可汗学院新SAT数学真题下载

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SAT考试数学练习题

SAT考试数学练习题

SAT 考试数学练习题 2来源 : 91SAT 考试网时间 : 2009 年 08 月 20 日1. If f(x) = │(x² –50)│, what is the value of f( -5) ?A. 75B. 25C. 0D. -25E. -752. ( √2 - √3 )² =A. 5 - 2√6B. 5 - √6C. 1 - 2√6D. 1 - √2E. 13. 230 + 230 + 230 + 230 =A. 8120B. 830C. 232D. 230E. 2264. Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?A. 10B. 8C. 6D. 4E. 25. In the figure above AD = 4, AB = 3 and CD = 9. What is the area of triangle AEC ?A. 18B. 13.5C. 9D. 4.5E. 3答案:1.Correct Answer: BExplanation:If x = -5, then (x² – 50) = 25 – 50 = -25But the sign │x│ means the absolute value of x (the distance between the number and zero on the number line). Absolute values are always positive.│-25 │ = 252.Correct Answer: AExplanation:Expand as for (a + b)2.(√2 - √3)(√2 - √3) = 2 - 2(√2 + √3) + 3 = 5 - 2 √63.Correct Answer: CExplanation:All four terms are identical therefore we have 4 (230).But 4 = 22, and so we can write 22. 230Which is equivalent to 2324. Correct Answer: BExplanation:Amy can travel clockwise or anticlockwise on the diagram.Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes. Similarly, anticlockwise she has four different routes.Total routes = 85.Correct Answer: DExplanation:If we take AE as the base of triangle AEC, then the height is CD.The height of the triangle is therefore, 9 (given).To find the base we need to see that triangles AEB and CDE are similar. The ratio AB: CD, is therefore equal to the ratio AE: ED. The given information shows that the ratio is 3:9, or 1:3. Now dividing AD (4) in this ratio gives us AE as 1.The area of AEC = ½ base x heigh t=1/2 x 9 = 4.5SAT 考试数学练习题 3来源 : 91SAT 考试网时间 : 2009 年 08 月 20 日1.Which of the following could be a value of x, in the diagram above?A. 10B. 20C. 40D. 50E.any of the above2.Helpers are needed to prepare for the fete.Each helper can make either 2 large cakes or 35small cakes per hour.The kitchen is available for 3hours and20 large cakes and 700 small cakes are needed. How many helpers are required?A. 10B. 15C. 20D. 25E. 303.Jo's collection contains US,Indian and British stamps.If the ratio of US to Indian stamps is 5to 2and the ratio of Indian to British stamps is 5to 1,what is the ratio of US to British stamps?A. 5 : 1B. 10 : 5C. 15 : 2D. 20 : 2E. 25 : 24.A 3by 4rectangle is inscribed in circle.What is the circumference of the circle?A.2.5πB.3πC.5πD.4πE. 10π5.Two sets of 4consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set?A. 4B.7C.8D. 12E. it cannot be determined from the information given.答案:1.Correct Answer: BExplanation:The marked angle, ABC must be more than 90 degrees because it is the external angle of triangle BDC, and must be equal to the sum of angles BDC (90) and DCB. Also ABC is not a straight line and must be less than 180. Therefore 90 < 5x < 180 The only value of x which satisfies this relation is 20.2.Correct Answer: AExplanation:20large cakes will require the equivalent of 10helpers working for one hour.700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10helpers.3.Correct Answer: EExplanation:Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number. US : Indian = 5 : 2,n n d ian :British =5: 1.Multiply the first by 5,and the second by 2.Now US : Indian = 25 : 10, and Indian : British = 10 : 2 Hence the two ratios can be combined and US : British = 25 : 24.Correct Answer: CExplanation:Draw the diagram.The diagonal of the rectangle is the diameter of the circle. The diagonal is the hypotenuse of a 3,4,5triangle,and is therefore,5. Circumference = π.diameter = 5π5.Correct Answer: DExplanation:If two sets of four consecutive integers have one integer in common,the total in the combined set is 7., and we can write the sets as n + (n + 1) + (n + 2) + (n + 3 ) and (n + 3) + (n + 4) + (n + 5) + (n + 6) Note that each term in the second set is 3more than the equivalent term in the first set.Since there are four terms the total of the differences will be 4x 3=12SAT 考试数学练习题 4来源 : 91SAT 考试网时间 : 2009 年 08 月 20 日1. If f(x) = (x + 2) / (x-2) for all integers except x=2, which of the following has the greatest value?A. f(-1)B. f(0)C. f(1)D. f(3)E. f(4)2. ABCD is a square of side 3, and E and F are the mid points of sides AB and BC respectively. What is the area of the quadrilateral EBFD ?A. 2.25B. 3C. 4D. 4.5E. 63. If n ≠ 0, which of the following mus t be greater than n?I 2nII n²III 2 - nA. I onlyB. II onlyC. I and II onlyD. II and III onlyE. None4. After being dropped a certain ball always bounces back to 2/5 of the height of its previous bounce. After the first bounce it reaches a height of 125 inches. How high (in inches) will it reach after its fourth bounce?A. 20B. 15C. 8D. 5E. 3.25. n and p are integers greater than 15n is the square of a number75np is the cube of a number.The smallest value for n + p isA. 14B. 18C. 20D. 30E. 50答案:1.Correct Answer: DExplanation:You can solve this by back solving – substitute the answer choices in the expression and see which gives the greatest value.satA (-1 + 2) / (-1-2) = -2 / 2 = -1;B (0 + 2) / (0-2) = 2/ -2 = -1;C (1 + 2) / (1-2) = 3/-1 = -3;D (3 + 2) / (3-2) = 5/1 = 5 ;E (4+ 2) / (4-2) = 6/2 = 3If you had just chosen the largest value for x you would have been wrong. So although itlooks a long method, it is actually quick and accurate since the numbers are really simple and you can do the math in your head.2.Correct Answer: DExplanation:(Total area of square - sum of the areas of triangles ADE and DCF) will give the area of the quadrilateral 9 - (2 x ½ x 3 x 1.5) = 4.53.Correct Answer: EExplanation:Remember that n could be positive negative or a fraction. Try out a few cases: In case I, if n is -1, then 2n is less than n. In case II, if n is a fraction such as ½ then n2 will be less than n. Incase III, if n is 2, then 2-n = 0, which is less than n. Therefore, none of the choices must be greaterthan n4.Correct Answer: CExplanation:If after each bounce it reaches 2/5 of the previous height, then after the second bounce it will reach 2/5 x 125. After the third it will reach 2/5 x 2/5 x 125. After the fourth it will reach 2/5 x 2/5 x 2/5 x 125. This cancels down to 2 x 2 x 2 = 85.Correct Answer: AExplanation:The smallest value for n such that 5n is a square is 5. 75np can now be written as 75 x 5 x p. This gives prime factors.... 3 x 5 x 5 x 5 x p To make the expression a perfect cube, p will have to have factors 3 x 3 , and hence p =9 n + p = 5 + 9 = 14SAT 考试数学练习题 5来源 : 太傻网考试频道整理时间 : 2009 年 08 月 27 日1. If f(x) = x² – 3, where x is an integer, which of the following could be a value of f(x)?I 6II 0III -6A. I onlyB. I and II onlyC. II and III onlyD. I and III onlyE. I, II and IIICorrect Answer: A解析:Choice I is correct because f(x) = 6 when x=3. Choice II is incorrect because to make f(x) =0, x² would have to be 3. But 3 is not the square of an integer. Choice III is incorrect because to make f(x) = 0, x² would have to be –3 but squares cannot be negative. (The minimum value for x2 is zero; hence, the minimum value for f(x) = -3)2. For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?A. 48B. 49C. 50D. 51E. 52Correct Answer: C解析:1 < 4n + 7 < 200. n can be 0, or -1. n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1. The largest value for n will be an integer < (200 - 7) /4. 193/4 = 48.25, hence 48. The number of integers between -1 and 48 inclusive is 503. In the following correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?A. 23B. 22C. 18D. 16E. 14Correct Answer: B解析:First you must realize that the sum of two 2-digit numbers cannot be more that 198 (99 + 99). Therefore in the given problem D must be 1. Now use trial and error to satisfy the sum 5A +BC = 143. A + C must give 3 in the units place, but neither can be 1 since all the digits have to be different. Therefore A + C = 13. With one to carry over into the tens column, 1 + 5 + B = 14, and B = 8. A + C + B + D = 13 + 8 + 1 = 224. 12 litres of water a poured into an aquarium of dimensions 50cm length , 30cm breadth, and 40 cm height. How high (in cm) will the water rise?(1 litre = 1000cm³)A. 6B. 8C. 10D. 20E. 40Correct Answer: B解析:Total volume of water = 12 liters = 12 x 1000 cm3. The base of the aquarium is 50 x 30 = 1500cm3. Base of tank x height of water = volume of water. 1500 x height = 12000; height = 12000 / 1500 = 85. Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?A. 11/P + 6B. P/11 +6C. 17 - P/6D. 17/PE. 11.5PCorrect Answer: A解析:Let Ben’s age now be B. Anita’s age now is A. (A - 6) = P(B - 6)But A is 17 and therefore 11 = P(B - 6). 11/P = B-6(11/P) + 6 = BSAT 考试数学练习题 6来源 : 太傻网考试频道整理时间 : 2009 年 08 月 27 日1. The distance from town A to town B is five miles. C is six miles from B. Which of the following could be the distance from A to C?I 11II 1III 7A. I onlyB. II onlyC. I and II onlyD. II and III onlyE. I, II, or III. Correct Answer: E 解析:Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11, but anywhere in between is possible.2. √5 percent of 5√5 =A. 0.05B. 0.25C. 0.5D. 2.5E. 25Correct Answer: B解析:We can write the statement mathematically, using x to mean ‘of’ and /100 for ‘per cent’ . S o ( √5/100) x 5√5 = 5 x 5 /100 = 0.253. If pqr = 1 , rst = 0 , and spr = 0, which of the following must be zero?A. PB. QC. RD. SE. TCorrect Answer: D解析:If pqr = 1, none of these variable can be zero. Since spr = 0 , and since p and r are not zero, s must be zero. (Note that although rst = 0, and so either s or t must be zero, this is not sufficient to state which must be zero)4.A. 1/5B. 6/5C. 6³D. 64 / 5E. 64Correct Answer: E解析:65 = 64x 6(64 x 6) - 64 = 64(6 - 1) = 64 x 5 Now, dividing by 5 will give us 645. -20 , - 16 , - 12 , -8 ....In the sequence above, each term after the first is 4 greater than the preceding term. Which of the following could not be a term in the sequence?A. 0B. 200C. 440D. 668E. 762Correct Answer: E解析:All terms in the sequence will be multiples of 4. 762 is not a multiple of 4SAT 考试数学练习题 7来源 : 太傻网考试频道整理时间 : 2009 年 08 月 27 日1. If a² = 12, then a4 =A. 144B. 72C. 36D. 24E. 16Correct Answer:A解析:a4 = a2 x a2 = 12 x 12 = 1442. If n is even, which of the following cannot be odd?I n + 3II 3nIII n² - 1A. I onlyB. II onlyC. III onlyD. I and II onlyE. I, II and IIICorrect Answer: B解析:In case I , even plus odd will give odd. In case II, odd times even will give even. In case III even squared is even, and even minus odd is odd. (You can check this by using an easy evennumber like 2 in place of n). Only case II cannot be odd.3. One side of a triangle has length 8 and a second side has length 5. Which of the following could be the area of the triangle?I 24II 20III 5A. I onlyB. II onlyC. III onlyD. II and III onlyE. I, II and IIICorrect Answer: D解析:The maximum area of the triangle will come when the given sides are placed at right angles. If we take 8 as the base and 5 as the height the area = ½ x 8 x 5 = 20. We can alter the angle between the sides to make it less or more than 90, but this will only reduce the area. (Draw it out for yourself). Hence the area can be anything less than or equal to 20.4. A certain animal in the zoo has consumed 39 pounds of food in six days. If it continues to eat at the same rate, in how many more days will its total consumption be 91 pounds?A. 12B. 11C. 10D. 9E. 8Correct Answer: E解析:Food consumed per day = 39/6. In the remaining days it will consume 91 - 39 pounds = 52 pounds. Now divide the food by the daily consumption to find the number of days. 52 / (39/6) = 52 x (6 / 39) = 85. A perfect cube is an integer whose cube root is an integer. For example, 27, 64 and 125 are perfect cubes. If p and q are perfect cubes, which of the following will not necessarily be a perfect cube?A. 8pB. pqC. pq + 27D. -pE. (p - q)6Correct Answer: C解析:A perfect cube will have prime factors that are in groups of 3; for example 125 has the prime factors 5 x 5 x 5 , and 64 x 125 will also be a cube because its factors will be 4 x 4 x 4 x 5 x 5 x 5. Consider the answer choices in turn. 8 is the cube of 2, and p is a cube, and so the product will also be a cube. pq will also be a cube as shown above.pq is a cube and so is 27, but their sum need not be a cube. Consider the case where p =1 and q = 8, the sum of pq and 27 will be 35 which has factors 5 x 7 and is not a cube. -p will be a cube. Since the difference between p and q is raised to the power of 6, this expression will be a cube (with cube root = difference squared).SAT 考试数学练习题 8来源 : 太傻网考试频道整理时间 : 2009 年 08 月 27 日6. What is the length of the line segment in the x-y plane with end points at (-2,-2) and (2,3)?A. 3B. √31C. √41D. 7E. 9Correct Answer: C解析:Sketch a diagram and calculate the distance (hypotenuse of a right triangle) using Pythagoras theorem.Vertical height of triangle = 5 ; horizontal side = 4 ; hypotenuse = √(25 + 16) = √417. n is an integer chosen at random from the set{5, 7, 9, 11 }p is chosen at random from the set{2, 6, 10, 14, 18}What is the probability that n + p = 23 ?A. 0.1B. 0.2C. 0.25D. 0.3E. 0.4Correct Answer:A解析:Each of the integers in the first set could be combined with any from the second set, giving a total of 4 x 5 = 20 possible pairs. Of these the combinations that could give a sum of 23 are (5 + 18), and (9 + 14). This means that the probability of getting a sum of 23 is 2/20 = 1/108. A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 15%. Staff are allowed a further 10% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ?A. 0.75DB. 0.76DC. 0.765DD. 0.775DE. 0.805DCorrect Answer: C解析:If the price is reduced by 15 %, then the new price will be 0.85D. If this new price is further reduced by 10%, the discounted price will be 0.9 x 0.85D = 0.765D9. All the dots in the array are 2 units apart vertically and horizontally. What is the length of the longest line segment that can be drawn joining any two points in the array without passing through any other point ?A. 2B. 2√2C. 3D. √ 10E. √20Correct Answer: E解析:The longest line segment that can be drawn without passing through any dots other than those at the beginning and end of the segment, such a line could go from the middle dot in the top row to either the bottom left or right dot. In any case the segment will be the hypotenuse of a right triangle with sides 2 and 4. Using Pythagoras theorem the hypotenuse will be √(2 ² + 4 ² ) = √2010. If the radius of the circle with centre O is 7 and the measure of angle AOB is 100, what is the best approximation to the length of arc AB ?A. 9B. 10C. 11D. 12E. 13Correct Answer: D解析:If the radius is 7, the circumference = 14π . The length of the arc is 100/360 of the circumference. Taking π as 22/7 we get. (100 x 14 x 22) / (360 x 7) which reduces to 440/ 36 = 12.22 (i.e. approx. 12)。

