高三第一学期期中考试试题

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上海师范大学附属中学2024-2025学年高三上学期期中考试英语试题(无答案)

上海师范大学附属中学2024-2025学年高三上学期期中考试英语试题(无答案)

上师大附中2024学年第一学期期中考试高三年级英语学科I. Listening Comprehension 25%Section A 10%Directions:In Section A, you will hear ten short conversations between two speakers. At the end of each conversation, a question will be asked about what was said. The conversations and the questions will be spoken only once. After you hear a conversation and the question about it, read the four possible answers on your paper, and decide which one is the best answer to the question you have heard.1. A. She doesn’t work hard in maths. B. She is inferior to him in maths.C. She didn’t do well in this test.D. She is good at maths.2.A. The library will be closed later this afternoon.B. The computers in the library are not working.C. The man needs his computer all afternoon.D. The woman has lent her computer to somebody else.3. A. Going to the opera is time-consuming.B. There is no time left to book opera tickets.C. She would like to go with the man to the opera.D. She will help the man pay for the opera tickets.4. A. Worth the price. B. Expensive. C. Mysterious. D. Good for health.5. A. 11 a.m. B. 12p.m. C.1p.m. D.3p.m.6. A. The woman will have to call her roommate.B. The woman may have to change her living arrangement.C. The woman does not clean her apartment often enough.D. The woman should not spend so much time on the phone.7. A. She also thinks the lecture interesting.B. She was too tired to enjoy the lecture.C. She missed the lecture this morning.D. She did not finish the reading before the lecture.8. A. Her work experience. B. The courses she has taken.C. Her knowledge of the graduate school.D. The description of her academic performance.9. A. The woman just had her coat cleaned.B. The woman is not angry with the man.C. The woman does not like to drink coffee in the afternoon.D. It was not the woman’s coat that the man spilled coffee on.10. A. She hopes to get into art school. B. She is working as a commercial artist.C. She has talents other than drawing.D. She cannot decide upon a career.Section BDirections:In Section B, you will hear two short passages and one longer conversation, and you will be asked several questions on each of the passages and the conversation. The passages and the conversation will be read twice, but the questions will be spoken only once. When you hear a question, read the four possible answers on your paper and decide which one would be the best answer to the question you have heard.Questions 11 through 13 are based on the following passage.11. A. Kids threw litter everywhere. B. The camp director gave rude orders.C. Mysterious plastic litter was found.D. Kids’ joint effort led to a clean camp.12. A. By taking pictures of the litter he picked up.B. By sharing photos of the terribly dirty planet.C. By keeping a record of crowdsourced cleaning-up.D. By inspiring kids to pick up five pieces of litter every day.13. A. There is strength in numbers. B. Birds can help to pick up litter.C. Litter is artistic and approachable.D. More straws should be used in the cafe.Questions 14 through 16 are based on the following passage.14. A. Alcohol and coffee. B. Coffee and chicken.C. Hotpot and drinks.D. Chicken and meat.15. A. Movies are available to people in Shanghai at midnight.B. People in Hangzhou attach great importance to dinner.C. A total of nine online platforms provided data for the report.D. People in Beijing voted Starbucks as their favorite drink.16. A. People’s eating habits in different regions of China.B. The impact of mobile payment on Chinese lifestyles.C. The differences in nightlife among residents in Chinese cities.D. The financial pressure residents felt from the nightlife activities.Questions 17 through 20 are based on the following conversation.17. A. He hasn’t found a job yet.B. He plans to start looking after the final exams.C. He’s had several interviews.D. He’s expecting an offer from The New York Times.18. A. Writer. B. Interviewer. C. Newspaper reporter. D. Teacher.19. A. New York. B. Boston. C. Chicago. D. Los Angeles.20. A. Continue his education. B. Delay his graduation.C. Change his career plan.D. Continue job hunting.I. Grammar and Vocabulary20%Section A 10%Directions:After reading the passage below, fill in the blanks to make the passage coherent and grammatically correct. For the blanks with a given word, fill in each blank with the proper form of the given word for the other blanks, use one word that best fits each blank.Emotional DebtMany people today live under the weight of debt from loans or credit cards. As harmful as financial debt is, there is 21 that is even more damaging—emotional debt.Dr. James Richards states that emotional debt occurs when we experience emotional pain 22 remains unresolved. If the pain is not dealt with, it will affect our entire lives. Throughout the years, we have chances for happiness, love and success. But unresolved pain can emerge and cause us to respond in ways that aren’t reasonable, 23 (result) in destroyed relationships and lost opportunities.When we have a tendency 24 (respond) inappropriately, we often hurt those around us. Unfortunately, our unsettled problems sometimes become too much for them to handle and cause them to abandon the relationship.People with destructive patterns 25 check their lives for signs of unresolved pain, for your emotional debt can come from various forms of past unfair, cruel or violent treatment or neglect. The fact is 26 you are probably holding onto painful memories of controlling parents or very demanding teachers. Any negative emotion that you have controlled over the year can come back to cause harm 27 you least expect it.Recognize your feelings, but don’t focus on them all the time, because acknowledging and challenging your pain is difficult, but recognizing it is the first step 28 dealing with it. Admit you are angry about the past, and discuss it with someone you trust, or write it down because this will ease some of the danger and hatred you 29 (keep) bottled up for years. Refuse to be a victim and accept responsibility for dealing with your painful past because this puts you in charge and limits the power your emotions have over you.Take specific steps to resolve your emotional debt now 30 30 deal with the consequences later. Section B 10%Directions:Complete the following passage by using the words in the box. Each word can only be used once. Note that there is one word more than you need.(A)A. claimedB. cuisineC. securingD. addingE. fuelingF. madeG. opponent H. seed I. historic J. tough K. venueZheng Secures Historic Tennis Gold for ChinaChina’s women’s ace Zheng Qinwen has carved her name in tennis history after winning the country’s first singles Olympic gold medal in Paris on Saturday, 31 her meteoric career rise with another major accolade(荣誉).China’s world No. 7 Zheng was the sixth 32 in the 64-draw Olympic tournament. She lived up to her favorite status in the final against Donna Vekic of Croatia at the Roland Garros Stadium, beating her 21st-ranked 33 four times while conceding only one of her service games to prevail 6-2,6-3 at the iconic site of the red clay Grand Slam to win the gold medal.It was only China’s second Olympic gold medal in tennis, following a women’s doubles title won by Li Ting and Sun Tiantian at Athens 2004, and the first in singles.After 34 the win with a forehand winner down the line, Zheng lay down on her back to rousing cheers across the Court Philippe-Chatrier, soaking up the 35 moment for her own career and for the sport’s profile in China.It was the second Olympic tennis medal won by the Chinese delegation in Paris, after mixed doubles pair Zhang Zhizhen and Wang Xinyu 36 a silver medal in Friday’s final, which was won by Czech team Katerina Siniakova and Tomas Machac at the same 37 .“Nothing can describe my feeling right now, it’s unreal. I’ve always been hoping to get a medal for China. Finally I 38 it.” an emotional Zheng said during the on-court interview.“I did everything I could. I think my country will be proud of me, I feel proud of myself. The success is for all my team members, my families and whoever supported me, not just for me.I just fought every single match. There were two matches that I almost lost on my way to the final, especially 0-4 down in the second set against Iga (Swiatek) in the semis. I feel the energy of all the support, knowing that I play for my country. I just never gave up and tried to find every single solution,” Zheng said of her 39 path to success.And for the celebration? The 21-year-old native of Hubei province just wants to join her family and enjoy some home. 40“I haven’t thought about it yet. For sure to eat some Chinese food, after having eaten chicken and rice every day here, nothing much of flavor,” she said with a grin.III. Reading Comprehension (45%)Section A 15%Directions: For each blank in the following passage there are four words or phrases marked A, B, C and D. Fill in each blank with the word or phrase that best fits the context.As newborns, we enter the world by inhaling. In leaving, we exhale. (In fact, in many languages the word “exhale” is synonymous with “ 41 .”) Breathing is so central to life that it is no wonder humankind long ago noted its value not only to survival but to the 42 of the body and mind and began controlling it to improve well-being.As early as the first millennium B.C., both the Tao religion of China and Hinduism placed importance on a “vital principle” that flows through the body, a kind of energy or internal breath. The Chinese call this energy qi, and Hindus call it prana (one of the key concepts of yoga). A little later, in the West, the Greek term pheuma and the Hebrew term ruah both 43 the breath and the divine presence.44 for how to modulate(调节) breathing and influence health and mind appeared centuries ago as well. Pranayama(“breath retention”) yoga was the first to build a theory around respiratory(呼吸的) control, holding that 45 breathing was a way to increase longevity.In more modern times, German psychiatrist Johannes Heinrich Schultz developed “autogenic training” in the 1920s as a method of 46 . The approach is partly 47 slow and deep breathing and is probably still the best-known breathing technique for relaxation in the West today.Yoga and meditation have inspired many of the breathing exercises used today. The 48 of controlled respiration were first theoretically suggested centuries ago by the practitioners of pranayama yoga.What is the best time to 49 slow-breathing techniques? One is during occasional episodes of 50 —for example, before taking an exam, competing in a sporting event or even attending a routine meeting at work. These exercises may also help when insomnia strikes. In 2012 Suzanne M. Bertisch of Harvard Medical School and her colleagues reported, based on survey data, that more than 20 percent of American insomniacs do these breathingexercises to have a 51 sleep.But respiratory techniques do not work only for acute stresses or sleep problems; they can also relieve chronic anxiety. They are particularly 52 in people with psychiatric disorders such as phobias(恐惧症), depression and post-traumatic stress disorder(创伤后压力). In 2015 Stefania Doria and her colleagues at Fatebenefratellie Oftalmico Hospital in Milan, Italy, offered 10 training sessions to 69 patients with anxiety or depressive disorders. The rescarchers observed a significant 53 in symptoms at the end of the sessions.But why confine breathing techniques to 54 emotions? It is also worth applying them during pleasurable moments, to take the time to appreciate and remember them. In short, one can pause and breathe for 55 as well as to calm down.41. A. changing B. recovering C. dying D. destroying42. A. strengthening B. maintaining C. building D. functioning43. A. dealt with B. referred to C. led to D. consisted of44. A. Policies B. Recommendations C. Clues D. Habits45. A. labored B. slowed C. deepened D. controlled46. A. relaxation B. development C. illustration D. communication47. A. based on B. intended for C. adapted to D. compared with48. A. difficulties B. performances C. benefits D. harms49. A. improve B. master C. apply D. pioneer50. A. thrill B. stress C. excitement D. calm51. A. restless B. dreamy C. light D. profound52. A. sensitive B. powerful C. effective D. safe53. A. decrease B. discovery C. difference D. development54. A. diverse B. delicate C. personal D. negative55. A. anxiety B. enjoyment C. fear D. reliefSection B 22%Directions: Read the following three passages. Each passage is followed by several questions or unfinished statements. For each of them there are four choices marked A, B, C and D. Choose the one that fits best according to the information given in the passage you have just read.(A)It’s normal for young children to cheat when they’re playing board games. As they grow older, they realize that the fun is actually in taking part in the game, not necessarily in winning it. By the time they reach their teens, they have usually learned not to cheat. Sadly, this was not the case for a player in a national board game championship held annually in the US. The player wanted to win so much that he turned to cheating.The board game was Scrabble. In the game, players have to make words from individual letters on small squares called “tiles,” and then put the words on a board. Two of the most useful tiles in the game are the blanks, which are tiles without any letters on them. A blank isn’t worth any points, but a player can use it to replace any letter of the alphabet.The cheater in this particular competition was a 15-year-old boy from Orlando, Florida. He had surprisedorganizers in the early stages of the competition by beating some of the best players, despite the fact that he had never played in competitions before. This made some of the other players suspicious, including the man who caught him, 43-year-old Arthur Moore. Moore had already played the boy the day before, and Moore had won the game, although the boy had had both of the blank tiles. In Scrabble, before a new game starts, the players put the tiles from the previous game back into a small bag. This time, Moore had a good look at the tiles on the table before he and his opponent put them in the bag to start the game. He was not surprised to see that the two blanks were together on the table in front of the boy. As the two players were putting the tiles into the bag. Moore watched the boy’s left hand. He saw the boy pick up the two blanks, and put his hand under the table. This was the signal for Moore to call one of the organizers and accuse the boy of cheating.When the boy was taken away for questioning, he admitted to taking the two blanks during the game and hiding them under the table. As a result of his cheating, the competition director disqualified him and banned him from playing in the competition again.56. According to the passage, why do young children cheat in board games?A. They are eager to win.B. They dislike the games.C. They don’t know what cheating is.D. They don’t want to take part in the games.57. Why are the two blank tiles most useful in Scrabble?A. They are the most obvious tiles in the game.B. Players can decide how many points they are worth.C. Players earn more points if they leave the tiles unused.D. They can be used when players don’t have the right letter.58. The word “suspicious” (in paragraph 3) most probably means “ ”.A. supportiveB. disappointedC. mistrustfulD. honoured59. How did the boy cheat?A. By putting the tiles into his own bag.B. By hiding the blank tiles for future use.C. By cooperating with his opponent secretly.D. By lying that he had never played the game.BEssential oils can have a major impact on your mood and health. “When you apply an oil to your skin, it affects your physical state. When you inhale them, it affects your mental state,” says the “grande dame” of aromatherapy Jeanne Rose, author of The Aromatherapy Book: Applications and Inhalations.A few drops of eucalyptus on your skin will help heal a burn and smelling a pine tree might make you think of childhood Christmases. You can put a few drops on a tissue, or add some to water to spritz around the room or use in a diffuser (喷雾器) or vaporizer.Be very careful, however, when applying oils to the skin. Always dilute them in another oil, like palm coconut or olive to prevent burns or allergic reactions.“A rule of thumb is 15 drops per one ounce of cream, oil or lotion,” says Sylla Sheppard-Hanger, the founder and director of Atlantic institute of Aromatherapy in Tampa, Florida.Here’s the oil to reach for when you need to:Digest a big meal: A few drops of diluted peppermint. “It calms down the digestive system,” Rose says.Forget it’s freezing outside: “Conifer oils, like pine, black spruce, cedar and Christmas fir, can help combat seasonal affective disorder when inhaled,” Rose says. Citrus oils like orange or tangerine, which are reminders of summertime, are also good.Settle down after a big party: Sweet marjoram and lavender are sedatives. “They’ll knock your kids right out,” Sheppard-Hanger says.Get out of bed on a dark, cold morning: Peppermint, or any mint really, can provide a morning jolt when inhaled.Kill germs: Spray citrus oils or tree oils like pine, to help clean the air during sickness. Decongest a nose: Eucalyptus, spruce or rosemary work for this. Try inhaling a few drops on a tissue to help with clogged nasal passages due to a cold.60. What kind of readers is likely to buy The Aromatherapy Book: Applications and Inhalations?A. Gardeners providing related raw materials for manufacturers of essential oils.B. Researchers dedicated to inventing new essential oils to keep people in good health.C. Common people hoping to improve health condition with essential oils.D. Psychotherapist seeking treatments for serious mental and physical disorders.61. What is the appropriate way of using essential oils?A. Spritz the oil directly around a room.B. Mix them with cream in proportion.C. Smell the fragrance from the bottle.D. Apply oils to treat skin allergy.62. The oils that can relieve your symptom of a bad cold are .A. peppermint oilsB. conifer oilsC. citrus oilsD. spruce oilsCMany early approaches to language technology—and particularly translation—got stuck in a conceptual dead end: the rules-based approach. In translation, this meant trying to write rules to analyse the text of a sentence in the language of origin, breaking it down into a sort of abstract “interlanguage” and rebuilding it according to the rules of the target language. These approaches showed early promise. But language is full of ambiguities and exceptions, so such systems were hugely complicated and easily broke down when tested on sentences beyond the simple set they had been designed for.Nearly all language technologies began to get a lot better with the application of statistical methods, often called a “brute force” approach. This relies on software scanning vast amounts of data, looking for patterns and learning from precedent. For example, in parsing language (breaking it down into its grammatical components), the software learns from large bodies of text that have already been parsed by humans. It uses what it has learned to make its best guess about a previously unseen text. In machine translation, the software scans millions of words already translated by humans, again looking for patterns. In speech recognition, the software learns from a body of recordings and the transcriptions made by humans.Thanks to the growing power of processors, falling prices for data storage and, most crucially, the explosion in available data, this approach eventually bore fruit. Mathematical techniques that had been known for decades cameinto their own, and big companies with access to enormous amounts of data were ready to benefit.The final advance, which began only about five years ago, came with the arrival of deep learning through digital neural networks (DNNs). These are often claimed to have qualities similar to those of the human brain: “neurons” are connected in software, and connections can become stronger or weaker in the process of learning. But Nils Lenke, head of research for a language technology company, explains matter-of-factly that “DNNs are just another kind of mathematical model,” the basis of which had been well understood for decades. What changed was the hardware being used.Almost by chance, DNN researchers discovered that the graphical processing units (GPUs) used to produce graphics in applications like video games were also brilliant at handling neural networks. The technique has already produced big leaps in quality for all kinds of deep learning, including decoding handwriting, recognising faces and classifying images. Now they are helping to improve all manner of language technologies, often bringing enhancements of up to 30%. That has shifted language technology from usable at a pinch to really rather good. But so far no one has quite worked out what will move it on from merely good to reliably great.63. According to the passage, which of the following is a problem of the rules-based approach?A. Rules are difficult to identify in some languages.B. It is impossible to find all the rules in a language.C. The rules are often misinterpreted by researchers.D. There are always rules too abstract to understand64. has a part to play in enabling the “brute force” approach to gradually bear fruit.A. The increasing amount of dataB. The falling prices of scanning softwareC. The availability of recordings and transcriptsD. The wider knowledge people have of language65. Which of the following is Nils Lenke most likely to agree with about DNNs?A. They are a big breakthrough.B. They depend more on hardware.C. They are not innovative by nature.D. They haven’t been scientifically proved.66. What does the writer imply about GPUs?A. They are inferior to DNNs in their quality of deep learning.B. They have made language technology reliably greater than ever.C. They have achieved limited success regarding language technology.D. They help enhance language technologies by means of image classification.Section C 8%Directions:Read the following passage. Fill in each blank with a proper sentence given in the box. Each sentence can be used only once. Note that there are two more sentences than you need.A. This is a trend that is only expected to continue.B. But if we wish to keep any real measure of biodiversity on the planet, we may have to lean on zoos far more than many people realize.C. Those species that are held in zoos are already protected from any such events and trends.D. Many others are already extinct in the wild and only survive thanks to populations kept in captivity.E. Climate change has harmed over half mammal species on the endangered species list.F. However, despite their high numbers in collections around the world, they are the most threatened mammalian group on the planet.The World Needs ZoosZoos play an important role in the world for conservation and education. They are particularly important for endangered species. Many animals are critically endangered and may go extinct in the wild, but in zoos, they are going strong. 67 Even those critical of zoos often recognize that it is better to have species preserved somewhere than lose them altogether. In fact, species that are common can also come under serious threat before people realize it.Take the ring-tailed lemur of Madagascar for example. These lemurs are almost common in zoos as they breed well in captivity and the public are fond of them. 68 A recent survey suggests that up to 95 percent of the wild populations have been lost since 2000. This means that the remaining individuals are at serious risk. One bad year or a new disease could wipe out those which still remain in the wild.Such trends are not isolated. The giraffe is another very common species in zoos. Unlike the lemurs, giraffes are widespread in the countries across much of sub-Saharan Africa. Yet giraffe populations have gone down by a third in the last thirty years. While less dramatic than the drop in lemur numbers, this is obviously a major loss and again, whole populations (which some scientists think are of unique subspecies) are on the verge of extinction.69 Ongoing and future issues from climate change can have unexpected effects on wildlife. It will become more difficult for conservationists to predict which species might be at risk. As it is, experts are struggling to continue monitoring the species that are already known to be vulnerable, so it is easy to see why common species might be overlooked. People might not take the great loss of local species seriously on the assumption that these animals are heavily populated elsewhere, but unfortunately that is not always the case.There will, I suspect, always be resistance to the argument for keeping animals in captivity and I will not defend the zoos that are badly managed and in desperate need of improvement or closure. 70 If even common species can lose their population in only several years, it may be too late to save them in the wild.第Ⅱ卷(共25分)IV. Summary Writing 10%Directions: Read the following passage. Summarize the main idea and the main point(s) of the passage in no more than 60 words. Use your own words as far as possible.71. Are we greening our cities, or just greenwashing them?Architecture and urban design is chasing a green fever dream. Everywhere you look, there are plans for “sustainable” buildings, futuristic eco-cities and aquaponic (复合养殖)farms on the roof, each promising to add a green touch to the modern city.All of these are surely good ideas at some level. They are trying to repair some of the damage our lifestyle has done to the planet. But, despite the rhetoric of reuniting the city with nature, today’s green urban dream is too often about bringing a technologically controlled version of nature into the city and declaring the problem solved, rather than looking at the deeper causes of our environmental and urban problems.One of the most striking examples is Apple’s “spaceship” campus now under construction in Silicon Valley. Though it seems to be sustainable and energy efficient—80 percent of its 175-acre site is preserved for landscaping, it is by any measure a huge, expensive and massively resource-intensive project. As a suburban white-collar workplace, it must include vast garages for 13,000 Apple employees. Thus, it will leave no smaller environmental footprint than a traditional office park.Designing a perfect green building or eco-city isn’t enough to save the world. Although our buildings, like our cars, have been inefficient environmentally, architecture isn’t directly responsible for humanity’s disastrous environmental impacts. An economic system based on the destruction of nature is the real problem. No green building can help us repair the ecological damage we have caused, nor can any number of aquaponic farms bring us back to the real nature.Instead of adding “nature” to the urban lifestyle, architects may work to design better relationships between our cities and nature and to promote just relationships between the people in them.V. Translation 15% (3+3+4+5)Directions: Translate the following sentences into English, using the words given in the brackets.72.高额的旅行支出是对公司资源的巨大耗费。

