华南农业大学期末考试试卷(A)答案
华南农业大学反刍动物疾病学期末考试试卷(带答案)
华南农业大学期末考试试卷(A卷)考试科目:反刍动物疾病学考试类型:(闭卷)考试时间:120 分钟学号姓名年级一.填空题(每个空1分,20分)1.临床常见的奶牛病毒性传染性疾病包括:、、、、、、、等。
2.反刍动物的胃是,由、、和四部分组成,前三部分称为,无腺体,只有是真胃分泌胃液。
3.奶牛先天性不孕包括:、、和生殖道畸形,生殖道畸形包括:、。
二.名词解释(每题2分,10分)1.结核病2.肉孢子虫病3.子宫积水4.指(趾)间皮炎5.瘤胃积食三.简答题(每题10分,30分)1.简述牛副结核病流行病学特点和临床症状。
2.简述瘤胃酸中毒的定义、病因和治疗方法。
3.简述弓形体病流行病学特点和临床症状。
四.详细说明奶牛疾病性不孕的种类及其病因、临床症状和诊断方法。
(20分)五.详细说明奶牛创伤性网胃腹膜炎的病因、病理发生过程、临床症状、诊断和治疗方法。
(20分)华南农业大学期末考试试卷(A卷)标准答案考试科目:反刍动物疾病学考试类型:(闭卷)考试时间:120 分钟学号姓名年级专业一.填空题(每个空1分,20分)4.临床常见的奶牛病毒性传染性疾病包括:口蹄疫、牛传染性鼻气管炎、疯牛病、牛流热、牛病毒性腹泻(黏膜病)、牛地方性白血病、蓝舌病、赤羽病等。
5.反刍动物的胃是复室胃,由瘤胃、网胃、瓣胃和皱胃四部分组成,前三部分称为前胃,无腺体,只有皱胃是真胃分泌胃液。
6.奶牛先天性不孕包括:幼稚病、两性畸形、异性孪生不孕和生殖道畸形,生殖道畸形包括:子宫角畸形、子宫颈畸形。
二.名词解释(每个2分,10分)1.结核病(是由分枝杆菌引起的家禽、家畜、人以及多种动物的一种慢性传染病。
)2.肉孢子虫病是由肉孢子虫寄生于肌肉中引起的一种人畜共患病,虫体主要寄生在食道肌肉。
3.子宫积水由慢性卡他性子宫内膜炎发展而来,子宫内积有棕黄色、红褐色或灰白色稀薄或粘稠液体。
4.指(趾)间皮炎没有扩延到皮下组织的指(趾)间皮肤的急性或慢性炎症。
华农物化第二学期期末试卷及答案
(2)当c=0.200mol·dm-3时,表面吸附量Γ为: + 准
装 订 线
h
t 准 t
(3) bc ≫
t h遨r h ………………………………………...……………3分
准 ⸲ + 准
t
t tt t t t tt
t
⸲ +
t t
准
t
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t 准
t
t 准
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t h遨r h …………………….…3分 t
线 装 订
3
得分
三、问答题(本大题共3小题,每小题5分,共15分)
1. 在水平放置的玻璃毛细管中分别加入少量的纯水和汞,毛细管中液体两端 的液体分别呈什么形状?如果分别在管外的右端液体处微微加热,管中的 液体将向哪一方移动?在无重力状态下将一根短毛细管接触水滴,会发生 什么现象?
4
2. 已知平行反应A 施?
华南农业大学期末考试试卷(A 卷)
2011 学年第 学号
装 订 线
一 学期 姓名 一 二
考试科目: 考试时间: 年级专业 三 四
物化学 120 分钟
考试类型: (闭卷)考试
题号 得分 评阅人
总分
得分
一、选择题(本大题共12小题,每小题2分,共24分)
( )1.某反应速率常数的量纲为(浓度)-1·(时间)-1,则该反应为: A.一级反应 B.二级反应 C.三级反应 D.零级反应 ( )2.若电池反应Fe + Cu2+ →Cu + Fe2+ 是热力学自发过程,则:
A.反应一定是放热反应 B. Fe电极是正极,Cu电极是负极 C. Fe2+的活度大于Cu2+的活度 D.φ(Cu2+|Cu) >φ(Fe2+|Fe) ( )3.活化能为零的反应是: A. A·+BC→AB+C· C. A2+M→2A·+M
华南农业大学期末考试试卷
华南农业大学期末考试试卷华南农业大学期末考试试卷(A卷)2003学年第二学期考试科目:应用概率统计评卷人:学生姓名:学号:专业年级:成绩:一、填空题(每小题2分,本题共16分)1、设随机变量,则。
(已知标准正态分布函数值:)2、设随机变量服从泊松分布且具有方差2,那么的分布律为。
3、设一维连续型随机变量的概率密度函数为,则随机变量的概率密度函数为。
4、以下是利用MINITAB对变量和的线性相关性作回归分析所得结果,由此判定回归方程是。
The regression equation isy = 0.63 + 0.040 xAnalysis of VarianceSource DF SS MS F PRegression 1 0.178 0.178 0.13 0.725Residual Error 9 12.200 1.356Total 10 12.3785、设总体是它的一个样本,则服从分布。
6、设正态总体的均方差,该总体的一个容量为的样本的样本均值,则总体均值的置信水平为95%的置信区间是。
7、在双因素有交互作用的方差分析中,设因素有3个水平,因素有2个水平,每个处理作两次重复试验,则试验误差平方和的自由度。
8、设关于的线性回归方程为,则。
()二、单项选择题(每小题2分,本题共18分)1、设则。
2、设是相互独立的两个随机变量,则。
3、二维随机变量的分布函数。
4、多个相互独立的服从正态分布的随机变量的线性组合服从。
二项分布泊松分布均匀分布正态分布5、以下哪一个MINITAB命令用于作回归分析。
6、以下哪一个MATLAB命令用于求定积分。
7、设总体,对检验水平,欲检验方差由容量为的一个样本计算出来的统计量的观察值应与作比较。
8、参数的点估计量的无偏性指的是。
9、设是总体的一个样本,则总体方差的矩法估计量是。
三、计算题(每小题8分,本题共56分)1、在次品率为5%的一批产品中任取5件,求其中至少有两件次品的概率。
华南农业大学期末考试试卷A
华南农业大学期末考试试卷A华南农业大学期末考试试卷(A)————————————————————————————————作者:————————————————————————————————日期:华南农业大学期末考试试卷(A卷)2006学年第一学期考试科目:数据库原理与方法考试类型:(闭卷)考试时间:120 分钟学号姓名年级专业2004 题号一二三四五六七总分得分评阅人________________________________________________________________ _____________ Instructions to candidates:1. This paper consists of 7 questions.2. Answer all questions on the answer sheets.3. Hand in the answer sheets, and this paper can be taken away.Question 1: (20 marks) Define the following terms. Each term is worth 2 marks.a. DBMSb. Metadatac. Entity-relationship data modeld. Candidate Keye. DDL and DMLf. ACIDg. Deadlockh. Concurrency schedulei. Timestampj. LogQuestion 2: (21 marks) Consider a factory managementdatabase including the following data objects:●factory: Each factory has a name, a location, and a factory director name. Afactory has workshops and depositories.●workshop: Each workshop has a unique id, a wor kshop director, a locationand a telephone number. Accessories and products are manufactured in theworkshops.●depository:Each depository has a unique id, a depository director and atelephone number. Accessories and products are stored in the depository.●accessory: Each accessory has a unique id, a weight and a price.●product: Each product has a unique id and a price.●worker: Each worker has a unique id, a name, an age, a type of work.Start_date indicates the date of starting to work in a workshop, andemployee_length indicates the length of working in a workshop;The system requirements are:● A factory has more than one workshop and more than one depository.● A workshop has more than one workers and each worker only works forone workshop.● A works hop can make various accessories and products. The number ofaccessories and the number of products manufactured in each workshop isrecorded respectively.● A depositor stores various accessories and products. The number ofaccessories and the number of products stored in each depositor is recordedrespectively.●Each accessory can be manufactured by more than one workshop. Similarly,each product also can be manufactured by more than one workshop.● A product can be made by various accessories and a kind of accessory canbe used to make various products. The number of accessories each productis made by should be recorded.a. Draw an E-R diagram design for this database. [7 marks]b. Represent this database design as a set of relation schemas. Select a primary key for each relation (this can be indicated by underlining the selected attributes) and indicate foreign key for each relation as follows:product_accessory (product_id, accessory_id, accessory_numbers)-- FK product_id reference product-- FK accessory_id reference accessory[14 marks] Question 3(15 marks) Consider a teaching database including student number(S#), course number(C#), grade(G), teacher number(TN), department of teacher(D). The database has the following information:●student number and course number represent student and course respectively.