山西省运城市2019-2020学年高一上学期期末调研测试英语试题(含答案)

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【期末试卷】2019-2020学年高一上学期期末考试英语试卷（新高考卷）笔试部分附参考答案

【期末试卷】2019-2020学年高一上学期期末考试英语试卷（新高考卷）笔试部分附参考答案按秘密级事项管理★启用前2019-2020 高一上学期期末考试英语试卷(新高考卷)注意事项:1. 答卷前，考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上。

2. 回答选择题时，选出每小题答案后，用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其他答案标号。

回答非选择题时，将答案写在答题卡上。

写在本试卷上无效。

3. 考试结束后，将本试卷和答题卡一并交回。

第一部分阅读(共两节，满分50分)第一节(共15小题；每小题2.5分，满分37.5 分)阅读下列短文，从每题所给的A、B、C、D四个选项中选出最佳选项。

AArtificial intelligence (AI) is practically everywhere today. There are so many products out there which use AI. Some are being developed, some are already in use, and some failed and are being improved, so it’s very difficult to name a few of them and regard them as the best.ViIt is an AI personal trainer which is mainly concerned with fitness and coaching. It, however, requires the use of bio-sensing earphones and other fitness tracking equipment (设备)! It can play your favourite music while you work out and all you have to worry about is the exercise you’re doing.Deep TextDo you ever wonder how an ad appears suddenly just whenyou are looking for something similar? This is because of Deep Text. It uses real-time consumer (消费者) information to produce data which in turn is used to target consumers. Thus, if you search online for flight tickets from Bangalore to Delhi, it is very likely that an ad relating to hotels in Delhi will soon follow.Hello EggIf you live alone and miss your mother because you always miss your breakfast or don’t know what to eat for dinner, the n Hello Egg is exactly what you are looking for. A very healthy choice of the 2-minute noodles and oats, Hello Egg provides you with a detailed weekly meal plan about the needs of your body. It is truly a modern AI-powered home cooking tool for the young.WordsmithYou can put Mr. Smith into your Microsoft Excel using their free API, and let it write up detailed analysis (分析) of the stories behind your numbers. It can produce detailed reports on thousands of pages of spreadsheets in seconds.1.What can we learn about Vi from the text?A. It is an AI music player.B. It is a bio-sensing earphone.C. It doesn’t work without bio-sensing earphones.D. It can make you more energetic while you work out.2. Which can help you improve cooking skill?A.Hello Egg.B.Deep Text.C.Vi.D.Wordsmith.3. What can Wordsmith do for us?A.Produce a detailed report.B.Book a ticket ahead of time.C.Provide us with a detailed meal plan.D.Offer us information on hotels for traveling.BA couple in their 60s has travelled 12,000 miles across 16 countries from Britain to China — riding their bikes the entire way. Grandparents Peter and Chris stepped on the long journey after deciding to “do something a bit different”. They traversed (横穿) cities, deserts, mountains and everything in between across Europe, the Middle East and the East Asia. The married couple of 37 years enjoyed themselves with delicious local food and spent most nights inside a tiny tent put up wherever they could find shelter.Peter, 66, said the moment they finally had a look at the famous Great Wall after a year and a half of cycling 30 miles a day was “really exciting”. At the end of their journey, the special pair didn’t fly home but instead choose to book a cabin (舱) inside a 400m-long container ship. The final part was a three-week voyage from Singapore across the Indian Ocean and into the Mediterranean Sea before arriving at Southampton.“You never know what the day is going to bring. All you know is that you aregoing to get on your bike and cycle. Every day is an adventure and every day is new. Overall, the experience is absolutely unbelievable, ” Peter said.Peter and Chris initially set out to cycle from Britain in January 2017 but were forced home. They had cycled all the way to Hungary when Peter slipped on tiles and broke his leg. After seven months of recovery, the couple set out again in Britain. They finally arrived in China in November 2018.Both Peter and Chris agreed that the best part of the entiretrip was coming across the kindness of strangers along the way, many of whom invited the couple for food and drink. Chris, 64, said, “It was a wonderful experience, particularly wonderful because of the amazing people we met along the way.”4.What’s the couple’s purpose of taking the long journey?A.To try something new.B.To break the world record.C. To go across 16 countries by bike.D. To celebrate their 37-year marriage.5. How did the couple go back to their home after the trip to China?A. By cycling.B. By train.C. By plane.D. By sea.6. Why did the couple put off their trip in 2017?A. Peter had an accident.B. They ran out of their money.C. They met with a heavy snow.D. Peter fell ill suddenly in Hungary.7. What’s the best part of the trip for the couple?A. The beautiful scenes.B. The help from others.C. The delicious food and drink.D. The kindness from other cyclists.CHundreds of thousands of lives were saved in 2017 alone because of the improvement of the environment, according to a new research. Fine particle pollution declined rapidly following the new rules on industrial emissions and the promotion of cleanfuels, according to the study, published on Monday in the National Academy of Sciences of the United States of America. The study, which focused on the period from 2013-2017, was conducted by a group of Chinese researchers and scientists.PM2.5, as this kind of pollution is known, is so small that it can enter the bloodstream, potentially leading to cancer, stroke and heart attack in the long term. After rapid industrialization and weak regulations left the country with a reputation for smog and bad air quality, Chinese authorities started to take air pollution seriously in 2008.In 2013, Beijing had PM2.5 concentrations 40 times higher than levels recommended by the World Health Organization (WHO), and the governmentintroduced its toughest-ever clean air policies that year. The study found “signif icant declines” in PM2.5 levels across China from 2013-2017, with new standards for thermal power plants and industrial boilers, the replacement of old factories, and new emissions rules for vehicles. The authors say this “confirms the effectiveness of Chi na’s recent clean air actions.”These recent actions have seen Beijing fall out of the top 100 most-polluted cities in Asia in recent years, with the pollution levels 10% lower across Chinese cities between 2017 and 2018, according to a report by Greenpeace and AirVisual. Shanghai, the country’s largest city and financial capital, has also made environmental advances, such as adopting strict recycling regulations. Public pressure has been the driving force of pollution policy in China.Air pollution is a global issue, and India is now home to 22 of the 30 most polluted world cities, according to the Greenpeace and AirVisual report. In the US, a recent study said air pollutionwas linked to more than 107,000 deaths in 2011 and cost the country $866 billion.8. What saved many lives in China?A. China’s clean air policies.B. The increased particle pollution.C. The study by researchers.D. The reduction of the clean fuels.9. Why did PM2.5 cause many diseases?A. It was called smog.B. It made the air cleaner.C. It went into the blood.D. It had a bad reputation.10. When did Chinese government decide to treat the pollution?A. In 2008.B. In 2013.C. In 2017.D. In 2018.11. What did people in Shanghai do to protect the environment?A. They built the thermal power plants.B. They stopped using industrial boilers.C. They made Shanghai financial capital.D. They tried to recycle some rubbish.DIn the 1994 film Forrest Gump, there’s a famous saying, “Life is like a box of chocolates; you never know what you’re gonna get.” The surprise is part of the fun. Now blind box toys are bringing the magic of surprise to online shopping.A blind box toy is hidden inside uniform packaging(包装) butinvisible from the outside. You don’t know what will be inside, although the toys typically come from pop culture, ranging from movies to comics and cartoons.Blind boxes have caught on since they were first introduced from Japan to China in 2014. According to a 2019 Tmall report, the mini-series of Labubu blind box. designed by Hong Kong -born Kasing Lung, was named Champion of Unit Sales with 55,000 sold in just 9 seconds during the Singles Day shopping event. Most customers for blind boxes are young people aged 18 to 35.According to The Paper, blind box toys are popular in part because of their cute appearances. The typically cute cartoon figurines (小塑像) come in miniature (微型的) sizes, making them suitable for display almost anywhere.Even if blind boxes are not their top choice for decorations(装饰品), the mystery and uncertainty of the process also attracts people. It’s the main reason why people buy blind boxes one after another.“Fear of the unknown is always a part of the box-opening process,” said Miss Cao, 24, who lives and works in Shenyang. Speaking to Sina News, she said: “Until you open all the boxes, you cannot know what it is inside.”Opening a blind box is a delightful little surprise for our mundane daily lives, something small but fun to wait for each day, week or month. When people open this simple little box, they may be disappointed, but the uncertainty is part of the fun. People will open more blind boxes and hope for a better outcome.When someone re-makes Forrest Gump, don't be surprised if he says, “Life is like a blind box.”12.What feature of blind boxes attracts people?A.They often get toys designed by famous artists.B.They don’t know what they’ve got until they open them.C.They can learn about pop culture from the packaging.D.They can experience the excitement of online shopping.13.Why does Miss Cao love blind box toys?。

山西省运城市高中联合体2020-2021学年高一上学期期中考试英语含答案

运城市高中联合体2020高一期中调研测试英语考生注意：1.本试卷分选择题和非选择题两部分。

满分150分，考试时间120分钟。

2.答题前，考生务必用直径0.5毫米黑色墨水签字笔将密封线内项目填写清楚。

3.考生作答时，请将答案答在答题卡上。

选择题每小题选出答案后，用2B铅笔把答题卡上对应题目的答案标号涂黑；非选择题请用直径0.5毫米黑色墨水签字笔在答题卡上各题的答题区域内作答，超出答题区域书写的答案无效，在试题卷、草稿纸上作答无效．．．．．．．．．．．．．．．．．．．．．．．．．．．。

4.本卷命题范围：外研版至Book1Module5。

第一部分听力(共两节，满分20分)第一节(共5小题；每小题1分，满分5分)听下面5段对话，每段对话后有一个小题。

从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What does the man want to do?e the bathroom.B.Wash his hair.C.Clean his teeth.2.What is the woman good at?A.Waterskiing.B.Windsurfing.C.Swimming.3.Where does this conversation most probably take place?A.On a farm.B.At home.C.In a restaurant.4.What does the man ask the woman to do?A.Get on the train.B.Hurry to the airport.C.Buy a ticket.5.What is the probable relationship between the speakers?A.Classmates.B.Teacher and student.C.Director and actor.第二节(共15小题，每小题1分，满分15分)听下面5段对话或独白。

山西省运城市2014学年第二学期高三调研测试英语1

山西省运城市2014学年第二学期高三调研测试英语1高考英语2014-04-11 1302运城市2014—2014学年第二学期高三调研测试英语试题本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分，满分150分，考试时间120分钟。

请在答卷页上作答。

第一卷(选择题共115分)第一部分：听力(共两节，满分30分；不计入总分)第一节(共5小题；每小题1.5分，满分7.5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有2014秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1．What will probably happen to the woman?A．Miss her flight． B．Catch her flight． C．Cancel her flight．2．Where is the dialogue taking place?A．In the classroom． B．In front of a computer． C．At the doctor's．3．What do we know from the conversation?A．Joe Smith has been ill．B．Joe's wife is going to New York．C．The man met Joe Smith on the street yesterday．4．Who wants to borrow the camera?A．John． B Alice． C．Jane．5．When will the meeting be held?A．At 2 pm tomorrow． B．At 3 pm today． C．At 3 pm tomorrow．第二节(共15小题；每小题1.5分，满分22.5分)听下面5段对话或独白，每段对话或白后有几个小题，从题中所给的A、B、C 三个选项中选出最佳选项，并标在试卷的相应位置。

2019-2020学年度第二学期期末调研考试高一英语试题【含答案】

2019-2020学年度第⼆学期期末调研考试⾼⼀英语试题【含答案】2019-2020 学年度第⼆学期期末调研考试⾼⼀英语试题选择题部分第⼀部分听⼒（共两节，满分30分）做题时，先将答案标在试卷上。

录⾳内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第⼀节（共5⼩题；每⼩题1.5分，满分7.5分）听下⾯5段对话。

每段对话后有⼀个⼩题，从题中所给的A、B、C三个选项中选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关⼩题和阅读下⼀⼩题。

每段对话仅读⼀遍。

1.What will Peter do at 10:00 tomorrow?A. Go camping.B. Stay at home.C. Have a meeting.2.How much did the woman pay for the skirt?A. $10.B. $20.C.$40.3.What's the weather like now?A. Cloudy.B. Sunny.C. Rainy.4. When does the supermarket open on the weekend?A.At 6:00 am.B. At8:00 am.C.At 9:00 am.5.What will the woman do for her mother's birthday?A. Buy a gift.B.Throw a party.C.Make a cake.第⼆节（共15⼩题；每⼩题1.5分，满分22.5分）听下⾯5段对话或独⽩。

每段对话或独⽩后有⼏个⼩题，从题中所给A、B、C三个选项中选出最佳选项。

听每段对话或独⽩前，你将有时间阅读各个⼩题，每⼩题5秒钟；听完后，各⼩题将给出5秒钟的作答时间。

每段对话或独⽩读两遍。

听第6段材料，回答第6、7题。

6. Where does the woman want to go?A.The nearest bank.B.The nearest hospital.C.The nearest post office.7. How will the woman go there?A. By bus.B. By car.C. On foot.听第7段材料，回答第8、9题。

山西省吕梁市、运城市2022—2023学年度第一学期期末调研考试-高三英语试题(后附参考答案)

