辽宁省普兰店市第一中学2018年10月2018~2019学年度高一第一学期期中考试数学试题及参考答案教师专用

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2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试英语试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试英语试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试英语试题时间:100分钟满分:120分范围:必修一;M1~M5(新题型加续写)注意事项:1.答题前填写好自己的姓名、班级、考号等信息2.请将答案正确填写在答题卡上第二部分阅读理解(共两节,满分35分)第一节(共10小题;每小题2.5分,满分25分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项,并在答题纸上将该项涂黑。

AIf you don't use a dictionary.What should you do instead?The first thing you can do is trying to guess what the word means.Often the surrounding context gives a very clear idea of the meaning of the word.Even if you can't work out the meaning exactly,you may be able to get a vague idea,enough to enable you to continue reading.Sometimes it is impossible to guess the meaning of a word from the context and then you will have to decide whether the word is important enough to make it worthwhile stopping and looking it up in a dictionary or whether you can just pass it by.Many times in your reading,you will come across words which you don't know,but which do not prevent you from understanding all the main points of the text.You can make your dictionary used much more efficiently if you only look up the words which are necessary to understand the text and this means that you must develop the skill to decide whether the words are worth looking up.21. What does the underlined word "vague" mean?A.mysterious.B.not clear.C.exact.D.important.22. In our reading some words we don't knowA.help us to understand the surrounding context wellB.don't prevent us understanding the main points of the textC.will be remembered foreverD.are borrowed from other languages23. In this passag e the writerA.advised us to use the dictionary as much as possibleB.told us not to be discouraged when we use a dictionary in our English study.C.gave us some advice on how to deal with these unknown wordsD.introduced some ways to take notes in the course of reading.BHave you ever thought of quitting your job when you feel exhausted? Maybe most of you would say ―yes‖. After a particularly busy period at work, I decided to get away from it all by going on a hike in the mountains in southern France.Before I left, I read an interesting story in a magazine. It rea d, ―Once, while I was riding on a crowded bus, the man sitting next to me threw his cell phone out of the window when his phone rang. I was surprised. He looked at me, shrugged (耸耸肩) and looked away. I had no idea whether it was his or stolen or whether he even knew what a cell phone was or not, but he clearly wanted to be free of it, because it clearly troubled him. ‖Billions of people across the world use cell phones. Though cell phones are a wonderful way for communication, they often do t he exact opposite. Using cell phones can increase stress within families and friends.So when I recently returned home, I got rid of my cell phone. Now I go outside without taking my phone wi th me. I’ve noticed things in my neighborhood I never noticed before, such as gardens. I’ve met new people, started conversations with neighbors I didn’t speak to before and talked with some of my friends face to face instead of chatting over the phone.Instead of keeping me off from the world, stopping using my cell p hone has helped me get even closer to my family and friends.24. According to the story, the man on the bus threw away his cell phone because ______.A. it didn’t work properlyB. it was stolen from someone elseC. he didn’t like the phone’s styleD. he didn’t want to be bothered by it25. We can learn from the passage that cell phones ______.A. are too expensive for many peopleB. are of no use to the authorC. can also get people into troubleD. can make life more interesting26. What can we learn about the author?A. He wan ts t o own a garden now.B. He always chatted with his neighbors.C. He used to take his cell phone when going outside.D. He once threw away his cell phone.27. The main purpose of the passage is to ______.A. tell us not to let cell phones control our livesB. encourage others to hike with him in FranceC. share his experiences in France with usD. teach us how to get along with neighborsCAlexis, 17, sat quietly in the passenger seat of her dad’s car. She let her eyes lazily scan, the landscape for wildlife. Then a deer came into view about 200 yards in front of them. ―Dad, there’s a deer there!‖ Alexis said. It w as a male deer with sharp antlers(角) on each side of its head.As the car moved closer, Alexis saw that the deer’s head was bent toward the ground. Then she heard a scream and saw an arm fly up near the deer’s head. Alexis realized the deer was attacking a woman. Sue, a 44-year-old mother, had been out for her morning run. The deer followed her and edged closer. ―I knew I was in trouble,‖ Sue says. She went to pick up a stick for self-defense, and the deer charged. It lifted her with its antlers and threw her into the air. Sue could feel blood flew down her leg. Within seconds, the deer had pushed her off the road.When Alexis and her father pulled up, the deer was throwing Sue like a doll. Alexis looked into the woman’s terrified eyes, and before her father had even stopped the car, the teenager jumped quickl y out of the car and ran toward the deer. ―I was kicking it to get its attention,‖ she says. Then her father, who had followed his daughter, pushed the deer away from the women.Alexis helped Sue i nto the car, and then applied a piece of cloth to Sue’s injured leg. ―We’re going to get you to a hospital,‖ Alexis said. Then she heard her father shout loudly. He had been knocked to the ground. Alexis took hold of a hammer from the car and ran to where her father lay on his back. She beat the deer’s head and neck, but the blows didn’t scare it away. ―I was losing faith,‖ she says. ―A couple more strikes, Alexis,‖ said her father. ―You can do it.‖ Turning the hammer around, Alexis closed her eyes and beat the deer’s neck with all her strength. When she opened her eyes, the deer was running away. Alexis got in the driver’s seat and sped toward the nearest hospital.After Sue was treated, she tearfully thanked her rescuers. ―You expect a teenage girl to get on the phone and call for help,‖ she says, ―not to beat up a deer.‖28.What was Sue doing when she was attacked by the deer?A.She was driving home. B.She was resting on the road.C.She was taking exercise. D.She was feeding wild animals.29.The underlined word ―edged‖ in paragraph 2 probably means _________.A.changed B.moved C.attacked D.cut30.What did Alexis do to save Sue?A.She pushed the deer away.B.She hit the deer with her feet.C.She drove the car to hit the deer.D.She beat the deer with a hammer.第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

辽宁省普兰店市第一中学2019届高三上学期期中考试英语试卷(含答案)

辽宁省普兰店市第一中学2019届高三上学期期中考试英语试卷(含答案)

2018—2019学年度上学期月考试卷高三英语范围:高考范围第一部分听力(略)第二部分阅读理解(共两节, 满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。

AYou probably know who Hillary Diane Rodham Clinton is, but you may not have heard of Margaret Munnerlyn Mitchell if you are not interested in foreign literature. Of the outstanding ladies listed below, who is your favorite?Jane Austen (16 December, 1775-18 July, 1817)Jane Austen, a famous English writer, was born at Steventon, Hampshire. She began writing early in life, although the prejudices (偏见) of her times forced her to have her books published anonymously (匿名).She wrote many books of romantic fiction about the gentry (贵族). Her works made her one of the great masters of the English novel. Only four of her novels were printed while she was alive. They were Sense and Sensibility (1811), Pride and Prejudice (1813), Mansfield Park (1814) and Emma(1815).Charlotte Bronte (21 April, 1816-31 March, 1855)She first published her works, including Jane Eyre, under the false name of Currer Bell. Her first novel, The Professor, was rejected by many publishers. It was not printed until 1857. She is famous for her novel Jane Eyre (1847), which was very popular when it was printed. Jane Eyre was a strong story of a plain, brave, clever woman struggling with her passions, reasons, and social condition.Margaret Munnerlyn Mitchell (8 November, 1900-16 August, 1949)She was an American author and journalist, a lifelong resident and native of Atlanta, Georgia. One novel by Mitchell was published during her lifetime, the American Civil-War-Era novel, Gone with the Wind, for which she won the National Book Award for Most Distinguished Novel of 1936 and the Pulitzer Prize for Fiction in 1937. In more recent years, a collection of Mitche ll’s girlhood writings and a novel she wrote as a teenager, Lost Laysen, have been published. A collection of articles written by Mitchell for The Atlanta Journal was republished in book form.21. Why did Jane Austen publish her books with a false name?A. She lacked confidence.B. She was not well educated.C. Women were discriminated.D. Women were well protected.22. Which novel was set in the background of war?A. Sense and Sensibility.B. Gone with the Wind.C. Lost Laysen.D. The Professor.23. Who won the most prizes for her works?A. Margaret Munnerlyn Mitchell.B. Charlotte Bronte.C. Hillary Diane Rodham Clinton.D. Jane Austen.24. What can we infer about the women mentioned in the text?A. They were all fond of poetry.B. They all died in their forties.C. Their works were once rejected.D. They are famous for their great works.BUS scientists say they have poured cold water on the theory that washing hands with hot water kills more germs (细菌) than unheated water. The small study of 20 people found using water at 15C (59F) left hands as clean as water heated to 38C (100F).National Health Service (NHS) recommends that people wash their hands in either cold or warm water. In this study, scientists at Rutgers University-New Brunswick wanted to find out if popular assumptions about the benefits of warm or hot water and official guidance on hot water —given to the food industry in the US - held true. They asked 20 people to wash their hands 20 times each day with water that was 15C (59F), 26C (79F) or 38 degrees (100F). Volunteers were also asked to experiment with varying amounts of soap. Before they started the tests, their hands were covered in harmless bugs. Researchers say there was no difference in the amount of bugs removed as the temperature of the water or the amount of soap changed.Prof Donald Schaffner said: “People need to feel comfortable when they are washing their hands but as far as effectiveness goes, this study shows us that the temperature of the water used did not matter.”However, the researchers accept their study is small and say more extensive work is needed to determine the best ways to remove harmful bacteria.In the UK, NHS experts say people can use cold or hot water to wash their hands. They say hands should be washed for at least 20 seconds and stress the importance of using enough soap to cover the whole surface of the hands. Their guidance focuses on rubbing hands together in various ways to make sure each surface of each hand is clean.25. What does the underlined phrase “poured cold water” in Paragraph 1 probably mean?A. Proved.B. Created.C. Contradicted.D. Accepted.26. After they washed their hands with either hot or cold water,_______.A. volunteers nearly had the same amount of germ removedB. volunteers all talked about American food industryC. volunteers still had much germ on their handsD. volunteers all didn’t feel very comfortable27. How do researchers feel about their study?A. It is popular.B. It is incomplete.C. It is convincing.D. It is abstract.28. Which of the following is the best title for the text?A. Using Cold Water Instead of Hot WaterB. How to Use Cold Water to Wash HandsC. It Is Better to Wash Hands in Cold WaterD. Washing Hands in Cold Water as Good as in Hot WaterCSome people would argue that life experience is important for being a motivational speaker, but an 11-year-old kid from Pakistan is proving that all you really need is an inspirational speech and confidence.At just 11 years of age, Hammad Safi has accomplished what most of us won’t be able to do in a lifetime. He is the youngest motivational speaker in Pakistan, and probably the world, a free writer, TV anchor and a lecturer at a University , where he teaches students twice his age. He has been referred to as a “super kid”, a “child extraordinaire”, “motivational guru” and even “the little genius of Pakistan”.“He is not an ordinary child. I have seen abilities in him. That’s why I have appointed special teachers for him,” Safi’s father, Abdul Rehman Khan, said, “I want him to become a special leader. I’m very proud… For his abilities, for his intelligence.Abdul’s description may seem exaggerated (夸张的)– he is Ha mmad’s father after all – but the boy is indeed capable beyond his years. How many 11-year-olds do you know that can command the attention of thousands of adults while speaking on serious topics like success, life challenges or responsibility? Hammad can, and he does it with ease, relying on his great charm, practiced hand gestures and a confidence that attracts his audiences greatly.“A few months ago I was really disappointed with life… I was thinking about suicide, because there are no jobs and no succes s in life,” a student said, “Then I saw a movie of Hammad Safi. I thought if an 11-year-old child can do anything, why can’t I?”That is what makes Safi so special, his power to get his message across and inspire people much older than him.Many in Pakista n are astonished by Hammad’s self-confidence and his ability to lecture on important subjects, but there are also those who believe that this role is depriving the boy of his childhood.29. Which statement about Hammad Safi is not correct?A. His audience is much older than he is.B. He is the youngest motivational speaker in the world.C. People in Pakistan think highly of Hammad Safi.D. His father is also proud of him very much.30. What can’t you learn from Hammad Safi’s speech?A. We can realize the importance of responsibility.B. We can get confidence to deal with life challenges.C. We can remember the happy memory of childhood.D. We can understand the relationship between confidence and success.31. What does the underlined word “depriving” in the last paragraph mean?A. To guarantee that somehing will happen.B. To make somebody imagine.C. To take away something by force.D. To give up something all by oneself.32. What is the main idea of the passage?A. It introduces a very famous speaker.B. It tells that people in Pakistan are living without motivation.C. It tells us how to give people confidence.D. It introduces a young motivational speaker.DYou know the feeling-you have left your phone at home and feel anxious, as if you have lost your c onnection to the world. “Nomophobia”(无手机恐惧症) affects teenagers and adults alike. You can even do an online test to see if you have it. Last week, researchers from Hong Kong warned that nomophobia is infecting everyone. Their study found that people who use their phones to store, share and access personal memories suffer most. When users were asked to describe how they felt about their phones, words such as “hurt” (neck pain was often reported) and “alone” predicted higher levels of nomophobia.“The findings of our study suggest that users regard smartphones as their extended selves and get attached to the devices,” said Dr. Kim Ki Joon. “People experience feelings of anxiety and unpleasantness when separated from their phones.” Meanwhile, an American study s hows that smartphone separation can lead to an increase in heart rate and blood pressure.So can being without your phone really give you separation anxiety? Professor Mark Griffiths, psychologist and director of the International Gaming Research Unit at Nottingham Trent University, says it is what is on the phone that counts-the social networking that creates Fomo (fear of missingout).“We are talking about an internet-connected device that allows people to deal with lots of aspects of their lives,” says Griffiths. “You would have to surgically remove a phone from a teenager because their whole life is rooted in this device.”Griffiths thinks attachment theory, where we develop emotional dependency on the phone because it holds details of our lives, is a s mall part of nomophobia. For “screenagers”, it is Fomo that creates the most separation anxiety. If they can’t see what’s happening on Snapchat or Instagram, they become panic-stricken about not knowing what’s going on socially. “But they adapt very quickl y if you take them on holiday and there’s no Internet,” says Griffiths.33. Which of the following may Dr. Kim Ki Joon agree with?A. We waste too much time on phones.B. Phones have become part of some users.C. Addiction to phones makes memories suffer.D. Phones and blood pressure are closely linked.34. According to Giffiths, we get nomophobia because_________.A. we are accustomed to having a phone on usB. we need our phones to help us store informationC. we worry we may miss out what our friends are doingD. we fear without phones we will run into a lot of trouble35. Where can you probably find the above passage?A. In a research report.B. In a fashion brochure.C. In a science textbook.D. In a popular science magazine.第二节:(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试物理试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试物理试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试物理试题时间:90分钟满分:100分范围:必修一前三章一、选择题。