SAT数学习题及答案下载

SAT数学习题及答案下载

SAT数学习题及答案下载下面为大家精选了一些SAT数学考试练习题,同学们可适当进行下载练习。

1. Which of the following could be a value of x, in the diagram above?A. 10B. 20C. 40D. 50E. any of the above2. Helpers are needed to prepare for the fete. Each helper can make either 2 large cakes or 35 small cakes per hour. The kitchen is available for 3 hours and 20 large cakes and 700 small cakes are needed. How many helpers are required?A. 10B. 15C. 20D. 25E. 303. Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?A. 5 : 1B. 10 : 5C. 15 : 2D. 20 : 2E. 25 : 24. A 3 by 4 rectangle is inscribed in circle. What is the circumference of the circle?A. 2.5πB. 3πC. 5πD. 4πE. 10π5. Two sets of 4 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set?A. 4B. 7C. 8D. 12E. it cannot be determined from the information given.6. If f(x) = (x + 2) / (x-2) for all integers except x=2, which of the following has the greatest value?A. f(-1)B. f(0)C. f(1)D. f(3)E. f(4)7. ABCD is a square of side 3, and E and F are the mid points of sides AB and BC respectively. What is the area of the quadrilateral EBFD ?A. 2.25B. 3C. 4D. 4.5E. 68. If n ≠ 0, which of the following must be greater than n?I 2nII n²III 2 - nA. I onlyB. II onlyC. I and II onlyD. II and III onlyE. None9. After being dropped a certain ball always bounces back to 2/5 of the height of its previous bounce. After the first bounce it reaches a height of 125 inches. How high (in inches) will it reach after its fourth bounce?A. 20B. 15C. 8D. 5E. 3.210. n and p are integers greater than 15n is the square of a number75np is the cube of a number.The smallest value for n + p isA. 14B. 18C. 20D. 30E. 50。

可汗学院新增SAT阅读和语法真题PDF下载

可汗学院新增SAT阅读和语法真题PDF下载

可汗学院新增SAT阅读和语法真题PDF下载可汗学院新增SAT阅读和语法真题PDF下载可汗学院9月份又新增了SAT阅读7篇及语法真题6篇,现在一共有75篇SAT阅读真题和54篇SAT 语法真题。

下半年的SAT考试的小伙伴绝不能错过的第一手资料。

想要下载的同学,请移步:/sat/baokaochangshi/610399.html早前SAT可汗学院官方就已经放出了68篇阅读,目前一共有75篇SAT阅读真题,如果想要下载之前的68篇阅读真题,请点击:新SAT阅读真题下载(68篇)同样,加上这次放出来的6篇SAT语法真题,现在一共有54篇语法真题,如果想要下载之前的48篇可汗学院SAT语法真题,下载请点击:新SAT语法真题下载(48以下是可汗学院新增SAT阅读真题Literature L2原文及题目,想要下载本次新增的全部真题及答案,请移步:/sat/baokaochangshi/610399.htmlLiterature L2Questions 1-11 are based on the following passage.This passage is adapted from Linda Niehoff, “Like Magic Waiting.”?2015 by Linda Niehoff.We walked through the field a long time, pushing tall grass out of the way, before we saw anything. I’d p luck ticks out of my hair later and scratch red bumps. I hoped it was worth it.“How much longer?” I asked. I wondered now if it was just a story Tamara told in her bedroom with the window propped open and flies buzzing everywhere. There were always flies and the sour smell of hog drifting in on dusty Saturday afternoons.We’d already flipped through shiny magazines andsmelled their thick scent. We’d smeared watermelon polish on our nails for a moment that’d probably never come. Then we rolled the magazines up and slapped at the never-ending flies. Coming out here was the only thing left to do.“Sometimes it takes a second to find,” Tamara said as she stopped and scanned the field, and I said nothing because I still wanted to believe her.I turn ed back around. From here the sagging trailer was the size of a thumbprint. It was hard to believe we’d been crammed inside—it seemed too small to hold us. You could block it out with a finger and make it disappear.The late summer sun sank low in the far row of trees and looked like moving globs of light. If I squinted my eyes and let them go all blurry, it glittered just like magic waiting. Or how I pictured magic might look if I could ever find it.“Should we go back?” I asked, right as she pointed.“There it is.”At first I couldn’t make it out. Weeds and golden grass had pierced the wood and pushed through, making it hard to tell what it had been. I was just about to ask her where when I saw the face.Its teeth were bared in an eternal grin. A tiger. Or a lion,maybe. A few feet away lay a camel. And I thought I saw a giraffe, but it was hard to tell. The framework was gone. Probably cut up and sold for firewood a long time ago.“I told you,” she said, but I didn’t look at her.I bent down and touched its head, the lion or tiger, and traced my newly painted nail along a red wooden vein. It was a long-ago ribbon or maybe even a rose, now bled of color except for one faint crimson line that clung to its splinters and wouldn’t let go. The wood l et out a rotting sigh, and the smell of damp and soil rose up like something whispered. It looked old. And not just because of the rotting wood. It looked old-fashioned.“Where’d it come from?” I asked.“Don’t know,” T amara said. “It’s always been here. Even my mo m remembers it from when she was a girl.”“She never rode it?”Tamara shook her head.Somebody had carved each eye, each tooth, each wild,blowing curl and set it out in a farmer’s field. Others had stood in line, clutching sweaty coins, j ust to ride around in circles to the sound of a calliope. Until it wasn’t enough anymore. Or maybe there was just too much to keep it standing. Too much sky pressing down, and now it was just wooden bones.I wished I could have seen him twirling madly, head lifted high and proud, but there was still a fierceness in his gaze thatnot even a prison of weeds could hold. Even though the earth was slowly swallowing him, it was like he wouldn’t stop fighting.I looked up at Tamara, but I could see that she di dn’t care,not really.“It’s just a pile of wood,” she said when she saw how I looked at her.But I wanted to tell her to shut up. This was haunted ground.A whole other world had moved and swallowed and ached unseen under this one with cries and laughter and screams. For a moment, I could almost hear it on the hot breath of wind that brushed my cheek. I strained to listen before the cicada song rose up and sang it away. Tamara shrugged and chewed on a nail. She was already peeling off the watermelon polish.问题:1A main purpose of the passage is to develop a narrative thatA) entertains the reader by presenting a series of light- hearted, humorous anecdotes.B) engages the reader by with holding information to create interest and anticipation.C) involves the reader in an intricate mystery that the characters are unable to resolve.D) inspires compassion in the reader by portraying a tragic event in the narrator’s life.2Over the course of the passage, the main focus shifts from aA) recollection of the beginning of a friendship to a portrayal of the current state of that friendship.B) narration of an individual’s thoughts to a description of a setting.C) depiction of a search to a reflection on the object of that search.D) discussion of a plan to an account of that plan’s failed execution.3It can reasonably be inferred that the time the narrator spends with Tamara on Saturdays generallyA) is largely focused on completing chores.B) involves a great deal of routine.C) prevents her from being outside.D) consists of her listening to Tamara tell stories.4Paragraph 6 (lines 22-25) primarily senses to provide a sense of the narrator’sA) longing for the extraordinary.B) respect and appreciation for the natural world.C) curiosity about her physical surroundings.D) alienation from those around her.5When the narrator observes that part of the lion or tiger is "bled of color" in line 39, she most nearly means that the color hasA) spread over that area.B) harmed the wood in that area.C) faded from that area.D) been deliberately removed from that area.6In context, the phrase “Until it wasn’t enough anymore” in lines 53-54 most likely refers to which event?A) The wooden animals no longer resembled real creatures.B) People lost interest in riding on the wooden animals.C) The artist stopped creating new wooden figures.D) People decided to take apart the frame for firewood.7In the passage, the narrator characterizes the lion or tiger as appearingA) resolute.B) pretentious.C) foolish.D) resigned.8The narrator’s reac tion to the ruins suggests that she is someone whoA) engages her imagination when encountering new situations.B) finds herself drawn to dangerous environments.C) feels reluctant to let others see her emotional responses to events.D) exercises caution in expressing her observations.9Which choice provides the best evidence for the answer to the previous question?A) lines 32-34 (“Its … tell”)B) lines 43-44 (“It … old-fashioned")C) lines 50-51 (“Somebody … field”)D) lines 67-70 (“A whole …cheek”)10The interactions between the narrator and Tamara suggest which main difference in their personalities?A) Tamara values learning about the past while the narrator is only interested in her present situation.B) Tamara prefers to spend time indoors while the narrator prefers to spend time outside.C) Tamara is eager to take risks while the narrator prefers activities that are safe.D) Tamara is indifferent to her surroundings while the narrator views her surroundings with awe11Which choice provides the best answer to the previous question?A) lines 15-17 (“Sometimes … her”)B) lines 26-27 (“Should … is")C) lines 45-47 (“Where'd … girl")D) lines 64-67 (“It's … ground”)。

(2021年整理)SAT数学真题精选

(2021年整理)SAT数学真题精选

SAT数学真题精选编辑整理:尊敬的读者朋友们:这里是精品文档编辑中心,本文档内容是由我和我的同事精心编辑整理后发布的,发布之前我们对文中内容进行仔细校对,但是难免会有疏漏的地方,但是任然希望(SAT数学真题精选)的内容能够给您的工作和学习带来便利。

同时也真诚的希望收到您的建议和反馈,这将是我们进步的源泉,前进的动力。

本文可编辑可修改,如果觉得对您有帮助请收藏以便随时查阅,最后祝您生活愉快业绩进步,以下为SAT数学真题精选的全部内容。

SAT数学真题精选1. If 2 x + 3 = 9, what is the value of 4 x – 3 ?(A) 5 (B) 9 (C) 15 (D) 18 (E) 212。

If 4(t + u) + 3 = 19, then t + u = ?(A) 3 (B) 4 (C) 5 (D) 6 (E) 73。

In the xy-coordinate (坐标) plane above, the line contains the points (0,0)and (1,2)。

If line M (not shown) contains the point (0,0) and is perpendicular (垂直) to L, what is an equation of M?(A) y = —1/2 x (B) y = —1/2 x + 1 (C) y = — x (D) y = — x + 2 (E) y = -2x4. If K is divisible by 2,3, and 15, which of the following is also divisible by these numbers?(A) K + 5 (B) K + 15 (C) K + 20 (D) K + 30 (E) K + 455. There are 8 sections of seats in an auditorium. Each section contains at least 150 seats but not more than 200 seats。

CB携手可汗学院共发布了4套新SAT试题可免费练习-智课教育出国考试

CB携手可汗学院共发布了4套新SAT试题可免费练习-智课教育出国考试

智 课 网 S A T 备 考 资 料CB携手可汗学院共发布了4套新SAT试题可免费练习-智课教育出国考试2015年6月2日,College Board和可汗学院合作为考生们免费提供了4套完整的心SAT练习题,考生们可以免费在线进行练习了,下面小编为大家简单介绍一下练习的流程。

参加2016年新SAT考试的考生们不用再担心没有习题可以练习了,2015年6月2日,College Board和可汗学院合作为考生们免费提供了4套完整的心SAT练习题,考生们可以免费在线进行练习了,下面小编为大家简单介绍一下练习的流程。

第一步:考生们注册登陆后会看见下面这样的页面,可以选择测试SAT还是PSAT,考生们选择SAT就可以了。

第二步:选择SAT后,系统会问你是选择现行的SAT测试,新SAT 的测试题,还是不确定。

第三步:选择新SAT后,进入加一个界面,考生们可选择SAT单项练习(数学,写作,阅读)或者是官方完整的套题。

第四步:加入我们选择了阅读练习题,就会看到这样一个界面。

第五步:进入阅读测试界面以后,我们会看到提示有4个等级的测试题,等级越高的难度越大,考生们可以从LEVEL1开始练习,同时系统会提示在线练习时不计时的。

第六步:点击下一步,考生们就可以开始在线练习了,如下是在线测试的界面。

第七步: 测试完成之后,系统会自动完成对考生们测试的测试诊断,考生们还可以点击返回查看原文,答案解析(如下图所示)值得一提的是,可汗学院的在线测试平台不仅提供了诊断性测试(di agnostic quiz),还提供考试建议和计划(tips andplanning),还有完整的测试题目(full-length exams), 如果考生选择了完整的测试题,那么就要在规定时间内完成,并且系统会不可以跨区域答题,在做完一套题目之后才能解锁进入下一套模拟题,总是这对于SAT 考生是一个很好的学习平台,希望大家能充分学习利用。

可汗学院介绍:可汗学院(Khan Academy),是由孟加拉裔美国人萨尔曼·可汗创立的一家教育性非营利组织,主旨在于利用网络影片进行免费授课,现有关于数学、历史、金融、物理、化学、生物、天文学等科目的内容,教学影片超过2000段,机构的使命是加快各年龄学生的学习速度。

sat试题及答案

sat试题及答案

sat试题及答案SAT试题及答案一、阅读理解(共20题,每题2分,总计40分)1. 根据文章A,作者主要讨论了什么主题?A. 环境保护的重要性B. 科技发展对环境的影响C. 可持续发展的策略D. 气候变化的成因答案:C2. 文章B中提到的“生态足迹”是指什么?A. 人类对自然资源的消耗量B. 人类对环境的污染程度C. 人类对生物多样性的影响D. 人类对气候系统的影响答案:A...20. 文章T中作者对于未来的看法是什么?A. 悲观的B. 乐观的C. 中立的D. 无法确定答案:B二、写作(共1题,总计20分)21. 根据所给材料,写一篇不少于500字的议论文,阐述你对“教育公平”的看法。

