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2014年中考物理总复习讲学稿2

2014年中考物理总复习讲学稿2

2014年中考物理总复习讲学稿2第二章 物态变化【复习目标】1. 能区别固、液和气三种物态,能描述这三种物态的基本特征。

2. 能说出生活环境中常见的温度值,了解液体温度计的工作原理;会测量温度,尝试对环境温度问题发表自己的见解。

3. 通过实验探究物态变化过程,能用熔点或沸点的知识解释自然现象。

4. 能用水的三态变化解释自然界中的一些水循环现象;有节约用水的意识,了解水资源与人类生存和社会发展的关系。

【知识梳理】1.物质的三种状态:__________、 __________、 __________。

2.在下列空中填写适当的物态变化名称,并标明吸热或放热3.摄氏度规定:它以通常情况下 的温度作为0度,以____________的温度为作100度。

4.常用的液体温度计是利用测温液体的 性质工作的。

普通实验室温度计的分度值为_______;体温计的分度值为_________,量程为 。

-12℃读作________________。

5. 如图1所示温度计读数:甲________ 乙__________ 6.液体汽化的两种方式是________和_______。

7.影响蒸发快慢的因素有 、 、。

8.理发师在洗头后常用电吹风将头发吹干,头发比自然情况下干的快的原因是(1)___________,(2)___________。

9.影响水沸腾的因素有 、 。

10.制糖工业中,为了防止糖汁烧焦变质,应用_____________的方法________沸点(升高/降低)。

11.液体沸腾必须同时满足下列两个条件① ,② 。

12.使气体液化的二种方法: 、 。

13.夏天,剥开冰棍包装纸,看到冰棍冒“白气”,这里的“白气”是如何形成的? ;冬天人也呼出白气,这又是如何形成的?____________________________________________。

14.秋天早晨,小草上的露珠是由________方法使水蒸气液化形成的;气体打火机里的丁烷是用________方法使其成为液态的。

2014年高考英语一轮总复习语法专题复习_1.名词课件

2014年高考英语一轮总复习语法专题复习_1.名词课件

4.表示地点的名词作定语,说明被修饰的名词存在或发 生的地方。如:America's culture 美国文化。 5.表示性别或身份的名词作定语。如:a female elephant 一头母象。 6.表示泛指的时间名词作定语。如:evening dress 晚礼 服; rooster year stamp 鸡年邮票。但表示具体的时间名词作 定语,则要用所有格形式来表达。如:yesterday's news 昨天的 消息;an hour's drive 一小时的车程。
【答案】 B。前面“the+姓氏的复数”指一家人或夫妇 选 两个;后面表示“一个姓„„的人”,为泛指概念,因此姓氏 的前面加不定冠词 a。
3.名词在特殊情况下的复数使用 有些名词在使用时总是用其复数形式, thanks, clothes, 如: congratulations,goods,works,shoes,trousers 等。有些短语 也要求用名词复数形式: make preparations for 为„„作准备 take pains to do sth. 努力做某事 make both ends meet 收支平衡 keep ties with 同„„保持联系 be in high spirits 兴致勃勃;情绪很高 do/make repairs 进行修理
三 、名词所有格 (一)名词所有格由“名词+'s”构成,“'s”所有格常适用于 以下各词: today's newspaper, five weeks' 1 表示时间的名词 holiday the earth's atmosphere, the 2 表示自然现象的名词 tree's branches 表示国家城市等地方 the country's plan, the world's 3 population, China's industry 的名词 the ship's crew, majority's view, 4 表示工作群体的名词 the team's victory

【高考领航】2014高考数学总复习 8-4 直线与圆、圆与圆的位置关系练习 苏教版

【高考领航】2014高考数学总复习 8-4 直线与圆、圆与圆的位置关系练习 苏教版

【高考领航】2014高考数学总复习 8-4 直线与圆、圆与圆的位置关系练习 苏教版【A 组】一、填空题1.若直线l :ax +by =1与圆C :x 2+y 2=1有两个不同交点,则点P (a ,b )与圆C 的位置关系是________.解析:由题意得圆心(0,0)到直线ax +by =1的距离小于1,即d =1a 2+b 2<1,所以有a 2+b 2>1,∴点P 在圆外.答案:在圆外2.(2011·高考某某卷)设圆C 与圆x 2+(y -3)2=1外切,与直线y =0相切,则C 的圆心轨迹为________.解析:设圆心C (x ,y ),由题意得x -02+y -32=y +1(y >0),化简得x 2=8y -8.答案:x 2=8y -83.(2011·高考某某卷)在圆x 2+y 2-2x -6y =0内,过点E (0,1)的最长弦和最短弦分别为AC和BD ,则四边形ABCD 的面积为________.解析:由题意可知,圆的圆心坐标是(1,3)、半径是10,且点E (0,1)位于该圆内,故过点E (0,1)的最短弦长|BD |=210-12+22=25(注:过圆内一定点的最短弦是以该点为中点的弦),过点E (0,1)的最长弦长等于该圆的直径,即|AC |=210,且AC ⊥BD ,因此四边形ABCD 的面积等于12|AC |×|BD |=12×210×25=10 2.答案:10 24.(2011·高考某某卷)若曲线C 1:x 2+y 2-2x =0与曲线C 2:y (y -mx -m )=0有四个不同的交点,则实数m 的取值X 围是________.解析:整理曲线C 1方程得,(x -1)2+y 2=1,知曲线C 1为以点C 1(1,0)为圆心,以1为半径的圆;曲线C 2则表示两条直线,即x 轴与直线l :y =m (x +1),显然x 轴与圆C 1有两个交点,知直线l 与x 轴相交,故有圆心C 1到直线l 的距离d =|m1+1-0|m 2+1<r =1,解得m ∈⎝ ⎛⎭⎪⎫-33,33,又当m =0时,直线l 与x 轴重合,此时只有两个交点,应舍去. 答案:(-33,0)∪(0,33) 5.(2012·高考某某卷)过点P (1,1)的直线,将圆形区域{(x ,y )|x 2+y 2≤4}分为两部分,使得这两部分的面积之差最大,则该直线的方程为________.解析:设过P 点的直线为l ,当OP ⊥l 时,过P 点的弦最短,所对的劣弧最短,此时,得到的两部分面积之差最大.易求得直线的方程为x +y -2=0. 答案:x +y -2=06.已知圆C 过点(1,0),且圆心在x 轴的正半轴上,直线l :y =x -1被圆C 所截得的弦长为22,则过圆心且与直线l 垂直的方程为________.解析:设所求直线的方程为x +y +m =0,圆心(a,0),由题意知:(|a -1|2)2+2=(a -1)2,解得a =3或a =-1,又因为圆心在x 轴的正半轴上,∴a =3,故圆心坐标为(3,0),而直线x +y +m =0过圆心(3,0),∴3+0+m =0, 即m =-3,故所求直线的方程为x +y -3=0. 答案:x +y -3=07.(2012·高考某某卷)直线x +3y -2=0与圆x 2+y 2=4相交于A ,B 两点,则弦AB 的长度等于________.解析:如图所示:解Rt △ACO ,|OC |为圆心到直线x +3y -2=0的距离, |OC |=|0+3×0-2|12+32=1, |OA |=r =2,|AC |=|OA |2-|OC |2=22-12=3, |AB |=2|AC |=2 3 答案:2 3 二、解答题8.圆经过点A (2,-3)和B (-2,-5).(1)若圆的面积最小,求圆的方程;(2)若圆心在直线x -2y -3=0上,求圆的方程. 