静安区2007学年第二学期高三年级模拟检测
静安区高三第二学期调研模拟卷
静安区高三第二学期调研模拟卷静安区2005学年第二学期高三年级模拟检测英语试卷(120分钟完成; 总分:150分)2006. 4.第I卷 (共105分)(第I卷试题的答案请做在答题卡上)I.Listening ComprehensionPart A Short Conversations (每小题1分,共10分)Directions: In Part A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.21. A. A taxi driver. B. A car salesman.C. A secretary.D. A car repairman.2. A. Spanish. B. Chinese.C. Japanese.D. German.3. A. She can do the work herself.B. She should phone a friend.C. She’s just switched off the light.D. She’s already replaced the shelf.4. A. Boss and secretary. B. Teacher and student.C. Dentist and patient.D. Salesman and customer.5. A. She’s waited for him for a long time.B. There wasn’t much of selection at the supermarket.C. The man wants to be the owner of the supermarket.D. The man bought quite a lot in a3supermarket.6. A. 30 cents. B. 35 cents.C. 40 cents.D. 45 cents.7. A. Tuesday. B. Wednesday.C. Thursday.D. Friday.8. A. At a grocery store. B. At an electrical shop.C. At a gift shop.D. At a bank.9. A. He had used up all his money.B. He had some trouble with his lungs.C. He didn’t plan to stay for a long time.D. A young couple were not friendly to him.10. A. He shouldn’t be relaxed.B. He’s already an hour late.C. He’s too nervous to calm down.D. He can’t wait to be interviewed.Part B Passages (每小题2分,共12分) Directions: In Part B, you will hear two short4passages, and you will be asked three questions on each of the passages. The passages will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. A comfortable house. B. Children’s education.C. Health insurance.D. Traveling.12. A. Play with the children.B. Help her do some cleaning.C. Lift heavy furniture.D. Wash and dry the dishes.13. A. Because he thinks men are stronger5than women.B. Because a woman helps financially.C. Because he loves a woman’s job.D. Because it is easier than the work outside the home.Questions 14 through 16 are based on the following passage.14. A. Space amount. B. Comfort zone.C. Arm’s length.D. Accidental touch.15. A. South Americans. B. Asians.C. North Americans.D. Greeks.16. A. Relationship. B. Culture style.C. Language.D. Personality.6Part C Longer Conversations (每小题1分,共8分)Directions: In Part C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with information you have heard. Write your answers on your answer sheet.Blanks 17 through 20 are based on the following conversation.Name: Nicholas.Address: _____17_____ SpringVale.Departure date: 10, _____18_____.Things that should be done before she Lock the doors and shut the windows.7leaves: Cancel the_____19_____ andpapers.Tell the _____20_____and ask them tocontact the police ifanything suspicioushappens.Complete the form. Write ONE WORD for each answer.Blanks 21 through 24 are based on the following conversation.89Complete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and Vocabulary (每小题1分,共20分) Directions: Beneath each of the following sentences there are four choices marked A, B,C and D. Choose the one answer that best completes the sentence. What ’s the matter with Jerry ’s wife? She has to have a minor _____21_____as soon as possible.Why does Jerry want to have a few days off? Hehas to _____22_____his daughter while his wife is in hospital.Why can ’t the baby ’s grandparents come to help?Becausethey live rather _____23_____. When will Jerry go back to work?Next _____24_____.25. In their hearts, some American women think it is men’s business to earn money and _____ to spend it.A. theyB. theirsC. theirD. them26. Yesterday Mrs. Green went to the market, _____ some bananas and visited her cousin.A. boughtB. to buyC. buyingD. having bought27. Many possible means _____ to attract more customers, but I think none of them really work.A. have tried outB. have been tried outC. has tried outD. has been tried out28. The fried scallops ( 扇贝) we ate at the restaurant yesterday is marvelous. I’d like to have it again even if it costs _____.10A. as twice muchB. much as twiceC. twice as muchD. as much twice29. Johnny, You _____ play with the knife, you _____ hurt yourself.A. won’t … can’tB. shouldn’t …mustC. mustn’t …mayD. can’t …shouldn’t30. As we know, in a chemical change, energy can’t be created, _____.A. nor it can be destroyedB. neither is it destroyedC. neither can it be destroyedD. nor is it destroyed31. Everyone hopes that we can do somethingto make things better, so we can’t help but ______ under the stress.A. working`B. to workC. workedD. work32.They need to reserve the restaurant and select the menu months before their father’s birthday party, _____?A. don’t theyB. needn’t theyC. mustn’t theyD. need they33. With the students dressed in uniforms _____ in the hall, the visiting professor delivered an impressive speech on the art of language.A. seatedB. seatingC. to be seatingD. being seated34. _____, and you won’t get into trouble.A. Eating a balanced diet and taking regular exerciseB. Eat a balanced diet and take regular exerciseC. If you eat a balanced diet and take regular exerciseD. If eating a balanced diet and taking regular exercise35. _____ in a well-known university is what everybody wishes for.A. EducatedB. Being educatedC. To educateD. Educating36._____ the name Henry Ford is associated with cars, he himself had many i nterests other than cars.A. WhenB. AlthoughC. AsD. What37. They could only read such stories _____ had been rewritten in simple English.A. asB. whichC. thatD. what38. _____ both of them should be employed needs ___ .A. If … consideringB. What … to considerC. That … to considerD. Whether … considering39. A few years ago, the belief becamegeneral _______ orange juice and milkshould never be drunk at the same meal.A. thatB. whatC. and thatD.which40. In most urban and suburban areas of theworld, sick people go to a doctor _____ treatment.A. inB. ofC. forD. by41. According to some doctors, one of theways to prevent us from growing old is to make sure that our brains get enough ______.A. performanceB. sportC. experienceD. exercise42. The ice cream cone, the hamburger, andiced tea were all introduced at the 1904 Louisiana Purchase Exposition ___ known as the St. Louis Fair.A. peacefullyB. informallyC. incorrectlyD. occasionally43.These comments are not directly _____ tothis enquiry.A. closeB. nearC. relevantD. previous44.Fresh air, enough exercise and nutritiousfood _____ to good health.A. contributeB. addC. belongD. helpIV. Cloze (每小题1分,共20分)Directions: For each blank in the following passages there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.(A)Most children with healthy appetites are ready to eat almost anything that is offered them and a child rarely dislikes food unless it is badly cooked. The __45__ a meal is cooked and served is most important and an __46__served meal will often improve a child’s appetite. Never ask a child whether he likes or dislikes a food and never __47__ likes and dislikes in front of him or allow anybody else to do so. If the father says he hates fat meat or the mother __48__ vegetables in the child’s hearing he is likely to copy this procedure. Take it __49__granted that he likes everything and he probably will. Nothing healthful should be omitted from the meal because of a __50__ dislike. At meal times it is a good idea to give a child a small portion and let him __51__ back for a second helping rather than give him as much as he is likely to eat all at once. Do not talk too much to the child __52__ meal times, but let him get on with his food, and do not allow him to leave the table immediately after a meal or he will __53__ learn to swallow his food so he can hurry back to his toys. Under__54__ circumstances must a child be coaxed (哄)or forced to eat.45. A .idea B. performance C. plan D. way46. A. adequately B. attractively C. urgently D. eagerly47. A. remark B. tell C. discuss D. argue48. A. opposes B. denies C. refusesD. offends49. A. with B. as C. over D. for50 A. supposed B. proved C. considered D. carried51 A. ask B. come C. return D. take52. A. on B. across C. by D. during53. A. hurriedly B. soon C. fast D.slowly54. A. some B. any C. such D. no( B )How many different kinds of emotions do you feel? You may be surprised to find that it is very hard to specify all of them. Not only are emotional feelings hard to describe in words, they are difficult to __55__. As a result, two people rarely agree on all of them. However, there are a number of __56__ emotions that people experience.When we receive something that we want, or something happens that we like, we usually feel joy or happiness. Joy is a positive and powerful emotion, __57__ for which we all strive. It is natural to be happy, and all of us __58__ happiness. As a general rule, joy __59__ when we reach a desired goal or obtaina desired object.