●for each course a student enrolls, he receives a grade.●each course can only be taught by one teacher, but a teacher can teach multiplecourses.●each teacher only can work for one department.a. Define the set of non trivial functional dependencies. [6 marks]b. Suppose all the five attributes form a relation R, indicate in which normal form the relation is.[3 marks]c. Give a lossless, dependency-preserving decomposition in to 3NF of schema R. [6 marks] Question 4 :(12 marks) Consider the following relational schema:Employee (empno, name, office, age)Books (isbn, title, authors, publisher)Loan (empno, isbn, year)Write the following queries in relational algebra. All queries carry equal marks.a. Find the empno of employees who have borrowed a book published by McGraw-Hill.b. Find the name and age of employees who have borrowed a book published by McGraw-Hill.c. Find the name and office of employees who have borrowed a book published by McGraw-Hill since 2000.d. Assume each employee only can borrow one book. Find the empno of employees who have not borrowed a book published by McGraw-Hill.Question 5: (16 marks) Consider the following schema of a sales database: market(mno, street, city)item(ino, iname, color)sales(mno, ino, price)The market relation provides a list of markets with market number(mno), street and city where the market lies. The mno is unique for each market. The item relation provides a list of items with item number(ino), item name(iname) and the color. The ino is unique for each item. The sales relation lists for the price of each item in each market. The key of this relation is mno and ino.Write the following queries in SQL. All queries carry equal marks.a. Find the average price of the item with ino ‘abc2164’which is sold in Guangzhou and color is red.b. Find the mnos of the markets which hold the items ’pc100’ and ‘jk375’.c. Find the inos, inames, and colors of the items which are sold in market ‘rs225’but not in market ’az507’.d. Find the ino, the highest price and the lowest price of each item whose highestprice is greater than its lowest price by 100.Question 6: (8 marks) Let R = (A, B, C), and let r1 and r2 both be relations on schema R, give an expression in SQL that is equivalent to each of the following queries.a. r 1 ∪ r 2b. r 1 ∩ r 2c. r 1 - r 2d. ∏AB (r 1) ∏BC (r 2)Question 7: (8 marks) Figure 1 indicates the log of serial transactions. A is recorded when time is T c and the system failure occurs when time is T f . When the system recovers from the crash, the undo and redo operations should be applied.T cT fcheck point system failureT 1T 2T 3T 4Figure 1: the log of serial transactionsa. Construct the undo-list and redo-list.b. Explain the difference of undo and redo operation.华南农业大学期末考试试卷(A卷-Answer Sheets)2006学年第一学期考试科目:数据库原理与方法考试类型:(闭卷)考试时间:120 分钟学号姓名年级专业2004 题号一二三四五六七总分得分评阅人Question 1:a. DBMSb. Metadatac. Entity-relationship data modeld.Candidate Keye. DDL and DMLf. ACIDg. Deadlockh.Concurrency schedulei. Timestampj. Log。
华南农业大学期末06考试试卷答案
华南农业大学期末考试试卷(A卷)2005学年第二学期考试科目:实验动物疾病学考试类型:闭卷考试时间:120分钟学号姓名年级专业题号一二三四五总分得分评阅人罗满林一、名词解释(每题2分,共 10 分)1.实验动物2.近交系动物3.转基因动物4.悉生动物5.SPF动物二、填空题(每空1分,共30 分)1.3R是指、和。
2.在生物学实验中评价实验动物质量要求的“三性”是指,和3.亚屏障系统,屏障系统和隔离系统的空气洁净度要求分别是:,和级。
4.家兔的常用品种包括,,和。
5.按临诊表现,鼠痘可分为,和 3种病型。
6.普通级实验动物饲养的辅助设施包括,,和。
7.泰泽氏病是由所致,以多发性坏死,出血性坏死为特征。
8.兔球虫病按寄生部位和症状的不同,可分为型、型及型,但临床实际所见多为型。
9.犬性成熟期个月。
妊娠期天,每年发情次三、正误题(每题1分,共5分)1.小鼠:生育期为2年,其产仔胎数6~10胎。
2.家兔的交配方法有三种,即自然交配,人工辅助交配和人工授精法。
3.大鼠自身不能合成维生素C,因此饲料中一定要注意维生素 C的补充。
4.犬嗅觉特别灵敏,但触觉不敏感。
5.疑似仙台病毒感染,可采取小鼠或大鼠的鼻腔、气管分泌物或肺组织悬液,处理后接种8~10日鸡胚尿囊腔的方法,进行病毒分离。
四、简答题(任选4个,每题5分,共20分)1.亚屏障系统如何分区进行管理的?2.选择实验动物应注意的问题有哪些?3.家兔的采食习性有何特点?4.清洁级动物的微生物控制要求有哪些?5.实验动物的饲养环境受哪些理化因素影响?五、问答题(共35分)1.试述兔出血症的临诊症状和病变要点(12分)。
2.如何进行兔腹泻的综合性防治(13分)3.兔螨病和兔皮肤霉菌病治疗方法和药物使用上有何不同(10分)?华南农业大学期末考试试卷(B卷)2005学年第二学期考试科目:实验动物疾病学考试类型:闭卷考试时间:120分钟学号姓名年级专业题号一二三四五总分得分评阅人罗满林一、名词解释(每题2分,共 10 分)1.实验动物学2.杂交群动物3.封闭群动物4.清洁级动物5.无菌动物三、填空题(每空1分,共30 分)1.AEIR分别是指、、和。
华南农业大学期末考试试卷(A卷)(标准答案)
规律:控制不同性状的非等位基因分布在非同源染色体上,在减数分裂形成配子时非同源染 色体之间发生随机组合,因而这些非等位基因可以自由组合。(2.5 分)
3. 测量矮脚鸡和芦花鸡以及它们杂种的体重,得到下列的平均体重和表型方差(见下表), 请计算体重的广义和狭义遗传率。
矮脚鸡 芦花鸡 F1 F2 B1B B2B
华南农业大学期末考试试卷(A 卷)(标准答案)
2007 学年第一学期 考试科目: 遗传学
学号
考试类型:(闭卷) 姓名
考试时间: 120 分钟 年级专业
题号
一
二
三
四
五
总分
得分
评阅人
一、名词解释(每个 2 分,共 20 分) 测交 是指被测验的个体与隐性纯合体间的杂交(1.5 分)。根据测交子代所表现的表型种 类和比例,可以确定被测验个体的基因型(0.5 分)。
度,可确定物种分歧的大致时间。(√)
四、简答题(每题 5 分,共 30 分)
1. 写出下列专业术语的英文名称
(1)等位基因; (2)染色体组; (3)连锁;
allele;
genome;
linkage;
(4)遗传; heredity;
(5)表型 phenotype
2. 分离规律及自由组合规律的遗传实质是什么? 答:分离规律:控制相对性状的一对等位基因位于同源染色体上,在减数分裂形成配子时两 条同源染色体被分配到不同的细胞中,其上的等位基因也随之发生分离。(2.5 分)自由组合
平均(斤) 方差
1.4
0.1
6.6
0.5
3.4
0.3
3.6
1.2
2.5
0.8
4.8
1.0
华南农业大学期末考试试卷1
华南农业大学期末考试试卷( A 卷)一、填空题(20分,每空0.5 分)1、一种植物的完整的拉丁学名是由属名、种加词和命名人三部分组成。
2、苏铁科中着生胚珠的地方称大孢子叶;银杏科中着生胚珠的地方称珠座;松科(杉科)中着生胚珠的地方称珠鳞。
3、在竹亚科我们学过的属中,每节二分枝的属有刚竹属(毛竹属);地下茎为单轴型的有刚竹属(毛竹属);粉单竹的地下茎类型是合轴型(合轴丛生)。
