ansys热分析例题
Ansys热分析教程 第九章
例题 - 飞轮铸造分析
在时间 = 956 秒时，显示几乎所有材料已经凝固。象推测的一样， 中心材料凝固最慢:
例题 - 飞轮铸造分析
对于 相变 区域:
Use the average specific heat : C avg
C s C l
2 specific heat, C ,
*
and the latent heat, L, to find an equivalent
for the liquid - to - solid transitio n : C
P ro p erty M eltin g Po in t D en sity C s, S o lid S p ecific H eat C l,L iq u id S p ecific H eat L , L aten t H eat (or fr om L x D en sity) V alu e 696 C 3 2707 kg /m 896 J/kg - C 1050 J/kg - C 3956 440 J/kg 3 1.0704 e9 J/m
沙模外侧面和顶面有对流。 在底面和中心线无边界条件(绝热)。
例题 - 飞轮铸造分析
• • • • • 瞬态载荷步在删除初始温度后开始。 打开时间积分。使用反向欧拉时间积分。 打开线性搜索工具。 终止时间为 2400 秒(40分)。 初始时间步为0.01秒。最小和最大时间步分别设为0.0001和100秒。
H
相变时热焓变化相对温度 变化而言十分迅速。
注: 本图中, Tl -Ts 很小。对于纯材料， Tl -Ts 应该为0。
潜热
Ts
“模糊区”
Tl
T
控制方程
系统产生相变时，其控制方程如下:
workbench热分析案例
•6
划分网 格
网格剖分： 采用ansys的mesh块对导入 的几何体进行网格划分，网 格为四面体网格，网格最大 边长为5mm。
•1
定 义 边 界条件
墙壁外表面： 采用convection边界条件， 设定外界空气温度10℃， 换热系数为0.36W/㎡·k。
•2
定义边界条件
墙壁内表面：
裸露于空气的表面采用 convection边界条件，拟 定外界空气温度20℃， 换热系数为0.36W/㎡·k， 与热源接触表面采用耦合 边界条件。
•3
定 义边界条件
热源： 与墙体平行的壁面采用 temperature边界条件，定 义其温度为50℃，其余壁 面均为绝热边界条件。
•4
结 果及分析
温度场云图：
通过显示计算得出的温度 场可以看出该模型的最小 温度值出现在墙体外表面 顶部与底部，在该模型中 温度场关于yz平面对称。
•
结 果及分析
稳态ansys热分析数值模拟
稳态热分析数值模拟实例1——短圆柱体的热传导过程1、问题描述有一短圆柱体，直径和高度均为1m，其结构如图7.1所示，现在其上端面施加大小为100℃的均匀温度载荷，圆柱体下端面及侧面的温度均为0℃，试求圆柱体内部的温度场分布（假设圆柱体不与外界发生热交换，圆柱体材料的热传导系数为30 W/（m•℃））。
图7.1 圆柱体结构示意图2、三维建模应用Pro-E软件对固体计算域进行三维建模，实体如图7.2所示：图7.2 圆柱体三维实体图3、网格划分采用流动传热软件CFX的前处理模块ICEM对计算域进行网格划分，得到如图7.3所示的六面体网格单元。
流场的网格单元数为640，节点数为891。
图7.3 圆柱体网格图4、模拟计算及结果采用流动传热软件CFX稳态计算，定义圆柱体材料的热传导系数为30 W/(m•℃)，求解时选取Thermal Energy传热模型。
固体上壁面的边界条件设置为100℃的温度，侧面和下壁面边界条件为0℃的温度。
求解方法采用高精度求解，计算收敛残差为10-4。
图7.4为计算得到的圆柱体中心剖面的温度等值线分布图。
数据文件及结果文件在steady文件夹内。
图7.4 圆柱体中心剖面的温度等值线分布瞬态热分析数值模拟实例详解实例1——型材瞬态传热过程分析1、问题描述有一横截面为矩形的型材，如图7.5所示。
其初始温度为500℃，现突然将其置于温度为20℃的空气中，求1分钟后该型材的温度场分布及其中心温度随时间的变化规律（材料性能参数如表7.1所示）。
表7.1 材料性能参数密度ρkg/m3 导热系数W/(m•℃)比热J/(kg•℃)对流系数W/(m2•℃)2400 30 352 110图7.5 型材横截面示意图2、三维建模应用Pro-E软件对固体计算域进行三维建模，实体如图7.6所示：图7.6 型材三维实体图3、网格划分采用流动传热软件CFX的前处理模块ICEM对计算域进行网格划分，得到如图7.7所示的六面体网格单元。
ANSYS热应力分析经典例题
ANSYS热应力分析例题实例1——圆简内部热应力分折：有一无限长圆筒，其核截面结构如图13—1所示，简内壁温度为200℃，外壁温度为20℃，圆筒材料参数如表13．1所示，求圆筒内的温度场、应力场分布。
该问题属于轴对称问题。
由于圆筒无限长，忽略圆筒端部的热损失。
沿圆筒纵截面取宽度为10M的如图1 3—2所示的矩形截面作为几何模型。
在求解过程中采用间接求解法和直接求解法两种方法进行求解。
间接法是先选择热分析单元，对圆筒进行热分析，然后将热分析单元转化为相应的结构单元，对圆筒进行结构分析；直接法是采用热应力藕合单元，对圆筒进行热力藕合分析。
/filname,exercise1-jianjie/title,thermal stresses in a long/prep7 $Et,1,plane55Keyopt,1,3,1 $Mp,kxx,1,70Rectng,0.1,0.15,0,0.01 $Lsel,s,,,1,3,2Lesize, all,,,20 $Lsel,s,,,2,4,2Lesize,all,,,5 $Amesh,1 $Finish/solu $Antype,staticLsel,s,,,4 $Nsll,s,1 $d,all,temp,200lsel,s,,,2 $nsll,s,1 $d,all,temp,20allsel $outpr,basic,allsolve $finish/post1 $Set,last/plopts,info,onPlnsol,temp $Finish/prep7 $Etchg,ttsKeyopt,1,3,1 $Keyopt,1,6,1Mp,ex,1,220e9 $Mp,alpx,,1,3e-6 $Mp,prxy,1,0.28Lsel,s,,,4 $Nsll,s,1 $Cp,8,ux,allLsel,s,,,2 $Nsll,s,1 $Cp,9,ux,allAllsel $Finish/solu $Antype,staticD,all,uy,0 $Ldread,temp,,,,,,rthAllsel $Solve $Finish/post1/title,radial stress contoursPlnsol,s,x/title,axial stress contoursPlnsol,s,y/title,circular stress contoursPlnsol,s,z/title,equvialent stress contoursPlnsol,s,eqv $finish/filname,exercise1-zhijie/title,thermal stresses in a long/prep7 $Et,1,plane13Keyopt,1,1,4 $Keyopt,1,3,1Mp,ex,1,220e9 $Mp,alpx,,1,3e-6 $Mp,prxy,1,0.28MP,KXX,1,70Rectng,0.1,0.15,0,0.01 $Lsel,s,,,1,3,2Lesize, all,,,20 $Lsel,s,,,2,4,2Lesize,all,,,5 $Amesh,1Lsel,s,,,4 $Nsll,s,1 $Cp,8,ux,allLsel,s,,,2 $Nsll,s,1 $Cp,9,ux,allALLSEL $Finish/solu $Antype,staticLsel,s,,,4 $Nsll,s,1 $d,all,temp,200lsel,s,,,2 $nsll,s,1 $d,all,temp,20allsel $outpr,basic,allsolve $finish/post1 $Set,last/plopts,info,onPlnsol,temp/title,radial stress contoursPlnsol,s,x/title,axial stress contoursPlnsol,s,y/title,circular stress contoursPlnsol,s,z/title,equvialent stress contoursPlnsol,s,eqv $finish318页实例2——冷却栅管的热应力分析图中为一冷却栅管的轴对称结构示意图，其中管内为热流体，温度为200℃，压力为10Mp,对流系数为11 0W／(m2•℃)；管外为空气，温度为25℃，对流系数为30w／(mz．℃)。
Ansys模拟水结冰的热分析过程
Ansys模拟水结冰的热分析过程一、问题描述：对一茶杯水的结冰过程进行分析，水和茶杯的初始温度为0℃，环境温度为-10℃，杯子侧面和顶面的对流换热系数为12.5W/m^2·℃，杯子放在桌面上，假设桌面可以对杯子底面提供-10℃的温度载荷。
计算3000s之后的温度分布。
模型如下：茶杯底面外径54.41mm，内径50mm，高度85mm，顶面内径60mm，抽壳厚度为5mm（内部水的高度80mm）。
分析采用SI单位制，水的材料属性如下：导热率：0.6密度：1000比热容：4200/prep7！进入前处理模块et,1,70！定义70单元mp,kxx,1,0.6！设置材料属性mp,c,1,4200mp,dens,1,1000mptemp,1,-10,-1,0,10mpdata,enth,1,1,0,37.8e6,79.8e6,121.8e6！焓值定义mp,kxx,2,70mp,dens,2,7833mp,c,2,448这里定义1号材料为水，2号材料为茶杯3、定义参数r1=50e-3r2=60e-3r3=54.41e-3r4=65e-3h1=80e-3h2=85e-34、建模wprot,,-90！旋转工作平面/pnum,volu,1！打开体积显示/view,1,1,1,1！Iso视角cone,r1,r2,0,h2,0,90！建立水的1/4圆台模型cone,r3,r4,0,h2,0,90！建立茶杯轮廓模型wpoff,,,h2-h1！移动工作平面vsbw,all！用工作平面切割体，方便扫掠划分网格vovlap,all！对体进行叠分操作vglue,all！对体进行粘接操作numcmp,all！压缩所有编号wpcsys,-1,0！工作平面回归原点/replot！重新显示5、对体赋予材料属性vsel,,,,1,3！体积1到3vatt,2,,1！赋予2号材料属性vsel,,,,4！体积4vatt,1,,1！赋予1号材料属性Allsel！选择所有/pnum,mat,1！打开材料编号显示Vplot！模型显示模型显示如上，紫色部分为茶杯，材料属性2 6、分网esize,2.5e-3！单元尺寸2.5e-3vsweep,all！扫掠划分网格划分如上，可见网格密度还是可以接受的。
ANSYS热应力分析实例
6
设置材料属性
1.给定材料的导热系数40W/(m·℃) 。
Main Menu> Preprocessor> Material Props> Material Models
7
建立实体模型（国际单位制）
1. 创建矩形A1：x1,y1(0,0)、x2,y2(0.01,0.07) MainMenu>Preprocessor>Modeling>Create>Areas>Rectangle>By Dimensions 2. 创建矩形A2：x1,y1(0,0.05)、x2,y2(0.08,0.07) 3.显示面的编号 Utility Menu>PlotCtrls>Numbering 4. 对面A1和A2进行overlap操作 Main Menu>Preprocessor>Modeling>Operate>Booleans> Overlap>Areas
12
13
求解
Main Menu>Solution>Solve>Current LS
14
查看温度场分布
Main Menu>General Postproc>Plot Results>Contour Plot>Nodal Solu
15
16
保存
稳态温度场计算完毕，下面修改分析文件名称，进行热应力计算。
注：S标志表示对称约束。
28
求解
Main Menu>Solution>Solve>Current LS
29
查看计算结果
Main Menu>General Postproc>Plot Results>Contour Plot>Nodal Solu
ansys热分析实例教程