答案:略三、数学(共20题,每题2分,总计40分)22. 如果一个圆的半径是5厘米,那么它的面积是多少平方厘米?A. 78.5B. 100C. 157D. 196答案:A23. 一个直角三角形的两条直角边分别是3厘米和4厘米,那么它的斜边是多少厘米?A. 5B. 6C. 7D. 8答案:A...41. 如果一个数列的前三项是2, 4, 6,那么这个数列的第10项是多少?A. 20B. 22C. 24D. 26答案:A四、语法(共20题,每题2分,总计40分)42. 下列句子中,语法正确的是:a) She is one of the student who is going to the concert.b) He has more books than me.c) The children was playing in the park.d) I have been living here for two years.答案:d43. 选择正确的动词形式填空:The teacher _______ (explain/explained) the concept to the students yesterday.答案:explained...61. 选择正确的形容词填空:The _______ (boring/interested) lecture made the audience fell asleep.答案:boring五、词汇(共10题,每题2分,总计20分)62. 选择与“innovative”意思相近的词:A. TraditionalB. ConservativeC. CreativeD. Outdated答案:C63. 选择与“compromise”意思相反的词:A. AgreementB. DisputeC. ConflictD. Resolution答案:C...71. 选择与“meticulous”意思相同的词:A. CarelessB. SloppyC. ThoroughD. Haphazard答案:C请注意:以上内容为示例,实际SAT试题及答案会根据考试的具体内容而有所不同。

SAT真题免费下载0910S06-推荐下载

SAT真题免费下载0910S06-推荐下载

1. The widely documented ______between these two diseases has prompted scientises to undertake studies to determine if treating one can ______ the other.A. disconnect…cureB. corellation…ward offC. linkage…duplicateD. disparity…bring aboutE. incoherency eliminate2. Essentially a blues artist, Robert Cray plays music influenced by progressive rock, yet he remains ______ the blues tradition.A. superior toB. hampered byC. distinct fromD. grounded inE. ambivalent toward3. The new composite material exhibits an extraordinary degree of ______, which enable it to be molded into almost any shape.A. plasticityB. resonanceC. inertnessD. buoyancyE. impermeability4. The forest ranger cautioned the hikers that their proposed rout might prove dangerous, but they ignored her ______.A. vacillationB. indiscretionC. admonitionD. transgressionE. prohibition5. Eager to improve upon their journalistic skills, Ines and Juanita were disappointed in their editor for criticisms that were often more ______ than ______.A. didactic…extemporaneousB. captious…edifyingC. perceptive…incisiveD. quibbling…inaptE. constructive…diplomaticSection 6Questionw 6-9 are based on the following passages.Passage 1I love to nap. When after-lunch grogginess hits and my eyelids start to droop, nothing makes me happier than finding a comtable spot and drifting off to sleep.But to my family, my napping is the sign of a basic character flaw.“You’re napping again? You’re so lazy!”They’re not the only ones who feel this way. To be an enthusiastic napper in twenty-first-century North America is to be out of step with your time and place. A nap is seen as a sign of weakness, either physical or moral. Healthy, productive adults do not nap.Passage 2Sleep researchers have shown that the human body is programmed to become sleepy in the early afternoon. In some cultures people doze after the midday meal. But in many industrializednations, the usual response is to try to jump-start the system with caffeine, a tactic that sleep experts say creates only the illusion of efficiency and alterness.“napping should not be frowned upon,” writes one researcher, “It should have the status of daily exercise.”And in fact restorative naps may be making a comeback. Recognizing that many employees are chronically sleep deprived, some companies have set up nap rooms. If labor unions are interested in worker welfare, they should make such accommodation a standard item in contract negotiations.6. The “Sleep researchers” (line 12, Passage 2) would most likely characterize the “grogginess” (line 1, Passage 1) as a(A) potentially dangerous problem(B) symptom of stress(C) normal human pattern(D) response to an excess of caffeine(E) personal failure7. Passage 2 indicates that the view expressed in the final sentence of Passage 1 (“Healthy…nap”) has been(A) helpful for those who act on it(B) evident in every human culture(C) supported by sleep researchers(D) opposed by many labor unions(E) rejected by some employers8.The author of Passage 2 would most likely agree with which statement about the “tactic” (16)?(A) It is not understood by sleep experts.(B) It is not encouraged by employers.(C) It is less effective than it appears to be.(D) It is often difficult to implement(E) It is adopted only for rare emergencies.9. The sleep expert quoted in Passage 2 (lines 19-20) would most likely consider the position taken by the “family” (line 4, Passage 1) to be(A) self-contradictory(B) misguided(C) idiosyncratic(D) ambiguous(E) sympatheticQuestion 10-15 are based on the following passagesPassage 1 is from the introduction to a Zen Buddhist manual on the art of “mindfulness”, the practice of paying close attentino to the present moment. Passage 2 is from an essay by a United States author.Passage 1Every morning, when we wake up, we have 24 brand-new hours to live. What a precious gift! We have the capacity to live in a way that these 24 hours will bring peace, joy, and happiness to ourselves and to others.Peace is right here and now, in ourselves and in everything we do and see. The question is whether or not we are in touch with it. We don’t have to travel far away to enjoy the blue sky. We don’t have to leave our city or even our neighborhood to enjoy the eyes of a beautiful child. Even the air we breathe can be a source of joy.We can smile, breathe, walk, and eat our meals in a way that allows us to be in touch with the abundance of happiness that is available. We are very good at preparing how to live, but not very good at living. We know how to sacrifice ten years for a diploma, and we are willing to work very hard to get a job, a car, a house, and so on. But we have difficulty remembering that we are alive in the present moment, the only moment there is for us to be alive. Every breath we take, every step we make, can be filled with joy, peace, and serenity. We need only to be awake, alive in the present moment.Passage 2The argument of both the hedonist and the guru is that we were but to open ourselves to the richness of the moment, to concentrate on the feast before us, we would be filled with bliss. I have lived in the present from time to time and can tell you that it is much overrated. Occasionally, as a holiday from stroking one’s memories or brooding about future worries, I grant you, it can be a nice change of pace. But to “be here now,” hour after hour, would never work. I don’t even approve of stories written in the present tense. Ads for poets who never use a past participate, they deserve the eternity they are striving for. Besides, the present has a way of intruding whether you like it or not. Why should I go out of my way to meet it? Let it splash on me from time to time, like a car going through a puddle, and I, on the sidewalk of my solitude, will salute it grimly like any other modern inconvenience.If I attend a concert, obviously not to listen to the music but to find a brief breathing space in which to meditate on the past and future. I realize that there may be moments when the music invades my ears and I am forced to pay attention to it, note for note. I believe I take such intrusions gracefully. The present is not always an unwelcome guest, remembering or brooding time.10.The author of Passage 1 would most likely view the author of Passage 2 as(A) attaching too much importance to the views of others(B) advocating an action without considering the consequences(C) paying attention exclusively to the most difficult aspects of life(D) squandering a precious opportunity on a daily basis(E) failing to respect the feelings of other people11. In line 2, “precious” most nearly means(A) affected(B) adorable(C) elegant(D) meticulous(E) valuable12. In line 16, the list (“a job…house”) presents things that most people(A) assume they will eventually obtain(B) eventually realize are overrated(C) are unwilling to make sacrifices for(D) believe that everyone is entitled to(E) see as worth much effort to acquire13. The author of Passage 1 would most likely respond to the “argument” (line 22, Passage 2)with(A) complete agreement(B) partial acceptance(C) absolute neutrality(D) studied disinterest(E) surprised disbelief14. In lines 33-37, the “present” is characterized as(A) a dangerous threat(B) an elusive concept(C) an unsolvable puzzle(D) an unavoidable imposition(E) a burdensome obligation15. Which of the following phrases from Passage 2 would the author of Passage 1 most likelychoose as a title for Passage 1?(A) “the hedonist and the guru” (line 22)(B) “the feast before us” (line 24)(C) “the sidewalk of my solitude” (line 36)(D) “a brief breathing space” (line 39)(E) “an unwelcome guest” (line 43)Questions 16-24 are based on the following passage.This passage was written by a geologist and published in 2001.Not long ago, while browsing in a bookstore, I came across a volume entitled The New Atlas of the Universe. The title of this handsome work, I admit, took me aback. Line Could it be true that the entire cosmos had really been5 probed, explored, mapped, and updated? But the book turned out to be far less than this, and therefore, in many ways, far more interesting. It was, in fact, an atlas of our solar system (a somewhat provincial version of "the universe"), consisting mainly of detailed images and maps10 of the planets and their moons, along with respective lists of surface features recently identified by various spacecraft.This might sound rather humdrum. Yet another view of Jupiter's giant red spot? One more close-up of Saturn's auroral rings? Mars, as we know it so well, still a rusty,15 windswept, and boulder-strewn surface? Such was the visual chorus I expected to find, a coda of images tanta¬mount to photographic clichés. But I was in for a number of striking surprises. Leafing through the pages of this book, I found myself entering a "universe" I had no idea20 existed.As a geologist, I had been generally aware of the visual riches culled from the two Voyager space probes launched by the United States in the late 1970s. These robot eyes sent out to wander among the worlds and satellites of25 Jupiter, Saturn, Uranus, and Neptune had reportedly brought back tales and wonders of these geographical new worlds. This I had known; but here was the overwhelming evidence, of which I had been ignorant. Here were images that revealed worlds of unaccountable30 feature and action. Here were the violently eruptive sulfur volcanoes on Jupiter's moon lo, spewing gases and ions far into space. Here were the eerie, spidery lines of Jupiter's moon Europa, stretching for hundreds of miles just beneath a glazed skin of frozen methane.35 Here, too, were the gigantic, broken ice cliffs on Uranus' moon Miranda, rising to heights that dwarfed even the Himalayas, and the multiform terrain of Neptune's moon Triton, whosepatchwork landscapes seemed grafted onto each other without reason or order, as40 if by collision.To geologists, the Earth is huge and visually infinite. This is a conceptual necessity. With its innumerable sub-fields and levels of scale, the geological Terra is a universe all its own. The famous portrait of our planet as a single45 ball, swirling with cloud, taken by Apollo astronauts on their way to the Moon, is in no way a geological view. It is too distant, too complete, too unified—indeed, toomuch like the Moon itself. It is therefore something else: an aesthetic vision that has left the gravity of science50 behind.Habituated by my own geological training and knowledge, I was not quite prepared upon opening this New Atlas of the Universe to encounter the faces of so many worlds, dangling in the black of space, their features available to55 the eye for instant interpretation. Within this book, each planet and moon had its accompanying map. composed of a computer-generated image that flattened its subject out on a single rectangular strip—the so-called Mercator projection. This, too, seemed interesting: a technique60 literally 400 years old invented at the height of the early colonial era, the Age of Exploration, now being employed to make visible the most advanced geographies in a new age of discovery. Indeed, what might Mercator have thought were it suggested to him that his scheme would65 one day be used to plot landscapes so far from terrestrial in aspect as to reflect back, in their magnificent alienness, the very idea of an old and exhausted Earth?16.In lines 1-20, the author introduces The New Atlas of the Universe primarily by(A)inviting comparisons of maps in the book with maps of Earth(B)reviewing traditional ideas about Earth's geology(C)provoking curiosity about his personal achievements(D)hypothesizing in advance about what the book might contain(E)establishing his extensive knowledge of the field of astronomy17.The author’s response to the anticipated images of Jupiter, Saturn, and Mars (lines 12-15) can best be likened to that of(A) a singer looking over yet another arrangement of a familiar song(B) a chef tasting an herb for the first time(C)an art historian discovering the influence of one artist on another(D) a child finding a favorite toy that had been lost(E)an inventor testing a variety of specialized designs18.In lines 30-40 ("Here ... collision"), the author lists geographical details primarily in order to(A)emphasize the novelty and diversity of the photographs(B)describe the alarming appearance of the satellites(C)provide factual data about distant places(D)praise the accomplishments of the Voyager program(E)explain a personal fascination with new places and sights19. In lines 43-44 ("the geological... own"), the author conveys a sense of the(A)astounding ability scientists have to look beyond Earth(B)satisfaction that geological study brings to those who pursue it(C)vastness of the array of Earth's features that geologists study(D)surface features that Earth has in common with other planets(E)need to persuade the reader that geology is a worthy endeavor20. The photograph of Earth taken from space is "in no way a geological view" (line 46) because(A) a cloud cover obscures much of the Earth's outline(B)the picture was not taken by trained photographers(C)the image lacks the level of detail that is at the heart of what interests geologists(D)Earth appears to exist outside the law of gravity(E)geologists have a different aesthetic view of the Earth's surface21.The author indicates that the atlas portrays "faces" (line 53) in such a way that their "features" (line 54) are(A)grossly distorted(B)partially obscured(C)artificially enhanced(D)mysteriously attractive(E)immediately understandable22.The author finds which aspect of the "Mercator projection" (lines 58-59) most remarkable?(A)Its original role in the colonization of parts of the world(B)Its usefulness in modern technological applications(C)Its application of landscape design techniques to mapmaking(D)Its ability to render three-dimensional objects as flat(E)Its anticipation of scientific pursuits of the distant future23. In line 65, "plot" most nearly means(A)plan(B)chart(C)conspire(D)conceive(E)narrate24. Which best describes the function of the question in lines 63-67 ("Indeed ... Earth")?(A)It challenges an age-old assumption.(B)It engages in historical speculation.(C)It introduces a novel hypothesis.(D)It provokes a scientific controversy.(E)It creates a sense of foreboding.。

2025年普通高等学校招生全国统一考试仿真拟卷(T8联盟)数学试题(含答案)

2025年普通高等学校招生全国统一考试仿真拟卷(T8联盟)数学试题(含答案)

2025年普通高等学校招生全国统一考试仿真拟卷(T8联盟)数学试题一、单选题:本题共8小题,每小题5分,共40分。

在每小题给出的选项中,只有一项是符合题目要求的。

1.已知集合A={x∈R|2a−1<x<a2+a},B={x∈R|2x−3x+1≤1},若A∩B=(−1,2),则实数a=( )A. −2B. 0C. 1D. 1或−22.已知z1=1+i,z2=a2+4ai,若z1z2∈R,则实数a的值为( )A. −4B. 0C. −4或0D. 43.从集合{1,2,3,⋯,9}中任取3个数,取出的三个数之和是3的倍数的概率为( )A. 37B. 514C. 27D. 134.已知A(0,1),B(0,−1),C是A关于直线x−2y=0的对称点,则BA⋅BC=( )A. 25B. 35C. 45D. 655.甲、乙、丙等八个人围成一圈,要求甲、乙、丙三人两两不相邻,则不同的排列方法有( )A. 720种B. 1440种C. 2880种D. 4320种6.已知三棱锥P−ABC满足AB=3,BC=4,AC=5,且其体积为42,若点P(正投影在△ABC内部)到AB,BC,AC的距离相等,则三棱锥的表面积为( )A. 18B. 21C. 24D. 277.在△ABC中,M为边AB的中点,若∠ACM=π4,则∠ABC的最大值为( )A. π6B. π4C. π3D. π28.已知指数函数f(x)=a x,若f(f(x))=x有且只有两个不等根,则a的取值范围是( )A. (0,e−e)B. [e−e,1)C. (1,e1e)D. [e1e,+∞)二、多选题:本题共3小题,共18分。

