高级中学 2015-2016 学年第二学期期末测试
2020年高考生物原创专题卷:《遗传的基本规律》
原创生物专题卷专题遗传的基本规律考点28 基因的分离定律及其应用 5颗星(1-10题,31题)考点29 基因的自由组合定律及其应用 5颗星(11-22题,32题)考点30 自由组合定律的变式 3颗星(23-30题,33题)考试时间:90分钟满分:90分说明:请将选择题正确答案填写在答题卡上,主观题写在答题纸上第I卷(选择题)一、选择题(本题共30小题,每小题2分,共60分。
在每小题给出的四个选项中,只有一项是最符合题目要求的。
)1.【来源】2016-2017学年福建省龙岩市一级达标校高二上学期期末考点28 易下列有关一对相对性状遗传的叙述,错误的是()A. 通过测交可以推测被测个体产生配子的种类和比例B. 自交可用于鉴别和保留纯合的抗锈病(显性)小麦C. 能说明基因分离定律实质的是F2的表现型比为3:1D. 在一个种群中,若仅考虑一对等位基因,可有6种不同的交配类型2.【来源】2016-2017学年江苏省南京市高二学业水平第一次模拟考点28 易下列测交或自交的组合中,叙述正确的是()A. 纯合子测交后代都是纯合子B. 纯合子自交后代都是纯合子C. 杂合子自交后代都是杂合子D. 杂合子测交后代都是杂合子3.【来源】2015-2016学年江苏省海安高级中学高二下学期学业测试考点28 易鼠的黄色和黑色是一对相对性状,按基因的分离定律遗传。
研究发现,多对黄鼠交配,后代中总会出现约1/3的黑鼠,其余均为黄鼠。
由此推断合理的是()A. 鼠的黑色性状由显性基因控制B. 后代黄鼠中既有杂合子又有纯合子C. 老鼠体色的遗传不遵守孟德尔遗传定律D. 黄鼠与黑鼠交配,后代中黄鼠约占1/24.【来源】2016-2017学年安徽省安庆市高二上学期期末考点28 中难下列一对亲本杂交的实验中,能判定紫花和白花显隐关系的是()①紫花×紫花——紫花②紫花×紫花——301紫花+110白花③紫花×白花——紫花④紫花×白花——98紫花+107白花A. ①和②B. ②和③C. ③和④D. ①和④5.【来源】山东省德州市2017届高三第一次模拟考试理综考点28 中难果蝇的有眼(E)对无眼(e)为显性,E、e基因位于Ⅳ号常染色体上。
杭州高级中学2015-2016学年高一新生分班模拟考试数学试题(解析版)
浙江省杭州高级中学2015-2016学年高一新生分班模拟考试数学试题一、选择题:本大题共8个小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.下列结论正确的是()A.3a2b﹣a2b=2B.单项式﹣x2的系数是﹣1C.使式子有意义的x的取值范围是x>﹣2D.若分式的值等于0,则a=±12.在下列艺术字中既是轴对称图形又是中心对称图形的是()A.B.C.D.3.如图所示,将正方形纸片三次对折后,沿图中AB线剪掉一个等腰直角三角形,展开铺平得到的图形是()A.B.C.D.4.今年,我省启动了“关爱留守儿童工程”.某村小为了了解各年级留守儿童的数量,对一到六年级留守儿童数量进行了统计,得到每个年级的留守儿童人数分别为10,15,10,17,18,20.对于这组数据,下列说法错误的是()A.平均数是15 B.众数是10 C.中位数是17 D.方差是5.如图,A、B、C三点在正方形网格线的交点处,若将△ABC绕着点A逆时针旋转得到△AC′B′,则tanB′的值为()A.B.C.D.6.如图是自行车骑行训练场地的一部分,半圆O的直径AB=100,在半圆弧上有一运动员C 从B点沿半圆周匀速运动到M(最高点),此时由于自行车故障原地停留了一段时间,修理好继续以相同的速度运动到A点停止.设运动时间为t,点B到直线OC的距离为d,则下列图象能大致刻画d与t之间的关系是()A.B.C.D.7.如图,在平面直角坐标系中,直线y=﹣3x+3与x轴、y轴分别交于A、B两点,以AB为边在第一象限作正方形ABCD,点D在双曲线(k≠0)上.将正方形沿x轴负方向平移a个单位长度后,点C恰好落在该双曲线上,则a的值是()A.1 B.2 C.3 D.48.如图,分别过点P i(i,0)(i=1、2、…、n)作x轴的垂线,交的图象于点A i,交直线于点B i.则的值为()A.B.2 C.D.二、填空题9.如图,AB=AC,∠BAC=120°,AB的垂直平分线交BC于点D,那么∠ADC=度.10.定义新运算“*”规则:a*b=,如1*2=2,*=,若x2+x﹣1=0两根为x1,x2,则x1*x2=.11.二次函数y=ax2+bx+c(a≠0)的图象如图所示,对称轴为x=1,给出下列结论:①abc >0;②b2=4ac;③4a+2b+c>0;④3a+c>0,其中正确的结论是.(写出正确命题的序号)12.已知两个正数a,b,可按规则c=ab+a+b扩充为一个新数c在a,b,c三个数中取两个较大的数,按上述规则扩充得到一个新数,依次下去,将每扩充一次得到一个新数称为一次操作,(1)若a=1,b=3,按上述规则操作三次,扩充所得的数是;(2)若p>q>0,经过6次操作后扩充所得的数为(q+1)m(p+1)n﹣1(m,n为正整数),则m+n的值为.三、解答题(本大题共5小题,共60分.解答应写出文字说明、证明过程或演算步骤.)13.先化简,再求值:( +)÷,其中a=﹣1.(2)已知关于x,y的二元一次方程的解满足x<y,求m的取值范围.14.2015年1月,市教育局在全市中小学中选取了63所学校从学生的思想品德、学业水平、学业负担、身心发展和兴趣特长五个维度进行了综合评价.评价小组在选取的某中学七年级全体学生中随机抽取了若干名学生进行问卷调查,了解他们每天在课外用于学习的时间,并绘制成如下不完整的统计图.根据上述信息,解答下列问题:(1)本次抽取的学生人数是;扇形统计图中的圆心角α等于;补全统计直方图;(2)被抽取的学生还要进行一次50米跑测试,每5人一组进行.在随机分组时,小红、小花两名女生被分到同一个小组,请用列表法或画树状图求出她俩在抽道次时抽在相邻两道的概率.15.已知,如图,AB是⊙O的直径,点C为⊙O上一点,OF⊥BC于点F,交⊙O于点E,AE与BC交于点H,点D为OE的延长线上一点,且∠ODB=∠AEC.(1)求证:BD是⊙O的切线;(2)求证:CE2=EH•EA;(3)若⊙O的半径为5,sinA=,求BH的长.16.大学毕业生小王响应国家“自主创业”的号召,利用银行小额无息贷款开办了一家饰品店.该店购进一种今年新上市的饰品进行销售,饰品的进价为每件40元,售价为每件60元,每月可卖出300件.市场调查反映:调整价格时,售价每涨1元每月要少卖10件;售价每下降1元每月要多卖20件.为了获得更大的利润,现将饰品售价调整为60+x(元/件)(x>0即售价上涨,x<0即售价下降),每月饰品销量为y(件),月利润为w(元).(1)直接写出y与x之间的函数关系式;(2)如何确定销售价格才能使月利润最大?求最大月利润;(3)为了使每月利润不少于6000元应如何控制销售价格?17.如图,把两个全等的Rt△AOB和Rt△COD分别置于平面直角坐标系中,使直角边OB、OD在x轴上.已知点A(1,2),过A、C两点的直线分别交x轴、y轴于点E、F.抛物线y=ax2+bx+c经过O、A、C三点.(1)求该抛物线的函数解析式;(2)点P为线段OC上一个动点,过点P作y轴的平行线交抛物线于点M,交x轴于点N,问是否存在这样的点P,使得四边形ABPM为等腰梯形?若存在,求出此时点P的坐标;若不存在,请说明理由.(3)若△AOB沿AC方向平移(点A始终在线段AC上,且不与点C重合),△AOB在平移过程中与△COD重叠部分面积记为S.试探究S是否存在最大值?若存在,求出这个最大值;若不存在,请说明理由.浙江省杭州高级中学2015-2016学年高一新生分班模拟考试数学试题参考答案与试题解析一、选择题:本大题共8个小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.下列结论正确的是()A.3a2b﹣a2b=2B.单项式﹣x2的系数是﹣1C.使式子有意义的x的取值范围是x>﹣2D.若分式的值等于0,则a=±1【考点】二次根式有意义的条件;合并同类项;分式的值为零的条件.菁优网版权所有【分析】根据二次根式有意义的条件、单项式、合并同类项、分式有意义的条件解答.【解答】解:3a2b﹣a2b=2a2b,A错误;单项式﹣x2的系数是﹣1,B正确;使式子有意义的x的取值范围是x≥﹣2,C错误;若分式的值等于0,则a=1,错误,故选:B.2.在下列艺术字中既是轴对称图形又是中心对称图形的是()A.B.C.D.【考点】中心对称图形;轴对称图形.菁优网版权所有【分析】根据轴对称图形与中心对称图形的概念求解.【解答】解:A、是轴对称图形,不是中心对称图形.故错误;B、是轴对称图形,不是中心对称图形.故错误;C、不是轴对称图形,也不是中心对称图形.故错误;D、是轴对称图形,也是中心对称图形.故正确.故选D.3.如图所示,将正方形纸片三次对折后,沿图中AB线剪掉一个等腰直角三角形,展开铺平得到的图形是()A.B.C.D.【考点】剪纸问题.菁优网版权所有【分析】根据题意直接动手操作得出即可.【解答】解:找一张正方形的纸片,按上述顺序折叠、裁剪,然后展开后得到的图形如图所示:故选A.4.今年,我省启动了“关爱留守儿童工程”.某村小为了了解各年级留守儿童的数量,对一到六年级留守儿童数量进行了统计,得到每个年级的留守儿童人数分别为10,15,10,17,18,20.对于这组数据,下列说法错误的是()A.平均数是15 B.众数是10 C.中位数是17 D.方差是【考点】方差;加权平均数;中位数;众数.菁优网版权所有【分析】根据方差、众数、平均数和中位数的计算公式和定义分别进行解答即可.【解答】解:平均数是:(10+15+10+17+18+20)÷6=15;10出现了2次,出现的次数最多,则众数是10;把这组数据从小到大排列为10,10,15,17,18,20,最中间的数是(15+17)÷2=16,则中位数是16;方差是: [2(10﹣15)2+(15﹣15)2+(17﹣15)2+(18﹣15)2+(20﹣15)2]==.则下列说法错误的是C.故选:C.5.如图,A、B、C三点在正方形网格线的交点处,若将△ABC绕着点A逆时针旋转得到△AC′B′,则tanB′的值为()A.B.C.D.【考点】锐角三角函数的定义;旋转的性质.菁优网版权所有【专题】压轴题.【分析】过C点作CD⊥AB,垂足为D,根据旋转性质可知,∠B′=∠B,把求tanB′的问题,转化为在Rt△BCD中求tanB.【解答】解:过C点作CD⊥AB,垂足为D.根据旋转性质可知,∠B′=∠B.在Rt△BCD中,tanB==,∴tanB′=tanB=.故选B.6.如图是自行车骑行训练场地的一部分,半圆O的直径AB=100,在半圆弧上有一运动员C 从B点沿半圆周匀速运动到M(最高点),此时由于自行车故障原地停留了一段时间,修理好继续以相同的速度运动到A点停止.设运动时间为t,点B到直线OC的距离为d,则下列图象能大致刻画d与t之间的关系是()A.B.C.D.【考点】动点问题的函数图象.菁优网版权所有【专题】压轴题.【分析】设运动员C的速度为v,则运动了t的路程为vt,设∠BOC=α,当点C从运动到M 时,当点C从M运动到A时,分别求出d与t之间的关系即可进行判断.【解答】解:设运动员C的速度为v,则运动了t的路程为vt,设∠BOC=α,当点C从运动到M时,∵vt==,∴α=,在直角三角形中,∵d=50sinα=50sin=50sin t,∴d与t之间的关系d=50sin t,当点C从M运动到A时,d与t之间的关系d=50sin(180﹣t),故选:C.7.如图,在平面直角坐标系中,直线y=﹣3x+3与x轴、y轴分别交于A、B两点,以AB为边在第一象限作正方形ABCD,点D在双曲线(k≠0)上.将正方形沿x轴负方向平移a个单位长度后,点C恰好落在该双曲线上,则a的值是()A.1 B.2 C.3 D.4【考点】反比例函数综合题.菁优网版权所有【分析】作CE⊥y轴于点E,交双曲线于点G.作DF⊥x轴于点F,易证△OAB≌△FDA≌△BEC,求得A、B的坐标,根据全等三角形的性质可以求得C、D的坐标,从而利用待定系数法求得反比例函数的解析式,进而求得G的坐标,则a的值即可求解.【解答】解:作CE⊥y轴于点E,交双曲线于点G.作DF⊥x轴于点F.在y=﹣3x+3中,令x=0,解得:y=3,即B的坐标是(0,3).令y=0,解得:x=1,即A的坐标是(1,0).则OB=3,OA=1.∵∠BAD=90°,∴∠BAO+∠DAF=90°,又∵直角△ABO中,∠BAO+∠OBA=90°,∴∠DAF=∠OBA,∵在△OAB和△FDA中,,∴△OAB≌△FDA(AAS),同理,△OAB≌△FDA≌△BEC,∴AF=OB=EC=3,DF=OA=BE=1,故D的坐标是(4,1),C的坐标是(3,4).代入y=得:k=4,则函数的解析式是:y=.∴OE=4,则C的纵坐标是4,把y=4代入y=得:x=1.即G的坐标是(1,4),∴CG=2.故选:B.8.如图,分别过点P i(i,0)(i=1、2、…、n)作x轴的垂线,交的图象于点A i,交直线于点B i.则的值为()A.B.2 C.D.【考点】二次函数综合题.菁优网版权所有【专题】压轴题;规律型.【分析】根据A i的纵坐标与B i纵坐标的绝对值之和为A i B i的长,分别表示出所求式子的各项,拆项后抵消即可得到结果.【解答】解:根据题意得:A i B i=x2﹣(﹣x)=x(x+1),∴==2(﹣),∴++…+=2(1﹣+﹣+…+﹣)=.故选A二、填空题9.如图,AB=AC,∠BAC=120°,AB的垂直平分线交BC于点D,那么∠ADC=60度.【考点】线段垂直平分线的性质;三角形的外角性质.菁优网版权所有【专题】计算题.【分析】由三角形的外角性质知∠ADC=∠BAD+∠B,又已知∠BAC=120°,根据三角形内角和定理易得∠B,而AB的垂直平分线交BC于点D,根据垂直平分线的性质知∠BAD=∠B,从而得解.【解答】解:由AB=AC,∠BAC=120°,可得∠B=30°,因为点D是AB的垂直平分线上的点,所以AD=BD,因而∠BAD=∠B=30°,从而∠ADC=60度.10.定义新运算“*”规则:a*b=,如1*2=2,*=,若x2+x﹣1=0两根为x1,x2,则x1*x2=.【考点】根与系数的关系.菁优网版权所有【专题】新定义.【分析】根据公式法求得一元二次方程的两个根,然后根据新运算规则计算x1*x2的值则可.【解答】解:在x2+x﹣1=0中,a=1,b=1,c=﹣1,∴b2﹣4ac=5>0,所以x1=,x2=或x1=,x2=,∴x1*x2=*=,故答案为.11.二次函数y=ax2+bx+c(a≠0)的图象如图所示,对称轴为x=1,给出下列结论:①abc >0;②b2=4ac;③4a+2b+c>0;④3a+c>0,其中正确的结论是①④.(写出正确命题的序号)【考点】二次函数图象与系数的关系.菁优网版权所有【分析】根据抛物线开口方向,对称轴的位置,与x轴交点个数,以及x=﹣1,x=2对应y 值的正负判断即可.【解答】解:由二次函数图象开口向上,得到a>0;与y轴交于负半轴,得到c<0,∵对称轴在y轴右侧,且﹣=1,即2a+b=0,∴a与b异号,即b<0,∴abc>0,选项①正确;∵二次函数图象与x轴有两个交点,∴△=b2﹣4ac>0,即b2>4ac,选项②错误;∵原点O与对称轴的对应点为(2,0),∴x=2时,y<0,即4a+2b+c<0,选项③错误;∵x=﹣1时,y>0,∴a﹣b+c>0,把b=﹣2a代入得:3a+c>0,选项④正确,故答案是:①④.12.已知两个正数a,b,可按规则c=ab+a+b扩充为一个新数c在a,b,c三个数中取两个较大的数,按上述规则扩充得到一个新数,依次下去,将每扩充一次得到一个新数称为一次操作,(1)若a=1,b=3,按上述规则操作三次,扩充所得的数是255;(2)若p>q>0,经过6次操作后扩充所得的数为(q+1)m(p+1)n﹣1(m,n为正整数),则m+n的值为21.【考点】推理与论证.菁优网版权所有【分析】(1)a=1,b=3,按规则操作三次,第一次:c=7;第二次c=31;第三次c=255;(2)p>q>0 第一次得:c1=pq+p+q=(q+1)(p+1)﹣1;第二次得:c2=(p+1)2(q+1)﹣1;所得新数大于任意旧数,故经过6次扩充,所得数为:(q+1)8(p+1)13﹣1,故可得结论.