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(解析版)河南省平顶山市、许昌市、汝州2017-2018学年高二上学期第三次联考数学(文)试题

(解析版)河南省平顶山市、许昌市、汝州2017-2018学年高二上学期第三次联考数学(文)试题

高二数学(文科)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1. 已知命题,则是()A. B.C. D.【答案】C【解析】根据全称命题与存在性命题的关系,可知命题的否定为:,故选C.2. 已知函数的值域为集合,不等式的解集为集合,则()A. B. C. D.【答案】C【解析】由函数的值域为,不等式的解集为,所以,故选C.3. 下列命题为特称命题的是()A. 任意一个三角形的内角和为B. 棱锥仅有一个底面C. 偶函数的图象关于轴垂直D. 存在大于1的实数,使【答案】D【解析】对于选项A、B、C都为全称命题,选项D中,根据特称命题的概念,可得命题“存在大于的实数,使”中含有存在量词,所以D为特称命题,故选D.4. 若椭圆的焦点坐标为()A. B. C. D.【答案】D【解析】由椭圆,可得,则,所以该椭圆的焦点坐标为,故选D.5. 设等差数列的首项为,若,则的公差为()A. B. C. D.【答案】B【解析】设等差数列的公差为,则,解得,故选B.6. “”是“方程表示焦点x在上的椭圆”的()A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】A【解析】若方程表示焦点在轴上的椭圆,则,所以,所以是方程表示焦点在轴上的椭圆的充分不必要条件,故选A.7. 在中,角所对的边分别为,则的周长为()A. B. C. D.【答案】C【解析】因为,所以,由余弦定理,得,所以的周长为,故选C.8. 若以双曲线的实轴长比虚轴长多,则该双曲线的离心率为()A. B. C. D.【答案】B【解析】由椭圆的方程,可得,所以,又,所以,所以,故选B.9. 设变量满足约束条件,则的最大值是()A. B. C. D.【答案】A【解析】画出满足条件的平面区域,如图所示,当直线和直线交于点时,此时的坐标为,易知,当时,取得最大值,此时最大值为.10. 已知分别是双曲线的左右焦点,点在此双曲线的右支上,且,则的面积为()A. B. C. D.【答案】D【解析】由双曲线的方程,可知,则,又,由双曲线的定义可知,所以,则,所以的面积等于,故选D.11. 已知某曲线的方程为,给出下列两个命题:命题若,则该曲线为双曲线;命题若,则该曲线为椭圆,则下列叙述错误的是()A. 是真命题B. 的逆命题是真命题C. 是真命题D. 的逆命题是真命题【答案】D【解析】若,则该曲线为双曲线,且该曲线为双曲线时,,所以命题是真命题且其逆命题也为真命题;若曲线为椭圆,则或,所以的逆命题是假命题,故选D.点睛:本题考查了椭圆与双曲线的标准方程,解答中熟记椭圆的标准方程和双曲线的标准方程的形式是解答的关键.12. 设双曲线的左焦点,过的直线交双曲线的左支于(在的上方)两点,轴,,若为钝角,则双曲线的离心率的取值范围是()A. B. C. D.【答案】A【解析】由题意易知,因为为钝角,所以,即,所以,又,所以,故选A.点睛:本题考查了双曲线的离心率的求解问题,其中解答中涉及到双曲线的标准方程及其简单的几何性质的应用,此类问题解答中熟记双曲线的几何性质和合理转化条件是解答的关键.第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)13. 双曲线的渐近线方程是__________.【答案】【解析】由双曲线的方程,可得,所以其渐近线方程为.14. 在中,角所对的边分别为,则 __________.【答案】【解析】在中,由,则,所以,由正弦定理可得.15. 已知,若,则的最小值为__________.【答案】【解析】∵m>0,n>0,2m=1﹣2n,即2m+2n=1.则=2(m+n)()=2(30+)当且仅当n=3m=时取等号.故答案为:96.点睛:这个题目考查了基本不等式求最值的应用,解决二元问题的方法有,不等式的应用,变量集中法,二元化一元的方法,等等。

河南省平顶山市、许昌市、汝州高二上学期第三次联考历史试题(解析版) Word版含解析

河南省平顶山市、许昌市、汝州高二上学期第三次联考历史试题(解析版) Word版含解析

本试卷主要考试内容:人教版必修3(第一~六单元)第I卷(选择题共48分)选择题(本大题共24小题,每小题2分,共48分。

在每小题给出的四个选项中,只有一项是符合题目要求的。

)1. 春秋战国时期有位思想家认为:“恶’是自然,而善”却是人为的,只有用‘礼义’对人性加以节制、改造,才能把人导人善。

”材料中的这位思想家可能是A. 孟子B. 墨子C. 韩非D. 荀子【答案】D【解析】根据材料中“礼义”、“法度”可以判断其主张礼法并施,因此这位思想家应为荀子,故D项正确。

孟子主张仁政,墨子主张兼爱非攻,韩非子主张改革和法治,排除ABC。

点睛:本题的解题关键是““恶’是自然,而善”却是人为的,只有用‘礼义’对人性加以节制、改造,才能把人导人善。

”,容易联想到荀子的著名的性恶论。

2. 西汉著作《五行五事》中说,如果君王不知礼节,树木就长不直,并且夏天常有暴风;如果君王言不守信,反复无常,秋天霹雳天气就特别多;如果君王不听劝谏,刚愎自用,春夏季节将暴雨成灾。

这些思想A. 阐述了天人互渗的关系B. 有利于规范君主的行为C. 完善了儒学的思想体系D. 蕴含了一定的辩证意识【答案】B【解析】据材料“如果君王不知礼节,树木就长不……刚愎自用,春夏季节将暴雨成灾”并结合所学知识可知,这反映了天人感应的思想,这有利于规范约束君主的行为,故B项正确;“天人感应”不等于天人互渗的关系,故A项错误;西汉时期没有完善儒学的思想体系,故C项错误;材料也无法体现辩证意识的内容,故D项错误。

故选B。

3. 宋理学家追求“平天下”,即建立以“均平”为特征的至理、至公、至正的理想社会;陆九渊提出“欲平治天下,当今之世,舍我其谁”的主张。

对此合理的解释是A. “平天下”体现了理学家的济世精神B. 理学家的追求超越了他们的阶级属性C. 宋金对峙成为“平天下”的思想源泉D. 陆九渊的自信超越了当时的知识分子【答案】A【解析】由材料““平天下”,即建立以“均平”为特征的至理、至公、至正的理想社会”,可见“平天下”体现了理学家的济世精神,故选A;理学家代表地主阶级利益,维护封建专制统治,排除B;早期儒学思想是“平天下”的思想源泉,排除C;陆九渊的自信也受当时时代和阶级的限制,没有超越当时的知识分子,排除D。

