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Delta 水龙头产品说明书
2 5/16"58mm12"305mm9 3/8"238mm7 7/16"188mmFor 1/2" NPSM Male Thread)Compression FittingsFor Clarity 3/8" NPT x 32" RiserFinger HookItems Not Shown For 5/8" O.D. Copper Tubing BushingLock Nut &Mounting SurfaceSteel Supply Hoses18" Flexible Stainless EasyInstall (Remove Compression Nut Quarter-TurnEterna Cartridges w/Spring Checks &Lever Handles w/ Color Coded Indexes __________________________Date_________Product Specifications:Model No.Item No.T&S BRASS AND BRONZE WORKS, INC.B-0111-CModel Specified_____________________ Quantity______ Customer/Wholesaler______________________________ Contractor_______________________________________Flexible Hose & 0.65 GPM Low Flow Spray Valve12" L-Tube, Flexible Stainless Steel Supply Hoses, 32" Riser, 20" Travelers Rest, SC 296902 Saddleback Cove / P.O. Box 1088Quarter-Turn Eterna Cartridges w/ Spring Checks, Lever Handles, Pre-Rinse Unit: EasyInstall Single Hole Deck Mount Mixing Faucet, Architect/Engineer_________________________________Travelers Rest, SC: 800-476-4103 • Simi Valley, CA: 800-423-0150 • Fax: 864-834-3518 • This Space for Architect/Engineer ApprovalJob Name Product Compliance:ASME A112.18.1 / CSA B125.1NSF 61 - Section 9NSF 372 (Low Lead Content)2019 DOE PRSV - Class IRough-In Requirement:Ø 1 1/2" [38mm] Mounting HoleLow Flow 0.65 GPM Deck FlangeØ 2 1/4" [57mm]Spray Valve B-0107-C B-0020-HFlexible Stainless Steel Hose38 9/16"980mm1 7/8"48mm Maximum ThicknessITEM NO.SALES NO.DESCRIPTION1B-0107-C 0.65 GPM Low Flow Spray Valve 2010476-45#27 Washer3000907-45Spray Valve Hold Down Ring 4002987-40Grip Handle5001014-45Washer, B-0100 Hose Barrel6B-0020-H2A 20" Flexible Stainless Steel Hose, Less Handle7B-0020-H 20" Flexible Stainless Steel Hose 8002882-4012" L-Tube 9004R Finger Hook10000376-403/8" NPT x 32" Riser11EZ-K EasyInstall Kit: Nut, Bushing, O-Ring & Lock Washer 12001065-45O-Ring13014200-45Star Washer, Anti-Rotation14012442-40NS Quarter-Turn Eterna Cartridge w/ Spring Check, LTC15002711-40NS Quarter-Turn Eterna Cartridge w/ Spring Check, Handle, Blue Index & Screw, LTC16018506-19NS Blue Button Index, Press-in 17002290-45Lock Washer 18000965-45Lock Nut19012534-4518" Flexible Supply Hose (2)20012443-40NS Quarter-Turn Eterna Cartridge w/ Spring Check, RTC21001638-45NS Lever Handle (New Style)22002712-40NS Quarter-Turn Eterna Cartridge w/ Spring Check, Handle, Red Index & Screw, RTC 23000925-45Lab Handle Screw24001193-19NSRed Button Index, Press-in1234567282423222120171819910131211141516Model No.Item No.T&S BRASS AND BRONZE WORKS, INC.Travelers Rest, SC: 800-476-4103 • Simi Valley, CA: 800-423-0150 • Fax: 864-834-3518 • B-0111-C2 Saddleback Cove / P.O. Box 1088Travelers Rest, SC 29690Product Compliance:ASME A112.18.1 / CSA B125.1NSF 61 - Section 9NSF 372 (Low Lead Content)2019 DOE PRSV - Class IPre-Rinse Unit: EasyInstall Single Hole Deck Mount Mixing Faucet, Quarter-Turn Eterna Cartridges w/ Spring Checks, Lever Handles, 12" L-Tube, Flexible Stainless Steel Supply Hoses, 32" Riser, 20" Flexible Hose & 0.65 GPM Low Flow Spray ValveProduct Specifications:。
重力传感器产品说明书
HEAVY-DUTY INDUSTRIAL SWITCHESSINgLE oR DUAL SETPoINT,PSW-700 SeriesDual external setpoint calibrationadjustment PSW-700 Series pressure switches are built for the rugged industrial setting. The internal setpoints allow adjustments while keeping the electrical component isolated from the environment. Both the internal and external setpoints have a range scale, allowing fast, easy setup.PSW-722, ±10 inH 2O range, shown much smaller than actual size.U Division 1 RatingU Single or Dual Setpoints, Tamper ResistantU Heavy-Duty Enclosure U Rated NEMA 4X, 7, 9 (IP66)U Terminal Block Wiring U High-TemperatureOperation to 200°C (392°F) Process Temperature (Stainless Steel Model Only)PSW-710, 715-7171/4 NPT1/4 NPT (F)PSW-731-7351/2 NPTPSW-702-704, 708, 709SPECIFICATIONSApprovals: UL listed; Class I, Division 1 and 2, Groups B, C and D; Class II, Groups E, F and G; Class III Repeatability: ±1% range Process Temperature:Stainless Steel: -57 to 204°C (-70 to 400°F)Brass: -40 to 149°C (-40 to 300°F) Buna-N: -23 to 93°C (-10 to 200°F)Ambient Temperature:-50 to 71°C (-58 to 160°F), except for models 703 to 705, which are -18 to 71°C (0 to 160°F). Setpoint typically shifts less than 1% of range for a 28°C (50°F) ambient temperature change.Shock: Setpoint repeats after 15 g, 10 ms durationVibration: Setpoint repeats after 2.5 g at 5 to 500 HzOutput: 1 SPDT or 2 SPDT 15 A 125/250/480 VacEnclosure: Low copper-cast epoxy-coated aluminumElectrical Connection: 3⁄4 NPT conduit; internal screw terminals Dimensions:psi Ranges:230 (max) H x 125 W x 108 mm D (9 x 4.9 x 4.3") H 2O Ranges:W and D = 153 mm (6") Weight: Approx. 1.7 kg (4 lb)PSW-721-72INDUSTRIAL SWITCHES PSW-707, 0 to 500 psirange, shown smallerthan actual size。
冀教版六年级英语上册期中测试题及答案
满分:100分时间:60分钟得分:听力部分一、听录音,选出你所听到的单词。
(10分)( )1.A. Mr. B. Ms. C. Mrs.( )2.A. clock B. card C. class( )3.A. time B. table C. them( )4.A. home B. house C. him( )5.A. dirty B. driver C. do二、听录音,写单词,补全句子。
(10分)1. We have nine today.2. I have a small .3. My bedroom is on the second .4. It s past ten now.5. I go to school on foot.三、听录音,判断下列句子与所听内容是(T)否(F)相符。
(10分)( )1. Here s the kitchen.( )2. What would you like for breakfast?( )3. The tomatoes are in the fridge.( )4. I live too far from my school.( )5. I often help my mother on Sunday.四、听录音,选择与所听内容相符的图片。
(10分)( )1. A. B.( )2. A. B.( )3. A. B.( )4. A. B.( )5. A. B.笔试部分五、给单词选择正确的汉语意思。
(5分)( )1.Mr. A. 先生 B. 太太 C. 女士( )2.put A. 穿 B. 有 C. 放;安置( )3.always A . 总是;永远 B. 有时 C. 从不( )4.him A. 他们 B. 他 C. 她( )5.breakfast A. 早餐 B. 午餐 C. 晚餐六、看图片,写单词,补全句子。
(5分)1. She is so .2. We have anew .3. We have a big .4. Look atthe .5. This is an English .七、按要求写单词。
重庆市巴蜀中学2020届高三高考适应性月考卷(十)文科数学
巴蜀中学2020届高考适应性月考卷（十）文科数学注意事项：1．答题前，考生务必用黑色碳素笔将自己的姓名准考证号、考场号、座位号在答题卡上填写清楚． 2．每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号．在试题卷上作答无效．3．考试结束后，请将本试卷和答题卡一并交回．满分150分，考试用时120分钟．一、选择题（本大题共12小题，每小题5分，共60分．在每小题给出的四个选项中，只有一项是符合题目要求的）．1．已知全集U R =，集合{}2430A x x x =-+，{1,0,1,2,3}B =-，则A B =（ ）A ．{}1,0-B ．{}1,2C ．{}0,1,2D ．{}1,2,3 2．已知等差数列{}n a 的前n 项和为n S ，55a =，则9S =（ ） A ．25 B ．45 C ．60 D ．903．已知双曲线222:1y C x b-=的一条渐近线是y =，则双曲线C 的离心率是（ ）A ．2BC ．3D ．44．渝康码是腾讯和支付宝与重庆市政府合作推出的重庆电子健康码，用户申请使用渝康码，凭此码出入小区，学校，医院，商业，公共交通，办公楼宇，交通卡口等．如图，健康人员的渝康码是黑白相间的．已知某个重庆市民的渝康码是边长为15cm 的正方形，利用随机模拟的方法向该渝康码内投入900个点，其中落入黑色部分的点的个数为480个，则该渝康码的黑色部分的面积约为（ ）2cm ．A ．105B ．115C ．120D ．1355．已知1ln 3a =，lg3b =，122c =，则a ，b ，c 的大小关系为（ ）A ．a b c <<B ．a c b <<C ．b c a <<D ．b a c <<6．抛物线2:2(0)C y px p =>的焦点为F ，抛物线上一点(2,)(0)M b b >到焦点的距离为3，则b 的值为（ ）A B ．2 C ． D ．4 7．已知平面αβ⊥，l αβ=，m α⊂，n β⊂，则m n ⊥是m l ⊥的（ ）A ．充分不必要条件B ．必要不充分条件C ．充要条件D ．既不充分也不必要条件 8．一个算法的程序框图如图所示，则该程序输出的结果是（ ）A ．5B ．1C ．15 D ．179．已知在矩形ABCD 中，24AB BC ==，E 为AB 的中点，沿着DE 将ADE △翻折到PDE △，使平面PDE ⊥平面EBCD ，则PC 的长为（ ）A ．B ．C ．4D ．610．如图，重庆欢乐谷的摩天轮被称为“重庆之眼”，其旋转半径为50米，最高点距离地面120米，开启后按逆时针方向旋转，旋转一周大约18分钟．将摩天轮看成圆面，在该平面内，以过摩天轮的圆心且垂直于地平面的直线为y 轴，该直线与地平面的交点为坐标原点建立平面直角坐标系，某人在最低点的位置坐上摩天轮的座舱，摩天轮开始启动，并记该时刻为0t =，则此人距离地面的高度()f t 与摩天轮运行时间t （单位：分钟）的函数关系式为（ ）A ．()50sin20(0)9f t t t π=+ B ．()50sin 70(0)92f t t t ππ⎛⎫=-+ ⎪⎝⎭C ．()50sin 20(0)92f t t t ππ⎛⎫=-+⎪⎝⎭ D ．()50sin 70(0)9f t t t ππ⎛⎫=-+ ⎪⎝⎭11．以罗尔中值定理、拉格朗日中值定理、柯西中值定理为主体的“中值定理”反映了函数与导数之间的重要联系，是微积分学重要的理论基础，其中拉格朗日中值定理是“中值定理”的核心内容．其定理陈述如下：如果函数()y f x =在闭区间[,]a b 上连续，在开区间(,)a b 内可导，则在区间(,)a b 内至少存在一个点0(,)x a b ∈，使得()0()()()f b f a f x b a '-=-，0x x =称为函数()y f x =在闭区间[,]a b 上的中值点，则函数()sin f x x x =在区间[0,]π上的“中值点”的个数为（ ）1.41≈ 1.73≈， 3.14π≈．A ．1B ．2C ．3D ．412．已知平面向量OA ，OB ，OP ，OQ ，满足：||2OA =，||1OB =，且()0OB OB OA ⋅-=，若OP tOA =，(1)OQ t OB =-，其中01t ，则||PQ 的最小值为（ ）A ．27 B ．37C ．7D ．7二、填空题（本大题共4小题，每小题5分，共20分）． 13．已知复数22z i=-，其中i 为虚数单位，则z 的共轭复数z =________． 14．已知甲、乙两个盒子，其中甲盒中有大小完全相同的红、黄、白三个球，乙盒中有大小完全相同的红、黄两个球，现从两个盒子中各取一个球，则两个小球颜色不同的概率为________．15．已知函数32()(1)3f x x a x ax =+--为一个奇函数，则()f x 在[2,3]-上的最大值为________．16．已知数列{}n a 中11a =-，当2n 时，1123,,n n n a a a n n --⎧=⎨+⎩为奇数为偶数，记26n n b a =+，则1n nbb +=________；数列{}n b 前n 项和n S =________．（第一空2分，第二空3分） 三、解答题（共70分．解答应写出文字说明，证明过程或演算步骤）． 17．（本小题满分12分）ABC △的内角A ，B ，C 的对边分别为a ，b ，c ，A 是锐角，且sin 2cos b A a B c +=．（1）求角A ；（2）若D 为AC 边上一点，2BC BD =， 5AB =，且ABD △的面积为2，求sin C ． 18．（本小题满分12分）如图，在四棱锥P ABCD -中，BP ⊥平面PDC ，四边形ABCD 是一个直角梯形，AD BC ∥，90ABC ∠=︒，12AD AB BC ==．（1）求证：CD ⊥平面PBD ；（2）若AB BP PA ==，且P ABCD V -=P ABD -的侧面积． 19．（本小题满分12分）新型冠状病毒肺炎是一种传染性极强的肺炎临床上，核酸检测是新冠肺炎患者确诊的重要依据、是最关键的一环．为什么要做核酸检测呢？简单来说，核酸类似病毒的“指纹”、身份证，找到核酸，就等于确定了病毒的身份与性质．核酸是生物的最基本组成物质和生物学研究的基础物质．病毒是一种个体微小，结构简单的非细胞生物，病毒中也有核酸，且只含一种核酸（DNA 或RNA ），所以，检测到核酸，也就等于揪住了病毒的尾巴．新型冠状病毒感染者，经过治疗，如果核酸检测第一种为阴性，就说明病毒已经消失或者已不再具备造成感染的能级、数量．某生物制药公司生产了两种不同规格型号的新冠病毒核酸检测试剂盒．检测单个样本得知核酸检测结果所需的时间记为X （单位：分钟）．现两种试剂盒检测的样本各有20个，统计检测所需时间，得到如图的茎叶图．（1）试通过平均数比较两种试剂盒哪一种检测更快捷；（2）在改变了试剂盒的生产工艺后，组织了2000名志愿者参加了核酸检测，记录检测时间，得到如下统计数据：800 1200判断是否有99.5%的把握认为核酸检测时间与试剂盒生产工艺有关？附：22()()()()()n ad bc K a b c d a c b d -=++++，其中n a b c d =+++．20．（本小题满分12分）已知函数()()a xf x x e a R =∈，()()ln ()g x f x f x =-． （1）当0a =时，求曲线()y g x =在点(1,(1))g 处的切线方程； （2）当1a =时，若()01g x =，求证：01325x <<． 21．（本小题满分12分）已知椭圆2222:1(0)x y C a b a b+=>>的焦距为4，短轴长为4．（1）求该椭圆的标准方程；（2）已知点P ，过点P 作相互垂直的两条直线分别交椭圆于另一点A ，B ，求点P 到AB 距离的最大值．请考生在第22、23两题中任选一题作答，并用2B 铅笔在答题卡上把所选题目的题号涂黑．注意所做题目的题号必须与所涂题目的题号一致，在答题卡选答区域指定位置答题．如果多做，则按所做的第一题计分． 22．（本小题满分10分）【选修4-4：坐标系与参数方程】在直角坐标系中，以原点为极点，x 轴的正半轴为极轴建立极坐标系，已知曲线:4cos C ρθ=，直线l 的参数方程为321x t y t =+⎧⎨=-+⎩（t 为参数），直线l 与曲线C 分别交于M ，N 两点．（1）写出曲线C 和直线l 的普通方程； （2）若点(3,1)P -，求||||PM PN ⋅的值． 23．（本小题满分10分）【选修4-5：不等式选讲】 已知函数()|21||21|f x x x =+--．（1）若不等式()|4|f x ax +的解集包含[1,2]，求a 的取值范围； （2）若()f x 的值域为A ，且,a b A ∈，证明：|4||22|ab a b ++．巴蜀中学2020届高考适应性月考卷（十）文科数学参考答案一、选择题（本大题共12小题，每小题5分，共60分）．【解析】 1．[1,3]A =，{1,2,3}AB =，故选D ．2．()199599452a a S a +===，故选B ．3．依题意b =A ．4．设该渝康码的黑色部分的面积为x ，则480120225900x x =⇒=，故选C ． 5．1ln ln 303=-<，0lg31<<，1221>，所以a b c <<，故选A ．6．由焦半径公式232pMF =+=，2p =，24y x =，∴28b =，b =，故选C ． 7．m n ⊥不能推出m l ⊥，由面面垂直的性质定理可知m l m n ⊥⇒⊥，故选B ．8．第一次进入循环体：1i =，是，2i =，1T =，1553P ==；第二次进入循环体：2i =，是，3i =，2T =，515P ==；第三次进入循环体：3i =，是，4i =，3T =，17P =；第四次7进入循环体：4i =，否，输出17P =，故选D ．9．当平面PDE ⊥平面EBCD 时，∵CE DE ⊥，平面PDE平面EBCD DE =，∴CE ⊥平面PDE ，CE DP ⊥，∵DP PE ⊥，PE EC E =，∴DP ⊥平面PEC ，DP PC ⊥，所以PC =A ．10．由已知()sin()(0,0)f t A t B A ωϕω=++>>，205012070A B A A B B ⎧-+==⎧⇒⎨⎨+==⎩⎩，18T =，2189ππω==，当0t =时，sin 1ϕ=-，2πϕ=-，()50sin 70(0)92f t t t ππ⎛⎫=-+⎪⎝⎭，故选B ．11．由()sin 2sin 3f x x x x π⎛⎫==+⎪⎝⎭，知()2cos 3f x x π⎛⎫'=+⎪⎝⎭．由拉格朗日中值定理：令()0()()f b f a f x b a -'=-，即00()(0)2cos cos 303f f x x ππππ-⎛⎫⎛⎫+==⇒+= ⎪ ⎪-⎝⎭⎝⎭，0(0,)x π∈，由11,2π⎛⎫--- ⎪⎝⎭，结合余弦函数图象易知方程在区间(0,)π内有2解，故在2区间[0,]π上的“中值点”有2个，故选B ．12．由()0OB OB OA ⋅-=，得到OA 与OB 的夹角60θ=︒，进而||2OP t =，|1OQ t =-∣，且OP 与OQ的夹角60θ=︒，||4PQ t ==．当27t =时，min ||7m OP OQ =-=，故选D ．二、填空题（本大题共4小题，每小题5分，共20分）．【解析】 13．242255z i i ==+-，4255z i =-． 14．甲盒中的三个球记为R ，Y ，W ，乙盒中的两个球记为r ，y ，则共有(,)R r ，(,)R y ，(,)Y r ，(,)Y y ，(,)W r ，(,)W y ，6种情况，则42()63P A ==． 15．10a -=，3()3f x x x =-，2()333(1)(1)f x x x x '=-=+-，(1)2f -=，(3)18f =，∴max ()18f x =． 16．()2122212222366262666n n n n n n n n a b a a b a a a +++⋅+++⋅+====+++，则1264b a =+=，则数列{}n b 是首项为14b =，公比2q =的等比数列，()24122412n n n S +-==--．三、解答题（共70分．解答应写出文字说明，证明过程或演算步骤）． 17．（本小题满分12分）解：（1）由正弦定理：sin sin 2sin cos sin sin()B A A B C A B +==+， （1分） 所以sin sin 2sin cos sin cos cos sin B A A B A B A B +=+，因为sin 0B >，即有sin 2cos A A =， （3分）2sin cos cos A A A ⇒=，因为A 是锐角，cos 0A >，所以12sin 1sin 2A A =⇒=，所以6A π=． （6分） （2）如图，因为5AB =，6A π=，所以1sin 22ABD S AB AD A =⋅⋅⋅=△，解得AD = （8分）在ABD △中，由余弦定理2cos 6π=，解得BD =BC = （10分）在ABC △中，由正弦定理15sin sin sin 28AB BC C C A ⨯=⇒==． （12分）18．（本小题满分12分）（1）证明：如图，设E 是BC 的中点，连接DE ，设12AD AB BC a ===，则BE EC a ==，因为AD BC ∥，90ABC ∠=︒，易得DE a =，且DE BC ⊥，所以BD DC ==．又2BC a =，由勾股定理得CD BD ⊥， （3分） 因为BP ⊥平面PDC ，CD ⊂平面PDC ，所以BP CD ⊥． （5分） 又因为BD ，BP 相交，所以CD ⊥平面PB D ． （6分）（2）解：设AB BP a ==，由（1）可得BD =，因为BP ⊥平面PDC ，所以BP PD ⊥．∵BP a =，∴PD a ==，在等腰三角形PBD 中，设O 是BD 的中点，∴PO BD ⊥，由（1）知：CD ⊥平面PBD ，所以CD PO ⊥．从而PO ⊥平面ABCD ，且122PO BD a ==， （8分） 由（1）中数据得2(2)322ABCDa a a a S +⋅==梯形， （9分）所以21134332P ABCDABCD a V S PO a -==⨯=⋅=梯形． （10分） 因为PAB △和PAD △为边长为4的等边三角形，PBD △是一个等腰直角三角形，所以88PAB PAD PBD S S S S =++==侧△△△． （12分）19．（本小题满分12分）解：（1）第一种更快， （1分） 第一种的平均时间为11531819212232324230231333543464826.820X ⨯++++⨯++⨯+⨯++++++==， （3分）第二种的平均时间为21821932324252262734352363840414923020X ⨯+⨯+++⨯++++⨯+++++⨯==， （5分）因为12X X <，所以第一种试剂盒检测更快捷． （6分） （2）由题可知400a =，600b =，800c =，200d =，1000a b +=，1200a c +=，1000c d +=，800b d +=，2000n a b c d =+++=，（8分） 所以2K 检验的估计值为222000(400200600800)333.333100010001200800K ⨯⨯-⨯=≈⨯⨯⨯， （10分）由于333.3337.879>， （11分） 所以有99．5%的把握认为核酸检测时间与试剂盒生产工艺有关． （12分）20．（本小题满分12分）（1）解：当0a =时，()xg x e x =-，()1xg x e '=-， ∴(1)1g e '=-，又(1)1g e =-，∴曲线()y g x =在点(1,(1))g 处的切线方程为(1)y e x =-． （4分）（2）证明：当1a =时，令()xt f x xe ==，则()ln g x t t =-， 由0t >，则0x >．令()ln h t t t =-，则11()1t h t t t-'=-=． 当(0,1)t ∈时，()0h t '<，()h t 单调递减； 当(1,)t ∈+∞时，()0h t '>，()h t 单调递增，∴min min ()()(1)1g x h t h ===，当且仅当1t =时取等号， （8分） 所以()01g x =．当且仅当()0001x t f x x e ===时，∵()(1)0(0)xf x x e x '=+>>，∴()f x 在(0,)+∞上递增．又1211122f e ⎛⎫== ⎪⎝⎭，3533155f e ⎛⎫==≈> ⎪⎝⎭， ∴()01325f f x f ⎛⎫⎛⎫<< ⎪ ⎪⎝⎭⎝⎭，又()f x 在(0,)+∞上递增， ∴01325x <<．（12分） 21．（本小题满分12分）解：（1）由题意得，2c =，2b =，所以方程为22184x y +=． （4分） （2）设()11,A x y ，()22,B x y ，若直线AB 的斜率不存在，则设直线:AB x t =，()()(221212122(2)20PA PB x x y yt y ⋅=--+=-+-=又∵22128t y +=，∴2t =或23t =，∴2t =时舍去，此时距离为43． （5分） 若直线AB 的斜率存在，设该直线为y kx m =+，代入椭圆方程得()222214280k x kmx m +++-=，122421kmx x k -+=+，21222821m x x k -=+． （6分）()()(121222PA PB x x kx m kx m ⋅=--+++ ()()2212121((2)4(k x x k m x x m =++-+++()()22222128((2)44(2121k m k m km m k k +--=-++++0==，∴(230k m k m +++=， （9分）∴2m k =-此时AB 过点P ）或者m =， （10分） ∴AB过定点2,33Q ⎛⎫-⎪ ⎪⎝⎭，距离d的最大值为||PQ = （12分） 22．（本小题满分10分）【选修4-4坐标系与参数方程】 解：（1）∵4cos ρθ=，∴24cos ρρθ=，∴224x y x +=，∴22(2)4x y -+=．∵321x ty t =+⎧⎨=-+⎩，∴250x y --=． （5分）（2）∵321x t y t =+⎧⎨=-+⎩，∴31x y ⎧=⎪⎪⎨⎪=-+⎪⎩，代入224x y x +=，得220t +-=，∴12t t +=，122t t =-，故12||||2PM PN t t ⋅==． （10分） 23．（本小题满分10分）【选修4-5：不等式选讲】（1）解：依题意得，当[1,2]x ∈时，不等式|21||21||4|x x ax +--+恒成立，即(21)(21)|4|x x ax +--+，即|4|2ax +恒成立， （3分） 展开得242ax -+，即62ax x--恒成立， ∵[1,2]x ∈，∴max 63x -⎡⎤=-⎢⎥⎣⎦，min22x -⎡⎤=-⎢⎥⎣⎦，∴32a --． （5分）（2）证明：∵()212121(21)2f x x x x x =+--+--=，所以()f x 的值域[2,2]A =-． （7分）又∵()()222222|4||22|81642ab a b a b ab a ab b +-+=++-++()()222222441644a b a b a b =--+=--，∵,[2,2]a b ∈-，∴24a ，24b ，∴()()22440a b --，所以22|4||22|ab a b ++，所以|4||22|ab a b ++． （10分）。
2020年普通高等学校招生全国统一考试理科数学全国3卷
