三版第08章-习题解答
新视野大学英语3读写教程第八单元答案
新视野大学英语3读写教程第八单元答案1. A good ___ is the first step to a good job. [单选题] *A. education(正确答案)B. unitC. textD. subject2. College education provides more ___for a bright future. [单选题] *A. lessonsB. coursesC. opportunities(正确答案)D. subjects3. He had a ___ to his wife who gave him the money to start his business. [单选题] *A. jobB. debt(正确答案)C. chanceD. career4. A ___ is helpful in looking for a job, but it doesn't mean a job. [单选题] *A. certificate(正确答案)B. gradeC. recordD. debt5. If you think getting a certificate means getting a job, you are ___ yourself. [单选题] *A. keepingB. havingC. cheating(正确答案)D. doing6. Try to have a real ___ of the course. Having it on your record doesn't mean much. [单选题] *A. understanding(正确答案)B. understandC. knowingD. know7. To be honest with yourself is to ___ yourself. [单选题] *A. look atB. doC. refuceD. respect(正确答案)8. The ___ of this country comes from its oil. [单选题] *A. wealth(正确答案)B. viewC. sympathyD. tale9. They agreed to meet the ___ week in the People's Park. [单选题] *A. exactB. following(正确答案)C. earlyD. late10. Generally speaking (一般来说), views on this subject ___ widely. [单选题] *A. manageB. succeedC. graduateD. differ(正确答案)11. The sick old man asked the doctor for ___ to get better soon. [单选题] *A. awardB. advice(正确答案)C. situationD. sheet12. We were all ___ to hear the news that Tom, the silly boy, had won an award. [单选题] *A. fluentB. rudeC. amazed(正确答案)D. successful13. Tony often ___ with his wife about money. [单选题] *A. argues(正确答案)B. interviewsC. embarrassesD. improves14. The little girl got much ___ from her father when she told him about her pains. [单选题] *A. detailB. energyC. sympathy(正确答案)D. suggestion15. I've learned from my uncle that dogs ___ people by their smell. [单选题] *A. improveB. recognize(正确答案)C. expectD. teach16. The classroom needs ___ . [单选题] *A. cleanB. to cleanC. to be cleaned(正确答案)D. being cleaned17. Wordsworth was one of the greatest poets ___ lived in the 19th century. [单选题] *A. whichB. whoC. thoseD. that(正确答案)18. ___ the population is too large, we have to take measures to control the birth rate. [单选题] *A. AlthoughB. Since(正确答案)C. IfD. Until19. As Edison grew ___ , he became more and more interested in science. [单选题] *A. elderB. the elderC. older(正确答案)D. the older20. Only in this way ___ catch up with your brothers. [单选题] *A. do you canB. can you(正确答案)C. you canD. you do can21. The teacher told his students to make the most of the opportunities ______ hand. [填空题] *空1答案:at22. He let the team ______ by not trying hard enough. [填空题] *空1答案:down23. Have you made ______ your mind what courses you are going to take yet? [填空题] *空1答案:up24. She learned the rules of the game step ______ step. [填空题] *空1答案:by25. Will the fine weather keep ______ ? [填空题] *空1答案:up26. ______ some extent you've done a good job. [填空题] *空1答案:To27. She speaks Japanese with a Chinese ______ . [填空题] *空1答案:accent28. One of the firefighters(消防队员) won a(an) ______ for bravery(勇敢). [填空题] *空1答案:award29. Hard work and good ideas will lead to ______ in business. [填空题] *空1答案:success30. Mr. Black ______ famous people every week in his radio program. [填空题] *空1答案:interviews31. Some young men started smoking without realizing what the ______ were. [填空题] *空1答案:risks32. Tony Green has worked very hard to make his dream a(an) ______ . [填空题] *空1答案:reality33. Ann speaks ______ Japanese, as she has lived there for three years. [填空题] *空1答案:fluent34. The box was very heavy, but Tom still ______ to carry it home. [填空题] *空1答案:managed35. There is a need ______ the skills in learning English. [填空题] *空1答案:for36. You are asking ______ trouble if you let your child play with fire. [填空题] *空1答案:for37. I didn't tell her the bad news, as I was afraid ______ making her sad. [填空题] *空1答案:of38. When he woke up, he found himself ______ the hospital. [填空题] *空1答案:in39. We should all take a leaf ______ of Lei Feng's book. [填空题] *空1答案:out40. Tom's dream is to become a doctor, and he is working very hard to turn his dream ______ a reality. [填空题] *空1答案:into41. Mr. White helped the poor old woman ______ of sympathy. [填空题] *空1答案:out42. My mother filled my glass ______ milk and her glass with tea. [填空题] *空1答案:with43. Tony was doing everything he could, trying to find ______ the girl's telephone number. [填空题] *空1答案:out44. I'm going to visit my aunt this weekend, and my brother is coming ______ well. [填空题] *空1答案:as45. The little girl was glad to see that the basket was filled ______ apples. [填空题] *空1答案:with46. 写作词汇:请填入以下10个单词的正确含义序号(A-J)A. 已婚B. 年龄C. 性别D. 婚姻状况E. 出生日期F. 离异G. 家庭住址H. 签名I. 名J. 姓1. First name___2. Last name___3. Signature___4. Age___5. Sex ___6. Marital status___7. Date of birth___8. Divorced___9. Home address___10. Married___ [填空题] *空1答案:I空2答案:J空3答案:H空4答案:B空5答案:C空6答案:D空7答案:E 空8答案:F 空9答案:G 空10答案:A。