【解答】解:(1)a=1,b=3,按规则操作三次,第一次:c=ab+a+b=1×3+1+3=7;第二次,7>3>1所以有:c=3×7+3+7=31;第三次:31>7>3所以有:c=7×31+7+31=255;(2)p>q>0 第一次得:c1=pq+p+q=(q+1)(p+1)﹣1;因为c>p>q,所以第二次得:c2=(c1+1)(p+1)﹣1=(pq+p+q)p+p+(pq+p+q)=(p+1)2(q+1)﹣1;所得新数大于任意旧数,所以第三次可得c3=(c2+1)(c1+1)﹣1=(p+1)3(q+1)2﹣1第四次可得:c4=(c3+1)(c2﹣1)﹣1=(p+1)5(q+1)3﹣1;第五次可得:c5=(p+1)8(q+1)5﹣1;故经过6次扩充,所得数为:(q+1)8(p+1)13﹣1∴m=8,n=13,∴m+n=21.故答案为:255;21.三、解答题(本大题共5小题,共60分.解答应写出文字说明、证明过程或演算步骤.)13.(1)先化简,再求值:( +)÷,其中a=﹣1.(2)已知关于x,y的二元一次方程的解满足x<y,求m的取值范围.【考点】分式的化简求值;二元一次方程组的解;解一元一次不等式.菁优网版权所有【分析】(1)先将括号内通分,计算加法、同时将除法转化为乘法,再约分即可得;(2)先将m看做已知的常数解方程组,再根据x<y得出关于m的不等式,解之可得.【解答】解:(1)原式=[+]•=•=•=,当a=﹣1时,原式==;(2)解方程组得:,∵x<y,∴m﹣<﹣,解得:m<﹣.14.2015年1月,市教育局在全市中小学中选取了63所学校从学生的思想品德、学业水平、学业负担、身心发展和兴趣特长五个维度进行了综合评价.评价小组在选取的某中学七年级全体学生中随机抽取了若干名学生进行问卷调查,了解他们每天在课外用于学习的时间,并绘制成如下不完整的统计图.根据上述信息,解答下列问题:(1)本次抽取的学生人数是30;扇形统计图中的圆心角α等于144°;补全统计直方图;(2)被抽取的学生还要进行一次50米跑测试,每5人一组进行.在随机分组时,小红、小花两名女生被分到同一个小组,请用列表法或画树状图求出她俩在抽道次时抽在相邻两道的概率.【考点】列表法与树状图法;扇形统计图;利用频率估计概率.菁优网版权所有【分析】(1)根据题意列式求值,根据相应数据画图即可;(2)根据题意列表,然后根据表中数据求出概率即可.【解答】解:(1)6÷20%=30,(30﹣3﹣7﹣6﹣2)÷30×360=12÷30×26=144°,答:本次抽取的学生人数是30人;扇形统计图中的圆心角α等于144°;故答案为:30,144°;补全统计图如图所示:(2)根据题意列表如下:设竖列为小红抽取的跑道,横排为小花抽取的跑道,小红小花 1 2 3 4 51 (2,1)(3,1)(4,1)(5,1)2 (1,2)(3,2)(4,2)(5,2)3 (1,3)(2,3)(4,3)(5,3)4 (1,4)(2,4)(3,4)(5,4)5 (1,5)(2,5)(3,5)(4,5)记小红和小花抽在相邻两道这个事件为A,∴.15.已知,如图,AB是⊙O的直径,点C为⊙O上一点,OF⊥BC于点F,交⊙O于点E,AE与BC交于点H,点D为OE的延长线上一点,且∠ODB=∠AEC.(1)求证:BD是⊙O的切线;(2)求证:CE2=EH•EA;(3)若⊙O的半径为5,sinA=,求BH的长.【考点】圆的综合题.菁优网版权所有【专题】证明题.【分析】(1)由圆周角定理和已知条件证出∠ODB=∠ABC,再证出∠ABC+∠DBF=90°,即∠OBD=90°,即可得出BD是⊙O的切线;(2)连接AC,由垂径定理得出,得出∠CAE=∠ECB,再由公共角∠CEA=∠HEC,证明△CEH∽△AEC,得出对应边成比例,即可得出结论;(3)连接BE,由圆周角定理得出∠AEB=90°,由三角函数求出BE,再根据勾股定理求出EA,得出BE=CE=6,由(2)的结论求出EH,然后根据勾股定理求出BH即可.【解答】(1)证明:∵∠ODB=∠AEC,∠AEC=∠ABC,∴∠ODB=∠ABC,∵OF⊥BC,∴∠BFD=90°,∴∠ODB+∠DBF=90°,∴∠ABC+∠DBF=90°,即∠OBD=90°,∴BD⊥OB,∴BD是⊙O的切线;(2)证明:连接AC,如图1所示:∵OF⊥BC,∴,∴∠CAE=∠ECB,∵∠CEA=∠HEC,∴△CEH∽△AEC,∴,∴CE2=EH•EA;(3)解:连接BE,如图2所示:∵AB是⊙O的直径,∴∠AEB=90°,∵⊙O的半径为5,sin∠BAE=,∴AB=10,BE=AB•sin∠BAE=10×=6,∴EA===8,∵,∴BE=CE=6,∵CE2=EH•EA,∴EH==,在Rt△BEH中,BH===.16.大学毕业生小王响应国家“自主创业”的号召,利用银行小额无息贷款开办了一家饰品店.该店购进一种今年新上市的饰品进行销售,饰品的进价为每件40元,售价为每件60元,每月可卖出300件.市场调查反映:调整价格时,售价每涨1元每月要少卖10件;售价每下降1元每月要多卖20件.为了获得更大的利润,现将饰品售价调整为60+x(元/件)(x>0即售价上涨,x<0即售价下降),每月饰品销量为y(件),月利润为w(元).(1)直接写出y与x之间的函数关系式;(2)如何确定销售价格才能使月利润最大?求最大月利润;(3)为了使每月利润不少于6000元应如何控制销售价格?【考点】二次函数的应用.菁优网版权所有【分析】(1)直接根据题意售价每涨1元每月要少卖10件;售价每下降1元每月要多卖20件,进而得出等量关系;(2)利用每件利润×销量=总利润,进而利用配方法求出即可;(3)利用函数图象结合一元二次方程的解法得出符合题意的答案.【解答】解:(1)由题意可得:y=;(2)由题意可得:w=,化简得:w=,即w=,由题意可知x应取整数,故当x=﹣2或x=﹣3时,w<6125,x=5时,W=6250,故当销售价格为65元时,利润最大,最大利润为6250元;(3)由题意w≥6000,如图,令w=6000,将w=6000带入﹣20≤x<0时对应的抛物线方程,即6000=﹣20(x+)2+6125,解得:x1=﹣5,将w=6000带入0≤x≤30时对应的抛物线方程,即6000=﹣10(x﹣5)2+6250,解得x2=0,x3=10,综上可得,﹣5≤x≤10,故将销售价格控制在55元到70元之间(含55元和70元)才能使每月利润不少于6000元.17.如图,把两个全等的Rt△AOB和Rt△COD分别置于平面直角坐标系中,使直角边OB、OD在x轴上.已知点A(1,2),过A、C两点的直线分别交x轴、y轴于点E、F.抛物线y=ax2+bx+c经过O、A、C三点.(1)求该抛物线的函数解析式;(2)点P为线段OC上一个动点,过点P作y轴的平行线交抛物线于点M,交x轴于点N,问是否存在这样的点P,使得四边形ABPM为等腰梯形?若存在,求出此时点P的坐标;若不存在,请说明理由.(3)若△AOB沿AC方向平移(点A始终在线段AC上,且不与点C重合),△AOB在平移过程中与△COD重叠部分面积记为S.试探究S是否存在最大值?若存在,求出这个最大值;若不存在,请说明理由.【考点】二次函数综合题.菁优网版权所有【专题】压轴题.【分析】方法一:(1)抛物线y=ax2+bx+c经过点O、A、C,利用待定系数法求抛物线的解析式;(2)根据等腰梯形的性质,确定相关点的坐标以及线段长度的数量关系,得到一元二次方程,求出t的值,从而可解.结论:存在点P(,),使得四边形ABPM为等腰梯形;(3)本问关键是求得重叠部分面积S的表达式,然后利用二次函数的极值求得S的最大值.解答中提供了三种求解面积S表达式的方法,殊途同归,可仔细体味.方法二:(1)略.(2)因为四边形ABPM为等腰梯形,只需AM=BP,且AM与BP不平行,利用两点间距离公式可求解.(3)设A’参数坐标,利用直线方程分别求出R,Q,K,T的参数坐标,根据S=S△QOT﹣S △ROK,求出S的面积函数,并求出S的最大值.【解答】方法一:解:(1)∵抛物线y=ax2+bx+c经过点O、A、C,可得c=0,∴,解得a=,b=,∴抛物线解析式为y=x2+x.(2)设点P的横坐标为t,∵PN∥CD,∴△OPN∽△OCD,可得PN=∴P(t,),∵点M在抛物线上,∴M(t,t2+t).如解答图1,过M点作MG⊥AB于G,过P点作PH⊥AB于H,AG=y A﹣y M=2﹣(t2+t)=t2﹣t+2,BH=PN=.当AG=BH时,四边形ABPM为等腰梯形,∴t2﹣t+2=,化简得3t2﹣8t+4=0,解得t1=2(不合题意,舍去),t2=,∴点P的坐标为(,)∴存在点P(,),使得四边形ABPM为等腰梯形.(3)如解答图2,△AOB沿AC方向平移至△A′O′B′,A′B′交x轴于T,交OC于Q,A′O′交x 轴于K,交OC于R.求得过A、C的直线为y AC=﹣x+3,可设点A′的横坐标为a,则点A′(a,﹣a+3),易知△OQT∽△OCD,可得QT=,∴点Q的坐标为(a,).解法一:设AB与OC相交于点J,∵△A′RQ∽△AOJ,相似三角形对应高的比等于相似比,∴=∴HT===2﹣a,KT=A′T=(3﹣a),A′Q=yA′﹣yQ=(﹣a+3)﹣=3﹣a.S四边形RKTQ=S△A′KT﹣S△A′RQ=KT•A′T﹣A′Q•HT=••(3﹣a)﹣•(3﹣a)•(﹣a+2)=a2+a﹣=(a﹣)2+由于<0,∴当a=时,S四边形RKTQ最大=,∴在线段AC上存在点A′(,),能使重叠部分面积S取到最大值,最大值为.解法二:过点R作RH⊥x轴于H,则由△ORH∽△OCD,得①由△RKH∽△A′O′B′,得②由①,②得KH=OH,OK=OH,KT=OT﹣OK=a﹣OH ③由△A′KT∽△A′O′B′,得,则KT=④由③,④得=a﹣OH,即OH=2a﹣2,RH=a﹣1,所以点R的坐标为R(2a﹣2,a﹣1)S四边形RKTQ=S△QOT﹣S△ROK=•OT•QT﹣•OK•RH=a•a﹣(1+a﹣)•(a﹣1)=a2+a﹣=(a﹣)2+由于<0,∴当a=时,S四边形RKTQ最大=,∴在线段AC上存在点A′(,),能使重叠部分面积S取到最大值,最大值为.解法三:∵AB=2,OB=1,∴tan∠O′A′B′=tan∠OAB=,∴KT=A′T•tan∠O′A′B′=(﹣a+3)•=a+,∴OK=OT﹣KT=a﹣(a+)=a﹣,过点R作RH⊥x轴于H,∵cot∠OAB=tan∠RKH==2,∴RH=2KH又∵tan∠OAB=tan∠ROH===,∴2RH=OK+KH=a﹣+RH,∴RH=a﹣1,OH=2(a﹣1),∴点R坐标R(2a﹣2,a﹣1)S四边形RKTQ=S△A′KT﹣S△A′RQ=•KT•A′T﹣A′Q•(x Q﹣x R)=••(3﹣a)﹣•(3﹣a)•(﹣a+2)=a2+a﹣=(a﹣)2+由于<0,∴当a=时,S四边形RKTQ最大=,∴在线段AC上存在点A′(,),能使重叠部分面积S取到最大值,最大值为.方法二:(1)略.(2)∵C(2,1),∴l OC:y=x,设P(t,),M(t,),∵四边形ABPM为等腰梯形,∴AM=BP且AM不平行BP,∴(t﹣1)2+(2+)2=(t﹣1)2+()2,∴2+=(无解)或2+=﹣,t1=2(舍),t2=,∴P(,).(3)∵A(1,2),C(2,1),∴l AC:y=﹣x+3,设A′(t,3﹣t),Q(t,),T(t,0),∵O′A′∥OA,∴K O′A′=K OA=2,∴l O′A′:y=2x+3﹣3t,∵l OC:y=x,∴R(2t﹣2,t﹣1),K(,0),∵S=S△QOT﹣S△ROK==﹣,∴t=时,S有最大值.。
广东省深圳市高级中学高一数学下学期期末考试试题 理
高级中学2014—2015学年第二学期期末测试高一理科数学本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分,第Ⅰ卷为1-12题,共60分,第Ⅱ卷为13-22题,共90分.全卷共计150分.考试时间为120分钟.第Ⅰ卷(本卷共60分)一、 选择题:(本大题共12题,每小题5分,共60分,在每小题给出的四个选项中,只有一项是符合题目要求的)1.已知集合A={}|(1)(4)0x x x +-<,集合B={}|2sin3y y x =,则A B= ( )A (-1 , 2] B ( 2 , 4 ) C [-2 , -1 ) D [-2 , 2]答案 C2.下列四个函数中,在(0,+∞)上为增函数的是 ( )A. ()3f x x =-B. 2()3f x x x =- C . ()1xf x x =+ D.2()log f x x =-答案:C3.某空间几何体的三视图如图所示,则该几何体的表面积为( )A .12+4 2B .18+8 2C .28D .20+8 2答案 D4.在△ABC 中,若2cos B sin A =sin C ,则△ABC 的形状是 ( ).A .等边三角形B .等腰三角形C .直角三角形D .等腰直角三角形 答案 B5.已知a 是实数,则函数()1sin f x a ax =+的图象不可能...是( )答案:D6. 已知数列{}n a 为等比数列,n S 是它的前n 项和,若2312a a a ⋅=,且4a 与27a 的等差中项为54,则5S = A .35 B .33 C .3l D .29 答案 C7.在空间四边形ABCD 中,AB =CD ,AD =BC ,AB ≠AD ,M ,N 分别是对角线AC 与BD 的中点,则MN 与( ) A .AC ,BD 之一垂直 B .AC ,BD 都垂直 C .AC ,BD 都不垂直D .AC ,BD 不一定垂直答案 B8.设变量y x ,满足⎪⎩⎪⎨⎧≤+≤≥110y y x x ,则()2x y +的最大值是 ( )A 9B 3C 2D 1 答案 A9.设l 为直线,αβ、两个不同的平面.下列命题中正确的是 ( )A .若l ∥α,l ∥β,则α∥βB .若l ⊥α,l ⊥β,则α∥βC .若l ⊥α,l ∥β,则α∥βD .若α⊥β,l ∥α,则l ⊥β答案 B10. 两圆相交于两点(1,3)A 和(, )B m n ,且两圆圆心都在直线20x y --=上,则m n +的值是 ( ) A. 1 B. 2 C. 3 D. 4 答案 D11.当点P 在圆x 2+y 2=1上变动时,它与定点Q (3,0)的连结线段PQ 的中点的轨迹方程是( )A .(x +3)2+y 2=4 B .(x -3)2+y 2=1 C .(2x -3)2+4y 2=1 D .(2x +3)2+4y 2=1答案 C12.已知向量a 与b 的夹角为θ,定义b a ⨯为a 与b 的“向量积”,且b a ⨯是一个向量,它的θ=,若(2,0)u =r ,(1,u v -=r r=+)(v u ( ).A 34.B 3 .C 6 .D 32答案 D第Ⅱ卷(本卷共计90分)二、填空题:(本大题共4小题,每小题5分,共20分)13.△ABC 的三个内角A ,B ,C 所对的边分别为a ,b ,c ,asin Asin B +bcos 2A =2a ,则b a =____________.14.等差数列{}n a 的前n 项的和为n S ,若1171024,a S S ==.则n S 取最大值时n 的值为_____________. 答案 13或1415.已知正方体的棱长为a a=________. 答案 216.曲线1y =(2)4y k x =-+有两个交点,则实数k 的取值范围是_______________.答案 53124⎛⎤⎥⎝⎦, 三、解答题:(本大题共6小题,共70分,解答应写出文字说明,证明过程,或演算步骤) 17.(本题满分10分)在△ABC 中,内角A ,B ,C 的对边分别为a ,b ,c ,向量m =(2sin B ,-3),n =⎝⎛⎭⎪⎫cos 2B ,2cos 2B2-1且m ∥n .(1)求锐角B 的大小;(2)如果b =2,求S △ABC 的最大值.解 (1)∵m ∥n ,∴2sin B ⎝⎛⎭⎪⎫2cos 2B2-1=-3cos 2B ,∴sin 2B =-3cos 2B ,即tan 2B =- 3.又B 为锐角,∴2B ∈(0,π),∴2B =2π3,∴B =π3 …………5分(2)∵B =π3,b =2,由余弦定理cos B =a 2+c 2-b22ac ,得a 2+c 2-ac -4=0.又a 2+c 2≥2ac ,代入上式, 得ac ≤4(当且仅当a =c =2时等号成立).S △ABC =12ac sin B =34ac ≤3(当且仅当a =c =2时等号成立),即S △ABC 的最大值为 3.……10分18.