1.【ID:4002701】已知集合，，则中元素的个数为()A.B.C.D.【答案】C【解析】解：集合，，．中元素的个数为．故选：C．2.【ID:4002702】复数的虚部是()A.B.C.D.【答案】D【解析】解：，复数的虚部是．故选：D．3.【ID:4002703】在一组样本数据中，，，，出现的频率分别为，，，，且，则下面四种情形中，对应样本的标准差最大的一组是()A. ，B. ，C. ，D. ，【答案】B【解析】解：选项A：，所以；同理选项B：，；选项C：，；选项D：，；故选：B．4.【ID:4002704】模型是常用数学模型之一，可应用于流行病学领域．有学者根据公布数据建立了某地区新冠肺炎累计确诊病例数(的单位：天)的模型：，其中为最大确诊病例数．当时，标志着已初步遏制疫情，则约为()A.B.C.D.【答案】C【解析】解：由已知可得，解得，两边取对数有，解得，故选：C．5.【ID:4002705】设为坐标原点，直线与抛物线：交于，两点，若，则的焦点坐标为()A.B.C.D.【答案】B【解析】解：将代入抛物线，可得，，可得，即，解得，所以抛物线方程为：，它的焦点坐标．故选：B．6.【ID:4002706】已知向量，满足，，，则()A.B.C.D.【答案】D【解析】解：向量，满足，，，可得，．故选：D．7.【ID:4002707】在中，，，，则()A.B.C.D.【答案】A【解析】解：在中，，，，由余弦定理可得；故；，故选：A．8.【ID:4002708】右图为某几何体的三视图，则该几何体的表面积是()A.B.C.D.【答案】C【解析】解：由三视图可知几何体的直观图如图：几何体是正方体的一个角，，、、两两垂直，故，几何体的表面积为：，故选：C．9.【ID:4002709】已知，则()A.B.C.D.【答案】D【解析】解：由，得，即，得，即，即，则，故选：D．10.【ID:4002710】若直线与曲线和圆都相切，则的方程为()A.B.C.D.【答案】D【解析】解：直线与圆相切，那么直线到圆心的距离等于半径，四个选项中，只有A，D满足题意；对于A选项：与联立可得：，此时：无解；对于D选项：与联立可得：，此时解得；直线与曲线和圆都相切，方程为，故选：D．11.【ID:4002711】设双曲线：的左、右焦点分别为，，离心率为，是上一点，且，若的面积为，则()A.B.C.D.【答案】A【解析】解：由题意，设，，可得，，，，可得，可得，解得．故选：A．12.【ID:4002712】已知，．设，，，则()A.B.C.D.【答案】A【解析】解：，；，，，；，，，，综上，．故选：A．13.【ID:4002713】若，满足约束条件，则的最大值为________．【答案】7【解析】解：先根据约束条件画出可行域，由解得，如图，当直线过点时，目标函数在轴上的截距取得最大值时，此时取得最大值，即当，时，．故答案为：．14.【ID:4002714】的展开式中常数项是________（用数字作答）．【答案】24015.【ID:4002715】已知圆锥的底面半径为，母线长为，则该圆锥内半径最大的球的体积为________．【答案】【解析】解：因为圆锥内半径最大的球应该为该圆锥的内切球，如图，圆锥母线，底面半径，则其高，不妨设该内切球与母线切于点，令，由，则，即，解得，，故答案为：．16.【ID:4002716】关于函数有如下四个命题：①的图象关于轴对称．②的图象关于原点对称．③的图象关于直线对称．④的最小值为．其中所有真命题的序号是________．【答案】②③【解析】解：对于①，由可得函数的定义域为，故定义域关于原点对称，由；所以该函数为奇函数，关于原点对称，所以①错②对；对于③，由，所以该函数关于对称，③对；对于④，令，则，由双勾函数的性质，可知，，所以无最小值，④错；故答案为：②③．17. 设数列满足，．（1）【ID:4002717】计算，，猜想的通项公式并加以证明．【答案】见解析【解析】解：，，，，由此可猜测的通项公式为．证明：当时，左边，右边，等式成立．假设当时等式成立，即，则当时，，等式成立．综上所述，对都成立．（2）【ID:4002718】求数列的前项和．【答案】，【解析】解：由得，，，①，②，得：，综上，数列的前项和，．18. 某学生兴趣小组随机调查了某市天中每天的空气质量等级和当天到某公园锻炼的人次，整理数据得到下表(单位：天)：（1）【ID:4002719】分别估计该市一天的空气质量等级为，，，的概率．【答案】见解析【解析】解：设表示事件“该市一天的空气质量等级”．由表格数据得：；；；．（2）【ID:4002720】求一天中到该公园锻炼的平均人次的估计值(同一组中的数据用该组区间的中点值为代表)．【答案】【解析】由题意得：一天中到该公园锻炼的平均人次的估值一天中到该公园锻炼的平均人次的估值为．（3）【ID:4002721】若某天的空气质量等级为或，则称这天“空气质量好”；若某天的空气质量等级为或．则称这天“空气质量不好”，根据所给数据，完成下面的列联表．并根据列联表，判断是否有的把握认为一天中到该公园锻炼的人次与该市当天的空气质量有关？附：，【答案】见解析【解析】由题意得：(空气质量好，人数)；(空气质量好，人数)；(空气质量不好，人数)；(空气质量不好，人数)；，可以有的把握认为一天中到该公园锻炼的人次与该市当天的空气质量有关．19. 如图，在长方体中，点，分别在棱，上，且，．（1）【ID:4002722】证明：点在平面内．【答案】见解析【解析】解：连接，；取的三等分点，，且，四边形为平行四边形，，又长方体性质易得：，，，，，在同一平面内，在平面内．（2）【ID:4002723】若，，，求二面角的正弦值．【答案】【解析】解：以为坐标原点，方向为轴，方向为轴，方向为轴，在长方体内建立空间直角坐标系，易得：，，，，，，，，设平面的法向量，则，，令，则可以为，设平面的法向量，，，令，则可以为，，二面角的正弦值为．20. 已知椭圆：的离心率为，，分别为的左、右顶点．（1）【ID:4002724】求的方程．【答案】【解析】，，，，即，的方程为．（2）【ID:4002725】若点在上，点在直线上，且，，求的面积．【答案】【解析】设，，，则，，①，又，②，由①，，代入②式：，，，不妨设，代入①：，时，；时，；，或，，①，，，：，即，且，，．②，，，：，即，且，，，综上所述，．方法：由，设，点，根据对称性，只需考虑的情况，此时，，，有①，又，②，又③，联立①②③得或，当时，，，，同理可得当时，，综上，的面积是．21. 设函数，曲线在点处的切线与轴垂直．（1）【ID:4002726】求．【答案】【解析】解：，，．（2）【ID:4002727】若有一个绝对值不大于的零点，证明：所有零点的绝对值都不大于．【答案】见解析【解析】，，令，，，，，，，时，，，，，，，若，，则，则，，，，所有零点都在上．解法：设为的一个零点，根据题意，，且，则，由，令，，当时，，当时，可知在，上单调递减，在上单调递增．又，，，，．设为的零点，则必有，即，，得，即．所有零点的绝对值都不大于．22. 在直角坐标系中，曲线的参数方程为(为参数且)，与坐标轴交于，两点．（1）【ID:4002728】求．【答案】【解析】解：与坐标轴交于，，则令或，即或，则或(舍)或或(舍)，，，，，，，则，坐标为，，．（2）【ID:4002729】以坐标原点为极点，轴正半轴为极轴建立极坐标系，求直线的极坐标方程．【答案】【解析】：，即，由，，则直线极坐标方程为：．23. 设，，，，．（1）【ID:4002730】证明：．【答案】见解析【解析】解：，且，，．（2）【ID:4002731】用表示，，的最大值，证明：．【答案】见解析【解析】不妨设为最大值，，则由，，，，，即．。
Frymaster 电子炸锅使用说明书
Frymaster L.L.C., PO Box 51000, Shreveport, Louisiana 71135-1000 Shipping Address: 8700 Line Avenue, Shreveport, Louisiana 71106FRYMASTER ELECTRIC FRYERS ARE MANUFACTURED FOR USE WITH THE TYPE VOLTAGE SPECIFIED ON THE FRYER RATING PLATE LOCATED ON THE FRYER DOOR. FOR PROPER INSTALLATION PROCEDURES IN THE UNITED STATES, REFER TO THE LATEST EDITION OF THE NATIONAL ELECTRIC CODE ANSI/N.F.P.A. NO. 70; IN CANADA, CANADIAN ELECTRICAL CODE PART 1, CSA-22.1. INFORMATION ON THE CONSTRUCTION AND INSTALLATION OF VENTILATING HOODS MAY BE OBTAINED FROM THE LATEST EDITION OF THE "STANDARD FOR THE INSTALLATION OF EQUIPMENT FOR THE REMOVAL OF SMOKE AND GREASE LADEN VAPORS FROM COMMERCIAL COOKING EQUIPMENT", N.F.P.A. NO. 96. COPIES OF THESE ELECTRICAL STANDARDS ARE AVAILABLE FROM THE NATIONAL FIRE PROTECTION ASSOCIATION, BATTERY MARCH PARK, QUINCY, MASS. 02269THE FRYER(S) MUST BE INSTALLED WITH A 15 CM (six inch) CLEARANCE AT BOTH SIDES AND ADJACENT TO COMBUSTIBLE CONSTRUCTION. A MINIMUM OF 60 CM (24-inches) SHOULD BE PROVIDED AT THE FRONT OF THE FRYER(S)DOOR.THIS MANUAL SHOULD BE KEPT IN A CONVENIENT LOCATION AND REFERRED TO WHEN ANY PROBLEM OCCURS AND FOR FUTURE REFERENCE.FOR YOUR SAFETY, DO NOT STORE OR USE GASOLINE OR OTHER FLAMMABLE VAPORS AND LIQUIDS IN THE VICINITY OF THIS OR ANY OTHER APPLIANCE.TABLE OF CONTENTSPAGE ORDERING/SERVICEINFORMATION (2)1. PARTSINFORMATION (2)2. IMPORTANTINSTRUCTIONS (4)3. INSTALLATION4. INITIAL STARTUP INSTRUCTIONS (5)5. DAILYOPERATIONS (7)6. CLEANING AND MAINTENANCE (9)PROCEDURES (10)7. SERVICEDIAGRAMS (11)8. WIRINGLIST (12)9. PARTS1. PARTS ORDERING/SERVICE INFORMATIONParts orders must be placed directly with your local Frymaster Parts Distributor. A list of International Factory Authorized Service Centers was included with the fryers when shipped from the factory. If you do not have access to this list, please contact the Frymaster Technical Services Department at 1-800-551-8633 or 1-318-865-1711.To help speed your order, the following information is required:Model Number:Serial Number:Type of Gas or Voltage:Part Number:Service information may be obtained by calling your local Factory Authorized Service Center. A list of these agencies was packed with your fryer.Service information may also be obtained by calling the Frymaster Technical Services Department. When calling, please have the following information available:Model Number:Serial Number:Type of Gas or Voltage:Nature of Service Problem:Please have ready any other information that you think may be helpful in solving your service problem.PARTS ORDERING/SERVICE INFORMATION CANADA -- Garland Commercial Ranges, Ltd., 1177 Kamato Road, Mississauga, Ontario L4W1X4.Note: Retain and store this manual in a safe place for future use. Additional copies may be obtained from your authorized service center.2. IMPORTANT INFORMATION2.1. IntroductionThe V-14 and V-17 Series are deep-well, open-pot fryers designed for cooking a variety of fried products. Read the instructions in this manual thoroughly before attempting to install, operate or service this equipment.2.2. Operating, Installation, and Service PersonnelOperating information for FRYMASTER equipment has been prepared for use by qualifiedand/or authorized operating personnel only.All installation and service on FRYMASTER equipment must be performed by qualified,certified, licensed, and/or authorized installation or service personnel.Service may be obtained by contacting your local Factory Authorized Service Center.2.3. DefinitionsQualified and/or Authorized Operating PersonnelQualified or authorized operating personnel are those who have carefully read the information in this manual and have familiarized themselves with the equipment functions or have hadprevious experience with the operation of equipment covered in this manual.Qualified Installation PersonnelQualified installation personnel are: individuals, a firm, corporation, or a company whicheither in person or through a representative are engaged in, and are responsible for theinstallation of electrical wiring from the building electric meter, main control box, or service outlet to the electrical appliance. Qualified installation personnel must be experienced in such work, be familiar with all electrical precautions required, and have complied with allrequirements of applicable national, European Community and local codes.Qualified Service PersonnelQualified service personnel are those familiar with FRYMASTER equipment and have been authorized by THE FRYMASTER CORPORATION. All authorized service personnel are required to be equipped with a complete set of service parts manuals and stock a minimum amount of parts for FRYMASTER equipment.A list of Frymaster Factory Authorized Service Centers was included with the fryer whenshipped from the factory. If you do not have access to this list, please contact the FrymasterCustomer Service Department, using the number listed on the front of this manual. Failure to use qualified service personnel will void the Frymaster warranty.2.4. Shipping Damage Claim ProcedurePlease note that the FRYMASTER equipment was carefully inspected and packed by skilled personnel before leaving the factory. The transportation company assumes full responsibility for safe delivery upon acceptance of the equipment.What to do if equipment arrives damaged:A. File Claim for Damages Immediately--Regardless of extent of damage.B. Visible Loss or Damage--Be sure this is noted on the freight bill or express receipt and issigned by the person making the delivery.C. Concealed Loss or Damage--If damage is unnoticed until equipment is unpacked, notifyfreight company or carrier immediately and file a concealed damage claim. This should bedone within 15 days of date of delivery. Be sure to retain container for inspection.FRYMASTER DOES NOT ASSUME RESPONSIBILITYFOR DAMAGE OR LOSS INCURRED IN TRANSIT3. INSTALLATION INSTRUCTIONSPROPER INSTALLATION IS ESSENTIAL TO EFFICIENT AND TROUBLE-FREE OPERATION. ANY ALTERATION OF THE EQUIPMENT VOIDS THE FRYMASTERWARRANTY.Note: Before installing the newly-arrived equipment, inspect it carefully for visible and concealed damage. See Section 2.4.3.1. Caster/Leg InformationIf it is necessary to install legs or casters, follow the instructions provided in the accessories package shipped with the fryer.3.2. LevelingPlace a carpenter’s spirit level across the top of the fryer and level the unit both front-to-back and side-to-side. If it is not level, the unit may not function efficiently, the oil may not drain properly for filtering and in a line-up it may not match adjacent units.If the floor is uneven or has a decided slope, a smooth platform is recommended for placingthe unit on and not relying on leg/caster thread adjustment.3.3. Electrical ConnectionsPOWER REQUIREMENTSThe electrical power supply for the fryers MUST be the same as indicated on the rating and serial number plate located on the fryer door.MODEL VOLTAGE PHASE WIRESERVICE MIN.SIZEAWG(mm2)AMPS PER LEGL1 L2 L3V14 230/380 3 4 6 (16) 21 21 21 V14 240/415 3 4 6 (16) 20 20 20 V17 230/380 3 4 6 (16) 26 26 26 V17 240/415 3 4 6 (16) 24 24 24Plan and carry out installation in accordance with local codes.Connections: Connections to the terminal block and grounding lug should be made through the hole provided for this purpose in the junction box.Wiring Diagram: It is attached to the inside of the fryer door. Amperage for each unit depends on the type of installation and accessories supplied with the unit.4. INITIAL STARTUP INSTRUCTIONS4.1. CleaningNew units are wiped clean with solvents at the factory to remove any visible signs of dirt, oil, grease, etc. remaining from the manufacturing process, then coated lightly with oil. Wash thoroughly with hot, soapy water to remove any film residue and dust or debris before food preparation, then rinse out and wipe dry. Wash any accessories shipped with the unit as well.Close the drain valve completely and remove the crumb screen. Make sure the screws holding the thermostat and high-limit control sensing bulbs into the vessel are tight.4.2. Heating The VesselThis step checks heater element operation, initial thermostat calibration, and cleans the vessel for initial food production.A. Fill the fryer vessel with hot or cold water to the oil level line scribed in the back of thetank.B. Set the thermostat/temperature controller dial to approximately 105ºC (220ºF), just abovethe boiling point of water.C. Turn the power switch to ON. The heater elements will begin heating.D. When the water starts to boil, turn the dial to below 100ºC (210ºF). The elements willturn off and the water will stop boiling.E. When satisfied that the elements and thermostats operate properly, drain the vessel anddry thoroughly. Refill fry vessel with shortening as directed in Section 4.3.4.3. Fill With Cooking Oil/ShorteningNote: Cooking oil/shortening capacity of Value-H14 and Value-H17 Series fryers is 25 liters. (50 lbs.) at 21ºC (70ºF).A. Close the frypot drain valve.B. Place the power switch to the OFF position.C. Remove the baskets and basket support rack.D. When using liquid shortening, fill the empty frypot to the bottom oil-level line.E. When using solid shortening, either melt it first, or cut into small pieces and pack intocool zone (bottom) of the frying vessel. Be careful to not leave any air spaces or disturbthe thermostat and high limit bulbs. Continue to tightly pack the shortening, then lowerthe elements. Pack additional shortening in between and on top of the elements until levelwith the bottom oil level line.F. Replace the basket support rack on top of the heating element.G. Place the ON/OFF switch in the ON position. Melt shortening by turning the heaters“ON” for about five or ten seconds, “OFF” for a minute, repeating cycle until shorteningis melted. If oil starts to smoke while melting this way, shorten the “ON” cycle andlengthen the “OFF” cycle. Smoke shows that you are scorching the shortening and cuttingits useful life.H. Once the shortening is melted, set the thermostat for normal cooking temperature.4.4. Before Relocating Fryermoving. If a leg becomes damaged during movement, contact your service agent forimmediate repair/replacement.A. Turn fryer ON/OFF switch to OFF. Unplug the power cord from the source.B. Relocate the fryer for service accessibility.C. After servicing is complete, return the fryer to the operating position. Plug all powercords into source. Attach the restraining devices.5. DAILY OPERATION5.1. General UseA. For consistent quality product, convenience and long-term savings, use a high-qualityliquid frying oil.B. Although a temperature of 177ºC (350ºF) is recommended for most cooking operations,set the fryer at the lowest possible temperature which produces a high quality end productwhile ensuring maximum life of frying oil/shortening.C. When the fryer is not in use, the thermostat should be set lower than that used duringcooking.5.2. Turn On ProceduresA. Always be sure vessel is full before turning fryer on. Follow instructions in Section 4.3.B. Turn fryer on, and set thermostat to the desired cooking temperature.5.3. FilteringAlways consult the filter manufacturer's operation instructions for the recommended filtering procedure.The following procedure is recommended to drain and filter your cooking oil/shortening whena filter machine is not available:A. Turn the fryer ON/OFF switch to the OFF position. Screw the drain pipe (provided withfryer) into the drain valve. Make sure the drain extension is firmly screwed into the drain valve and that the curved end is pointing down.B. Position a metal container with sealable cover under the drain extension. The metal containerand cover must be able to withstand the hot cooking oil/shortening and hold hot liquids.Frymaster recommends that a Frymaster filter cone holder and filter cone be used when a filter machine is not available. If you are using the Frymaster filter cone holder and cone, be sure that the cone holder rests securely on the metal container.C. Open the drain valve slowly