__60__ people often desire different goals and objects, it is understandable that one person may find joy in repairing an automobile, while another may find joy in solving a maths problem. Of course, we often share __61__ goals or interests, and therefore we can experience joy together. This may be in sports, in the arts, in learning, in raising a family, or in just being together.When we have difficulty in obtaining desired objects or reaching desired goals we experience __62__ emotions such as anger and grief. When little things get in our way, we experience minor frustrations and tensions. For example, if you are dressing to go out __63__ a date(约会),you may feel frustrated when a zipper breaks or a button falls off. The more difficulty you have in reaching a goal,the more frustrated you may feel and the more angry you may become. If you really want something to happen, and you feel it __64__ happen, but someone or something stops it, you may become quite angry.55. A. list B. recognize C. arrangeD. understand56. A. necessary B. vital C. essential D. basic57. A. the other B. one C. very one D. only one58. A. put aside B. remind of C. look at D. search for59. A. happens B. takes C. occursD. seems60. A. For B. When C. SinceD. Being61. A. same B. common C. positive D. different62. A. bad B. harmful C. uneasyD. negative63. A. on B. in C. for D. to64. A. will B. shall C. shouldD. wouldIV. Reading Comprehension (A—D篇每小题2分; E 篇每小题1分,共35分)Directions:Read the following passages. Each passage is followed by several questions or unfinished statements. For each of them, there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)Decreasing the greenhouse gas emissions(散发) that many scientists believe cause global warming is a complicated international problem. But all of us can do ourpart at home, according to Jose Ramon Villarin, a leading scientist in this field in Manila.“Anything that uses electricity, water or fuel increases greenhouse gas emissions,” says Villarin. The good news is that everyone can take a few simple steps to help the situation and cut bills on the way.●Take a Walk: Whenever possible, walk orbike—both are good for your health—instead of driving a car. Too far to walk? Use public transport.●Read the Label: Try to buy energy-efficientappliances. Many countries, including Singapore and the Philippines, are introducing labels that show the energy-efficiency ofwhite goods.●Shut off the Motor: When waiting in yourcar for more than a minute, turn off the engine rather than let it run. Restarting burns less petrol than letting it run.●Insulate(隔热): Seal spaces around doorsand windows to keep air-conditioning from escaping, and clean the unit’s filter(过滤网)now and then to keep it running efficiently.“Cutting energy waste might seem like small contribution to a large problem,”Villarin says, “but a collective change in behavior could have a major impact.”65. To decrease the greenhouse gas emissions, people have been advised to do all the following EXCEPT ______ in this passage.A. buy energy-saving appliancesB. take exercise in the open airC. keep the filter of air-conditioner cleanD. cut energy waste66. What is the effect of the greenhouse gas emission according to many scientists?A. Global warming.B. Air pollution.C. Bad health.D. Waste of energy.67. The underlined word seal in line 14 probably means ______.A. closing an entrance or container sothat air or liquid cannot enter or leaveitB. closing a letter or parcel by sticking theedges togetherC. making room by taking away anything that blocks, or coversD. deciding on, fixing or making the lastarrangements(B)ThermometersTo measure a temperature you need a thermometer. The problem is deciding which t y p e t o c h o o s e.Mercury thermometers (I)These are made of glass. They have a bulb at one end containing mercury. When the temperature rises, the mercury expands and moves further along the narrow tube. Mercury thermometers can’t measure temperature below -30°C because the mercury goes solid. Most just cover the range from 0°C to 100°C.The clinical thermometers (II)Doctors and nurses use a special type of mercury thermometer to measure the temperature of human body:●It only covers a few degrees either side of the average body temperature and measures these temperatures very accurately.●The tube has a narrow bend at the bottom to stop the mercury running back into the bulb. This means you can take the reading after the thermometer has been taken out ofthe patient’s mouth. You have to shake the mercury back into the bulb.Alcohol thermometers (III)These work in just the same way as mercury thermometers. But they are cheaper, easier to read, and they can measure lower temperatures. Alcohol doesn’t turn solid until -155°C.If you have a thermometer in your fridge or freezer (IV), it’s probably an alcohol thermometer.68. Most mercury thermometers measure temperature from __________.A. -115°C to 100°CB. -30°C to 120°CC. -60°C to 100°CD. 0°C to 100°C69 C linical thermometers have a bend in the tube because __________.A. they measure a narrow range of temperaturesB. the bulb must be kept separate from the threadC. it prevents the mercury in the bulb from getting warmD. it allows time for an accurate reading of temperature70. Thermometers work on the principle that __________.A. temperatures remain steady while being readB. liquids run from high points to lower pointsC. most matters expand as they get warmerD. they have a thread that is easier to read71. The article on thermometers most likely came from __________.A. a medical journalB. a science text bookC. instructions in a first aid kitD. an electrical store specializing inrefrigeration(C )The first hotels were very different from today’s hotels. They were small inns built along the road. Later, as people began to travel by train, hotels were built in the centers of large cities. Usually located near railroad stations, these hotels were many stories tall and hundreds of rooms.Although trains were a popular means of travel for some time, automobiles slowly began to take their place. Automobile travel caused problems for city hotels, which did not have parking space for so many cars.People who traveled by automobile needed a different kind of hotel. They needed places to stay that were near highways and had room to park. Motorists did not like to drive inheavy city traffic to reach a hotel. The answer to the motorists, problems came when a new kind of hotel was built. These new buildings were called motels, a word made from the first part of MOTORIST and the last part of HOTELS.Motels were much smaller than hotels. Built on round level, often in separate units, they were more convenient for people traveling. The separate units also made them quieter than hotels. Best of all, there was more than enough room for cars to park.Now many big hotels in the cities are being torn down. They can no longer make enough money to stay in business. In their place, many small motels have been built on the outskirts of cities. Motels have become a big business in the United States.72.Hotels became less popular because theyusually did not have __________.A. large enough rooms for big familiesB. place for cars to park inC. sufficient ground roomsD. quiet and convenient units73.Motels are usually __________.A. large, high buildings built in the downtown areasB. large, low buildings built around city centersC. small, high buildings built on the outskirtsD. small, low buildings built along highways outside the city74.The reason why many big hotels are being torn down is that __________.A. they are losing their competition to motelsB. people need the materials to buildsmall motelsC. it costs too much money to stay in a hotelD. cities are usually short of land for building motels75.On the whole, this passage is about __________.A. motorists’ problems out on the highwayB. the reason why a new kind of hotel came into beingC. which place is better for people to stay for the nightD. how to find a place to park your car during travel( D )In recent years many countries of the worldhave been faced with the problem of how to make their workers more productive. Some experts claim the answer is to make jobs more varied. But do more varied jobs lead to greater productivity? There is evidence to suggest that while variety certainly makes the worker’s life more enjoyable, it does not actually make him work harder.Other experts feel that giving the worker freedom to do his job in his own is important and there is no doubt that this is true. The problem is that this kind of freedom cannot easily be given in the modern factory with its complicated machinery which must be used in a fixed way. Another important consideration is how much each worker contributes to the product he is making. In most factories the worker sees only one small part of the product. Some car factories are now experimentingwith having many small production lines rather than one large one, so that each worker contributes more to the production of the cars on his line. It would seem that not only is degree of worker contribution an important factor, therefore, but it is also one we can do something about.To what extent does more money lead to greater productivity? The workers themselves certainly think this important. But perhaps they want more money only because the work they do is so boring. Money just lets them enjoy their spare time more. A similar argument may explain demands for shorter working hours. Perhaps if we succeed in making their jobs more interesting, they will neither want more money, nor will shorter working hours be so important to them.76. Which of these possible factors leading togreater productivity is NOT true?A. To make jobs more varied.B. To give the worker freedom to do his job in his own way.C. Degree of work contribution.D. Workers’ efficiency is not an important problem, nowadays.77. Why do workers want more money?A. To make up for the boredom of their jobs.B. To enjoy more spare time.C. To make their jobs more interesting.D. To demand shorter working hours.78. The last sentence in this passage means that if we succeed in making w orkers’ jobs more interesting __________.A. they will want more moneyB. they will demand shorter working hoursC. more money and shorter working hoursare important factorsD. more money and shorter working hours will not be so important to them79. In this passage, the author tells us__________.A. the workers need more trainingB. possible factors leading to greater efficiencyC. to what extent more money leads togreater productivityD. how to make workers’ jobs moreinteresting( E )Directions: Read the text and choose the most suitable heading from this list for each paragraph of the text. There is one extra heading.A. Image promoted bygenerous donationB. Radiation withsports eventsC. Benefit fromcooperationD. Expected jump insalesE. Promote sales byincreasing investmentF. Investment in otherfieldsCoca Cola, the US soft drink giant, which has already won a dominant position in the mainland beverages market, is stepping up its investment to further expand sales.81Since the company’s return to the mainland in 1979,its marketing efforts have been linked to sports events. “With the Beijing 2008 OlympicGames drawing near, Coca Cola will further unfold its expansion plan in sports, to give a combined push to the undertaking together with the Beijing Olympic Organizing Committee, and to inject more freshness and life into the Coca Cola brand,” Etchells says.The company has also promoted its brand image through charitable activities. In the past 25 years on the mainland, it has donated a total of 40 million yuan (US$4.8 million) to education, environmental protection and other charities.Etchells says an important element of the company’s success in China has been the especially close relationship established with its bottling partners, principally theState-owned China National Cereals, Oils and Foodstuffs Import and Export Corporation Hong Kong-based Swire Pacific and Kerry of Malaysia.In an interview with China Daily, Etchells said his company would also increase its invest-ment in production facilities and product research and development. In addition, he expects that the company will step up its recruitment efforts to meet projected demand.第II卷(共45分)I. Translation ( 1—4 每小题3分; 5—6每小题4分,共20分)Directions: Translate following sentences into English, using the words given in the brackets.1. 我希望你尽快实施这项计划。
上海市静安区2007—2008学年第一学期期末教学质量检测高三数学试卷
上海市静安区2007—2008学年第一学期期末教学质量检测高三数学试卷(本试卷满分150分 考试时间120分钟) 2008.1注意:1.答卷前考生务必将学校、班级、姓名、学号等填写清楚。
2.本试卷为文理合卷,有(理)标记的题目为理科考生解答题,有(文)标记的题目为文科考生解答题,其余试题为所有考生共答题。
一. 填空题(本大题满分44分)本大题共有11题,只要求直接填写结果,每题4分. 1. 设全集U = Z ,A={1,3,5,7,9},B={1,2,3,4,5,6},则右图中阴影部分表示的集合是 { }.2. 设函数)(x f 是奇函数且周期为3,)2008(1)1(f f ,则-=-= .3. 已知xx x f 22log1log 1)(+-=(21>x ),则=-)53(1f. 4. 已知向量a 与b 都是单位向量,它们的夹角为120︒,且3=+b a k ,则实数k 的值是.5.(理)点)1,1(A 到直线02sin cos =-+θθy x 的距离的最大值是 . (文)函数)]2,0((2)(∈+=x xx x f 的值域是 .6.(理)若一个三棱锥中有一条棱长为x (其中30<<x ),其余各棱长均为1,则它的体积=)(x V .(文)已知正三棱柱的底面正三角形边长为2,侧棱长为3,则它的体积=V . 7. (理)设满足不等式23)2(<+-x x a 的解集为A ,且A ∉1,则实数a 的取值范围是 .(文)不等式232<+-x x 的解集是 .8. (理)已知对于任意正整数n ,都有321n a a a n =+++ ,则)111111(lim 32-++-+-+∞→n n a a a = .(文)9412lim+++∞→n n n = .9.已知直线0325:=++y x l ,直线l '经过点)1,2(P 且与l 的夹角等于45︒,则直线l '的一般方程是 .10.设方程022=+-m x x 的两个虚数根为α、β,且2=-βα,则实数m 的值是 . 11. 给出下列四个结论:①函数x y a =(0a >且1a ≠)与函数log x a y a =(0a >且1a ≠)的定义域相同; ②函数)0(3>⋅=k k y x (k 为常数)的图像可由函数3x y =的图像经过平移得到; ③函数11221xy =+-(0≠x )是奇函数且函数)21131(+-=xx y (0≠x )是偶函数;④函数x y cos =是周期函数.其中正确结论的序号是___________________.(填写你认为正确的所有结论序号)二.选择题(本大题满分16分)本大题共有4题,每题都给出四个结论,其中有且只有一个结论是正确的,把正确结论的代号写在题后的圆括号内得4分,否则一律得零分. 12.已知πα<<0,21cos sin =+αα ,则α2cos 的值为 ( ).(A )47; (B )47-; (C )47±; (D )43-.13. (理)nxx 2)1(-展开式中的中间项是 ( ).(A )nn C 2; (B )2121)1(x C n n n ---; (C )n n n C 2)1(-; (D )2121)1(-++-xC n n n .(文)不等式组⎪⎩⎪⎨⎧≤≤≤≥+-100022y x y x 表示的平面区域形状是一个 ( ).(A )三角形; (B )矩形; (C )梯形; (D )五边形.14. 一工厂生产的100个产品中有90个一等品,10个二等品,现从这批产品中抽取4个,则其中恰好有一个二等品的概率为 ( ). (A )41004901C C -; (B )4100390110490010C C C C C +; (C )4100110C C ; (D )4100390110C C C .15.已知函数x y ωsin =在]3,3[ππ-上是减函数,则实数ω的取值范围是 ( ).(A )]23,(-∞-; (B ))0,23[-; (C )]23,0(; (D )),23[∞+.三.解答题(本大题满分90分)本大题共有6题 解答下列各题必须写出必要的步骤. 16.(本题满分12分).设复数θθsin cos 2i z ++=,],0[πθ∈,i +=1ω,求||ω-z 的取值范围.17. (本题满分14分)第1小题满分4分,第2小题满分10分.已知平面向量→a =(3,-1),→b = (23,21).(1)求b a ⋅;(2)设b x a c )3(-+=,b x a y d +-=(其中0≠x ),若d c ⊥,试求函数关系式)(x f y =并解不等式7)(>x f .18. (本题满分14分)理科第1小题满分6分,第2小题满分8分;文科第1小题满分8分,第2小题满分6分.(理) 如图,已知四棱锥ABCD P -的底面ABCD 是边长为a 的正方形,点O 为该正方形的中心,侧棱PD PB PC PA ==,. (1)求证:四棱锥ABCD P -是正四棱锥;(2)设点Q 是侧棱PD 的中点,且PD 的长为a 2.求异面直线OQ 与AB 所成角的大小.(用反三角函数表示) (文)如图,在棱长为2的正方体1111D C B A ABCD -中,点F E 、分别是棱AB 、AD 的中点.求: (1)异面直线1BC 与EF 所成角的大小; (2)三棱锥EFC A -1的体积V .19. (本题满分14分)第1小题满分6分,第2小题满分8分.由市场调查得知:某公司生产的一种产品,如果不作广告宣传且每件获利a 元,那么销售量为b 件;如果ABCDPOQAA 1BCDB 1C 1D 1F作广告宣传且每件售价不变,那么广告费用n 千元..比广告费用(1-n )千元..时的销售量多nb 21⨯件(*N n ∈).(1) 试写出销售量n S 与n 的函数关系式;(2) 当400010==b a ,时公司应作几千元..广告,销售量为多少件时,才能使去掉广告费用后的获利最大?20. (本题满分18分) 理科第1小题满分6分,第2小题满分12分;文科第1小题满分8分,第2小题满分10分.(理)已知3021,,,a a a 是首项为1,公比为2的等比数列.对于满足300<≤k 的整数k ,数列3021,,,b b b 由⎩⎨⎧≤<--≤≤=-++时时3030,,301,30n k a k n a b k n k n n 确定.记30302211b a b a b a C +++= .求:(1)1=k 时C 的值; (2)C 最小时k 的值.(文)已知等差数列{a n }的首项a 1=0且公差d ≠0, b n =2na (n ∈N *),S n 是数列{b n }的前n 项和.(1) 求S n ; (2) 设T n =nn b S (n ∈N *),当d >0时,求n n T +∞→lim .21. (本题满分18分) 第1小题满分4分,第2小题满分6分,第3小题满分8分. 设ba x f x x++-=+122)((b a ,为实常数).(1) 当1==b a 时,证明:)(x f 不是奇函数; (2) 设)(x f 是实数集上的奇函数,求a 与b 的值;(3) (理) 当)(x f 是实数集上的奇函数时,证明对任何实数x 、c 都有33)(2+-<c c x f 成立.(文)求(2)中函数)(x f 的值域.参考答案与评分标准1.{}6,4,2; 2. 1; 3.412; 4. 21or k -=; 5. (理)22+,(文)),22[+∞; 6.(理)23121x x -;(文)33;7. (理)]8,(--∞;(文)),3()8,(+∞---∞ ; 8. (理)31;(文)09.直线l ':01137=--y x 和01373=-+y x ; 10.2=m ; 11.①②③④ 12.B ; 13. C ; 14. D ; 15. B16.22)1(sin )1(cos |)1(sin )1(cos |||-++=-++=-θθθθωi z =)4cos(223)sin (cos 23πθθθ++=-+ ………6′∵]45,4[4πππθ∈+,∴]22,1[)4cos(-∈+πθ ………10′则]5,12[||-∈-ωz ………12′17. (1)0=⋅b a ; ………4′ (2)由d c ⊥得,0)3(4=-+-x x y , ………6′ 所以)3(41-=x x y ; ………8′7)3(41>-x x 变形得:02832>--x x ,解得47-<>x x 或. ………14′18.(理)(1)连接PO ,因为PC PA =,所以AC PO ⊥; ………2′ 同理BD PO ⊥;所以ABCD PO 平面⊥; ………4′ 又因为O 是正方形ABCD 的中心,所以四棱锥ABCD P -是正四棱锥.…6′ (2)因为点Q 是侧棱PD 的中点,所以PB OQ //,所以ABP ∠是异面直线OQ 与AB 所成的角. ………10′ 在△PAB 中计算得:A B P ∠=41arccos;所以异面直线OQ 与AB 所成角的大小为41arccos . ………14′用向量解答参照上述标准给分,示例:解法2:以O 为原点,正方形对角线为y x ,轴,)0,0,22(),0,22,0(a B a A -,)214,0,0(a P ,)414,0,42(a a OQ -=,)0,22,22(a a AB =, ………10′设OQ 与AB 的夹角为θ,则41cos -=θ。
高中化学上海静安区20072008学年下学期高三年级教学质量检测试题
高中化学上海静安区20072008学年下学期高三年级教学质量检测试题 2019.091,某中学社会实践活动小组利用假期对当地钢铁厂进行了调研,对从矿石开始到钢铁产出的工艺流程有了较全面的感性认识。
请你参与计算该社会实践活动小组感兴趣的问题:(1)将6.62g铁矿石样品投入适量的盐酸中(充分反应),过滤,然后在滤液中加过量的NaOH溶液,充分反应后,过滤、洗涤、灼烧得4.80g Fe2O3。
现以该铁矿石为原料炼铁,若生产过程中铁元素损失4%,计算每生产1.00t生铁(含铁96%),至少需要这种铁矿石多少吨?(保留两位小数)(2)取某钢样粉末28.12g(假设只含Fe和C),在氧气流中充分反应,得到CO2气体224mL(标准状况)。
①计算此钢样粉末中铁和碳的物质的量之比。
②再取三份不同质量的钢样粉末分别加到100mL相同浓度的H2SO4溶液2,石油中不含有A.烷烃 B.烯烃 C.环烷烃 D.芳香烃3,氯化钠等盐可作融雪剂,科学原理是A.氯化钠密度大 B.氯化钠价格低C.氯化钠熔点高 D.氯化钠溶液熔点低4,胶体区别于其他分散系的本质特征是A.能通过滤纸 B.不能通过半透膜C.分散质颗粒直径为1-100nm D.能发生丁达尔现象5,自然界的硫单质主要以S8的形式存在,将S8加热可得到S2、S4、S6等,S2、S4、S6、S8互称为A.同素异形体 B.同位素 C.同系物 D.同分异构体6,2008年3月20日媒体报导,挪威和荷兰正在开发一种新能源-盐能.当海水和淡水混合时,温度将升高0.1o C,世界所有入海口的这种能源相当于电力需求的20%。
