a foreign language is to study the language in its cultural context. [单选题] *A. approach(正确答案)B. wayC. mannerD. road10、—Can you play tennis? —______, but I’m good at football.()[单选题] *A. Yes, I can(正确答案)B. Yes, I doC. No, I can’tD. No, I don’t11、I _______ play the game well. [单选题] *A. mustB. can(正确答案)C. wouldD. will12、As for the quality of this model of color TV sets, the ones made in Chine are by no means _____ those imported. [单选题] *A inferior thanB less inferior toC less inferior thanD. inferior to(正确答案)13、Reading()the lines, I dare say that the government are more worried than they admitted. [单选题] *A. behindB. between(正确答案)C. alongD. among14、In winter, animals have a hard time_____anything to eat. [单选题] *A.to findB.finding(正确答案)C.foundD.to finding15、The students in that university are not fewer than()in our university. [单选题] *A. the oneB. thatC. themD. those(正确答案)16、You should stick to your()and tell him you won' t do the thing. [单选题] *A. principle(正确答案)B. qualityC. contactD. influence17、Will you see to()that the flowers are well protected during the rainy season? [单选题] *A. it(正确答案)B. meC. oneD. yourself18、--Why are you late for school today?--I’m sorry. I didn’t catch the early bus and I had to _______ the next one. [单选题] *A. wait for(正确答案)B. ask forC. care forD. stand for19、There are many beautiful _______ in the wardrobe. [单选题] *A. bookB. dresses(正确答案)C. cell phoneD. grocery20、Wang Dong usually gets up at 6:00 _______ he can catch the early school bus. [单选题] *A. as ifB. so that(正确答案)C. untilD. after21、52.I'm happy to ________ a birthday card from an old friend. [单选题] *A.buyB.makeC.loseD.receive(正确答案)22、______ the morning of September 8th, many visitors arrived at the train station for a tour.()[单选题] *A. FromB. ToC. InD. On(正确答案)23、She _______ be here. [单选题] *A. is gladB. is so glad to(正确答案)C. am gladD. is to24、95.-Dad, can we walk? ? ? ? ? ? ?the road now?-No,we? ? ? ? ? ? ? ? ? ? . We have to wait until the light turns green. [单选题] *A.across, needn’tB.across, mustn’t(正确答案)C.though, can’tD.through, mustn't25、—What were you doing when the rainstorm came?—I ______ in the library with Jane. ()[单选题] *A. readB. am readingC. will readD. was reading(正确答案)26、33.Body language is even___________ and ___________ than any other language. [单选题] *A.stronger, loudB.strong, louderC.strong, loudD.stronger, louder (正确答案)27、I don’t know how to improve my English. Can I ask you for some _______? [单选题] *A. answersB. advice(正确答案)C. questionsD. words28、—______is my notebook?—Look! It’s in your schoolbag.()[单选题] *A. WhatB. WhichC. Where(正确答案)D. How29、The classmates can' t()Alice from her twin sister. [单选题] *A. speakB. tell(正确答案)C. talkD. say30、_____he was seriously ill, I wouldn’t have told him the truth. [单选题] *A.If I knewB.Had I known(正确答案)C.Did I knowD.Were I known。
初一下册语文所有单元作文题目大全
初一下册语文所有单元作文题目大全全文共8篇示例,供读者参考篇1亲爱的小伙伴们,大家好!我是小明,今年读初一。
最近我们老师布置了很多作文题目,都是从初一下册语文课本里出的。
写作文可是个大工程呢!不过放心,有我这个小学霸在,肯定能给你们总结出一份超级全面的作文题目大全。
我先从第一单元"语言"说起吧。
在这个单元里,老师布置了"一个动作用语言形容"、"学习一种新语言的体会"等作文题目。
你们可以想象一下,如果要形容"奔跑"这个动作,会用什么词语来描述呢?比如"飞奔""迅捷"等等。
