008作品题
008-湖南省评标专家库试题《职业道德-多选》
多项选择题1、根据《湖南省综合评标专家库和评标专家管理办法》，评标专家采用公开征集和定向征集相结合的方式评聘。
申请评标专家应当符合国家法律法规及（BCD）条件。
A、从事相关专业领域工作满六年并具有高级职称或同等专业水平B、熟悉有关招投标的法律、法规、规章和政策，并具有招标项目类似的实践经验C、遵守国家有关法律、法规和职业道德，服从管理，自觉接受监督，无不良记录D、能够认真、公正、诚实、廉洁地履行职责2、根据《湖南省综合评标专家库和评标专家管理办法》，关于对湖南省综合评标专家库评标专家实行网上请假制度的说法，以下正确的是（AB）。
A、评标专家因工作、身体等原因连续两个月以内不能参加评标活动的，应当事先登录个人页面进行请假B、请假时间超过两个月的，需网上请假并向省发改委书面说明原因C、请假时间两个月之内的，仅需向省发改委书面说明原因D、正常结束请假时间的，评标专家应及时登录个人页面销假3、根据《湖南省综合评标专家库和评标专家管理办法》，评标专家复审是对评标专家聘期内（ABCD）等情况进行综合考核。
A、业务能力B、个人信用C、履职情况D、培训教育情况4、根据《湖南省综合评标专家库和评标专家管理办法》，评标专家复审时有下列（ABCD）情形之一的不予通过。
A、未在规定时间内按要求递交相关复审材料的B、未能通过继续教育、综合考核的C、聘任期间受到“警告”累计达三次及以上D、聘任期间受到“严重警告”累计达二次及以上的5、根据《湖南省综合评标专家库和评标专家管理办法》，有下列情形（ABCD）之一的，可直接解聘评标专家。
A、继续教育或连续2 次年度考核不合格的B、确认抽取信息后，两次无正当理由无故不参加评标的C、因身体健康原因不能胜任评标工作的D、因工作调动，不再适宜担任评标专家的6、根据《湖南省综合评标专家库和评标专家管理办法》，评标专家享有以下权利（ACD）。
A、对评标专家管理提出意见和建议B、查询与本人相关的评标抽取记录，可就有效期（12 个月）内评标抽取记录的疑问要求省有关行政监督部门或者网络终端解答C、对省有关部门作出的处理决定提出申诉D、对湖南省综合评标专家库中个人信息提出修改意见7、根据《湖南省综合评标专家库和评标专家管理办法》，评标专家应履行以下义务（ABC）。
城市轨道交通概论综合试题(含答案)——008
城市轨道交通概论综合试题008一、填空题1.钢轨的标准长度有___________和____________两种。
2.城市轨道交通车站站务人员的岗位要求包括：站长、、、的岗位要求。
3.城市轨道交通客运服务质量控制由服务质量模式、__________________、_______________________组成。
4.我国城市轨道交通运营管理模式主要有____________________管理方式和___________________管理方式两种。
5.线路平面的组成要素是直线和___ ____。
6.世界大多数国家的地铁和轻轨普遍采用的标准轨距。
7.独轨交通从构造形式上可以分为和两种。
我国的第一条独轨交通在建成。
8.我国城轨车辆实施_____________行车惯例，正线分为________________、________________。
9.线网设计一般分为可行性研究阶段、、、 4个阶段。
二、单选题1.搜集列车运行信息的子系统是（）A．列车自动保护子系统 B.列车自动运行子系统 C. 列车自动监督子系统2.防护信号机中表示所防护的道岔开通折返线，准许列车按规定速度越过该信号机运行至折返点的是一个（）灯光。
A、绿色B、白色C、红色D、蓝色3.（）是目前世界上最先进的一种地铁隧道方法。
A、明挖法B、盖挖法C、沉管法D、盾构法4.制动系统是车辆运行安全重要保证，我国地铁车辆最初采用（）A、SD数字制动机B、电气控制模拟直通电空制动系统C、VE型电空制动D、DK型电空制动5.铁路和地铁之间的连接线为（）A、联络线B、渡线C、区间线路D、折返线6.具有AFC设备的操作与管理的能力，处理票务报表与台账、对车站票务事件处理的能力和对票务员监督和管理的能力是（）的岗位职责。
A、行车值班员B、客运值班员C、售票员D、厅巡7.1863年，世界上第一条地铁线路在（）建成通车，线路全长6.4km。
A、英国伦敦B、美国芝加哥C、日本东京D、北京8.列车运行图按列车之间运行速度差异分为（）运行图A、单线和多线B、成对和非成对C、平行和非平行D、连发和追踪9.城市轨道交通设置控制保护区的范围正确的是（）A、地下车站与隧道周边外侧30米。
17份福建自考00812中国现当代作家作品专题研究历年真题
17份福建自考00812中国现当代作家作品专题研究历年真题
复习指导、院校专业选择
各专业科目真题、复习资料
请关注公众号[高升专升本]领取
自考每年考两次，教材更新的速度也一般，就算换很多也只是换版本而已，因此它的考试范围在大多是情况下是不会变化太大的，而考试范围不怎么变化的情况下，历年真题就成为了非常重要的复习资料，因为知识点能考的题库其实是有限的，在自考这种考试频率下，很容易就出现原题。
谢老师教育为大家尽可能收集相关专业的历年真题，并且会给出参考答案解析，对于在职自考的同学来说，如果时间实在有限的情况下，可以直接使用真题复习（前提是真题年份够多，但是建议还是要至少过一遍教材，这样才能尽可能提高通过率）。
今天为大家分享的是：
1月：2014年
4月：2004—2014年
10月：2014—2018年
真题使用建议：
1、较为老旧的可以直接拿来进行教材之余的练习，如果实在没时间看教材，就多翻看几遍真题，但是建议最好要看教材，有一个整体感观更容易记忆，不要抱侥幸心理觉得原题都在上面！
2、最近几年的真题（一般是五到八年），更前面的三到五年，用来进行阶段小测；
3、最新年份的两三年进行全真模考。
注：全真模考一定要打印出来，按照考试安排的时间进行模拟，小测要不要打印出来视情况而定，练习的话没必要，这样可以尽可能地节省时间、金钱和纸张。
高压电工作业考试题库008
1、一般防护安全用具，通常也具有较高的绝缘性能。
正确答案：错误2、绝缘杆可以平放在地面上，但不得靠在墙上以防变形。
正确答案：错误3、为保证安全，停电检修的设备或线路的开关，可以采取挂临时接地线或拉开接地开关的方式进行。
正确答案：错误4、遮拦是防止检修人员走错位置，误入带电间隔的防护装置。
正确答案：正确5、变配电室的临时接地线可以不分组编号，但应摆放整齐。
正确答案：错误6、变配电室值班员发现设备缺陷，无论消除与否均应做好记录正确答案：正确7、变配配电室交接班时发生事故，应由接班人员处理，交班人员协助。
正确答案：错误8、运行中的10kV中置式开关柜，操作小车摇进或摇出时，因为站在绝缘垫上，可以不带绝缘手套。
正确答案：错误9、倒闸操作票是保证人身与设备安全，防止误操作的重要措施。
正确答案：正确10、检修的电气设备停电后，在装设接地线之前，必须用合格的验电器检验有无电压。
正确答案：正确11、变压器零序保护动作跳闸，不能合闸试送，必须查明原因。
正确答案：正确12、展开式原理接线图是以集中的形式，表示二次设备之间的电气连接。
正确答案：错误13、变配电室的光字牌安装在信号屏上，通常包括显示事故跳闸和显示运行异常两种。
正确答案：正确14、变配电室中央信号回路，只能用來反映二次设备的工作状态。
正确答案：错误15、带有防护外壳的干式变压器，装有误开门报警或跳闸装置。
正确答案：正确16、变配电室的设备巡视，也包括对继电保护装置的巡视检查。
正确答案：正确17、瞬时电流速断保护，只能保护被保护线路的一部分，不能保护线路全长。
正确答案：正确18、继电保护装置必须满足选择性等6个基本要求。
正确答案：错误19、氧化锌避雷器具有结构简单，工频续流大的特点。
正确答案：错误20、巡视检查避雷器引线及接地引下线，应无烧伤痕迹和断股现象。
正确答案：正确21、从电器商店新购避雷器一组，检查外观无破损，即可安装投入使用。
正确答案：错误22、接地极、接地线的连接多采用搭接，其中扁钢搭接长度为宽度的2倍。
结构化面试008——人际关系类新员工如何和老员工相处(题干+答题)
【题干8】你是新进单位的工作人员，你们科室科长事必躬亲，做事认真，注重细节，科员老刘工作积极性不高，为人冷淡，科员小王新进单位两年，为人热情，工作积极，请问你该如何与他们相处？【考察能力】人际关系【示范答题】各位考官，考生开始答题：不同的同事有不同的性格和风格，这是不可控的，最关键的是对我们自身而言，要去不断的增强自身的一个适应性和主动性，跟不同性格的同事都应该去相处好。
具体而言，面对题干中的三个人物，我会按照如下方式去进行相处：首先，面对我们的科长，他事必躬亲，做事认真，说明我们的科长对于工作的要求非常高，他的责任心也是非常的强的。
那我跟他相处主要是要做好几个方面，第一，做事一定要有一个完美主义的态度，做事不能有一种差不多，觉得无所谓的心态，一定要把事情做到极致。
第二，面对领导，在细节上，他可能会去指出我们的一些小问题，那我千万不能去误会，以为领导是过于的严苛，吹毛求疵，以为这些指出来的东西是没有必要的，我要认识到领导指出来是为了工作做得更好。
可能这种情况，有些时候我们作为新人在情绪上会有点压力，那在这种情况下一定要去做好自己的一个情绪的调整和心理的调整工作，我认为这一点是至关重要的。
第三，我觉得在我们的科长手下去做事，一定要增强自身的执行力，具体体现就是领导所安排的每一个事情，我们都要明确好工作完成的时间点，以及每一个事情所细分出来的每一个小任务，按照规划推进整体的工作并及时和领导汇报工作进度，汇报相应的工作的时候，一定不能像一些群平常的汇报，比如说只汇报重点工作，我们一定要去事无巨细地把一些细节和工作完成的经过都能如实详尽的跟领导做一个汇报，便于领导了解全面。
第四，在跟科长一起相处的时候，我们在做一些关键工作，尤其是重要工作的时候一定要多请示科长意见，多了解领导对于各项工作的一个要求，也只有这样我们才能够避免，因为我们经验的缺乏，或考虑的缺乏导致工作完成的不全面。
这是在和领导科长进行相处是的一些做法。
008药理学练习题-第八章肾上腺素受体激动药 (1)
第八章肾上腺素受体激动药一．选择题A型题（最佳选择题，按试题题干要求在五个备选答案中选出一个最佳答案。
）1．溺水、麻醉意外引起的心脏骤停应选用：BA．去甲肾上腺素B．肾上腺素C．麻黄碱D．多巴胺E．地高辛2．防治蛛网膜下腔或硬膜外麻醉引起的低血压应选用： CA．异丙肾上腺素B．多巴胺C．麻黄碱D．肾上腺素E．去甲肾上腺素3．能促进神经末梢递质释放，对中枢有兴奋作用的拟肾上腺素药是：DA．异丙肾上腺素B．肾上腺素C．多巴胺D．麻黄碱E．去甲肾上腺素4．治疗青霉素引起的过敏性休克的首选药是；EA．多巴酚丁胺B．异丙肾上腺素C．去甲肾上腺素D．多巴胺E．肾上腺素5．具有舒张肾血管的拟肾上腺素药是：BA．间羟胺B．多巴胺C．去甲肾上腺素D．肾上腺素E．麻黄碱6．过量氯丙嗪引起的低血压，选用对症治疗药物是：DA．异丙肾上腺素B．麻黄碱C．肾上腺素D．去甲肾上腺素E．多巴胺7．微量肾上腺案与局麻药配伍目的主要是：DA．防止过敏性休克B．中枢镇静作月C．局部血管收缩，促进止血D．延长局麻药作用时间及防止吸收中毒E．防止出现低血压8．治疗鼻炎、鼻窦炎出现的鼻粘膜充血，选用的滴鼻药是： D A．去甲肾上腺素B．肾上腺素C．异丙肾上腺素D．麻黄碱E．多巴胺9．可用于治疗上消化道出血的药物是：CA．麻黄碱B．多巴胺C．去甲肾上腺案D．异丙肾上腺素E．肾上腺素10．反复应用麻黄碱引起快速耐受性的原因是：DA．受体被阻断B．受体数目减少C．代偿性胆碱能神经功能增强D．递质耗损排空，储存减少E．肝药酶诱导，加快代谢11．静滴剂量过大或时间过长最易引起肾功能衰竭的药物是：C A．异丙肾上腺素B．肾上腺素C．去甲肾上腺素D．多巴胺E．间羟胺12．下列叙述的错误项是：DA．多巴胺激动α、β1和多巴胺受体B．异丙肾上腺素激动β1和β2受体C．麻黄碱激动α、β1β2受体D．去甲肾上腺素激动α和β2受体E．肾上腺素激动α和β受体13．少尿或无尿的休克思者应禁用：EA．山莨菪碱B．异丙肾上腺素C．多巴胺D．阿托品E．去甲肾上腺素14．下列用药过量易引起心动过速、心室颠动的药物是：D A．间羟胺B．去甲肾上腺素C．麻黄碱D．肾上腺素E．多巴胺15．伴有心收缩力减弱及尿量减少的休克患者应选用：EA．间羟胺B．肾上腺素C．多巴酚丁胺D．去甲肾上腺素E．多巴胺16．异丙肾上腺素治疗哮喘剂量过大或过于频繁易出现的不良反应是：D A．中枢兴奋症状B．体位性低血压C．舒张压升高D．心悸或心动过速E．急性肾功能衰竭17．肾上腺素作用于心血管系统的受体是：EA．β1受体B．β1和β2受体C．α和β1受体D．α和β2受体E．α、β1和β2受体18．去甲肾上腺素作用最显著的组织器官是：EA．眼睛B．腺体C．胃肠和膀胀平滑肌D．骨骼肌E．皮肤、粘膜及腹腔内脏血管B型题（配伍题，按试题题干要求在五个备选答案中给每个试题选配一个最佳答案，每个备选答案可选用一次或一次以上，也可不选用。
Chap008金融机构管理课后题答案