to avoid splattering. If splattering occurs, exercise extremecaution.D. If the drain valve becomes clogged with food particles, use the Fryer's Friend (poker-liketool). Use this tool from the inside of the frypot ONLY. Grip the tool on the handle as far as possible away from the cooking oil/shortening in the frypot. DO NOT hammer on the drain valve. This damages the drain valve ball.Note: For safe, convenient draining and disposing of used oil/shortening, Frymaster recommends the use of the Frymaster shortening disposal unit (SDU). The SDU is available through your local distributo r.E. After draining the oil/shortening, clean all food particles and residual oil/shortening fromthe frypot before refilling.F. Close the drain valve and refill the frypot with clean, filtered oil/shortening.5.4. ClosingA. When closing for the night, turn the fryer ON/OFF switch to OFF position.B. Filter oil in fryers.C. Put frypot cover in place over frypot.5.5. ShutdownWhen shutting down for periods longer than overnight, drain the frying oil/shortening andclean the vessel thoroughly. Either discard the frying oil/shortening or filter it and return it to the vessel and cover the vessel. Turn the power switch and the thermostat to OFF.If the vessel is not stainless steel, and it is to be left empty, apply a light coat of shortening to the entire interior of the vessel to prevent corrosion and possible rust.6. CLEANING AND MAINTENANCE6.1. General:Any piece of equipment works better and lasts longer when maintained properly and keptclean. Cooking equipment is no exception. The fryer should be kept clean during theworking day and thoroughly cleaned at the end of each day.6.2. Daily:Wash all removable parts. Be sure to dry all parts thoroughly. Clean all exterior surfaces of the fryer. Do not use cleansers, steel wool, or any other abrasive material on the stainlesssteel or enamel surfaces.Filter the cooking oil and replace if necessary. Under heavy use conditions, the oil should be filtered more often than once a day.6.3. WeeklyA. Completely drain the oil from the fryer into either the filter or a steel container. Do notuse a glass or plastic container.B. Clean the vessel in the following manner:1. Close the drain valve and refill with either a good commercial cleaning solution andwater, or water and strong detergent.2. Set the operating thermostat to 104ºC (220ºF). Bring to a rolling boil, then turn theheat down to a simmer and let the mixture stand until the deposits and/or carbon spots canbe readily removed with scrub pad or scrub brush.3. Scrub the vessel walls, bottom and heating elements.4. Drain vessel and rinse with clean water.5. Refill with water, set operating thermostat to above 100ºC (212ºF), and boil again.Once boiling is completed, turn operating thermostat off, drain, rinse, and dry thevessel and elements thoroughly.C. Immediately refill with cooking oil or frying compound as directed in Section 4.3.6.4. PeriodicThe fryer should be checked and adjusted periodically by qualified service personnel as partof a regular kitchen maintenance program.6.5. Stainless Steel CareAll stainless steel fryer cabinet parts should be wiped regularly with hot soapy water duringthe day, and with a liquid cleanser designed for stainless steel at the end of each day.A. Do not use steel wool or abrasive cloths, cleansers or powders.B. Do not use a metal knife, spatula or any other metal tool to scrape stainless steel!Scratches are almost impossible to remove.C. If it is necessary to scrape the stainless steel to remove any encrusted materials, soak thearea first to soften the deposit, then use a wood or nylon scraper only.7. SERVICE PROCEDURES7.1. Thermostat CalibrationA. Insert a good grade thermometer or pyrometer probe approximately 8-10cm (3-4 inches)into the cooking oil/shortening near the fryer temperature sensing probe.B. Turn thermostat knob to the desired frying temperature.C. Turn the fryer ON/OFF switch to the ON position and heat the shortening to thethermostat temperature setting. Stir if necessary to get all cooking oil/shortening in bottomof frypot melted.D. Allow the heating elements to cycle ON and OFF three times after reaching the thermostattemperature setting. When the elements come on the fourth time, the thermometer readingshould be within 2ºC (5ºF) of the thermostat knob setting. If it is not, calibrate as follows:1. Remove the thermostat knob by pulling straight out on the knob with a firm steadypull.2. Insert a small flat blade screwdriver into the center of the thermostat shaft and turn theadjusting screw clockwise to decrease and counter-clockwise to increase. DO NOTallow the thermostat shaft to turn while turning the adjusting screw. Turn the screw in¼ turn increments, checking calibration after each adjustment.3. After each adjustment, reinstall the thermostat knob, and allow the shortening to cooluntil the heating element comes on.4. Compare the thermometer or pyrometer reading and the thermostat knob setting whenthe elements come on.5. Repeat Steps 5.a. through 5.d. until thermometer or pyrometer reading and knobsetting agree within 2ºC (5ºF).6. If calibration cannot be obtained for any reason, call a Factory Authorized ServiceCenter.7. Remove thermometer or pyrometer probeNote: The heating element must cycle ON at the calibration point.8. WIRING DIAGRAM9. PARTS LISTS9.1. Control/Component BoxItem No. Part Number Description1 807-1692 Thermostat, SunneThermostat816-0139 Knob,2 807-0044 Switch, Red On/Off3 810-1202 Contactor, 40 Amp, 3 Pole4 807-1169 Transformer,208-220-240 / 24 volt5 807-1174 Fuse, 250V, 3 Amp, Slow Blow6 807-1268 Terminal Block, Single Pole (Neutral)7 807-0065 Terminal Block, Field Wiring8 807-0070 Terminal Lug, Ground9.2. Miscellaneous PartsItem No. Part Number Description1 810-0356 Caster, 5” without Brake2 806-5043 Leg* 806-3811 Legs (Package of 4)3 810-0357 Caster, 5”, With BrakeAssembly4 806-4926 DoorHanger5 803-0028 BasketCap6 910-4408 Topthermostat* 807-0063 Hi-Limit* 910-1614 Guard, Operating Thermostat* 806-6993 Drain Valve, 1-1/4”* 810-0820 Handle, Drain ValveExtension* 812-1226SP DrainV14/17* 823-1775SP Frypot,* 807-2645 Heating Element, V14 / 220V* 807-2641 Heating Element, V17 / 220V* 807-2644 Heating Element, V14 / 240/415V* 807-2645 Heating Element, V17 / 240/415V* 807-2647 Heating Element, V14 / 380V* 807-2648 Heating Element, V17 / 380VFrymaster, L.L.C., 8700 Line Avenue, PO Box 51000, Shreveport, Louisiana 71135-1000Shipping Address: 8700 Line Avenue, Shreveport, Louisiana 71106 TEL 1-318-865-1711FAX (Parts) 1-318-219-7140(Tech Support) 1-318-219-7135Price: $6.00 PRINTED IN THE UNITED STATESSERVICE HOTLINE 1-800-551-8633819-5250。
高考数学一轮复习第六章数列课时规范练30等比数列
课时规范练30等比数列基础巩固组1.(2020河南开封定位考试)等比数列{a n}的前n项和为S n,若a3+4S2=0,则公比q=()A.-1B.1C.-2D.22.(2020东北师大附中、重庆一中、吉大附中、长春十一中等高三联合考试)等比数列{a n}各项均为正数,若a1=1,a n+2+2a n+1=8a n,则{a n}的前6项和为()A.1365B.63C.6332D.136510243.(多选)设等比数列{a n}的前n项和为S n,且满足a6=8a3,则()A.数列{a n}的公比为2B.数列{a n}的公比为8C.63=8D.63=94.(2020全国2,理6)数列{a n}中,a1=2,a m+n=a m a n.若a k+1+a k+2+…+a k+10=215-25,则k=()A.2B.3C.4D.55.(2020福建龙岩高三教学质量检查)由实数构成的等比数列{a n}的前n项和为S n,a1=2,且a2-4,a3,a4成等差数列,则S6=()A.62B.124C.126D.1546.(多选)设等比数列{a n}的公比为q,则下列结论正确的是()A.数列{a n a n+1}是公比为q2的等比数列B.数列{a n+a n+1}是公比为q的等比数列C.数列{a n-a n+1}是公比为q的等比数列D.数列1是公比为1的等比数列7.(2020浙大附中模拟)已知数列{a n}的前n项和为S n,且+1=pS n+q(n∈N*,p≠-1),则“a1=q”是“{a n}为等比数列”的()A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件8.设等比数列{a n}的前n项和为S n,若63=3,则96=.9.已知{a n}是递减的等比数列,且a2=2,a1+a3=5,则{a n}的通项公式为;a1a2+a2a3+…+a n+1(n∈N*)=.10.(2018全国3,理17)等比数列{a n}中,a1=1,a5=4a3.(1)求{a n}的通项公式;(2)记S n为{a n}的前n项和,若S m=63,求m.公众号：一枚试卷君11.在①数列{a n}的前n项和S n=12n2+52n;②函数f(x)=sinπx-23cos2π2x+3的正零点从小到大构成数列{x n},a n=x n+83;③2-a n--12−-1=0(n≥2,n∈N*),a n>0,且a1=b2这三个条件中任选一个,补充在下面的问题中,若问题中的M存在,求出M的最小值;若M不存在,说明理由.问题:数列{b n}是首项为1的等比数列,b n>0,b2+b3=12,且,设数列1log3r1的前n项和为T n,是否存在M∈N*,使得对任意的n∈N*,T n<M?综合提升组12.(多选)(2020山东威海模考)设等比数列{a n}的公比为q,其前n项和为S n.前n项积为T n,并且满足条件a1>1,a7·a8>1,7-18-1<0.则下列结论正确的是()A.0<q<1B.a7·a9>1C.S n的最大值为S9D.T n的最大值为T713.(2020辽宁大连第二十四中学模拟)《九章算术》中的“两鼠穿墙题”是我国数学的古典名题:“今有垣厚若干尺,两鼠对穿,大鼠日一尺,小鼠也日一尺,大鼠日自倍,小鼠日自半,问何日相逢,各穿几何?”题意是:“有两只老鼠从墙的两边打洞穿墙,大老鼠第一天进一尺,以后每天加倍;小老鼠第一天也进一尺,以后每天减半.”如果墙足够厚,S n为前n天两只老鼠打洞长度之和,则S n=尺.14.设数列{a n}的前n项和为S n,已知a1=1,a2=2,且a n+2=2S n-S n+1+3,记b n=log2a2n-1+log2a2n,则b n=.创新应用组15.(多选)(2020山东青岛高三模拟)在悠久灿烂的中国古代文化中,数学文化是其中的一朵绚丽的奇葩.《张丘建算经》是我国古代有标志性的内容丰富的众多数学名著之一,大约创作于公元五世纪.书中有如下问题:“今有女善织,日益功疾,初日织五尺,今一月织九匹三丈,问日益几何?”.其大意为:“有一女子擅长织布,织布的速度一天比一天快,从第二天起,每天比前一天多织相同数量的布,第一天织5尺,一个月共织了九匹三丈,问从第二天起,每天比前一天多织多少尺布?”.已知1匹=4丈,1丈=10尺,若这一个月有30天,记该女子这一个月中的第n天所织布的尺数为a n,b n=2,对于数列{a n},{b n},下列选项中正确的为()A.b10=8b5B.{b n}是等比数列C.a1b30=105D.3+5+72+4+6=20919316.(2020浙江十校联考)已知数列{a n}满足a1=35,a n+1=32+1,n∈N*.(1)求证:数列1-1为等比数列.(2)是否存在互不相等的正整数m,s,t,使m,s,t成等差数列,且a m-1,a s-1,a t-1成等比数列?如果存在,求出所有符合条件的m,s,t;如果不存在,请说明理由.参考答案课时规范练30等比数列1.C因为a3+4S2=0,所以a1q2+4a1+4a1q=0.因为a1≠0,所以q2+4q+4=0,所以q=-2.故选C.2.B∵等比数列{a n}各项均为正数,且a n+2+2a n+1=8a n,∴a n q2+2a n q=8a n,即q2+2q=8,可得q=2或q=-4(舍去),∴S6=1(1-6)1-=63.故选B.3.AD因为等比数列{a n}的前n项和为S n,且满足a6=8a3,所以63=q3=8,解得q=2,所以63=1-61-3=1+q3=9.故选AD.4.B设该女子第一天织布x尺,则(1-25)1-2=5,得x=531,所以前n天所织布的总尺数为531(2n-1).由531(2n-1)≥30,得2n≥187,则n的最小值为8.故选B.5.C由题意知2a3=a2-4+a4,设{a n}的公比为q,则212=1-4+13,1=2,解得q=2,则S6=2(1-26)1-2=126.故选C.6.AD对于A,由r1-1=q2(n≥2)知,数列{a n a n+1}是公比为q2的等比数列,故A正确;对于B,当q=-1时,数列{a n+a n+1}的项中有0,不是等比数列,故B错误;对于C,当q=1时,数列{a n-a n+1}的项中有0,不是等比数列,故C错误;对于D,1r11=r1=1,所以数列1是公比为1的等比数列,故D正确.故选AD.7.C因为a n+1=pS n +q ,所以当n ≥2时,a n =pS n-1+q ,两式相减得a n+1-a n =pa n ,即当n ≥2时,r1=1+p.当n=1时,a 2=pa 1+q.所以当a 1=q 时,21=1+p ,满足上式,故数列{a n }为等比数列,所以满足充分性;当{a n }为等比数列时,有a 2=pa 1+q=(1+p )a 1,解得a 1=q ,所以满足必要性.故选C .8.73(方法1)由等比数列的性质可知S 3,S 6-S 3,S 9-S 6仍成等比数列,由已知得S 6=3S 3,∴6-33=9-66-3,即S 9-S 6=4S 3,S 9=7S 3,∴96=73.(方法2)因为{a n }为等比数列,由63=3,设S 6=3k ,S 3=k (k ≠0),所以S 3,S 6-S 3,S 9-S 6为等比数列,即k ,2k ,S 9-S 6成等比数列,所以S 9-S 6=4k ,解得S 9=7k ,所以96=73=73.9.a n =4×12n-1323×1-14n由a 2=2,a 1+a 3=5,{a n }是递减的等比数列,得a 1=4,a 3=1,所以q=12,a n =4×12n-1,则a 1a 2+a 2a 3+…+a n +1是首项为8,公比为14的等比数列的前n 项和.故a 1a 2+a 2a 3+…+a n +1=8+2+12+…+8×14n-1=8×[1-(14)]1-14=323×1-14n .10.解(1)设{a n }的公比为q ,由题设得a n =q n-1.由已知得q 4=4q 2,解得q=0(舍去),q=-2或q=2.故a n =(-2)n-1或a n =2n-1.(2)若a n =(-2)n-1,则S n =1-(-2)3.由S m =63得(-2)m =-188,此方程没有正整数解.若a n =2n-1,则S n =2n -1.由S m =63得2m =64,解得m=6.综上,m=6.11.解设数列{b n }的公比为q (q>0),因为数列{b n }是首项为1的等比数列,且b n >0,b 2+b 3=12,所以q 2+q-12=0,解得q=3(q=-4不合题意,舍去),所以b n =3-1.若选①,由S n =12n 2+52n ,可得-1=12(n-1)2+52(n-1)(n ≥2),两式相减可得a n =n+2(n ≥2),又因为a 1=S 1=3也符合上式,所以a n =n+2,所以1log 3r1=1(r2)=121−1r2,则T n =121-13+12−14+13−15+…+1−1r2=34−121r1+1r2.因为1r1+1r2>0,所以T n <34,由题意可得M≥34,又因为M∈N*,所以存在M满足题意,并且M的最小值为1.若选②,f(x)=sinπx-23cos2π2x+3=sinπx-3cosπx=2sinπx-π3,令f(x)=0,可得πx-π3=kπ,k∈Z,解得x=k+13,k∈Z,即x n=n-1+13=n-23,故a n=x n+83=n+2,同上①,则存在M满足题意,并且M的最小值为1.若选③,则由2-a n--12−-1=0,得(a n--1-1)(a n+-1)=0.又因为a n>0,所以a n--1-1=0,即a n-=1,所以数列{a n}是公差为1的等差数列.又因为a1=b2,则a1=3,所以a n=n+2.-1同上①,则存在M满足题意,并且M的最小值为1.12.AD∵a1>1,a7·a8>1,可知q>0,又7-18-1<0,∴a7>1,a8<1,∴0<q<1,故A正确;a7a9=82<1,故B错误;∵a1>1,0<q<1,∴数列{a n}为各项均为正数的递减数列,∴S n无最大值,故C错误;又a7>1,a8<1,∴T7是数列{T n}中的最大项,故D正确.故选AD.13.2n-12-1+1由题意可知,大老鼠每天打洞的距离是以1为首项,2为公比的等比数列,前n天打洞的距离之和为1-21-2=2n-1.小老鼠每天打洞的距离是以1为首项,12为公比的等比数列,前n天打洞的距离之和为1-(12)1-12=2-12-1.所以S n=2n-1+2-12-1=2n-12-1+1.14.2n-1∵a1=1,a2=2,且a n+2=2S n-S n+1+3,∴当n=1时,a3=2-3+3=2.∵a n+2=2S n-S n+1+3,∴当n≥2时,a n+1=2S n-1-S n+3.两式相减可得,a n+2-a n+1=2(S n-S n-1)-(S n+1-S n)(n≥2),即当n≥2时,a n+2-a n+1=2a n-a n+1,即a n+2=2a n.∵a3=2a1,∴数列{a n}的奇数项和偶数项分别成等比数列,公比均为2,∴a2n=2×2n-1=2n,a2n-1=1×2n-1=2n-1,∴b n=log2a2n-1+log2a2n=n-1+n=2n-1.15.BD由题意可知,数列{a n}为等差数列,设数列{a n}的公差为d,a1=5,由题意可得30a1+30×292=390,解得d=1629,∴a n=a1+(n-1)d=16r12929.∵b n=2,∴r1=2r12=2r1-=2d(非零常数),则数列{b n}是等比数列,故B正确;∵5d=5×1629=8029≠3,∴105=(2)5=25d≠23,∴b10≠8b5,故A错误;a30=a1+29d=5+16=21,∴a1b30=5×221>105,故C错误;∵a4=a1+3d=5+3×1629=19329,a5=a1+4d=5+4×1629=20929,∴3+5+72+4+6=3534=54=209193,故D正确.故选BD.16.(1)证明因为a n+1=32+1,所以1r1=13+23,所以1r1-1=131-1.因为a1=35,则11-1=23.所以数列1-1是首项为23,公比为13的等比数列.(2)解不存在.理由如下,由(1)知,1-1=23×13n-1=23,所以a n=33+2.假设存在互不相等的正整数m,s,t满足条件,则有+=2,(-1)2=(-1)(-1).由a n=33+2与(a s-1)2=(a m-1)(a t-1),得33+2-12=33+2-133+2-1.即3m+t+2×3m+2×3t=32s+4×3s.因为m+t=2s,所以3m+3t=2×3s.因为3m+3t≥23r=2×3s,当且仅当m=t时等号成立,这与m,s,t互不相等矛盾.所以不存在互不相等的正整数m,s,t满足条件.。
【高三英语】Z20名校联盟2023-2024学年高三上学期第一次联考英语试题(解析版)
Z20名校联盟（浙江省名校新高考研究联盟）2023-2024学年高三上学期第一次联考英语试题学校:___________姓名：___________班级：___________考号：___________二、阅读理解The ebike has become an essential item, and even the King has been spotted riding one. According to the market research company Mintel, sales have almost tripled over the past five years. While ebikes have become increasingly commonplace, they are still undeniably expensive. You can pick up a perfectly adequate push bike for £300, but most ebikes cost nearly £2,000. Now, Cycling Electric, designed to help consumers choose an ebike, offers the following recommendations.Best folding bikeCarbo Model XPrice: £2, 799 | Weight: 13.3kgRange: up to 34 milesThis is one of the most convenient bikes, from a little-known label. The lightweight Carbo X is the perfect example of convenience thanks to its carbon frame and belt drive, instead of a metal bike chain. This makes it lighter and less likely to get messy than an electric Brompton, with its more traditional, oily chain.Most stylishTemple Cycles ClassicPrice: from £2, 995 | Weight: 19kgRange: up to 74 milesThis Bristol-based brand is known for its elegant pushbikes, which are hand-built in the city.This is its electric version. It’s a very sleek and functional commuter option and not too heavy. Temples have fewer proprietary (品牌专卖的) parts and so are serviceable in any bike shop. Stylish as they may be, the VanMoofs and the Cowboys can be a bit more complex to get back-up and service.The money-no-object optionRiese & Müller Nevo4 GT Vario GXPrice: £5, 380 | Weight: 28.4kgRange: up to 93 milesThis is a prime example of the attention to detail delivering a high-quality experience in functionality, comfort and practicality — if you can afford it. It has the capacity to handle 25kg of luggage in a pannier, powerful road lights and a beautifully smooth motor.21．What is the advantage of the Temples over other stylish ebike brands?A．They are more lightweight. B．They have more functions.C．They have easier access to service. D．They are more comfortable.22．Which ebike will a consumer probably choose, who cares most about an excellent experience?A．Carbo Model X. B．The VanMoofs and the Cowboys.C．Temple Cycles Classic. D．Riese & Müller Nevo4 GT Vario GX. 23．Where is the text probably taken from?A．An online post. B．A magazine column.C．A market research report. D．An official document.【答案】21．C 22．D 23．B【导语】本文是一篇应用文，主要介绍的是Cycling Electric推荐的三款电动自行车。
[名师原创解析]2020届四川省巴蜀中学高考适应性月考卷(二)理科数学试题
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第九套 - 1
全国名校
合卷：河北邯郸焦子奇
【考点】三角函数的性质
【命题意图】本题考查了三角函数的性质，分类讨论的数学思想，考查了学生的逻辑思维能
力和运算能力。
答案：D.