08热力学第二定律习题解答
第八章热力学第二定律一选择题1. 下列说法中,哪些是正确的?( )(1)可逆过程一定是平衡过程;(2)平衡过程一定是可逆的;(3)不可逆过程一定是非平衡过程;(4)非平衡过程一定是不可逆的。
A. (1)、(4)B. (2)、(3)C. (1)、(3)D. (1)、(2)、(3)、(4)解:答案选A。
2. 关于可逆过程和不可逆过程的判断,正确的是( )(1) 可逆热力学过程一定是准静态过程;(2) 准静态过程一定是可逆过程;(3) 不可逆过程就是不能向相反方向进行的过程;(4) 凡是有摩擦的过程一定是不可逆的。
A. (1)、(2) 、(3)B. (1)、(2)、(4)C. (1)、(4)D. (2)、(4)解:答案选C。
3. 根据热力学第二定律,下列哪种说法是正确的?( )A.功可以全部转换为热,但热不能全部转换为功;B.热可以从高温物体传到低温物体,但不能从低温物体传到高温物体;C.气体能够自由膨胀,但不能自动收缩;D.有规则运动的能量能够变成无规则运动的能量,但无规则运动的能量不能变成有规则运动的能量。
解:答案选C。
4 一绝热容器被隔板分成两半,一半是真空,另一半是理想气体,若把隔板抽出,气体将进行自由膨胀,达到平衡后:( )A. 温度不变,熵增加;B. 温度升高,熵增加;C. 温度降低,熵增加;D. 温度不变,熵不变。
解:绝热自由膨胀过程气体不做功,也无热量交换,故内能不变,所以温度不变。
因过程是不可逆的,所以熵增加。
故答案选A 。
5. 设有以下一些过程,在这些过程中使系统的熵增加的过程是( )(1) 两种不同气体在等温下互相混合;(2) 理想气体在等体下降温;(3) 液体在等温下汽化;(4) 理想气体在等温下压缩;(5) 理想气体绝热自由膨胀。
A. (1)、(2)、(3)B. (2)、(3)、(4)C. (3)、(4)、(5)D. (1)、(3)、(5) 解:答案选D 。
二 填空题1.在一个孤立系统内,一切实际过程都向着 的方向进行。
计算机组成原理第八章课后部分答案
8.1 CPU有哪些功能?画出其结构框图并简要说明每个部件的作用。
解:CPU的主要功能是执行存放在主存储器中的程序即机器指令.CPU是由控ALU:实现算逻运算寄存器:存放操作数CU:发出各种操作命令序列的控制部件中断系统:处理异常情况和特殊请求8.2 什么是指令周期?指令周期是否有一个固定值?为什么?解:指令周期:指取出并执行完一条指令所需的时间。
由于计算机中各种指令执行所需的时间差异很大,因此为了提高CPU运行效率,即使在同步控制的机器中,不同指令的指令周期长度都是不一致的,也就是说指令周期对于不同的指令来说不是一个固定值。
8.3 画出指令周期的流程图,分别说明图中每个子周期的作用。
解:指令周期流程图取指周期:取指令间址周期:取有效地址执行周期:取操作数(当指令为访存指令时)中断周期:保存程序断点8.4 设CPU内有这些部件:PC、IR、SP、AC、MAR、MDR、CU。
(1)画出完成简洁寻址的取数指令“LDA@X”(将主存某地址单元的内容取至AC中)的数据流(从取指令开始)。
(2)画出中断周期的数据流。
解:CPU中的数据通路结构方式有直接连线、单总线、双总线、三总线等形式,目前大多采用总线结构,直接连线方式仅适用于结构特别简单的机器中。
下面采用单总线形式连接各部件,框图如下:(1)LDA@X指令周期数据流程图:(2)中断周期流程图如下:8.7 什么叫系统的并行性?粗粒度并行和细粒度并行有什么区别?解:并行性:包含同时性和并发性。
同时性指两个或两个以上的事件在同一时刻发生,并发性指两个或多个事件在同一时间段发生。
即在同一时刻或同一时间段内完成两个或两个以上性质相同或性质不同的功能,只要在时间上存在相互重叠,就存在并行性。
粗粒度并行是指多个处理机上分别运行多个进程,由多台处理机合作完成一个程序,一般算法实现。
细粒度并行是指在处理机的指令级和操作级的并行性。
8.8 什么是指令流水?画出指令二级流水和四级流水的示意图,它们中哪一个更能提高处理器速度,为什么?解:指令流水:指将一条指令的执行过程分为n个操作时间大致相等的阶段,每个阶段由一个独立的功能部件来完成,这样n个部件可以同时执行n条指令的不同阶段,从而大大提高CPU的吞吐率。
《曾谨言 量子力学教程 第3版 笔记和课后习题 含考研真题 》读书笔记思维导图
02
第2章 一维势场中的 粒子
03
第3章 力学量用算符 表达
04
第4章 力学量随时间 的演化与对称性
05 第5章 中心力场
06
第6章 电磁场中粒子 的运动
目录
07 第7章 量子力学的矩 阵形式与表象变换
08 第8章 自 旋
09
第9章 力学量本征值 问题的代数解法
010 第10章 微扰论
011 第11章 量子跃迁
7.2 课后习题详 解
7.1 复习笔记
7.3 名校考研真 题详解
第8章 自 旋
8.2 课后习题详 解
8.1 复习笔记
8.3 名校考研真 题详解
第9章 力学习题详 解
9.1 复习笔记
9.3 名校考研真 题详解
第10章 微扰论
10.2 课后习题 详解
10.1 复习笔记
第1章 波函数与Schrödinger 方...
1.2 课后习题详 解
1.1 复习笔记
1.3 名校考研真 题详解
第2章 一维势场中的粒子
2.2 课后习题详 解
2.1 复习笔记
2.3 名校考研真 题详解
第3章 力学量用算符表达
3.2 课后习题详 解
3.1 复习笔记
3.3 名校考研真 题详解
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《读写教程3》Unit 8练习答案
新视野大学英语《读写教程》第3册(第二版)Key to ExercisesUnit EightSection APre-reading Activities(P. 202)What would a clone do for me? Wow! If I had a clone I’d finally have free time.I’d tell her to do a ll my work.She would wash clothes,cook dinner,and take care of my husband and children.She’d go to the office for me as well, and do everything I dislike.And while she was doing that,I’d relax.Or, better yet.I’d travel.I’d see the great cities of the world,like Shanghai, Paris, and San Francisco.But wait.If my clone took care of my family,then my family would love the clone more than me! She’d be the one they’d go to with their problems, and she’d g ive them advice and love.Do I really want to miss this? No, I’ve changed my mind.Having a clone would be terrible.1. Free time.2. Her family would love the clone more than her.3. (Open-ended.)Comprehension of the TextI. (p. 208)1.A world with human clones.2.President Clinton ordered a national commission to study the legal and moral implications of cloning.3.Because twins have shared the same environment within the mother, are usually raised in the same family, and so forth.4.Whether Dolly will be able to give birth to lambs.5.Because cloning would increase the chances for a tissue match from 25 percent to nearly 100 percent.6.Because pigs have organs similar in size to humans’.7.Most honored sir or madam.8.The creation of a new and disrespected social class“the clones”.VocabularyIII. (p. 208-209)IV. (p. 209)V. (p. 210)CollocationVI. (p. 210-211)Word BuildingVII. (p. 211-212)VIII. (p. 212)Sentence StructureIX. (p. 213)1. What if I say no2. What if they don’t know3. What if we can’t finish it on time4. What if this happens to us someday5. What if he has lied to usX. (p. 213)1. The Bosnian peace talks are continuing in Geneva today with the new proposals at the top of the agenda.2. All of Southern Africa is suffering from a severe drought with Mozambique and Zimbabwe among the worse-hit countries.3. The Europe Summit in Paris is drawing to an end with