Chapter EightInterest Rate Risk IChapter OutlineIntroductionThe Central Bank and Interest Rate RiskThe Repricing ModelRate-Sensitive AssetsRate-Sensitive LiabilitiesEqual Changes in Rates on RSAs and RSLsUnequal Changes in Rates on RSAs and RSLsWeaknesses of the Repricing ModelMarket Value EffectsOveraggregationThe Problem of RunoffsCash Flows from Off-Balance Sheet ActivitiesThe Maturity ModelThe Maturity Model with a Portfolio of Assets and Liabilities Weakness of the Maturity ModelSummaryAppendix 8A: Term Structure of Interest RatesUnbiased Expectations TheoryLiquidity Premium Theory Market Segmentation TheorySolutions for End-of-Chapter Questions and Problems: Chapter Eight1. What was the impact on interest rates of the borrowed reserves targetingregime used by the Federal Reserve from 1982 to 1993The volatility of interest rates was significantly lower than under the nonborrowed reserves target regime used in the three years immediately prior to 1982. Figure 8-1 indicates that both the level and volatility of interest rates declined even further after 1993 when the Fed decided that it would target primarily the fed funds rate as a guide for monetary policy.2. How has the increased level of financial market integration affectedinterest ratesIncreased financial market integration, or globalization, increases the speed with which interest rate changes and volatility are transmitted among countries. The result of this quickening of global economic adjustment is to increase the difficulty and uncertainty faced by the Federal Reserve as it attempts to manage economic activity within the U.S. Further, because FIs have become increasingly more global in their activities, any change in interest rate levels or volatility caused by Federal Reserve actions more quickly creates additional interest rate risk issues for these companies.3. What is the repricing gap In using this model to evaluate interest raterisk, what is meant by rate sensitivity On what financial performance variable does the repricing model focus Explain.The repricing gap is a measure of the difference between the dollar value of assets that will reprice and the dollar value of liabilities that will reprice within a specific time period, where reprice means the potential to receive a new interest rate. Rate sensitivity represents the time interval where repricing can occur. The model focuses on the potential changes in the net interest income variable. In effect, if interest rates change, interest income and interest expense will change as the various assets and liabilities are repriced, that is, receive new interest rates.4. What is a maturity bucket in the repricing model Why is the length oftime selected for repricing assets and liabilities important when using the repricing modelThe maturity bucket is the time window over which the dollar amounts of assets and liabilities are measured. The length of the repricing period determines which of the securities in a portfolio are rate-sensitive. The longer the repricing period, the more securities either mature or need to be repriced, and, therefore, the more the interest rate exposure. An excessively short repricing period omits consideration of the interest rate risk exposure of assets and liabilities are that repriced in the period immediately following the end of the repricing period. That is, it understates the rate sensitivity of the balance sheet. An excessively long repricing period includes many securities that are repriced at different times within the repricing period, thereby overstating the rate sensitivity of the balance sheet.5. Calculate the repricing gap and the impact on net interest income of a 1percent increase in interest rates for each of the following positions:Rate-sensitive assets = $200 million. Rate-sensitive liabilities =$100 million.Repricing gap = RSA - RSL = $200 - $100 million = +$100 million.NII = ($100 million)(.01) = +$ million, or $1,000,000.Rate-sensitive assets = $100 million. Rate-sensitive liabilities =$150 million.Repricing gap = RSA - RSL = $100 - $150 million = -$50 million.NII = (-$50 million)(.01) = -$ million, or -$500,000.Rate-sensitive assets = $150 million. Rate-sensitive liabilities =$140 million.Repricing gap = RSA - RSL = $150 - $140 million = +$10 million.NII = ($10 million)(.01) = +$ million, or $100,000.a. Calculate the impact on net interest income on each of the abovesituations assuming a 1 percent decrease in interest rates.NII = ($100 million) = -$ million, or -$1,000,000.NII = (-$50 million) = +$ million, or $500,000.NII = ($10 million) = -$ million, or -$100,000.b. What conclusion can you draw about the repricing model from theseresultsThe FIs in parts (1) and (3) are exposed to interest rate declines(positive repricing gap) while the FI in part (2) is exposed to interest rate increases. The FI in part (3) has the lowest interest rate riskexposure since the absolute value of the repricing gap is the lowest,while the opposite is true for part (1).6. What are the reasons for not including demand deposits as rate-sensitiveliabilities in the repricing analysis for a commercial bank What is the subtle, but potentially strong, reason for including demand deposits inthe total of rate-sensitive liabilities Can the same argument be madefor passbook savings accountsThe regulatory rate available on demand deposit accounts is zero. Although many banks are able to offer NOW accounts on which interest can be paid, this interest rate seldom is changed and thus the accounts are not really sensitive. However, demand deposit accounts do pay implicit interest in the form of not charging fully for checking and