海淀区2024-2025学年第一学期期中高三语文试题及答案

海淀区2024-2025学年第一学期期中高三语文试题及答案

海淀区2024—2025学年第一学期期中练习高三语文2024.11 本试卷共8页,150分。

考试时长150分钟。

考生务必将答案答在答题纸上,在试卷上作答无效。

考试结束后,将本试卷和答题纸一并交回。

一、本大题共5小题,共18分。

阅读下面材料,完成1-5题。

材料一唐代《括地志》云:“太行数千里,始于怀而终于幽,为天下之脊。

”《尚书·禹贡》中已出现“太行”之名:“太行、恒山,至于碣石,入于海。

”在古人的理解中,太行山直通碣石山及海域,不仅绵长,而且广大。

比大更甚谓之“太”,古代地理学者有“天下之山,莫大于太行”的共识。

太行山从北向南呈“S”形,东西宽40-50公里,由群山组成一个极大的“矩阵”。

其中名山荟萃,诸峰林立,王屋、云台、狼牙、五台等山峰自南而北牵手耸立,仿佛华夏大地上的另一道长城。

剧烈的造山运动和千百万年的冰蚀水侵,使太行山随处可见落差巨大的断崖峭壁和深不可测的深山峡谷,形成了多样的自然地貌。

山顶平台、山崖平台、山崖陡坎组成了阶梯状地形,高峻壁立、连绵不绝的长崖三面围合形成了围谷或瓮形山谷,还有百转深幽的曲峡、一线天式的地缝,棱角鲜明、嶙峋峥嵘的塔峰丛、岩墙、孤峰、石柱等。

