[Karrigell]Karrigell Web开发入门第一季

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_Hustle_S01E01_

_Hustle_S01E01_

00:00:05,000 --> 00:00:10,000{\c&HFFFFFF&}{\fnSimhei}{\fs20} {\bord0}本作品由{\fnTahoma}{\fs28}{\c&HFFAE1A&}Norm HALFCD Team{\fnSimhei}{\c&HFFFFFF&}{\fs20}倾情奉献\N{\fs16}{\b0}{\bord0}{\shad0}{\c&HFFFFFF&}感谢原作提供资源.仅供学习交流.严禁用于商业行为\N{\fs14}{\3c&H2F2F2F&}{\4c&H000000&}{\fsp0}{\c&H26F4FF&}请自觉于下载后24小时内删除!如果喜欢本片,请购买正版!200:00:10,000 --> 00:00:15,000{\c&HFFFFFF&}{\fnSimhei}{\fs20} {\bord0}更多精彩尽在{\fnTahoma}{\fs24}{\c&HFFAE1A&}300:00:15,000 --> 00:00:20,000{\c&HFFFFFF&}{\fnSimhei}{\fs20} {\bord0}压制:{\c&HFFAE1A&}{\fs24}鬼谷子{\c&HFFFFFF&}{\fs20}字幕:{\c&HFFAE1A&}{\fs24}鬼谷子\N{\fnTahoma}{\fs20}{\b1}{\c&HFFFFFF&}Compression:{\c&HFFAE1A&}{\fs24}GV-Sir {\c&HFFFFFF&}{\fs20}Subtitles:{\c&HFFAE1A&}{\fs24}GV-Sir400:00:42,000 --> 00:00:46,000飞天大盗第1季第1集S01E01 The Con is On500:01:17,120 --> 00:01:18,951- 我来付小费- 谢了- I'll get the tip. - Thank you.600:01:20,120 --> 00:01:21,917- 谢了兄弟- 保重- Thanks,lad. - Keep well.700:01:22,000 --> 00:01:23,479- 再见- 再见- Cheerio. - Bye.800:01:57,520 --> 00:02:00,751把刀放下伙计安静一下行吗?Put the cleaver down,mate.Everybody calm down,all right?900:02:00,840 --> 00:02:04,469你们真想翻身嘛我这次可是通杀If you all want to chance it,I'll tell you now,I've got a full house.1000:02:07,040 --> 00:02:09,031全押上怎样?All in,right?1100:02:15,800 --> 00:02:18,075- 你丢了这个- 哦非常感谢伙计- You dropped this. - Thank you very much.1200:02:18,160 --> 00:02:19,718请你一杯怎么样?Can I buy you a drink?1300:02:19,800 --> 00:02:22,360- 当然没问题- 想喝什么?- All right,sure.Why not? - What'll you have?1400:02:23,560 --> 00:02:25,630- 威士忌谢谢- 一杯威士忌- Scotch,thanks very much. - Scotch.1500:02:35,560 --> 00:02:36,675行了!All right!1600:03:15,120 --> 00:03:16,109忙吗?Busy?1700:03:57,720 --> 00:04:00,792Ash 找个轻松点的生财之道吧Ash.There are easier ways to earn a living.1800:04:09,480 --> 00:04:10,595MickeyMickey.1900:04:12,720 --> 00:04:14,119太好了How good!2000:04:14,440 --> 00:04:16,476不是在做梦吧Have I missed you or what?2100:04:18,160 --> 00:04:20,674- 快车道上的生活不错嘛- 还不错!- How's life in the fast lane? - It's good.2200:04:27,200 --> 00:04:30,192这是城里唯一的生财之道了不是边开车边吃汉堡包..It's the only game in town.If they're not eating a hamburger...2300:04:30,280 --> 00:04:32,840就是在摆弄CD机..要么就是在接电话or fiddling with the CD player,they're on the phone.2400:04:32,920 --> 00:04:35,150没人会注意路况的No one watches the road anymore.2500:04:35,240 --> 00:04:36,229谢了EddieCheers,Eddie.2600:04:37,360 --> 00:04:39,635你呢怎么样?So what about you?How was it?2700:04:41,480 --> 00:04:44,074完全不同的经历别提了A new experience.One I don't care to repeat.2800:04:46,240 --> 00:04:47,878那现在在做什么呢?So what now then?2900:04:49,840 --> 00:04:51,910算是收山之作了I feel like one last score.3000:04:52,000 --> 00:04:53,513- 玩大的还小的? - 大的- Long or short? - Long.3100:04:53,600 --> 00:04:55,477没人再敢玩大的了吧No one is playing the long con anymore.3200:04:55,560 --> 00:04:59,269没人敢玩是因为他们不会玩一起来吧最后一次了They don't because they can'e on,one last time.3300:04:59,440 --> 00:05:03,115然后我就金盆洗手功成身退希望不会功败垂成Then I'll stop.I'll retire on my terms.Not because I've been beat.3400:05:09,520 --> 00:05:12,034你知道没有你我做不到的You know I can't do it without you.3500:05:12,960 --> 00:05:16,509- 什么时候开始? - 早开始了Albert已经下套了- When do we start? - Already have.Albert's got a mark.3600:05:16,600 --> 00:05:19,194不过当务之急是能搞定酒店吗?But first things first.Can you swing a hotel?3700:05:19,320 --> 00:05:21,038小菜一碟!Can Pavarotti sing?3800:05:41,240 --> 00:05:43,117我们已经在监视Stone了We've already got Stone under surveillance.3900:05:43,200 --> 00:05:45,634- 是的我知道长官- 那为什么还是窃贼猖獗?- I understand that,sir. - Then why the heavy mob?4000:05:45,720 --> 00:05:48,678我们得到可靠情报Stone正准备和新目标接头...We've had intelligence Stone's next target is well connected...4100:05:48,760 --> 00:05:50,193高手间的较量plays golf with the Chancellor.4200:05:50,280 --> 00:05:54,319看来他有个精英团队为什么不先警示他?So he's got friends in high places.Why don't you just warn him off?4300:05:54,400 --> 00:05:55,958一方面我们监督他....Whilst we are keen to protect him...00:05:56,040 --> 00:05:59,032一方面我们希望Stone主动放弃we're even more keen to see Stone put away again.4500:05:59,120 --> 00:06:01,111- 没别的选择了? - 没有- Have I got a choice? - No.4600:06:04,840 --> 00:06:06,432好了大家听着All right,listen up.4700:06:06,520 --> 00:06:10,354这位是从总部来的监察探长Martin DePalmaThis is Detective Inspector Martin DePalma from Central.4800:06:10,680 --> 00:06:13,752他是来视察Mickey Stone的案子He's here to oversee the Mickey Stone surveillance.4900:06:13,840 --> 00:06:15,478尽可能满足他的需要Give him what he wants.5000:06:15,560 --> 00:06:18,552- 任何行动先经过我的同意- 是的- Any overtime comes through me first. - Sir.5100:06:23,680 --> 00:06:27,514Terri Hodges警官我负责这个案子Sgt.Terri Hodges.I've been heading up the surveillance.5200:06:27,720 --> 00:06:30,359很好先看看我们都知道些什么Good.Then let's see what you've got.5300:06:47,320 --> 00:06:49,151好的再见!All right,cheers.5400:06:55,680 --> 00:06:56,874<i>Ashley Morgan</i><i>Ashley Morgan.</i>5500:06:56,960 --> 00:06:59,599道上人称Ash或"三只脚"Colloquially known as Ash or "Three Socks."5600:06:59,680 --> 00:07:02,274- "三只脚"? - 在狱中得名- Three Socks? - He got the name in prison.5700:07:02,360 --> 00:07:04,874就在他第一次从澡堂里出来之后After his first visit to the shower block.5800:07:04,960 --> 00:07:08,475他是个百宝箱不管你想要什么Ash Morgan都弄得到He's a fixer.Whatever you want,Ash Morgan will find it.5900:07:08,560 --> 00:07:11,313在10年前的一次酒吧打斗中导致头骨骨折He got a skull fracture in a barroom brawl 10 years ago.6000:07:11,400 --> 00:07:13,550然后他就以此为谋生之法He uses it to work the flop.6100:07:16,280 --> 00:07:18,999假装被车撞然后去医院.....Bounces over a car,goes to hospital...6200:07:19,080 --> 00:07:22,038X光检查出骨折保险公司理赔x-ray shows the fracture,insurance company pays out.6300:07:28,680 --> 00:07:31,558<i>Albert Stroller 赌场老手</i><i>Albert Stroller.Habitual gambler.</i>6400:07:31,640 --> 00:07:36,350赌马轮盘纸牌Albert都玩他负责下套Gee-gees,casinos,card games.Albert plays them all.He's the roper.6500:07:36,440 --> 00:07:39,830找到下手目标骗取他的信任再介绍给团伙的其他成员He finds the marks,sucks them in,and introduces them to the mob.6600:07:39,920 --> 00:07:43,799通常以退役军人或退休银行家的身份Usually plays the part of ex-serviceman or retired banker.6700:07:43,880 --> 00:07:47,350事实上他是南美中西部的皮鞋销售商In reality he was a shoe salesman in the American Midwest.6800:07:47,440 --> 00:07:51,115据说他的商店倒闭后员工过剩Legend has it,when his store closed down and the staff made redundant...6900:07:51,200 --> 00:07:55,432他从银行骗了6万美金并和他们的同伙平分he conned the company out of $60,000 and shared it amongst his coworkers.7000:07:55,520 --> 00:07:57,192他在70年代逃往英国He fled to England in the '70s...7100:07:57,280 --> 00:08:00,431初尝甜头之后便一发不可收拾but by then he'd got the taste and hasn't looked back since.7200:08:00,520 --> 00:08:02,476一旦Stroller找到了目标...Once Stroller's got his mark...7300:08:03,480 --> 00:08:05,789<i>骗局进入新流程</i><i>it's time to move up to the next level.</i>7400:08:08,040 --> 00:08:09,553<i>首脑人物</i><i>The insideman.</i>7500:08:10,120 --> 00:08:13,237<i>Michael Stone 也叫"Mickey Bricks"</i><i>Michael Stone. Also known as "Mickey Bricks."</i>7600:08:13,600 --> 00:08:18,151他总是单独行动诈骗专家从未失手过He's in a class all on his own.A long con player.Never been convicted.7700:08:18,840 --> 00:08:21,115对所有的反诈骗探员来说...It is a matter of personal pride...7800:08:21,200 --> 00:08:25,557找到证据并亲手逮捕他将会是件非常值得骄傲的事to every fraud investigator in the country,to be the one who nails him.7900:08:25,640 --> 00:08:29,758他因为一件无关的案件在监狱里服役了2年刚刚释放Just finished his first spell in prison for an unrelated crime.He served two years.8000:08:29,840 --> 00:08:34,072传言这次是他的收山之作错过这次机会游戏就结束了Rumors are,this is his last score.We miss him this time,it's game over.8100:08:34,160 --> 00:08:36,549我们认为这是他们的新猎物We think this is their next mark.8200:08:37,400 --> 00:08:38,799<i>Peter Reginald Williams</i>Peter Reginald Williams...8300:08:38,880 --> 00:08:41,59980年代初期开始从事制药行业started a pharmaceutical business in the early '80s.8400:08:41,680 --> 00:08:44,353他的第一任妻子Sara出生富豪世家His first wife Sara was from old money.8500:08:44,440 --> 00:08:48,558他借用了她的家族关系得到了许多政府的研究项目He used her family's connections in the government to get research contracts.8600:08:48,640 --> 00:08:50,835- 从哪儿下手? - 他很贪婪- Where's the in? - He is greedy.8700:08:51,600 --> 00:08:53,955- 我来付小费- 谢谢- I'll get the tip. - Thank you.00:08:54,040 --> 00:08:56,952<i>尽管他常常名列富豪榜的前500名</i><i>Regularly makes the Top 500 rich list.</i>8900:08:59,360 --> 00:09:02,796<i>但对于小钱却总是斤斤计较</i><i>But would cross the street to pick up ?coin.</i>9000:09:04,600 --> 00:09:06,875最近他娶了个年轻漂亮的太太He recently bagged himself a new young wife.9100:09:06,960 --> 00:09:11,192不过她大肆挥霍的程度远远超出了他的预计But she's high maintenance and spends his cash faster than he'd like.9200:09:12,320 --> 00:09:15,073他对漂亮脸蛋没有一点招架能力He's generally a sucker for a pretty face.9300:09:15,160 --> 00:09:19,756花钱取悦她们裙子越短他给的越多Spends money to impress.The shorter the skirt,the looser he gets.9400:09:22,080 --> 00:09:24,435听上去你对他很感兴趣AlbertSounds like you really warmed to this guy,Albert.9500:09:24,520 --> 00:09:28,308没错此人贪婪成性睚眦必报(多谢老黑)Yes.He's an objectionable little man,with the morals of an alley cat.9600:09:28,400 --> 00:09:30,311那正是你的目标That's marks for you.9700:09:32,080 --> 00:09:36,232这个团伙不是骗养老金的小混混This crew isn't about conning little old ladies out of their pension.9800:09:36,320 --> 00:09:38,550他们有严格的组织结构They're strictly major league.9900:09:38,920 --> 00:09:42,515还有要记得Mickey Bricks 总以为他比我们聪明得多And remember,Mickey Bricks thinks he's cleverer than us.10000:09:42,800 --> 00:09:45,394我们永远抓不到他的把柄That there's no way we can catch him.10100:09:46,400 --> 00:09:48,231我们要证明他错了Let's prove him wrong.10200:09:55,440 --> 00:09:56,873是时候下手了Time to get an edge.10300:10:01,560 --> 00:10:02,670MickeyMickey10400:10:13,360 --> 00:10:16,670- 我忘了什么了吗? - 两年里就一通电话- Did I miss something? - One phone call in two years.10500:10:17,720 --> 00:10:20,154是啊你知道我讨厌占线Yeah,you know how I hate queuing.10600:10:22,200 --> 00:10:24,270我已经集合到所有的人了I've got the crew together.10700:10:24,720 --> 00:10:26,039所有的?Everyone?10800:10:35,360 --> 00:10:36,429Albert?Albert?10900:10:37,400 --> 00:10:40,233我们出发了是的带他来吧We're on.Yeah,bring him in.11000:10:48,640 --> 00:10:51,234别给他小费Tony 他的服务太烂了Don't tip him,Tony.That service was shite.11100:10:55,360 --> 00:10:58,272- 你的钱包掉了- 不是我的- You've dropped your wallet. - It's not mine.11200:11:01,520 --> 00:11:03,351不少钱啊That's a lot of money.11300:11:04,280 --> 00:11:09,229看看Mark Hamilton Clacy Hughes的股东Let's see."Mark Hamilton.Clacy Hughes Associates."11400:11:10,200 --> 00:11:12,589你打算怎么办?找寻失主?What do you say?Finders keepers?11500:11:13,080 --> 00:11:16,117说得没错先看看他是不是住在这里You are a card.Let's see if he's staying here.11600:11:16,560 --> 00:11:17,813我们在地上找到了这个We found this on the floor.11700:11:17,814 --> 00:11:20,030先生我会把这个还给Hamilton先生的I'll see Mr.Hamilton gets it,sir.11800:11:20,120 --> 00:11:23,556不,我不这么认为告诉我们他在哪个房间No,I don't think so.Just tell us which room he's in.11900:11:32,080 --> 00:11:34,878- 她是谁? - Stacie Monroe- Who's she? - Stacie Monroe.12000:11:35,480 --> 00:11:38,392她嫁给了Jake Henry 一个惯偷诈骗犯She was married to short con artist Jake Henry.12100:11:38,480 --> 00:11:41,358几乎都是诱惑手法一直都很顺利They worked the badger mostly.Did well,too.12200:11:41,440 --> 00:11:45,149然而五年前Jake卷了他俩所有的积蓄消失了Then Jake took all their savings and ran for the hills five years ago. 12300:11:45,240 --> 00:11:47,231真是个让人值得敬佩的贼So much for honor amongst thieves.12400:11:47,320 --> 00:11:49,470别把结婚誓言当真了Not to mention your wedding vows.12500:11:50,160 --> 00:11:54,119谣传Stone在遇到他老婆前跟她有过一腿Word is,she and Stone had a thing once.Before he met his wife.12600:11:54,440 --> 00:11:56,568不单有张漂亮的脸她也是个高手Not just a pretty face.She's sharp.12700:11:56,569 --> 00:11:58,831在Stone的团队里也是出类拔萃的Maybe even in Stone's league.12800:12:05,000 --> 00:12:06,274是谁?Who is it?12900:12:06,360 --> 00:12:08,715- Mr.Hamilton? - 您是哪位?