other services. Further, when market interest rates rise, customers draw down their DDAs, which may cause the bank to use higher cost sources of funds. The same or similar arguments can be made for passbook savings accounts.7. What is the gap ratio What is the value of this ratio to interest raterisk managers and regulatorsThe gap ratio is the ratio of the cumulative gap position to the total assets of the bank. The cumulative gap position is the sum of the individual gaps over several time buckets. The value of this ratio is that it tells the direction of the interest rate exposure and the scale of that exposure relative to the size of the bank.8. Which of the following assets or liabilities fit the one-year rate or repricing sensitivity test91-day . Treasury bills Yes1-year . Treasury notes Yes20-year . Treasury bonds No20-year floating-rate corporate bonds with annual repricing Yes30-year floating-rate mortgages with repricing every two years No30-year floating-rate mortgages with repricing every six months YesOvernight fed funds Yes9-month fixed rate CDs Yes1-year fixed-rate CDs Yes5-year floating-rate CDs with annual repricing YesCommon stock No9. Consider the following balance sheet for WatchoverU Savings, Inc. (in millions):Assets Liabilities and EquityFloating-rate mortgages Demand deposits(currently 10% annually) $50 (currently 6% annually) $7030-year fixed-rate loans Time deposits(currently 7% annually) $50 (currently 6% annually $20Equity $10 Total Assets $100 Total Liabilities & Equity$100a. What is WatchoverU’s expected net interest income at year-endCurrent expected interest income:$5m + $3.5m = $8.5m.Expected interest expense: $4.2m + $1.2m = $5.4m.Expected net interest income: $8.5m - $5.4m = $3.1m.b. What will be the net interest income at year-end if interest ratesrise by 2 percentAfter the 200 basis point interest rate increase, net interest incomedeclines to:50 + 50 - 70 - 20(.06) = $9.5m - $6.8m = $2.7m, a decline of $0.4m.c. Using the cumulative repricing gap model, what is the expected netinterest income for a 2 percent increase in interest rates Wachovia’s' repricing or funding gap is $50m - $70m = -$20m. The change in net interest income using the funding gap model is (-$20m) = -$.4m.d.What will be the net interest income at year-end if interest ratesincrease 200 basis points on assets, but only 100 basis points onliabilities Is it reasonable for changes in interest rates to affectbalance sheet in an uneven manner WhyAfter the unbalanced rate increase, net interest income will be 50 +50 - 70 - 20(.06) = $9.5m - $6.1m = $3.4m, an increase of $0.3m. It isnot uncommon for interest rates to adjust in an uneven manner over two sides of the balance sheet because interest rates often do not adjust solely because of market pressures. In many cases the changes areaffected by decisions of management. Thus you can see the difference between this answer and the answer for part a.10. What are some of the weakness of the repricing model How have largebanks solved the problem of choosing the optimal time period forrepricing What is runoff cash flow, and how does this amount affect the repricing model’s analysisThe repricing model has four general weaknesses:(1) It ignores market value effects.(2) It does not take into account the fact that the dollar value of ratesensitive assets and liabilities within a bucket are not similar. Thus, if assets, on average, are repriced earlier in the bucket thanliabilities, and if interest rates fall, FIs are subject to reinvestment risks.(3) It ignores the problem of runoffs, that is, that some assets are prepaidand some liabilities are withdrawn before the maturity date.(4) It ignores income generated from off-balance-sheet activities.Large banks are able to reprice securities every day using their own internal models so reinvestment and repricing risks can be estimated for each day ofthe year.Runoff cash flow reflects the assets that are repaid before maturity and the liabilities that are withdrawn unsuspectedly. To the extent that either of these amounts is significantly greater than expected, the estimated interest rate sensitivity of the bank will be in error.11. Use the following information about a hypothetical government securitydealer named . Jorgan. Market yields are in parenthesis, and amounts are in millions.Assets Liabilities and EquityCash $10 Overnight Repos $1701 month T-bills %) 75 Subordinated debt3 month T-bills %) 75 7-year fixed rate % 1502 year T-notes %) 508 year T-notes %) 1005 year munis (floating rate)% reset every 6 months) 25 Equity 15 Total Assets $335 Total Liabilities & Equity$335a. What is the funding or repricing gap if the planning period is 30 days91 days 2 years Recall that cash is a noninterest-earning asset.Funding or repricing gap using a 30-day planning period = 75 - 170 = -$95 million.Funding gap using a 91-day planning period = (75 + 75) - 170 = -$20 million.Funding gap using a two-year planning period = (75 + 75 + 50 + 25) - 170 = +$55 million.b. What is the impact over the next 30 days on net interest income if allinterest rates rise 50 basis points Decrease 75 basis pointsNet interest income will decline by $475,000. NII = FG(R) = -95(.005) = $0.475m.Net interest income will increase by $712,500. NII = FG(R)= -95(.0075) = $0.7125m.c.The following one-year runoffs are expected: $10 million for two-yearT-notes, and $20 million for eight-year T-notes. What is the one-year repricing gapFunding or repricing gap over the 1-year planning period = (75 + 75 + 10 + 20 + 25) - 170 = +$35 million.d. If runoffs are considered, what is the