这些具有典型意义的地貌被称为“太行地貌”。

太行山东麓群峰拔地,列嶂摩天。

尤其是南太行,与平原之间几乎没有过渡,犹如被直接劈开了一样。

而西麓则黄土深厚,相对徐缓。

这样差别巨大的地貌是怎么形成的呢?北宋沈括登太行山时,在山崖间发现了一些海螺贝壳,指出“此乃昔日之海滨,今东距海已近千里”。

现代地质学研究证实了他的论断,240万年前,太行山开始大幅隆起,东侧盆地则不断沉陷,东麓的大断裂便造成了地形上的一升一降。

新生的太行山如一道巨型城墙,阻挡了西北季风带来的滚滚沙尘,在太行山西侧沉积成地球上面积最大的黄土高原。

众多的河流又硬生生在墙体上冲出一条条孔道,将滚滚泥沙一股脑儿倾泻入古华北海,长出了30多万平方公里的华北平原。

太行山东西两侧的华北平原和黄土高原是中华民族的摇篮,巍巍八百里太行用它的铮铮铁骨支撑起了摇篮中的中华文明。

山东省聊城市2024-2025学年高三上学期英语期中考试英语试题(含解析)

山东省聊城市2024-2025学年高三上学期英语期中考试英语试题(含解析)

2024~2025学年度第一学期期中教学质量检测高三英语试题注意事项:1.答卷前,考生务必将自己的姓名、考生号等填写在答题卡和试卷指定位置上。

2回答选择题时,选出每小题答案后,用铅笔把答题卡上对应题目的答案标号涂黑。

如需改动,用橡皮擦干净后,再选涂其他答案标号。

回答非选择题时,将答案写在答题卡上,写在本试卷上无效。

3.考试结束后,将本试卷和答题卡一并交回。

第一部分听力(共两节,满分30分)第一节(共5小题;每小1.5分,满分75分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C 三个选项中选出最佳选项。

并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题,每段对话仅读一遍。

例:How much is the shirtA. 19.15.B. 9.18.C. 9.15.答案是C.1. What books does the woman usually read in the libraryA. Storybooks.B. Course books.C. Science books.2. What is Mike’s father nowA. An expressman.B. A teacher.C. A photographer.3. When does the woman expect to arrive at the destinationA. At about 4:00.B. At about 6:00.C. At about 6:30.4. What will the man probably do this weekendA. Practice tennisB. Play volleyball.C. Watch a baseball game.5. What are the speakers mainly talking aboutA. A training program.B. A singing contest.C. A karaoke bar.第二节(共15小题:每小题1.5分,满分22.5分)听下面5段对话或独白。

山东省菏泽市2024-2025学年高三上学期期中考试历史试题(含答案)

山东省菏泽市2024-2025学年高三上学期期中考试历史试题(含答案)

菏泽市2024—2025学年度第一学期期中考试高三历史试题本试题卷共8页,19题。

全卷满分100分,考试用时90分钟。

注意事项:1.答题前,先将自己的姓名、准考证号填写在答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。

2.选择题的作答:选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答:用签字笔直接写在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后,请将本试题卷和答题卡一并上交。

一、选择题:本题共15小题,每小题3分,共45分。

在每个小题给出的四个选项中,只有一项是符合题目要求的。

1.考古发现,红山文化中心墓葬随葬玉器数量多、质量纯、选料精、体积大、工艺讲究;第三等级墓有随葬玉器和中、小型石棺;第四等级墓有讲究的石棺;附属墓只有简单的墓坑。

这可以用于说明()A.玉器是随葬必需品B.早期国家的形成C.墓葬地域特征明显D.社会贫富的分化2.周成王即位后,周公旦营造洛邑,将九鼎迁至洛邑,并请成王亲自主持祭礼,将九鼎安放在明堂之中。

周公这一举措旨在()A.实现权力的高度集中B.宣扬政权的合法性C.缓解宗周镐京的压力D.推动洛邑的城市化3.《商君书》将秦君塑造成明一法度、任力不任德的“圣王”;《吕氏春秋》继而将秦君塑造成既能养生治国、又能偃荡兵聚的“圣王”。

这一变化主要是由于()A.礼乐制度的崩溃B.黄老之学的盛行C.政治形势的需要D.君主专制的形成4.汉初《津关令》中记载了许多关于严格盘查金器、铜、铁等金属出关中的规定。

这反映了当时政府意图()A.实施盐铁官营B.取消地方铸币权C.坚持重农抑商D.保障王朝的安全5.《唐律疏议·名例》“妇人有官品邑号”条规定:“诸妇人有官品及邑号,犯罪者,各依其品,从议、请、减、赎、当、免之律,不得荫亲属。

”此条“疏议”专为此规定做了说明:“依礼,‘凡夫人,从其夫之爵位’。

河南省2024-2025学年高三上学期11月期中英语试题(含解析)

河南省2024-2025学年高三上学期11月期中英语试题(含解析)

2024-2025学年度(上)高三期中考试英语试题考试时间:120分钟;满分:120分注意事项:1.答题前填写好自己的姓名、班级、考号等信息2.请将正确答案填写在答题卡上第I卷(选择题)第一部分阅读(共两节,满分50分)第一节(共15小题;每小题2.5分,满分37.5分)阅读下列短文,从每题所给的A、 B、C D四个选项中选出最佳选项。

ADriver WantedClean driving license (执照).Must be of smart appearance.Age over 25.Apply to (申请): Capes Taxi, 17 Palace Road, Royston.Air Hostesses for International Flights WantedApplicants (申请者) must be between 20 and 33 years old.Height: 1. 6 m to 1. 75m.Education to GCSE standard.Two languages. Must be able to swim.Apply to: Recruitment (招聘) office, Southern Airlines, Heathrow Airport West. HR 37 KK.Teachers NeededFor private language school.Having college education.Teaching experience unnecessary.Apply to: The Director of Studies, Instant Languages Ltd. 279 Canal Street, Royston. 1.What prevents Jack, an experienced taxi driver, working for Capes Taxi?A.Unable to speak a foreign language.B.Punished for speeding and wrong parking.C.Fond of beer and wine.D.Not having college education.2.What prevents Mary, aged 25, becoming an air hostess?A.She has never worked as an air hostess before.B.She doesn't feel like working long hours flying abroad.C.She can't speak Japanese very well.D.She once broke a traffic law and was fined3.Which of the following is not mentioned in the three advertisements?A.Education.B.Working experience.C.Male or female.D.Marriage.B“Colour” and “color”, “favourite” and “favorite”, “honour” and “honor”… Have you ever wondered why Americans spell those words without a “u”? Is it because they are lazy? Of course not. In fact, the difference in spelling was started by Noah Webster(1758 — 1843). He was a teacher who reformed (改革) English to make American identity (特征) stronger. Linguists (语言学家) celebrate his birthday on October 16 every year.After the Revolutionary War (1775 — 1783), Webster believed that Americans should have their own dictionary, rather than rely on British dictionaries. He dropped the British “u” in some words. And he changed “centre” into “center” for children to learn English by spelling words more like what they sounded. He used “subway” instead of British word “underground”. Some other examples are “soccer” and “football”, “fall” and “autumn”.Webster wasn’t shy about expressing his opinions. In defining (定义) preposterous(unreasonable), he wrote: “A republican government in the hands of female is preposterous.” Webster spent 28 years on the project before completing the 70,000-word dictionary with his American-style spelling in 1828. He also added local words.His dictionary was widely used in schools. Linguists believed it helped a new country achieve unity (统一) and cultural independence at a time when most people cared about political freedom.“He was the creator of our language and the creator of American identity,” said Joshua Kendall, who is working on a book about Webster. “He at last brought us together through our language.”4.Which is NOT true about Webster’s dictionary?A.It has local words in it.B.It is a 70,000-word dictionary.C.All the words are spelled without “u”.D.Its words are in American-style spelling.5.What does the underlined phrase “rely on” in Paragraph 2 mean?A.Depend on.B.Trust in.C.Put up with.D.Give up. 6.What do people think of Webster’s dictionary?A.It is the only dictionary that Americans still use today.B.It helped to bring Americans together besides its cultural influence.C.It has no influence on the development of American English.D.It helped to make American English more useful than British English.7.What’s the main idea of the passage?A.The development of the British English.B.American English is better than British English.C.Noah Webster added local words to the dictionary.D.Noah Webster wrote an American English dictionary and reformed English.COne August afternoon, Richard Allen dropped off his last passenger, Mrs. Carey. Lifting two grocery bags, he followed her across the yard and stood on the step of her house. Glancing up, he saw a large wasp (黄蜂) nest under the roof. Allen had heard that wasps can become more likely to sting (蜇) in summer. He mentioned this to Mrs. Carey, who had opened the door.“Oh, they don’t bother me,” she said lightly. “I go in and out all the time.”Anxiously, Allen looked at the nest again—— to see the wasps flying straight at him. “Hurry!” he shouted to Mrs. Carey. “Get in!”She stepped quickly inside. Allen ran for his mini-bus. Too late; they were upon him. Just as he jumped aboard, half a dozen red spots showed on his arm, and he felt more on his back and shoulders.As he was driving down the road, Allen felt as if something was burning at the back of his neck, and the “fire” was spreading forward toward his face. And immediate anxiety took hold of him.Allen knew that stings could cause some persons to die. But he had been stung the previous summer and the after-effects soon passed. However, what he didn’t know what that the first sting had turned his body into a time bomb waiting for the next to set off an explosion.Miles from the nearest medical assistance, Allen began to feel his tongue thick and heavy and his heartbeat louder. Most frightening, he felt his breathing more and more difficult. He reached for the radio mike (话筒), trying to call the mini-bus center, but his words were hardly understandable. Signals were also poor that far out. He knew a rescue team was on 24-hour duty at the Amherst Fire Department’s north station. So his best chance was to make a run for it.Rushing down the mountain, Allen tried not to panic, focusing his mind on each sharp turn. He was almost through the last of them when he felt sure he was going into shock (休克). Just then he reached for the radio mike again.“Call fire station,” he shouted, concentrating to form the words. “Emergency. Bee sting. Emergency. There in ten minutes.”“Five-ten,” the center replied.Hold on, Allen thought. Keep your eyes open. Breathe. Keep awake.At last he reached the station. Two firemen ran out. Allen felt their hands grasp him before he hit the ground. You made it, he thought.8.It is mentioned in the passage that wasps are more likely to attack when _______.A.there are huge noisesB.strangers are approachingC.the air is filled with food smellD.the hottest season comes around9.Allen didn’t know that if stung by wasps again, he would _______.A.have no after-effectsB.suffer from sharper painC.surely lose his lifeD.become more sensitive10.Allen failed at his first attempt to send his message to the mini-bus center because _______.A.he was unable to speak clearlyB.his radio equipment was poorC.he was in a state of shockD.no one was on duty11.Which would be the best title for the passage?A.Allen, A Helpless DriverB.Wasps, Bloody KillersC.A Race Against DeathD.War Against WaspsDArmy ants are mainly distributed in South America and Africa and mostly live in the Amazon River basin. They like to live in groups and generally one or two million in a group. They are migratory, have no fixed on the move. When encountering obstacles such as gaps, army ants are able to connect their bodies to each other and build a bridge for large groups of ants to pass through, saving crawling distance. The bridge can be built and removed very quickly, in seconds.Christopher Reid of the University of Sydney’s Insect Behaviour and Ecology Laboratory, said that when studying the ant bridge, he initially assumed that once the ant bridge was built the two end positions of the bridge would be fixed, and the bridge itself would be relatively stationary (不动的).However, after observation, it was found that the ant bridge would constantly change according to the army ants’ knowledge of the outside world. The ant bridge can move slowly from the original position, increasing the number of ants in the bridge, extending the length of the bridge, so that other ants may save a lot of efforts by using the ant bridge instead of taking other routes. In this way, it can continuously compress the distance to the target area.Meanwhile, the researchers have also found that the changing ant bridge does not always achieve the shortest distance. When the bridge is extended to a certain extent, the number of ants involved in the construction of the ant bridge will not continue to increase, and the length of the bridge will stop growing.Researchers believe that army ants use the best methods in the construction of bridges. Since the ants involved in building the bridge are unable to participate in other work, the colony stops putting in more ants as soon as it finds that the number of ants put into extending the bridge is out of balance with the number of ants needed for other jobs.12.What is mainly introduced about army ants in paragraph 1?A.Their migration.B.Their distribution.C.Their living habits.D.Their hunting targets.13.What did the research find about the bridge built by army ants ?A.It becomes longer constantly.B.It keeps unchanged once built.C.It achieves the shortest distance.D.It is adjusted according to the needs.14.What does the underlined word “compress” mean in paragraph 3?A.Reduce.B.Calculate.C.Neglect.D.Judge.15.What is the writing purpose of the text ?A.To stress the importance of cooperation.B.To explain army ants’ incredible strength.C.To show army ants’ collective intelligence.D.To indicate the harmony between nature and human.第二节(共5小题;每小题2.5分,满分12.5分)根据下面短文,从短文后的选项中选出能填入空白处的最佳选项。