解:(1)要使圆的面积最小,则AB 为圆的直径, 圆心C (0,-4),半径r =12|AB |=5,所以所求圆的方程为:x 2+(y +4)2=5. (2)法一:因为k AB =12,AB 中点为(0,-4),所以AB 中垂线方程为y +4=-2x , 即2x +y +4=0,解方程组⎩⎪⎨⎪⎧2x +y +4=0,x -2y -3=0,得⎩⎪⎨⎪⎧x =-1,y =-2.所以圆心为(-1,-2).根据两点间的距离公式,得半径r =10, 因此,所求的圆的方程为(x +1)2+(y +2)2=10. 法二:设所求圆的方程为(x -a )2+(y -b )2=r 2, 根据已知条件得⎩⎪⎨⎪⎧2-a 2+-3-b 2=r 2-2-a 2+-5-b 2=r 2a -2b -3=0⇒⎩⎪⎨⎪⎧a =-1,b =-2,r 2=10.所以所求圆的方程为(x +1)2+(y +2)2=10.9.已知圆C 的方程为x 2+y 2=1,直线l 1过定点A (3,0),且与圆C 相切.(1)求直线l 1的方程;(2)设圆C 与x 轴交于P 、Q 两点,M 是圆C 上异于P 、Q 的任意一点,过点A 且与x 轴垂直的直线为l 2,直线PM 交直线l 2于点P ′,直线QM 交直线l 2于点O ′.求证:以P ′Q ′为直径的圆C ′总过定点,并求出定点坐标.解:(1)∵直线l 1过点A (3,0),且与圆C :x 2+y 2=1相切,设直线l 1的方程为y =k (x -3),即kx -y -3k =0,则圆心O (0,0)到直线l 1的距离为d =|3k |k 2+1=1,解得k =±24,∴直线l 1的方程为y=±24(x -3). (2)证明:对于圆C 的方程x 2+y 2=1,令y =0,则x =±1,即P (-1,0),Q (1,0).又直线l 2过点A 且与x 轴垂直,∴直线l 2方程为x =3.设M (s ,t ),则直线PM 的方程为y=ts +1(x +1).解方程组⎩⎪⎨⎪⎧x =3,y =ts +1x +1得P ′(3,4ts +1). 同理可得Q ′(3,2ts -1). ∴以P ′Q ′为直径的圆C ′的方程为(x -3)(x -3)=(y -4t s +1)(y -2t s -1)=0, 又s 2+t 2=1,∴整理得(x 2+y 2-6x +1)+6s -2ty =0,若圆C ′经过定点,只需令y =0,从而有x 2-6x +1=0,解得x =3±22, ∴圆C ′总经过定点,定点坐标为(3±22,0).【B 组】一、填空题1.若圆x 2+y 2=4与圆x 2+y 2+2ay -6=0(a >0)的公共弦长为23,则a =________.解析:方程x 2+y 2+2ay -6=0与x 2+y 2=4. 相减得2ay =2,则y =1a.由已知条件22-32=1a,即a =1.答案:12.(2013·某某十校联考)已知圆C 的半径为1,圆心在第一象限,且与y 轴相切,与x 轴相交于点A 、B ,若AB =3,则该圆的标准方程是________.解析:根据AB =3,可得圆心到x 轴的距离为12,故圆心坐标为⎝ ⎛⎭⎪⎫1,12,故所求圆的标准方程为(x -1)2+⎝ ⎛⎭⎪⎫y -122=1.答案:(x -1)2+⎝ ⎛⎭⎪⎫y -122=13.在平面直角坐标系xOy 中,已知圆x 2+y 2=4上有且只有四个点到直线12x -5y +c =0的距离为1,则实数c 的取值X 围是________.解析:由题设得,若圆上有四个点到直线的距离为1,则需圆心(0,0)到直线的距离d 满足0≤d <1.∵d =|c |122+52=|c |13,∴0≤|c |<13,即c ∈(-13,13). 答案:(-13,13)4.直线l 与圆x 2+y 2+2x -4y +a =0(a <3)相交于A ,B 两点,若弦AB 的中点C 为(-2,3),则直线l 的方程为________.解析:圆的方程可化为(x +1)2+(y -2)2=5-a .由圆的几何性质可知圆心(-1,2)与点C (-2,3)的连线必垂直于l ,∴k AB =--1+22-3=1,∴l 的方程为x -y +5=0. 答案:x -y +5=05.