海水和淡水混合时,温度升高最可能的原因是A.发生了盐分解反应B.发生了水分解反应C.由于浓度差产生放热 D 盐的溶解程度增大7,以下实验需在集气瓶里加少量水或细沙的是A.铜丝在氯气中燃烧 B.铁丝在氧气中燃烧C.磷在氯气中燃烧 D.氢气在氯气中燃烧8,以下物理量没有确切意义的是A.25o C时醋酸的电离度 B.25o C时KNO3在水中的溶解度C.25o C时水的离子积 D.0o C、101.3kPa时氢气的密9,以N A表示阿佛加德罗常数,下列说法正确的是A. 30g甲醛和醋酸的混合物含N A个碳原子 C.1.8g重水有N A个质子B. 1 mol Cl2与足量水反应时转移电子数为2N A个 D.1 mol CaC2有N A个C-C键10,氯水不稳定,要现用现配,下列吸收氯气制备氯水的装置最合理的是11,以下性质比较正确的是A.密度:1-氯己烷>1-氯戊烷>1-氯丁烷B.熔点:钠>钠钾合金>钾C.键长:碳碳单键>苯环中碳碳键>碳碳双键D.离子半径:Be2+>Li+>H-12,将m g铜片在空气中灼烧片刻,在石英管中用以下气体充分加热,固体仍为m g的是①CO ②H2③C2H5OH(g)④CH3CHO(g)A.①②③④ B.①② C.①②③ D.①②④13,以下化学试剂的保存方法不当的是14,25o C时,将1mol/L的醋酸钠溶液用水稀释至0.1mol/L, 溶液中增大的是A. c(OH-) B. c(CH3COOH)C. c(H+) D.c(CH3COO-)/c(CH3COOH)15,已知C(s,石墨) → C(s,金刚石)- 1.9KJ,且知金刚石密度更大,则C(s,石墨)与C(s,金刚石)的比较,正确的是A.等质量时,后者能量更高更稳定B.等质量时,前者在空气中完全燃烧放热更多C.高温高压有利于前者转化为后者D.前者熔化只需破坏范德华力,后者则需破坏共价键16,下列离子方程式错误的是A.NH4Cl溶液与NaOH溶液混合NH4+ + OH-→ NH3·H2OB.氢氧化钡溶液与硫酸溶液反应得到中性溶液Ba2++OH-+ H++SO42-→ BaSO4↓+H2OC.NaHCO3溶液与过量的Ba(OH)2溶液混合HCO3- + Ba2+ + OH-→ BaCO3↓+H2OD.苯酚钠溶液中通入少量CO2气体O--+ CO2 + H2OH+ HCO317,关于电解CuCl2溶液的叙述正确的是A.负极发生还原反应B. 正极发生氧化反应C. 电解过程中,溶液的pH不变D. 电解过程中,阴极质量增加18,下列实验过程中产生的现象与对应的图形相符合的是① NaHSO3粉末加入HNO3溶液中②H2S气体通入SO2水溶液中③NaOH溶液滴入Ba(HCO3)2溶液中④CO2气体通入澄清石灰水中A .①② B.②③ C.②④ D.③④A .①② B.②③ C.②④ D.③④19,10 mL气体A2与30 mL气体B2恰好反应生成20 mL气体C(体积均在同温同压下测定),则C的化学式为AB3,可作此判断的理论依据是A.元素周期律 B.能量守恒与转换定律C.质量守恒定律 D.阿伏加德罗定律20,以下是进行氨氧化制硝酸的实验装置图,有关叙述正确的是A 烧杯中石蕊溶液变红B .烧瓶中发生喷泉现象C .加热后,通过Cr 2O 3的气体由无色变为红棕色D .Cr 2O 3起氧化剂的作用试题答案1, (1)解:6.62g 铁矿石中铁的质量为m (Fe )=4.80g ×112160=3.36g生产1.00t 生铁至少需铁矿石的质量为:m (铁矿石)=6.621.0096% 3.3614%g t g⨯⨯-≈1.97t(2)① n (C )=10.22422.4LL mol -⋅=0.010molm (C )=0.010mol ×l2g ·mol -1=0.12g1(283120.12)()5650:1()0.010g g n Fe g mol n C mol --⋅==即此钢样粉末中铁和碳的物质的量之比为50︰1 ② 根据实验Ⅲ可得:Fe+H2SO4→FeSO4+H2↑1 mol 22.4L n(H2SO4) 2.800L n(H2SO4)=0.125molc(H2SO4)=0.1250.1molL=1.25mol·L-1③当钢样粉末中的铁未全部溶解时(m>1.406g),剩余的固体质量为:(5.624+mg)-0.125mol×56g·mol-1=(m-1.376)g当钢样粉末中的铁全部溶解时(m≤1.406g),剩余的固体质量为:(5.624+m)g×0.1228.12gg=(5.624)0.1228.12mg+⨯2, B3, D4, C5, A6, C7, B8, A9, A 10, D 11, C 12, C 13, A 14, C 15, C 16, B 17, D 18, C 19, C、D 20, A、C。
2002007学年上海静安区高三第一学期期末教学质量检测试卷
5. 右图是某种植物正常的体细胞 (示细胞中的染色体)。
下列可能是该植物的基因型的是2006-2007学年度上海市静安区高三第一学期期末教学质量检测试卷本试卷分为第I 卷(第1-5页)和第II 卷(第6-12页)两部分,全卷共12页。
满分150分。
考试时间为120分钟。
第I 卷(共60分)考生注意:1 •答第I 卷前,务必在答题卡上用钢笔或圆珠笔清楚填写姓名、准考证号,并用铅笔正确 涂写准考证号。
2. 第I 卷(1-32题),由机器阅卷,答案必须全部涂写在答题卡上, 考生应将代表正确答案 的小方格用铅笔涂黑。
注意试题题号和答题纸编号一一对应, 不能错位。
答案写在试卷上一 律不给分。
3.第I 卷为单选题;不分叉,全部为必答题。
选择题1分题 1.下列化合物中含有的化学元素种类最少的一组是A 抗体和干扰素B 纤维素和脱氧核糖C 性激素和叶绿素D ATP 和酶2.F 列生物中,不具有叶绿体,但具有细胞壁的是①噬菌体 ②大肠杆菌③颤藻 ④绿藻3. A ①②①③②④②③在下列生物中,既以 DNA 乍为遗传物质, 又具有相同代谢类型的一组生物是A 人和蘑菇蓝藻和大肠杆菌 4. C 噬菌体和烟草花叶病毒 乳酸菌和硝化细菌食品通过辐射保鲜主要是为了 A 使食品基因突变 使食品遗传物质改变 C 使食品上的微生物死亡 使食品发生染色体变异A ABCdB AaaaC BBbbDDDdD AaBbCcDd 6.酸雨已成为一个全球性环境问题,酸雨的危害不 包括A 伤害陆地植物的叶和芽 B延缓森林中有机物质的分解 C 硫酸沿食物链富集并危害人体D杀死水生生物,破坏营养结构 7 •细胞是生命的单位。
下列有关叙述错误的是8.在光线明亮的实验室里,用白色洋葱表皮细胞做质壁分离实验,在显微镜视野中能清晰2分题物因素分别主要是12.在小型圆底烧瓶内盛等量的 H 2Q ,迅速加入等量的下列图示中的物质,烧瓶口紧包一个小气球,使烧瓶沉于烧杯底部的同一位置。
上海市静安区2007-2008学年度高三第一学期期末检测物理试题
上海市静安区2007-2008学年度高三第一学期期末检测物理试题2008.1考生注意:1.本卷有答题纸,答题前,考生务必将姓名、考号等填写在答题纸的指定位置,答卷时间为120分钟。
2.全卷共23题,每道题的解答都要写在答题纸的对应位置,考试结束只交答题纸。
3.第19、20、21、22、23题要求写出必要的文字说明,方程式和重要的演算步骤。
只写出最后答案,而未写出主要演算过程的,不能得分。
4.有数字计算的问题,答案中必须明确写出数值和单位,有关重力加速度的数值计算一律取10 m/s 2。
一、填空题:(40分)本大题共8小题,每小题5分。
1、2007年10月24日我国自主研制的“嫦娥一号”月球探测卫星发射升空。
“嫦娥一号”在绕月工作轨道的运动可视为匀速圆周运动,轨道半径为R (约等于月球半径)。
此前曾有宇航员在月球上做自由落体实验,将某物体由距月球表面高h 处释放,经时间t 后落到月球表面,据上述信息可推出“嫦娥一号” 绕月运行的速率约为 。
假设地球、月球都静止不动,卫星在近地轨道变轨后,靠惯性飞向月球,若卫星变轨时的动能小于卫星飞到月球过程中需要克服地球引力做的功,则探测卫星 (选填“可能”或“不可能”)到达月球。
水平击出一2、如右图所示,某人从高出水平地面h 的坡上的作用,高尔个质量为m 的高尔夫球。
由于恒定的水平风力则该球从被夫球竖直地落入距击球点水平距离为L 的A 穴。
被击出时的击出到落入A 穴所花的时间为_________,球初速度大小为_________。
3、如下图所示,某人乘雪橇从雪坡经A 点滑至B 点,接着沿水平路面滑至C 点停止.人与雪橇的总质量为70kg ,在BC 段所受阻力恒定,表中记录了沿坡滑下过程中的有关数据,根据图象和表格中的数据可知人与雪橇从A 到B 的过程中,损失的机械能为 ;在BC 段所受阻力的大小为 。
4.一定质量的理想气体从状态a 变化到状态b 再变化到状态c 最后又变化到状态a ,其P-1/V 图如右图所示,图线ab 与横轴平行,ac 延长线通过坐标原点。
青浦区2007学年第二学期高三年级模拟抽查考试试卷
2007学年第二学期高三年级模拟考试(青浦、杨浦、静安三区联考)语文试卷Q.2008.4(考试时间:150分钟满分:150分)(注:答案请写在答题纸上,否则不予评分)一阅读(80分)(一)阅读下文,完成1—5题。
(15分)谈谈中国的传统文化张岱年⑴中国文化是世界三大文化体系之一,在上古时代是独立发展的,形成人类文化的一个独立典型。
直到十五世纪,中国文化始终居于世界文化的前列。
中国的“四大发明”传入西方后,促进了西方近代科技的迅速发展,而在中国本土却没有起到变革的作用。
十六世纪以后,西方科学技术突飞猛进,至十七世纪中叶起,逐渐形成西方近代文明,中国则落后了。
到十九世纪,中国受到资本主义列强的侵略欺凌,中国人民发愤图强,经过一百多年的艰苦奋斗,终于“站起来了”。
从此,中国文化的发展也进入了一个新的时代。
⑵中国在近代的落后,表明近代中国文化存在一些严重缺点:中国没有孕育自己的近代实验科学,又没有产生近代民主制度。
五四新文化运动,提出“科学”与“民主”,确实揭示了文化改造的主要任务。
尽管中国没有产生自己的实验科学,但是,中国古代的科学知识也还是相当丰富的。
⑶在文化问题上,要避免两种不正确的倾向,即既要反对全盘西化论,也要反对中国文化优越论。
应当运用唯物辩证法,把中西文化各自的贡献综合起来,创造新的中国文化和世界文化。
⑷作为一个中国人,就是要有民族自尊心、自信心。
而培养民族自尊自信,需要了解优秀的民族文化传统。
中国优秀的传统文化,现在不是讲得太多,而是还没有被充分地发扬。
所谓批判继承,当然是要有所批判,但主要还是要把优秀的传统继承下来,发扬光大。
⑸一些人对中国古代文化缺乏了解,光羡慕西方文化。
其实,中国古代有许多深刻思想,但是因为中国古书的文字简要,有时就很难理解,不像西方著作长篇大论讲得那么详细。
中、西哲人各有短长,中国古代思想家虽论证欠缺,但也直截了当,意蕴丰富,废话不多。
⑹中国文化主要还是儒家的。
静安区2007学年第一学期高三学科模拟测试(精)
静安区2007学年第一学期高三学科模拟测试生物学试卷2008.1本试卷分为第I卷(第1-5页)和第II卷(第6-13页)两部分,全卷共13页。
满分150分。
考试时间为120分钟。
第I卷 (共60分)考生注意:1.答第I卷前,务必在答题卡上用钢笔或圆珠笔清楚填写姓名、准考证号,并用铅笔正确涂写准考证号。
2.第I卷(1-32题),由机器阅卷,答案必须全部涂写在答题卡上,考生应将代表正确答案的小方格用铅笔涂黑。
注意试题题号和答题纸编号一一对应,不能错位。
答案写在试卷上一律不给分。
1分题1.将下列细胞或细胞器置于蒸馏水中,不会破裂的是A. 红细胞B. 叶绿体C. 线粒体D. 洋葱表皮细胞2.在同一种生物体内,有丝分裂后期细胞中的染色体数目是减数分裂第二次分裂后期细胞的A.1倍B.2倍C.4倍D.8倍3.在噬菌体侵染细菌的实验中,如果用32P和35S分别标记噬菌体的DNA和蛋白质外壳,结果复制出来的绝大多数噬菌体A.含32P和35S B.不含32P和35S C.含32P、不含35S D.不含32P、含35S4. 纤维素、纤维素酶、纤维素酶基因的基本组成单位分别是A.葡萄糖、葡萄糖和氨基酸 B.葡萄糖、氨基酸和脱氧核糖核酸C.葡萄糖、氨基酸和脱氧核苷酸 D.多糖、蛋白质和DNA5.科学家利用“同位素标记法”研究了许多化学反应的详细过程。
下列说法正确的是A.用15N标记核苷酸掌握了分裂期染色体形态和数目的变化规律B.用180标记H20证明了CO2是光合作用的原料C.用14c标记C02最终探明了CO2中碳元素在光合作用中的转移途径D.用35S标记噬菌体的DNA,并以此侵染细菌证明了DNA是遗传物质6. 如果某种植物器官呼吸时的氧气吸收量大于二氧化碳释放量,该器官最可能是A.萌发的花生种子 B.花生幼苗 C.水稻根 D.水稻叶7.洋葱根尖生长点细胞中由一个共同的着丝点相连的两条染色单体上所携带的全部基因本应完全相同,但实际上却有不相同的,其原因可能是A 复制时发生了差错B 联会时染色单体间发生了交叉互换C 发生基因突变或交叉互换D 该洋葱不是纯合体8.用高度分化的植物细胞、组织或器官进行组织培养都可以形成愈伤组织,下列叙述中错.误.的是A.该愈伤组织是细胞经过脱分化和分裂形成的B.该愈伤组织的细胞没有全能性C.该愈伤组织是由排列疏松的薄壁细胞组成D.该愈伤组织可以形成具有生根发芽能力的胚状结构2 分题9. 青少年每天都必须摄入足量的蛋白质,有关原因叙述正确的是①蛋白质在体内不能贮存②蛋白质不能全部由糖类和脂肪在体内转化而成③蛋白质提供生命活动所需的大部分能量④体内的蛋白质每天要少量分解一些,更换新的⑤蛋白质是青少年长身体的重要原料A. ②③④B. ①③④⑤C. ②④⑤D. ①②④⑤10.一位在南极科学考察站工作的科学家,当他由温暖的室内来到寒冷的户外时,其下列各项生理变化与下图变化趋势相符的是①皮肤血管血流量的变化②身体耗氧量的变化③肾上腺素分泌量④汗腺的分泌量A.①③B.②④C.②③ D.①④11.在DNA分子双螺旋结构中,碱基A与T之间有两个氢键,碱基C与G之间有三个氢键。
青浦区2007学年第二学期高三年级模拟抽查考试试卷
2007学年第二学期高三年级模拟考试(青浦、杨浦、静安三区联考)语文试卷Q.2008.4(考试时间:150分钟满分:150分)(注:答案请写在答题纸上,否则不予评分)一阅读(80分)(一)阅读下文,完成1—5题。
(15分)谈谈中国的传统文化张岱年⑴中国文化是世界三大文化体系之一,在上古时代是独立发展的,形成人类文化的一个独立典型。
直到十五世纪,中国文化始终居于世界文化的前列。
中国的“四大发明”传入西方后,促进了西方近代科技的迅速发展,而在中国本土却没有起到变革的作用。
十六世纪以后,西方科学技术突飞猛进,至十七世纪中叶起,逐渐形成西方近代文明,中国则落后了。
到十九世纪,中国受到资本主义列强的侵略欺凌,中国人民发愤图强,经过一百多年的艰苦奋斗,终于“站起来了”。
从此,中国文化的发展也进入了一个新的时代。
⑵中国在近代的落后,表明近代中国文化存在一些严重缺点:中国没有孕育自己的近代实验科学,又没有产生近代民主制度。
五四新文化运动,提出“科学”与“民主”,确实揭示了文化改造的主要任务。
尽管中国没有产生自己的实验科学,但是,中国古代的科学知识也还是相当丰富的。
⑶在文化问题上,要避免两种不正确的倾向,即既要反对全盘西化论,也要反对中国文化优越论。
应当运用唯物辩证法,把中西文化各自的贡献综合起来,创造新的中国文化和世界文化。
⑷作为一个中国人,就是要有民族自尊心、自信心。
而培养民族自尊自信,需要了解优秀的民族文化传统。
中国优秀的传统文化,现在不是讲得太多,而是还没有被充分地发扬。
所谓批判继承,当然是要有所批判,但主要还是要把优秀的传统继承下来,发扬光大。
⑸一些人对中国古代文化缺乏了解,光羡慕西方文化。
其实,中国古代有许多深刻思想,但是因为中国古书的文字简要,有时就很难理解,不像西方著作长篇大论讲得那么详细。
中、西哲人各有短长,中国古代思想家虽论证欠缺,但也直截了当,意蕴丰富,废话不多。
⑹中国文化主要还是儒家的。
静安区2007学年第一学期高三年级模拟检测
静安区2007学年第一学期高三年级模拟检测历史试卷2008.1(考试时间:120分钟,总分:150分)选择题请用2B铅笔填涂在答题卡上,其它题书写在答题纸上,做在题卷上无效。
一、选择题(本题共30小题,每小题2分,共60分,)1.《国语•齐语》载:“……美金以铸剑戟,试诸狗马;恶金以铸鉏、夷、斤、斸,试诸壤土”。
郭沫若释“美金”、“恶金”分别指青铜和铁器。
与郭沫若得出这一结论相匹配的历史事实是战国时期A.青铜产量有限,故主要用作武器、礼器;铁器已广泛应用于农业生产B.青铜颜色亮丽;铁器颜色深暗C.青铜高贵,宜作武器;铁器低贱,仅作农具D.青铜质地坚硬不易酸化;铁器质地粗糙且易锈蚀2.《史记•秦始皇本纪》载:“(二十六年)分天下以为三十六郡”。
明代张岱所著《夜航船》也记载:“始皇初并天下,罢诸侯,置守尉,遂分天下为三十六郡,每郡置一守、一丞、两尉以典之。
”由此可知秦A.废除贵族特权 B.君主专制加强C.加强中央集权 D.设置三公九卿3.下图分别是欧洲人笔下的《匈奴骑兵图》、出土文物匈奴骑兵俑、匈奴骑兵铜像,它们共同佐证了《史记》中有关匈奴的相关记载A.“逐水草迁徙”B.“能弯弓,尽为甲骑”C.“习战攻以侵伐”D.“毋城郭”、“毋文书”4.右图是一幅美国现代政治漫画,它要表达的核心思想是A.种族歧视,白人至贵B.种族有别,政治平等C.白人居西,黄人居东D.三大人种,文化不同5.文帝四年中……(淳于)意,以刑罪当传西之长安。
少女缇萦……上书曰:“妄父为吏……今坐法当刑。
妾切痛死者不可复生而刑者不可复续,虽欲改过自新,其道莫由,终不可得.妄愿入身为官婢,以赎父刑罪,使得改行自新也。
”书闻,上悲其意,此岁中亦除肉刑法。
这就是中国的经典故事——“缇萦救父”。
故事虽不是史实,但可以印证历史。
本故事不能印证的是A.西汉时存在残害肢体的刑罚 B.“以礼入法”是中国古代的立法指导思想C.汉代奴婢制度依然存在 D.儒家思想是西汉初年的统治思想6.伯里克利说:“我们的制度是别人的模范,而不是我们模仿其他任何其他的人的。
高中化学上海静安区20072008学年下学期高三年级教学质量检测试题
高中化学上海静安区20072008学年下学期高三年级教学质量检测试题 2019.091,合成氨工业对国民经济和社会发展具有重要的意义。
哈伯法合成氨需要在20-50MPa的高压和500℃的高温下,并用铁作为催化剂,氨的转化率为10%-15%;最近美国俄勒冈大学的化学家使用了一种名为trans-Fe(DMeOPrPE)2的催化剂,在常温下合成出氨。
下列有关说法中错误的是A.哈伯法合成氨是吸热反应,新法合成氨是放热反应B.新法合成和哈伯法相比不需要在高温条件下,可节约大量能源C.新法合成能在常温下进行是因为不需要断裂化学键D.新的催化剂降低了反应所需要的能量2,已知反应2A(g) B(?)+ 2C(?) - Q (Q>O),满足如图所示的关系,则下列说法中正确的是A.B、C可能均为非气态B.若B是气态,则C一定也只能是气态C.若B为固态,则C一定为气态D.B、C可能均是气态焰色反应是变化(选填“化学”或“物理”)。
(2)X的气态氢化物的电子式为__________ ,最高价氧化物对应的水化物与其氢化物化合生成的盐在实际应用中可以作。
(3)元素Y的最高氧化物对应的水化物其浓溶液有三大特性为、、。
(4)工业上制备Z所用的方法是。
4,在上个世纪,人们很早就得到高氯酸和高碘酸及其盐,但无论用什么方法都得不到+7价溴的化合物。
直到1968年,有个名叫Appelman的化学家用发现不久的XeF2和HBrO3反应,首次检测出BrO4-。
随后在1971年用XeF2和含KOH、KBrO3的水溶液反应,得到了很纯的KBrO4晶体。
(1)已知XeF2和水反应放出氧气和氙气,氟则以化合态留在水溶液中。
其化学方程式为:___________________________________________________________。
该反应中的氧化剂是_______________,被氧化的元素是_______________。
上海市杨浦区、静安区2007年高三二模考试数学(文理合卷)