the US in danger of being completely isolated.4. With the King in prison, the chief commander came to power and ruled the country.5. With stability itself under threat, the reforms deserve all the support they can get.TranslationXI. (p. 214)1. It sounds like a good idea, but what if it’s a trick?2. Cities and towns in this area suffered a lot from the earthquake with Jiujiang and Ruichang among the worst-hit.3. He complained that they should not have got involved in it in the first place.4. For Mary’s sake, I can lend you my car to get around your transport problem.5. In theory it’s feasible to clone a child to harvest organs, but in practice it would be psychologically harmful to the chi ld.6. He published an article under the name of Braver which stresses the idea that the process of cloning animals would work for humans as well. XII. (p. 214)1. 你说你不会把时间浪费在约会上,但如果遇到吸引你的男子,你会怎么办呢?2. 为了帮助艾滋病患者,需要有新的措施,地方社团、非政府机构、政府和国际组织之间要建立密切的合作关系。
《初等数论》第三版习题解答
《初等数论》第三版习题解答第一章整数的可除性§1整除的概念·带余除法1.证明定理3定理3若a1,a2,,an都是m得倍数,q1,q2,,qn是任意n个整数,则q1a1q2a2证明:qnan是m得倍数.a1,a2,an都是m的倍数。
pn使a1p1m,a2p2m,存在n个整数p1,p2,又q1,q2,,anpnm,qn是任意n个整数qnanq1a1q2a2q1p1mq2p2m(p1q1q2p2即q1a1q2a2qnpnmqnpn)mqnan是m的整数2.证明3|n(n1)(2n1)证明n(n1)(2n1)nn(1n)(2nn(n1)(n2)n(1n)n(又n(n1)(n2),(n1)n(n2)是连续的三个整数故3|n(n1)(n2),3|(n1)n(n1)3|n(n1)(n2)(n1)n(n1)从而可知3|n(n1)(2n1)3.若a某0by0是形如a某by(某,y是任意整数,a,b是两不全为零的整数)的数中最小整数,则(a某0by0)|(a某by).1/77证:a,b不全为0在整数集合Sa某by|某,yZ中存在正整数,因而有形如a某by的最小整数a某0by0某,yZ,由带余除法有a某by(a某0by0)qr,0ra某0by0则r(某某0q)a(yy0q)bS,由a某0by0是S中的最小整数知r0a某0by0|a某bya某0by0|a某by(某,y为任意整数)a某0by0|a,a某0by0|ba某0by0|(a,b).又有(a,b)|a,(a,b)|b(a,b)|a某0by0故a某0by0(a,b) 4.若a,b是任意二整数,且b0,证明:存在两个整数,t使得abt,|t||b|2成立,并且当b是奇数时,,t是唯一存在的.当b是偶数时结果如何?证:作序列即存在一个整数q,使2222若b0则令,tabaq2bqb,则同样有t22(ii)当q为奇数时,若b0则令q1q1,tabab,则有222/77下证唯一性当b为奇数时,设abtb1t1则tt1b(1)b而tbb,t1tt1tt1b矛盾故1,tt122b为整数2当b为偶数时,,t不唯一,举例如下:此时3bbbbbb1b2(),t1,t122222§2最大公因数与辗转相除法1.证明推论4.1推论4.1a,b的公因数与(a,b)的因数相同.证:设d是a,b的任一公因数,d|a,d|b由带余除法abq1r1,br1q2r2,rnqn1,0rn1rnrn1(a,b)rnd|abq1r1,d|br1q2r2,┄,d|rn2rn1qnrn(a,b),即d是(a,b)的因数。
第3册全新版大学英语综合教程Unit8课后答案
第3册全新版大学英语综合教程Unit8课后答案第3册全新版大学英语综合教程Unit8课后答案全新版大学英语综合教程在内容设计上每单元围绕一个反映当代生活实际的主题展开,同时兼顾语言知识、应用技能、学习策略和跨文化交际等方面内容的有机融合,指导学生全面深入地获取并掌握与各主题有关的`语言文化知识及丰富的语料。
下面是店铺分享的全新版大学英语综合教程3答案,欢迎大家阅读!Text AContent questions1.at his mother’s funeral, the writer swore that one day he’d do something about conditions like hers2.one night,the writer went out for dreinks with another gentleman whose father had died of ALS. They talked about their parents then and wanted to do something as a legacy for them. The stem cell research company Stemagen thus came into existence3.they are concerned about the reproductive possibilities of cloning when Dolly was born4.human reproductive cloning is ethically wrong because the majority of reproductive clones in other species are actually abnormal,with very high miscarriage rates, very high stillbirth rates, fetal anomalies, death soon after birth,etc.5.the writer shows a positive attitude towards therapeutic cloning. He holds that therapeutic cloning does not involve any type of rist to human life and actually provides tremendous potential for the relief of suffering in human beings who are undergoing some awful things.6.the writer honestly thinks that someone will attempt human reproductive cloning and there is no way to stop it7.because by doing so, they could make cloning very real so that people around the world know that cloning is coming along8.their purpose in creating disease-specific stem cell lines is to study the causes of specific diseases,and then research a variety of treatments for these diseases. If the stem cell lines are created for any given individual and are later transplated back into the individual, they will not be rejected by the individual.9.the writer holds that in reality it is transcendent because when you look through the microscope, you see what you may have looked like a long ago, at least in part10.it brought teras to his eyes because the research was done for his mother,and he realized that if she had only been able to live a few years longer, maybe they could have used this technology to help her11.in the process of analysis, the embroys were destroyed by necessity. In other words, to get the genetic material from inside the cells to analyze it, they had to destroy the cell\12.because the writer thinks that logically, an embryo is not life, although it is a potential life. The vast majorityof embroys never become life—they just generate , don't implant and dieLanguage sense enhancement1) in some ways 2)make the most of 3)individual 4)replicated 5)roadmap 6)in place 7) resulst from 8)dissuade 9)Quite honestly 10)legislateVocabulary1.1) complications 2)tremendous 3)brillian 4)analysis \5)transplant , transplant 6)In a sense 7)consented 8)In some ways 9)eyesight10)in reality 11)implanted 12) procedures2. 