至于学习新语言的体会,我相信很多同学都有过英语、日语等语言课的学习经历,就可以写写自己的感受。
接下来是第二单元"识字"。
在这个单元里,老师布置了"如何更好地识记生词"、"我最喜欢的一个汉字"等作文题目。
对于识记生词,我的小诀窍就是要联系实际生活场景,把单词和自己熟悉的事物联系在一起就容易记住多了。
至于最喜欢的汉字,同学们不妨挑一个自己觉得最有意思的字,然后从字形、字义、典故等角度好好分析一番。
再来看看第三单元"习作"。
这一单元的作文题目包括"如何提高书面表达能力"、"我最喜欢的一篇文章"。
书面表达能力对写作很重要,我们可以多读名著名作,潜移默化地把优秀的表达方式学会。
同时也要勤加练习,写一些日记、读书笔记等,日积月累,水到渠成。
最喜欢的那篇文章,说不定是我们语文课本上的一篇吧?第四单元是"议论"。
作文题目有"我心目中最伟大的人"、"人生什么最重要"。
每个人心中都有自己敬佩崇拜的伟大人物,也许是祖国的英雄,也许是家乡的楷模;至于人生什么最重要,我觉得朋友、健康、快乐都是不可或缺的。
220-2021学年部编七下语文课时练习附答案名第六单元著导读:《海底两万里》快速阅读
名著导读:《海底两万里》快速阅读一、填空题1.小明在复习自己读过的科幻类小说时,发现一张掉落的插图(如图)。
根据画面内容,他应将此页放回《(1)》一书中去,理由是(2)。
2.填空。
《海底两万里》的作者是,他被公认为是“ ”,小说讲述了一个神奇的故事:。
3.曾经有这样一个人:在人类还没有发明电报的时候,他小说中的人物已经在用电报传递信息;在人类还没有制造出飞机的时候,他小说中的人物已经驾驶直升机来往;在人类还没有着手登月工程的时候,他小说中的人物已经坐在一颗大炮弹里,被巨炮发射到月球上;……这个人就是。
他是法国著名的科幻和探险小说家,他的作品形象夸张地反映了19 世纪“机器时代”人们征服自然、改造世界的意志和幻想,并成为西方和日本现代科幻小说的先河。
我国的科幻小说大多也受到他作品的启发和影响。
他的《海底两万里》是一部纯虚构的科幻小说,书中、、太空飞行等想像情节如今都已经变成现实,可见(小说类别)往往也是在科学研究基础上的推理和预言,能在一定程度上促进科学的发展。
4.名著阅读。
这个不幸的人恐怕是没救了,有谁能把他从这紧紧缠绕着的触角中解救出来呢?不过,他还是向那条章鱼扑过去,大斧一挥,又砍断章鱼的一根触角。
大副也同样怒火中烧,与攀到艇上的另一条章鱼展开搏斗。
……他满身血污,一动不动地站在舷灯旁,凝视着吞噬了他的笫二个伙伴的大海。
大滴的泪珠从他的眼眶里滚了出来。
选段出自《》(书名),作品中的“他”是(人名),从选段中可以看出“他”是个(性格)的人。
5.《海底两万里》主要讲述“鹦鹉螺号”潜艇的船长尼摩邀诮著名博物学家阿龙纳斯在海底旅行的故事。
这次旅行从太平洋出发,经过了许多地方,也经历了很多险情。
请把下列冒险经历和其所发生的地点对应。
(请将答案字母写在相应的横线上)①印度洋②红海③南极。
6.运用课外阅读积累的知识,完成下面的填空。
《》是凡尔纳的“海洋三部曲”之一,小说讲述的是一位叫的船长,驾着自己设计制造的潜水艇“诺第留斯号”,在大海中自由航行的故事。
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Unit 6 Don’t eat in class.一、根据汉语意思或首字母提示完成句子1. Don’t stand o______. Come in please.2. He likes w_____ to school. He thinks it’s good for his health.3. Go to w_____ your hands, they are too dirty.4. Don’t f_____ with each other.5. “No talking” is one of the library r_____.6. Don’t t_____ in the reading room.7. Do you have to ______(穿) a school uniform today?8. They must be on t ______。
9. I can’t _______(会见我的朋友) after school. I have to go home.10. There are _______(太多) rules in her room.二、用所给单词的适当形式填空。
1. Mary is only four years old, but she can ______( read).2. _____( arrive not) late for class.3. Does Tom have to _____( finish )his homework by five?4. She practices _____( play )the piano every day.5. The people here are very ______( health).三、单项选择。
1. Let’ s _____ our dorm’ s (寝室的) rules。
A. getB. setC. makeD. plan2. — Mom, can I go to play football now?—No, you _____ finish your homework first.A. mustB. canC. couldD. may3. Mr. Green will arrive _____ Beijing this afternoon.A. atB. inC. onD. to4. I _____ to cook now.A. have notB. don’t haveC. had notD. didn’t have5. _____ I smoke here?A. MustB. NeedC. CanD. Have to 6. _____ draw on the wall.A. NotB. NoC. Doesn’tD. Don’t7. The visitors _____ our school yesterday morning.A. got toB. reached toC. arrivedD. arrive in8. My mother is not very well, _____ she works very hard.A. orB. butC. andD. too9. _____ do you think about Hangzhou?A. HowB. WhichC. WhereD. What10. They don’t have to _____ their school uniforms.A. dressB. have onC. put onD. wear11. Don’t wat ch TV _____ school nights.A. atB. inC. \D. on12. You can’t eat _____ outside the dining hall.A. inB. atC. \D. on13. Students can’t _____ music in the hallways.A. listenB. hearC. hear toD. listen to14. A kid _____ breakfast every morning, because it’s good for his health.A. have toB. has toC. has to haveD. has to has15. It’s not good _____ in class.A. talkB. to talkC. talksD. talked四、按要求改写句子1. We can wear hats in school. (改为否定句)________________________________________.2. No food in class. (改为同义句)________________________________________.