吕梁市2022-2023学年第一学期期末调研测试高三英语试题2023.本试题满分150分，考试时间120分钟。

答案一律写在答题卡上。

注意事项：1.答题前，考生务必先将自己的姓名、准考证号填写在答题卡上，认真核对条形码上的姓名、准考证号，并将条形码粘贴在答题卡的指定位置上。

2.答题时使用0.5毫米的黑色中性（签字）笔或碳素笔书写，字体工整、笔迹清楚。

3.请按照题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效。

4.保持卡面清洁，不折叠，不破损。

第一部分听力（共两节，满分30分）做题时，先将答案标在试卷上，录音内容结束后，你将有两分钟的时间将试卷上的答案转涂到答题卡上。

听力部分不计入总分。

第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例如：How much is the shirt?A.£ 19.15.答案是B。

1.Who is the woman?A.A bus driver.B.£ 9. 15.B.A policewoman.2.When does the woman want to take the class?A.On Thursday.B.On Friday.3.What did the speakers do last weekend?A.They studied at home.B.They went hiking.4.Where are the speakers?A.In a library.B.In a study room.5.What will the woman do next?A.Stand on the hill alone.B.Take a picture for the man.C.Visit Chicago with the man.高三英语试题第1页（共10页）C.£ 9. 18.C.A passenger. C.On Saturday. C.They played tennis.C.In a bookstore.运城市2022-2023学年度高三第一学期期末调研测试英语参考答案第一部分听力1-5AACCB6-10BBCAA11-15BBAAC16-20CBBCA第二部分阅读理解A:21-23BCD B:24-27:BADD C:28-31BADB D:32-35:CDCB36-40EABFG第三部分语言知识运用41-45.CDACB46-50.CBCBD51-55.CADDA56.gathering57.the58.have seen59.and60.with61.who62.looking63.kicked64.planned65.approximately 第四部分写作第一节书面表达Dear Jim,I am quite disturbed these days as I have a disagreement with my parents over my career choice.I just can’t help writing to tell about it and ask for your advice.I have always dreamed of being a tourist guide,which will offer me great opportunities to broaden my horizon and enrich my experience.However,my parents hope that I should go in for professions with a secure income and stable life like teachers or doctors.I am caught in a dilemma.Is it better to obey my parents and take a career that I don’t enjoy but guarantee long-term stability?Or should I go against my parents’will and pursuit a career that brings me happiness and satisfaction?What would you do if you were in my position?I really hope that you can give me some advice.Yours,Li Hua【分析】本文是一篇应用文，由于和父母在未来职业选择上意见不一，于是写信给国外朋友Jim写信倾诉自己的苦恼并请他给提些建议。

2019-2020学年山西省运城市高一上学期期中调研测试数学试题(解析版)