1)focus 2)come forward 3)result from 4)go through5)carry out 6)work on 7)feed on 8)settled over3. 1)resulted from a childhood illness2)was condemmed by the trade unions as endangering jobs3)in place,even those with presistent, long-term mental illness can usually learn to manage their symptoms and live productive lives4)but apparently showed disapproval of his behaviour5)you should make the most of any advice which you can get from the interviewer4. 1)misconceptions, potential, make the most of ,2)donated, cntentious issue, and opponents3)a fraud , in some ways, condemn himII Collocation1)permission to adopt her2)a willingness to restart peace talks3)failure to find meaning in life4)his determination to realize his ideals5)attempt to blow up the bridge6)an opportunity to pursue a college degree下载文档润稿写作咨询。
08热力学第二定律习题解答
第八章热力学第二定律一选择题1. 下列说法中,哪些是正确的( )(1)可逆过程一定是平衡过程;(2)平衡过程一定是可逆的;(3)不可逆过程一定是非平衡过程;(4)非平衡过程一定是不可逆的。
A. (1)、(4)B. (2)、(3)C.(1)、(3) D. (1)、(2)、(3)、(4)解:答案选A。
2. 关于可逆过程和不可逆过程的判断,正确的是 ( )(1) 可逆热力学过程一定是准静态过程;(2) 准静态过程一定是可逆过程;(3) 不可逆过程就是不能向相反方向进行的过程;(4) 凡是有摩擦的过程一定是不可逆的。
A. (1)、(2) 、(3)B. (1)、(2)、(4) C. (1)、(4) D. (2)、(4)解:答案选C。
3. 根据热力学第二定律,下列哪种说法是正确的( )A.功可以全部转换为热,但热不能全部转换为功;B.热可以从高温物体传到低温物体,但不能从低温物体传到高温物体;C.气体能够自由膨胀,但不能自动收缩;D.有规则运动的能量能够变成无规则运动的能量,但无规则运动的能量不能变成有规则运动的能量。
解:答案选C。
4 一绝热容器被隔板分成两半,一半是真空,另一半是理想气体,若把隔板抽出,气体将进行自由膨胀,达到平衡后:( )A. 温度不变,熵增加;B. 温度升高,熵增加;C. 温度降低,熵增加;D. 温度不变,熵不变。
解:绝热自由膨胀过程气体不做功,也无热量交换,故内能不变,所以温度不变。
因过程是不可逆的,所以熵增加。
故答案选A 。
5. 设有以下一些过程,在这些过程中使系统的熵增加的过程是 ( )(1) 两种不同气体在等温下互相混合;(2) 理想气体在等体下降温;(3) 液体在等温下汽化;(4) 理想气体在等温下压缩;(5) 理想气体绝热自由膨胀。
A. (1)、(2)、(3)B. (2)、(3)、(4) C. (3)、(4)、(5) D. (1)、(3)、(5)解:答案选D。
二填空题1.在一个孤立系统内,一切实际过程都向着的方向进行。
数学分析课本(华师大三版)-习题及答案08
第八章 不定积分习题§1 不定积分概念与基本积分公式1. 验证下列等式,并与(3)、(4)两式相比照:(1)()()C x f dx x f +=⎰/; (2)()()C x f x df +=⎰2. 求一曲线()x f y =,使得在曲线上每一点()y x ,处的切线斜率为x 2,且通过点()5,2.3. 验证x x y sgn 22=是x 在()+∞∞-,上的一个原函数. 4. 据理说明为什么每一个含有第一类间断点的函数没有原函数? 5. 求下列不定积分:(1)⎰⎪⎪⎭⎫ ⎝⎛-+-dx x x x 32311; (2)⎰⎪⎪⎭⎫ ⎝⎛-dx x x 21; (3)⎰gxdx 2; (4)()⎰+dx x x232;(5)⎰-dx x2443; (6)()⎰+dx x x 2213; (7)⎰xdx 2tan ; (8)⎰xdx 2sin ;(9)⎰-dx x x x sin cos 2cos ; (10)⎰⋅dx x x x22sin cos 2cos ;(11)⎰•dt t t 2310; (12)⎰dx x x x ;(13)⎰⎪⎪⎭⎫⎝⎛+-+-+dx x x x x 1111; (14)()⎰+dx x x 2sin cos ; (15)()⎰•dx x x 2cos cos ; (16)()⎰--dx e e x x 3§2 换元积分法与分部积分法1. 应用换元积分法求下列不定积分:(1)()⎰+dx x 43cos ; (2)⎰dx xex 22;(3)⎰+dx x 121; (4)()⎰+dx x n1;(5)⎰⎪⎪⎭⎫⎝⎛-+-dx x x 2231131; (6)⎰+dx x 322;(7)⎰-dx x 38; (8)⎰-dx x3571; (9)⎰dx x x 2sin ; (10)⎰⎪⎭⎫ ⎝⎛+dx x 42sin 12π;(11)⎰+dx x cos 11; (12)⎰+dx x sin 11;(13)⎰xdx csc ; (14)⎰-dx xx 21;(15)⎰+dx x x 44; (16)⎰dx x x ln 1;(17)()⎰-dx x x 3541; (18)⎰-dx x x 283; (19)()⎰+dx x x 11; (20)⎰xdx cot ;(21)⎰xdx 5cos ; (22)⎰dx x x cos sin 1;(23)⎰-+dx e e xx 1; (24)⎰+--dx x x x 83322;(25)()⎰++dx x x 3212; (26)⎰+dx ax 221;(27)()⎰+dx ax23221; (28)⎰-dx xx 251;(29)⎰-dx xx31; (30)⎰++-+dx x x 1111.2. 应用分部积分法求下列不定积分:(1)⎰xdx arcsin ; (2)⎰xdx ln ; (3)⎰xdx x cos 2; (4)⎰dx x x3ln ;(5)()⎰dx x 2ln ; (6)⎰dx x arctan ; (7)()⎰⎥⎦⎤⎢⎣⎡+dx x x ln 1ln ln ; (8)()⎰dx x 2arcsin ;(9)⎰xdx 3sec ; (10)()⎰>±022a dx a x .3. 求下列不定积分:(1)()[]()()⎰-≠1/ααdx x f x f ; (2)()()[]⎰+dx x f x f2/1;(3)()()⎰dx x f x f /; (4)()()⎰dx x f e x f /.4. 证明:(1)若 ,3,2,tan ==⎰n xdx I n n ,则21tan 11----=n n n I x n I ; (2)若()⎰=xdx x n m I n m sin cos ,,则当0≠+n m 时,()()(),3,2,,2,1sin cos ,21sin cos ,1111=-+-++-=-+-++=-++-m n n m I nm n n m x x n m I nm m n m x x n m I n m n m5. 利用上题的递推公式计算:(1)⎰xdx 3tan ; (2)⎰xdx 4tan ;(3)⎰xdx x 42sin cos .6. 导出下列不定积分对于正整数n 的递推公式:(1)⎰=dx e x I kx n n ; (2)()⎰=dx x I nn ln ; (3)()⎰=dx x I n n arcsin ; (4)⎰=xdx e I nx n sin α. 7. 利用上题的递推公式计算:(1)⎰dx e x x 23; (2)()⎰dx x 3ln ; (3)()⎰dx x 3arcsin ; (4)⎰xdx e x 3sin . §3有理函数和可化为有理函数的不定积分1. 求下列不定积分:(1)⎰-dx x x 13; (2)⎰+--dx x x x 12722; (3)⎰+dx x 113; (4)⎰+dx x 114;(5)()()⎰+-dx xx 22111; (6)()⎰++-dx x xx 221222.2. 求下列不定积分:(1)⎰-dx x cos 351; (2)⎰+dx x 2sin 21;(3)⎰+dx x tan 11; (4)⎰-+dx xx x 221;(5)⎰+dx x x 21; (6)⎰+-dx xxx 1112. 总练习题求下列不定积分: (1)⎰--dx xx x 4312; (2)⎰xdx x arcsin ; (3)⎰+dx x 11; (4)⎰xdx e x 2sin sin ;(5)⎰dx ex; (6)⎰-dx x x 112;(7)⎰+-dx x x tan 1tan 1; (8)()⎰--dx x xx 322; (9)⎰dx x 4cos 1; (10)⎰xdx 4sin ; (11)⎰+--dx x x x 43523; (12)()⎰+dx x 1arctan ; (13)⎰+dx x x 247; (14)⎰++dx x x x1tan tan tan 2; (15)()⎰-dx x x 10021; (16)⎰dx xx2arcsin ; (17)⎰⎪⎭⎫⎝⎛-+dx x x x 11ln (18) ⎰dx xx 7cos sin 1; (19)⎰⎪⎭⎫⎝⎛+-dx x x e x 211;(20)⎰=dx uv I n n ,其中x b a v x b a u 2211,+=+=,求递推形式解.