大学物理实验计算题
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1.用50分度游标卡尺测量铜环的内径K=6次,测量数据如下,d i =,,,,,,单位毫米,计算测量结果,并用不确定度表示测量结果。
()
%
2.097.19/0
3.003.097.1903.002.002.002.0102.0197.192
22
6
1
==±==+===⨯==
=--=
=∑=E mm d mm
U U U mm
U mm
n t
U mm
n d
d
mm
d B A d B d A i
i d σσ解:
2.用流体静力称衡法测固体密度的公式为:ρ=[m/(m-m1)] ρ0,若测得m=(±)g ,m 1=(±)g,
ρ0=(±)g/cm 3,求:ρ±U ρ
3
3
013
2
0212122
1122211202
02
12
122/02.091.2/91.2/02.0)())
(())((
cm g cm
g m m m cm g U m m m U m m m U m m m U U U U p m m m m m m ±==⎥⎦
⎤
⎢⎣⎡-==-+--+--=⎪⎪⎭
⎫
⎝⎛∂∂+⎪
⎪⎭⎫
⎝⎛∂∂+⎪⎪⎭⎫ ⎝⎛∂∂=ρρρρρρ
ρρρ解:
3.用有效数字运算规则计算下列各式:
⑴.1.02000.10.5000.400.2⨯+⨯+⨯
⑵.201080.63
-⨯
⑶.
()00
.2989.52.2480.2⨯-
解:(1)601.02000.10.5000.400.2=⨯+⨯+⨯
)
(2)3
3
1078.6201080.6⨯=-⨯
(3)()9.600
.2989.52.2480.2=⨯-
4.(1)=-+12.93.20475.8 (2)=⨯-⨯2
3
102.41025.5 (3)
=⨯+30
.26
.4)2.1036.9(
(4)=⨯2
00.10π
解:(1)6.1912.93.20475.8=-+ {
(2)3
2
3
1083.4102.41025.5⨯=⨯-⨯
(3)
3930
.26
.4)2.1036.9(=⨯+
(4) 2.31400.102
=⨯π 5.(1)=-+753.951.236457.68
(2)=⨯⨯0.30000.200
.40360.9
(3)=⨯2
00.604
1π
(4)
=-⨯--⨯)
140.31400.23()0.10831103()
450.945.18(00.80
解(1)21.295753.951.236457.68=-+
(2)
24.60.30000.200
.40360.9=⨯⨯
(3)282700.604
12
=⨯π
~
(4)
8.1)
140.31400.23()0.10831103()
450.945.18(00.80=-⨯--⨯
6.(1)
=+⨯-+⨯0.11000
.10)00.7700.78()
412.46.5(0.100
(2)=-+137.032.5347.72 (3)=÷⨯2005.3793.8 (4)=⨯-⨯1
2
107.1107.8 解:(1)
3101.10.11000
.10)00.7700.78()
412.46.5(0.100⨯=+⨯-+⨯
(2)53.77137.032.5347.72=-+
(3) 15.02005.3793.8=÷⨯ (4) 2
12105.8107.1107.8⨯=⨯-⨯ 7.(1)=+÷3.5109.76
—
(2)
=-2
2
200.3)00.400.5(
(3)=⨯-989.5)2.2480.2(
(4)=⨯-⨯+⨯1.02000.10.50000.400.2 解:(1)0.133.5109.76=+÷
(2)
0.100.3)00.400.5(2
22=-
(3)14989.5)2.2480.2(=⨯-
(4)561.02000.10.50000.400.2=⨯-⨯+⨯ 8.(1)=-⨯201080.63
(2)=-+28.520234.7
(3)=-++01.0701.2347.172 《
(4)=÷⨯100.2231.5
解:(1)3
3
1078.6201080.6⨯=-⨯ (2)2228.520234.7=-+
(3)24401.0701.2347.172=-++ (4)0.1100.2231.5=÷⨯ 9.(1)=⨯-⨯3
3
109.0109.7 (2)
]
20[3.22079.6是常数=+÷
(3)=÷⨯519.623.328
(4)=⨯-⨯1007.42.17.503 解:(1)3
33100.7109.0109.7⨯=⨯-⨯
、
(2)
]
20[6.23.22079.6是常数=+÷
(3)14519.623.328=÷⨯
(4)2
103.11007.42.17.503⨯=⨯-⨯