广东省深圳市南山区外国语学校2020-2021学年第二学期九年级第一次模拟考试数学试卷(4月)

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南山区第二外国语(海德学校)2020-2021学年第二学期七年级期中考试数学试卷 -答案

南山区第二外国语(海德学校)2020-2021学年第二学期七年级期中考试数学试卷 -答案
解:(1)如图 1,延长 EP 交 CD 于 M, ∵AB∥CD, ∴∠AEP=∠GMP, ∵∠EPG 是△PGM 的外角, ∴∠EPG=∠PMG+∠PGC=∠AEP+∠PGC;
(2)如图 2,∵EF 平分∠PEB, ∴可设∠BEF=∠PEF=α, ∵AB∥CD, ∴∠GFE=∠BEF=α, ∴四边形 PGFE 中,∠PGF=360°﹣∠P﹣2α, ∴∠PGC=180°﹣(360°﹣∠P﹣2α)=∠P+2α﹣180°, ∵∠EFG 是△FGH 的外角, ∴∠FGH=∠EFG﹣∠EHG=α﹣∠EHG, 又∵QG 平分∠PGC, ∴∠PGC=2∠FGH, 即∠P+2α﹣180°=2(α﹣∠EHG), 整理可得,∠P+2∠EHG=180°. 故答案为:∠P+2∠EHG=180°.
19.小明骑自行车去上学,当他以往常的速度骑了一段路时,忽然想起要买某本书,于是又 折回到刚经过的一家书店,买到书后继续赶去学校.以下是他本次上学离家距离与时间 的关系示意图.根据图中提供的信息回答下列问题:
(1)小明家到学校的距离是 1500 米?书店到学校的距离是 900 米? (2)小明在书店停留了 4 分钟,本次上学途中,小明一共行驶了 2700 米。 (3)在整个上学的途中 12-14 时间段小明骑车速度最快?最快的速度是 450 米/分钟? (4)如果小明不买书,以往常的速度去学校,需要 7.5 分钟?本次上学比往常多用
2020-2021 年度第二学期七年级期中考试数学试卷
(南山第二外国语海德学校)
参考答案与试题解析
一.选择题(共 10 小题)
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广东省深圳市2020-2021学年上学期九年级英语期末试卷分类汇编:信息匹配(部分答案)

广东省深圳市2020-2021学年上学期九年级英语期末试卷分类汇编:信息匹配(部分答案)

广东省深圳市2020-2021学年上学期九年级英语期末试卷分类汇编信息匹配广东省深圳市光明区2020-2021 学年九年级上学期期末考试英语试题第三节信息匹配下面的材料A~F分别给出了六条建议。

请根据Noah、.Emelia 、Joshua、Reagan和Lily 五位同学的情况,帮助他们选择合适的建议,并在答题卡上将相应的字母编号涂黑。

(共5 小题,每小题1分)A. It can be sad when people don't believe what you say. You might think about why this has been happening. Be true to everyone. Over time, your honesty will speak for itself and people will know they can trust you.B. Tell your mom how you feel, Perhaps you both can find some time for just the two of you. Maybe each of your siblings wants the same. Be sure to share your mom—she loves every one of you!C. What exciting news for you and your sister! It shows your parents are confident with your musical talent. Talk to your parents and sister. Together, make a clear plan for the lessons. You'll do a good job.D. It's certainly possible for a person to be strong and gentle, often at the same time. If you practice kindness often, you may discover many chances to be strong and gentle at the same time,E. It's great that you want to say "thank you". Make a list of the people who do things for you. Another idea is to write thank-you notes, You may be surprised by how much a thank-you note can mean to someone!F. It's common for one to feel a little uncomfortable when he or she receives praise or attention. It shows people enjoy what you've done and they feel proud of you. You should feel proud of yourself, too\31. My parents are asking me to teach my sister piano. Any tips? ——Noah32.1 always feel strange when people clap for me. What should I do? ——Emelia33. People say I'm lying, even though Tm not. ——Joshua34.1 think I can be strong, but my friends think I'm gentle. ——Reagan35.1 have six siblings (兄弟姐妹),I want to spend time alone with my mom, but I can’t.——Lily 答案:31 — 35 CFADB广东省深圳市龙岗区2020-2021 学年九年级上学期期末考试英语试题第三节信息匹配下面的材料A-F分别介绍了六条网友回复信息, 请根据Tina, Mike,Betty, Toby和Nick的烦恼, 帮助他们选出最合适的回复, 并将其标号填入提前括号内。

2020-2021学年广东省深圳市中考模拟化学试卷(含答案)

2020-2021学年广东省深圳市中考模拟化学试卷(含答案)

2020-2021学年广东省深圳市九年级(下)第一次质检化学试卷一、单项选择题Ⅰ:(本大题共8小题,每小题1.5分,共12分。

在每小题列出的四个选项中,只有一项最符合题意。

)1.(1.5分)中华文明灿烂辉煌,在古代就有许多发明和创造。

下列叙述中不涉及到化学变化的是()A.制作石器B.烧制陶瓷C.粮食酿酒D.使用火药2.(1.5分)下列图示实验操作正确的是()A.B.C.D.3.(1.5分)下列化学符号中数字“2”表示的意义,正确的是()A.CO2:表示二氧化碳中含有2个氧原子B.N2:表示2个氮原子C.2Na:表示2个钠原子D.O2﹣:表示氧的化合价为﹣2价4.(1.5分)根据图中提供的信息判断,下列说法不正确的是()A.①③属于同种元素B.②表示的元素常见化合价为+1价C.硒元素的相对原子质量是34D.③④为稳定结构5.(1.5分)甲烷(CH4)和水反应可以制水煤气,其反应的微观示意图如图,下列叙述正确的是()A.甲烷中碳元素的质量分数为20%B.甲烷(CH4)中碳元素化合价为+4价C.反应前后分子数目不变D.该反应中,生成C和D的分子个数比为1:36.(1.5分)把一定量甲、乙、丙、丁四种物质放入一个密闭容器中,在一定条件下充分反应,测得反应前后各物质的质量如下表所示。

下列说法正确的是()物质甲乙丙丁反应前质量/g1051216反应后质量/g8530xA.反应中甲和丙的质量比为1:8B.x=0C.该反应是分解反应D.乙一定是该反应的催化剂7.(1.5分)下列说法不正确的是()A.煤的燃烧可能造成酸雨的原因是排放大量SO2B.利用肥皂水可以区分硬水和软水C.炒菜时油锅着火可用锅盖盖灭D.图书档案起火时,用干粉灭火器灭火8.(1.5分)在溶质为Cu(NO3)2、AgNO3和Al(NO3)3的溶液中加入一定量的锌粉,充分反应后过滤,得到滤渣和蓝色滤液。

下列判断正确的是()A.向滤渣中加入稀盐酸可能有气泡产生B.滤渣中一定有Ag,可能有Cu和ZnC.滤液中一定无AgNO3D.滤液中可能有四种金属离子二、单项选择题Ⅱ:(本大题共4小题,每小题2分,共8分。

2020-2021深圳市南山二外高中三年级数学下期末第一次模拟试卷(含答案)

2020-2021深圳市南山二外高中三年级数学下期末第一次模拟试卷(含答案)

2020-2021深圳市南山二外高中三年级数学下期末第一次模拟试卷(含答案)一、选择题1.已知2a ib i i+=+ ,,a b ∈R ,其中i 为虚数单位,则+a b =( ) A .-1 B .1 C .2 D .3 2.设是虚数单位,则复数(1)(12)i i -+=( )A .3+3iB .-1+3iC .3+iD .-1+i3.抛掷一枚质地均匀的硬币两次,在第一次正面向上的条件下,第二次反面向上的概率为( ) A .14B .13C .12D .234.已知a r 与b r均为单位向量,它们的夹角为60︒,那么3a b -r r 等于( )A .7B .10C .13D .45.两个实习生每人加工一个零件.加工为一等品的概率分别为23和34,两个零件是否加工为一等品相互独立,则这两个零件中恰有一个一等品的概率为A .12B .512C .14D .166.函数y ()y ()f x f x ==,的导函数的图像如图所示,则函数y ()f x =的图像可能是A .B .C .D .7.已知双曲线C :22221x y a b -= (a >0,b >0)的一条渐近线方程为52y x =,且与椭圆221123x y +=有公共焦点,则C 的方程为( ) A .221810x y -=B .22145x y -=C .22154x y -=D .22143x y -=8.某学校组织学生参加英语测试,成绩的频率分布直方图如图,数据的分组一次为[)[)[)20,40,40,60,60,80,[80,100].若低于60分的人数是15人,则该班的学生人数是( )A .45B .50C .55D .9.设双曲线22221x y a b-=(0a >,0b >)的渐近线与抛物线21y x =+相切,则该双曲线的离心率等于( ) A .3B .2C .6D .510.已知a R ∈,则“0a =”是“2()f x x ax =+是偶函数”的( ) A .充分不必要条件 B .必要不充分条件 C .充分必要条件D .既不充分也不必要条件11.已知,m n 是两条不同的直线,α,β是两个不同的平面,给出下列命题:①若m αP ,m n ⊥,则n α⊥; ②若m α⊥,n αP ,则m n ⊥;③若,m n 是异面直线,m α⊂,m βP ,n β⊂,n αP ,则αβ∥; ④若,m n 不平行,则m 与n 不可能垂直于同一平面. 其中为真命题的是( ) A .②③④B .①②③C .①③④D .①②④12.一个几何体的三视图如图所示,其中正视图是一个正三角形,俯视图是一个等腰直角三角形,则该几何体的外接球的表面积为( )A .43π B .83π C .163πD .203π二、填空题13.如图,一辆汽车在一条水平的公路上向正西行驶,到处时测得公路北侧一山顶D 在西偏北的方向上,行驶600m 后到达处,测得此山顶在西偏北的方向上,仰角为,则此山的高度________ m.14.事件,,A B C 为独立事件,若()()()111,,688P A B P B C P A B C ⋅=⋅=⋅⋅=,则()P B =_____.15.某大学为了解在校本科生对参加某项社会实践活动的意向,拟采用分层抽样的方法,从该校四个年级的本科生中抽取一个容量为300的样本进行调查.已知该校一年级、二年级、三年级、四年级的本科生人数之比为4:5:5:6,则应从一年级本科生中抽取_______名学生.16.已知函数()(ln )f x x x ax =-有两个极值点,则实数a 的取值范围是__________. 17.幂函数y=x α,当α取不同的正数时,在区间[0,1]上它们的图像是一族美丽的曲线(如图).设点A (1,0),B (0,1),连接AB ,线段AB 恰好被其中的两个幂函数y=x α,y=x β的图像三等分,即有BM=MN=NA ,那么,αβ等于_____.18.在ABC △中,角A ,B ,C 的对边分别为a ,b ,c ,若cos 1cos2cos 1cos2b C Cc B B+=+,C 是锐角,且27a =,1cos 3A =,则ABC △的面积为______. 19.在体积为9的斜三棱柱ABC —A 1B 1C 1中,S 是C 1C 上的一点,S —ABC 的体积为2,则三棱锥S —A 1B 1C 1的体积为___.20.()sin 5013=oo________________.三、解答题21.已知数列{}n a 满足1112,22n n n a a a ++==+. (1)设2nn na b =,求数列{}n b 的通项公式; (2)求数列{}n a 的前n 项和n S ; (3)记()()211422nnn n n nn c a a +-++=,求数列{}n c 的前n 项和n T .22.某小组共10人,利用假期参加义工活动,已知参加义工活动次数为1,2,3的人数分别为3,3,4,现从这10人中随机选出2人作为该组代表参加座谈会.()1设A 为事件“选出的2人参加义工活动次数之和为4”,求事件A 发生的概率; ()2设X 为选出的2人参加义工活动次数之差的绝对值,求随机变量X 的分布列和数学期望. 23.在直角坐标系xOy 中,直线l 1的参数方程为2+,,x t y kt =⎧⎨=⎩(t 为参数),直线l 2的参数方程为2,,x m m m y k =-+⎧⎪⎨=⎪⎩(为参数).设l 1与l 2的交点为P ,当k 变化时,P 的轨迹为曲线C . (1)写出C 的普通方程;(2)以坐标原点为极点,x 轴正半轴为极轴建立极坐标系,设()3:cos sin 0l ρθθ+=,M 为l 3与C 的交点,求M 的极径.24.已知函数()()2f x x 2a 1x 2alnx(a 0)=-++>.()1求()f x 的单调区间;()2若()f x 0≤在区间[]1,e 上恒成立,求实数a 的取值范围.25.随着“互联网+交通”模式的迅猛发展,“共享自行车”在很多城市相继出现。

(广东深圳卷)2022年中考数学第二次模拟考试(A4考试版)

(广东深圳卷)2022年中考数学第二次模拟考试(A4考试版)