习题答案§1 不定积分概念与基本积分公式2.12+=x y .5.(1)C x x x x +-+-342342; (2)C x x x +-+3334ln 3; (3)C gx+2; (4)C x x x +•++6ln 629ln 94ln 4; (5)C x +arcsin 23; (6)()C x x +-arctan 31; (7)C x x +-tan ; (8)()C x x +-2sin 241;(9)C x x +-cos sin ; (10)C x x +--cot tan ;(11)C t+90ln 90; (12)C x +815158; (13)C x +arcsin 2; (14)C x x +-2cos 21; (15)C x x +⎪⎭⎫ ⎝⎛+3sin 31sin 21; (16)C e e e e x xx x ++----33313331; §2 换元积分法与分部积分法1.(1)()C x ++43sin 31; (2)C e x +2241; (3)C x +-12ln 21; (4)()C n x n ++++111;(5)()C x x++3arcsin 313arcsin ;(6)C x ++2ln 222; (7)()C x +--33892; (8)()C x +--3257103; (9)C x +-2cos 21; (10)C x +⎪⎭⎫ ⎝⎛+-42cot 21π;(11)C x+2tan; (12)C x x +-sec tan ; (13)C x x ++-cot csc ln ; (14)C x +--21;(15)C x +2arctan412; (16)C x +ln ln ;(17)()C x +--251101; (18)C x x ++-22ln28144;(19)C xx+-1ln; (20)C x +sin ln ; (21)C x x x ++-53sin 51sin 32sin ;(22)C x +tan ln ; (23)C e x+arctan ; (24)C x x ++-83ln 2; (25)()C x x x ++-+++2123121ln ;(26)C a x x +++22ln ; (27)C ax ax ++222;(28)()()()C x x x+---+--2522322121511321;(29)C x x x x x x ++------11ln 3625676616161216567; (30)C x x x +++++-11ln414.2.(1)C x x x +-+21arcsin ; (2)C x x x +-ln ; (3)C x x x x x +-+sin 2cos 2sin 2;(4)()C x x ++-1ln 2412; (5)()C x x x x x ++-2ln 2ln 2; (6)()C xx x +-+2arctan 1212;(7)()C x x +ln ln ; (8)()C x x x x x +--+2arcsin 12arcsin 22;(9)()C x x x x +++tan sec ln tan sec 21; (10)C x a x a a x x +⎪⎭⎫ ⎝⎛+±±±22222ln 21.3.(1)()()C x f +++111αα; (2)()()C x f +arctan ; (3)()C x f +ln . 5.(1)C x x ++cos ln tan 212; (2)C x x x ++-tan tan 313;(3)C x x x x +--4sin 641sin cos 611633. 6.(1)11--=n kx n n I kn e x k I ; (2)()1ln --=n nn nI x x I ;(3)()()()2121arcsin 1arcsin -----+=n n nn I n n x x n x x I ;(4)()()[]21221cos sin sin 1---+-+=n n ax n I n n x n x a x e an I . 7.(1)C x x x e x+⎪⎭⎫⎝⎛-+-83434321232;(2)()()[]C x x x x +-+-6ln 6ln 3ln 23;(3)()()C x x x x x x x +----+222316arcsin 6arcsin 13arcsin ;(4)()C x x x x x e x+-+-cos 3sin 3cos sin 3sin 10123. §3有理函数和可化为有理函数的不定积分1.(1)C x x x x +-+++1ln 2323; (2)()C x x +--34ln 2; (3)()C x x x x +-++-+312arctan 3111ln 6122; (4)C x x x x x x +-++-++22212arctan 421212ln 82; (5)()()C x x x x x ++---+--141arctan 211ln 811ln 4122; (6)()()C x x x x ++-+++-12arctan 251222352; 2.(1)C x +⎪⎭⎫ ⎝⎛2tan 2arctan 21; (2)C x +⎪⎪⎭⎫ ⎝⎛tan 26arctan 66; (3)C xx x +++2sin cos ln 21; (4)C x x x x +-++--21432512arcsin87; (5)C x x x ++++221ln ; (6)C x x x x +---+22111ln. 总练习题(1)C x x x +--4312134534132454; (2)C x x x x x +-+-22141arcsin 41arcsin 21; (3)()C x x ++-1ln 22; (4)()C x e x +-1sin 2sin ;(5)()C x ex+-12; (6)C x+1arccos ;(7)C x x ++sin cos ln ; (8)()C x x x +-----221232ln ; (9)C x x ++3tan 31tan ; (10)C x x x ++-4sin 3212sin 4183; (11)C x x x +-++-2112ln 32; (12)()C x x x x x ++++-+22ln 1arctan ;(13)()C x x ++-2ln 214144; (14)C x x +⎪⎪⎭⎫ ⎝⎛+-31tan 2arctan 32; (15)()()()C x x x +-+------979899197114911991; (16)C xx x x +-+--211lnarcsin 1; (17)C x x x x ++⎪⎭⎫ ⎝⎛-+-11ln 212; (18)C x x +⎪⎭⎫⎝⎛+5tan 511tan 2; (19)C xe x++21; (20)()()[]121121122--++=n n n I b a b a n u v b n I典型习题解答1.(§1 第5题(13))求⎰⎪⎪⎭⎫ ⎝⎛+-+-+dx x x x x 1111 解:C x dx x xx x dx x x x x +=⎪⎪⎭⎫⎝⎛--+-+=⎪⎪⎭⎫⎝⎛+-+-+⎰⎰arcsin 211111111222.(§2 第1题(21))求⎰xdx 5cos解:()C x x x x d x xdx ++-=-=⎰⎰53225sin 51sin 32sin sin sin 1cos3.(§2 第1题(23))求⎰-+dx e e x x 1解:C e e de dx e e xx x x x+=+=+⎰⎰-arctan 112 4.(§2 第2题(9))求⎰xdx 3sec()C x x x x xdx xdxxdx x x xdxx x x xdxx x x x xd xdx +++=∴+-=--=-==⎰⎰⎰⎰⎰⎰⎰tan sec ln 21tan sec 21sec sec sec tan sec sec 1sec tan sec sec tan tan sec tan sec sec 33223解:5.(§2 第题(2))若()⎰=xdx x n m I n m sin cos ,,则当0≠+n m 时,()()(),3,2,,2,1sin cos ,21sin cos ,1111=-+-++-=-+-++=-++-m n n m I nm n n m x x n m I nm m n m x x n m I n m n m证明:()()()()()()()2,1sin cos ,,21sin cos ,cos sin 11cos sin 111sin cos cos cos 1sin 111sin cos sin cos 11sin 1sin cos 1sin cos ,11112112211211111-+-++-=-+-++=∴+--+-++=-+-++=-+++=+=-++--+--+--++-+-⎰⎰⎰⎰⎰n m I n m n n m x x n m I n m I nm m n m x x n m I xdx x n m xdx x n m n x x xdx x x n m n x x xdx x m n xn x x n x xd n m I n m n m mn m n n m m n n m m n n m n m 同理, 6.(§3 第1题(4))求⎰+dx x 114解:()()⎰⎰⎰⎰-⎪⎭⎫ ⎝⎛+⎪⎭⎫ ⎝⎛+++⎪⎭⎫ ⎝⎛-⎪⎭⎫ ⎝⎛-=+--+=+211211211112111224224x x x x d x x x x d dx x x x dx xC xx x x x x +++-+--=2121ln 24121arctan221。
全新版大学英语第三册同步辅导答案第8单元