2019-2020学年山西省运城市高一上学期期中调研测试数学试题一、单选题1．若集合{|62}A x x =-剟，{|23}B x x =-<<，则()A B =Rð（）A ．{|63}x x -<≤B ．{|62}x x -<…C ．{|62}x x -≤≤-D ．{|6x x <-或3}x …【答案】C【解析】根据集合的基本运算先求R B ð再求()RA B ð即可.【详解】因为R {|2B x x =-…ð或3}x …,所以()R {|62}A B x x ⋂=--剟ð 故选：C. 【点睛】本题主要考查集合的基本运算,属于基础题型. 2．函数()()1ln 24f x x x =-+-的定义域是( ) A ．)2,4⎡⎣B ．()2,+∞C ．()()2,44,⋃+∞D ．)()2,44,⎡⋃+∞⎣【答案】C【解析】根据对数真数大于零，分式分母不为零列不等式组，解不等式组求得函数的定义域. 【详解】由题意得20,40,x x ->⎧⎨-≠⎩解得()()2,44,x ∈+∞.故选：C. 【点睛】本小题主要考查函数定义域的求法，属于基础题.3．把“2019”中的四个数字拆开，可构成集合{}2,0,1,9，则该集合的所有真子集的个数为（） A ．7B ．8C ．15D ．16【答案】C【解析】根据元素个数为n 的集合真子集个数为 21n -求解即可. 【详解】集合{}2,0,1,9中共有四个元素,故其子集的个数为4216=个,所以其真子集的个数为16115-=.故选：C 【点睛】本题主要考查知识点元素个数为n 的集合真子集个数为 21n -.属于基础题型. 4．已知函数2(1)3f x x x +=-+，则()f x =（） A ．235x x -+ B ．25x x -+ C ．233x x -+ D ．23x x ++【答案】A【解析】换元设1t x =+,再反解代入2(1)3f x x x +=-+即可. 【详解】设1t x =+,则1x t =-,则22()(1)(1)335f t t t t t =---+=-+,即2()35f x x x =-+.故选：A. 【点睛】本题主要考查利用换元法求函数解析式的问题,属于基础题型. 5．已知5log 2a =，0.9log 1.1b =，0.92c -=，则( ) A ．a b c << B ．b c a << C ．a c b << D ．b a c <<【答案】D【解析】根据对数的性质判断10,02a b <<<，根据指数的性质判断12c >，由此得出三者的大小关系. 【详解】因为5510log 2log 2a <=<=，0.9log 1.10b =<，0.911222c --=>=，所以b a c <<.故选：A. 【点睛】本小题主要考查指数式、对数式比较大小，属于基础题.6．函数()3ln x f x x=的图象大致为（）A ．B ．C ．D ．【答案】D【解析】分析函数()y f x =的定义域、奇偶性以及函数()y f x =在()0,1和()1,+∞上的函数值符号，可得出正确选项. 【详解】自变量x 满足0ln 0x x ⎧>⎪⎨≠⎪⎩，解得0x ≠且1x ≠±，则函数()y f x =的定义域为()()()(),11,00,11,-∞--+∞U U U .()()()33ln ln x x f x f x x x--==-=--Q ，则函数()y f x =为奇函数，当01x <<时，ln 0x <，()0f x ∴<，当1x >时，ln 0x >，()0f x ∴>. 故选：D. 【点睛】本题考查函数图象的识别，一般从函数的定义域、奇偶性、单调性、零点和函数值符号来进行判断，考查分析问题和解决问题的能力，属于中等题.7．函数()212()log 295f x x x =+-的单调递增区间为（） A ．1(,5),2⎛⎫-∞-⋃+∞⎪⎝⎭B ．(,5)-∞-C ．1,2⎛⎫+∞ ⎪⎝⎭D ．(0,)+∞【答案】B【解析】先求出()212()log 295f x x x =+-的定义域,再利用同增异减以及二次函数的图像判断单调区间即可. 【详解】令22950x x +->,得f(x)的定义域为1(,5),2⎛⎫-∞-⋃+∞⎪⎝⎭,根据复合函数的单调性规律,即求函数2295t x x =+-在1(,5),2⎛⎫-∞-⋃+∞ ⎪⎝⎭上的减区间,根据二次函数的图象可知(,5)-∞-为函数2295t x x =+-的减区间. 故选：B 【点睛】本题主要考查对数函数的定义域以及复合函数的单调区间等,属于基础题型.8．已知函数()f x 满足1,0()2,0xx f x ax a x ⎧⎛⎫≤⎪ ⎪=⎨⎝⎭⎪->⎩是R 上的单调函数，则a 的取值范围是A ．[1,0)-B ．(1,0)-C ．(,0)-∞D ．[1,)-+∞【答案】A【解析】根据12xy ⎛⎫= ⎪⎝⎭单调递减可知()f x 单调递减，从而得到一次函数单调递减及分段处函数值的大小关系，由此求得结果. 【详解】12xy ⎛⎫= ⎪⎝⎭在0x ≤时单调递减 y ax a ∴=-在0x >时单调递减 0a ∴<又()f x 在R 上单调递减 012a ⎛⎫∴≥- ⎪⎝⎭，即1a ≥- 综上所述：[)1,0a ∈- 本题正确选项：A 【点睛】本题考查根据分段函数的单调性求解参数范围的问题，易错点是忽略分段处的函数值的大小关系，属于常考题型.9．已知()f x ，()g x 分别是定义在R 上的偶函数和奇函数，若()()12x f x g x ++=，则()1g -= A ．32-B ．32C ．52D ．52-【答案】A【解析】根据奇偶性可得()()12x f x g x -+-=，构造方程组求得()g x 解析式，代入1x =-即可求得结果.【详解】()(),f x g x Q 分别为R 上的偶函数和奇函数 ()()()()12x f x g x f x g x -+∴-+-=-=又()()12x f x g x ++= ()()111222x x g x +-+∴=- ()()1311422g ∴-=⨯-=- 本题正确选项：A 【点睛】本题考查函数值的求解问题，涉及到构造函数法求解函数解析式、函数奇偶性的应用等知识.10．函数113()934x x f x --⎛⎫=-++ ⎪⎝⎭在[)1,-+∞上的值域为（） A ．3,34⎛⎫⎪⎝⎭B ．3,34⎡⎤-⎢⎥⎣⎦C ．3,34⎡⎤⎢⎥⎣⎦D ．(,3]-∞【答案】C【解析】令13xt ⎛⎫= ⎪⎝⎭换元得23()3(03)4g t t t t =-++<…,再根据二次函数的值域求解方法求解即可. 【详解】1213113()9334334x x xx f x --⎛⎫⎛⎫⎛⎫=-++=-+⨯+ ⎪⎪ ⎪⎝⎭⎝⎭⎝⎭, 令13xt ⎛⎫= ⎪⎝⎭,因为[1,)x ∈-+∞,所以(0,3]t ∈,原函数的值域等价于函数2233()33(03)42g t t t t t ⎛⎫=-++=--+< ⎪⎝⎭…的值域,所以3(),34f x ⎡⎤∈⎢⎥⎣⎦. 故选：C 【点睛】本题主要考查了与二次函数有关的复合函数问题,利用换元法再根据二次函数的图像性质求解值域即可.属于基础题型.11．已知定义在R 上的函数()f x 满足()()3221f x f x -=-,且()f x 在[1, )+∞上单调递增,则（） A ．()()()0.31.130. 20.54f f log f <<B ．()()()0.31.130. 240.5f f f log <<C ．()()()1.10.3340.20.5f f f log <<D ．()()()0.31.130.50.24f log f f <<【答案】A【解析】由已知可得()f x 的图象关于直线1x =对称.因为0.3 1.130.21log 0.5141-<-<-，又()f x 在[1,)+∞上单调递增,即可得解.【详解】解：依题意可得,()f x 的图象关于直线1x =对称. 因为()()()0.31.1330.20,1,0.5 2 1,,044,8log log ∈=-∈-∈,则0.31.130.21log 0.5141-<-<-，又()f x 在[1,)+∞上单调递增, 所以()()()0.31.130.20.54f f log f <<.故选:A. 【点睛】本题考查了函数的对称性及单调性，重点考查了利用函数的性质判断函数值的大小关系，属中档题.12．已知函数()222,0,log ,0,x x x f x x x ⎧--≤⎪=⎨>⎪⎩若1234x x x x <<<，且()()()()1234f x f x f x f x ===，现有结论：①121x x +=-；②341x x =；③412x <<；④.123401x x x x <<这四个结论中正确的个数是( ) A ．1 B ．2C ．3D ．4【答案】C【解析】画出函数()f x 的图像，根据二次函数的对称性、值域和对数函数运算，结合图像，判断四个结论的正确性. 【详解】画出函数()f x 的大致图象如下图.得出122x x +=-，341x x =，故①错误②正确；由图可知412x <<，故③正确；因为121x -<<-，()()()22121111122110,1x x x x x x x =--=--=-++∈，所以()1234120,1x x x x x x =∈，故④正确.故选C. 【点睛】本小题主要考查分段函数的图像与性质，考查二次函数的对称性和值域，考查对数运算，考查数形结合的数学思想方法，属于基础题.二、填空题13．已知函数2(2)1,0,()2,0,f x x f x x x -+>⎧=⎨+⎩…则(5)f =_______. 【答案】6【解析】根据分段函数的分段定义域分析代入(5)f 直至算出具体函数值即可. 【详解】由题意知2(5)(3)1(1)2(1)3(1)236f f f f =+=+=-+=-++=. 故答案为：6【点睛】本题主要考查分段函数求值的问题,属于基础题型. 14．若幂函数()222()22m mf x m m x -=+-在(0,)+∞上为减函数，则m =_______.【答案】1【解析】根据幂函数的定义可知2221m m +-=,再代入指数中判断是否为减函数即可. 【详解】由已知2221m m +-=,解得3m =-或1m =.当3m =-时,15()f x x =在(0,)+∞上为增函数,不符合题意；当1m =时,1()f x x -=在(0,)+∞上为减函数,符合题意.故答案为：1 【点睛】本题主要考查根据幂函数求解参数的问题,同时也考查了幂函数的单调性.属于基础题型.15．设函数2log ,0,()2,0,xx x f x x ⎧>=⎨⎩…则函数2()3()8()4g x f x f x =-+的零点个数是_______. 【答案】5【解析】先求解关于()f x 的方程23()8()40f x f x -+=的根,再根据所得的根2()3f x =和()2f x =与原函数2log ,0,()2,0,x x x f x x ⎧>=⎨⎩…数形结合进行交点个数的求解即可.【详解】令函数2()3()8()4[3()2][()2]0g x f x f x f x f x =-+=--=则2()3f x =或者()2f x =,又函数2log ,0,()2,0xx x f x x ⎧>=⎨⎩…的图像如图所示：由图可得方程2()3f x =和()2f x =共有5个根,即函数2()3()8()4g x f x f x =-+有5个零点. 故答案为：5 【点睛】本题主要考查了复合函数零点问题,重点是先求出关于()f x 的方程的根,再将所求得的根看成纵坐标从而数形结合求与原函数的交点个数即可.属于中等题型. 16．用max{,,}a b c 表示,,a b c 三个数中的最大值，设{}2()max ln ,1,4(0)f x x x x x x =--->，则()f x 的最小值为_______.【答案】0【解析】将{}2()max ln ,1,4(0)f x x x x x x =--->中三个函数的图像均画出来,再分析取最大值的函数图像,从而求得最小值. 【详解】分别画出ln y x =-,1y x =-,24y x x =-的图象,取它们中的最大部分,得出()f x 的图象如图所示,故最小值为0.故答案为：0 【点睛】本题主要考查数形结合的思想与常见函数的图像等,需要注意的是在画图过程中需要求解函数之间的交点坐标从而画出准确的图像,属于中等题型.三、解答题 17．化简或求值．（10,0)a b >>；（2）11232012720.148π-⎛⎫⎛⎫+-+ ⎪ ⎪⎝⎭⎝⎭．【答案】（1）1132a b ；（2）101【解析】（1）将根式运算化成指数幂运算，根据指数幂的运算法则可求得结果；（2）根据指数幂运算的运算法则求值即可. 【详解】（1）原式()()112333213121133221213322b a ab b a a b a b a b a b ab --⎛⎫ ⎪⨯⎝⎭====⎛⎫⨯ ⎪⎝⎭（2）原式1123329133311001101410222-⎡⎤⎛⎫⎛⎫⎛⎫=+-+=+-+=⎢⎥ ⎪ ⎪⎪⎝⎭⎝⎭⎝⎭⎢⎥⎣⎦【点睛】本题考查指数幂运算法则化简求值的问题，属于基础题. 18．已知集合{|34}A x x =-≤<，{|131}B x a x a =+<-…. （1）当2a =时，求A B ；（2）若AB B =，求a 的取值范围.【答案】（1）{|35}A B x x ⋃=-剟；（2）5,3⎛⎫-∞ ⎪⎝⎭【解析】(1)代入2a =,再计算AB 即可.(2)利用集合的包含关系列出对应的端点的不等式再求解即可. 【详解】(1)因为2a =,所以{|35}B x x =<…,因为{|34}A x x =-<…,所以{|35}A B x x ⋃=-剟. (2)因为AB B =,所以B A ⊆.当B =∅时,B A ⊆符合题意,此时131a a +-…,即1a …. 当B =∅时,因为B A ⊆,所以131,13,314,a a a a +<-⎧⎪+-⎨⎪-<⎩… 解得513a <<. 综上,a 的取值范围是5,3⎛⎫-∞ ⎪⎝⎭.【点睛】本题主要考查集合的基本运算,同时注意B A ⊆时需要考虑B =∅的情况即可.属于中等题型.19．2019年，随着中国第一款5G 手机投入市场，5G 技术已经进入高速发展阶段.已知某5G 手机生产厂家通过数据分析，得到如下规律：每生产手机()010x x ≤≤万台，其总成本为()G x ，其中固定成本为800万元，并且每生产1万台的生产成本为1000万元（总成本=固定成本+生产成本），销售收入()R x 万元满足()24004200,05,20003800,510.x x x R x x x ⎧-+≤≤=⎨-<≤⎩（1）将利润()f x 表示为产量x 万台的函数；（2）当产量x 为何值时，公司所获利润最大？最大利润为多少万元？【答案】(1) ()24003200800,05,10004600,510.x x x f x x x ⎧-+-≤≤=⎨-<≤⎩(2) 当产量为4万台时，公司所获利润最大，最大利润为5600万元.【解析】（1）先求得总成本函数()G x ，然后用()()()f x R x G x =-求得利润()f x 的函数表达式.（2）用二次函数的最值的求法，一次函数最值的求法，求得当产量x 为何值时，公司所获利润最大，且求得最大利润.【详解】（1）由题意得()8001000G x x =+.因为()24004200,05,20003800,510.x x x R x x x ⎧-+≤≤=⎨-<≤⎩所以()()()24003200800,05,10004600,510.x x x f x R x G x x x ⎧-+-≤≤=-=⎨-<≤⎩ （2）由（1）可得，当05x ≤≤时，()()240045600f x x =--+.所以当4x =时，()max 5600f x =（万元）当510x <≤时，()10004600f x x =-，()f x 单调递增，所以()()105400f x f ≤=（万元）.综上，当4x =时，()max 5600f x =（万元）.所以当产量为4万台时，公司所获利润最大，最大利润为5600万元.【点睛】本小题主要考查分段函数模型在实际生活中的运用，考查二次函数、一次函数最值有关问题的求解，属于基础题.20．已知二次函数()f x 满足(0)2f =，且(1)()23f x f x x +-=+.（1）求()f x 的解析式；（2）设函数()()2h x f x tx =-，当[1,)x ∈+∞时，求()h x 的最小值；（3）设函数12()log g x x m =+，若对任意1[1,4]x ∈，总存在2[1,4]x ∈，使得()()12f x g x >成立，求m 的取值范围.【答案】（1）2()22f x x x =++；（2）min 252,2,()21, 2.t t h x t t t -⎧=⎨-++>⎩…；（3）7m < 【解析】(1) 根据二次函数()f x ,则可设2()(0)f x ax bx c a =++≠,再根据题中所给的条件列出对应的等式对比得出所求的系数即可.(2)根据(1)中所求的()f x 求得2()2(1)2h x x t x =+-+,再分析对称轴与区间[1,)+∞的位置关系进行分类讨论求解()h x 的最小值即可.(3)根据题意可知需求()f x 与()g x 在区间上的最小值.再根据对数函数与二次函数的单调性求解最小值即可.【详解】(1)设2()(0)f x ax bx c a =++≠.①∵(0)2f =,∴(0)2f c ==,又∵(1)()1f x f x x +-=+,∴22(1)(1)2223a x b x ax bx x ++++---=+,可得223ax a b x ++=+,∴21,3,a ab =⎧⎨+=⎩解得12a b =⎧⎨=⎩，，即2()22f x x x =++. (2)由题意知,2()2(1)2h x x t x =+-+,[1,)x ∈+∞,对称轴为1x t =-.①当11t -…,即2t …时,函数h(x)在[1,)+∞上单调递增,即min ()(1)52h x h t ==-；②当11t ->,即2t >时,函数h(x)在[1,1)t -上单调递减,在[1,)t -+∞上单调递增,即2min ()(1)21h x h t t t =-=-++.综上,min 252,2,()21, 2.t t h x t t t -⎧=⎨-++>⎩… (3)由题意可知min min ()()f x g x >,∵函数()f x 在[1,4]上单调递增,故最小值为min ()(1)5f x f ==,函数()g x 在[1,4]上单调递减,故最小值为min ()(4)2g x g m ==-+,∴52m >-+,解得7m <.【点睛】本题主要考查利用待定系数法求解二次函数解析式的方法,二次函数对称轴与区间关系求解最值的问题,以及恒成立和能成立的问题等.属于中等题型.21．已知函数()21()22x x f x t t e e =---是定义域为R 的奇函数. （1）求t 的值；（2）判断()f x 在R 上的单调性，并用定义证明；（3）若函数221()2()x x g x e kf x e=+-在[0,)+∞上的最小值为-2，求k 的值. 【答案】（1）3t =或1t =-；（2）增函数，证明见解析；（3）2k =【解析】(1)由()f x 是定义域为R 的奇函数,利用(0)0f =求解得出t 的值.(2) 设12x x <,再计算()()12f x f x -的正负进行单调性的判断即可.(3)代入1()x x f x e e =-至221()2()x x g x e kf x e =+-中,令1()x x f x u e e=-=进行换元,再利用二次函数的方法分析最值求参数即可.【详解】(1)因为()f x 是定义域为R 的奇函数,所以(0)0f =,即2(0)230f t t =--=,解得3t =或1t =-, 可知1()x x f x e e=-,经检验,符合题意. (2) ()f x 在R 上单调递增.证明如下：设12x x <,则()()()2121212121111e e e e 1e e e e x x x x x x x x f x f x ⎛⎫-=--+=-+ ⎪⋅⎝⎭. 因为12x x <,所以120e e x x <<,所以12e e 0x x -<,12110e ex x +>⋅,可得()()120f x f x -<. 因为当12x x <时,有()()120f x f x -<,所以()f x 在R 单调递增.(3)由(1)可知2221111()e 2e e 2e 2e e e e x x x x x x x x g x k k ⎛⎫⎛⎫⎛⎫=+--=---+ ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭, 令1()e ex x u f x ==-,则2()22h u u ku =-+, 因为()f x 是增函数,且0x …,所以(0)0u f =…. 因为221()e 2()ex x g x kf x =+-在[0,)+∞上的最小值为-2, 所以()h u 在[0,)+∞上的最小值为-2.因为222()22()2h u u ku u k k =-+=-+-,所以当0k …时,2min ()()22h u h k k ==-=-,解得2k =或2k =-(舍去)；当k 0<时,22min ()(0)222h u h k k ==+-=≠-,不合题意,舍去.综上可知,2k =.【点睛】本题主要考查奇函数的性质,单调性的证明以及换元法求解二次函数的复合函数问题的最值与范围问题.属于中等题型.22．已知函数2()(2)f x x m x m =+--，()()f x g x x=，且函数(2)y f x =-是偶函数.（1）求()g x 的解析式；. （2）若不等式(ln )ln 0g x n x -…在21,1e ⎡⎫⎪⎢⎣⎭上恒成立，求n 的取值范围；（3）若函数()()()22222log 49log 4y g x k x =++⋅-+恰好有三个零点，求k 的值及该函数的零点.【答案】（1）6()4(0)g x x x x =-+≠；（2）52n -…；（3）6k =，该函数的零点为0，2-，2.【解析】(1)根据(2)y f x =-是偶函数求得表达式算出m 的值,进而求得()g x 的解析式即可.(2)换元令ln x t =,再求解(ln )ln g x n x -的最小值,化简利用二次不等式进行范围运算即可.(3)换元令()22log 4x p +=,结合复合函数的零点问题,分析即可.【详解】(1)∵2()(2)f x x m x m =+--,∴22(2)(2)(2)(2)(6)83f x x m x m x m x m -=-+---=+-+-.∵(2)y f x =-是偶函数,∴60m -=,∴6m =.∴2()46f x x x =+-, ∴6()4(0)g x x x x=-+≠. (2)令ln x t =,∵21,1x e ⎡⎫∈⎪⎢⎣⎭, ∴[2,0)t ∈-,不等式(ln )ln 0g x n x -…在21,1e ⎡⎫⎪⎢⎣⎭上恒成立,等价于()0g t nt -…在[2,0)t ∈-上恒成立,∴2264646411t t n t t t t t-+=-+=-++…. 令2641z t t =-++,1s t =,则12s -…,256412z s s =-++-…,∴52n -…. (3)令()22log 4x p +=,则2p …,方程()()()22222log 490log 4g x k x ++⋅-=+可化为2()90g p k p +⋅-=,即62490k p p p -++-=,也即25(26)0p p k p-+-=. 又∵方程()()()22222log 490log 4g x k x ++⋅-=+有三个实数根, ∴25(26)0p p k p-+-=有一个根为2,∴6k =. ∴2560p p -+=,解得2p =或3p =.由()22log 42x +=,得0x =,由()22log 43x +=,得2x =±,∴该函数的零点为0,-2,2.【点睛】本题主要考查了二次函数的解析式的求解方法以及换元法求复合函数的应用,包括二次函数的范围问题等与函数零点的问题.属于难题.。

2020学年高一英语上学期第一次月考试题(含解析)

2019学年度上学期第一次月考高一英语试卷本试卷分：120分测试时间：100分钟第I卷第一部分阅读理解 (共两节，满分40分)第一节(共15小题;每小题2分，满分30分)阅读下列短文，从每题所给的四个选项(A, B, C和D)中.选出最佳选项.AA couple from Miami, Bill and Simone Butler, spent sixty –six days in a life-raft (救生艇) in the seas of Central America after their boat sank.Twenty-one days after they left Panama in their boat, Simony, they met some whales (鲸鱼). “They started to hit the side of the boat,” said Bill, “and then suddenly we heard water.” Two minutes later, the boat was sinking. They jum ped into the life-raft and watched the boat go under the water.For twenty days they had tins of food, biscuits, and bottles of water. They also had a fishing-line and a machine to make salt water into drinking water— two things which saved their lives. They caught eight to ten fish a day and ate them raw (生的). Then the line broke. “So we had no more fish until something very strange happened. Some sharks (鲨鱼) came to feed, and the fish under the raft were afraid and came to the surface. I caught them with my hands.”About twenty ships passed them, but no one saw them. After fifty days at sea their life-raft was beginning to break up. Then suddenly it was all over. A fishing boat saw them and picked them up. They couldn’t stand up. So the captain carried the m onto his boat and took them to Costa Rica. Their two months at sea was over.1. Bill and Simone were traveling ______ when they met some whales.A. in a life-raftB. in MiamiC. in SimonyD. in Panama2. During their days at sea, ______ saved their lives.A. tins of food and bottles of waterB. a fishing-line and a machineC. whales and sharksD. Twenty passing ships3. After their boat sank, the couple ______.A. jumped into the life-raftB. heard waterC. watched the boat go under waterD. stayed in the life-raft4. When they saw the fishing boat which later picked them up, ________.A. they were too excited to stand upB. they couldn’t wait to climb onto the boatC. their life –raft was beginning to break upD. they knew their two months at sea would be over【答案】1. C 2. B 3. D 4. D【解析】本文是一篇记叙文。