(本题满分12分)如图,正四面体S ABC -中,其棱长为2. (1)求该几何体的体积;(2)已知M ,N 分别是棱AB 和SC 的中点.求直线BN 和直线SM 所成的角的余弦值. 223ABC SO =MC ,取MC BN NE =2,直线和直线所成的角的余弦值为B M AN CS19.(本题满分12分)已知直线l :y =k (x +22)与圆O:224x y +=相交于A 、B 两点,O 是坐标原点,三角形ABO 的面积为S .(1)试将S 表示成k 的函数S (k ),并求出它的定义域; (2)求S 的最大值,并求取得最大值时k 的值. 解::如图,(1)直线l 议程 ),0(022≠=+-k k y kx 原点O 到l 的距离为2122kk oc +=弦长222218422K K OC OA AB +-=-=△ABO 面积2221)1(2421K K K OC AB S +-==),0(11,0≠<<-∴>K K AB )011(1)1(24)(222≠<<-+-=∴K k kk k k S 且 ……6分(2) 令.81)43(224132241)1(24)(22222+--=-+-=+-=∴t t t k k k k S∴当t=43时, 33,31,431122±===+k k k 时, 2max =S ……12分 20. (本题满分12分)如图,在直三棱柱111ABC A B C -中,平面1A BC ⊥侧面11A ABB ,且12AA AB ==(1) 求证:AB BC ⊥;(2) 若直线AC 与平面1A BC 所成的角为6π,求锐二面角1A AC B --的大小.BA 1CAB 1C 1,121,112<<=+t tk解:(1)证明:如右图,取1A B 的中点D ,连接AD , 因1AA AB =,则1AD A B ⊥ 由平面1A BC ⊥侧面11A ABB , 且平面1A BC侧面11A ABB 1A B =,得1AD A BC ⊥平面,又BC ⊂平面1A BC , 所以AD BC ⊥.因为三棱柱111ABC A B C —是直三棱柱, 则1AA ABC ⊥底面, 所以1AA BC ⊥. 又1=AA AD A ,从而BC ⊥侧面11A ABB ,又AB ⊂侧面11A ABB ,故AB BC ⊥. ………………6分(2)连接CD ,由(1)可知1AD A BC ⊥平面,则CD 是AC 在1A BC 平面内的射影 ∴ ACD ∠即为直线AC 与1A BC 平面所成的角,则=6ACD π∠在等腰直角1A AB ∆中,12AA AB ==,且点D 是1A B 中点∴ 112AD A B ===2ADC π∠,=6ACD π∠AC = 过点A 作1AE AC ⊥于点E ,连DE由(1)知1AD A BC ⊥平面,则1AD AC ⊥,且AEAD A =∴ AED ∠即为二面角1A AC B --的一个平面角BA1CAB 1C 1DE且直角1A AC ∆中:11A A AC AE AC ===又AD =2ADE π∠∴ sin =AD AED AE ∠==1A AC B --为锐二面角∴ =3AED π∠,即二面角1A AC B --的大小为3π…………12分 21. (本题满分12分) 设数列{}n a 的前n 项和为n S ,设n a 是n S 与2的等差中项, 数列{}n b 中,11b =,点1(,)n n P b b +在直线2y x =+上.(1) 求,n n a b ;(2) 若数列{}n b 的前n 项和为n B ,比较12111nB B B +++与2的大小; (3) 令1212nn nb b b T a a a =+++,是否存在正整数M ,使得n T M <对一切正整数n 都成立?若存在,求出M 的最小值;若不存在,请说明理由。
江苏省张家港高级中学2015-2016学年高一下学期期中考试数学试题Word版含答案
2015~2016学年第二学期期中考试三校联考高 一 年级 数学 试卷命题学校:张家港高级中学 命题人:赵松一、填空题:本题共14小题,每小题5分,共70分.请把答案填写在答题纸上..... 1.已知集合{}{}{}1,1,3,2,21,1a A B AB =-=-=,则实数a 的值为 ▲ .2.化简:sin13ocos17o+cos13osin17o= ▲ .3.已知数列{n a }的通项公式为22n a n n=+,那么110是它的第 ▲ 项. 4. 不等式122x x ->+的解集是 ▲ . 5.设x ,y 满足约束条件⎩⎪⎨⎪⎧x -y ≥-1,x +y ≤3,x ≥0,y ≥0,则z =x -2y 的取值范围是 ▲ .6.若数列1,,,,4a b c 成等比数列,则b 的值为____ ▲ __.7.已知△ABC 的三个内角A 、B 、C 成等差数列,且边a=4,c=3,则△ABC 的面积为_ ▲ __.8.等差数列{}n a 前n 项和为n S ,若7916a a +=,77S =,则12a = ▲ .9.若关于x 的不等式2260tx x t -+<的解集(,)(1,)a -∞+∞,则a 的值为 ▲ .10.已知数列{}n a 满足===-3711,2,5a a a a a nn n 则▲ .11.在等式cos()(1)1=★的括号中,填写一个锐角,使得等式成立,这个 锐角是 ▲ .12.已知数列{a n }的前n 项和S n =n 2-4n +2,则|a 1|+|a 2|+…+|a 10|= ▲ .13.设△ABC 的面积为S ,20S AB AC ⋅=.若||3BC =,则S 的最大值为 ▲ .14.已知f (x )是定义在R 上不恒为零的函数,对于任意的x ,y ∈R ,都有f (x ·y )=xf (y )+yf (x ) 成立.数列{a n }满足a n =f (2n )(n ∈N *),且a 1=2.则数列的通项公式a n = ▲ .二、解答题:本大题共6小题,共计90分,请在答题卡指定区域内作答,解答时应写出文字说明、证明过程或演算步骤.15.已知函数()sin()cos 6f x x x π=++(1)求函数()f x 的最大值,并写出当()f x 取得最大值时x 的取值集合;(2)若(0,),()265f ππαα∈+=,求()2f α的值 .16. 已知各项均为正数的等比数列{}n a 中,244,16a a ==.(1)求公比q ;(2)若35,a a 分别为等差数列{}n b 的第3项和第5项,求数列{}n b 的通项公式.17.在四边形中ABCD ,已知9,6,2AB BC CP PD ===. (1)若四边形中ABCD 是矩形,求AP BP ⋅的值;(2)若四边形中ABCD 是平行四边形,且AP BP ⋅=6,求AB 与AD 夹角的余弦值.18.已知函数2()3f x x ax =++.(1)当x R ∈时,()f x a ≥恒成立,求a 的取值范围; (2)当[]2,2x ∈-时,()f x a ≥恒成立,求a 的取值范围.19.如图,甲船从A 处以每小时30海里的速度沿正北方向航行,乙船在B 处沿固定方向匀速航行,B 在A 北偏西0105方向且与A相距20分钟到达C处时,乙船航行到甲船的北偏西0120方向的D 处,此时两船相距10海里. (1)求乙船每小时航行多少海里? (2)在C 处的北偏西030方向且与CE ,暗礁E海里范围内为航行危险区域.问:甲、乙两船按原航向和速度航行有无危险? 请说明理由.20.设数列{a n },a 1=1,1122n n n a a +=+,数列{b n },12n n n b a -=.(1)求证:数列{b n }为等差数列,并求出{b n }的通项公式; (2)数列{}n a 的前n项和为n S ,求n S ; (3) 正数数列{d n }满足n d ={d n }的前n 项和为D n ,求不超过100D 的最大整数的值.答案:一.填空题:1.1 2.123.4 4.{}|52x x -<<- 5.[]3,3- 6.2 7.3 3 8.15 9.-3 10. 4 11.040 12.66 1314.n ·2n 解答题:15.(1)f(x)=23sinx+21cosx+cosx=3sin(x+)3π……………….. 3分 当x+3π=2k )2(2πππ∈+k 即x=2k 时)(6Z k ∈+ππ …………….5分f(x)取得最大值3. ……………6分 此时x 的取值集合为}⎩⎨⎧∈+=Zk k x x ,62ππ ……………….7分(2)由(1)得f(x)=)3sin(3π+x 又f(533cos 3)36sin(3)6==++=+αππαπα 即cos 53=α ……….8分 54sin )2,0(=∴∈απα ………………….10分2524cos sin 22sin ==ααα 2572cos -=α ………………….12分 ααπαα2cos 232sin 23)32sin(3)2(+=+=∴f ………………... 13分 =5021324- ………………... 14分16.解:(1)由已知得21341416a a q a a q ==⎧⎪⎨==⎪⎩,∴24q =, ……4分 又0q >,∴2q =. ……6分(2)由(1)可得2n n a =.∴33558,32b a b a ====. ……8分设等差数列{}n b 的公差为d ,则3281253d -==-, ……10分 ∴()83121228n b n n =+-⨯=-. ……14分17.(1)13AP AD DP AD DC =+=+uu u r uuu r uu u r uuu r uuu rQ23B P B C C P B C D C=+=-u ur u uu r u ur u uu r u u ur ……3分 12()()33AP BP AD DC BC DC ∴⋅=+-uu u r uu r uuu r uuu r uu u r uuu rQ 四边形ABCD 是矩形 0AD DC ∴⋅=uuu r uuu r (2)分22()36811899AP BP AD BC DC ∴⋅=⋅-=-⨯=uu u r uu r uuu r uu u r uuu r …….7分②12()()633AP BP AD AB AD AB ∴⋅=+-=uu u r uu r uuu r uu u r uuu r uu u r……10分2212639AD AB AD AB ∴-⋅-⨯=uuu r uu u r uuu r uu u r 1123AB AD ∴⋅=uuu r uuu r …..12分设AB uu u r 与AD uuu r 的夹角为θ,则196cos 123θ⨯⨯= …….13分2c o s 3θ∴=即AB uu u r 与AD uuu r 的夹角的余弦值为23 …….15分18.(1),()x R f x a ∈≥恒成立,230x ax a ∴++-≥恒成立, (2)则24(3)0,6 2.a a a ∆=--≤∴-≤≤ .........5 故a 的取值范围是[]6,2- (6)(2)22()()3,24a a f x x =++-讨论对称轴与[]2,2-的位置关系,得到a 的取值满足下列条件:222222,,22(2)(2)34a a a a f a f a a ⎧-<-<⎧⎧⎪-≤--≥⎪⎪⎪⎨⎨⎨⎪⎪⎪-≥≥-≥⎩⎩⎪⎩或或, (12)解得72a -≤≤, (14)∴当[]2,2x ∈-时,()f x a ≥恒成立,a 的取值范围为[]7,2- (15)19.(1)连结AD ,由题意知CD=10,AC=060,10306020=∠=⋅ACD 是等边三角形ACD ∆∴ …………………. 2分∴AD=10, 又∠DAB=450 (3)分在10045cos 2AD BD ABD 0222=⋅-+=∆AB AD AB 中,由余弦定理得 BD=10 , V=10⋅3=30海里 ………………… 5分答:乙船的速度为每小时30海里 ………………….6分 (2) 延长CE 交BD 于F,过E 分别作EP ,于P AC ⊥EH ⊥BD 于H233430sin 3383000>==∴=∠EP ECP 甲船没有危险 …………………………10分3310tan3010CF 60,30000===∠∴=∠又 DFC HDC0Rt FEH EH 133EF ∴=∆==<在中,..15乙船有危险 ……………………… 16分20.(1)由1122n n n a a +=+,得11221n n n n a a -+=+. ………………2分 又12n n n b a -=,所以11n+n b b +=又b 1=a 1=1, ………………4分 所以数列{b n }是以1为首项,1为公差的等差数列.n b n =. ……………….6分 (2)12n n na -= ………………..7分 所以01211232222n n n S -=++++①,123112322222n nnS =++++,② 由①-②, 得112111[1()]111112212()2122222222212n n n n n n n n n n n n S ---=-=-=--=--+++++ (9)所以1242n n nS -=-+. …………….10分 (3)22222222211(1)(1)1(1)(1)nn n n n d n n n n ++++=++=++ ………………11分(1)111111(1)(1)1n n n d n n n n n n ++==+=+-+++, ……………….14分 所以100111111111(1)(1)(1)(1)101122334100101101D =+-++-++-+++-=-,.15分 所以,不超过100D 的最大整数为100. ……………..16分。
2015年全国普通高等学校统一考试(全国新课标Ⅰ卷)
滁州高级中学联谊会2015-2016学年度第二学期期末考试高一语文参考答案1.【答案】C(原文:需要日益严密的立法,更需要“毫无例外”的执法。
)2.【答案】D(属于措施,不属于原因。
)3.【答案】C(A. 应是“既需要内心的自我约束,更需要外部的无缝监管”。
B.应是“以对老百姓安全负责的菩心肠,祭出犯罪行为的雷霆手段。
D.应是“负有食品安全监督管理职责的”国家机关工作人员,“滥用职权”或者“玩忽职守”。
)4.【答案】C【试题分析】封建时代君主面南而坐,臣子面北朝拜。
北面而事之,正是臣下面北侍君之礼。
5.【答案】B6.【答案】D【试题分析】“刘备以逸待劳”错误。
刘备此时正处于“新败之后”,并非“以逸待劳”。
7.【答案】(1)现在将军外表上假托服从的名义,但内心里怀着犹豫不决的心思,局势危急而不能决断,(离)大祸临头没几天了!得分点:外,表面上。
托,假托。
内,内心里。
无日,没有多少日子,言很快。
以上各1分,句意1分,共5分。
(2)听说追逐刘豫州,轻装的骑兵一日一夜行军三百多里,这就是常说的‘强弓发出的箭到了尽头,按情势连鲁国的薄绢也穿不透’啊!得分点:轻骑,轻装的骑兵。
强弩之末,强弓发出的箭到了尽头。
势,指箭的情势,名词作状语。
缟,薄绢。
以上各1分,句意1分,共5分。
【参考译文】曹操将要顺着长江向东进发,诸葛亮对刘备说:“事情很危急,请(让我)奉命去向孙将军求救。
”于是(诸葛亮)与鲁肃一起去拜见孙权。
诸葛亮(在)柴桑见到了孙权,劝孙权说:“(现在)天下大乱,将军(您)在江东起兵,刘豫州在汉南招收兵马,与曹操共同争夺天下。
现在曹操削平大乱,(中原)大致已稳定,(他)于是攻破荆州,声威震动天下。
英雄没有施展本领的地方,所以刘豫州逃到这里,希望将军估量自己的实力来对付这个局面!如果(您)能拿江东的兵力同中原对抗,不如趁早同他断绝关系;如果不能,为什么不放下武器、捆起铠甲,面朝北向曹操称臣呢!现在将军外表上假托服从的名义,但内心里怀着犹豫不决的心思,局势危急而不能决断,(离)大祸临头没几天了!”孙权说:“假若像你所说,刘豫州为什么不投降曹操呢?”诸葛亮说:“田横,(不过是)齐国的一个壮士罢了,还能恪守节义不受屈辱;何况刘豫州(是)汉王室的后代,英明才智超过所有的当代人,众人敬仰他,就像河水流入大海一样。
江苏省通州高级中学2015-2016学年度高一年级第二次阶段考试生物试卷(必修)
江苏省通州高级中学2015—2016学年度高一年级第二次阶段考试生物试卷(必修)命题人:高洁审核人:秦秀芳一、单选题(本题包括35小题,每小题2分,共70分。
每小题只有一个选项符合题意)1. 杂合紫花豌豆自交后代同时出现紫花和白花,这种现象在遗传学上称为()A. 性别决定B. 完全显性C. 性状分离D. 伴性遗传【分析】本题考查性状分离的概念,意在考查考生的识记能力。
解答此题的关键是理解性状分离的概念。