山东省菏泽市2024-2025学年高三上学期期中考试 化学含答案

山东省菏泽市2024-2025学年高三上学期期中考试 化学含答案

菏泽市2024-2025学年度第一学期期中考试高三化学试题(答案在最后)本试卷共8页,20题。

全卷满分100分。

考试用时90分钟。

注意事项:1.答题前,先将自己的姓名、准考证号填写在答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。

2.选择题的作答:每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答:用签字笔直接写在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后,请将本试题卷和答题卡一并上交。

可能用到的相对原子质量:H 1C 12一、选择题:本题共10小题,每小题2分,共20分。

在每小题给出的四个选项中,只有一项是符合题目要求的。

1.北宋画家王希孟绘制的《千里江山图》被誉为中国古代青绿山水画的巅峰之作,绘制中使用了一种主要成分为()()3322Cu OH CO 的颜料。

下列有关()()3322Cu OH CO 的说法正确的是()A.受热分解可得到CuOB.可溶于水C.是混合物D.不能与酸反应2.在2024年的国庆节期间,万架无人机点亮深圳的夜空,上演了一场科技与艺术交织的表演。

在无人机的制备过程中要用到多种材料,下列说法错误的是()A.机身通常使用碳纤维、玻璃纤维,它们属于无机非金属材料B.一般选用锂聚合物电池提供电能,该电池的能量密度很高C.通信系统需要使用光纤,光纤的主要成分是硅D.用于制作螺旋桨的塑料应具有强度高、寿命长等特点3.下列物质溶于水中形成的溶液能导电,但本身是非电解质的是()A.2Cl B.3HNO C.葡萄糖D.2SO 4.类比推理是研究、学习的一种重要的思维方法。

下列由实际事实推断出的类推结果正确的是()选项实际事实类推结果A 2Cl 、2Br 能与Fe 化合生成3FeCl 、3FeBr 2I 也能和Fe 化合生成3FeI B 氢氧化钠能将3NaHCO 转化为23Na CO 氢氧化钠能将3NaHSO 转化为23Na SO C2SO 通入2BaCl 溶液无明显现象2SO 通入()32Ba NO 溶液也无明显现象DNaOH 与盐酸中和反应的反应热H ∆=157.3kJ mol --⋅NaOH 与醋酸中和反应的反应热H ∆=157.3kJ mol --⋅5.利用下列实验装置能达到相应实验目的的是()实验装置实验目的A.定量测定化学反应速率B.转移溶液C.稀释浓硫酸D.制备()3Fe OH胶体6.高铜酸钠2NaCuO是一种黑色难溶于水的固体,酸性或高温条件下不稳定。

江苏省徐州市2024-2025学年高三上学期11月期中考试语文试题(有答案)

江苏省徐州市2024-2025学年高三上学期11月期中考试语文试题(有答案)

江苏省徐州市2024~2025 学年度第一学期高三年级期中抽测语文试题本试卷满分 150 分考试用时 150 分钟。

注意事项:1.答卷前,考生务必将自己的姓名、考生号、考场号和座位号填写在答题卡上。

用2B 铅笔将试卷类型填涂在答题卡相应位置上。

将条形码横贴在答题卡右上角“条形码粘贴处”。

2.作答选择题时,选出每小题答案后,用 2B 铅笔在答题卡上对应题目下面的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案。

答案不能答在试卷上。

3.非选择题必须用黑色字迹的签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新答案;不准使用铅笔和涂改液。

不按以上要求作答无效。

4.考生必须保持答题卡的整洁。

考试结束后,将试卷和答题卡一并交回。

一、现代文阅读(35 分)(一)现代文阅读I(本题共5小题,19分)阅读下面的文字,完成 1~5 题。

材料一:20世纪初以来,随着数学和计算机技术的发展,跨学科研究日益深入,人们发现,自然界及人类社会面临的许多现实问题不是孤立存在的,它们之间具有复杂的关联性和整体性,人类需要处理越来越“复杂、变化、多样”的问题。

系统科学的创始人贝塔朗菲在当时就指出,“我们被迫在一切知识领域中运用'整体’或'系统’概念来处理复杂性问题”随着整体论在现代生物学以及心理学等学科的成功复兴和发展,这种特别关注“整体性”的系统思维方式受到许多学科的认可,并被应用。

尽管不同学者或学派对系统的定义各有侧重,但都强调系统组成要素之间的“关系”是系统之所以成为系统,或者说具有系统性的关键。

贝塔朗菲将系统定义为“相互作用着的若干要素的复合体”。

这种相互作用指的是:“若干要素(p),处于若干关系(R) 中,以致一个要素p在R中的行为不同于它在另一关系R中的行为。

如果要素的行为在R和R中并无差异,那么就不存在相互作用,要素的行为就不依赖于R和R。

”也有学者认为“一个系统是客体与客体之间相互关系的集合”。

山东省菏泽市2024-2025学年高三上学期期中考试地理试题 含答案

山东省菏泽市2024-2025学年高三上学期期中考试地理试题 含答案

菏泽市2024-2025学年度第一学期期中考试高三地理试题本试题卷共8页,19题。

全卷满分100分,考试用时90分钟。

注意事项:1.答题前,先将自己的姓名、准考证号等填写在答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。

2.选择题的作答:选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答:用签字笔直接写在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后,请将本试题卷和答题卡一并上交。

一、选择题:本题共15小题,每小题3分,共45分。

在每个小题给出的四个选项中,只有一项是符合题目要求的。

古文献记载:“哀牢山,滇之祖脉。

登巅约六十里,上极寒,下极热。

”此山成为2024年国庆爆火的旅游打卡点,以多种不明生物、布满瘴气、指南针失灵等神秘现象吸引众多探险爱好者探秘。

下图为哀牢山地理位置图。

据此完成1~2题。

1.形成哀牢山幽深秘境环境特点的地质作用是①板块挤压,地壳抬升②板块张裂,地壳下陷③风力侵蚀④流水侵蚀A.①③B.②④C.②③D.①④2.网传布满瘴气的现象与当地多雨雾天气有一定关系,产生这种现象的原因是①地形崎岖陡峭,气温低②纬度低,气候湿热③植被丰富,空气湿度大④山地封闭,水汽不易扩散A.①②③B.①②④C.①③④D.②③④河流作为水和物质通往海洋的重要“运输管道”和“生物反应器”,在全球碳循环中发挥着重要作用。

河流碳库分为溶解性有机碳(DOC)、颗粒态有机碳(POC)、溶解性无机碳(DIC)以及颗粒态无机碳(PIC)。

下图为河流碳循环过程示意图。

据此完成3~4题。

3.下列现象能影响河流外源碳输入的是①流域内湿地占比②河流内植物的光合作用③流域内碳酸盐岩和硅酸盐岩的风化作用④流域内土壤有机碳含量A.①②③B.②③④C.①②④D.①③④4.与海河相比,珠江的碳循环特点是A.碳输入量大,碳输出量小B.碳输入量小,碳输出量小C.碳输入量大,碳输出量大D.碳输入量小,碳输出量大十一国庆假期小明乘船到丁岛旅游,北京时间10月5日11:56,小明发现太阳在正南方天空,且身影长度比身高略短。

辽宁省滨城高中联盟2024-2025学年高三上学期期中考试数学试题(含答案)

辽宁省滨城高中联盟2024-2025学年高三上学期期中考试数学试题(含答案)