2022年中考数学第二次模拟考试(深圳卷)(本卷共22小题,满分100分,考试用时90分钟)注意事项:1.答卷前,考生务必将自己的姓名、准考证号填写在答题卡上。

2.回答第Ⅰ卷时,选出每小题答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑。

如需改动,用橡皮擦干净后,再选涂其他答案标号。

写在本试卷上无效。

3.回答第Ⅱ卷时,将答案写在答题卡上。

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4.考试结束后,将本试卷和答题卡一并交回。

5.考试范围:中考全部内容。

第Ⅰ卷(选择题,共30分)一、选择题(本大题共10个小题,每小题3分,共30分,每小题均有四个选项,其中只有一项符合题目要求,答案涂在答题卡上)1.(2022·浙江温州·模拟预测)某零件如图所示,它的俯视图是( )A .B .C .D .2.(2022·浙江宁波·模拟预测)﹣3的相反数是( )A .3B .±3C .13D .﹣133.(2022·浙江温州·模拟预测)某小组英语听力口语考试的分数依次为:25,29,27,25,22,30,26,这组数据的中位数是( )A .27B .26C .25.5D .254.(2022年广东省肇庆市四会市九年级下学期中考数学一模)在平面直角坐标系中,点(3,2)关于x 轴对称的点的坐标为( )A. (3,2)-B. (2,3)-C. (2,3)-D. (3,2)-5.(2022年广东省珠海市文园中学九年级下学期第一次模拟)下列运算正确的是( )A. 235a a a ⋅=B. 623a a a ÷=C. 624a a -=D. ()2323ab a b -=6.(2022年广东省佛山市禅城区中考一模)将不等式组1113x x >⎧⎪⎨≤⎪⎩的解集在数轴上表示,正确的是( ) A.B. C. D.7.(广东省韶关市南雄市20212022学年九年级第一次质检)抛物线y =(x ﹣1)2﹣2的顶点坐标为( )A. (1,2)B. (1,﹣2)C. (﹣1,2)D. (﹣1,﹣2) 8.(2022·浙江·温州市瓯海区外国语学校一模)如图, 在Rt ABC 中, 90CAB ∠=, 点,A B 分别在墙面ED 和地面FD 上, 且斜边BC ∥ED , 若1,AC CBA ∠α==, 则AD 的长为 ( ).A .cos tan αα⨯B .tan cos ααC .cos tan ααD .1cos tan αα⨯ 9.(2020•菏泽)一次函数y =acx +b 与二次函数y =ax 2+bx +c 在同一平面直角坐标系中的图象可能是( )A .B .C .D .10.(2021·浙江杭州·二模)如图,在等边三角形ABC 的AC ,BC 边上分别任取一点P ,Q ,且AP =CQ ,AQ 、BP 相交于点O .下列四个结论:①若PC =2AP ,则BO =6OP ;②若BC =8,BP =7,则PC =5;③AP 2=OP •AQ ;④若AB =3,则OC 3 )A .①②④B .①③④C .②③④D .①②③第Ⅱ卷(非选择题,共70分)二、填空题(本大题共5个小题,每小题3分,共15分,答案写在答题卡上)11.(2022年广东省佛山市南海区中考一模数学)分解因式:328a a -=______.12.(2022年广东省中山市九年级下学期第一次模拟)若x 2﹣3x =﹣3,则3x 2﹣9x +7的值是 _____. 13.(2022年广东省肇庆市四会市九年级下学期中考数学一模)如图,在菱形ABCD 中,30A ∠=︒,取大于12AB 的长为半径,分别以点A ,B 为圆心作弧相交于两点,过此两点的直线交AD 边于点E (作图痕迹如图所示),连接BE ,BD ,则EBD ∠的度数为_________.14.(2022·广东·江门市新会东方红中学模拟预测)如图,在Rt △ABC ,∠B =90°,∠ACB =50°.将Rt △ABC 在平面内绕点A 逆时针旋转到△AB ′C ′的位置,连接CC ′.若AB ∥CC ′,则旋转角的度数为_____°.15.(2021·广东·市大望学校一模)如图,在平面直角坐标系xOy 中,直线1y fx =与双曲线2g y x =相交于(2,3)A 、()2,3B --两点,C 是第一象限内双曲线上一点,连接CA 并延长交y 轴与点P ,连接BP ,BC .若PBC ∆的面积是24,则点C 的坐标为________.三、解答题(本大题共6个小题,共55分,解答过程写在答题卡上)16.(5分)先化简,再求值:2244412m m mm m-+-÷-+,其中21m+=.17.(6分)在如图所示的直角坐标系中,解答下列问题:(1)分别写出A、B两点的坐标;(2)将△ABC绕点A顺时针旋转90°,画出旋转后的△AB1C118.(8分)(2022年广东省佛山市南海区中考一模数学)随着社会的发展,私家车变得越来越普及,使用节能低油耗汽车,对环保有着非常积极的意义,某市有关部门对本市的某一型号的若干辆汽车,进行了一项油耗抽样实验:即在同一条件下,被抽样的该型号汽车,在油耗1L的情况下,所行驶的路程(单位:km)进行统计分析,结果如图所示:(注:记A为12~12.5,B为12.5~13,C为13~13.5,D为13.5~14,E为14~14.5)请依据统计结果回答以下问题:(1)试求进行该试验的车辆数;(2)请补全频数分布直方图;(3)若该市有这种型号的汽车约900辆(不考虑其他因素),请利用上述统计数据初步预测,该市约有多少辆该型号的汽车,在耗油1L的情况下可以行驶13km以上?19.(8分)如图,以△ABC的边BC为直径作⊙O,点A在⊙O上,点D在线段BC的延长线上,AD=AB,∠D=30°.(1)求证:直线AD是⊙O的切线;(2)过点O作OE∥AB交AC与点E,若直径BC=4,求OE的长.20.(8分)某水果批发商经销一种水果,进货价是12元/千克,如果销售价定为22元/千克,每日可售出500千克;经市场调查发现,在进货价不变情况下,若每千克涨价1元,日销售量将减少20千克.(1)若要每天销售盈利恰好为6000元,同时又可使顾客得到实惠,每千克应涨价为多少元?(2)当销售价是多少时,每天的盈利最多?最多是多少?21.(10分)函数y =14x 2+bx +c 图象交x 轴于A ,B 两点(点A 在左侧)、交y 轴交于点C .已知:OB =2OA ,点F 的坐标为(0,2),△AFB ≌△ACB .(1)求抛物线解析式;(2)抛物线上点P 在第一象限,当∠OCB =2∠PCB 时,求点P 的坐标;(3)抛物线上的点D 在第一象限内,过点D 作直线DE ⊥x 轴于点E ,当7OE =20DE 时,直接写出点D 的坐标;若点M 在抛物线上,点N 在抛物线的对称轴上,是否存在以点B ,D ,M ,N 为顶点的四边形是平行四边形?若存在,请求出所有符合条件的点M 的坐标;若不存在,请说明理由.22.(10分)如图,已知E 为正方形ABCD 的边AD 上一点,连结CE ,点B 关于CE 的对称点为B '连结B D ',并延长B D '交BA 的延长线于点F ,延长CE 交B ′F 于点G ,连结BG ,BB '.(1)请写出所有与CBG ∠相等的角(必须用图中所给的字母);(2)请判断BGB '△的形状,并证明;(3)若2AE DE =,6BC =,求BB '的长.。

2020-2021学年九年级下学期第一次教学质量检测历史试题(含答案)

2020-2021学年九年级下学期第一次教学质量检测历史试题(含答案)

顺德区2020—2021学年度第二学期九年级第一次教学质量检测历史一、单项选择题(本大题30小题,每小题2分,共60分。

每小题列出的四个选.项中只有一个是正确的。

请将答题卡上对应题目所选的选项涂黑)1.历史学家钱穆曾说过:各民族最先历史断难脱离“传说”与带有“神话”之部分。

若严格排斥传说,则古史即无从说起……欲排斥某项传说,应提出与此传说相反之确据。

此主张适合研究A北京人 B.河姆渡人 C.半坡人 D.炎帝黄帝2.《吕氏春秋》中有记载:昔者汤克夏而正天下。

天大旱,五年不收,汤乃以身祷于桑林,曰:“余一人有罪,无及万夫。

万夫有罪,在余一人。

无以一人之不敏,使上帝鬼神伤民之命。

”这一记载符合A.儒家思想B.道家思想C.法家思想D.墨家思想3.有学者认为:它对帝国并不是新东西,也不是起源于秦。

但公元前221年的改革至关重要,它断然摒弃了重立列国的思想,从而为中央统一全帝国各地的集权管辖提供了各种手段。

“它”的实行A.导致了地方势力膨胀B.开创了历代地方行政模式C.引发了秦末农民起义D.加强了国家对文化的管理4.有学者认为:“张骞两次出使西域,拓展了汉王朝的视野,引发了汉王朝与中亚、西亚各国相互贸易的强烈愿望,促成了西汉政府对丝绸之路的开辟和经营。

”该学者认为张骞A.开辟并经营丝绸之路B.拓展了汉朝西部疆域C.最早开始了对外交流D.促进了中外经贸往来5.题5图是关于东汉时期政治局势的一幅漫画。

此漫画反映的历史现象A.利于皇帝行使君权B.加剧地方割据混战C.造成东汉政治腐朽D.直接导致东汉灭亡6.十六国时期,虽然“五胡”内侵、战乱频仍,但是各少数民族统治者大多实行“崇儒兴学”的政策。

这一政策A.确立了儒学正统地位B.促进了北方民族交融C.推动了北方人口南迁D.加速了门阀政治形成7黄仁宇认为:迄至武则天御驾归西之日,她的帝国没有面临到任何真实的危机。

也有学者认为:武则天的统治起到承前启后的枢纽作用,史称“武周之治”。

广东省深圳市南山区第二实验学校2020-2021学年八年级上学期开学考试英语试题

广东省深圳市南山区第二实验学校2020-2021学年八年级上学期开学考试英语试题

广东省深圳市南山区第二实验学校2020-2021学年八年级上学期开学考试英语试题学校:___________姓名:___________班级:___________考号:___________一、单项选择1.—Does Mr. Miller love his dog?—Yes. Whenever he goes out, he takes it with him.A.No matter who B.No matter when C.No matter what 2.—What do you think of the new film?—It’s so interesting that we all love it.A.lovely B.great C.funny3.—How is your work going?—So far it has been easy, but things may change.A.Until now B.Just now C.In the future 4.—What do you usually do when you’re in trouble?—I usually ask my parents for suggestions.A.mind B.space C.advice 5.—What’s the ending of the story?—The little girl succeeded in finding her parents in the end.A.at first B.at last C.in time 6.—Tony, before handing in your paper, you’d better look it over carefully.—I see, Mum.A.copy it B.check it C.control it7.—How much is the white sweater?—It’s 300 yuan.A.What’s the price of B.Why not buy C.How do you like 8.—Can you speak Russian?—No, but I know a bit of French.A.a few B.a kind C.a little9.A(n)________ is someone who wins a game, competition, etc.A.winner B.guest C.inventor10.The boy ________ himself behind a tree, so his mother couldn’t find him.A.taught B.enjoyed C.hid11.—What did you say to your little brother just now?—I told him not to _______ our parents any more. We’ve grown up.A.learn from B.depend on C.look after 12.—What’s the most important thing for a teacher?—The most important thing is to _______ his or her students.A.respect B.punish C.operate13.—What does your father do, Jack?—He is a worker in the food _______. He likes his job.A.company B.museum C.countryside 14.—What do you know about Peter?—He likes doing his homework and listening to music _______.A.at any time B.at the same time C.at any times15.—I hear they’re going to _______ Romeo and Juliet school hall this Friday.—Really? I can’t wait to see it.A.get up B.take out C.put on二、完形填空and Lewis saw a large mass(一团)of gray smoke coming from the car. So Lewis asked hisbus.16.A.compared B.punished C.caught D.drove 17.A.invention B.direction C.pollution D.rule 18.A.bad B.good C.helpful D.valuable 19.A.way B.habit C.problem D.order 20.A.happily B.slowly C.hardly D.possibly 21.A.early B.late C.relaxed D.popular 22.A.drawing about B.talking about C.moving about D.thinking about 23.A.mention B.give C.pick D.produce 24.A.car B.bike C.bus D.plane 25.A.useful B.boring C.tiny D.harmful三、阅读单选People are always good at inventing things. Let’s learn about some inventions that can26.Which is TRUE about the wingsuit?A.You can buy it at a very low price.B.It is a very new invention.C.Its price is lower than before.D.It looks like a kind of fish.27.What can the new solar water distiller do?A.It can turn the salty water into clean drinking water.B.It can turn the dirty water into clean drinking water.C.It can make the clean drinking water warm soon.D.It can make the clean drinking water cold soon.28.Whom can the “enable talk glove” help?A.A little kid.B.A deaf person.C.A person without arms.D.A blind person.29.What can we learn about Cameron?A.He invented the Deepsea Challenger Submarine by himself.B.He joined in the competition the year before last.C.He stayed in the Challenger Deep for more than four hours.D.He set a record by going down to the bottom of the Challenger Deep alone. 30.What’s the passage mainly about?A.The history of some inventions.B.Some useful inventions.C.Ways to invent things.D.Great people in history.Shimada Kouji comes from Fukuoka, Japan. In May 2010, he was invited by a Wuhan student who studied in Japan to teach the skill of making curry (咖喱). At that time, Shimadahad visited some cities in China, including Wuhan, since 1982.“I really love China and Chinese culture,” he said. “After several months’ living in the city, I decided to stay here.” In November 2010, he opened his first restaurant in Wuhan. It became highly popular with young fans of curry and later he opened the second restaurant near Wuhan University.“Wuhan people are warm, kind and energetic,” he said. “I fell in love with the city and got used to life here.”Over the past 10 years, his restaurants have also attracted (吸引) lots of young people who are interested in Japanese language and culture, so he’s set up a free Japanese language course at his restaurant.After the city was shut down in late January to fight against COVID-19, all restaurants were closed, including Shimada’s. This seriously influenced his business. Although his relatives and friends in Japan advised him to return to his hometown, he still chose to stay in Wuhan. “I’ve seen Wuhan as my second hometown, and I hope I can join together with the city when it’s in trouble,” he said. “Through the epidemic (疫情), we can clearly see how great the Chinese government and the Chinese people are.”31.When did Shimada Kouji visit Wuhan for the first time?A.Before 1982B.In 2010C.In 2020D.Between 1982 and 201032.What does the underlined word “It” in paragraph 2 refer to?A.The Wuhan city.B.The curry food.C.The skill of making curry.D.Shimada’s first restaurant in Wuhan. 33.Which of the facts may show Shimada’s love for Wuhan?A.He opened two bookstores in Wuhan.B.He set up an expensive Japanese course for people in Wuhan.C.He didn’t fear COVID-19 and chose to stay in Wuhan.D.He decided to go back to Japan during COVID-19.34.Which of the following is TRUE according to the passage?A.Shimada Kouji came to Wuhan in 2010 because he wanted to visit his relatives.B.Shimada Kouji thinks highly of China and Chinese people.C.The epidemic didn’t have a big influence on Shimada’s restaurants.D.Shimada’s relatives and friends agreed with his idea of staying in Wuhan.35.What does the passage mainly talk about?A.A Japanese man who is full of love for Wuhan.B.A Japanese man’s restaurants in Wuhan.C.Warm and honest people in Wuhan.D.Wuhan in the eyes of a Japanese man.As an English learner, I used to translate(翻译)an English sentence into Chinese word by word when I wanted to recite it. Later, I found it not clever to learn English in this way. Take the sentence “How do you do?” for example. If you look up each word in the dictionary, one at a time, what’s your translation? It must be a wrong sentence in your own language.Languages do not just have different sounds,and they are also different in many ways. It is important to master the rules for word order in the study of English, too. If words are put in a wrong order in the sentences, the listeners can’t understand the speakers’ sentences easily. Sometimes when the order of the words in an English sentence is changed, the meaning of the sentence is changed, too. Let me give you an example.She only likes apples.Only she likes apples.In the process of learning English, you must try your best to get the spirit of the language and use it as the English speakers do. If you can do this, you will be closer to learning it well. Would you like to have a try like this now?36.How did the writer use to learn English according to the beginning of the passage?A.In a wrong way.B.Without any help.C.In a right way.D.Without working hard.37.What can we know about learning English from the passage?A.We should look up every word in the dictionary.B.We shouldn’t translate every word into our own language.C.We need to put every word into our own language.D.We must read word by word.38.What’s the writer’s opinion about learning English?A.It is difficult to understand different sounds.B.It is impossible to remember the word order.C.It is important to master the rules for word order.D.It is easy to master the rules for word order.39.What can we know from the passage?A.The only difference between languages is the sound.B.Most people in China can not use English as the English speakers do.C.Sometimes the order of words can influence a sentence’s meaning.D.The writer likes remembering English words.40.What is the main idea of the passage?A.You should translate every word into Chinese when you learn English.B.You didn’t need to notice the word order if you learn English.C.You should always turn to a dictionary when you learn English.D.You should try your best to master the spirit of the language you learn.四、阅读还原6选5阅读短文及文后选项,选出可以填入空白处的最佳选项。