4、在我们学过的植物中,台湾相思等的叶退化为叶状柄;木麻黄等的叶退化为齿状轮生,且花为裸花。
5、油杉是松科植物;水松是杉科植物;竹柏是罗汉松科植物。
6、竹亚科植物的竹箨是由箨叶、箨鞘、箨耳和箨舌四部分组成。
7、树木学是研究树木的分类、生物学和生态学特性、地理分布及经济利用一门学科。
8、白兰、壳菜果(米老排)、高山榕这3种植物在枝条上有一个非常明显的共同特征,这个特征是有托叶环痕。
9、请把下列拉丁名翻译成中名:(1)松属Pinus (2)桉属Eucalyptus (3)羊蹄甲属Bauhinia(4)榕属Ficus (5)荔枝属Litch (6)王棕属Roystonea(7)含笑属Michelia (8)乌桕属Sapium10、请把下列拉丁名翻译成中名:(1)Cycas 苏铁属(2)Cinnamomum 樟属(3)Camellia (山)茶属(4)Castanopsis 锥(栲属)(5)Citrus 柑桔属(6)Cunninghamia 杉木属(7)Cupressus 柏木属(8)Caryota 鱼尾葵属11、在广东林业中常用的速生用材树种有杉木、尾叶桉等,经济林树种有油茶和板栗等。
3 二、选择题(20 分,每个选择1分)1、(山)茶属的果实类型是(B )。
A、浆果B、蒴果C、核果D、坚果2、广州市的市花是( B )。
A、木芙蓉B、木棉C、牡丹 D 、银杏3、下列植物中,花瓣顶端撕裂的是(B )。
A、白兰B、尖叶杜英C、油茶D、木棉4、下列特征中,为大戟科植物普遍具有的特征是(B )。
华南农业大学期末考试试卷( A 卷)
答案:(1)分子遗传知识应用,标记辅助选择等;(2)数量遗传学知识应用,参考遗传力进行表型选择、综合选择指数等;(3)群体遗传学知识应用,亲缘关系分析、品种分类及选配等;(4)非孟德尔遗传应用,印迹、核外遗传等;(5)遗传学技术应用:生物反应器、动物克隆、转基因的应用等。
PAGE 3
2、阐述并比较原核生物和真核生物基因表达调控的过程。
答案:
(1)原核生物和真核生物基因表达调控的共同点:
a 结构基因均有调控序列;
b 表达过程都具有复杂性,表现为多环节;
c 表达的时空性,表现为不同发育阶段和不同组织器官上的表达的复杂性;
(2)与原核生物比较,真核生物基因表达调控具有自己的特点:
3. 动物体内的淋巴细胞有B、T两种,其中细胞免疫依赖 T 淋巴细胞介导,而体液免疫依赖 B 淋巴细胞发挥作用。
4.染色体数量具有物种特异性,如人的染色体有23对,猪的染色体有19对,鸡的染色体有39对。
5. 染色体结构变异包括 缺失 、 重复 、 倒位 和 易位 四种类型。
(三)、选择题(每题2分,共14分)
1.形成三色猫的遗传机制为(B)
A.母体效应 B.剂量补偿效应 C.基因组印迹 D.核外遗传
2.人的全基因组大小约为(C)
A.1.0×106 B. 1.0×109 C. 3.0×106 D. 3.0×109
3.以下有关遗传力的描叙错误的是(D)
C. Southern杂交 D.原位杂交
(四)、简答题(每题5分,共10分)
1.说明杂种优势的含义及做出简单解释。
答案:(1)两个亲本杂交,子一代个体的某一数量性状并不等于两个亲本的平均,而是高于亲本的平均,甚至超出亲本范围,比两个亲本都高,叫做杂种优势。表现在生活力,繁殖力,抗逆性以及产量和品质上;(2)杂种优势的形成机制有三种假说:A.生活力假说,杂种在生活力上要优于两亲本;B.显性假说,杂合态中,隐性有害基因被显性有利基因的效应所掩盖,杂种显示出优势;C.超显性假说:基因处于杂合态时比两个纯合态都好。
华南农业大学期末考试答案(A卷).doc
考试科目:计算机科学技术导论考试类型:(闭卷)考试时间:120分钟2005学年第一学期华南农业大学期末考试答案(A 卷)班级 _______________ 学号 _____________ 姓名 _______________题号二三五总分得分评阅人•、单项选择题(每小题2分,共30分)1 D2 D 3A 4C5B 6C 7B 8C 9A10D 11C12A13B14C15D二、判断题(对的打“ 丁”,错的打“X”,每小题1分,共10分) 1 X 2 X 3 J4 V5 X 6V 7 X 8 V 9 7 10X三、专业术语翻译(请给出下列专业术语的中文名称,每个1分,共15 分) 1 随机存彳诸器(Random Access Memory) 2 屮央处理器(Central Processing Unit)3基木输入输出系统(Basic I 叩ut Output System) 4 操作系统(Operate System)5 结构化杳询语 ^(Structured Query Language)6 软件能力成熟度模型(Capability Maturity Model for software)7 统一建模语言(Unified Model Language)8 数据库管理系统(Database Management System)9 联合图像专家组(Joint Picture Experts Group) 10 虚拟现实(Virtual Reality)11传输控制协议/网络协议(Transmission Control Protocol/ Internet Protocol)12域名系统(Domain Name System)13远稈登陆服务14计算机辅助设计(Computer-Aided Design)15局域网(Local Area Network)评分细则:写对一个给1分,屮英文均可s简篆题C得题5分,*351答:1)计算机是由运算器、控制器、存储器、输入设备和输出设备5大部分组成。
(完整版)作物育种学总论期末试卷及答案
华南农业大学期末考试试卷(A卷)201*-201*学年第二学期考试科目:植物育种学考试类型:(闭卷)考试考试时间:120分钟学号姓名年级专业10级农生、农信、农贸一、填空题(本大题共30空,每空0.5分,共15分)1、自然异交率≤4%是典型的自花授粉作物,自然异交率在50%~100%之间的是典型的作物,自然异交率介于两者之间的是作物。
2、现代化农业对作物品种的要求是、、、适应机械化。
3、下列作物的品种间杂交第一代是否分离?(在空白处注明是或否)小麦;甘薯;玉米。
4、根据瓦维洛夫的学说,作物起源中心有两个主要特征,即基因的多样性和显性基因的频率较高,所以又可名为基因中心和中心。
5、杂交育种中,单交组合代分离最大,复交组合代分离最大。
6、〔(甲×乙)×甲〕×甲的杂交式中,甲为亲本,乙为亲本。
7、诱变育种的作用主要表现在两方面,育成大量和提供大量。
8、诱变育种的M1代应采取方法控制分蘖,只收获上的种子。
9、远缘杂交主要有两方面的障碍:和。
10、同源多倍体无论植株、器官还是细胞的最大特征是。
11、遗传的雄性不育分为:和两种类型。
12、环境胁迫可分为:、和三大类。
13、作(植)物抗病性机制有:、、和等。
14、根据雄性不育的花粉败育特征,可以将花粉败育分为:无花粉型、、圆败和染败等四种类型。
二、单项选择题(本大题共10小题,每小题1分,共10分)1、作物育种的基本目的是培育符合()的新品种。
A.自然条件B.生产条件C.经济条件D.人类需要2、种质资源就是指作物的()。
A.所有品种B.地方品种C.新品种D.一切基因资源3、水稻品种南种北引时,以()易于成功。
A.早熟品种B.晚熟品种C.高产品种D.所有品种4、自花授粉作物纯系会产生遗传的变异的原因有()。
A.自交分离B.基因杂合性C.基因型纯合化D.天然杂交和基因突变5、杂交育种后代的选育方法中,集团混合选择法是在()。
A.早代不选,F4-F8代才开始选株建系B.分离世代每株只留一粒种子混合播种,F4-F8代才选取株建系C.在第一分离世代开始按成熟期,株高等相近类型归类,混收混播,至F4-F8代才选株建系D.分离世代选优株混收混播,F4-F8代才选取株建系6、在花粉培养中,所培养的外植体的染色体数目是()。
华南农业大学期末考试试卷A卷及练习参考答案管理学基础课件
华南农业大学期末考试试卷(A卷)2008学年第一学期考试科目:管理学基础考试类型:(闭卷)考试时间:120 分钟学号姓名年级专业[Pay attention: please write your answers in the answer sheet][注意:请把答案填写在答题纸上]I.True/False(1 point per statement, total 10 points)1.The four processes of management are completely independent and should be treated as separate activities. 2.Scientific management theorists believed there was "one best way" for a job to be done.3.Development of alternatives is the step between identification of decision criteria and allocation of weights to criteria.4.Individuals who prefer the team role of explorer-promoter are patient and usually have the control skills to ensure that the ideas are followed through in detail.5.If an individual is low in the authority hierarchy, he/she is also not close to the power core.6.Mintzberg found that managers—regardless of the type of organization or the level in the organization—perform similar roles.7.The norming stage of team development is one of intragroup conflict.8.In order to fulfill the grand strategy, managers will seek to position their units so that they can gain a relative advantage over their competition.9.According to Herzberg, working conditions and salary are examples of hygiene factors.10.The method of monitoring, comparing and correcting is what we called controlling process.II.Choose the only one correct answer for each question (2 point per question, total 40 points)1. Which of the following is not one of the six elements of structure?a) work specializationb) chain of commandc) span of controld) technology2. If a college cuts the cost by using mostly part-time teachers and at the same time fails to adequately educate its students, it can be said to be doing the wrong things well. In other words, the college is_____:a) efficient and