本题12小题,每题4分,共48分。

1~8题单选,9~12题多选,全部选对得4分,部分选对得2分,有错选或不选不得分。

1. 在电视连续剧《西游记》中,常有孙悟空“腾云驾雾”的镜头,如图所示,通常是采用“背景拍摄法”:让“孙悟空”站在平台上,做着飞行的动作,在他的背后展现出蓝天和急速飘动的白云,同时加上烟雾效果;摄影师把人物动作和飘动的白云及下面的烟雾等一起摄入镜头.放映时,观众就感觉到“孙悟空”在“腾云驾雾”.这时,观众所选的参考系是( )A. 飘动的白云B. 平台C. 孙悟空D. 镜头2. 下列说法中正确的是( )A . 体积很小的点为研究方便又称之为质点B . 第一节课是七点四十这是时间C . 单向直线运动时的位移就是路程D . 瞬时速度的大小通常叫速率3. 汽车以大小为20 m/s的速度做匀速直线运动.刹车后获得的加速度的大小为5 m/s2,那么刹车后2 s内与刹车后6 s内汽车通过的位移之比为()A. 1∶1B. 3∶1C. 4∶3D. 3∶44. 运动质点从原点出发,沿x轴做直线运动,各时刻的位置和瞬时速度如表所列。

则下列说法正确是:( )A. 质点运动是匀速直线运动B. 质点运动是匀加速直线运动C. 质点在第3s内的平均速度是2m/sD. 质点在第2.5s末的速度是2.5m/s5. 如图所示,某小孩沿滑梯下滑。

在下滑的过程中,小孩受到几个力的作用( )A.受到重力、下滑力与支持力的作用B.受到重力、下滑力与摩擦力的作用C.受到重力、支持力和摩擦力的作用D.受到重力、下滑力、支持力和摩擦力的作用6.屋檐隔一定时间滴下一滴水,当第5滴正欲滴下时,第1滴刚好落到地面,而第3滴与第2滴分别位于高1m的窗子的上、下沿,如图所示,g 取10m/s2,则此屋檐离地面的距离为:()A.3.2mB.3.0mC.2.5mD.2.2m7. 下图为节日里悬挂灯笼的一种方式,A、B点等高,O为结点,轻绳AO、BO长度相等,拉力分别为F A、F B,灯笼受到的重力为G。

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试数学试题(精品解析版)

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试数学试题(精品解析版)

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试数学试题一.选择题:(本大题共12小题,每小题5分,在每小题给出的四个选项中,只有一项是符合题目要求的.)1.已知集合,,则=()A. {-1,0}B. {0,1}C. {-1,0,1}D. {0,1,2}【答案】A【解析】【分析】解出集合B的元素,再由集合的交集的概念得到结果即可.【详解】=,,则={-1,0}故答案为:A .【点睛】高考对集合知识的考查要求较低,均是以小题的形式进行考查,一般难度不大,要求考生熟练掌握与集合有关的基础知识.纵观近几年的高考试题,主要考查以下两个方面:一是考查具体集合的关系判断和集合的运算.解决这类问题的关键在于正确理解集合中元素所具有属性的含义,弄清集合中元素所具有的形式以及集合中含有哪些元素.二是考查抽象集合的关系判断以及运算.2.下列函数中,在区间上为增函数的是A. B. C. D.【答案】C【解析】【分析】根据已知函数的规律得到函数的增减性,即可.【详解】为减函数,B. 为减函数,C. 在上是增函数,D. 在所给区间内是减函数。

故答案为:C.【点睛】本题考查了函数的单调性判断,函数的单调性,一般小题直接判断函数在所给区间内是否连续,接着再判断当x变大时y的变化趋势,从而得到单调性.3.若函数f对于任意实数x总有且f在区间上是减函数,则()A. B.C. D.【答案】B【解析】【分析】f(﹣x)=f(x)可得f(x)为偶函数,结合f(x)在区间(﹣∞,1]上是减函数,即可作出判断【详解】∵f(﹣x)=f(x),∴f(x)为偶函数,又f(x)在区间(﹣∞,﹣1]上是减函数,f(2)=f(﹣2),﹣2<﹣<﹣1,∴f(﹣1)<f(﹣)<f(2).故选:B.【点睛】本题考查函数的奇偶性与单调性,关键在于根据其奇偶性将要比较的数转化到共同的单调区间上,利用单调性予以解决,属于基础题4.若,则下列不等式中不成立的是A. B. C. D.【答案】B【解析】试题分析:由不等式的性质可得,,成立,假设成立,则由与已知矛盾,故选B考点:不等式的性质5.已知函数,若,则的值是().A. B. C. D. 【答案】C【解析】【分析】根据,可分情况讨论当a>0,和当时,分情况讨论即可.【详解】已知,当时,解得a=-3,满足题意;当a>0时,-2a=10,解得a=-5,舍去;故a=-3.故答案为:C.【点睛】求分段函数的函数值,要先确定要求值的自变量属于哪一段区间,然后代入该段的解析式求值,当出现的形式时,应从内到外依次求值;求某条件下自变量的值,先假设所求的值在分段函数定义区间的各段上,然后求出相应自变量的值,切记代入检验,看所求的自变量的值是否满足相应段自变量的取值范围.6.不等式的解集是()A. B.C. D.【答案】B【解析】,即,解得或,即不等式的解集是,故选B.7.下列命题中,真命题的是()A. B.C. D. 对恒成立【答案】D【解析】【分析】A,举出反例即可;B,可判断原方程无解,即可得到B错误;C,,解得a<0或a>1,可判断出命题错误,D,举出a的值即可.【详解】,错误,当x=0.2时,不满足;B.方程的判别式小于0,故方程无解,故B错误;C,,解得a<0或a>1,故C不正确;D令a>1,即可满足条件,对任意的x均有成立,故正确。

辽宁省普兰店市第一中学2018_2019学年高一历史上学期期中试题(含解析)

辽宁省普兰店市第一中学2018_2019学年高一历史上学期期中试题(含解析)

2018—2019学年度上学期期中考试高一历史时间:90分钟满分:100分范围:必修一:第1~4单元一、选择题:(30*2=60分)1.“周幽王烽火戏诸侯”、“孔子周游列国”,与“诸侯”、“列国”的产生相关的制度是A. 禅让制B. 世袭制C. 分封制D. 郡县制【答案】C【解析】试题解析:本题主要考查西周的政治制度。

“周幽王烽火戏诸侯”“孔子周游列国”与“诸侯”“列国”都与西周实行分封制有关。

周天子把土地和平民、奴隶,分给亲属、功臣等,封他们为诸侯,诸侯要孝忠周天子,材料中的制度是分封制,C项正确,ABD三项均排除。

故选C。

2.王国维在《殷周制度论》中指出:“周人制度之大异于商者,一曰立子立嫡之制……二曰庙数之制,三曰同姓不婚之制。

”其中“立子立嫡之制”是指A. 禅让制B. 宗法制C. 分封制D. 礼乐制【答案】B【解析】宗法制是按照血缘关系继承王位的原则,最大特点是嫡长子继承制,故B项正确;A是原始社会首领承袭制度,A错误;C是西周时期政治制度,和宗法制互为表里,C错误;礼乐制是配合分封制的礼仪制度,故D项错误。

点睛:西周时期的政治、经济与文化3.秦统一后,在全国范围内建立了强大的中央集权制度。

权力的高度集中,成为秦朝政治制度的基本特征。

权力高度集中的标志表现为:A. 中央实行三公九卿制B. 地方实行郡县制C. 从中央到地方建立一整套选拔及考核官吏的制度D. 皇权至上和皇位世袭【答案】D【解析】权力高度集中是指权力都集中于皇帝一人手中,即皇权是至上的并且皇位还是世袭的,选D 是符合题意的,正确;中央实行三公九卿制、地方实行郡县制属于权力集中,但并非权力高度集中的标志,所以选项A、B均不符合题意,排除;选拔及考核官吏的制度和权力高度集中无关联,选项C不符合题意,排除;故本题选D。