河南省平顶山市、许昌市、汝州2020-2021学年高二上学期第三次联考数学(理)试题

河南省平顶山市、许昌市、汝州2020-2021学年高二上学期第三次联考数学(理)试题

河南省平顶山市、许昌市、汝州2020-2021学年高二上学期第三次联考数学(理)试题学校:___________姓名:___________班级:___________考号:___________一、单选题1.双曲线221916x y -=的渐近线方程是( )A .916y x =±B .169y x =±C .43y x =±D .34yx 2.已知命题31:(0,),()()log 2xp a f x a x ∀∈+∞=-在定义域内是单调函数,则p ⌝为( )A .31:(0,),()()log 2x p a f x a x ⌝∃∈+∞=-在定义域内不是单调函数B .31:(0,),()()log 2xp a f x a x ⌝∃∈+∞=-在定义域内是单调函数C .31:(,0),()()log 2xp a f x a x ⌝∃∈-∞=-在定义域内不是单调函数D .31:(,0),()()log 2xp a f x a x ⌝∀∈-∞=-在定义域内不是单调函数3.设等差数列{}n a 的首项为2-,若41224a a +=,则{}n a 的公差为 ( ) A .1B .2C .4D .84.下列命题为特称命题的是 ( ) A .任意一个三角形的内角和为0180 B .棱锥仅有一个底面C .偶函数的图象关于y 轴垂直D .存在大于1的实数x ,使lg 12x +<5.若椭圆22219x y m+=(0<m <3)的长轴比短轴长2,则m = ( )A .32B .85C .1D .26.“25m >”是“方程222113x y m +=-表示焦点在x 上的椭圆”的A .充分不必要条件B .必要不充分条件C .充要条件D .既不充分也不必要条件7.在ABC ∆中,角,,A B C 所对的边分别为,,,sin :sin 2cos a b c A B c C ===则ABC ∆的周长为( )A .3+B .C .3+D .38.若以双曲线2221(0)4x y a a -=>的左右焦点和点为顶点的三角形为直角三角形,则该双曲线的离心率为( )AB C .2D 9.已知12,F F 分别是双曲线22236x y -=的左右焦点,点M 在此双曲线的右支上,且1MF =12MF F 的面积为( )A .B .6C .D .10.若322x y +=,则84x y +的最小值为( )A .4B .C .2D .11.给出下列三个命题:1:,2sin 2cos 3p x x x x ∃∈+=+R ;2:1p x ≠“或3y ≠”是“3xy ≠”的必要不充分条件,3:p 若lg lg 0a b +=,则2a b +≥.那么,下列命题为真命题的是 A .12p p ∧ B .()12p p ∨⌝ C .23p p ∧D .()23p p ⌝∧12.已知椭圆2222:1(0)x y C a b a b+=>>的左顶点为A ,上顶点为B ,过椭圆C 的右焦点作x 轴的垂线交直线AB 于点D ,若直线OD 的斜率是直线AB 的斜率的(4)k k >倍,其中,O 为坐标原点,则椭圆C 的离心率的取值范围为( ) A .(1,14) B .1(0,)4C .1(,1)3D .1(0,)3二、填空题13.命题“若3x ≥,则2214x x -+>”的否命题为__________.14.在ABC ∆中,角,,A B C 所对的边分别为1,,,cos ,3a b c A a ==sin b B= __________.15.设变量x,y 满足约束条件{x −y +2≥0x +y −4≥04x −y −4≤0,则y+2x+1的最大值是__________.16.已知焦距为4的双曲线22221(0,0)x y a b a b-=>>的左右顶点分别为12,,A A M 是双曲线上异于12,A A 的任意两点,若12,1,MA MA k k 依次成等比数列,则双曲线的标准方程是__________.三、解答题17.已知函数()22.1f x x x =++ (1)若()1,x ∈-+∞,求()f x 的最小值,并指出此时x 的值; (2)求不等式()22f x x ≥+的解集.18.(1)已知点,A B 的坐标为(1,0),(1,0)-,直线,PA BP 相交于点P ,且它们的斜率之积是19-,求动点的轨迹方程; (2)已知定点F 的坐标为(0,2),P 为动点,若以线段PF 为直径的圆恒与x 轴相切,求动点P 的轨迹方程.19.设:p “关于x 的不等式2504x ax a -++>的解析为R ”,:q “函数()12xf x x a ⎛⎫=-+ ⎪⎝⎭在区间()1,2-上有零点”.(1)若q 为真,求a 的取值范围;(2)若p q ∧为假,p q ∨为真,求a 的取值范围.20.已知椭圆M 与椭圆22:195x y N +=有相同的焦点,且椭圆M 过点()0,2.(1)求M 的长轴长;(2)设直线2y x =+与M 交于,A B 两点(A 在B 的右侧),O 为原点,求·OA OB . 21.已知数列{}n a 满足123(1)(1)(1)(1)1n a a a a n +⋅+⋅+⋅⋅+=+.(1)求数列{}n a 的通项公式;(2)若正整数m 满足12233416364m m a a a a a a a a +++++=,求m 的值.22.如图,椭圆2222:1(0)x y E a b a b +=>>的离心率为2,且椭圆E 经过点,已知点(0,2)Q ,过点(0,1)P 的动直线l 与椭圆E 相交于,A B 两点,B '与B 关于y 轴对称.(1)求E 的方程;(2)证明:,,Q A B '三点共线.参考答案1.C 【解析】由220916x y -=,得43y x =±。

河南省平顶山市、许昌市、汝州2017-2018学年高二数学上学期第三次联考试题 文(扫描版)

河南省平顶山市、许昌市、汝州2017-2018学年高二数学上学期第三次联考试题 文(扫描版)

河南省平顶山市、许昌市、汝州2017-2018学年高二数学上学期第三
次联考试题文(扫描版)
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河南省平顶山市、许昌市、汝州2024届高三第三次模拟考试物理试卷含解析

河南省平顶山市、许昌市、汝州2024届高三第三次模拟考试物理试卷含解析

河南省平顶山市、许昌市、汝州2024届高三第三次模拟考试物理试卷请考生注意:1.请用2B 铅笔将选择题答案涂填在答题纸相应位置上,请用0.5毫米及以上黑色字迹的钢笔或签字笔将主观题的答案写在答题纸相应的答题区内。

写在试题卷、草稿纸上均无效。

2.答题前,认真阅读答题纸上的《注意事项》,按规定答题。

一、单项选择题:本题共6小题,每小题4分,共24分。

在每小题给出的四个选项中,只有一项是符合题目要求的。

1、如图所示,将直径为d ,电阻为R 的闭合金属环从匀强磁场B 中拉出,这一过程中通过金属环某一截面的电荷量为( )A .24B d R π B .2Bd R πC .2Bd RD .2Bd Rπ 2、2019年9月29日下午在第十三届女排世界杯中,中国女子排球队以十一战全胜的战绩卫冕世界杯冠军,如图所示为运动员朱婷在后排强攻。

若运动员朱婷此时正在后排离球网3m 处强攻,速度方向水平。

设矩形排球场的长为2L ,宽为L (实际L 为9m),若排球(排球可视为质点)离开手时正好在3m 线(即3L 线)中点P 的正上方高h 1处,球网高H ,对方运动员在近网处拦网,拦网高度为h 2,且有h 1>h 2 >H ,不计空气阻力。