effectiveb) efficient but not effectivec) effective but not efficientd) neither efficient nor effective3. _____ is the term used to describe the hypotheses of the scientific management theorists and the general administrative theorists.a)Contingency approachb)Human resourcesc)Human relationsd)Classical approach4. Michael Porter proposed that management must select a(n) _____ ,which will give its unit a distinct advantage by capitalizing on the strengths of the organization and the industry it is in.a)growth opportunityb)competitive strategyc)organizational chartd)vision5. An office supply firm that has three departments based upon retail, wholesale, and governmental customers is using which of the following types of departmentalization?a) functionalb) productc) customerd) geographic6. Mary Parker Follet was a social philosopher who taught that organizations should be based on _____ rather than _____.a)individualism; group ethicb)ethics; profitsc)efficiency; profitsd)group ethic; individualism7. Which of the following is not a result of work that has become too specialized?a)fatigueb)low productivityc)poor qualityd)lower turnover8. Creative College is opening a satellite(卫星)campus to accommodate working adults. Creative College is pursuing a(n) _____ strategy.a)acquisitionb)retrenchmentc)growthd)combination9. The management theory jungle was developed by_____.a)Maslowb)Herzbergc)Ouchid)Koontz10. Jim has the ability to "dock"(扣去) paychecks of employees who arrive at work past 9:05 AM. What kind of power does Jim possess?a)coercive powerb)legitimate powerc)expert powerd)referent power11. Linda has spent the day trying to determine what the role of their company. Goals were then developed based on their vision of the company's mission. Linda spent her day on the _____ process.a) planningb) organizingc) leadingd) controlling12. Which of the following is a hidden aspect of organizational behavior?a)strategiesb)technologyc)group normsd)formal authority13. Deborah's work team does its own hiring and scheduling and is even responsible for evaluating each other's performance. Deborah is part of a _____ team.a)self-managedb)virtualc)problem-solvingd)cross-functional14. Harry's Company apparently has overgrown its market. It can no longer compete successfully due to its size and formalization. Thus it is reducing its size in order to once again become competitive. This is known as which of the following strategies?a)growthb)stabilityc)retrenchmentd)combination15. Who developed Theory X and Theory Y?a)McGregorb)Maslowc)McClellandd)Herzberg16. Jill has been teaching for 18 years. Each day she arrives at work smiling and ready to teach another room full of students. She loves her job. This describes which of the following?a)job satisfactionb)job involvementc)organizational developmentd)organizational commitment17. When we describe people in terms such as quiet, introvert, aggressive or loyal, we are addressing _____.a)attitudesb)behaviorsc)needs and wantsd)personality traits18. A structure that is high in specialization, formalization, and centralization is a(n) _____.a)strategic organizationb)mechanistic organizationc)organic organizationd)matrix organization19. The managers who work most closely with the operatives are known as_____.a)top managementb)middle managementc)first-line managersd)operative managers20. Maslow's hierarchy of needs proposes that an individual begins by satisfying _____ needs.a)self-actualizationb)esteemc)physiologicald)safetyⅢNotion explanation. (4 points each notion, total 20 points)1.MBO2.Hawthorne effect3.Boundaryless organization4.Social loafing5.BenchmarkingIV Medium-length answer. (10 points each question, total 20 points)1.What are differences between functional and divisional structures? Give an example for these two types ofbureaucratic structure.2.What are Mintzberg’s managerial roles? Cite examples of activities managers you know would do whenperforming these roles.V Reading comprehension. (Choose the only one correct answer for each question. 2 point per question, total 10 points)Nike is the number one sports brand in the World. The market for sports shoes and garments(服装) is very competitive. Phil Knight (Founder and CEO) is often quoted as saying that ‘Business is war without b ullets.’The war is especially intense(激烈) in today’s economic declination. Over the past years, Nike has gained its success partly from the competency at research and development, as is evidenced by its evolving and innovative product range. However, the income of the business is still heavily dependent upon its share of the footwear market. Nike has no factories. It does not tie up cash in buildings and manufacturing workers. They then manufacture wherever they can produce high quality product at the lowest possible price. Interestingly, consumers that wear Nike product do not always buy it to participate in sport. Some would argue that in youth culture especially, Nike is a fashion(时尚) brand. Nike actively sponsors(赞助) activities such as the World Cup (soccer) and The Olympics to gain reputation in emerging markets such as China.1. Nike heavily depends upon the footwear market to make