【解答】在杂种后代中,同时出现显性性状和隐性性状的现象叫性状分离。
综上所述,C符合题意,ABD不符合题意。
故选C。
2. 已知豌豆的高茎对矮茎是显性,欲知一高茎豌豆的基因型,最简便的办法是()A. 让它与另一纯种高茎豌豆杂交B. 让它与另一杂种高茎豌豆杂交C. 让它与另一株矮茎豌豆杂交D. 让它进行自花传粉【分析】本题考查孟德尔遗传定律的应用,意在考查学生能理解所学知识的要点,把握知识间的内在联系的能力。
解答此题的关键是掌握判断基因型的方法。
【解答】推测基因型可用杂交和自交的方法,但豌豆是自花传粉,而且是闭花受粉植物,故最简单的办法是自交。
综上所述,D正确,ABC错误。
故选D。
3. 为了观察减数分裂各时期的特点,实验材料选择恰当的是()A. 马蛔虫受精卵B. 鸡肝脏C. 小鼠睾丸D. 洋葱表皮【分析】本题考查观察细胞减数分裂实验的相关知识,意在考查学生能理解所学知识要点的能力。
解答此题的关键是掌握能进行减数分裂的材料。
【解答】减数分裂是发生在有性生殖过程中,应选择生殖器官,马蛔虫受精卵进行的是有丝分裂,鸡肝脏和洋葱表皮已高度分化,一般情况下不分裂,小鼠的睾丸是雄性生殖器官,该器官进行旺盛的减数分裂过程,而且产生的精子数量较多,适宜作为观察材料。
综上所述,C符合题意,ABD不符合题意。
故选C。
4. 纯合黄圆豌豆(YYRR)与绿色皱粒豌豆(yyrr)杂交,F1全是黄色圆粒,F1自交得到F2,在F2中纯合的绿色圆粒有2000个,推测纯合的绿色圆粒有()A. 500个B. 1000个C. 2000个D. 4000个【分析】本题考查自由组合定律,意在考查考生识记所列知识点,并能运用所学知识做出合理的判断或得出正确的结论的能力。
湖北省孝感高级中学2015-2016学年高一英语下学期期末考试试题
孝感高中2015—2016学年度高一下学期期末考试英语试题考试时间:150分钟满分:150分本试卷分第Ⅰ卷(阅读题)和第Ⅱ卷(表达题)两部分第Ⅰ卷第一部分: 听力(共两节,满分30分)第一节(共5小题;每小题1. 5分,满分7. 5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题并阅读下一小题。
每段对话仅读一遍。
1.How does the woman probably feel?A.Surprised. B.Ridiculous. C.Angry.2.What does the woman mean?A.She hasn’t started yet. B.She has just started. C.She has finished.3.What wi ll the woman do this afternoon?A.Go to a concert with the man.B.Take care of her parents.C.Wait for the washing machine to be repaired.4.Where does the conversation probably take place?A.At an airport. B.In a restaurant. C.In a post office.5.Which flight will the man probably take?A.The 6 o’clock flight this afternoon.B.The 2 o’clock flight to morrow afternoon.C.The 6 o’clock flight tomorrow afternoon.第二节(共15小题;每小题1. 5分,满分22. 5分)听下面5段对话或独白。
人教版高一语文下册期末测试精选题目(含答案)5
人教版高一下册期末测试精选题目(含答案) 学校:___________姓名:___________班级:___________考号:___________一、文言文阅读阅读下面文言文,完成后面题目。
(共12分,选择题每题2分,翻译4分)游褒禅山记王安石褒禅山亦谓之华山。
唐浮图慧褒始舍于其址,而卒葬之;以故其后名之曰“褒禅”。
今所谓慧空禅院者,褒之庐冢也。
距其院东五里,所谓华山洞者,以其乃华山之阳名之也。
距洞百余步,有碑仆道,其文漫灭,独其为文犹可识,曰“花山”。
今言“华”如“华实”之“华”者,盖音谬也。
其下平旷,有泉侧出,而记游者甚众,所谓前洞也。
由山以上五六里,有穴窈然,入之甚寒,问其深,则其好游者不能穷也,谓之后洞。
余与四人拥火以入,入之愈深,其进愈难,而其见愈奇。
有怠而欲出者,曰:“不出,火且尽。
”遂与之俱出。
盖余所至,比好游者尚不能十一,然视其左右,来而记之者已少。
盖其又深,则其至又加少矣。
方是时,余之力尚足以入,火尚足以明也。
既其出,则或咎其欲出者,而余亦悔其随之而不得极夫游之乐也。
于是余有叹焉。
古人之观于天地、山川、草木、虫鱼、鸟兽,往往有得,以其求思之深而无不在也。
夫夷以近,则游者众;险以远,则至者少。
而世之奇伟、瑰怪、非常之观,常在于险远,而人之所罕至焉,故非有志者不能至也。
有志矣,不随以止也,然力不足者,亦不能至也。
有志与力,而又不随以怠,至于幽暗昏惑而无物以相之,亦不能至也。
然力足以至焉,于人为可讥,而在己为有悔;尽吾志也而不能至者,可以无悔矣,其孰能讥之乎?此余之所得也。
余于仆碑,又以悲夫古书之不存,后世之谬其传而莫能名者,何可胜道也哉!此所以学者不可以不深思而慎取之也。
四人者:庐陵萧君圭君玉,长乐王回深父,余弟安国平父、安上纯父。
至和元年七月某日,临川王某记。
(选自普通高中课程标准实验教科书《语文·必修2》)1.对下列句中加点词的解释,不正确的一项是A.则其好游者不能穷也好:喜好B.而世之奇伟、瑰怪、非常之观观:景象C.至于幽暗昏惑而无物以相之相:帮助D.后世之谬其传而莫能名者名:名称2.(小题2)下列加点词的意义和用法,相同的一组是A.距其院东五里其孰能讥之乎?B.夫夷以近,则游者众然力足以至焉C.有怠而欲出者险以远,则至者少D.有穴窈然,入之甚寒此余之所得也3.(小题3)下列句中加点的词语与现代汉语意思相同的一项是A.比好游者尚不能十一B.于是余有叹焉C.然力不足者,亦不能至也D.此所以学者不可以不深思而慎取之也4.(小题4)下列对文章内容的理解和分析,不正确的一项是A.这是一篇记叙与议论相结合的散文,阐释了“学者”治学的道理。
C语言中职期末试卷
**市中职中学2015—2016年度(下)期末《C 语言程序设计基础》试卷(考试时间:60分钟 总分:100分 适应班级: 级 班)注:1、答题前,务必将自己的班级、姓名、学号填写在相应的位置上。
2、请将答案按照题号顺序在各题目的答题区域内作答;保持答题卷清洁。
3、超出答题区域书写的答案无效。
一、填空题(每题2分,共30分)1、C 语言源程序是由 组成的,人们称C 语言为高级语言,一个函数由函数头、 两部分组成。
2、定义值为2016的符号常量VER 的命令是: 。
3、实型常量的十进制小数形式要求小数点两边 ,而指数形式中E(或e)的前后必须有数字,后边的数必须为 。
4、表达式5/2的值和表达式 (double)5/2 的值分别是 、 。
5、连续输入多个数值型数据时,数据之间用 分隔。
6、格式转换说明符要与输入地址列表中的变量 。
7、C 语言规定,为了在程序中能够正确使用输入输出函数,需要在源程序开始写上 预处理命令。
8、程序设计的初期一般用自然语言、流程图、伪代码等工具来表示算法,其中 表示具有直观、易于交流的特点。
9、模块化程序设计的思路是 。
在C 语言中实现程序化模块的工具是 。
10、C 语言规定,逻辑真用1表示,逻辑假用0表示。
设x 为整形变量,值为1,则表达式(x&&1)= =(x%2)的值为 。
11、与数学表达式|x|>10意思相同的C 语言表达式为 。
二、单项选择题(每题3分,共30分)(注:表示空格)1.下面正确的整型常量是()。
A.009B.x789 C.2e3D.9002.在C语言中,要求运算数必须是整型的运算符是()。
A、/ B、++ C、*=D、%3.有如下程序,若要求x1、x2、y1、y2的值分别为10、20、A、B,正确的数据输入是()。
int x1,x2;char y1,y2;scanf(“%d%d”,&x1,&x2);scanf(“%c%c”,&y1,&y2);A.1020AB B.10 20 ABC C.10AB 20AB D10 20AB4.根据下面的程序及数据的输入和输出的形式,程序中输入语句的正确形式应该为()。
学15—16学年下学期高二期末考试英语试题(附答案)
2015-2016学年度第二学期高二年级英语学科期末试卷(注意:本试卷共八页,共六题,满分120分,时间100分钟)第I卷第一部分听力(共两节,满分20分)第一节(共5个小题:每小题1分,满分5分)听下面5段对话。
每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. What’s the weather like in Boston now?A. Warm.B. Cold.C. Hot.2. Where does this conversation probably take place?A. On a bus.B. At the airport.C. At a bus stop.3. How does the man shop for groceries?A. By car.B. By bike.C. On foot.4. What’s the woman going to do?A. Play soccer.B. Buy some medicine for the man.C. Pick up Sally’s children.5. What is true about the woman’s Chinese?A. She just began studying.B. She has studied it for almost two years.C. Chinese is her native language.第二节(共15小题:每小题1分,满分15分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C 三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
江苏省西亭高级中学2015—2016学年度第二学期工作总结
江苏省西亭高级中学2015—2016学年度第二学期工作总结在区委、区政府、区政府教育督导室和区教育局的领导下,在全体师生员工的共同努力下,江苏省西亭高级中学继续围绕:醇化师德师风、实化管理常规的“强基固本”行动,优化育人目标、促进全面发展的“质量提升”行动,整合生活素养、活化科学实践的“特色凝练”行动,强化校园安全、推进校安工程的“护校安园”行动,不断深化教育教学改革,科学管理,提高质量,取得了理想的成绩。
本学期以来,学校先后获得南通市、区两级文明单位和青年文明号争创集体、通州区卫生工作先进集体、区食品安全学校等荣誉称号。
一、党委工作:贯彻落实党风廉政建设“两个责任”,把“两学一做”落到实处学校党委切实担负起党风廉政建设主体责任,把党风廉政建设和反腐败工作摆上重要议事日程,融入到教师队伍建设和课程改革发展各项工作中。
学校党委和班子成员树立不抓党风廉政建设就是严重失职的意识,坚持抓早抓小,管好班子,带好队伍,切实担负起党风廉政建设第一责任人的责任,班子成员认真抓好分管部门的党风廉政建设,落实“一岗双责”,践行“三严三实”,以党风促教风,以教风促学风,以学风促校风,坚持不懈地抓好党风廉政建设。
学校召开了“两学一做”集中学习活动动员大会,校党委领导班子带头上好党课,带领全体党员“学党规党章、学系列讲话、做合格党员”,并组织全体党员参加“党规党章测试”;通过政治学习、业务学习、每周召开行政中心组会议等活动深入开展“两学一做”,凝聚了干部、党员、教师创新的底气、增强了服务的能力,养成了清廉的正气,推进校园和谐、文明建设。
二、德育工作:用“绿色德育”引导“亭中习惯”,拓展教育发展新空间本学期,政教线坚定“优质、特色、多元”发展的总目标。
继续坚持“以人为本,德育为先”的方针,以培育和践行社会主义核心价值观为指导,以提升学生的生活素养为重点,以“八礼四仪”教育行动为抓手,紧紧围绕学校中心工作,进一步彰显我校“绿色德育”“提升生活素培养”的办学特色。
深圳市高级中学2015-2016学年高二下学期期中考试物理试卷 含答案
深圳市高级中学2015—2016学年第二学期期中测试高二物理命题人:朱立光审题人:钟早鸣本试卷由两部分组成.第一卷,共65分;第二卷,共35分.全卷由第Ⅰ卷和第Ⅱ卷两部分构成,第Ⅰ卷为1~8题,第Ⅱ卷为9~13题.全卷满分:100分.考试时间:90分钟.注意事项:1、答第一卷前,考生务必将自己的姓名、准考证号、考试科目用铅笔涂写在答题卡上.2、每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑.如需改动用橡皮擦干净后,再涂其它答案,不能答在试题卷上.3、考试结束,监考人员将答题卡按座位号、页码顺序收回.第Ⅰ卷(高二上学期及以前基础知识和能力,共65分)一、单项选择题:(本题共4小题;每小题5分,共20分.)1.两相邻的匀强磁场区域的磁感应强度大小不同,方向平行.一速度方向与磁感应强度方向垂直的带电粒子(不计重力),从较强磁场区域进入到较弱磁场区域,粒子的:A.轨道半径减小,角速度增大B.轨道半径减小,角速度减小C.轨道半径增大,角速度增大D.轨道半径增大,角速度减小2.如图所示,一物块在拉力F T作用下沿水平方向做匀速运动.则拉力F T与摩擦力F f的合力的方向为:A.可能向上偏右B.可能向上偏左C.一定竖直向上D.无法判定3.如图所示,在同一轨道平面上的几个人造地球卫星A、B、C 绕地球做匀速圆周运动,某一时刻它们恰好与地球在同一直线上,下列说法中正确的是:A.根据v=错误!可知,运行速度满足v A>v B>v CB.运转角速度满足ωA>ωB>ωCC.向心加速度满足a A<a B<a CD.此后,A最先回到图示位置4.目前世界上输送功率最大的直流输电工程--哈(密)郑(州)特高压直流输电工程已正式投入运行.高压直流输电具有无感抗、无容抗、无同步问题等优点.已知某段直流输电线长度L=200 m,通有从西向东I=4 000 A的恒定电流,该处地磁场的磁感应强度B=5×10—5T,磁倾角(磁感线与水平面的夹角)为5°(sin 5°≈0。
人教版数学高三期末测试精选(含答案)3
【答案】A
15.设 Sn 为等差数列an 的前 n 项和,若 3S3 S2 S4 , a1 2 ,则 a5
A. 12
B. 10
C.10
D.12
【来源】2018 年全国普通高等学校招生统一考试理科数学(新课标 I 卷)
【答案】B
16.若圆的半径为 4,a、b、c 为圆的内接三角形的三边,若 abc=16 2 ,则三角形的
b
c
a
A.都大于 2
B.都小于 2
C.至少有一个不大于 2
D.至少有一个不小于 2
【来源】2015-2016 湖南常德石门一中高二下第一次月考文科数学卷(带解析)
【答案】D
5. ABC 中, A 、 B 、 C 的对边的长分别为 a 、 b 、 c ,给出下列四个结论: ①以 1 、 1 、 1 为边长的三角形一定存在;
人教版数学高三期末测试精选(含答案)
学校:___________姓名:___________班级:___________考号:___________
评卷人 得分
一、单选题
1.在 ABC 中, a 2 3 0°或150
B. 60 或120
A.等腰直角三角形 B.直角三角形
C.等腰三角形
D.等边三角形
【来源】2013-2014 学年河南省郑州一中高二上学期期中考试文科数学试卷(带解析)
【答案】C
21.在△ABC 中,如果 sin A : sin B : sin C 2 : 3 : 4 ,那么 cosC 等于 ( )
2
A.
3
B. 2 3
【答案】D
10.在锐角 ABC 中,a ,b ,c 分别是角 A ,B ,C 的对边,a b cosC 3 c sin B , 3
管理局第一高级中学15—16学年下学期高二开学考试英语试题(附答案)
红兴隆管理局第一高级中学2015-2016学年度第二学期开学考试英语试卷注:卷面分值120分;时间:90分钟。