effect on net interest incomeat year-end if interest rates rise 50 basis points Decrease 75 basispointsNet interest income will increase by $175,000. NII = FG(R) = 35 = $0.175m.Net interest income will decrease by $262,500, NII = FG(R) = 35 = -$0.2625m.12. What is the difference between book value accounting and market valueaccounting How do interest rate changes affect the value of bank assets and liabilities under the two methods What is marking to marketBook value accounting reports assets and liabilities at the original issue values. Current market values may be different from book values because they reflect current market conditions, such as interest rates or prices. This is especially a problem if an asset or liability has to be liquidated immediately. If the asset or liability is held until maturity, then the reporting of book values does not pose a problem.For an FI, a major factor affecting asset and liability values is interestrate changes. If interest rates increase, the value of both loans (assets) and deposits and debt (liabilities) fall. If assets and liabilities are held until maturity, it does not affect the book valuation of the FI. However, ifdeposits or loans have to be refinanced, then market value accounting presents a better picture of the condition of the FI.The process by which changes in the economic value of assets and liabilities are accounted is called marking to market. The changes can be beneficial as well as detrimental to the total economic health of the FI.13. Why is it important to use market values as opposed to book values whenevaluating the net worth of an FI What are some of the advantages ofusing book values as opposed to market valuesBook values represent historical costs of securities purchased, loans made, and liabilities sold. They do not reflect current values as determined by market values. Effective financial decision-making requires up-to-date information that incorporates current expectations about future events. Market values provide the best estimate of the present condition of an FI and serve as an effective signal to managers for future strategies.Book values are clearly measured and not subject to valuation errors, unlike market values. Moreover, if the FI intends to hold the security until maturity, then the security's current liquidation value will not be relevant. That is, the paper gains and losses resulting from market value changes will never be realized if the FI holds the security until maturity. Thus, the changes in market value will not impact the FI's profitability unless the security is sold prior to maturity.14. Consider a $1,000 bond with a fixed-rate 10 percent annual coupon (Cpn %)and a maturity (N) of 10 years. The bond currently is trading to amarket yield to maturity (YTM) of 10 percent. Complete the followingtable.From Par, $ From Par, %N Cpn % YTM Price Change in Price Change in Price8 10% 9% $1, $ %9 10% 9% $1, $ %10 10% 9% $1, $ %10 10% 10% $1,10 10% 11% $ -$ %11 10% 11% $ -$ %12 10% 11% $ -$ %Use this information to verify the principles of interest rate-pricerelationships for fixed-rate financial assets.Rule One: Interest rates and prices of fixed-rate financial assets move inversely. See the change in price from $1,000 to $ for the change in interest rates from 10 percent to 11 percent, or from $1,000 to $1, when rates change from 10 percent to 9 percent.Rule Two: The longer is the maturity of a fixed-income financial asset, the greater is the change in price for a given change in interest rates.A change in rates from 10 percent to 11 percent has caused the 10-yearbond to decrease in value $, but the 11-year bond will decrease in value $, and the 12-year bond will decrease $.Rule Three: The change in value of longer-term fixed-rate financialassets increases at a decreasing rate. For the increase in rates from 10 percent to 11 percent, the difference in the change in price between the 10-year and 11-year assets is $, while the difference in the change in price between the 11-year and 12-year assets is $.Rule Four: Although not mentioned in the text, for a given percentage () change in interest rates, the increase in price for a decrease in ratesis greater than the decrease in value for an increase in rates. Thus for rates decreasing from 10 percent to 9 percent, the 10-year bond increases $. But for rates increasing from 10 percent to 11 percent, the 10-year bond decreases $.15. Consider a 12-year, 12 percent annual coupon bond with a required returnof 10 percent. The bond has a face value of $1,000.a. What is the price of the bondPV = $120*PVIFAi=10%,n=12 + $1,000*PVIFi=10%,n=12= $1,b. If interest rates rise to 11 percent, what is the price of the bondPV = $120*PVIFAi=11%,n=12 + $1,000*PVIFi=11%,n=12= $1,c. What has been the percentage change in priceP = ($1, - $1,/$1, = or – percent.d. Repeat parts (a), (b), and (c) for a 16-year bond.PV = $120*PVIFAi=10%,n=16 + $1,000*PVIFi=10%,n=16= $1,PV = $120*PVIFAi=11%,n=16 + $1,000*PVIFi=11%,n=16= $1,P = ($1, - $1,/$1, = or – percent.e. What do the respective changes in bond prices indicateFor the same change in interest rates, longer-term fixed-rate assets have a greater change in price.16. Consider a five-year, 15 percent annual coupon bond with a face value of$1,000. The bond is trading at a market yield to maturity of 12 percent.a. What is the price of the bondPV = $150*PVIFAi=12%,n=5 + $1,000*PVIFi=12%,n=5= $1,b. If the market yield to maturity increases 1 percent, what will be thebond’s new pricePV = $150*PVIFAi=13%,n=5 + $1,000*PVIFi=13%,n=5= $1,c. Using your answers to parts (a) and (b), what is the percentage changein the bond’s price as a result of the 1 percent increase in interest ratesP = ($1, - $1,/$1, = or – percent.d. Repeat parts (b) and (c) assuming a 1 percent decrease in interestrates.PV = $150*PVIFAi=11%,n=5 + $1,000*PVIFi=11%,n=5= $1,P = ($1, - $1,/$1, = or percente. What do the differences in your answers indicate about the rate-pricerelationships of fixed-rate assetsFor a given percentage change in interest rates, the absolute value of the increase in price caused by a decrease in rates is greater than the absolute value of the decrease in price caused by an increase in rates.17. What is maturity gap How can the maturity model be used to immunize anFI’s portfolio What is the critical requirement to allow maturitymatching to have some success in immunizing the balance sheet of an FIMaturity gap is the difference between the average maturity of assets and liabilities. If the maturity gap is zero, it is possible to immunize the portfolio, so that changes in interest rates will result in equal but offsetting changes in the value of assets and liabilities and net interest income. Thus, if interest rates increase (decrease), the fall (rise) in the value of the assets will be offset by a perfect fall (rise) in the value of the liabilities. The critical assumption is that the timing of the cash flows on the assets and liabilities must be the same.18. Nearby Bank has the following balance sheet (in millions):Assets Liabilities and EquityCash $60 Demand deposits $1405-year treasury notes $60 1-year Certificates of Deposit $160 30-year mortgages $200 Equity $20Total Assets $320 Total Liabilities and Equity$320What is the maturity gap for Nearby Bank Is Nearby Bank more exposed to an increase or decrease in interest rates Explain whyM A = [0*60 + 5*60 + 200*30]/320 = years, and ML= [0*140 + 1*160]/300 = .Therefore the maturity gap = MGAP = – = years. Nearby bank is exposed toan increase in interest rates. If rates rise, the value of assets will decrease much more than the value of liabilities.19. County Bank has the following market value balance sheet (in millions,annual rates):Assets Liabilities and EquityCash $20 Demand deposits $10015-year commercial loan @ 10% 5-year CDs @ 6% interest,interest, balloon payment $160 balloon payment $21030-year Mortgages @ 8% interest, 20-year debentures @ 7% interest$120monthly amortizing $300 Equity $50Total Assets $480 Total Liabilities & Equity $480a. What is the maturity gap for County BankMA= [0*20 + 15*160 + 30*300]/480 = years.ML= [0*100 + 5*210 + 20*120]/430 = years.MGAP = – = years.b. What will be the maturity gap if the interest rates on all assets andliabilities increase by 1 percentIf interest rates increase one percent, the value and average maturity of the assets will be:Cash = $20Commercial loans = $16*PVIFAn=15, i=11% + $160*PVIFn=15,i=11%= $Mortgages = $,294*PVIFAn=360,i=9%= $MA= [0*20 + *15 + *30]/(20 + + = yearsThe value and average maturity of the liabilities will be: Demand deposits = $100CDs = $*PVIFAn=5,i=7% + $210*PVIFn=5,i=7%= $Debentures = $*PVIFAn=20,i=8% + $120*PVIFn=20,i=8%= $ML= [0*100 + 5* + 20*]/(100 + + = yearsThe maturity gap = MGAP = – = years. The maturity gap increased because the average maturity of the liabilities decreased more than the average maturity of the assets. This result occurred primarily because of the differences in the cash flow streams for the mortgages and the debentures.c. What will happen to the market value of the equityThe market value of the assets has decreased from $480 to $, or $. The market value of the liabilities has decreased from $430 to $, or $. Therefore the market value of the equity will decrease by $ - $ = $, or percent.d. If interest rates increased by 2 percent, would the bank be solvent The value of the assets would decrease to $, and the value of the liabilities would decrease to $. Therefore the value of the equity would be $. Although the bank remains solvent, nearly 65 percent of the equity has eroded because of the increase in interest rates.20. Given that bank balance sheets typically are accounted in book valueterms, why should the regulators or anyone else be concerned about howinterest rates affect the market values of assets and liabilitiesThe solvency of the balance sheet is an important variable to creditors of the bank. If the capital position of the bank decreases to near zero, creditors may not be willing to provide funding for the bank, and the bank may need assistance from the regulators, or may even fail. Thus any change in the market value of assets or liabilities that is caused by changes in the level of interest rate changes is of concern to regulators.21. If a bank manager is certain that interest rates were going to increasewithin the next six months, how should the bank manager adjust thebank’s maturity gap to take advantage of this antici pated increase What if the manager believed rates would fall Would your suggestedadjustments be difficult or easy to achieveWhen rates rise, the value of the longer-lived assets will fall by more the shorter-lived liabilities. If the maturity gap (or duration gap) is positive, the bank manager will want to shorten the maturity gap. If the repricing gap is negative, the manager will want to move it towards zero or positive. If rates are expected to decrease, the manager should reverse these strategies. Changing the maturity, duration, or funding gaps on the balance sheet often involves changing the mix of assets and liabilities. Attempts to make these changes may involve changes in financial strategy for the bank