Temperature distribution in a CylinderWe wish to compute the temperature distribution in a long steel cylinder with inner radius 5 inches and outer radius 10 inches. The interior of the cylinder is kept at 75 deg F, and heatis lost on the exterior by convection to a fluid whose temperature is 40 deg F. The convection coefficient is 0.56 BTU/hr-sq.in-F and the thermal conductivity for steel is 0.69 BTU/hr-in-F.1. Start ANSYS and assign a job name to the project. Run Interactive -> set working directory and jobname.2. Preferences -> Thermal will show -> OK3. Recognize symmetry of the problem, and a quadrant of a section through the cylinder is created using ANSYS area creation tools. Preprocessor -> Modeling -> Create -> Areas -> Circle -> Partial annulusThe following geometry is created.4. Preprocessor -> Element Type -> Add/Edit/Delete -> Add -> Thermal Solid -> Solid 8 node 77 -> OK -> Close5. Preprocessor -> Material Props -> Isotropic -> Material Number 1 -> OKEX = 3.E7 (psi)DENS = 7.36E-4 (lb sec^2/in^4)ALPHAX = 6.5E-6PRXY = 0.3KXX = 0.69 (BTU/hr-in-F)6. Mesh the area and refine using methods discussed in previous examples.7. Preprocessor -> Loads -> Apply -> Temperatures -> NodesSelect the nodes on the interior and set the temperature to 75.8. Preprocessor -> Loads -> Apply -> Convection -> LinesSelect the lines defining the outer surface and set the convection coefficient to 0.56 and the fluid temp to 40.9. Preprocessor -> Loads -> Apply -> Heat Flux -> LinesTo account for symmetry, select the vertical and horizontal lines of symmetry and set the heat flux to zero.10. Solution -> Solve current LS11. General Postprocessor -> Plot Results -> Nodal Solution -> TemperaturesThe temperature on the interior is 75 F and on the outside wall it is found to be 45. These results can be checked using results from heat transfer theory.BackThermal Stress of a Cylinder using Axisymmetric ElementsA steel cylinder with inner radius 5 inches and outer radius 10 inches is 40 inches long and has spherical end caps. The interior of the cylinder is kept at 75 deg F, and heat is lost on the exterior by convection to a fluid whose temperature is 40 deg F. The convection coefficient is 0.56 BTU/hr-sq.in-F. Calculate the stresses in the cylinder caused by the temperature distribution.The problem is solved in two steps. First, the geometry is created, the preference set to'thermal', and the heat transfer problem is modeled and solved. The results of the heat transfer analysis are saved in a file 'jobname.RTH' (Results THermal analysis) when you issue a save jobname.db command.Next the heat transfer boundary conditions and loads are removed from the mesh, the preference is changed to 'structural', the element type is changed from 'thermal' to 'structural', and the temperatures saved in 'jobname.RTH' are recalled and applied as loads.1. Start ANSYS and assign a job name to the project. Run Interactive -> set working directory and jobname.2. Preferences -> Thermal will show -> OK3. A quadrant of a section through the cylinder is created using ANSYS area creation tools.4. Preprocessor -> Element Type -> Add/Edit/Delete -> Add -> Solid 8 node 77 -> OK ->Options -> K3 Axisymmetric -> OK5. Preprocessor -> Material Props -> Isotropic -> Material Number 1 -> OKEX = 3.E7 (psi)DENS = 7.36E-4 (lb sec^2/in^4)ALPHAX = 6.5E-6PRXY = 0.3KXX = 0.69 (BTU/hr-in-F)6. Mesh the area using methods discussed in previous examples.7. Preprocessor -> Loads -> Apply -> Temperatures -> NodesSelect the nodes on the interior and set the temperature to 75.8. Preprocessor -> Loads -> Apply -> Convection -> LinesSelect the lines defining the outer surface and set the coefficient to 0.56 and the fluid temp to 40.9. Preprocessor -> Loads -> Apply -> Heat Flux -> LinesSelect the vertical and horizontal lines of symmetry and set the heat flux to zero.10. Solution -> Solve current LS11. General Postprocessor -> Plot Results -> Nodal Solution -> TemperatureThe temperature on the interior is 75 F and on the outside wall it is found to be 43.12. File -> Save Jobname.db13. Preprocessor -> Loads -> Delete -> Delete All -> Delete All Opts.14. Preferences -> Structural will show, Thermal will NOT show.15. Preprocessor -> Element Type -> Switch Element Type -> OK (This changes the element to structural)16. Preprocessor -> Loads -> Apply -> Displacements -> Nodes(Fix nodes on vertical and horizontal lines of symmetry from crossing the lines of symmetry.)17. Preprocessor -> Loads -> Apply -> Temperature -> From Thermal AnalysisSelect Jobname.RTH (If it isn't present, look for the default 'file.RTH' in the root directory)18. Solution -> Solve Current LS19. General Postprocessor -> Plot Results -> Element Solution - von Mises StressThe von Mises stress is seen to be a maximum in the end cap on the interior of the cylinder and would govern a yield-based design decision.Back。
ANSYS流体与热分析第10章热分析典型工程实例
第10 章热分析典型工程实例本章要点拉伸特征旋转特征扫掠特征混合特征孔特征壳特征本章案例某型号手机电池的散热分析冷库复合隔热板热量流动分析电子元器件散热装置温度分析10.1 工程实例1——某型号手机电池的散热分析该算例为某型手机电池的散热分析，如图10-1为某型号手机背面的照片，图中可见手机的电池的位置。
在手机工作时，电池可向外传递热量。
使用手机的读者应该都体会过手机电池发热的现象，特别是在长时间接打电话时，这种现象尤为明显。
本实例对某型号手机进行分析，电池的标准电压为3.7V，电池容量为750mAh。
试求手机开机状态下外壳的温度分布。
手机的各部分材料性能参数如表10.1所示。
图10-1 手机背面照片在计算分析过程中我们将手机看做三个组成部分：塑料外壳、手机内部材料和手机电池。
忽略手机内部线路和芯片，可以将手机电池看做唯一热源。
简化后的手机模型如图10-2所示，图中单位均为cm。
本实例拟采用Solid Tet 10node 87单元进行分析。
由于电池功率和环境温度均可视为恒定不变，因此分析类型为稳态。
图10-2 简化后的手机模型由电池的电压和电流可以算得电池的功率：==⨯=P UI 3.70.75 2.775W电池的体积为：3=⨯⨯=V0.040.010.050.00002m电池的发热量：3==Q P/V138750W/m——附带光盘“Ch10\实例10－1_start”——附带光盘“Ch10\实例10－1_end”——附带光盘“A VI\Ch10\10－1.avi”1、定义分析文件名1、选择Utility Menu>File>Change Jobname，在弹出的单元增添对话框中输入Example10-1，然后点击OK按钮。
2、选择Main Menu>Preferences，弹出Preferences for GUI Filtering对话框，点选Thermal复选框，单击OK按钮关闭该对话框。
ansys热分析实例教程
Temperature distribution in a CylinderWe wish to compute the temperature distribution in a long steel cylinder with inner radius 5 inches and outer radius 10 inches. The interior of the cylinder is kept at 75 deg F, and heatis lost on the exterior by convection to a fluid whose temperature is 40 deg F. The convection coefficient is 0.56 BTU/hr-sq.in-F and the thermal conductivity for steel is 0.69 BTU/hr-in-F.1. Start ANSYS and assign a job name to the project. Run Interactive -> set working directory and jobname.2. Preferences -> Thermal will show -> OK3. Recognize symmetry of the problem, and a quadrant of a section through the cylinder is created using ANSYS area creation tools. Preprocessor -> Modeling -> Create -> Areas -> Circle -> Partial annulusThe following geometry is created.4. Preprocessor -> Element Type -> Add/Edit/Delete -> Add -> Thermal Solid -> Solid 8 node 77 -> OK -> Close5. Preprocessor -> Material Props -> Isotropic -> Material Number 1 -> OKEX = 3.E7 (psi)DENS = 7.36E-4 (lb sec^2/in^4)ALPHAX = 6.5E-6PRXY = 0.3KXX = 0.69 (BTU/hr-in-F)6. Mesh the area and refine using methods discussed in previous examples.7. Preprocessor -> Loads -> Apply -> Temperatures -> NodesSelect the nodes on the interior and set the temperature to 75.8. Preprocessor -> Loads -> Apply -> Convection -> LinesSelect the lines defining the outer surface and set the convection coefficient to 0.56 and the fluid temp to 40.9. Preprocessor -> Loads -> Apply -> Heat Flux -> LinesTo account for symmetry, select the vertical and horizontal lines of symmetry and set the heat flux to zero.10. Solution -> Solve current LS11. General Postprocessor -> Plot Results -> Nodal Solution -> TemperaturesThe temperature on the interior is 75 F and on the outside wall it is found to be 45. These results can be checked using results from heat transfer theory.BackThermal Stress of a Cylinder using Axisymmetric ElementsA steel cylinder with inner radius 5 inches and outer radius 10 inches is 40 inches long and has spherical end caps. The interior of the cylinder is kept at 75 deg F, and heat is lost on the exterior by convection to a fluid whose temperature is 40 deg F. The convection coefficient is 0.56 BTU/hr-sq.in-F. Calculate the stresses in the cylinder caused by the temperature distribution.The problem is solved in two steps. First, the geometry is created, the preference set to'thermal', and the heat transfer problem is modeled and solved. The results of the heat transfer analysis are saved in a file 'jobname.RTH' (Results THermal analysis) when you issue a save jobname.db command.Next the heat transfer boundary conditions and loads are removed from the mesh, the preference is changed to 'structural', the element type is changed from 'thermal' to 'structural', and the temperatures saved in 'jobname.RTH' are recalled and applied as loads.1. Start ANSYS and assign a job name to the project. Run Interactive -> set working directory and jobname.2. Preferences -> Thermal will show -> OK3. A quadrant of a section through the cylinder is created using ANSYS area creation tools.4. Preprocessor -> Element Type -> Add/Edit/Delete -> Add -> Solid 8 node 77 -> OK ->Options -> K3 Axisymmetric -> OK5. Preprocessor -> Material Props -> Isotropic -> Material Number 1 -> OKEX = 3.E7 (psi)DENS = 7.36E-4 (lb sec^2/in^4)ALPHAX = 6.5E-6PRXY = 0.3KXX = 0.69 (BTU/hr-in-F)6. Mesh the area using methods discussed in previous examples.7. Preprocessor -> Loads -> Apply -> Temperatures -> NodesSelect the nodes on the interior and set the temperature to 75.8. Preprocessor -> Loads -> Apply -> Convection -> LinesSelect the lines defining the outer surface and set the coefficient to 0.56 and the fluid temp to 40.9. Preprocessor -> Loads -> Apply -> Heat Flux -> LinesSelect the vertical and horizontal lines of symmetry and set the heat flux to zero.10. Solution -> Solve current LS11. General Postprocessor -> Plot Results -> Nodal Solution -> TemperatureThe temperature on the interior is 75 F and on the outside wall it is found to be 43.12. File -> Save Jobname.db13. Preprocessor -> Loads -> Delete -> Delete All -> Delete All Opts.14. Preferences -> Structural will show, Thermal will NOT show.15. Preprocessor -> Element Type -> Switch Element Type -> OK (This changes the element to structural)16. Preprocessor -> Loads -> Apply -> Displacements -> Nodes(Fix nodes on vertical and horizontal lines of symmetry from crossing the lines of symmetry.)17. Preprocessor -> Loads -> Apply -> Temperature -> From Thermal AnalysisSelect Jobname.RTH (If it isn't present, look for the default 'file.RTH' in the root directory)18. Solution -> Solve Current LS19. General Postprocessor -> Plot Results -> Element Solution - von Mises StressThe von Mises stress is seen to be a maximum in the end cap on the interior of the cylinder and would govern a yield-based design decision.Back。
ANSYS_热分析报告(两个实例)有限元热分析报告上机指导书
第四讲 热分析上机指导书CAD/CAM 实验室，USTC实验要求：1、通过对冷却栅管的热分析练习，熟悉用ANSYS 进展稳态热分析的根本过程，熟悉用直接耦合法、间接耦合法进展热应力分析的根本过程。
2、通过对铜块和铁块的水冷分析，熟悉用ANSYS 进展瞬态热分析的根本过程。
容1：冷却栅管问题问题描述：本实例确定一个冷却栅管〔图a 〕的温度场分布与位移和应力分布。
一个轴对称的冷却栅结构管为热流体，管外流体为空气。
冷却栅材料为不锈钢，特性如下：W/m ℃×109 MPa×10-5/℃边界条件：〔1〕管：压力：6.89 MPa流体温度：250 ℃对流系数249.23 W/m 2℃〔2〕管外：空气温度39℃对流系数：62.3 W/m 2℃假定冷却栅管无限长，根据冷却栅结构的对称性特点可以构造出的有限元模型如图b 。
其上下边界承受边界约束，管部承受均布压力。
练习1－1：冷却栅管的稳态热分析步骤：1. 定义工作文件名与工作标题1) 定义工作文件名：GUI: Utility Menu> File> Change Jobname ，在弹出的【ChangeJobname 】对话框中输入文件名Pipe_Thermal ，单击OK 按钮。
2) 定义工作标题：GUI: Utility Menu> File> Change Title ，在弹出的【Change Title 】对话框中2D Axisymmetrical Pipe Thermal Analysis ，单击OK 按钮。
3) 关闭坐标符号的显示：GUI: Utility Menu> PlotCtrls> Window Control> WindowOptions ，在弹出的【Window Options 】对话框的Location of triad 下拉列表框中选择No Shown 选项，单击OK 按钮。
ANSYS流体与热分析第10章热分析典型工程实例
第10 章热分析典型工程实例本章要点拉伸特征旋转特征扫掠特征混合特征孔特征壳特征本章案例某型号手机电池的散热分析冷库复合隔热板热量流动分析电子元器件散热装置温度分析10.1 工程实例1——某型号手机电池的散热分析该算例为某型手机电池的散热分析，如图10-1为某型号手机背面的照片，图中可见手机的电池的位置。
在手机工作时，电池可向外传递热量。
使用手机的读者应该都体会过手机电池发热的现象，特别是在长时间接打电话时，这种现象尤为明显。
本实例对某型号手机进行分析，电池的标准电压为3.7V，电池容量为750mAh。
试求手机开机状态下外壳的温度分布。
手机的各部分材料性能参数如表10.1所示。
图10-1 手机背面照片在计算分析过程中我们将手机看做三个组成部分：塑料外壳、手机内部材料和手机电池。
忽略手机内部线路和芯片，可以将手机电池看做唯一热源。
简化后的手机模型如图10-2所示，图中单位均为cm。
本实例拟采用Solid Tet 10node 87单元进行分析。
由于电池功率和环境温度均可视为恒定不变，因此分析类型为稳态。
图10-2 简化后的手机模型由电池的电压和电流可以算得电池的功率：==⨯=P UI 3.70.75 2.775W电池的体积为：3=⨯⨯=V0.040.010.050.00002m电池的发热量：3==Q P/V138750W/m——附带光盘“Ch10\实例10－1_start”——附带光盘“Ch10\实例10－1_end”——附带光盘“A VI\Ch10\10－1.avi”1、定义分析文件名1、选择Utility Menu>File>Change Jobname，在弹出的单元增添对话框中输入Example10-1，然后点击OK按钮。
2、选择Main Menu>Preferences，弹出Preferences for GUI Filtering对话框，点选Thermal复选框，单击OK按钮关闭该对话框。
稳态热分析案例(ANSYS 15.0版)
本例题的主要部分为一个圆筒形罐，其上沿径向有一材料一样的接管（如图？？？？所所示），罐内流动着450°F（232°C）的高温流体，接管内流动着100°F（38 °C）的低温流体，两个流体区域由薄壁管隔离。
罐的对流换热系数为250Btu/hr-ft2-o F（1420watts/m2-°K），接管的对流换热系数随管壁温度而变，它的热物理性能如表？？？所示。
要求计算罐与接管的温度分布。
表？？？？6.5.1 预处理Step 1: 确定分析标题起动ANSYS后，开始一个分析，需要输入一个标题，按下面方法进行操作：1.选择Utility Menu> File> Change Title，弹出相应对话框2.输入 Steady-state thermal analysis of pipe junction。
3.点击OK。
Step 2: 设置分析单位系统You need to specify units of measurement for the analysis. For this pipe junction example, measurements use the U. S. Customary system of units (based on inches).To specify this, type the command /UNITS,BIN in the ANSYS Input window and press ENTER.在分析之前，需要为分析系统设定单位系统，Step 3: Define the Element TypeThe example analysis uses a thermal solid element. To define it, do the following:1.Choose Main Menu> Preprocessor> Element Type> Add/Edit/Delete. TheElement Types dialog box appears.2.Click on Add. The Library of Element Types dialog box appears.3.In the list on the left, scroll down and pick (highlight) "Thermal Solid." In thelist on the right, pick "Brick20node 90."4.Click on OK.5.Click on Close to close the Element Types dialog box.Step 4: Define Material PropertiesTo define material properties for the analysis, perform these steps:1.Choose Main Menu> Preprocessor> Material Props> Material Models.The Define Material Model Behavior dialog box appears.2.In the Material Models Available window, double-click on the followingoptions: Thermal, Density. A dialog box appears.3.Enter .285 for DENS (Density), and click on OK. Material Model Number 1appears in the Material Models Defined window on the left.4.In the Material Models Available window, double-click on the followingoptions: Conductivity, Isotropic. A dialog box appears.5.Click on the Add Temperature button four times. Four columns are added.6.In the T1 through T5 fields, enter the following temperature values: 70, 200,300, 400, and 500. Select the row of temperatures by dragging the cursoracross the text fields. Then copy the temperatures by pressing Ctrl-c.7.In the KXX (Thermal Conductivity) fields, enter the following values, in order,for each of the temperatures, then click on OK. Note that to keep the unitsconsistent, each of the given values of KXX must be divided by 12. You canjust input the fractions and have ANSYS perform the calculations.8.35/128.90/129.35/129.80/1210.23/128.In the Material Models Available window, double-click on Specific Heat. Adialog box appears.9.Click on the Add Temperature button four times. Four columns are added.10.With the cursor positioned in the T1 field, paste the five temperatures bypressing Ctrl-v.11.In the C (Specific Heat) fields, enter the following values, in order, for each ofthe temperatures, then click on OK..113.117.119.122.12512.Choose menu path Material> New Model, then enter 2 for the new MaterialID. Click on OK. Material Model Number 2 appears in the Material ModelsDefined window on the left.13.In the Material Models Available window, double-click on Convection orFilm Coef. A dialog box appears.14.Click on the Add Temperature button four times. Four columns are added.15.With the cursor positioned in the T1 field, paste the five temperatures bypressing Ctrl-v.16.In the HF (Film Coefficient) fields, enter the following values, in order, foreach of the temperatures. To keep the units consistent, each value of HF must be divided by 144. As in step 7, you can input the data as fractions and letANSYS perform the calculations.426/144405/144352/144275/144221/14417.Click on the Graph button to view a graph of Film Coefficients vs.temperature, then click on OK.18.Choose menu path Material> Exit to remove the Define Material ModelBehavior dialog box.19.Click on SAVE_DB on the ANSYS Toolbar.Step 5: Define Parameters for Modeling1.Choose Utility Menu> Parameters> Scalar Parameters. The ScalarParameters window appears.2.In the window's Selection field, enter the values shown below. (Do not enterthe text in parentheses.) Press ENTER after typing in each value. If you makea mistake, simply retype the line containing the error.RI1=1.3 (Inside radius of the cylindrical tank)RO1=1.5 (Outside radius of the tank)Z1=2 (Length of the tank)RI2=.4 (Inside radius of the pipe)RO2=.5 (Outside radius of the pipe)Z2=2 (Length of the pipe)3.Click on Close to close the window.Step 6: Create the Tank and Pipe Geometry1.Choose Main Menu> Preprocessor> Modeling> Create> Volumes>Cylinder> By Dimensions. The Create Cylinder by Dimensions dialog boxappears.2.Set the "Outer radius" field to RO1, the "Optional inner radius" field to RI1,the "Z coordinates" fields to 0 and Z1 respectively, and the "Ending angle"field to 90.3.Click on OK.4.Choose Utility Menu>WorkPlane> Offset WP by Increments. The OffsetWP dialog box appears.5.Set the "XY, YZ, ZX Angles" field to 0,-90.6.Click on OK.7.Choose Main Menu> Preprocessor> Modeling> Create> Volumes>Cylinder> By Dimensions. The Create Cylinder by Dimensions dialog boxappears.8.Set the "Outer radius" field to RO2, the "Optional inner radius" field to RI2,the "Z coordinates" fields to 0 and Z2 respectively. Set the "Starting angle"field to -90 and the "Ending Angle" to 0.9.Click on OK.10.Choose Utility Menu>WorkPlane> Align WP with> Global Cartesian. Step 7: Overlap the Cylinders1.Choose Main Menu> Preprocessor> Modeling> Operate> Booleans>Overlap> Volumes. The Overlap Volumes picking menu appears.2.Click on Pick All.Step 8: Review the Resulting ModelBefore you continue with the analysis, quickly review your model. To do so, follow these steps:1.Choose Utility Menu>PlotCtrls> Numbering. The Plot Numbering Controlsdialog box appears.2.Click the Volume numbers radio button to On, then click on OK.3.Choose Utility Menu>PlotCtrls> View Settings> Viewing Direction. Adialog box appears.4.Set the "Coords of view point" fields to (-3,-1,1), then click on OK.5.Review the resulting model.6.Click on SAVE_DB on the ANSYS Toolbar.Step 9: Trim Off Excess VolumesIn this step, delete the overlapping edges of the tank and the lower portion of the pipe.1.Choose Main Menu> Preprocessor> Modeling> Delete> Volume andBelow. The Delete Volume and Below picking menu appears.2.In the picking menu, type 3,4 and press the ENTER key. Then click on OK inthe Delete Volume and Below picking menu.Step 10: Create Component AREMOTEIn this step, you select the areas at the remote Y and Z edges of the tank and save them as a component called AREMOTE. To do so, perform these tasks:1.Choose Utility Menu> Select> Entities. The Select Entities dialog boxappears.2.In the top drop down menu, select Areas. In the second drop down menu,select By Location. Click on the Z Coordinates radio button.3.Set the "Min,Max" field to Z1.4.Click on Apply.5.Click on the Y Coordinates and Also Sele radio buttons.6.Set the "Min,Max" field to 0.7.Click on OK.8.Choose Utility Menu> Select> Comp/Assembly> Create Component. TheCreate Component dialog box appears.9.Set the "Component name" field to AREMOTE. In the "Component is madeof" menu, select Areas.10.Click on OK.Step 11: Overlay Lines on Top of AreasDo the following:1.Choose Utility Menu>PlotCtrls> Numbering. The Plot Numbering Controlsdialog box appears.2.Click the Area and Line number radio boxes to On and click on OK.3.Choose Utility Menu> Plot> Areas.4.Choose Utility Menu>PlotCtrls> Erase Options.5.Set "Erase between Plots" radio button to Off.6.Choose Utility Menu> Plot> Lines.7.Choose Utility Menu>PlotCtrls> Erase Options.8.Set "Erase between Plots" radio button to On.Step 12: Concatenate Areas and LinesIn this step, you concatenate areas and lines at the remote edges of the tank for mapped meshing. To do so, follow these steps:1.Choose Main Menu> Preprocessor> Meshing> Mesh> Volumes> Mapped>Concatenate> Areas. The Concatenate Areas picking menu appears.2.Click on Pick All.3.Choose Main Menu> Preprocessor> Meshing> Mesh> Volumes> Mapped>Concatenate> Lines. A picking menu appears.4.Pick (click on) lines 12 and 7 (or enter in the picker).5.Click on Apply.6.Pick lines 10 and 5 (or enter in picker).7.Click on OK.Step 13: Set Meshing Density Along Lines1.Choose Main Menu> Preprocessor> Meshing> SizeCntrls>ManualSize>Lines> Picked Lines. The Element Size on PickedLines picking menu appears.2.Pick lines 6 and 20 (or enter in the picker) .3.Click on OK. The Element Sizes on Picked Lines dialog box appears.4.Set the "No. of element divisions" field to 4.5.Click on OK.6.Choose Main Menu> Preprocessor> Meshing> Size Cntrls>ManualSize>Lines> Picked Lines. A picking menu appears.7.Pick line 40 (or enter in the picker).8.Click on OK. The Element Sizes on Picked Lines dialog box appears.9.Set the "No. of element divisions" field to 6.10.Click on OK.Step 14: Mesh the ModelIn this sequence of steps, you set the global element size, set mapped meshing, then mesh the volumes.1.Choose Utility Menu> Select> Everything.2.Choose Main Menu> Preprocessor> Meshing> Size Cntrls>ManualSize>Global> Size. The Global Element Sizes dialog box appears.3.Set the "Element edge length" field to 0.4 and click on OK.4.Choose Main Menu> Preprocessor> Meshing>Mesher Opts. The MesherOptions dialog box appears.5.Set the Mesher Type radio button to Mapped and click on OK. The SetElement Shape dialog box appears.6.In the 2-D shape key drop down menu, select Quad and click on OK.7.Click on the SAVE_DB button on the Toolbar.8.Choose Main Menu> Preprocessor> Meshing> Mesh> Volumes> Mapped>4 to 6 sided. The Mesh Volumes picking menu appears. Click on Pick All. Inthe Graphics window, ANSYS builds the meshed model. If a shape testingwarning message appears, review it and click Close.Step 15: Turn Off Numbering and Display Elements1.Choose Utility Menu>PlotCtrls> Numbering. The Plot Numbering Controlsdialog box appears.2.Set the Line, Area, and Volume numbering radio buttons to Off.3.Click on OK.Step 16: Define the Solution Type and OptionsIn this step, you tell ANSYS that you want a steady-state solution that uses a program-chosen Newton-Raphson option.1.Choose Main Menu> Solution> Analysis Type> New Analysis. The NewAnalysis dialog box appears.2.Click on OK to choose the default analysis type (Steady-state).3.Choose Main Menu> Solution> Analysis Type> Analysis Options. TheStatic or Steady-State dialog box appears.4.Click on OK to accept the default (“Program-chosen”) for "Newton-Raphsonoption."Step 17: Set Uniform Starting TemperatureIn a thermal analysis, set a starting temperature.1.Choose Main Menu> Solution> Define Loads> Apply> Thermal>Temperature> Uniform Temp. A dialog box appears.2.Enter 450 for "Uniform temperature." Click on OK.Step 18: Apply Convection LoadsThis step applies convection loads to the nodes on the inner surface of the tank.1.Choose Utility Menu>WorkPlane> Change Active CS to> GlobalCylindrical.2.Choose Utility Menu> Select> Entities. The Select Entities dialog boxappears.3.Select Nodes and By Location, and click on the X Coordinates and From Fullradio buttons.4.Set the "Min,Max" field to RI1 and click on OK.5.Choose Main Menu> Solution> Define Loads> Apply> Thermal>Convection> On Nodes. The Apply CONV on Nodes picking menu appears.6.Click on Pick All. The Apply CONV on Nodes dialog box appears.7.Set the "Film coefficient" field to 250/144.8.Set the "Bulk temperature" field to 450.9.Click on OK.Step 19: Apply Temperature Constraints to AREMOTE Component1.Choose Utility Menu> Select> Comp/Assembly> Select Comp/Assembly.A dialog box appears.2.Click on OK to select component AREMOTE.3.Choose Utility Menu> Select> Entities. The Select Entities dialog boxappears.4.Select Nodes and Attached To, and click on the Areas,All radio button. Clickon OK.5.Choose Main Menu> Solution> Define Loads> Apply> Thermal>Temperature> On Nodes. The Apply TEMP on Nodes picking menuappears.6.Click on Pick All. A dialog box appears.7.Set the "Load TEMP value" field to 450.8.Click on OK.9.Click on SAVE_DB on the ANSYS Toolbar.Step 20: Apply Temperature-Dependent ConvectionIn this step, apply a temperature-dependent convection load on the inner surface of the pipe.1.Choose Utility Menu>WorkPlane> Offset WP by Increments. A dialog boxappears.2.Set the "XY,YZ,ZX Angles" field to 0,-90, then click on OK.3.Choose Utility Menu>WorkPlane> Local Coordinate Systems> CreateLocal CS> At WP Origin. The Create Local CS at WP Origin dialog boxappears.4.On the "Type of coordinate system" menu, select "Cylindrical 1" and click onOK.5.Choose Utility Menu> Select> Entities. The Select Entities dialog boxappears.6.Select Nodes, and By Location, and click on the X Coordinates radio button.7.Set the "Min,Max" field to RI2.8.Click on OK.9.Choose Main Menu> Solution> Define Loads> Apply> Thermal>Convection> On Nodes. The Apply CONV on Nodes picking menu appears.10.Click on Pick All. A dialog box appears.11.Set the "Film coefficient" field to -2.12.Set the "Bulk temperature" field to 100.13.Click on OK.14.Choose Utility Menu> Select> Everything.15.Choose Utility Menu>PlotCtrls> Symbols. The Symbols dialog box appears.16.On the "Show pres and convect as" menu, select Arrows, then click on OK.17.Choose Utility Menu> Plot> Nodes. The display in the Graphics Windowchanges to show you a plot of nodes.Step 21: Reset the Working Plane and Coordinates1.To reset the working plane and default Cartesian coordinate system,choose Utility Menu>WorkPlane> Change Active CS to> GlobalCartesian.2.Choose Utility Menu>WorkPlane> Align WP With> Global Cartesian. Step 22: Set Load Step OptionsFor this example analysis, you need to specify 50 substeps with automatic time stepping.1.Choose Main Menu> Solution> Load Step Options> Time/Frequenc>Time and Substps. The Time and Substep Options dialog box appears.2.Set the "Number of substeps" field to 50.3.Set "Automatic time stepping" radio button to On.4.Click on OK.Step 23: Solve the Model1.Choose Main Menu> Solution> Solve> Current LS. The ANSYS programdisplays a summary of the solution options in a /STAT command window.2.Review the summary.3.Choose Close to close the /STAT command window.4.Click on OK in the Solve Current Load Step dialog box.5.Click Yes in the Verify message window.6.The solution runs. When the Solution is done! window appears, click onClose.Step 24: Review the Nodal Temperature Results1.Choose Utility Menu>PlotCtrls> Style> Edge Options. The Edge Optionsdialog box appears.2.Set the "Element outlines" field to "Edge only" for contour plots and click onOK.3.Choose Main Menu> General Postproc> Plot Results> Contour Plot>Nodal Solu. The Contour Nodal Solution Data dialog box appears.4.For "Item to be contoured," pick "DOF solution" from the list on the left, thenpick "Temperature TEMP" from the list on the right.5.Click on OK. The Graphics window displays a contour plot of the temperatureresults.Step 25: Plot Thermal Flux VectorsIn this step, you plot the thermal flux vectors at the intersection of the pipe and tank.1.Choose Utility Menu>WorkPlane> Change Active CS to> Specified CoordSys. A dialog box appears.2.Set the "Coordinate system number" field to 11.3.Click on OK.4.Choose Utility Menu> Select> Entities. The Select Entities dialog boxappears.5.Select Nodes and By Location, and click the X Coordinates radio button.6.Set the "Min,Max" field to RO2.7.Click on Apply.8.Select Elements and Attached To, and click the Nodes radio button.9.Click on Apply.10.Select Nodes and Attached To, then click on OK.11.Choose Main Menu> General Postproc> Plot Results> Vector Plot>Predefined. A dialog box appears.12.For "Vector item to be plotted," choose "Flux & gradient" from the list on theleft and choose "Thermal flux TF" from the list on the right.13.Click on OK. The Graphics Window displays a plot of thermal flux vectors. Step 26: Exit from ANSYSTo leave the ANSYS program, click on the QUIT button in the Toolbar. Choose an exit option and click on OK.。
ansys workbench稳态热分析
Workbench -Mechanical Introduction Introduction作业6.1稳态热分析作业6.1 –目标Workshop Supplement •本作业中，将分析下图所示泵壳的热传导特性。
•确切说是分析相同边界条件下的塑料（Polyethylene）泵壳和铝（Aluminum）泵壳。
）泵壳•目标是对比两种泵壳的热分析结果。
作业6.1 –假设Workshop Supplement 假设：•泵上的泵壳承受的温度为60度。
假设泵的装配面也处于60度下。
•泵的内表面承受90度的流体。
•泵的外表面环境用一个对流关系简化了的停滞空气模拟，温度为20度。
作业6.1 –Project SchematicWorkshop Supplement •打开Project 页•从Units菜单上确定：–项目单位设为Metric (kg, mm, s, C, mA, mV)–选择Display Values in Project Units…作业6.1 –Project SchematicWorkshop Supplement 1.在Toolbox中双击Steady-State Thermal创建一个新的Steady State Thermal（稳态Steady State Thermal热分析）系统。
1.2.在Geometry上点击鼠标右键选择p y，导入文Import Geometry件Pump_housing.x_t 2.…作业6.1 –Project SchematicWorkshop Supplement3.双击Engineering Data得到materialproperties（材料特性） 3.4.选中General Materials的同时，点击Aluminum Alloy和Polyethylene旁边的‘+’符号，把它们添加到项目中。
5.Return to Project（返回到项目）4.5.Workshop Supplement…作业6.1 –Project Schematic6.把Steady StateThermal 拖放到第一个系统的Geometry 上。
Ansys作业——瞬态热分析
Ansys作业——瞬态热分析Ansys作业—瞬态热分析问题描述瞬态热分析实例1⏹长方形的板，几何参数及其边界条件如图3-6 所示。
板的宽度为5cm，其中间有一个半径为1cm 的圆孔。
板的初始温度为20℃，将其右侧突然置于温度为20℃且对流换热系数为100W/M2℃的流体中，左端置于温度为500℃的温度场，试计算：⏹（1）第1s 和第50s板内的温度分布情况。
⏹（2）整个板在前50s内的温度变化过程。
⏹（3）圆孔边缘A点处温度随时间变化曲线。
1.建立有限元模型首先建立瞬态传热分析所需的有限元模型，选择单元。
(1) 选择热分析单元，操作如下：GUI：Main Menu > Preprocessor > Element Type > Add/Edit/Delete在弹出的对话框中，单击Add。
在单元类型库对话框中选择Plane55单元。
单击OK。
命令：ET,1,PLANE55(2) 定义材料属性首先进入Define Material Model Behavior 对话框，操作如下：GUI：Main Menu > Preprocessor > Material Props下面定义瞬态热分析所需的材料参数，如热传导率、比热容及材料密度：定义热传导GUI：Main Menu > Preprocessor > Material Props > Thermal > Conductivity > Isotropic 在弹出的定义材料热传导率对话框中的KXX 栏键入“5”。
命令：MPDATA,KXX,1,,5定义比热容GUI：Main Menu > Preprocessor > Material Props > Thermal > Specific Heat在弹出的定义比热容对话框中的C栏键入“200”。
命令：MPDATA,C,1,,200定义密度GUI：Main Menu > Preprocessor > Material Props > Thermal > Density在弹出密度定义对话框中的DENS栏键入“5000”。
ansys热分析例题
(瞬态)a n s y s热分析例题2(总5页)--本页仅作为文档封面，使用时请直接删除即可----内页可以根据需求调整合适字体及大小--问题描述：一个30公斤重、温度为70℃的铜块,以及一个20公斤重、温度为80℃的铁块，突然放入温度为20℃、盛满了300升水的、完全绝热的水箱中,如图所示。
过了一个小时，求铜块与铁块的最高温度(假设忽略水的流动)。
材料热物理性能如下：热性能单位制铜铁水导热系数W/m℃ 383 37密度Kg/m 8889 7833 996比热J/kg℃ 390 448 4185菜单操作过程：一、设置分析标题1、选择“Utility Menu>File>Change Jobname”，输入文件名Transient1。
2、选择“Utility Menu>File>Change Title”输入Thermal Transient Exercise 1。
二、定义单元类型1、选择“Main Menu>Preprocessor”，进入前处理。
2、选择“Main Menu>Preprocesor>Element Type>Add/Edit/Delete”。
选择热平面单元plane77。
三、定义材料属性1、选择“Main Menu>Preprocessor>Material Props>Material Models”，在弹出的材料定义窗口中顺序双击Thermal选项。
2、点击Conductivity，Isotropic，在KXX框中输入383；点击Density，在DENS框中输入8898；点击Specific Heat，在C框中输入390。
3、在材料定义窗口中选择Material>New Model，定义第二种材料。
4、点击Conductivity，Isotropic，在KXX框中输入70；点击Density，在DENS框中输入7833；点击Specific Heat，在C框中输入448。
四个ANSYS热分析经典例子
实例1：某一潜水艇可以简化为一圆筒，它由三层组成，最外面一层为不锈钢，中间为玻纤隔热层，最里面为铝层，筒内为空气，筒外为海水，求内外壁面温度及温度分布。
几何参数：筒外径30 feet总壁厚2 inch不锈钢层壁厚0.75inch玻纤层壁厚1 inch铝层壁厚0.25inch筒长200 feet导热系数不锈钢8.27BTU/hr.ft.o F玻纤0.028 BTU/hr.ft.o F铝117.4 BTU/hr.ft.o F边界条件空气温度70 o F海水温度44.5 o F空气对流系数2.5 BTU/hr.ft2.o F海水对流系数80 BTU/hr.ft2.o F沿垂直于圆筒轴线作横截面，得到一圆环，取其中1 度进行分析，如图示。
/filename，Steady1/title，Steady-state thermal analysis of submarine/units，BFTRo=15 !外径(ft)Rss=15-(0.75/12) !不锈钢层内径ft)Rins=15-(1.75/12) !玻璃纤维层内径(ft)Ral=15-(2/12) !铝层内径(ft)Tair=70 !潜水艇内空气温度Tsea=44.5 !海水温度Kss=8.27 !不锈钢的导热系数(BTU/hr.ft.oF)Kins=0.028 !玻璃纤维的导热系数(BTU/hr.ft.oF)Kal=117.4 !铝的导热系数(BTU/hr.ft.oF)Hair=2.5 !空气的对流系数(BTU/hr.ft2.oF)Hsea=80 !海水的对流系数(BTU/hr.ft2.oF)prep7et，1，plane55 !定义二维热单元mp，kxx，1，Kss !设定不锈钢的导热系数mp，kxx，2，Kins !设定玻璃纤维的导热系数mp，kxx，3，Kal !设定铝的导热系数pcirc，Ro，Rss，-0.5，0.5 !创建几何模型pcirc，Rss，Rins，-0.5，0.5pcirc，Rins，Ral，-0.5，0.5aglue，allnumcmp，arealesize，1，，，16 !设定划分网格密度lesize，4，，，4lesize，14，，，5lesize，16，，，2Mshape，2 !设定为映射网格划分mat，1amesh，1mat，2amesh，2mat，3amesh，3/SOLUSFL，11，CONV，HAIR，，TAIR !施加空气对流边界SFL，1，CONV，HSEA，，TSEA !施加海水对流边界SOLVE/POST1PLNSOL ！输出温度彩色云图finish实例2一圆筒形的罐有一接管，罐外径为3 英尺，壁厚为0.2 英尺，接管外径为0.5 英尺，壁厚为0.1英尺，罐与接管的轴线垂直且接管远离罐的端部。
一个经典的ansys热分析实例(流程序)
/PREP7/TITLE,Steady-state thermal analysis of pipe junction/UNITS,BIN ! 英制单位；Use U. S. Customary system of units (inches)! /SHOW, ! Specify graphics driver for interactive runET,1,90 ! Define 20-node, 3-D thermal solid elementMP,DENS,1,.285 ! Density = .285 lbf/in^3MPTEMP,,70,200,300,400,500 ! Create temperature tableMPDATA,KXX,1,,8.35/12,8.90/12,9.35/12,9.80/12,10.23/12! 指定与温度相对应的数据材料属性；导热系数；Define conductivity valuesMPDATA,C,1,,.113,.117,.119,.122,.125! Define specific heat values（比热）MPDATA,HF,2,,426/144,405/144,352/144,275/144,221/144! Define film coefficient;除144是单位问题，上面的除12也是单元问题! Define parameters for model generationRI1=1.3 ! Inside radius of cylindrical tankRO1=1.5 ! Outside radiusZ1=2 ! LengthRI2=.4 ! Inside radius of pipeRO2=.5 ! Outside pipe radiusZ2=2 ! Pipe lengthCYLIND,RI1,RO1,,Z1,,90 ! 90 degree cylindrical volume for tankWPROTA,0,-90 ! 旋转当前工作的平面；从Y到Z旋转-90度；；Rotate working plane to pipe axisCYLIND,RI2,RO2,,Z2,-90 ! 角度选择在了第四象限；90 degree cylindrical volume for pipeWPSTYL,DEFA ! 重新安排工作平面的设置；另外WPSTYL,STAT to list the status of the working plane；；Return working plane to default settingBOPT,NUMB,OFF ! 关掉布尔操作的数字警告信息；Turn off Boolean numbering warningVOVLAP,1,2 ! 交迭体；Overlap the two cylinders/PNUM,VOLU,1 ! 体编号打开；Turn volume numbers on/VIEW,,-3,-1,1/TYPE,,4 ! 精确面的显示；Precise hidden display/TITLE,Volumes used in building pipe/tank junctionVPLOTVDELE,3,4,,1 ! 修剪一些体与体相关的体的因素都删掉；Trim off excess volumes! Meshing 网格划分ASEL,,LOC,Z,Z1 ! Select area at remote Z edge of tankASEL,A,LOC,Y,0 ! Select area at remote Y edge of tankCM,AREMOTE,AREA ! 为面建立数组；Create area component called AREMOTE/PNUM,AREA,1/PNUM,LINE,1/TITLE,Lines showing the portion being modeledAPLOT/NOERASE ! 预防抹去LPLOT ! Overlay line plot on area plot/ERASEACCAT,ALL ! 连接面和线的准备映射；Concatenate areas and lines at remote tank edgesLCCAT,12,7LCCAT,10,5LESIZE,20,,,4 ! 4 divisions through pipe thicknessLESIZE,40,,,6 ! 6 divisions along pipe lengthLESIZE,6,,,4 ! 4 divisions through tank thicknessALLSEL ! Restore full set of entitiesESIZE,.4 ! Set default element size线的默认划分数MSHAPE,0,3D ! Choose mapped brick meshMSHKEY,1 ! 映射网格SAVE ! Save database before meshingVMESH,ALL ! Generate nodes and elements within volumes/PNUM,DEFA ! 重新安排数字规格/TITLE,Elements in portion being modeledEPLOTFINISH/COM, *** Obtain solution ***/SOLUANTYPE,STATIC ! Steady-state analysis typeNROPT,AUTO ! 自动选择牛顿-拉普森Program-chosenNewton-Raphson optionTUNIF,450 ! 给结点统一的温度；Uniform starting temperature at all nodesCSYS,1 ! 1 —Cylindrical with Z as the axis of rotation NSEL,S,LOC,X,RI1 ! Nodes on inner tank surfaceSF,ALL,CONV,250/144,450 ! 为结点指定表面载荷；对流；Convection（对流）；load at all nodesCMSEL,,AREMOTE ! 选择子集组合；Select AREMOTE component NSLA,,1 ! Nodes belonging to AREMOTED,ALL,TEMP,450 ! 设定边界温度条件Temperature constraints at those nodesWPROTA,0,-90 ! Rotate working plane to pipe axisCSWPLA,11,1 ! 在工作区声明本地的圆柱体系；Define local cylindrical c.s at working planeNSEL,S,LOC,X,RI2 ! Nodes on inner pipe surfaceSF,ALL,CONV,-2,100 ! 这里的-2表示材料2；；Temperature-dep. convection load at those nodesALLSEL/PBC,TEMP,,1 ! 边界符号的显示Temperature b.c. symbols on/PSF,CONV,,2 ! Convection symbols on 箭头显示/TITLE,Boundary conditionsNPLOTWPSTYL,DEFACSYS,0AUTOTS,ON ! Automatic time steppingNSUBST,50 ! Number of substepsKBC,0 ! Ramped loading (default)OUTPR,NSOL,LAST ! 显示最后一次的结点约束；Optional command for solution printoutSOLVEFINISH/COM, *** Review results ***/POST1/EDGE,,1 ! Displays only the "edges（刀口, 利刃, 锋, 优势, 边缘, 优势, 尖锐）" of an object；Edge display/PLOPTS,INFO,ON ! Legend column on/PLOPTS,LEG1,OFF ! Legend header off 圆柱数列的头部/WINDOW,1,SQUARE ! SQUA, form largest square window within the current graphics area；Redefine window size/TITLE,Temperature contours at pipe/tank junctionPLNSOL,TEMP ! Plot temperature contoursCSYS,11NSEL,,LOC,X,RO2 ! Nodes and elements at outer radius of pipeESLN ! 选择单元NSLE ! 选择结点/SHOW,,,1 ! 向量显示；Vector mode/TITLE,Thermal flux vectors at pipe/tank junctionPLVECT,TF ! Plot thermal flux（热通量）vectorsFINISH。
ANSYS热应力分析-实例
Workshop Supplement
练习4B 热应力分析 直接耦合场
带翅片的管
4B. 热应力分析 – 直接应力场
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说明 •
Workshop Supplement
在这个练习题中,我们将 用直接应力场的方法重做前面的题目。 这个轴对称的翅片将被用来分析以前施加的热和结构荷载。
4B. 热应力分析 – 直接应力场
Workshop Supplement
4A.热应力分析 –耦合场
带翅片的管
Workshop Supplement
4A.热应力分析 –耦合场
带翅片的管
14e. 画纵向(轴向)的应力图:
– – Main Menu > General Postproc > Plot Results > -Contour Plot- Nodal Solu ... • 拾取 “Stress” 和 “Y-direction SY”, 然后按 [OK] 或用命令: PLNSOL,S,Y
Utility Menu > Select > Everything 或用命令: CP,1,UY,ALL ALLSEL,ALL
4A. 热应力分析 –耦合场
带翅片的轴对称管
11. 将内部压力施加在线上:
– Main Menu > Preprocessor > Loads > -Loads- Apply > Pressure > On Lines + • – 拾取线 9和13, 然后按 [OK] • 将VALUE设为 1000, 然后按 [OK] 或用命令: SFL,9,PRES,1000 SFL,13,PRES,1000
–
9.
基于ANSYS WORKBENCH的通电导线的热分析
基于ANSYS WORKBENCH的通电导线的热分析本篇文章是关于ANSYS WORKBENCH的耦合场分析的一个例子。
一根导线在通稳恒电流后会发热，这属于电-热耦合分析，例子本身很简单，只是说明WORKBENCH自带的耦合分析系统的使用。
【问题描述】一根裸露导线，电阻为R，通过电流为I，需要计算电线中心温度和表面温度。
已知导线的长度为0.1米，截面半径为0.005米，导线的热传导率是60.5瓦每米摄氏度，电阻率是1.7e-1欧姆米，电流大小是20安培，环境温度是20摄氏度，导线裸露表面与空气的对流换热系数是5瓦特每平方米摄氏度。
（注：该题来自于《ANSYS 13.0 WORKBENCH数值模拟技术》，许京荆编著）【问题分析】ANSYS WORKBENCH中自带热电分析系统，可以直接进行热电耦合分析。
使用过程与一般分析相同。
【求解过程】1.打开ANSYS WORKBENCH14.52.创建热-电分析系统。
3.创建材料模型。
双击engineering data进入到工程数据中。
系统默认的钢材的热传导率和电阻率与已知条件相同，不需要修改。
退回到WB界面。
4.创建几何模型。
双击geometry进入到DM中，选择长度单位是毫米。
其尺寸如下图退出DM.5.划分网格。
6.设置边界条件。
设置一个端面电压为零。
设置另外一个端面的电流为20安。
对外圆柱面设置对流边界条件。
7.求解。
8.后处理。
温度云图。
整个导体温度均匀。
电压云图。
焦耳热云图。
ANSYS温度场例题分析