- Mr.Hamilton? - Who wants to know?13000:12:08,840 --> 00:12:11,434我想我们发现了您的东西We think we found something of yours.13100:12:12,240 --> 00:12:13,639您的钱包Your wallet.13200:12:23,720 --> 00:12:24,9943块53.50.13300:12:27,520 --> 00:12:29,988给你两次机会找到——"她"I'll give you two gos to find the lady.13400:12:30,120 --> 00:12:33,237- 可以行3块5 - 拿去吧- Yeah,right.3.50. - Take that.13500:12:36,440 --> 00:12:38,749你不该在这里混DannyShouldn't you be somewhere,Danny?13600:12:38,840 --> 00:12:40,796这样吧简单点Tell you what,I'll make it easy for you.13700:12:40,880 --> 00:12:43,758我把这个Q的一个角折起来象这样I'll take the Queen,turn the corner up.Like that.13800:12:47,440 --> 00:12:48,793开始了Here we go.13900:12:55,520 --> 00:12:59,229选一张不来钱你错了就请我喝一杯Choose.No money.If you get it wrong,just buy me a drink.14000:13:06,160 --> 00:13:08,515- 再来一杯- 真是个讨人厌的家伙- Same again,please. - You're a very sick person.14100:13:08,600 --> 00:13:10,431只是天赋而已Just naturally gifted.14200:13:12,120 --> 00:13:14,395听说了嘛Mickey Bricks放出来了You heard Mickey Bricks is out?14300:13:15,680 --> 00:13:18,956- 那个诈骗行家? - 最终的赢家- Plays the long con,right? - Top of the food chain.14400:13:19,920 --> 00:13:23,037怎么样?你认为他能教我些什么?So what?You reckon he could teach me something?14500:13:23,160 --> 00:13:26,311我怎么知道?你们这帮家伙都让我崇拜What do I know?All you guys freak me out.14600:13:26,560 --> 00:13:29,074不过他们都说他是最棒的But they say he's the best.14700:13:32,640 --> 00:13:35,234他现在住在London Park酒店He's booked in the London Park Hotel.14800:13:35,520 --> 00:13:37,670- 想要什么? - 一杯威士忌- Yes,mate? - Whiskey,please.14900:13:41,040 --> 00:13:42,268谢谢Thank you.15000:13:47,440 --> 00:13:49,078为你们干杯先生们Here's to you,gentlemen.15100:13:49,160 --> 00:13:52,072我一直认为世界上不可能再有诚实的人了I didn't think there were any honest men left in the world.15200:13:52,160 --> 00:13:54,594- 仅剩一两个了吧- 那就为诚实的人们干杯!- One or two. - Here's to honest men.15300:13:56,920 --> 00:14:01,198- 该让我好好的感谢你们一番- 不不我们不是冲这个来的- You must let me thank you properly. - No.We wouldn't hear of it.15400:14:01,280 --> 00:14:03,794就当是回家的车费Even if it's only the cab fare home.15500:14:04,000 --> 00:14:05,319稍等一下Excuse me.15600:14:33,320 --> 00:14:34,753说到哪儿了?Where were we?15700:14:34,840 --> 00:14:39,118哦是的我在极力说服你们收取你们应得的回报I was trying to persuade you to take something in return for your kindness.15800:14:39,200 --> 00:14:41,302是不是大家都认为"有钱能使鬼推磨"It's a strange state of affairs15900:14:41,303 --> 00:14:43,034一旦有人做了拾金不昧的善举if one chap can't do a favor for another...16000:14:43,120 --> 00:14:45,111反而会显得格格不入?without money rearing its ugly head.16100:14:45,200 --> 00:14:49,034有一天你也会有机会来帮助我们的One day you may be in a position to do something similar for us.16200:14:49,120 --> 00:14:52,795你知道我有可能...我有个建议You know,I just might.I have a suggestion.16300:14:53,280 --> 00:14:57,751明天有个贸易公司想让我给他们一小笔投资A business associate has asked me to make an investment for him tomorrow.16400:14:57,840 --> 00:15:01,958如果你们同意的话算你们投资500英磅如何?If you'll allow me,I'll put in,say,?00 for you?16500:15:05,200 --> 00:15:08,795我把给你们的钱作为投资基金你们等着收利润就行I'll take the ?00 back,you just get to keep the profit.16600:15:10,360 --> 00:15:11,759那对我来说没什么损失It'll have cost me nothing...16700:15:11,840 --> 00:15:15,469不过我能感觉好点好歹我为你们做了点事but at least I'll feel happier knowing I've done something.16800:15:16,720 --> 00:15:18,836真是慷慨!That sounds very generous.16900:15:19,760 --> 00:15:20,875就这样!Good.17000:15:24,760 --> 00:15:26,079谢谢!Thank you.17100:15:26,160 --> 00:15:28,310这项投资我能问下是关于什么的吗?This investment,can I ask what it is?17200:15:28,400 --> 00:15:31,358就是些股票什么没什么新鲜的Just stocks and shares.Nothing too exciting.17300:15:32,160 --> 00:15:33,513但愿是真的Fingers crossed.17400:15:33,920 --> 00:15:36,275我确信那并不重要I'm sure that won't be necessary.17500:15:45,560 --> 00:15:49,553- 你觉得怎么样? - 我觉得象是个稳赚不赔的买卖- What do you think? - Looks like a no-Iose situation to me.17600:15:49,640 --> 00:15:51,312我就喜欢这种My favorite kind.17700:15:51,760 --> 00:15:53,751他们大约1小时前离开They left about an hour ago.17800:15:53,840 --> 00:15:57,150Stroller离开Williams之后又重新回到酒店Stroller dropped Williams off,then went back to the hotel.17900:16:05,480 --> 00:16:08,756嗨Mickey 很高兴...我是想...好吧这样轻松点Hi,Mickey.Nice to...I was just...Okay,all right,take care.18000:16:08,840 --> 00:16:12,071嗨Mickey 你好啊我是Danny 我只是想...Hi,Mickey.How're you doing?Danny.I was just...18100:16:20,400 --> 00:16:22,391这家伙显然很有兴趣This guy moves in high circles.18200:16:22,480 --> 00:16:24,710我要找些特别的东西刺激下他It'll take something special to impress him.18300:16:24,800 --> 00:16:26,472一旦Ash施展出他的魔法That's exactly what he'll get.18400:16:26,560 --> 00:16:29,028他一定会如愿以偿的As soon as Ash starts working his magic.18500:16:29,120 --> 00:16:31,759有没有想要找个年轻女郎Albie?Have you ever thought of a younger woman,Albie?18600:16:31,840 --> 00:16:34,718亲爱的象我这样的年纪还能想其他的吗?My dear,at my age,I think of little else.18700:16:50,520 --> 00:16:52,829Stone先生嗨我是Danny BlueMr.Stone?Hi.Danny Blue.18800:16:53,280 --> 00:16:56,033很高兴见到你也许你听说过我Pleased to meet you.You've probably heard of me.18900:16:56,120 --> 00:17:00,318没有?好吧我不是来搞破坏的那我直接说重点吧No?All right.I'm not gonna mess you about.I'll come straight to the point.19000:17:00,400 --> 00:17:03,198我知道你在做笔大买卖我想加入I know you're playing a score.I want in.19100:17:03,560 --> 00:17:05,869- 加入什么? - 加入..你知道的..这场游戏- In what? - In.You know,in the game.19200:17:05,960 --> 00:17:10,158我想学我真的很想学点东西我想能不能进来聊一会I want to learn.I really want to learn.I'll just come inside for a little chat.19300:17:10,240 --> 00:17:11,798房间很漂亮不是吗?This is nice,isn't it?19400:17:12,080 --> 00:17:16,551我很棒我可以帮你考虑一下吧我愿意为你效劳I'm good.I can help you.Think of it like that.I'll do that for you.19500:17:16,640 --> 00:17:18,517我了解所有的老把戏你到哪一步了?I know all the old plays.What're you doing?19600:17:18,600 --> 00:17:21,558设套?不是?下饵?收网?The Wire?No?The Rag?The Pay-Off?19700:17:21,640 --> 00:17:25,915告诉我到哪儿了我会跟上的我能帮上忙You tell me once,that's it.Bosh,it's in.19800:17:28,080 --> 00:17:31,072我猜你也看过<i>《骗中骗》</i> 是不是?I bet you watched <i>The Sting,</i> too,didn't you?19900:17:28,080 --> 00:17:31,072{\an8}《骗中骗》1973年电影20000:17:31,960 --> 00:17:33,678从没听说过Never heard of it.20100:17:34,600 --> 00:17:38,718- 不别把我拒之门外- 我想我该这么做- You're not gonna shut the door,are you? - Yeah,I thought I might.20200:17:58,200 --> 00:18:00,555什么时候收网?So when do we pick them up?20300:18:02,080 --> 00:18:03,308等待时机We wait.20400:18:04,240 --> 00:18:05,912我要拿到所有的东西I want everything.20500:18:06,000 --> 00:18:09,276所有参与者,钱,不留一丝机会All the players,the money.Nothing left to chance.20600:18:09,360 --> 00:18:10,634据我们所知...As far as we can make out...20700:18:10,720 --> 00:18:13,632Mickey Bricks还没有足够的钱来实施这次的诈骗Mickey Bricks doesn't have the money to bankroll a con like this.20800:18:21,240 --> 00:18:25,153<i>他们会外出敛财那些靠小偷小摸而来的钱</i><i>They'll go out and try and raise what they can with short cons.</i>20900:18:38,880 --> 00:18:42,031<i>他们需要车最高档的那种</i><i>They'll need a car,top of the range.</i>21000:18:42,640 --> 00:18:46,633<i>不会很显眼但一定很显尊贵</i><i>Not too flash, but something that oozes class.</i>21100:18:53,880 --> 00:18:55,359停车吗先生?Parking,sir?21200:19:00,720 --> 00:19:02,915- 给你- 谢谢!- Here. - Thank you.21300:19:22,800 --> 00:19:25,598<i>显然上帝这次也站在他们这边</i><i>God help anyone who runs into them today.</i>21400:19:58,840 --> 00:20:00,239抱歉!I'm sorry.21500:20:37,480 --> 00:20:38,799<i>240</i><i>240.</i>21600:20:39,920 --> 00:20:41,239<i>125</i><i>125.</i>21700:20:43,400 --> 00:20:44,435够了?Enough?21800:20:44,520 --> 00:20:46,351- 算房租吗? - 不算- What about this place? - Sorted.21900:20:46,440 --> 00:20:47,793那就够了Then it's enough.22000:20:53,440 --> 00:20:57,558先生们正如我们约定的我替你们投资了500英镑.... As promised,gentlemen,I invested the ?00 on your behalf...22100:20:57,640 --> 00:20:59,596这些...是你们的所得and this is the return.22200:21:00,600 --> 00:21:02,875我希望没有令你们失望I hope you're not disappointed.22300:21:04,320 --> 00:21:06,311哈有1000英镑了吧?There must be ?,000 here.22400:21:06,400 --> 00:21:09,278准确的说是1950英镑?,950,to be precise.22500:21:10,640 --> 00:21:13,359- 这份回报还真不错- 我那份比你的要糟- That's quite a return. - I've had worse.22600:21:14,640 --> 00:21:17,518我敢打赌你一定赚翻了Made quite a killing yourself,I'll wager.22700:21:17,800 --> 00:21:19,233绝对不会!So shoot me.22800:21:19,440 --> 00:21:21,556别怪我多管闲事不过我觉得...Forgive me for prying,but I get the feeling...22900:21:21,640 --> 00:21:24,791这类的投资难道连一点风险都没有吗?there was little or no risk in this particular investment.23000:21:24,880 --> 00:21:26,711绝对不会有No risk whatsoever.23100:21:28,040 --> 00:21:32,158那么先生们我要失陪一会去开个会So,if you'll excuse me,gentlemen,I do have a meeting.23200:21:32,240 --> 00:21:35,710等等我在想我们为什么不再投资一回?Wait.I mean,why don't we go again?23300:21:38,400 --> 00:21:39,719再投资?Again?23400:21:41,840 --> 00:21:44,877Tony Hamilton先生已经够慷慨了Tony,Mr.Hamilton has been more than generous.23500:21:46,960 --> 00:21:48,279谢谢Thank you.23600:21:54,880 --> 00:21:56,871- 有事吗? - 亲爱的他在吗?- Can I help you? - Love,is he in?23700:21:59,720 --> 00:22:01,790- 对不起- 再见到你真是太好了- Excuse me. - Good to see you again.23800:22:01,880 --> 00:22:03,552打扰了先生们你好吗?Excuse me,gentlemen.How are you?23900:22:03,640 --> 00:22:07,155Hamilton先生我想亲自与你握个手Mr.Hamilton.I want to shake you by the hand.24000:22:07,360 --> 00:22:11,751你真是非常非常的了不起很抱歉我曾经怀疑过你的能力You are a very great man,and I'm sorry I ever doubted you.24100:22:12,320 --> 00:22:16,518当初我给你那笔钱的时候有那么一刹那我觉得....When I gave you that money,I did,for one second,consider the possibility...24200:22:16,600 --> 00:22:19,910你有可能会..你知道的我真不想再说出来了that you could have been,you know...I can't even say it.24300:22:20,000 --> 00:22:22,230说吧没关系想说就说吧Go ahead.Please.Get it off your chest.24400:22:22,320 --> 00:22:24,754我以为你可能会是个骗子I thought you could have been one of those conmen.24500:22:24,840 --> 00:22:27,070我可能再也见不到他和那笔钱了你们知道我说的什么I might never see my money or him ever again.24600:22:27,440 --> 00:22:31,070结果砰-- 眨眼工夫全回来了连本带利....Then,bang-- suddenly full be sent return just high interest of24700:22:32,760 --> 00:22:36,196难以置信我得喝一杯亲爱的请给我杯威士忌Unbelievable.I need a drink.Scotch,please,darling.24800:22:36,480 --> 00:22:41,349忘了介绍先生们这是Redford先生我的一个客户I'm sorry,gentlemen.This is Mr.Redford,a client of mine.24900:22:41,520 --> 00:22:45,479Redford先生这是Tony Monroe 和Peter WilliamsMr.Redford,this is Tony Monroe and Peter Williams.25000:22:45,560 --> 00:22:47,232Peter 你好Peter,how do you do?25100:22:47,320 --> 00:22:50,198我还想再投资这次我要加本金I'm ready to go again,but this time I wanna go bigger.25200:22:50,280 --> 00:22:53,272可以不过现在不合时宜...Fine.But this is neither the time nor the place to...25300:22:53,360 --> 00:22:54,429我都准备好了I'm ready.25400:22:55,840 --> 00:22:58,308Helen 替我送送Tony和Peter好吗?Perhaps you'd like to show Tony and Peter out?25500:22:58,400 --> 00:22:59,753不等等我想...No,wait.25600:23:00,880 --> 00:23:04,998如果有其他的投资机会我也很想了解一下If there's another deal up for grabs,I'd like to hear about it.25700:23:06,680 --> 00:23:09,478- Tony? - 当然我也想听听- Tony? - Absolutely,yes.25800:23:13,160 --> 00:23:16,436谢谢明早我的司机会去接你Thank you.My car will pick you up tomorrow morning.25900:23:16,520 --> 00:23:17,589谢了Thank you.26000:23:24,320 --> 00:23:27,551我不是行家不过...一切进展的很顺利I'm no expert,but I'd say that went like a dream.26100:23:36,040 --> 00:23:38,235- 可以加入了? - 算你一份- So am I in? - You're in.26200:23:54,240 --> 00:23:55,309谢谢!Thank you.26300:26:40,880 --> 00:26:41,869出发!Go.264。