profit would be classified as which of the following?a) weaknessb) strengthc) threatd) opportunity2. The fact that the market for sports shoes and garments is very competitive would be which of the following?a) weaknessb) strengthc) threatd) opportunity3. Nike continues to bring evolving and innovative product range would be classified as which of the following?a) weaknessb) strengthc) threatd) opportunity4. Nike is a fashion brand among youngsters would be classified as which of the following?a) weaknessb) strengthc) threatd) opportunity5. The economic declination is a_____ factor for Nike.a) positiveb) neutralc) negatived) normal华南农业大学期末考试答题纸(A卷)2008学年第一学期考试科目:管理学基础考试类型:(闭卷)考试时间:120 分钟学号姓名年级专业II.Choose the only one correct answer for each question (2 points each question, total 40 points). Notion explanation. (4 points each notion, total 20 points)6.MBOManagement by objectives (2 points)Four elements: jointly determined objectives; explicit time period; specific objectives; periodically review (0.5 each)7.Hawthorne effectSocial norms or standards are the key determinants of individual behavior in a group. (4 points)8.Boundaryless organizationAn organization that is not defined or limited by boundaries or categories imposed by traditional structures; attempt to eliminate vertical, horizontal, and inter-organizational barriers. (4 points)9.Social loafingThe tendency of an individual in a group to decrease his or her effort because responsibility and individual achievement cannot be measured. (4 points)10.BenchmarkingSearching for best practices among competitors and noncompetitors. (4 points)IV Medium-length answer. (10 points each question, total 20 points)3.What are differences between functional and divisional structures? Give an example for these two types ofbureaucratic structure.Functional structure refers to an organization in which similar and related occupational specialties are grouped together. (1 point)The strength lies in the advantages that accrue from work specialization. Results in economies of scale, minimizes duplication, satisfy employees etc. (2 points)but people tend to lose sight of the best interests of the organization as a whole; no one function is totally responsible for the results. (2 points)A company divides its department into accounting, hr, producing, marketing employed the functional structure. (2 point)Divisional structure is made up of self-contained units. (1 point)It focuses on results, frees the headquarters staff from being concerned with operating details; but the major disadvantage lies in the duplication of activities and resources. (2 points)Companies like GE and PepsiCo have the divisional structure. (1 point)4.What are Mintzberg’s managerial roles? Cite examples of activities managers you know would do whenperforming these roles.Interpersonal—roles consist of being the figurehead for the organization, assuming the leadership role, and acting as a liaison for the organization. Examples (3 points)Informational—roles consist of being a monitor of current information which is then dispersed to employees needing that information; also involves being the spokesperson for the organization. Examples (3 points) Decisional—roles consist of being an entrepreneur for the organization, handling disturbances, allocating resources, and negotiating. Examples (4 points)V Reading comprehension. (Choose the only one correct answer for each question. 2 point per question,1. FTFFT FTTTTddcdc dbbcbH.FTTTF FTFTTAcbabcd3. FTFTF TFFFTccbcc dcbdc aadbc dacacdba5.TTFFF TFFTTDABDC CACAD C1.What is the difference between line authority and staff authority?Line authority entitles a manager to direct the work of an employee. Staff authority functions to support, assist, advise, and generally reduce some of the informational burdens of those with line authority.pare and contrast authority and power.●Authority comes from the position, not the person.●Power is the ability of an individual to influence decisions, which may not be reflected in their levelof authority. French and Raven suggested five bases of power: reward, coercive, legitimate, referent, and expert.●Authority is a two dimensional concept while the power is a three-dimensional one. One shouldmove up in the hierarchy to gain higher authority, but in order to be more powerful, managers could move up or move inward to have closer relationship with those people representing the power core.3.set an example to clarify each of five types of departmentalization that are available. Departmentalization types examples (departments in certain organization)Functional marketing, HR, R&D, financing etc.Product food, clothes, home appliances, etc.Customer personal clients, government, VIP etc.Geographic Great China, North America, EUProcess validation, registration, payment, etc.4.What is a matrix structure? What is its primary strength? What are its major disadvantages?●Matrix structure—an organization in which specialists from functional departments are assigned towork on one or more projects led by a project manager.●Primary strength—can facilitate coordination of a multiple set of complex and interdependentprojects, while still retaining the economies that result from keeping functional specialists groupedtogether.