部编版2019---2020学年度下学期小学五年级语文期末测试卷及答案

最新部编版2019---2020学年度下学期小学五年级语文期末测试卷及答案-CAL-FENGHAI.-(YICAI)-Company One12最新部编版2019---2020学年度下学期小学五年级语文期末测试卷及答案（满分：100分时间： 90分钟）题号一二三四五六七八九十总分得分一、选择题。

（共12分）1.下面加点字的读音全都正确的一项是（）。

A.提供．（ɡòn ɡ）—供．认（ɡōn ɡ）晃．眼（hu ǎn ɡ）—摇头晃．脑（hu àn ɡ）B.停泊．（b ó）—血泊．（p ō）监．牢（ji ān ）—国子监．（ji àn ）C.丈夫．（f ū）—逝者如斯夫．（f ū）喧哗．（hu á）—哗．哗流水（hu á）2.下面加点的字书写全都正确的一项是（）。

A.师傅．副．业负．担附．庸 B.俊．马竣．工严骏．峻．杰 C.树稍．船艄．捎．话梢．胜一筹3.下面句子中加点的字哪一项解释有误（） A.其人弗能应．也。

应：应答。

B.果．有杨梅。

果：果然。

C.未闻．孔雀是夫子家禽。

闻：听说。

4.下列句子中没有语病的一项是（）。

A.此次家长会上，学校领导认真总结并听取了家委会成员的建议B.今天全班都来参加毕业典礼彩排，只有龙一鸣一人请假C.中国为了实现半导体国产化这一夙愿，展现出毫不松懈的态度5.下面三幅书法作品中，哪一幅是怀素草书《千字文》（局部）（）A. B. C.6.对这幅漫画的寓意理解正确的一项是（）。