点睛:a.皇帝独尊:成为秦王朝政治制度的基本特征;b.皇位世袭:“家天下”的皇位继承制是君主权力集中的另一体现。

c.皇权至上:全国的政治、经济、军事等一切大权,都由皇帝总揽;中央和地方的主要官员也都由皇帝任免。

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试生物试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试生物试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试生物试题时间:90分钟满分:100分范围:必修1第1-4章,第五章第一节一酶的作用和本质;一、单选题(每题2分,共60分)1.草履虫能进行运动和分裂,其完成各项生命活动的前提条件是()A.细胞保持完整性 B.细胞具有遗传物质 C.细胞膜完整 D.细胞含有细胞核2.在实验中需要控制各种变量,其中人为改变的变量是( )A.因变量B.自变量C.无关变量D.控制变量3.下列四组生物中,都属于真核生物的一组是()A.SARS病毒和蘑菇B.大肠杆菌和草履虫C.蓝藻和酵母菌D.衣藻和变形虫4.下列关于胆固醇的叙述,错误的是()A.胆固醇在动物内脏、蛋黄等食物中含量丰富B.只要不摄入胆固醇,体内就不会有胆固醇C.胆固醇是构成细胞膜的重要成分D.老年人的血管内壁上容易造成胆固醇沉积5.关于细胞学说建立的过程,下列哪项说法错误()A.细胞学说建立的过程是一个从宏观到微观的认识过程B.细胞学说建立的过程是从理性思维到感性认识的过程C.细胞学说在修正、发展的过程中前进D.显微镜是细胞学说建立过程中的重要工具6.以下能够表达碳原子与生物大分子之间关系的是()A.碳原子→碳链→单体→多聚体B.碳原子→碳链→多聚体→单体C.碳原子→单体→多聚体→碳链D.碳原子→多聚体→单体→碳链7.由1分子磷酸、1分子碱基和1分子化合物a构成了化合物b,如图所示,则下列叙述正确的是()A.若m为腺嘌呤,则b肯定为腺嘌呤脱氧核苷酸B.若a为核糖,b则为DNA的基本组成单位C.若m为尿嘧啶,则DNA中肯定不含b这种化合物D.若由b构成的核酸主要分布在细胞质中,则a必为脱氧核糖8.右图是用光学显微镜观察植物叶片表皮气孔时的几个操作步骤。

要把显微镜视野中的图像从右图中的甲转为乙,规范的操作步骤是()①移动载玻片②调节光圈和反光镜③转动转换器④转动细准焦螺旋⑤转动粗准焦螺旋A.①③②④B.②③④①C.④③①⑤D.③②①⑤9.下列与细胞膜进行细胞间的信息交流功能无关..的是()A.内分泌细胞分泌激素到靶细胞B.精子与卵细胞之间的识别和结合C.胞间连丝D.水分在细胞间运输10.血红蛋白分子中含574 个氨基酸,4 条肽链。

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试历史试题

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试历史试题

2018—2019学年度上学期期中考试高一历史时间:90分钟满分:100分范围:必修一:第1~4单元一、选择题:(30*2=60分)1.“周幽王烽火戏诸侯”、“孔子周游列国”,与“诸侯”、“列国”的产生相关的制度是A. 禅让制B. 世袭制C. 分封制D. 郡县制【答案】C【解析】试题解析:本题主要考查西周的政治制度。

“周幽王烽火戏诸侯”“孔子周游列国”与“诸侯”“列国”都与西周实行分封制有关。

周天子把土地和平民、奴隶,分给亲属、功臣等,封他们为诸侯,诸侯要孝忠周天子,材料中的制度是分封制,C项正确,ABD三项均排除。

故选C。

2.王国维在《殷周制度论》中指出:“周人制度之大异于商者,一曰立子立嫡之制……二曰庙数之制,三曰同姓不婚之制。

”其中“立子立嫡之制”是指A. 禅让制B. 宗法制C. 分封制D. 礼乐制【答案】B【解析】宗法制是按照血缘关系继承王位的原则,最大特点是嫡长子继承制,故B项正确;A是原始社会首领承袭制度,A错误;C是西周时期政治制度,和宗法制互为表里,C错误;礼乐制是配合分封制的礼仪制度,故D项错误。

点睛:西周时期的政治、经济与文化3.秦统一后,在全国范围内建立了强大的中央集权制度。

权力的高度集中,成为秦朝政治制度的基本特征。

权力高度集中的标志表现为:A. 中央实行三公九卿制B. 地方实行郡县制C. 从中央到地方建立一整套选拔及考核官吏的制度D. 皇权至上和皇位世袭【答案】D【解析】权力高度集中是指权力都集中于皇帝一人手中,即皇权是至上的并且皇位还是世袭的,选D 是符合题意的,正确;中央实行三公九卿制、地方实行郡县制属于权力集中,但并非权力高度集中的标志,所以选项A、B均不符合题意,排除;选拔及考核官吏的制度和权力高度集中无关联,选项C不符合题意,排除;故本题选D。

点睛:a.皇帝独尊:成为秦王朝政治制度的基本特征;b.皇位世袭:“家天下”的皇位继承制是君主权力集中的另一体现。

c.皇权至上:全国的政治、经济、军事等一切大权,都由皇帝总揽;中央和地方的主要官员也都由皇帝任免。

辽宁省大连市普兰店一中2018-2019学年高一上学期期中考试化学试题 Word版含答案

辽宁省大连市普兰店一中2018-2019学年高一上学期期中考试化学试题 Word版含答案

2018—2019学年度上学期月考高一化学时间:90分钟满分:100分范围:必修一1.2.3章可能用到的相对原子质量:H:1 C:12 N:14 O:16 Na:23 Si:28 S:32 Mg:24 Al:27 Fe:56 Zn:65 Cu:64第I卷(选择题共54分)一、选择题(本题包括 18小题,每小题3分,共54分。

每小题只有一个选项符合题意)1. 对于易燃、易爆、有毒的化学物质,往往会在其包装上面贴上危险警告标签。

下面所列物质,贴错了包装标签的是()。

2.分类法在化学学科的发展中起到了非常重要的作用,下列分类标准合理的是()。

A.将酸分为一元酸、二元酸等:分子组成中含有氢原子的数目B.强电解质与弱电解质:溶液的导电能力大小C.溶液与胶体:本质不同的原因是能否发生丁达尔现象D.氧化还原反应的本质:有电子转移3. 下列实验操作:①过滤;②取固体试剂;③蒸发;④取液体试剂;⑤溶解。

一定要用到玻璃棒的是()。

A. ①③⑤B. ②③④C.①③④D. ③④⑤4.下列物质中既能导电,又属于强电解质的一组物质是()A.醋酸溶液、食盐晶体B.熔融状态的KOH、熔融状态的NaCl C.NaOH溶液、纯HNO3 D.液氨、石灰水5.下列实验操作中正确的是()A.用试管取出试剂瓶中的Na2CO3溶液,发现取量过多,为了不浪费,又把过量的试剂倒入试剂瓶中B.Ba(NO3)2溶于水,可将含有Ba(NO3)2的废液倒入水池中,再用水冲入下水道C.用蒸发方法使NaCl从溶液中析出时,应将蒸发皿中NaCl溶液全部蒸干才停止加热D.分液操作时,分液漏斗中下层液体从下口放出,上层液体从上口倒出6.用NA表示阿伏加德罗常数的值。

下列叙述正确的是()A.1 mol OH−中含有电子数为10NAB.常温常压下,17 g氨气中所含原子数为NAC.标准状况下,11.2 L水中含有的分子数是0.5NAD.1 mol/L BaCl2溶液中含有的氯离子数为2NA7.有两种金属混合物3.4g,与足量的盐酸反应放出H22.24L(标况下),这两种金属可能是()A.铜和铁B.镁和铝C.锌和铝D.锌和铁8. 下列反应必须加入氧化剂才能实现的是()A.KMnO4→K2MnO4B.CH4→CO2 C.SO2→SO32-D.H2O2→O29. 某溶液中仅含有Na+、Mg2+、SO 42-、Cl-四种离子(不考虑水电离出的H+和O H-),其中三种离子物质的量浓度之比为c(Na+)∶c(Mg2+)∶c(Cl-)=3∶5∶5。

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试历史试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试历史试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试历史试题★祝考试顺利★注意事项:1、答题前,请先将自己的姓名、准考证号用0.5毫米黑色签字笔填写在试题卷和答题卡上的相应位置,并将准考证号条形码粘贴在答题卡上的指定位置。

用2B铅笔将答题卡上试卷类型A后的方框涂黑。

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答案用0.5毫米黑色签字笔写在答题卡上对应的答题区域内,写在试题卷、草稿纸和答题卡上的非选修题答题区域的答案一律无效。

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6、考试结束后,请将本试题卷、答题卡、草稿纸一并依序排列上交。

一、选择题:(30*2=60分)1.“周幽王烽火戏诸侯”、“孔子周游列国”,与“诸侯”、“列国”的产生相关的制度是A. 禅让制B. 世袭制C. 分封制D. 郡县制【答案】C【解析】试题解析:本题主要考查西周的政治制度。

“周幽王烽火戏诸侯”“孔子周游列国”与“诸侯”“列国”都与西周实行分封制有关。

周天子把土地和平民、奴隶,分给亲属、功臣等,封他们为诸侯,诸侯要孝忠周天子,材料中的制度是分封制,C项正确,ABD三项均排除。

故选C。

2.王国维在《殷周制度论》中指出:“周人制度之大异于商者,一曰立子立嫡之制……二曰庙数之制,三曰同姓不婚之制。

”其中“立子立嫡之制”是指A. 禅让制B. 宗法制C. 分封制D. 礼乐制【答案】B【解析】宗法制是按照血缘关系继承王位的原则,最大特点是嫡长子继承制,故B项正确;A是原始社会首领承袭制度,A错误;C是西周时期政治制度,和宗法制互为表里,C错误;礼乐制是配合分封制的礼仪制度,故D项错误。

辽宁省大连市普兰店市第一中学2018-2019学年高一上学期期中考试数学试题含答案

辽宁省大连市普兰店市第一中学2018-2019学年高一上学期期中考试数学试题含答案

辽宁省大连市普兰店市第一中学2018-2019学年高一上学期期中考试数学试题一、选择题:本大题共12小题,每小题5分,在每小题给出的四个选项中,只有一项是符合题目要求的.1.已知集合{}2,1,0,1,2--=A ,()(){}021<+-=x x x B ,则B A =( ) A. {}0,1-B. {}1,0C. {}1,0,1-D. {}2,1,02.下列函数中,在区间上为增函数的是( ) A.B. C. D.3.若函数()x f 对于任意实数x 总有()()x f x f =-,且()x f 在区间(]1,∞-上是减函数,则( )A .B .C.D .4.若0<<b a ,则下列不等式中不成立的是( ) A. b a >B.ab a 11>- C.ba 11> D. 22b a >5.已知函数,若,则的值是( )A.B.C.D.6.不等式的解集是( ) A. B.C.D.7.下列命题中,真命题的是( ) A.B. 2,1R ∃∈+=-x x xC.D. 对恒成立8. “”是“”的( ) A. 充要条件B. 必要不充分条件()0,23y x =-1y x=21y x =+y x =-3()(1)(2)2f f f -<-<3(1)()(2)2f f f -<-<3(2)(1)()2f f f <-<-3(2)()(1)2f f f <-<-()21,0{ 2,0x x f x x x +≤=->()10f a =a 33±3-5-301xx -<+()(),31,-∞-⋃+∞()(),13,-∞-⋃+∞()1,3-()3,1-()20,,1x x ∀∈+∞>()20,,a a a ∀∈+∞>()20,,1a x a ∃∈+∞+>x R ∈1x >2x x >C. 充分不必要条件D. 既不必要也不充分条件9.函数()2211x y x x +=>-的最小值是( )A.23+2B.23-2C.2 3D.210.如图所示的图像表示的函数的解析式为( )A. y =|x -1|(0≤x ≤2) B. y =32|x -1|(0≤x ≤2) C. y =|x -1|(0≤x ≤2)D. y =1-|x -1|(0≤x ≤2)11.下列命题中正确的是 ( ) A .函数423(0)y x x x=-->的最小值为2- B .设集合{}{}|51,|8,R =><-=<<+⋃=S x x x T x a x a S T 或,则a 的取值范围是31a -≤≤-C .在直角坐标系中,点223(23,)2m m m m -+--在第四象限的充要条件是312m -<<或23m <<D .若集合{}|(2)0A x Z x x =∈+≤,则集合A 的子集个数为712.已知定义在上的函数的图像经过点,且在区间单调递减,又知函数为偶函数,则关于的不等式的解为 ( ) A .B .C .D .二、填空题:本大题共4小题,每小题5分. 13.函数()2x f x -=的定义域为________.14.已知,则的最小值为________.15.若命题“2000,(1)10R ∃∈+-+<x xa x ”是真命题,则实数a 的取值范围是________.3232-32-R )(x f )0,3(M )(x f ),2[+∞)2(+x f x 0)1(>+x f )3,1()4,1()4,2()2,0(21x y +=24xy+16.设0a b >>,则211()a ab a a b ++-的最小值是________. 三、解答题:解答应写出文字说明,证明过程或演算步骤.17.(本小题10分)已知集合{|3},{|2A x a x a B x x =≤≤+=<-或6}x >. (1)若AB =Φ,求a 的取值范围;(2)若“x A ∈”是“x B ∈”的充分条件,求a 的取值范围.18.(本小题12分)已知不等式()06412>+--x x a 的解集为{}13<<-x x .(1)求a 的值;(2)若不等式032≥++mx ax 的解集为R ,求实数m 的取值范围.19.(本小题12分)(1)若12,x x 是方程2220180x x +-=的两个根,求221212(1)(1)x x x x ++--的值.(2)已知集合2{|230,}A x mx x m R =-+=∈,若A 中元素至多只有一个,求m 的取值范围.20.(本小题12分)(1)已知0,0,x y >> 且 322,x y xy +=求的最大值以及相应的x 和y的值;(2)已知,R +∈a b ,且1,a b +=求11a b+的最小值; (3)已知方程()230x m x m +-+=的两个根都是正数,求实数m 的取值范围.21.(本小题12分)围建一个面积为360 m 2的矩形场地,要求矩形场地的一面利用旧墙(利用旧墙需维修),其他三面围墙要新建,在旧墙的对面的新墙上要留一个宽度为2 m 的进出口,如图所示,已知旧墙的维修费用为45元/m ,新墙的造价为180元/m ,设利用的旧墙的长度为x (x >0)(单位:米). (1)将总费用y 表示为x 的函数;(2)试确定x ,使修建此矩形场地围墙的总费用最小,并求最小总费用.22.(本小题12分)函数是定义在上的奇函数,且. (1)确定的解析式;(2)判断并证明在上的单调性;(3)解不等式.()24ax b f x x -=-()2,2-()113f =()f x ()f x ()2,2-()()10f t f t -+<【参考答案】一、选择题 二、填空题13.[)()1,22,⋃+∞ 14. 15.(,1)(3,)-∞-+∞ 16.4三、解答题 17. 解:(1)A B =Φ,2,2336a a a ≥-⎧∴∴-≤≤⎨+≤⎩.a ∴的取值范围是23a -≤≤.(2)“x A ∈”是“x B ∈”的充分条件,A B ∴⊆,6a ∴>或32a +<-,a ∴的取值范围是6a >或5a <-.18.解:(1)由已知,,且方程的两根为,.有,解得;(2)不等式的解集为R ,则,解得,实数的取值范围为.19. 解:(1)由根与系数的关系得:12122,2018.x x x x +=-=-22212121212121221212122(1)(1)()2()1()()1(2)(2018)(2)12025.++--=+-+-++=+--++=-----+=x x x x x x x x x x x x x x x x x x(2)①当0m =时,32x =,满足题意. ②当m ≠0时,方程2230mx x -+=至多只有一个解,则0∆≤,即4120m -≤,13m ∴≥, 综上所述,m 的取值范围是0m =或13m ≥. 20.解:(1)11,32a b ==时ab 最大值为16;(2)12a b ==时取得最小值4; (3)01m <≤.21. 解: (1)设矩形的另一边长为a m ,则y =45x +180(x -2)+180·2a =225x +360a -360.由已知xa =360,得a =360x ,∴y =225x +3602x-360(x >0).(2)∵x >0,∴225x +3602x ≥2225×3602=10 800,∴y =225x +3602x -360≥10 440.当且仅当225x =3602x时,等号成立.即当x =24 m 时,修建围墙的总费用最小,最小总费用是10 440元22.解:(1)由函数是定义在上的奇函数知,所以, 经检验,时是上的奇函数,满足题意. 又,解得,故,. (2)是上增函数.证明如下:在任取且,则,,,,所以,即, 所以是上增函数.(3)因为是上的奇函数,所以由得,,又是上增函数,所以解得,从而原不等式的解集为.()24ax b f x x -=-()2,2-()004bf -==0b =0b =()24axf x x=-()2,2-()211413a f ==-1a =()24xf x x =-()2,2x ∈-()f x ()2,2-()2,2-12,x x 12x x <210x x ->1240x x +>2140x ->2240x ->()()()()()()211221212222212144444x x x x x x f x f x x x x x -+-=-=----0>()()21f x f x >()f x ()2,2-()f x ()2,2-()()10f t f t -+<()()()1f t f t f t -<-<-()f x ()2,2-1,{212, 22,t t t t -<--<-<-<<112t -<<11,2⎛⎫- ⎪⎝⎭。

辽宁省普兰店市第一中学2019届高三上学期期中考试 数学(文)

辽宁省普兰店市第一中学2019届高三上学期期中考试 数学(文)

2018—2019学年度上学期期中考试高三数学(文科)时间:120分钟满分:150分范围:集合与常用逻辑用语,函数,导数及应用,三角函数,解三角形,平面向量,复数,数列,不等式,立体几何,解析几何(直线方程,两直线位置关系)本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

第Ⅰ卷(选择题,共60分)一、选择题(本大题共12小题,每小题5分,共60分。

每小题只有一个正确答案)1.已知全集U R =,集合{}2|60 A x x x =--≥,{}| 1 B x x =≥,则()U C A B ⋂= ( )A. {}|1 3 x x ≤<B. {}|2 3 x x ≤<C. {}| 3 x x >D. ∅2.已知z为复数的共轭复数,且()11i z i -=+,则z为() A.i -B. iC. 1i -D. 1i +3.若扇形的面积3π8,半径为1,则扇形的圆心角为() A.32πB.34π C.38π D.316π 4.已知实数,x y 满足24{24 0x y x y y -≥+≤≤,则32z x y =-的最小值是()A. 4B. 5C. 6D. 75.已知0.5log 5m =,35.1n -=,0.35.1p =,则实数,,m n p 的大小关系为() A. m p n << B. m n p << C. n m p <<D. n p m <<6.已知向量()1,1a =,()24,2a b +=,则向量,a b 的夹角的余弦值为()A.B.C.D. 7.中国古代数学著作《算法统宗》中有这样一个问题:“三百七十八里关,初行健步不为难,次日脚痛减一半,六朝才得到其关,要见次日行里数,请公仔细算相还.”其意思为:“有一个人走378里路,第一天健步行走,从第二天起脚痛每天走的路程为前一天的一半,走了6天后到达目的地,请问第二天走了()A. 96里B. 48里C. 192里D. 24里8. 下列命题错误..的是() A. 命题“若p 则”与命题“若q ⌝,则p ⌝”互为逆否命题 B. 命题“x ∃∈R, 20x x ->”的否定是“R,”C. ∀0x >且1x ≠,都有12x x+> D. “若”的逆命题为真9. 函数()262xf x x x e =-+的极值点所在的区间为() A. ()0,1B. ()1,0-C. ()1,2D. ()2,1--10. 如果两直线与互相平行,那么它们之间的距离为()A. B. C. D.11. 已知的三个内角、、所对的边长分别是、、,且,若将函数的图像向右平移个单位长度,得到函数的图像,则的解析式为()A. B.C.D.12. 一个直三棱柱的三视图如图所示,其中俯视图是一个顶角为23π的等腰三角形,则该直三棱柱外接球的体积为()A.B.203πC. 25πD.第Ⅱ卷(共90分)二、填空题(本大题共4小题,每题5分,共20分)13. 在ABC ∆中,2b =,3c =,且tan A =ABC ∆的面积为_______.14. 曲线()ln f x x x =在点()10P ,处的切线l 与两坐标轴围成的三角形的面积是__________. 15. 已知两个正实数x ,y 使x +y =4,则使不等式14x y+≥m 恒成立的实数m 的取值范围是____________.16. 已知数列{}n a 满足1133,2n n a a a n +=-=,则na n的最小值为_____. 三 、解答题(本大题共6小题共70分。

普兰店区一中2018-2019学年上学期高三数学10月月考试题

普兰店区一中2018-2019学年上学期高三数学10月月考试题

普兰店区一中2018-2019学年上学期高三数学10月月考试题 班级__________ 座号_____ 姓名__________ 分数__________一、选择题1. 不等式ax 2+bx+c <0(a ≠0)的解集为R ,那么( ) A .a <0,△<0 B .a <0,△≤0C .a >0,△≥0D .a >0,△>02. 下列四个命题中的真命题是( )A .经过定点()000,P x y 的直线都可以用方程()00y y k x x -=-表示B .经过任意两个不同点()111,P x y 、()222,P x y 的直线都可以用方程()()()()121121y y x x x x y y --=-- 表示C .不经过原点的直线都可以用方程1x ya b+=表示 D .经过定点()0,A b 的直线都可以用方程y kx b =+表示3. 二项式(x 2﹣)6的展开式中不含x 3项的系数之和为( ) A .20 B .24C .30D .364.+(a ﹣4)0有意义,则a 的取值范围是( )A .a ≥2B .2≤a <4或a >4C .a ≠2D .a ≠45. 已知a n =(n ∈N *),则在数列{a n }的前30项中最大项和最小项分别是( )A .a 1,a 30B .a 1,a 9C .a 10,a 9D .a 10,a 306. 如图,棱长为的正方体1111D ABC A B C D -中,,E F 是侧面对角线11,BC AD 上一点,若 1BED F 是菱形,则其在底面ABCD 上投影的四边形面积( )A .12 B .34C. 2 D .34-7. 若命题“p 或q ”为真,“非p ”为真,则( )A .p 真q 真B .p 假q 真C .p 真q 假D .p 假q 假8. 若集合,则= ( )ABC D9. 已知命题p :对任意()0x ∈+∞,,48log log x x <,命题:存在x ∈R ,使得tan 13x x =-,则下列命题为真命题的是( )A .p q ∧B .()()p q ⌝∧⌝C .()p q ∧⌝D .()p q ⌝∧ 10.在△ABC 中,内角A ,B ,C 的对边分别是a ,b ,c ,若a 2﹣b 2=bc ,sinC=2sinB ,则A=( )A .30°B .60°C .120°D .150° 11.经过点()1,1M 且在两轴上截距相等的直线是( ) A .20x y +-= B .10x y +-=C .1x =或1y =D .20x y +-=或0x y -=12.已知函数f (x )=⎩⎪⎨⎪⎧log 2(a -x ),x <12x ,x ≥1若f (-6)+f (log 26)=9,则a 的值为( )A .4B .3C .2D .1二、填空题13.设变量y x ,满足约束条件22022010x y x y x y --≤⎧⎪-+≥⎨⎪+-≥⎩,则22(1)3(1)z a x a y =+-+的最小值是20-,则实数a =______.【命题意图】本题考查线性规划问题,意在考查作图与识图能力、逻辑思维能力、运算求解能力. 14.一个椭圆的长轴的长度、短轴的长度和焦距成等差数列,则该椭圆的离心率是 .15.图中的三个直角三角形是一个体积为20的几何体的三视图,则h =__________.16.已知函数()()31,ln 4f x x mxg x x =++=-.{}min ,a b 表示,a b 中的最小值,若函数()()(){}()min ,0h x f x g x x =>恰有三个零点,则实数m 的取值范围是 ▲ .17.设,x y 满足条件,1,x y a x y +≥⎧⎨-≤-⎩,若z ax y =-有最小值,则a 的取值范围为 .三、解答题18.(本小题满分12分)如图长方体ABCD -A 1B 1C 1D 1中,AB =16, BC =10,AA 1=8,点E ,F 分别在A 1B 1,D 1C 1上,A 1E =4,D 1F =8,过点E ,F ,C 的平面α与长方体的面相交,交线围成一个四边形.(1)在图中画出这个四边形(不必说明画法和理由); (2)求平面α将长方体分成的两部分体积之比.19.求下列曲线的标准方程:(1)与椭圆+=1有相同的焦点,直线y=x 为一条渐近线.求双曲线C 的方程.(2)焦点在直线3x ﹣4y ﹣12=0 的抛物线的标准方程.20.(本小题12分)在多面体ABCDEFG 中,四边形ABCD 与CDEF 是边长均为a 正方形,CF ⊥平面ABCD ,BG ⊥平面ABCD ,且24AB BG BH ==. (1)求证:平面AGH ⊥平面EFG ;(2)若4a =,求三棱锥G ADE -的体积.【命题意图】本题主要考查空间直线与平面间的垂直关系、空间向量、二面角等基础知识,间在考查空间想象能力、逻辑推理能力,以及转化的思想、方程思想.21.(本小题满分12分)如图,多面体ABCDEF 中,四边形ABCD 为菱形,且60DAB ∠=,//EFAC ,2AD =,EA ED EF ===.(1)求证:AD BE ⊥;(2)若BE =-F BCD 的体积.22.如图1,∠ACB=45°,BC=3,过动点A 作AD ⊥BC ,垂足D 在线段BC 上且异于点B ,连接AB ,沿AD 将△ABD 折起,使∠BDC=90°(如图2所示),(1)当BD 的长为多少时,三棱锥A ﹣BCD 的体积最大;(2)当三棱锥A ﹣BCD 的体积最大时,设点E ,M 分别为棱BC ,AC 的中点,试在棱CD 上确定一点N ,使得EN ⊥BM ,并求EN 与平面BMN 所成角的大小。

辽宁省普兰店市第一中学2019届高三上学期期中考试 英语

辽宁省普兰店市第一中学2019届高三上学期期中考试 英语

2018—2019学年度上学期月考试卷高三英语时间:100分钟满分:120分范围:高考范围第一部分听力(略)第二部分阅读理解(共两节, 满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。

AYou probably now who Hillary Diane Rodham Clinton is, but you may not have heard of Margaret Munnerlyn Mitchell if you are not interested in foreign literature. Of the outstanding ladies listed below, who is your favorite?Jane Austen (16 December, 1775-18 July, 1817)Jane Austen, a famous English writer, was born at Steventon, Hampshire. She began writing early in life, although the prejudices (偏见) of her times forced her to have her boos published anonymously (匿名).She wrote many boos of romantic fiction about the gentry (贵族). Her wors made her one of the great masters of the English novel. Only four of her novels were printed while she was alive. They were Sense and Sensibility (1811), Pride and Prejudice (1813), Mansfield Par (1814) and Emma(1815).Charlotte Bronte (21 April, 1816-31 March, 1855)She first published her wors, including Jane Eyre, under the false name of Currer Bell. Her first novel, The Professor, was rejected by many publishers. It was not printed until 1857. She is famous for her novel Jane Eyre (1847), which was very popular when it was printed. Jane Eyre was a strong story of a plain, brave, clever woman struggling with her passions, reasons, and social condition.Margaret Munnerlyn Mitchell (8 November, 1900-16 August, 1949)She was an American author and journalist, a lifelong resident and native of Atlanta, Georgia. One novel by Mitchell was published during her lifetime, the American Civil-War-Era novel, Gone with the Wind, for which she won the National Boo Award for Most Distinguished Novel of 1936 and the Puliter Prie for Fiction in 1937. In more recent years, a colle ction of Mitchell’s girlhood writings and a novel she wrote as a teenager, Lost Laysen, have been published. A collection of articles written by Mitchell for The Atlanta Journal was republished in boo form.21. Why did Jane Austen publish her boos with a false name?A. She laced confidence.B. She was not well educated.C. Women were discriminated.D. Women were well protected.22. Which novel was set in the bacground of war?A. Sense and Sensibility.B. Gone with the Wind.C. Lost Laysen.D. The Professor.23. Who won the most pries for her wors?A. Margaret Munnerlyn Mitchell.B. Charlotte Bronte.C. Hillary Diane Rodham Clinton.D. Jane Austen.24. What can we infer about the women mentioned in the tet?A. They were all fond of poetry.B. They all died in their forties.C. Their wors were once rejected.D. They are famous for their great wors.BUS scientists say they have poured cold water on the theory that washing hands with hot water ills more germs (细菌) than unheated water. The small study of 20 people found using water at 15C (59F) left hands as clean as water heated to 38C (100F).National Health Service (NHS) recommends that people wash their hands in either cold or warm water. In this study, scientists at Rutgers University-New Brunswic wanted to find out if popular assumptions about the benefits of warm or hot water and official guidance on hot water —given to the food industry in the US - held true. They ased 20 people to wash their hands 20 times each day with water that was 15C (59F), 26C (79F) or 38 degrees (100F). Volunteers were also ased to eperiment with varying amounts of soap. Before they started the tests, their hands were covered in harmless bugs. Researchers say there was no difference in the amount of bugs removed as the temperature of the water or the amount of soap changed.Prof Donald Schaffner said “People need to feel comfortable when they are washing their hands but as far as effectiveness goes, this study shows us that the temperature of the water used did not matter.”However, the researchers accept their study is small and say more etensive wor is needed to determine the best ways to remove harmful bacteria.In the U, NHS eperts say people can use cold or hot water to wash their hands. They say hands should be washed for at least 20 seconds and stress the importance of using enough soap to cover the whole surface of the hands. Their guidance focuses on rubbing hands together in various ways to mae sure each surface of each hand is clean.25. What does the underlined phrase “poured cold water” in Paragraph 1 probably mean?A. Proved.B. Created.C. Contradicted.D. Accepted.26. After they washed their hands with either hot or cold water,_______.A. volunteers nearly had the same amount of germ removedB. volunteers all taled about American food industryC. volunteers still had much germ on their handsD. volunteers all didn’t feel very comfortable27. How do researchers feel about their study?A. It is popular.B. It is incomplete.C. It is convincing.D. It is abstract.28. Which of the following is the best title for the tet?A. Using Cold Water Instead of Hot WaterB. How to Use Cold Water to Wash HandsC. It Is Better to Wash Hands in Cold WaterD. Washing Hands in Cold Water as Good as in Hot WaterCSome people would argue that life eperience is important for being a motivational speaer, but an 11-year-old id from Paistan is proving that all you really need is an inspirational speech and confidence.At just 11 years of age, Hammad Safi has accomplished what most of us won’t be able to do in a lifetime. He is the youngest motivational speaer in Paistan, and probably the world, a free writer, TV anchor and a lecturer at a University , where he teaches students twice his age. He has been referred to as a “super id”, a “child etraordinaire”, “motivational guru” and even “the little genius of Paistan”.“He is not an ordinary child. I have seen abilities in him. That’s why I have appointed special teachers for him,” Safi’s father, Abdul Rehman han, said, “I want him to become a special leader. I’m very proud… For his abilities, for his intelligence.Abdul’s description may seem eaggerated (夸张的)–he is Hammad’s father a fter all – but the boy is indeed capable beyond his years. How many 11-year-olds do you now that can command the attention of thousands of adults while speaing on serious topics lie success, life challenges or responsibility? Hammad can, and he does it with ease, relying on his great charm, practiced hand gestures and a confidence that attracts his audiences greatly.“A few months ago I was really disappointed with life… I was thining about suicide, because there are no jobs and no success in life,” a student said, “Then I saw a movie of Hammad Safi. I thought if an 11-year-old child can do anything, why can’t I?”That is what maes Safi so special, his power to get his message across and inspire people much older than him.Many in Paistan are astonished by Hammad’s self-confidence and his ability to lecture on important subjects, but there are also those who believe that this role is depriving the boy of hischildhood.29. Which statement about Hammad Safi is not correct?A. His audience is much older than he is.B. He is the youngest motivational speaer in the world.C. People in Paistan thin highly of Hammad Safi.D. His father is also proud of him very much.30. What can’t you learn from Hammad Safi’s speech?A. We can realie the importance of responsibility.B. We can get confidence to deal with life challenges.C. We can remember the happy memory of childhood.D. We can understand the relationship between confidence and success.31. What does the underlined word “depriving” in the last paragra ph mean?A. To guarantee that somehing will happen.B. To mae somebody imagine.C. To tae away something by force.D. To give up something all by oneself.32. What is the main idea of the passage?A. It introduces a very famous speaer.B. It tells that people in Paistan are living without motivation.C. It tells us how to give people confidence.D. It introduces a young motivational speaer.DYou now the feeling-you have left your phone at home and feel anious, as if you have lost your connection to the wo rld. “Nomophobia”(无手机恐惧症) affects teenagers and adults alie. You can even do an online test to see if you have it. Last wee, researchers from Hong ong warned that nomophobia is infecting everyone. Their study found that people who use their phones to store, share and access personal memories suffer most. When users were ased to describe how they felt about their phones, words such as “hurt” (nec pain was often reported) and “alone” predicted higher levels of nomophobia.“The findings of our study suggest th at users regard smartphones as their etended selves and get attached to the devices,” said Dr. im i Joon. “People eperience feelings of aniety and unpleasantness when separated from their phones.” Meanwhile, an American study shows that smartphone separation can lead to an increase in heart rate and blood pressure.So can being without your phone really give you separation aniety? Professor Mar Griffiths, psychologist and director of the International Gaming Research Unit at Nottingham Trent University,says it is what is on the phone that counts-the social networing that creates Fomo (fear of missing out).“We are taling about an internet-connected device that allows people to deal with lots of aspects of their lives,” says Griffiths. “You would have to sur gically remove a phone from a teenager because their whole life is rooted in this device.”Griffiths thins attachment theory, where we develop emotional dependency on the phone because it holds details of our lives, is a small part of nomophobia. For “screenagers”, it is Fomo that creates the most separation aniety. If they can’t see what’s happening on Snapchat or Instagram, they become panic-stricen about not nowing what’s going on socially. “But they adapt very quicly if you tae them on holiday and there’s no Internet,” says Griffiths.33. Which of the following may Dr. im i Joon agree with?A. We waste too much time on phones.B. Phones have become part of some users.C. Addiction to phones maes memories suffer.D. Phones and blood pressure are closely lined.34. According to Giffiths, we get nomophobia because_________.A. we are accustomed to having a phone on usB. we need our phones to help us store informationC. we worry we may miss out what our friends are doingD. we fear without phones we will run into a lot of trouble35. Where can you probably find the above passage?A. In a research report.B. In a fashion brochure.C. In a science tetboo.D. In a popular science magaine.第二节:(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

辽宁省普兰店市第一中学2019届高三上学期期中考试政治试卷(含答案)

辽宁省普兰店市第一中学2019届高三上学期期中考试政治试卷(含答案)

2018—2019学年度上学期月考高三政治时间:90分钟满分:100分范围:必修1 1-9课;一、单项选择(每题2分,共48分)1、近年,知乎、分答等知识付费平台快速发展,知识付费的用户超过5000万人。

最受用户欢迎的付费内容有:职业技能、投资理财、生活兴趣等。

对知识付费的正确认识是( )①知识产品付费提高获取成本,不利于知识创新②付费产品的价格受用户需求影响③知识付费产品是商品,因为具有使用价值④付费平台的出现,有利于知识价值的实现A.①②B. ①③C. ③④D. ②④2、中国是世界上最大的原油进口国。

2018年3月26日,中国原油期货在上海正式挂牌交易,这为我国将来全面采用人民币结算进口原油创造了有利条件。

我国进口原油的结算方式由人民币结算代替美元结算( )①有利于国内炼油企业规避美元汇率风险,增强经营确定性②意在打破“石油美元”的垄断地位,促进人民币汇率稳定③是加速我国金融对外开放,推动资本全球化的战略性举措④可扩大人民币的国际经济影响,加速人民币国际化的进程A.①②B. ①④C. ②③D. ③④3、2018年3月23日,人民币对美元中间价为1:6.6185,而2017年3月23日为1: 6.7654。

不考虑其他因素,下列对人民币币值变动趋势推导合理的是()A. 人民币贬值→美元可以兑换更多人民币→中国对美国投资不断增加B. 人民币贬值→美国来华旅游的费用降低→利于我国旅游产业的发展C. 人民币升值→美商对我国投资成本上升→影响我国吸收外国资本D. 人民币升值→美元计价的商品价格降低→我国出口商品的数量增加4、如图中P是价格,Q是数量,D1、D2是需求曲线,如不考虑其他因素,下列情形最有可能导致A商品需求曲线由D1向D2方向移动的是( )①A是国内汽柴油,汽柴油价格上涨②A是一次性塑料包装或餐具,向巨量使用一次性塑料包装或餐具的电商平台、快递企业、外卖平台收取污染处理费③A是一次性塑料包装或餐具,向一次性塑料包装和餐具生产企业收取污染处理费④A是新能源汽车,汽柴油价格持续下调A.①②B. ①③C. ②④D. ③④5、2017年12月27日,财政部等4部门宣布,自2018年1月1日至2020年12月31日,对购置的新能源汽车免征车辆购置税,这将引起新能源汽车供需量的变化(注:P、Q分别表示新能源汽车的价格和数量,D1、D2和S1、S2分别表示政策变动前后的需求曲线和供给曲线),其他条件不变,下图能正确反映这一变化的是( )6、2017 年10 月20 日,华为在上海召开年度旗舰新品发布会,正式在国内推出华为Mate10、MatelOPro 以及MatelOPro 保时捷定制版三都手机,售价分别为3899 元起、4899 元起与8999元。

辽宁省普兰店市第一中学2019届高三上学期期中考试数学(理)试题(解析版)

辽宁省普兰店市第一中学2019届高三上学期期中考试数学(理)试题(解析版)

2018—2019学年度上学期期中考试高三数学(理科)第Ⅰ卷(选择题,共60分)一、选择题(本大题共12小题,每小题5分,共60分。

每小题只有一个正确答案)1.已知集合,,则下图中阴影部分所表示的集合为()A. B.C. D.【答案】D【解析】求解二次不等式可得:,则,由Venn图可知图中阴影部分为:.本题选择D选项.2.在等差数列中,前项和满足,则()A. 7B. 9C. 14D. 18【答案】B【解析】,所以,选B.3.若扇形的面积,半径为,则扇形的圆心角为()A. B. C. D.【答案】B【解析】【分析】根据扇形的面积公式求出扇形的弧长,然后可求出扇形的圆心角.【详解】设扇形的弧长为,半径为,则.由题意得,∴,∴该扇形的圆心角.故选B .【点睛】本题考查扇形面积、弧长的有关运算,解题时注意公式中各量间的关系,并能对公式作出适当的变形,属于基础题.4.( )A.B.C.D.【答案】A 【解析】,故选:A5.已知,,,则实数的大小关系为( )A. B.C.D.【答案】B 【解析】.所以.故选B.点睛:比较大小的一般方法有:作差,作商,利用函数单调性,借助中间量比较大小. 6.已知向量,,则向量的夹角的余弦值为( )A. B. C. D.【答案】C 【解析】 【分析】先求出向量,再根据向量的数量积求出夹角的余弦值.【详解】∵,∴.设向量的夹角为,则.故选C.【点睛】本题考查向量的线性运算和向量夹角的求法,解题的关键是求出向量的坐标,然后根据数量积的定义求解,注意计算的准确性,属于基础题.7.中国古代数学著作《算法统宗》中有这样一个问题:“三百七十八里关,初行健步不为难,次日脚痛减一半,六朝才得到其关,要见次日行里数,请公仔细算相还.”其意思为:“有一个人走378里路,第一天健步行走,从第二天起脚痛每天走的路程为前一天的一半,走了6天后到达目的地,请问第二天走了()A. 96里B. 48里C. 192里D. 24里【答案】B【解析】记每天走的路程里数为,易知是公比的等比数列,由题意知,故选A.8.下列命题错误的是A. 命题“若则”与命题“若,则”互为逆否命题B. 命题“R, ”的否定是“,”C. 且,都有D. “若,则”的逆命题为真【答案】D【解析】【分析】对给出的四个选项分别进行判断可得结果.【详解】对于选项A,由逆否命题的定义可得,命题“若则”的逆否命题为“若,则”,所以A 正确.对于选项B,由含量词的命题的否定可得,命题“R, ”的否定是“,”,所以B正确.对于选项C,当且时,由基本不等式可得.所以C正确.对于选项D,命题“若,则”当时不成立,所以D不正确.故选D.【点睛】由于类似问题考查的内容较多,解题的关键是根据每个命题对应的知识解决,要求对相关知识要有一个整体性的掌握,本题考查综合运用知识解决问题的能力.9.函数的极值点所在的区间为()A. B. C. D.【答案】A【解析】【分析】求出导函数,然后运用函数零点存在性定理进行验证可得所求区间.【详解】∵,∴,且函数单调递增.又,∴函数在区间内存在唯一的零点,即函数的极值点在区间内.故选A.【点睛】本题考查函数零点存在性定理的应用,解答本题时要弄清函数的极值点即为导函数的零点,同时还应注意只有在导函数零点左右两侧的函数值变号时,该零点才为极值点,否则导函数的零点就不是极值点.10.已知,则的值为()A. B. C. D.【答案】C【解析】由题意可得:,则:.本题选择C选项.11.已知的三个内角所对的边长分别是,且,若将函数的图像向右平移个单位长度,得到函数的图像,则的解析式为()A. B.C. D.【答案】D【解析】由,利用正弦定理得:,整理得:,利用余弦定理:,则,,将图象向右平移个单位长度单位,得到,故选D.【方法点睛】本题主要考查正弦定理及余弦定理的应用以及三角形图象的平移变换,属于难题.在解与三角形有关的问题时,正弦定理、余弦定理是两个主要依据. 除了直接利用两定理求边和角以外,恒等变形过程中,一般来说,当条件中同时出现及、时,往往用余弦定理,而题设中如果边和正弦、余弦函数交叉出现时,往往运用正弦定理将边化为正弦函数再结合和、差、倍角的正余弦公式进行解答.12.符号表示不超过的最大整数,如,定义函数.给出下列四个结论:①函数的定义域是R,值域为[0,1];②方程有无数个解;③函数是增函数.其中正确结论的序号有()A. ①③B. ③C. ②D. ②③【答案】C【解析】若,则,不符合题意,故①错误.由于,故函数不是增函数,③错误.,故选.【点睛】本题主要考查新定义函数性质的判断.是一个常见的新定义的形式,按照新定义,符号表示不超过的最大整数,由此可以得到函数的性质.又定义函数,当时,表示的小数部分.由于①③是错误的,利用排除法,可以选出选项.第Ⅱ卷(共90分)二、填空题(本大题共4小题,每题5分,共20分)13.在△ABC中,,,且,则△ABC的面积为_______.【答案】【解析】【分析】由得到,然后根据三角形的面积公式可得所求.【详解】∵,∴,且为锐角.又,∴.∴.故答案为.【点睛】本题考查三角形面积的计算,解题时需要分清需要的条件,然后逐步求解即可,考查分析和计算能力.14.曲线在点处的切线与两坐标轴围成的三角形的面积是__________.【答案】【解析】【分析】根据导数的几何意义求出切线方程,再求出切线与两坐标轴的交点,最后可得所求三角形的面积.【详解】∵,∴,∴.∴所求切线方程为,即.令得;令得.∴切线与两坐标轴围成的三角形的面积是.故答案为.【点睛】本题考查导数的几何意义,考查计算能力和转化能力,属于简单题.15.已知向量,满足,,,则__________.【答案】【解析】【分析】由可得,然后根据数量积的运算律可得.【详解】∵,∴.又,,∴.∴,∴.故答案为.【点睛】解答本题时注意这一结论的运用,同时还应注意要进行合理的变形,考查计算能力,属于基础题.16.已知数列满足,则的最小值为_____.【答案】【解析】【分析】根据累加法求出数列的通项公式,然后得到的表达式,再根据表达式的特征求出最小值即可.【详解】∵,∴.∴,又满足上式,∴.∴.结合函数的单调性可得:当时,单调递减;当时,单调递增.又,∴的最小值为.故答案为.【点睛】解答本题时注意两点:(1)用累加法求数列的通项公式时,需注意是否要验证第一项的值是否满足通项公式,若满足,则写成一个式子的形式;若不满足,则需把通项公式写成分段函数的形式.(2)用基本不等式求最值时,要注意等号成立的条件,若不满足等号成立的条件,则要利用函数的单调性求解.三、解答题(本大题共6小题共70分。

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试语文试题Word版含答案

辽宁省普兰店市第一中学2018-2019学年高一上学期期中考试语文试题Word版含答案

2018—2019学年度上学期期中考试高一语文时间:150分钟满分:150分范围:必修一第一单元中国现代诗歌:必修一《烛之武退秦师》;必修二《赤壁赋》;必修三《六国论》《劝学》、中国古代诗歌《静女》《无衣》第I卷阅读题一、现代文阅读(35分)(一)论述类文本阅读阅读下面的文字,完成1-3题。

(每题3分,共9分)?红楼梦?的开篇神话① ?红楼梦?是由一个神话故事开端的。

说的是大荒山无稽崖下,有一块女娲补天时未被采用的石头,幻化为神瑛侍者,每天用甘露浇灌三生石畔上的一棵绛珠仙草,后来仙草修成女儿身,愿把一生所有的眼泪还他的情。

因此一事,便引出一部悲金悼玉的?红楼梦?。

②故事虽然说来荒唐无稽,但是任何神话都有其尘根俗缘。

曹雪芹编造的这个神话故事,毫无疑问也是有其现实的基础的。

那么,?红楼梦?中的这块顽石,到底生于何方何地呢? 作者说是本于“大荒山,无稽崖”,用脂砚斋评说的话来说,就是“荒唐也,无稽也”,亦即是无可稽考之处。

在我看来,这是作者和评批者有意让读者处于扑朔迷离之中,它应当是真有其处的。

依据相关材料揆情度理,我认为,它应当是我国东北部的长白山。

在远古时代,人们便称此山为“大荒山”。

我国第一部地理学著作?山海经?中记载:“大荒之中有山,名不咸,在肃慎之国。

”肃慎,位于我国东北的东北部;不咸,蒙语即神仙的意思;不咸山,即仙山。

长白山天池之畔有一天豁峰,山峰形状奇特,山石巨大,其中最大的一块,便名曰“补天石”。

“绛珠仙草”又是什么呢? 我认为,它即是长白山上的名贵特产人参。

人参常被称为“神草”或“仙草”,长着对生的绿叶,绿叶中间挺立着一株长长的花柱,柱上结着一串串红宝石似的珠果,颜色绛红绚丽,形状如同南国红豆,晶莹剔透。

这样看来,这个“绛珠仙草”不是人参又是什么呢?③ “神瑛侍者”呢? 他似是“神鹰”的谐音。

很早以前,满族人中间流传着一个神话:有三个仙女在长白山天池里洗澡,有一只神鸟(也有称说神鹰的)噙来一颗绛红的仙果放到最小的仙女佛库伦的衣服上,仙女吞下红果后生个男孩,便是清世祖先布库里雍顺。

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试地理试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试地理试题

2018-2019学年辽宁省普兰店市第一中学高一上学期期中考试地理试题时间:90分钟满分:100分范围:必修一全部说明:本试题包括第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分。

第Ⅰ卷(选择题60分)本卷共30小题,每小题2分,共60分。

每小题只有一个答案是最符合题目要求的。

“一闪一闪亮晶晶,满天都是小星星,挂在天空放光明,好像许多小眼睛……”是一首大家耳熟能详的童谣。

据此回答第1小题。

1.下列全部属于天体的一组是()A.星云和运行中的通信卫星B.太空中的云雾状物质和天空中飘动的云朵C.陨落地表的流星体残骸和“神舟十号”返回舱D.等待发射的“天宫一号”目标飞行器下图为中国探月工程标识,该标识以中国书法的笔触,抽象勾勒出一轮圆月,一双小脚印踏临其上,象征着探测月球的终极梦想。

据此回答2~3题。

2. 我国预计2018年发射嫦娥四号探测器,该探测器的飞行运动空间不属于()A. 银河系B. 河外星系C. 总星系D. 太阳系3. 该探测器将在月球背面实现人类航天器的首次软着陆,届时会受到诸多来自宇宙空间的威胁,其中科学家难以估计的威胁可能是月球表面()A. 空气过于稀薄B. 宇宙辐射太强C. 陨石撞击多发D. 地球引力偏小2018年3月9日,东亚及东南亚地区迎来了一场日食。

其中东南亚部分地区可见日全食,全食带从印度洋北部开始,经过印度尼西亚、西太平洋部分岛屿,在太平洋东北部结束。

下图为某天文爱好者拍摄的某次日全食照片。

据此回答4~5题。

4.发生在图中太阳被遮挡的部分的太阳活动有()A. 黑子B. 耀斑C. 太阳风D.黑子、耀斑5.日全食照片中未被遮住的这一层在太阳大气剧烈活动时产生的影响可能是()A.影响我国南方地区的交通运输B.影响我国北方地区的有线网络通信C.轮船航行过程中指南针突然失灵D.流星现象突然异常增多6. 地球上水循环、大气运动和生命活动的主要动力是()A. 重力势能B. 生物能C. 太阳辐射能D. 地热能1971年,湖南长沙马王堆一号汉墓中出土一幅彩绘帛画。

辽宁省普兰店市第一中学2019届高三物理上学期期中考试 物理

辽宁省普兰店市第一中学2019届高三物理上学期期中考试 物理

2018—2019学年度上学期月考高三物理时间:90分钟满分:100分范围:必修一必修二选修3-1第一章--第二章第七节本试卷分第Ⅰ卷(选择题)和第Ⅱ卷(非选择题)两部分第Ⅰ卷(选择题,共48分)一.选择题(每小题4分,共48分。

1-8为单选,9--12为多选。

全部选对得4分,对而不全得2分。

)1、我国的传统文化和科技是中华民族的宝贵精神财富,四大发明促进了科学的发展和技术的进步,对现代仍具有重大影响。

下列说法正确的是( )A. 春节有放鞭炮的习俗,根炮炸响的瞬间,动量守恒但能量不守恒B. 火箭是我国的重大发明,现代火箭发射时,火箭对喷出气体的作用力大于气体对火箭的作用力C. 指南针的发明促进了航海和航空,静止时指南针的N极指向北方D. 装在炮带中的火药燃绕爆炸时,化学能全部转化为弹片的动能2、静止在水面上的船长为L.质量为M,一个质量为m的人站在船头,当此人由船头走到船尾时,不计水的阻力,船移动的距离是()A.mL/M B.mL/(M+m)C.mL/(M—m)D.(M—m)L/(M+m)3、物体A和B的质量均为m,且分别与跨过定滑轮的轻绳连接(不计绳与滑轮、滑轮与轴之间的摩擦),在用水平变力F拉物体B沿水平方向向右做匀速直线运动的过程中,下列说法正确的是()A. 绳的拉力大于A的重力B. 物体A匀速上升C. 物体A减速上升D. 绳的拉力先大于A的重力,后变为小于A的重力4、如图所示,两个物块A. B用竖直的轻弹簧连接后悬挂在天花板上,已知物块A的质量为物块B质量的2倍,重力加速度为g.两个物块均处于静止状态,现在突然剪断物块A与天花板之间一的竖直轻绳,剪断瞬间( )A. 物块A的加速度等于g .B. 物块A的加速度等于1.5gC. 物块B的加速度等于0.5gD. 物块B的加速度等于3g5、某质点做直线运动,运动速率的倒数与位移的关系如图,则下列说法正确的是( )A. 质点做匀加速直线运动B. 质点做匀减速直线运动C. 图线的斜率等于质点运动的加速度D. 四边形BBˊCˊC的面积的物理意义是质点从C到Cˊ所用的时间6、如图所示,粗糙水平圆盘上,质量相等的A.B两物块叠放在一起,随圆盘一起做匀速圆周运动,则下列说法正确的是()A. B的向心力是A的向心力的2倍B. 盘对B的摩擦力是对B对A的摩擦力的2倍C. A有沿半径向外滑动的趋势,B有沿半径向内滑动的趋势D. 若B先滑动,则A、B之间的动摩擦因数小于B与盘之间的动摩擦因数7、如图所示,实线为方向未知的三条电场线,从电场中M 点以相同速度飞出a、b 两个带电粒子,运动轨迹如图中虚线所示,则( )A. a 一定带正电,b 一定带负电B. a 的速度将减小,b 的速度将增大C. 两个粒子的动能一个增加一个减小D. a 的加速度将减小,b 的加速度将增大8、如图所示,水平桌面上固定一个竖直挡板,现将一个球体A与截面为直角三角形的物块B 叠放在一起,用水平外力F缓缓向左推动B,使A缓慢升高,设备接触面均光滑,则该过程中( )A. A和B均受三个力作用B. B对桌面的压力越越大C. A对B的压力越越大D. A对墙面的压力大小保持不变9、如图所示,电键闭合,电流表、电压表均为理想电表,若电阻R1断路,则下列说法中正确的是()A. 电流表示数变大B. 电压表示数变大C. 电内电路消耗的功率变大D. R3消耗的功率变大10、如图所示,为发射地球同步卫星的简化轨道示意图,先将卫星发射至近地环绕轨道I上.在卫星经过P点时点火实施变轨进入椭圆轨道Ⅱ,最后在远地点Q再次点火,将卫星送人同步轨道卫Ⅲ上,下列判断正确的是( )A. 卫星沿轨道Ⅱ运动的周期可能等于沿轨道Ⅲ运动的周期B. 卫屋在轨道Ⅰ上运动至P点的速率小于卫星在轨道Ⅱ上运动至同一点的速率C. 卫星沿椭圆轨道运动时,经过P、Q两点处的向心加速度大小相等D. 卫星沿轨道Ⅰ运动至P点的加速度等于沿轨道运动至P点的加速度11、一质量为1 g的质点静止于光滑水平面上,从t=0时刻开始,受到水平外力F作用,外力F随时间的变化如图所示.下列判断正确的是()A. 0~2 s内外力的平均功率是4 WB. 第2 s内外力所做的功是4 JC. 第2 s末外力的瞬时功率最大D. 第1 s末与第2 s末外力的瞬时功率之比为9∶412、如图所示,一固定光滑斜面与水平面间的夹角为θ,轻质弹簧的一端固定在斜面底端的挡板上,另一端与斜面上质量为m的物块连接.开始时用手拉住物块使弹簧伸长1,放手后物块由静止开始下滑,到达最低点时弹簧压缩了2,重力加速度为g。