●Major disadvantages—creates confusion and has a propensity to sponsor power struggles.pare functional and divisional structure.Both are bureaucratic design of organizations.●Functional structure groups similar or related occupational specialties together. While divisionalstructure is self-contained, composed of autonomous units or divisions, with managers having fully responsibility for a product or service.●Advantages of functional structure accrue from work specialization. 1. putting like specialtiestogether results in economies of scale, minimizes duplication of personnel and equipment; 2. itmakes employees comfortable and satisfied since they have same interests.Chief advantage of divisional structure is that it focuses on results, also it frees the headquarters staff from operating details so that they can focus on long-term strategic planning.●Weaknesses of functional structure: organizational interests might be lost in pursuit of functionalgoals; no one function is totally responsible for results; members become insulated and have littleunderstanding about peers in other functions.The major disadvantage of divisional structure is the duplication of activities and resources.。
华南农业大学期末考试试卷(A卷)
华南农业大学期末考试试卷(A卷) (答案)2005学年第2学期考试科目:无土栽培原理与技术/Principles and Techniques of Hydroponics 考试类型:(第一部分开卷,第二部分闭卷) 考试时间: 120 分钟第一部分:一、名词解释(每题3分,共9分):1. Soilless Culture / HydroponicsSoilless culture/ hydroponics is the planting method with nutrient solution other than natural soil, to provide nutrients, water and oxygen.2. Stock of Nutrient Solution FormulaThe concentration of nutrient solution is made up according to the stipulated amount of the formulation.3. Mixed MediumMixed medium is the medium mixed with two or more than two media according to the proportion.二、填空(每题2分,共12分):1. The theoretical basis of soilless culture is the theory of mineral nutrition . The key content of this theory is mineral is the major sources of plant nutrition .2. There are 17 essential nutrient elements for plant growth. A nutrient solution usually contains 12/13 essential elements, they are N, P, K, Ca, Mg, S, Fe, Mn, Zn, Cu, B, Mo, Cl .3. Functions of solid media are fixing and Supporting plants , water retention , aeration and buffering effect .4. Management of nutrient solution usually includes the control of concentration ,pH , DO and temperature of the nutrient solution.5. The Electric Conductivity of nutrient solution is usual less than 4~5 mS/cm , otherwise plants will suffer from salinity stress .6. Mini hydroponics units can be used in family , school ,hotel , etc.三、选择题(将唯一正确答案的编号填入括号中,每空1分,共10分):1. The yield of lettuce in hydroponics is about ( B ) (A. 300~400Kg; B. 3 000~4 000Kg; C. 30 000~40 000Kg) per 0.067 ha (1 mu) per crop. Soilless culture system itself ( B ) (A. has; B. hasn’t) the function to plant vegetables contrary to the seasons.2. The major nitrogen source of most nutrient solutions is ( A ) (A. NO3--N;B. NH4+-N;C. NH2-N). Because they are ( B ) (A. physiologically acid salts;B. physiologically alkaline salts;C. organic salts). When they are absorbed by plants, the pH value of the nutrient solution will ( B )(A. decrease; B. increase).3. The cation exchange capacity (CEC) of ( B ) (A. rockwool; B. peat;C. sand;D. gravel) is highest (among the four media). This medium belongs to ( A ) (A. active medium; B. inactive medium; C. mixed medium).4. The circulatory system of nutrient solution in hydroponics usually use( D )(A. iron tube; B. aluminium tube; C. copper tube; D. plastic tube).5. ( A ) (A. Methyl alcohol; B. Potassium permanganate; C. Calcium hypochlorite) can be used to sterilized organic media, such as ( C ) (A. foamed plastics; B. rockwool; C. coconut husk; D. pearlite).四、问答题(每题10分,共20分):1. Please discuss the advantages and disadvantages of Deep Flow Technique (DFT).2. What are the principles for composition of nutrient formulation?Answer:1. The advantages of Deep Flow Technique (DFT) are:(1) Total capacity of the solution is large, and the constitute and concentration are stable.(2) The air problem can be dissolved with the roots suspending above the solution and the solution flows frequently.(3) The culture equipment can be built easily and can be used for a long time.(4) Many kinds of plants can be grew well in DFT.(5) The utilization ratio of nutrient solution is about 90%~95%.The disadvantages of Deep Flow Technique (DFT) are:(1) Some diseases can spread rapidly through the system.(2) Initial capital cost is higher.(3) Demands high-level technology of management.2. The principles for composition of nutrient formulation are:1)Nutrient solution must contain all essential nutrient elements.2)All of the compounds must be in the form that can be absorbed by plant roots.3)Amount and ratio of the compounds should be in accordance with the demandsof plant growth.4)Total concentration and pH value of the compounds should meet the demandsfor plant growth.5)The compounds must keep up the efficiency for a long time during the period ofplant growth.6)The change in pH value caused by the absorption of major compounds by plantsshould be minimum and the physiological acidity should be kept stable.第二部分:一、名词解释(每题3分,共9分):1. 表观吸收成分组成浓度/ Apparent absorption constitute concentration表观吸收成分组成浓度(n/w)是植物对各种养分的吸收量(n, mmol)和吸收消耗的水量(w, L)的比值,单位为mmol/L。