(2013·某某模拟)从圆x 2-2x +y 2-2y +1=0外一点P (3,2)向这个圆作两条切线,则两切线夹角的余弦值为________.解析:圆的方程整理为(x -1)2+(y -1)2=1,C (1,1), ∴sin ∠APC =15,则cos ∠APB =cos2∠APC=1-2×⎝ ⎛⎭⎪⎫152=35. 答案:356.直线2x -y +m =0与圆x 2+y 2=5交于A 、B 两点,O 为坐标原点,若OA ⊥OB ,则m 的值为________.解析:当OA ⊥OB 时,圆心(0,0)到直线2x -y +m =0的距离等于22r , ∴|m |5=22· 5. ∴m =±5210.答案:±51027.由直线y =x +1上的一点向圆(x -3)2+y 2=1引切线,则切线长的最小值为________.解析:如图所示,设直线上一点P ,切点为Q , 圆心为M ,则|PQ |即为切线长,MQ 为圆M 的 半径,长度为1,|PQ |=|PM |2-|MQ |2=|PM |2-1,要使|PQ |最小,即求|PM |的最小值,此题转化为求直线y =x +1上的点到圆心M 的最小距离,设圆心到直线y =x +1的距离为d ,则d =|3-0+1|12+-12=22,∴|PM |的最小值为22, ∴|PQ |=|PM |2-1≥222-1=7.答案:7 二、解答题8.(2013·某某模拟)已知圆C :(x +1)2+y 2=4和圆外一点A (1,23),(1)若直线m 经过原点O ,且圆C 上恰有三个点到直线m 的距离为1,求直线m 的方程; (2)若经过A 的直线l 与圆C 相切,切点分别为D ,E ,求切线l 的方程及D 、E 两切点所在的直线方程.解:(1)方法一:圆C 的圆心为(-1,0),半径r =2, 圆C 上恰有三个点到直线m 的距离为1, 则圆心到直线m 的距离恰为1,由于直线m 经过原点,圆心到直线m 的距离最大值为1.所以满足条件的直线就是经过原点且垂直于OC 的直线,即y 轴,所以直线方程为x =0.方法二:圆C 的圆心为(-1,0),半径r =2,圆C 上恰有三个点到直线m 的距离为1. 则圆心到直线m 的距离恰为1.设直线方程为y =kx ,d =|-k -0|1+k 2=1,k 无解. 直线斜率不存在时,直线方程为x =0显然成立. 所以所求直线为x =0.(2)设直线方程为y -23=k (x -1),d =|-2k +23|1+k 2=2,解得k =33, 所求直线为y -23=33(x -1), 即3x -3y +53=0,斜率不存在时,直线方程为x =1,∴切线l 的方程为x =1或3x -3y +53=0,过点C 、D 、E 、A 有一外接圆,x 2+(y -3)2=4,即x 2+y 2-23y -1=0, 过切点的直线方程为x +3y -1=0.9.已知圆M :(x -1)2+(y -1)2=4,直线l :x -y -6=0,A 为直线l 上一点.(1)若AM ⊥直线l ,过A 作圆M 的两条切线,切点分别为P ,Q ,求∠PAQ 的大小;(2)若圆M 上存在两点B ,C ,使得∠BAC =60°,求点A 横坐标的取值X 围. 解:(1)圆M 的圆心M (1,1),半径r =2,直线l 的斜率为-1,而AM ⊥l ,∴k AM =1. ′∴直线AM 的方程为y =x .由⎩⎪⎨⎪⎧ y =x ,x +y -6=0解得⎩⎪⎨⎪⎧x =3,y =3,即A (3,3). 如图,连结MP , ∵∠PAM =12∠PAQ ,sin ∠PAM =PM AM=23-12+3-12=22, ∴∠PAM =45°,∴∠PAQ =90°.(2)过A (a ,b )作AD ,AE ,分别与圆M 相切于D ,E 两点,因为∠DAE ≥∠BAC ,所以要使圆M 上存在两点B ,C ,使得∠BAC =60°,只要做∠DAE ≥60°. ∵AM 平分∠DAE , ∴只要30°≤DAM <90°.类似于第(1)题,只要12≤sin∠DAM <1,即2a -12+b -12≥12且a -12+b -12≥12<1. 又a +b -6=0,解得1≤a ≤5, 即a 的取值X 围是[1,5].。