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辽宁省普兰店市第一中学2018年10月2018~2019学年度高一第一学期期中考试数学试题一.选择题:(本大题共12小题,每小题5分,在每小题给出的四个选项中,只有一项是符合题目要求的.)1.已知集合,,则=( )A. {-1,0}B. {0,1}C. {-1,0,1}D. {0,1,2}【试题参考答案】A【试题分析】解出集合B的元素,再由集合的交集的概念得到结果即可.【试题解答】=,,则={-1,0} 故答案为:A .高考对集合知识的考查要求较低,均是以小题的形式进行考查,一般难度不大,要求考生熟练掌握与集合有关的基础知识.纵观近几年的高考试题,主要考查以下两个方面:一是考查具体集合的关系判断和集合的运算.解决这类问题的关键在于正确理解集合中元素所具有属性的含义,弄清集合中元素所具有的形式以及集合中含有哪些元素.二是考查抽象集合的关系判断以及运算.2.下列函数中,在区间上为增函数的是A. B. C. D.【试题参考答案】C【试题分析】根据已知函数的规律得到函数的增减性,即可.【试题解答】为减函数,B. 为减函数,C. 在上是增函数,D.在所给区间内是减函数。

故答案为:C.本题考查了函数的单调性判断,函数的单调性,一般小题直接判断函数在所给区间内是否连续,接着再判断当x变大时y的变化趋势,从而得到单调性.3.若函数f对于任意实数x总有且f在区间上是减函数,则( )A. B.C. D.【试题参考答案】B【试题分析】f(﹣x)=f(x)可得f(x)为偶函数,结合f(x)在区间(﹣∞,1]上是减函数,即可作出判断【试题解答】∵f(﹣x)=f(x),∴f(x)为偶函数,又f(x)在区间(﹣∞,﹣1]上是减函数,f(2)=f(﹣2),﹣2<﹣<﹣1,∴f(﹣1)<f(﹣)<f(2).故选:B.本题考查函数的奇偶性与单调性,关键在于根据其奇偶性将要比较的数转化到共同的单调区间上,利用单调性予以解决,属于基础题4.若,则下列不等式中不成立的是A. B. C. D.【试题参考答案】B特殊值法,令5.已知函数,若,则的值是( ).A. B. C. D.【试题参考答案】C【试题分析】根据,可分情况讨论当a>0,和当时,分情况讨论即可.【试题解答】已知,当时,解得a=-3,满足题意;当a>0时,-2a=10,解得a=-5,舍去;故a=-3.故答案为:C.求分段函数的函数值,要先确定要求值的自变量属于哪一段区间,然后代入该段的解析式求值,当出现的形式时,应从内到外依次求值;求某条件下自变量的值,先假设所求的值在分段函数定义区间的各段上,然后求出相应自变量的值,切记代入检验,看所求的自变量的值是否满足相应段自变量的取值范围.6.不等式的解集是( )A. B.C. D.【试题参考答案】B,即,解得或,即不等式的解集是,故选B.7.下列命题中,真命题的是( )A. B.C. D. 对恒成立【试题参考答案】D【试题分析】A,举出反例即可;B,可判断原方程无解,即可得到B错误;C,,解得a<0或a>1,可判断出命题错误,D,举出a的值即可.【试题解答】,错误,当x=0.2时,不满足;B.方程的判别式小于0,故方程无解,故B错误;C,,解得a<0或a>1,故C不正确;D 令a>1,即可满足条件,对任意的x均有成立,故正确。

故答案为:D.要判定特称命题“”是真命题,只需在集合中找到一个元素,使成立即可;如果在集合中,使成立的元素不存在,那么这个特称命题是假命题.判断特称命题的真假时,一定要结合生活和数学中的丰富实例,通过相关的数学知识进行判断.8.“”是“”的( )A. 充要条件B. 必要不充分条件C. 充分不必要条件D. 既不必要也不充分条件【试题参考答案】C的充要条件为或,所以是的充分不必要条件。

故选C。

9.函数的最小值是( )A. 2+2B. 2-2C. 2D. 2【试题参考答案】A【试题分析】先将函数变形可得y==(x﹣1)++2,再利用基本不等式可得结论.【试题解答】y==(x﹣1)++2∵x>1,∴x﹣1>0∴(x﹣1)+≥2(当且仅当x=+1时,取等号)∴y=≥2+2故选:A.本题考查函数的最值,考查基本不等式的运用,属于中档题.在利用基本不等式求最值时,要特别注意“拆、拼、凑”等技巧,使其满足基本不等式中“正”(即条件要求中字母为正数)、“定”(不等式的另一边必须为定值)、“等”(等号取得的条件)的条件才能应用,否则会出现错误.10. 如图中的图象所表示的函数的解析式为( )A.B.C.D.【试题参考答案】B【试题分析】分段求解:分别把0≤x≤1及1≤x≤2时的解析式求出即可.【试题解答】当0≤x≤1时,设f(x)=kx,由图象过点(1,),得k=,所以此时f(x)=x;当1≤x≤2时,设f(x)=mx+n,由图象过点(1,),(2,0),得,解得所以此时f(x)=.函数表达式可转化为:y=|x-1|(0≤x≤2)故答案为:B本题考查函数解析式的求解问题,本题根据图象可知该函数为分段函数,分两段用待定系数法求得.11.下列命题中正确的是 ( )A. 函数的最小值为B. 设集合,则的取值范围是C. 在直角坐标系中,点在第四象限的充要条件是或D. 若集合,则集合的子集个数为7【试题参考答案】C【试题分析】A根据均值不等式得到最值;B,根据题干条件得到;C,点位于第二象限即;D集合化为子集个数为:8个.【试题解答】A,函数=,最大值为,故A不正确;B,集合,则,故B不正确;C. 在直角坐标系中,点在第四象限的充要条件是,故C正确;D. 集合=子集个数为:8个.故答案为:C。

这个题目考查的是命题真假的判断,用到均值不等式求最值,集合的并集运算,点所在象限和坐标的特点的关系,以及集合子集个数的判断. 在利用基本不等式求最值时,要特别注意“拆、拼、凑”等技巧,使其满足基本不等式中“正”(即条件要求中字母为正数)、“定”(不等式的另一边必须为定值)、“等”(等号取得的条件)的条件才能应用,否则会出现错误.12.已知定义在上的函数的图像经过点,且在区间单调递减,又知函数为偶函数,则关于的不等式的解为 ( )A. B. C. D.【试题参考答案】D【试题分析】由题意可得f(3)=0,f(﹣x+2)=f(x+2),即函数f(x)关于直线x=2对称,f(x)在(﹣∞,2]单调递增,且f(1)=f(3)=0,可得1<x+1<3,解不等式即可得到所求解集.【试题解答】定义在R上的函数f(x)的图象经过点M(3,0),可得f(3)=0,f(x)在区间[2,+∞)单调递减,又知函数f(x+2)为偶函数,可得f(﹣x+2)=f(x+2),即函数f(x)关于直线x=2对称,f(x)在(﹣∞,2]单调递增,且f(1)=f(3)=0,由f(x+1)>0,可得1<x+1<3,解得0<x<2,即解集为(0,2),故选:D.本题考查函数的奇偶性、单调性和对称性的应用,注意定义法的应用,考查不等式解法,属于中档题.二.填空题:(本大题共4小题,每小题5分)13.函数的定义域为________【试题参考答案】【试题分析】函数的定义域为:,写成区间形式即可.【试题解答】函数的定义域为:即故答案为:.常见的求定义域的类型有:对数,要求真数大于0即可;偶次根式,要求被开方数大于等于0;分式,要求分母不等于0,零次幂,要求底数不为0;多项式要求每一部分的定义域取交集。

14.已知,则的最小值为________________【试题参考答案】,则,当且仅当,等号成立,所以的最小值为故答案为.【易错点晴】本题主要考查利用基本不等式求最值,属于难题. 利用基本不等式求最值时,一定要正确理解和掌握“一正,二定,三相等”的内涵:一正是,首先要判断参数是否为正;二定是,其次要看和或积是否为定值(和定积最大,积定和最小);三相等是,最后一定要验证等号能否成立(主要注意两点,一是相等时参数否在定义域内,二是多次用或时等号能否同时成立).15.若命题“”是真命题,则实数a的取值范围是 ________ 【试题参考答案】【试题分析】根据二次函数的性质得到关于a的不等式,解出即可.【试题解答】∃x0∈R,x2+(a﹣1)x+1<0,则△=(a﹣1)2﹣4>0,解得:a>3或a<﹣1,故答案为:.本题考查了特称命题的真假,考查二次函数的性质,是一道基础题.一般命题的否定通常是保留条件否定其结论,得到真假性完全相反的两个命题;含有一个量词的命题的否定,是在否定结论的同时,改变量词的属性,即全称量词改为存在量词,存在量词改为全称量词.注意:命题的否定只否定结论,而否命题是条件与结论都否定.16.设a>b>0,则的最小值是_______.【试题参考答案】4a2+=a2-ab+ab+=a(a-b)++ab+≥2+2=4.当且仅当a(a-b)=1且ab=1,即a=,b=时取等号.三.解答题:解答应写出文字说明,证明过程或演算步骤.17.已知集合或.(1)若,求的取值范围;(2)若“”是“”的充分条件,求的取值范围.【试题参考答案】(1); (2)或.【试题分析】(1),故得到;(2)根据题意得到,故或即可.【试题解答】(1),,的取值范围是(2)因为“”是“”的充分条件,或的取值范围是或.判断充要条件的方法是:①若p⇒q为真命题且q⇒p为假命题,则命题p是命题q的充分不必要条件;②若p⇒q为假命题且q⇒p为真命题,则命题p是命题q的必要不充分条件;③若p⇒q为真命题且q⇒p为真命题,则命题p是命题q的充要条件;④若p⇒q为假命题且q⇒p为假命题,则命题p是命题q的即不充分也不必要条件.⑤判断命题p与命题q所表示的范围,再根据“谁大谁必要,谁小谁充分”的原则,判断命题p与命题q的关系.18.已知不等式的解集为(1)求a的值;(2)若不等式的解集为R,求实数m的取值范围.【试题参考答案】(1); (2).【试题分析】(1)根据题意得到方程的两根为,由韦达定理可得到结果;(2)不等式的解集为R,则解出不等式即可.【试题解答】(1)由已知,,且方程的两根为.有,解得;(2)不等式的解集为R,则,解得,实数的取值范围为.这个题目考查了根和系数的关系,涉及到两根关系的题目,多数是可以考虑韦达定理的应用的,也考查到二次函数方程根的个数的问题.19.(1)若是方程的两个根,求的值.(2)已知集合,若中元素至多只有一个,求的取值范围. 【试题参考答案】(1); (2)或.【试题分析】(1)根据韦达定理得到,代入韦达定理得到结果即可;(2)①当时满足题意;②当0时,方程为二次的,只需要.【试题解答】(1)由根与系数的关系得:(2)①当时,,满足题意.②当0时,方程至多只有一个解,则,即,综上所述,的取值范围是或.这个题目考查了根和系数的关系,涉及到两根关系的题目,多数是可以考虑韦达定理的应用的,也考查到二次函数方程根的个数的问题.20.(1)已知 且 的最大值以及相应的和的值; (2)已知,且求的最小值;(3)已知方程的两个根都是正数,求实数的取值范围。

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