滨城高中联盟2024-2025学年度上学期高三期中Ⅰ考试数学试卷命题人:大连市第二十高级中学卢永娜校对人:大连市第二十高级中学苑清治第Ⅰ卷(选择题共58分)一、选择题:本题共8小题,每题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1.已知集合,,则( )A .B .C .D .2.“”是“函数在上单调递减”的( )A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件3.在中,点D 在边AB 上,.记,,则( )A .B .C .D .4.函数的值域为( )A .B .C .D .5.函数的单调递增区间为( )A .B .C .D .6.已知,,则( )A .B .C .D .7,设是定义域为R 的偶函数,且在单调递增,则()A .B .C .D .8.已知向量,,函数.若对于任意的,,且(){}lg 3M x y x ==-{}2N y y =>M N = ∅()2,3()3,+∞()2,+∞π2ϕ=-()sin 2y x ϕ=+π,02x ⎡⎤∈-⎢⎥⎣⎦ABC △2AD DB =CB a = CD b = CA =32a b-32a b+23a b +23a b-+()cos 2cos f x x x =+[]0,3[]1,3-[]1,2-[]0,2()()23log 4f x x =-()0,+∞(),0-∞()2,+∞(),2-∞-()1os 4c αβ+=tan tan 2αβ=()cos αβ-=34-112-11234()f x ()0,+∞233221log 223f f f --⎛⎫⎛⎫⎛⎫>> ⎪⎪ ⎪⎝⎭⎝⎭⎝⎭233221log 223f f f --⎛⎫⎛⎫⎛⎫>> ⎪ ⎪⎪⎝⎭⎝⎭⎝⎭23322122log 3f f f --⎛⎫⎛⎫⎛⎫>> ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭23322122log 3f f f --⎛⎫⎛⎫⎛⎫>> ⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭(),1a x = ()sin ,sin cos b x x x =+ ()f x a b =⋅ 1x 2π0,2x ⎡⎫∈⎪⎢⎣⎭,均有成立,则实数t 的取值范围为( )A .B .C .D .二、选择题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.9)A .B .C .D.10.已知向量,,则( )A .B .与向量共线的单位向量是C .D .向量在向量上的投影向量是11.已知函数,且对,都有,把图象上所有的点,纵坐标不变,横坐标变为原来的,再把所得函数的图象向右平移个单位,得到函数的图像,则下列说法正确的是( )A .B .C .为偶函数D .在上有1个零点第Ⅱ卷(非选择题 共92分)三、填空题:本题共3小题,每小题5分,共15分.12.已知向量,,若,则实数______.13.已知函数,若,,且,则的最小值是______.14.已知函数,则的最大值是______.四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15.(本小题满分13分)12x x ≠()()1212x x f x f x t e e ->-[)0,+∞[)1,+∞(],1-∞(],0-∞1tan151tan15+︒-︒tan 20tan 4020tan 40︒+︒︒︒)sin 503tan10︒+︒22tan151tan 15︒-︒()4,2a = ()6,2b =-20a b +=a ()a b a+⊥ a b 12b-()()π2cos 033f x x ωω⎛⎫=+<< ⎪⎝⎭x ∀∈R ()π3f x f x ⎛⎫''=- ⎪⎝⎭()f x 12π4()g x 1ω=()2π3g x g x ⎛⎫-=-⎪⎝⎭π6g x ⎛⎫+⎪⎝⎭()g x π0,2⎛⎫⎪⎝⎭()4,3a =- (),9b m =-a b ∥m =()323f x x x =+0m >0n >()()()230f m f n f +-=29m n+()2211222024sin log sin 2024cos log cos f x x x x x =+()f x已知.(1)求的值;(2)若,是方程的两个根,求的值.16.(本小题满分15分)已知函数在时取得极大值1.(1)求曲线在点处的切线方程;(2)求过点与曲线相切的直线方程.17.(本小题满分15分)已知函数为奇函数.(1)求实数a 的值;(2)设函数,若对任意的,总存在,使得成立,求实数m 的取值范围.18.(本小题满分17分)已知函数,.(1)求函数的极值;(2)若函数在区间上单调递增,求a 的最小值;(3)如果存在实数m 、n ,其中,使得,求的取值范围.19.(本小题满分17分)已知函数的图象如图所示.()()π2sin πsin 323π135cos 3cos 2π2x x x x ⎛⎫-+ ⎪⎝⎭=⎛⎫++- ⎪⎝⎭tan x sin x cos x 20x mx n -+=23m n +()323f x x x bx c =-++0x =()y f x =()()3,3f ()0,2()y f x =()221x x af x +=+()22log log 24x xg x m =⋅+(]20,1x ∈[]12,8x ∈()()12g x f x =()ln f x x x =()()1,011,02f x x xg x x x +⎧>⎪⎪+=⎨⎪+≤⎪⎩()f x ()xf x y ae x=-()1,2m n <()()g m g n =n m -()()πsin 0,0,2f x A x A ωϕωϕ⎛⎫=+>>≤⎪⎝⎭(1)求函数的单调递增区间;(2)求函数在上的最大值和最小值;(3)若函数在内恰有781个零点,求实数m 、n 的值.()f x ()π226x x f f h x =⎛⎫⎛⎫-⎪ ⎪⎝⎭⎝⎭π0,2⎡⎤⎢⎥⎣⎦()2π26π1x x g x f mf ⎛⎫- ⎪⎛⎫=+- ⎪⎝⎭⎭⎝()()*0,πn n ∈N滨城高中联盟2024-2025学年度上学期高三期中Ⅰ考试数学参考答案题号1234567891011答案CAD BCA BDABCCDABD12.1213.14.101215.(1)∵,∴,解得;(2)由题意可得,∴,,∴.16.(1),则,由题意可得,解得,即,,令,解得或,故在,上单调递增,在上单调递减,则在处取得极大值1,即,符合题意.(写经检验,当,时,在处取得极大值也给分)∵,,则切点坐标为,切线斜率,∴曲线在点处的切线方程为,即(2)由(1)可得:,,设切点坐标为,切线斜率,323()()π2sin πsin 2sin cos 323π5sin 3cos 135cos 3cos 2π2x x x x x x x x ⎛⎫--+ ⎪-⎝⎭==+⎛⎫++- ⎪⎝⎭2tan 135tan 313x x -=+tan 2x =sin cos sin cos x x mx x n +=⎧⎨=⎩()223sin cos 3sin cos 15sin cos m n x x x x x x +=++=+222sin cos tan 2sin cos sin cos tan 15x x x x x x x x ===++2231535m n +=+⨯=()323f x x x bx c =-++()236f x x x b '=-+()()0001f b f c '==⎧⎪⎨==⎪⎩01b c =⎧⎨=⎩()3231f x x x =-+()236f x x x '=-()0f x '>2x >0x <()f x (),0-∞()2,+∞()0,2()f x 0x =0b =1c =0b =1c =()f x 0x =()31f =()39f '=()3,19k =()y f x =()()3,3f ()193y x -=-9260x y --=()3231f x x x =-+()236f x x x '=-()32000,31x x x -+20036k x x =-则切线方程为,∵切线过点,则,整理得,即或,∴切线方程为或,即或.17.(1)由题意可得,函数的定义域为R ,因为是奇函数,所以,可得,经检验,对于,成立,所以.(2)由(1)可得因为,所以,,,,,所以当时的值域,(其他方法求值域酌情给分)又,,设,,则,当时,取最小值为,当时,取最大值为,即在上的值域,又对任意的,总存在,使得成立,即,所以,解得,即实数m 的取值范围是.18.(1)∵定义域为,,∴当时,;当时,;()()()32200003136y x x x x x x --+=--()0,2()()()322000023136x x x x x --+=--()()2001210x x -+=01x =12-()131y x +=--1151842y x ⎛⎫-=+ ⎪⎝⎭320x y +-=15480x y -+=()f x ()10011af +==+1a =-x ∀∈R ()()f x f x -=-1a =-()21212121x xx f x -==-++(]0,1x ∈(]21,2x∈(]212,3x+∈111,2132x ⎡⎫∈⎪⎢+⎣⎭221,213x ⎛⎤-∈-- ⎥+⎝⎦2110,213x ⎛⎤-∈ ⎥+⎝⎦(]0,1x ∈()f x 10,3A ⎛=⎤ ⎥⎝⎦()f x ()()()2222log log log 1log 224x xg x m x x m =⋅+=--+[]2,8x ∈2log t x =[]1,3t ∈()()21232y t t m t t m =--+=-++32t =14m -+3x =2m +()g x []2,8x ∈1,24B m m ⎡⎤=-++⎢⎥⎣⎦(]20,1x ∈[]12,8x ∈()()12g x f x =A B ⊆104123m m ⎧-+≤⎪⎪⎨⎪+≥⎪⎩5134m -≤≤51,34⎡⎤-⎢⎥⎣⎦()f x ()0,+∞()1ln f x x '=+()10,x e -∈()0f x '<()1,x e -∈+∞()0f x '>∴在上单调递减,在上单调递增,∴的极小值为,无极大值.(2)依题可知,,在上恒成立,显然,所以,设,,,所以在上单调递增,,故,即,即a 的最小值为.(3)方法1:由已知,则函数在、上为增函数,若存在实数m 、n ,其中,使得,则,,由可得,则,故,令,,,可得当时,,此时函数单调递减,当时,,此时函数单调递增,故,,又因为,,且,所以,,因此,的取值范围是.方法2:由已知,则函数在、上为增函数,若存在实数m 、n ,其中,使得,则,,令,则,可得,由可得,令,其中,令可得,()f x ()10,e -()1,e -+∞()f x ()11f e e-=-ln xy ae x =-10x y ae x '=-≥()1,20a >1x xe a≥()xg x xe =()1,2x ∈()()10xg x x e '=+>()g x ()1,2()()1g x g e >=1e a ≥1a e ≥1e()()ln 1,01,02x x g x x x ⎧+>⎪=⎨+≤⎪⎩()g x (],0-∞()0,+∞m n <()()g m g n =20m -<≤01n e <≤-()()g m g n =()1ln 12mn +=+()2ln 12m n =+-()2ln 12n m n n -=-++()()2ln 12x x x ϕ=-++(]0,1x e ∈-()211011x x x x ϕ-'=-==++1x =01x <<()0x ϕ'<()x ϕ11x e <<-()0x ϕ'>()x ϕ()()min 132ln 2x ϕϕ==-()02ϕ=()11e e ϕ-=-12e -<()32ln 22h t -≤<n m -[)32ln 2,2-()()ln 1,01,02x x g x x x ⎧+>⎪=⎨+≤⎪⎩()g x (],0-∞()0,+∞m n <()()g m g n =20m -<≤01n e <≤-()()g m g n t ==()ln 112t n mt ⎧=+⎪⎨=+⎪⎩122t n e m t ⎧=-⎨=-⎩20m -<≤01t <≤()21th t n m e t =-=-+01t <≤()20th t e '=-=ln 2t =当时,,此时函数单调递减,当时,,此时函数单调递增,故当时,,又因为,,且,所以,,因此,的取值范围是.(其他方法酌情给分)19.(1)由图象可得,最小正周期,则,由,所以,,又,则易求得,所以,由,,得,,所以单调递增区间为,.(2)由题意得,因为,所以,①从而可知,即因此,0ln 2t <<()0h t '<()h t ln 21t <≤()0h t '>()h t 01t <≤()()min ln 232ln 2h t h ==-()02h =()11h e =-12e -<()32ln 22h t -≤<n m -[)32ln 2,2-1A =7ππ2π1212T ⎛⎫=⨯-=⎪⎝⎭2π2Tω==77πsin 2π11212f ϕ⎛⎫⎛⎫=⨯+=- ⎪ ⎪⎝⎭⎝⎭5π2π3k ϕ=-+k ∈Z π2ϕ≤π3ϕ=()πsin 23x x f ⎛⎫=+ ⎪⎝⎭πππ2π22π232k x k -+≤+≤+k ∈Z 5ππππ1212k x k -+≤≤+k ∈Z 5πππ,π1212k k ⎡⎤-++⎢⎥⎣⎦k ∈Z ()ππsin sin 2263x x h x f f x x⎛⎫⎛⎫⎛⎫=-=+⎪ ⎪ ⎪⎝⎭⎝⎭⎝⎭111sin sin 2cos 2244x x x x x ⎛⎫==-+ ⎪ ⎪⎝⎭1π1sin 2264x ⎛⎫=-+ ⎪⎝⎭π02x ≤≤ππ5π2666x -≤-≤πππsin sin 2sin 662x ⎛⎫⎛⎫-≤-≤ ⎪ ⎪⎝⎭⎝⎭1πsin 2126x ⎛⎫-≤-≤ ⎪⎝⎭1π130sin 22644x ⎛⎫≤-+≤ ⎪⎝⎭故在上的最大值为,最小值为0.(3),令,可得,令,得,易知,方程必有两个不同的实数根、,由,则、异号,①当且或者且时,则方程和在区间均有偶数个根,不合题意,舍去;②当且时,则方程和在区间均有偶数个根,不合题意,舍去;③当,时,当时,只有一根,有两根,所以关于x 的方程在上有三个根,由于,则方程在上有780个根,由于方程在区间上有两个根,方程在区间上有一个根,因此,不合题意,舍去;④当,时,当时,只有一根,有两根,所以关于x 的方程在上有三个根,由于,则方程在上有780个根,由于方程在区间上只有一个根,方程在区间上两个根,此时,满足题意;因此,,,得,综上,,.(其他方法酌情给分)()h x π0,2⎡⎤⎢⎥⎣⎦34()ππcos 2sin 1226x g x f x mf x m x ⎛⎫⎛⎫=-+-=+⎪ ⎪⎝⎭⎝⎭()0g x =22sin sin 10x m x --=[]sin 1,1t x =∈-2210t mt --=0∆>1t 2t 1212t t =-1t 2t 11t >210t -<<101t <<21t <-1sin x t =2sin x t =()0,πn 101t <<201t <<1sin x t =2sin x t =()0,πn 11t =-212t =()0,2πx ∈sin 1x =-1sin 2x =22sin sin 10x m x --=()0,2πx ∈78132601=⨯+22sin sin 10x m x --=()0,520π1sin 2x =()520π,521πsin 1x =-()521π,522π11t =212t =-()0,2πx ∈sin 1x =1sin 2x =-22sin sin 1x m x --()0,2πx ∈78132601=⨯+22sin sin 10x m x --=()0,520πsin 1x =()520π,521π1sin 2x =-()521π,522π521n =1122m ⎛⎫⎪⎝=+⎭-1m =1m =521n =。

河北省保定市2024-2025学年高三上学期10月期中考试数学试题(含答案)

河北省保定市2024-2025学年高三上学期10月期中考试数学试题(含答案)