第一部分阅读理解(共两节,满分40分)第一节(共15小题:每小题2分,满分30分)阅读下列短文,从每题所给的四个选项中,选出最佳选项,并在答题卡上将该项涂黑。
AI spotted (发现;认出) him at the checkout counter, bagging at No.14. His arms shook violently as he placed a box of eggs into a plastic bag. He wore a name card upon which he had wiritten “Jerry” in kindergarten handwriting. He looked middle-aged but his mental age must have been about 12.Ever since I smiled at him the first time he bagged my groceries at my local supermarket, Jerry has followed me around like an adoring fan. His lack of boundaries makes me uncomfortable. I don’t know how to avoid being noticed by him. I don’t want to speak to the manager —my complaint could get him fired. So I started avoiding him.I can still remember the hurt I felt when I was 10 and our neighbor Mrs. Ward didn’t respond when I said hello with David and Diane. Instead, she hurried out of the supermarket, leaving me holding my brother and sister’s hands. I realized at that moment that I hated Mrs. Ward’s reaction. Why, then, years later, was I acting as she had?I picked up a magazine Real Simple. The beautiful photos did nothing to straighten out the guilt in me. I was being ridiculous. The last three times I have seen Jerry, I rushed. There are other stores, but I chose this one because it employs people with disabilities. I want people like my brothers to have jobs. I don’t want them to be ignored, the way I am avoiding Jerry.1. We know from the text that Jerry ________A. suffered from fragile X syndromeB. had a mental age not matching his real ageC. couldn’t write his nameD. only had a kindergarten education2. Why did the author feel uncomfortable?A. Jerry was like a fan of herB. Real Simple couldn’t straighten out her guiltC. Jerry always stepped on her feetD. Jerry didn’t keep a proper distance from her3. We can infer from the text that ________.A. there are many people like Mrs. WardB. the store the author visited treated the disabled equallyC. most employees in the supermarket are disabledD. the store manager ignored people with disabilities4.What is the author’s attitude towards people with disabilities?A. cautiousB. unconcernedC. ridiculousD. caringBGet the Emergency World Radio FREEThe U.S. Department of Homeland Security advises that every American home have an emergency (紧急情况) radio.Every home needs an emergency radio in the event of hurricanes, tornadoes, earthquakes, electric power outages and even terrorist attacks.Be Prepared in Any SituationThis Dynamo Emergency World Band Radio picks up the full AM/FM spectrum (频谱) and worldwide shortwave bands.Most importantly, the Dynamo Emergency World Band Radio includes:●Hand crank generator (in case batteries fail)●Emergency flashlightNewsmax Magazine’s Special Offer --- $20 Bonus (红利)Newsmax magazine wants every American family to have this emergency radio and will send it to youfor FREE. Just pay our standard shipping and handling charge of $5.95.When you order you FREE Dynamo Emergency World Band Radio, you’ll also receive four free issues of Newsmax magazine---a $20 value --- yours FREE.Newsmax magazine brings you stories the major media won’t report. But even they can’t ignore Newsmax magazine --- which has been introduced on Meet the Press, CNN, Fox News, Rush Limbaugh, MSNBC, and many other television networks.Each month in Newsmax magazine you’ll read hard-hitting investigative reports and special comments from Ben Stein, Dick Morris, Bill O’Reilly, Michael Reagan, Christopher Ruddy, and many others.Dick Morris from Fox News calls Newsmax “a must read” for every American. Call or go online today to get the Dynamo Emergency World Band Radio and 4 months of Newsmax magazine----a combined value of $50 --- FREE.Get Your FREE Emergency RadioPlease hurry! This is a limited time offer!Order online: / Parade 234Order by phone:1-800-933-86135. According to the U.S. Department of Homeland Security, the emergency radio should ________.A. be a household necessityB. be offered for freeC. be used as a flashlightD. work without batteries6. What’s the original price of the Dynamo Emergency World Band Radio?A. $5.95B. $20C. $30D. $507.What can we learn about Newsmax magazine?A. It comes out monthlyB. It mainly contains adsC. It belongs to Fox NewsD. It can only be ordered online8. What does Dick Morris think of Newsmax magazine?A. There’s no market for itB. It needs improvingC. It’s worth readingD. It has a long way to goCDriving to a friend’s house on a recent evening, I was attracted by the sight of the full moon rising just above my friend’s rooftop. I stopped to watch it for a few moments, thinking about what a pity it is that most city people --- myself included --- usually miss sights like this because we spend most of our lives indoors.My friend had also seen it. He grew up living in a forest in Europe, and the moon meant a lot to him then. It had touched much of his life.I know the feeling. Last December I took my seven-year-old daughter to the mountainous jungle of northern India with some friends. We stayed in a forest rest house with no electricity or running hot water. Our group had campfires outside every night, and indoors when it was too cold outside. The moon grew to its fullest during our trip. Between me and the high mountains lay three or four valleys. Not a light shone in them and not a sound could be heard. It was one of the quietest places I have ever known, a bottomless well of silence. And above me was the full moon, which struck me deeply.Today our lives are filled with glass, metal, plastic and fiber-glass. We have television, cell phones, electricity, heaters and ovens and air-conditioners, cars, computers.Struggling through traffic that evening at the end of a tiring day, most of it spent indoors, I thought, “Before long, I would like to live in a small cottage. There I will grow vegetables and read books and walk in the mountains. And perhaps write, but not in anger. I may become an old man there, and wear the bottoms of my trousers rolled and measure out my life in coffee spoons. But I will be able to walk outside on a cold silent night and touched the moon.”9. The best title for the passage would be _________.A. Touched by the MoonB. Break away from Modern lifeC. A Bottomless well of SilenceD. The Pleasures of Modern Life10. The writer felt sorry for himself because __________.A. there was too much pollution.B. he failed to see the fullest moon.C. he didn’t adapt to modern inventionsD. there were too many accidents on the road.11. Modern things are mentioned mainly to ___________.A. show that the writer likes city life very much.B. tell us that people greatly benefit from modern life.C. explain that people have less chances to enjoy nature.D. show that we can also enjoy nature at home through them.12. The author wrote the passage to __________.A. show the love for the moonlight.B. want to communicate longing for modern life.C. advise modern people to learn to live.D. express the feeling of returning to nature.DWhen it comes to success in business and success in life, there are few qualities as important as confidence.People