上海市杨浦区、静安区2006-2007学年第二学期高三年级教学质量检测数学试卷班级_______姓名_____________学号_______ 一、 填空题(本大题满分48分)本大题共有12题,每题4分,只要求直接填写结果.1、直线210x y -+=的倾斜角为___________.(用反三角函数表示)2、(理)0lg lg 22=+x x 的解是 . (文)0224=-+xx 的解是 . 3、已知b x f x+=2)(的反函数为)(1x f-,若)(1x fy -=的图像经过点)25(,P ,则b 的值是_________.4、在△ABC 中,a 、b 、c 分别是三内角A 、B 、C 所对应的三边,已知bc c a b +-=222,则cos A 的值是_____________.5、若集合{}{}a x x B x x A <-=<<=1,40,且A B ⊆,则实数a 的取值范围是 .6、若{}n a 为等差数列,且212lim=++∞→n a nn ,则公差d 的值是_________.7、(理)已知正四棱锥的底面面积为42cm ,体积为43cm ,设它的侧面上的斜高与底面所成角的大小为θ,则sin θ的值是 .(文)V ,底面边长为a ,则它的高为___________.8、(理)已知圆的极坐标方程是2cos ρθ=,则在相应的直角坐标系中圆心的坐标是____.(文)函数a xx x f +-=1)(为奇函数,则实数a 的值是__________. 9、(理)已知n n n x a x a a x x x +++=++++++ 102)1()1()1(,若n a a a a n n -=++++-510121 ,则n 的值是________.(文)已知实数y x ,满足不等式组⎪⎩⎪⎨⎧≥≤+≤02,y y x x y ,那么函数y x z 3+=的最大值是 .10、设过抛物线24y x =的焦点F 的直线交抛物线于A 、B 两点,且AB 中点为M ,则点M的轨迹方程是_________________.11、已知集合{}9630,,,=A ,从中任取两个元素分别作为点()y x P ,的横坐标与纵坐标,则点P 恰好落入圆10022=+y x 内的概率是__________.12、已知函数)2(log )()1(+=+n n f n (n 为正整数),若存在正整数k 满足:k n f f f f =⋅⋅)()3()2()1( ,那么我们将k 叫做关于n 的“对整数”.当∈n [1,100]时,则“对整数”的个数为____________个. 二、选择题 (本大题满分16分)13、设甲是乙的充分非必要条件,乙是丙的充要条件,那么丙是甲的 ( ) .(A) 充分非必要条件 (B) 必要非充分条件 (C) 充要条件 (D) 既非充分又非必要条件14、同时满足三个条件:①有反函数;②是奇函数;③其定义域与值域相等的函数是( ) .(A )1)(+=x x f (B )x x x f sin )(2+=(C )222)(xx x f -+= (D )3)(x x f -=15、设圆的方程是()()2222x a y b a b -++=+(其中a >0且b >0),给出下列三种说法:(1)该圆的圆心坐标为()a ,b .(2)该圆过原点.(3)该圆与x 轴相交于两个不同点.其中 ( )(A )只有(1)与(2)正确 (B )只有(1)与(3)正确 (C )只有(2)与(3)正确 (D )(1)、(2)与(3)都正确16、设奇函数)(x f 的定义域为实数集R ,且满足)1()1(-=+x f x f ,当)10[,∈x 时, 12)(-=x x f .则)25()2()23()1()21()0(f f f f f f +++++的值为( ) .(A)12+ (B) 12- (C ) 0 (D ) 1三、解答题 (本大题满分86分)本大题共有6题,解答下列各题必须写出必要的步骤.17、(本题满分12分)(理)设虚数z 满足4z a z+=(其中a 为实数).(1)求z ;(2)若22z -=,求a 的值.(文)设复数z 满足211=+z z ,求z . 18、(本题满分12分)第1小题6分,第2小题6分. (理)在长方体ABCD -1111A B C D 中(如图),ABCDEA 1B 1C 1D 1SRQ PCAB11==AA AD ,2AB=,点E 是棱AB 上的动点.(1)当异面直线1AD 与EC 所成角为060时,请你确 定动点E 的位置.(2)求三棱锥C -1DED 的体积.(文)在正四棱锥P -ABCD 中(如图),若异面直线PA 与BC 所成角的正切值为2,底面边长AB =4.(1)求侧棱与底面ABCD 所成角的大小.(2)求四棱锥P -ABCD 的体积.19、(本题满分14分)本题共2小题,第1小题7分,第2小题7分.设A 是由符合以下性质的函数()f x 组成的集合:对任意的x ≥0,()f x ∈(1,4],且()f x 在[0,+∞)上是减函数.(1)判断函数()1f x =2-x 及 ()2f x =1+3⋅x)21((0≥x )是否属于集合A ?并简要说明理由.(2) 把(1)中你认为是集合A 中的一个函数记为)(x g ,若不等式()()2g x g x ++≤k对于任意的x ≥0总成立,求实数k 的取值范围.20、(本题满分14分)本题共2小题,第1小题7分,第2小题7分.如图,某小区准备绿化一块直径为BC 的半圆形空地,ABC ∆外的地方种草,ABC ∆的内接正方形PQRS 为一水池,其余地方种花.若BC=a, ABC=θ∠,设ABC ∆的面积为1S ,正方形PQRS 的面积为2S ,将比值21S S 称为“规划合理度”. (1)试用a ,θ表示1S 和2S .(2)(理)当a 为定值,θ变化时,求“规划合理度”取得最小值时的角θ的大小.(文)当a 为定值,015=θ时,求“规划合理度”的值.A BC PD21、(本题满分16分)本题共3小题,第1小题4分,第2小题6分,第3小题6分.设向量)2(,x a =,)12(-+=x n x b , (n 为正整数),函数b a y ⋅=在[0,1]上的最小值与最大值的和为n a ,又数列{}n b 满足:()12121999121101010n n n n nb n b b b ---⎛⎫⎛⎫+-+⋅⋅⋅++=++⋅⋅⋅++ ⎪⎪⎝⎭⎝⎭. (1) 求证:1+=n a n .(2) 求n b 的表达式.(3) 若n n n c a b =-⋅,试问数列{}n c 中,是否存在正整数k ,使得对于任意的正整数n ,都有n k c c ≤成立?证明你的结论.(注:)(21a a a ,=与{}21a a a ,=表示意义相同) 22、(本题满分18分)本题共3小题,第1小题4分,第2小题6分,第3小题8分.(理)设斜率为1k 的直线L 交椭圆C :1222=+y x 于B A 、两点,点M 为弦AB 的中点,直线OM 的斜率为2k (其中O 为坐标原点,假设1k 、2k 都存在). (1)求1k ⋅2k 的值.(2)把上述椭圆C 一般化为22221x y a b+=(a >b >0),其它条件不变,试猜想1k 与2k 关系(不需要证明).请你给出在双曲线22221x y a b -=(a >0,b >0)中相类似的结论,并证明你的结论. (3)分析(2)中的探究结果,并作出进一步概括,使上述结果都是你所概括命题的特例. 如果概括后的命题中的直线L 过原点,P 为概括后命题中曲线上一动点,借助直线L 及动点P ,请你提出一个有意义的数学问题,并予以解决.(文)设21F F 、分别为椭圆C :22221x y m n +=(m >0,n >0且m n ≠)的两个焦点. (1)若椭圆C 上的点A(1,23)到两个焦点的距离之和等于4,求椭圆C 的方程.(2)如果点P 是(1)中所得椭圆上的任意一点,且021=⋅PF PF ,求21F PF ∆的面积.(3)若椭圆C 具有如下性质:设N M 、是椭圆C 上关于原点对称的两点,点Q是椭圆上任意一点,且直线QM与直线QN的斜率都存在,分别记为QM K 、QN K ,那么QM K 和QNK 之积是与点Q位置无关的定值.试问:双曲线22221x y a b-=(a >0,b >0)是否具有类似的性质?并证明你的结论.通过对上面问题进一步研究,请你概括具有上述性质的二次曲线更为一般的结论,并说明理由上海市杨浦区、静安区2006-2007学年第二学期高三年级教学质量检测数学试卷参考答案1.2arctan , 2. (理科)1x =或210x -=;(文科)0x =, 3. 1 4. 125.3a ≥6. 47.24V a8. (理科)()1 ,0; (文科)1- 9. (理科)8; (文科)4 10. ()221y x =- 11. 5612. 513. B 14.D 15.C 16.B 17、(理科)本题共2小题,第1小题6分,第2小题6分 解:设()z x yi x, y R =+∈≠且y0 -----------2分 则22444x yi z x yi a R z x y -+=++=∈+ 2240yy x y∴-=+-------------4分 ()224 x y y 0∴+=≠ --------------------------------6分又 22z -=得()2224x y -+=∴或1x ,y==1112 z ∴== ----10分 a=∴4z z+=2 ------------------------12分(文科)(本题满分12分) 解法一:由211=+z z 得,0222=+-z z ,-----------------2分 解一元二次方程得14z ==i z 41541±=。
上海静安区高三物理第二学期质量检测试卷
上海静安区2007-2008学年度高三物理第二学期质量检测试卷考生注意:1.本卷有答题纸,答题前,考生务必将姓名、考号等填写在答题纸的指定位置。
2.全卷共24题,每道题的解答都要写在答题纸的对应位置,考试结束只交答题纸。
3.本试卷一、四大题中,小题序号后标有字母A的试题,适合于使用一期课改教材的考生;标有字母B的试题适合于使用二期课改教材的考生;其它未标字母A或B的试题为全体考生必做的试题.不同大题可以选择不同的A类或B类试题,但同一大题的选择必须相同.若在同一大题内同时选做A类、B类两类试题,阅卷时只以A类试题计分.一、填空题(20分)。
本大题共5小题,每小题4分。
答案写在答题纸的指定位置。
本大题中第l、2、3小题为分叉题。
分A、B两类,考生可任选一类答题.A类题(适合于使用一期课改教材的考生)1A.如图所示,两根相同的轻弹簧竖直立在水平地面,弹簧上端平放着一根质量为m、长为L的金属棒ab,ab所在处的空间有水平方向且与ab棒垂直的匀强磁场,磁感强度为B。
给金属棒通电,弹簧刚好处于原长状态,则棒中电流强度为__________;方向__________。
2A.利用光电管产生光电流的电路如图所示.电源的正极应接在端(填“a”或“b”);若电流表读数为8μA,则每秒从光电管阴极发射的光电子至少是个(已知电子电量为l.6×10-19C)3A.在如图所示电路中,R1=R2>r,滑动变阻器R3的滑片P从上端向下移动过程中,电压表示数的变化是___________;外电路消耗的功率的变化是__________.( 填变大、变小或不变)B类题(适合于使用二期课改教材的考生) 1B.粒子a和粒子b以相同的速度垂直飞入匀强磁场,在磁场中粒子a发生偏转,粒子b仍按原方向前进,如图所示。
忽略重力的影响,由运动轨迹可以判断粒子a带_______电荷;若它们进入磁场前的动能相等,则磁场中运动一段时间后,粒子a的动能_______粒子b的动能。
数学_2007年上海市杨浦区、静安区高考数学二模试卷(文理合卷)_(含答案)
2007年上海市杨浦区、静安区高考数学二模试卷(文理合卷)一、填空题(本大题满分48分)本大题共有12题,每题4分,只要求直接填写结果.1. 直线2x−y+1=0的倾斜角为________.(用反三角函数表示)2. (理)lg2x+lgx2=0的解是________.3. 方程4x+2x−2=0的解是________.4. 已知f(x)=2x+b的反函数为f−1(x),若y=f−1(x)的图象经过点P(5, 2),则b的值是________.5. 在△ABC中,a、b、c分别是三内角A、B、C所对应的三边,已知b2=a2−c2+bc,则cosA的值是________.6. 若集合A={x|0<x<4},B={x||x−1|<a},且A⊆B,则实数a的取值范围是________.7. 若{a n}为等差数列,且limn→+∞a n2n+1=2,则公差d的值是________.8. 已知正四棱锥的底面面积为4cm2,体积为4cm3,设它的侧面上的斜高与底面所成角的大小为θ,则sinθ的值是________.9. (文)已知正三棱柱体积为√3V,底面边长为a,则它的高为________.10. 已知圆的极坐标方程是ρ=2cosθ,则在相应的直角坐标系中圆心的坐标是________.11. 若函数f(x)=x−1x+a为奇函数,则实数a的值是________.12. (理)已知(1+x)+(1+x)2+...+(1+x)n=a0+a1x+...+a n x n,若a1+a2+...+a n−1+a n=510−n,则n的值是________.13. 已知实数x,y满足不等式组{y≤xx+y≤2y≥0,则目标函数z=x+3y的最大值为________.14. 设过抛物线y2=4x的焦点F的直线交抛物线于A、B两点,且AB中点为M,则点M的轨迹方程是________.15. 已知集合A={0, 3, 6, 9},从中任取两个元素分别作为点P(x, y)的横坐标与纵坐标,则点P恰好落入圆x2+y2=100内的概率是________.16. 已知函数f(n)=log(n+1)(n+2)(n为正整数),若存在正整数k满足:f(1)⋅f(2)⋅f(3)…f(n)=k,那么我们将k叫做关于n的“对整数”.当n∈[1, 100]时,则“对整数”的个数为________个.二、选择题(本大题满分16分)17. 设甲是乙的充分非必要条件,乙是丙的充要条件,那么丙是甲的()A 充分非必要条件B 必要非充分条件C 充要条件D 既非充分又非必要条件18. 同时满足三个条件:①有反函数;②是奇函数;③其定义域与值域相等的函数是()A f(x)=|x|+1B f(x)=x2+sinxC f(x)=2x+2−x2D f(x)=−x319. 设圆的方程是(x−a)2+(y+b)2=a2+b2(其中a>0且b>0),给出下列三种说法:(1)该圆的圆心坐标为(a, b).(2)该圆过原点.(3)该圆与x轴相交于两个不同点.其中( )A 只有(1)与(2)正确B 只有(1)与(3)正确C 只有(2)与(3)正确D (1)、(2)与(3)都正确20. 设奇函数f(x)的定义域为实数集R ,且满足f(x +1)=f(x −1),当x ∈[0, 1)时,f(x)=2x −1.则f(0)+f(12)+f(1)+f(32)+f(2)+f(52)的值为( )A √2+1B √2−1C 0D 1−√2三、解答题(本大题满分86分)本大题共有6题,解答下列各题必须写出必要的步骤. 21. (理)设虚数z 满足z +4z =a (其中a 为实数).(1)求|z|;(2)若|z −2|=2,求a 的值.22. (文)设复数z 满足z +1z=12,求z .23.(理)在长方体ABCD −A 1B 1C 1D 1中(如图),AD =AA 1=1,AB =2,点E 是棱AB 上的动点.(1)当异面直线AD 1与EC 所成角为60∘时,请你确 定动点E 的位置. (2)求三棱锥C −DED 1的体积.24. 在正四棱锥P −ABCD 中(如图),若异面直线PA 与BC 所成角的正切值为2,底面边长AB =4.(1)求侧棱与底面ABCD 所成角的大小. (2)求四棱锥P −ABCD 的体积.25. 集合A 是由适合以下性质的函数f(x)组成的:对于任意的x ≥0,f(x)∈(1, 4],且f(x)在[0, +∞)上是减函数.(1)判断函数f 1(x)=2−√x 及f 2(x)=1+3⋅(12)x (x ≥0)是否在集合A 中?试说明理由;(2)对于(1)中你认为是集合A 中的函数f(x),不等式f(x)+f(x +2)≤k 对于任意的x ≥0总成立.求实数k 的取值范围.26. 如图,某小区准备绿化一块直径为BC 的半圆形空地,△ABC 外的地方种草,△ABC 的内接正方形PQRS 为一水池,其余地方种花.若BC =a ,∠ABC =θ,设△ABC 的面积为S 1,正方形PQRS 的面积为S 2,将比值S1S 2称为“规划合理度”.(1)试用a ,θ表示S 1和S 2. (2)(理)当a 为定值,θ变化时,求“规划合理度”取得最小值时的角θ的大小. (3)(文)当a 为定值,θ=150时,求“规划合理度”的值.27. 设向量a →=(x,2),b →=(x +n,2x −1)(n 为正整数),函数y =a →⋅b →在[0, 1]上的最小值与最大值的和为a n ,又数列{b n }满足:nb 1+(n −1)b 2+⋯+2b n−1+b n =(910)n−1+(910)n−2+⋯+910+1.(1)求证:a n =n +1 (2).(2)求b n 的表达式.(3)若c n =−a n ⋅b n ,试问数列{c n }中,是否存在正整数k ,使得对于任意的正整数n ,都有c n ≤c k 成立?证明你的结论.(注:a →=(a 1,a 2)与a →={a 1,a 2}表示意义相同) 28. (理)设斜率为k 1的直线L 交椭圆C:x 22+y 2=1于A 、B 两点,点M 为弦AB 的中点,直线OM 的斜率为k 2(其中O 为坐标原点,假设k 1、k 2都存在). (1)求k 1⋅k 2的值. (2)把上述椭圆C 一般化为x 2a2+y 2b 2=1(a >b >0),其它条件不变,试猜想k 1与k 2关系(不需要证明).请你给出在双曲线x 2a 2−y 2b 2=1(a >0, b >0)中相类似的结论,并证明你的结论.(3)分析(2)中的探究结果,并作出进一步概括,使上述结果都是你所概括命题的特例.如果概括后的命题中的直线L 过原点,P 为概括后命题中曲线上一动点,借助直线L 及动点P ,请你提出一个有意义的数学问题,并予以解决.29. (文)设F 1、F 2分别为椭圆C:x 2m 2+y 2n 2=1(m >0,n >0且m ≠n)的两个焦点. (1)若椭圆C 上的点A(1, 32)到两个焦点的距离之和等于4,求椭圆C 的方程.(2)如果点P 是(1)中所得椭圆上的任意一点,且PF 1→⋅PF 2→=0,求△PF 1F 2的面积. (3)若椭圆C 具有如下性质:设M 、N 是椭圆C 上关于原点对称的两点,点Q 是椭圆上任意一点,且直线QM 与直线QN 的斜率都存在,分别记为K QM 、K QN ,那么K QM 和K QN 之积是与点Q 位置无关的定值.试问:双曲线x 2a 2−y 2b 2=1(a >0, b >0)是否具有类似的性质?并证明你的结论.通过对上面问题进一步研究,请你概括具有上述性质的二次曲线更为一般的结论,并说明理由.2007年上海市杨浦区、静安区高考数学二模试卷(文理合卷)答案1. arctan22. x=1或x=10−23. 04. 15. 126. a≥37. 48. 3√1010.9. 4a2V10. (1, 0)11. −112. 813. 414. y2=2(x−1)15. 5616. 517. B18. D19. C20. B21. 解:设z=x+yi(x,y∈R且y≠0)则z+4z =x+yi+4x−4yix2+y2=a∈R∴ y−4yx2+y2=0∴ x2+y2=4(y≠0),即|z|=2;又|z−2|=2得(x−2)2+y2=4,与x2+y2=4(y≠0)联立解得x=1,y=√3或x=1,y=−√3∴ z1=1+√3i,z2=1−√3i∴ a=z+4z=222. 解:设z=a+bi(a, b∈R),由z+1z =12得,a+bi+1a+bi=12,由复数相等得{a+aa2+b2=12b−ba2+b2=0,当b=0时,实数a不存在;所以a2+b2=1,并且a+aa2+b2,所以解得a =14,b =±√154, 所以z =14±√154i . 23. 解:(1)以DA 为x 轴,以DC 为y 轴,以DD′为z 轴,建立空间直角坐标系.设 E(1, t, 0)则A(1, 0, 0),D(0, 0, 0),D′(0, 0, 1),C(0, 2, 0) 则D′A →=(1, 0, −1),CE →=(1, t −2, 0)根据数量积的定义及已知得:D′A →⋅CE →=1=√2⋅√1+(t −2)2⋅cos60∘ ∴ t =2∴ E 的位置是AB 中点.(2)V C−DED 1=V D 1−DEC =13⋅S △DEC ⋅DD 1=13⋅12⋅2⋅1⋅1=1324. 解:(1)过P 作斜高PE ,PO ⊥底面ABCD ,AD // BC∴ ∠PAD 为异面直线PA 与BC 所成的角θ且tanθ=2在Rt △PEA 中tanθ=2=PE AE 且AE =2所以PE =4,PA =2√5 正四棱锥P −ABCD 的高为PO =2√3在Rt △POA 中,∴ sin∠PAO =√155∴ ∠PAO =arcsin√155, 侧棱与底面ABCD 所成角的大小为arcsin √155( 或写成arccos √105) (2)V P−−ABCD =13⋅42⋅2√3=32√3325. 解:(1)∵ f 1(49)=2−√49=−5∉(1, 4],∴ f 1(x)不在集合A 中.…又∵ x ≥0,∴ 0<(12)x ≤1,∴ 0<3⋅(12)x ≤3,从而1<1+3⋅(12)x ≤4.∴ f 2(x)∈(1, 4].又f 2(x)=1+3⋅(12)x 在[0, +∞)上为减函数,∴ f 2(x)=1+3⋅(12)x 在集合A 中.…(2)当x ≥0时,f(x)+f(x +2)=2+154⋅(12)x ≤234.又由已知f(x)+f(x +2)≤k 对于任意的x ≥0总成立,∴ k ≥234.