解析：（浙江衢州汪强）
当 ω > 0 时， 5π ≤ ω ⋅ π + π < 13π ，即 2 ≤ ω < 6 ，所以 ω = 2，3，4，5 ；
全国名校
合卷：河北邯郸焦子奇
❿ 巴蜀中学 2020 届高考适应性月考卷（二）
理数
10.（巴蜀中学 2020 届高考适应性月考卷（二）理数）已知 AB ⋅ AC = 0, BC = 4, P 是三角
形 ABC 平面内任意一点，且满足| PA |= 1, PB ⋅ PC 的最小值是（ ）.
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第九套 - 4
全国名校
合卷：河北邯郸焦子奇
f (x) 的导函数，若关于 x 的方程 f '(x) − f (x) = 0 有两个不等的根，则实数a 的取值范围是 x +1
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【考点】导数与零点问题
【命题意图】此题对学生能力要求较高，是拉开学生得分档次的题目.本题考查了学生利，
第九套 - 2
全国名校
合卷：河北邯郸焦子奇
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解法 3：极限法 2
l1,l2 重合时，直线 AM 即抛物线在点 A 处的切线，直线 BN 即抛物线在点 B 处的切线，
联立直线l1 与抛物线C 消去 y 得 xA + xB = 2pk ，由阿基米德三角形知 xA + xB = 2xE ，
In-Process and Bulk Drug Product Holding Times说明书
Regulatory Basis:FDA Quality Systems RegulationsReference: FDA CFR - Code of Federal Regulations Title 21General Discussion:This Document sets out guidelines for the determination and validation of in-process and bulk product holding times.Maximum allowable hold times should be established for bulk and in-process drug products (where applicable). Typically one lot can be used for validating hold times. Data to justify the hold time can be collected during development on pilot scale batches, during process validation, via a historical review of batch data, or as part of a deviation with proper testing.Although there are no specific regulations or document documents on bulk product holding times, good manufacturing practice dictates that holding times should be validated to ensure that in-process and bulk product can be held, pending the next processing step, without any adverse effect to the quality of the material. This practice is supported by indirect references made to determining holding times in various FDA document documents, FDA regulations as follows:__ “if a firm plans to hold bulk drug products in storage…..stability data should be provided to demonstrate that extended storage in the described containersdoes not adversely affect the dosage form”.__ “stability data also may be necessary when the finished dosage form is stored in interim containers prior to filling into the marketed package. If the dosageform is stored in bulk containers for over 30 days, real-time stability dataunder specified conditions should be generated to demonstrate comparablestability to the dosage form in the marketed package. Interim storage of thedosage form in bulk containers should generally not exceed six months”.__ “when appropriate, time limits for the completion of each phase of production shall be established to assure the quality of the drug product.” .Thisregulation could be interpreted to include the time for holding bulk product aspart of the production process. “holding times (includes storage times) studiesmay be conducted during development or carried out in conjunction withprocess validation lots and shall be representative of full scale holding conditions”.For purposes of clarification, refer to Appendix A for definitions relating to bulkholding time. Holding time data may be generated in the following situations:•Bulk holding studies may be conducted on product developmental pilot scale batches to demonstrate comparable stability to the dosage form in the marketedpackage.•Holding data may be generated as part of a process validation study. Data can be collected on the bulk product itself after holding or collected after the heldproduct has been packaged.Typically, if these in-process products are used within 24 hours of manufacturing, no bulk holding time studies are deemed necessary. An in-process product that is held for longer than 24 hours should be monitored for physical characteristics and microbialcontamination. A solution/suspension should be held for the defined hold period. Atthe test points, a sample should betaken from the storage container and tested. Results obtained should be compared with the initial baseline data of the solution/suspensioncontrol sample results.Typical tests include the following: Microbial count; Yeast/Mould count; SpecificGravity; and Viscosity.3) Holding time considerations for Tablet Cores, Extended-Release Beads orPellets.Typically, in-process products such as cores, extended-release beads or pellets may be held for up to 30 days from their date of production without being retested prior touse. An in-process product that is held for longer than 30 days should be monitoredfor stability under controlled, long-term storage conditions for the length of theholding period. A representative portion of the core/bead/pellet should be held for the defined hold period. At the test points, a sample should be taken from the storagecontainer and tested. Results obtained should be compared with the initial baselinedata of the core/bead/pellet control sample results.Typical tests include the following: Hardness; Friability; Appearance;Dissolution/Disintegration; Assay; Degradation Products (where applicable); andMoisture Content.4)Holding time considerations for Bulk Tablets and Capsules.Typically, bulk tablets and capsules may be held for up to 30 days from their date ofproduction without being retested prior to use. A bulk product that is held for longerthan 30 days should be monitored for stability under controlled, long-term storageconditions for the length of the holding period. Interim storage of the dosage form inbulk containers should generally not exceed six months. At the test points, a sampleshould be taken from the storage container and tested. Results obtained should becompared with the initial baseline data of the tablet/capsule control sample results.Typical tests include the following: Hardness; Friability; Appearance; Dissolution (in the case of controlled and extended release products, the establishment of adissolution profile is recommended); Disintegration; Assay; Degradation Products(where applicable); Moisture Content, and microcount (where applicable).5) Holding time considerations for Oral Liquids and Semi-Solids (Suspensions,Creams, and Ointments).Typically, liquid and semi-solid dosage form products should be held for no morethan 5 days without a hold time study. Full scale batches should be used for thesestudies. Samples should be taken from the holding vessel after transfer from themanufacturing vessel, and again at the completion of the holding period. Multiplesamples should be taken at each time point if holding can impact product uniformity.Samples would be taken to prove that product uniformity of actives and preservatives。
2023年12月英语六级考试真题及答案详解和听力原文第二套
12月英语六级考试真题第二套Part I Writing （30minutes）Directions: For this part, you are allowed 30 minutes to write a short essay based on the picture below. You should focus on the difficulty in acquiring useful information in spite of advanced information technology. You are required to write at least 150 words but no more than 200 words．Part ⅡListening Comprehension (30 minutes)Section ADirections : In this section, you will hear 8 short conversations and 2 long conversations. At the end of each conversation, one or more questions will be asked about what was said. Both the conversation and the questions will be spoken only once. After each question there will be a pause. During the pause, you must read the four choices marked A., B., C. and. D., and decide which is the best answer. Then mark the corresponding letter on Answer Sheet 1 with a single line through the centre.1. A. The restaurant offers some specials each day.B. The restaurant is known for its food varieties.C. The dressing makes the mixed salad very inviting.D. The woman should mix the ingredients thoroughly.2. A. He took over the firm from Mary. C. He failed to foresee major problems.B. He is running a successful business. D. He is opening a new consulting firm.3. A. Someone should be put in charge of office supplies.B. The man can leave the discs in the office cabinet.C. The man may find the supplies in the cabinet.D. The printer in the office has run out of paper.4. A. He has to use a magnifying glass to see clearly.B. The woman can use his glasses to read.C. He has the dictionary the woman wants.D. The dictionary is not of much help to him.5. A. Redecorating her office.B. Majoring in interior design.C. Seeking professional advice.D. Adding some office furniture.6. A. Problems in port management.B. Improvement of port facilities.C. Delayed shipment of goods.D. Shortage of container ships.7.A. Their boss. B. A colleague. C. Their workload. D. A coffee machine.8. A. Call the hotel manager for help.B. Postpone the event until a later date.C. Hold the banquet at a different place.D. Get an expert to correct the error.Questions 9 to 11 are based on the conversation you have just heard.9 .A. He shares some of the household duties.B. He often goes back home late for dinner.C. He cooks dinner for the family occasionally.D. He dines out from time to time with friends.10. A. To take him to dinner.B. To talk about a budget plan.C. To discuss an urgent problem.D. To pass on an important message.11. A. Foreign investors are losing confidence in India's economy.B. Many multinational enterprises are withdrawing from India.C. There are wild fluctuations in the international money market.D. There is a sharp increase in India's balance of payment deficit. Questions 12 to 15 are based on the conversation you have just heard.12. A. They have unrealistic expectations about the other half.B. They may not be prepared for a lifelong relationship.C. They form a more realistic picture of life.D. They try to adapt to their changing roles.13. A. He is lucky to have visited many exotic places.B. He is able to forget all the troubles in his life.C. He is able to meet many interesting people.D. He is lucky to be able to do what he loves.14.A. It is stressful. B. It is full of time. C. It is all glamour. D. It is challenging15. A. Bothered. B. Amazed. C. Puzzled. D. Excited.Section BDirections : In this section, you will hear 3 short passages. At the end of each passage, you will hear some questions. Both the passage and the questions will be spoken only once. After you hear a question, you must choose the best answer from the four choices marked A., B.,C. and D . Then mark the corresponding letter on Answer Sheet I with a single line through the centre.Passage OneQuestions 16 to 18 are based on the passage you have just heard.16. A. Maintain the traditional organizational culture.B. Learn new ways of relating and working together.C. Follow closely the fast development of technology.D. Learn to be respectful in a hierarchical organization.17. A. How the team integrates with what it is supposed to serve.B. How the team is built to keep improving its performance.C. What type of personnel the team should be composed of.D. What qualifications team members should be equipped with.18. A. A team manager must set very clear and high objectives.B. Teams must consist of members from different cultures.C. Team members should be knowledgeable and creative.D. A team manager should develop a certain set of skills.Passage TwoQuestions 19 to 22 are based on the passage you have just heard.19. A. It is a platform for sharing ideas on teaching at the University of Illinois.B. It was mainly used by scientists and technical people to exchange text.C. It started off as a successful program but was unable to last long.D. It is a program allowing people to share information on the Web.20. A. He visited a number of famous computer scientists.B. He met with an entrepreneur named Jim Clark.C. He sold a program developed by his friends.D. He invested in a leading computer business.21. A. They had confidence in his new ideas.B. They trusted his computer expertise.C. They were very keen on new technology.D. They believed in his business connections.Passage ThreeQuestions 22 to 25 are based on the passage you have just heard.22. A. Prestige advertising.B. Institutional advertising.C. Word of mouth advertising.D. Distributing free trial products.23. A. To sell a particular product.B. To build up their reputation.C. To promote a specific service.D. To attract high-end consumers.24. A. By using the services of large advertising agencies.B. By hiring their own professional advertising staff.C. By buying media space in leading newspapers.D. By creating their own ads and commercials.25. A. Decide on what specific means of communication to employ.B. Conduct a large-scale survey on customer needs.C. Specify the objectives of the campaign in detail.D. Pretest alternative ads or commercials in certain regions.Section CDirections: In this section, you will hoar a passage three times. When the passage is read for the first time, you should listen carefully for its general idea. When the passage is read for the second time, you are required to fill in the blanks with the exact words you have just hoard. Finally, when the passage is read for the third time, you should chock what you have written.Extinction is difficult concept to grasp. It is an（26）concept. It's not at all like the killing of individual life forms that can be renewed through normal processes of reproduction. Nor is it simply（27）numbers. Nor is it damage that can somehow be remedied or for which some substitute can be found. Nor is it something that simply affects our own generation. Nor is it something that could be remedied by some supernatural power. It is rather an（28）and final act for which there is no remedy on earth or in heaven. A species once extinct is gone forever. However many generations （29)us in coming centuries, none of them will ever see this species that we extinguish. Not only are we bringing about the extinction of life（30）, we are also making the land and the air and the sea so toxic that the very conditions of life are being destroyed.（31）basic natural resources, not only are the nonrenewable resources being（32）in a frenzy ( 疯狂) of processing, consuming, and（33）, but we are also mining much of our renewable resources, such as the very soil itself on which terrestrial (地球上旳) life depends.The change that is taking place on the earth and in our minds is one of the greatest changes ever to take place in human affairs, perhaps the greatest, since what we are talking about is not simply another historical change or cultural （34）, but a change of geological and biological as well as psychological order of（35).Part ⅢReading Comprehension (40 minutes)Section ADirections: In this section, there is a passage with ten blanks. You are required to select one word for each blank from a list of choices given in a word bank following the passage. Read the passage through carefully before making yourchoices. Each choice in the bank is identified by a letter. Please mark the corresponding letter for each item on Answer Sheet 2 with a single line through the centre. You may not use any of the words in the bank more than once.Questions 36 to 45 are based on the following passage.It seems to be a law in the technology industry that leading companies eventually lose their positions, often quickly and brutally. Mobile phone champion Nokia, one of Europe's biggest technology success stories, was no（36）, losing its market share in just a few years.In , Nokia accounted for more than 40% of mobile phone sales（37）But consumers'preferences were already（38）toward touch-screen smart phones. With the introduction of Apple's phone in the middle of that year, Nokia's market share（39）rapidly and revenue plunged. By the end of , Nokia had sold its phone business to Microsoft.What sealed Nokia's fate was a series of decisions made by Stephen Elop in his position as CEO, which he（40）in October . Each day that Elop spent in charge of Nokia, the company's market value declined by $ 23 million, making him, by the numbers, one of the worst CEOs in history. But Elop was not the only person at（41）Nokia's board resisted change, making it impossible for the company to adapt to rapid shifts in the industry. Most（42）, Jorma Ollila, who had led Nokia's transition from an industrial company to a technology giant, was too fascinated by the company's（43）success to recognize the change that was needed to sustain its competitiveness. The company also embarked on a（44）cost-cutting program, which included the elimination of thousands of jobs. This contributed to the(45) of the company’s once-spirited culture.which had motivated employees to take risks and make miracles. Good leaders left the company, taking Nokia's sense of vision and directions with them. Not surprisingly, much of Nokia's most valuable design and programming talent left as well.A. assumedB. biasC. desperateD. deteriorationE. exceptionF. faultG. incidentallyH. notablyI. previousJ. relayedK. shiftingL. shrankM. subtleN. transmittingO. worldwideSection BDirections : In this section, you are going to read a passage with ten statements attached to it. Each statement contains information given in one of the paragraphs. Identify the paragraph from which the information is derived. You may choose a paragraph more than once.Each paragraph is marked with a letter. Answer the questions by marking the corresponding letter on Answer Sheet 2.First-Generation College-Goers: Unprepared and Behind Kids who are the first in their families to brave the world of higher education come on campus with little academic know—how and are much more likely than their peers to drop out before graduation.[ A] When Nijay Williams entered college last fall as a first—generation student and Jamaican immigrant, he was academically unprepared for the rigors of higher education. Like many first—generation students, he enrolled in a medium-sized state university many of his high school peers were also attending, received a Pell Grant, and took out some small federal loans to cover other costs.Given the high price of room and board and the closeness of the school to his family, he chose to live at home and worked between 30 and 40 hours a week while taking a full class schedule.[ B] What Nijay didn't realize about his school—Tennessee State University—was its frighteningly low graduation rate: a mere 29 percent for its first-generation students. At the end of his first year, Nijay lost his Pell Grant of over $ 5,000 after narrowly missing the 2.0 GPA cut-off, making it impossible for him to continue paying for school.[ C ]Nijay represents a large and growing group of Americans: first—generation college students who enter school unprepared or behind. To make matters worse, these schools are ill-equipped to graduate these students—young adults who face specific challenges and obstacles. They typically carry financial burdens that outweigh those of their peers, are more likely to work while attending school, and often require significant academic remediation (补习).