2020-2021学年度翰林中英文学校九年级第一次模拟考试 数学试卷

2020-2021学年度翰林中英文学校九年级第一次模拟考试 数学试卷

s场要对一块麦田施底肥,现有化肥若干千克.如果每公顷施肥 400
千克,那么余下化肥 800 千克;如果每公顷施肥 500 千克,那么缺少化肥 300
千克.若设现有化肥 x 千克,则可列方程为( )
18.(本题 10 分)钟南山院士谈到防护新型冠状病毒肺炎时说:“我们需要重 视防护,但也不必恐慌,尽量少去人员密集的场所,出门戴口罩,在室内注
15.老师在黑板上随手写下一串数字“002 200 220”,则数字“0”出现的频率是
_______. 16.日常生活中主要运用“十进制”数,而“十六进制”广泛应用于电子技术、 计算机编程等领域.十六进制在数学中是一种“逢 16 进 1”的进位制,一般用
数字 0 到 9 和字母 A 到 F 表示,其中用 A,B,C,D,E,F 分别表示 10,
A.109.2 米 B.136.5 米 C.242.7 米 D.303.3 米
12.求1 2 22 23 22013 的值,可令 S 1 2 22 22013 ,则
2S 2 22 23 22014 ,因此 2S S 22014 1 .仿照以上推理,计算
出1 5 52 53 52013 的值为(
意通风,勤洗手,多运动,少熬夜.”某社区为了加强社区居民对新型冠状 病毒肺炎防护知识的了解,通过微信群宣传新型冠状病毒肺炎的防护知识,
确的是( )
与白球相同的红球,混匀后再从袋子中随机摸出 20 个球,发现其中有 4 个 红球.根据小明的方法估计袋中白球有( )
A.200 个
B.100 个
C.50 个
D.40 个
6.在同一平面坐标系中,一次函数 y mx n2 与二次函数 y x2 m 的图
象可能是( )
A.

2020-2021学年上学期广东省深圳市南山区期末考试九年级数学试卷 (Word版 含解析)

2020-2021学年上学期广东省深圳市南山区期末考试九年级数学试卷  (Word版 含解析)

广东省深圳市南山区2020-2021学年九年级(上)期末数学试卷一、选择题(本题有10小题,每小题3分,共30分.在每小题给出的四个选项中,只有一项是符合题目要求的,请将正确的选项用铅笔涂在答题卡上)。