2024年高三摸底考数学试题本试卷共4页,19小题,满分150分.考试用时120分钟.注意事项:1.答题前,请务必将自己的姓名、准考证号用黑色字迹的签字笔或钢笔分别填写在试题卷和答题卡上.将条形码横贴在答题卡“条形码粘贴处”.2.作答选择题时,选出每小题答案后,用2B 铅笔把答题卡上对应题目选项的答案信息点涂黑;如需改动,用橡皮擦干净后,再选涂其他答案,答案不能答在试卷上.3.非选择题必须用黑色字迹钢笔或签字笔作答,答案必须写在答题卡各题目指定区域内相应位置上;如需改动,先划掉原来的答案,然后再写上新的答案;不准使用铅笔和涂改液.不按以上要求作答的答案无效.4.考生必须保持答题卡的整洁.考试结束后,将试卷和容题卡一并交回.一、选择题:本题共8小题,每小题5分,共40分.每小题给出的四个选项中,只有一个选项是正确的.1.已知,则()A.B. C. D.2.已知是的共轭复数,则()A.0 B. C.2D.3.已知向量,且,则()A.1B.2C.D.04.若一个球的体积和表面积数值相等,则该球的半径的数值为()A.2B.3C.45.设函数为偶函数.当满足时,|有最小值2,则和的值分别是()A. B.C. D.6.若中,角所对的边分别为平分交于,且,则(){}1,{5,}A xx B x x x ==<∈N ∣∣…A B ⋂={}0,1{}1[]0,1(]0,1()21i ,1i z z -=+z z =2i 2-()()1,1,2,a b λ==- ()0b λ=> a b ⋅= 1-r ()()πcos 0,2f x x ωϕωϕ⎛⎫=+><⎪⎝⎭12,x x ()()122f x f x -=12x x -∣ωϕπ,0ωϕ==ππ,2ωϕ==ππ,22ωϕ==π,02ωϕ==ABC ,,A B C ,,,4,16,a b c a b CD ==ACB ∠AB D 4CD =BD =B.3C.D.7.已知且,则的最小值是()A.12 B.16 C.15 D.148.已知函数若关于的方程至少有5个不等的实数解,则的取值范围是()A. B. C. D.二、多选题:本题共3小题,每小题6分,共18分.每小题给出的四个选项中,有多项符合题目要求.全部选对的得6分,选对但不全的得部分分,有选错的得0分.9.函数的图象经过()A.第一象限 B.第二象限C.第三象限D.第四象限10.若是平面的一条斜线,,直线平面且直线,记直线与平面所成的角为,则下列说法正确的是()A.与是一对异面直线B.若点和分别为直线上和平面内异于点的点,则C.若和分别是直线与上的动点,则满足且的直线不唯一D.过直线有且只有唯一平面与直线平行11.若函数存在两个极值点,下列说法正确的是()A.时满足条件B.不存在实数使得均为正整数C.当时,D.对任意正整数,均存在对应的,使得三、填空题:本题共3小题,每小题5分,共计15分.12.已知曲线在处的切线斜率为4,则实数的值为__________.13.函数的最小正周期是__________,在上的单调递减区间是__________.0ab >21a b +=221a b ab++()()1,11,22,17,x x f x f x x ⎧--<⎪=⎨-⎪⎩………x ()f x a =a []1,0-[]2,0-[]4,0-[]8,0-()11x y a a a=->αl O α⋂=a ⊂αO ∉a αθa A B αO AOB ∠θ…M N a MN l ⊥MN a ⊥a ()21ln 2f x x x mx x =--()1221,x x x x >1m =m 12,x x 321x x …m n 12,x x ()222112ln x x n x x -=13e 1x y ax -=++1x =a ()2cos sin cos 1f x x x x =++()f x ()0,π14.已知递增数列共有项(为定值)且各项均不为零,末项.若从数列中任取两项和,当时,仍是数列中的项,则数列的通项公式__________(用含和的式子表示.)四、解答题:本题共5小题,共77分.解答应写出文字说明、证明过程或演算步骤.15.(13分)已知向量.(1)若,且,求的值;(2)设函数,求函数的值域.16.(15分)已知直三棱柱中,,且,点分别为线段和的中点.(1)证明:平面;(2)求平面与平面的夹角.17.(15分)在中,角的对边分别为.(1)求角;(2)若,求的值;(3)在(2)的条件下,若边,点为线段上的动点,点为线段上的动点,且线段平分的面积,求线段长度的最小值.18.(17分)已知函数.{}n a m *,m m ∈N 1m a ={}n a i a j a i j <j i a a -{}n a {}n a n a =m n ()3cos ,1,sin ,2a x b x ⎛⎫==- ⎪⎝⎭ a ∥b ()0,πx ∈sin cos x x -()()π2,0,4f x a b a x ⎡⎤=+⋅∈⎢⎥⎣⎦ ()f x 111ABC A B C -12AB BC BB ===AB BC ⊥,E F AC 1CC 1A E ⊥BEF 1ABC BEF ABC ,,A B C 2,,,cos cos b a c a b c B C-=B 2222b c ac =+cos C 2c =D AB E BC DE ABC DE ()()e sin 2,2cos x f x x x g x x =+-=-(1)已知直线是曲线的切线,求实数a 的值;(2)求函数的单调区间;(3)求证:恒成立.19.(17分)已知数列,其前项和为,对任意正整数恒成立,且.(1)证明:数列为等比数列,并求实数的值;(2)若,数列前项和为,求证:;(3)当时,设集合,集合中元素的个数记为,求数列的通项公式.0x y a -+=()[],0,πy g x x =∈()f x ()()f x g x …{}n a n n S ,2n n n S a μ=-1212a a +={}n a μ21log n n b a =()n b n n T 2ln 2n n T +>1n …{}123232,1n n n i j i j B a a a a i j ++=+⋅<+<⋅<∣…*,i j ∈N n B n c {}n c2024年高三数学摸底试题参考答案一、选择题:(每小题5分,共40分)1.A2.B3.C4.B5.D6.C7.D8.B8.解析:由题意的图象如图所示,问题转化为函数的图象与直线的至少有5个公共点,故的范围是B 正确.二、多选题:(每小题6分,共18分)9.ABC11.解析:当时在上单调递增.此时至多有一个极值点,不符合题意.当时,若;若.在上单调递增,在上单调递减.又当时.当时,故只需A 错误.此时且由于是的两个零点且.则若为正整数则.此时.()f x ()f x y a =a []2,0.-()()()()1ln 0;0mx f x x mx x f x x x'-=->='>'0m ≤()()0f x f x ≥∴'''()0,∞+()f x 0m >()10,,0x f x m ⎛⎫⎪⎭''∈> ⎝()1,,0x f x m ∞⎛⎫∈+⎭''< ⎪⎝()f x ∴'10,m ⎛⎫ ⎪⎝⎭1,m ∞⎛⎫+ ⎪⎝⎭0x +→()f x ∞'→-x ∞→+()f x ∞'→-1110ln 100.e f m m m '⎛⎫>⇒->⇒<< ⎪⎝⎭1e m>()()e 1e 0,10f m f m '=->-'=<12,x x ()f x '12x x <121e 1e x x m <<⎧⎪⎨>>⎪⎩1x 12x =()()2ln22ln2242ln242ln22ln2042f m m f m x '=-⇒=⇒='-=-=⇒=所以存在使得均为正整数,B 错误.由于和是函数与直线交点的横坐标.当时恰有.所以当时,必有当(注:由图象与直线交点变化情况可知m 越小,越小,越大.m 越大,越大,越小)所以当时,m正确..由于当时此时,当时此时故的取值范围是,即对任意正整数均存在使得.D 正确综上可知:CD 正确.三、填空题:(每个小题5分,共15分)12.113.;(开闭区间均给分)14.14.解析:由题意:,若则.而是递增数列中的项,这与是ln22m =12x x 111212212ln ln ln ln x mx x x m x x mx x x =⎧⇒==⇒⎨=⎩2x ()ln x g x x =y m ===m =12x x ==321x x =0m <≤321x x ≥m >321x x <ln x y x=y m =1x 2x 1x 2x 321x x ≥()()()()()22212121212121121212ln ln ln x x x x x x x x x x x x x x x x mx mx m+-+---===++0m +→21x x ∞-→+21x x m∞-→+1e m →210x x +-→210x x m-→()222112ln x x x x -()0,∞+n 12,x x ()222112ln x x n x x -=ππ5π,88⎡⎤⎢⎥⎣⎦n m 10a ≠10a <11m m a a a ->=1m a a -{}n a 1m a =数列的最大项矛盾.故必有.因为数列是单调递增数列,所以有.从而有且它们均为数列中的项.因此由上可知所以数列是以为首项,以为公差的等差数列.所以四、解答题:(本题共5小题,共77分)15.(13分)解:(1),,又,,;(2)由题意:10a >{}n a 12301m a a a a <<<<<=2131411m m a a a a a a a a a -<-<-<<-< {}n a 121212a a a a a =-⇒=23131213a a a a a a a =-⇒=+=34143114a a a a a a a =-⇒=+=.⋯⋯⋯11111m m m m a a a a a a ma --=-⇒=+=11a m ={}n a 11a m=1m n n a m=a ∥3,cos sin 2b x x ∴-= 3tan 2x ∴=-()0,πx ∈ sin x x ∴==sin cos x x ∴-=1cos sin ,2a b x x ⎛⎫+=+- ⎪⎝⎭ ()()()2122cos sin ,cos ,12cos 2sin cos 12f x a b a x x x x x x ⎛⎫∴=+⋅=+-⋅=+- ⎪⎝⎭ πsin2cos224x x x ⎛⎫=+=+ ⎪⎝⎭,的值域是16.(15分)(1)证明平面平面,又,又平面又平面.又即.又平面.(2)解:如图所示,以点为原点,为轴,为轴建立空间直角坐标系,易得设平面的法向量,则,取,则法向量.由(1)可知平面的法向量.平面与平面的夹角为.πππ3π0,,2,4444x x ⎡⎤⎡⎤∈∴+∈⎢⎥⎢⎥⎣⎦⎣⎦ ()∴f x ⎡⎣1A A ⊥ ,ABC BE ⊂1,ABC A A BE ∴⊥,.AB BC AE EC BE AC ==∴⊥ 1A A AC A BE ⋂=∴⊥ 11ACC A 1A E ⊂ 111,A ACC A E BE ∴⊥1tan tan A EA EFC ∠∠== 11ππ22A EA EFC EFC FEC A EA FEC ∠∠∠∠∠∠∴=+=∴+= 1A E EF ⊥1.EF BE E A E ⋂=∴⊥BEFB BA x BC y 11(2,0,0),(0,0,0),(0,2,2),(2,0,2),(1,1,0)A B C A E ()()12,0,0,0,2,2,BA BC == 1ABC (),,n x y z = 120,220n BA x n BC y z ⋅==⋅=+= 1y =()0,1,1n =-()11,1,2A E =-- BEF 111cos ,||A E n A E n A E n ⋅∴<>===⋅ 1ABC BEF π617.(15分)解:(1),,,(2),又,(3)若边由(1)(2)可知,,令,则,又由余弦定理得:(当时等号成立).18.(17分)解:(1),,解得切点为,2,sin cos 2sin cos cos sin cos cos b a c B C A B B C B C -=∴=- sin cos cos sin 2sin cos B C B C A B∴+=1sin 2sin cos ,cos 2A A B B ∴=∴=()π0,π,3B B ∈∴=222π1,232B b a c ac =∴=+-⋅ 2222b c ac =+ 233,,22ac a a c b ∴=∴=∴=222cos 2a b c C ab +-∴===2c =π3,3a b B ===1sin 2ABC BDE S ac B S ∴==∴= ,BD m BE n ==132BDE S mn ==∴= 2221232DE m n mn mn =+-≥=m n ==DE ∴()[]sin ,0,πg x x x =∈' ()sin 1g x x ='∴=π,2x =∴π,22⎛⎫ ⎪⎝⎭ππ20,222a a ∴-+=∴=-(2),当时,单调递减当时,,单调递增,单调递递增.综上所述,在上单调递减,在上单调递增.(3)证明:恒成立恒成立恒成立.令,则令则单调递增,又,当时,,即单调递减;当时,,即单调递增;恒成立.19.(17分)解:(1)令可得,即.令可得,即,所以又.,两式相减可得,数列为首项为4,公比为2得等比数列.(2)证明:由(1)可知,所以.()e cos 2xf x x =+'- (],0x ∞∈-()()e 1,cos 1,0,xx f x f x ≤'≤≤∴[)0,x ∞∈+()e sin ,e 1,sin 1x xf x x x =-≥'≤'()()0,f x f x ≥'∴''∴()()()00,f x f f x ='≥'∴()f x (],0∞-[)0,∞+()()f xg x ≥e sin 2cos 20x x x x ⇔+-+-≥sin cos 2210e xx x x +--⇔+≥()sin cos 221e x x x x h x +--=+()()()()cos sin 2sin cos 222sin e e x x x x x x x x x h x ---+'---==()sin m x x x =-()()1cos 0,m x x m x =-≥∴'()00m = ∴(],0x ∞∈-()0m x ≤()()0,h x h x '≤[)0,x ∞∈+()0m x ≥()()0,h x h x '≥()()()()00,h x h f x g x ∴≥=∴≥1n =112S a μ=-1a μ=2n =222S a μ=-1222a a a μ+=-22a μ=1212,4a a μ+=∴= 112424n n n n S a S a --=-⎧⎨=-⎩ 1122,2n n n n n a a a a a --=-∴=∴{}n a 12n n a +=211log 1n n b a n ==+要证成立,只需证,即令,当时,单调递增,(3)时,集合,即3中元素个数,等价于满足的不同解,如果.则.盾!如果j ,则,矛盾!,又,,即,共个不同解,所以.11122,ln ln .121n n n i i n i T i i ==++==++∑∑ ∴2ln 2n n T +>12ln 11n n n +>++11ln 111n n ⎛⎫>+ ⎪++⎝⎭()()()()1ln 1,10,0,11x f x x x f x x x x ∞=-+==>'-∈+++∴()0,x ∞∈+()f x ()()()1ln 100,01f x x x f f n ⎛⎫=-+>=∴> ⎪+⎝⎭112ln 1,ln 112n n T n n +⎛⎫∴>+∴> ⎪++⎝⎭1n ≥{}123232n n n i j i j B a a a a ++=+⋅<+<⋅∣1*22232,1,,,n i j n n i j i j B +⋅<+<⋅≤<∈N 1322232n i j n +⋅<+<⋅(),i j 2j n <+1122222232i j i n n n n +++++=⋅……2n >+31222232i j i n n +++≥+>⋅2j n ∴=+()12223224232220n n n n n ++-⋅=+⋅-⋅=+> 1222212322222222232n n n n n n n n ++++++∴⋅<+<+<<+<+=⋅ 1,2,3,,i n = n (),i j ()1n c n n =≥。