华南农业大学期末考试-试卷( A 卷)
华南农业大学期末考试试卷( A 卷)2006学年第二学期考试科目:计算机网络(选修)考试时间:120 分钟学号姓名年级专业一、选择题(1分* 30 = 30分)1、一座大楼内的一个计算机网络系统,属于()A、VPNB、LANC、MAND、W AN2、不同的交换方式具有不同的性能。
如果要求数据在网络中的传输延时最小,应选用的交换方式是。
A、线路交换B、报文交换C、分组交换D、信元交换3、通信系统必须具备的三个基本要素是()A、终端、电缆、计算机B、信号发生器、通信线路、信号接收设备C、信源、通信媒体、信宿D、终端、通信设施、接收设备4、OSI/RM 的三个主要概念是。
A、体系结构、模型、交换B、子网、分层、元语C、服务、接口、协议D、W AN、MAN、LAN5、随着电信和信息技术的发展,国际上出现了所谓“三网融合”的趋势,下列不属于三网之一的是( )。
A、传统电信网B、算机网(主要指互联网)C、有线电视网D、卫星通信网6、以下哪一个选项按顺序包括了OSI模型的各个层次A、物理层,数据链路层,网络层,传输层,会话层,表示层和应用层B、物理层,数据链路层,网络层,传输层,系统层,表示层和应用层C、物理层,数据链路层,网络层,转换层,会话后,表示层和应用层D、表示层,数据链路层,网络层,传输层,会话层,物理层和应用层7、在三种CSMA中,具有“一旦侦听到传输介质空闲就发送数据,如果侦听到传输介质忙,继续监听,直到侦听到传输介质空闲后立即发送数据;如果发现冲突就退避,然后再尝试”的特征。
A、1—坚持CSMAB、非坚持CSMAC、0—坚持CSMAD、P—坚持CSMA8、在TCP/IP网络中,IP协议提供主机之间的分组传输服务。
A、可靠的面向连接的B、不可靠的面向连接的C、可靠的无连接的D、不可靠的无连接的9、计算机网络中可共享的资源主要有。
A、数据B、硬件C、软件D、上述所有10、什么是R S - 2 3 2 ?A、一个标准的串行接口B、一个高速的串行接口C、一个ISDN接口D、一个ATM交换机11、采用串行线路连接到网络时,如果希望能够支持动态分配IP地址,那么数据链路协议应该采用( )协议。
华南农业大学期末考试试卷(A经济学专用)(DOC)
华南农业大学期末考试试卷(A 卷)答题纸2012-2013学年第 1学期 考试科目: 经济计量学 考试类型:(闭卷)考试 考试时间: 120 分钟学号 姓名 年级专业一、单选题(本大题共20小题,每小题1分,共20分)【答题要求:请将该大题的答案依次抄写在下列指定空格处】1.变量显著性检验t 统计量的表达式是( )。
2.在双对数线性模型lnY i =ln β0+β1lnX i +u i 中,β1的含义是( ) A .Y 关于X 的增长量 B .Y 关于X 的发展速度 C .Y 关于X 的边际倾向 D .Y 关于X 的弹性3.在二元线性回归模型:i i 22i 110i u XX Y +β+β+β=中,1β表示( ) A .当X 2不变、X 1变动一个单位时,Y 的平均变动 B .当X 1不变、X 2变动一个单位时,Y 的平均变动 C .当X 1和X 2都保持不变时, Y 的平均变动 D .当X 1和X 2都变动一个单位时, Y 的平均变动4.关于多元线性回归模型的F 检验与t 检验的关系,描述正确的是( )。
A.关于变量的显著性t 检验全部通过时,模型总体显著的F 检验一定通过。
B.关于模型总体显著的F 检验通过时,变量的显著性t 检验一定全部通过。
)var(.11..ˆ.ˆˆˆˆ2222bb b ye e y s b b jj jii i ijjt D k n n t C t B b t A j-=---∙==-=∑∑∑∑C. F检验与t检验是等价的。
D.F检验与t检验没有任何关系。
5.DW检验法适用于检验()A.异方差B.序列相关C.多重共线性D.设定误差6.如果X为随机解释变量,Xi 与随机误差项ui相关,即有Cov(Xi,ui)≠0,则普通最小二乘估计 ˆ是()A.有偏的、一致的B.有偏的、非一致的C.无偏的、一致的D.无偏的、非一致的7.设某商品需求模型为Yt =β+β1Xt+ ut,其中Y是商品的需求量,X是商品价格,为了考虑全年4个季节变动的影响,假设模型中引入了4个虚拟变量,则会产生的问题为()A.异方差性B.序列相关C.不完全的多重共线性D.完全的多重共线性8.当截距和斜率同时变动模型Yi =α+α1D+β1Xi+β2(DXi)+ui退化为截距变动模型时,能通过统计检验的是()A.α1≠0,β2≠0 B.α1=0,β2=0C.α1≠0,β2=0 D.α1=0,β2≠09.若随着解释变量的变动,被解释变量的变动存在两个转折点,即有三种变动模式,则在分段线性回归模型中应引入虚拟变量的个数为()A.1个B.2个C.3个D.4个10.对于无限分布滞后模型Yt =α+βXt+β1Xt-1+β2Xt-2+…+ut,无法用最小二乘法估计其参数是因为()A.参数有无限多个B.没有足够的自由度C.存在严重的多重共线性D.存在序列相关11.对自回归模型进行自相关检验时,若直接使用DW检验,则DW值趋于()A .0B .1C .2D .412.当某商品的价格下降时,如果其需求量的增加幅度稍大于价格的下降幅度,则该商品的需求( ) A .缺乏弹性 B .富有弹性 C .完全无弹性 D .完全有弹性13.根据实际样本资料建立的回归模型是( ) A .理论模型 B .回归模型 C .样本回归模型 D .实际模型14.双对数模型Y=A e rt K a L ß u 中,Y 、K 和L 分别表示产出、资本和劳动投入,则参数a 的经济含义是( )A .Y 关于K 的增长率 B. Y 关于K 的发展速度 C. 资本产出弹性 D. 资本产出乘数15回归分析中使用的距离是点到直线的垂直坐标距离。
华南农业大学期末考试试卷(A卷)
华南农业大学期末考试试卷(A卷)2005学年第一学期考试科目:管理信息系统考试类型:闭卷考试时间:120分钟学号姓名年级专业一、选择题。
给下列每题空格处的4个备选答案中选出1个正确答案,将答案的正确号码填在题后的空格内。
(每题1分,共20分)1.管理信息系统是一些功能子系统的联合。
每个子系统包含四个信息处理单元,它为四个不同管理层次服务。
按区域,按产品,按顾客的销售数量进行定期分析等,是属于。
A.业务处理 B.运行控制 C.管理控制 D.战略计划2.制造资源计划(MRPII)理论相对于闭环物料需求计划理论解决了问题A. 物料的相对需求B. 能力需求计划C.资金流及成本核算D. 整个供应链资源配置3.下列哪些特性描述不属于JIT(准时制生产)方式特点。
A. 致力于追求零库存B. 严格执行预定生产计划C. 充分发挥工人主观能动性D.强调供应链合作与优化4.在数据库的规范化理论中,第三范式意味着,关系中消除了所有非主属性对主属性的。
A. 传递依赖B. 局部依赖C. 不完全依赖D. 有条件依赖5.下列特性不属于浏览器/服务器(B/S)计算模式相对于客户机/服务器计算模式的优点。
A. 系统升级维护更加方便B. 系统可移植性好C. 系统安全性更好D. 降低了客户端硬件性能要求6.诺兰模型描述了。
A. 企业成长过程中信息系统建设规律B. 企业过程与数据类之间的“产生”和“利用”关系C. 系统分析过程中建立的逻辑模型D. 系统设计过程中建立的物理模型7.不是原型法开发系统过程特点的是A. 循环往复的反馈B. 开发周期短C. 能较好满足需求D. 整体性强8.软件项目的进度管理有许多方法,不仅能表达子任务的依赖关系,还可以找出关键任务。
A. 关键时间表B. 甘特图C. 网络图D. 时标网状图9.面向对象的基本思想是通过建立和客观实际相对应的对象,并通过这些对象的组合来创建具体应用。
对象是。
A. 数据结构的封装体B. 数据以及在其上操作的封装体C. 程序功能模块的封装体D. 一组有关事件的封装体10. 发展CASE的目的是提高。
华南农业大学期末考试试卷
华南农业大学期末考试试卷-----------------------作者:-----------------------日期:华南农业大学期末考试试卷(A 卷)一、 填空题(每题2分,10题共20分)1. 通常取晶闸管的断态重复峰值电压 UDRM 和反向重复峰值电压 URRM 中 较小的标值作为该器件的额定电压。
选用时,额定电压要留有一点裕量,一般取额定电压为正常工作时的晶闸管所承受峰值电压的2~3倍。
2. 晶闸管额定电流为100A ,通过半波交流电时,电流的波形系数为K f =1.57,电流的有效值计算为/2m I ,则通过电流最大值m I 为 314 A 。
3. 单相全波可控整流电路中,晶闸管承受的最大反向电压为 1.41 U 2 。
三相半波可控整流电路中,晶闸管承受的最大反向电压为 2.45U 2 。
(电源相电压为U 2)4. 要使三相全控桥式整流电路正常工作,对晶闸管触发方法有两种,一是用 宽脉冲 触发;二是用 双窄脉冲 触发。
5. 单相交流调压电阻性负载电路的移相范围在 0度~ 180度 内,在阻感性负载时移相范围在 功率因素角 ~ 180度 内。
6. 交流调压电路和交流调功电路异同点: 电路结构相同,控制方式不同,(交流调压电路采用移相触发对一个周期内导通角控制,调功电路对导通周波数与阻断周波数的比值进行控制) 。
7. 电压型逆变电路中的反馈二极管的作用是 给交流侧向直流侧反馈的无功能量提供通道 。
8. 变流电路的换流方式有 器件换流 、 电网换流 、 负载换流 、 强迫换流 等四种。
9. 180°导电型三相桥式逆变电路,晶闸管换相是在 同一相上下两个桥臂 元件之间进行;而120º导电型三相桥式逆变电路,晶闸管换相是在 上桥臂或者下桥臂组内 上的元件之间进行的。
10. PWM 逆变电路的控制方法有 计算法 、调制法和 规则采样法 三种。
其中调制法又可分为 同步调制法 、 异步调制法 两种。
(完整版)《社会统计学》样题附答案
华南农业大学期末考试试卷(A卷)学年第学期考试科目:社会统计学考试类型:(开卷)考试时间:120 分钟一、单项选择题(请将正确选项的序号填在答题纸相应的位置。
)1.社会统计中的变量一般分四个层次,其中最高层次的变量是。
A、定类变量B、定序变量C、定距变量D、定比变量2.标准正态分布的均值一定。
A、等于1B、等于-1C、等于0D、不等于03.计算中位值时,对于未分组资料,先把原始资料按大小顺序排列成数列,然后用公式确定中位值所在位置。
A、n/2B、(n-1)/2C、(n+2)/2D、(n+1)/24.下列统计指标中,对极端值的变化最不敏感的是。
A、众值B、中位值C、四分位差D、均值5.如果原假设是总体参数不小于某一数值,即大于和等于某一数值,应采用的检验是。
A、两端检验B、右端检验C、左端检验D、无法判断6.在一个右偏的分布中,大于均值的数据个数将。
A、不到一半B、等于一半C、超过一半D、视情况而定7.下列关于“回归分析和相关分析的关系”的说法中不正确的是。
A、回归分析可用于估计和预测B、相关分析是研究变量之间的相互依存关系的密切程度C、相关分析不需区分自变量和因变量D、回归分析是相关分析的基础8.假定男性总是与比自己年轻3岁的女性结婚,那么夫妻年龄之间的积距相关系数r为。
A、-1 < r< 0B、0 < r< 1C、r = 1D、r = -19.“4、6、8、10、12、26”这组数据的集中趋势宜用测量。
A、众值B、中位值C、均值D、平均差10.某校期末考试,全校语文平均成绩为80分,标准差为4.5分,数学平均成绩为87分,标准差为9.5分。