1.如图,这是由5个大小相同的正方体搭成的几何体,该几何体的左视图()A.B.C.D.2.下列命题是假命题的是()A.四个角相等的四边形是矩形B.对角线相等的平行四边形是矩形C.对角线垂直的四边形是菱形D.对角线垂直的平行四边形是菱形3.在一个不透明的口袋中,装有若干个红球和3个黄球,它们除颜色外没有任何区别,摇匀后从中随机摸出一个球,记下颜色后再放回口袋中,通过大量重复摸球实验发现,摸到黄球的频率是0.2,则估计盒子中红球的个数大约是()A.20个B.16个C.15个D.12个4.一元二次方程x2+2x﹣1=0的根的情况是()A.有两个不相等的实数根B.有两个相等的实数根C.只有一个实数根D.没有实数根5.△ABC与△A′B′C′是位似图形,且△ABC与△A′B′C′位似比是1:2,已知△ABC的面积是10,则△A′B′C′的面积是()A.10B.20C.40D.806.关于反比例函数y=﹣,下列说法不正确的是()A.函数图象分别位于第二、四象限B.函数图象关于原点成中心对称C.函数图象经过点(﹣6,﹣2)D.当x<0时,y随x的增大而增大7.如图.AB∥CD∥EF,AF、BE交于点G,下列比例式错误的是()A.B.C.D.8.如图,已知点A是反比例函数y=(x>0)的图象上一点,AB∥x轴交另一个反比例函数y=(x>0)的图象于点B,C为x轴上一点,若S△ABC=2,则k的值为()A.4B.2C.3D.19.如图,在菱形ABCD中,对角线AC、BD交于点O,且AC=6,BD=8,过A点作AE垂直BC,交BC于点E,则的值为()A.B.C.D.10.如图,在矩形ABCD中,E是AD边的中点,BE⊥AC,垂足为点F,连接DF,下面四个结论:①CF=2AF;②AD=CD;③DF=DC;④△AEF∽△CAB;⑤S四边形CDEF=S△ABF.其中正确的结论有()A.2个B.3个C.4个D.5个二、填空题(本题有5小题,每小题3分,共15分.把答案填在答题卡上).11.已知==,且a+b﹣2c=6,则a的值为.12.小王同学想利用树影测量校园内的树高.他在某一时刻测得小树高为1.5米时,其影长为1.2米,当他测量教学楼旁的一棵大树的影长时,因大树靠近教学楼,有一部分影子在墙上.经测量,地面部分影长为6.4米,墙上影长为1.4米,那么这棵大树高约为米.13.设m、n是方程x2+x﹣1001=0的两个实数根,则m2+2m+n的值为.14.如图,在矩形ABCD中,E是边AB的中点,连接DE交对角线AC于点F,若AB=4,AD=3,则CF的长为.15.如图,在平面直角坐标系中,矩形ABCD的顶点A、D分别在x轴、y轴上,对角线BD∥x轴,反比例函数y =(k>0,x>0)的图象经过矩形对角线的交点E.若点A(2,0)、D(0,4),则反比例函数的解析式为.三、解答题:(16题6分,17题6分,18题7分,19题8分,20题9分,21题9分,22题10分,共计55分)16.解下列方程:(1)2(x﹣2)2=x2﹣4.(2)2x2﹣4x﹣1=0.17.甲、乙、丙、丁四位同学参加校田径运动会4×100米接力跑比赛,因为丁的速度最快,所以由他负责跑最后一棒,其他三位同学的跑步顺序随机安排.(1)请用画树状图或列表的方法表示甲、乙、丙三位同学所有的跑步顺序;(2)请求出正好由丙将接力棒交给丁的概率.18.如图,在菱形ABCD中,E为对角线BD上一点,且AE=DE,连接CE.(1)求证:CE=DE.(2)当BE=2,CE=1时,求菱形的边长.19.某商店准备销售一种多功能旅行背包,计划从厂家以每个30元的价格进货,经过市场发现当每个背包的售价为40元时,月均销量为280个,售价每增长2元,月均销量就相应减少20个.(1)若使这种背包的月均销量不低于130个,每个背包售价应不高于多少元?(2)在(1)的条件下,当该这种书包销售单价为多少元时,销售利润是3120元?(3)这种书包的销售利润有可能达到3700元吗?若能,请求出此时的销售单价;若不能,请说明理由.20.如图,在平面直角坐标系中,直线y=3x+b经过点A(﹣1,0),与y轴正半轴交于B点,与反比例函数y=(x>0)交于点C,且BC=2AB,BD∥x轴交反比例函数y=(x>0)于点D,连接AD.(1)求b、k的值;(2)求△ABD的面积;(3)若E为射线BC上一点,设E的横坐标为m,过点E作EF∥BD,交反比例函数y=(x>0)的图象于点F,且EF=BD,求m的值.21.问题背景如图(1),在四边形ABCD中,∠B+∠D=180°,AB=AD,∠BAD=α,以点A为顶点作一个角,角的两边分别交BC,CD于点E,F,且∠EAF=α,连接EF,试探究:线段BE,DF,EF之间的数量关系.(1)特殊情景在上述条件下,小明增加条件“当∠BAD=∠B=∠D=90°时”如图(2),小明很快写出了:BE,DF,EF之间的数量关系为.(2)类比猜想类比特殊情景,小明猜想:在如图(1)的条件下线段BE,DF,EF之间的数量关系是否仍然成立?若成立,请你帮助小明完成证明;若不成立,请说明理由.(3)解决问题如图(3),在△ABC中,∠BAC=90°,AB=AC=4,点D,E均在边BC上,且∠DAE=45°,若BD=,请直接写出DE的长.22.(1)证明推断:如图(1),在正方形ABCD中,点E、Q分别在边BC、AB上,DQ⊥AE于点O,点G、F分别在边CD、AB上,GF⊥AE.①填空:DQ AE(填“>”“<”或“=”);②推断的值为;(2)类比探究:如图(2),在矩形ABCD中,=k(k为常数).将矩形ABCD沿GF折叠,使点A落在BC 边上的点E处,得到四边形FEPG,EP交CD于点H,连接AE交GF于点O.试探究GF与AE之间的数量关系,并说明理由;(3)拓展应用:在(2)的条件下,连接CP,当k=时,若=,GF=2,求CP的长.参考答案与试题解析一.选择题(共10小题)1.如图,这是由5个大小相同的正方体搭成的几何体,该几何体的左视图()A.B.C.D.【分析】找到从几何体的左边看所得到的图形即可.【解答】解:左视图有2列,每列小正方形数目分别为2,1.故选:A.2.下列命题是假命题的是()A.四个角相等的四边形是矩形B.对角线相等的平行四边形是矩形C.对角线垂直的四边形是菱形D.对角线垂直的平行四边形是菱形【分析】根据矩形的判定对A、B进行判断;根据菱形的判定方法对C、D进行判断.【解答】解:A、四个角相等的四边形是矩形,为真命题,故A选项不符合题意;B、对角线相等的平行四边形是矩形,为真命题,故B选项不符合题意;C、对角线垂直的平行四边形是菱形,为假命题,故C选项符合题意;D、对角线垂直的平行四边形是菱形,为真命题,故D选项不符合题意.故选:C.3.在一个不透明的口袋中,装有若干个红球和3个黄球,它们除颜色外没有任何区别,摇匀后从中随机摸出一个球,记下颜色后再放回口袋中,通过大量重复摸球实验发现,摸到黄球的频率是0.2,则估计盒子中红球的个数大约是()A.20个B.16个C.15个D.12个【分析】利用大量重复实验时,事件发生的频率在某个固定位置左右摆动,并且摆动的幅度越来越小,根据这个频率稳定性定理,可以用频率的集中趋势来估计概率,这个固定的近似值就是这个事件的概率.【解答】解:设红球有x个,根据题意得,3:(3+x)=1:5,解得x=12,经检验:x=12是原分式方程的解,所以估计盒子中红球的个数大约有12个,故选:D.4.一元二次方程x2+2x﹣1=0的根的情况是()A.有两个不相等的实数根B.有两个相等的实数根C.只有一个实数根D.没有实数根【分析】先计算出根的判别式△的值,根据△的值就可以判断根的情况.【解答】解:∵在方程x2+2x﹣1=0中,△=22﹣4×1×(﹣1)=8>0,∴方程x2+2x﹣1=0有两个不相等的实数根.故选:A.5.△ABC与△A′B′C′是位似图形,且△ABC与△A′B′C′位似比是1:2,已知△ABC的面积是10,则△A′B′C′的面积是()A.10B.20C.40D.80【分析】根据位似变换的性质得到△ABC∽△A′B′C′,根据相似三角形的面积比等于相似比的平方是解题的关键.【解答】解:∵△ABC与△A′B′C′是位似图形,且△ABC与△A′B′C′位似比是1:2,∴△ABC∽△A′B′C′,相似比为1:2,∴=()2=,∵△ABC的面积是10,∴△A′B′C′的面积是40,故选:C.6.关于反比例函数y=﹣,下列说法不正确的是()A.函数图象分别位于第二、四象限B.函数图象关于原点成中心对称C.函数图象经过点(﹣6,﹣2)D.当x<0时,y随x的增大而增大【分析】根据反比例函数图象上点的坐标特征对C进行判断;根据反比例函数的性质对A、B、D进行判断.【解答】解:反比例函数y=﹣,k=12<0,A、函数图象分别位于第二、四象限,故本选项说法正确;B、函数图象关于原点成中心对称,故本选项说法正确;C、函数图象经过点(﹣6,2),故本选项说法不正确;D、当k<0,双曲线的两支分别位于第二、四象限,在每一象限内y随x的增大而增大,故本选项说法正确;故选:C.7.如图.AB∥CD∥EF,AF、BE交于点G,下列比例式错误的是()A.B.C.D.【分析】根据平行线分线段成比例定理进行判断即可.【解答】解:A、由AB∥CD∥EF,则,所以A选项的结论正确;B、由AB∥CD∥EF,则,所以B选项的结论正确;C、由AB∥CD∥EF,则,所以C选项的结论正确;D、由AB∥CD∥EF,则,所以D选项的结论错误;故选:D.8.如图,已知点A是反比例函数y=(x>0)的图象上一点,AB∥x轴交另一个反比例函数y=(x>0)的图象于点B,C为x轴上一点,若S△ABC=2,则k的值为()A.4B.2C.3D.1【分析】由点A是反比例函数y=的图象上,可得S△AOD=3,根据等底同高的三角形面积相等可得S△AOB=S=2,进而求出S△BOD=1,再根据点B在反比例函数y=(x>0)的图象上,求出S△BOD=1,进而求出k △ACB的值.【解答】解:延长AB交y轴于点D,连接OA、OB,∵点A是反比例函数y=(x>0)的图象上,AB∥x轴,∴S△AOD=|k|=×6=3,S△AOB=S△ACB=2,∴S△BOD=S△AOD﹣S△AOB=3﹣2=1,又∵点B在反比例函数y=(x>0)的图象上,∴S△BOD=|k|=1,∴k=2,k=﹣2(舍去),故选:B.9.如图,在菱形ABCD中,对角线AC、BD交于点O,且AC=6,BD=8,过A点作AE垂直BC,交BC于点E,则的值为()A.B.C.D.【分析】利用菱形的性质即可计算得出BC的长,再根据面积法即可得到AE的长,最后根据勾股定理进行计算,即可得到BE的长,进而得出结论.【解答】解:∵四边形ABCD是菱形,∴CO=AC=3,BO=BD=4,AO⊥BO,∴BC===5,∵S菱形ABCD=AC•BD=BC×AE,∴AE==.在Rt△ABE中,BE===,∴CE=BC﹣BE=5﹣=,∴的值为,故选:C.10.如图,在矩形ABCD中,E是AD边的中点,BE⊥AC,垂足为点F,连接DF,下面四个结论:①CF=2AF;②AD=CD;③DF=DC;④△AEF∽△CAB;⑤S四边形CDEF=S△ABF.其中正确的结论有()A.2个B.3个C.4个D.5个【分析】依据△AEF∽△CBF,即可得出CF=2AF;依据△BAE∽△ADC,即可得到AD=CD;过D作DM ∥BE交AC于N,依据DM垂直平分CF,即可得出DF=DC;依据∠EAC=∠ACB,∠ABC=∠AFE=90°,即可得到△AEF∽△CAB;设△AEF的面积为s,则△ABF的面积为2s,△CEF的面积为2s,△CDE的面积为3s,四边形CDEF的面积为5s,进而得出S四边形CDEF=S△ABF.【解答】解:∵AD∥BC,∴△AEF∽△CBF,∴,∵AE=AD=BC,∴=,∴CF=2AF,故①正确;设AE=a,AB=b,则AD=2a,∵BE⊥AC,∠BAD=90°,∴∠ABE=∠ADC,而∠BAE=∠ADC=90°,∴△BAE∽△ADC,∴,即b=a,∴AD=CD,故②正确;如图,过D作DM∥BE交AC于N,∵DE∥BM,BE∥DM,∴四边形BMDE是平行四边形,∴BM=DE=BC,∴BM=CM,∴CN=NF,∵BE⊥AC于点F,DM∥BE,∴DN⊥CF,∴DM垂直平分CF,∴DF=DC,故③正确;∵四边形ABCD是矩形,∴AD∥BC,∠ABC=90°,AD=BC,∵BE⊥AC于点F,∴∠EAC=∠ACB,∠ABC=∠AFE=90°,∴△AEF∽△CAB,故④正确;如图,连接CE,由△AEF∽△CBF,可得,设△AEF的面积为s,则△ABF的面积为2s,△CEF的面积为2s,∴△ACE的面积为3s,∵E是AD的中点,∴△CDE的面积为3s,∴四边形CDEF的面积为5s,∴S四边形CDEF=S△ABF,故⑤正确.故选:D.二.填空题(共5小题)11.已知==,且a+b﹣2c=6,则a的值为12.【分析】直接利用已知比例式假设出a,b,c的值,进而利用a+b﹣2c=6,得出答案.【解答】解:∵==,∴设a=6x,b=5x,c=4x,∵a+b﹣2c=6,∴6x+5x﹣8x=6,解得:x=2,故a=12.故答案为:12.12.小王同学想利用树影测量校园内的树高.他在某一时刻测得小树高为1.5米时,其影长为1.2米,当他测量教学楼旁的一棵大树的影长时,因大树靠近教学楼,有一部分影子在墙上.经测量,地面部分影长为6.4米,墙上影长为1.4米,那么这棵大树高约为9.4米.【分析】根据在同一时刻,不同物体的物高和影长成比例计算.【解答】解:设这棵大树高为x,根据平行投影特点:在同一时刻,不同物体的物高和影长成比例.可得树高比影长为=1.25,则有==0.8,解可得:x=9.4米.13.设m、n是方程x2+x﹣1001=0的两个实数根,则m2+2m+n的值为1000.【分析】由于m、n是方程x2+x﹣1001=0的两个实数根,根据根与系数的关系可以得到m+n=﹣1,并且m2+m ﹣1001=0,然后把m2+2m+n可以变为m2+m+m+n,把前面的值代入即可求出结果【解答】解:∵m、n是方程x2+x﹣1001=0的两个实数根,∴m+n=﹣1,并且m2+m﹣1001=0,∴m2+m=1001,∴m2+2m+n=m2+m+m+n=1001﹣1=1000.故答案为:1000.14.如图,在矩形ABCD中,E是边AB的中点,连接DE交对角线AC于点F,若AB=4,AD=3,则CF的长为.【分析】根据矩形的性质可得出AB∥CD,进而可得出∠F AE=∠FCD,结合∠AFE=∠CFD(对顶角相等)可得出△AFE∽△CFD,利用相似三角形的性质可得出==2,利用勾股定理可求出AC的长度,再结合CF =•AC,即可求出CF的长.【解答】解:∵四边形ABCD为矩形,∴AB=CD,AD=BC,AB∥CD,∴∠F AE=∠FCD,又∵∠AFE=∠CFD,∴△AFE∽△CFD,∴==2.∵AC==5,∴CF=•AC=×5=.故答案为:.15.如图,在平面直角坐标系中,矩形ABCD的顶点A、D分别在x轴、y轴上,对角线BD∥x轴,反比例函数y =(k>0,x>0)的图象经过矩形对角线的交点E.若点A(2,0)、D(0,4),则反比例函数的解析式为y =.【分析】根据平行于x轴的直线上任意两点纵坐标相同,可设B(x,4).利用矩形的性质得出E为BD中点,∠DAB=90°.根据线段中点坐标公式得出E(x,4).由勾股定理得出AD2+AB2=BD2,列出方程22+42+(x ﹣2)2+42=x2,求出x,得到E点坐标,即可求得反比例函数的解析式.【解答】解:∵BD∥x轴,D(0,4),∴B、D两点纵坐标相同,都为4,∴可设B(x,4).∵矩形ABCD的对角线的交点为E,∴E为BD中点,∠DAB=90°.∴E(x,4).∵∠DAB=90°,∴AD2+AB2=BD2,∵A(2,0),D(0,4),B(x,4),∴22+42+(x﹣2)2+42=x2,解得x=10,∴E(5,4).∵反比例函数y=(k>0,x>0)的图象经过点E,∴k=5×4=20,∴反比例函数的解析式为y=故答案为y=.三.解答题16.解下列方程:(1)2(x﹣2)2=x2﹣4.(2)2x2﹣4x﹣1=0.【分析】(1)先移项得到2(x﹣2)2﹣(x﹣2)(x+2)=0,然后利用因式分解法解方程;(4)利用配方法解方程即可.【解答】解:(1)2(x﹣2)2﹣(x﹣2)(x+2)=0,(x﹣2)(2x﹣4﹣x﹣2)=0,所以x1=2,x2=6;(2)x2﹣2x=,x2﹣2x+1=+1,即(x﹣1)2=,∴x﹣1=±,所以x1=1+,x2=1﹣.17.甲、乙、丙、丁四位同学参加校田径运动会4×100米接力跑比赛,因为丁的速度最快,所以由他负责跑最后一棒,其他三位同学的跑步顺序随机安排.(1)请用画树状图或列表的方法表示甲、乙、丙三位同学所有的跑步顺序;(2)请求出正好由丙将接力棒交给丁的概率.【分析】(1)画树状图即可得出答案;(2)共有6个等可能的结果,正好由丙将接力棒交给丁的结果有2个,再由概率公式求解即可.【解答】解:(1)画树状图如图:(2)由(1)得:共有6个等可能的结果,正好由丙将接力棒交给丁的结果有2个,∴正好由丙将接力棒交给丁的概率为=.18.如图,在菱形ABCD中,E为对角线BD上一点,且AE=DE,连接CE.(1)求证:CE=DE.(2)当BE=2,CE=1时,求菱形的边长.【分析】(1)证△ABE≌△CBE(SAS),即可得出结论;(2)连接AC交BD于H,先由菱形的性质可得AH⊥BD,BH=DH,AH=CH,求出BH、EH的长,由勾股定理求出AH的长,再由勾股定理求出AB的长,即可得出结果.【解答】(1)证明:∵四边形ABCD是菱形,∴∠ABE=∠CBE,AB=CB,在△ABE和△CBE中,,∴△ABE≌△CBE(SAS),∴AE=CE,∵AE=DE,∴CE=DE;(2)解:如图,连接AC交BD于H,∵四边形ABCD是菱形,∴AH⊥BD,BH=DH,AH=CH,∵CE=DE=AE=1,∴BD=BE+DE=2+1=3,∴BH=BD=,EH=BE﹣BH=2﹣=,在Rt△AHE中,由勾股定理得:AH===,在Rt△AHB中,由勾股定理得:AB===,∴菱形的边长为.19.某商店准备销售一种多功能旅行背包,计划从厂家以每个30元的价格进货,经过市场发现当每个背包的售价为40元时,月均销量为280个,售价每增长2元,月均销量就相应减少20个.(1)若使这种背包的月均销量不低于130个,每个背包售价应不高于多少元?(2)在(1)的条件下,当该这种书包销售单价为多少元时,销售利润是3120元?(3)这种书包的销售利润有可能达到3700元吗?若能,请求出此时的销售单价;若不能,请说明理由.【分析】(1)设每个背包的售价为x元,则月均销量为(280﹣×20)个,根据月均销量不低于130个,即可得出关于x的一元一次不等式,解之取其最大值即可得出结论;(2)根据总利润=每个的利润×月均销量,即可得出关于x的一元二次方程,解之取其较小值即可得出结论;(3)根据总利润=每个的利润×月均销量,即可得出关于x的一元二次方程,由根的判别式△=﹣36<0,即可得出这种书包的销售利润不能达到3700元.【解答】解:(1)设每个背包的售价为x元,则月均销量为(280﹣×20)个,依题意,得:280﹣×20≥130,解得:x≤55.答:每个背包售价应不高于55元.(2)依题意,得:(x﹣30)(280﹣×20)=3120,整理,得:x2﹣98x+2352=0,解得:x1=42,x2=56(不合题意,舍去).答:当该这种书包销售单价为42元时,销售利润是3120元.(3)依题意,得:(x﹣30)(280﹣×20)=3700,整理,得:x2﹣98x+2410=0.∵△=(﹣98)2﹣4×1×2410=﹣36<0,∴该方程无解,∴这种书包的销售利润不能达到3700元.20.如图,在平面直角坐标系中,直线y=3x+b经过点A(﹣1,0),与y轴正半轴交于B点,与反比例函数y=(x>0)交于点C,且BC=2AB,BD∥x轴交反比例函数y=(x>0)于点D,连接AD.(1)求b、k的值;(2)求△ABD的面积;(3)若E为射线BC上一点,设E的横坐标为m,过点E作EF∥BD,交反比例函数y=(x>0)的图象于点F,且EF=BD,求m的值.【分析】(1)作CH⊥y轴于点H,把点A坐标代入直线解析式中求出b,求出点B坐标,再用相似三角形的性质求出CH、BH,求出点C坐标,即可求出k;(2)先求出点D坐标,求出BD,根据三角形的面积公式计算,得到答案;(3)先求出EF=2,设出点E坐标,分0<m<2、m>2两种情况,表示出点F坐标,根据反比例函数图象上点的坐标特征建立方程求解,即可得出结论.【解答】解:(1)作CH⊥y轴于点H,∵直线y=3x+b经过点A(﹣1,0),∴﹣1×3+b=0,解得,b=3,对于直线y=3x+3,当x=0时,x=3,∴点B的坐标为(0,3),即OB=3,∵CH∥OA,∴△AOB∽△CHB,∴==,即==,解得,CH=2,BH=6,∴OH=OB+BH=9,∴点C的坐标为(2,9),∴k=2×9=18;(2)∵BD∥x轴,∴点D的纵坐标为3,∴点D的横坐标为=6,即BD=6,∴△ABD的面积=×6×3=9;(3)EF=BD=×6=2,设E(m,3m+3),当0<m<2时,点F的坐标为(m+2,3m+3),∵点F在反比例函数y=上,∴(m+2)(3m+3)=18,解得,m1=﹣4(舍去),m2=1,当m>2时,点F的坐标为(m﹣2,3m+3),∵点F在反比例函数y=上,∴(m﹣2)(3m+3)=18,解得,m3=(舍去),m4=,综上所述,m的值为1或.21.问题背景如图(1),在四边形ABCD中,∠B+∠D=180°,AB=AD,∠BAD=α,以点A为顶点作一个角,角的两边分别交BC,CD于点E,F,且∠EAF=α,连接EF,试探究:线段BE,DF,EF之间的数量关系.(1)特殊情景在上述条件下,小明增加条件“当∠BAD=∠B=∠D=90°时”如图(2),小明很快写出了:BE,DF,EF之间的数量关系为BE+DF=EF.(2)类比猜想类比特殊情景,小明猜想:在如图(1)的条件下线段BE,DF,EF之间的数量关系是否仍然成立?若成立,请你帮助小明完成证明;若不成立,请说明理由.(3)解决问题如图(3),在△ABC中,∠BAC=90°,AB=AC=4,点D,E均在边BC上,且∠DAE=45°,若BD=,请直接写出DE的长.【分析】(1)将△ABE绕点A逆时针旋转90°,得到△ADG,据此知AE=AG,BE=DG,∠BAE=∠DAG.证△AFE≌△AFG得EF=FG,从而得出答案;(2)将△ABE绕点A逆时针旋转α得到△ADH,知∠ABE=∠ADH,∠BAE=∠DAH,AE=AH,BE=DH,证△AEF≌△AHF得EF=FH=DF+DH=DF+BE;(3)将△AEC绕点A顺时针旋转90°,得到△AE′B,连接DE′.据此知BE′=EC,AE′=AE,∠C=∠ABE′,∠EAC=∠E′AB,由AB=AC=4知∠ABC+∠ABE′=90°,即∠E′BD=90°,从而得E′B2+BD2=E′D2.易证△AE′D≌△AED得DE=DE′,根据DE2=BD2+EC2可得答案.【解答】解:(1)BE+DF=EF,如图1,将△ABE绕点A逆时针旋转90°,得到△ADG,∵∠ADC=∠B=∠ADG=90°,∴∠FDG=180°,即点F,D,G共线.由旋转可得AE=AG,BE=DG,∠BAE=∠DAG.∵∠BAE+∠DAF=∠BAD﹣∠EAF=90°﹣45°=45°,∴∠DAG+∠DAF=45°,∴∠EAF=∠F AG,∴△AFE≌△AFG(SAS),∴EF=FG.又∵FG=DG+DF=BE+DF,∴BE+DF=EF,故答案为:BE+DF=EF.(2)成立.证明:如图2,将△ABE绕点A逆时针旋转α得到△ADH,可得∠ABE=∠ADH,∠BAE=∠DAH,AE=AH,BE=DH.∵∠B+∠ADC=180°,∴∠ADH+∠ADC=180°,∴点C,D,H在同一直线上.∵∠BAD=α,∠EAF=α,∴∠BAE+∠F AD=α,∴∠DAH+∠F AD=α,∴∠F AH=∠EAF,又∵AF=AF,∴△AEF≌△AHF(SAS),∴EF=FH=DF+DH=DF+BE;(3)DE=,如图3,将△AEC绕点A顺时针旋转90°,得到△AE′B,连接DE′.可得BE′=EC,AE′=AE,∠C=∠ABE′,∠EAC=∠E′AB,在Rt△ABC中,∵AB=AC=4,∴∠ABC=∠ACB=45°,BC=4,∴∠ABC+∠ABE′=90°,即∠E′BD=90°,∴E′B2+BD2=E′D2.易证△AE′D≌△AED,∴DE=DE′,∴DE2=BD2+EC2,即DE2=,解得.22.(1)证明推断:如图(1),在正方形ABCD中,点E、Q分别在边BC、AB上,DQ⊥AE于点O,点G、F分别在边CD、AB上,GF⊥AE.①填空:DQ=AE(填“>”“<”或“=”);②推断的值为1;(2)类比探究:如图(2),在矩形ABCD中,=k(k为常数).将矩形ABCD沿GF折叠,使点A落在BC 边上的点E处,得到四边形FEPG,EP交CD于点H,连接AE交GF于点O.试探究GF与AE之间的数量关系,并说明理由;(3)拓展应用:在(2)的条件下,连接CP,当k=时,若=,GF=2,求CP的长.【分析】(1)①由正方形的性质得AB=DA,∠ABE=90°=∠DAH.所以∠HAO+∠OAD=90°,又知∠ADO+∠OAD=90°,所以∠HAO=∠ADO,于是△ABE≌△DAH,可得AE=DQ.②证明四边形DQFG是平行四边形即可解决问题.(2)结论:=k.如图2中,作GM⊥AB于M.证明:△ABE∽△GMF即可解决问题.(3)如图2中,作PM⊥BC交BC的延长线于M.利用相似三角形的性质求出PM,CM即可解决问题.【解答】(1)①解:∵四边形ABCD是正方形,∴AB=DA,∠ABE=90°=∠DAQ.∴∠QAO+∠OAD=90°.∵AE⊥DQ,∴∠ADO+∠OAD=90°.∴∠QAO=∠ADO.∴△ABE≌△DAQ(ASA),∴AE=DQ.故答案是:=;②解:∵DQ⊥AE,FG⊥AE,∴DQ∥FG,∵FQ∥DG,∴四边形DQFG是平行四边形,∴FG=DQ,∵AE=DQ,∴FG=AE,∴=1.故答案为:1.(2)解:结论:=k.理由:如图2中,作GM⊥AB于M.∵AE⊥GF,∴∠AOF=∠GMF=∠ABE=90°,∴∠BAE+∠AFO=90°,∠AFO+∠FGM=90°,∴∠BAE=∠FGM,∴△ABE∽△GMF,∴=,∵∠AMG=∠D=∠DAM=90°,∴四边形AMGD是矩形,∴GM=AD,∴===k.(3)解:如图2中,作PM⊥BC交BC的延长线于M.由=,可以假设BE=3k,BF=4k,EF=AF=5k,∵=,FG=2,∴AE=3,∴(3k)2+(9k)2=(3)2,∴k=1或﹣1(舍弃),∴BE=3,AB=9,∵BC:AB=2:3,∴BC=6,∴BE=CE=3,AD=PE=BC=6,∵∠EBF=∠FEP=∠PME=90°,∴∠FEB+∠PEM=90°,∠PEM+∠EPM=90°,∴∠FEB=∠EPM,∴△FBE∽△EMP,∴==,∴==,∴EM=,PM=,∴CM=EM﹣EC=﹣3=,∴PC==.。