[ D ] Matt Rubinoff directs I'm First, a nonprofit organization launched last October to reach out to this specific population of students. He hopes to distribute this information and help prospective college-goers fad the best post-secondary fit. And while Rubinoff believes there are a good number of four—year schools that truly care about these students and set aside significant resources and programs for them, he says that number isn't high enough.[ E ] "It's not only the selective and elite institutions that provide those opportunities for a small subset of this population," Rubinoff said, adding that a majority of first-generation undergraduates tend toward options such as online programs, two—year colleges, and commuter state schools."Unfortunately, there tends to be a lack of information and support to help students think bigger and broader. "[ F] Despite this problem, many students are still drawn to these institutions--and two-year schools in particular. As a former high school teacher, I saw students choose familiar, cheaper options year after year. Instead of skipping out on higher education altogether, they chose community colleges or state schools with low bars for admittance.[ G]"They underestimate themselves when selecting a university," said Dave Jarrat, a marketing executive for InsideTrack, a for—profit organization that specializes in coaching low-income students and supporting colleges in order to help students thrive. "The reality of it is that a lot of low-income kids could be going to elite universities on a full ride scholarship and don't even realize it. "[ H] "Many students are coming from a situation where no one around them has the experience of successfully completing higher education, so they are coming in questioning themselves and their college worthiness," Jarrat continued. That helps explain why, as I'm First's Rubinoff indicated, the schools to which these students end up resorting can end up being some of the poorest matches for them. The University of Tennessee in Knoxville offers one example of this dilemma. A flagship university in the South, the school graduates just 16 percent of its first—generation students, despite its overall graduation rate of 71 percent. Located only a few hours apart, The University of Tennessee and Tennessee State are worth comparing. Tennessee State's overall graduation rate is a tiny 39 percent, but at least it has a smaller gap between the outcomes for first—generation students and those of their peers.[ I] Still, the University of Tennessee deserves credit for being transparent. Many large institutions keep this kind of data secret—or at least make it incredibly difficult to find The University of North Carolina at Chapel Hill, for instance, admits only that the graduation rate for its first—generation pupils is "much lower" than the percentage of all students who graduate within four years (81 percent).[ J] It is actually quite difficult to freed reliable statistics on the issue for many schools. Higher education institutions are, under federal law, required to report graduation rates, but these reports typically only include Pell recipient numbers —not necessarily rates specific to first—generation students. Other initiatives fail to break down the data, too. Imagine how intimidating it can be for prospective students unfamiliar with the complexities of higher education to navigate this kind of information and then identify which schools are the best fit.[ K] It was this lack of information that prompted the launch of I'm First in , originally as an ann. of its umbrella organization, the Center For Student Opportunity."If we can help to direct students to more of these types of campuses and help students to understand them to be realistic and accessible places, have them apply to these schools at greater frequency and ultimately get in and enroll, we are going to raise the success rate," Rubinoff said, citing a variety of colleges ranging from large state institutions to smaller private schools.[ L] Chelsea Jones, who now directs student programming at I'm First, was a first—generation college student at Howard. Like other student new to the intimidating higher—education world, she often struggled on her path to college, "There wasn't really a college—bound culture at my high school," she said. "I wanted to go to college but I didn't reallyknow the process. " Jones became involved with a college—access program through Princeton University in high school. Now, she attributesmuch of her understanding of college to that: "But once I got to campus, it was a completely different ball game that no one really prepared me for. "[ M] She was fortunate, though. Howard, a well—regarded historically black college, had an array of resources for its first—generation students, including matching kids with counselors, commenting first—generation students to one another, and TRIO, a national program that supported 200 students on Howard's campus. Still, Jones represents a small percentage of first-generation students who are able to gain entry into more elite universities, which are often known for robust financial aid packages and remarkably high graduation rates for first—generation students.(Harvard, for example, boasts a six—year graduation rate for underrepresented minority groups of 98 percent. ) [ N]Christian Vazquez, a first—generation Yale graduate, is another exception, his success story setting him far apart from students such as Nijay. "There is a lot of support at Yale, to an extent, after a while, there is too much support," he said, half—joking about the countless resources available at the school. Students are placed in small groups with counselors ( trained seniors on campus) ;they have access to cultural and ethnic affinity (联络) groups, tutoring centers and also have asummer orientation specifically for first—generation students ( the latter being one of the most common programs for students).[ O]"Our support structure was more like : ' You are going to get through Yale; you are going to do well,' " he said, hinting at mentors (导师), staff, and professors who all provided significant support for students who lacked confidence about "belonging" at such a top institution.46. Many first—generation college—goers have doubts about their abilities to get a college degree.47. First—generation college students tend to have much heavier financial burdens than their peers.48. The graduation rate of first—generation students at Nijay's university was incredibly low.49. Some top institutions like Yale seem to provide first—generation students with more support than they actually need.50. On entering college, Nijay Williams had no idea how challenging college education was.51. Many universities simply refuse to release their exact graduation rates for first-generation students.52. According to a marketing executive, many students from low-income families don't know they could have achance of going to an elite university.53. Some elite universities attach great importance to building up the first—generation students' serf—confidence.54. I'm First distributes information to help first-generation college-goers find schools that are most suitable for them.55. Elite universities tend to graduate fan’s-generation students at a higher rate.Section CDirections: There are 2 passages in this section. Each passage is followed by some questions or unfinished statements. For each of them there are four choices marked A., B., C. and D . You should decide on the best choice and mark the corresponding letter on Answer Sheet 2 with a single line through the centre.Passage OneQuestions 56 to 60 are based on the following passage.Saying they can no longer ignore the rising prices of health care, some of the most influential medical groups in the nation are recommending that doctors weigh the costs, not just the effectiveness of treatments, as they make decisions about patient care. The shift, little noticed outside the medical establishment but already controversial inside it, suggests that doctors are starting to redefine their roles, from being concerned exclusively about individual patients to exerting influence on how healthcare dollars are spent. In practical terms, the new guidelines being developed could result in doctors choosing one drug over another for cost reasons or even deciding that a particular treatment—at the end of life, for example—is too expensive. In the extreme, some critics have said that making treatment decisions based on cost is a form of rationing. Traditionally, guidelines have heavily influenced the practice of medicine, and the latest ones are expected to make doctors more conscious of the economic consequences of their decisions, even though there's no obligation to follow them. Medical society guidelines are also used by insurancecomoanies to help determine reimbursement (报销) policies. Some doctors see a potential conflict in trying to be both providers of patient care and facial.Overseers. "There should be forces in society who should be concerned about the budget, but they shouldn't be functioning simultaneously as doctors," said Dr. Martin Samuels at a Boston hospital. He said doctors risked losing the trust of patients if they told patients, "I'm not going to do what I think is best for you because I think it's bad for the healthcare budget in Massachusetts. " Doctors can face some grim trade—offs. Studies have shown, for example, that two drugs are about equally effective in treating macular degeneration, and eye disease. But one costs $ 50 a dose and the other close to $ 2,000. Medicare could save hundreds of millions of dollars a year if everyone used the cheaper drug, Avastin, instead ofthe costlier one, Lucentis. But the Food and Drug Administration has not approved Avastin for use in the eye. and using it rather than the alternative, Lucentis, might carry an additional, although slight, safety risk. Should doctors consider Medicare's budget in deciding what to use?"I think ethically (在道德层面上) we are just worried about the patient in front of us and not trying to save money for the insurance industry or society as a whole," said Dr. Donald Jensen. Still, some analysts say that there's a role for doctors to play in cost analysis because not many others are doing so. "In some ways," said Dr. Daniel Sulmasy, "it represents a failure of wider society to take up the issue. "56. What do some most influential medical groups recommend doctors do?A. Reflect on the responsibilities they are supposed to take.B. Pay more attention to the effectiveness of their treatments.C. Take costs into account when making treatment decisions.D. Readjust their practice in view of the cuts in health care.57. What were doctors mainly concerned about in the past?A. Specific medicines to be used.B. Effects of medical treatment.C. Professional advancement.D. Patients' trust.58. What may the new guidelines being developed lead to?A. The redefining of doctors' roles.B. Overuse of less effective medicines.C. Conflicts between doctors and patients.D. The prolonging of patients' suffering.59. What risk do doctors see in their dual role as patient care providers and financial overseers?A. They may be involved in a conflict of interest.B. They may be forced to divide their attention.C. They may have to use less effective drugs.D. They may lose the respect of patients.60. What do some experts say about doctors' involvement in medical cost analysis?A. It may add to doctors' already heavy workloads.B. It will help to save money for society as a whole.C. It results from society's failure to tackle the problem.D. It raises doctors' awareness of their social responsibilities.Passage TwoQuestions 61 to 65 are based on the following passage.Economic inequality is the "defining challenge of our time," President Barack Obama declared in a speech last monthto the Center for American Progress. Inequality is dangerous, he argued, not merely because it doesn't look good to have a large gap between the rich and the poor, but because inequality itself destroys upward mobility, making it harder for the poor to escape from poverty. "Increased inequality and decreasing mobility pose a fundamental threat to the American Dream," he said. Obama is only the most prominent public figure to declare inequality Public Enemy No. 1 and the greatest threat to reducing poverty in America. A number of prominent economists have also argued that it's harder for the poor to climb the economic ladder today because the rungs (横档) in that ladder have grown farther apart.For all the new attention devoted to the 1 percent, a new dam set from the Equality of Opportunity Project at Harvard and Berkeley suggests that, if we care about upward mobility overall, we're vastly exaggerating the dangers of the rich—poor gap. Inequality itself is not a particularly strong predictor of economic mobility, as sociologist Scott Winship noted in a recent article based on his analysis of this data. So what factors, at the community level, do predict if poor children will move up the economic ladder as adtdts? what explains, for instance, why the Salt Lake City metro area is one of the 100 largest metropolitan areas most likely to lift the fortunes of the poor and the Atlanta metro area is one of the least likely?Harvard economist Raj Cherty has pointed to economic and racial segregation, community density, the size of a community's middle class, the quality of schools, commitments religiosity, and family structure, which he calls the "single strongest correlate of upward mobility. " Chetty finds that communities like Salt Lake City, with high levels of two-parent families and religiosity, are much more likely to see poor children get ahead than communities like Atlanta, with high levels of racial and economic segregation. Chetty has not yet issued a comprehensive analysis of the relative predictive power of each of these factors. Based on my analyses of the data. of the factors that Chetty has highlighted, the following three seem to be most predictive of upward mobility in a given community.1. Per-capita (人均) income growth2. Prevalence of single mothers ( where correlation is strong, but negative)3. Per-capita local government spending In other words, communities with high levels of per-capita income growth, high percentages of two-parent families, and high local government spending-which may stand for good schools-are the most likely to help poor children relive Horatio Alger's rags-to-riches story.61. How does Obama view economic inequality?A. It is the biggest obstacle to social mobility.B. It is the greatest threat to social stability.C. It is the No. 1 enemy of income growth.D. It is the most malicious social evil of our time.62. What do we learn about the inequality gap from Scott Winship's data analysis?。
增益通150WLDMOS置于2496MHz-2690MHz兼的对ста精度高效LDMOS强力输出输出
BLC9G27LS-151AVPower LDMOS transistorRev. 3 — 24 May 2017Product data sheet 1. Product profile1.1General description150W LDMOS packaged asymmetrical Doherty power transistor for base stationapplications at frequencies from 2496MHz to 2690MHz.Table 1.Typical performanceTypical RF performance at T case = 25 ︒C in the Doherty demo board.Test signal f V DS P L(AV)G pηD ACPR(MHz)(V)(W)(dB)(%)(dBc)1-carrier W-CDMA2496 to 26902828.215.548-30 [1][1]Test signal: 3GPP test model 1; 1 to 64 DPCH; PAR=7.2dB at 0.01% probability on CCDF.1.2Features and benefits⏹Excellent ruggedness⏹High efficiency⏹Low thermal resistance providing excellent thermal stability⏹Decoupling leads to enable improved video bandwidth⏹Lower output capacitance for improved performance in Doherty applications⏹Designed for low memory effects providing excellent pre-distortability⏹Internally matched for ease of use⏹Integrated ESD protection⏹Compliant to Directive 2002/95/EC, regarding Restriction of Hazardous Substances(RoHS)1.3Applications⏹RF power amplifier for LTE base stations and multi carrier applications in the2496MHz to 2690MHz frequency range2. Pinning informationTable 2.Pinning[1]Connected to flange.3. Ordering informationTable 3.Ordering informationType number PackageName Description Version BLC9G27LS-151AV-air cavity plastic earless flanged package; 6 leads SOT1275-14. Limiting valuesTable 4.Limiting valuesIn accordance with the Absolute Maximum Rating System (IEC 60134).Symbol Parameter Conditions Min Max UnitV DS drain-source voltage-65VV GS gate-source voltage-5+13VT stg storage temperature-65+150︒CT j junction temperature[1]-225︒C[1]Continuous use at maximum temperature will affect the reliability, for details refer to the online MTFcalculator.5. Thermal characteristicsTable 5.Thermal characteristicsSymbol Parameter Conditions Typ UnitR th(j-case)thermal resistance from junction to case T case=80︒C; I Dq=280mA;V GS(amp) peak = 0.85 VP L = 28.2 W0.314K/WP L = 44.7 W0.270K/W6. CharacteristicsTable 6.DC characteristicsT j = 25 ︒C unless otherwise specified.Symbol Parameter Conditions Min Typ Max UnitMain deviceV(BR)DSS drain-source breakdown voltage V GS=0V;I D=0.5mA65--VV GS(th)gate-source threshold voltage V DS=10 V; I D=50mA 1.52 2.5VV GSq gate-source quiescent voltage V DS=28 V; I D=300mA 1.75 2.3 2.85VI DSS drain leakage current V GS=0V;V DS=32V-- 1.4μA-10.9-AI DSX drain cut-off current V GS=V GS(th)+3.75 V;V DS=10VI GSS gate leakage current V GS=11V;V DS=0V--140nAg fs forward transconductance V DS=10V;I D=50 mA-0.53-S-285460mΩR DS(on)drain-source on-state resistance V GS=V GS(th) + 3.75V;I D=1.75APeak deviceV(BR)DSS drain-source breakdown voltage V GS=0V;I D=1.1mA65--VV GS(th)gate-source threshold voltage V DS=10 V; I D=110mA 1.52 2.5VV GSq gate-source quiescent voltage V DS=28 V; I D=660mA 1.65 2.2 2.75VI DSS drain leakage current V GS=0V;V DS=32V-- 1.4μA-23.8-AI DSX drain cut-off current V GS=V GS(th)+3.75 V;V DS=10VI GSS gate leakage current V GS=11V;V DS=0V--140nAg fs forward transconductance V DS=10V;I D=110mA- 1.16-S-130215mΩR DS(on)drain-source on-state resistance V GS=V GS(th) + 3.75V;I D=3.85ATable 7.RF characteristicsTest signal: 1-carrier W-CDMA; PAR = 7.2 dB at 0.01% probability on the CCDF;3GPP test model1; 1 to 64 DPCH; f1=2496MHz; f2=2690MHz; RF performance at V DS=28V;I Dq=280mA (main); V GS(amp)peak=0.8V; T case=25︒C; unless otherwise specified; in anasymmetrical Doherty production test circuit at frequencies from 2496MHz to 2690 MHz.Symbol Parameter Conditions Min Typ Max UnitG p power gain P L(AV)=28W14.415.6-dBRL in input return loss P L(AV)=28W--11-7dBηD drain efficiency P L(AV)=28W4146-%ACPR adjacent channel power ratio P L(AV)=28W--30-25dBcTable 8.RF characteristicsTest signal: pulsed CW; t p=100μs; δ=10%; f=2690MHz; RF performance at V DS = 28 V;I Dq=280mA(main); V GS(amp)peak=0.8V; T case = 25 ︒C; unless otherwise specified; tested in anasymmetrical Doherty production test circuit at frequencies from 2496MHz to 2690MHz.Symbol Parameter Conditions Min Typ Max UnitP L(3dB)output power at 3 dB gain compression135155-W7. Test information7.1Ruggedness in Doherty operationThe BLC9G27LS-151AV is capable of withstanding a load mismatch corresponding to aVSWR=10: 1 through all phases under the following conditions: V DS=28V;I Dq=200mA (main); V GS(amp)peak=0.85V; P L=50 W(1-carrier W-CDMA);f=2496MHz.7.2Impedance informationTable 9.Typical impedance of main deviceMeasured load-pull data of main device; I Dq = 300 mA (main); V DS = 28 V.f Z S [1]Z L [1]P L [2]ηD [2]G p [2](MHz)(Ω)(Ω)(W)(%)(dB)Maximum power load2496 6.2 - j7.7 3.3 - j7.771.555.818.12600 6.1- j5.9 3.3 - j7.771.355.718.52690 3.6 - j5.4 3.3 - j7.766.954.919.1Maximum drain efficiency load2496 6.2 - j7.7 6.4 - j5.752.863.520.32600 6.1- j5.9 6.0 - j5.952.164.321.12690 3.6 - j5.4 5.0 - j5.048.561.821.5[1]Z S and Z L defined in Figure1.