___________________________________________?4. You can’t eat in class(改为祈使句)_______________________________________________5. Do your homework at school. (改为否定句)_________________________________________________.五、根据所给单词,写出正确的形式。
1. Does Tom have to ___________ (do)his homework by five?2. She practices ___________(play) the piano every day.3. Don’t ___________(eat) in the classroom, Emily.六、句型转换 (10分)A) 根据题后要求完成句子。
(5分)1. Run in the hallways. (否定句)__________ __________ in the hallways.2. I have to get up at six. (一般疑问句)_________ you _________ to get up at six?3. I can eat in the dining hall. (提问)___________ __________ you eat?4. We have to clean the room. (提问)__________ do you have to __________?5. late, can, arrive, for, we, not, school (连成一句)_________________________________________.6.Could you please not close the window?(改为祈使句) ______ ______ the window, please!7.Do your homework after school!(改为否定句) ______ ______ your homework after school!8.I have to do my homework after school.(改为一般疑问句)______ you ______ to do ______ homework after school?拓展训练一、按要求改写句子。
1. I can sing this song in English. (变成否定句)2. Eat food in the classroom. (变成否定句)3. He has to do his homework at school. (变成否定句)4. You can watch TV after supper. (变成祈使句)5. They can play basketball after school. (变成一般疑问句)6. Mr King has to stay at home. (对划线部分提问) 二.按照例句改写句子。
例:Put on your new clothes. (the old clothes) Don’t put on the old clothes.1. Catch the big fish. (the small ones)2. Take the bag to your bedroom. (the clock)3. Fly your kite. (his kite)4. Put them on the desk. (under the chair)5. Go to the classroom. (the teachers’ room)6. Look at the blackboard. (your book)三、用动词的正确形式填空1. The students often go ( swim) in summer.2. The traffic lights are red. Please ( go).4. It’s six o’c lock now. Jack (read) newspapers.5. Mr. Wang (leave) Shanghai 50 years ago.6. I enjoy ( listen) to music.7. Would you like ( play) ping-pong with me?8. Can you ( help) us?四、句型转换。
1. Please run quickly. (改为否定句) _______ _______ quickly, please.2. It’s sunny now. (对划线部分提问) _______ _______ _______ now?4. At school, we have to clean the blackboard. (对划线部分提问)_______ _______ we have to _______ at school?5. We can listen to music in the music room. (用in the classroom 改为选择疑问句)_______ we listen to music in music room _______ in the classroom?6.She wears sunglasses.(对划线部分提问) does she ?7.I went to Shanghai with my family.(对划线部分提问)you to Shanghai with?8.The sun is shining.(对划线部分提问) the weather?9.Listen to music in hallways.(改为否定句) listen to music in hallways.10.At school,we must clean the classroom.(改为同义句)At school,we clean the classro om.。