广东省2020-2021学年上学期九年级英语期末试卷分类汇编:书面表达(部分答案)

广东省2020-2021学年上学期九年级英语期末试卷分类汇编:书面表达(部分答案)

广东省深圳市2020-2021学年上学期九年级英语期末试卷分类汇编书面表达广东省深圳市光明区2020-2021 学年九年级上学期期末考试英语试题IV. 书面表达(15分)2020年深圳公园文化节(Park Culture Season of Shenzhen)期间深圳市各大公园举办了各种文化活动。

你参加了哪项活动?请你根据以下提示,写一则活动评论。

(参考词汇:荧光夜跑shining run;沙滩音乐节beach music festival;网球公开赛open tennis tournament;欢乐剧场happy theater)要点:1. 你参加了哪项(些)活动?2. 活动的内容。

3. 谈谈你的感受和想法。

注意:1.80词左右,开头已给出,不计入总词数内;2.文中不得出现真实姓名和校名;3.可适当増加细节,以使条理清楚、行文连贯;4.标点正确,书面整洁。

Park Culture Season of Shenzhen is a yearly event. _________________________________ _______________________________________________________________________________ _______________________________________________________________________________ _______________________________________________________________________________ _______________________________________________________________________________ _______________________________________________________________________________ 答案:One possible version:Park Culture Season of Shenzhen is a yearly event. During the season, different kinds of events were held in the parks around the city. This year, I went to quite a few events, such as the music festival at the beach and the happy theater. At the music festival, I enjoyed many pieces of pop music and traditional music. At the happy theater, there were many plays for children. I had agood time there. Thanks to all people's hard work, Shenzhen has developed very fast in recent years. I feel proud of my city. I will work hard and try to play a role in building a better city in the future.1. 评分原则:A. 采用整体印象评分法。

深圳市2020—2021学年第一学期教学质量检测九年级语文试题

深圳市2020—2021学年第一学期教学质量检测九年级语文试题

深圳市2020-2021学年第一学期教学质量检测九年级语文试卷说明:本试卷考试时长120分钟,满分120分.必须在答题卷上作答,在试题卷上作答无效.• • •一、基础(26分)班级组织了“小说天地”综合性学习活动,请根据要求完成1〜5题。

【活动一,小说开讲】听完一场小说讲座后,小福同学做了如下笔记,请根据笔记内容回答1〜3题。

笔记一:中国传统小说从说唱文学演变而来,小说是“小道”的观念①,古人曾将小说视为茶余饭后的谈资.后来小说逐渐形成以讲故事为主、设悬念吸引读者的特点.而中国现代以来的新小说受西方小说的影响,在叙事上向内转,出现淡化故事情节,加强心理描写的倾向.笔记二:中国传统的说书人遵循以小说“劝人向善”的准则,小说中蕴含了读者所认可的文化价值观,包括除暴安良、善恶有报以及仁义礼智信等.现代新小说继承了传统小说中的文化价值观,也吸收现代思想,例如平等、博爱、人对理想②zi zi的j而n的追求等.其内容与我国的社会主义核心价值观相通,在帮助读者树立正确价值观方面有着不可③轻觑的作用.青少年读者对小说的精神塑造是寓教于乐、涧物无声的.• •1 .字音字形考查。

(2分,每空1分)(1)根据拼音写词语:②zi zi bu judn ()(2)给加点词语注音:③轻觑()2 ,请从下列词语中选择最恰当的一项填入①处。

(2分)A,与日俱增 B.根深蒂固 C.不足为据 D.断章取义3 .文段画线句有语病,请写出修改后的正确表述。

(2分)【活动二,小说荐读】小福同学在班级小说荐读活动中列出了以下书单,请你根据书单内容回答4〜5题。

____ _____________4,这份书单中“现代小说”部分出现常识性错误,请你纠正,并用复句表述。

(2分)5 .书单推荐“网络小说”引发班级同学热烈讨论,有同学表示自己只读网络流行小说,不读经典名著。

请你就“网络流行小说阅读能否取代经典阅读”发表看法,要求观点明确,有说服力,’60字左右・(4分)6 .默写。

广东省深圳是百合外国语学校2020-2021学年九年级上学期期中英语试题

广东省深圳是百合外国语学校2020-2021学年九年级上学期期中英语试题

广东省深圳是百合外国语学校2020-2021学年九年级上学期期中英语试题学校:___________姓名:___________班级:___________考号:___________一、单项选择1.We can test one’s knowledge through a ________.A.talk show B.travel show C.talent show D.quiz show 2.Which of the following jobs gets to decide the roles for the TV programs?A.cameraman B.make-up artist C.director D.host3.I think Li Xueqin is one of the strongest ________ in the talk show contest.A.contestant B.contestants C.astronomers D.actress4.I am dying to ________ this time.A.win the prize B.win the prise C.praise D.defeat5.________ will help us learn more about the health condition of our body and cure the disease before it gets worse.A.Medical examinations B.Medicine exams C.ExerciseD.Vitamin6.________ his clothes were old and worn, they looked clean and of good quality.A.As though B.Because C.Since D.Although 7.Jack ________ a kind-hearted man.A.seems B.become C.turns D.feels8.________ can be really hard to quit.A.Smoke B.To smoke C.Smoking D.That smoke 9.________ at the appointment on time is very important.A.To go B.Arrive C.We arrive D.To arrive 10.You worked in London three years ago, ________?A.did you B.don’t you C.didn’t you D.were you 11.My mom is always ________ my studies.A.worried of B.worried about C.nervous about D.anxious of 12.Mary’s _________, so she hasn’t had dinner for two weeks.A.lost weight B.gain weight C.on a diet D.go diet 13.We shouldn’t _________ other’s weaknesses. That’s very mean.A.make jokes about B.joke of C.laugh forD.respect14.It was ________ of Bob ________ the bees which accidently broke into the classroom.A.friendly, to kill B.lovely, to kill C.cruel, to kill D.cruel, killing 15.Jane ________ her time when she was young. Now she feels her life is hard and hopeless.A.regretted wasting B.regret wasting C.cherishedD.regretted to waste16.Kelsey had the ________ a good educational background.A.advantage about B.disadvantage C.advantage ofD.weakness of17.My son has ________ me mad! He’s been crying for an hour to get the toy car.A.driven B.drive C.make D.been made 18.Eating with the mouth open is a very ________ habit.A.good B.annoying C.exciting D.respected 19.She was watching Tom and Jerry, ________ out loud.A.laugh B.smile C.weeping D.laughing 20.The Iceland team ________ by the French team in the World Cup in 2008.A.beat B.is beated C.was beaten D.won 21.Don’t worry. We still have ________ time.A.many B.a number of C.very little D.plenty of 22.Today’s my payday and I’d like to ________ myself to a big meal.A.invite B.treat C.pay D.give23.________, Jerry performed quite well on stage.A.To my surprise B.In general C.As a result D.Altogether 24.It’s ________ go to bed early and have a balanced diet.A.important that B.a necessity that C.improper to D.necessary to 25.What’s your ________ online classes?A.comment about B.view on C.thinking on D.think about 26.We should ________ in too much fat, oil and sugar.A.avoid taking B.avoid to C.take D.stay away from 27.Mona _______ rather than ________.A.prefers to go skiing; make a snowmanB.likes running; play the pianoC.prefered to draw; made snowmanD.likes painting; to play the computer games28.Sarah decided to order ________ for lunch.A.a salad, a glass of coffee, and fried eggsB.noodles, a cup of coffee and fried eggC.two sandwich, a cup of coffee, and fried eggD.two hamburger, one salad, a large cola29.Did you ask the teacher ________ on the second day?A.what we needed to bring the ID cardB.when and where we should meetC.how shall me get thereD.what should we take30.Which of the following statements is correct?A.I think you should not fix the computer in this way.B.I suggest you to try this brand.C.Can you tell me how can I get to the nearest subway station?D.My brother advised me to take more exercise.二、完形填空Some people are born blind. Others are born deaf. Some people lose arms or legs inmuch harder time than we do. I think we should work harder to help these people and makethese laws, they should be followed more strictly.I also think people of China should have a greater understanding of the 39 that disabled people face. If they 40 that there’s a problem, they can help to find a solution.31.A.has B.of C.with D.have 32.A.easier B.funnier C.harder D.more excited 33.A.fancy B.convenient C.clear D.small 34.A.below B.through C.over D.down 35.A.Without B.With C.No have D.For 36.A.get up B.get in C.go up D.get around 37.A.who B.that C.whom D.one 38.A.criminal B.changed C.similar D.opposite 39.A.challenges B.changes C.improvement D.accidents 40.A.say B.announce C.realize D.discuss三、阅读单选41.How much are a The other Bennet Sister and a The Way We Eat Now?A.$22. 98.B.$24. 98.C.$25. 98.D.$26. 98. 42.Questions and Answers About Plastic is aimed at helping the ________ to understand the environment problems.A.adults B.kids C.senior D.teenagers 43.Which of the following statements is correct about The Way We Eat Now?A.Modern food is damaging the health of people.B.Modern food hasn’t had much influence on our life style.C.This book intends to encourage people to stay away from traditional food.D.Its purpose is to let people have a better understanding about the food we are having now.44.If someone is stressed out from work, which book do you suggest?A.The Other Bennet Sister.B.The Way We Eat Now: Ways for Eating in a World of Change.C.Questions and Answers About Plastic.D.Funny Ha, Ha.Q: At recess (课间休息), I don’t know what to do because all my friends are playing games I don’t like. So I end up standing by myself at recess doing nothing. What should I do? Alex Ride, 13.Al: In fact, recess was my least favorite part of the school day for Grades 1 to 5. I was never really into playing kickball. So, like you, I spent many days at recess standing alone. Take advantage of the time you have. Books are good for a lonely recess, because they takeyou out of your world and into another. If reading isn’t your thing, then try making new friends. Some other things I would do were chess and paper cutting. Whatever you want to do, don’t let your time get wasted. Johnny Hayes, 15.A2: When I was 13, half my friends threw themselves into kickball recess which was too vigorous (剧烈的) for me right after lunch. So, like you. I stood around a lot. Then, one day, my teacher, Susie, asked me, “What do you want to do?” I had no answer for her. But suddenly, it came to me: marbles! I asked a few friends, and they were happy to join me. Now, I’ m not suggesting you play marbles, only if you think that’s what you feel like doing and it can make you happy. And one last idea: There’s no harm in trying games your friends are playing that you think you won’t like. You might just surprise yourself.Philip Galanes, adult.45.Who is asking for advice?A.Alex Rider.B.Johnny Heyes.C.Suie.D.Philip Galanes. 46.One of Philip’s suggestion is to ________.A.read a book B.talk to a teacherC.do what you feel like doing D.stand without doing anything 47.Why do Johnny and Philip mention the kickball game at their school?A.To show they shared similar experiences.B.To show they were good at the kickball game.C.To encourage Alex to make good use of the extra time.D.To encourage Alex to surprise himself with a new game.48.Which part of a newspaper may this passage be taken from?A.Science Study B.Art Style C.Sports World D.TeenageProblemFights at school sometimes happen. But how can you keep away from a fight? Here’s something you can do.Be calm. Sometimes, you feel so angry that you really want to teach somebody a lesson. But being angry can’t solve problems. Neither can a fight. Instead, you can bring yourself more problems. In the school, everyone involved in a fight will be punished, no matter who started it. There are no winners in a fight.Shout loudly. If you know someone is coming up behind you to attack, turn towards theperson with your hands up in front of your body and loudly say “stop” before walking away. Loud voice can usually make the attacker calm down. If the person doesn’t stop, cry for help by calling out the name of a teacher whose office is nearby._________ Your friend may ask you to join in a fight. Learn to say no. Helping him to fight is not really helping him. If you really want to give him a hand, try to persuade him to give up. Also you can tell him if he gets involved in a fight, he may get hurt and be punished. Then, try to learn why he wants a fight and help him find a right way to deal with the problem.49.The underlined word means ________.A.hug B.try to hurt or kill someone C.stopD.attract50.Which of the following sentences can be put into the blank “________”.A.Face bravely B.Join in a fight C.Learn to refuse D.Talk to someone 51.The passage is written to ________.A.help students keep away from fightsB.warn students not to fightC.advise students to help each otherD.encourage students to work hard52.The passage is written in a/an ________ tone.A.kind B.angry C.humorous D.sadThis painting is called The Fighting Temeraire. Temeraire is the name of the big, old sailing ship that you can see on the left of the picture. People chose this picture to be the greatest painting in Britain.J. M. W. Turner painted it in 1839. It shows the old sailing ship, on the River Thames near London. There’s a small tugboat pulling the old ship. It’s in fact taking the Temeraire on its last journey. In the background we can see the sun setting.The picture, however, is more than just a painting of two boats in the evening. The artist wanted to show the end of an era. The time of the beautiful, old sailing ships is coming to anend. That’s why we see this happening at sunset. In the little, brown tugboat we can see the new industrial era starting. The tugboat is small and dark and it’s making a lot of smoke but it’s very strong, because it’s pulling the much bigger ship.The painting shows a real event. Turner watched the Temeraire taking its trip up the Thames, but he changed some of the details. He painted the old ship white and gold so that it looks like a ghost. In fact, the real ship was black and yellow. We also see the sun setting behind the ship, but in fact, the ship travelled towards the sunset. However, Turner wanted to show the sun setting on the time of the beautiful old sailing ships.Turner painted it when he was quite old, so perhaps he wanted to show the sun setting on his own life, too. He loved the painting and he never sold it. You can see it today in the National Gallery in London.53.The Fighting Temeraire ________.A.is the name of a big sailing shipB.was thought the best painting in BritainC.shows two nice new shipsD.was painted by a famous young artist.54.What does the tugboat stand for according to the passage?A.The new industrial eraB.The beautiful eraC.The painter’s own lifeD.The white and gold ghost55.Which of the following statements is true?A.The color of the real sailing ship was gold and white.B.In the painting the sailing ship was going towards the sunset.C.Finally Turner sold his painting because he didn’t like it.D.Today the painting was kept in the National Gallery in London.56.What can we infer from the last two paragraphs?A.The painting The Fighting Temeraire is so outdated that it’s stored in the National Gallery.B.British people probably don’t like to recall the past.C.Turner was sad that he grew old.D.The Fighting Temeraire is considered to be the greatest painting in Britain not onlybecause of its painting skill but also because of its historical meaning.Playing video games and getting money for it seems like a dream job for many of today’s teenagers. But is it all fun and games?Pro (professional) gaming is certainly big business. In 2017, there were more than 3, 000 gaming competitions and over 10, 000 professional players worldwide. A large number of people watch their competitions online, and successful gamers can get more than 1, 000, 000 dollars from prize money and ads. The industry is thriving.Becoming a professional is not just about being good at playing games—it also takes a lot of hard work. Some pro gamers practice for fourteen hours a day. “You need to spend much time and put all your effort into it”, says exgamer George.It can be a difficult job as well. Stress is a big problem for gamers. Tiredness is another, and injuries are common. Top player Hai Lam had wrist problems after years of pro gaming. Careers are short, and many gamers retire before they get 30 and try to find another job. 57.How many pro players were there around the world in 2017?A.130, 000.B.More than 3. 000.C.Over 1, 000, 000.D.More than 10, 000.58.What does the underlined word “thriving” in Paragraph 2 mean?A.Getting worse.B.Booming.C.Developing slowly.D.Coming to an end.59.What’s the main idea of the passage?A.The career as a professional gamer doesn’t last long.B.Professional gaming isn’t all fun and games.C.Being a professional gamer is a good choice for teenagers.D.Being a professional gamer is an easy way to make money.60.Professional gaming can be ________.A.relaxing, meaningless, boring B.fun, easy, relaxingC.relaxing, hard, exhausting D.difficult, tiring, stressful四、根据句意填空五、用所给单词的正确形式填空六、语法填空expect one and had warned us it would be included in the final grade. The test began. Sure(minute) except the very last one: What is the name of the old lady, who cleans the lecture hall? I thought it was a joke. I’d seen the old lady many times. She’ d been working in thebecause of it. But then one student put up his hand. He hadn’t finished the test, either. “I’mlast question?’’ “Certainly,” our professor 80 (smile). “In your future jobs...”I’ve never forgotten that lesson. I also learned that the cleaner’s name was Sherry.Aunt Linda’s RepliesDear Anna,It’s right of you to worry about your friend John. It’s not necessary for her to stay on81 diet because of the fact that she’s thin. It happens all the time that we worry about82 (we) looks, so she’s not alone.Dear Peter,You did the right thing at that moment. You’ll feel terribly sorry otherwise. You should still act the same way 83 the same situation if it happens again. There’s no need to listen to your friend on that. How terrible 84 them to laugh at a sick lady!Dear Simon,It’s common for people to wear braces nowadays. Remember, the moment you stop 85 (pay) attention to your friends, they will stop laughing at you. We know it hurts sometimes, 86 think of the days when you can smile beautifully with straight teeth just in a few 87 (month) time!Dear Julie,I would suggest that you talk to your sister 88 (many). Tell her when she can play the piano and when she can borrow your things. Spend some time with her every day 89 you will end up with living 90 (happy) with your sister.七、课内填空fat, oil and sugar. He also stated that it’s necessary for me to have a moreSamuel: What’s a balanced diet?Doris: A balanced diet means kinds of healthy food every day.Research shows that each day you should have plenty of fruit, vegetables and such as noodles and bread. And, in general, you should have and eggs, and less meat.八、书信作文92.Lori是一名初一的学生,因面临第一次期中考试和家长会感到有些焦虑,上课状态欠佳,请你以师哥师姐身份,给她些建议:1. 注意学习和运动及爱好的间的关系;2. 充分休息,上课提高效率;3. 给出1—2条你自己的其它建议。