在每小题给出的选项中,有多项符合题目要求。

9.已知点Q(4,2),直线l:ax+by+c=0,其中b是a,c的等差中项,过点P(−5,6)作直线l的垂线,垂足为H,则( )A. 直线l过定点B. PH的最大值为10C. QH的最小值为2D. QH的最大值为1110.已知a,b,c∈R,满足a2+b2+c2=4,且(a−2)(b−2)(c−2)=abc,则下列结论正确的有( )A. a +b +c =2B. ab +bc +ac <1C. a 的最小值为−23D. a 的最小值为−111.已知正项数列{a n }满足a 0=34,2a n +1=1−1−a n (n ∈N),则下列说法正确的有( )A. a 1=14 B. 存在k ∈N ,使得a k +1>a k C. a n <sin π3⋅2nD. a 1+a 2+⋯+a n <π227三、填空题:本题共3小题,每小题5分,共15分。

可汗学院新SAT阅读真题下载(68篇)

可汗学院新SAT阅读真题下载(68篇)

可汗学院新SAT阅读真题下载到目前为止,新版SAT可汗学院官方不断放出更多真题,已经放出了68篇阅读,具体如下:Level 2 22篇,Level 3 21篇,Level 4 17篇,8篇Diagnostic Quiz,共68篇阅读!想要下载可汗学院68篇阅读真题的同学,请移步:/sat/news/603917.htmlLevel 2Science篇1Passage adapted from Nikhil Swaminathan, "Eat (Less) to Live (Longer)," ©2007 by Scientific American.Scientists have known for more than 70 years that the one surefire way to extend the lives of animals was to cut calories by an average of 30 to 40 percent. The question was: Why? Now a new study begins to unravel the mystery and the mechanism by which reducing food intake protects cells against aging and age-related diseases.Researchers report in the journal Cell that the phenomenon is likely linked to two enzymes—SIRT3 and SIRT4—in mitochondria (the cell's powerhouse that, among other tasks, converts nutrients to energy). They found that a cascade of reactions triggered by lower caloric intake raises the levels of these enzymes, leading to an increase in the strength and efficiency of the cellular batteries. By invigorating the mitochondria, SIRT3 and SIRT4 extend the life of cells, by preventing flagging mitochondria from developing tiny holes (or pores) in their membranes that allow proteins that trigger apoptosis, or cell death, to seep out into the rest of the cell."We didn't expect that the most important part of this pathway was in the mitochondria," says David Sinclair, an assistant professor of pathology at Harvard Medical School and a study co-author. "We think that we've possibly found regulators of aging."In 2003 Sinclair's lab published a paper in Nature that described the discovery of a gene that switched on in the yeast cell in response to calorie restriction, which Sinclair calls a "master regulator in aging." Since then, his team has been searching for an analogous gene that plays a similar role in the mammalian cell.The researchers determined from cultures of human embryonic kidney cells that lower caloric intake sends a signal that activates a gene inside cells that codes for the enzyme NAMPT (nicotinamide phosphoribosyltransferase). The two- to four-fold surge in NAMPT in turn triggers the production of a molecule called NAD (nicotinamide adenine dinucleotide), which plays a key role in cellular metabolism and signaling.The uptick in NAD levels activates the SIRT3 and SIRT4 genes, increasing levels of their corresponding SIRT3 and SIRT4 enzymes, which then flood the interior of the mitochondria. Sinclair says he's not sure exactly how SIRT3 and SIRT4 beef up the mitochondria's energy output, but that events leading to cell death are at the very least delayed when there are vast quantities of the enzymes.SIRT3 and SIRT4 are part of a family called sirtuins (SIRT1, which helps extend cell life by modulating the number of repair proteins fixing DNA damage both inside and outside the cell's nucleus, is also a member). SIRT is short for sir-2homologue—a well-studied protein that is known to extend yeast cell longevity. According to Sinclair, all of the mammalian SIRT genes (and their proteins) are possible drug targets for therapies aimed at extending life, as well as staving off age-related illnesses, such as Alzheimer's disease, cancers and metabolic disorders, like diabetes."I think SIRT3 is the next most interesting sirtuin from a drug development standpoint," Sinclair says. "It does protect cells, but there's growing evidence that it may mediate the benefits of exercise as well."Sinclair's lab is now working on developing what he calls a possible "supermouse" with elevated levels of NAMPT to see if it lives longer and is more disease-resistant than normal mice.Matt Kaeberlein, a pathologist at the University of Washington in Seattle, says that Sinclair's team has an interesting hypothesis connecting the mitochondria to longevity, but that it needs to be more directly tested in the context of dietary restriction. "If the NAMPT-overexpressing mice are long-lived and disease resistant, that will provide more support for this idea."Lifespan of Groups of Mice With Different Levels of Caloric ReductionAdapted from Weindruch R, et al. (1986). "The Retardation of Aging in Mice by Dietary Restriction: Longevity, Cancer, Immunity, and Lifetime Energy Intake." Journal of Nutrition, April, 116(4), 641-54.QUESTION 1 OF 11The author indicates that caloric reduction extends the life of a mammalian cell by11 The author indicates that caloric reduction extends the life of a mammalian cell byA) turning off those genes involved in apoptosis, or cell death.B) forcing the mitochondria to utilize different energy sources for fuel.C) reducing the production of NAD (nicotinamide adenine dinucleotide).D) initiating a series of steps that results in the increased production of certain enzymes.2 Based on the passage, SIRT-3 and SIRT-4 indirectly affect cell longevity byA) strengthening the mitochondrial membrane.B) fixing damage to the cell’s DNA.C) initiating cell death.D) diminishing the efficiency of the cell’s mitochondria.3 Which choice provides the best evidence for the answer to the previous question?A) lines 7-9 (“Researchers ... mitochondria”)B) lines 13-18 (“By ... cell.”)C) lines 38-41 (“The ... mitochondria”)D) lines 41-44 (“Sinclair ... enzymes”)94 The author’s use of the words “powerhouse” and “batteries” in the second paragraph serves mainly toA) emphasize that mitochondria are the most important components of the cell.B) suggest that mitochondria use an electrical gradient to produce energyC) stress that mitochondria are the main sources of energy for the cell.D) imply that mitochondria need to be recharged in order to function efficiently5 As used in line 15 (“flagging”), “flagging” most nearly meansA) breaking.B) shrinking.C) folding.D) weakening.6 The main purpose of the fifth paragraph (lines 30-37) is toA) suggest that caloric reduction has a different effect on yeast cells than mammalian cells.B) highlight the important role that the kidney plays in the aging process.C) clarify the intermediate steps between caloric reduction and improved mitochondrial efficiency.D) identify the negative relationship between NAMPT production and NAD production.7 The author implies that the results of Sinclair’s study will enable future scientists toA) reverse the aging process.B) diagnose patients with age-related illnesses from an earlier age.C) create mice that are essentially immortal.D) more effectively treat a number of age-related illnesses.8 Which choice provides the best evidence for the answer to the previous question?A) lines 45-50 (“SIRT ... longevity.”)B) lines 50-54 (“According ... diabetes.”)C) lines 59-62 (“Sinclair’s ... mice”)D) lines 67-69 (“If ... idea”)9 The main purpose of the graph is toA) illustrate the relationship between caloric intake and longevity in different groups of mice.B) highlight how caloric reduction affects SIRT-3 enzyme production in different groups of mice.C) suggest that caloric reduction affects mice differently than it affects yeast.D) indicate that it is likely impossible to produce a genetically enhanced “supermouse.”10 How does the information in the graph relate to the author’s claim that caloric reduction increases the longevity of mammalian cells?A) It supports the claim, but suggests that the differences in longevity are marginal after a 25% caloric reduction.B) It supports the claim since the average lifespan of each group of mice increases as caloric reduction increases.C) It does not support the claim since the group of mice that did not have any caloric reduction had the highest survival rate after 35 months.D) It does not support the claim since all four groups of mice had the same average lifespan.11 It can reasonably be inferred from the graph that, 30 months into the study,A) all of the mice in the “55% caloric reduction”group were still alive.B) all of the mice in the “25% caloric reduction”group were still alive.C) approximately 50% of the mice in the “no caloric reduction” group we re still alive.D) none of the mice in the “no caloric reduction” group were still alive.。

(完整版)sat数学考试试题

(完整版)sat数学考试试题

(完整版)sat数学考试试题SAT数学真题精选1. If 2 x + 3 = 9, what is the value of 4 x – 3 ?(A) 5 (B) 9 (C) 15 (D) 18 (E) 212. If 4(t + u) + 3 = 19, then t + u = ?(A) 3 (B) 4 (C) 5 (D) 6 (E) 73. In the xy-coordinate (坐标) plane above, the line contains the points (0,0) and (1,2). If line M (not shown) contains the point (0,0) and is perpendicular (垂直)to L, what is an equation of M?(A) y = -1/2 x(B) y = -1/2 x + 1(C) y = - x(D) y = - x + 2(E) y = -2x4. If K is divisible by 2,3, and 15, which of the following is also divisible by these numbers?(A) K + 5 (B) K + 15 (C) K + 20 (D) K + 30 (E) K + 455. There are 8 sections of seats in an auditorium. Each section contains at least 150 seats but not more than 200 seats. Which of the following could be the number of seats in this auditorium?(A) 800 (B) 1,000 (C) 1,100 (D) 1,300 (E) 1,7006. If rsuv = 1 and rsum = 0, which of the following must be true?(A) r < 1 (B) s < 1 (C) u= 2 (D) r = 0 (E) m = 07. The least integer of a set of consecutive integers (连续整数) is –126. if the sum of these integers is 127, how many integers are in this set?(A) 126 (B) 127 (C) 252 (D) 253 (E) 2548. A special lottery is to be held to select the student who will live in the only deluxe room in a dormitory. There are 200 seniors, 300 juniors, and 400 sophomores who applied. Each senior’s name is placed in the lottery 3 times; each junior’s name, 2 time; and each sophomore’s name, 1 times. If a student’s name is chosen at random from the names in the lottery, what is the probability that a senior’s name will be chosen?(A)1/8 (B) 2/9 (C) 2/7 (D) 3/8 (E) 1/2Question #1: 50% of US college students live on campus. Out of all students living on campus, 40% are graduate students. What percentage of US students are graduate students living on campus?(A) 90% (B) 5% (C) 40% (D) 20% (E) 25% Question #2: In the figure below, MN is parallel with BC and AM/AB = 2/3. What is the ratio between the area of triangle AMN and the area of triangle ABC?(A) 5/9 (B) 2/3 (C) 4/9 (D) 1/2 (E) 2/9Question #3: If a2 + 3 is divisible by 7, which of the following values can be a?(A)7 (B)8 (C)9 (D)11 (E)4Question #4: What is the value of b, if x = 2 is a solution of equation x2 - b · x + 1 = 0?(A)1/2 (B)-1/2 (C)5/2 (D)-5/2 (E)2Question #5: Which value of x satisfies the inequality | 2x | < x + 1 ?(A)-1/2 (B)1/2 (C)1 (D)-1 (E)2Question #6: If integers m > 2 and n > 2, how many (m, n) pairs satisfy the inequality m n < 100?(A)2 (B)3 (C)4 (D)5 (E)7Question #7: The US deer population increase is 50% every 20 years. How may times larger will the deer population be in 60 years ?(A)2.275 (B)3.250 (C)2.250 (D)3.375 (E)2.500 Question #8: Find the value of x if x + y = 13 and x - y = 5.(A)2 (B)3 (C)6 (D)9 (E)4Question #9:The number of medals won at a track and field championship is shown in the table above. What is the percentage of bronze medals won by UK out of all medals won by the 2 teams?(A)20% (B)6.66% (C)26.6% (D)33.3% (E)10%Question #10: The edges of a cube are each 4 inches long. What is the surface area, in square inches, of this cube?(A)66 (B)60 (C)76 (D)96 (E)65Question #1: The sum of the two solutions of the quadratic equation f(x) = 0 is equal to 1 and the product of the solutions is equal to -20. What are the solutions of the equation f(x) = 16 - x ?(a) x1 = 3 and x2 = -3 (b) x1 = 6 and x2 = -6(c) x1 = 5 and x2 = -4 (d) x1 = -5 and x2 = 4(e) x1 = 6 and x2 = 0Question #2: In the (x, y) coordinate plane, three lines have the equations:l1: y = ax + 1l2: y = bx + 2l3: y = cx + 3Which of the following may be values of a, b and c, if line l3 is perpendicular to both lines l1 and l2?(a) a = -2, b = -2, c = .5 (b) a = -2, b = -2, c = 2(c) a = -2, b = -2, c = -2 (d) a = -2, b = 2, c = .5(e) a = 2, b = -2, c = 2Question #3: The management team of a company has 250 men and 125 women. If 200 of the managers have a master degree, and 100 of the managers with the master degree are women, how many of the managers are men without a master degree? (a) 125 (b) 150 (c) 175 (d) 200 (e) 225 Question #4: In the figure below, the area of square ABCD is equal to the sumof the areas of triangles ABE and DCE. If AB = 6, then CE =(a) 5 (b) 6 (c) 2 (d) 3 (e) 4Question #5:If α and β are the angles of the right triangle shown in the figure above, then sin2α + sin2β is equal to:(a) cos(β)(b) sin(β)(c) 1 (d) cos2(β)(e) -1 Question #6: The average of numbers (a + 9) and (a - 1) is equal to b, where a and b are integers. The product of the same two integers is equal to (b - 1)2. What is the value of a?(a) a = 9 (b) a = 1 (c) a = 0 (d) a = 5 (e) a = 11Question #1: If f(x) = x and g(x) = √x, x≥ 0, what are the solutions of f(x) = g(x)? (A) x = 1 (B)x1 = 1, x2 = -1(C)x1 = 1, x2 = 0 (D)x = 0(E)x = -1Question #2: What is the length of the arc AB in the figure below, if O is the center of the circle and triangle OAB is equilateral? The radius of the circle is 9(a) π(b) 2 ·π(c) 3 ·π(d) 4 ·π(e) π/2 Question #3: What is the probability that someone that throws 2 dice gets a 5 and a 6? Each dice has sides numbered from 1 to 6.(a)1/2 (b)1/6 (c)1/12 (d)1/18 (e)1/36 Question #4: A cyclist bikes from town A to town B and back to town A in 3 hours. He bikes from A to B at a speed of 15 miles/hour while his return speed is 10 miles/hour. What is the distance between the 2 towns?(a)11 miles (b)18 miles (c)15 miles (d)12 miles (e)10 miles Question #5: The volume of a cube-shaped glass C1 of edge a is equal to half the volume of a cylinder-shaped glass C2. The radius of C2 is equal to the edge of C1. What is the height of C2?(a)2·a /π(b)a / π(c)a / (2·π) (d)a / π(e)a + πQuestion #6: How many integers x are there such that 2x < 100, and at the same time the number 2x + 2 is an integer divisible by both 3 and 2?(a)1 (b)2 (c) 3 (d) 4 (e)5Question #7: sin(x)cos(x)(1 + tan2(x)) =(a)tan(x) + 1 (b)cos(x)(c)sin(x) (d)tan(x)(e)sin(x) + cos(x)Question #8: If 5xy = 210, and x and y are positive integers, each of the following could be the value of x + y except:(a)13 (b) 17 (c) 23 (d)15 (e)43Question #9: The average of the integers 24, 6, 12, x and y is 11. What is the value of the sum x + y?(a)11 (b)17 (c)13 (d)15 (e) 9Question #10: The inequality |2x - 1| > 5 must be true in which one of the following cases?I. x < -5 II. x > 7 III. x > 01.Three unit circles are arranged so that each touches the other two. Find the radii ofthe two circles which touch all three.2.Find all real numbers x such that x + 1 = |x + 3| - |x - 1|.3.(1) Given x = (1 + 1/n)n, y = (1 + 1/n)n+1, show that x y = y x.(2) Show that 12 - 22 + 32 - 42 + ... + (-1)n+1n2 = (-1)n+1(1 + 2 + ... + n).4.All coefficients of the polynomial p(x) are non-negative and none exceed p(0). Ifp(x) has degree n, show that the coefficient of x n+1 in p(x)2 is at most p(1)2/2.5.What is the maximum possible value for the sum of the absolute values of thedifferences between each pair of n non-negative real numbers which do not exceed 1?6.AB is a diameter of a circle. X is a point on the circle other than the midpoint of thearc AB. BX meets the tangent at A at P, and AX meets the tangent at B at Q. Show that the line PQ, the tangent at X and the line AB are concurrent.7.Four points on a circle divide it into four arcs. The four midpoints form aquadrilateral. Show that its diagonals are perpendicular.8.Find the smallest positive integer b for which 7 + 7b + 7b2 is a fourth power.9.Show that there are no positive integers m, n such that 4m(m+1) = n(n+1).10.ABCD is a convex quadrilateral with area 1. The lines AD, BC meet at X. Themidpoints of the diagonals AC and BD are Y and Z. Find the area of the triangle XYZ.11.A square has tens digit 7. What is the units digit?12.Find all ordered triples (x, y, z) of real numbers which satisfy the following systemof equations:xy = z - x - yxz = y - x - zyz = x - y - z。