因此所求实数k 的取值范围是[234, +∞). …26. 解:(1)在Rt △ABC 中,AB =acosθ,AC =asinθ,S 1=12AB ⋅AC =12a 2sinθcosθ设正方形的边长为x 则BP =x sinθ,AP =xcosθ,由BP +AP =AB ,得xsinθ+xcosθ=acosθ,故x =asinθcosθ1+sinθcosθ 所以S 2=x 2=(asinθcosθ1+sinθcosθ)2 (2)S 1S 2=12⋅(1+sinθcosθ)2sinθcosθ=(1+12sin2θ)2sin2θ=1sin2θ+14sin2θ+1,令t =sin2θ,因为0<θ<π2, 所以0<2θ<π,则t =sin2θ∈(0, 1] 所以S1S 2=1t+14t +1=g(t),g′(t)=−1t2+14<0, 所以函数g(t)在(0, 1]上递减,因此当t =1时g(t)有最小值g(t)min =g(1)=94,此时sin2θ=1,θ=π4所以当θ=π4时,“规划合理度”最小,最小值为94. (3)θ=150时,S 1=14a 2sin30∘=18a 2,S 2=(asin30∘2+sin30∘)2=a 225,所以,S 1S 2=25827. 解:(1)证明:对称轴x =−n+42<0,所以y =x 2+(n +4)x −2在[0, 1]上为增函数---a n =(−2)+(n +3)=n +1−−(2)解:由nb 1+(n −1)b 2+⋯+2b n−1+b n =(910)n−1+(910)n−2+⋯+910+1, 得,(n −1)b 1+(n −2)b 2+...+b n−1=(910)n−2+⋯+910+1两式相减, 得b 1+b 2+⋯+b n =(910)n−1=S n∴ 当n =1时,b 1=S 1=1 当n ≥2时,b n =S n −S n−1=−110(910)n−2 即b n ={1……当n =1时−110(910)n−2…当n ≥2时(3)由(1)与(2)得c n =−a n b n ={−2……当n =1时n+110(910)n−2…当n ≥2时设存在自然数k ,使对n ∈N ,c n ≤c k 恒成立 当n =1时,c 2−c 1=2310>0⇒c 2>c 1当n ≥2时,c n+1−c n =(910)n−2⋅8−n100,∴ 当n <8时,c n+1>c n当n =8时,c n+1=c n ,当n >8时,c n+1<c n所以存在正整数k =9,使对任意正整数n ,均有c 1<c 2<...<c 8=c 9>c 10>c 11>…28. (解一):(1)设直线方程为y =k 1x +b ,代入椭圆方程并整理得:(1+2k 12)x 2+4k 1bx +2b 2−2=0, x 1+x 2=−4k 1b 1+2k 2,又中点M 在直线上,所以y 1+y 22=k 1⋅x 1+x 22)+b从而可得弦中点M 的坐标为(−2bk11+2k 12,2b1+2k 12),k 2=−12k 1,所以k 1k 2=−12.(解二)设点A(x 1, y 1),B(x 2, y 2),中点M(x 0, y 0) 则x 0=x 1+x 22,y 0=y 1+y 22K 2=y 0x 0=y 1+y 2x 1+x 2,k 1=y 2−y1x 2−x 1又12x 12+y 12=1与12x 22+y 22=1作差得 −12=(y 2−y 1)(y 2+y 1)(x 2−x 1)(x 2+x 1)所以 K 1K 2=−12 (2)对于椭圆,K 1K 2=−b 2a 2已知斜率为K 1的直线L 交双曲线x 2a 2+y 2b 2=1(a >0, b >0)于A ,B 两点,点M 为弦AB 的中点,直线OM 的斜率为k 2(其中O 为坐标原点,假设K 1、k 2都存在). 则k 1,k 2⋅的值为b 2a 2.(解一)设直线方程为y =k 1x +d ,代入x 2a 2+y 2b 2=1((a >0, b >0)方程并整理得:(b 2−a 2k 12)x 2−2k 1a 2dx −(ad)2−(ab)2=0 12(y 1+y 2)=db 2b 2−a 2k 12,所以K 2=y 0x 0=y 1+y 2x 1+x 2=b 2k 1a 2,k 1=y 2−y 1x 2−x 1,即k 1k 2=b 2a 2(解二)设点A(x 1, y 1),B(x 2, y 2),中点中点M(x 0, y 0) 则x 0=x 1+x 22,y 0=y 1+y 22,K 2=y 0x 0=y 1+y 2x 1+x 2,k 1=y 2−y 1x 2−x 1又因为点A ,B 在双曲线上,则x 12a 2−y 12b 2=1与x 22a 2−y 22b 2=1作差得 a 2b 2=(y 2−y 1)(y 2+y 1)(x 2−x 1)(x 2+x 1)=k 1k 2 即k 1k 2=b 2a 2(3)对(2)的概括:设斜率为k 1的直线L 交二次曲线C:mx 2+ny 2=1(mn ≠0)于A ,B 两点,点M 为弦AB 的中点,直线OM 的斜率为k 2(其中O 为坐标原点,假设k 1,k 2、都存在),则k 1k 2=−mn .提出问题与解决问题满分分别为,提出意义不大的问题不得分,解决问题的分值不得超过提出问题的分值.提出的问题例如:直线L 过原点,P 为二次曲线线mx 2+ny 2=1(mn ≠0)上一动点,设直线L 交曲线于A ,B 两点,当P 异于A ,B 两点时,如果直线PA ,PB 的斜率都存在,则它们斜率的积为与点P 无关的定值.解法1:设直线方程为y =kx ,A ,B 两点坐标分别为(x 1, y 1)、(−x 1, −y 1),则y 1=kx 1 把y =kx 代入mx 2+ny 2=1得(m +nk 2)x 2=1, K PA ⋅K PB =(y 0−y 1)(y 0+y 1)(x 0−x 1)(x 0+x 1)=y 02−y 12x 02−x 12,所以K PA ⋅K PB =1−mx 02n −k2m+nk 2x 02−1m+nk 2=m−m(m+nk 2)x 02n(m+nk 2)x 02−n =−mn提出的问题的例如:直线L:y =x ,P 为二次曲线mx 2+ny 2=1(mn ≠0)上一动点,设直线L 交曲线于A ,B 两点.试问使∠APB =30∘的点P 是否存在?问题例如:1)直线L 过原点,P 为二次曲线线mx 2+ny 2=1(mn ≠0)上一动点,设直线L 交曲线于A ,B 两点,求PA +PB 的值.2)直线l 过原点,P 为二次曲线mx 2+ny 2=1(mn ≠0)上一动点,设直线L 交曲线于A ,B 两点,求S △PAB 的最值. 29. 解:(1)当m >n 时,由椭圆定义得 2m =4,∴ m =2 又点A(1, 32)在椭圆上 所以1m 2+94n 2=1,∴ n 2=3∴ x 24+y 23=1同理,当m <n 时,椭圆方程x 23+y 24=1(2)当m >n 时,由椭圆定义得 PF 1+PF 2=2m ,PF 12+PF 22=4 解得 PF 1PF 2=6 所以△PF 1F 2的面积为3同理,当m <n 时,△PF 1F 2的面积也为3(3)设M ,N 是双曲线x 2a2−y 2b 2=1(a >0, b >0)上关于原点对称的两点,点Q 是椭圆上任意一点,且直线QM 与直线QN 的斜率都存在,分别记为K QM ,K QN ,那么K QM ,K QN 之积是与点Q 位置无关的定值.设点M(x 1, y 1),N(−x 1, −y 1).Q(x 0, y 0) 则x 12a 2−y 12b 2=1,x 02a 2−y 02b 2=1 作差得(y 1−y 0)(y 1+y 0)(x 1−x 0)(x 1+x 0)=b 2a 2所以K QM K QN =b 2a 2设M ,N 是二次曲线mx 2+ny 2=1上关于原点对称的两点,点Q 是二次曲线上任意一点,且直线QM与直线QN的斜率都存在,分别记为K QM,K QN,那么K QM K QN=−mn证明设点点M(x1, y1),N(−x1, −y1).Q(x0, y0)则mx12+ny12=1,mx02+ny02=1作差得(y1−y0)(y1+y0)(x1−x0)(x1+x0)=−mn∴ K QM K QN=−mn。
静安区2007学年第二学期教学质量检测修改
静安区2007学年第二学期教学质量检测九年级数学试卷 2008.4.3(满分150分,考试时间100分钟)一、选择题:(本大题共6题,每题4分,满分24分)1.下列二次根式中,与24互为有理化因式的是( ).(A );2 (B );3 (C );6 (D )12.2.如果关于x 的一元二次方程022=+-a x x 有两个实数根,那么a 的取值范围为( ).(A );1>a (B );1<a (C );1≥a (D )1≤a . 3.函数32--=x y 的图像不经过( ).(A )第一象限; (B )第二象限; (C )第三象限; (D )第四象限. 4.两名射击运动员分别射靶5次,甲命中的环数如下:8, 7, 10, 9, 6;乙命中的环数的平均数为8,方差为1.6,那么下列说法中正确的是( ). (A )甲的成绩较好; (B )乙的成绩较好; (C )甲的稳定性较高; (D )乙的稳定性较高.5.下列条件中,不能判断四边形ABCD 是平行四边形的为( ).(A ) AB //CD ,AD //BC ; (B )AB =CD ,AD =BC ; (C ) AB //CD ,AD =BC ; (D )AB //CD ,AB =CD .6.如果直线上一点到⊙O 的圆心O 的距离大于⊙O 的半径,那么这条直线与⊙O 的位置关系是( ).(A )相交; (B )相切;(C )相离; (D )相交、相切、相离都有可能. 二.填空题:(本大题共12题,满分48分)7. 计算:2233a a ⋅=__________.8.如果分式112--x x 值为零,那么x 的值为____________.9.方程32=+x 的根是____________.10.用换元法解分式方程0111222=++-+xx x x 时,如果设y x x =+12,那么原方程化为关于y 的整式方程是_____________________. 11.函数y =32+x 的定义域是_____________.12.如果反比例函数的图像经过点(2,3),那么这个反比例函数的解析式为___________. 13.某校有300学生参加一次考试,随机抽取40人的考试成绩作为样本,样本数据落在80~85分之间的频率是0.25,可以估计该校学生考试成绩在80~85分之间的学生约有______人.14.在等腰△ABC 中,AB =AC , ∠A =80°那么∠B =_____________度.15.在Rt △ABC 中,∠C =90°,AB =2,将这个三角形绕点C 旋转60°后,AB 的中点D落在点D ′处,那么DD ′的长为 .16.在⊙O 中,直径AB 的长为6,OD ⊥弦AC ,D 为垂足,BD 与OC 相交于点E ,那么OE 的长为__________.17.不透明的布袋里装有4个白球和1个黑球,除颜色外其它都相同,从中任意取出2个球,那么取到1个白球和1个黑球的概率为________.18.在四边形ABCD 中,如果=,那么与相等的向量是__________. 三、(本大题共7题,第21、22、23、24题每题10分,第25、26题每题12分,第27题14分,满分78分) 19.化简:(3232---x x x -12-x x)11+÷x ,并求321-=x 时的值.20. 解方程组:⎪⎩⎪⎨⎧=-+-=-.012,02222y y x xy x )2()1(21.如图,在△ABC 中,∠ACB =90º,CD 是高,BD =1,∠CBD 的正切值为2.(1) 求AD 的长;(2) 如果点E 在以B 为圆心BA 为半径的弧上,CE //AB ,求sin ∠EBA 的值.22. 已知:如图,在△ABC 中,点D 、E 分别是边AB 、BC 的中点,点F 、G 是边AC 的三等分点,DF 、EG 的延长线相交于点H . 求证:(1)四边形FBGH 是平行四边形; (2)四边形ABCH 是平行四边形.ADBCE第21题图第22题图23.如图,在直角坐标系xOy 中,抛物线6622+-=ax ax y 与y 轴的公共点为A ,点B 、C 在此抛物线上,AB //x 轴,∠AOB =∠COx ,OC =52. (1) 求点A 、B 、C 的坐标; (2) 求抛物线的顶点坐标.24.两位学生在操场上练习跑步,甲学生比乙学生每分钟可多跑1个来回,甲学生跑21个来回比乙学生跑20个来回少用3分钟.问:甲、乙两位学生每分钟分别跑几个来回?25.如图,在四边形ABCD 中,∠B =90°,AD //BC ,AB =4,BC =12,点E 在边BA 的延长线上,AE =2,点F 在BC 边上,EF 与边AD 相交于点G ,DF ⊥EF ,设AG =x , DF =y . (1)求y 关于x 的函数解析式,并写出定义域; (2)当AD =11时,求AG 的长;(3)如果半径为EG 的⊙E 与半径为FD 的⊙F 相切,求这两个圆的半径.第25题图静安区2007学年第二学期教学质量检测九年级数学试卷参考答案及评分标准2008.4.3 一、选择题:(本大题共8题,每题3分,满分24分) 1.C ; 2.D ; 3.A ; 4.D ; 5.C ; 6.D . 二.填空题:(本大题共12题,满分48分)7.65a ; 8.–1; 9.7=x ; 10.0122=-+y y ; 11.23-≥x ; 12.xy 6=; 13.75; 14.50; 15.1; 16.1; 老17.52; 老18.22. 新17.52; 新18..三、(本大题共7题,第21、22、23、24题每题10分,第25、26题每题12分,第27题14分,满分78分)19.解:原式=11])1)(1()1)(3(3[+÷-+-+--x x x x x x x ……………………………………(3分)=)1(])1)(1()1)(1(1[+⋅-+--+-x x x xx x x ……………………………………(2分)=x -11.………………………………………………………………………(2分) 当32321+=-=x 时,………………………………………………………(1分)原式=311--=231-.………………………………………………………(2分) 20.解:由(1)得:0=x 或02=-y x .……………………………………………(2分) 由(2)得:01=-+y x 或01=+-y x .……………………………………(2分) 所以原方程组可化为:⎩⎨⎧=-+=;01,0y x x ⎩⎨⎧=+-=;01,0y x x ⎩⎨⎧=-+=;01,2y x y x ⎩⎨⎧=+-=.01,2y x y x …………………(2分) 解这四个方程组得原方程组的解为:⎩⎨⎧==;1,011y x ⎩⎨⎧==;1,022y x ⎪⎪⎩⎪⎪⎨⎧==;31,3233y x ⎩⎨⎧-=-=.1,244y x (4分) 21. 解:(1) 在△ABC 中, ∵∠ACB =90º, CD 是高,∴∠ACD +∠BCD =∠CBD +∠BCD =90º,∴∠ACD =∠CBD ,∴tan ∠ACD =tan ∠CBD =2. ………………………………(2分)在Rt △BCD 中,CD =BD CBD ∠⋅tan =12⨯=2. ………………………………(2分) 在Rt △ACD 中,AD =CD ACD ∠⋅tan =22⨯=4. ………………………………(2分) (2) 过点E 作EH ⊥AB ,垂足为H ,………………………………………………(1分)∵CE //AB ,CD ⊥AB ,∴EH =CD =2,…………………………………………(1分) ∵点E 在以B 为圆心BA 为半径的弧上,∴BE =AB =AD +BD =5,……………(1分)∴sin ∠EBA=52=BE EH .………………………………………………………(1分)22.证明:(1)∵点F 、G 是边AC 的三等分点,∴F 、G 分别是AG 、CF 的中点,∵点D 是AB 的中点,∴DF //BG ,即FH //BG .…………………………(3分) 同理: GH // BF .……………………………………………………………(1分) ∴四边形FBGH 是平行四边形.……………………………………………(1分)(2)联结BH ,交FG 于点O ,……………………………………………………(1分) ∵四边形FBGH 是平行四边形,∴OB =OH ,OF =OG .……………………(2分) ∵AF =CG ,∴OA =OC .………………………………………………………(1分) ∴四边形ABCH 是平行四边形.……………………………………………(1分) 23.解:(1)A (0,6),…………………………………………………………………(1分)∵AB //x 轴,∴点B 的纵标为6,∴66262+-=ax ax ,…………………(1分) ∵,0≠a ∴.3,021==x x ∴点B 的坐标为(6,3).…………………………(1分)∴OB =536322=+.51533sin ===∠OB AB AOB .…………………(2分) 过点C 作CD ⊥x 轴,垂足为D ,∵∠AOB =∠COD ,25152s i n s i n =⋅=∠⋅=∠⋅=A O B OC COD OC CD ,……………………(2分)∴OD =42022-=-CD OC =4.∴C (4,2).…………………………(1分) (2)∵点C 在此抛物线上,∴6461622+⋅-⋅=a a ,∴.21-=a ………(1分) ∴抛物线为632++-=x x y ,…………………………………………………(1分)∵433)23(649)493(22+--=+++--=x x x y ,……………………………(1分)∴抛物线的顶点坐标为(433,23).……………………………………………(1分)24.解:设乙学生每分钟跑x 个来回,…………………………………………………(1分)则甲学生每分钟跑)1(+x 个来回.……………………………………………(1分)由题意得320121-=+xx .………………………………………………………(4分)去分母,整理得020432=-+x x .…………………………………………(2分)解得,3101-=x 22=x .………………………………………………………(2分)经检验它们都是原方程的根,但310-=x 不符合题意.……………………(1分)当2=x 时,.31=+x答:甲两位学生每分钟跑3个来回,乙学生每分钟跑2个来回.………………(1分) 25.解:(1)∵AD //BC ,∠B =90º,∴∠EAG =∠B =90º,∴EG =.4222x AG AE +=+………………………………………………(1分)∵,AEEG AB FG = ∴FG =2242244x x AE EG AB +=+⋅=⋅.…………………(1分)∵∠DFG =∠EAG =90º,∠EGA =∠DGF ,∴△DFG ∽△EAG .…………(1分) ∴AG AE GF DF =,∴x xy 2422=+,……………………………………………(1分)∴y 关于x 的函数解析式为xx y 244+=,定义域为40≤<x .…………(2分)(2)∵△DFG ∽△EAG ,∴,AG FG EG GD =∴x x xGD 22424+=+,∴GD =x x 228+. (2分) 当AD =11时,11282=++xx x ,………………………………………………(1分)38,121==x x . …………………………………………………………………(1分) 经检验它们都是原方程的根,且符合题意,所以AG 的长为1或38.(3)当⊙E 与⊙F 外切时,EF =EG +FD =EG +FG ,∴FD =FG ,∵△DFG ∽△EAG ,∴∠E =∠AGE =∠FGD =∠GDF .∴AG =AE =2;……(1分)∴⊙E 的半径EG =22,⊙F 的半径FD =24.……………………………(1分) 当⊙E 与⊙F 内切时,EF = FD –EG ,∴32224444x xx x +-+=+,∵042≠+x ,∴3=14-x,∴1=x .………………………………………(1分)∴⊙E 的半径EG =514=+,⊙F 的半径FD =54.…………………(1分)所以⊙E的半径为22,⊙F的半径为42;或⊙E的半径为5,⊙F的半径为45.。
静安区2007学年下学期高三年级教学质量检测.