2020-2021深圳市南山二外小学二年级数学下期末第一次模拟试卷(含答案)

2020-2021深圳市南山二外小学二年级数学下期末第一次模拟试卷(含答案)

2020-2021深圳市南山二外小学二年级数学下期末第一次模拟试卷(含答案)一、选择题1.下面()大约是1千克。

A. 2只鸡蛋B. 5袋大米C. 6个苹果D. 10个1元硬币2.李强体重75()。

A. 吨B. 千克C. 克3.一件衣服的价格是385元,一件裤子的价格是249元,大约一共要()元.A. 600B. 640C. 5504.7618中的6表示()。

A. 6个一B. 6个十C. 6个百5.算式□4÷8=6……○中,○里最大填( ),□内填( ),此题选( )。

A. 6,54B. 7,55C. 8,566.下面的数中,除以6没有余数的是()A. 14B. 24C. 347.教师节,6个班的同学做花,每班9朵,送给老师45朵,还有多少朵?A. 9×6=54(朵) 54+45=99(朵)B. 9×6=54(朵) 54-45=9(朵)8.从48中连续减8,减( )次后结果为0。

A. 8B. 6C. 79.下面物体的运动属于旋转的是()。

A. B. C. D.10.用一根长30米的绳子,可以剪成()根6米长的绳子。

A. 5B. 6C. 2411.心心幼儿园新进了一批玩具。

玩具个数(个)812610A. 20B. 36C. 18D. 26二、填空题12.一瓶墨水重100克,________瓶墨水重1千克。

13.796-208中,796接近________,202接近________,计算结果大约是________。

14.________÷________=________(盘)……________(个)________÷________=________(个)……________(个)15.比3个9的和多7的数是________。

16.拨动算盘是________现象.17.观察下图,●的个数是☆的________倍。

☆☆☆☆●●●●●●●●●●●●18.数一数,填一填。

2020-2021学年度第二学期九年级第一次模拟考试 物理试卷(含答案)

2020-2021学年度第二学期九年级第一次模拟考试 物理试卷(含答案)

2020-2021学年度第二学期九年级第一次模拟考试物理试卷(满分:70分考试时长:60分钟)考生注意:1.物理部分共20道小题,总分70分,理化总时间100分钟。

2.请将选择题(1~15小题)的答案用2B铅笔填涂在答题卡的指定位置。

请将非选择题的解答写在答题卡的指定位置。

3.考试完毕只交答题卡。

第一卷客观题(35分)一、单选题(共10小题,每题2分,共20分。

每小题只有一个选项符合题意,错选、不选该题不得分)1.下列估测最接近实际的是()A.人体正常体温39℃B.雾霾颗粒的直径约为1cmC.一颗鸡蛋质量约为500gD.空调正常工作时的电流大约为4.5A2.关于声现象,下列说法中正确的是()A.声音的传播不需要介质,真空可以传播声音B.“闻其声而知其人”主要是根据音色来判断C.“震耳欲聋”指声音的音调高D.在高速路的两旁设置隔音墙是为了消除噪声3.下列说法中正确的是()A.白光由红、黄、蓝三种色光组成B.近视眼成像在视网膜后,用凹透镜矫正C.树在地上的影子和小孔成像的成像原理相同D.能看见花谷里黄色的花是因为它吸收了黄光4.自然界中的云、雨、雪、雾、露、霜等现象,都是水的物态发生变化形成的,下图中描述的物理现象理解正确的是()A.雾的形成是液化现象,吸收热量B.露的形成是熔化现象,放出热量C.雾凇的形成是凝华现象,放出热量D.雪的形成是凝固现象,吸收热量5.足球运动中蕴含着许多物理知识,下列说法正确的是()A.飞行的足球,受到重力和推力的作用B.足球在飞行过程中,它的运动状态不发生改变C.踢出去的足球能继续飞行是因为足球具有惯性D.飞行的足球,若所受的力全部消失它将立即停止运动6.如图所示物体A,B叠放在水平地面上,对A施加水平向右的拉力F,A,B一起向右做匀速直线运动,下列说法正确的是()①A受的摩擦力向左,大小为F②A对B的摩擦力向右,大小为F③物体B受到四个力的作用④地面对B的摩擦力向左,大小为FA.只有②③正确B.只有①②正确C.只有①②④正确D.①②③④都正确7.下列有关说法正确的是()A.以天然气为燃料,汽车发动机的效率可以达到100%B.内能小的物体可以将热量传给内能大的物体C.热值越大的燃料,完全燃烧时放出的热量一定越多D.20C︒的水比10C︒的水含有的热量多8.超市的商品上贴有软磁条,消费者如果不买单,直接走出超市,软磁条没有消磁,防盗报警器上的检测头就会有电流产生,导致报警器响起。

广东省深圳南山区学府中学2020-2021学年九年级下学期开学考试化学试题(无答案)

广东省深圳南山区学府中学2020-2021学年九年级下学期开学考试化学试题(无答案)

学府中学九年级2021年开学测试化学学科试卷满分50分可能用到的相对原子质量:H1,C12,O16,N14,Ca-40,C135.5一、选择题(本大题包括8小题:每小题1.5分,共12分,每小题只有一个选项符合题意)1.下列变化中,属于化学变化的是()A.活性炭吸附冰箱内异味B.冬天河水结冰C.烟烧石灰石制生石灰D.分离空气制氧气2.下列实验操作正确的是()A.倾倒试剂B.滴加试剂C.液体加热D.量筒读数3.下表中1、2、3各项之间能构成右图包含关系的是4.下列实验现象的描述正确的是()A.木炭在氧气中燃烧产生明亮的黄色火焰B.磷在氧气中燃烧产生大量的白雾C.铁丝在氧气中燃烧,放出大量的热,火星四射,生成四氧化三铁D.硫在氧气中燃烧发出明亮蓝紫色火焰,生成有刺激性气味的气体5.下列有关催化剂的说法中误的是()A.催化剂就是二氧化锰B.催化剂能改变其他物质的化学反应速度C.在化学反应前后催化剂的质量没有改变D.在化学反应前后催化剂的化学性质没有改变6.实验室制取CO2一般分为五个步骤:①检查装置的气密性;②连接、组装仪器;③向长颈漏斗中注入稀盐酸;④向锥形瓶中放入大理石;⑤收集气体正确的操作顺序是()A.①②③④⑤B.①②④③⑤C.②①③④⑤D.②①④③⑤7.用“”和“”代表两种不同的单质分子,它们在一定条件下能发生化学反应,反应前后的微观示意图如下图所示,下列说法正确的是A.该反应是分解反应B.该反应有2种生成物C.每个生成物分子由4种属子构成D.参加反应的“”和“”分子的个数比是3:18.一个密闭容器中加入甲、乙、丙、丁四种物质,在一定条件下发生化学反应,测得数据见右表,下列说法中正确的是()A.x=9 gB.该反应是化合反应C.该反应中,丙物质一定做催化剂D.在该反应的化学方程式中,丙、丁的化学计量数比为1:1二、选择题(本大题包括4小题:每小题2分,共8分,每小题只有一个选项符合题意)9.某微粒结构示意图为,下列对该微粒的说法中不正确的是()A.x的值一定等于10B.核外电子是分层排布的C.具有稳定结构D.可能是阳离子成阴离子或电中性的原子10.通过下列实验可以得出的结论,其中不合理的是()A.甲实验中黄铜片能在铜片上刻画出痕迹可以说明黄铜的硬度比铜片大B.乙实验既可以说明分子在不停的运动着C.丙实验既可以说明二氧化碳能溶于水,又可以说明二氧化碳具有酸性D.丁实验既可以说明一氧化碳具有还原性,又可以说明一氧化碳具有可燃性11.“雪碧”是一种无色的碳酸饮料,将少量“雪碧”滴入紫色石蕊试液中,然后再加热,溶液的颜色变化情况是()A.先变红色后变紫色B.变红后颜色不再改变C.先变无色后变红 B.先变蓝色后变紫色12.30g某化合物完全燃烧,生成88g二氧化碳和54g水,该化合物中()A.只含碳、氢两种元素B.含碳、氢元素,可能含有氧元素C.含有碳、氢、氧三种元素D.无法确定三、非选择题:本大题共4小题共30分13、(10分化学方程式2分个)已知:①二氧化碳气体既不溶于饱和NaHCO3溶液,也不与NaHCO3反应;NaHCO+ HCl=NaCl+H O+CO②322某学生欲用浓盐酸与大理石反应制取净干燥的二氧化碳气体,实验室提供了下列装置和药品,请回答相关问题:(1)仪器①的名称是________________,仪器②的名称是___________________。