A.有些医生自己生病了，却不愿意进行急救B.讽刺少数医生良心出了问题却不承认，不改正C.有些人总喜欢把没有生病的人送进抢救室二、用修改符号修改下面的一段话。

（共2分）马老师多么和蔼可亲呀！上课时，他教我们耐心地写字的方法；下课时，他常常和我们在一起。

昨天下午，他给淘淘补了一天的课，他非常感动马老师。

山西省运城市2024届高三上学期期末调研测试数学试题含答案解析

运城市2023-2024学年第一学期期末调研测试高三数学试题考试时间120分钟．答案一律写在答题卡上.注意事项：1.答题前，考生务必先将自己的姓名、准考证号填写在答题卡上，认真核对条形码上的姓名、准考证号，并将条形码粘贴在答题卡的指定位置上.2.答题时使用0.5毫米的黑色中性（签字）笔或碳素笔书写，字体工整、笔迹清楚.3.请按照题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效.4.保持卡面清洁，不折叠，不破损.一、单项选择题：本题共8小题，在每小题所给的四个选项中，只有一项是符合题目要求的.1.复数i12i z =-，则z 等于（）A .1B.C.2D.552.设x ∈R ，则“03x ≤≤”是“02xx ≤-”的（）A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件3.已知e ()1exaxf x =-是奇函数，则=a （）A.2- B.1- C.2D.14.第33届夏季奥运会预计2024年7月26日至8月11日在法国巴黎举办，这届奥运会将新增2个竞赛项目和3个表演项目．现有三个场地A ，B ，C 分别承担这5个新增项目的比赛，且每个场地至少承办其中一个项目，则不同的安排方法有（）A.150种B.300种C.720种D.1008种5.设0.814a ⎛⎫= ⎪⎝⎭，0.3log 0.2b =，0.3log 0.4c =，则a ，b ，c 的大小关系为（）A.a b c >>B.b a c >>C.c a b >>D.b c a>>6.已知双曲线2222:1(0,0)x y C a b a b-=>>的左、右焦点分别为1F ，2F ，A 为C 的右顶点，以12F F 为直径的圆与C 的一条渐近线交于P ，Q 两点，且3π4PAQ ∠=，则双曲线C 的离心率为（）A.B.213C.D.37.已知等差数列{}n a 中，97π12a =，设函数44()cos sin cos 1f x x x x x =---，记()n n y f a =，则数列{}n y 的前17项和为（）A.51- B.48- C.17- D.08.已知四棱锥P ABCD -的底面是边长为4的正方形，3PA PB ==，45PAC ∠= ，则直线PD 与平面ABCD 夹角的正弦值为（）A.31717B.21717 C.53D.23二、多项选择题：本题共4小题，在每小题给出的选项中，有多项符合题目要求.9.关于下列命题中，说法正确的是（）A.若事件A 、B 相互独立，则()()P A B P A =B.数据63，67，69，70，74，78，85，89，90，95的第45百分位数为78C.已知()0.65P A =，()0.32P AB =，则()0.33P AB =D.已知~(0,1)N ξ，若(1)P p ξ≤=，则()1102P p ξ-≤≤=-10.已知函数()ππtan 124f x x ⎛⎫=++ ⎪⎝⎭，则（）A.()f x 的一个周期为2B.()f x 的定义域是1,Z 2x x k k ⎧⎫≠+∈⎨⎬⎩⎭C.()f x 的图象关于点1,12⎛⎫⎪⎝⎭对称D.()f x 在区间[]1,2上单调递增11.如图，正方体1111ABCD A B C D -的棱长为2，P 是直线1A D 上的一个动点，则下列结论中正确的是（）A.1C P 的最小值为B.PB PC +的最小值为C.三棱锥1B ACP -的体积为83D.以点B 为球心，263为半径的球面与面1AB C 在正方体内的交线长为33π12.已知抛物线()220x py p =>的焦点为F ，过点F 的直线l 与抛物线交于A 、B 两点，与其准线交于点D ，F 为AD 的中点，且6AF =，点M 是抛物线上 BA间不同于其顶点的任意一点，抛物线的准线与y 轴交于点N ，抛物线在A 、B 两点处的切线交于点T ，则下列说法正确的是（）A.抛物线焦点F 的坐标为()0,3B.过点N 作抛物线的切线，则切点坐标为33,24⎛⎫± ⎪⎝⎭C.在FMN 中，若MN t MF =，t ∈R ，则tD.2TFAF BF=⋅三、填空题：本题共4小题.13.已知向量(2,1)a =- ，(1,)b λ=，若()a a b ⊥- ，则λ=____________.14.512x x ⎛⎫- ⎪⎝⎭的展开式中3x 的系数为______.15.过原点的动直线l 与圆22410x y x +-+=交于不同的两点A ，B .记线段AB 的中点为P ，则当直线l 绕原点转动时，动点P 的轨迹长度为____________.16.设12,x x 是函数21()e 1,()2xf x ax a =-+∈R 的两个极值点，若213x x ≥，则a 的范围为____________.四、解答题：本题共6小题，解答应写出文字说明、证明过程或演算步骤.17.在ABC 中，角A ，B ，C 的对边分别是a ，b ，c ，且2cos 2b C a c =-.（1）求角B 的大小；（2）若b =，D 为AC 边上的一点，3BD =，且______________，求ABC 的面积．①BD 是B ∠的平分线；②D 为线段AC 的中点.（从①，②两个条件中任选一个，补充在上面的横线上并作答）.18.已知递增的等比数列{}n a 满足22a =，且1a ，2a ，31a -成等差数列.（1）求{}n a 的通项公式；（2）设()()112n n n a n b a n ⎧-⎪=⎨⎪⎩为奇数为偶数，求数列{}n b 的前20项和.19.如图，在圆柱体1OO 中，1OA =，12O O =，劣弧11A B 的长为π6，AB 为圆O的直径．（1）在弧AB 上是否存在点C （C ，1B 在平面11OAAO 同侧），使1BC AB ⊥，若存在，确定其位置，若不存在，说明理由；（2）求二面角111A O B B --的余弦值．20.某学校进行趣味投篮比赛，设置了A ，B 两种投篮方案.方案A ：罚球线投篮，投中可以得2分，投不中得0分；方案B ：三分线外投篮，投中可以得3分，投不中得0分.甲、乙两位员工参加比赛，选择方案A 投中的概率都为()0001p p <<，选择方案B 投中的概率都为13，每人有且只有一次投篮机会，投中与否互不影响.（1）若甲选择方案A 投篮，乙选择方案B 投篮，记他们的得分之和为X ，()334P X ≤=，求X 的分布列；（2）若甲、乙两位员工都选择方案A 或都选择方案B 投篮，问：他们都选择哪种方案投篮，得分之和的均值较大？21.已知椭圆2222:1(0)x y C a b a b+=>>的焦距为12,A A ，上顶点为B ，且1tan 2A BO ∠=．（1）求椭圆C 的方程；（2）若过2A 且斜率为k 的直线l 与椭圆C 在第一象限相交于点Q ，与直线1A B 相交于点P ，与y 轴相交于点M ，且223PA MQ QA MP =．求k 的值．22.已知函数2()ln x f x e a x =-，函数ln ()m xg x n x+=+的图象在点(1,(1))g 处的切线方程为30y -=.（1）讨论()f x 的导函数()f x '的零点的个数；（2）若0a ≤，且()f x 在[),e +∞上的最小值为2e e ，证明：当0x >时，()()f x g x ≥.运城市2023-2024学年第一学期期末调研测试高三数学试题考试时间120分钟．答案一律写在答题卡上.注意事项：1.答题前，考生务必先将自己的姓名、准考证号填写在答题卡上，认真核对条形码上的姓名、准考证号，并将条形码粘贴在答题卡的指定位置上.2.答题时使用0.5毫米的黑色中性（签字）笔或碳素笔书写，字体工整、笔迹清楚.3.请按照题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效.4.保持卡面清洁，不折叠，不破损.一、单项选择题：本题共8小题，在每小题所给的四个选项中，只有一项是符合题目要求的.1.复数i12iz=-，则z等于（）A.1B. C.2D.5【答案】D【解析】【分析】利用复数代数形式的乘除运算化简，然后直接利用复数模的公式求解即可.【详解】结合题意可得：()()()i12ii2i2i12i12i12i555 z+-+-====+ --+，所以55z==.故选：D.2.设x∈R，则“03x≤≤”是“02xx≤-”的（）A.充分不必要条件B.必要不充分条件C.充要条件D.既不充分也不必要条件【答案】B【解析】【分析】解分式不等式，求出解集，根据真子集关系得到答案.【详解】()20220x xxx x⎧-≤≤⇒⎨--≠⎩，解得02x≤<，由于02x≤<是03x≤≤的真子集，故03x≤≤是02xx≤-的必要不充分条件.故选：B3.已知e()1exaxf x=-是奇函数，则=a（）A.2-B.1-C.2D.1【答案】C 【解析】【分析】根据()()f x f x -=-得到方程，求出2a =.【详解】由题意得()()f x f x -=-，即e e1e 1ex x ax ax--=---，所以e e e 11eax x xax ax-=---，故e e ax x x -=，所以ax x x -=，解得2a =.故选：C4.第33届夏季奥运会预计2024年7月26日至8月11日在法国巴黎举办，这届奥运会将新增2个竞赛项目和3个表演项目．现有三个场地A ，B ，C 分别承担这5个新增项目的比赛，且每个场地至少承办其中一个项目，则不同的安排方法有（）A.150种B.300种C.720种D.1008种【答案】A 【解析】【分析】分3,1,1和2,2,1两种情况，结合排列组合知识进行求解.【详解】若三个场地分别承担3,1,1个项目，则有3113521322C C C A 60A ⋅=种安排，若三个场地分别承担2,2,1个项目，则有2213531322C C C A 90A ⋅=种安排，综上，不同的安排方法有6090150+=种.故选：A5.设0.814a ⎛⎫= ⎪⎝⎭，0.3log 0.2b =，0.3log 0.4c =，则a ，b ，c 的大小关系为（）A.a b c >> B.b a c >> C.c a b>> D.b c a>>【答案】D 【解析】【分析】首先将对数式和指数式与临界值比较，再判断大小关系.【详解】 1.61122a ⎛⎫=< ⎪⎝⎭，即102a <<，0.3log 0.21b =>，即1b >，因为20.40.3<，所以20.30.3log 0.4log 0.31>=，即0.31log 0.42>，且0.30.3log 0.4log 0.31<=，则112c <<，所以b c a >>.故选：D6.已知双曲线2222:1(0,0)x y C a b a b-=>>的左、右焦点分别为1F ，2F ，A 为C 的右顶点，以12F F 为直径的圆与C 的一条渐近线交于P ，Q 两点，且3π4PAQ ∠=，则双曲线C 的离心率为（）A.B.213C.D.3【答案】C 【解析】【分析】联立圆与渐近线方程，得到()(),,,P a b Q a b --，进而得到π4OAQ ∠=，利用直线斜率得到方程，求出2b a =，得到离心率.【详解】由题意得，以12F F 为直径的圆的方程为222x y c +=，(),0A a ，渐近线方程为b y x a=±，联立222x y c by xa ⎧+=⎪⎨=⎪⎩，解得x a =±，不妨令()(),,,P a b Q a b --，故π2OAP ∠=，因为3π4PAQ ∠=，所以3πππ424OAQ ∠=-=，所以0tan 1π4AQ b k a a --===--，解得2b a =，故离心率c e a ===.故选：C7.已知等差数列{}n a 中，97π12a =，设函数44()cos sin 3cos 1f x x x x x =---，记()n n y f a =，则数列{}n y 的前17项和为（）A.51- B.48- C.17- D.0【答案】C 【解析】【分析】根据三角恒等变换化简()f x 的表达式，判断其图象关于点7π(,1)12-成中心对称，结合等差数列性质可得11721697π2212a a a a a +=+===⨯ ，从而得117216810()()()()()()2f a f a f a f a f a f a +=+==+=- ，由此即可求得答案.【详解】由题意知44()cos sin 3cos 1f x x x x x =---()()2222cos sin cos sin 321x x x x x =+--πcos 23212cos 213x x x ⎛⎫=-=+- ⎪⎝⎭，当7π12x =时，7ππ2cos 20123⎛⎫⨯+= ⎪⎝⎭，即()f x 关于点7π(,1)12-成中心对称，由于等差数列{}n a 中，97π12a =，故11721697π2212a a a a a +=+===⨯ ，故117216810()()()()()()2(1)2f a f a f a f a f a f a +=+==+=⨯-=- ，97ππ()2cos 211123f a ⎛⎫=⨯+-=- ⎪⎝⎭，故数列{}n y 的前17项和为1217()()()f a f a f a +++[][][]1172168109()()()()()()()f a f a f a f a f a f a f a =+++++++ 8(2)117=⨯--=-，故选：C8.已知四棱锥P ABCD -的底面是边长为4的正方形，3PA PB ==，45PAC ∠= ，则直线PD 与平面ABCD 夹角的正弦值为（）A.31717B.21717 C.53D.23【答案】B 【解析】【分析】首先求AC ，再作出PO ⊥平面ABCD ，根据垂直关系，以及等面积转化，确定垂足点O 的位置，以及PO ，再求线面角的正弦值.【详解】如图，由题意可知，AC =PAC △中，根据余弦定理可知293223172PC =+-⨯⨯=，则PC =过点P 作PO ⊥平面ABCD ，OM AB ⊥，连结PM ，ON BC ⊥，连结PN ，因为PO ⊥平面ABCD ，AB ⊂平面ABCD ，所以PO AB⊥OM PO O = ，且,OM PO ⊂平面POM所以AB ⊥平面POM ，PM ⊂平面POM ，所以AB PM ⊥，又因为3PA PB ==，所以2MA MB ==，同理PN BC ⊥，PBC 中，916171cos 2343PBC +-∠==⨯⨯，则22sin 3PBC ∠=，根据等面积公式，11344232PN ⨯⨯⨯=⨯⨯，所以PN =，3NC ===，OD ==又2ON MB ==，所以2PO ==，则PD ==直线PD 与平面ABCD 夹角的夹角为PDO ∠，sin17PO PDO PD ∠===.故选：B【点睛】关键点点睛：本题的关键是确定垂足O 的位置，以及垂直关系的转化.二、多项选择题：本题共4小题，在每小题给出的选项中，有多项符合题目要求.9.关于下列命题中，说法正确的是（）A.若事件A 、B 相互独立，则()()P A B P A =B.数据63，67，69，70，74，78，85，89，90，95的第45百分位数为78C .已知()0.65P A =，()0.32P AB =，则()0.33P AB =D.已知~(0,1)N ξ，若(1)P p ξ≤=，则()1102P p ξ-≤≤=-【答案】AC 【解析】【分析】根据独立事件的乘法公式以及条件概率的概率公式可判断A ；根据百分位数的定义求出第45百分位数判断B ；根据对立事件的概率公式以及条件概率的概率公式可判断C ；根据正态分布的对称性可判断D.【详解】对于A ，若事件A 、B 相互独立，则()()()P AB P A P B =,而()()()()()()()P AB P A P B P A B P A P B P B ===，A 正确；对于B ，数据63，67，69，70，74，78，85，89，90，95已为从小到大排列，共10个数，又45%10 4.5⨯=，故第45百分位数为第5个数74，B 错误；对于C ，由于()0.65P A =，()0.32P AB =，故()03232()()06565P BA .P B |A P A .===，则3233()1()16565P B |A P B |A =-=-=，故()()33(|)()0.650.3365P B A P A P AB P BA ====⨯，C 正确；对于D ，由于~(0,1)N ξ，(1)P p ξ≤=，故(1)1P p ξ>=-，故(1)(1)1P P p ξξ<-=>=-，故()11(1)(1)221102P p p P ξξ<-=--≤≤==---，D 错误，故选：AC10.已知函数()ππtan 124f x x ⎛⎫=++ ⎪⎝⎭，则（）A.()f x 的一个周期为2B.()f x 的定义域是1,Z 2x x k k ⎧⎫≠+∈⎨⎬⎩⎭C.()f x 的图象关于点1,12⎛⎫⎪⎝⎭对称D.()f x 在区间[]1,2上单调递增【答案】ACD 【解析】【分析】利用正切函数的图象与性质一一判定选项即可.【详解】对于A ，由()ππtan 124f x x ⎛⎫=++ ⎪⎝⎭可知其最小正周期π2π2T ==，故A 正确；对于B ，由()ππtan 124f x x ⎛⎫=++ ⎪⎝⎭可知πππ1π2,Z 2422x k x k k +≠+⇒≠+∈，故B 错误；对于C ，由()ππtan 124f x x ⎛⎫=++ ⎪⎝⎭可知1πππ2242x x =⇒+=，此时()f x 的图象关于点1,12⎛⎫⎪⎝⎭对称，故C 正确；对于D ，由()ππtan 124f x x ⎛⎫=++⎪⎝⎭可知[]ππ3π5π1,2,2444x x ⎡⎤∈⇒+∈⎢⎣⎦，又tan y x =在π3π,22⎡⎤⎢⎥⎣⎦上递增，显然3π5π,44⎡⎤⊂⎢⎥⎣⎦π3π,22⎡⎤⎢⎥⎣⎦，故D 正确.故选：ACD11.如图，正方体1111ABCD A B C D -的棱长为2，P 是直线1A D 上的一个动点，则下列结论中正确的是（）A.1C P的最小值为B.PB PC +的最小值为C.三棱锥1B ACP -的体积为83D.以点B 为球心，263为半径的球面与面1AB C 在正方体内的交线长为33π【答案】ABD 【解析】【分析】对于选项A ，即求正三角形的高，判断为正确；对于选项B ，将空间问题平面化即可判定为正确；对于选项C ，去一个特殊点，计算其体积，判断为错误；对于选项D ，先求出球与平面的交线，然后判断有多少在正方体内，求出其长度即可.【详解】对于A ，11C A D为边长为的等边三角形，1C P 的最小值即该等边三角形的高，为3cos302== A正确；对于B，如图，将等边1A BD 绕1A D 旋转到与平面11A DCB 共面，显然()min PB PC BC +=====，故B 正确；对于C，当P 在D 上时，1111148223333B ACP B ACD ACD V V S BB --==⋅⋅=⨯=≠ ，故C 错误；对于D，设点B 到平面1AB C 的距离为d ,11B AB C B ABC V V --= ，111133AB C ABC S d S BB ∴⋅=⋅ ，11222222d ∴⨯=⨯⨯⨯，3d =，以点B 为球心，3为半径的球面与面1AB C 在正方体内的交线是以1AB C V 中心为圆心，233==为半径的圆，如图，圆有一部分在正方体外，233OM =，由A 得133OH h ==，cos 2OH MOH OM ∠==，所以45MOH ∠= ，90MON ∠= ，所以有36090313604-⨯=圆周在正方体内部，其长度为12332ππ433⨯⨯=，故D 对.故选：ABD.12.已知抛物线()220x py p =>的焦点为F ，过点F 的直线l 与抛物线交于A 、B 两点，与其准线交于点D ，F 为AD 的中点，且6AF =，点M 是抛物线上 BA间不同于其顶点的任意一点，抛物线的准线与y 轴交于点N ，抛物线在A 、B 两点处的切线交于点T ，则下列说法正确的是（）A.抛物线焦点F 的坐标为()0,3B.过点N 作抛物线的切线，则切点坐标为33,24⎛⎫± ⎪⎝⎭C.在FMN 中，若MN t MF =，t ∈R ，则tD.2TFAF BF=⋅【答案】CD 【解析】【分析】设点,2p D t ⎛⎫-⎪⎝⎭，可得出点A 的坐标，利用抛物线的定义可求得p 的值，可判断A 选项；设切线方程为32y kx =-，将切线方程与抛物线方程联立，由判别式为零求出k 的值，可求得切点的坐标，可判断B 选项；利用抛物线的定义结合B 选项可判断C 选项；证明出AT BT ⊥，FT AB ⊥，结合直角三角形的几何性质可判断D 选项.