2024 SAT考试数学历年题目精粹

2024 SAT考试数学历年题目精粹

2024 SAT考试数学历年题目精粹SAT考试是许多学生考入大学的重要考试之一,其中数学部分是考生需要面对的一项挑战。

为了帮助考生更好地备考SAT数学,本文将精选并解析2024年SAT考试数学部分的历年题目,以供参考。

第一部分:选择题题目1:一个矩形的宽度是它的长度的一半,若该矩形的面积为12,求其周长是多少?A. 12B. 14C. 16D. 18解析:设矩形的长度为l,则宽度为l/2。

根据面积的定义,我们可以列出方程l*(l/2)=12。

解方程得到l=4。

根据周长的计算公式,周长为2*l+2*(l/2)=14,选项B为正确答案。

题目2:若函数f(x)定义为f(x)=3x+1,求f(f(2))的值。

A. 9B. 10C. 11D. 12解析:由题意可知,f(2)=3*2+1=7。

将7代入函数f(x),得到f(f(2))=f(7)=3*7+1=22。

选项D为正确答案。

题目3:已知一个等差数列的公差为3,前两个数的和为10,求这个等差数列的第n个数。

A. 3n-1B. 3n-2C. 3n-3D. 3n-4解析:设等差数列的首项为a,第n个数为an。

根据题意可得到方程a+(a+3)=10,解得a=3。

利用等差数列的通项公式an=a+(n-1)d,代入公差d=3和首项a=3,得到an=3+3(n-1)=3n。

选项A为正确答案。

第二部分:填空题题目1:若a为正整数,满足2a+5=11,则a的值为____________。

解析:将已知条件代入方程,得到2a+5=11,解得a=3。

填入空格中为3。

题目2:一个矩形的面积为25,其中宽度为5,长度为_________。

解析:设矩形的长度为l,则根据面积的定义可得到方程5l=25,解得l=5。

填入空格中为5。

第三部分:解答题题目:一辆汽车以40 mph的速度行驶了3小时,另一辆汽车以50 mph的速度行驶了t小时。

若两辆汽车行驶的距离相同,求t的值。

解析:汽车行驶的距离等于速度乘以时间,可以列出方程40*3=50*t,解得t=2.4。

SAT OG官方指南数学习题10套

SAT OG官方指南数学习题10套

SAT OG官方指南数学习题10套The Official SAT Study Guide(Maths Part)Translator: 安东尼Practice Test 1P396Section 31.如果x = 4,下面哪一个是最大的值。

2.火车A,B, 和C 同时以不同的速度经过一个火车站。

火车A的速度是火车B的速度的三倍,然后火车C的速度是火车A的速度的两倍。

如果火车B的速度是每小时7英里,请问火车C的速度是多少每小时多少英里?3.如果x,5x,和6x 的平均值是8,那x的值是多少?4.一个图标上不能有两个同样x坐标的点哪一个图标符合上面所提的要求?5.上面这个韦恩图解展示了在30个上科学的学生中学习蝴蝶,学习蝗虫,两个一起学习或者是两个都没有学习的学生人数。

只学习蝴蝶的学生占总人数的多少百分比?6.在上面的图标里,AB = CD。

t的数值是多少?7. 如果3x² = 4y = 12, 那么x²y 的数值是多少?8. 在上面的图解里,圆圈都是相切的和紧紧挨着的(tangent)。

圆圈A的圆心也是最大的那个圆圈的圆心。

如果圆圈A的半径是2,圆圈B的半径是4,还有圆圈C的半径是4,那么最大的那个圆圈的半径是多少?9. 在上面的图解里,线上所有的标记都是相等的。

那么x的数值是多少?10. 在上面的图标里,x的数值是多少?11. 当正整数k 除以7以后,余数是6. 那K+2 除以7的余数是多少?12. 上面的图表展示了一个关于每深入海洋15英尺所对应的气压的函数。

如果每深入海洋1英尺,海洋的气压增长是同样的话,那下面哪一个图表符合上面的数据。

13. 在一数列里,第一个数字是1. 如果每后面一个数是前面一个数乘以-2 的乘积,那么这一串数字的第六个数是什么?14. 如果(2x - 5)(2x +5)= 5,那么4x²的值是多少?15. A点的坐标是(p,r),然后|p| > |r|. 下面哪一个会是直线AB的斜度?16. 如果3a + 4b = b,下面哪一个一定等于6a + 6b?17. 在上面这个直角三角形中,直线EF │| 直线AC。

sat数学练习题

sat数学练习题

SAT数学练习题一、代数基础1. 如果3x 5 = 7,那么x的值是多少?2. 解方程:2(3x 4) + 4 = 5x + 23. 已知a ≠ 0,求表达式(a 3)²的最小值。

4. 简化表达式:(2x³ 3x²) (4x³ 5x²)5. 若x + y = 10,x y = 4,求x和y的值。

二、几何图形1. 计算直角三角形的斜边长度,已知两条直角边分别为3和4。

2. 在一个等边三角形中,每条边的长度为6,求该三角形的周长。

3. 已知圆的半径为5,求该圆的面积。

4. 计算长方体的体积,长、宽、高分别为8、6和4。

5. 若一个正方形的对角线长度为10,求正方形的面积。

三、数据分析、统计与概率2. 从一副52张的扑克牌中随机抽取一张,求抽到红桃的概率。

3. 一个袋子里有5个红球、3个蓝球和2个绿球,随机抽取一个球,求抽到蓝球或绿球的概率。

5. 某班级有30名学生,其中18名喜欢篮球,15名喜欢足球,5名两者都喜欢。

求至少喜欢一项运动的学生人数。

四、函数与方程1. 已知函数f(x) = 2x + 3,求f(5)的值。

2. 若g(x) = 3x² 4x + 1,求g(1)的值。

3. 解不等式:2x 5 > 74. 已知函数h(x) = x² 4x + 4,求h(x)的最小值。

5. 求函数k(x) = |x 3|在x = 2时的导数值。

五、数列与级数1. 计算数列1, 3, 5, 7, 9的前5项和。

2. 已知等差数列的第3项为7,第5项为11,求首项和公差。

3. 求等比数列8, 24, 72的下一项。

4. 计算数列2, 4, 8, 16, 32的第6项。

5. 已知数列的通项公式为an = 3n 2,求前5项的和。

六、实际问题解决1. 小明购买了3本书和2支笔,共花费了45元。

如果每本书比每支笔贵5元,求每本书和每支笔的价格。

2. 一辆汽车以60公里/小时的速度行驶,另一辆汽车以80公里/小时的速度行驶。

SAT数学练习题(四)-智课教育出国考试.

SAT数学练习题(四)-智课教育出国考试.

智课网 S A T 备考资料SAT数学练习题(四-智课教育出国考试SAT数学练习题 1If f(x = x2 – 3, where x is an integer, which of the following could be a value of f(x?I 6II 0III -6A. I onlyB. I and II onlyC. II and III onlyD. I and III onlyE. I, II and IIICorrect Answer: A解析:Choice I is correct because f(x = 6 when x=3. Choice II is incorrect because to make f(x = 0, x2 would have to be 3. But 3 is not the square of an integer. Choice III is incorrect because to make f(x = 0, x2 would have to be –3 but squares cannot be negative. (The minimum value for x2 is zero; hence, the minimum value for f(x = -3SAT数学练习题 2For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?A. 48B. 49C. 50D. 51E. 52Correct Answer: C解析:1 < 4n + 7 < 200. n can be 0, or -1. n cannot be -2 or any other negative integer or the expression 4n + 7 will be lessthan1. The largest value for n will be an integer < (200 - 7 /4. 193/4 = 48.25, hence 48. The number of integers between -1 and 48 inclusive is 50SAT数学练习题 3In the following correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?A. 23B. 22C. 18D. 16E. 14Correct Answer: B解析:First you must realize that the sum of two 2-digit numbers cannot be more that 198 (99 + 99. Therefore in the given problem D must be 1. Now use trial and error to satisfy the sum 5A + BC = 143. A + C must give 3 in the units place, but neither can be 1 since all the digits have to be different. Therefore A + C = 13. With one to carry over into the tens column, 1 + 5 + B = 14, and B = 8. A + C + B + D = 13 + 8 + 1 = 22SAT数学练习题 412 litres of water a poured into an aquarium of dimensions 50cm length , 30cm breadth, and 40 cm height. How high (in cm will the water rise?(1 litre = 1000cm3A. 6B. 8C. 10D. 20E. 40Correct Answer: B解析:Total volume of water = 12 liters = 12 x 1000 cm3. The base of the aquarium is 50 x 30 = 1500cm3. Base of tank x height of water = volume of water. 1500 x height = 12000; height = 12000 / 1500 = 8SAT数学练习题 5Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?A. 11/P + 6B. P/11 +6C. 17 - P/6D. 17/PE. 11.5PCorrect Answer: A解析:Let Ben’s age now be B. Anita’s age now is A. (A - 6 = P(B - 6 But A is 17 and therefore 11 = P(B - 6. 11/P = B-6(11/P + 6 = B。

可汗学院新SAT语法真题下载

可汗学院新SAT语法真题下载

可汗学院新S A T语法真题下载-CAL-FENGHAI-(2020YEAR-YICAI)_JINGBIAN可汗学院新SAT语法真题下载到目前为止,新版SAT可汗学院官方不断放出更多真题,已经放出了68篇阅读,且之前已经和大家分享过可汗学院新SAT阅读真题,想要下载的同学,请点击:新SAT阅读真题下载(共68篇,且已全)目前可汗学院一共放出41篇新SAT数学真题!想要下载的同学,请点击:新SAT数学真题下载(共41篇)分享了可汗学院的数学和阅读真题后,还有我们的可汗学院SAT语法真题。

截止到6月前,可汗学院一共放出了48套新SAT语法真题,想要吗?下载请点击:新SAT语法真题下载(共48篇)(网址:/sat/news/606541.html)可汗学院新SAT语法真题(部分)Questions 1-5 are based on the following passage. 1Searching for GuinevereStories of kings and queens have captivated readers for centuries, and arguably, the tales of King Arthur and Guinevere are among the most enchanting. Arthur ruled the kingdom of Camelot, and Guinevere was his queen. But were they real people or fictional charactersThe debate has continued for centuries. Though many scholars have found evidence that the legendary Arthur was, at the very least, based on a real person who lived in Britain roughly between 450 and (1) 500 CE. They continue to search for the historical identity of Guinevere. Guinevere first appeared as King Arthur’s queen in one of the most wide lystudied works of Arthurian literature, (2)The History of the Kings of Britain. This book was written by Geoffrey of Monmouth around 1135 CE. Geoffrey’s historical treatment of the legend is often(3)sited as evidence that the queen of Camelot existed, as the book chronicles the lives of a number of historical rulers.*God help those who help themselves. We help those who trust us. Contact Wechat:satxbs123, help is waiting.1A) NO CHANGEB) 500 CE. ContinuingC) 500 CE, continuingD) 500 CE, they continueWhich choice most effectively combines the sentences at the underlined portion?A) The History of the Kings of Britain, and this bookB) The History of the Kings of Britain, whichC) a book called The History of the Kings of Britain,as thisD) a book called The History of the Kings of Britain,and this3A) NO CHANGEB) insightedC) citedD) incitedGuinevere is identified by Geoffrey as a noblewoman of Roman descent who met King Arthur in the court of Duke Cador of Cornwall, where she lived as a ward. (4)In Malory’s portrayal, Guinevere had no real power as a monarch but served as a kind of spiritual leader, providing guidance and moral support to the knights in their roles as defenders of the kingdom. Le Morte d’Arthur was also one of the first works to reference Guinevere’s romance with the knight, Sir Lancelot.As many Arthurian scholars know, the distinction between history and literature was blurred in the Middle Ages. Consequently, the true identity of Guinevere may never be known with certainty. Yet regardless of whether Guinevere was real or fictional, her story (5) had endured centuries—and through each retelling, she continues to live on in the imaginations of people around the world.4At this point, the author wants to add a sentence which effectively sets up the portrayal of Guinevere discussed in the rest of the paragraph. Which choice best accomplishes this goal?A) Three centuries later, however, Thomas Malory painted a very different portrait of Guinevere in Le Morte d’Arthur.B) Sir Thomas Malory was an English knight and Member of Parliament who also wrote extensively about the history of the British monarchy.C) Many historians believe that the portrayal of Arthur and Guinevere in Sir Thomas Malory’s Le Morte d’Arthur was actually a political commentary on the War of the Roses (1455-1487CE).D) In Le Morte d’Arthur, Sir Thomas Malory describes an idyllic England under King Arthur and Guinevere, which eventually collapses into chaos and political unrest. E. I would be guessing.A) NO CHANGEB) was enduringC) would have enduredD) has enduredQuestions 1-5 are based on the following passage. 1Cometary Missions: Trajectory for SuccessScientists have been launching cometary missions since 1978. The first one, a joint mission by the European Space Agency, and the National Aeronautics and Space Administration (NASA), was a “flyby” in which the spacecraft collected data while passing around Comet Giacobini-Zinner. (1)However, the landing of the Rosetta space probe on comet 67P/Churyumov-Gerasemenko in 2014 was different: it marked the first time that a probe landed on a( 2 )comet and giving scientists an unprecedented opportunity to study the surface of a comet. In order to continue this valuable research, additional missions are needed; thus, it is critical that more funding be allocated for this purpose.The 2014 Rosetta mission provided a rare opportunity for scientists to test a number of hypotheses regarding the composition of (3) comets; the distribution of organic compounds in our solar system and the origins of life on Earth. Unlike other cometary missions, the Rosetta spacecraft contained a probe, Philae, that was able to land on the surface of a comet. *Rack your brain and you don't know why.Follow Wechat: satxbs123, she can help you!1At this point, the writer wants to add accurate information from the graph. Which choice best accomplishes this goal?A) From 1978 to 2014, the number of successful missions increased from 28 percent to 72 percent.B) Before 2014, the majority of attempted cometary missions were considered unsuccessful.C) Between then and 2014, 72 percent of the cometary missions were successful.D) Of the missions attempted since then, 44 percent have been successful.2A) NO CHANGEB) comet, but it gaveC) comet, yet givesD) comet, givingA) NO CHANGEB) comets, the distribution of organic compounds in our solar system,C) comets, the distribution of organic compounds in our solar system;D) comets; the distribution of organic compounds in our solar system,。

SAT考试数学练习题第九套_SAT_problem_solving_practice_test_9

SAT考试数学练习题第九套_SAT_problem_solving_practice_test_9

SAT考试数学练习题第九套 SAT problem solving practice test 91. (3 x 104) + (2 x 10²) + (4 x 10) =A. 302400B. 32400C. 30240D. 3240E. 3242. Andy solves problems 74 to 125 inclusive in a Math exercise. How many problems does he solve?A. 53B. 52C. 51D. 50E. 493.If x and y are integers, and 3x + 2y = 13, which of the following could be the value of y ?A. 0B. 1C. 2D. 3E. 44.In triangle ABC, AD = DB , DE is parallel to BC, and the area of triangle ABC is 40. What is the area of triangle ADE ?A. 10B. 15C. 20D. 30E. it cannot be determined from the information given5. If n > 0 , which of the following must be true?I n² > 1II n - n² < 0III 2n - 1 > 0A. I onlyB. II onlyC. III onlyD. I and II onlyE. none6.If the slope of a line is ½ and the y-intercept is 3, what is the x-intercept of the same line?A. 6B. 3/2C. 0D. -2/3E. -67.6 people meet for a business lunch. Each person shakes hands once with each other person present. How many handshakes take place?A. 30B. 21C. 18D. 15E. 108.If x² - y² = 55, and x - y = 11, then y =A. 8B. 5C. 3D. -8E. -39.In a sports club with 30 members, 17 play badminton and 19 play tennis and 2 do not play either. How many members play both badminton and tennis?A. 7B. 8C. 9D. 10E. 1110. Rectangle ABCD has a perimeter of 26. The half circle with diameter AD has an area of 8π. What is the perimeter of the part of the figure that is not shaded?A. 26 + 4πB. 18 + 8πC. 18 + 4πD. 14 + 4πE. 14 + 2πSAT数学练习题第9套参考答案1.Correct Answer: CExplanation:2 x 104 = 30,000; 2 x 102 = 200; 4 x 10 = 40The total is 30,2402.Correct Answer: BExplanation:To find how many problems in the series we need to take the difference and add one.125 - 74 = 51; 51 + 1 =523.Correct Answer: CExplanation:Substitute the given values for y and check whether you get an integer value for x.For example, using 0 we get 3x = 13; x = 13/3 which is not a whole number. The right answer is 2, since 3x + 2(2) = 13; 3x = 13 - 4 = 9; x = 9/3 = 3.4.Correct Answer: AExplanation:The big triangle ABC is similar to the small triangle ADE because their bases are parallel. If corresponding side of two similar triangles are known the ratio of the areas is also known. In this case, let AD be one unit, then AB is 2 units (given that AB = AD + DB). The ratios of the sides is 1 : 2. The ratio of the areas will be (1)2 : (2)2 ; 1 : 4Since the big triangle has area 40, using the ratio, the small has area 10.5.Correct Answer: EExplanation:Given that n is positive, it could be a positive fraction, 1, or a fraction of whole number greater than 1.If n = 1, then case I is not true since n2 = 1Likewise in II if n = 1, n - n2 = 0, and the statement is not true.In III, if n = ½, then 2n - 1 = 0, and again the statement is incorrect.6.Correct Answer: EExplanation:The equation for a straight line is y = mx + c, where m = slope and c = y-intercept.Putting the given values in this equation we have y = x/2 + 3The x-intercept occurs where y = 0. Thus, 0 = x/2 + 3 ; -3 = x/2 ; -6 =x7.Correct Answer: DExplanation:Imagine the first person of the six. He or she will have to shake hands with each of the other 5. Now turn to the second person. He or she will have to shake with the other five, but he she has already shaken with the first person. This means 4 new handshakes. The third person will have to shake with 5 - 2 = 3 people, and so on. Total handshakes = 5 + 4 + 3 + 2 + 1 = 158.Correct Answer: EExplanation:x2 - y2 can be expressed as (x + y)(x - y); since x - y =11 we can write (x + y)11 = 55; therefore x + y = 5Adding the two equations x + y = 5 and x - y = 11 we get2x = 16; x = 8Therefore 8 - y = 11; y = -39.Correct Answer: BExplanation:Since 2 do not play either, there are 28 members who play one sport or the other. Let the number who play both be n.Total (28) will be made up of only badminton players (17 - n), plus onlytennis (19 - n) and those who play both (n).28 = (17 - n) + (19 - n) + n28 = 36 - n ; n = 810.Correct Answer: CExplanation:The total perimeter of the un-shaded part is made up of three sides of the rectangle and the perimeter of the half-circle.The area of a half circle = ½ π r28 π = ½ π r2; therefore r = 4The perimeter of the half circle is ½ 8 π = 4 πThe diameter of the circle (8) = the length of the rectangle.Total perimeter of the rectangle = 26Three sides measure 26 - 8 = 18 Ans. 18 + 4π。