某学生语文得了83分,数学得了92分,从相对名次的角度看,该生的成绩考得更好。
A、数学B、语文C、两门课程一样D、无法判断二、多项选择题(多选、错选均不得分,漏选得部分分。
请将正确选项的序号填在答题纸相应的位置。
)1.下列变量中属于定类层次的是。
华南农业大学期末考试试卷(A)答案(
华南农业大学期末考试试卷(A)答案(12 2 21 2 22 1 A ⎛⎫ ⎪= ⎪ ⎪⎝⎭, (2分) 因为特征多项式为2(1)(5)I A λλλ-==+-,所以特征值是1-(二重)和5. (4分)把特征值1λ=-代入齐次线性方程组()0I A X λ-=得应于特征值1λ=-的特征向量为12(1,0,1),(0,1,1)T T αα=-=-. 将12,αα正交化:11(1,0,1)T βα==-,211(,1,)22Tβ=--,再将12,ββ单位化得1Tη=,2(T η=, (8分)把特征值5λ=代入齐次线性方程组()0I A X λ-=得对应于特征值5λ=的特征向量为3(1,1,1)Tα=.再将3α单位化得3Tη=. (10分) 令123(,,)0P ηηη⎛⎫ ⎪ ⎪ ⎪== ⎪ ⎪ ⎪ ⎪ ⎪⎝⎭则P 是一个正交矩阵,且满足第6页共3页1100010005T P AP P AP --⎛⎫ ⎪==- ⎪ ⎪⎝⎭.所以,正交变换X PY =为所求,它把二次型化成标准形222123123(,,)5f x x x y y y =--+.(12分)六﹑证明:必要性由123,,l l l 交于一点得方程组 230230230ax by c bx cy a cx ay b ++=⎧⎪++=⎨⎪++=⎩有解,可知 231()()230()10231a b c b c R A R A bc a a b c c a c a b a b =⇒=⇒++= (2分) 由于2221211[()()()]01b c c a b a c b a c a b=--+-+-≠,所以0a b c ++=(3分)充分性:0()a b c b a c ++=⇒=-+第7页共3页 2222222()2[()][()]022312366()10231a b ac b ac a c a c a c b c a b c a b c b c b c a b c a a b c c a c a b c a b a b ⎫⇒=-=-+=-++-≠⎪⎪⎪⎬⎪==++=⎪⎪⎭又因为()()2R A R A ⇒==, (5分) 因此原方程组有唯一解,即123,,l l l 交于一点. (6分)。
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华南农业大学期末考试试卷(A卷)2006学年第一学期考试科目:数据库原理与方法考试类型:(闭卷)考试时间:120 分钟参考答案:Question 1:a. A database-management system (DBMS) is a collection of interrelated dataand a set of programs to access those data.b.Metadata is data about data.c.The E-R data model is a widely used data model for database design. Itprovides a convenient grapical representation to view data, relationships, and constraints.d. A superkey of an entity set is a set of one or more attributes that, takencollectivly, allows us to identify uniquely an entity in the entity set. Such minnimal superkeys are called candidate keys.e. A data-manipulation language (DML) is a language than enables users toaccess or manipulate data. A data-definition language (DDL) is a language for specifying the database schema and as well as other properties of the data.f.Transactions are required to have the ACID properties: atomicity,consistency, isolation, and durability. Atomicity ensures that either all the effects of transaction are reflected in the database, or none are; Consistency ensures that, if the database is initially consistent, the execution of the transaction leaves the database in a consistent state. Isolation ensures that concurrently executing transactions are isolated from on another. Durablity ensures that, once a transaction has been committed, that transaction’s udpates do not get lost, even if there is a system failure.g.It is a state where neither of these transactions can ever proceed with itsnormal execution.h.Concurrency schedule consists of a sequence of instructions from varioustransactions which run concurrently.i. A unique fixed timestamp is associated with each transaction in the system.The timestamp of the transaction determine the serializability order.j.The most widely used structure for recording database modifications is the log. The log is a sequence of log records, recording all the update activitiesin the database.Question 2:a.b: Relation schemas:factory(name, director, location) workshop(wid, director, location, telephone) depositor(did, director, telephone) accessory(aid, weight, price)product(pid, price)worker(worker_id, name, start_date)f_w(name, wid, number)--FK name reference factory--FK wid reference workshopf_d(name, did, number)--FK name reference factory--FK did reference depositorw_a(wid, aid, number)--FK wid reference workshop--FK aid reference accessoryw_p(wid, pid, number)--FK wid reference workshop--FK pid reference productd_a(did, aid, number)--FK did reference depositor--FK aid reference accessoryd_p(did, pid, number)--FK did reference depositor--FK pid reference producta_p(aid, pid, number)--FK aid reference accessory--FK pid reference productw_w(wid, worker_id, number)--FK wid reference workshop--FK worker_id reference workerQuestion 3:a.F={(S#,C#)→G,C#→TN,TN→D}b.1NFc.∵Fm={(S#, C#)→G,C#→TN,TN→D}∴P={R1,R2,R3}The definition of R1,R2 and R3 is:R1=(S#, C#, G)R2=(C#, TN)R3=(TN, D)Question 4:a. ∏empnoδpublisher=’McGraw-Hill’(Loan Books)b. ∏name,age δpublisher=’McGraw-Hill’(Employee Loan Books)c. ∏name,office δpublisher=’McGraw-Hill’∧ year>2000 (Employee Loan Books)d. ∏empno (Loan)-∏empnoδpublisher=’McGraw-Hill’(Loan Books)Question 5:a.select avg(price)from market m, sales s, item iwhere m.mno=s.mno and s.ino=i.inoand m.city=’Guangzhou’ and i.ino=’abc2164’ and color = ‘red’b.select mnofrom saleswhere ino=’pc100’intersectselect mnofrom saleswhere ino=’jk375’c.select ino, iname, colorfrom itemwhere ino in ( select inofrom saleswhere mno=’rs225’exceptselect inofrom saleswhere mno=’az507’)d.select ino, max(price), min(price)from salsegroup by inohaving max(price)-min(price)>100Question 6:a.(select * from r1) union (select * from r2)b.(select * from r1) intersect (select * from r2)c.(select * from r1) except (select * from r2)d.select r1.A, r2.B, r1.Cfrom r1, r2where r1.B = r2. BQuestion 7:a. undo-list: T4redo-list: T2,T3b. undo(T i) restores the value of all data items updated by transaction T i to the old values.redo(T i) sets the value of all data items updated by transaction T i to the new values.。