[2]at 3 dB gain compression.Table 10.Typical impedance of peak deviceMeasured load-pull data of peak device; I Dq = 600 mA (peak); V DS = 28 V.f Z S [1]Z L [1]P L [2]ηD [2]G p [2](MHz)(Ω)(Ω)(W)(%)(dB)Maximum power load24967.2 - j8.6 4.1- j9.1146.958.217.626008.0- j6.3 4.1- j9.1141.156.017.92690 6.0 - j2.8 5.0 - j10.0137.355.718.3Maximum drain efficiency load24967.2 - j8.6 5.8- j6.2115.565.319.526008.0- j6.3 5.4 - j5.5103.264.220.22690 6.0 - j2.8 4.8 - j5.998.562.820.6[1]Z S and Z L defined in Figure1.[2]at 3 dB gain compression.7.3Recommended impedances for Doherty designTable 11.Typical impedance of main device at 1:1 loadMeasured load-pull data of main device; I Dq = 300 mA (main); V DS = 28 V.f Z S [1]Z L [1]P L [2]ηD [3]G p [3](MHz)(Ω)(Ω)(dBm)(%)(dB) 2496 6.2 - j7.7 3.7 - j7.048.141.518.5 2600 6.1- j5.9 3.7 - j7.148.042.018.7 2690 3.6 - j5.4 3.7 - j7.248.042.019.3[1]Z S and Z L defined in Figure1.[2]at 3 dB gain compression.[3]at P L(AV)=44.5 dBm.Table 12.Typical impedance of main device at 1:2.5 loadMeasured load-pull data of main device; I Dq = 300 mA (main); V DS = 28 V.f Z S [1]Z L [1]P L [2]ηD [3]G p [3](MHz)(Ω)(Ω)(dBm)(%)(dB) 2496 6.2 - j7.7 6.8 - j12.946.25520.7 2600 6.1- j5.9 6.0 - j14.146.75421.3 2690 3.6 - j5.4 5.5- j13.745.95321.8[1]Z S and Z L defined in Figure1.[2]at 3 dB gain compression.[3]at P L(AV)=44.5 dBm.7.4VBW in Doherty operationThe BLC9G27LS-151AV shows 100MHz (typical) video bandwidth in Doherty demo board in 2600MHz at V DS=28V;I Dq=250 mA and V GS(amp)peak=0.8V.7.5Test circuit[1]American Technical Ceramics type 600F or capacitor of same quality [2]Murata or capacitor of same qualityTable 13.List of components See Figure 2 for component ponentDescriptionValue RemarksC1, C2, C3, C4, C6, C7, C8multilayer ceramic chip capacitor 9.1pF [1]C5multilayer ceramic chip capacitor 4.3pF [1]C9, C11multilayer ceramic chip capacitor 1 μF, 50V [2]C10, C12, C13, C14, C15, C16multilayer ceramic chip capacitor 10 μF, 50V [2]C17, C18electrolytic capacitor 1000 μF, 100V R1resistor 51 ΩSMD 0805R2. R3resistor9.1 ΩSMD 08057.6Graphical data 7.6.1Pulsed CW7.6.21-Carrier W-CDMA7.6.32-Tone VBW8. Package outlineFig 9.Package outline SOT1275-19. Handling informationTable 14.ESD sensitivityESD model ClassCharged Device Model (CDM); According to ANSI/ESDA/JEDEC standard JS-002C2A [1]Human Body Model (HBM); According to ANSI/ESDA/JEDEC standard JS-001 2 [2][1]CDM classification C2A is granted to any part that passes after exposure to an ESD pulse of 500V, but failsafter exposure to an ESD pulse of 750V.[2]HBM classification 2 is granted to any part that passes after exposure to an ESD pulse of 2000V, but failsafter exposure to an ESD pulse of 4000V.10. AbbreviationsTable 15.AbbreviationsAcronym Description3GPP3rd Generation Partnership ProjectCCDF Complementary Cumulative Distribution FunctionCW Continuous WaveDPCH Dedicated Physical CHannelESD ElectroStatic DischargeLDMOS Laterally Diffused Metal-Oxide SemiconductorLTE Long Term EvolutionMTF Median Time to FailurePAR Peak-to-Average RatioSMD Surface Mounted DeviceVBW Video BandWidthVSWR Voltage Standing Wave RatioW-CDMA Wideband Code Division Multiple Access11. Revision historyTable 16.Revision historyDocument ID Release date Data sheet status Change notice SupersedesBLC9G27LS-151AV v.320170524Product data sheet-BLC9G27LS-151AV v.2 Modifications:•Table2 on page2: change simplified outline•Table3 on page2: change version to SOT1275-1•Figure9 on page10: change package outline drawing to SOT1275-1BLC9G27LS-151AV v.220161202Product data sheet-BLC9G27LS-151AV v.1 BLC9G27LS-151AV v.120160226Product data sheet--12. Legal information12.1 Data sheet status[1]Please consult the most recently issued document before initiating or completing a design.[2]The term ‘short data sheet’ is explained in section “Definitions”.[3]The product status of device(s) described in this document may have changed since this document was published and may differ in case of multiple devices. The latest product statusinformation is available on the Internet at URL .12.2 DefinitionsDraft — The document is a draft version only. The content is still under internal review and subject to formal approval, which may result in modifications or additions. Ampleon does not give any representations or warranties as to the accuracy or completeness of information included herein and shall have no liability for the consequences of use of such information.Short data sheet — A short data sheet is an extract from a full data sheet with the same product type number(s) and title. A short data sheet is intended for quick reference only and should not be relied upon to contain detailed and full information. For detailed and full information see the relevant full data sheet, which is available on request via the local Ampleon sales office. In case of any inconsistency or conflict with the short data sheet, the full data sheet shall prevail.Product specification — The information and data provided in a Product data sheet shall define the specification of the product as agreed between Ampleon and its customer, unless Ampleon and customer have explicitly agreed otherwise in writing. In no event however, shall an agreement be valid in which the Ampleon product is deemed to offer functions and qualities beyond those described in the Product data sheet.12.3 DisclaimersLimited warranty and liability — Information in this document is believed to be accurate and reliable. However, Ampleon does not give any representations or warranties, expressed or implied, as to the accuracy or completeness of such information and shall have no liability for the consequences of use of such information. Ampleon takes no responsibility for the content in this document if provided by an information source outside of Ampleon.In no event shall Ampleon be liable for any indirect, incidental, punitive, special or consequential damages (including - without limitation - lost profits, lost savings, business interruption, costs related to the removal or replacement of any products or rework charges) whether or not such damages are based on tort (including negligence), warranty, breach of contract or any other legal theory.Notwithstanding any damages that customer might incur for any reason whatsoever, Ampleon’s aggregate and cumulative liability towards customer for the products described herein shall be limited in accordance with the Terms and conditions of commercial sale of Ampleon.Right to make changes — Ampleon reserves the right to make changes to information published in this document, including without limitation specifications and product descriptions, at any time and without notice. This document supersedes and replaces all information supplied prior to the publication hereof.Suitability for use — Ampleon products are not designed, authorized or warranted to be suitable for use in life support, life-critical or safety-critical systems or equipment, nor in applications where failure or malfunction of an Ampleon product can reasonably be expected to result in personal injury, death or severe property or environmental damage. Ampleon and its suppliers accept no liability for inclusion and/or use of Ampleon products in such equipment or applications and therefore such inclusion and/or use is at the customer’s own risk.Applications — Applications that are described herein for any of these products are for illustrative purposes only. Ampleon makes no representation or warranty that such applications will be suitable for the specified use without further testing or modification.Customers are responsible for the design and operation of their applications and products using Ampleon products, and Ampleon accepts no liability for any assistance with applications or customer product design. It is customer’s sole responsibility to determine whether the Ampleon product is suitable and fit for the customer’s applications and products planned, as well as for the planned application and use of customer’s third party customer(s). Customers should provide appropriate design and operating safeguards to minimize the risks associated with their applications and products.Ampleon does not accept any liability related to any default, damage, costs or problem which is based on any weakness or default in the customer’s applications or products, or the application or use by customer’s third party customer(s). Customer is responsible for doing all necessary testing for the customer’s applications and products using Ampleon products in order to avoid a default of the applications and the products or of the application or use by customer’s third party customer(s). Ampleon does not accept any liability in this respect.Limiting values — Stress above one or more limiting values (as defined in the Absolute Maximum Ratings System of IEC60134) will cause permanent damage to the device. Limiting values are stress ratings only and (proper) operation of the device at these or any other conditions above those given in the Recommended operating conditions section (if present) or the Characteristics sections of this document is not warranted. Constant or repeated exposure to limiting values will permanently and irreversibly affect the quality and reliability of the device.Terms and conditions of commercial sale — Ampleon products are sold subject to the general terms and conditions of commercial sale, as published at /terms, unless otherwise agreed in a valid written individual agreement. In case an individual agreement is concluded only the terms and conditions of the respective agreement shall apply. Ampleon hereby expressly objects to applying the customer’s general terms and conditions with regard to the purchase of Ampleon products by customer.No offer to sell or license — Nothing in this document may be interpreted or construed as an offer to sell products that is open for acceptance or the grant, conveyance or implication of any license under any copyrights, patents or other industrial or intellectual property rights.Export control — This document as well as the item(s) described herein may be subject to export control regulations. Export might require a prior authorization from competent authorities.Document status[1][2]Product status[3]DefinitionObjective [short] data sheet Development This document contains data from the objective specification for product development. Preliminary [short] data sheet Qualification This document contains data from the preliminary specification.Product [short] data sheet Production This document contains the product specification.Non-automotive qualified products — Unless this data sheet expressly states that this specific Ampleon product is automotive qualified, the product is not suitable for automotive use. It is neither qualified nor tested in accordance with automotive testing or application requirements. Ampleon accepts no liability for inclusion and/or use of non-automotive qualified products in automotive equipment or applications.In the event that customer uses the product for design-in and use in automotive applications to automotive specifications and standards, customer (a) shall use the product without Ampleon’ warranty of the product for such automotive applications, use and specifications, and (b) whenever customer uses the product for automotive applications beyond Ampleon’ specifications such use shall be solely at customer’s own risk, and (c) customer fully indemnifies Ampleon for any liability, damages or failed product claims resulting from customer design and use of the product for automotive applications beyond Ampleon’ standard warranty and Ampleon’ product specifications.Translations — A non-English (translated) version of a document is for reference only. The English version shall prevail in case of any discrepancy between the translated and English versions.12.4 TrademarksNotice: All referenced brands, product names, service names and trademarks are the property of their respective owners.Any reference or use of any ‘NXP’ trademark in this document or in or on the surface of Ampleon products does not result in any claim, liability or entitlement vis-à-vis the owner of this trademark. Ampleon is no longer part of the NXP group of companies and any reference to or use of the ‘NXP’ trademarks will be replaced by reference to or use of Ampleon’s own trademarks.13. Contact informationFor more information, please visit: For sales office addresses, please visit: /sales14. Contents1 Product profile. . . . . . . . . . . . . . . . . . . . . . . . . . 11.1 General description . . . . . . . . . . . . . . . . . . . . . 11.2 Features and benefits. . . . . . . . . . . . . . . . . . . . 11.3 Applications . . . . . . . . . . . . . . . . . . . . . . . . . . . 12 Pinning information. . . . . . . . . . . . . . . . . . . . . . 23 Ordering information. . . . . . . . . . . . . . . . . . . . . 24 Limiting values. . . . . . . . . . . . . . . . . . . . . . . . . . 25 Thermal characteristics . . . . . . . . . . . . . . . . . . 26 Characteristics. . . . . . . . . . . . . . . . . . . . . . . . . . 37 Test information. . . . . . . . . . . . . . . . . . . . . . . . . 47.1 Ruggedness in Doherty operation . . . . . . . . . . 47.2 Impedance information. . . . . . . . . . . . . . . . . . . 47.3 Recommended impedances for Doherty design 57.4 VBW in Doherty operation . . . . . . . . . . . . . . . . 57.5 Test circuit. . . . . . . . . . . . . . . . . . . . . . . . . . . . . 67.6 Graphical data . . . . . . . . . . . . . . . . . . . . . . . . . 77.6.1 Pulsed CW . . . . . . . . . . . . . . . . . . . . . . . . . . . . 77.6.2 1-Carrier W-CDMA . . . . . . . . . . . . . . . . . . . . . . 87.6.3 2-Tone VBW. . . . . . . . . . . . . . . . . . . . . . . . . . . 98 Package outline. . . . . . . . . . . . . . . . . . . . . . . . 109 Handling information. . . . . . . . . . . . . . . . . . . . 1110 Abbreviations. . . . . . . . . . . . . . . . . . . . . . . . . . 1111 Revision history. . . . . . . . . . . . . . . . . . . . . . . . 1212 Legal information. . . . . . . . . . . . . . . . . . . . . . . 1312.1 Data sheet status . . . . . . . . . . . . . . . . . . . . . . 1312.2 Definitions. . . . . . . . . . . . . . . . . . . . . . . . . . . . 1312.3 Disclaimers. . . . . . . . . . . . . . . . . . . . . . . . . . . 1312.4 Trademarks. . . . . . . . . . . . . . . . . . . . . . . . . . . 1413 Contact information. . . . . . . . . . . . . . . . . . . . . 1414 Contents. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . 15Please be aware that important notices concerning this document and the product(s)described herein, have been included in section ‘Legal information’.© Ampleon Netherlands B.V.2017.All rights reserved.For more information, please visit: For sales office addresses, please visit: /sales。
2024年全国高考英语新高考I卷讲评
此外，温室周围的丝绸之路花园带领游客进行一次受古代丝绸之路影响的旅程。通过古 代丝绸之路，丝绸及许多植物品种首次被引入英国。这些植物包括现代西方最爱的迷迭 香、薰衣草和茴香。花园中还有一条蜿蜒的小径，指引游客穿越丝绸之路的十二个地区。 该路径还为游客提供了300多种植物品种供游客欣赏。
拓展
“walk”一般主要作为动词和名词使用。 作为名词时，如：Take a walk in the park.（在公园里散散步）。 作为动词时，如：I walk to school every day.（我每天步行去上学）。 在“walk sb through”这个短语中，“walk”用作动词，主要有以下含 义和用法： “walk”在这里表示“引导、带领、陪着（某人）走（过某个过程、步骤 等）”，强调以一种逐步的、引导式的方式陪伴某人经历或完成某事。 例如： The trainer will walk you through the entire procedure. （培训师会带领你完成整个过程。） It's my responsibility to walk him through this difficult time. （我的责任是陪着他度过这段艰难时期。）
Heatherwick Studio recently built a greenhouse at the edge of the National
Trust’s Woolbeding Gardens. This beautiful structure, named Glasshouse, is at the
through a journey influenced by the ancient Silk Road, by which silk as well as many plant species came to Britain for 61the first time. These plants included
ELCO EDM-76 闹钟说明书