naturally have different levels of confidence.Some have a higher level of confidence than others do, but even those whose confidence is lacking can learn to build their level of confidence and reach their most important goals.Increasing self confidence is one of the most common reasons people give for seeking the help of psychologists and other professionals.One of the many places where a greater level of confidence is useful is in the workplace.We all know how difficult it can be, for instance, to ask the boss for a raise.This process can be extremely difficult for those who lack confidence in their own abilities.After all, if you are unsure about your own abilities, how will you ever convince your boss that you deserve more money for the work you do?Even if you are not asking for that big raise, having plenty of confidence in your abilities is important to success.If you are certain of your abilities, chances are that those around you, whether they are your coworkers, your colleagues or your superiors, will see that confidence, and that will help to assure them that you are the best at what you do.Being thought of as the person to go to, and being seen as an expert in your chosen field, is naturally very important to success on the job.If you can make yourself the person people go to for guidance and advice, you will help to protect yourself from the ever present danger ofdownsizing(裁员).After all, if you are a recognized expert at the office, you will be regarded as an indispensable member of the team.Having a high level of confidence, after all, does not mean overlooking the places where you could improve.Knowing what you do well and where you need help will help you enjoy increased success and confidence.13.What is the passage mainly about?A.The influence of confidence on one's life.B.The difference of people's confidence..C.The judgment on one's confidence.D.The importance of confidence to success14.Psychologists and other professionals can offer help to those ______.A.who think their goals are hard to reach B.who expect to give guidance to othersC.who want to ask the boss for a raise D.who dream to be recognized experts15.What does the underlined word "indispensable" in Paragraph 5 probably mean? A.outgoing B.important C.attractive D.energetic第二节(共5小题:每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
湖北省孝感高级中学2015-2016学年高二下学期期末考试英语试题
第Ⅰ卷第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上,录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。
第一节(共5小题;每小题1.5分,满分7.5分)听下面5段对话,每段对话后有一个小题。
从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。
每段对话仅读一遍。
1.What’s the man probably?A.A repairman.B.A fireman.C.A policeman.2.What’s the possible relationship between the two speakers?A.Mother and son.B.Customer and shopkeeper.C.Husband and wife.3.What’s Tom going to do after class?A.Do some sports.B.Go to the library.C.Go to the bookstore.4.What’s wrong with the speakers?A.They lose their way.B.They took the wrong bus.C.They can’t find their map.5.What was the woman most probably doing last night?A.Watching TV at home.B.Expecting a phone call.C.Talking to her friends.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或独白。
每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。
听每段对话或独白前,你将有时间阅读各个小题,每小题5秒钟;听完后,各小题将给出5秒钟的作答时间。
【全国市级联考】山东省德州市高二高级中学2016-2017学年第二学期期末质量检测理科数学试题
绝密★启用前【全国市级联考】山东省德州市高二高级中学2016-2017学年第二学期期末质量检测理科数学试题试卷副标题考试范围:xxx ;考试时间:69分钟;命题人:xxx学校:___________姓名:___________班级:___________考号:___________注意事项.1.答题前填写好自己的姓名、班级、考号等信息 2.请将答案正确填写在答题卡上第I 卷(选择题)一、选择题(题型注释)1、为大力提倡“厉行节约,反对浪费”,某市通过随机询问100名性别不同的居民是否能做到“光盘”行动,得到如下的列联表:( )做不到“光盘” 能做到“光盘” 男 45 10 女 30 15 附:P (K 2k ) 0.10 0.05 0.025 k 2.706 3.841 5.024参照附表,得到的正确结论是A .在犯错误的概率不超过l %的前提下,认为“该市居民能否做到…光盘‟与性别有关”B .在犯错误的概率不超过l %的前提下,认为“该市居民能否做到…光盘‟与性别无关”C .有90%以上的把握认为“该市居民能否做到…光盘‟与性别有关”D .有90%以上的把握认为“该市居民能否做到…光盘‟与性别无关”2、用反证法证明命题“设为实数,则方程至少有一个实根”时,要做的假设是( ) A .方程没有实根 B .方程至多有一个实根C .方程至多有两个实根D .方程恰好有两个实根3、,则( )A .B .C .D .4、已知随机变量服从正态分布,且,则( )A .B .C .D .25、已知直线过点,且与曲线在点处的切线互相垂直,则直线的方程为( ) A .B .C .D .6、如果的展开式中各项系数之和为2,则展开式中的系数是( ) A . B .C .16D .7、已知,为的导函数,则的图象大致是( )A .B .C .D .8、已知为定义在上的单调递增函数,是其导函数,若对任意总有,则下列大小关系一定正确的是( )A .B .C .D .9、设是虚数单位,若,则复数的共轭复数是( )A .B .C .D .10、用数学归纳法证明“()”时,由的假设证明时,不等式左边需增加的项数为( )A .B .C .D .11、一批产品的合格率为90%,检验员抽检时出错率为10%,则检验员抽取一件产品,检验为合格品的概率是( )A .0.81B .0.82C .0.90D .0.91第II 卷(非选择题)二、填空题(题型注释)12、曲线,所围成的封闭图形的面积为 .13、已知6件不同产品中有2件是次品,现对它们依次进行测试,直至找出所有次品为止,若恰在第4次测试后,就找出了所有次品,则这样的不同测试方法数是( ) A .24B .72C .96D .36014、设某种机械设备能够连续正常工作10000小时的概率为,能够连续正常工作15000小时的概率为,现有一台连续工作了10000小时的这种机械,它能够连续正常工作到15000小时的概率是__________.15、若,则的值为__________.16、如果对定义在区间上的函数,对区间内任意两个不相等的实数,都有,则称函数为区间上的“函数”,给出下列函数及函数对应的区间:①;②;③;④,以上函数为区间上的“函数”的序号是__________.(写出所有正确的序号)三、解答题(题型注释)17、近几年来,我国许多地区经常出现干旱现象,为抗旱经常要进行人工降雨,现由天气预报得知,某地在未来5天的指定时间的降雨概率是:前3天均为,后2天均为,5天内任何一天的该指定时间没有降雨,则在当天实行人工降雨,否则,当天不实施人工降雨.(1)求至少有1天需要人工降雨的概率; (2)求不需要人工降雨的天数的分布列和期望.18、在一次抽样调查中测得样本的6组数据,得到一个变量关于的回归方程模型,其对应的数值如下表:(1)请用相关系数加以说明与之间存在线性相关关系(当时,说明与之间具有线性相关关系);(2)根据(1)的判断结果,建立关于的回归方程并预测当时,对应的值为多少(精确到).附参考公式:回归方程中斜率和截距的最小二乘法估计公式分别为:,,相关系数公式为:.参考数据:,,,.19、已知复数.(1)若,求;(2)取什么值时,是纯虚数.20、已知函数.(1)当时,求在上的值域;(2)若函数有三个不同的零点,求的取值范围.21、已知函数.(1)求函数的单调区间;(2)若关于的不等式恒成立,求整数的最小值.22、在直角坐标系中,曲线的参数方程为:(为参数),以原点为极点,轴正半轴为极轴,建立极坐标系,曲线的极坐标方程为.(1)求直角坐标系下曲线与曲线的方程;(2)设为曲线上的动点,求点到上点的距离的最大值,并求此时点的坐标. 23、选修4-5:不等式选讲已知函数.(Ⅰ)当时,解不等式;(Ⅱ)若关于的不等式恒成立,求实数的取值范围.参考答案1、C2、A3、B4、D5、B6、C7、A8、A9、D10、C11、B12、13、C14、15、16、①②17、(1)(2) x的分布列是:3.118、(1) 与之间存在线性相关关系;(2)0.38 ,.19、(1) ;(2) .20、(1) ;(2) .21、(1) 当时,的单调递增区间为,无减区间,当时,的单调递增区间为,单调递减区间为;(2)2.22、(1) ,;(2) 最大值为, .23、(1) 解集为或;(2) 的取值范围为.【解析】1、试题分析:由表计算得:,所以有90%以上的把握认为“该市居民能否做到…光盘‟与性别有关”,选C.考点:线性相关2、反证法证明问题时,反设实际是命题的否定,∴用反证法证明命题“设为实数,则方程至少有一个实根”时,要做的假设是:方程没有实根。
兵团三校 2015-2016学年第二学期高二期末考试试卷
兵团三校(第四师第一中学、第五师高级中学、第七师高级中学)2015-2016学年第二学期高二期末联考英语试卷命题人:马继海第Ⅰ卷注意事项:1.答第Ⅰ卷前,考生务必将自己的姓名、准考证号填写在本试卷和答题卡相应位置上。
2.选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。
如需改动,应用橡皮擦干净后,在选涂其他答案标号。
不能答在本试卷上,否则无效。
第一部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C、D)中,选出最佳选项,并在答题卡上将该项涂黑。
AIf I had to choose what language to learn next, it’s a tough decision but it’d probably be German because many people that know several languages tell me that German is their favorite language in terms of expressing themselves. And I think it might have something to do with the vast amount of vocabulary the German language has. So I think it’d be really difficult but a fun challenge.Elena (Canada, teacher)I think I’d like to learn French next because it’s a very romantic(浪漫的) language and it could be very useful in different job situations. Besides, I think it could help me understand English a bit more as well, since it was previously the language of diplomacy(外交)。
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高级中学2015-2016 学年第二学期期末测试初二英语英语试卷(考试时间:80分钟满分:85分)I. 词汇测试(15 分)i. 从下面每小题的A、B、C 三个选项中选出可以替换划线部分的最佳选项,并在答题卡上将相应的字母编号涂黑。