Key to Unit 8Text A Human Cloning: A Scientist’s Story课前预习Directions: Read the text and find out the English versions for the following expressions.1. 引起了世人的关注draw attention from the world (P.226, Introductory paragraph)2. 失明,丧失视力lose eyesight (P.226, Para.1)3. 去世pass away (P.226, Para.1)4. 集中于,关注在focus on (P.227, Para.5)5. 从医学观点看from a medical standpoint (P.227, Para.6)6. 与它相关的宗教问题religious issues associated with it (P.227, Para.6)7. 极大的可能性tremendous potential (P.227, Para.8)8. 缓解痛苦the relief of suffering (P.227, Para.8)9. 经受,经历go through (P.227, Para.8)10. 在某种程度上in some ways (P.227, Para.9)11. 充分利用make the most of (P.227, Para.9)12. 适当的,在合适的位置in place (P.228, Para.10)13. 由……引起,是……的结果result form (P.228, Para.10)14. 劝阻……做……dissuade... from... (P.228, Para.10)15. 通过立法加以阻止legislate... away (P.228, Para.11)16. 被说成是……be spoken of as... (P.228, Para.12)17. 科学界scientific community (P.228, Para.12)18. 基因材料,遗传物质genetic material (P.228, Para.16)19. 干细胞系列stem cell lines (P.229, Para.17)20. 至多,不超过no more than (P.229, Para.17)21. 事实上,实际上in reality (P.229, Para.19)22. 科学造假行为scientific fraud (P.229, Para.21)23. 由于客观情况的需要,不得已by necessity (P.230, Para.22)24. 在某种意义上in a sense (P.230, Para.25)巩固应用I. Directions: Now you’ve learned T ext A in detail. Let’s check how much you’ve learned from it! Please translate the Chinese expressions in the following sentences into English. Be sure to use expressions from the text.1.She developed complications related to diabetes (P.226, Para.1) (患上糖尿病引起的并发症).When she lost her eyesight and most of her ability to walk (大部分行走能力), it was absolutely horrifying (惊恐万分) for me.2.The reason is that the majority of (P.227, Para.6) (大多数) reproductive clones in otherspecies are actually abnormal, with very high miscarriage rates (高流产率), death soon after birth, et cetera (等等).3.I didn’t anticipate it would create a firestorm of controversy (P.228, Para.14) (掀起轩然大波)that it’s created.4.I think by coming forward (P.228, Para.15) (自告奋勇,主动) and putting a face to it we madeit very real. I believe that very soon it will be used therapeutically, so I think our purpose was served (P.228, Para.15) (我们的目的达到了).5.If the stem cell lines are created for any given individual (P.229, Para.18) (针对某一特定个体)and are later transplanted back into (被移植回) the individual, they will not be rejected (排异) by the individual.6.When I looked down and saw that cloned blastocyst (胚泡), it brought tears to my eyes (P.229,Para.20) (使我热泪盈眶).7.It does n’t make sense (P.230, Para.27) (讲得通,合乎情理) to me that it’s such an emotionaland contentious topic (惹人激动,引起争议的话题).II. Language FocusEx. I. Translate the following English expressions into Chinese and Chinese into English.1. 死于分娩引起的并发症die from complications related to childbirth (P.237, I-1-1)2. 巨大的差异tremendous difference (P.237, I-1-2)3. 行为分析behavior analysis (P.237, I-1-4)4. 骨髓移植bone marrow transplant (P.237, I-1-5)5. 尊严与价值感 a sense of dignity and worth (P.237, I-1-10)6. 常规清洁程序routine cleaning procedures (P.238, I-1-12)7. 生物的多样性the variety of life (P.238, I-2-3)8. 进行医疗检查go through a medical examination (P.238, I-2-4)9. 适当的治疗treatment in place (P.239, I-3-3)10. 捐赠的器官donated organs (P.239, I-4-2)11. 一个正直的人 a man of integrity (P.240, I-4-3)12. 出现,开始存在come into existence (P.242, Cloze-2, L.1)13. 抱有…的目的with the intention/aim of (P.242, Cloze-2, L.4)14. 从技术观点来看from a technical standpoint (P.242, Cloze-2, L.17)15. stark reality of the financial crisis 金融危机的严酷现实(P.237, I-1-6)16. nursing home 疗养院,养老院(P.237, I-1-10)17. make an urgent appeal for 紧急呼吁(P.238, I-2-2)18. work on sophisticated project 从事复杂高级的项目(P.238, I-2-6)19. a feeling of dread settled over her 一种恐惧的感觉笼罩着她(P.238, I-2-8)20. live a productive live 过充实的生活(P.239, I-3-3)21. deeply held values 根深蒂固的价值观(P.242, Cloze-1, L.9)22. out of line with…与……不一致,不协调(P.242, Cloze-2, L.11) Ex. II. Please translate the Chinese expressions in the following sentences into English. Be sure to use expressions from the exercises.1. Silent birds arrive in their full songs and lifeless flowers burst forth in brilliant bloom (P.237, I-1-3) (绽放出灿烂的花朵).2. In reality they live in an isolated world (P.237, I-1-10) (事实上他们生活在一个孤立的世界) cut off from both family and the wider community.3. Museums that focus more on concepts and ideas (P.238, I-2-1) (更多地关注在观念和想法上) than on collections of objects.4. His parents stayed calm but apparently showed disapproval of his behavior (P.239, I-3-4) (显示出对他行为的不赞同) .5. What really matters is whether we make the most of what nature has provided (P.239, I-4-1) (我们是否充分利用了大自然的馈赠).6. Using financial incentives to increase the supply of transplant organs has been a contentious issue (P.240, I-4-2) (一个引起争议的话题), and the divisions among supporters and opponents (P.240, I-4-2) (支持者和反对者之间的分歧) are deep and emotional.III. Language EnhancementEx. I. Translate the following Chinese sentences into English.1. 互联网从某种意义上说就像一个大的团体项目,全世界数百万的人都有机会为这一项目做贡献。
结构化学习题解答(第八章)