2014届高考数学总复习 第2讲 证明不等式的基本方法课件 理 新人教A版选修4-5

2014届高考数学总复习 第2讲 证明不等式的基本方法课件 理 新人教A版选修4-5
第2讲 证明不等式的基本方法
不同寻常的一本书,不可不读哟!
1.了解证明不等式的基本方法:比较法、综合法、分析 法、反证法、放缩法.
2. 会用柯西不等式证明一些简单的不等式以及求一些特定
函数的极值.
1种必会方法 综合法往往是分析法的相反过程,其表述简单、条理清 楚.当问题比较复杂时,通常把分析法和综合法结合起来使 用,以分析法寻找证明的思路,而用综合法叙述、表达整个证 明过程.
则3a2≥2b2,则3a2-2b2≥0.
又a-b≥0,∴(a-b)(3a2-2b2)≥0, 即3a3-2ab2-3a2b+2b3≥0, 则3a3+2b3≥3a2b+2ab2. 故原不等式成立.
证法二 (分析法) 要证3a3+2b3≥3a2b+2ab2, 只需证3a3+2b3-3a2b-2ab2≥0,
例2 已知a,b,c均为正数,证明:a2+b2+c2+
1 1 1 + + 2≥6 a b c
3,并确定a,b,c为何值时,等号成立.
[审题视点] 因为a,b,c均为正数,且a+b+c≥ 3 abc,故可利用三个正数的算术——几何平均不等式证明. 3
[证明]
2
因为a,b,c均为正数,
核心要点研究
例1 [2013· 广州模拟]已知a>0,b>0,求证:( b3≥ab+ ab2.
[审题视点]
a
)3+
本题主要考比较法证明.
[证明]
( a)3+b3-(ab+ ab2)
=[( a)3-ab]+[b3- ab2] =a( a-b)-b2( a-b) =( a-b)(a-b2) =( a-b)[( a)2-b2] =( a-b)2( a+b). 因为a>0,b>0,所以 a+b>0,又( a-b)2≥0, 所以( a -b)2( a +b)≥0,从而( a )3+b3-(ab+ a

2014届高考生物总复习 课时提升作业(七)第3章 第3节物质的跨膜运输 苏教版必修1

2014届高考生物总复习 课时提升作业(七)第3章 第3节物质的跨膜运输 苏教版必修1

(金榜题库)2014届高考生物总复习课时提升作业(七)第3章第3节物质的跨膜运输苏教版必修1(45分钟 100分)一、选择题(包括12小题,每小题5分,共60分)1.RNA聚合酶参与细胞核内DNA的转录,其进入方式是( )A.简单扩散B.易化扩散C.主动运输D.非跨膜运输2.在培养玉米的营养液中加入某种负离子,结果发现玉米根细胞在吸收该种负离子的同时,对氯离子的吸收减少了,但对钾离子的吸收没有受影响,最可能的原因是( )A.该种负离子妨碍了ATP的形成B.该种负离子抑制了主动运输C.该种负离子抑制了细胞呼吸D.该种负离子和氯离子的载体蛋白相同3.下图表示物质跨膜运输的一种方式。

