计算时间差以及比较日期大小

02.java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
03.java.util.Date end = dfs.parse("2004-03-26 13:31:40");
04.long between=(end.getTime()-begin.getTime())/1000;//除以1000是为了转换成秒
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
long min=((l/(60*1000))-day*24*60-hour*60);
long s=(l/1000-day*24*60*60-hour*60*60-min*60);
05.long day1=between/(24*3600);
06.long hour1=between%(24*3600)/3600;
07.long minute1=between%3600/60;
08.long second1=between%60/60;
09.System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");
11.System.err.println("格式不正确");
12.}
13.int result=pareTo(c2);
try
{
Date d1 = df.parse("2004-03-26 13:31:40");
Date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
System.out.println(""+day+"天"+hour+"小时"+min+"分"+s+"秒");
方法三：
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01.SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
02.String s2="2008-01-29 09:12:11";
03.java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
04.java.util.Calendar c1=java.util.Calendar.getInstance();
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");
java计算时间差及比较时间大小
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01.String s1="2008-01-25 09:12:09";
java 比较时间大小
String s1="2008-01-25 09:12:09";
String s2="2008-01-29 09:12:11";
java.text.DateFormat df=new java.text.SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
07.long days = diff / (1000 * 60 * 60 * 24);
08.}
09.catch (Exception e)
10.{
11.}
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
/xiarenwang/article/details/6578078
javaz中对日期时间的处理比较多，代码中列出了3中日期时间计算差值的方法。
比如：现在是2004-03-26 13：31：40
过去是：2004-01-02 11：30：24
我现在要获得两个日期差，差的形式为：XX天XX小时XX分XX秒
long second1=between%60/60;
System.out.println(""+day1+"天"+hour1+"小时"+minute1+"分"+second1+"秒");
====================================================
方法一：
比如：现在是2004-03-26 13：31：40
过去是：2004-01-02 11：30：24
我现在要获得两个日期差，差的形式为：XX天XX小时XX分XX秒
方法一：
DateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date date=df.parse("2004-01-02 11:30:24");
long l=now.getTime()-date.getTime();
long day=l/(24*60*60*1000);
long hour=(l/(60*60*1000)-day*24);
SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date now = df.parse("2004-03-26 13:31:40");
java.util.Date date=df.parse("2004-01-02 11:30:24");
java.util.Calendar c1=java.util.Calendar.getInstance();
java.util.Calendar c2=java.util.Calendar.getInstance();
try
{
c1.setTime(df.parse(s1));
c2.setTime(df.parse(s2));
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
try
{
Date d1 = df.parse("2004-03-26 13:31:40");
Date d2 = df.parse("2004-01-02 11:30:24");
long diff = d1.getTime() - d2.getTime();
long days = diff / (1000 * 60 * 60 * 24);
03.java.util.Date date=df.parse("2004-01-02 11:30:24");
04.long l=now.getTime()-date.getTime();
05.long day=l/(24*60*60*1000);
06.long hour=(l/(60*60*1000)-day*24);
}catch(java.text.ParseException e){
System.err.println("格式不正确");
}
int result=pareTo(c2);
if(result==0)
System.out.println("c1相等c2");
else if(result<0)
SimpleDateFormat dfs = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
java.util.Date begin=dfs.parse("2004-01-02 11:30:24");
java.util.Date end = dfs.parse("2004-03-26 13:31:40");
}
catch (Exception e)
{