(共7小题,每小题1分)( )1.According to your description, I think you did a good job.A.At the end ofB. Because ofC. On the basis of( )2.I want to have a rest because I am bored with drawing.A.am good atB. am interestedC. get tired of( )3.We are going to set off for Shanghai next week.A.getB. leaveC. reach( )4.Parents should keep children from touching electricity.A.keep doingB. stop...fromC. hear...from( )5.How did you discover this nice place?A.meetB. makeC. find( )6.If you satisfy my plan, please say yes.A.are pleased withB. know aboutC. prepare for( )7.If you have an obligation to do something, it is your duty to do that thing.wB. rightC. responsibilityii. 根据句子意思,从下面每小题的A、B、C 三个选项中选出可以填入空白处的最佳选项,并在答题卡上将相应的字母编号涂黑。
(共8小题,每小题1分)( )8.A(n) is a person who does work without being paid for it.A.servantB. assistantC. volunteer( )9.---- How can you cut the paper in the of a bird?---- I followed the tips from a post on the Internet.B. heightC. shape( )10.He lived up to his promise.A.faithfullyB. lovelyC. loudly( )11.His eyes almost in surprise when he saw the accident.A.died outB. shut outC. popped out ( )12.If a player a point in a match, he or she gets a point in it.A.appearsB. scoresC. records( )13.---- Some people kill endangered animals for their meat and fur. It is terrible.---- Yes, many of those animals are now.A.in factB. in advanceC. in danger( )14.You can solve this problem or in groups.A.carefullyB. separatelyC. certainly( )15.On weekend, I have nothing to do but in the streets.A.make itB. come aroundC. lie aroundII. 完形填空(15 分,每空1.5 分)阅读下面短文,从短文所给的A、B、C 三个选项中选出能填入相应空白处的最佳选项,并在答题卡上将相应的字母编号涂黑。
(共10 小题,每小题1.5 分)Last week, all the teachers and students of our school watched a special performance.The second programme 1 me. The performer was very young, but his hands had both been burnt in a big fire. I did not dare to look at his wrists very 2 .What I did was to listen to his song quietly. It was called “Late Autumn” and he sang with a low gentle voice. Though it was warm spring, I felt a bit chilly and a little sentimental (感伤的) as if it was late autumn.“How much love and pain is 3 in the heart? I want to hold your hand again.” When I heard this, I tried to hold back my 4 . Holding her hand is just a dream. I hope that he finds a lovely girl for company one day, though he can’t hold hand. There was another young man who used his feet as his “hands” 5 his arms had been cut off. His handwriting greatly 6 us. Two big characters -- “Flying High” expressed his wish.All the performers were young except their special teacher who was over forty years old. Despite their 7 , the young performers gave off a(n) 8 glow. To be Young means to have all kinds of possibilities. We should challenge our 9 and go beyond ourselves.As long as we work hard, miracles (奇迹) will happen sooner or later. Just 10 on to a belief --“Where there is a will, there is a way.”1. A. inspired B. required C. warned2. A. nervously B. specially C. closely3. A. given B. hidden C. hid4. A. curiosity B. words C. tears5. A. until B. if C. because6. A. attacked B. reminded C. impressed7. A. pain B. disability C. difficulty8. A. youthful B. colorful C. calm9.10.A. limitsA. goB. desireB. hangC. learningC. knowIII. 阅读理解(30 分)阅读下列短文,从短文所给的A、B、C 三个选项中选择最佳选项,并在答题卡上将相应的字母编号涂黑。
(共20 小题,每小题1.5 分)ADragon Dance (舞龙) is a kind of traditional dance in Chinese culture. It has been spread all over China and to the whole world.Traditionally, dragons were made of wood and cloth. However, in the modem times, dragons are much lighter because they are made of lighter materials like plastics. The length of dragons can be from around 25 to 35 meters for acrobatic (杂技的) models, and up to 50 to 70 meters for the largest parade styles because people believe that the longer the dragon is, the more luck it will bring. A small organization cannot run a very long dragon because it requires great human power, much money and special skills.The Dragon Dance itself began during the Han Dynasty. And it was started by the Chinese who had shown great respect towards the dragon. It was already a popular event during the Song Dynasty. At that time, it became a popular activity like the Lion Dance. People could often see it during some important festivals. In the Qing Dynasty, the Dragon Dance Team of Fuzhou was invited to put on a show in Beijing. And the emperor spoke highly of it. The emperors of ancient China thought themselves as the dragons. ( )1.What are dragons traditionally made of?A.Gold.B. Paper.C. Wood and cloth.D. Plastics.( )2.How long is a dragon for the largest parade style?A.About 25 meters.B. About 35 meters.C. About 30 meters.D. About 70 meters.( )3.What does the underlined word “it” refer to?A.very long dragonB. A small o rganizationC. A paradeD. An acrobatic model( )4.When did the Dragon Dance become popular?A.During the Han Dynasty.B. During the Song Dynasty.C. During the Tang Dynasty.D. During the Qing Dynasty.( )5.What can we know from the passage?A.A small organization can run a very long d ragon.B.The Dragon Dance began during the Han Dynasty.C.Dragon Dance was started by a man who met a dragon.D.The ancient emperors of China were dragons in fact.BHave you ever wondered why birds sing? Maybe you thought that they were just happy. A fter all, you probably sing when you are happy.Some scientists believe that birds do sing some of the time just because they are happy. However, they sing most of the time for a very different reason. Their singing is actually a warning to other birds to stay out of their territory.Do you know what a “territory” is? A territory is an area that an animal, usually the male, claims as its own. Only he and his family are welcome there. No other families of the same species are welcome. Your house is your tertiary where only your family and friends arc welcome. If a stranger should enter your territory and threaten you, you might shout. Probably this would be enough to frighten him away.If so, you have actually frightened the stranger away without having to fight him. A bird does the same thing. But he expects an outsider almost any time, especially at nesting (筑巢) season. So he is screaming all the time, whether he can see an outsider or not. This screaming is what we call bird’s song, and it is usually enough to keep an outsider away.( )6.Most of the time bird’s singing is actually .A.an expression of happinessB. a way of warningC. an expression of angerD. a way of greeting( )7.What is a bird’s“territory”?A.A place where families of other species are not a ccepted.B.A place where a bird may shout at the top of its voice.C.An area for which birds fight against each other.D.An area which a bird considers to its own.( )8.Why do birds keep on singing at nesting season?A.Because they wart to invite more friends.B.Because their singing helps frighten outsiders away.C.Because they want to find outsiders embed.D.Because their singing helps get rid of their fears.( )9.How does the writer explain birds’s inging?A.By comparing birds with human beings.B.By reporting experiment results.C.By describing bird’s daily life.D.By telling a bird’s story.