rC C (1 a / 4) 2 (1 b / 4) 2 (1 c / 4) 2 a 3 4 3 356.7 pm 4 154.4 pm 密度D ZM / NV (8 12.0 g / 6.02 1023 ) /(356.7 1010 cm) 3 3.51g cm
[8.31] 已知NaCl晶体立方晶胞参数a=563.94pm实验测得衍射 111的衍射角θ=5.100,求实验所用X射线的波长。 [解 ]: 2 2 2 1/ 2 hkl
d
a /(h k l )
563.94 pm / 3 325.59 pm d 2 sin 325.59 pm 2 sin 5.10 57.9 pm
[8.26] 用Cu Kα射线测得某晶体的衍射图,从中量得 以下数据。试查PDF卡片,鉴定此晶体可能是什么。 2θ/(0) 27.3 31.8 45.5 53.9 56.6 66.3 75.5 I/I0 18 100 80 5 21 20 20
[解]:利用PDF卡片鉴定晶体时,需先把衍射角2θ数据 换算成d值(d=λ/2Sinθ)如下:(λ=154.2pm) 2θ/(0) 27.3 31.8 45.5 53.9 56.6 66.3 75.5 d/pm 326.7 281.4 199.4 170.1 162.6 141.0 125.9 I/I0 18 100 80 5 21 20 20 按这组d-I/I0值查表,得知它为NaCl晶体。
rTi O (0.31a) 2 (0.31a) 2 0.438a 0.438 458pm 201pm
[8.19] 金属镍的立方晶胞参数a=352.4pm,试求d200,d111,d220。 [解]:立方晶系的衍射指标hkl和衍射面间距dhkl的关系为:
大学物理3第08章习题分析与解答
习题8-6图IOR 第八章 恒定磁场8-1 均匀磁场的磁感强度B 垂直于半径为r 的圆面.今以该圆周为边线,作一半球面S ,则通过S 面的磁通量的大小为[ ]。
(A) B r 22π (B) B r 2π (C) 0 (D) 无法确定 分析与解 根据高斯定理,磁感线是闭合曲线,穿过圆平面的磁通量与穿过半球面的磁通量相等。
正确答案为(B )。
8-2 下列说法正确的是[ ]。
(A) 闭合回路上各点磁感强度都为零时,回路内一定没有电流穿过(B) 闭合回路上各点磁感强度都为零时,回路内穿过电流的代数和必定为零 (C) 磁感强度沿闭合回路的积分为零时,回路上各点的磁感强度必定为零(D) 磁感强度沿闭合回路的积分不为零时,回路上任意点的磁感强度必定为零分析与解 由磁场中的安培环路定理,磁感强度沿闭合回路的积分为零时,回路上各点的磁感强度不一定为零;闭合回路上各点磁感强度为零时,穿过回路的电流代数和一定为零。
正确答案为(B )。
8-3 磁场中的安培环路定理∑⎰=μ=⋅nLI1i i0d l B 说明稳恒电流的磁场是[ ]。
(A) 无源场 (B) 有旋场 (C) 无旋场 (D) 有源场分析与解 磁场的高斯定理与安培环路定理是磁场性质的重要表述,在恒定磁场中B 的环流一般不为零,所以磁场是涡旋场;而在恒定磁场中,通过任意闭合曲面的磁通量必为零,所以磁场是无源场;静电场中E 的环流等于零,故静电场为保守场;而静电场中,通过任意闭合面的电通量可以不为零,故静电场为有源场。
正确答案为(B )。
8-4 一半圆形闭合平面线圈,半径为R ,通有电流I ,放在磁感强度为B 的均匀磁场中,磁场方向与线圈平面平行,则线圈所受磁力矩大小为[ ]。
(A) B R I 2π (B)B R I 221π (C) B R I 241π (D) 0 分析与解 对一匝通电平面线圈,在磁场中所受的磁力矩可表示为B e M ⨯=n IS ,而且对任意形状的平面线圈都是适用的。
08练习题解答:第八章 单总体假设检验
第八章 单总体假设检验练习题:1. 某市去年进行的调查显示该市市民上下班花费的平均时间为75.45分钟。
今年 有两条地铁线路开通,今年某报社在全市随机抽取了60名市民对其上下班时间进行调查,调查结果如下表所示:(单位:分钟)60 60 56 48 48 70 80 70 55 70 75 65 120 60 54 54 20 50 60 60 90 58 36 80 60 68 90 58 64 64 80 40 45 58 54 50 40 58 70 58 50 48 62 64 55 36 80 40 48 66 585850386810080908865(1)请计算这60名市民今年每天上下班在公交车上花费的时间的平均数x 和标准差S 。
(2)请陈述研究假设1H 和虚无假设0H 。
(3)若显著性水平为0.05,能否认为该市市民上下班变得更加便利了。
解: (1) x 60+60++88+653700== 61.676060= ,17.10S ====(2)研究假设1H :75.45μ<虚无假设0H :75.45μ≥ (3)采用Z 检验:,===-61.6775.45 6.24x Z ,假设方向明确,采用一端(左)检定,显著性水平为0.05时,否定域 1.65Z ≤-,检验统计值(Z=-6.24<-1.65)落在否定域中,因此可以否定虚无假设,接受研究假设,也就是说在0.05的显著性水平上,该市居民上下班变得更加便利了。
2.某大学去年的调查显示,该校学生每周体育锻炼平均时间为5.2个小时,今 年在全校6000名学生中随机抽取了20名学生进行调查,得到下面的数据:(单 位:小时)5.54 3 3 3.5 2.5 5 96 4 42812768924(1)请计算这20学生每天体育锻炼时间的平均数和标准差S 。
(2)请陈述研究假设1H 和虚无假设0H 。
(3)若显著性水平为0.05,能否认为该校学生体育锻炼的时间有所增加?解:(1) 5.5426107.55.38220x ++++==== ;2.72S ====(2)研究假设1H : 5.2μ>虚无假设0H : 5.2μ≤ (3)采用小样本t 检验:df=20-1=190.288x x t SE μ-==== 假设方向明确,采用一端(右端)检验,显著性水平为0.05时否定域为 1.729t ≥, 检验统计值(t =0.028<1.729)没有落在否定域中,因此不能否定虚无假设,即在0.05的显著性水平下,不能认为该校学生体育锻炼的时间有所增加。
电路理论课后习题解答08
电路理论课后习题解答08第八章相量法8-1如果已知I1??5秒?314t?60?? a、 i2?10罪?314t?60?? a、 i3?4cos?314t?60?? a、(1)写出上述电流的相量并绘制相量图;(2) I1和I2之间以及I1和I3之间的相位差;(3)绘制I1的波形图;(4)若将i1表达式中的负号去掉将意味着什么?(5)求i1的周期t和频率f。
解决方案:(1)I1??5秒?314t?60 5秒?314t?60?? 180度?A.5秒?314t?120度?i2?10si?n3t1?4.因此,I1、I2和I3的相量表达式为.??6?041ts?3?1?0coo30i1?52??120a,i2?o.102??30a,i3?o.42?60aO其相量图如图(a)所示5+ji1?t?060?120??0??30+1-2.5-5t(a)题解8-1图(b)(2)? 12?? 1.2.90度?13?? 1.3.有关180o(3)波形图,请参见图(b)(4)意味着i1的初相位超前了180o,即i1的参考方向反向。
(5)t?220ms,f?1t?50hz8-2如果已知具有相同频率的两个正弦电压的相量为U1?50? 30,u2??100?? 150伏o..其频率f?100hz。
求:(1)写出u1,u2的时域形式;(2)u1与u2的相位差。
解决方案:(1)OU1?T502cos?2.英尺?30度??502cos?628t?30点?五、u2?t1002cos?2?ft?150.o.o??1002cos?628t?150?180oo??1002cos?628t?30o?v(2) u1?50? 30岁,u2?100? 30ov,所以相位差是??0,即它们是同相的。
8-3已知三个电压源的电压分别为:ua?2202cos??t?10??v,乌布?2202cos??T110? 五、加州大学?2202cos??T130?? v、求:(1)三个电压之和;(2)uab,ubc;(3)画出它们的相量图。
控制工程基础课件,王益群,孔祥东,第三版第八章
Gh ( j )
相频特性为
sin 2 T (1 - cos T )2
T
sin(T / 2) T / 2
Gh ( j ) arctan
- (1 - cos T ) T T arctan - tan sinT 2 2
第八章 计算机采样控制系统
1 E ( j ) T
根据采样频率 s 的大小, ( j ) 可能有两种情况:一种是 s 2max ,采样信号的 E 频谱不会发生重迭,如图8-6a所示。另一种是s 2max 谱发生重迭,如图8-6b所示。
E * ( j ) E * ( j )
k -
E ( j( k s ))
香农(Shannon)采样定理 只有当 s 2max 时,采样后的离散信号才能保持原连续信 号的信息,可无失真地恢复为原来的连续信号。
第八章 计算机采样控制系统
§8-2 信号的采样与保持 三、保持器
采用时域外推原理的装置。 保持器(Holder): 1.零阶保持器概念 零阶保持器是采用恒值外推规律的保持器。 它的作用是把采样时刻 kT 的采样值e(kT ) 恒定不变地保持(外推)到下一采样时刻 ( k 1)T 。
(n) y(k ) c1(n-1) y(k ) cn -1y(k ) cn y(k )
d 0 (m) r (k ) d1(m-1) r (k ) d n -1r (k ) d n r (k )
第八章 计算机采样控制系统
§8.4 采样控制系统的数学模型
第八章 计算机采样控制系统
§8-3 Z变换和Z反变换
解 因为 F ( s )
a 1 1 - at ,由拉氏反变换知,f (t ) 1 - e ,故由例8-1和 s(s a) s s a
计算机组成与设计第三版-第八章课后答案
1.
中断是一种重要的输入输出方式,它不仅可以减少CPU用于完
成入出操作的时间,而且使设备准备数据(完成读写操作)和CPU并行执行,
还支持多台设备并发地和CPU交换数据,从而极大的提高了计算机系统的总
体性能;在用多台处理机构建成一个计算机系统时,中断是解决I/O设备之
间进行信息传送和功能分配、任务切换的关键机制。
堆栈中,保存信息一定要完整完成,以保证被停下来的程序得以继续正常运行。
4.
判别中断源,转中断服务:找出中断服务程序的入口地址。多个中断源
时找出中断优先级最高的中断源。
5.
开中断,以便尽快地进入可以响应更高级别中断请求的运行状态。
6.
若有更高级别中断请求到来,则进行新的中断响应过程。
7.
执行中断服务程序,完成后准备返回主程序,为此,执行关中断。
2.