考点05 整式的加减(原卷版)

考点05 整式的加减(原卷版)

考点05 整式的加减(包含三部分:同类项、去括号与添括号、整式的加减)一、同类项1.若单项式212ax y 与–y 5x b +1是同类项,那么a 、b 的值分别是( ) A .a =5,b =1B .a =5,b =2C .a =–5,b =1D .a =–5,b =22.(陕西省榆林市清涧县2019–2020学年七年级上学期期末数学试题)若单项式||58m x y 和2nx y -是同类项,则21m n ++=( ) A .11B .10C .8D .43.(辽宁省大连市庄河市2019–2020学年七年级上学期期末数学试题)下列各式中是同类项的是( ) A .2ab -和2abc B .3x y 和23xy C .mn 和nm -D .a 和b4.(湖南省怀化市鹤城区2019–2020学年七年级上学期期末数学试题)已知-25a 2m b 和7b 3-n a 4是同类项,则m +n 的值是( ) A .2B .3C .4D .65.(福建省三明市宁化县2019–2020学年七年级上学期期末数学试题)下列各组式子中,是同类项的是( )A .23a b 与23ab -B .3a 与23aC .3ab 与2ba -D .3ab 与3bc6.(湖南省长沙市天心区长郡教育集团2019–2020学年七年级上学期期末数学试题)下列各组单项式中,不是同类项的是( )A .24a y 与223yaB .313xy 与313xy - C .22abx 与223x ba D .27a n 与29an - 7.(广西钦州市2019–2020学年七年级下学期期末数学试题)已知24a b x y 与33b ax y 是同类项,则a b +的值为( ) A .1-B .0C .1D .28.(山东省德州市夏津县第二实验中学2020–2021学年七年级上学期10月月考数学试题)下列各式中,不是同类项的是( ) A .–2019和2020B .a 和πC .–4x 3y 2和5x 3y 2D .a 2b 和–3ba 29.(河北省衡水市饶阳县2019–2020学年七年级上学期期末数学试题)下列各组单项式中为同类项的是( )A .3a 与2aB .2020与2019C .2xy 与2xD .2a b 与23b a10.(重庆市第二十九中学校2019–2020学年七年级上学期期中数学试题)式子x m y 2与x 3y n 是同类项,则m +n =( ) A .6B .5C .4D .311.(河南省三门峡市渑池县2019–2020学年七年级上学期期末数学试题)下列各组式子中,不是同类项的是( ) A .ab -与baB .π与25C .20.2a b 与215ba - D .23a b 与23b a -12.(四川省遂宁市射洪中学外国语实验学校2019–2020学年七年级上学期期中数学试题)下列各组中,不是同类项的是( ) A .2R π与2R π B .2x y -与22yx C .xπ与5x πD .53与3513.(山东省德州市夏津县第二实验中学2020–2021学年七年级上学期10月月考数学试题)若–5x m +3y 与2x 4y n +3是同类项,则m +n =____.14.(湖南省岳阳市华容县2019–2020学年七年级上学期期末数学试题)若2y m n -与x m n 是同类项,则x y +=___________.15.(山东省济南市天桥区2019–2020学年七年级上学期期末数学试题)已知32x y a b +与-212x ya b -是同类项,则(x +y )(x -y )=_______16.(福建省漳州市2019–2020学年七年级上学期期末数学试题)如果单项式6m x y 和33yx 是同类项,则m =__________.17.(广东省深圳市宝安区2019–2020学年七年级上学期期末数学试题)若42m xy +-与133n x y -是同类项,则m n +的值是___________18.(黑龙江省哈尔滨市五常市2019–2020学年七年级上学期期末数学试题)若316a x y -和123b x y +-是同类项,则ab =__________.19.(浙江省宁波市镇海区2019–2020学年七年级上学期期末质量检测数学试题)若单项式12m a b -与212na b 是同类项,则n m 的值是______. 20.(新疆2019–2020学年七年级上学期期末数学试题)若213-xy 与252m n x y -+是同类项,则n m -=____.21.(广东省深圳市罗湖区罗湖外语学校初中部2019–2020学年七年级上学期期中数学试题)已知2a m b +4a 2b n =6a 2b ,则m +n 为______.22.(新疆生产建设兵团第六师2019–2020学年七年级上学期期末数学试题)若23x y -与2m n x y 是同类项,则m =_____,n =______;23.若63m x y 和2365n x y --是同类项,则m n +的值是_______24.(福建省泉州市第五中学2019–2020学年七年级上学期期中数学试题)1312x a b -与515y a b +-是同类项,则y x =________25.(陕西省西安市西北工业大学附属中学2019–2020学年七年级上学期期末数学试题)若516m x y 和21n x y +是同类项,那么2m n +的值是________.26.(浙江省绍兴市越城区文澜中学2019–2020学年七年级下学期期中数学试题)若–2a m b 4与5a 3b 2+n 可以合并成一项,则m n =_____.27.单项式3m a n 3与-n -b m 2的和仍是单项式,则a -b =______.28.(湖南省岳阳十中人教版2019–2020学年七年级上学期期末数学试题)已知–3x 1–2a y b +2与7479x y -是同类项,则a b =_____.29.(江西省吉安市峡江县2019–2020学年七年级下学期期末数学试题)若–8x m y 2+5x 3y 2n =–3x 3y 2,则m +n =___________.30.(广东省云浮市郁南县2019–2020学年七年级下学期期末数学试题)已知434m n m x y -与5n x y 是同类项,则m n +的值是_______.31.(广西百色市田东县2019–2020学年七年级上学期期末数学试题)若23m a b 与23nab 是同类项,则12m n -=_______________.32.(重庆市梁平区2019–2020学年七年级下学期期末数学试题)已知562y a b +与22452x ya b --是同类项,则x =______,y =______.33.(北京市通州区2019–2020学年七年级下学期期中数学试题)已知整式2a x +y b 3–a 2b x –y 可以合并,那么代数式(x +y )(x –y )的值是_____.34.(河北省廊坊市三河市2019–2020学年七年级上学期期末数学试题)如果单项式1b xy +-与2312a x y ﹣是同类项,那么()ab -=__________.35.(江苏省常州市兰陵中学2019–2020学年七年级上学期12月月考数学试题)如果单项式0.5ab m –2与–a 3–n b 5是同类项,那么m =_____,n =_____. 36.先化简,再求值,12a 2b –[32a 2b –(3abc –a 2c )+4a 2c ],其中a ,b ,c 满足关于x 、y 的单项式cx 2a +2y 2与–4xy b +4的和为0.二、去括号与添括号2020–2021学年度???学校9月月考卷学校:___________姓名:___________班级:___________考号:___________一、单选题1.(广东省清远市阳山县2019–2020学年七年级上学期期中数学试题)下列去括号错误的是 A .a –(b +c )=a –b –c B .a +(b –c )=a +b –c C .2(a –b )=2a –bD .–(a –2b )=–a +2b2.(广东省深圳市罗湖区罗湖外语学校初中部2019–2020学年七年级上学期期中数学试题)下列各式从左到右正确的是( ) A .-(3x +2)=-3x +2 B .-(-2x -7)=-2x +7 C .-(3x -2)=3x +2D .-(-2x -7)=2x +73.(河北省邢台市南宫市2019–2020学年七年级上学期期末数学试题)下列整式中,去括号后得a –b +c 的是( ) A .a –(b +c ) B .–(a –b )+c C .–a –(b +c )D .a –(b –c )4.(福建省泉州市第五中学2019–2020学年七年级上学期期中数学试题)下列去括号正确的是( ) A .()a b c a b c +-=++B .()a b c a b c --=--C .()a b c a b c --=-+D .()a b c a b c +-=-+5.(广东省深圳市南山区南山区第二外国语学校2019–2020学年七年级上学期期中数学试题)已知3,2a b c d -=+=,则()()a c b d +--的值是()A .–1B .1C .–5D .56.(四川省遂宁市射洪中学外国语实验学校2019–2020学年七年级上学期第三次月考数学试题)去括号()a b c d -+-后的结果是( )A .a b c d -+-B .a b c d ---C .a b c d ++-D .a b c d --+7.下列去括号正确的是( ) A .a +(-3b +2c -d )=a -3b +2c -d B .-(-x 2+y 2)=-x 2-y 2 C .a 2-(2a -b +c )=a 2-2a -b +cD .a -2(b -c )=a +2b -c8.(甘肃省张掖市高台县南华初级中学2019—2020学年七年级上学期期中数学试题)下列各式与2x -(-3y -4z )相等的是( ) A .2x +(-3y +4z ) B .2x +(3y +4z ) C .2x +(3y -4z )D .2x +(-3y -4z )9.(广西贺州市平桂区2019–2020学年七年级上学期期中数学试题)下列各式中,去括号或添括号正确的是( )A .()22a b c a b c -+=-+B .(1)1a b c a b c ---=++-C .()22a x y a x y -+=+--D .()()x a y b x y a b -+-=+--10.(广东省汕尾市2019–2020学年七年级下学期期末数学试题)下列整式的运算中,正确的是( ) A .33x x += B .2(3)62a a --=-+ C .325a a a +=D .3232a a a -=11.(重庆市璧山区2019–2020学年七年级上学期期中数学试题)下列去括号正确的是( ) A .a –(b –c )=a –b –c B .x 2–[–(–x +y )]=x 2–x +y C .m –2(p –q )=m –2p +qD .a +(b –c –2d )=a +b –c +2d12.下列式子正确的是( ) A .x–(y–z )=x–y–z B .–(x–y+z )=–x–y–zC .x+2y –2z=x –2(z+y )D .–a+b+c+d=–(a–b )–(–c–d )13.(甘肃省金昌市金川总校第五中学2019–2020学年八年级上学期期中1–6班数学试题)下列变形正确的是( ) A .a +b –c =a –(b –c )B .a +b +c =a –(b +c )C .a –b +c –d =a –(b –c +d )D .a –b +c –d =(a –b )–(c –d )14.下列等式:(1)-a -b =-(a -b ),(2)-a +b =-(-b +a ),(3)4-3x =-(3x -4),(4)5(6-x )=30-x ,其中一定成立的等式的个数是( ) A .1个B .2个C .3个D .4个15.(广东省汕头市龙湖区2019–2020学年八年级上学期期末数学试题)下列添括号正确的是( ) A .()x y x y +=-- B .()x y x y -=-+ C .()x y x y -+=--D .()x y x y --=--16.(四川省遂宁市射洪中学外国语实验学校2019–2020学年七年级上学期第三次月考数学试题)3222(3)y xy x y -+-–232()xy y -17.(重庆市第二十九中学校2019–2020学年七年级上学期期中数学试题)合并同类项: (1)(2xy –y )–(–y +xy );(2)(3a 2–ab +7)–2(–4a 2+2ab +7).18.(四川省渠县第四中学2019–2020学年七年级上学期期中数学试题)观察下列各式:(1)-a +b =-(a -b );(2)2-3x =-(3x -2);(3)5x +30=5(x +6);(4)-x -6=-(x +6).探索以上四个式子中括号的变化情况,思考它和去括号法则有什么不同?利用你探索出来的规律,解答下面的题目: 已知a 2+b 2=5,1-b =-2,求-1+a 2+b +b 2的值.19.(上海市静安区实验中学七年级上学期沪教版五四制第九章第2节整式的加减)添括号:32312523x x x x (_________);a b c a b c[b +(_________)][b –(_________)];20.(2020年广东省东莞市可园中学中考数学二模试题)如果m –n =3,那么2m –2n –3的值是_____. 21.(2020年山东省济宁市任城区九年级中考三模数学试题)若2a b +=,则代数式322a b --=.三、整式的加减1.老师在黑板上书写了一个正确的演算过程,随后用手掌捂住了一个多项式,形式如()2222153x x x x --+=-+-,则所捂住的多项式是_____.2.(山东省德州市夏津县第二实验中学2020–2021学年七年级上学期10月月考数学试题)先化简,再求值:–a 2b +(3ab 2–a 2b )–2(2ab 2–a 2b ),其中a =1,b =–2.3.(广东省佛山市顺德区杏坛中学2019–2020学年七年级下学期6月月考数学试题)先化简,再求值:[(x +y )2+y (2x –y )–8xy ]÷2x ,其中x =2,y =–1.4.先化简再求值:(1)22113124323x x y x y ⎛⎫⎛⎫--+-+⎪ ⎪⎝⎭⎝⎭,其中32x =,2y =-;(2)()()2222222232x x xy yxxy y +--+--+,其中2x =,12y. 5.已知A –B =7a 2–7ab ,且B =–4a 2+6ab +7. (1)求A 等于多少?(2)若|a +1|+(b –2)2=0,求A 的值.6.小郑在一次测验中计算一个多项式A 减去5xy −3yz +2xz 时,不小心看成加5xy −3yz +2xz ,计算出错误结果为2xy +6yz −4xz ,试求出原题目中的正确结果是多少.7.(广东省佛山市顺德区2019–2020学年七年级上学期期末数学试题)已知A =3x 2+x +2,B =–3x 2+9x +6.(1)求2A –13B ; (2)若2A –13B 与32C -互为相反数,求C 的表达式;(3)在(2)的条件下,若x =2是C =2x +7a 的解,求a 的值.8.(辽宁省大连市甘井子区2019–2020学年七年级上学期期末数学试题)化简,并求值:233A x =-,21312B x x =--,当12x =-时,求2A B -的值. 9.(重庆市沙坪坝区第八中学校2019-2020学年七年级上学期期末数学试题)先化简,再求值 (1)()223421332a a a a -+-+-,其中23a =- (2)()()22352542m mn mn m -+--+,其中22m mn -=10.(江西省赣州市寻乌县2019–2020学年七年级上学期期末数学试题)已知a 是绝对值等于1的负数,b 是最小的正整数,c 的倒数是2,求:2323234[2(54)]a b abc a b abc a b -+--11.(广东省梅州市大埔县2019–2020学年七年级下学期期末数学试题) 先化简,再求值.22(2)(2)24xy xy x y xy ⎡⎤+--+÷⎣⎦,其中2x =,12y12.先化简,再求值:22773212x y xy xy x y xy ⎡⎤⎛⎫---++ ⎪⎢⎥⎝⎭⎣⎦,其中7x =,17y =. 13.(内蒙古乌兰察布市凉城县2019–2020学年七年级上学期期末数学试题)(1)已知22231A x xy y B xxy =++-=-,,若()2230x y ++-=,求2A B -的值;(2)已知多项式与2212x my +-多项式236nx y -+的差中不含有2,x y ,求m n mn ++的值.14.(河北省邢台市南宫市2019–2020学年七年级上学期期末数学试题)已知代数式A=x2+3xy+x–12,B =2x2–xy+4y–1(1)当x=y=–2时,求2A–B的值;(2)若2A–B的值与y的取值无关,求x的值.。