DESPERTADOR DIGITALModelo: EDM-76Leer las instrucciones antes de su uso y guárdelas para futuras consultasEstimado cliente,Le agradecemos que se haya decidido por la compra de un producto de la marca ELCO, en concreto el modelo EDM-76. Su tecnología, diseño y funcionalidad junto con el hecho de superar las más estrictas normas de calidad le comportarán total satisfacción durante mucho tiempo. El contenido de este manual puede ser actualizado para un mejor servicio. Reservado el derecho de realizar cambios en este manual sin previo aviso.1.Pantalla alternativa: hora/ temperatura.2.Dígitos LED en color blanco .3.Formato 12/24horas.4.Temperatura °C y °F.5.Calendario desde el año 2000 hasta el año 2099.6. 3 niveles de luminosidad.7. 3 Alarmas.8.Modo de ahorro de energía.9.Funcionamiento a red y pilas.a 4 pilas tipo AAA. (no incluidas)TemperaturaPulse el botón de “UP” para cambiar entre los modos de °C ó °F.Fahrenheit CentígradosAjustes del brillo en pantallaEn esta opción podrá cambiar la intensidad de iluminación de los dígitos en pantalla.Tome nota que automáticamente la intensidad de iluminación se pondrá al mínimo desde las 18:00h hasta las 7:00.Para ajustar la iluminación manualmente, mantener pulsado durante 3 segundos el botón “UP” y en pantalla aparecerá “L3”, a continuación pulse el botón “DOWN” cambiará la intensidad de la iluminación a “L2” que es la intermedia y si vuelve a pulsar el botón “DOWN” cambiará la intensidad de la iluminación a “L1” que es la mínima. Para aumentar la intensidad de iluminación, pulsar el botón “UP” hasta la intensidad deseada.Brillo alto Brillo medio Brillo bajo Ahorro de energiaEn este apartado existen dos modos:ON:sd Es un sistema de ahorro de energía para un bajo consumo, es decir que la pantalla permanece encendida durante 5 segundos y luego se apaga automáticamente, pero la hora sigue su curso.--:sd En este modo la pantalla siempre permanecerá encendida.Modo pantalla siempre visible Modo pantalla ahorro energía(autoapagado)PantallaHay dos modos de ver la pantalla, pulse una vez el botón “SET”Dp-1: Hora y temperatura en pantalla durante 5 segundos y cambia a mostrarsee n pantalla el formato calendario, el porcentaje de humedad permanecesiempre visible en pantalla en este modo.Dp-2: En este modo siempre permanecerá fijo en pantalla la hora, temperatura y porcentaje de humedad.Modo hora siempre fija Modo pantalla alternativaHoraEn esta opción podrá ajustar la hora, minutos y el calendario.Dentro del modo normal de hora, mantenga pulsado durante 3 segundos el botón “SET” y la pantalla se pondrá en intermitencia.La secuencia de ajustes es como a continuación se indica:Calendario > mes > día > 12h/24h > hora > minutos > alarma 1 > alarmar 2 > alarma 3 > on:e > salirAjuste 12/24 horasUna vez terminado de ajustar el calendario, accederá al modo de ajuste del formato 12/24h, pulse los botones “UP” ó “DOWN” para seleccionar el formato deseado en pantalla.AlarmaEste reloj digital tiene 3 alarmas y cada alarma tiene una duración de 1 minuto.Configuración alarma 1:Mantenga pulsado el botón “SET” hasta que aparezca los dígitos en intermitencia en la pantalla y luego pulse varias veces seguidas el botón “SET” otra vez hasta ver en pantalla “on:A1” para acceder a la configuración de la ala rma 1, pulse el botón “UP” para activar o desactivar la alarma 1, (on quiere decir alarma activada / -- quiere decir alarma desactivada) después pulse “SET” y la pantalla se pondrá en intermitencia para ajustar la alarma 1 a la hora deseada mediante la pulsación de los botones “UP” y “DOWN”,Configuración alarma 2:Después de configurar la alarma 1, pulse el botón “SET” para acceder a la configuración de la alarma 2, “on:A2”, pulse el botón “UP” para activar o desactivar la alarma 2, (on quiere decir alarma activada / -- quiere decir alarma desactivada) después pulse “SET” y la pantalla se pondrá en intermitencia para ajustar la alarma 2 a la hora deseada mediante la pulsación de los botones “UP” y “DOWN”,Configuración alarma 3:Después de configurar la alarma 2, pulse el botón “SET” para acceder a la configuración de la alarma 3, “on:A3”, pulse el botón “UP” para activar o desactivar la alarma 3, (on quiere decir alarma activada / -- quiere decir alarma desactivada) después pulse “SET” y la pantalla se pondrá en intermitencia para ajustar la alarma 3 a la hora deseada mediante la pulsación de los botones “UP” y “DOWN”,Configuración de alarma semanal:Después de configurar la alarma 3, pulse el botón “SET” para acceder a la configuración de la alarma semanal (Lunes a Viernes) o de fin de semana, en pantalla aparecerá “-:E”, pulse los botones “UP” ó “DOWN” para seleccionar entre “on:E (Alarma de Lunes a Viernes)” ó “--:E”. (alarma de Lunes a Domingo).Apagar alarma diaria Encender alarma diaria1.El despertador está acabado en madera lo cual necesita usarse en un lugar deambiente seco y ventilado. Tenga cuidado de que no se caiga al suelo cuando lo esté utilizando para evitar dañar las esquinas y otras partes del despertador. 2.Cuando utilice este despertador digital, es aconsejable que utilice pilas alcalinatipo AAA. Si nota que los dígitos en pantalla empiezan a disminuir su intensidad o se pone en intermitencia, por favor cambie las pilas viejas por unas nuevas. 3.También puede utilizar el reloj despertador con un adaptador enchufado a lared eléctrica.4.Si se encuentra con cualquier tipo de problema durante la configuración de lahora, puede pulsar el botón “RESET” situado en la parte trasera para reiniciar el reloj despertador.5.El sensor de la temperatura está situado en la parte trasera del relojdespertador, entonces para una mejor medición de la temperatura por favor no colocar detrás del reloj despertador nada frío ni caliente.-Despertador digital.-Cable USB.-Manual de instrucciones.•Debido a continuas mejoras el diseño y características pueden variar sin previo aviso. ECOLOGIA Y RECICLABILIDAD DEL PRODUCTO❖Los materiales que constituyen el envase de este aparato, están integrados en un sistema de recogida, clasificación y reciclado de los mismos. Si desea deshacerse de ellos, puede utilizar los contenedores apropiados para cada tipo de material.❖El producto está exento de concentraciones de sustancias que sepuedan considerar dañinas para el medio ambiente.Este símbolo significa que si desea deshacerse del producto, una vez transcurrida la vida del mismo, debe depositarlo por los medios adecuadosa manos de un gestor de residuos autorizado para la recogida selectiva de Residuos de Aparatos Eléctricos y Electrónicos (RAEE).TARJETA DE GARANTIAMODELO_________________________FECHA DE COMPRA____________________________ Nº DE SERIE_______ _______________FECHA DE CADUCIDAD_________________________ NOMBRE DEL CLIENTE__________________________________________________________Este artículo está garantizado durante dos años.La presente garantía quedara anulada si el producto ha sufrido daño por accidente, sulfatación de la pila, ó utilización indebida.En caso de avería, durante el periodo de garantía, es indispensable la presentación de esta tarjeta debidamente cumplimentada, para que el producto sea reparado en garantía a su distribuidor o a Electrónica de Consumo-1, S.A. C/. Rufino González Nº6 28037 Madrid Telf.: 91 304 76 56El consumidor tiene derecho a la reparación totalmente gratuita de los vicios o defectos originarios.Asimismo, el consumidor tiene derecho, en caso de que la reparación no fuera satisfactoria, a la sustitución del producto por otro igual o de idénticas características.。
亚太地区2020环氧树脂产品手册说明书
目录简介 3液体环氧树脂，D.E.R.™ 300系列和D.E.H.™固化剂 6 双酚A环氧树脂 6双酚F环氧树脂 6低粘度环氧树脂共混物，改性环氧树脂 6改性胺固化剂 7低温固化剂 7酚醛型环氧树脂D.E.N.™ 400系列7 溴化环氧树脂与无卤树脂，D.E.R.™ 500系列和PROLOGIC™系列9 低溴环氧树脂 9高溴环氧树脂 9特种环氧树脂 - 溴化 9特种环氧树脂 - 无溴 10包含环氧树脂和固化剂的磷化合物 10固体环氧树脂和涂料用树脂，D.E.R.™ 600系列和D.E.H.™固化剂 12双酚A固体环氧树脂12双酚A环氧树脂溶液14适用于SER的固体固化剂14水性环氧树脂和水性环氧固化剂 16水性环氧树脂16水性固化剂 16柔性环氧树脂D.E.R.™ 700系列 16 AIRSTONE™和MARK复合系统 18浸剂18粘合剂18层压，手糊成型 18模具 19拉挤成型19纤维缠绕成型 19铸造 19 FORTEGRA™增韧添加剂 20POLY-CARB MARK产品 20附录 – 产品监管 22液体环氧树脂，D.E.R.™ 300系列和D.E.H.™固化剂 22酚醛型环氧树脂D.E.N.™ 400系列 22溴化环氧树脂与无卤树脂，D.E.R.™ 500系列和PROLOGIC™系列23固体环氧树脂和涂料用树脂，D.E.R.™ 600系列和D.E.H.™固化剂 24水性环氧树脂和水性环氧固化剂 24柔性环氧树脂D.E.R.™ 700系列 25AIRSTONE™和MARK复合系统 25FORTEGRA™增韧添加剂 26 POLY-CARB MARK产品 26提升性能和差异化发展环氧树脂技术是风能、工程建设和铜箔基板等全球各类行业创新的基础要素。
Olin是这一领域的佼佼者，我们运用先进的环氧树脂技术来解决材料领域的严峻挑战，为满足社会对能源、交通、电子设备和基础设施的日常需求贡献力量。
作为一家国际化学品制造商，Olin主要生产氯、苛性钠、氢氧化钾、乙烯基、环氧树脂、氯化有机物和漂白剂产品。
Goodman A200356产品说明书
Product SpecificationsA200356Illustrations and photographs are only representative. Some product models may vary.A200326EASIER TO SELL•Up to 98% AFUE in upflow and horizontal positions Up to 96.7% AFUE in downflow•Modulating heating operation (40% - 100% capacity)•ION™ Communicating Control System•Xtra SEER Variable speed ECM blower motor •Supports single and multi-stage cooling units•Dehumidification feature in cooling•All sizes can be installed in California air quality management districts with a 40 ng/J NOx emissions limit.•Cabinet air leakage less than 2.0% at 1.0 in. W.C. and cabinet air leakage less than 1.4% at 0.5 in. W.C. when tested in accordance with ASHRAE standard 193TOUGHER•Flame roll-out sensors standard•Adjustable heating blower OFF delay •Factory set blower ON delay •RPJ® primary heat exchanger•Stainless steel secondary heat exchanger•High temperature limit control designed to prevent overheating •Direct ignition with Silicon Nitride ignitorQUIETER•Operates quieter at lower heating rates•Variable speed induced draft combustion blower•Variable speed, constant airflow, communicating ECM blower motor •Insulated steel cabinetEASIER TO INSTALL AND SERVICE•Direct vent (2-pipe) or ventilated combustion air •24 V AC humidifier terminal •Electronic air cleaner terminal•35” (889mm) high, for ease of installation and room for service •Quarter turn knobs for easy door removal and secure attachment •Factory shipped for natural gas, with propane gas conversion kits available•Four position - upflow/downflow/horizontal (left/right) installation •At least twelve different venting configurations •Through the casing flue pipe for counterflowor horizontal applications with accessory kit (order separately)•Concentric vent available•Simple troubleshooting of gas valve•Self-configuring and communicating control•Slide out heat exchanger assembly and blower assemblyLIMITED WARRANTY *•10 year No Hassle Replacement™ limited warranty•Lifetime heat exchanger limited warranty with timely registration •5 year parts limited warranty- With timely registration, an additional 5 year parts limited warranty * For residential applications only. See warranty certificate for complete details and restrictions, including warranty coverage for other applications.G97CMNModulating, 4-Way MultipoiseVariable Speed, Condensing Gas Furnace!CARBON MONOXIDE POISONING AND FIRE HAZARDFailure to follow this warning could result in personal injury, death,and/or property damage.This furnace is not designed for use in recreation vehicles,manufactured (mobile) homes or outdoors.Failure to follow this warning could result in personal injury, death,and/or property damage.SYST0101CW Recommended (sold separately)Use of the AHRI Certified TM Mark indicates a manufacturer's participation in the program. For verification of certification for individual products,go to .Model Number Input(BTUH)Efficiency AFUEENERGY STAR®Cooling Capacity CFM range@ .5 in. w.c. (125 Pa)Dimensions H x W x D Inches (Millimeters)Shipping Wt. Lbs (Kg)Upflow/Hz Downflow 97CMN0601714A 60,00097.0%95.0%X 510-133535 x 17-1/2 x 29-1/2 (889 x 445 x 750)154 (69)97CMN0602120A 60,60098.0%96.7%X 540-190535 x 21 x 29-1/2 (889 x 533 x 750)159 (72)97CMN0801714A 80,00097.0%95.0%X 490-137535 x 17-1/2 x 29-1/2 (889 x 445 x 750)164 (74)97CMN0802120A 80,00097.0%95.0%X 750-194535 x 21 x 29-1/2 (889 x 533 x 750)169 (77)97CMN1002122A 100,00097.0%95.0%X 715-216035 x 21 x 29-1/2 (889 x 533 x 750)179 (80)97CMN1202422A120,00097.0%95.0%X680-218535 x 24-1/2 x 29-1/2 (889 x 622 x 750)203 (91)MODEL NUMBER NOMENCLATUREA190043For California Residents:For installation in SCAQMD only: This furnace does not meet the SCAQMD Rule 1111 14 ng/J NOx emission limit, and thus is subject to a mitigation fee of up to $450. This furnace is not eligible for the Clean Air Furnace Rebate Program: FURNACE COMPONENTSA190145DIGIT POSITION 12,34567-910,1112,131415||||||||||BRAND A, B, C…1, 2, 3…EFFICIENCY08 = 800 CFM 10 = 1000 CFM 12 = 1200 CFM 14 = 1400 CFM 16 = 1600 CFM 20 = 2000 CFM 22 = 2200 CFMMAJOR SERIESMINOR SERIES026 = 26,000 BTU/h 040 = 40,000 BTU/h 045 = 45,000 BTU/h …….155 = 155,000 BTU/h14 = 14.2”17 = 17.5”21 = 21.0”24 = 24.5”FEATUREHEATING INPUTCABINET WIDTHCOOLING CAPACITYF, G, N, R C = Constant Airflow Variable-Speed ECME =Fixed-Speeds, Constant Torque (FCT) ECM P = PSCV = Variable Speed , Constant Torque (VCT) 80 - 80% AFUE 92 - 92% AFUE 95 - 95% AFUE 96 - 96% AFUE 97 - 97% AFUEM - Modulating S - Single Stage T - Two StageL = Low NOxM = Mobile/Manufactured Home N = Standard NOx U = Ultra Low NOxMOTOR TYPEHEATING STAGESECMINSIDE DOOR FIGURE).BOARDHOT SURFACEMINIMUM CLEARANCES TO COMBUSTIBLE MATERIALS FOR ALL UNITS - IN(MM)DIMENSIONAL DRAWINGA200327POSITIONCLEARANCEREARFRONT (Combustion air openings in furnace and in structure)1 (25)Required for service**.Consult your local building codes.24 (610)All Sides of Supply Plenum *1 (25)Sides 0Vent0Top of Furnace1 (25)FURNACE SIZEABCDSHIP WT.LB (KG) CABINET WIDTH OUTLET WIDTH BOTTOM INLET WIDTHAIR INTAKE 060171417-1/2 (445)15-7/8 (403)16 (406)8-3/4 (222)147.5 (66.9)060212021 (533)19-3/8 (492)19-1/2 (495)10-1/2 (267)165.5 (75.1)080171417-1/2 (445)15-7/8 (403)16 (406)8-3/4 (222)151.5 (68.7)080212021 (533)19-3/8 (492)19-1/2 (495)10-1/2 (267)169.5 (76.9)100212221 (533)19-3/8 (492)19-1/2 (495)10-1/2 (267)176.5 (80.0)120242224-1/2 (622)22-7/8 (581)23 (584)12-1/4 (311)201.0 (91.2)U.S. ECCN: Not Subject to Regulation (N.S.R.)NOTE: ALL DIMENSIONS IN INCH (MM)PHYSICAL DATAHeating Capacity and Efficiency060171406021200801714080212010021221202422Input Maximum Heat(BTUH)60,00060,60080,00080,000100,000120,000 Intermediate Heat(BTUH)39,00039,00052,00052,00065,00078,000 Minimum Heat(BTUH)24,00024,00032,00032,00040,00048,000Output Maximum Heat(BTUH)59,00060,00078,00078,00098,000117,000 Intermediate Heat(BTUH)38,00039,00051,00051,00064,00076,000 Minimum Heat(BTUH)24,00024,00031,00031,00039,00047,000Certified Temperature Rise Range ºF (ºC)Maximum Heat35 - 65(19 - 36)35 - 65(19 - 36)40 - 70(22 - 39)40 - 70(22 - 39)45 - 75(25 - 42)45 - 75(25 - 42) Intermediate Heat50 - 80(28 - 44)40 - 70(22 - 39)50 - 80(28 - 44)50 - 80(28 - 44)50 - 80(28 - 44)50 - 80(28 - 44)Minimum Heat35 - 65(19 - 36)25 - 55(14-31)35 - 65(19 - 36)35 - 65(19 - 36)35 - 65(19 - 36)35 - 65(19 - 36)Airflow Capacity and Blower DataRated External Static Pressure (in. w.c.)Heating0.120.120.150.150.200.20 Cooling0.50.50.50.50.50.5Airflow Delivery@ Rated ESP (CFM)Maximum Heat107510801500134515751820 Intermediate Heat5306907507959551100 Minimum Heat415555620595745900 Cooling133519051375194521602185Cooling Capacity (tons)400 CFM/ton3 4.5 3.5 4.5 5.5 5.5 350 CFM/ton 3.5 5.54 5.566Direct-Drive Motor Type Electronically Commutated Motor (ECM)Direct-Drive Motor HP1/211/2111 Motor Full Load Amps7.712.87.712.812.812.8 RPM Range300 - 1300Speed Selections Variable (Communicating)Blower Wheel Dia x Width in.11 x 811 x 1011 x 811 x 1011 x 1011 x 11 Air Filtration System Field Supplied FilterFilter Used for Certified Watt Data**.See Accessory List for part numbers available.325531-20*Electrical DataInput Voltage Volts-Hertz-Phase115-60-1Operating Voltage Range Min-Max104 -127Maximum Input Amps Amps9.014.19.014.114.114.1 Unit Ampacity Amps12.018.412.018.418.418.4 Minimum Wire Size AWG141214121212Maximum Wire Length @ Minimum Wire Size Feet303130313131 (M)(9.4)(9.5)(9.4)(9.5)(9.5)(9.5)Maximum Fuse/Ckt Bkr(Time-Delay Type Recommended)Amps152015202020 Transformer Capacity (24vac output)40 VAExternal Control Power Available Heating27.9 VA Cooling34.6 VAControlsGas Connection Size1/2" - NPTBurners (Monoport)334456 Gas Valve (Redundant)Manufacturer White RogersMinimum Inlet Gas pressure (in. wc) 4.5Maximum Inlet Gas pressure (in. wc)13.6Manufactured (Mobile) Home Kit not approved for MH useTwinning Kit not approved for twinningIgnition Device Silicon NitrideHeating Blower Control (Heating Off-Delay)Adjustable: 90, 120, 150, 180 secondsCooling Blower Control (Time Delay Relay)90 secondsCommunication System ION™ Communicating Control SYST0101CW Thermostat Connections R, W/W1, W2 Y/Y2, Y1, G, Com 24V, DHUMAccessory Connections EAC (115vac); HUM (24vac); 1-stg AC (via Y/Y2)AIR DELIVERY - CFMCooling4 and Heating Air Delivery - CFM (Bottom Return5 With Filter)(SW1-5 and SW4-3 set to OFF, except as indicated. See notes 1 and 2.)Unit Size:0601714Clg/CF Switch settings External Static Pressure (ESP)Clg Switches SW2-3SW2-2SW2-10.10.20.30.40.50.60.70.80.9 1.0 Clg Default:OFF OFF OFF1060107010801080107510651050103510251010 CF Switches SW3-3SW3-2SW3-1Low-Clg Default:OFF OFF OFF545530*********See note 4Cooling Airflow(SW2) Low-Cooling Airflow (SW3)OFF OFF ON545530*********See note 4OFF ON OFF710710710695690See note 4OFF ON ON875880890895895890885880870855 ON OFF OFF1060107010801080107510651050103510251010 ON OFF ON1235124012501255125512501230119011551115 ON ON OFF1235124012501255125512501230119011551115 ON ON ON1235124012501255125512501230119011551115 Maximum Clg Airflow21425142514051370133513001260122511901155CF Switches SW3-3SW3-2SW3-1Cont. Fan Default:OFF OFF OFF545530*********See note 4Continuous Fan Airflow (SW3)OFF OFF ON545530*********See note 4OFF ON OFF710710710695690See note 4OFF ON ON875880890895895890885880870855 ON OFF OFF1060107010801080107510651050103510251010 ON OFF ON1060107010801080107510651050103510251010 ON ON OFF1060107010801080107510651050103510251010 ON ON ON1060107010801080107510651050103510251010Heating (SW1)Maximum Heat Airflow31075108510951095109010801065105010351020 Intermediate Heat Airflow3535515505515495See note 4Minimum Heat Airflow3420410415400380See note 4Unit Size:0602120Clg/CF Switch settings External Static Pressure (ESP)Clg Switches SW2-3SW2-2SW2-10.10.20.30.40.50.60.70.80.9 1.0 Clg Default:OFF OFF OFF1735173517251715170016851665165016251605 CF Switches SW3-3SW3-2SW3-1Low-Clg Default:OFF OFF OFF540525525520540See note 4Cooling Airflow(SW2) Low-Cooling Airflow (SW3)OFF OFF ON540525525520540See note 4OFF ON OFF680725725720720See note 4OFF ON ON925915910895900890875865860855 ON OFF OFF1070107510801070108010751055104510301020 ON OFF ON1215124512351220122012101200119511851175 ON ON OFF1380138513951390139513901380136513551340 ON ON ON1735173517251715170016851665165016251605 Maximum Clg Airflow21955195019401925190518851855181517451685CF Switches SW3-3SW3-2SW3-1Cont. Fan Default:OFF OFF OFF540525525520540See note 4Continuous Fan Airflow (SW3)OFF OFF ON540525525520540See note 4OFF ON OFF680725725720720See note 4OFF ON ON925915910895900890875865860855 ON OFF OFF925915910895900890875865860855 ON OFF ON925915910895900890875865860855 ON ON OFF925915910895900890875865860855 ON ON ON925915910895900890875865860855Heating (SW1)Maximum Heat Airflow31080108510951090109510851070105510451030 Intermediate Heat Airflow3685725730725730See note 4Minimum Heat Airflow3560555555550565See note 40801714Clg/CF Switch settings External Static Pressure (ESP)Clg Switches SW2-3SW2-2SW2-10.10.20.30.40.50.60.70.80.9 1.0 Clg Default:OFF OFF OFF1055106510801075106510501045103510251005 CF Switches SW3-3SW3-2SW3-1Low-Clg Default:OFF OFF OFF520505505495490See note 4Cooling Airflow(SW2) Low-Cooling Airflow (SW3)OFF OFF ON520505505495490See note 4OFF ON OFF665685680660665See note 4OFF ON ON885895905900900895885875860845 ON OFF OFF1055106510801075106510501045103510251005 ON OFF ON1245124512551255126012551250123512201185 ON ON OFF1245124512551255126012551250123512201185 ON ON ON1245124512551255126012551250123512201185 Maximum Clg Airflow21520148514501415137513351300126512251190CF Switches SW3-3SW3-2SW3-1Cont. Fan Default:OFF OFF OFF520505505495490See note 4Continuous Fan Airflow (SW3)OFF OFF ON520505505495490See note 4OFF ON OFF665685680660665See note 4OFF ON ON885895905900900895885875860845 ON OFF OFF885895905900900895885875860845 ON OFF ON885895905900900895885875860845 ON ON OFF885895905900900895885875860845 ON ON ON885895905900900895885875860845Heating (SW1)Maximum Heat Airflow31520148514501415137513351300126512251190 Intermediate Heat Airflow3755745755755765See note 4Minimum Heat Airflow3620625630620610See note 4Unit Size:0802120Clg/CF Switch settings External Static Pressure (ESP)Clg Switches SW2-3SW2-2SW2-10.10.20.30.40.50.60.70.80.9 1.0 Clg Default:OFF OFF OFF1745175517551760175517501745172517051685 CF Switches SW3-3SW3-2SW3-1Low-Clg Default:OFF OFF OFF700710750725750See note 4Cooling Airflow(SW2) Low-Cooling Airflow (SW3)OFF OFF ON700710750725750See note 4OFF ON OFF830860870890960See note 4OFF ON ON1045104510601070107010701095109010801070 ON OFF OFF1215122012451240123512351225122012351235 ON OFF ON1370137013901390140013951400139013901385 ON ON OFF1745175517551760175517501745172517051685 ON ON ON1745175517551760175517501745172517051685 Maximum Clg Airflow21920192019451945194519601950194019151900CF Switches