据图分析正确的是( )A.这种运输方式可逆浓度梯度进行B.水分子是以这种方式进入细胞的C.细胞产生的能量增加会提高物质的运输速率D.载体蛋白在物质运输过程中形状会发生改变4.用酶解法除去新鲜紫色洋葱鳞片叶的外表皮细胞的细胞壁得到原生质体,将其置于0.3 g/mL的蔗糖溶液中,一段时间后,原生质体一定不发生( )A.质壁分离B.渗透失水C.颜色加深D.吸水力增大5.(2013·某某模拟)在植物细胞质壁分离复原过程中,能正确表达细胞吸水速率变化过程的是( )6.如图所示,把体积与质量浓度相同的葡萄糖溶液与蔗糖溶液用半透膜(允许溶剂和葡萄糖通过,不允许蔗糖通过)隔开,开始时和一段时间后液面情况是( )A.甲高于乙B.乙高于甲C.甲先高于乙,乙后高于甲D.乙先高于甲,甲后高于乙7.(2013·某某模拟)下图表示小肠绒毛上皮细胞中的细胞膜对不同物质的运输(每种运输的方向由箭头表明,黑点的数量代表每种物质的浓度),下列叙述正确的是( )A.a物质可能是氧气,b物质可能是葡萄糖B.a物质可能是水,b物质可能是甘油C.a物质可能是胆固醇,b物质可能是氧气D.a物质可能是葡萄糖,b物质可能是氨基酸8.(2013·某某联考)物质进出细胞的方式有跨膜运输(被动运输和主动运输)和非跨膜运输(内吞和外排)。

2014中考英语补全对话总复习

2014中考英语补全对话总复习

中考英语总复习补全对话复习题50套补全对话一A: 1 . ? B: They are talking about yesterday's football match.A: Oh, I watched it on TV. Beijing Team had very good teamwork. Didn't you watch it? B: 2 . . I did my homework and forgot the time. When I turned on the TV, it had finished already.A: 3 ! But Beijing Team will play again this evening.B: 4. ______________________________? A: Sure. You'd better finish your homework earlier if you want to watch it. Remember,"5.B: That's a good idea. (Looking at his watch.) Oh, I haven't much time left. I'd better hurry to finish my homework.补全对话二.A: 1. ? B: Not yet. Exercise 3 is too difficult for me. A: Don't worry. 2 ____________ . B: It's very kind of you. But I think I can do it myself. Can you lend me your English-Chinese dictionary?A: With pleasure. 3. ______________________..B: Thanks. 4. ________________, is Miss Gao at the teachers' office?A: Oh, no. She's out at the moment. B: 5._______________________? Do you know? I have some questions to ask her.A: I think she is at the library. She told me she wanted to borrow some books.B: I have to wait for her.补全对话三Dick: Excuse me, Lucy. Have you got a dictionary?Lucy: Sorry, I haven't. You may ask Meimei. 1___________________________.Dick: Excuse me, Meimei. Have you got a dictionary?Meimei: Yes. 2. __________________________.Dick: Thank you. I'll give it back soon. By the way, tomorrow is my birthday.3. ________________?Meimei: Yes, I'd love to. 4. ___________________?Dick: About seven o' clock..Meimei: I'll try to be there on time,but 5 _________________________.Dick: It doesn't matter. Work must come first.补全对话四(Sue=S Ken=K)S: Hello, Ken! Could you give me a lift?K: 1.____________________________, I don't have a car right nowS: Oh, that's too bad! I want to go to the Central Hospital.K: Why? 2______________________________?S: No, I'm all right. My English teacher is there. She is ill now and is to leave the hospital today.K: I see. 3. ____________________________?S: I've already got some flowers from my mother's garden.K: Well, well. 4. ___________________________.S: But, what a pity! I can't see Linda now. No car and no driver.K: Wrong. You have a good driver here.5. ___________________________. S: Really? That's great. It's very kind of you, Ken.K: It's my pleasure.补全对话五(Zhang=Z Mr.Smith=M)Z: Hello, are you Mr. Smith from the United States?M: Yes, Robert Smith. Please call me Robert. .1. __________________________.Z: My pleasure. Welcome to China. My name is Zhang Lin. You can call me Lin. This is my card.M: Thank you. And 2. ______________________.Z: Oh, good, thanks. How was the journey? M: 3 . _________________, although a little tiring.Z: Then let's get your things and go to the hotel now.M: Oh, thank you. 4. _______________________?Z: It's about thirty minutes' drive. By the way, we are going to have a dinner party for you this evening.M: It's very kind of you. 5. ___________________?Z: Six thirty. I'll pick you up at six o'clock. M: OK. See you then.Z: Bye.补全对话六Robert=R Jack=JJ: Hello, Robert. Are you free on Saturday morning?R: Yes. 1.___________________________? J: There is a basketball match at the Sports Center. Do you want to watch it?R: Sure. 2. _________________________? J: Our school Vs No. 1 Middle School.R: 3. __________________________! Let'sgo to cheer for our team.J: Yeah. No.1 Middle School Team is not easy to beat.R: So the match will be exciting. 4. ____________?J: 8:30. Do you think you can get up on time? R: Of course. 5. __________________________.J: OK. There will be three school buses waiting for us in front of the library. Let's meet there at 8:30.R: All right. See you then.补全对话七A: Morning! What can I do for you?B: We'd like to make a trip for a weekend holiday, please.A: There are many travel paths. 1. _____________?B: We'd like to choose Jinggang mountains. A: It's really worth visiting. 2. ________________?B: We're not sure. Which hotel do you think is comfortable?A: The Holiday Hone is very good. What's more important, 3. __________________________..B: We don't want to live in an expensive hotel. That's what we'll do.A: 4. _____________________________? B: OK. I'll ask my wife to fill in this form. By the way, Is it all right if we pay by credit card?A: 5. __________________. Enjoy your weekend.B: Thank you.补全对话八A: Hi, Bruce. Good news for you.B: 1. ____________________________? A: You won the first prize in the English competition.B: Wow! I'm so glad to hear that.2.____________?A: Our English teacher did. She said three of the students in our class won the prize.B: What about you?A: 3. _________________, too. I think I was luckythis time.B: So great! Congratulations!A: It's a great day for us today. Let's go out and relax ourselves, shall we?B: Good idea. But 4.________________________?A: To the park, OK?B: All right. But I have to go home and tell my mother first. See you later.A: 5. ___________________________.补全对话九A: Hello, Mary. 1. __________________________?B. Fine, thank you, Lucy.A: Mary, 2. ____________________________.B. It's so kind of you to say that.A: Where did you buy the skirt?B: 3. ____________________________? A: In Hangzhou? Well, Hangzhou is a very beautifulCity. 4. ________________________?B: Last month.A: Did you go there with your father?B. No, 5. _________________________. A: England?B: Yes, on business.补全对话十(Rob=R Mom=M)R: Hi, Mom. I'm home!M: 1._________________? It's almost 5:00. R: Sorry. I was at Sam's house.M: 2.