an introduction to actor network theory

an introduction to actor network theory

an introduction to actor network theory
Actor Network Theory(ANT)是一种社会学分析方法,也被称为异质建构论。

该理论由法国社会学家布鲁诺·拉图尔(Bruno Latour)、米歇尔·卡龙(Michel Callon)和约翰·劳(John Law)提出。

ANT的基本思想是,科学技术实践是由多种异质成分彼此联系、相互建构而形成的网络动态过程。

ANT有三个核心概念:行动者(actor)、转义者(mediator)和网络(network)。

行动者既可以指人类,也包括观念、技术、生物、组织、思想等非人的物体。

在ANT中,任何通过制造差别而改变了事物状态(在网络中起到了changesomething的作用)的东西都可以被称为行动者。

即便是存在于网络中却没有任何action、没有造成任何改变的元素,也不能称为“actor”。

行动者和转义者通过互动形成网络,这种网络动态过程不仅涉及物质实体,还涉及观念、文化和话语等非物质实体。

ANT强调的是多元性、异质性和动态性,而不是传统的中心性、普遍性和静态性。

ANT的应用非常广泛,可以用于研究各种社会现象和科技发展,例如技术扩散、创新扩散、政策制定等。

ANT作为一种分析方法,有助于深入理解社会现象和科技发展的复杂性,因为它强调了行动者和转义者的互动关系以及网络动态过程的重要性。

通过ANT,我们可以更好地理解社会现象和科技发展的多元性、异质性和动态性,为解决现实问题提供更全面的视角和方法。

crawller

crawller

简化版网络爬虫(Web Crawler)一、基本部分你要编写一个通过HTTP协议与Web服务器通信的程序。

例如浏览器就是一个能够和Web服务器通信的HTTP客户端。

本项目的目标是实现一个简单的HTTP客户端程序,能够自动的通过用户输入的关键字来抓取网页。

你编写的自动的网页爬虫称为KeywordHunter。

项目的具体描述:运行参数:StartURL:爬虫开始抓取的URL。

例如:80/index.html,默认端口号为80。

SearchKeyword:爬虫机器人寻找的关键字。

最多100个字符。

如果当爬取深度为5时仍然没有找到关键字,则认为机器人找不到。

深度的意思是这样定义的:StartURL定义深度为1,StartURL中的所有链接集合U的深度为2,集合U中的所有链接的深度为3,依次类推。

OutputDir:如果这个参数不为空,则所有抓取到的网页需要保持到OutputDir路径下。

KeywordHunter的可执行文件命名必须为KeywordHunter 。

你的程序运行命令应该像这样:KeywordHunter /index.html FindMeTxt OutputDir或者KeywordHunter /index.html FindMeTxtExit Code:当程序运行没有错误时,返回0。