静安区2007学年下学期高三年级教学质量检测化学试卷(满分150分,时间120分钟)2008.04.说明:1.请将正确答案写在答题卷上。
答案不能写在试题卷上,写在试题卷上一律不给分。
2.本卷可能用到的相对原子质量H—1 C—12 N—14 O—16 F—19 Na—23 Mg—24 S—32 Cl—35.5 K—39 Ca—40 Mn—55 Fe—56 Br—80 I—127 Xe—131 Ba—137第Ⅰ卷(共66分)一、选择题(共10分,每小题2分,只有一个正确选项。
)1.石油中不含有A.烷烃B.烯烃C.环烷烃D.芳香烃2.氯化钠等盐可作融雪剂,科学原理是A.氯化钠密度大B.氯化钠价格低C.氯化钠熔点高D.氯化钠溶液熔点低3.胶体区别于其他分散系的本质特征是A.能通过滤纸B.不能通过半透膜C.分散质颗粒直径为1—100nm D.能发生丁达尔现象4.自然界的硫单质主要以S8的形式存在,将S8加热可得到S2、S4、S6等,S2、S4、S6、S8互称为A.同素异形体 B.同位素 C.同系物 D.同分异构体5.2008年3月20日媒体报导,挪威和荷兰正在开发一种新能源—盐能.当海水和淡水混合时,温度将升高0.1o C,世界所有入海口的这种能源相当于电力需求的20%。
海水和淡水混合时,温度升高最可能的原因是A.发生了盐分解反应B.发生了水分解反应C.由于浓度差产生放热D盐的溶解程度增大.二、选择题(共36分,每小题3分,只有一个正确选项)6.以下实验需在集气瓶里加少量水或细沙的是A.铜丝在氯气中燃烧B.铁丝在氧气中燃烧C.磷在氯气中燃烧D.氢气在氯气中燃烧7.以下物理量没有确切意义的是A.25o C时醋酸的电离度B.25o C时KNO3在水中的溶解度C.25o C时水的离子积D.0o C、101.3kPa时氢气的密度8.以N A表示阿佛加德罗常数,下列说法正确的是A. 30g甲醛和醋酸的混合物含N A个碳原子C.1.8g重水有N A个质子B. 1 mol Cl2与足量水反应时转移电子数为2N A个D.1 mol CaC2有N A个C-C键9.氯水不稳定,要现用现配,下列吸收氯气制备氯水的装置最合理的是水水水水NaOH溶液10.以下性质比较正确的是A.密度:1-氯己烷>1-氯戊烷>1-氯丁烷B.熔点:钠>钠钾合金>钾C.键长:碳碳单键>苯环中碳碳键>碳碳双键D.离子半径:Be2+>Li+>H-11.将m g铜片在空气中灼烧片刻,在石英管中用以下气体充分加热,固体仍为m g的是①CO ②H2③C2H5OH(g)④CH3CHO(g)A.①②③④B.①②C.①②③D.①②④12.13. 25o C时,将1mol/L的醋酸钠溶液用水稀释至0.1mol/L, 溶液中增大的是A.c(OH-) B.c(CH3COOH)C.c(H+) D.c(CH3COO-)/c(CH3COOH)14.已知C(s,石墨) →C(s,金刚石)- 1.9KJ,且知金刚石密度更大,则C(s,石墨)与C(s,金刚石)的比较,正确的是A.等质量时,后者能量更高更稳定B.等质量时,前者在空气中完全燃烧放热更多C.高温高压有利于前者转化为后者D.前者熔化只需破坏范德华力,后者则需破坏共价键15.下列离子方程式错误的是A.NH4Cl溶液与NaOH溶液混合NH4+ + OH-→ NH3·H2OB.氢氧化钡溶液与硫酸溶液反应得到中性溶液Ba2++OH-+H++SO42-→ BaSO4↓+H2OC.NaHCO3溶液与过量的Ba(OH)2溶液混合HCO3-+ Ba2+ + OH-→ BaCO3↓+H2OD.苯酚钠溶液中通入少量CO2气体O--+ CO2 + H2OH+ HCO316.关于电解CuCl2溶液的叙述正确的是A.负极发生还原反应B. 正极发生氧化反应C. 电解过程中,溶液的pH不变D. 电解过程中,阴极质量增加17.下列实验过程中产生的现象与对应的图形相符合的是①NaHSO3粉末加入HNO3溶液中②H2S气体通入SO2水溶液中③NaOH溶液滴入Ba(HCO3)2溶液中④CO2气体通入澄清石灰水中A .①②B.②③C.②④D.③④三、选择题(本题共20分,每小题4分,每小题有一个或两个正确选项。
上海市静安区年第二学期高三年级模拟检测数学(文、理)
上海市静安区2006年第二学期高三年级模拟检测数学试卷(满分150分,时间120分钟)考生注意:1. 各题号后未注明的试题是所有考生都要做的试题,如题号后注明(文)、(理)则分别表示该题供文、理考生做。
2. 可使用符合规定的计算器答题。
一、 填空题(本大题满分48分)本大题共有12题,每题4分,只要求直接填写结果. 1.已知2i i bi a +=+ (其中b a 、为实数,i 为虚数单位),则=+b a __________. 2.过点A (0,2)且与直线0123=-+y x 垂直的直线方程为________________. 3.若点)cos ,(sin ααP 在第二象限,则角α的终边在第 象限. 4.对于集合{}{}162≤-=≤--=a x x B x x x A 和,若B B A =⋂,则实数a 的取值范围是__________.5.在一个袋子里有18个红球和2个白球,现从中随机拿出3个,则其中至少有一个白球的概率是__________(用分数表示). 6.(理)方程12)232(log 2+=⋅-x x 的解x =____________.(文)方程)3(log )3(log )102(log 444x x x -++=+的解x =_____________. 7.(理)经过点A (a ,0)(a >0),且与极轴正方向夹角为5π的直线的极坐标方程为_____________.(文)不等式组⎪⎩⎪⎨⎧≥≤+≥+-0001y y x y x 表示的区域的面积是___________.8.(理)函数)32cos()3sin(ππ++=x x y 的值域是_____________.(文)已知某工程由下列工序组成,则工程总时数为_________天.工序a b c d e 紧前工序 —— —— a 、b a c 、d工时数(天)34 25 1 9.(理)设21x x 、是方程035122=+-x x 的两个根,则=+21x x __________. (文)设C x ∈,则方程0522=+-x x 的根为 ___________.10.已知函数)(x f 是定义在R 上的奇函数,且)(x f y =的图像关于21=x 对称,则___________)5()4()3()2()1(=++++f f f f f .11.已知无穷等比数列{}n a (n 为正整数)的首项211=a ,公比21=q .设2122321-+++=n n a a a T ,则n n T +∞→lim =_____________.12.已知命题:椭圆192522=+y x 与双曲线151122=-y x 的焦距相等.试将此命题推广到一般情形,使已知命题成为推广后命题的一个特例: 二、 选择题(本大题满分16分)本大题共有4题,每题都给出四个结论,其中有且只有一个结论是正确的,必须把正确结论的代号写在题后的圆括号内,选对得 4分,否则一律得零分.13. 已知βα,均为锐角,p :)sin(sin βαα+<;q :2πβα<+.则p 是q 的……( )(A )充分非必要条件 (B )必要非充分条件 (C )充分必要条件 (D )既非充分又非必要条件14.已知直角坐标平面上四点 A 、B 、C 、D ,)27()65()21(-=-==,,,,,CD BC AB ,则一定共线的三点是 …………………………………………………………( ) (A )A 、B 、C (B )B 、C 、D (C )A 、C 、D (D )A 、B 、D (说明:)(21a a a ,=与{}21a a a ,=表示意义相同)15.(理)已知复数i z i z 21,22221--=+=在复平面上对应的点分别为A 、B ,将复平面沿虚轴折起,使两个半平面互相垂直,此时A 、B 两点之间的距离是( ) (A )4 (B )5 (C )6 (D )7(文)已知复数i z i z 22,2221--=+=在复平面上对应的点分别为A 、B ,点B 绕点A 逆时针旋转90︒到达点C .则点C 所对应的复数为……………………( ) (A )i 222- (B )i 26- (C )i 42+- (D )i 22-16.某水电站的蓄水池有2个进水口,1个出水口,每个进水口进水量与时间的关系如图甲所示,出水口出水量与时间的关系如图乙所示.已知某天0点到6点进行机组试运行,试机时至少打开一个进水口,且该水池的蓄水量与时间(时间单位:小时)的关系如图丙所示:丙乙甲56436521V (万米3)O(时间)V (万米3)O(时间)11V (万米3)(时间)O给出以下三个判断:①0点到3点只进水不出水;②3点到4点,不进水只出水;③4点到6点不进水不出水. 则上述判断中一定正确的是………………………( )AB CDE AB CDE A B C D(A )① (B )② (C )①③ (D )②③三、解答题(本大题满分86分)本大题共有6题,解答下列各题必须写出必要的步骤. 17. (本题满分12分)(理)如图所示,已知长方体ABCD —A 1B 1C 1D 1中,AC 与BD 交于E 点,且AB =AD =2,两条异面直线A 1D 与AC 所成的角的大小为1010arccos,求:长方体ABCD —A 1B 1C 1D 1的体积.(文)本题共有2个小题,每小题满分6分. 如图所示,已知正四面体ABCD 的棱长为2,点E 为棱AD 的中点,求:(1)正四面体ABCD 的体积;(2)直线CE 与平面BCD 所成的角的大小(用反三角函数值表示). 18.(本题满分12分) 本题共有2个小题,每1小题满分6分. 在ABC ∆BC =30,外接圆的半径R =17. (1)求A ∠的大小;(用反三角函数值表示) (2)(理)若112=⋅AC AB ,求ABC ∆的周长.(文)若112=⋅AC AB ,求ABC ∆的面积.19.(本题满分14分) 本题共有3个小题,第1小题满分5分,第2小题满分6分,第3小题满分3分.某种洗衣机在洗涤衣服时,需经过进水、清洗、排水、脱水四个连续的过程.假设进水时水量匀速增加,清洗时水量保持不变.已知进水时间为4分钟,清洗时间为12分钟,排水时间为2分钟,脱水时间为2分钟.洗衣机中的水量y (升)与时间x (分钟)之间的关系如下表所示: x 0 2 4 16 16.5 17 18 … y 0 20 40 40 29.5 20 2 …请根据表中提供的信息解答下列问题:(1)试写出当x ∈[0,16]时y 关于x 的函数解析式,并画出该函数的图像;(2)根据排水阶段的2分钟点(x ,y )的分布情况,可选用b xa y +=或d x c y +-=2)20((其中a 、b 、c 、d 为常数),作为在排水阶段的2分钟内水量y与时间x 之间关系的模拟函数.试分别求出这两个函数的解析式;(3)请问(2)中求出的两个函数哪一个更接近实际情况?(写出必要的步骤) 20.(本题满分14分)本题共有2个小题,第1小题满分6分,第2小题满分8分.设函数)10(3)(≠>+=a a a a x f x 且其中. (1)求函数)(1x fy -=的解析式;y (升) x (分)O 20(2)(理)设)(log )(a x x g a -=,是否存在实数a ,使得当]3,2[++∈a a x 时,恒有1)()(1≤+-x g x f 成立?若存在,求出a 的取值范围;若不存在,请说明理由.(文)设)(log )(a x x g a -=,当10<<a 时,求函数)()()(1x g x fx h +=- 在闭区间]3,2[++a a 上的最小值与最大值.21. (本题满分16分)本题共有3个小题,第1小题满分6分,第2小题满分4分,第3小题满分6分.一个数表如图所示:对于任意的正整数n ,表中第n +1行中的数均由第n 行中的数按相同规律生成得到.设n K 表示位于第n 行的数的个数,n S 表示第n 行各数的和. (1) 试求6K 、6S ; (2) 求n S ;(3) 若ni a 表示数表中第n 行第i 个数,试用ni a 表示第n +1行中由ni a 所生成的数(写出它们之间的关系式).22.(本题满分18分)本题共有3个小题,第1小题满分4分,第2小题满分6分,第3小题满分8分.已知动圆过定点)0,21(F ,且与定直线21:-=x l 相切. (1)求动圆圆心M 的轨迹方程;(2)设点O 为坐标原点, P 、Q 两点在动点M 的轨迹上,且满足OP ⊥OQ ,OP =OQ ,求等腰直角三角形POQ 的面积;(3)(理)设一直线l 与动点M 的轨迹交于R 、S 两点, 若1-=⋅OS OR 且14422<≤RS ,试求该直线l 的倾斜角的取值范围.(文)设过点)0,21(F 的直线l 与动点M 的轨迹交于R 、S 相异两点,试求△ROS 面积的取值范围.第一行 1第二行 -1 4 第三行 1 2 - 4 7第四行 -1 4 -2 5 4 -1 -7 10静安二模参考解答与评分建议一、填空题1. 0;2. 2x -3y+6=0;3. 四;4. 21≤≤-a ;5.9527; 6.(文理)-1; 7.(理))5(sin 5sinθππρ-=a ;(文)1/4;8.(理)]432,432[-+-;(文)9; 9.(理)1; (文)2i 1x ±=10.0; 11.4/15;12.椭圆)161(a 16a y a x 22222>=-+与双曲线)16b 1(0b16y b x 22222<<=--的焦距相等; 椭圆12222=+b y a x 与双曲线)(122222222d c b a d y c x +=-=-的焦距相等二、选择题13.B 14.D 15.(文理)B 16.A 三、17.(理)[解法一]如图建立空间直角坐标系, …(2分) 由题意,得A(0,0,0),C(2,2,0),)0,2,0(D , …(4分)设A 1点的坐标为),0,0(z )0(>z ,则{}0,2,2=AC ,{}z D A -=,2,01 …(6分) 设θ的夹角为与AC D A 1则04cos 42221>=+⋅=⋅θz AC D A , 因为A 1D 与AC 所成的角的大小为1010arccos1010cos =∴θ…(8分) 解方程441010222=+⋅z 得4=z ,故1AA 的长度是4, …(10分)又11111AA AD AB V D C B A ABCD ⨯⨯=--,AB CD EA 1B 1CD xyzABCDEA 1B 1C 1DF 因此长方体ABCD —A 1B 1C 1D 1的体积是16 …(12分)[解法二]过D 引AC 的平行线,交BA 的延长线于F ,则∠A 1DF 是异面直线A 1D 与AC 所成的角。
上海市2007年高三年级联合考试--文综
上海市2007年高三年级3月联合考试文科综合能力测试本试卷分为第Ⅰ卷和第Ⅱ卷两部分。
满分150分,考试时间120分钟。
第Ⅰ卷(共72分)考生注意:1.答第Ⅰ卷前,考生务必将试卷和答题卡上用钢笔或圆珠笔清楚填写学校、班级、姓名、学号。
2.第Ⅰ卷(1—24小题)为单选题,由机器阅卷,答案必须全部涂在答题卡上。
考生应将代表正确答案的小方格用铅笔涂黑。
注意试题题号和卡编号一一对应,不能错位。
答案需要更改时,必须将原选项用橡皮擦去,重新选择,答案不能写在试卷上,写在试卷上一律不给分。
1.在26届国际天文学会联合会大会上,科学家们对冥王星是否应属于行星的问题争执不下,最后只好通过投票的方式来决定,这表明()A.意识对客观事物的正确反映B.意识能够反作用于客观事物C.世界上只有尚未被认识的事物,没有不可认识的事物D.同一事物在不同人的头脑里可以有不同的反映2.最近由于受伊朗核问题等一系列时件的影响,国际时场原油价格发生波动。
国际市场原油价格的变化是()①由原油内在的价值决定的②由市场供求决定的③受经济波动的影响④受国际政治因素的影响A.①②③B.①③④C.②③④D.①②④3.“十一五”期间,必须继续把解决好“三农”问题作为全党工作的重中之重。
大力促进粮食增产和农民增收,免收农村义务教育阶段中小学生的全部学杂费,进一步推进农民工工伤保险和大病治疗保障工作等。
这体现了()①我国把农村工作作社会主义现代化建设的中心②我国党和政府坚持对人民负责的原则③我国社会主义民主的本质④社会保障基金全部由国家财政支出A.①②B.①④C.②③D.②④4.金猪贺岁迎新春,在辞旧迎新的时刻不少人选择去饭店轻松享受合家团聚。
年夜饭预定逐渐升温表明()①人们的消费水平逐步提高②人们的商品性消费比重相应增大③我国的恩格尔系数提高④随着社会和经济发展人们生活水平有了提高A.①②③B.①③④C.②③④D.①②④5.近年来,在国外发生的涉及中国公民的突发事件中,人们总能发现中国驻外领事馆工作人员的身影。
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静安区2007学年第二学期高三年级模拟检测英语试卷2008. 4.本试卷分为第I卷(第1-11页)和第II 卷(第12页)两部分。
全卷共12页。
满分150分。
考试时间120分钟。
第I卷(共 105 分)考生注意:1.答第I卷前,考生务必在答题卡和答题纸上用钢笔或圆珠笔清楚填写学校、姓名、准考证号,并用铅笔在答题卡上正确涂写准考证号。
2.第I卷(1-16小题,25---84小题)由机器阅卷,答案必须全部涂写在答题卡上。
考生应将代表正确答案的小方格用铅笔涂黑。
注意试题题号和答题卡编号一一对应,不能错位。
答案需要更改时,必须将原选项用橡皮擦去,重新选择。
答案写在试卷上一律不给分。
第I卷中的第17-24小题和第II卷的试题,其答案写在答题纸上,如写在试卷上则无效。
I. Listening ComprehensionSection A: Short ConversationsDirections: In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. The traffic is too heavy. B. He can’t get up that early.C. There is no bus that early.D. He is always late.2. A. In her office. B. At home.C. In a phone box.D. In a supermarket.3. A. Jane is going to be an accountant.B. Jane is eager to go home for the vacation.C. Jane won’t spend the summer at home.D. Jane is already on her way home.4. A. Tuesday morning. B. Tuesday afternoon.C. Wednesday morning.D. Wednesday afternoon.5. A. They will meet Mike on the way. B. They will have an early start.C. Mike is usually late.D. Mike may not come tomorrow.6. A. One-fourth of the book. B. Three-fourths of the book.C. Half of the book.D. Forty-one pages.7. A. It was even better than what it is. B. It is even better than what it was.C. It is better than what people say.D. It is as good as what it used to be.8. A. Doctor and nurse. B. Boss and secretary.C. Dentist and patient.D. Salesman and customer.9. A. She has no desire to teach.B. She doesn’t want to graduate.C. She likes all her teachers equally.D. She has no idea where to go.10. A. He wants to say good-bye at the airport.B. He would like her to take a day off.C. He likes to watch the planes take off.D. He thinks she should take the bus to the airport.Section B:PassageDirections: In Section B, you will hear two short passages, and you will be asked three questions on each of the passages. The passages will be read twice but the questions will be spoken only once. When you hear a question, read the four possible answers in your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. Whether he is single or married. B. How much he earns.C. How long he has worked.D. How many children he has.12. A. He wanted to express his gratitude. B. He wanted to ask for more money.C. He found his tax was too high.D. He thought he should pay more.13. A. Five pounds. B. Fifty poundsC. Forty-five pounds.D. Sixty pounds.Questions 14 through 16 are based on the following news.14. A. 23. B. 24. C. 25. D. 34.15. A. To buy sports facilities. B. To buy blackboards.C. To build new primary schoolsD. To make TV programmes.16. A. The United States. B. Sweden.C. Spain.D. Four different countries.Section C: Longer ConversationsDirections: In Section C, you will hear two longer conversations. The conversations will be read twice. After you hear each conversation, you are required to fill in the numbered blanks with the information you have heard. Write your answers on your answer sheet.Blanks 17 through 20 are based on the following conversation.Complete the form. Write ONE WORD for each answer.Blanks 21 through 24 are based on the following conversation.Complete the form. Write NO MORE THAN THREE WORDS for each answer.II. Grammar and VocabularySection ADirections: Beneath each of the following sentences there are four choices maked A, B, C andD. Choose the one answer that best completes the sentence.25. They have a clear view _____ him and he can hold the important eye contact.A. ofB. overC. withD. at26. Everyone I know who has tried it has hurt _____somehow.A. itselfB. herselfC. themselvesD. ourselves27. The war continues as a fresh UN appeal for a ceasefire_____.A. rejectedB. is rejectedC. has rejectedD. has been rejected28. Her appearance has changed a lot after the cosmetic surgery and I ___ not recognize her.A. mustB. canC. needD. will29. When her younger brother was being bullied she _____ to his defense.A. leaptB. had leaptC. was leaptD. had been leapt30. In contemporary times, _____ the difference between wild and farm-raised waterfowl (水禽) more dramatically apparent than with goose.A. is nowhereB. nowhere isC. nowhere it isD. it is nowhere31. When full _____, the Blue Whale measures 110 feet in length.A. is grownB. growingC. grownD. grows32. In fact, many of our guests ask for accommodations here _____they come.A. at timeB. first timeC. for the first timeD. each time33. There are several tests you can apply to find out_____ .A. how is an old treeB. how old is a treeC. how is old a treeD. how old a tree is34. Sandy could do nothing but ______ to his teacher that he was wrong.A. admittingB. admittedC. admitD. to admit35.These stones extend down the watercourse, _____ water flows with the aid of a simplesubmersible pump.A. in whichB. at whichC. on whichD. over which36. Please read the _____ information before taking this medication.A. accompanyingB. accompaniedC. to accompanyD. accompany37.It was due to luck _____ judgment _____ the driver succeeded in avoiding an accident.A. better than … whenB. other than … whenC. more than … thatD. rather than … that38. In order to search for the escaped prisoner, the police decided to question _____ comesalong the road.A. whoB. whomC. whoeverD. whomever39. Nobody believed his reason for being absent from the class_____ he had to meet hisuncle at the airport.A. whyB. thatC. whereD. because40. The book discusses _____ the ideal female form has been for different centuries andcultures.A. thatB. howC. whichD. whatSection BDirections: Complete the following passage by using the words in the box.Each word can only be used once. Note that there is one word more than you need.Some desert animals can survive the summer heat and dryness because they are very unusual. The camel, for example, can __41__and bear an increase in the temperature of its body and its blood of 9℃ without anything bad happening to it. In addition, it can drink a lot of water at one time; then store enough water in parts of its body to supply its needs for two weeks or more. The kangaroo rat, on the other hand, gets all the water it needs from water that it produces when it __42__. However, most animals need to maintain a __43__ constant body temperature, and will die if it rises more than 5℃. Therefore, they need to find some way tostay away from the heat of the summer sun. Nor can many animals either store or produce water in their bodies, as the camel and kangaroo rat can. So they must find ways to keep their bodies from losing water because of the heat. Because very few desert animals can survive the high temperature of a __44__summer’s day, most of them are __45__only in the night. Only after the sun has __46__does the desert come fully to life. The night is relatively cool, and the darkness provides__47__, not only from the sun, but also from other animals and from the birds. So the coming of darkness is the __48__for the large majority of animals and insects to start again their search for water and food. When morning comes, most of them seek shelter again: many go underground; __49__ all find some dark and cool places where they can keep away from the sun’s heat.III. Reading ComprehensionSection ADirections: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.If you walk through the streets of any big city at six or seven in the morning, the chances are you will see women hurrying along, pushing prams(婴儿推车). You may see more than one woman 50 on the same door and, as it opens, quickly kiss the child, hand 51 a package of nappies and hurry off down the street to clock on the early 52 in an office, leaving their children to a child-minder ——a woman who may be doing the job legally or illegally, well or 53 . Brian Jackson, director of the Child-Minding Researching Unit, and his 54 have done a great deal of work in finding out what it means for a child to spend the first years of life 55 the care of a child-minder.By law, anyone who looks after a child for more than two hours a day and gets paid must be registered in the government. 