为了使球能落到对方场地且不被对方运动员拦住,则球离开手的速度v 的最大范围是(排球压线不算犯规) ( )A .11432()32L g L g v h H h <≤-B .2211432()322L g L L g v h H h ⎛⎫⎛⎫<≤+ ⎪ ⎪-⎝⎭⎝⎭C .121432()32L g L g v h h h ≤-D .22121432()322L g L L g v h h h ⎛⎫⎛⎫⋅<≤+⋅ ⎪ ⎪-⎝⎭⎝⎭3、目前在太阳系内一共已经发现了约127万颗小行星,但这可能仅是所有小行星中的一小部分.若某颗小行星在离太阳中心R 处做匀速圆周运动,运行的周期为T ,已知引力常量为G ,仅利用这三个数据,可以估算出太阳的( ) A .表面加速度大小 B .密度 C .半径 D .质量4、关于固体、液体、气体和物态变化,下列说法中正确的是( )A .晶体一定具有各向异性的特征B .液体表面张力是液体内部分子间的相互作用C .0℃的铁和0℃的铜,它们的分子平均速率相同D .一定质量的某种理想气体状态改变时,内能不一定改变5、甲、乙两个质点沿同一直线运动,它们的位移一时间图象如图所示。

河南省平顶山市汝州第三中学高二物理联考试卷带解析

河南省平顶山市汝州第三中学高二物理联考试卷带解析

河南省平顶山市汝州第三中学高二物理联考试卷含解析一、选择题:本题共5小题,每小题3分,共计15分.每小题只有一个选项符合题意1. (多选)空间存在方向垂直于纸面向里的匀强磁场,图中的正方形为其边界。

一细束由两种粒子组成的粒子流沿垂直于磁场的方向从O点入射。

这两种粒子带同种电荷,它们的电荷量、质量均不同,但其比荷相同,且都包含不同速率的粒子。

不计重力。

下列说法正确的是()A.入射速度相同的粒子在磁场中的运动轨迹一定相同B. 入射速度不同的粒子在磁场中的运动时间一定不同C.在磁场中运动时间相同的粒子,其运动轨迹一定相同D.在磁场中运动时间越长的粒子,其轨迹所对的圆心角一定越大参考答案:AD2. (单选)带电粒子运动方向垂直匀强磁场方向时,会受到洛伦兹力的作用,下列表述正确的是()A.洛伦兹力对带电粒子不做功B.洛伦兹力不改变带电粒子的动能C.带电粒子所受的力跟运动速度有关D.洛伦兹力只能改变带电粒子的运动方向参考答案:D3. (多选)如图所示是一个水平放置的玻璃圆环型小槽,槽内光滑,槽的宽度和深度处处相同,现将一直径略小于槽宽的带正电小球放在槽中,让它受绝缘棒打击后获得一初速度v0,与此同时,有一变化的磁场垂直穿过玻璃圆环型小槽外径所对应的圆面积,磁感应强度的大小跟时间成正比,其方向竖直向下,设小球在运动过程中电荷量不变,那么()A.小球受到的向心力大小不变B.小球受到的向心力大小不断增加C.洛伦兹力对小球做了正功D.小球受到的磁场力逐渐变大参考答案:解:A、由麦克斯韦电磁场理论可知,磁感应强度随时间均匀增大时,将产生一个恒定的感应电场,由楞次定律可知,此电场方向与小球初速度方向相同,由于小球带正电,电场力对小球做正功,小球的速度逐渐增大,向心力也随着增大,故A错误,B正确.C、洛伦兹力对运动电荷不做功,故C错误.D、带电小球所受洛伦兹力F=qBv,随着速度的增大而增大,故D正确.故选:BD4. 如图8所示,小球沿水平面以初速v0通过O点进入半径为R的竖直半圆弧轨道,不计一切阻力。

河南省平顶山市、许昌市、汝州高二化学上学期第三次联考试题(含解析)(2021年整理)

河南省平顶山市、许昌市、汝州高二化学上学期第三次联考试题(含解析)(2021年整理)

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学试题第Ⅰ卷(选择题共48分)一、选择题:(本题包括16小题,每小题3分,共48分。

每小题只有一个选项符合题意)1。

2017年8月,四川九寨沟地震造成了重大人员财产损失.地震救援中需要使用大量的消毒剂,下列消毒剂属于强电解质的是( )A. 高锰酸钾B. 二氧化氯 C。

酒精 D。

过氧化氢【答案】A【解析】A、高锰酸钾具有强氧化性,能杀菌消毒,属于强电解质,A正确;B、二氧化氯具有强氧化性,能杀菌消毒,属于非电解质,B错误;C、酒精是非电解质,C错误;D、过氧化氢属于弱电解质,D错误,答案选A。

2. 下列说法正确的是( )A。

向0.1mol/ LNa2CO3溶液中滴加酚酞,溶液变红B。

Al3+、NO3—、Cl—、CO32-、Na+可大量共存于pH=2的溶液中C。

乙醇和乙酸都能溶于水,都是电解质D. 分别与等物的量的HCl 和H2SO4反应时,消耗NaOH 的物质的量相同【答案】A【解析】A、碳酸钠水解,溶液显碱性,向0。

1mol/LNa2CO3溶液中滴加酚酞,溶液变红,A正确;B、Al3+与CO32—水解相互促进,不能大量共存,pH=2的溶液显酸性,碳酸根离子也不能大量共存,B错误;C、乙醇是非电解质,C错误;D、盐酸是一元强酸,硫酸是二元强酸,分别与等物的量的HCl和H2SO4反应时,消耗NaOH的物质的量不相同,D错误,答案选A。

河南省平顶山市、许昌市、汝州高二数学上学期第三次联考试题文(含解析)

河南省平顶山市、许昌市、汝州高二数学上学期第三次联考试题文(含解析)