当发生例如无效命令参数时,返回1。

程序正确运行,但关键字没有找到不算错误。

KeywordHunter 必须使用HTTP Get请求来获取StartURL的内容。

然后开始搜索关键字,如果发现关键字,则KeywordHunter 报告该page的URL和关键字所在的行,然后停止运行。

如果没有找到关键字,则抓取当前页面的所有链接,进行层次搜索。

该程序运行停止条件为:1、找到了关键字;2、当搜索到深度为5时,仍未找到关键字。

KeywordHunter 需要从已经存在的HTTP服务器上面爬取页面,例如:/index.html,伯克利学习的服务器。

密码编码学与网络安全(第五版)答案

密码编码学与网络安全(第五版)答案

Chapter 1: Introduction (5)Chapter 2: Classical Encryption Techniques (7)Chapter 3: Block Ciphers and the Date Encryption Standard (13)Chapter 4: Finite Fields (21)Chapter 5: Advanced Encryption Standard (28)Chapter 6: More on Symmetric Ciphers (33)Chapter 7: Confidentiality Using Symmetric Encryption (38)Chapter 8: Introduction to Number Theory (42)Chapter 9: Public-Key Cryptography and RSA (46)Chapter 10: Key Management; Other Public-Key Cryptosystems (55)Chapter 11: Message Authentication and Hash Functions (59)Chapter 12: Hash and MAC Algorithms (62)Chapter 13: Digital Signatures and Authentication Protocols (66)Chapter 14: Authentication Applications (71)Chapter 15: Electronic Mail Security (73)Chapter 16: IP Security (76)Chapter 17: Web Security (80)Chapter 18: Intruders (83)Chapter 19: Malicious Software (87)Chapter 20: Firewalls (89)A NSWERS TO Q UESTIONS1.1The OSI Security Architecture is a framework that provides a systematic way of definingthe requirements for security and characterizing the approaches to satisfying thoserequirements. The document defines security attacks, mechanisms, and services, and the relationships among these categories.1.2 Passive attacks have to do with eavesdropping on, or monitoring, transmissions.Electronic mail, file transfers, and client/server exchanges are examples oftransmissions that can be monitored. Active attacks include the modification of transmitted data and attempts to gain unauthorized access to computer systems.1.3 Passive attacks: release of message contents and traffic analysis. Active attacks:masquerade, replay, modification of messages, and denial of service.1.4 Authentication: The assurance that the communicating entity is the one that it claims to be.Access control: The prevention of unauthorized use of a resource (i.e., this service controls who can have access to a resource, under what conditions access can occur, and what those accessing the resource are allowed to do).Data confidentiality: The protection of data from unauthorized disclosure.Data integrity: The assurance that data received are exactly as sent by an authorized entity(i.e., contain no modification, insertion, deletion, or replay).Nonrepudiation: Provides protection against denial by one of the entities involved in a communication of having participated in all or part of the communication.Availability service: The property of a system or a system resource being accessible and usable upon demand by an authorized system entity, according to performancespecifications for the system (i.e., a system is available if it provides services according to the system design whenever users request them).1.5 See Table 1.3.C HAPTER 2C LASSICAL E NCRYPTION T ECHNIQUESR2.1 Plaintext, encryption algorithm, secret key, ciphertext, decryption algorithm.2.2 Permutation and substitution.2.3 One key for symmetric ciphers, two keys for asymmetric ciphers.2.4 A stream cipher is one that encrypts a digital data stream one bit or one byte at atime. A block cipher is one in which a block of plaintext is treated as a whole and used to produce a ciphertext block of equal length.2.5 Cryptanalysis and brute force.2.6 Ciphertext only. One possible attack under these circumstances is the brute-forceapproach of trying all possible keys. If the key space is very large, this becomesimpractical. Thus, the opponent must rely on an analysis of the ciphertext itself, generally applying various statistical tests to it. Known plaintext. The analyst may be able to capture one or more plaintext messages as well as their encryptions.With this knowledge, the analyst may be able to deduce the key on the basis of the way in which the known plaintext is transformed. Chosen plaintext. If the analyst is able to choose the messages to encrypt, the analyst may deliberately pickpatterns that can be expected to reveal the structure of the key.2.7 An encryption scheme is unconditionally secure if the ciphertext generated by thescheme does not contain enough information to determine uniquely thecorresponding plaintext, no matter how much ciphertext is available. Anencryption scheme is said to be computationally secure if: (1) the cost of breaking the cipher exceeds the value of the encrypted information, and (2) the timerequired to break the cipher exceeds the useful lifetime of the information.2.8 The Caesar cipher involves replacing each letter of the alphabet with the letterstanding k places further down the alphabet, for k in the range 1 through 25.2.9 A monoalphabetic substitution cipher maps a plaintext alphabet to a ciphertextalphabet, so that each letter of the plaintext alphabet maps to a single unique letter of the ciphertext alphabet.2.10 The Playfair algorithm is based on the use of a 5 5 matrix of letters constructedusing a keyword. Plaintext is encrypted two letters at a time using this matrix.2.11 A polyalphabetic substitution cipher uses a separate monoalphabetic substitutioncipher for each successive letter of plaintext, depending on a key.2.12 1. There is the practical problem of making large quantities of random keys. Anyheavily used system might require millions of random characters on a regularbasis. Supplying truly random characters in this volume is a significant task.2. Even more daunting is the problem of key distribution and protection. For everymessage to be sent, a key of equal length is needed by both sender and receiver.Thus, a mammoth key distribution problem exists.2.13 A transposition cipher involves a permutation of the plaintext letters.2.14 Steganography involves concealing the existence of a message.2.1 a. No. A change in the value of b shifts the relationship between plaintext lettersand ciphertext letters to the left or right uniformly, so that if the mapping isone-to-one it remains one-to-one.b. 2, 4, 6, 8, 10, 12, 13, 14, 16, 18, 20, 22, 24. Any value of a larger than 25 isequivalent to a mod 26.c. The values of a and 26 must have no common positive integer factor other than1. This is equivalent to saying that a and 26 are relatively prime, or that thegreatest common divisor of a and 26 is 1. To see this, first note that E(a, p) = E(a,q) (0 ≤ p≤ q < 26) if and only if a(p–q) is divisible by 26. 1. Suppose that a and26 are relatively prime. Then, a(p–q) is not divisible by 26, because there is noway to reduce the fraction a/26 and (p–q) is less than 26. 2. Suppose that a and26 have a common factor k > 1. Then E(a, p) = E(a, q), if q = p + m/k≠ p.2.2 There are 12 allowable values of a (1, 3, 5, 7, 9, 11, 15, 17, 19, 21, 23, 25). There are 26allowable values of b, from 0 through 25). Thus the total number of distinct affine Caesar ciphers is 12 26 = 312.2.3 Assume that the most frequent plaintext letter is e and the second most frequentletter is t. Note that the numerical values are e = 4; B = 1; t = 19; U = 20. Then we have the following equations:1 = (4a + b) mod 2620 = (19a + b) mod 26Thus, 19 = 15a mod 26. By trial and error, we solve: a = 3.Then 1 = (12 + b) mod 26. By observation, b = 15.2.4 A good glass in the Bishop's hostel in the Devil's seat—twenty-one degrees andthirteen minutes—northeast and by north—main branch seventh limb east side—shoot from the left eye of the death's head— a bee line from the tree through the shot fifty feet out. (from The Gold Bug, by Edgar Allan Poe)2.5 a.The first letter t corresponds to A, the second letter h corresponds to B, e is C, sis D, and so on. Second and subsequent occurrences of a letter in the keysentence are ignored. The resultciphertext: SIDKHKDM AF HCRKIABIE SHIMC KD LFEAILAplaintext: basilisk to leviathan blake is contactb.It is a monalphabetic cipher and so easily breakable.c.The last sentence may not contain all the letters of the alphabet. If the firstsentence is used, the second and subsequent sentences may also be used untilall 26 letters are encountered.2.6The cipher refers to the words in the page of a book. The first entry, 534, refers topage 534. The second entry, C2, refers to column two. The remaining numbers are words in that column. The names DOUGLAS and BIRLSTONE are simply words that do not appear on that page. Elementary! (from The Valley of Fear, by Sir Arthur Conan Doyle)2.7 a.2 8 10 7 9 63 14 54 2 8 1056 37 1 9ISRNG BUTLF RRAFR LIDLP FTIYO NVSEE TBEHI HTETAEYHAT TUCME HRGTA IOENT TUSRU IEADR FOETO LHMETNTEDS IFWRO HUTEL EITDSb.The two matrices are used in reverse order. First, the ciphertext is laid out incolumns in the second matrix, taking into account the order dictated by thesecond memory word. Then, the contents of the second matrix are read left toright, top to bottom and laid out in columns in the first matrix, taking intoaccount the order dictated by the first memory word. The plaintext is then read left to right, top to bottom.c.Although this is a weak method, it may have use with time-sensitiveinformation and an adversary without immediate access to good cryptanalysis(e.g., tactical use). Plus it doesn't require anything more than paper and pencil,and can be easily remembered.2.8 SPUTNIK2.9 PT BOAT ONE OWE NINE LOST IN ACTION IN BLACKETT STRAIT TWOMILES SW MERESU COVE X CREW OF TWELVE X REQUEST ANYINFORMATION2.10 a.b.2.11 a. UZTBDLGZPNNWLGTGTUEROVLDBDUHFPERHWQSRZb.UZTBDLGZPNNWLGTGTUEROVLDBDUHFPERHWQSRZc. A cyclic rotation of rows and/or columns leads to equivalent substitutions. Inthis case, the matrix for part a of this problem is obtained from the matrix ofProblem 2.10a, by rotating the columns by one step and the rows by three steps.2.12 a. 25! ≈ 284b. Given any 5x5 configuration, any of the four row rotations is equivalent, for atotal of five equivalent configurations. For each of these five configurations,any of the four column rotations is equivalent. So each configuration in factrepresents 25 equivalent configurations. Thus, the total number of unique keysis 25!/25 = 24!2.13 A mixed Caesar cipher. The amount of shift is determined by the keyword, whichdetermines the placement of letters in the matrix.2.14 a. Difficulties are things that show what men are.b. Irrationally held truths may be more harmful than reasoned errors.2.15 a. We need an even number of letters, so append a "q" to the end of the message.Then convert the letters into the corresponding alphabetic positions:The calculations proceed two letters at a time. The first pair:The first two ciphertext characters are alphabetic positions 7 and 22, whichcorrespond to GV. The complete ciphertext:GVUIGVKODZYPUHEKJHUZWFZFWSJSDZMUDZMYCJQMFWWUQRKRb. We first perform a matrix inversion. Note that the determinate of theencryption matrix is (9 ⨯ 7) – (4 ⨯ 5) = 43. Using the matrix inversion formulafrom the book:Here we used the fact that (43)–1 = 23 in Z26. Once the inverse matrix has beendetermined, decryption can proceed. Source: [LEWA00].2.16 Consider the matrix K with elements k ij to consist of the set of column vectors K j,where:andThe ciphertext of the following chosen plaintext n-grams reveals the columns of K:(B, A, A, …, A, A) ↔ K1(A, B, A, …, A, A) ↔ K2:(A, A, A, …, A, B) ↔ K n2.17 a.7 ⨯ 134b.7 ⨯ 134c.134d.10 ⨯ 134e.24⨯ 132f.24⨯(132– 1) ⨯ 13g. 37648h.23530i.1572482.18 key: legleglegleplaintext: explanationciphertext: PBVWETLXOZR2.19 a.b.2.20your package ready Friday 21st room three Please destroy this immediately.2.21 y the message out in a matrix 8 letters across. Each integer in the key tellsyou which letter to choose in the corresponding row. Result:He sitteth between the cherubims. The isles may be gladthereof. As the rivers in the south.b.Quite secure. In each row there is one of eight possibilities. So if the ciphertextis 8n letters in length, then the number of possible plaintexts is 8n.c. Not very secure. Lord Peter figured it out. (from The Nine Tailors)3.1 Most symmetric block encryption algorithms in current use are based on the Feistelblock cipher structure. Therefore, a study of the Feistel structure reveals theprinciples behind these more recent ciphers.3.2 A stream cipher is one that encrypts a digital data stream one bit or one byte at atime. A block cipher is one in which a block of plaintext is treated as a whole and used to produce a ciphertext block of equal length.3.3 If a small block size, such as n = 4, is used, then the system is equivalent to aclassical substitution cipher. For small n, such systems are vulnerable to a statistical analysis of the plaintext. For a large block size, the size of the key, which is on the order of n 2n, makes the system impractical.3.4 In a product cipher, two or more basic ciphers are performed in sequence in such away that the final result or product is cryptographically stronger than any of the component ciphers.3.5 In diffusion, the statistical structure of the plaintext is dissipated into long-rangestatistics of the ciphertext. This is achieved by having each plaintext digit affect thevalue of many ciphertext digits, which is equivalent to saying that each ciphertext digit is affected by many plaintext digits. Confusion seeks to make the relationship between the statistics of the ciphertext and the value of the encryption key ascomplex as possible, again to thwart attempts to discover the key. Thus, even if the attacker can get some handle on the statistics of the ciphertext, the way in which the key was used to produce that ciphertext is so complex as to make it difficult todeduce the key. This is achieved by the use of a complex substitution algorithm. 3.6 Block size: Larger block sizes mean greater security (all other things being equal)but reduced encryption/decryption speed. Key size: Larger key size means greater security but may decrease encryption/decryption speed. Number of rounds: The essence of the Feistel cipher is that a single round offers inadequate security but that multiple rounds offer increasing security. Subkey generation algorithm:Greater complexity in this algorithm should lead to greater difficulty ofcryptanalysis. Round function: Again, greater complexity generally means greater resistance to cryptanalysis. Fast software encryption/decryption: In many cases, encryption is embedded in applications or utility functions in such a way as topreclude a hardware implementation. Accordingly, the speed of execution of the algorithm becomes a concern. Ease of analysis: Although we would like to make our algorithm as difficult as possible to cryptanalyze, there is great benefit inmaking the algorithm easy to analyze. That is, if the algorithm can be concisely and clearly explained, it is easier to analyze that algorithm for cryptanalyticvulnerabilities and therefore develop a higher level of assurance as to its strength.3.7 The S-box is a substitution function that introduces nonlinearity and adds to thecomplexity of the transformation.3.8 The avalanche effect is a property of any encryption algorithm such that a smallchange in either the plaintext or the key produces a significant change in theciphertext.3.9 Differential cryptanalysis is a technique in which chosen plaintexts with particularXOR difference patterns are encrypted. The difference patterns of the resultingciphertext provide information that can be used to determine the encryption key.Linear cryptanalysis is based on finding linear approximations to describe thetransformations performed in a block cipher.3.1 a. For an n-bit block size are 2n possible different plaintext blocks and 2n possibledifferent ciphertext blocks. For both the plaintext and ciphertext, if we treat theblock as an unsigned integer, the values are in the range 0 through 2n– 1. For amapping to be reversible, each plaintext block must map into a uniqueciphertext block. Thus, to enumerate all possible reversible mappings, the blockwith value 0 can map into anyone of 2n possible ciphertext blocks. For anygiven mapping of the block with value 0, the block with value 1 can map intoany one of 2n– 1 possible ciphertext blocks, and so on. Thus, the total numberof reversible mappings is (2n)!.b. In theory, the key length could be log2(2n)! bits. For example, assign eachmapping a number, from 1 through (2n)! and maintain a table that shows themapping for each such number. Then, the key would only require log2(2n)! bits, but we would also require this huge table. A more straightforward way todefine the key is to have the key consist of the ciphertext value for eachplaintext block, listed in sequence for plaintext blocks 0 through 2n– 1. This iswhat is suggested by Table 3.1. In this case the key size is n⨯ 2n and the hugetable is not required.3.2 Because of the key schedule, the round functions used in rounds 9 through 16 aremirror images of the round functions used in rounds 1 through 8. From this fact we see that encryption and decryption are identical. We are given a ciphertext c.Let m' = c. Ask the encryption oracle to encrypt m'. The ciphertext returned by the oracle will be the decryption of c.3.3 a.We need only determine the probability that for the remaining N – t plaintextsP i, we have E[K, P i] ≠ E[K', P i]. But E[K, P i] = E[K', P i] for all the remaining P iwith probability 1 – 1/(N–t)!.b.Without loss of generality we may assume the E[K, P i] = P i since E K(•) is takenover all permutations. It then follows that we seek the probability that apermutation on N–t objects has exactly t' fixed points, which would be theadditional t' points of agreement between E(K, •) and E(K', •). But apermutation on N–t objects with t' fixed points is equal to the number of wayst' out of N–t objects can be fixed, while the remaining N–t–t' are not fixed.Then using Problem 3.4 we have thatPr(t' additional fixed points) = ⨯Pr(no fixed points in N – t – t' objects)=We see that this reduces to the solution to part (a) when t' = N–t.3.4Let be the set of permutations on [0, 1, . . ., 2n– 1], which is referredto as the symmetric group on 2n objects, and let N = 2n. For 0 ≤ i≤ N, let A i be all mappings for which π(i) = i. It follows that |A i| = (N– 1)! and= (N–k)!. The inclusion-exclusion principle states thatPr(no fixed points in π)=== 1 – 1 + 1/2! – 1/3! + . . . + (–1)N⨯ 1/N!= e–1 +Then since e–1≈ 0.368, we find that for even small values of N, approximately37% of permutations contain no fixed points.3.53.6 Main key K = 111…111 (56 bits)Round keys K1 = K2=…= K16 = 1111..111 (48 bits)Ciphertext C = 1111…111 (64 bits)Input to the first round of decryption =LD0RD0 = RE16LE16 = IP(C) = 1111...111 (64 bits)LD0 = RD0 = 1111...111 (32 bits)Output of the first round of decryption = LD1RD1LD1 = RD0= 1111…111 (32 bits)Thus, the bits no. 1 and 16 of the output are equal to ‘1’.RD1 = LD0 F(RD0, K16)We are looking for bits no. 1 and 16 of RD1 (33 and 48 of the entire output).Based on the analysis of the permutation P, bit 1 of F(RD0, K16) comes from thefourth output of the S-box S4, and bit 16 of F(RD0, K16) comes from the second output of the S-box S3. These bits are XOR-ed with 1’s from the correspondingpositions of LD0.Inside of the function F,E(RD0) ≈ K16= 0000…000 (48 bits),and thus inputs to all eight S-boxes are equal to “000000”.Output from the S-box S4 = “0111”, and thus the fourth output is equal to ‘1’,Output from the S-box S3 = “1010”, and thus the second output is equal to ‘0’.From here, after the XOR, the bit no. 33 of the first round output is equal to ‘0’, and the bit no. 48 is equal to ‘1’.3.7 In the solution given below the following general properties of the XOR functionare used:A ⊕ 1 = A'(A ⊕ B)' = A' ⊕ B = A ⊕ B'A' ⊕ B' = A ⊕ BWhere A' = the bitwise complement of A.a. F (R n, K n+1) = 1We haveL n+1 = R n; R n+1 = L n⊕ F (R n, K n+1) = L n⊕ 1 = L n'ThusL n+2 = R n+1 = L n' ; R n+2 = L n+1 = R n'i.e., after each two rounds we obtain the bit complement of the original input,and every four rounds we obtain back the original input:L n+4 = L n+2' = L n ; R n+2 = R n+2' = R nTherefore,L16 = L0; R16 = R0An input to the inverse initial permutation is R16 L16.Therefore, the transformation computed by the modified DES can berepresented as follows:C = IP–1(SWAP(IP(M))), where SWAP is a permutation exchanging the positionof two halves of the input: SWAP(A, B) = (B, A).This function is linear (and thus also affine). Actually, this is a permutation, the product of three permutations IP, SWAP, and IP–1. This permutation ishowever different from the identity permutation.b. F (R n, K n+1) = R n'We haveL n+1 = R n; R n+1 = L n⊕ F(R n, K n+1) = L n⊕ R n'L n+2 = R n+1 = L n⊕ R n'R n+2 = L n+1⊕ F(R n+1, K n+2) = R n≈ (L n⊕ R n')' = R n⊕ L n⊕ R n'' = L nL n+3 = R n+2 = L nR n+3 = L n+2⊕ F (R n+2, K n+3) = (L n≈ R n') ⊕ L n' = R n' ⊕1 = R ni.e., after each three rounds we come back to the original input.L15 = L0; R15 = R0andL16 = R0(1)R16 = L0⊕ R0' (2)An input to the inverse initial permutation is R16 L16.A function described by (1) and (2) is affine, as bitwise complement is affine,and the other transformations are linear.The transformation computed by the modified DES can be represented asfollows:C = IP–1(FUN2(IP(M))), where FUN2(A, B) = (A ⊕ B', B).This function is affine as a product of three affine functions.In all cases decryption looks exactly the same as encryption.3.8 a. First, pass the 64-bit input through PC-1 (Table 3.4a) to produce a 56-bit result.Then perform a left circular shift separately on the two 28-bit halves. Finally,pass the 56-bit result through PC-2 (Table 3.4b) to produce the 48-bit K1.:in binary notation: 0000 1011 0000 0010 0110 01111001 1011 0100 1001 1010 0101in hexadecimal notation: 0 B 0 2 6 7 9 B 4 9 A 5b. L0, R0 are derived by passing the 64-plaintext through IP (Table 3.2a):L0 = 1100 1100 0000 0000 1100 1100 1111 1111R0 = 1111 0000 1010 1010 1111 0000 1010 1010c. The E table (Table 3.2c) expands R0 to 48 bits:E(R0) = 01110 100001 010101 010101 011110 100001 010101 010101d. A = 011100 010001 011100 110010 111000 010101 110011 110000e. (1110) = (14) = 0 (base 10) = 0000 (base 2)(1000) = (8) = 12 (base 10) = 1100 (base 2)(1110) = (14) = 2 (base 10) = 0010 (base 2)(1001) = (9) = 1 (base 10) = 0001 (base 2)(1100) = (12) = 6 (base 10) = 0110 (base 2)(1010) = (10) = 13 (base 10) = 1101 (base 2)(1001) = (9) = 5 (base 10) = 0101 (base 2)(1000) = (8) = 0 (base 10) = 0000 (base 2)f. B = 0000 1100 0010 0001 0110 1101 0101 0000g. Using Table 3.2d, P(B) = 1001 0010 0001 1100 0010 0000 1001 1100h. R1 = 0101 1110 0001 1100 1110 1100 0110 0011i. L1 = R0. The ciphertext is the concatenation of L1 and R1. Source: [MEYE82]3.9The reasoning for the Feistel cipher, as shown in Figure 3.6 applies in the case ofDES. We only have to show the effect of the IP and IP–1 functions. For encryption, the input to the final IP–1 is RE16|| LE16. The output of that stage is the ciphertext.On decryption, the first step is to take the ciphertext and pass it through IP. Because IP is the inverse of IP–1, the result of this operation is just RE16|| LE16, which isequivalent to LD0|| RD0. Then, we follow the same reasoning as with the Feistel cipher to reach a point where LE0 = RD16 and RE0 = LD16. Decryption is completed by passing LD0|| RD0 through IP–1. Again, because IP is the inverse of IP–1, passing the plaintext through IP as the first step of encryption yields LD0|| RD0, thusshowing that decryption is the inverse of encryption.3.10a.Let us work this from the inside out.T16(L15|| R15) = L16|| R16T17(L16|| R16) = R16|| L16IP [IP–1 (R16|| L16)] = R16|| L16TD1(R16|| L16) = R15|| L15b.T16(L15|| R15) = L16|| R16IP [IP–1 (L16|| R16)] = L16|| R16TD1(R16 || L16) = R16|| L16 f(R16, K16)≠ L15|| R153.11PC-1 is essentially the same as IP with every eighth bit eliminated. This wouldenable a similar type of implementation. Beyond that, there does not appear to be any particular cryptographic significance.3.13a.The equality in the hint can be shown by listing all 1-bit possibilities:We also need the equality A ⊕ B = A' ⊕ B', which is easily seen to be true. Now, consider the two XOR operations in Figure 3.8. If the plaintext and key for anencryption are complemented, then the inputs to the first XOR are alsocomplemented. The output, then, is the same as for the uncomplementedinputs. Further down, we see that only one of the two inputs to the secondXOR is complemented, therefore, the output is the complement of the outputthat would be generated by uncomplemented inputs.b.In a chosen plaintext attack, if for chosen plaintext X, the analyst can obtain Y1= E[K, X] and Y2 = E[K, X'], then an exhaustive key search requires only 255rather than 256 encryptions. To see this, note that (Y2)' = E[K', X]. Now, pick atest value of the key T and perform E[T, X]. If the result is Y1, then we knowthat T is the correct key. If the result is (Y2)', then we know that T' is the correctkey. If neither result appears, then we have eliminated two possible keys withone encryption.3.14 The result can be demonstrated by tracing through the way in which the bits areused. An easy, but not necessary, way to see this is to number the 64 bits of the key as follows (read each vertical column of 2 digits as a number):2113355-1025554-0214434-1123334-0012343-2021453-0202435-0110454- 1031975-1176107-2423401-7632789-7452553-0858846-6836043-9495226-The first bit of the key is identified as 21, the second as 10, the third as 13, and so on.The eight bits that are not used in the calculation are unnumbered. The numbers 01 through 28 and 30 through 57 are used. The reason for this assignment is to clarify the way in which the subkeys are chosen. With this assignment, the subkey for the first iteration contains 48 bits, 01 through 24 and 30 through 53, in their naturalnumerical order. It is easy at this point to see that the first 24 bits of each subkey will always be from the bits designated 01 through 28, and the second 24 bits of each subkey will always be from the bits designated 30 through 57.3.15 For 1 ≤ i ≤ 128, take c i∈ {0, 1}128 to be the string containing a 1 in position i andthen zeros elsewhere. Obtain the decryption of these 128 ciphertexts. Let m1,m2, . . . , m128 be the corresponding plaintexts. Now, given any ciphertext c which does not consist of all zeros, there is a unique nonempty subset of the c i’s which we can XOR together to obtain c. Let I(c) ⊆ {1, 2, . . . , 128} denote this subset.ObserveThus, we obtain the plaintext of c by computing . Let 0 be the all-zerostring. Note that 0 = 0⊕0. From this we obtain E(0) = E(0⊕0) = E(0) ⊕ E(0) = 0.Thus, the plaintext of c = 0 is m = 0. Hence we can decrypt every c ∈ {0, 1}128.3.16a. This adds nothing to the security of the algorithm. There is a one-to-onereversible relationship between the 10-bit key and the output of the P10function. If we consider the output of the P10 function as a new key, then thereare still 210 different unique keys.b. By the same reasoning as (a), this adds nothing to the security of the algorithm.3.17s = wxyz + wxy + wyz + wy + wz + yz + w + x + zt = wxz + wyz + wz + xz + yz + w + y3.18OK4.1 A group is a set of elements that is closed under a binary operation and that isassociative and that includes an identity element and an inverse element.4.2 A ring is a set of elements that is closed under two binary operations, addition andsubtraction, with the following: the addition operation is a group that iscommutative; the multiplication operation is associative and is distributive over the addition operation.C HAPTER 4F INITE F IELDS。

kuebler 一般操作手册

kuebler 一般操作手册

kuebler 一般操作手册Kubernetes(简称Kuebler)是一个开源的容器编排系统,用于自动化容器化应用程序的部署、扩展和管理。

以下是Kuebler的一般操作手册:1. 安装和配置:首先,您需要在您的环境中安装和配置Kubernetes。

您可以从Kubernetes的官方网站上下载适合您操作系统的安装包,并按照说明进行安装。

安装完成后,您需要配置网络和存储等基础设施。

2. 创建集群:在安装和配置好Kubernetes后,您需要创建一个集群。

集群是Kubernetes中的一个基本概念,它由一组节点组成,节点上运行着容器。

您可以使用kubeadm等工具来创建一个新的集群。

3. 部署应用程序:一旦集群创建完成,您就可以开始部署应用程序了。

在Kubernetes中,应用程序由一组容器组成,这些容器共同运行并协作。

您可以使用Kubernetes提供的各种API和工具来部署应用程序,例如kubectl命令行工具或Kubernetes的自定义资源定义(CRD)。

4. 管理和监控:一旦应用程序部署完成,您需要对其进行管理和监控。

Kubernetes提供了许多工具和API来监视和管理集群和应用程序的状态。

例如,您可以使用kubectl命令行工具来获取集群和应用程序的状态信息,使用Prometheus等工具来收集和存储监控数据。

5. 扩展和升级:随着应用程序的需求增加或变化,您可能需要扩展或升级应用程序。

Kubernetes提供了许多工具和策略来帮助您实现这一目标,例如自动缩放和滚动更新等。

6. 故障排查:如果集群或应用程序出现问题,您需要进行故障排查。

Kubernetes提供了许多工具和日志来帮助您找到问题所在并解决它们。

例如,您可以使用kubectl命令行工具来获取容器的日志或诊断信息。

以上是Kuebler的一般操作手册,希望对您有所帮助。

请注意,这只是一个概述,具体的操作步骤和细节可能因您的环境和需求而有所不同。

GPD_TEE_SE_API_v1.0

GPD_TEE_SE_API_v1.0
GlobalPlatform Device Technology
TEE Secure Element API
Version 1.0 Public Release
July 2013 Document Reference: GPD_SPE_024
Copyright 2012-2013 GlobalPlatform, Inc. All Rights Reserved. Recipients of this document are invited to submit, with their comments, notification of any relevant patent rights or other intellectual property rights of which they may be aware which might be necessarily infringed by the implementation of the specification or other work product set forth in this document, and to provide supporting documentation. The technology provided or described herein is subject to updates, revisions, and extensions by GlobalPlatform. Use of this information is governed by the GlobalPlatform license agreement and any use inconsistent with that agreement is strictly prohibited.

《跟Wakaba酱一起学网站制作》笔记

《跟Wakaba酱一起学网站制作》笔记

《跟Wakaba酱⼀起学⽹站制作》笔记策划阶段明确制作⽹站的⽬的宣传⽹站电⼦商务⽹站企业⽹站品牌⽹站店铺⽹站确定⽬标⽤户明确⽹站定位——此⽹站是为谁设计的,提供什么,然后才有可能成为抓住来访⼈的好⽹站6W1H思考框架who ⽹站是为谁做的when 他什么时候使⽤这个⽹站where 在哪⽤这个⽹站what 这个⽹站提供什么whom 谁来提供why 为什么要⽤这个⽹站how 怎么使⽤这个⽹站在设定⽬标⽬标时,经常容易有“20多岁的⼥性”这样模糊的描述,所有20多岁的⼥性,真的会有相同的思考⽅式,⽣活⽅式吗?虽然都是20多岁,但有各种群体,如本科⽣,专科⽣,公司职员等。

全国20多岁的⼥性不可能有共同的兴趣。

⽬标⽤户不能太泛化,不然会使“怎么推销,推销什么”这件事变得很不聚焦。

所以需要了解⾃⼰⽬标⽤户的思考⽅式和⽣活⽅式。

“兴趣是什么”,“周末如何度过”,“会分享的开⼼事是什么”等更具体的⾏为模式。

书中例⼦Web相关商品商店who ⽹站是为谁做的想给互联⽹⾏业⼈员送礼物,但不知道送什么的⼈when 他什么时候使⽤这个⽹站考虑送什么的时候where 在哪⽤这个⽹站电脑或⼿机what 这个⽹站提供什么印有独特Web相关团的T恤,马克杯whom 谁来提供将要成为互联⽹产品经理的Wakaba酱why 为什么要⽤这个⽹站想知道互联⽹产品经理喜欢什么样的东西,遇到适合的想买下来作为礼物送给他how 怎么使⽤这个⽹站送什么好啊->他是互联⽹产品经理啊->搜索“互联⽹产品经理礼物”->找到Wakaba Shop->购买制造架构图为了不让⽬标⽤户迷惑,快速找到想要的东西,准备好最合适的切⼊点。

为什么要有架构图架构图是根据⽤户需求⽽建⽴的。

当⽤户进⼊⽹站后,便于迅速找到所要寻求的某种信息或体验,提升⽹站的访问性能。

通过画出⽹站整体的架构图,可以清楚⽹站的内容及其必要程度。

例⼦新电影宣传⽹站⽬标⽤户的需求对应切⼊点电影讲了什么?故事演员都有谁?演员阵容导演是谁? staff哪些电影院有上映?上映电影院Wakaba Shop⽬标⽤户的需求对应切⼊点有什么样的物品?商品列表是谁?⽤什么样的理念做的?⽹站介绍咨询⽅式有哪些?咨询⼊⼝设定优先级通过思考⽹站的⽬的和⽬标⽤户想要看到的东西,给刚刚想出来的切⼊点设定好先后顺序。

SAE J4002-2010

SAE J4002-2010

3.2
H-point Travel Path ....................................................................................................................................... 6
SAE reviews each technical report at least every five years at which time it may be reaffirmed, revised, or cancelled. SAE invites your written comments and suggestions.
3.5
BOFRP (Ball of Foot Reference Point) ......................................................................................................... 7
3.6
Copyright © 2010 SAE International
All rights reserved. No part of this publication may be reproduced, stored in a retrieval system or transmitted, in any form or by any means, electronic, mechanical, photocopying, recording, or otherwise, without the prior written permission of SAE.

BSEN61427-1-2013

BSEN61427-1-2013
© 2013 CENELEC All rights of exploitation in any form and by any means reserved worldwide for CENELEC members. Ref. No. EN 61427-1:2013 E
CENELEC
BS EN 61427-1:2013 EN 61427-1:2013
BS EN 61427-1:2013
National foreword
BRITISH STANDARD
This British Standard is the UK implementation of EN 61427-1:2013. It is identical to IEC 61427-1:2013. Together with BS EN 61427-2, it supersedes BS EN 61427:2005 which will be withdrawn upon publication of all parts of this series. The UK participation in its preparation was entrusted to Technical Committee PEL/21, Secondary cells and batteries. A list of organizations represented on this subcommittee can be obtained on request to its secretary. This publication does not purport to include all the necessary provisions of a contract. Users are responsible for its correct application. © The British Standards Institution 2014. Published by BSI Standards Limited 2014 ISBN 978 0 580 74813 4 ICS 27.160; 29.220.20

virilog语法总结

virilog语法总结

1、verilog特点:★区分大小写,所有关键字都要求小写★不是强类型语言,不同类型数据之间可以赋值和运算★ //是单行注释可以跨行注释★描述风格有系统级描述、行为级描述、RTL级描述、门级描述,其中RTL级和门级别与具体电路结构有关,行为级描述要遵守可综合原★门级描述使用门级模型或者用户自定义模型UDP来代替具体基本元件,在IDE中针对不同FPGA器件已经有对应的基本元件原语verlog语法要点2、语句组成:★ module endmodule之间由两部分构成:接口描述和逻辑功能描述★ IO端口种类: input output inout★相同位宽的输入输出信号可以一起声明, input[3:0] a,b; 不同位宽的必须分开写★内部信号为reg类型,内部信号信号的状态: 0 1 x z, 3‘bx1=3’bxx1 x/z会往左扩展 3‘b1=3’b001 数字不往左扩展★逻辑功能描述中常用assign描述组合逻辑电路,always既可以描述组合逻辑电路又可以描述时序逻辑电路,还可以用元件调用方法描述逻辑功能★ always之间、assign之间、实例引用之间以及它们之间都是并行执行,always内部是顺序执行3、常量格式: <二进制位宽><‘><进制><该进制的数值>:默认进制为10进制默认位宽为32位位宽是从二进制宽度角度而言的由位宽决定从低位截取二进制数2’hFF=2‘b11,通常由被赋值的reg变量位宽决定parameter常用于定义延迟和变量位宽,可用常量或常量表达式定义4、变量种类: wire reg memory① IO信号默认为wire类型,除非指定为reg类型(reg和wire 的区别)wire可以用作任何输入输出端口wire包括input output inoutwire不带寄存功能assign赋值语句中,被赋值的信号都是wire类型assign之所以称为连续赋值,是因为不断检测表达式的变化reg类型可以被赋值后再使用,而不是向wire一样只能输出reg类型变量初始值为xalways模块里被赋值的信号都必须定义为reg类型,因为always 可以反复执行,而reg表示信号的寄存,可以保留上次执行的值reg类型变量与integer变量不同,即使赋负值,实质上也是按二进制无符号数存储的,integer是有符号数verilog中所有内部信号都是静态变量,因为它们的值都在reg中存储起来② memory型只有一维数组,由reg型变量组成memory初始化只能按地址赋值,不能一次性赋值1*256的memory写法: reg mema[255:0] mema[3]=0; 不同位宽的变量之间赋值,处理之前都以被赋值的变量位宽为准扩展或截取A[a:b] 无论a b谁大,a总是实际电路的信号高位,b总是实际电路的信号低位算术运算中如果有X值则结果为Xfor循环中的变量另外定义成integer,因为它不是实际信号,有正负;reg则以无符号数存在5、运算符(其他简单的书上有自己看)== 和!=只比较0、1,遇到z或x时结果都为x (x在if中算做假条件),结果可能是1、0、x===和!==比较更加苛刻,包括x和z的精确比较,结果可能是0、1 &&的结果只有1‘b1或1’b0两种, A&A的结果位宽则是与A相同的{1,0}为 64‘h100000000,所以拼接运算中各信号一定要指定位宽移位运算左移将保留 4'b1000<<1等于5'b10000,右移则舍弃 4'b0011等于4'b0001数字电路里位运算应用普遍,包括按位逻辑运算、移位运算、拼接运算、缩减运算6、非阻塞式赋值<=与阻塞式赋值=(比较)阻塞:在同一个always过程中,后面的赋值语句要等待前一个赋值语句执行完,后面的语句被该赋值语句阻塞非阻塞:在同一个always过程中,非阻塞赋值语句是同时进行的,排在后面的语句不会被该赋值语句阻塞<=:块结束后才能完成赋值块内所有<=语句在always块结束时刻同时赋值<=右边各变量的值是上一次时钟边沿时,这些变量当时的值用于描述可综合的时序电路=:=语句结束之后过程always才可能结束在always过程中,begin end块内按先后顺序立即赋值,在fork join内同时赋值(可能造成冲突)与assign连用描述组合电路begin end中阻塞的含义:begin ...@(A) B=C...; end 如果A事件不发生则永远不能执行下去,被阻塞了由于时钟的延时(往往在ps级),多个always(posedge)之间究竟谁先执行是个未知数使用八原则:(1)时序电路建模时,采用非阻塞赋值(2)锁存器电路建模时,采用非阻塞赋值。

无尺度网络--摘自《科学美国人》

无尺度网络--摘自《科学美国人》

无尺度网络--摘自《科学美国人》提交者:mostai日期: 2007/5/28 23:38 阅读: 614 评分:8.33/6来源:《科学美国人》中文版2003.7摘要:这是一篇非常好的文章,文笔流畅,浅显易懂,强烈推荐!网络有随机网络和无尺度网络,许多网络包括因特网"人类社会和人体细胞代谢网络等,都是无尺度网络。

研究无尺度网络,对于防备黑客攻击、防治流行病和开发新药等,都具有重要的意义。

(原文:Scale-Free Networks, pp50-59, May2003) 撰文/Albert-Laszlo Barabasi, Eeic Bonabeau)Tag:无尺度网络复杂系统《科学美国人》中文版2003.7作者介绍Albert-Laszlo Barabasi和Eric Bonabeau研究了从因特网到昆虫群落等一系列复杂系统的行为和特性。

Barabasi是美国圣母大学的霍夫曼物理学教授。

并在校内指导对复杂网络的研究,他著有《连结:网络新科学》一书。

Bonabeau为美国麻省剑桥咨询公司"伊可系统"的首席科学家,专门运用复杂科学方面的工具来开发商业机会。

他与别人合作撰写了《虫群智慧:从自然系统到人工系统》一书。

这是他在本刊上第二次发表文章。

一个实例:如图所示,因特网是一个无尺度网络,其中某些站点似乎与无数的其他站点相连结 (参见右图的星爆形结构细节)。

本图绘制于2003年2月6日,描绘了从某一测试站点到其他约10万个站点的最短连结路径。

图中以相同的颜色来表示相类似的站点。

大脑,是由轴突相连结的神经细胞网络,而细胞本身,又是由生化反应相连结的分子网络。

社会也是一个网络,它由友情、家庭和职业关系彼此连结。

在更大的尺度上,食物链和生态系统可以看作由物种所构成的网络。

科技领域的网络更是随处可见:因特网、电力网和运输系统都是实例。

就连在文章中我们用以向你传递思想的语言,也是一种藉由语法相互串连在一起的文字网络。

SimplifiedChinese01

SimplifiedChinese01

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Ae E R g Contents and Commentw T C g E t With soundb E b E w K R[[URL/zskj/1013/japanese.html [CTRL]+ClickSimplifiedChinese04w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gw K T C g Kanji Japanese-Chinese Site Web Site NameWb VocabularyCategoryx Level x Middle Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and CommentL T C gSame writing with different meaningURLhttp://moli.cims.hokudai.ac.jp/~sato/index.php?TopPage [CTRL]+ClickSimplifiedChinese05w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gO Education NetworkWeb Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb EInstruction of kaiwa and grammarURL/web/xyz/[CTRL]+ClickSimplifiedChinese06w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gV Grand Ball Japanese Language Web Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb E R ec L xRich of contents on kaiwa and grammarURL/index.php?xname=EU09LV0 [CTRL]+ClickSimplifiedChinese07w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gJapan T[rWeb Site NameWE Kanji and DictionaryCategoryx Level x Basic Levelw Kw K c[ Training ToolLearning Style] Evaluation. Ae E R g Contents and Commentw K p c[Dictionary for Training ToolURL/dic/[CTRL]+ClickSimplifiedChinese08w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gP Training ExpertWeb Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation Ae E R g Contents and Commentb E R ec L xRich of contents on kaiwa and grammarURL/ziliao/ziliao_3365_1.html [CTRL]+ClickSimplifiedChinese09w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gw Online Learning Japanese Web Site NameWb E Kaiwa and GrammarCategoryx Level x Middle Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb E R ec L xRich of contents on kaiwa and grammarURL/Html/clksxry/[CTRL]+ClickSimplifiedChinese10w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gWeb Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb EMovie of kaiwa and grammarURL/playlist_show/id_281800_orderby_9.html [CTRL]+ClickSimplifiedChinese11w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gNHK JapaneseWeb Site NameWb E Kaiwa and Grammar Categoryx Level x Middle Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb E R ec L x E tRich conversation and grammar contents with MovieURLhttp://www.nhk.or.jp/lesson/chinese/index.html [CTRL]+ClickSimplifiedChinese12w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gK Online JapaneseWeb Site NameWE Grammar and Composition Categoryx Level x Advanced Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentx E p T C gAdvanced Expression, Taiwanese SiteURL/sc/[CTRL]+ClickSimplifiedChinese13w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gBlue Wood Japanese Language Web Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb E R ec L xRich of contents on kaiwa and grammarURL/[CTRL]+ClickSimplifiedChinese14w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C ge g Sushi TestWeb Site NameWJapanese TestCategoryx Level x Middle Levelw Kh E e g Drill and TestLearning Style] Evaluation. Ae E R g Contents and CommentC C[l b gJapanese language test of JFTDURLhttp://momo.jpf.go.jp/sushi/index.php?LangFlag=c [CTRL]+ClickSimplifiedChinese15w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C go S Nikkei Japan Study Center Web Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb E R ec L x E tRich of kaiwa and grammar with soundURL.hk/ecmanage/page4.php#a [CTRL]+ClickSimplifiedChinese16w K Web T C gJapanese Language Training Web Site, Simplified Chinese Language Sort H PWeb T C gDangDang Japanese Language Web Site NameWb E Kaiwa and GrammarCategoryx Level x Basic Levelw K[g A TutorialLearning Style] Evaluation. Ae E R g Contents and Commentb E R ec L xRich of contents on kaiwa and grammarURL/[CTRL]+Click。

WEB前端线上系统课(20k+标准)-大神coderwhy全程直播授课【完整】分享学习

WEB前端线上系统课(20k+标准)-大神coderwhy全程直播授课【完整】分享学习

WEB前端线上系统课(20k+标准)-⼤神coderwhy全程直播授课【完整】分享学习链接: 提取码: iamh作者-\/ 307570512前端性能优化建议性能优化是把双刃剑,有好的⼀⾯也有坏的⼀⾯。

好的⼀⾯就是能提升⽹站性能,坏的⼀⾯就是配置⿇烦,或者要遵守的规则太多。

并且某些性能优化规则并不适⽤所有场景,需要谨慎使⽤,请读者带着批判性的眼光来阅读本⽂。

前端性能的⼀个重要指标是页⾯加载时间,不仅事关⽤户体验,也是搜索引擎排名考虑的⼀个因素。

来⾃Google的数据表明,⼀个有10条数据0.4秒能加载完的页⾯,变成30条数据0.9秒加载完之后,流量和⼴告收⼊下降90%。

Google Map ⾸页⽂件⼤⼩从100KB减⼩到70-80KB后,流量在第⼀周涨了10%,接下来的三周涨了25%。

亚马逊的数据表明:加载时间增加100毫秒,销量就下降1%。

尽量减少 HTTP 请求个数——须权衡使⽤CDN(内容分发⽹络)为⽂件头指定 Expires 或 Cache-Control ,使内容具有缓存性。

避免空的 src 和 href使⽤ gzip 压缩内容把 CSS 放到顶部把 JS 放到底部避免使⽤ CSS 表达式将 CSS 和 JS 放到外部⽂件中减少 DNS 查找次数精简 CSS 和 JS避免跳转剔除重复的 JS 和 CSS配置 ETags使 AJAX 可缓存尽早刷新输出缓冲使⽤ GET 来完成 AJAX 请求延迟加载预加载减少 DOM 元素个数根据域名划分页⾯内容尽量减少 iframe 的个数避免 404减少 Cookie 的⼤⼩使⽤⽆ cookie 的域减少 DOM 访问开发智能事件处理程序⽤代替 @import避免使⽤滤镜优化图像优化 CSS Spirite不要在 HTML 中缩放图像——须权衡favicon.ico要⼩⽽且可缓存保持单个内容⼩于25K打包组件成复合⽂本前端框架vue、react源码如何深⼊学习第⼀步:可以从lodash这种⼯具库开始看,因为都是⽐较⼩块的函数,⽐较好上⼿理解,也容易调试看效果。

51CTO学院-跟着瓦利哥学写OS视频课程

51CTO学院-跟着瓦利哥学写OS视频课程

51cto学院-跟着瓦利哥学写OS视频课程课程目标上完课,就可以实现一个自己命名的小OS了。

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3操作系统是如何启动的(1/3)[免费观看]19分钟从插电到进入加载内核的整个过程bios的原理虚拟机的原理动手写一个软盘启动的hell o world4操作系统是如何启动的(2/3)28分钟从插电到进入加载内核的整个过程bios的原理虚拟机的原理动手写一个软盘启动的he llo world5操作系统是如何启动的(3/3)11分钟从插电到进入加载内核的整个过程bios的原理虚拟机的原理动手写一个软盘启动的he llo world6从实模式到保护模式(1/2)44分钟* 实模式的原理* 保护模式的原理* 从实模式到保护模式的跳转* 动手写一个在保护模式的hello world7从实模式到保护模式(2/2)33分钟* 实模式的原理* 保护模式的原理* 从实模式到保护模式的跳转* 动手写一个在保护模式的hello world8虚拟内存的原理与实现48分钟* 资源是有限的* 线性地址与物理地址* 回顾分段* 理解分页* 动手写一个分页版的hello world9硬件中断的原理与实践51分钟* 中断的本质* bios中的中断* 常用的中断* 时钟中断与多任务* 动手实现键盘中断输入的hello world10异常的原理与实践41分钟* 异常的分类* 系统调用* 缺页中断的实现样例11多任务的实现原理45分钟* 认识TSS * 回顾时钟中断* 动手实现一个分别打印A&B的多任务OS12真正的多任务实现37分钟* 如何创建新任务* 系统调用的原理* fork系统调用的原理与实现* 实现一个可以fork 新任务的os13进入C语言的世界33分钟* 为什么要用C写OS * C代码与汇编代码的链接* 用户态程序使用C实现的样例14新程序的加载与执行37分钟* 应用程序是怎么被加载和执行的* exec系统调用的原理与实现* 可执行程序的格式*实现一个可以exec新任务的os课程地址:/course/course_id-1974.html。