短圆柱体的热传导过程问题：一短圆柱体,直径和高度均为1m,现在其上端面施加大小为100℃的均匀温度载荷,圆柱体下端面及侧面的温度均为0℃,试求圆柱体内部的温度场分布假设圆柱体不与外界发生热交换;圆柱体材料的热传导系数为30W/m·℃;求解：第一步：建立工作文件名和工作标题在ANSYS软件中建立相应的文件夹,并选择Thermal复选框;第二部：定义单元类型在单元类型element type中选择thermal solid和quad 4node 55,在单元类型选择数字element type reference number输入框中输入1,在单元类型选择框里选择Axisymmetric,其余默认即可;第三步：定义材料性能参数在材料性能参数对话框中输入圆柱体的导热系数30.第四步：创建几何模型、划分网格创建数据点,输入点坐标;在第一个输入框中输入关键点编号1,并输入第一个关键点坐标0、0、0,重复输入第二个、第三个、第四个关键点,相应的坐标分别为20.5,0,0；30.5,1,0；40,1,0;结果如下图1所示：在模型中创建直线,选择编号为1、2的关键点生成一条直线,在选取2、3生成一条直线,同样选择编号为3、4和编号为4、1的关键点生成另外两条直线;结果如下图2所示：之后在plot numbering controls对话框,分别打开KP Keypoint numbers、LINE line numbers、AREA Area numbers,建立直线L1、L2、L3、L4线段;生成几何模型,如下图所示：在L1、L3线段上划分20个单元,并将L2、L4划分成40个单元格,并在模型上选取编号为A1的平面,如下图所示：将结果进行保存;第五步：加载求解选择分析类型Steady-State,在Select Entities对话框,第一个下拉列表框中选择Lines,在第二个下拉列表中选择By Num,第三个单选框中选择From Full;选择线段L1、L2;重复上述操作,在Select Entities对话框,第一个下拉列表框中选择Nodes,在第二个下拉列表中选择Attached to,第三个单选框中选择Lines,all;并在Lab2 DOFs to be constrained 列表中选择TEMP,在VALUE Load TEMP value输入框中输入0;在Select Entities对话框,第一个下拉列表框中选择Lines,在第二个下拉列表中选择By Num,第三个单选框中选择From Full选择L3线段,重复上述操作,在Select Entities对话框,第一个下拉列表框中选择Nodes,在第二个下拉列表中选择Attached to,第三个单选框中选择Lines,all;并在Lab2 DOFs to be constrained 列表中选择TEMP,在VALUE Load TEMP value输入框中输入100;加载结果如下图所示：单击Solve Current Load Step对话框中点击OK,ANSYS开始求解;并将结果进行保存;第六步：输出温度场分布图在Item,Comp Item to be contoured列表中选择DOF solution Temperature TEMP,在KUNND Items to be plotted单选框中选择Def shape only,单击OK将显示温度场分布等值图,结果如下图所示：。
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问题描述：一个30公斤重、温度为70℃的铜块,以及一个20公斤重、温度为80℃的铁块，突然放入温度为20℃、盛满了300升水的、完全绝热的水箱中,如图所示。
过了一个小时，求铜块与铁块的最高温度(假设忽略水的流动)。
材料热物理性能如下：热性能单位制铜铁水导热系数W/m℃ 383 37密度Kg/m 8889 7833 996比热J/kg℃ 390 448 4185菜单操作过程：一、设置分析标题1、选择“Utility Menu>File>Change Jobname”，输入文件名Transient1。
2、选择“Utility Menu>File>Change Title”输入Thermal Transient Exercise 1。
二、定义单元类型1、选择“Main Menu>Preprocessor”，进入前处理。
2、选择“Main Menu>Preprocesor>Element Type>Add/Edit/Delete”。
选择热平面单元plane77。
三、定义材料属性1、选择“Main Menu>Preprocessor>Material Props>Material Models”，在弹出的材料定义窗口中顺序双击Thermal选项。
2、点击Conductivity，Isotropic，在KXX框中输入383；点击Density，在DENS框中输入8898；点击Specific Heat，在C框中输入390。
3、在材料定义窗口中选择Material>New Model，定义第二种材料。
4、点击Conductivity，Isotropic，在KXX框中输入70；点击Density，在DENS框中输入7833；点击Specific Heat，在C框中输入448。
5、在材料定义窗口中选择Material>New Model，定义第三种材料。
6、点击Conductivity，Isotropic，在KXX框中输入.61；点击Density，在DENS框中输入996；点击Specific Heat，在C框中输入4185。
四、创建几何模型1、选择“Main Menu>Preprocessor>-Modeling->Create>-Areas->Retangle>By Dimensions”，输入X1=0, Y1=0, X2=, Y2=, 点击Apply；输入X1=, Y1=, X2= ,Y2=, 点击Apply；输入X1= Y1=, X2= Y2=+, 选择OK。
2、选择“Main Menu>Preprocessor>-Modeling->Operate>Booleans>Overlap”，选择Pick All。
3、选择“Utility Menu>Plotctrls>Numbering>Areas, on”。
4、选择“Utility Menu>Plot>Areas”。
五、划分网格1、选择“Main Menu>Preprocessor>-Attributes->Define->All Areas”，选择材料1。
2、选择“Main Menu>Preprocessor>Meshing->Size Cntrls->-Manualsize->-Global->Size”，输入单元大小。
3、选择“Main Menu>Preprocessor>Meshing->Mesh->-Areas->Mapped>3 or 4 sided”，选择铜块。
4、选择“Main Menu>Preprocessor>-Attributes->Define->All Areas”，选择材料2。
5、选择“Main Menu>Preprocessor>Meshing->Mesh->-Areas->Mapped>3 or 4 sided”，选择铁块。
6、选择“Main Menu>Preprocessor>-Attributes->Define->All Areas”，选择材料3。
7、选择“Main Menu>Preprocessor>Meshing->Size Cntrls->-Manualsize->-Global->Size”，输入单元大小。
8、选择“Main Menu>Preprocessor>Meshing->Mesh->-Areas->Free”，选择水箱。
9、选择“Utility Menu>Plot>Area”。
六、进行稳态分析设置初始条件1、选择“Main Menu>Solution>-Analysis Type->New Analysis”，选择Transient，定义为瞬态分析。
2、选择“Main Menu>Solution>-Load Step Opts>Time/Frenquenc>Time Integration”，将TIMINT设定为 off，首先进行稳态分析。
3、选择“Main Menu>Solution>-Load Step Opts>Time/Frenquenc>Time-Time Step”，设定TIME为、DELTIM也为4、选择“Utility Menu: Select>Entities”，在对话框中自上而下依次选择：Elements，By Attributes，Material num，在“Min， Max”框中输入3，选择From Full，点击APPLY；选择选择Nodes，Attached to, Element，点击OK。
5、选择“Main Menu>Solution>-Loads->Apply>-Thermal->Temperature>On Nodes”，选择Pick All, 输入20。
6、选择“Utility Menu: Select>Entities”，在对话框中自上而下依次选择：Elements，By Attributes，Material num，在“Min， Max”框中输入2，选择From Full，点击APPLY；选择选择Nodes，Attached to, Element，点击OK。
7、选择“Main Menu>Solution>-Loads->Apply>-Thermal->Temperature>On Nodes”，选择Pick All, 输入80。
8、选择“Utility Menu>Select>Entities”，在对话框中自上而下依次选择：Elements，By Attributes，Material num，在“Min， Max”框中输入1，选择From Full，点击APPLY；选择选择Nodes，Attached to, Element，点击OK。
9、选择“Main Menu>Solution>-Loads->Apply>-Thermal->Temperature>On Nodes”，选择Pick All, 输入70。
10、选择“Utility Menu>Select Everything”。
11、Main Menu>Solution>-Solve->Current LS”。
七、进行瞬态分析1、选择“Main Menu>Solution>-Load Step Opts>Time/Frenquenc>Time-Time Step”，设定TIME=3600,DELTIM=26, 最小、最大时间步长分别为2, 200, 将Autots设置为ON。
2、选择“Main Menu>Solution>-Load Step Opts>Time/Frenquenc>Time Integration”，将TIMINT设置为ON。
3、选择“Main Menu>Solution>-Loads->Delete>-Thermal->Temperature>On Nodes”，选择Pick All，删除稳态分析定义的节点温度。
4、选择“Main Menu>Solution>-Load Step Opts>Output Ctrls->DB/Results”，选择Every Substeps。
5、选择“Main Menu>Solution>-Solve->Current LS”。
八、后处理1、选择“Main Menu>TimeHist PostPro”，进入POST26。
2、选择“Main Menu>TimeHist PostPro>Define Variables”，点击Add，选择Solution summary，点击OK，在User specified label框中输入dtime，选择Solution Items和StepTime，点击OK定义子步时间为2号变量。
3、选择“Main Menu>TimeHist PostPro>Define Variables”，点击Add，选择Nodal result，点击OK，在User specified label框中输入T_Copper，在Node number框中输入node,,0)，点击OK定义3号变量。
同理可以定义其他节点解。
4、选择“Main Menu>TimeHist PostPro>Graph Virables”，输入变量代号，显示各变量随时间变化的曲线。
5、选择“Main Menu>General Postproc”，进入POST1。
6、选择“Main Menu>General Postproc>-Read Results->Last set”。
7、选择“Main Menu>General Postproc>Plot result>Nodal Solution”，选择temperature。
等效的命令流方法/filename,transient1/title, Thermal Transient Exercise 1!进入前处理/prep7et,1,plane77! 定义单元类型mp,kxx,1,383! 定义材料热性能参数mp,dens,1,8889!1～铜，2～铁，3～水mp,c,1,390mp,kxx,2,70mp,dens,2,7837mp,c,2,448mp,kxx,3,mp,dens,3,996mp,c,3,4185!创建几何实体rectnag,0,,0,rectang,,,,rectang,布尔操作/pnum,area,1aplot!划分网格aatt,1,1,1eshape,2esize,amesh,2aatt,2,1,1amesh,3aatt,3,1,1eshape,3esize,amesh,4/pnum,mat,1eplotfinish/soluantype,transtimint,off!先作稳态分析,确定初始条件time,!设定只有一个子步的时间很小的载荷步deltim,esel,s,mat,,3nsle,sd,all,temp,20esel,s,mat,,2nsle,sd,all,temp,80esel,s,mat,,1nsle,sd,all,temp,70allselsolve!得到初始温度分布!进行瞬态分析time,3600timint,on!打开时间积分deltim,26,2,200!设置时间步长，最大及最小时间步长autots,on!打开自动时间步长ddelet,all,temp!删除稳态分析中定义的节点温度outres,all,1!将每个子步的值写入数据库文件solvefinishsave!进入POST26后处理/post26solu,2,dtime,,dtime!2～每一子步采用的时间步长nsol,3,node,,0),temp,,T_Copper!3～铜块的中心点nsol,4,node,,0),temp,,T_Iron!4～铁块的中心点nsol,5,node(30,0,0),temp,,T_H2O_Bot!5～水箱的底部nsol,6,node(30,50,0),temp,,T_H2O_Top!6～水箱的顶部nsol,7,node(0,25,0),temp,,T_H2O_Left!7～水箱的左部nsol,8,node(60,25,0),temp,,T_H2O_Right!8～水箱的右部Plvar,2plvar,3,4,5,6,7,8finish!进入POST1后处理/post1!设置为最后一个载荷子步set,lastesel,s,mat,,1nsle,sesel,s,mat,,2 nsle,s plnsol,temp finish。