which may notbe easy to accomplish. Later in the text, methods of achieving the same results using derivatives will be explored.22. Consumer Bank has $20 million in cash and a $180 million loan portfolio.The assets are funded with demand deposits of $18 million, a $162 million CD and $20 million in equity. The loan portfolio has a maturity of 2years, earns interest at the annual rate of 7 percent, and is amortized monthly. The bank pays 7 percent annual interest on the CD, but theinterest will not be paid until the CD matures at the end of 2 years.a. What is the maturity gap for Consumer Bank= [0*$20 + 2*$180]/$200 = yearsMA= [0*$18 + 2*$162]/$180 = yearsMLMGAP = – = 0 years.b. Is Consumer Bank immunized or protected against changes in interestrates Why or why notIt is tempting to conclude that the bank is immunized because thematurity gap is zero. However, the cash flow stream for the loan and the cash flow stream for the CD are different because the loan amortizesmonthly and the CD pays annual interest on the CD. Thus any change in interest rates will affect the earning power of the loan more than the interest cost of the CD.c. Does Consumer Bank face interest rate risk That is, if marketinterest rates increase or decrease 1 percent, what happens to thevalue of the equityThe bank does face interest rate risk. If market rates increase 1percent, the value of the cash and demand deposits does not change.However, the value of the loan will decrease to $, and the value of the CD will fall to $. Thus the value of the equity will be ($ + $20 - $18 - $ = $. In this case the increase in interest rates causes the marketvalue of equity to increase because of the reinvestment opportunities on the loan payments.If market rates decrease 1 percent, the value of the loan increases to $, and the value of the CD increases to $. Thus the value of the equitydecreases to $.d. How can a decrease in interest rates create interest rate riskThe amortized loan payments would be reinvested at lower rates. Thuseven though interest rates have decreased, the different cash flowpatterns of the loan and the CD have caused interest rate risk.23. FI International holds seven-year Acme International bonds and two-yearBeta Corporation bonds. The Acme bonds are yielding 12 percent and the Beta bonds are yielding 14 percent under current market conditions.a. What is the weighted-average maturity of FI’s bond portfolio if 40percent is in Acme bonds and 60 percent is in Beta bondsAverage maturity = x 7 years + x 2 years = 4 yearsb. What proportion of Acme and Beta bonds should be held to have aweighted-average yield of percentLet X* + (1 - X)* = . Solving for X, we get 25 percent. In order to get an average yield of percent, we need to hold 25 percent of Acme and 75 percent of Beta.c. What will be the weighted-average maturity of the bond portfolio ifthe weighted-average yield is realizedThe average maturity of the portfolio will decrease to x 7 + x 2 = years.24. An insurance company has invested in the following fixed-incomesecurities: (a) $10,000,000 of 5-year Treasury notes paying 5 percentinterest and selling at par value, (b) $5,800,000 of 10-year bonds paying7 percent interest with a par value of $6,000,000, and (c) $6,200,000 of20-year subordinated debentures paying 9 percent interest with a parvalue of $6,000,000.a. What is the weighted-average maturity of this portfolio of assets= [5*$10 + 10*$ + 20*$]/$22 = 232/22 = yearsMAb. If interest rates change so that the yields on all of the securitiesdecrease 1 percent, how does the weighted-average maturity of theportfolio changeTo determine the weighted-average maturity of the portfolio for a rate decrease of 1 percent, the new value of each security must be determined. This calculation will require knowing the YTM of each security before the rate change.T-notes are selling at par, so the YTM = 5 percent. Therefore, the new value will bePV = $500,000*PVIFAn=5,i=4% + $10,000,000*PVIFn=5,i=4%= $10,445,182.10-year bonds: Par = $6,000,000, PV = $5,800,000, Cpn = 7 percent YTM= %. The new PV = $420,000*PVIFAn=10,i=% + $6,000,000*PVIFn=10,i=%= $6,222,290.Debentures: Par = $6,000,000, PV = $6,200,000, Cpn = 9 percentpercent. The new PV = $540,000*PVIFAn=20,i=% + $6,000,000*PVIFn=20,i==$6,820,418.The total value of the assets after the change in rates will be$23,487,890, and the weighted-average maturity will be [5*10,445,182 +10*6,222,290 + 20*6,820,418]/23,487,890 = 250,857,170/23,487,890 = years.c. Explain the changes in the maturity values if the yields increase by 1 percent.。
2018年10月福建省自考00812中国现当代作家作品专题研究试题及答案含评分标准
2018年10月高等教育自学考试福建省统一命题考试中国现当代作家作品专题研究试卷(课程代码00812)本试卷满分100分，考试时间l50分钟。
考生答题注意事项：1．本卷所有试题必须在答题卡上作答。
答在试卷上无效，试卷空白处和背面均可作草稿纸。
2．第一部分为选择题。
必须对应试卷上的题号使用2B铅笔将“答题卡”的相应代码涂黑。
3．第二部分为非选择题。
必须注明大、小题号，使用0．5毫米黑色字迹签字笔作答。
4．合理安排答题空间，超出答题区域无效。
第一部分选择题一、单项选择题(本大题共l0小题，每小题2分，共20分)在每小题列出的四个备选项中只有一个是最符合题目要求的。
请将其选出并将“答题卡”的相应代码涂黑。
未涂、错涂或多涂均无分。
1．下列不属于“五四新文化运动的四大副刊”的是A．《学灯》 B．《京报副刊》 C．《晨报副刊》 D．《每周评论》2．将封建统治者痛斥为“四眼狗、独眼龙、烂脚阿二、缺嘴阿四”的作家是A．钱玄同 B．刘半农 C．陈独秀 D．李大钊3．《巴黎的鳞爪》的作者是A．徐志摩 B．梁绍文 C．冰心 D．孙福熙4．下列作品中不属于《泽泻集》的是A．《故乡的野菜》 B．《荔枝》 C．《谈酒》 D．《乌篷船》5．下列鲁迅杂文集作品，按时间顺序排列正确的是①《伪自由书》②《三闲集》③《且介亭杂文》A．①②③ B．①③② C．②③① D．②①③6．下列作家中，以细菌学科学小品为大众所熟悉，《细菌的衣食住行》的作者是A．董纯才 B．顾均正 C．高士其 D．贾祖璋7．关于鲁迅杂文的思想和艺术特质，在二十世纪三四十年代曾发生过三次争论，第二次争论发生在A．上海 B. 北平 C．南京 D．延安8．下列作家中，不属于昆明杂文作家群的是A．闻一多 B．谢觉哉 C．吴晗 D．钱钟书9．为中国30年代方兴未艾的报告文学创作提供了“好范例”，该作品是捷克著名报告文学家基希的A．《未来的秘密》 B．《战地日记》 C．《秘密的中国》 D．《洪流》10．报告文学作品《海上的遭遇》、《诺尔曼。
2#008年高考试题——数学理(江西卷)(有答案解析及评分标准)
绝密★启用前2008年普通高等学校招生全国统一考试（江西卷） 理科数学本试卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）两部分，第Ⅰ卷1至2页，第Ⅱ卷3至4页，共150分。