SW3-3SW3-2SW3-1Cont. Fan Default:OFF OFF OFF700710750725750See note 4Continuous Fan Airflow (SW3)OFF OFF ON700710750725750See note 4OFF ON OFF830860870890960See note 4OFF ON ON1045104510601070107010701095109010801070 ON OFF OFF1215122012451240123512351225122012351235 ON OFF ON1370137013901390140013951400139013901385 ON ON OFF1370137013901390140013951400139013901385 ON ON ON1370137013901390140013951400139013901385Heating (SW1)Maximum Heat Airflow31340135513701385138013851400140013851380 Intermediate Heat Airflow3780810835840845See note 4Minimum Heat Airflow3595595600595605See note 41002122Clg/CF Switch settings External Static Pressure (ESP)Clg Switches SW2-3SW2-2SW2-10.10.20.30.40.50.60.70.80.9 1.0 Clg Default:OFF OFF OFF1820182518401845184018351825180517801770 CF Switches SW3-3SW3-2SW3-1Low-Clg Default:OFF OFF OFF750740745730715See note 4Cooling Airflow(SW2) Low-Cooling Airflow (SW3)OFF OFF ON750740745730715See note 4OFF ON OFF900900915910905See note 4OFF ON ON1070107510951095109010851095108010651070 ON OFF OFF1280128513051305131013051295130012901285 ON OFF ON1440144514651465147014851480148514751460 ON ON OFF1820182518401845184018351825180517801770 ON ON ON2135214021402135214021302115210020702015 Maximum Clg Airflow22160216521752170216021502135212020652020CF Switches SW3-3SW3-2SW3-1Cont. Fan Default:OFF OFF OFF750740745730715See note 4Continuous Fan Airflow (SW3)OFF OFF ON750740745730715See note 4OFF ON OFF900900915910905See note 4OFF ON ON1070107510951095109010851095108010651070 ON OFF OFF1280128513051305131013051295130012901285 ON OFF ON1440144514651465147014851480148514751460 ON ON OFF1440144514651465147014851480148514751460 ON ON ON1440144514651465147014851480148514751460Heating (SW1)Maximum Heat Airflow31570157515951595160016051600160015901575 Intermediate Heat Airflow3950955965975970See note 4Minimum Heat Airflow3755745750735720See note 4Unit Size:1202422Clg/CF Switch settings External Static Pressure (ESP)Clg Switches SW2-3SW2-2SW2-10.10.20.30.40.50.60.70.80.9 1.0 Clg Default:OFF OFF OFF1850185518601855185018301805177517501730 CF Switches SW3-3SW3-2SW3-1Low-Clg Default:OFF OFF OFF930925915900885See note 4Cooling Airflow(SW2) Low-Cooling Airflow (SW3)OFF OFF ON765745740705680See note 4OFF ON OFF930925915900885See note 4OFF ON ON10951100111011051085See note 4ON OFF OFF1265125512651280127512851270126012501230 ON OFF ON1465145514701465146514701455145014351415 ON ON OFF1850185518601855185018301805177517501730 ON ON ON2200220022002190218521702145208519901890 Maximum Clg Airflow22200220022002190218521702145208519901890CF Switches SW3-3SW3-2SW3-1Cont. Fan Default:OFF OFF OFF930925915900885See note 4Continuous Fan Airflow (SW3)OFF OFF ON765745740705680See note 4OFF ON OFF930925915900885See note 4OFF ON ON10951100111011051085See note 4ON OFF OFF1265125512651280127512851270126012501230 ON OFF ON1465145514701465146514701455145014351415 ON ON OFF1465145514701465146514701455145014351415 ON ON ON1465145514701465146514701455145014351415Heating (SW1)Maximum Heat Airflow31815182018251820181517951775174517201700 Intermediate Heat Airflow310951100111011051085See note 4Minimum Heat Airflow3905900890875855See note 4See NOTES following table© 2020 Carrier. All rights reserved.A Carrier Company Edition Date: 08/20Catalog No: 440 56 4521 02Replaces: 440 56 4521 01NOTES:1.Nominal 350 CFM/ton cooling airflow is delivered with SW1-5 and SW4-3 set to OFF. Set SW1-5 to ON for nominal 400 CFM/ton (+15% airflow). Set SW4-3 to ON for nominal 325 CFM/ton (-7% airflow).Set both SW1-5 and SW4-3 to ON for nominal 370 CFM/ton (+7% airflow).This applies to Cooling and Low-Cooling airflow, but does not affect continuous fan airflow.The above adjustments in airflow are subject to motor horsepower range/capacity.2.Maximum cooling airflow is achieved when switches SW2-1, SW2-2, SW2-3 and SW1-5 are set to ON, and SW4-3 is set to OFF.3.All heating CFM’s are when low/medium heat rise adjustment switch (SW1-3) and comfort/efficiency adjustment switch (SW1-4) are both set to OFF.4.Ductwork must be sized for high-heating CFM within the operational range of ESP. Operation within the blank areas of the chart is not recommended because high-heat operation will be above 1.0 ESP.5.All airflow on 21” casing size furnaces are 5% less on side return only installations.6.Return air above 1800 CFM on 24.5” casing sizes requires two sides, one side and bottom or bottom only, to allow sufficient airflow to the furnace.ORIFICESACCESSORIESPART NUMBER COMPONENT NAME DESCRIPTION 060171406021200801714080212010021221202422NAHB00101CT EXTERNAL TRAP KIT CONDENSATE TRAP XXXXX XNAHA00110DA DRAIN ACCESSORY 1/2” CPVC to 3/4” PVC (10PACK)X X X X X X NAHA002CV VENT TERMINATION KIT 2” CONCENTRIC VENT X X X X X NAHA001CV 3” CONCENTRIC VENT X X X X X X NAHA00101VC INTERNAL VENT KITTHROUGH THE CABINETX X X X X X NAHA00301VT DIRECT VENT TERMINATION KIT 2” BRACKET X X X X X NAHA00401VT 3” BRACKET X X X X X X NAHA00101CK INLET AIR PIPE COUPLING COUPLING FOR POLYPROPYLENE VENTSYSTEMSX X X X X X NAHA00101HV HORIZONTAL INSTALLATION KIT TRAP GROMMET (direct Ventapplication only)X X X X X X NAHA00101HH FREEZE PROTECT KIT CONDENSATE DRAIN LINE -TAPEX X X X X X NAHA00201HH CONDENSATE FREEZEPROTECT KIT CONDENSATE TRAP WITHHEAT PADX X X X X X NAHA01101SB FLOOR BASE KIT COMBUSTIBLE FLOOR X X X X X X AGAGC9NPS01B**.Factory authorized and field installed. Gas conversion kits are CSA recognized.GAS CONVERSION KIT NATURAL TO PROPANE X X X X X X AGAGC9PNS01B *PROPANE TO NATURAL X X X X X X 1188594†GAS VALVE TOWER PORT ADAPTER KIT ADAPTER FOR GAS VALVE X X X X X X 325531-402††.Order through FAST Part.X = Accessory availableWASHABLE FILTER (SINGLE PACK)16” x 25” x 3/4” FILTER X -X ---325531-403†20” x 25” x 3/4” FILTER -X -X X -325531-404†24” x 25” x3/4” FILTER-----X FHG1625-2†BOTTOM FILTER RACK (WITHOUT FILTER)16” x 25” RACK X -X ---FHG2025-2†20” x 25” RACK-X -X X -FHG2424-2†24.5” x 24” RACK -----X NAHB00101CA COIL ADAPTER KITWITH NO OFFSET X X X X X X NAHB00201CA WITH SINGLE OFFSET X X X X X X NAHB00301CA WITH DOUBLE OFFSETX X X X X X NAHA01701RA RETURN AIR KIT 17-1/2” wide X -X ---NAHA02101RA 21” wide -X -X X -NAHA02401RA 24-1/2” wide-----X SYST0101CW ION™ CONTROLSYSTEMCOMMUNICATING SYSTEMCONTROLX X X X X X NAHA00101MS MOTOR SIMULATOR ECM MOTOR SIMULATOR KIT X X X X X X NAHA001NKCONDENSATE NEUTRALIZER KITNEUTRALIZES CONDENSATEXXXXXXPart Number Gas Type Orifice SizePart Number Gas Type Orifice SizePart Number Gas Type Orifice Size1185612Natural 421183809Natural 461184256Propane 541176928Natural 431185613Natural 471185615Propane 551185574Natural 441185614Natural481185616Propane 561177213Natural 451185617Propane 1.25 mm 1185618Propane 1.30 mm。
氧化铍 吨度
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高考理科数学模拟竞优卷第一卷
2020届高考理科数学模拟竞优卷第一卷1、已知集合{}2|60A x x x =∈--<Z ，{}|1B x x =>-，则A B ⋂=()A.{}|13x x -<<B.{}012,, C.{}1012-,,, D.{}210--,,2、复数z 满足()1i 34i z -=+，则z =()A.17i22-+ B.17i 22+ C.55i 22- D.55i 22+3、某学校为了解1000名新生的近视情况，将这些学生编号为000，001，002，…，999，从这些新生中用系统抽样的方法抽取100名学生进行检查，若036号学生被抽到，则下面4名学生中被抽到的是（）A.008号学生B.200号学生C.616号学生D.815号学生4、已知(1)n x λ+的展开式中第三项的二项式系数与第四项的二项式系数相等,且2012(1)n n n x a a x a x a x λ+=++++ ,若12242n a a a ++= ,则实数λ=()A.3B.2C.1D.45、已知R x y ∈,，且0x y ＞＞，则（）A ．11x y ->B ．sin sin 0x y ->C ．11022x y⎛⎫⎛⎫-< ⎪ ⎪⎝⎭⎝⎭D ．ln ln 0x y +>6、若向量,a b满足2,3,a b a b ==-= ()a ab ⋅+=（）A ．5B ．6C ．7D ．87的程序框图，则图中和中应分别填入()A.6k T ≤=?; B.7k T ≤?;C.6k T ≤?;D.6k T ≥=?;8、已知圆柱的轴截面是边长为2的正方形，且该圆柱的内切球1O 的表面积为1S ，该圆开始柱的上、下底面的圆周都在球2O 上，球2O 的表面积为2S ，则12:S S =()A. B.1:2D.2:19、在ABC △中，,,a b c 分别是角,,A B C 的对边,若sin cos 0b A B =,且2b ac =，则a c b+的值为()A.2C.22D.410、关于函数()sin sin f x x x =+有下述四个结论：①()f x 是偶函数②()f x 在区间π(,π)2单调递增③()f x 在[]π,π-有4个零点④()f x 的最大值为2其中所有正确结论的编号是（）A.①②④B.②④C.①④D.①③11、已知椭圆()2222:10x y C a b a b +=>>的左、右顶点分别为12A A ，，焦点坐标为(0)c ±,，过1A 的直线与圆222x y c +=切于点N ，与双曲线2222:1x y E c b-=在第一象限交于M 点，且满足12MA MA ⊥若椭圆C 的离心率为1e ，双曲线E 的离心率为2e ，则211e e +的值为()A.165C.655D.12、已知函数()(),0ln ,0x e x f x x x ⎧≥⎪=⎨-<⎪⎩，若函数())(2g x f x ax a =++恰好有3个零点，则实数a的取值范围为()A.321,12e ⎛⎤-- ⎥⎝⎦B.1211,2e ⎡⎫--⎪⎢⎣⎭ C.321,12e ⎡⎤--⎢⎥⎣⎦ D.12,2e ⎛⎤⎥⎝⎦13、已知函数2()xf x e x =-的图象在点(1,(1))f 处的切线过点()0,a ,则a =__________.14、若直线1240l x y ：－＋＝与2430l mx y ：－＋＝平行，则两平行直线12l l ，间的距离为_________.15、已知某几何体的三视图如图所示，则该几何体的表面积为.16、已知P 是抛物线24y x =上一动点，定点A ，过点P 作PQ y ⊥轴于点Q ，则PA PQ +的最小值是_______17、已知n S 为数列{}n a 的前n 项和，满足()21n n n a S n +=+，且35a =.(1)求数列{}n a 的通项公式；(2)若()111322n a n n b a -=++⨯，求数列{}n b 的前n 项和n T .18、如图，在多面体ABCD 中，平面ADEF ⊥平面ABCD .四边形ADEF 为正方形，ABCD 为梯形，且//AD BC ，ABD ∆是边长为1的等边三角形，M 为线段BD 中点，3BC =.(1)求证：AF BD ⊥；(2)求直线MF 与平面CDE 所成角的正弦值；(3)线段BD 上是否存在点N ，使得直线//CE 平面AFN ？若存在，求BNBD的值；若不存在，请说明理由.19、第7届世界军人运动会于2019年10月18日至27日在湖北武汉举行，赛期10天，共设置射击、游泳、田径、篮球等27个大项，329个小项.共有来自100多个国家的近万名现役军人同台竞技.前期为迎接军运会顺利召开，武汉市很多单位和部门都开展了丰富多彩的宣传和教育活动，努力让大家更多的了解军运会的相关知识，并倡议大家做文明公民.武汉市体育局为了解广大民众对军运会知识的知晓情况，在全市开展了网上问卷调查，民众参与度极高，现从大批参与者中随机抽取200名幸运参与者，他们得分（满分100分）数据，统计结果如下：组别[)30,40[)40,50[)50,60[)60,70[)70,80[)80,90[)90,100频数5304050452010（1）若此次问卷调查得分整体服从正态分布，用样本来估计总体，设,μσ分别为这200人得分的平均值和标准差（同一组数据用该区间中点值作为代表），求,μσ的值（,μσ的值四舍五入取整数），并计算()5193P X <<；（2）在（1）的条件下，为感谢大家参与这次活动，市体育局还对参加问卷调查的幸运市民制定如下奖励方案：得分低于μ的可以获得1次抽奖机会，得分不低于μ的可获得2次抽奖机会，在一次抽奖中，抽中价值为15元的纪念品A 的概率为23，抽中价值为30元的纪念品B 的概率为13.现有市民张先生参加了此次问卷调查并成为幸运参与者，记Y 为他参加活动获得纪念品的总价值，求Y 的分布列和数学期望，并估算此次纪念品所需要的总金额.（参考数据：()0.6827P X μδμδ-<≤+≈；(22)0.9545P X μδμδ-<≤+≈；(33)0.9973P X μδμδ-<≤+≈.）20、已知椭圆()2222:10x y C a b a b+=>>的左，右焦点分别为()()122,0,2,0F F -，点151,3P ⎛-- ⎝⎭在椭圆C 上.（1）求椭圆C 的标准方程；（2）是否存在斜率为-1的直线l 与椭圆C 相交于M,N 两点，使得11F M F N =若存在，求出直线的方程；若不存在，说明理由.21、已知函数()21x x f x e-=(e 为自然对数的底数).（1）求函数()f x 的零点0x ，以及曲线()y f x =在0x x =处的切线方程；（2）设方程()()0f x m m =>有两个实数根1x ，2x ，求证：121212x x m e ⎛⎫-<-+⎪⎝⎭.22、在平面直角坐标系xOy 中，曲线C 的参数方程为sin x y αα⎧=⎪⎨=⎪⎩([]0,π,a α∈为参数).以坐标原点O 为极点，x 轴的正半轴为极轴建立极坐标系，直线l 的极坐标方程为πcos 44ρθ⎛⎫ ⎪⎝⎭-=.(1)求C 的普通方程和l 的直角坐标方程.(2)射线()2π03θρ=>和()π03θρ=>分别与曲线C 交于点A B ,，与直线l 交于点D C ,，求四边形ABCD 的面积.23、已知不等式32231x x -->的解集为A .(1)求A .(2)若m n A ∈，，且4m n +=，证明:22811n m m n +≥--.答案以及解析1答案及解析：答案：B解析：依题意，知{}260A x x x =∈--<Z |{}|23x x =∈-<<Z {}1012=-,,,，{}|1B x x =>-｝，故{}012A B ⋂=,,，故选B.2答案及解析：答案：D解析：由已知条件，得34i +=，则()()()515i 515i 1i i 1i 22z =+-++==-，故选D.3答案及解析：答案：C解析：由题意得抽样间隔为100010100=，因为036号学生被抽到，所以被抽中的初始编号为006号，之后被抽到的编号均是10的整数倍与6的和，故选：C.4答案及解析：答案：B解析：由(1)n x λ+得展开式中第三项的二项式系数与第四项的二项式系数相等,得23n nC C =解得5n =,所以5250125(1)x a a x a x a x λ+=++++ ,令0x =得01a =,令1x =,得50125(1)243x a a a a λ+=++++= ,所以13λ+=,解得2λ=5答案及解析：答案：C解析：由0x y >>,则110y x xy xy--=<，故A 错误，根据正弦函数的图象和性质，无法比较sin x 与sin y 的大小，故B 错误，根据指数函数的性质可得11022xy⎛⎫⎛⎫⎪ ⎪⎝⎭⎝⎭-<，故C 正确，根据对数的运算性质，ln ln ln x y xy +=，当01xy < 时，ln 0xy ，故D 错误6答案及解析：答案：C解析：向量,a b满足2,3||,a b a b ==-= ，可得4927a b +-⋅=，可得3a b ⋅=，则24)37(a a b a a b ⋅+=+⋅=+=7答案及解析：答案：C解析：根据题意，运行该程序，则T ，1k =；T ，2k =；T ，3k =；T 4k =；T ，5k =；T =，6k =；T =7k =，结束循环结合选项可知，C 选项满足题意.故选C.8答案及解析：答案：B解析：设球1O 和球2O 的半径分别为r R ，，因为该圆柱的轴截面是边长为2的正方形，所以1r =，R =221212S r S R ⎛⎫=== ⎪⎝⎭，故选B.9答案及解析：答案：A解析：ABC ∆中,由sin cos 0b A B -⋅=,利用正弦定理得sin sin cos 0B A A B -=，∴tan B =,故π3B =.由余弦定理得222222cos b a c ac B a c ac =+-⋅=+-,即22)3(b a c ac =+-，又2b ac =,所以22)4(b a c =+,求得2a cb +=10答案及解析：答案：C解析：()()()sin sin sin sin f x x x x x f x -=-+-=+= ,()f x ∴为偶函数,故①正确．当2x ππ<<时，()2sin f x x =，它在区间,2π⎛⎫π ⎪⎝⎭单调递减，故②错误．当0x π≤≤时，()2sin f x x =，它有两个零点：0,π；当0x π-≤<时，()()sin sin 2sin f x x x x =--=-，它有一个零点：π-，故()f x 在[],-ππ有3个零点：0-π,,π，故③错误．当[]()2,2x k k k *∈ππ+π∈N时，()2sin f x x =；当[]()2,22x k k k *∈π+ππ+π∈N时，()sin sin 0f x x x =-=，又()f x 为偶函数，()f x ∴的最大值为2，故④正确．综上所述①④正确，故选C ．11答案及解析：答案：D解析：易知222a b c =+，所以12A A ，为双曲线2222:1x y E c b-=的左、右焦点，连接ON (O 为坐标原点)，则1ON A M ⊥.因为直线与圆222x y c +=切于点N ，所以ON c =，所以1A N b =，12A M b =，222A M ON c ==.由双曲线的定义，知122A M A M c -=，即222b c c -=，得2b c =，从而椭圆的离心率1c e a ==2ae c ==，故211e e +=.故选D12答案及解析：答案：B解析：函数()()2g x f x ax a =++有3个零点，等价于函数()y f x =的图象与直线2y ax a =--有3个交点.易知直线2y ax a =--恒过点1,02⎛⎫- ⎪⎝⎭，过点1,02⎛⎫- ⎪⎝⎭作函数(0)x y e x =≥的图象的切线，设切点为00()x y ，，则00x y e =.因为x y e '=，所以切线的斜率1012x y k e x ==+，即0012x e x x =+，解得012x =，所以121k e =.又过点(0)1,，1,02⎛⎫- ⎪⎝⎭的直线与曲线()y f x =恰有3个交点，且该直线的斜率22k =，所以函数()y f x =的图象与直线2y ax a =--有3个交点时，1222e a <-≤，解得12112a e -≤<-.综上，实数a 的取值范围为1211,2e ⎡⎫--⎪⎢⎣⎭故选B.13答案及解析：答案：1解析：∵()2x f x e x =-，∴()()11,2x f e f x e x '=-=-，∴()12f e '=-，∴函数()2x f x e x =-的图象在点()()1,1f 处的切线的方程为()()()121y e e x --=--，即()21y e x =-+，∵直线()21y e x =-+过点()0,a ，∴()2011a e =-⨯+=14答案及解析：答案：52解析：若直线1:240l x y -+=与2:430l mx y -+=平行，则有43124m -=≠-，求得2m =，两直线即1:2480l x y -+=与2:2430l x y -+=，则两平行直线12,l l 间的距离为52=15答案及解析：解析：由三视图还原该几何体的直观图如图所示，易知AA BB CC '''，，均垂直于底面ABC ，且1AA '=，2BB '=，3CC '=，1AC BC ==，AC BC ⊥，所以AB B C ''==，A B ''，A C ''=B C A B ''''⊥，所以该几何体的表面积()()()12231131112222S ++⨯+⨯⨯=++++=.16答案及解析：答案：2解析：由抛物线24y x =可知，其焦点坐标为(1,0)F ，准线1x =-，设点P 到其准线的距离为d ，根据抛物线的定义可的d PF =则点P 到y 轴的距离为1PQ PF =-，且3FA ==则112PA PQ PA PF FA +=+-≥-=（当且仅当,,A P F 三点共线时取等号），所以PA PQ +的最小值为2.17答案及解析：答案：(1)由()21n n n a S n +=+，得()1n n na S n n =+-①，所以()()1111n n n a S n n +++=++②，由②-①，得()1112n n n n a na a n +++-=+，所以12n n a a +-=，故数列{}n a 是公差为2的等差数列.因为35a =，所以112225a d a +=+⨯=，解得11a =，所以()12121n a n n =+-=-.(2)由(1)得，134n n b n -=+⨯，所以()011123444n n T n -=++⋯++⨯+++L ()1143214n n n +-=+⨯-()1412n n n +=+-.解析：18答案及解析：答案：（1）证明：因为ADEF 为正方形，所以AF AD ⊥．又因为平面ADEF ⊥平面ABCD ，且平面ADEF ⋂平面ABCD AD =，所以AF ⊥平面ABCD ．所以AF BD ⊥．（2）取AD 中点O,EF 中点K ，连接OB ，OK.于是在ABD ∆中，OB OD ⊥，在正方ADEF 中OK OD ⊥，又平面ADEF ⊥平面ABCD ，故OB ⊥平面AFEF ，进而OB OK ⊥，即OB, OD, OK 两两垂直．分别以,,OB OD OK 为x 轴，y 轴,z 轴建立空间直角坐标系（如图）．于是，3,0,02B ⎛⎫ ⎪⎪⎝⎭，10,,02D ⎛⎫ ⎪⎝⎭,32C ⎛⎫ ⎪ ⎪⎝⎭,1E 0,,12⎛⎫ ⎪⎝⎭,311M ,0,F 0,442⎛⎫⎛⎫- ⎪ ⎪ ⎪⎝⎭⎝⎭所以3335,,1,,0,(0,0,1)4422MF CD DE ⎛⎫⎛⎫=-== ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭设平面CDE 的一个法向量为(,,)n x y z = ，则00CD n DE n ⎧⋅=⎪⎨⋅=⎪⎩即350220x y z ⎧--⋅=⎪⎨⎪=⎩令5x =-，则y =，则(n =-．设直线MF 与平面CDE 所成角为θ，||3sin |cos ,|14||||MF n MF n MF n θ⋅=<>==(3)要使直线//CE 平面AFN ，只需AN //CD ，设,[0,1]BN BD λλ=∈,则1,,,0222n n n x y z λ⎛⎫⎛⎫-=- ⎪ ⎪ ⎪ ⎪⎝⎭⎝⎭,1,,02n n nx y zλ===,1,,02Nλ⎫⎪⎪⎝⎭，所以11,,022ANλ⎫=-+⎪⎪⎝⎭,又5(,0)2CD=-，由//AN CD112252λ+=-，解得2=[0,1]3λ∈所以线段BD上存在点N,使得直线//CE平面AFN，且2=3BNBD解析：19答案及解析：答案：（1）由已知频数表得：5304050452010()3545556575859565200200200200200200200E X=⨯+⨯+⨯+⨯+⨯+⨯+⨯=，22222()(3565)0.025(4565)0.15(5565)0.2(6565)0.25(7565)0.225 D X=-⨯+-⨯+-⨯+-⨯+-⨯22(8565)0.1(9565)0.05210+-⨯+-⨯=，由2196225σ<<，则1415σ<<，而214.5210.5210=>，所以14σ≈，则X服从正态分布(65,14)N，所以(22)() (5193)(2)2P X P XP X P Xμσμσμσμσμσμσ-<<++-<<+ <<=-<<+=0.95450.68270.81862+==；（2）显然，()()0.5P X P Xμμ<=≥=，所以所有Y的取值为15，30，45，60，121(15)233P Y==⨯=，111227(30)2323318P Y==⨯+⨯⨯=，1211122(45)2332339P Y==⨯⨯+⨯⨯=，1111(60)23318P Y==⨯⨯=，所以Y的分布列为：Y 15304560P 1371829118所以1721()1530456030318918E Y =⨯+⨯+⨯+⨯=，需要的总金额为：200306000⨯=.解析：20答案及解析：答案：（1）因为椭圆C 的左右焦点分别为()12,0F -，()22,0F ，所以2c =.由椭圆定义可得22a =,解得a =所以222642b a c =-=-=,所以椭圆C 的标准方程为22162x y +=（2）假设存在满足条件的直线l ，设直线l 的方程为y x t =-+，由22162x y y x t ⎧+=⎪⎨⎪=-+⎩得223()60x x t +-+-=，即()2246360x tx t -+-=，()222(6)443696120t t t ∆=--⨯⨯-=->，解得t -<<,设()11,M x y ，()22,N x y ，则1232t x x +=,212364t x x -=,由于11F M F N =，设线段MN 的中点为E ，则1F E MN ⊥，所以111F EMN K K =-=又3,44t t E ⎛⎫⎪⎝⎭，所以141324F Et Kt==+，解得4t =-.当4t =-时，不满足t -<<.所以不存在满足条件的直线l .解析：21答案及解析：答案：（1）由()210x x f x e -==，得1x =±，∴函数的零点01x =±.()221xx x f x e --'=，()12f e '-=，()10f -=.曲线()y f x =在1x =-处的切线方程为()21y e x =+.()21f e'=-，()10f =，∴曲线()y f x =在1x =处的切线方程为()21y x e=--.（2）()221xx x f x e --'=.当(() 11x ∈-∞-++∞ ，时，()0f x '>；当(1 1x ∈-+时，()0f x '<.∴()f x 的单调递增区间为(() 1 1-∞++∞，，，单调递减区间为(1.由（1）知，当1x <-或1x >时，()0f x <；当11x -<<时，()0f x >.下面证明：当()1 1x ∈-，时，()()21e x f x +>.当()1 1x ∈-，时，()()()21112121002x x x x e x f x e x e e +--+>⇔++>⇔+>.易知，()112x x g x e +-=+在[]1 1x ∈-，上单调递增，而()10g -=，∴()()10g x g >-=对()1 1x ∀∈-，恒成立，∴当()1 1x ∈-，时，()()21e x f x +>.由()21y e x y m⎧=+⎪⎨=⎪⎩得12m x e =-.记112m x e '=-.不妨设12x x <，则12111x x -<<-<<，∴121221212m x x x x x x x e ⎛⎫''-<-=-=--⎪⎝⎭.要证121212x x m e ⎛⎫-<-+⎪⎝⎭，只要证2112122m x m e e ⎛⎫⎛⎫--≤-+ ⎪ ⎪⎝⎭⎝⎭，即证21x m ≤-.又∵2221x x m e -=，∴只要证222211x x x e-≤-，即()()()222110x x e x -⋅-+≤.∵()21 1x ∈，即证()2210x e x -+≥.令()()()11x x x e x x e ϕϕ'=-+=-，.当()1 0x ∈时，()0x ϕ'<，()x ϕ为单调递减函数；当()0,1x ∈时，()0x ϕ'>，()x ϕ为单调递增函数.∴()()00x ϕϕ≥=，∴()2210x e x -+≥，∴121212x x m e ⎛⎫-<-+⎪⎝⎭.解析：22答案及解析：答案：(1)由sin x y αα⎧⎪⎨=⎪⎩，消去参数α，得2212x y +=.因为[]0,πα∈，所以0y ≥.即曲线C 的普通方程为221()02x y y +=≥由πcos 44ρθ⎛⎫ ⎪⎝⎭-=，得22422θρθ⎫+⎪⎪⎭=⎝，将cos sin x y ρθρθ=⎧⎨=⎩代上式，简得x y +=，所以直线l 的直角坐标方程为0x y +-.(2)由(1)知，曲线C 的方程为221()02x y y +=≥，将cos sin x y ρθρθ=⎧⎨=⎩代入上式，得2222cos sin 12ρθρθ+=()2ππ2π,k k k θ≤≤+∈Z .将π3θ=代入上式，解得2147ρ=，所以2147OB =，将2π3θ=代人上式，解得2147ρ=，所以2147OA =.将π3θ=代入πcos 44ρθ⎛⎫ ⎪⎝⎭-=，解得4ρ=，即4OC =.将2π3θ=代入πcos 44ρθ⎛⎫ ⎪⎝⎭-=，解得4ρ=，即4OD =+.所以四边形ABCD 的面积1π1πsin sin 2323S OD OC OA OB =⋅-⋅⋅114422=⨯⨯⨯⨯.解析：23答案及解析：答案：(1)当32x >时，原不等式可化为3)32(21x x -->，得352x <<；当302x ≤≤时，原不等式可化为()32231x x +->，得312x <≤；当0x <时，原不等式可化为()32231x x -+->，无解.综上，)5(1A =,.(2)m n A ∈Q ,，1m ∴>，1n >，10m ∴->，1n ->0.欲证22811n m m n +≥--，只需证()()3232811n n m m m n -+-≥--，即证()()()()2222888m n m mn n m n mn m n +-+-+≥-++，即证()22312240m n mn +-+≥，即证()23212240m n mn mn ⎡⎤+--+≥⎣⎦，即证4mn ≤.242m n mn ⎛⎫⎪⎝⎭+≤=Q ，当且仅当2m n ==时取等号，∴原不等式成立.解析：。
2020年四川省高考数学试卷(理科)(新课标Ⅲ)
2020年四川省高考数学试卷（理科）（新课标Ⅲ）一、选择题：本题共12小题，每小题5分，共60分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1. 已知集合A ={(x, y)|x, y ∈N ∗, y ≥x}，B ={(x, y)|x +y =8}，则A ∩B 中元素的个数为( ) A.3 B.2 C.4 D.62. 复数11−3i 的虚部是（ ） A.−110B.−310C.110D.3103. 在一组样本数据中，1，2，3，4出现的频率分别为p 1，p 2，p 3，p 4，且∑ 4i=1p i ＝1，则下面四种情形中，对应样本的标准差最大的一组是（ ） A.p 1＝p 4＝0.4，p 2＝p 3＝0.1 B.p 1＝p 4＝0.1，p 2＝p 3＝0.4 C.p 1＝p 4＝0.2，p 2＝p 3＝0.3 D.p 1＝p 4＝0.3，p 2＝p 3＝0.24. Logistic 模型是常用数学模型之一，可应用于流行病学领域．有学者根据公布数据建立了某地区新冠肺炎累计确诊病例数I(t)（t 的单位：天）的Logistic 模型：I(t)=K 1+e −0.23(t−53)，其中K 为最大确诊病例数．当I(t ∗)＝0.95K 时，标志着已初步遏制疫情，则t ∗约为( )(ln 19≈3) A.63 B.60C.69D.665. 设O 为坐标原点，直线x ＝2与抛物线C:y 2＝2px(p >0)交于D ，E 两点，若OD ⊥OE ，则C 的焦点坐标为（ ） A.(12, 0)B.(14, 0)C.(2, 0)D.(1, 0)6. 已知向量a →，b →满足|a →|＝5，|b →|＝6，a →⋅b →=−6，则cos <a →，a →+b →>=( ) A.−1935 B.−3135C.1735D.19357. 在△ABC 中，cos C =23，AC ＝4，BC ＝3，则cos B ＝（ ）A.13B.19C.12D.238. 如图为某几何体的三视图，则该几何体的表面积是（ ）A.4+4√2B.6+4√2C.4+2√3D.6+2√39. 已知2tan θ−tan (θ+π4)＝7，则tan θ＝（ ） A.−1 B.−2 C.1 D.210. 若直线l 与曲线y =√x 和圆x 2+y 2=15都相切，则l 的方程为（ ） A.y ＝2x +12B.y ＝2x +1C.y =12x +1D.y =12x +1211. 设双曲线C:x 2a 2−y 2b 2=1(a >0, b >0)的左、右焦点分别为F 1，F 2，离心率为√5．P 是C 上一点，且F 1P ⊥F 2P ．若△PF 1F 2的面积为4，则a ＝（ ）A.2B.1C.4D.812. 已知55<84，134<85．设a ＝log 53，b ＝log 85，c ＝log 138，则（ ） A.b <a <cB.a <b <cC.b <c <aD.c <a <b二、填空题：本题共4小题，每小题5分，共20分。
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2020年我国高端装备制造业增速将超30%
2015年12月15日，由工业和信息化部主办的2015全国装备制造业智能制造现场经验交流会在西安召开。
工业和信息化部副部长辛国斌出席会议并讲话，他提出，做好发展规划、实施方案、行动计划的制定工作；集中力量建设国家智能制造标准体系，做好重点领域标准的制定工作，软件和系统方案的提供以及知识产权的保护，提升智能制造支撑能力；重点突破自主安全可控的关键技术装备的研发与工程应用，抓好智能装备研发生产和生产过程的智能化，积极推动智能制造试点示范，以及传统制造业智能化改造工作。
随着我国制造2025战略的提出，我国装备制造特别是高端装备制造业迎来了发展的春天。
信息技术与先进制造技术高速发展，我国智能制造装备的发展深度和广度日益提升，以新型传感器、智能控制系统、工业机器人、自动化成套生产线为代表的智能制造装备产业体系初步形成，一批具有知识产权的重大智能制造装备实现突破，2010年工业自动化控制系统和仪器仪表、数控机床、工业机器人及其系统等部分智能制造装备产业领域销售收入超过3000亿元。
高端装备制造业增速将超30%
我国高端装备制造业2012年的销售收入约为2.58万亿元。
按照《高端装备制造产业十二五规划》，到2015年，我国高端装备制造业销售收入超过6万亿元，在装备制造业中的占比提高到15%；根据前瞻产业研究院发布的《2014-2020年高端装备制造产业发展前瞻与投资战略规划分析报告》，2011-2015年我国高端装备制造产业的销售收入复合增长率达到32.3%。
到2020年，高端装备制造产业销售收入在装备制造业中的占比提高到25%，工业增加值率较十二五末提高2个百分点，将高端装备制造业培育成。