( )10.What’s the main idea of this article?A.The reason why birds nest.B.How birds sing.C.The reason why birds sing.D.How birds protect their nests.CDo you remember the name of your kindergarten teacher? Mine was called Mrs. White and I remember thinking she must be related to Walt Disney’s Snow White because she had the same dark hair, red lips and fair skin.I don’t remember much about what we learned in her class, but my mother told me that we used to write a lot. I would bring back what I wrote and she would look at it and see there were so many mistakes but no red corrections. Instead, Mrs. White would put a star and sometimes even a “Good!” This made me happy but it worried my mother. When my mom went to meet Mrs. White at a parent-teacher meeting, she asked her why she never corrected my mistakes or pointed out grammatical errors.Mrs. White said that she taught in this way because she didn’t want to dampen our spirits or enthusiasm. She told my mother that while spelling and grammar could wait, the wonder of words wouldn’t. 1 didn’t know the details of their conversation and as I grew up I learned to use words with confidence.I suddenly realize that if Mrs. White had used her red pen more accurately I probably wouldn’t he telling you about this now. I look back and think she must have been a rather extraordinary teacher. She encouraged joy, wonder and excitement -- even if our expression of it was wrong -- because she understood that to bloom is better than not to bloom. A bud once nipped never opens.And thanks to Mrs. White I had no worries about writing what I meant because life is beautiful.( )11.When the author talked about his kindergarten teacher, .A.he could remember her classes wellB.he believed that she was very beautifulC.he didn’t believe what his mother told himD.be thought her classes were quite interesting( )12.How did Mrs. White deal with the kids’w riting?A.She pointed out every mistake with red correction.B.She didn’t bother with mistakes as there were too many.C.She put a star or a “Good” on their writing.D.She explained all the kids’ doubts about writing.( )13.Why didn’t Mrs. White correct mistakes in the kids’w riting?A.She wanted to save time.B.She wanted to make the parents anxious.C.She wanted to encourage the kids to love writing.D.She wanted to make the kids happy.( )14.The underlined word “dampen” in Paragraph 3 means making something .A.wetB. more interestingC. less strongD. more difficult( )15.“What does the author think of his kindergarten teacher?A.She had a way to deal with naughty kids.B.She should have changed her of teaching.C.She could be better as a high school teacher.D.She helped him to be confident in writing.DThe majority of astronauts from America have been men. At the start of the space programme there was strong resistance from some people against having women in space. However, some women were very keen to become astronauts and in the end they were successful. In 1978, NASA(美国航天局) began the first training programme for women astronauts.Judy Resnick and Christa McAuliffe were both astronauts and they were both women, but in many other ways they were very different. Both of them were on Flight STS-51-L. Judy Resnick . was born in 1949 and studied engineering at university and went on to obtain a PhD (博士学位) in1977. She was a member of the first group of women selected for astronaut training in 1978, and in 1984, she became the second woman in space. During that flight, she helped to launch three new satellites and she carried out a programme of research. She was, in many ways, a professional astronaut whose whole life was devoted to space travel.Christa McAuliffe was born in 1948 and she was an astronaut almost by accident. In 1984, NASA decided to find a teacher who could accompany astronauts into space. They hoped that she would be able to communicate with students from space and encourage every one of them to be interested in space travel. Christa was a secondary teacher in history and social studies. She was a gifted teacher and she was selected from over 11,000 applicants to go on flight STS-51-L. She was also a very good communicator and she immediately established a very good relationship with the news media (radio, television and newspapers). It was partly because of this that there was a great deal of interest and excitement about the flight. Thousands of students in schools and universities all around the country hoped to communicate with Christa in space. Millions of people were watching her flight with great interest. It is partly because of the excitement over McAuliffe’s place in the flight that the disaster in 1986 had such an effect on people.( )16.We can learn from the first two paragraphs that .A.Judy was against the idea of having women in space at firstB.Judy was the first woman selected for astronaut trainingC.Judy helped to launch three new satellites at the age of 35D.Judy carried out a programme during her second space travel( )17.Christa McAuliffe was chosen for training because .A.she was popular with the news mediaB.she expected to give history lessons in spaceC.she was an excellent teacher and communicatorD.she made the students in space very excited( )18.The reason why there was great interest in Flight STS-51-L is that .A. both Christa and Judy got PhD degrees in the same yearB. a young secondary school teacher was on the flightC. students were going to learn more about space travelD. it was the first time for women to travel in space( )19.Which saying is true according to the article?A.Few women wanted to become astronauts at the start the space programme.B.Christa was a secondary teacher in history and economics.C.Christa dreamt to be an astronaut when she was young.D.Many people disagreed to have women in space at first.( )20.What would be the best title for the passage?A.Two AstronautsB. Flight STS-51-LC. Travelling in SpaceD. The TrainingIV. 语法填空(10 分)(共10 小题,每小题1分)A TV program has become popular in China recently. It has made people all over China become interested in writing Chinese characters (汉字).The 1 (increase) use of computers and smart phones 2 (leave)most young people hardly able to write by hand. Many of them 3 (be) even unable to remember the 10,000 characters used in daily life 4 Electronic devices’help.CCTV started the Chinese Character Dictation Competition to improve the population’s handwriting skills. Contestants (参与者) on the show were school pupils, but it was 5 (find) that 70% of adults in the audience were unable to remember how to write the word “chan chu”.Because computers allow people to type characters 6 (simple) by entering pinyin. They don’t need to remember how to write them. “The keyboard age has a bi g influence 7the handwriting of Chinese characters.” Guang Zhengwen, who designed and directed the show said.He added that he hoped to encourage people 8 (keep) it alive as an art form. Hao Mingjian, an editor of a magazine, 9 (put) his heart into Chinese characters, said, “ 10 (learn) Chinese goes on throughout your life. If you stop using them for a long time, it is very likely that you will forget them.”V. 书面表达(共15 分)目前,深圳正在开展智慧校园建设,电子书包也开始逐步走近中小学课堂。