第Ⅰ卷 考生注意：答题前，考生务必将自己的准考证号、姓名填写在答题卡上，考生要认真核对答题卡上粘贴的条形码的“准考证号、姓名、考试科目”与考生本人准考证号、姓名是否一致。
第I 卷每小题选出答案后，用2B 铅笔把答题卡上对应题目的答案标号涂黑，如需改动，用橡皮擦干净后，再选涂其他答案标号。
第Ⅱ卷用黑色墨水签字笔在答题卡上作答。
若在试题卷上作答，答案无效。
考试结束，监考员将试题卷、答题卡一并收回。
参考公式如果事件,A B 互斥，那么 球的表面积公式()()()P A B P A P B +=+ 24S R π=如果事件,A B ，相互独立，那么 其中R 表示球的半径()()()P A B P A P B ⋅=⋅ 球的体积公式如果事件A 在一次试验中发生的概率是p ，那么343V R π=n 次独立重复试验中恰好发生k 次的概率 其中R 表示球的半径()(1)kk n k n n P k C p p -=-一．选择题：本大题共12小题，每小题5分，共60分。
在每小题给出的四个选项中，只有一项是符合题目要求的。
1．在复平面内，复数sin 2cos 2z i =+对应的点位于A ．第一象限B ．第二象限C ．第三象限D ．第四象限 2．定义集合运算:{},,.A B z z xy x A y B *==∈∈设{}1,2A =,{}0,2B =,则集合A B *的所有元素之和为A ．0B ．2C ．3D ．63．若函数()y f x =的值域是1[,3]2，则函数1()()()F x f x f x =+的值域是A ．1[,3]2B ．10[2,]3 C ．510[,]23 D ．10[3,]3 4．1x →=A ．12B ．0C ．12-D ．不存在 5．在数列{}n a 中，12a =， 11ln(1)n n a a n +=++，则n a =A ．2ln n +B ．2(1)ln n n +-C ．2ln n n +D ．1ln n n ++6．函数tan sin tan sin y x x x x =+--在区间3(,)22ππ内的图象是 7．已知1F 、2F 是椭圆的两个焦点，满足120MF MF ⋅=的点M 总在椭圆内部，则椭圆离心率的取值范围是A ．(0,1)B ．1(0,]2 C． D．8．610(1(1++展开式中的常数项为A ．1B ．46C ．4245D ．4246 9若121212120,01a ab b a a b b <<<<+=+=,且，则下列代数式中值最大的是A ．1122a b a b + B ．1212a a b b + C ．1221a b a b + D ．12AB-CD-10．连结球面上两点的线段称为球的弦。
试题008——第六章实数单元测试题四
第六章实数单元测试题四姓名_____________ 成绩_____________(一)、精心选一选（每小题 分，共 分)1． 有下列说法：（1）无理数就是开方开不尽的数； （2）无理数包括正无理数、零、负无理数； （3）无理数是无限不循环小数；（4）无理数都可以用数轴上的点来表示。
其中正确的说法的个数是（ ） A ．1 B ．2 C ．3 D ．42．如果一个实数的平方根与它的立方根相等，则这个数是（ ） A ． 0 B ． 正整数 C ． 0和1 D ． 1 3.能与数轴上的点一一对应的是（ ）A 整数B 有理数C 无理数D 实数 4. 下列各数中，不是无理数的是 （ ）A.7B. 0.5C. 2πD. 0.151151115…）个之间依次多两个115( 5．()20.7-的平方根是（ ）A ．0.7-B ．0.7±C ．0.7D ．0.49 6. 下列说法正确的是（ ）A ． 0.25是0.5 的一个平方根B ．.正数有两个平方根，且这两个平方根之和等于0C ． 7 2 的平方根是7D ． 负数有一个平方根7.一个数的平方根等于它的立方根，这个数是 （ ） A.0 B.－1 C.1 D.不存在8.下列运算中，错误的是 （ ） ①1251144251=，②4)4(2±=-，③3311-=- ④2095141251161=+=+A ． 1个 B. 2个 C. 3个 D. 4个9. 若225a =，3b =，则b a +的值为 （ ）A ．-8B ．±8C ．±2D ．±8或±2 (二)、细心填一填 (每小题 分，共 分)10．在数轴上表示3-的点离原点的距离是 。
设面积为5的正方形的边长为x ,那么x =11. 9的算术平方根是 ；94的平方根是 ,271的立方根是 ,－125的立方根是 . 12.25-的相反数是 ，32-= ；13. =-2)4( ； =-33)6( ； 2)196(= . 38-= .14. 比较大小:3 2；215- 5.0； (填“>”或“<”)15. 要使62-x 有意义，x 应满足的条件是 16.已知051=-+-b a ，则2)(b a -的平方根是________；17.若102.0110.1=，则± 1.0201= ； 18. 一个正数x 的平方根是2a -3与5-a ，则a=________；19.一个圆它的面积是半径为3cm 的圆的面积的25倍，则这个圆的半径为_______. (三)、用心做一做 （ 分，大概 小题)20．（6分）将下列各数填入相应的集合内。
电气工程师《(发输变电)专业基础》真题_008
2016年电气工程师<(发输变电)专业基础>真题第1题(单项选择题)图示电路中，电流I为( ).A.2.25AB.2AC.1AD.0.75A正确答案:A，第2题(单项选择题)已知某电源的开路电压为220V，内阻为50Ω，如果把一个负载电阻R接到此电源上，当R为下列何值时，负载获得最大功率( )A.25ΩB.50ΩC.100ΩD.125Ω正确答案:B，第3题(单项选择题)日光灯可以等效为一RL串联电路，将一日光灯接于50HZ的正弦交流电压源上，测得端电压为220V，电流为0.4A，有功功率为40W，那么，该日光灯吸收的无功功率为( ).A.78.4KVARB.68.4KVARC.58.4KVARD.48.4KVAR正确答案:A，第4题(单项选择题)A.(4+J13)ΩB.(8+J26)ΩC.(9+J5)ΩD.(3+J10)Ω正确答案:B，第5题(单项选择题)一电阻R=20Ω，电感L=0.25MH和可变电容相串联，为了接收到某广播电台560KHZ的信号，可变电容C应调至( ).A.153PFB.253PFC.323PFD.353PF第6题(单项选择题)图示三相电路中，工频电源线电压为380V，对称感性负载的有功功率P=15KW，功率因数COSφ=0.6，为了将线路的功率提高到COSφ=0.95，每相应并联的电容器的电容量C为( ).A.110.74μFB.700.68μFC.705.35μFD.710.28μF正确答案:A，第7题(单项选择题)图示电路，换路前已处于稳定状态，在T=0时开关K打开，换路后的电感电流IL(R)为( ).A.(3-E-0.05T)AB.(3+E-0.05T)AC.(3+E-20T)AD.(3-E-20T)A第8题(单项选择题)在真空中，半径为R的均匀带电半球面，其面电荷密度为σ，该半球面球心处的电场强度值为( ).正确答案:B，第9题(单项选择题)真空中两平行均匀带电平板相距为D，面积为S，且有D2正确答案:B，第10题(单项选择题)电阻R1=10Ω和电阻R2=5Ω相并联，已知流过这两个电阻的总电流I=3A，那么，流过电阻R1的电流I1为( ).A.0.5AB.1AC.1.5AD.2A正确答案:B，第11题(单项选择题)图示电路中，电流I为( ).A.0.5AB.1AC.1.5AD.2A正确答案:A，第12题(单项选择题)图示电路，当电流源IS1=5A，电流源IS2=2A 时，电流I=1.8A;当电流源IS1=2A，电流源IS2=8A时，电流I=0A.那么，当电流源IS1=2A，电流源IS1=-2A时，则电流I为( ).A.0.5AB.0.8AC.0.9AD.1.0A正确答案:D，第13题(单项选择题)图示电路，含源二端口的入端电阻RIN为下列哪项数值( )A.5ΩB.10ΩC.15ΩD.20Ω正确答案:C，第14题(单项选择题)正确答案:C，第15题(单项选择题)在RLC串联电路中，已知R=10Ω，L=0.05H，C=50μF，电源电压为U(T)=20+90SIN(ωT)+30SIN(3ωT+45°)V，且电源电压角频率为ω=314RAD/S，则电路中的电流为( ).正确答案:A，第16题(单项选择题)一RLC串联电路中，C=1μF，L=1H，当R小于下列哪项数值时，放电过程是振荡性质的( )A.1000ΩB.2000ΩC.3000ΩD.4000Ω正确答案:B，第17题(单项选择题)特性阻抗ZC=100Ω，长度为的无损耗线，输出端接有负载ZL=(200+J300)Ω，输入端接有内阻为100Ω，电压为500∠0°V的电源，传输线输入端的电压为( ).A.372.68∠-26.565°VB.372.68∠26.565°VC.-372.68∠26.565°VD.-372.68∠-26.565°V正确答案:A，第18题(单项选择题)晶体管的参数受温度影响较大，当温度升高时，晶体管的β、ICBO和UBE的变化情况分别为( ).A.β增加，ICBO和UBE减小B.β和ICBO增加，UBE减小C.β和UBE减小，ICBO增加D.β、ICBO和UBE都增加正确答案:B，第19题(单项选择题)四位双向移位寄存器74194组成的电路如图所示，74194的功能表如表所示，该电路的状态转换图为( ).A.图(A)B.图(B)C.图(C)D.图(D)正确答案:A，第20题(单项选择题)利用CMOS集成施密特触发器组成的多谐振荡器如图所示，设施密特触发器的上、下限阀值电平分别为则电路的振荡周期约为( ).A.0.7RCB.1.1RCC.1.4RCD.2.2RC正确答案:C，第21题(单项选择题)一台三相双绕组变压器，额定容量SN=100KVA，额定电压U1N/U2N=3000/400V，YYN0连接，现将其改为3000/3400V的升压自耦变压器，改接后其额定容量与电磁容量之比为( ).A.8.5B.7.5C.1.1333D.1正确答案:A，第22题(单项选择题)A.3428.5KVAB.5226.67KVAC.5600.5VD.5625.5V正确答案:B，第23题(单项选择题)同步发电机突然发生三相短路后励磁绕组中的电流分量有( ).A.直流分量，周期交流B.倍频分量、直流分量C.直流分量、基波交流分量D.周期分量、倍频分量正确答案:C，第24题(单项选择题)A.107.6KAB.91.48KAC.76.1KAD.60.99KA正确答案:A，第25题(单项选择题)关于自耦变压器的运行方式，以下描述正确的是( ).A.联合运行方式下，当高压侧同时向中压侧和低压侧送电时，最大传输功率受公共绕组容量的限制B.联合运行方式下，当中压侧同时向高压侧和低压侧送电时，最大传输功率受串联绕组容量的限制C.联合运行方式下，当高压侧同时向中压侧和低压侧送电时，最大传输功率受第三绕组容量的限制D.联合运行方式下，当中压侧同时向高压侧和低压侧送电时，最大传输功率受公共绕组容量的限制正确答案:D，第26题(单项选择题)气体中固体介质表面滑闪放电的特征是( ).A.碰撞电离B.热电离C.阴极发射电离D.电子崩电离正确答案:B，第27题(单项选择题)下列哪种方法会使电场分布更加劣化( )A.采用多层介质并在电场强的区域采用介电常数较小的电介质B.补偿杂散电容C.增设中间电极D.增大电极曲率半径正确答案:C，第28题(单项选择题)电力系统中输电线路架空地线采用分段绝缘方式的目的是( ).A.减小零序阻抗B.提高输送容量C.增强诱雷效果D.降低线路损耗正确答案:D，第29题(单项选择题)图示已知一幅值ε=1000KV的直流电压源在T=0时刻合闸于波阻抗Z=200Ω、300KM长的空载架空线路传播，传播速度为300KM/MS，下列哪项为线路中点的电压波形( )正确答案:C，第30题(单项选择题)在真空中，有两条长直导线各载有5A的电流，分别沿X，Y轴正向流动，在(40，20，0)CM处的磁感应强度B的大小为( ).A.2.56*10-6TB.3.58*10-6TC.4.54*10-6TD.5.53*10-6T正确答案:A，第31题(单项选择题)一个由钢条组成的接地体系统，已知其接地电阻为100Ω，土壤的电导率γ=10-2S/M，设有短路电流500A从钢条流入地中，有人正以0.6M的步距向此接地体系统前进，前足距钢条中心2M，则跨步电压为下列哪项数值( )(可将接地体系统用一等效的半球形接地器代替之)A.420.2VB.520.2VC.918.2VD.1020.2V正确答案:C，第32题(单项选择题)电路如图所示，若更换晶体管，使B由50变为100，则电路的电压放大倍数约为( ).A.原来值的1/2B.原来的值C.原来值的2倍D.原来的4倍正确答案:C，第33题(单项选择题)电路如图所示，其中电位器RW的作用为( ).A.提高KCMRB.调零C.提高%7CAUD%7CD.减小%7CAUD%7C正确答案:B，第34题(单项选择题)若题22图所示电路的参数满足RC1=RC2=RC，RB1=RB2=RB，β1=β2=β，RBE1=RBE2=RBE.