2024-2025学年山东省菏泽市高三上学期期中数学试题及答案

2024-2025学年山东省菏泽市高三上学期期中数学试题及答案

菏泽市2024—2025学年度第一学期期中考试高三数学试题本试卷共4页,19题.全卷满分150分.考试用时120分钟.注意事项:1.答题前,先将自己的姓名、准考证号填写在答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置.2.选择题的作答:每小题选出答案后,用2B 铅笔把答题卡上对应题目的答案标号涂黑.写在试题卷、草稿纸和答题卡上的非答题区域均无效.3.非选择题的作答:用签字笔直接写在答题卡上对应的答题区域内.写在试题卷、草稿纸和答题卡上的非答题区域均无效.4.考试结束后,请将本试题卷和答题卡一并上交.一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.1. 已知集合{}{}202,0M x x N x x x =∈<<=-≤Z ∣∣,则M N = ( )A. {}0,1 B. {}1 C. {}1,1- D. ∅2. 已知函数()21f x +的定义域为[]1,2,则函数()1f x -的定义域为( )A. []1,2 B. []4,6 C. []5,9 D. []3,73. 已知2025π1sin sin 22αα⎛⎫-+=⎪⎝⎭,则cos2sin cos ααα=+( )A. 12-B.12C. 0D. 14. “函数()32f x x ax =-在[]2,3-上单调递增”是“3a ≤”的( )A. 充分不必要条件 B. 必要不充分条件C 充要条件D. 既不充分又不必要条件5. 过曲线9log =y x 上一点A 作平行于两坐标轴的直线,分别交曲线3log y x =于点,B C ,若直线BC 过原点,则其斜率为( )A. 1B.3log 22C.ln33D.2log 36.6. 函数()11ln sin 21x f x x x+=--的零点个数为( )A. 1B. 0C. 3D. 27. 自然界中许多流体是牛顿流体,其中水、酒精等大多数纯液体、轻质油、低分子化合物溶液以及低速流动的气体等均为牛顿流体;高分子聚合物的浓溶液和悬浮液等一般为非牛顿流体,非牛顿流体在实际生活和生产中有很多广泛的应用,如工业制造业常利用某些高分子聚合物做成“液体防弹衣”,已知牛顿流体符合牛顿黏性定律,即在一定温度和剪切速率范围内黏度值是保持恒定的:τηγ=,其中τ为剪切应力,η为黏度,γ为剪切速率;而当液体的剪切应力和剪切速率存在非线性关系时液体就称为非牛顿流体.其中宾汉流体(也叫塑性流体),是一种粘塑性材料,是非牛顿流体中比较特殊的一种,其在低应力下表现为刚体,但在高应力下表现为粘性流体(即粘度恒定),以牙膏为例,当我们挤压它的力较小时,它就表现为固体,而当力达到一个临界值,它就会变成流体,从开口流出.如图是测得的某几种液体的流变τγ-曲线,则其中属于牙膏和液体防弹衣所用液体的曲线分别是( )A. ①和④B. ③和④C. ③和②D. ①和②8. 已知函数()()1e xf x x =-,点(),m n 在曲线()y f x =上,则()()f m f n -( )A. 有最大值为1e -,最小值为1 B. 有最大值为0,最小值为1e-C. 有最大值为0,无最小值D. 无最大值,有最小值为1e-二、选择题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.9 已知0c b a <<<,则( )A. ac bc <B. 333b c a +< C.a c ab c b+>+D.<10. 已知函数()21,2,5,2xx f x a b c d x x ⎧-≤⎪=<<<⎨->⎪⎩,且()()()()f a f b f d f c ==<,则( )A. 1a ≤- B. []1,4c ∈ C. ()20,5ad ∈ D. 222a b +=.11. 把一个三阶魔方看成是棱长为1的正方体,若顶层旋转x 弧度π02x ⎛⎫<<⎪⎝⎭,记表面积增加量为()S f x =,则( )A. π6f ⎛⎫=⎪⎝⎭B. ()f x 的图象关于直线π3x =对称C. S 呈周期变化D. 6S ≤-三、填空题:本题共3小题,每小题5分,共15分.12. 命题:“所有能被4整除的正整数能被2整除”的否定是______.13. 已知函数()sin2cos2f x x a x =+,将()f x 的图象向左平移π6个单位长度,所得图象与曲线()y f x =关于原点对称,则()0f =______.14. 已知22,e x ⎡⎤∈⎣⎦时,2log 2axx x ax ≥⋅,则正数a 的最大值为______.四、解答题:本题共5小题,共77分.解答应写出必要的文字说明,证明过程或演算步骤.15. 记ABC V 内角,,A B C 的对边分别为,,a b c ,已知πsin sin ,63C C b ⎛⎫+== ⎪⎝⎭,ABC V的面积为(1)求C ;(2)求ABC V 的周长.16. 已知函数()π2sin 43⎛⎫=- ⎪⎝⎭f x x .(1)求()f x 的单调递减区间;(2)若ππ,68x ⎡⎤∈-⎢⎥⎣⎦,求()()23-=+f x y f x 的最大值.17. 记锐角ABC V 的内角,,A B C 的对边分别为,,a b c ,已知cos 2cos cos c CA b B-=.(1)求B ;的(2)延长AC 到D ,使2,15AC CD CBD =∠= ,求tan A .18. 已知函数()()2e xf x x a =-.(1)求()f x 单调区间;(2)设12,x x 分别为()f x 的极大值点和极小值点,记()()()()1122,,,A x f x B x f x .证明:直线AB 与曲线()y f x =交于另一点C .19. 已知函数()()sin tan sin 2f x x x x =+-,其中01x <<,(1)证明:21cos 12x x >-;(2)探究()f x 否有最小值,如果有,请求出来;如果没有,请说明理由.的是菏泽市2024—2025学年度第一学期期中考试高三数学试题本试卷共4页,19题.全卷满分150分.考试用时120分钟.注意事项:1.答题前,先将自己的姓名、准考证号填写在答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置.2.选择题的作答:每小题选出答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑.写在试题卷、草稿纸和答题卡上的非答题区域均无效.3.非选择题的作答:用签字笔直接写在答题卡上对应的答题区域内.写在试题卷、草稿纸和答题卡上的非答题区域均无效.4.考试结束后,请将本试题卷和答题卡一并上交.一、选择题:本题共8小题,每小题5分,共40分.在每小题给出的四个选项中,只有一项是符合题目要求的.【1题答案】【答案】B【2题答案】【答案】B【3题答案】【答案】A【4题答案】【答案】A【5题答案】【答案】B【6题答案】【答案】A【7题答案】【答案】D【8题答案】【答案】B二、选择题:本题共3小题,每小题6分,共18分.在每小题给出的选项中,有多项符合题目要求.全部选对的得6分,部分选对的得部分分,有选错的得0分.【9题答案】【答案】ABD 【10题答案】【答案】BCD 【11题答案】【答案】AD三、填空题:本题共3小题,每小题5分,共15分.【12题答案】【答案】存在能被4整除的正整数不能被2整除【13题答案】【答案】【14题答案】四、解答题:本题共5小题,共77分.解答应写出必要的文字说明,证明过程或演算步骤.【15题答案】【答案】(1)π3C =(2)10+【16题答案】【答案】(1)π5ππ11π,224224k k ⎡⎤++⎢⎥⎣⎦,()k ∈Z (2)0【17题答案】【答案】(1)45B =(2)2+【18题答案】【答案】(1)单调增区间为()(),2,,a a ∞∞--+,单调减区间为(2,)a a - (2)证明见解析【19题答案】【答案】(1)证明见解析(2)没有,理由见解析。

山东省菏泽市2024-2025学年高三上学期期中考试政治试题

山东省菏泽市2024-2025学年高三上学期期中考试政治试题

菏泽市 2024—2025 学年度第一学期期中考试高三思想政治试题本试卷共8页,19题。

全卷满分100分。

考试用时90分钟。

注意事项:1.答题前,先将自己的姓名、准考证号等填写在答题卡上,并将准考证号条形码粘贴在答题卡上的指定位置。

2.选择题的作答:选出每小题答案后,用2B铅笔把答题卡上对应题目的答案标号涂黑。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

3.非选择题的作答:用签字笔直接写在答题卡上对应的答题区域内。

写在试题卷、草稿纸和答题卡上的非答题区域均无效。

4.考试结束后,请将本试题卷和答题卡一并上交。

一、选择题:本大题共15 小题,每小题3分,共45分。

在以下每小题的四个选项中,只有一项是符合题意的。

1.马克思在《1844年经济学哲学手稿》指出:“工人生产得越多,他能够消费的越少;他创造的价值越多,他自己越没有价值、越低贱;工人的产品越完美,工人自己越畸形;工人创造的对象越文明,工人自己越野蛮。

”材料说明①劳动所生产的对象和劳动相对立②少数资本家占有大多数生产资料③资本家无偿占有了工人的剩余劳动④生产社会化程度越高,工人越被剥削A.①③B.①④C.②③D.②④2.党的二十届三中全会指出,当前和今后一个时期是以中国式现代化全面推进强国建设、民族复兴伟业的关键时期,中国式现代化是在改革开放中不断推进的,也必将在改革开放中开辟广阔前景。

这是基于①中国式现代化拓展了发展中国家走向现代化的途径②当下处于中华民族史上最为广泛而深刻的社会变革时期③中国式现代化是强国建设、民族复兴的唯一正确道路④对外开放是我国的基本国策,改革是中国的第二次革命A.①②B.①③C.②④D.③④3.李大钊曾说,青年要“为世界进文明,为人类造幸福,以青春之我,创建青春之家庭,青春之国家,青春之民族,青春之人类,青春之地球,青春之宇宙”。