河南省平顶山市、许昌市、汝州2017-2018学年高二数学上学期第三次联考试题文(含解析)第Ⅰ卷(共60分)一、选择题:本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的.1. 已知命题,则是()A. B.C. D.【答案】C【解析】根据全称命题与存在性命题的关系,可知命题的否定为:,故选C.2. 已知函数的值域为集合,不等式的解集为集合,则()A. B. C. D.【答案】C【解析】由函数的值域为,不等式的解集为,所以,故选C.3. 下列命题为特称命题的是()A. 任意一个三角形的内角和为B. 棱锥仅有一个底面C. 偶函数的图象关于轴垂直D. 存在大于1的实数,使【答案】D【解析】对于选项A、B、C都为全称命题,选项D中,根据特称命题的概念,可得命题“存在大于的实数,使”中含有存在量词,所以D为特称命题,故选D.4. 若椭圆的焦点坐标为()A. B. C. D.【答案】D【解析】由椭圆,可得,则,所以该椭圆的焦点坐标为,故选D.5. 设等差数列的首项为,若,则的公差为()A. B. C. D.【答案】B【解析】设等差数列的公差为,则,解得,故选B.6. “”是“方程表示焦点x在上的椭圆”的()A. 充分不必要条件B. 必要不充分条件C. 充要条件D. 既不充分也不必要条件【答案】A【解析】若方程表示焦点在轴上的椭圆,则,所以,所以是方程表示焦点在轴上的椭圆的充分不必要条件,故选A.7. 在中,角所对的边分别为,则的周长为()A. B. C. D.【答案】C【解析】因为,所以,由余弦定理,得,所以的周长为,故选C.8. 若以双曲线的实轴长比虚轴长多,则该双曲线的离心率为()A. B. C. D.【答案】B【解析】由椭圆的方程,可得,所以,又,所以,所以,故选B.9. 设变量满足约束条件,则的最大值是()A. B. C. D.【答案】A【解析】画出满足条件的平面区域,如图所示,当直线和直线交于点时,此时的坐标为,易知,当时,取得最大值,此时最大值为.10. 已知分别是双曲线的左右焦点,点在此双曲线的右支上,且,则的面积为()A. B. C. D.【答案】D【解析】由双曲线的方程,可知,则,又,由双曲线的定义可知,所以,则,所以的面积等于,故选D.11. 已知某曲线的方程为,给出下列两个命题:命题若,则该曲线为双曲线;命题若,则该曲线为椭圆,则下列叙述错误的是()A. 是真命题B. 的逆命题是真命题C. 是真命题D. 的逆命题是真命题【答案】D【解析】若,则该曲线为双曲线,且该曲线为双曲线时,,所以命题是真命题且其逆命题也为真命题;若曲线为椭圆,则或,所以的逆命题是假命题,故选D.点睛:本题考查了椭圆与双曲线的标准方程,解答中熟记椭圆的标准方程和双曲线的标准方程的形式是解答的关键.12. 设双曲线的左焦点,过的直线交双曲线的左支于(在的上方)两点,轴,,若为钝角,则双曲线的离心率的取值范围是()A. B. C. D.【答案】A【解析】由题意易知,因为为钝角,所以,即,所以,又,所以,故选A.点睛:本题考查了双曲线的离心率的求解问题,其中解答中涉及到双曲线的标准方程及其简单的几何性质的应用,此类问题解答中熟记双曲线的几何性质和合理转化条件是解答的关键.第Ⅱ卷(共90分)二、填空题(每题5分,满分20分,将答案填在答题纸上)13. 双曲线的渐近线方程是__________.【答案】【解析】由双曲线的方程,可得,所以其渐近线方程为.14. 在中,角所对的边分别为,则 __________.【答案】【解析】在中,由,则,所以,由正弦定理可得.15. 已知,若,则的最小值为__________.【答案】【解析】∵m>0,n>0,2m=1﹣2n,即2m+2n=1.则=2(m+n)()=2(30+)当且仅当n=3m=时取等号.故答案为:96.点睛:这个题目考查了基本不等式求最值的应用,解决二元问题的方法有,不等式的应用,变量集中法,二元化一元的方法,等等。

2017-2018学年河南省平顶山市、许昌市、汝州高二上学期第三次联考生物试题(附答案)

2017-2018学年河南省平顶山市、许昌市、汝州高二上学期第三次联考生物试题(附答案)

2017-2018学年河南省平顶山市、许昌市、汝州高二上学期第三次联考生物试题(附答案)第Ⅰ卷(选择题共50分)一、选择题(本大题共25小题,每小题2分,共50分。

在每小题给出的四个选项中,只有―项是符合题目要求的)1.在正常情况下可以出现在人体内环境中的是A.纤维素B.糖原C.核酸D.核酸2.一个完整的反射弧至少需要的神经细胞的数目是A.2个B.3个C.4个D.5个3.人体内环境稳态的调节能力是有一定限度的。

下列现象与内环境稳态失调有关的是A.饮水不足时,抗利尿激素释放量增多B.接受抗原刺激后,B细胞进行增殖和分化C.车祸发生时,驾驶人因失血过多而休克D.在高原训练时,运动员体内红细胞增多 .4.下图是突触局部模式图,下列说法错误的是A.①的化学本质是糖蛋白B.②传递到①,反射过程完成C.④代表突触前膜D.⑤内的液体是组织液5.当人体长时间大量运动后,血液中的水、无机盐、葡萄糖等物质会被大量消耗,下列有关此时机体调节活动变化的迅速,正确的是A.胰岛A细胞和胰岛B细胞的活动都减弱B.胰岛A细胞和胰岛B细胞的活动都加强C.胰岛B细胞的活动加强,胰岛A细胞的活动减弱D.下丘脑合成和垂体分泌抗利尿激素的活动都加强6.下列关于免疫细胞和特异性免疫的叙述,不正确的是A.免疫细胞是指机体内发挥免疫作用的细胞B.一个角细胞内的基因数目与其产生抗体的种类数是不相同的C.记忆细胞再次接触相应抗原时,能迅速增殖产生大量抗体D.细胞免疫中,效应T细胞可以攻击被抗原入侵的宿主细胞7.下列实例能证明低浓度的生长素会促进植物生长,而高浓度的生长素则会抑制植物生长的是①植物的向光性②顶端优势③根的向地性生长④茎的背地性生长A.①②③B.①②C.③④D.②③8.下列关于植物激素的叙述,错误的是A.脱落酸可促进果实的衰老和脱落B.植物茎尖的细胞可利用色氨酸合成生长素C.可从植物细胞中提取乙烯利来促进果实成熟D.在某些植物中一定浓度的生长素可促进乙烯的合成9.利用发生了向光弯曲的燕麦胚芽鞘制作成切片并观察,绘制出如下背光侧和向光侧的细胞形态示意图,由此可得出的结论是A.生长素能促进细胞分裂,胚芽鞘的弯曲部位是①B.生长索能促进细胞伸长,胚芽鞘的弯曲部位是②C.生长素能促进细胞分裂,胚芽鞘的弯曲部位是②D.生长素能促进细胞伸长,胚芽鞘的弯曲部位是①10.下图表示四个不同种群中不同年龄的个体所占的比例,其中种群密度可能会越来越大的是11.图甲为某一神经纤维示意图,将一电流表的a、b两电极置于膜外,在X处给予适宜刺激,测得电位变化如图乙所示。

河南省平顶山市、许昌市、汝州2017-2018学年高二英语上学期第三次联考试卷及答案【word版】.doc

河南省平顶山市、许昌市、汝州2017-2018学年高二英语上学期第三次联考试卷及答案【word版】.doc

【推荐】河南省平顶山市、许昌市、汝州2017-2018学年高二英语上学期第三次联考试卷及答案第三次联考英语试题考生注意:1.本试卷共150分,共8页。

考试时间120分钟。

2.请将各题答案填涂在答题卡上。

第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1. 5分,满分7. 5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt?A.£19.15.B. £9. 18.C. £9.15.答案是C。

1. What does the woman mean?A. She can't type the letter now.B. She plans to write a letter herself.C. She doesn’t understand the man’s re quest.2. What did the woman do while she was in Brighton?A. She stayed in a hotel.B. She lived near a campus.C. She camped outside.3. Where does the conversation probably take place?A. In a supermarket.B. In a kitchen-C. In a library,4. What can we learn from the conversation?A. The professor has changed his reading task.B. Some students at the back can’t hear the professor.C. Some of the students are not on the professor's class list.5. Who is the woman?A, A college student. B. A high school student. C. A college teacher.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或对白,每段对话或独白后有几个小题,从题中所给的A、B、C 三个选项中选出最佳选项,并标在试卷的相应位置,听每段对话或独白前,你将有时间阅读各个小题。

河南省平顶山市、许昌市、汝州2017-2018学年高二上学期第三次联考化学试题含答案

河南省平顶山市、许昌市、汝州2017-2018学年高二上学期第三次联考化学试题含答案

第Ⅰ卷 (选择题共48分)一、选择题:(本题包括16小题,每小题3分,共48分。

每小题只有一个选项符合题意)1.2017年8月,四川九寨沟地震造成了重大人员财产损失.地震救援中需要使用大量的消毒剂,下列消毒剂属于强电解质的是() A .高锰酸钾B.二氧化氯C.酒精D.过氧化氢2.下列说法正确的是()A.向0。

1mol/ LNa2CO3溶液中滴加酚酞,溶液变红B.Al3+、NO3-、Cl-、CO32-、Na+可大量共存于pH=2的溶液中C.乙醇和乙酸都能溶于水,都是电解质D.分别与等物的量的HCl 和H2SO4反应时,消耗NaOH 的物质的量相同3.下列物质的电离方程式书写正确的是( )A.NaHS=Na++H++S2—B.H2SO3==2H++SO32-C.HClO=H++ClO—D.Ba(OH)2=Ba2++2OH-4.一定量的锌粉和足量的稀硫酸反应制取H2,下列措施会减慢反应速率而又不影响生成氢气的量的是()A.加少量CuSO4溶液B.加少量浓盐酸C.加CH3COONa 溶液D.加KNO3溶液5.将0.01mol的下列物质分别加入(或通入)等量的水中,溶液体积变化忽略不计,其中在水溶液中的导电能力最强的是() A.H2S B.CH3COONH4 C.AgClD.CO26.将a、b、c、d 四块金属片浸泡在稀硫酸中,用导线两两相连。

若a、d 相连,a为负极;c、d相连,c极产生大量气泡;b、c相连,b 为正极;则这四种金属中金属性最强的是()A.a B.b C.c D.d7.下图是某氢氧燃料电池构造示意图。

下列关于该电池的说法不正确的是()A.a 电极是负极B.该电池的总反应为2H2+O2=2H2OC.电子由b电极通过灯泡流向a 电极D.氢氧燃料电池是环保电池8.用铜片、银片、Cu(NO3)2溶液、AgNO3溶液、导线和盐桥(装有琼脂KNO3的U 形管)构成一个原电池.以下有关该原电池的叙述正确的是()①在外电路中,电流由铜电极流向银电极②正极反应为Ag++e—=Ag③②实验过程中取出盐桥,原电池仍继续工作④将铜片没入AgNO3溶液中发生的化学反应与该原电池反应相同A.①②B.②③C.②④D.③④9.下列过程或现象与盐类水解无关的是()A.使用热的纯碱溶液去油污B.浓氨水有刺激性气味C.明矾、氯化铁常用于净水D.硫化钠浓溶液有臭味10.某研究性学习小组欲完成反应2HCl+2Cu=2CuCl+H2↑,设计了下列四个实验,你认为可行的是A B C D11.在水溶液中能大量共存的一组离子是()A.Al3+、Na+、OH-、SO42—B.H+、NH4+、CH3COO-、SO42—C.Na+、Ca2+、Cl-、CO32- D.K+、Ba2+、NO3—、Cl—12.X、Y两根金属棒插入Z溶液中构成下图的装置,实验中电流表指针发生偏转,同时X棒变粗,Y 棒变细,则X 、Y、Z可能是()选项X Y ZA Zn Cu稀硫酸B Cu Zn稀硫酸C Cu Ag 硫酸铜溶液D Ag Zn 硝酸银溶液13.T℃时,K sp[Cu(OH)2]= 2。

高二英语上学期第三次联考试题(含解析)

高二英语上学期第三次联考试题(含解析)

河南省平顶山市、许昌市、汝州2017—2018学年高二上学期第三次联考英语试题考生注意:1、本试卷共150分,共8页。

考试时间120分钟。

2、请将各题答案填涂在答题卡上、第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,您将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1、 5分,满分7。

5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,您都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is theshirt?A、£、B、£9、18、 C。

£。

答案是C。

1。

What doesthe woman mean?A。

She can’t type the letternow、B、She plans to write aletter herself、C、She doesn't understand the man's request、2。

What did the woman do whileshe was inBrighton?A。

Shestayed in a hotel。

B。

She lived near a campus、C、 She camped outside。

3、Where does the conversation probablytake place?A、In a supermarket、B。

In akitchen-C、 In a library,4。

What can we learnfrom the conversation?A、The professor has changed his readingtask、B、 Some students at the back can't hear the professor、C、Some of the students are not on the professor'sclass lis t、5、Who is the woman?A, A college student、 B、 A high school student、 C。

高二上学期第三次联考英语试题

高二上学期第三次联考英语试题

河南省平顶山市、许昌市、汝州2020-2021学年高二上学期第三次联考英语试题学校:___________姓名:___________班级:___________考号:___________一、阅读选择Mini Book Excerpts (节选)BiographyWhen Salinger learned that a car park was to be built on the land, the middle-aged writer was shocked and quickly bought the neighboring area to protect it.... The townspeople never forgot the rescue and came to help their famous neighbor.J. D.Salinger:A Life by Kenneth Slawenski(Random House,$27)Mystery“You’re a smart boy.Benny’s death was no accident, and you’re the only who saw it happen. Do you think the murderer should get away with it ? ”The boy was starting stubbornly at his lap again.A thought suddenly occurred to Annika ,“Did you …You recognized the man in the car , didn’t you?”The boy hesitated, twi sting his fingers ,“Maybe ,”he said quietly.Red Wolf by Liza Marklund(Atria Books, $25. 99)Short StoriesShe wants to say to him what she has learned , none of it in class. Some women are born stupid, and some women are too smart for their own good. Some women are born to give, and some women only know how to take. Some women learn who they want to be from their mothers, some who they don’t want to be. Some mothers suffer so their daughterswon’t.Some mothers love so their daughters won’t.You Are Free by Danzy Senna (Riverhead Books,$15)HumorDo your kids like to have fun? Come to Fun Times! Do you like to watch your kids having fun? Bring them to Fun Times! Fun Times! ’s “amusement cycling” is the most fun you can have in the United States right now. Why spend thousands of dollars flying to Disney World when you can spend less than half to that within a day’s drive lf most cities?Happy And Other Bad Thoughts by Larry Doyle(Ecco,$14. 99)1.What did Salinger do for his town?A.He built a car park. B.He tried to protect its land.C.He wrote some good novels. D.He rescued many townspeople. 2.The book You Are Free is mainly about .A.smart children B.happy daughtersC.different women D.suffering mothers3.Which book should readers choose, if they want to know something about Fun Times? A.Red Wolf.B.You Are Free.C.J. D.Salinger: A Life.D.Happy And Other Bad Thoughts.Joy Mangano was 33 and divorced. She had three kids under age 7, and was barely keeping up payments on her small two-bedroom home by working extra hours as a waitress. “There were times when I would lie in bed and think, I don’t know how I’m going to pay that bill,” Mangano says.But he had a special ability for seeing the obvious thing. She knew how hard it was to mop the floor. “I was tired of bending down, putting my hands in dirty water, wringing (拧) out a mop,” Mangano says. “So, There s gotta be a better way.How about a “self-wringing” mop? She designed a special tool you could twist in two directions at once, and still keep your hands clean and dry. She set out to sell it, first a few at flea markers.Then Mangano met with the media. But would couch potatoes (电视迷)buy a mop? The experts on shopping TV were less than certain. They gave it a try, and it failed. Mangano was sure it would sell if they’d let her do the on-camera display. She said, “Get me on that stage, and I will sell this mop because it’s a great item.”So QVC, a multinational corporation specializing in televised home shopping, took a chance on her. “ I got onstage and the phones went crazy. We sold every mop in minutes.”Today she’s president of Ingenious Designs, a multimillion-dollar company, and one of the stars of HSN, the Home Shopping Network. Talking about the household invention, Mangano says, “It is as natural for me as it is for a parent to talk about their child.”4.What is the first paragraph mainly about?A.Mangano’s small home.B.Mangano’s work experience.C.Mangano’s unhappy marriage.D.Mangano’s hard living conditions.5.Mangano sold the mop successfully with the help of .A.HSN B.QVCC.couch potatoes D.experts on shopping TV6.What does Mangano think of her invention?A.Special. B.Normal.C.Dissatisfied D.Unbelievable.7.What can we learn from the text?A.HSN is a business organization that sells goods on the Internet.B.The experts on shopping TV were confident about Mangano's mop.C.Mangano got the idea of self-wringing mop from her own experience.D.Mangano once had to work seven days a week to support her family.A device that stops drivers from falling asleep at the wheel is about to undergo testing at Department of Transport laboratories and could go on sale within 12 months.The system, called Driver Alert, aims to reduce deadly road accidents by 20% — 40% that are caused by tiredness. Airline pilots can also use it to reduce the 30% of all pilot-error accidents that are related to fatigue.Driver Alert is based on a computerized wristband (腕带).The device, worn by drivers or pilots gives out a sound about every four minutes during a car journey. After each sound the driver must respond by squeezing the steering wheel (方向盘). A sensor in the wristband detects this pressing action and measures the time between the sound and the driver’s response ‘Tiredness is directly related to a dri ver’s response time. Usually, a watchful driver would use about 400 milliseconds to respond, but once that falls to more than 500 milliseconds, it suggests that the driver is getting sleepy.In such cases the device gives out more regular and louder sounds, showing that the driver should open a window or stop for a rest. If the driver's response continues to slow down, the sounds become more frequent until a nonstop alarm warns that the driver must stop as soon aspossible.The device has been delivered to the department’s laboratories for testing. If these tests, scheduled for six months’ time, are successful, the makers will bring the product to market within about a year.8.Driver Alert is a device that can .A.keep drivers asleep.B.change drivers’ response accuracy.C.reduce the possibility of accidents.D.protect drivers when accidents happen9.What does the underlined word “fatigue” in Paragraph 2 mean?A.Illness. B.Tiredness.C.Carelessness, D.Impoliteness,10.How does Driver Alert work?A.By being used as a nonstop alarm all the time.B.By squeezing the steering wheel on the way.C.By reminding or warning drivers if necessary.D.By being worn on drivers* hands every moment.11.What do we know about Driver Alert?A.It must be fixed on the driver’s cars.B.It aims to prevent drivers from sleeping.C.It has gone through testing at laboratories.D.It isn't available to drivers at the moment.Conventional wisdom says that hardship can make us old before our time. In fact, a new study suggests that violence not only leaves long-term scars on children’s bodies, but also changes their DNA, causing changes that are equal to seven to ten years of premature aging.Scientists measured this by studying the ends of children’s chromosomes (染色体), called telomeres(端粒), says Idan Shalev, lead author of a study published in Molecular Psychiatry.Telomeres are special DNA sequences (序列)which prevent the DNA in chromosomes from separating. They get shorter each time a cell divides, until a cell cannot divide any more and dies.Several factors have been found to shorten telomeres, including smoking, radiation and psychological stresses such as being treated badly when young and taking care of a chronically ill person.In this study, researchers examined wheth er exposure to violence could make children’s telomeres shorten faster than normal. They interviewed the mothers of 236 children 3t ages 5, 7 and 10, asking whether the youngsters had been exposed to domestic violence between the mother and her partner; physical maltreatment by an adult; or bullying. Researchers measured the children's telomeres —in cells obtained by wiping the insides of their cheeks一at ages 5 and 10.Telomeres shortened faster in kids exposed to two or more types of violence, says Shalev. Unless that pattern changes, the study suggests, these kids could be expected to develop diseases of aging, such as heart attacks or memory loss, seven to 10 years earlier than their peers.Shlev says there is hope for these kids. His study found that, in rare cases, telomeres Better nutrition, exercise and stress reduction are three things that may be able to lengthen telomeres, he says.The study confirms a small but growing number of studies suggesting that early childhood adversity imprints itself in our chromosomes, says Charles Nelson, a professor of pediatrics and neuroscience at Harvard Medical School.12.The new study found that .A.hardship can change a child's memoryB.violence can speed up a child's agingC.violence leaves scars on a child s mindD.hardship has an effect on a child’s mind13.What does the underlined word “they” in Paragraph 3 refer to?A.Telomeres. B.Children.C.Chromosomes. D.DNA sequences.14.What can be inferred from the text?A.Violence can cause quick cell death in children’s body.B.Telomeres can help prevent chromosomes from separating.C.Children who have shorter telomeres have heart attacks later.D.Being treated badly will make a child’s telomeres shorten faster.15.What is the best title for the text?A.Violence and TelomeresB.The Function of TelomeresC.Violence Makes Children AgingD.DNA Influences Children’s Growth二、七选五Every boy and every girl expects their parents to give them more pocket money. 16.One main purpose is to let kids learn how to manage their own money. The amount of money that parents give to their children to spend as they wish differs from family to family. Timing is another consideration. Some children get weekly pocket money. 17.First of all, children are expected to make a choice between spending and saving. Then parents should make the children understand what is expected to pay for with the money. At first, some young children may spend all of the money soon after they receive it. 18.By doing so, these children will learn that spending must be done with a budget.In order to encourage their children to do some housework, some parents give pocket money if the children help around the home. 19.They believe helping at home is a norm part of family life.Pocket money can give children a chance to experience the three things they can do with the money. 20.They can spend it by buying things they want. They can save it for future use. Saving helps children understand that costly goals require sacrifice. Saving can also open the door to future saving and investing for children.A.Others get monthly pocket money.B.They can spend it by giving it to a good cause.C.Why do their parents just give them a certain amount?D.Some children are not good at managing their pocket money.E.Learning how to get money is very important for every child.F.Some experts think it not wise to pay the children for doing that.G.Parents are usually advised not to offer more money until the right time.三、完形填空Last month, I visited one of my old neighborhoods in New York. I had not been there fortwenty years and as I walked along the street, my mind was 21 by memories of the past.I saw the old 22 building where I had lived and the playground where I had played. As I viewed these once 23 surroundings, images of myself as a child there 24 . However, what I saw and what I remembered were not the same. I 25 realized that the best memories were those kept 26 .My old apartment building, as I remember, was bright and alive. It was more than just a place to live. It was a movie house, a space station, or whatever my young mind could27 . I would steal away with my friends and play in the 28 . This was always exciting because it was so cool and dark, and there were so many things there to 29 among. There was a small river in the back of the building, We would go there to lie in the shade of trees and enjoy ourselves.However, what I saw was 30 different. The apartment building was now in bad 31 . What was once more than a place to live in looked hardly worth 32 in. The windows were all 33 . The once clean walls were covered with dirty 34 . The river was hardly recognizable. The water was polluted and the trees and flowers were all35 . The once sweet-smelling river now smelled 36 . It was really heartbreaking to37 all this.I do not 38 having seen my old neighborhood. However, I do not think my 39 childhood memories can ever be the same. I suppose it is 40 when they say, “You can never go home again.”21.A.prevented B.pushed C.flooded D.produced22.A.store B.office C.experiment D.apartment23.A.strange B.familiar C.similar D.complex24.A.burst into tears B.came to mind C.came into effect D.came to light 25.A.sadly B.curiously C.luckily D.generally26.A.unharmed B.untouched C.uncompleted D.unmoved 27.A.imagine B.write C.save D.introduce28.A.classroom B.park C.basement D.library29.A.hide B.climb C.sit D.live30.A.hardly B.mostly C.regularly D.completely31.A.effect B.temper C.behavior D.condition32.A.playing B.living C.studying D.travelling33.A.old B.messy C.broken D.ugly34.A.marks B.names C.notes D.pictures35.A.green B.fresh C.dead D.rare36.A.funny B.tasty C.unusual D.terrible37.A.see B.say C.remember D.collect38.A.consider B.enjoy C.permit D.regret39.A.dark B.remote C.beautiful D.short40.A.fake B.true C.attractive D.interesting四、用单词的适当形式完成短文A rainforest is an area 41.(cover) by tall trees with the total high rainfall spreading quite equally through the year. Rainforests have a great effect on the world environment because they can take in heat from the sun and adjust the climate.42.the forest cover, these areas would reflect more heat into the atmosphere,43.(warm) the rest of the world. Losing the rainforests may also influence wind and rainfall patterns, potentially causing certain natural disasters all over the world.In the past hundred years, humans 44.(begin) destroying rainforests in search of three major resources: land for crops, wood for paper and other products, land for raising farm 45.(animal). This action affects the environment as a whole. For example, a lot of carbon dioxide in the air comes from burning the rainforests. People 46.(obvious) have a need for the resources we gain from cutting trees,47.we will suffer much more than we will benefit.Rainforests are often called the world’s drug store. More than 25% of the medicines we use today come from plants in rainforests. However, fewer than 1% of rainforest plants have been examined for their 48.(medicine) value. It is extremely likely 49.our best chance to cure diseases 50.(lie) somewhere in the world’s shrinking rainforests.五、短文改错51.假定英语课上老师要求同桌之间交换修改作文,请你修改你同桌写的以下作文。