2020-2021学年深圳市第二外国语学校高三英语第一次联考试题及答案解析

2020-2021学年深圳市第二外国语学校高三英语第一次联考试题及答案解析

2020-2021学年深圳市第二外国语学校高三英语第一次联考试题及答案解析第一部分阅读(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的A、B、C、D四个选项中选出最佳选项AConservation Volunteering in New ZealandWhether you are a student, professional or a retiree (退休者), anyone is welcome to make a difference and contribute to protecting some of the most beautiful islands in the world. Choose a suitable city and travelout to your conservation (保护) site to work with local people!Duration: 1-12 weeks Dates: Throughout the yearArrival day: Friday Return day: FridayRequirement: General level of fitness Age: 18+What will I be doing?Volunteer in New Zealand and enjoy conserving the environment through activities such as:·Tree planting·Walking trail construction·Protect native birds, insects, fish and penguins·Seed collection·Weed controlYou, and a group of up to 10 volunteers, will work under the guidance of a conservation team leader. Your team leader will give you regular safety instructions, inform you of the project aims and assist you with working effectively.No previous experience is necessary to join the project. All you need is a love of the environment and a fairly good level of fitness to help out!1.Who can sign up for this conservation volunteering project?A.A retired maths teacher.B.A primary school student.C.A scientist with heart disease.D.A businessman in a wheelchair.2.What can you do on the volunteer trip?A.Protect cultural sites and go shopping.B.Enjoy local sightseeing and go fishing.C.Protect weeds and build roads.D.Collect seeds and plant trees.3.From which is the text probably taken?A.A history book.B.A travel magazine.C.A research paper.D.A novel.BBeing an Olympian (奥运会选手) demands focus, determination, and a competitive spirit. Plus, representing your country is a lot of pressure. However, two athletes recently showed the world another quality that is definitely worth championing.Qatar's Mutaz Essa Barshim and Italy's Gianmarco Tamberi were competing in the high jump on Sunday when they reached a stalemate (僵局). Both men had managed to jump over a surprising 2.37 meters with no faults along the way. However, after three attempts neither managed the next level of 2.39 meters.An Olympic official suggested ajump-offbetween the two friends and rivals (竞争对手) to determine who would get the gold medal. But Barshim had another plan to reward their efforts.“Can we have two golds?” he asked the official.The official agreed and the two men jumped for joy. This was the first time a gold medal had been shared since 1912. “He is one of my best friends, not only on the track, but outside the track. We work together. This is a dream come true.” shared Barshim.The decision to share the medal was particularly meaningful to Tamberi. The Italian had suffered an ankle injury that prevented him from competing in the Rio Olympics in 2016, and it nearly put an end to his career altogether. So this year he brought along his cast to this year's Olympics with “Road to Tokyo 2021” to inspire him along the way.For Barshim, the gold has topped off his already impressive medal collection, having received a bronze and a silver medal in 2012 and 2016 respectively.Despite all the glory of receiving a gold medal for their countries, their achievement means so much more. These two individuals, trying to do their very best for their countries, have provided a wonderful example to all those competing in sports. They've summed up exactly what it means to take part in a global event with a generous and compassionate (有同情心的) spirit.4. What happened to Barshim and Tamberi in the competition?A. They ended in a tie.B. They quit the competition.C. They set a new record.D. They ran out of strength.5. What does the underlined word “jump-off” in Paragraph 3 refer to?A. Debate.B. Vote.C. Celebration.D. Extra round.6. Why was the gold medal particularly meaningful to Tamberi?A. It could bring him a lot of money.B. It may make up for his regret in 2016.C. It was a glory for his country.D. It could complete his medal collection.7. What does the author mainly want to convey in the text?A. The importance of sharing.B. The glory of winning gold medals.C. The valuable and special team spirit.D. The considerate and sharing Olympic spirit.CIf you’re looking for a reason to care about tree loss, this summer’s record-breaking heat waves might be it. Trees can lower summer daytime temperatures by as much as 10 degrees Fahrenheit, according to arecent study. But tree cover in US cities is shrinking (缩减). A study published last year by the US Forest Service found that we lost 36 million trees annually from urban and rural communities over a five-year period. “If we continue on this path, cities will become warmer, more polluted and generally unhealthier for inhabitants,” said David Nowak, a senior US Forest Service scientist and co-author of the study. Nowak says there are many reasons why our tree cover is declining, including hurricanes, tornadoes, fires, insects and disease. But the one reason for tree loss that humans can control is sensible development.Nowak says there is a downside to trees too, such as pollen allergy (花粉过敏) or large tailing branches in storms, and people don’t like sweeping leaves. But, he says, there are ways cities and counties can manage trees to help communities thrive (繁荣). Urban forests especially need our help to replace fallen trees. Unlike rural areas, it is very difficult for trees to repopulate themselves in a city environment with so much pavement and asphalt (沥青). “A lot of our native trees can’t actually find a place to drop a seed so they can regenerate,” explains Greg Levine, co-executivedirector of Trees Atlanta. “That’s why the community has to go in and actually plant a tree because the areas just aren’t natural anymore.”Nowak says the first step is caring for the trees on your own property (财产). “We think we pay for our house,and sowe must maintain it. But because we don’t pay for nature, we don’t need to. And that’s not necessarily true.”8. Why does the author mention “trees can lower summer daytime temperatures”?A. To tell the temperatures in summer are high.B. To explain the reason of tree loss.C. To tell trees are helpful.D. To introduce the topic.9. How can humans control tree loss according to Nowak?A. Develop cities in reasonable ways.B. Prevent fires form damaging trees.C. Improve climate to let trees grow.D. Decrease insects in cities.10. Why do forests in cities need our help?A. Because trees don’t grow in a city environment.B. Because native trees don’t drop seeds any more.C. Because trees in urban areas can’t regenerate naturally.D. Because humans want to plant more trees.11. What is the purpose of this passage?A. Describe the importance of trees in cities.B. Appeal people to protect trees in their surroundings.C. Ask people to plant trees with the author.D. Show the number of trees in theUSis declining.DPopularization has in some cases changed the original meaning of emotional (情感的) intelligence. Many people now misunderstand emotional intelligence as almost everything desirable in a person's makeup that cannotbe measured by an IQ test, such as character, motivation, confidence, mental stability, optimism and “people skills.” Research has shown that emotional skills may contribute to some of these qualities, but most of them move far beyond skill-based emotional intelligence.We prefer to describe emotional intelligence as a specific set of skills that can be used for either good or bad purposes. The ability to accurately understand how others are feeling may be used by a doctor to find how best tohelp her patients, while a cheater might use it to control potential victims. Being emotionally intelligent does not necessarily make one a moral person.Although popular beliefs regarding emotional intelligence run far ahead of what research can reasonably support, the overall effects of the publicity have been more beneficial than harmful. The most positive aspect of this popularization is a new and much needed emphasis (重视) on emotion by employers, educators and others interested in promoting social well-being. The popularization of emotional intelligence has helped both the public and researchers re-evaluate the functionality of emotions and how they serve people adaptively in everyday life.Although the continuing popular appeal of emotional intelligence is desirable, we hope that such attention will excite a greater interest in the scientific and scholarly study of emotion. It is our hope that in coming decades, advances in science will offer new perspectives (视角) from which to study how people manage their lives. Emotional intelligence, with its focus on both head and heart, may serve to point us in the right direction.12. What is a common misunderstanding of emotional intelligence?A. It can be measured by anIQ test.B. It helps to exercise a person’s mind.C. It includes a set of emotional skills.D. It refers to a person’s positive qualities.13. Why does the author mention “doctor” and “cheater” in paragraph 2?A. To explain a rule.B. To clarify a concept.C. To present a fact.D. To make a prediction.14. What is the author’s attitude to the popularization of emotional intelligence?A. Favorable.B. Intolerant.C. Doubtful.D. Unclear.15. What does the last paragraph mainly talk about concerning emotional intelligence?A. Its appeal to the public.B. Expectations for future studies.C. Its practical application.D. Scientists with new perspectives.第二节(共5小题;每小题2分,满分10分)阅读下面短文,从短文后的选项中选出可以填入空白处的最佳选项。

2020-2021学年广东省深圳市九年级上 学期期中考试英语试题(含答案)

2020-2021学年广东省深圳市九年级上 学期期中考试英语试题(含答案)

2020-2021学年初三上期中英语试题英语科试卷本试卷满分90分注意事项:1. 答卷前,考生务必在答题卡上用黑色字迹的钢笔或签字笔填写自己的考生号、姓名,并用2B铅笔把考生号在答题卡上涂黑,在答题卷上填写自己的考生号、姓名、试室号、座位号。

2. 选择题每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

如需要改动,用橡皮擦干净后,再选涂其他答案。

3. 非选择题必须用黑色字迹的钢笔或签字笔作答,答案必须写在答题卡各题目指定区域的相应位置上;如需要改动,先划掉原来的答案,然后再写上新的答案,改动的答案也不能超出指定的区域;不准使用铅笔、圆珠笔和涂改液。

不按以上要求作答的答案无效。

4. 考生必须保持答题卡的整洁,考试结束,将本试卷答卷和答题卡一并交回。

一、语法选择(共15小题;每小题1分,满分15分)阅读下面短文,按照句子结构的语法性和上下文连贯的要求,从各题所给的A、B、C和D项中,选出最佳选项。

I have received many Christmas gifts over the years. The best gift I have received was presented to me ___1___ a stranger. I have never even known his name and I only had a contact with him___2___ less than 60 seconds. His Christmas present to me changed ___3___ way I think about people and about Christmas.I hate Black Friday sales. It’s often a gathering of people ___4___ are there for many different reasons. Some are looking for one item for their loved one, or perhaps themselves. Their purposes completely have ___5___ to do with the festive time of year, and can just be summed up with one word, “cheap!”It was several years ago when my wife asked me___6___ her at the local department store on Black Friday morning. They had advertised a child’s bike ___7___ she wanted to buy for our son. We stood with a very large crowd, waiting for the manger to blow the whistle. I told my wife ___8___ we got a bike, fine, but if we did not, I was OK with that too.As ___9___ bikes began to gradually decrease, I saw my “polite” opportunity to reach my hands around the corner of one of the boxes. I ___10___ it and suddenly felt some mild resistance. I looked up to see one of ___11___ gentleman I had ever seen in my life. Frightening was not the word to describe his appearance. He was wearing lots of metal spiked leather around ___12___ arms and even his neck and he had tattoos too.I started to return the box ___13___ he gently pushed it back in my direction and back into my hands. He then directed it into my shopping car. He looked at me, smiled, and said, “Merry Christmas.” All the way home I ___14___ that this moment was by far the best Christmas gift I had ever received. The kindness of a stranger that broke all prejudice I may have had of certain types of people. The softness of a human heart can be seen in a simple act. I will never ___15___ it.1. A. with B. by C. about D. to2. A. in B. at C. on D. for3. A. a B. an C. the D. /4. A. who B. whom C. whose D. which5. A. something B. anything C. nothing D. everything6. A. meeting B. to meet C. met D. meet7. A. that B. who C. why D. what8. A. whether B. when C. if D. how9. A. the number of B. a number of C. numbers of D. an amount of10. A. lift B. lifted C. has lifted D. was lifting11. A. large B. larger C. largest D. the largest12. A. every B. each C. both D. all13. A. but B. or C. though D. and14. A. have thought B. was thinking C. am thinking D. think15. A. forgetting B. forgotten C. forget D. forgot二、完形填空(共10小题;每小题1分,满分10分)阅读下面短文,掌握其大意,然后从16~25各题所给的A、B、C和D项中,选出最佳选项,并在答题卡上将该项涂黑。

深圳市2020-2021学年度第一学期期中适应性考试语文试题

深圳市2020-2021学年度第一学期期中适应性考试语文试题

绝注一自但节不13字形自 强绝密★启用前 深圳注意事项:1.答卷前2.请按照题目指不准使3.考生必一、基础(27本学期,学“自强不息自身本性运行,但是中国人树立何谓自强?节,在危难面前不 ⑤ 。

自强.请你根据拼① 2.请你结合语A .见风使③ .请你根据提形 字源 圳市2020-本试卷共8页前,考生务必将照要求答题,必指定区域内相应使用涂改液。

不必须保证答题卡分)学校开展了“息”出自《周易,刚健有力,永立的自身理想,?自强是直面困前,不委曲求全强不息的真谛就拼音,写出相应语境,将正确的使舵提示,完成下列 “自”是“鼻人们习惯手指“自”(即鼻 篆文(弘表示动物发出(qiánɡ)或 -2021学年九年级语页,24题,满将自己的姓名、必须用黑色字迹应位置上;如需不按以上要求作卡的整洁。

考试自强不息”综易》“天行健,永不停息。

君子,却和“厚德困苦的意志,在全,不 ④ ;就是:脚踏实应的汉字。

(2 的选项写到相应 列表格。

(2分字源之义鼻”的本字,甲指本人鼻部位置鼻子)渐渐成了弘,声音大)出的巨大声音。

或迫使,尽力( 年度第一学期语文学科试满分120分,考、考生号、考迹的钢笔或签需改动,先划掉作答,视为无效试结束后,将综合性学习活动,君子以自强不子也应发挥主德载物”一起构在艰难面前不灰;自强是名利之实地地做好分内分)应的横线上。

B .妄自菲薄 ④ 分)义甲骨文像人的鼻置表达自己,于了第一人称。

(虫,爬行动。

引申义为力量(qiǎnɡ)。

期期中适应试题 考试用时120分考场号和座位号签字笔作答,答掉原来的答案,效。

将答题卡交回。

动,请根据要求不息”。

古人认主动性,勤勉不构成中华民族精灰心丧气,不 之外的坦荡,不内的每一件事。

② (3分)词性鼻子,于是⑥ 动物),量大的形容词副词 试卷类应性考试2分钟。

号填写在答题卡答案必须写在答,然后再写上新。

求完成1~6题认为,天体①k不懈,奋发进取精神的基本品格③ ;自强是不②jiǎo róu zà。

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