三年高考(2017-2019)各地文科数学高考真题分类汇总:集合
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集合
1.(2019全国Ⅰ文2)已知集合{}{}{}1,2,3,4,5,6,72,3,4,52,3,6,7U
A B ===,,,则U B A =I ð( )
A .{}1,6
B .{}1,7
C .{}6,7
D .{}1,6,7 2.(2019全国Ⅱ文1)已知集合={|1}A x x >-,{|2}B x x =<,则A ∩B =( ) A .(–1,+∞)
B .(–∞,2)
C .(–1,2)
D .∅
3.(2019全国Ⅲ文1)已知集合2{1,0,1,2}{1}A B x x =-=≤,,则A B =I ( )
A .{}1,0,1-
B .{}0,1
C .{}1,1-
D .{}0,1,2 4.(2019北京文1)已知集合A ={x |–1
(A )(–1,1) (B )(1,2) (C )(–1,+∞) (D )(1,+∞)
5.(2019天津文1)设集合, , ,则( )
(A ){2} (B ){2,3} (C ){-1,2,3} (D ){1,2,3,4}
6.(2019江苏1)已知集合{1,0,1,6}A =-,{|0,}B x x x =>∈R ,则A B =I .
7.(2019浙江1) 已知全集{}1,0,1,2,3U =-,集合{}0,1,2A =,{}1,0,1B =-,则U A B I ð=( )
A .{}1-
B .{}0,1
C .{}1,2,3-
D .{}1,0,1,3-
8.(2018全国卷Ⅰ)已知集合{0,2}=A ,{21012}=--,
,,,B ,则A B =I A .{0,2} B .{1,2} C .{0} D .{21012}--,
,,, 9.(2018浙江)已知全集{1,2,3,4,5}U =,{1,3}A =,则
A .∅
B .{1,3}
C .{2,4,5}
D .{1,2,3,4,5}
10.(2018全国卷Ⅱ)已知集合{}1,3,5,7A =,{}2,3,4,5B =,则A B =I
A .{3}
B .{5}
C .{3,5}
D .{}1,2,3,4,5,7
{}1,1,2,3,5A =-{}2,3,4B ={|13}C x R x =∈<„()A C B =I U =U A ð
11.(2018北京)已知集合{|||2}A x x =<,{2,0,1,2}B =-,则A B =I
A .{0,1}
B .{–1,0,1}
C .{–2,0,1,2}
D .{–1,0,1,2}
12.(2018全国卷Ⅲ)已知集合{|10}A x x =-≥,{0,1,2}B =,则A B =I
A .{0}
B .{1}
C .{1,2}
D .{0,1,2}
13.(2018天津)设集合{1,2,3,4}A =,{1,0,2,3}B =-,{|12}C x x =∈- ()A B C =U I A .{1,1}- B .{0,1} C .{1,0,1}- D .{2,3,4} 14.(2017新课标Ⅰ)已知集合{|2}A x x =<,{320}B x =->,则 A .3 {|}2 A B x x = C .3{|}2A B x x = D .A B =R U 15.(2017新课标Ⅱ)设集合{1,2,3}A =,{2,3,4}B =,则A B U = A .{1,2,3,4} B .{1,2,3} C .{2,3,4} D .{1,3,4} 16.(2017新课标Ⅲ)已知集合{1,2,3,4}A =,{2,4,6,8}B =,则A B I 中元素的个数为 A .1 B .2 C .3 D .4 17.(2017天津)设集合{1,2,6}A =,{2,4}B =,{1,2,3,4}C =,则()A B C =U I A .{2} B .{1,2,4} C .{1,2,4,6} D .{1,2,3,4,6} 18.(2017山东)设集合{}11M x x =-<,{} 2N x x =<, 则M N =I A .()1,1- B .()1,2- C .()0,2 D .()1,2 19.(2017北京)已知U =R ,集合{|22}A x x x =<->或,则U A ð= A .(2,2)- B .(,2)(2,)-∞-+∞U C .[2,2]- D .(,2][2,)-∞-+∞U 20.(2017浙江)已知集合{|11}P x x =-<<,{|02}Q x x =<<,那么P Q U = A .(1,2)- B .(0,1) C .(1,0)- D .(1,2) 答案 1.解析 因为{}1234567234{}}23{567U A B ===,,,,,,,,,,,,,,, 所以C 17{}6U A =,,, 则{67?}U B A =I ,ð. 故选C . 2.解析 (1,)A =-+∞,(,2)B =-∞,(1,2)A B =-I .故选C. 3.解析 因为{}1,0,1,2A =-,2{|1}{|1 1}B x x x x ==-剟?, 所以{}1,0,1A B =-I .故选A . 4.解析 由数轴可知,{}1A B x x =>U .故选C. 5.解析 设集合{}1,1,2,3,5A =-,{}13C x x =∈ 故选D. 6.解析 因为{}1,0,1,6A =-,{}|0,B x x x =>∈R , 所以{}{}{}1,0,1,6|0,1,6A B x x x =->∈=R I I . 7.解析 {1,3}U A =-ð,{1}U A B =-I ð .故选A . 8.A 【解析】由题意{0,2}A B =I ,故选A . 9.C 【解析】因为{1,2,3,4,5}U =,{1,3}A =,所以{2,4,5}.故选C . 10.C 【解析】因为{}1,3,5,7A =,{}2,3,4,5B =,所以{3,5}A B =I ,故选C . 11.A 【解析】{|||2}(2,2)A x x =<=-,{2,0,1,2}B =-,∴{0,1}A B =I ,故选A . 12.C 【解析】由题意知,{|10}A x x =-≥,则{1,2}A B =I .故选C . 13.C 【解析】由题意{1,0,1,2,3,4}A B =-U ,∴(){1,0,1}A B C =-U I ,故选C . 14.A 【解析】∵3{|}2B x x =<,∴3{|}2 A B x x = 15.A 【解析】由并集的概念可知,{1,2,3,4}A B =U ,选A . 16.B 【解析】由集合交集的定义{2,4}A B =I ,选B . 17.B 【解析】∵{1,2,4,6}A B =U ,(){1,2,4}A B C =U I ,选B . =U A ð