【详解】对于A 选项，抛物线()220x py p =>的焦点为0,2p F ⎛⎫ ⎪⎝⎭，准线方程为2py =-，设点,2p D t ⎛⎫-⎪⎝⎭，因为F 为线段AD 的中点，则3,2p A t ⎛⎫- ⎪⎝⎭，由抛物线的定义可得32622p p AF p =+==，解得3p =，则30,2F ⎛⎫⎪⎝⎭，A 错；对于B 选项，由A 选项可知，抛物线的方程为26x y =，点30,2N ⎛⎫-⎪⎝⎭，若切线的斜率不存在，则该直线与抛物线26x y =相交，且只有一个交点，不合乎题意，所以，切线的斜率存在，设切线的方程为32y kx =-，联立2326y kx x y⎧=-⎪⎨⎪=⎩可得2690x kx -+=，则236360k ∆=-=，解得1k =±，所以，切点横坐标为33k =±，纵坐标为()2393662k ==，故切点坐标为33,2⎛⎫± ⎪⎝⎭，B 错；对于C 选项，过点M 作ME 与直线32y =-垂直，垂足点为点E ，由抛物线的定义可得FM ME =，1cos MN MN t MFMEMNE===∠，由图可知，当直线MN 与抛物线26x y =相切时，锐角MNE ∠取最大值，此时，t取最大值，由B 选项可知，锐角MNE ∠的最大值为π4，故t的最大值为1πcos 4=，C 对；对于D 选项，设点()11,A x y 、()22,B x y ，若直线AB 的斜率不存在，则直线AB 与抛物线26x y =只有一个交点，不合乎题意，所以，直线AB 的斜率存在，设直线AB 的方程为32y kx =+，联立2632x y y kx ⎧=⎪⎨=+⎪⎩可得2690x kx --=，236360k '∆=+>，由韦达定理可得126x x k +=，129x x =-，对函数26x y =求导得3x y '=，所以，直线AT 的方程为()1113x y y x x -=-，即21136x x x y =-，同理可知，直线BT 的方程为22236x x x y =-，因为1219AT BT x x k k ==-，则AT BT ⊥，联立2112223636x x x y x x x y ⎧=-⎪⎪⎨⎪=-⎪⎩可得121232362x x x k x x y +⎧==⎪⎪⎨⎪==-⎪⎩，即点33,2T k ⎛⎫- ⎪⎝⎭，则()3,3FT k =-，而()()()21212121,,AB x x y y x x k x x =--=-- ，所以，()()2121330FT AB k x x k x x ⋅=---=，则FT AB ⊥，所以，90TBF BTF ATF ∠=-∠=∠ ，由tan tan TBF ATF ∠=∠可得TF AF BFTF=，所以，2TFAF BF =⋅，D 对.故选：CD.【点睛】方法点睛：圆锥曲线中的最值问题解决方法一般分两种：一是几何法，特别是用圆锥曲线的定义和平面几何的有关结论来求最值；二是代数法，常将圆锥曲线的最值问题转化为二次函数或三角函数的最值问题，然后利用基本不等式、函数的单调性或三角函数的有界性等求最值．三、填空题：本题共4小题.13.已知向量(2,1)a =- ，(1,)b λ=，若()a a b ⊥- ，则λ=____________.【答案】7【解析】【分析】运用平面向量垂直及减法、数乘、数量积坐标运算即可.【详解】因为(2,1)a =- ，(1,)b λ= ，所以(3,1)a b λ-=--，因为()a ab ⊥-，所以()()()()23110a a b λ⋅-=-⨯-+⨯-= ，解得7λ=.故答案为：7.14.512x x ⎛⎫- ⎪⎝⎭的展开式中3x 的系数为______.【答案】80-【解析】【分析】根据通项公式中x 的指数为3，列方程解得1r =，从而可得展开式中3x 的系数.【详解】512x x ⎛⎫- ⎪⎝⎭展开式的通项为()5521512r r r rr T C x--+=-⋅⋅(0,1,2,3,4,5)r =，令523-=r ，得1r =，所以展开式中3x 的系数为5115(1)2C --⋅⋅=80-.故答案为：80-【点睛】本题考查了根据通项公式求项的系数，属于基础题.15.过原点的动直线l 与圆22410x y x +-+=交于不同的两点A ，B .记线段AB 的中点为P ，则当直线l 绕原点转动时，动点P 的轨迹长度为____________.【答案】4π3【解析】【分析】根据垂径定理结合圆的定义及动直线过定点两圆位置关系确定P 的轨迹为圆弧计算即可.【详解】由题意可知圆22410x y x +-+=的圆心为()2,0C ，半径为r =，根据圆的性质可知CP l ⊥，则OCP △为直角三角形，即P 在以OC 为直径的圆上，设OC 中点为E ，该圆半径为R ，易知1R EC ==，又线段AB 的中点为P ，则P 在圆22410x y x +-+=的内部，如图所示其轨迹即 FCG.因为CF r ===，易得120FEC ∠= ，则120GEC ∠= ，所以 FCG 的弧长为21204π2π3603R ⨯⨯⨯=.故答案为：4π316.设12,x x 是函数21()e 1,()2xf x ax a =-+∈R 的两个极值点，若213x x ≥，则a 的范围为____________.【答案】23,ln 3⎡⎫+∞⎪⎢⎪⎣⎭【解析】【分析】根据极值点定义可将问题转化为y a =与exy x=有两个不同交点；利用导数可求得单调性，并由此得到()e xg x x=的图象；采用数形结合的方式可确定1201,x x <<<且e a >；假设213x x t ==，由()()12g x g x =可确定3ln 3t =，进而得到()()1223ln 3g x g x ==的值，结合图象可确定a 的取值范围.【详解】由21()e 1,()2xf x ax a =-+∈R ，可得()x f x ax e '=-，因为12,x x 是函数()f x 的两个极值点，所以12,x x 是e 0x ax -=的两根，当0x =时，方程不成立，故12,x x 是exa x=的两根，即y a =与e x y x =的图象有两个交点，令()e ,x g x x =则()()21e xx g x x -'=，当()(),00,1x ∞∈-⋃时，()0g x '<，当()1,x ∞∈+时，()0g x '>，所以()e xg x x =在()(),0,0,1∞-单调递减；在()1,∞+上单调递增.则()e xg x x=图象如下图所示，由图象可知：1201,x x <<<且e a >因为213x x ≥，所以213x x ≥，当213x x =时，不妨令213x x t ==，则13e e 3t tt t=，即13e 3et t =，化简得13e =3ln t =，当213x x =时，()()12ln 3g x g x ====，若213x x ≥，则23ln 3a ≥，即a 的取值范围为23,ln 3∞⎡⎫+⎪⎢⎪⎣⎭.故答案为：,ln 3∞⎡⎫+⎪⎢⎪⎣⎭.【点睛】方法点睛：本题考查根据极值点求解参数范围问题，可将问题转化为已知函数零点(方程根)的个数求参数值(取值范围)的问题，解决此类问题的常用的方法有：（1）直接法：直接求解方程得到方程的根，再通过解不等式确定参数范围；（2）分离参数法：先将参数分离，转化成求函数的值域问题加以解决；（3）数形结合法：先对解析式变形，进而构造两个函数，然后在同一平面直角坐标系中画出函数的图象，利用数形结合的方法求解.四、解答题：本题共6小题，解答应写出文字说明、证明过程或演算步骤.17.在ABC 中，角A ，B ，C 的对边分别是a ，b ，c ，且2cos 2b C a c =-.（1）求角B 的大小；（2）若b =，D 为AC 边上的一点，3BD =，且______________，求ABC 的面积．①BD 是B ∠的平分线；②D 为线段AC 的中点.（从①，②两个条件中任选一个，补充在上面的横线上并作答）.【答案】（1）π3B =（2）选①或选②均为【解析】【分析】（1）利用正弦定理将边化成角，然后利用sin Asin()B C =+进行代换，求出1cos 2B =，即可得出答案；（2）若选①：由等面积法得到)ac a c =+，由余弦定理得到2212a c ac +-=，联立求解即可得出答案；若选②：得()12BD BA BC =+，两边平法化简得2236a c ac ++=，由余弦定理得到2212a c ac +-=，联立求解即可得出答案.【小问1详解】由正弦定理知，2sin cos 2sin sin B C A C =-，sin sin()sin cos cos sin A B C B C B C =+=+ ，代入上式得2cos sin sin 0B C C -=，(0,π)C ∈ ，sin 0C ∴>，1cos 2B ∴=，(0,π)B ∈ ，π3B ∴=.【小问2详解】若选①：由BD 平分ABC ∠得：ABC ABD BCD S S S =+△△△，111sin 3sin 3sin 232626πππac a c ∴=⨯+⨯，即)ac a c =+.在ABC 中，由余弦定理得222π2cos3b ac ac =+-，2212a c ac ∴+-=，联立)2212ac a c a c ac ⎧=+⎪⎨+-=⎪⎩，得2()936ac ac -=，解得12ac =，11sin 12222ABC S ac B ∴==⨯⨯=△若选②：得()12BD BA BC =+，()()222211244BD BA BCBA BA BC BC =+=+⋅+，得2236a c ac ++=，在ABC 中，由余弦定理得222π2cos3b ac ac =+-，2212a c ac ∴+-=，联立22223612a c ac a c ac ⎧++=⎨+-=⎩，得12ac =，113sin 12222ABC S ac B ∴==⨯⨯=△18.已知递增的等比数列{}n a 满足22a =，且1a ，2a ，31a -成等差数列.（1）求{}n a 的通项公式；（2）设()()112n n n a n b a n ⎧-⎪=⎨⎪⎩为奇数为偶数，求数列{}n b 的前20项和.【答案】（1）12n n a -=（2）212323-【解析】【分析】（1）根据等差中项的性质得到13212a a a +-=，然后根据等比数列的通项公式列方程求解即可；（2）利用分组求和的方法计算即可.【小问1详解】设公比为()1q q >，因为1a ，2a ，31a -成等差数列，所以1314a a +-=，所以2250q q+-=，解得2q =或12q =（舍去），所以12n n a -=.【小问2详解】根据题意得()1234192013519246201102b b b b b b a a a a a a a a ++++++=++++-+++++ ()()02418024182222102222=++++-+++++ 101421014-=⨯--212323-=.19.如图，在圆柱体1OO 中，1OA =，12O O =，劣弧11A B 的长为π6，AB 为圆O 的直径．（1）在弧AB 上是否存在点C （C ，1B 在平面11OAAO 同侧），使1BC AB ⊥，若存在，确定其位置，若不存在，说明理由；（2）求二面角111A O B B --的余弦值．【答案】（1）存在，1B C 为圆柱1OO 的母线（2）25117【解析】【分析】（1）1B C 为圆柱1OO 的母线时，证明BC ⊥平面1AB C ，从而得出1BC AB ⊥；（2）以O 为原点，建立空间直角坐标系，利用向量法即可求得二面角111A O B B --的余弦值.【小问1详解】存在，当1B C 为圆柱1OO 的母线时，1BC AB ⊥．证明如下：连接BC ，AC ，1B C ，因为1B C 为圆柱1OO 的母线，所以1B C ⊥平面ABC ，又因为BC ⊂平面ABC ，所以1B C BC ⊥．因为AB 为圆O 的直径，所以BC AC ⊥．又1AC B C C ⋂=，1,AC B C ⊂平面1AB C ，所以BC ⊥平面1AB C ，因为1AB ⊂平面1AB C ，所以1BC AB ⊥．【小问2详解】以O 为原点，OA ，1OO 分别为y ，z 轴，垂直于y ，z 轴的直线为x 轴建立空间直角坐标系，如图所示，则1(0,1,2)A ，1(0,0,2)O ，(0,1,0)B -，因为劣弧11A B 的长为π6，所以111π6AO B ∠=，113,,222B ⎛⎫ ⎪ ⎪⎝⎭，则1(0,1,2)O B =--，111,,022O B ⎛⎫= ⎪ ⎪⎝⎭．设平面11O BB 的法向量(,,)m x y z =，则111201022O B m y z O B m x y ⎧⋅=--=⎪⎨⋅=+=⎪⎩，令3x =-，解得y =，32z =-，所以2m ⎛⎫=- ⎪ ⎪⎝⎭ ．因为x 轴垂直平面11A O B ，所以平面11A O B 的一个法向量(1,0,0)n =．所以cos ,17m n 〈〉==- ，又二面角111A O B B --的平面角为锐角，故二面角111A O B B --的余弦值为25117．20.某学校进行趣味投篮比赛，设置了A ，B 两种投篮方案.方案A ：罚球线投篮，投中可以得2分，投不中得0分；方案B ：三分线外投篮，投中可以得3分，投不中得0分.甲、乙两位员工参加比赛，选择方案A 投中的概率都为()0001p p <<，选择方案B 投中的概率都为13，每人有且只有一次投篮机会，投中与否互不影响.（1）若甲选择方案A 投篮，乙选择方案B 投篮，记他们的得分之和为X ，()334P X ≤=，求X 的分布列；（2）若甲、乙两位员工都选择方案A 或都选择方案B 投篮，问：他们都选择哪种方案投篮，得分之和的均值较大？【答案】（1）分布列见解析（2）答案见解析【解析】【分析】（1）根据()334P X ≤=得到方程，求出034p =，求出X 的所有可能值及对应的概率，得到分布列；（2）设甲、乙都选择方案A 投篮，投中次数为1Y ，都选择方案B 投篮，投中次数为2Y ，则()10~2,Y B p ，21~2,3Y B ⎛⎫⎪⎝⎭，计算出两种情况下的均值，由不等式，得到相应的结论.【小问1详解】依题意，甲投中的概率为0p ，乙投中的概率为13，于是得013(3)1(5)134P X P X p ≤=-==-=，解得034p =，X 的所有可能值为0，2，3，5，311(0)11436P X ⎛⎫⎛⎫==-⨯-= ⎪ ⎪⎝⎭⎝⎭，311(2)1432P X ⎛⎫==⨯-= ⎪⎝⎭，131(3)13412P X ⎛⎫==⨯-= ⎪⎝⎭，311(5)434P X ==⨯=，所以X 的分布列为：X 0235P161211214【小问2详解】设甲、乙都选择方案A 投篮，投中次数为1Y ，都选择方案B 投篮，投中次数为2Y ，则()10~2,Y B p ，21~2,3Y B ⎛⎫ ⎪⎝⎭，则两人都选择方案A 投篮得分和的均值为()12E Y ，都选择方案B 投篮得分和的均值为()23E Y ，则()()100142222E E Y p p Y ==⨯=，()()221333322E Y Y E ==⨯⨯=，若()()1223E Y E Y >，即042p >，解得0112p <<；若()()1223E Y E Y =，即042p =，解得012p =；若()()1223E Y E Y <，即042p <，解得0102p <<.所以当0112p <<时，甲、乙两位同学都选择方案A 投篮，得分之和的均值较大；当012p =时，甲、乙两位同学都选择方案A 或都选择方案B 投篮，得分之和的均值相等；当0102p <<时，甲、乙两位同学都选择方案B 投篮，得分之和的均值较大.21.已知椭圆2222:1(0)x y C a b a b+=>>的焦距为12,A A ，上顶点为B ，且1tan 2A BO ∠=．（1）求椭圆C 的方程；（2）若过2A 且斜率为k 的直线l 与椭圆C 在第一象限相交于点Q ，与直线1A B 相交于点P ，与y 轴相交于点M ，且223PA MQ QA MP =．求k 的值．【答案】（1）2214x y +=（2）1-【解析】【分析】（1）根据焦距和角的正切值得到方程，求出21b =，24a =，得到椭圆方程；（2）设出直线l 的方程，与椭圆方程联立，得到228214Q k x k-=+，再与直线1A B 方程联立，得到2421P kx k +=-，根据题干条件得到方程30P Q Q P x x x x +-=，代入求出答案，舍去不合要求的解.【小问1详解】由题意得2c =c =又1,AO a OB b ==，故1tan 2aA BO b∠==，即2a b =，又222a b c =+，解得21b =，24a =，故椭圆方程为2214x y +=；【小问2详解】直线l 的方程为()2y k x =-，0k <，与2214x y +=联立得()222214161640k x k x k +-+-=，设(),Q Q Q x y ，则22164214Q k x k -=+，解得228214Q k x k -=+，因为点Q 在第一象限，所以2282014Q k x k -=>+，解得214k >，直线1A B 方程为112y x =+，与()2y k x =-联立得2421k x k +=-，故2421P k x k +=-，()2y k x =-中，令0x =得2y k =-，故()0,2M k -，因为223PA MQ QA MP =，所以()()()()20320P Q Q Px x x x--=--，整理得30P Q Q P x x x x +-=，即2222248282243021141421k k k k k k k k +--+⋅+-⋅=-++-，化简得22310k k ++=，解得12k =-或1-，其中12k =-不满足214k >，舍去，1k =-满足要求，故1k =-.22.已知函数2()ln x f x e a x =-，函数ln ()m xg x n x+=+的图象在点(1,(1))g 处的切线方程为30y -=.（1）讨论()f x 的导函数()f x '的零点的个数；（2）若0a ≤，且()f x 在[),e +∞上的最小值为2e e ，证明：当0x >时，()()f x g x ≥.【答案】（1）当0a >时，()f x '存在唯一零点，当0a ≤时，()f x '无零点.（2）证明见解析【解析】【分析】（1）由题意得()f x 的定义域为(0,)+∞，2()2x af x e x'=-，然后分0a ≤和0a >两种情况讨论即可（2）先由条件求出1ln ()2x g x x+=+，然后要证()()f x g x ≥，即证()22ln 1xx e x --≥，令()2()2ln xh x x ex =--，然后利用导数得出min ()1h x =即可【详解】（1）由题意，得()f x 的定义域为(0,)+∞，2()2xa f x e x'=-.显然当0a ≤时，()0f x '>恒成立，()f x '无零点.当0a >时，取2()()2xa t x f x e x'==-，则22()40xa t x ex'=+>，即()f x '单调递增，又()0f a '>，2202a aa e a a f e e e ⎛⎫'=-< ⎪⎝⎭，所以导函数()f x '存在唯一零点.故当0a >时，()f x '存在唯一零点，当0a ≤时，()f x '无零点.（2）由（1）知，当0a ≤时，()f x 单调递增，所以22min ()()ee f x f e e a e ==-=，所以0a =.因为21ln ()m xg x x --'=，函数()g x 的图象在点(1,(1))g 处的切线方程为30y -=，所以1(1)01mg -'==，所以1m =.又1ln1(1)31g n +=+=，所以2n =，所以1ln ()2xg x x+=+.根据题意，要证()()f x g x ≥，即证2ln 12xx e x+≤-，只需证()22ln 1x x e x --≥.令()2()2ln xh x x e x =--，则22121()(21)(21)x x x h x x e x e x x +⎛⎫'=+-=+- ⎪⎝⎭.令21()(0)xF x ex x =->，则221()20x F x e x'=+>，所以()F x 在(0,)+∞上单调递增.又1404F ⎛⎫=-<⎪⎝⎭，1202F e ⎛⎫=-> ⎪⎝⎭，所以()F x 有唯一的零点,x ⎛⎫∈ ⎪⎝⎭01142.当()00,x x ∈时，()0<F x ，即()0h x '<，()h x 单调递减，当()0,x x ∈+∞时，()0F x >，即()0h x '>，()h x 单调递增，所以()()2min 000()2ln x h x h x x e x ==--.又因为()00F x =，所以0201ex x =，所以()0000020112ln 1221x h x x x x x e ⎛⎫⎛⎫=--=-+= ⎪ ⎪⎝⎭⎝⎭，故()()f x g x ≥.【点睛】本题考查了利用导数研究函数的零点个数，利用导数证明不等式，属于较难题.。