从零开始学习使用Ruby进行Web应用开发

从零开始学习使用Ruby进行Web应用开发

从零开始学习使用Ruby进行Web应用开发Ruby是一种简单而强大的编程语言,广泛应用于Web应用开发领域。

对于初学者来说,从零开始学习使用Ruby进行Web应用开发可能会有一些困惑,本文将以以下几个方面来介绍Ruby语言及其在Web开发中的应用。

第一章:Ruby语言基础为了更好地学习使用Ruby进行Web应用开发,首先需要对Ruby语言进行基础学习。

本章将介绍Ruby的语法、基本数据类型、控制流程和函数等内容。

同时,还会介绍如何编写简单的Ruby程序并运行。

掌握这些基础知识对于后续的学习和实践非常重要。

第二章:Ruby的Web开发框架Ruby提供了多个Web开发框架,其中最为知名的是Ruby on Rails(简称Rails)。

本章将详细介绍Rails框架的特点和使用方法。

通过学习Rails框架,可以快速构建一个完整的Web应用程序,并了解Rails框架中的Model-View-Controller(MVC)架构模式。

第三章:数据库操作与持久化Web应用通常需要与数据库进行交互,存储和获取数据。

本章将介绍在Ruby中如何进行数据库操作和数据持久化。

主要涉及与关系型数据库(如MySQL、PostgreSQL等)以及非关系型数据库(如MongoDB)的交互。

同时,还会介绍一些Ruby的ORM(对象关系映射)库,如Active Record,用于简化数据库操作。

第四章:Web应用的用户认证与授权在Web应用开发中,用户认证和授权是常见且重要的功能之一。

本章将介绍如何在Ruby中实现用户认证和授权,确保只有合法用户才能访问应用的特定资源。

涉及到的内容包括用户注册、登录、密码加密、访问控制等。

同时,还会介绍一些流行的认证与授权库,如Devise和CanCanCan。

第五章:前端开发与Ruby现代Web应用开发不仅需要后端的支持,还需要良好的前端交互和用户体验。

本章将介绍在Ruby中如何进行前端开发,包括使用HTML、CSS和JavaScript等技术来构建用户界面。

karel手册

karel手册

Karel手册:教你如何成为一名优秀的程序员Karel是一种编程语言,它的特点是简单易学,适合初学者入门。

Karel的语法规则简单,只有四个基本命令:前进、左转、右转和放置砖块。

这些命令可以用来编写各种各样的程序,例如让Karel在迷宫中找到出口,或者让Karel在平面上画出各种图形。

Karel手册就是为了帮助大家更好地掌握Karel这种编程语言而编写的。

Karel手册的第一章介绍了Karel的基本语法和命令。

在这一章中,我们学习了如何定义函数、如何使用条件语句和循环语句、如何读取和修改Karel的状态等等。

这些知识是编程的基础,也是我们学习Karel的必备知识。

Karel手册的第二章介绍了Karel的高级编程技巧。

在这一章中,我们学习了如何使用递归函数、如何使用列表和字典、如何处理异常等等。

这些知识是编写复杂程序所必需的,也是我们成为一名优秀的程序员所必备的技能。

除了介绍Karel的语法和命令,Karel手册还提供了大量的练习题和项目。

这些练习题和项目既可以帮助我们巩固所学知识,又可以让我们体验编写真正的程序的乐趣。

例如,在一个练习题中,我们需要编写一个程序,让Karel在一个迷宫中找到出口。

这个练习题涉及到了条件语句、循环语句、函数定义等多个知识点,是一个非常好的练手项目。

Karel手册不仅仅是一本教材,它还是一本启发灵感的书。

在阅读Karel手册的过程中,我们不仅可以学到编程的技巧,还可以学到编程的思想。

例如,在一个练习题中,我们需要编写一个程序,让Karel在一个平面上画出一朵花。

这个练习题不仅需要我们掌握循环语句和函数定义等知识,还需要我们有一定的想象力和创造力。

这种启发式的教学方法可以帮助我们培养创新思维和解决问题的能力,是非常有价值的。

Karel手册是一本非常优秀的编程教材,它不仅可以帮助初学者入门,还可以帮助我们成为一名优秀的程序员。

在阅读Karel手册的过程中,我们可以学到编程的基础知识和高级技巧,还可以体验编写真正程序的乐趣。

VulBi基础知识完整版教材

VulBi基础知识完整版教材

第1章 Visual Basic 基础知识完整版教材§1 Visual Basic的基础知识一、概念和术语1,对象(Object)事物都可称作对象,比如桌椅就是对象,在Visual Basic里对象主要分为两类:Form和Control。

Form:窗体或称表单,其实指的就是window。

Control:控件,指的是各种按钮、标签等等。

2,属性(Property)指的是对象的属性,比如姓名、性别、民族、籍贯都是你这个对象的属性。

Caption、Left、Name 是一个命令按钮的属性。

3,事件(Event)事件是发生在对象上的动作。

比如敲桌子是一个事件,它是发生在桌子这个对象上的一个动作。

比如Click、Dblclick或LostFocus是发生在文本框控件上的事件。

然而事件的发生不是随意的,某些事件仅发生在某些对象上而已,比如“逃避早操被抓住”可以发生在学生这个对象上,但它不会发生在老师这个对象上。

4,方法(Method)这是一个直译,是一个较难理解的概念,它是对象本身内含的函数或过程,它也是一个动作,但不称作事件,在Visual Basic 里,方法和事件是这样的:事件:Private Sub对象名_事件名(事件内容)End Sub方法:对象名.方法名所以方法是一个简单的不必知道细节的无法改变的事件,同样,方法也不是随意的,一些对象有一些特定的方法。

如果以上概念你记不住,不要紧,实践中你会明白一切,请继续学习。

二、Visual Basic 的开发周期1,想清楚你想做到什么;2,拿起笔在纸上画出你的用户界面;3,拿起鼠标在屏幕上画出你的用户界面,确定对象的属性;4,告诉计算机你要做的事;5,让程序运行,看看能否工作;6,如果不能工作,不必难过;7,找出那个错误,重新开始。

你应该养成一些良好的习惯,这样在你编大程序时不至于丢三落四,为一些本来可避免的错误反复做第六步和第七步。

三、Visual Basic的存储和运行1,编写的程序和对象的属性一块儿存在frm文件里;2,整个程序里包含着一个或许多frm文件,Visual Basic将所有frm文件名存入一个vbp文件里,若丢失了一个vbp文件,尽管frm文件仍在磁盘上,但程序将不能运行了;3,如果你的程序已经自以为成功了,你可以把它编译成EXE文件,这样做的好处是:(1)在没有Visual Basic 的环境下可以运行;(2)速度提高;(3)别人不知道你的编程方法,还以为你是个编程专家,对你的编程效率大加赞叹。

Karel机器人学Java

Karel机器人学Java

卡雷尔机器指令集2013年3月10日12:51卡雷尔机器人指导文档:<<Full_CN_karel.pdf>>卡雷尔基本动作指令:move()要求卡雷尔向前推进一步。

当一堵墙挡在卡雷尔面前的时候,卡雷尔不能响应move()这个命令。

turnLeft()要求卡雷尔向左转90度(逆时针转动)。

pickBeeper()要求卡雷尔捡起街角上的蜂鸣器,把这个蜂鸣器放到它的蜂鸣器收藏包里,这个包可容纳无限多的蜂鸣器。

除非这个蜂鸣器恰好在卡雷尔所在的街角上,卡雷尔不能响应这个pickBeeper()命令。

putBeeper()要求卡雷尔从蜂鸣器收藏包里拿出一个蜂鸣器,放在卡雷尔所在的街角上。

除非卡雷尔的蜂鸣器收藏包里有蜂鸣器,卡雷尔不能响应这个putBeeper()命令。

卡雷尔的这些命令,不能自己自动执行。

在卡雷尔可以执行这些命令之前,你需要先把它们写在一个卡雷尔程序里。

需要特别注意的是,这几个命令对卡雷尔的行为进行了限制。

如果卡雷尔试图做些非法的举动,像穿墙或者捡起一个不存在的蜂鸣器,一个错误就发生了。

在这时,卡雷尔会显示一条错误的信息,同时拒绝执行剩余的命令。

卡雷尔控制语句:1.条件语句。

条件语句是指在程序里这样一些语句,只有当特定的条件成立了,才会被执行。

在卡雷尔编程里,你可以使用“if”来指定条件语句。

a.“if"的条件形式If(条件检测){只有当条件满足时才会执行的语句}b."if"的扩展形式If(条件检测){只有当条件满足时才会执行的语句} else {只有当条件不满足时才会执行}2.迭代语句。

迭代语句是指在一个程序里,某些语句需要被反复执行,程序员称这个为“循环”。

卡雷尔支持两种不同的迭代语句。

“for”语句用于当你想按预定的次数重复执行一组命令的时候,“while”语句用于当你想在某些条件满足时,重复执行一组命令的时候a.”for"的语法for(int i=0;i<count;i++){重复执行的语句}这里的"count"是一个整数,指需要重复的次数。

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Karrigell是一个用纯Python写的web框架,它非常简单而且有很多的特性。

这个教程将会一步一步的说明如何使用Karrigell编写程序。

使用Karrigell开发是很简单的:∙分发包自带一些强大的东西:一个web服务器和一个数据库引擎,整个包的大小不到1MB∙不需要配置:只需解压包,运行服务器然后写代码即可∙程序可以是纯Python代码也可以是Python与HTML混合就像PHP一样;它没有模板语法,需要学习自定义标签人们发现Kariigell是如此的简单,可以像玩具一样只需一些入门或一些动态web服务器的知识就可以了。

如果要想写一个“Hello world!”程序,需要键入:print "Hello, world !"但是如果你看过它的文档,你可能会对这个玩具能做的事感到惊讶:∙简单的访问HTML表单∙可以在一个脚本内包含其它脚本∙非常简单的基于内存的session管理∙基本的HTTP身份验证∙HTTP重定向∙保护文件夹∙多语言版本的动态页面∙多样的编程方式,从把一个站点放在一个纯Python脚本中到像PHP一样一个脚本是一个页面的方式∙内含Cheetah模板系统∙自带一个非常快的异步web服务器∙支持虚拟主机∙支持gzip∙可以在Apache或Xitami下运行∙带有一个简洁和完整的调试器∙带有一个数据库管理系统还有更多的特性….更多的信息参见documentation1. Getting started首先,download最新版的Karrigell并且把它解压。

打开windows的命令行窗口并运行内置的服务器:>python Karrigell.py使用一个文本编辑器保存如下Python代码到webapps目录hello.py的文件里:print "hello world !"然后在web浏览器里键入http://localhost/hello.py查看结果默认的,Python脚本被渲染成HTML代码。

如果想使用纯文本格式可在代码里设置Content-Type 头,就像这样:RESPONSE['Content-Type'] = 'text/plain'print "hello world !"这个例子展示Karrigell如何工作的:脚本都运行在一个命名空间内。

RESPONSE是这个命名空间里可用的名字,它是一个字典控制着HTTP响应的头。

2. HTML forms让我们来看看在提交了一个HTML窗体后如何得到这些信息。

新建这些HTML代码片段并保存在hello.htm中<form action="hello.py">Say hello to <input name="user"><input type="submit" value="Ok"></form>这个页面显示用户名,并且可以提交到hello.py脚本这是如何让hello.py打印信息的脚本:print "Hello, " + _user内置的Karrigell名字空间在接受到自浏览器发送的数据后会有一个叫_user的变量,它是输入到user字段的字符串值(注意是以下划线开头的,它用来避免与Python的关键字或内置的名字冲突)。

也可以选择使用这样的语法:print "Hello, " + QUERY['user']QUERY是一个提交表单的字段名字的字典3. Logging and session management如果想在一个站点里标识一个用户,比如需要打印它的名字,最简单的技巧是session管理。

Karrigell使用另一个内置的名字一个叫Session()的函数来管理session,它返回一个可以设置任何属性的Python对象。

编辑脚本hello.py :print "Hello, " + _userSession().user = _userprint """What would you like to order :<form action="order.py">CD <input type="radio" name="type" value="CD">book <input type="radio" name="type" value="book"><input type="submit" value="Ok"></form>"""在第二行设置session对象的user属性值为_user。

Session对象是web浏览器特有的,因此它能保证和持久一个用户可以被其它脚本标识。

例如可以在order.py中使用:print "Hello %s" %Session().userprint "So you want to order a %s" %_type4. Authentication身份认证是一个非常常见的任务用来检查一个用户是否有执行一个任务的权限。

因此,要求用户需要输入登录名和密码,程序会在数据库里查看登录名/密码是否合法。

改变HTML页面来要求输入一个用户名和密码而不只是一个用户名:<form action="check.py">Login <input name="login"><br>Password <input type="password" name="password"><input type="submit" value="Ok"></form>check.py脚本是这样的:def is_valid(login,password):# replace this with a check in the users databasereturn login == 'login' and password == 'password'if is_valid(_login,_password):Session().login = _loginprint "Hello %s <br>" %_loginprint """What would you like to order :<form action="order.py">CD <input type="radio" name="type" value="CD">book <input type="radio" name="type" value="book"><input type="submit" value="Ok"></form>"""else:print "Sorry, you are not allowed to access this page"Session对象有了一个login属性后,就可以在其他脚本里通过测试这个属性来测试用户的合法性了:if hasattr(Session(),'login'):(show information for authorized users)else:(show information for unlogged visitors)当然也可以选择使用基本HTTP身份认证:一个要求输入登录名和密码的弹出式窗口。

为了达到验证的目的在命名空间里一个叫Authentication()的函数,像这样使用:def authTest():(check if AUTH_USER and AUTH_PASSWORD are in the database) Authentication(authTest,"Authentication test",/"Sorry, you are not allowed to access this page")print """What would you like to order :<form action="order.py">CD <input type="radio" name="type" value="CD">book <input type="radio" name="type" value="book"><input type="submit" value="Ok"></form>"""Authentication()带有3个参数:∙function:调用的函数,这个函数没有参数,但是它使用AUTH_USER和AUTH_PASSWORD 它们是在弹出窗口输入的用户名和密码,如果验证成功将会继续执行下面的脚本∙realm:是一个显示在弹出窗口上的字符串∙message:当function没有返回True时,验证未成功时返回的信息。

如果验证成功将会继续执行下面的脚本。

5. Karrigell services目前我们都是把脚本写在不同的文件里。

但是一些比较小的脚本就会变的乏味和难以维护。

我们可以使用Karrigell services:Python脚本的每一个函数匹配一个URL。

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