电位器滑动端调在中点，则该电路的差模输入电阻RID为( ).正确答案:A，第35题(单项选择题)电路如图所示，已知运放性能理想，其最大的输出电流为15MA，最大的输出电压幅值为15V，设晶体管T1和T2的性能完全相同，β=60，|UBE|=0.7V，RL=10Ω，那么，电路的最大不失真输出功率为( ).A.4.19WB.11.25WC.16.2WD.22.5W正确答案:C，第36题(单项选择题)JK触发器外部连接如图所示，则其输出可表达为( ).正确答案:D，第37题(单项选择题)正确答案:A，第38题(单项选择题)图示电路的逻辑功能为( ).A.四位二进制加法器B.四位二进制减法器C.四位二进制加/减法器D.四位二进制比较器正确答案:B，第39题(单项选择题)一台并励直流电动机，额定电压为110V，电枢回路电阻(含电刷接触电阻)为0.045Ω，当电动机加上额定电压并带一定负载转矩T1时，其转速为1000R/MIN，电枢电流为40A，现将负载转矩增大到原来的4倍(忽略电枢反应)，稳定后电动机的转速为( ).A.250R/MINB.684R/MINC.950R/MIND.1000R/MIN正确答案:C，第40题(单项选择题)一台三相绕线式感应电机，额定电压UN=380V，当定子加额定电压、转子不转并开路时的集电环电压为254V，定、转子绕组都为Y连接，已知定、转子一相的参数为R1=0.044Ω，X1σ=0.54Ω，R2=0.027Ω，X2σ=0.24Ω，忽略励磁电流，当定子加额定电压、转子堵转时的转子相电流为( ).A.304AB.203AC.135.8AD.101.3A正确答案:B，第41题(单项选择题)一台三相4极Y连接的绕线式感应电动机，FN=50HZ、PN=150KW、UN=380V，额定负载时测得其转子铜损耗PCU2=2210W，机械损耗PΦ=2640W、杂散损耗PZ=1000W，额定运行时的电磁转矩为( ).A.955NMB.958NMC.992NMD.1000NM正确答案:C，第42题(单项选择题)一台汽轮发电机，额定功率PN=15MW，额定电压UN=10.5KV(Y连接)，额定功率因数COSφN=0.85(滞后)，当其在额定状态下运行时，输出的无功功率Q为( ).A.9296KVARB.11250KVARC.17647KVARD.18750KVAR正确答案:A，第43题(单项选择题)一台汽轮发电机，额定容量SN=31250KVA，额定电压UN=10500V(星形连接)，额定功率因数COSφN=0.8(滞后)，定子每相同步电抗Xσ=7Ω(不饱和值)，此发电机并联于无限大电网运行，在额定运行状态下，将其励磁电流加大10%，稳定后功角δ将变为( ).A.32.24°B.35.93°C.36.87°D.53.13°正确答案:A，第44题(单项选择题)A.108.04VB.109.4VC.110VD.115V正确答案:C，第45题(单项选择题)输电线路单位长度阻抗ZL，导纳为YL，长度为L，传播系数为γ，波阻抗ZC为( ).正确答案:B，第46题(单项选择题)已知变压器铭牌参数，确定变压器电抗XT的计算公式( ).正确答案:B，第47题(单项选择题)电力系统的一次调频为( ).A.调速器自动调整的有差调节B.调频器自动调整的有差调节C.调速器自动调整的无差调节D.调频器自动调整的无差调节正确答案:A，第48题(单项选择题)在高压网中线路串联电容器的目的是( ).A.补偿系统容性无功调压B.补偿系统感性无功调压C.通过减少线路电抗调压D.通过减少线路电抗提高输送容量正确答案:D，第49题(单项选择题)中性点不接地系统，单相故障时非故障相电压升高到原来对地电压的( ).正确答案:D，第50题(单项选择题)正确答案:C，第51题(单项选择题)简单电力系统接线如下图所示，变压器变比为110(1+2*2.5%)/11KV，线路和变压器归算到高压侧的阻抗为27+J82.4Ω，母线I电压恒等于116KV，变压器低压母线最大负荷为20+J14MVA，最小负荷为10+J7MVA，母线J常调压保持10.5KV，满足以上要求时接在母线J上的电容器及变压器TJ的变比分别为下列哪组数值( )(不考虑电压降横分量和功率损耗)A.9.76MVAR，115.5/11KVB.8.44MVAR，121/11KVC.9.76MVAR，121/10.5KVD.8.13MVAR，112.75/11KV正确答案:D，第52题(单项选择题)下图中系统S参数不详，已知开关B的短路容量2500MVA，发电厂G和变压器T额定容量均为100MVA，X``D=0.195，X*T=0.105，三条线路单位长度电抗均为0.4Ω/KM，线路长度均为100KM，若母线A处发生三相短路，短路点冲击电流和短路容量分别为下列哪组数值( )(SB=100MVA)A.4.91KA，542.2MVAB.3.85KA，385.4MVAC.6.94KA，542.9MVAD.2.72KA，272.6MVA正确答案:C，第53题(单项选择题)已知图示系统变压器星形侧发生BC两相短路时的短路电流为IF，则三角形侧的单相线电流为( ).正确答案:B，第54题(单项选择题)发电机、变压器和负荷阻抗标幺值在图中(SB=100MVA)，试计算图示网络中F点发生两相短路接地时，短路点A 相电压和B相电流分别为( ).A.107.64KV，4.94KAB.107.64KV，8.57KAC.62.15KV，8.57KAD.62.15KV，4.94KA正确答案:D，第55题(单项选择题)关于桥形接线，以下说法正确的是( ).A.内桥接线一般适用于线路较长和变压器不需要经常切换的情况B.内桥接线一般适用于线路较短和变压器不需要经常切换的情况C.外桥接线一般适用于线路较短和变压器不需要经常切换的情况D.外桥接线一般适用于线路较长和变压器不需要经常切换的情况正确答案:A，第56题(单项选择题)当用于35KV及以下中性点不接地系统时，电压互感器剩余电压绕组的二次额定电压应选择为( ).正确答案:B，第57题(单项选择题)关于交流电弧熄灭后的弧隙电压恢复过程，以下描述正确的是( ).A.当触头间并联电阻小于临界电阻时，电压恢复过程为周期性的B.当触头间并联电阻大于临界电阻时，电压恢复过程为非周期性的C.开断中性点不直接接地系统三相短路时，首先开断的工频恢复电压为相电压的1.5倍D.开断中性点不直接接地系统三相短路时，首选开断相熄弧之后，其余两相电弧同时熄灭，每一相工频恢复电压为相电压的1.732倍正确答案:C，第58题(单项选择题)以下关于电流互感器的描述中，正确的是( ).A.电流互感器的误差仅与二次负荷有关系，与一次电流无关B.电流互感器的二次侧开路运行时，二次绕组将在磁通过零时感应产生很高的尖顶波电流，危及设备及人身安全C.某电流互感器的准确级和额定准确限制系数分别为5P和40，则表示在电力系统一次电流为40倍额定电流时，其电流误差不超过5%D.电流互感器的误差仅与一次电流有关，与二次负荷无关正确答案:C，第59题(单项选择题)影响气体中固体介质沿面闪络电压的主要因素是( ).A.介质表面平行电场分量B.介质厚度C.介质表面粗糙度D.介质表面垂直电场分量正确答案:B，第60题(单项选择题)提高不均匀电场中含杂质低品质绝缘油工频击穿电压的有效方法是( ).A.降低运行环境温度B.减小气体在油重的溶解量C.改善电场均匀程度D.油重设置固体绝缘屏障正确答案:C，。
008高等教育心理学最新题库60套
11、12岁以后
2-5岁
5-8岁
04根据皮亚杰儿童品德发展阶段理论，儿童的公正感以“平等”的观念为主要特征年龄阶段是（）
8-11、12岁
11、12岁以后
2-5岁
5-8岁
05根据皮亚杰儿童品德发展阶段理论，儿童的品德发展真正到了自律阶段的年龄是（）
8-11、12岁
11、12岁以后
2-5岁
掌握学习
个别化学习
接受学习
发现学习
18在教学中，教师引导学生回忆与当前学习有关的已学习的内容、个人生活经验。这样的做法是（）
呈现先行组织者
教材分析
优化认知结构
提供学习材料
19重过程，重视评价对象的主体性的，以促进评价对象发展为根本目的的教学评价是（）
发展取向的教学评价
成就取向教学评价
结果取向的教学评价
关注强化的作用
重视认知和情感
43斯金纳将反应区分为（）
条件反应
无条件反应
应答反应
操作反应
非条件反应
44附属内驱力的产生依赖两个条件，它们是（）
长者评价获的派生地位
个体的年龄
学生认可的长者的评价
强化物的特点
个体的性格
45罗杰斯的人本主义学习理论重视心理因素在学习中的作用，要求关注（）
学习动机
态度、价值观、情感
表象
符号
命题
概念
推理
53下列选项中属于程序性知识的是（）
方法
窍门
技术
策略
经验
54下列知识属于程序性知识范畴的是（）
技能性知识
定理性知识
元认知知识
认知策略知识
通识性知识
55下列表征方式中属于程序性知识的表征方式系统
【答案】CSJ008-无源器件、天线-考核试题 大学试卷试题
姓名：得分：一、单项选择题（每题2分；共20分）1.以下关于天线的描述错误的是：（D）A.天线是能够有效地向空间某特定方向辐射电磁波的装置。
B.天线是能够有效地接收空间某特定方向来的电磁波的装置。
C.无线电发射机输出的射频信号功率通过馈线输送到天线，由天线以电磁波形式辐射出去。
D.电磁波到达接收点后，由天线将全部功率接收下来并通过馈线送到无线电接收机。
2.天线的功能不包括（A）A.信号过滤B.能量转换C.定向辐射D.定向接收3.关于天线的增益，以下定义准确的是：（B）A.增益是指实际天线与理想的辐射单元在空间同一点处所产生的信号的功率密度之比。
B.增益是指在输入功率相等的条件下，实际天线与理想的辐射单元在空间同一点处所产生的信号的功率密度之比。
C.增益是指理想的辐射单元与实际天线在空间同一点处所产生的信号的功率密度之比。
D.增益是指在输入功率相等的条件下，理想的辐射单元与实际天线在空间同一点处所产生的信号的功率密度之比。
4.以下关于波瓣的描述错误的是：（C）A.波瓣宽度越窄，方向性越好，作用距离越远，抗干扰能力越强。
B.在主瓣最大辐射方向两侧,辐射强度降低10dB的两点间的夹角定义为10dB波瓣宽度。
C.在主瓣最大辐射方向两侧,功率密度降低三倍的两点间的夹角定义为3dB波瓣宽度。
D.波瓣宽度又称波束宽度或主瓣宽度或半功率角。
5.我们通常说的天线方向图指的是：（ B ）A.辐射方向图B.功率方向图C.场强方向图D.增益方向图6.关于双极化天线描述错误的是：（C）A.双极化天线辐射（或接收）两个极化在空间相互正交（垂直）的波。
B.常见的天线极化方向有水平/垂直极化和+45°/-45°极化。
C.天线向周围空间辐射电磁波。
人们规定：磁场的方向就是天线极化方向。
D.当接收天线的极化方向与来波的极化方向正交时，接收天线完全接收不到来波的能量。
7.下列天线不属于定向天线的是：（D）A.平板天线B.栅格天线C.扇形天线D.杆状天线8.以下关于无源器件的应用场合描述错误的是：（ B ）A.将WLAN信号与GSM信号共同在室内分布系统中传输，需要使用合路器。
008习题3(燃烧和火灾基本知识)(消防设施操作员习题库)
一、单项选择题1.下图中( )段是火灾初起阶段。
A. OAB. ABC.BCD. CD2.下图中( )段是火灾成长发展阶段。
A. OAB. ABC. BCD.CD3.下图中( )段是火灾猛烈燃烧阶段。
A. OAB. ABC. BCD. CD4.下图中( )段是火灾衰减熄灭阶段。
A. OAB. ABC. BCD. CD5.关于火灾初起阶段的描述中，( )是不会出现的情况。
A.最初着火的可燃物燃尽而终止B.可燃物燃尽后，具有良好的通风条件，火灾可再次发展C.通风不足，火灾可能自行熄灭D.受通风供氧条件的支配，以缓慢的燃烧速度继续燃烧6. 整个房间都充满了火焰，房间内所有可燃物表面部分都卷人火灾之中，使火灾转化为一种极为猛烈的燃烧，即产生了( )。
A.轰燃B.回燃C.闪燃D.阴燃7.轰燃是-般室内火灾最显著的特征和非常重要的现象，是火灾发展的重要转折点，它标志着室内火灾从( )阶段进入( )阶段，即火灾发展到了不可控制的程度。
A.初起，成长发展 B.成长发展，猛烈燃烧C.猛烈燃烧，衰减熄灭D.初起，猛烈燃烧8.一般来说，室内平均温度降到温度最高值的( )时，则认为火灾进人衰减熄灭阶段。
A.90%B.80%C.70%D.60%9.某一空间内，所有可燃物的表面全部卷人燃烧的瞬变过程，称为( )。
A.轰燃B.回燃C.闪燃D.阴燃10.当室内通风不良、燃烧处于缺氧状态时，由于氧气的引人导致热烟气发生的爆炸性或快速的燃烧现象，称为( )。
A.轰燃B.回燃C.闪燃D.阴燃11.建筑火灾蔓延是通过( ) 进行的，传热是火灾中的一个重要因素，它对火灾的引燃、扩大、传播、衰退和熄灭都有影响。
A.热传导B.热辐射C.热对流D.热传播12.( )是指物体一端受热，通过物体的分子热运动，把热量从温度较高一端传递到温度较低一端的过程。
A.热传导B.热辐射C.热对流D.热传播13.以电磁波形式传递热能的现象，叫做( )。
A.热传播B.热对流C.热传导D.热辐射14.热辐射是指物体以( )形式传递热能的现象。