习近平总书记指出,“教育引导青少年学生坚定马克思主义信仰、中国特色社会主义信念、中华民族伟大复兴信心,立报国强国大志向、做挺膺担当奋斗者”。

河南省名校联合体2025届高三上学期期中考试语文试题及答案

河南省名校联合体2025届高三上学期期中考试语文试题及答案

河南省名校联合体2025届高三期中考试语文试题一、现代文阅读(35分)(一)现代文阅读I(本题共5小题,19分)阅读下面文字,完成下面小题。

材料一:数学相关的逻辑推理能力一直是当下大模型的短板。

当前用户可以感知到的大模型,是基于海量文本的相关性进行训练分析,从而达到文本生成的人类平均水平。

但是,除了文本的分析和生成之外,人类对信息的搜集分析处理中最重要的是推理能力,包括逻辑推理、认知推理等。

逻辑推理即根据前提条件给出符合逻辑或潜在逻辑关系的结论,而数学运算是用精确的语言和符号进行纯逻辑的推演。

逻辑推理被认为是当前大模型最难攻克的一道关卡。

而除了逻辑推理之外,对有限的碎片信息进行不断重组、搜寻以找到信息全貌等,类似于传统侦探推理小说所呈现的“碎片信息拼凑分析”,也在大模型当前的能力范围之外。

目前,大模型所展现的应用场景主要局限在资料分析、内容生成等领域,而在涉及数字分析、逻辑推演等领域,大模型的想象空间依然有限。

很难想象,一个难以判断小数点后数字大小的大模型,能够在工业生产制造、金融计算等领域有广泛应用前景。

因此,国内外的大模型企业已经开始有意识地探索“如何训练大模型在特定条件下的推理能力”。

(摘编自王晓凯《分不清9.11和9.9大小,暴露大模型逻辑推理能力短板》)材料二:人工智能既然是一种技术,自然就会蔓延进入人的生活生产领域。

文学艺术生产是人类元状态的精神生产,洞穴中的壁画、结绳记事的环扣都是在为人类用精准的语言表达心灵世界做的漫长预热。

因此,从很早开始,计算机技术就已经与语言产生了勾连性的尝试。

与之进行远距离对应的是,超强人工智能在科幻作品中以各种瑰丽奇谲的面貌出现。

比如1968年电影《2001太空漫游》中的超级计算机,它能够自主判断处境,争取自己的命运,甚至表演出比人类有过之而无不及的谋虑诡计。

从现有发展水平上看,我们更需要讨论的是在现实和幻想之间处于过渡地带的强人工智能。

强人工智能“呈现”出与人近似的意识,与人类展开交互式学习。

北京市朝阳区2024-2025年高三上学期期中考试政治试题含解析

北京市朝阳区2024-2025年高三上学期期中考试政治试题含解析
④:某地在传统的人工除草和化学农药除草方法之外,又发明了生物防治的方法,这一做法在保留原有方法的基础上增加新的防治手段,体现了创新意识,④正确。
①:材料没有体现适度原则的要求,①与题意不符。
③:矛盾双方在一定条件下可以相互转化,斗争性与同一性是矛盾的基本属性,不能相互转化,③错误。
故本题选C。
5.亚里士多德说:“古今来人们开始哲理探索,都应起于对自然万物的惊异:他们先是惊异于种种迷惑的现象,逐渐积累一点一滴的解释,对一些较重大的问题,例如日月与星的运行以及宇宙之创生,作成说明。一个有所迷惑与惊异的人,每自愧愚蠢……他们探索哲理只是为想脱出愚蠢,他们为求知而从事学术,并无任何实用目的。这个可由事实为之证明:这类学术研究的开始,都在人生的必需品以及使人快乐安适的种种事物几乎全部获得了以后。”亚里士多德的上述思考( )
②:要勇建强国之功,迎难而上,依据价值判断作出价值选择,②错误。
④:要铸牢强国之基,弘扬时代精2.在中国,各式传统民居饱含“一方水土养育一方人”的智慧,让人们对家的情感有了寄托。江南水乡多为“粉墙黛瓦”的外观,“小桥流水人家”的意境浑然天成;闽西圆如明月的土楼依偎在青山绿水间,见证了客家人对“天圆地方、天人合一”的哲思和对“万事和合、子孙团圆”的珍视;点缀在沟梁峁塬间的窑洞,承载黄土地上的繁衍生息与家风绵延,安抚着陕北人的乡愁。下列对此理解最贴切的是( )
B:题干侧重于强调不同地理环境下的传统民居对人们家的情感所产生的影响,而选项分析的是各个民族交往、交流、交融对传统文化的影响,B不符合题意。
C:题干侧重于文化载体对人们情感世界的影响,而选项强调的是要按照当今时代社会生活需要来实现家文化的创新性发展,C不符合题意。
D:题干中“在中国,各式传统居民饱含‘一方水土养育一方人’的智慧,让人对家的情感有了寄托”,以及各地不同民居让人们产生了不同的对家的情感,表明各地民居中蕴含的家文化深刻影响着中国人的精神世界,故D正确。

北京市朝阳区2024-2025学年高三上学期期中考试地理试题含答案

北京市朝阳区2024-2025学年高三上学期期中考试地理试题含答案

北京市朝阳区2024~2025学年度第一学期期中质量检测高三地理试卷(考试时间90分钟满分100分)第一部分本部分共15题,每题3分,共45分。

在每题列出的四个选项中,选出最符合题目要求的一项。

巴黎奥运会于当地时间2024年7月26日19:30开幕,8月11日闭幕。

巴黎(48°52'N,2°25E)使用的时间为东一区的区时,奥运会期间正值当地使用夏令时(将时钟拨快1小时)。

据此回答第1—3题。

1.北京直播巴黎奥运会开幕时刻的时间是A.7月26日12:30B.7月26日11:30C.7月27日2:30D.7月27日1:302.巴黎奥运会期间A.地球公转速度逐渐变慢B.南极大陆极昼范围扩大C.当地日出方位逐渐南移D.时值我国小暑至立秋之间3.图1中能正确示意北京与巴黎昼长和正午太阳高度年变化范围的是图1A.①B.②C.③D.④2024年9月受台风“摩羯”影响,我国东南沿海多地受灾严重。

图2为台风“摩羯”生成至消亡每日14时的位置及中心气压值变化示意图,图3为2024年9月6日17时亚洲局部地区海平面气压分布图。

读图,回答第4—6题。

图2 图34.台风“摩羯”A.生成于北太平洋中部海域B.移动速度在120°E以东最慢C.移动方向为先向东再向北D.势力最强的时段出现在9月6日5.2024年9月6日17时A.甲地风向为偏南风B.乙地受高气压控制,气流下沉C.海南岛出现强降雨D.台湾海峡天气晴朗,风急浪高6.台风“摩羯”导致我国海南水产养殖业受损,其主要原因有①大风破坏水产养殖设施②风暴潮使养殖区海水水位降低③强降水改变养殖水环境④赤潮导致水生生物缺氧死亡A.①②B.①③C.②④D.③④图4为渤海最大可能潮差分布图(单位:米)。

读图,回答第7、8题。

图47.影响渤海潮差的主要因素是A.海湾形状B.洋流流向C.季风风向D.人类活动8.图中A.大连比葫芦岛近海潮汐能丰富B.甲处比乙处海水的盐度低C.乙处比甲处海水结冰期长D.葫芦岛比烟台近海海水温度高札达盆地位于喜马拉雅山和冈底斯山之间,海拔3700~4500米,盆地内分布着景观独特的札达土林。

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戴埠高级中学高三第一学期期中试题(数学)
2002年11月
得分:
1.已知集合{}1|≤=x x M ,{}p x x N ≥=|要使φ=N M ,则p 满足的条件是
A .1≥p
B .1>p
C .1≤p
D .1<p 2.设{}20|≤≤=x x M ,{}20|≤≤=y y N ,给出下列四个图象,其中能表示从集合M 到集合N 的函数关系的有 A .0个 B .1个 C .2个 D .3个
3.函数
x x x f ωω22cos sin -=0>ω的最小正周期为1,则 A .1=ω,()x f 在[]0,π-上是增函数, ()x f 为偶函数
B .πω=,()x f 在⎥⎦

⎢⎣⎡-0,21上是减函数,()x f 为偶函数
C . 1=ω,()x f 在[]0,π-上是减函数,()x f 为奇函数
D .πω=,()x f 在⎥⎦

⎢⎣⎡-0,21上是增函数,()x f 为奇函数
4.若函数()x f y =的定义域是[]2,1-,则函数()()()x f x f x g -+=的定义域是
A .[]2,2-
B .[]1,1-
C .[]1,2--
D .[]2,1 5.在区间[]1,1-上为减函数的是
A .x y 5=
B .()1log 2
1+=x y C .22
-+=x x y D .x y sin =
6.已知83cos sin =αα,且2

απ<<,则ααsin cos -的值
A .21
B .21-
C .41
D .4
1-
7.若()x
x f ⎪⎭
⎫ ⎝⎛=21,+
∈R b a ,,⎪⎭⎫
⎝⎛+=2b a f A ,()
ab f B =,⎪⎭⎫ ⎝⎛+=b a ab f C 2,则A ,B ,C 的大小关系为 A .C B A ≤≤ B .B C A ≤≤ C .A C B ≤≤ D .A B C ≤≤
8.把一个函数的图象按⎪⎭

⎝⎛=2,4πa 平移后得到的图象解析式为
24s i n +⎪⎭⎫ ⎝

+=πx y ,那么原来的函数解析式为
A .x y sin =
B .x y cos =
C .2sin +=x y
D .2cos +=x y
9.已知j i ,是互相垂直的单位向量j i a
2-=,j i b λ+=,若a ,b 的夹角为锐角,则λ的范围是
A .()⎪⎭⎫ ⎝⎛--∞-21,22,
B .⎪⎭⎫ ⎝⎛+∞,21
C .⎪⎭⎫ ⎝⎛+∞,32
D .⎪⎭⎫ ⎝

∞-32,
10.某城市加强环境保护,绿地面积每年都比上一年增长%10,经过x 年后,绿地面积可以增长为原来的y 倍,则函数()x f y =的图象大致是
11.公差不为零的等差数列的第二,第三,第七项恰好构成等比数列,则它的公比为
A .4-
B .4
1- C .41
D .4
12.已知数列{}n a 的通项公式98
97
--=n n a n ()N n ∈,则数列{}n a 前30项
的最大项和最小项分别是 A .301,a a B .91,a a C .910,a a D .3010,a a
13.函数()
1lg 3--=x x
y 的定义域是
14.等差数列{}n a 中,20161396=+++a a a a ,则=21S 15.如果不等式a x x ≤++-12有解,则实数a 的取值范围是
16.已知定义域为R 的函数()x f 满足当),4[+∞∈x 时,()x x f 2=,当()4,∞-∈x 时,()()2+=x f x f ,则()3log 2f 的值等于
三、解答题(共74分) 17.在ABC ∆中,已知53sin =A ,13
5
cos =B ,求C cos (本小题12分)
18.求证:c b a a
c c b b a 212121212121
log log log 2
log 2log 2log ++≤+++++ (本小题12分)
19.已知4=a ,3=b ,()()
61232=+⋅-b a b a
(1)求a 与b
的夹角;
(2)求b a +与b a
-;
(3)若a B A
=,b C A =,作ABC ∆,求ABC S ∆ (本小题12分)
20.已知数列{}n a 中,前n 项和n n S n 532+=,数列{}n b 中81=b ,0641=-+n n b b ,且存在常数C ,使得对一切正整数n ,n c n b a log +恒为常数M ,试求出C 和M 之值 (本小题12分)
21.已知函数()c
bx ax x f ++=1
2,()0,0,,>>∈b a R b a 且是奇函数当0>x 时,
()x f 有最小为2,设当点()y x P ,是函数图象上的点时,点()y a x Q --,2是函数()x g y =图象上的点
(1)求证:2b a =
(2)求函数()x g y =的表达式 (本小题12分)
22.已知定义在+R 上的函数()x f ,对任意的+∈R y x ,,恒有()()()y f x f y x f +=⋅成立 (1)求()1f 的值;
(2)求证:当+∈R x 时,()x f x f -=⎪⎭

⎝⎛1
(3)若1>x 时,恒有()0<x f ,试判断()x f 在()+∞,0上的单调性并说明理由。

(本小题14分)。

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