运算符重载的案例

p1=p2/p3;
cout<<p1.x<<","<<p1.y<<endl;
p1=p2++;//验证单目运算符重载
cout<<p1.x<<","<<p1.y<<endl;
bool p4;//验证关系运算符
p4=(p2==p3);
printf("%d",p4);
p4=(p2>p3);
point operator -(const point &p);//声明运算符重载-
point operator *(const point &p);//声明运算符重载*
point operator /(const point &p);//声明运算符重载/
//关系运算符重载
bool operator ==(const point &p);//声明运算符重载==
{
point temp;
temp.x=x/p.x;
temp.y=y/p.y;
return temp;
}
bool point::operator ==(const point &p)//==运算符重载
{
if(x==p.x&&y==p.y)
return true;
else
bool operator > (const point &p);//声明运算符重载>
//赋值运算符重载
point &operator =(const point &p);//声明赋值运算符重载=
//单目运算符重载
point operator ++();//声明运算符重载++
//point operator +(point p);
p1+=p2;
cout<<p1.x<<","<<p1.y<<endl;
//p1=p2;//验证赋值运算符重载*/
//cout<<p1.x<<","<<p1.y<<endl;
/* p1=p2-p3;
cout<<p1.x<<","<<p1.y<<endl;
p1=p2*p3;
cout<<p1.x<<","<<p1.y<<endl;
{
point temp;
temp.x=x+p.x;
temp.y=y+p.y;
return temp;
}
point point::operator -(const point &p)//-运算符重载
{
point temp;
temp.x=x-p.x;
temp.y=y-p.y;
return false;
}
bool point::operator > (const point &p)// >运算符重载
{
if(x>p.x&&y>p.y)
return true;
else
return false;
}
point & point::operator =(const point &p)//赋值运算符重载
return temp;
}
point point::operator *(const point &p)//*运算符重载
{
point temp;
temp.x=x*p.x;
temp.y=y*p.y;
return temp;
}
point point::operator /(const point &p)// /运算符重载
{
x=p.x;
y=p.y;
return *this;
}
point point::operator ++()
{
x++;
y++;
return *this;
}
int main(int argc, char* argv[])
{
//point p4(p);
//cout<<p.x<<","<<p.y<<endl;
int x;
int y;
point()
{
x=0;
y=0;
}
point(x=a;
y=b;
}
point(point &p);//声明拷贝构造函数
//双目运算符重载
point operator +(const point &p);//声明运算符重载+
{
x=p.x;
y=p.y;
cout<<"调用拷贝构造函数!"<<endl;
}
/*point point::operator +(point p)
{
point temp;
temp.x=x+p.x;
temp.y=y+p.y;
return temp;
}
*/
point point::operator +(const point &p)//+运算符重载
//point p(1,2);
//cout<<p.x<<","<<p.y<<endl;
point p1(1,2),p2(2,2),p3(3,2);
p1=p2+p3;//验证双目运算符重载
cout<<p1.x<<","<<p1.y<<endl;
cout<<"*************"<<endl;
point &operator +=(const point &p);
};
point &point::operator +=(const point &p)
{
x+=p.x;
y+=p.y;
return *this;
}
point::point( point &p)//构造拷贝构造函数
printf("%d",p4);*/
getchar();
return 0;
}
// Operator.cpp : Defines the entry point for the console application.
//
#include "stdafx.h"
#include<iostream.h>
#include<stdio.h>
class point
{
public: