半桥变压器设计步骤

*(10*B) *10 *Vol =
2.19
2
-3
*B
*10 * Wtfe = *10 * Wtfe =
-3
-3
Pfe=5.97*f *Bac Pfe= STEP NO.25 : P =Pcu+Pfe = STEP NO.26 : Vo
1.26
1.73
W Vs1 50.00 Vs2 0.00 g g g g Vs3 0.00
Vinmax(V): Vin(V): Vinmin(V): Vo(V): 流 Io(A): 率 f(Hz): D(us):
流. 路 降 數:
12 12 12 50 5 0.3
Vo(V): 流 Io(A): Ton(us) :
(10V ,50A 1.11)
0 0.25
Vo(V): 流 Io(A):
0 0.18
Pt( STEP NO.6 :
路) =
VA 6.4939 T cm
***
4
Ap=[(Pt*104)/(Kf*Ku*Kj*f*Bm)]1/(1-X) = STEP NO.7 : 數 Np=(VINmIN*Dmax)/(2*Bm*Ac*f) = STEP NO.7 : D. Dmin =Dmax/((1-Dmax)*K+Dmax) = Dmax =K*Dmin/((Dmin*(K-1)+1) = STEP NO.8 : 流 0.5 Ip=2*(2Dmax) *Eo*Io/Vinmin = STEP NO.9 : 流 度
量 (g): ( ):
37.62 %,不 1.61 % W W
45%.
d<
: 數:
0.100 81.00
參
度 數
Weight1 Ac 1.42
Weight2 MLT 8.22
Weight3 Wc 117.79
Weight4 column c1 column c2 column c3 column c4 Vol Wtfe AS Ku Kf
Байду номын сангаасX J=Kj*Ap =
us us A
554.92
A/cm2 mm
:
STEP NO.10 : dp = 11.287(Ip/J)1/2 = Rp=MLT*Np*Column C1* *10 STEP NO.12 : 2 Pcu = Ip *Rp = 路 ) STEP NO.13 : 流( Is Is Is Is STEP NO.14 :
2
: =Np*
1 2
+Ns*
2
2
=
流 流 流
2
N
/Wc = 37.62 % : N 2/Wc < 45% Rs1 Rs2 Rs3
STEP NO.17 : Rs=MLT*Ns*Column C* *10 STEP NO.18 : 2 Pcu =Io *Rs = STEP NO.19 : Pcu=Pcu +Pcu = STEP NO .20 : 率 =Pcu/(Po+Pcu)*100 = STEP NO.21 : 率 STEP NO.22 :
路 路
降 VDF(V) : 率 ( t( ):
POT Core( 狀 ) / 1 , 金 /2, /3
: ):
2
-
流/ 1
-
流/ 2
-
流/ 3
Core
度: :
:
25
: EI40/27/12 0.042
Ap 數 :
Bm :
Kj = X=
PRI
: :
:
cm4 SEC1
SEC2
SEC3
率:
: 0.01 0.020 mm 0.36 0.25 Pcu : Pfe :
Ap 1.6726
: STEP NO.1 : 流 Vs1 Eo = K*Vo + Vd = Eo = STEP NO.2 : 率 PSAC=Eo*Io= PSAC = PODC = STEP NO.3 : 率 STEP NO.4 : Pt ( Pt ( Pt ( 率( 路 0.5 流 ) = Po*(1/ +2 ) = 流 ) = Po*(1/ +1) = 流 ) = Po*(1/ +1) = V Ps1 VA VA 0.945 ) VA VA VA Ps2 Ps3 VA Vs2 Vs3 V
Vo = (Ns*Vinmin)/(4Np*Dmax)-Vd = STEP NO.27. 量 WG1=MLT*Np*Weight1 = WG2=MLT*Ns1*Weight2 = WG3=MLT*Ns2*Weight3 = WG4=MLT*Ns3*Weight4 = STEP NO.28. . 0.79 55.01 t = (P /(As*0.0005)) = STEP NO.29. . d < 2*65.5/f0.5 = STEP NO.30. 數. 2 PRI : n = (d/dMIN) = SEC1 : n = (d/dMIN) =
流 流 流
-6
mm
= W Is1 Is2 Is3 A A A A Ns1 Ns2 Ns3 T mm mm mm cm cm cm cm
= (1+2Dmax) /2*Io = = (2*Dmax) *Io =
路
0.5
0.5
= = 數
Ns=(2Np*Eo*Dmax)/(Vinmin/2) = STEP NO.15 : 0.943 0.211 0.179 STEP NO. 16 : N
2 SEC1 : n = (d/dMIN) = 2 SEC1 : n = (d/dMIN) = 2
V
mm
-6
= W W %
P =Po/ -Po = STEP NO.23 : Pfe=P -Pcu = STEP NO.24 : -3 1.41 1.77 Pfe=0.165*10 *f *B *Wtfe = : : :
路
W W W W W W
狀
Pfe=0.287*f Pfe=0.262*f
1.448 1.39