河南省平顶山市、许昌市、汝州2017_2018学年高二英语上学期第三次联考试题(含解析)

河南省平顶山市、许昌市、汝州2017_2018学年高二英语上学期第三次联考试题(含解析)

河南省平顶山市、许昌市、汝州2017-2018学年高二上学期第三次联考英语试题考生注意:1.本试卷共150分,共8页。

考试时间120分钟。

2.请将各题答案填涂在答题卡上。

第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1. 5分,满分7. 5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt?A.£19.15.B. £9. 18.C. £9.15.答案是C。

1. What does the woman mean?A. She can't type the letter now.B. She plans to write a letter herself.C. She doesn’t understand the man’s request.2. What did the woman do while she was in Brighton?A. She stayed in a hotel.B. She lived near a campus.C. She camped outside.3. Where does the conversation probably take place?A. In a supermarket.B. In a kitchen-C. In a library,4. What can we learn from the conversation?A. The professor has changed his reading task.B. Some students at the back can’t hear the professor.C. Some of the students are not on the professor's class list.5. Who is the woman?A, A college student. B. A high school student. C. A college teacher.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或对白,每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置,听每段对话或独白前,你将有时间阅读各个小题。

河南省平顶山市、许昌市、汝州2020┄2021学年高二上学期第三次联考英语试题

河南省平顶山市、许昌市、汝州2020┄2021学年高二上学期第三次联考英语试题

考生注意:1.本试卷共150分,共8页。

考试时间120分钟。

2.请将各题答案填涂在答题卡上。

第一部分听力(共两节,满分30分)做题时,先将答案标在试卷上。

录音内容结束后,你将有两分钟的时间将试卷上的答案转涂到答题卡上。

第一节(共5小题;每小题1. 5分,满分7. 5分)听下面5段对话。

每段对话后有一个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置。

听完每段对话后,你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

例:How much is the shirt?A.£19.15.B. £9. 18.C. £9.15.答案是C。

1. What does the woman mean?A. She can't type the letter now.B. She plans to write a letter herself.C. She doesn’t understand the man’s request.2. What did the woman do while she was in Brighton?A. She stayed in a hotel.B. She lived near a campus.C. She camped outside.3. Where does the conversation probably take place?A. In a supermarket.B. In a kitchen-C. In a library,4. What can we learn from the conversation?A. The professor has changed his reading task.B. Some students at the back can’t hear the professor.C. Some of the students are not on the professor's class list.5. Who is the woman?A, A college student. B. A high school student. C. A college teacher.第二节(共15小题;每小题1.5分,满分22.5分)听下面5段对话或对白,每段对话或独白后有几个小题,从题中所给的A、B、C三个选项中选出最佳选项,并标在试卷的相应位置,听每段对话或独白前,你将有时间阅读各个小题。

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一、选择题:本题共12小题,每小题4分,在每小题给出的四个选项中,第1~8题只有一项符合题目要求,第9~12题有多项符合题目要求。

全部选对得4分,选对但不全得2分,有选错的得0分
1.1820年4月,在一次讲课中,某位物理学家偶然地把导线沿南北方向放置在一个带玻璃罩的指南针的上方,通电时磁针转动了,随后,这位物理学家连续进行了大量研究,并与同年7月宣布发现了电流的磁效应,这位物理学家是
A .安培
B .奥斯特
C .伏特
D .密立根 2.下列说法正确的是 A .电荷的定向移动形成电流 B .电流的单位是伏特 C .电流有方向,是矢量 D .根据U
R I
可知,R 与I 成反比 3.关于磁感线,下列说法正确的是 A .磁感线是磁场中实际存在的曲线 B .两磁感线间的空隙处不存在磁场 C .磁感线都是从磁体的N 极指向S 极
D .在有磁场分别的空间内,任何一点只能画出一条磁感线
4.如图所示,直线A 、B 分别为某电源的路端电压与通过它的电流的关系图线和某电阻两端的电压与通过它的电流的关系的图线,用该电源和该电阻组成闭合电路时,电路中通过的电流为
A .1A
B .1.5A
C .2A
D .2.5A
5.如图所示,在某光滑水平面上固定两个异种点电荷12Q Q 、,它们的连线上有一点A ,将一带负电的点电荷放置在A 点时恰好受力平衡,若将某一带正电的点电荷放在A 点从静止释放,该点电荷将
A.静止不动 B.向左运动 C.向右运动 D.先向左运动后向右运动
6.两根材料相同的粗细均匀导线甲和乙,其横截面积之比为1:3,阻值之比为3:2,则导线甲、乙的长度之比为
A.1:3 B.1:2 C.2:3 D.3:1
7.一绝缘的轻质弹簧的两端系有质量相等的小球A、B,两小球带有等量异种电荷,且带电荷量均为q(可视为点电荷),A、B两小球放置在光滑的绝缘的水平面上,静止时,两小球之间距离是弹簧原长的0.8倍,若改变两小球所带电荷量,使两小球之间距离是弹簧原长的0.4倍后仍处于静止状态,则此时两小球的电荷量q1、q2与q的关系应满足
A.12
21
q q q = B.12
2
2
q q
q
= C.12
2
1
2
q q
q
= D.12
2
3
4
q q
q
=
8.图示为一已进行欧姆调零的欧姆表,用该欧姆表测一电阻R的阻值时,指针偏转至满
刻度的2
3
处,现用该欧姆表测一未知电阻的阻值,指针偏转到满刻度的
1
3
处,可知该电阻
的阻值为
A.2R B.3R C.4R D.5R
9.关于电势差,下列说法正确的是
A.电势差与电势零点的选取有关
B.电势差是标量,但有正负之分
C.电场中某两点间的电势差可能为零
D.若A、B两点间的电势差为正值,则将正电荷从A点移到B点静电力做正功10.下列单位中,属于磁通量的单位的是
A .Wb
B .1N A m -⋅⋅
C 2T m -⋅
D 1
N m A -⋅⋅
11.在图示电路中,E 为电源电动势,r 为电源内阻,1R 是半导体制成的NTC 热敏电阻,其阻值随温度的升高而减小,23R R 、为定值电阻,C 为电容器,L 为小灯泡,当所处环境温度下降时,下列判断正确的是
A .电流表的示数增大
B .R 2两端的电压减小
C .电容器C 所带的电荷量增大
D .小灯泡变暗
12.如图所示,在粗糙绝缘的水平面上固定一负点电荷Q ,在M 点无初速度释放一带有恒定电荷量的小物块,小物块在Q 的电场中运动到N 点静止,则从M 点运动到N 点的过程中
A .小物块所受到的摩擦力逐渐变小
B .M 点的电势一定低于N 点的电势
C .小物块具有的电势能逐渐增大
D .小物块电势能变化量的大小一定等于克服摩擦力做的功 二、非选择题
13.某同学设计的可调电源电路如图所示,0R 为保护电阻,P 为滑动变阻器的滑片,闭合开关S 。

(1)在接通外电路之前,为了保证外电路的安全,滑片P 应先置于______(选填“A 端”或“B 端”);
(2)若电源电路中不接入0R ,则在使用过程中,存在______(选填“断路”或“短路”)的风险。

14.某物理兴趣小组要将一个内阻未知的电流表改装成量程为3V 的电压表,为此他们用图示电路测定该电流表的内阻,实验室可提供的器材如下:
A .电流表G :满偏电流为300μA ,内阻未知
B .干电池E :电动势为3V ,内阻未知
C .滑动变阻器1R :最大阻值约为5k Ω,额定电流为1A
D .滑动变阻器2R :最大阻值约为16k Ω,额定电流为0.5A
E .电阻箱0R :0~9999.9Ω
F .开关两个,导线若干
(1)滑动变阻器R 应选用______(填“C ”或“D ”),将开关12S S 、都断开,连接好实物图,使滑动变阻器接入电路的电阻达到最大后,闭合开关1S ,移动滑动变阻器的滑片,使电流表G 的示数为200μA 。

(2)闭合开关2S ,调节电阻箱0R 的阻值为100Ω时电流表G 的示数为100μA ,则电流表G 的内阻r=______Ω。

(3)为将该电流表改装成量程为3V 的电压表,需串联电阻的阻值为________Ω。

15.在某匀强磁场中,长L=8cm 的通电导线垂直该磁场方向放置,当通过导线的电流,
10.1A I =时,它受到的磁场力大小31210F N -=⨯。

(1)求该处的磁感应强度大小1B ;
(2)若通电直导线的长度不变,通过导线的电流增大为20.5A I =,垂直放在该磁场的另一处,求此时该处的磁感应强度大小2B 和通电直导线受到的磁场力的大小2F 。

16.图示电路中,电源的电动势E=110V ,电阻121R =Ω,电动机的内阻00.5R =Ω,开关1S 始终闭合,当开关2S 断开时,电阻1R 消耗的电功率1525W P =;当开关2S 闭合时,电阻1R 消耗的电功率2336W P =,求:
(1)电源的内阻r ;
(2)当开关2S 闭合时,电动机输出的机械功率P 出
17、在示波管中,电子通过电子枪加速,进入偏转电场,然后射到荧光屏上,如图所示,质量为m ,电荷量为e 的电子从静止开始经过电压为1U 的加速电场加速,然后进入偏转电场,偏转电场中两极板间的距离为d ,板长为L ,电子射到荧光屏上的动能为k E ,电子重力不计,求
(1)电子进入偏转电场的速度大小0v ; (2)偏转电场的电压2U 。

参考答案
1B 2A 3D 4C 5A 6B 7D 8C 9BCD 10AD 11BC 12BD 13、(1)A (2)短路 14、(1)D (2)100(3)9900 15、(1)由磁感应强度的定义有1
110.25F B T I L
=
= (2)磁感应强度由磁场本身的决定,与通电直导线的长度以及导线中通过的电流无关,有:210.25B B T ==
当导线中通过的电流增大为20.5A I =时,由磁感应强度的定义式2
22F B I L
=
有:222F B I L =
解得2
2110F N -=⨯
16、(1)当开关2S 断开时,电动机被断路,此时电路中通过的电流为E
I R r
=
+ 由焦耳定律有211P I R =,解得r=1Ω
(2)当开关2S 闭合时,设1R 两端的电压为U
,有U =
设此时电源中通过的电流为'I ,由闭合电路的欧姆定律有:'E I r U =+ 流过1R 的电流为1I ,流过电动机的电流为2I ,有:11
U
I R =
,又12'I I I += 电动机的输出功率为2
220P UI I R =-出,解得1606W P =出
17、(1)电子在加速电场中加速时,根据动能定理可得2
0112
eU mv =
,解得0v =
(2)电子进入偏转电场后,有0L v t =,y v at =,2
eU a md
=
电子射出偏转电场时的合速度大小为v =
电子射出偏转电场后匀速到达荧光屏,有212
k E mv =
解得
2U =。

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