山西省运城市联校中学2019-2020学年高三英语期末试卷含解析

山西省运城市联校中学2019-2020学年高三英语期末试卷含解析一、选择题1. Tom is a determined person．He never allows ______ to lead him by the nose．A．anyone B．everyone C．nobody D．somebody参考答案：A2. You have helped me a lot. I can’t thank you enough.--- ____A. Think nothing of it.B. That’s right.C. I don’t think so.D. Be my guest.参考答案：A3. The police said the hackers were just looking to show off and get as much as possible.A. attitudeB. flameC. attentionD. dislike参考答案：C4. cheek A．chemistry B．charge C．technical D．character参考答案：B5. For us Senior Three students, 2014 is a special year, one _______ we are trying to be admitted to a desired university．A．what B．which C．where D．when参考答案：D6. ﹣It's said that Chris achieved high grades in the examination．﹣That's no surprise．He is______，you know．（）A．a dark horse B．a green handC．a wet blanket D．an early bird参考答案：D听说Chris在考试中取得了很高的分数．这不奇怪啊，你知道的，他很勤奋．本题考查词义辨析．a dark horse黑马（意外获胜的人）；a green hand新手；a wet blanket扫兴的人；an early bird勤奋的人．故选D．7. --Does the young man _____ there have possession of the company?--No, The company is _____ his father.A. standing; in the possession ofB. stood; in the possession ofC. standing; in possession ofD. stand; in possession of参考答案：A8. ------ Mr. Black, this is our language lab. Would you like to go in and have a look?------ OK. ________.A. Help yourselfB. This way, pleaseC. Follow meD. After you参考答案：D9. You may _____ find it hard to get along well with them.A. certainlyB. likelyC. possiblyD. probably参考答案：C10. I’m sorry I didn’t phone you, but I’ve been very busy____ the past couple weeks.A. beyondB. overC. withD. among参考答案：B11. One Friday, we were packing to leave for a weekend away____ my daughter heard cries for help.A. afterB. whileC. sinceD. when参考答案：D12. Kevin consulted his teacher about_______ he should study abroad after graduation．A. whetherB. whereC. whenD. that参考答案：A13. The written record of our conversation doesn’t what was actually said. There area lot of mistakes.A.correspond withB. relate toC. look intoD. compare with参考答案：A14. Isn’t it lovely to think that I ________ myself on the sunny b each tomorrow at this time.A. will enjoyB. will be enjoyingC. am enjoyingD. shall enjoy参考答案：B略15. In those days, our ________ concern was to provide people who were stopped by the snow storm with food and health care.A. normalB. constantC. permanentD. primary参考答案：D解析：形容词考查，此题和07年底的雪灾情景呼应，根据题意，在那些时候，我们主要的任务是给那些被暴风雪阻挡的人们提供食物和医疗救助,primary符合题意，normal表示正常的， constant表示恒定的 permanent表示永久的。

2019-2020山西省九年级上册期末英语(人教版)【试卷+答案】

沿此线折叠注意事项：1.本试卷分听力和笔试两部分。

全卷共12页，满分120分。

2.答题前，考生务必将自己的姓名、准考证号填写在本试卷相应的位置。

3.答案全部在答题卡上完成，答在本试卷上无效。

4.考试结束后，将本试卷和答题卡一并交回。

一、情景反应（每小题1分，共5分）本题共5个小题，每小题你将听到一组对话。

请你从每小题所给的A、B、C三幅图片中，选出的出的你的所的听的到的的的信的息的息的关的关的的一项，并在答题卡上将该项涂黑。

A B C1.A B C2.A B C3.4.A BCA B C5.二、对话理解（每小题1分，共5分）本题共5个小题，每小题你将听到一组对话和一个问题。

请你从每小题所给的A、B、C三个选项中，选出一个最佳选项，并在答题卡上将该项涂黑。

6.A.Zongzi. B.Mooncakes. C.Dumplings.7.A.She was heavy. B.She was thin. C.She was tiny.8.A.Tim’s. B.Mike’s. C.Carla’s.9.A.Relaxing music. B.Exciting music. C.Energetic music.10.A.There are many special mobile phone shells in the new store.B.The special mobile phone shell was made by hand.C.He stayed up shopping online.三、语篇理解（每小题1分，共5分）本题你将听到一篇短文。

请你根据短文内容和所提出的5个问题，从每小题所给的A、B、C三个选项中，选出一个最佳选项，并在答题卡上将该项涂黑。

11.What does Holly like doing in her free time?A.Reading books.B.Writing music pieces.C.Making paper cuttings.12.How was the weather in the morning?A.Cold.B.Sunny.C.Snowy.13.Where did the people learn to make paper cuttings?A.In the art museum.B.In the robot museum.C.In the history museum.14.How long did Holly spend making the paper cutting?A.5minutes.B.15minutes.C.50minutes.15.What does Holly want to tell us?A.We should go to the library often.B.Special experiences are unforgettable.C.We should get along well with others.山西省2019-2020学年第一学期九年级期末质量评估试题英语（人教版）九年级英语（人教版）第2页（共12页）九年级英语（人教版）第1页（共12页）听力部分（共20分）姓名准考证号四、听力填空（每小题1分，共5分）本题你将听到一篇短文。

山西省运城市2023-2024学年高三上学期期末调研测试英语答案

运城市2023-2024学年第一学期期末调研测试英语试题答案第一部分听力（共两节；每小题1.5分，满分30分）1-5 AABCA6-10 CB BAB11-15 ACACB16-20 BBACB第二部分阅读(共两节；每小题3分，满分60分)21-23 DCD 24-27 ACBD 28-31 BACA 32-35 DBAB36-40 CFADE第三部分语言运用 (共两节，满分50分)第一节(共15小题; 每小题2分，满分30分)41-45 CDABB 46-50 CDAAD 51-55 BDACB第二节（共10小题；每小题2分，满分20分）56. likes 57. skilled/skillful 58. which 59. a 60. surprised 61. simply62. and 63. has become 64. originating 65. for第四部分写作第一节（满分15分）Dear Peter,Learning your winning the first prize in the Chinese Traditional Culture Contest organized by my city, I'm writing to extend my sincere congratulations to you.It came as no surprise, for you are keenly interested in Chinese culture and have been continuously exploring it. Not only did you refer to abundant resources, but you also consulted many locals and professionals, which equipped you with comprehensive knowledge and a good command of Chinese culture.Congratulate you on your success again and I hope you can devote yourself to spreading the Chinese culture and making it more accessible to people around the world.Yours,Li Hua 第二节（满分25分）Suddenly, she thought of Landy, the girl being “pecked” by her classmates. “I’m going to take it home and take good care of it,” she said with a determined look. Back in school, Catherine spotted Landy sitting by herself in a corner. She kept her head down with her eyes fixed on the floor as usual. Catherine thought Landy was just like the poor little chicken, being teased and ignored by her classmates, merely due to her special height. She told other kids, “It’s time for me to make an apology to Landy.” Astonished at what she said, all the kids burst out screaming, “Talking to the long spaghetti? Are you crazy?”But Catherine walked directly toward Landy, regardless of what they said. “Hi, Landy. I’m sorry about the spaghetti thing.” Catherine murmured an apology, her face reddening. “I know it hurts you. Can you forgive me?" She figured Landy might just walk away. But she lifted her mistyeyes and nodded yes. Catherine wiped away her tears, giving her a warm hug. Moved by the scene, the other kids also came to offer their sincere apologies to Landy. From that day on, no one made up silly chants about Landy, and Catherine also gained an important life lesson that everyone should be treated equally no matter how special he or she was.听力录音原文Text 1W: The lecture was so boring. What did you think of it?M: It was endless! I was listening for the school bell the whole time.Text 2M: Look at that big field of cotton and that farm with those beautiful houses.W: You really get to know the countryside when you travel by train, don’t you?Text 3W: Hello, Red House Restaurant. What can I do for you?M: Yes, I’d like to book a table by the window for two at 11:30 this noon.Text 4W: Where are you going to plant the tree? By the front door?M: No, that would be silly. I’ll put it next to the garage.W: Wouldn’t it be better in the back yard?M: Well, you’re quite right.Text 5M: I’d like to speak to the manager, please.W: May I know what this is about?M: I’d like to see him about the position advertised in the website.W: Just a moment, please.Text 6M: How did this happen?W: Well, I wasn’t paying attention ⑦when I crossed the street, and ⑥I stepped in front of a taxi. I didn’t realize it was still moving.M: Where does it hurt?W:⑥My side hurts when I take a step.M: Okay, don’t try to walk anymore. Just rest.An ambulance is on the way. You could have easily been killed in an accident like this.W: Yes, I guess I could have. I will be cautious next time.Text 7W: Can you feel that the plane’s taking off now?M: No, nothing at all, it’s smooth and quiet.W: ⑨How do you like traveling by air?M: ⑧Oh, it’s speedy and very comfortable,I must say. I prefer it to traveling by train.W: Do you ever suffer from airsickness?M: No, I’ve never had such a feeling.W: Do you think air travel is just as safe as traveling by rail?M: Probably not.W: What kind of sensation do you have when the plane drops into an air pocket?M: It’s the same kind of sinking feeling you get when you go down fast on a lift.Text 8W: Excuse me. Could you spare a few minutes for an interview?M: I’ll be glad to.W: What do you plan to do after graduation from college?M: I don’t know yet. My parents expect me ⑩to work in the information technology field. W: Oh?⑩A popular profession. Is that what your dad does?M: No. ⑪He is an architectural designer.W: How about yourself? Are you fond of IT?M: Actually I’m interested in biology. I’ve been dreaming of becoming a biologist since I was very young.W: ⑫So you are majoring in biology, right?M: Yeah, ⑫but I also minor in computer science. So my degree will include both.W: You’re a really good student.M: Am I? Thanks.W: My last question for you. If you got job offers from companies in both fields, would you choose biology or IT?M: Hmm … It’s hard to say. Probably I would follow my childhood dreams.Text 9M: Hello, Nancy. This is Ted. How are you?W: Fine, thank you. A bit too busy, though, ⑬because I’m trying to put everything inorder in my new apartment.M: Did you move to a new apartment? When?W: Oh, I got a new job and the company was so far away from my home. So at last I decided to move here, a little nearer to my new office. I moved just the day before yesterday.M: Your new address?W: ⑭It’s on Huangpu Road, No. 466, near the People’s Square.M: Oh, that’s a good location. I’ll have to go see it someday. Well, now I wonder if you’d like to go to a concert tomorrow night. I think it will be good. ⑯And if I remember correctly, you did say you like country music.W: Yes, that’s right. I do. It’s nice of you to ask me, Ted. But I don’t think I can. I am very busy and tired today.M: Oh, well. Never mind. What about next Saturday?W: Oh, I’d like to very much, but what time exactly?M: ⑮Well, the concert next week starts at 7:30. We should get there at 7:15, a little earlier.W: Oh, good, that’ll be fine.M: Good, I’ll call you again when I get the tickets.W: Sure. Bye.Text 10Hi, everyone! Welcome to Mount Raven, the most popular ski place in the state. I’m Jessie Williams,⑰and this is our weekend weather report. This morning we’re seeing sun with cloudy periods as well as a few hours of light snowfall. ⑱Right now I am at the top of Mount Raven where the temperature is plus two and expected to rise to about six degrees by noon. Overnight temperatures will probably drop to at least minus seven. Tomorrow’s forecast calls for more snow with a high of zero and a low of minus twelve.With the wind chill factor, ⑲that could put us at a record low of minus twenty. Conditions are perfect for skiing this weekend, but if you’re determined to head out to the slopes tomorrow,⑳please remember to put on warm clothes to protect yourself from the cold, especially exposed areas like your ears, cheeks and hands. Now, we have to go back to the newsroom for a look at what’s happening in sports. Have a splendid weekend!。

山西省运城市2022-2023学年高一上学期期末调研测试化学试题含答案

运城市2022-2023学年第一学期期末调研测试高一化学试题（答案在最后）2023.本试题满分100分，考试时间75分钟。

答案一律写在答题卡上。

2.答题时使用0.5毫米的黑色中性（签字）笔或碳素笔书写，字体工整、笔迹清楚。

3.请按照题号在各题的答题区域（黑色线框）内作答，超出答题区域书写的答案无效。

4.保持卡面清洁，不折叠，不破损。

5.做选考题时，考生按照题目要求作答，并用2B 铅笔在答题卡上把所选题目对应的题目涂黑。

可能用到的相对原子质量：H —1 C —12 N —14 O —16 Na —23 S —32 Fe —56 一、单选题（每个小题只有一个答案，本题共9个小题，每题3分，共27分）1.化学在生产和日常生活中有着重要的应用，下表中用途与其性质或原理对应关系错误的是（）选项用途性质或原理A 硬铝是制造飞机和宇宙飞船的理想材料硬铝密度小、强度高具有较强的抗腐蚀能力B抗击新冠疫情时，84消毒液、75%酒精都可作为环境消毒剂二者都有较强的氧化性C工业上常用绿码42(SO )Fe 7H O ⋅处理废水中含有的重铬酸根离子()227Cr O -2Fe +具有还原性D 用小苏打治疗胃酸过多3NaHCO 可中和胃酸2.反应4222NH Cl NaNO NaCl N H O +=+↑+放热且产生气体，可用于冬天石油开采。

下列说法正确的是（）A.2N 的结构式N N =B.2H O 的电子式：2H :O:H -++⎡⎤⎣⎦C.35Cl -结构示意图：D.2NaNO 的电离方程式：22NaNO NO Na -+=+3.下列说法正确的是（）A.石墨和60C 互为同素异形体，相互转化是化学变化，属于非氧化还原反应B.因为胶粒比溶液中溶质粒子大，所以可以用过滤的方法把胶体中胶粒分离出来C.测定新制氯水的pH 时，先用玻璃棒酶取液体滴在pH 试纸上，再与标准比色卡对照D.铭（Tl ）与铝同族，推测其单质既能与盐酸反应产生氢气，又能与NaOH 溶液反应产生氢气 4.设A N 为阿伏加德罗常数的值，下列说法不正确的是（） A.246gNO 和24N O 的混合气体中含有的氧原子数为A 2N B.22mol /LMgCl 溶液中Cl -的数目为A 4NC.取2.3g 金属Na 在一定条件下与2O 反应，若Na 完全反应生成3.6g 产物，失去电子数为A 0.1ND.标准状况下，222.4LD 中子数为A 2N 5.下列钠及其化合物说法正确的是（）①将金属Na 投入硫酸铜溶液中，剧烈反应，析出红色固体； ②22Na O 投入到紫色石蕊试液中，溶液先变蓝，后褪色；③质量相等的3NaHCO 与23Na CO 分别与足量盐酸完全反应时，产生2CO 物质的量相等； ④鉴别3NaHCO 与23Na CO 溶液，可用()2Ca OH 溶液；⑤3NaHCO 固体可以做干粉灭火剂，金属钠起火可以用它来灭火；⑥3NaHCO 粉末中混有23Na CO ，可配制成溶液通入过量的2CO ，再低温结晶提纯得到。

2018-2019学年人教版高中英语高一上学期期末考试模拟测试题及答案-精编试题

2018-2019学年人教版高中英语高一上学期期末考试模拟测试题及答案-精编试题第一学期期末学业水平监测高一英语注意事项：1．本试卷分为第Ｉ卷﹙选择题﹚和第Ｉ卷﹙非选择题﹚两部分，共10页。

第Ｉ卷第1至第8页；第Ｉ卷第9至10页。

满分150分，考试时间120分钟。

2．答题前，请你务必将自己的姓名，准考证号用黑色墨水的0.5毫米签字笔填写在答题卡（卷）密封线内。

3．作答选择题必须用２Ｂ铅笔并把答题卡（卷）上对应的答案标号涂黑。

如需改动，用橡皮擦干净后，再选涂其它答案标号。

答第Ｉ卷时必须使用0.5毫米的黑色墨水签字笔书写在答题卡（卷）上的指定位置，在其它位置作答一律无效。

4．考试结束时，只交答题卡（卷）。

第Ⅰ卷（共三部分，满分90分）第一部分听力（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面５段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有１０秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1.What will the woman do?A。

Stay in doors.B。

Have a walk.C。

Get a coat.2.What will the speakers order?A。

XXX andcoke.3.How did the woman know about the fire?A。

She read about it.B。

She witnessed it.C。

She saw it on TV.4.What is the man worried about?A。

The match may be delayed.B。

Their car may go out of control.C。

They arrive late for the game.5.What does the man mean?A。

2019_2020学年高中英语unit1artperiodfourgrammar_subjunctivemood1教案含解析新人教版选修6

Period Four Grammar—Subjunctive Mood (1)感知以下课文原句，补全方框下的小题1．在虚拟条件句中，谓语动词用一般过去时(be动词常用were)表示与现在事实相反的情况，主句谓语则用“would/should/could/might＋动词原形”表示。

(如句1、2、4和5)2．在虚拟条件句中，谓语动词一般用过去完成时表示与过去事实可能不符的情况，主句则用“would/should/could/might＋have＋过去分词”表示。

(如句3)虚拟语气是英语考查的重点之一。

虚拟语气用来表示说话人所说的话并不是事实，而是一种假设、愿望、怀疑或推测。

其使用情况如下：一、虚拟语气在if条件从句中的用法注意：1．虚拟条件句中有had，should，were时，可将if去掉，把had，should，were提到主语之前，即倒装结构，如：Were theyherenow，they couldhelp us.如果现在他们在这里，他们就能帮助我们。

HadIworked harderatschool，I’dhavegot abetterjob.如果我在学校学习更努力的话，就会找到一份更好的工作。

Shouldheagree togothere，we wouldsend himthere.要是他答应去的话，我们就派他去。

2．有时条件从句表示的动作和主句表示的动作发生的时间不一致，这类句子称为错综时间条件句。

此时主、从句动词的形式应根据各自所表示的时间进行调整。

Ifhe hadtaken myadvicethen，he wouldn’tbe introublenow. 如果那时他听取了我的建议，现在他就不会有麻烦了。

Ifshe wereto leave，I wouldhaveheard aboutit.如果她要走，我会听说的。

3．某些介词或介词短语，如butfor，without，副词或连词，如otherwise，however，or，but等也可以表达一个暗含的虚拟的条件，这种情况下要仔细阅读上下文的语境。

山西省运城市2023-2024学年高三上学期摸底调研测试英语答案

运城市2023-2024学年度高三摸底调研测试英语答案1-5 CCBCB6-10 ABACA11-15 BCACC16-20 BACAB21-25 BACDD25-30 DCBAC31-35 CCBDA36-40 GFDAE41-45 BDCAB 46-50 CADBC 51-55AADBC56. Despite 57. preserving 58. more determined 59. conservation60. outweighed 61. to digitize 62. images 63. tirelessly64. on/ forward 65. where第一节One possible version：Dear fellows,A new column for the graduating students called “My school, I have something to say to you” is set up in our school newspaper. We are expecting your theme-related articles.We set no limit to the type—poems, essays, or novels are all welcome. Your contributions should cover your authentic experiences in your school life and genuine feelings that you want to extend. They are expected to be original and within 300 words. Please submit your articles before May 20th to *************************. Works chosen, you will get a certificate and 200 yuan in prize money.Write down your stories and keep your cherished memory alive. Looking forward to your works!The Editorial SectionMay 5th, 2023第二节One possible version：Soon after, all the negative words started to destroy me. I cried myself to sleep late in the night and woke up with swollen eyes the next morning, hardly able to get out of my room. Several days later, overwhelmed by depression, I refused to go to school and talk with someone and even refused food. It seemed that I was totally trapped in darkness. Thankfully, the magazines at hand helped to relieve my stress somehow. Everything changed from that day, when I happened to read an article.I saw a quote in the journal. “Once you choose your way of life, be brave to stick it out andnever return.” Reading it, I suddenly caught what it meant. I could either let myself down in the gossip or hug it as a chance to grow up and become better. So I reread the posts and reflected on my recent experiences. I realized that I was bothered because I cared so much about people’s bad comments that I lost heart and forgot my target. It’s time to face the situation bravely and stick to what I have always dreamed to do.听力录音原文Text 1W: We haven’t seen much of you lately in the hospital. Have you been away on business? M: No, I’ve been away on holiday with my family.Text 2W: You can change planes in either Chicago or Denver.M: You mean there’s no direct flight from New York to Phoenix?Text 3M: Those tickets on Tuesday are so expensive. Can’t you find anything better before Friday? W: Well, if we want cheaper tickets, we have to leave on Thursday.Text 4W: Oh, don’t throw that away!M: Why not? It’s been used already.W: You can get a new label and put it on top of the old address, and then you can buy a bigger stamp and put it on top of the old stamp.M: Good idea!Text 5M: Can I borrow your biology textbook? Mine was gone when I went back in the classroom. W: That happened to me once. I’d almost given up on finding it until I checked it at the information desk downstairs in the lobby.M: Oh, good idea.Text 6W: Is university pretty much what you expected, Sam?M: Well, ⑥I’ve been here two months now and I’m just getting used to it, really. It’s certainly not easy. In fact, the workload is more than I expected. I’ve got to do loads of reading, for example.W: How do you find the lectures?M: Well, ⑦the professors are great speakers and they know how to hold your interest. I’ve never been bored.Text 7M: You just said ⑧you’re interested in our position of production manager. Do you have experience in this position?W: Yes, I’ve worked in a similar position for three years.M: Could you tell me about some of your achievements from your previous job?W: Well, I made full use in my job of what I had learned in university and, since my work was sati sfactory, I was promoted to be a team leader after only one year. With our team’s hard work, ⑨we were able to reduce production costs by 15%, 3% more than your company’s goal for the coming year.M: Great! Could you tell me about your educational background?W: Of course. I have a bachelor’s degree in management from Peking University.M: Hmm, not bad. I wonder how much you know about our company.W: ⑩I’ve visited your company’s website. I know that your company is one of the Global 500 and the company’s stock price has increased by 10% recently because of its outstanding performance.M: OK, thank you. We’ll call you in a week if we would like to hire you.W: Thank you very much.Text 8W: Hi! It’s nice to see you. Where have you been these days?M: I went to Beijing for business.⑪I left last week on Wednesday and returned yesterday morning. Because it was Friday yesterday and the manager wasn’t going to work on the weekend,⑫I had to spend the whole day preparing a report about my Beijing business trip. I worked on it until I got a headache, but⑫I finished the report in time to send to the manager just half an hour before the end of the workday.W: No wonder you’re looking so tired. You’ve been working much too hard.M: True. That’s why I came here to the park to relax a bit.W: How was your business in Beijing?M: I could say it was a success —I was able to return earlier than I’d planned. I had thought my trip would last two weeks and I would have to spend Christmas alone.W: Congratulations! I hope you can enjoy yourself now.⑬Let’s get together sometime. M: OK. Goodbye!Text 9W: We’re looking for someone to sell our new software products internationally. The job requires independence and ⑭most importantly, a pleasant manner with customers.M: I agree...that’s important. I’ve worked in sales for years and have always tried to really listen to my customers to find out what they need. I think I’m really good at it.W: That’s g reat. What about your experience with software programs?M: Well, I’ve trained people how to use a similar software product for the past two years at my current job, so I really feel I know the product.W: Hmm...interesting, and your sales experience?M: I’ve been with my present company for four years and ⑮in my present position since two years ago. During that time, ⑯I’ve been named salesperson of the month three times, and have taken top sales awards several times as well.W: ⑰Impressive...Text 10Women like shopping, me included of course. I used to shop with my friends almost every week. ⑱But this year I decided to try to go for a year without shopping for clothes.I have to say it has been really hard. But I don’t want to give up. ⑱So why did I decide to do that?First, it’s about money. Last year, being tired of doing the work I disliked, I left my highly-paid job and found a job that doesn’t pay that much. But I was still spending a lot of money on clothes. As a result, I didn’t have any savings. I decided to spe nd less on clothes.Second, I already have a lot of clothes. ⑲According to a study, most women wear only 20-30% of their clothes. A year without shopping for clothes gave me a chance to wearthe clothes that I haven’t tried before. I wasn’t buying any new clothes, but I still had many new clothes to wear.Third, I have less time for shopping than before. Now I’m trying to lose some weight, ⑳so I go to the gym with friends on the weekend.If I were going shopping, I’d have no time to go to the gym.。

山西省运城市2019-2020学年高一上学期期末调研测试英语试题(含答案)

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