硬件故障报警与处理;如果出现硬件故障,发出硬件故障中断,
由CPU启动相关的中断处理程序来处系统的使用效率。
4. 统。
支持实时处理功能,可以把计算机用于各种过程的实时控制系
5.
中断是支持人机交互与联系的重要手段。
5
8.29简述一次中断处理的完整过程。
接口卡上通常还有一到几个用于数据缓冲的寄存器,以便适当降低 CPU和设备直接耦合的程度,解决它们运行速度不匹配的矛盾。
接口卡上通常还有处理中断请求、屏蔽和判优等逻辑线路,这是属 于总线从设备类型的设备主动向CPU提出自己操作要求的重要机制。
4
8.24中断在计算机系统中的作用有哪些?
答:中断是在完整运行一个程序的过程中,断续地以“插入”方式执行一 个完成特点处理功能的程序段。其作用:
答:一个完整的中断过程由中断请求、中断响应和中断处理3个阶段组成。
听力教程第三册答案UNIT8【范本模板】
UNIT 8Section One Tactics for ListeningPart 1 Spot DictationOnce upon a time, all- or almost all- businesses were (1) greedy and rapacious,sparing a thought for their (2)workers or the environment only in order to (3) work out how to exploit them. Then bosses found their (4)consciences, guided (or sometimes forced) by (5) customers or critics from the (6)non—profit world。
They discovered the idea that companies should not exist only to make a profit but to (7) serve society。
Thus corporate social responsibility (CSR) got its (8)start as a business fashion,and it is now hard to find a firm that has not (9) come up with an earnest (10)statement about its relations with the wider world. Thanks to this development,everyone, both (11)within and outside the business, will live happily (12) ever after。
Or will they?In the past two (13) decades, as CSR has become more and more popular,its (14)virtues have passed more or less (15)unquestioned。
商务英语综合教程第三册第8单元考学练答案
Unit 8 International TradeI Note-taking, Retelling & Summarizing1. International trade is the exchange of goods and services across international boundaries or territories.2. In most countries, it represents a significant share of GDP.3. While international trade has been presented throughout much of history like the Silk Road and Amber Road, its economic, social, and political importance has been on the rise in recent centuries.4. Industrialization, advanced transportation, globalization, multinational corporations, and outsourcing are all having a major impact.5. Increasing international trade is the primary meaning of "globalization".6. International trade is also a branch of economics, which, together with international finance, forms the larger branch of international economics.7. Traditionally trade was regulated through bilateral treaties between two nations.8. For centuries under the belief in Mercantilism most nations had high tariffs and many restrictions on international trade.9. In the 19th century, especially in Britain, a belief in free trade became paramount and this view has dominated thinking among western nations for most of the time since then.10. In the years since the Second World War, multilateral treaties like the GATT and World Trade Organization have attempted to create a globally regulated trade structure.II VocabularyA. Choose the best answer for each of the following.1. A2. C3. D4. B5. D6. B7. D8. C9. D10. B11. B12. B13. D14. A15. BB. Fill in the blanks with the correct form of the words given in the brackets.1.Abundance2.adjustparatively4.Consuming5.endowed6.externals7.logic8.induced9.invalidated10.lobbying11.multiplication12.objective13.remaining14.uneasy15.wreckedIII. Proofreading and Error Correction[1] for[2] also[3] cases[4]√[5] another[6] Surprising ly[7]would[8] coconuts[9] at[10] soIV. Sentence Transformation1.He convinced me of the necessity of making further enquiries before paying the money.2.We had a good time despite _the terrible whether____.3..His frequent depression is due to his inability to get about very much.4.There is no excuse _for being rude______.5.It is not worth waiting since we missed the last bus.V. TranslationA.1.It is likely that the court case in the future will be even messier than what she predicts now.2.In other words, when the wind is blowing at 120 kilometers per hour, most waves will be about twelve meters.3.It's worth reflecting how events of the past would have looked had tomorrow's technology been available at the time.4.The most exciting moment of the trip is when I climbed the Great Wall5.It still remains a mystery where and why he killed her.B.1.世界贸易组织,通过制定国际贸易的准则成为促进国际贸易的主要国际机构。
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(6) (7) (8) (9)
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月末库存成本=2 700×21.2=57 240(元) 本月耗用成本= 3 000 × 20 + 2 400 × 22 + 600 × 24 − 57 240 = 127 200 − 57 240 = 69 960 (元)
习题二 银行存款余款调节表 2000 年 12 月 项目 企业银行存款账面余额 加: 企业未入账的收入款项 (1) 存款利息 (2) 代收江西代款 减: 企业未入账的支出款项 (1) 代付电费 调节后存款余额 金额 42 594 488 11 880 3 120 51 842 项目 银行对账单金额 加:银行未入账的收入款项 (1) 存入转账支票 减:银行未入账的支出款项 (1) 开出支票#12359 金额 24 218 28 000
376 51 842
习题三
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第八章 财产清查—习题解答 200x 年 月 12 日 31 (1) (2) 凭证 编号 摘要 批准前: 盘盈设备一台 丢失电焊机一台 会计科目 借方金 额 17 500 17 500 1 200 1 600 2 800 49 49 148 148 2 500 2 500 300 300 78 78 17 500 17 500 1 200 1 200 49 49 148 148 1 500 1 000 2 500 300 300 78 78 1 460 1 460 2 400 2 400 贷方金 额
第八章 财产清查—习题解答 习题一 实地盘存制 以 存计耗) 实地盘存制(以实存计耗 (实地)月末库存数量=2 660 千克(盘存) 加权平均单价=
3 000 × 20 + 2 400 × 22 + 600 × 24 = 21.2 (元/千克) 3 000 + 2 400 + 600
月末库存成本= 2 660 × 21.2 = 56 392 (元) 本月耗用成本= 3 000 × 20 + 2 400 × 22 + 600 × 24 − 56 392 = 127 200 − 56 392 = 70 808 (元)
永续盘存制:(以账存计耗 永续盘存制 以账存计耗) 以账存计耗 (账面)月末库存数量=3 000+2 400+600−1 800−1 500=2 700(千克)(账存) 加权平均单价=
Hale Waihona Puke 3 000 × 20 + 2 400 × 22 + 600 × 24 = 21.2 (元/千克) 3 000 + 2 400 + 600
(3) (4) (5) (6) (7)
盘盈甲材料 7 千克 盘亏乙材料 车间在产品损失 盘亏丙材料 盘盈现金 批准后 盘盈设备转账 盘亏电焊机转账 盘盈甲材料转账 盘亏乙材料转账 应收保险赔款, 余额转账 盘亏丙材料 现金溢余转账 无法收回应收账 款转账 无法支付应付账 款转账
(1) (2) (3) (4) (5)
借: 固定资产 贷: 待处理财产损溢 借: 待处理财产损溢 累计折旧 贷: 固定资产 借: 原材料—甲材料 贷: 待处理财产损溢 借: 待处理财产损溢 贷: 原材料—乙材料 借: 待处理财产损溢 贷: 生产成本 借: 待处理财产损溢 贷: 原材料—丙材料 借: 现金 贷: 待处理财产损溢 借: 待处理财产损溢 贷: 以前年度损益调整 借: 营业外支出 贷: 待处理财产损溢 借: 待处理财产损溢 贷: 管理费用 借: 管理费用 贷: 待处理财产损溢 借: 其他应收款—保险赔款 营业外支出 贷: 待处理财产损溢 借: 其他应收款—某保管员 贷: 待处理财产损溢 借: 待处理财产损溢 贷: 营业外收入 借: 坏账准备 贷: 应收账款 借: 应付账款 贷: 营业外收入