SAT problem solving数学17套练习题

SAT problem solving数学17套练习题

SAT problem solving数学17套练习题SAT problem solving数学11. Of the following, which is greater than ½ ?A. 2/5B. 4/7C. 4/9D. 5/11E. 6/132. If an object travels at five feet per second, how many feet does it travel in one hour?A. 30B. 300C. 720D. 1800E. 180003. What is the average (arithmetic mean) of all the multiples of ten from 10 to 190 inclusive?A. 90B. 95C. 100D. 105E. 1104. A cubical block of metal weighs 6 pounds. How much will another cube of the same metal weigh if its sides are twice as long?A. 48B. 32C. 24D. 18E. 125. In a class of 78 students 41 are taking French, 22 are taking German and 9 students are taking both French and German. How many students are not enrolled in either course?A. 6B. 15C. 24D. 33E. 546.If f(x) = │(x² –50)│, what is the value of f(-5) ?A. 75B. 25C. 0D. -25E. -757.( √2 - √3 )² =A. 5 - 2√6B. 5 - √6C. 1 - 2√6D. 1 - √2E. 18. 230 + 230 + 230 + 230 =A. 8120B. 830C. 232D. 230E. 2269. Amy has to visit towns B and C in any order. The roads connecting these towns with her home are shown on the diagram. How many different routes can she take starting from A and returning to A, going through both B and C (but not more than once through each) and not travelling any road twice on the same trip?A. 10B. 8C. 6D. 4E. 210. In the figure above AD = 4, AB = 3 and CD = 9. What is the area of triangle AEC ?A. 18B. 13.5C. 9D. 4.5E. 3参考答案1.Correct Answer: BExplanation:One way to deal with fractions is to convert them all to decimals. (Using your calculator, divide the numerator by the denominator).In this case all you would need to do is to see which is greater than 0.5.Otherwise to see which is greater than ?, double the numerator and see if the result is greater than the denominator. In B, the correct answer, doubling the numerator gives us 8, which is bigger than 7.2.Correct Answer: EExplanation:If an object travels at 5 feet per second it covers 5x60 feet in one minute, and 5x60x60 feet in one hour. Answer = 18000 (E)3.Correct Answer: CExplanation:You could add up all the multiples of 10 (10 + 20 + 30 ....+190), and divide by the number of terms (19). Or you could realize that the average of an evenly spaced series of numbers is equal to the value of the middle term (or the average of the two middle terms if there are an even number of terms). The middle term out of 19 is the tenth term in the series = 100.4.Correct Answer: AExplanation:If you double the sides of a cube, the ratio of the surface areas of the old and new cubes will be 1: 4. The ratio of the volumes of the old and new cubes will be 1: 8.Weight is proportional to volume. So, If the first weighs 6 pounds, the second weighs 6x8 pounds =48.5.Correct Answer: CExplanation:You could solve this by drawing a Venn diagram. A simpler way is to realize that you can subtract the number of students taking both languages from the numbers taking French to find the number taking only French. Likewise find those taking only German. Then we have:Total = only French + only German + both + neither78 = (41-9) + (22-9) + 9 + neither.Not enrolled students = 246.Correct Answer: BExplanation:If x = -5, then (x²– 50) = 25 – 50 = -25But the sign │x│ means the absolute value of x (the distance between the number and zero on the number line). Absolute values are always positive.│-25 │ = 257.Correct Answer: AExplanation:Expand as for (a + b)2.(√2 - √3)(√2 - √3) = 2 - 2(√2 + √3) + 3 = 5 - 2 √68.Correct Answer: CExplanation:All four terms are identical therefore we have 4 (230).But 4 = 22, and so we can write 22. 230Which is equivalent to 2329.Correct Answer: BExplanation:Amy can travel clockwise or anticlockwise on the diagram.Clockwise, she has no choice of route from A to B, a choice of one out of two routes from B to C, and a choice of one out of two routes from C back to A. This gives four possible routes. Similarly, anticlockwise she has four different routes.Total routes = 810.Correct Answer: DExplanation:If we take AE as the base of triangle AEC, then the height is CD.The height of the triangle is therefore, 9 (given).To find the base we need to see that triangles AEB and CDE are similar. The ratio AB: CD, is therefore equal to the ratio AE: ED. The given information shows that the ratio is 3:9, or 1:3. Now dividing AD (4) in this ratio gives us AE as 1.The area of AEC = ½ base x height=1/2 x 9 = 4.5SAT problem solving数学21. Which of the following could be a value of x, in the diagram above?A. 10B. 20C. 40D. 50E. any of the above2. Helpers are needed to prepare for the fete. Each helper can make either 2 large cakes or 35 small cakes per hour. The kitchen is available for 3 hours and 20 large cakes and 700 small cakes are needed. How many helpers are required?A. 10B. 15C. 20D. 25E. 303. Jo's collection contains US, Indian and British stamps. If the ratio of US to Indian stamps is 5 to 2 and the ratio of Indian to British stamps is 5 to 1, what is the ratio of US to British stamps?A. 5 : 1B. 10 : 5C. 15 : 2D. 20 : 2E. 25 : 24. A 3 by 4 rectangle is inscribed in circle. What is the circumference of the circle?A. 2.5πB. 3πC. 5πD. 4πE. 10π5. Two sets of 4 consecutive positive integers have exactly one integer in common. The sum of the integers in the set with greater numbers is how much greater than the sum of the integers in the other set?A. 4B. 7C. 8D. 12E. it cannot be determined from the information given.6. If f(x) = (x + 2) / (x-2) for all integers except x=2, which of the following has the greatest value?A. f(-1)B. f(0)C. f(1)D. f(3)E. f(4)7. ABCD is a square of side 3, and E and F are the mid points of sides AB and BC respectively. What is the area of the quadrilateral EBFD ?A. 2.25B. 3C. 4D. 4.5E. 68.If n ≠ 0, which of the following must be greater than n?I 2nII n²III 2 - nA. I onlyB. II onlyC. I and II onlyD. II and III onlyE. None9. After being dropped a certain ball always bounces back to 2/5 of the height of its previous bounce. After the first bounce it reaches a height of 125 inches. How high (in inches) will it reach after its fourth bounce?A. 20B. 15C. 8D. 5E. 3.210. n and p are integers greater than 15n is the square of a number75np is the cube of a number.The smallest value for n + p isA. 14B. 18C. 20D. 30E. 50参考答案1.Correct Answer: BExplanation:The marked angle, ABC must be more than 90 degrees because it is the external angle of triangle BDC, and must be equal to the sum of angles BDC (90) and DCB.Also ABC is not a straight line and must be less than 180.Therefore 90 < 5x < 180The only value of x which satisfies this relation is 20.2.Correct Answer: AExplanation:20 large cakes will require the equivalent of 10 helpers working for one hour. 700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10 helpers.3.Correct Answer: EExplanation:Indian stamps are common to both ratios. Multiply both ratios by factors such that the Indian stamps are represented by the same number.US : Indian = 5 : 2, and Indian : British = 5 : 1. Multiply the first by 5, and the second by 2.Now US : Indian = 25 : 10, and Indian : British = 10 : 2Hence the two ratios can be combined and US : British = 25 : 24.Correct Answer: CExplanation:Draw the diagram. The diagonal of the rectangle is the diameter of the circle. The diagonal is the hypotenuse of a 3,4,5 triangle, and is therefore, 5.Circumference = π.diameter = 5π5.Correct Answer: DExplanation:If two sets of four consecutive integers have one integer in common, the total in the combined set is 7., and we can write the sets asn + (n + 1) + (n + 2) + (n + 3 ) and(n + 3) + (n + 4) + (n + 5) + (n + 6)Note that each term in the second set is 3 more than the equivalent term in the first set. Since there are four terms the total of the differences will be 4 x 3 = 126.Correct Answer: DExplanation:You can solve this by back solving – substitute the answer choices in the expression and see which gives the greatest value.satA (-1 + 2) / (-1-2) = -2 / 2 = -1;B (0 + 2) / (0-2) = 2/ -2 = -1;C (1 + 2) / (1-2) = 3/-1 = -3;D (3 + 2) / (3-2) = 5/1 = 5;E (4+ 2) / (4-2) = 6/2 = 3If you had just chosen the largest value for x you would have been wrong. So although it looks a long method, it is actually quick and accurate since the numbers are really simple and you can do the math in your head.7.Correct Answer: DExplanation:(Total area of square - sum of the areas of triangles ADE and DCF) will give the area of the quadrilateral9 - (2 x ½ x 3 x 1.5) = 4.58.Correct Answer: EExplanation:Remember that n could be positive negative or a fraction. Try out a few cases:In case I, if n is -1, then 2n is less than n.In case II, if n is a fraction such as ½ then n2 will be less than n.In case III, if n is 2, then 2-n = 0, which is less than n.Therefore, none of the choices must be greater than n9.Correct Answer: CExplanation:If after each bounce it reaches 2/5 of the previous height, then after the second bounce it will reach 2/5 x 125. After the third it will reach 2/5 x 2/5 x 125. After the fourth it will reach 2/5 x 2/5 x 2/5 x 125. This cancels down to 2 x 2 x 2 = 810.Correct Answer: AExplanation:The smallest value for n such that 5n is a square is 5.75np can now be written as 75 x 5 x p.This gives prime factors.... 3 x 5 x 5 x 5 x pTo make the expression a perfect cube, p will have to have factors 3 x 3 , and hence p =9n + p = 5 + 9 = 14SAT problem solving数学31. The distance from town A to town B is five miles. C is six miles from B. Which of the following could be the distance from A to C?I 11II 1III 7A. I onlyB. II onlyC. I and II onlyD. II and III onlyE. I, II, or III.2.√5 percent of 5√5 =A. 0.05B. 0.25C. 0.5D. 2.5E. 253. If pqr = 1 , rst = 0 , and spr = 0, which of the following must be zero?A. PB. QC. RD. SE. T4.A. 1/5B. 6/5C. 6³D. 64 / 5E. 645. -20 , -16 , -12 , -8 ....In the sequence above, each term after the first is 4 greater than the preceding term. Which of the following could not be a term in the sequence?A. 0B. 200C. 440D. 668E. 7626. If f(x) = x²– 3, where x is an integer, which of the following could be a value of f(x)?I 6II 0III -6A. I onlyB. I and II onlyC. II and III onlyD. I and III onlyE. I, II and III7. For how many integer values of n will the value of the expression 4n + 7 be an integer greater than 1 and less than 200?A. 48B. 49C. 50D. 51E. 528. In the following correctly worked addition sum, A,B,C and D represent different digits, and all the digits in the sum are different. What is the sum of A,B,C and D?A. 23B. 22C. 18D. 16E. 149. 12 litres of water a poured into an aquarium of dimensions 50cm length , 30cm breadth, and 40 cm height. How high (in cm) will the water rise?(1 litre = 1000cm³)A. 6B. 8C. 10D. 20E. 4010. Six years ago Anita was P times as old as Ben was. If Anita is now 17 years old, how old is Ben now in terms of P ?A. 11/P + 6B. P/11 +6C. 17 - P/6D. 17/PE. 11.5P参考答案1.Correct Answer: EExplanation:Do not assume that AB and C are on a straight line. Make a diagram with A and B marked 5 miles apart. Draw a circle centered on B, with radius 6. C could be anywhere on this circle. The minimum distance will be 1, and maximum 11, but anywhere in between is possible.2.Correct Answer: BExplanation:We can write the statement mathematically, using x to mean ‘of’ and /100 for ‘per cent’. So ( √5/100) x 5√5 = 5 x 5 /100 = 0.253.Correct Answer: DExplanation:If pqr = 1, none of these variable can be zero. Since spr = 0 , and since p and r are not zero, s must be zero. (Note that although rst = 0, and so either s or t must be zero, this is not sufficient to state which must be zero)4.Correct Answer: EExplanation:65 = 64x 6(64 x 6) - 64 = 64(6 - 1) = 64 x 5Now, dividing by 5 will give us 645.Correct Answer: EExplanation:All terms in the sequence will be multiples of 4.762 is not a multiple of 46.Correct Answer: AExplanation:Choice I is correct because f(x) = 6 when x=3Choice II is incorrect because to make f(x) = 0, x² would have to be 3. But 3 is not the square of an integer.Choice III is incorrect because to make f(x) = 0, x² would have to be –3 but squares cannot be negative.(The minimum value for x2 is zero; hence, the minimum value for f(x) = -3)7.Correct Answer: CExplanation:1 < 4n + 7 < 200n can be 0, or -1n cannot be -2 or any other negative integer or the expression 4n + 7 will be less than1.The largest value for n will be an integer < (200 - 7) /4193/4 = 48.25, hence 48The number of integers between -1 and 48 inclusive is 508.Correct Answer: BExplanation:First you must realize that the sum of two 2-digit numbers cannot be more that 198 (99 + 99). Therefore in the given problem D must be 1.Now use trial and error to satisfy the sum 5A + BC = 143A + C must give 3 in the units place, but neither can be 1 since all the digits have to be different. Therefore A + C = 13.With one to carry over into the tens column, 1 + 5 + B = 14, and B = 8.A + C +B + D = 13 + 8 + 1 = 229.Correct Answer: BExplanation:Total volume of water = 12 liters = 12 x 1000 cm3The base of the aquarium is 50 x 30 = 1500cm3Base of tank x height of water = volume of water1500 x height = 12000; height = 12000 / 1500 = 810.Correct Answer: AExplanation:Let Ben’s age now be BAnita’s age now is A.(A - 6) = P(B - 6)But A is 17 and therefore 11 = P(B - 6)11/P = B-6(11/P) + 6 = BSAT problem solving数学41. If a² = 12, then a4 =A. 144B. 72C. 36D. 24E. 162. If n is even, which of the following cannot be odd?I n + 3II 3nIII n² - 1A. I onlyB. II onlyC. III onlyD. I and II onlyE. I, II and III3. One side of a triangle has length 8 and a second side has length 5. Which of the following could be the area of the triangle?I 24II 20III 5A. I onlyB. II onlyC. III onlyD. II and III onlyE. I, II and III4. A certain animal in the zoo has consumed 39 pounds of food in six days. If it continues to eat at the same rate, in how many more days will its total consumption be 91 pounds?A. 12B. 11C. 10D. 9E. 85. A perfect cube is an integer whose cube root is an integer. For example, 27, 64 and 125 are perfect cubes. If p and q are perfect cubes, which of the following will not necessarily be a perfect cube?A. 8pB. pqC. pq + 27D. -pE. (p - q)66. What is the length of the line segment in the x-y plane with end points at (-2,-2) and (2,3)?A. 3B. √31C. √41D. 7E. 97. n is an integer chosen at random from the set{5, 7, 9, 11 }p is chosen at random from the set{2, 6, 10, 14, 18}What is the probability that n + p = 23 ?A. 0.1B. 0.2C. 0.25D. 0.3E. 0.48. A dress on sale in a shop is marked at $D. During the discount sale its price is reduced by 15%. Staff are allowed a further 10% reduction on the discounted price. If a staff member buys the dress what will she have to pay in terms of D ?A. 0.75DB. 0.76DC. 0.765DD. 0.775DE. 0.805D9. All the dots in the array are 2 units apart vertically and horizontally. What is the length of the longest line segment that can be drawn joining any two points in the array without passing through any other point ?A. 2B. 2√2C. 3D. √10E. √2010. If the radius of the circle with centre O is 7 and the measure of angle AOB is 100, what is the best approximation to the length of arc AB ?A. 9B. 10C. 11D. 12E. 13参考答案1.Correct Answer: AExplanation:a4 = a2 x a2 = 12 x 12 = 1442.Correct Answer: BExplanation:In case I , even plus odd will give oddIn case II, odd times even will give evenIn case III even squared is even, and even minus odd is odd.(You can check this by using an easy even number like 2 in place of n)Only case II cannot be odd.3.Correct Answer: DExplanation:The maximum area of the triangle will come when the given sides are placed at right angles. If we take 8 as the base and 5 as the height the area = ½ x 8 x 5 = 20We can alter the angle between the sides to make it less or more than 90, but this will only reduce the area. (Draw it out for yourself). Hence the area can be anything less than or equal to 20.4.Correct Answer: EExplanation:Food consumed per day = 39/6.In the remaining days it will consume 91 - 39 pounds = 52 poundsNow divide the food by the daily consumption to find the number of days52 / (39/6) = 52 x (6 / 39) = 85.Correct Answer: CExplanation:A perfect cube will have prime factors that are in groups of 3; for example 125 has the prime factors 5 x 5 x 5 , and 64 x 125 will also be a cube because its factors will be 4 x 4 x 4 x 5 x 5 x 5Consider the answer choices in turn.8 is the cube of 2, and p is a cube, and so the product will also be a cube.pq will also be a cube as shown above.pq is a cube and so is 27, but their sum need not be a cube. Consider the case where p =1 and q = 8, the sum of pq and 27 will be 35 which has factors 5 x 7 and is not a cube.-p will be a cube.Since the difference between p and q is raised to the power of 6, this expression will be a cube (with cube root = difference squared).6.Correct Answer: CExplanation:Sketch a diagram and calculate the distance (hypotenuse of a right triangle) using Pythagoras theorem.Vertical height of trian gle = 5 ; horizontal side = 4 ; hypotenuse = √(25 + 16) = √417.Correct Answer: AExplanation:Each of the integers in the first set could be combined with any from the second set, giving a total of 4 x 5 = 20 possible pairs.Of these the combinations that could give a sum of 23 are (5 + 18), and (9 + 14)This means that the probability of getting a sum of 23 is 2/20 = 1/108.Correct Answer: CExplanation:If the price is reduced by 15 %, then the new price will be 0.85DIf this new price is further reduced by 10%, the discounted price will be 0.9 x 0.85D = 0.765D9.Correct Answer: EExplanation:The longest line segment that can be drawn without passing through any dots other than those at the beginning and end of the segment, such a line could go from the middle dot in the top row to either the bottom left or right dot. In any case the segment will be the hypotenuse of a right triangle with sides 2 and 4. Using Pythagoras theorem the hypotenuse will be √(2 ² + 4 ² ) = √2010.Correct Answer: DExplanation:I f the radius is 7, the circumference = 14πThe length of the arc is 100/360 of the circumferenceTaking π as 22/7 we get(100 x 14 x 22) / (360 x 7) which reduces to 440/ 36 = 12.22 (i.e. approx. 12)SAT problem solving数学51. Sheila works 8 hours per day on Monday, Wednesday and Friday, and 6 hours per day on Tuesday and Thursday. She does not work on Saturday and Sunday. She earns $324 per week. How much does she earn in dollars per hour?A. 11B. 10C. 9D. 8E. 72. ABCD is a parallelogram. BD = 2. The angles of triangle BCD are all equal. What is the perimeter of the parallelogram?A. 12B. 9√3C. 9D. 8E. 3√33. If the product of 6 integers is negative, at most how many of the integers can be negative?A. 2B. 3C. 4D. 5E. 64. If a positive integer n, divided by 5 has a remainder 2, which of the following must be true?I n is oddII n + 1 cannot be a prime numberIII (n + 2) divided by 7 has remainder 2A. noneB. I onlyC. I and II onlyD. II and III onlyE. I, II and III5. A solid cube of side 6 is first painted pink and then cut into smaller cubes of side 2. How many of the smaller cubes have paint on exactly 2 sides?A. 30B. 24C. 12D. 8E. 66. Line l contains the points (3,1) and (4,4).If line m is a different line, parallel to line l in the same coordinate plane, which of the following could be the equation of line m?A. y = 3x - 8B. y = 1/3x - 3C. y = -3x - 8D. y = 3x + 1E. y = -8x + 37. In the figure above the square has two sides which are tangent to the circle. If the area of the circle is 4a²π, what is the area of the square?A. 2a²B. 4aC. 4a²D. 16a²E. 64a²8. A triangle has a perimeter 13. The two shorter sides have integer lengths equal to x and x + 1. Which of the following could be the length of the other side?A. 2B. 4C. 6D. 8E. 109. A machine puts c caps on bottles in m minutes. How many hours will it take to put caps on b bottles?A. 60bm/cB. bm/60cC. bc/60mD. 60b/cmE. b/60cm10. Paint needs to be thinned to a ratio of 2 parts paint to 1.5 parts water. The painter has by mistake added water so that he has 6 litres of paint which is half water and half paint. What must he add to make the proportions of the mixture correct?A. 1 litre paintB. 1 litre waterC. ½ litre water and one litre paintD. ½ litre paint and one litre waterE. ½ litre paint参考答案1.Correct Answer: CExplanation:Total hours worked = 8 x 3 + 6 x 2 = 36Total earned = 324. Hourly wage = 324 / 36 = 92.Correct Answer: DExplanation:Since the angles of BCD are all equal, it is an equilateral triangle. Therefore. Since one side is 2, BD and CD are also 2. These sides (totaling 4 units) represent half the perimeter of the parallelogram. Total perimeter = 8.3.Correct Answer: DExplanation:Multiplying two negatives (or any even multiple) results in a positive. But multiplying three negatives (or any odd multiple) gives a negative. If the result of multiplying 6 negatives is odd, the largest number of negative integers will be the largest odd number (i.e.5)4.Correct Answer: AExplanation:You can find the integers which when divided by 5 have a remainder 2 by adding 2 to all multiples of 5. So we have n = 9 , 12, 17, 22 etc.From this series we can see that n does not have to be odd.Also n + 1 can be a prime because, for example, 12 + 1 = 13And (n + 2) / 7 has a remainder 2 in some cases but not all.Remember the question asks us for what MUST be true, and we see that none of the statements are true in all cases.5.Correct Answer: CExplanation:When the larger cube is cut into smaller cubes, the corner cubes will have paint on three sides. The cubes in the middle of the faces will have paint on only one side, but the cubes cut from the edges will have paint on two sides. In this case, there will be only one cube one each edge (excluding the corners), and since there are 12 edges, there will be 12 cubes with paint on two sides. (Drawing a diagram will make this much clearer.)6.Correct Answer: DExplanation:Slope of the line l = (4 – 1) / (4 – 3) = 3/1 = 3Parallel lines have the same slope. In the equation of a straight line, y = mx + c, m represents the slope, so we are looking for an equation where m = 3But both answer choices A and D have slope 3.Now we calculate the intercept, c, for line l. Using the coordinate of one of the points on l, we get: 4 = (3 x 4) + c ; 4 – 12 = c; c = -8Hence, answer A is the equation of line l, and answer D must be the equation of a parallel line.7.Correct Answer: DExplanation:If the area of the circle is 4a2π , the radius will be the square root of 4a2 (i.e. 2a)The diameter will be 4a. The diameter is also the side of the square. Area of the square is (4a)2 = 16a28.Correct Answer: CExplanation:The measure of the third side of a triangle must lie between the sum and the difference of the other two sides. Using this fact along with the answer choices, we can eliminate the wrong answers.(A) cannot be right because 2 would not be the longest side.(B) cannot be right because again it would not be the longest side(C) could be right because the other two sides would be 3 and 4.(D) and (E) cannot be right because this third side would be greater than the sum of the other two sides.9.Correct Answer: BExplanation:Substitute sensible numbers and work out the problem. Then change the numbers back to letters. For example if the machine puts 6 caps on bottles in 2 minutes, it will put 6 /2 caps on per minute, or (6 /2) x 60 caps per hour. Putting letters back this is 60c/m.If you divide the required number of caps (b) by the caps per hour you will get time taken in hours. This gives bm/60c (Remember dividing by a fraction is the same as multiplying by its inverse.)10.Correct Answer: AExplanation:At the moment the paint is 3 liters of paint and 3 liters of water. We need to add to this to make the new ratio 2 liters paint to 1.5 liters water. As this is equivalent to 4 : 3 we can see that we have the right amount of water, and just need 1 liter of paint to make it correct.SAT problem solving数学61. Which of the following can be used to illustrate that not all prime numbers are odd?A. 1B. 2C. 3D. 4E. 52. What is the greatest of 3 consecutive integers whose sum is 24 ?A. 6B. 7C. 8D. 9E. 103. Considering the positions on the number line above, which of the following could be a value for x?A. 5/3B. 3/5C. -2/5D. -5/2E. none4. A piece of ribbon 4 yards long is used to make bows requiring 15 inches of ribbon for each. What is the maximum number of bows that can be made?A. 8B. 9C. 10D. 11E. 125. How many numbers between 200 and 400 begin or end with 3 ?A. 20B. 60C. 100D. 110E. 1206. If f(3) = 15 and f(5) = 45, which of the following could be f(x)?A. 4x + 3B. 2x²– 2xC. 2x² - xD. 2x² - 5E. 5x²7. PQRS is a parallelogram and ST = TR. What is the ratio of the area of triangle QST to the area of the parallelogram?A. 1 : 2B. 1 : 3C. 1 : 4D. 1 : 5E. it cannot be determined8. A picture is copied onto a sheet of paper 8.5 inches by 10 inches. A 1.5 inch margin is left all around. What area in square inches does the picture cover?A. 76B. 65C. 59.5D. 49E. 38.59. The table shows the results of a poll which asked drivers how many accidents they had had over the previous 5 years. What is the median number of accidents per driver?A. 0.5B. 1C. 1.5D. 2E. 410. If V = 12R / (r + R) , then R =A. Vr / (12 - V)B. Vr + V /12C. Vr - 12D. V / r - 12E. V (r + 1) /12参考答案:1.Correct Answer: BExplanation:The only even numbers in the list are 2 and 4, but 4 is not a prime. So 2 can be used to illustrate the statement that all primes are not odd.2.Correct Answer: DExplanation:The sum of three consecutive integers can be written as n + (n + 1) + (n + 2) = 3n + 3If the sum is 24, we need to solve the equation 3n + 3 = 24; 3n = 21; n = 7The greatest of the three numbers is therefore 7 + 2 = 93.Correct Answer: CExplanation:Since the cube lies between the number and its square on the number line, we must be looking for a negative fraction (between 0 and -1 on the number line). Only -2/5 is a negative fraction. (Try for yourself the results of squaring and cubing negative numbers less than -1, numbers greater than 1, positive fractions, 1 and -1, so that you can deal with all similar questions).4.Correct Answer: BExplanation:The maximum number of bows will be 4 yards (= 4 x 36 inches) divided by 15 inches.This gives 9.6. But as a fraction of a bow is no use, we can only make 9 bows.5.Correct Answer: DExplanation:The numbers will be 203, 213, 223, 233, 243, 253, 263, 273, 283, 293, then all the numbers from 300 to 399 inclusive.6.Correct Answer: C。

SAT数学真题精选

SAT数学真题精选

SAT数学真题精选SAT数学真题精选1. If 2 x + 3 = 9, what is the value of 4 x – 3 ?(A) 5 (B) 9 (C) 15 (D) 18 (E) 212. If 4(t + u) + 3 = 19, then t + u = ?(A) 3 (B) 4 (C) 5 (D) 6 (E) 73. In the xy-coordinate (坐标) plane above, the line contains the points (0,0) and (1,2). If line M (not shown) contains the point (0,0) and is perpendicular (垂直)to L, what is an equation of M?(A) y = -1/2 x(B) y = -1/2 x + 1(C) y = - x(D) y = - x + 2(E) y = -2x4. If K is divisible by 2,3, and 15, which of the following is also divisible by these numbers?(A) K + 5 (B) K + 15 (C) K + 20 (D) K + 30 (E) K + 455. There are 8 sections of seats in an auditorium. Each section contains at least 150 seats but not more than 200 seats. Which of the following could be the number of seats in this auditorium?(A) 800 (B) 1,000 (C) 1,100 (D) 1,300 (E) 1,7006. If rsuv = 1 and rsum = 0, which of the following must be true?(A) r < 1 (B) s < 1 (C) u= 2 (D) r = 0 (E) m = 07. The least integer of a set of consecutive integers (连续整数) is –126. if the sum of these integers is 127, how many integers are in this set?(A) 126 (B) 127 (C) 252 (D) 253 (E) 2548. A special lottery is to be held to select the student who will live in the only deluxe room in a dormitory. There are 200 seniors, 300 juniors, and 400 sophomores who applied. Each senior’s name is placed in the lottery 3 times; each junior’s name, 2 time; and each sophomore’s name, 1 times. If a student’s name is chosen at random from the names in the lottery, what is the probability that a senior’s name will be chosen?(A)1/8 (B) 2/9 (C) 2/7 (D) 3/8 (E) 1/2Question #1: 50% of US college students live on campus. Out of all students living on campus, 40% are graduate students. What percentage of US students are graduate students living on campus?(A)90%(B)5%(C)40%(D)20%(E)25%Question #2: In the figure below, MN is parallel with BC and AM/AB = 2/3. What is the ratio between the area of triangle AMN and the area of triangle ABC?(A) 5/9 (B) 2/3 (C) 4/9 (D) 1/2 (E) 2/9Question #3: If a2 + 3 is divisible by 7, which of the following values can be a?(A)7 (B)8 (C)9 (D)11 (E)4Question #4: What is the value of b, if x = 2 is a solution of equation x2 - b · x + 1 = 0?(A)1/2 (B)-1/2 (C)5/2 (D)-5/2 (E)2Question #5: Which value of x satisfies the inequality | 2x | < x + 1 ?(A)-1/2 (B)1/2 (C)1 (D)-1 (E)2Question #6: If integers m > 2 and n > 2, how many (m, n) pairs satisfy the inequality m n< 100?(A)2 (B)3 (C)4 (D)5 (E)7Question #7: The US deer population increase is 50% every 20 years. How may times larger will the deer population be in60 years ?(A)2.275 (B)3.250 (C)2.250 (D)3.375 (E)2.500 Question #8: Find the value of x if x + y = 13 and x - y = 5.(A)2 (B)3 (C)6 (D)9 (E)4Question #9:US UK Medals3 2 gold1 4 silver4 1 bronzeThe number of medals won at a track and field championship is shown in the table above. What is the percentage of bronze medals won by UK out of all medals won by the 2 teams?(A)20% (B)6.66% (C)26.6% (D)33.3% (E)10%Question #10: The edges of a cube are each 4 inches long. What is the surface area, in square inches, of this cube? (A)66 (B)60 (C)76 (D)96 (E)65Question #1: The sum of the two solutions of the quadratic equation f(x) = 0 is equal to 1 and the product of the solutions is equal to -20. What are the solutions of the equation f(x) = 16 - x ?(a) x1 = 3 and x2 = -3(b) x1 = 6 and x2 = -6(c) x1 = 5 and x2 = -4(d) x1 = -5 and x2 = 4(e) x1 = 6 and x2 = 0Question #2: In the (x, y) coordinate plane, three lines have the equations:l1: y = ax + 1l2: y = bx + 2l3: y = cx + 3Which of the following may be values of a, b and c, if line l3 is perpendicular to both lines l1 and l2?(a) a = -2, b = -2, c = .5(b) a = -2, b = -2, c = 2(c) a = -2, b = -2, c = -2(d) a = -2, b = 2, c = .5(e) a = 2, b = -2, c = 2Question #3: The management team of a company has 250 men and 125 women. If 200 of the managers have a master degree, and 100 of the managers with the master degree are women, how many of the managers are men without a master degree? (a) 125(b) 150(c) 175(d) 200(e) 225Question #4: In the figure below, the area of square ABCD is equal to the sum of the areas of triangles ABE and DCE. If AB = 6, then CE =(a) 5(b) 6(c) 2(d) 3(e) 4Question #5:If α and β are the angles of the right triangle shown in the figure above, then sin2α + sin2β is equal to:(a) cos(β)(b) sin(β)(c) 1(d) cos2(β)(e) -1Question #6: The average of numbers (a + 9) and (a - 1) is equal to b, where a and b are integers. The product of the same two integers is equal to (b - 1)2. What is the value of a?(a) a = 9(b) a = 1(c) a = 0(d) a = 5(e) a = 11Question #1: If f(x) = x and g(x) = √x, x≥ 0, what are the solutions of f(x) = g(x)? (A) x = 1(B)x1 = 1, x2 = -1(C)x1 = 1, x2 = 0(D)x = 0(E)x = -1Question #2: What is the length of the arc AB in the figure below, if O is the center of the circle and triangle OAB is equilateral? The radius of the circle is 9(a) π(b) 2 ·π(c) 3 ·π(d) 4 ·π(e) π/2 Question #3: What is the probability that someone that throws 2 dice gets a 5 and a 6? Each dice has sides numbered from 1 to 6.(a)1/2(b)1/6(c)1/12(d)1/18(e)1/36Question #4: A cyclist bikes from town A to town B and back to town A in 3 hours. He bikes from A to B at a speed of 15 miles/hour while his return speed is 10 miles/hour. What is the distance between the 2 towns?(a)11 miles (b)18 miles (c)15 miles (d)12 miles (e)10 miles Question #5: The volume of a cube-shaped glass C1 of edge a is equal to half the volume of a cylinder-shaped glass C2. The radius of C2 is equal to the edge of C1. What is the height ofC2?(a)2·a /π(b)a / π(c)a / (2·π) (d)a / π(e)a + πQuestion #6: How many integers x are there such that 2x< 100, and at the same time the number 2x + 2 is an integer divisible by both 3 and 2?(a)1 (b)2 (c) 3 (d) 4 (e)5Question #7: sin(x)cos(x)(1 + tan2(x)) =(a)tan(x) + 1 (b)cos(x)(c)sin(x) (d)tan(x)(e)sin(x) + cos(x)Question #8: If 5xy = 210, and x and y are positive integers, each of the following could be the value of x + y except:(a)13 (b) 17 (c) 23 (d)15 (e)43Question #9: The average of the integers 24, 6, 12, x and y is 11. What is the value of the sum x + y?(a)11 (b)17 (c)13 (d)15 (e) 9Question #10: The inequality |2x - 1| > 5 must be true in which one of the following cases?I. x < -5II. x > 7III. x > 01.Three unit circles are arranged so that each touches the other two. Find the radii ofthe two circles which touch all three.2.Find all real numbers x such that x + 1 = |x + 3| - |x - 1|.3.(1) Given x = (1 + 1/n)n, y = (1 + 1/n)n+1, show that x y = y x.(2) Show that 12 - 22 + 32 - 42 + ... + (-1)n+1n2 = (-1)n+1(1 + 2 + ... + n).4.All coefficients of the polynomial p(x) are non-negative and none exceed p(0). Ifp(x) has degree n, show that the coefficient of x n+1 in p(x)2 is at most p(1)2/2.5.What is the maximum possible value for the sum of the absolute values of thedifferences between each pair of n non-negative real numbers which do not exceed 1?6.AB is a diameter of a circle. X is a point on the circle other than the midpoint of thearc AB. BX meets the tangent at A at P, and AX meets the tangent at B at Q. Show that the line PQ, the tangent at X and the line AB are concurrent.7.Four points on a circle divide it into four arcs. The four midpoints form aquadrilateral. Show that its diagonals are perpendicular.8.Find the smallest positive integer b for which 7 + 7b + 7b2 is a fourth power.9.Show that there are no positive integers m, n such that 4m(m+1) = n(n+1).10.ABCD is a convex quadrilateral with area 1. The lines AD, BC meet at X. Themidpoints of the diagonals AC and BD are Y and Z. Find the area of the triangle XYZ.。

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可汗学院新SAT数学真题下载
到目前为止,新版SAT可汗学院官方不断放出更多真题,已经放出了68篇阅读,且之前已经和大家分享过可汗学院新SAT阅读真题,想要下载的同学,请点击:新SAT阅读真题下载(共68篇,且已全)
今天主要和大家分享可汗学院新SAT数学真题!目前可汗学院一共放出41篇新SAT数学真题!想要下载的同学,请点击:新SAT数学真题下载(共41篇)
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以下是部分可汗学院新SAT数学真题。

Solving linear equations
1. Solve for k:
k + 22 = 29
k =
Correct answer: 7 Difficulty level: 1
2. Solve for n:
-8 + n = 23
n =
Correct answer: 31 Difficulty level: 1
3. Solve for x:
x – 9 = 1
x =
Correct answer: 10 Difficulty level: 1
4. Solve for n:
18 = n - 18
n =
Correct answer: 36 Difficulty level: 1
5. Solve for k:
k + 10 = 27
k =
Correct answer: 17 Difficulty level: 1
6. Solve for t:
t + 25 = 26
t =
7. Solve for k:
-30 + k = 22
k =
Correct answer: 52 Difficulty level: 1
8.Solve for k:
19 = 14 + k
k =
Correct answer: 5 Difficulty level: 1
9. Solve for q:
3 = -8 + q
q =
Correct answer: 11 Difficulty level: 1
10. Solve for p:
10 = -19 + p
p =
Correct answer: 29 Difficulty level: 1
11. Solve for r:
-12 + r = 7
r =
Correct answer: 19 Difficulty level: 1
12. Solve for p:
p + 12 = 30
p =
Correct answer: 18 Difficulty level: 1
13. Solve for p:
p – 18 = 3
p =
Correct answer: 21 Difficulty level: 1
14. Solve for k:
30 = k + 23
k =
15. Solve for y:
25 = -14 + y
y =
Correct answer: 39 Difficulty level: 1
16. Solve for r:
20 = r + 11
r =
Correct answer: 9 Difficulty level: 1
17. Solve for z:
-26 + z = 15
z =
Correct answer: 41 Difficulty level: 1
18. Solve for p:
29 = p + 20
p =
Correct answer: 9 Difficulty level: 1
19. Solve for y:
24 = y + 19
y =
Correct answer: 5 Difficulty level: 1
20. Solve for n:
27 = 15 + n
n =
Correct answer: 12 Difficulty level: 1
21. Solve for k:
2 = -30 + k
k =
Correct answer: 32 Difficulty level: 1
22. Solve for n:
19 + n = 30
n =。

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