56 the punishment is a 50 pounds 57 . Local authorities are responsible for the 58 and supervision of minders. The regulations 59 adequate provision for fire, safety and health. Very few minders can 60 these. Yet, not many boroughs(自治区)give 61 assistance. “This means, ” Brian Jackson says, “that when you have one registered minder tested and proved by the local authorities, you can be sure that you will get a dozen unregistered, 62 minders at work. ”The researchers found themselves forced into the role of private investigators when they conduct their 63 . Getting up early to do a “Dawn Watch” following mothers through cold, dark streets and 64 where they left their babies, Jackson says, was a long, slow process.50. A. knock B. stop C. stick D. insist51. A. out B. at C. off D. over52. A. course B. shift C. round D. turn53. A. badly B. good C. pretty D. great54. A. fellows B. friends C. workers D. colleagues55. A. for B. to C. on D. in56. A. Therefore B. However C. Otherwise D. Moreover57. A. fee B. charge C. fine D. pain58. A. registration B. education C. supply D. payment59. A. require B. demand C. insist D. describe60. A. pay B. offer C. afford D. do61. A. legal B. financial C. formal D. traditional62. A. proved B. educated C. illegal D. bad63. A. oversight B. survey C. view D. statistics64. A. catching B. noting C. glimpsing D. writingSection BDirections: Read the following four passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)Walter had been a good high school student but not an excellent one. He got almost all Bs and a few Cs. He had done his homework most of the time and once in a while he had skipped class (旷课). When he got to Furnell, he didn’t change his study habits. As a result he got a bad grade on the first test in chemistry ——65 percent, or D. When the teaching assistant gave back his quiz, he also gave him some advice.“Look, Walter, I know you’re having problems with this course”, Gordon told Walter, “Remember that the teacher requires attendance. In other courses it might be okay to skip class once in a while, but not in this one. A good grade in chemistry depends on attendance, good homework, and going to lab every week. If you continue to do the quiz poorly, you’re going to have problems. ”Walter thought about his advice a lot over the weekend. “The teaching assistant was serious. I’m doing poorly, and I might fail chemistry. In that case I would have to leave Furnell. I don’t want to go home and find a job.” From that weekend he started studying very hard. In addition, he started to do all his assignments and to go to lab every week. After a month, he was able to answer almost all the quiz questions correctly.“I’m happy to see that you’re doing better in this course”teaching assistant said to Walter.“Yeah, me too. It’s a challenge to study every afternoon when I feel like playing football or video games. But now I know that chemistry is not an impossible course. ”65. During his first period in university, Walter______.A. goes to class every dayB. does only a small part of his homeworkC. skips class once in a whileD. studies very hard66. What advice did the teaching assistant NOT give Walter?A. Take a literature course.B. Start studying a lot.C. Do his homework.D. Go to class every day.67. If Walter failed chemistry at the end of the term, what would he need to do?A. Study hard for his other courses.B. Play video games every afternoon.C. Look for work in his hometown.D. Go to lab every week.68. In this reading, what was a challenge for Walter?A. To skip class once in a while.B. To change his study habits and do well in chemistry.C. To find a job at home.D. To major in chemistry.(B)69. During summer time, the front of the home may look _________.A. greenB. whiteC. redD. black70. Which of the following statements about the house is NOT true?A.You will spend extra money to build a room in the garage after buying thehouse.B.You can have enough room to enlarge your house after you buy it.C.You don’t need to water the plants in the garden by yourself.D.If you buy the house, you can also have the dishwasher and carpet.71. Wh at does the “Wheelchair Access” probably mean?A.It’s a kind of sidewalk built for disabled people.B.It’s an entrance to a house built for the disabled people.C.It’s a street built for the disabled people to have a walk.D. It’s a special path for the disabled people to get to the garage.(C)China Daily ——Huge investments go into the venue construction, which seem to be for nothing but the Games’ half-month glory alone. Moreover, large sums of money are required for their maintenance following the Games.This is a universal problem faced by all host cities. Moscow, Los Angeles, Seoul, Barcelona, Atlanta, Sydney and Athens have all had the same headache. The only difference lies in the degrees of intensity. Beijing, the next host city, is bound to find the same problem once the 2008 Olympics conclude.How can this be avoided? What can Beijing learn from its predecessors’ experiences and lessons? Athens, the immediate predecessor, is doing something about it and may offer some useful ideas for the Chinese capital in this regard.A company, the Greek Olympic Property SA, was founded in 2002 to handle venue affairs after the Athens Games. It began operating in 2004 and has been involved in the post-Olympic development and management of facilities, said Christos Hadjiemmanuil, president of the company, in an interview with a group of Chinese journalists last week in Athens.The operation of the company is governed by market forces much like privately owned firms, although the Greek Olympic Properties SA and all the venues are owned by the state, according to Hadjiemmanuil.The company oversees the management of 15 Olympic complexes (or 22 individual Olympic facilities) while the other two firms are in charge of the rest.All 15 complexes have been put forward for international bids for their post-Olympic use. The first-phase bidding has been completed but the outcome has yet to be announced. The second phase will be conducted at the end of February and the third phase at the end of March, according to Hadjiemmanuil.Fortunately, the venue construction contractors are currently responsible for the maintenance and management of the venues because the signed contracts stated that thecontractors should bear the maintenance costs of the venues in a given period of time after the Games, he said.72. According to the passage, ________ is/are probably required urgently after the OlympicGames are held.A. universal cooperationB. huge investmentsC. venue constructionD. money for maintenance73. From the passage, we can infer that ________.A. the Olympic Games will take place in different cities in turns, such as Moscow, LosAngeles, etc.B. Beijing will face many problems the 2008 Olympic Games will bringC. the city that hosts Olympic Games often face a lot of problems after the GamesD. the Beijingers are good at learning its predecessors’ experience s and lessons74. Which of the cities have better solved the post-game problems?A. Moscow.B. Beijing.C. Athens.D. Atlanta.75. Which is NOT true according to this passage?A. The Greek Olympic Property SA was founded to solve the headache caused by the 28thOlympic Games.B. Only the Greek Olympic Property SA is involved in the management of the Olympicfacilities.C. The Greek Olympic Property SA is governed by the Greek government, but it isoperated according to market economy.D. In a certain period of time after the 2004 Olympic Games, the Government of Athenswill not see to the repairs of the facilities.(D)Levittown was the name given to three suburban developments constructed in the post-World War II decades by Levitt and Sons, the most important private builder of this period. Using new mass production techniques they had learned while building housing for military personnel during the Second World War, they turned home building from a cottage industry into a major manufacturing process.During World War II, they received government contracts to build homes for war workers. Under deadline pressure, they developed mass production methods to build houses quickly. These techniques were carried over to their postwar suburban developments. On May 7, 1947, William Levitt announced his plans to build 2,000 houses in a former potato field in the state of New York. Then, by the time this Levittown was completed in 1951, it contained 17,450 homes for 75,000 people in New York. Levitt eventually built two more Levittowns, in the states of Pennsylvania and New Jersey. Each contained the same curving streets, community pools, and neighborhood parks, playgrounds as the first development did.Some observers criticized the monotonous uniformity of the Levittowns, charging thatthey are just the symbol of materialism, but Levittowns were overwhelmingly welcomed by the public. They were cheap, comfortable, efficient, and ideal for young people just starting out in life. Thousands of middle class people, especially some young couples, crowded in city apartments or still living with their parents, rushed to purchase them. Fourteen hundred contracts were signed in one day in 1949.Levittown symbolized the most significant social trend of the postwar era in the United States ——the flight to the suburbs. The resulting massive shift in population from the central city to the suburbs was accompanied by a baby “boom”that started after soldiers returned home from the Second World War and got married. By 1960, one-third of the nation’s population lived in the suburbs. The nation underwent its greatest increase in population since 1910.76. What does the passage mainly discuss?A. Levittown was built by William Levitt with the mass-production method.B. Levittown served as an ideal and leading example of social changes in the U.S. after theSecond World War.C. Increases in the population of the United States after the war.D. Why there was a housing shortage after the Second World War.77. What was the original reason for Levitt to use the method of mass production to buildhouses?A. In order to reduce the cost of the construction.B. He wished young Americans could have their own houses after the war.C. There was a population shift from central city to the suburbs.D. He was forced to do so because of the lack of time.78. One of the reasons Levittowns were criticized by some observers was that .A. the land on which the first Levittown was built was previously used for agricultureB. the methods Levitt used for construction were new to themC. the Levittown houses were lack of varietyD. home building shouldn’t be changed from a cottage industry into a majormanufacturing process79. What can be inferred from the passage?A. Levitt’s houses led to the great shift in population after the Second World War.B. William Levitt met the postwar need of young Americans to raise their childrenoutside the central city.C. Levittown became the world’s most perfectly planned community.D. The population of the United States increased sharply after the Second World War.Section CDirections: Read the following text and choose the most suitable heading from the list A-F for80.Telepathy is the ability to communicate without the use of the five senses (sight, hearing, touch, smell, taste). It’s an instinct that can be woken up in times of emergency or need. When we feel that something is happening or about to happen by instinct, we’re using resources within the unconscious mind. When the resources of two persons’ unconscious minds link together into the same frequency, we call it Telepathy.81.the ringing phone, you are probably a good receiver. If you think of a person and he/she calls you, you are most likely to be better at sending.82.You can easily put your abilities to the test. Think of somebody and will him or her to contact you. Be patient. The other person may not be a good receiver, but they should contact you much earlier than would normally be expected. Or whenever the phones ring, but try “feeling” who is contacting you. Don’t guess, but try to feel it with your mind. However, if neither of these works for you, it doesn’t mean that you have no ability of telepathy. As mentioned earlier, telepathy is most likely to turn up in case of emergency.83.other and find that their dreams had a clear connection. These people are probably linking to each other’s unconscious mind.84.The more people spend time together, the more likely they are to be able to link up to the other’s mind, especially when separated. There are two reasons for this. One is that they understand the other’s mind through time spent together; the other is that there is usually a strong desire to communicate. A mother will often sense that her child is in danger. This is due to the child’s eagerly wanting his or her mother, knowing that this person who would alwayswant to be there for them, and the mother’s deep desire to protect her child from ha rm.第II卷(共45分)I. TranslationDirections:Translate the following sentences into English, using the words given in the brackets.1.学校图书馆的新书受到了所有同学的欢迎。