____________________?R: Listening to music. Sam has a lot of great CDs. You should hear some of them.M: Maybe I'll do that sometime later.R: 3. ______________________?M: Now? I'm busy cooking.R: It doesn't matter. Sam let me borrow some of them. See?M: Sam let you borrow some of them?4. _________ __ . R: I only borrowed 15 CDs. Sam has more than 200.M: That's a lot of CDs. 5. ____________________.R: He does. He spends his mom's money, too.补全对话十一(Paul=P Jack=J)P: Hi, Jack!J: Hi!P: 1. _____________________?J: No, I missed it. By the time I got there, It had already finished.P: 2. _____________! It was a great football match.J: 3. _______________________?P: Wow. It was a big score. We beat them 5-3.J: Really? That's amazing! 4. _________________?P: Yeah. And I've never seen such an exciting match before! After 60 minutes, the American team was winning 3-2.J: Then what happened?P: 5. _______________________.J: Great.补全对话十二)A: What a fine day today! 1. _________________?B: That sounds like a good idea. 2.___________?A: Let's go to the little Hill.B: Shall we take the bus there?A: 3. ____________________. It's not very far.B: That will be OK. I'll ride my new bike my father bought me for my birthday last month.A:4____________________? B: Let's ask Mary and Jack to go with us. They planned to go last Sunday but it rained.A: Good! I'm sure they will be happy to.B: Have you got any idea what we are doing there?A: 5. ____________________.B: That will be fun.补全对话十三(Zhu Lei=Z Mei Ya=M)Z: Hello. Is Mei Ya in, please?M: 1. _____________________. Who is that? Z: This is Zhu Lei here. Have you watched the performance by Tai Lihua at CCTV Spring Festival Gala for 2005?M: 2. _______________________?Z: I haven't either. But it's said this is a very beautiful dance.M: 3. ___________________? Was it given by Tai Lihua only?Z: No, it was given by Tai Lihua and other 19 girls. And many people in the country were moved by it. M: Why were so many people moved? Was there something special about it?Z: Yes. These 20 girls are all deaf and mute ones. M: Oh, I understand. I hope I can have a chance to watch it.Z: Don't worry. Here comes the chance. Look, I've got two tickets for their performance in Wuhan Theatre tonight. 4. ____________________?M: Sure. How shall we get there?Z: 5. ___________________.?It is not far from here.M: OK, I'll wait for you at home at two. See you later.Z: See you.补全对话十四A: Hi, Ben! What are you doing these days?B: 1.____________________.A: Oh, what's wrong with her?B: 2. _________________. She had to see a doctor.The doctor said there was something wrong.A: I'm sorry to hear that. 3. __________________?B: A little better.A: 4. _____________________?B: No, thanks. I can do it all by myself. See you. A: 5. _____________________.补全对话十五Man: Come in and sit down, please. Woman: Thank you. Here's my personal information card.M: Nice to meet you, Mrs Morgan. 1. _______________?W: No, I haven't, but it's the kind of job I've always wanted to do.M: Really? 2. ______________________?W: Because I think it would give me a chance to develop the abilities I have learned in my job. M: 3. _______________________?W: I worked in a bookshop.M: 4. ________________________?W: Well, it was an interesting job, but I had a few arguments with my boss.M: 5. ________________________?W: He said he told me to type a letter for him and I didn't. I told him he didn't. He then got angry with me and said I was lying. But he just forgot it. M: Oh, I see. I will talk with the manager about it and inform you later.补全对话十六A: Excuse me, sir? Where is the nearest hotel? B: 1. ___________________. You may ask that policeman over there.A: Thank you all the same.(The man goes to the policeman.)A: Excuse me, 2._____________________? C: No, there isn't a hotel near here, but there is one near the Bank of China. A: 3. ____________________?C: It's about two kilometers away.A: 4. _____________________?C: You'd better take a taxi, because it's so late and there aren't any bused now.A: 5. _____________________.C: You're welcome.补全对话十七A: Laura, how are you today?B: Not very well. I've had a bad day.A: 1._______________________?B: I got up late this morning. 2. _______________.So I had to wait for another bus.A: Oh, bad luck! 3. _______________________? B: Yes. I was 30 minutes late. And what was worse, when I got to school, I found no one in the classroom!A: Where did they go?B: 4. ________________________. Our teacher told us about it, I forgot.A: 5. ______________________________?B: Yes, but when I found them, they were going back to school!补全对话十八A: Excuse me. 1._________________________? B: Sorry, I'm new here. You can ask my friend. He may know.C: The Children's Hospital? Er... It's a little far from here.A: 2. ___________________________?C: It's about 5 kilometres away.A: 3. ___________________________?C: Yes, the No. 15 bus will take you there.A: Where is the bus stop?C: 4. _________________________ and take the first turning on the right. You can see it on your left. You can't miss it.A: 5. ___________________________.C: You are welcome.补全对话十九A: Hi, Li Tao. There is going to be a talk about American music at the Children's Palace.1. ______________ ?B: I'd love to. 2. ________________________?A: A teacher from America.B: I think the talk will be interesting. 3. ______________________?A: At half past eight. Let's go together.B: Good. 4. _______________________? A: Outside the school gate.B: OK.补全对话二十(At Mr. White's office in a middle school) A: Hello! 1. _______________________? B: Speaking, please.A: I'm Peter's mother. I'd like to ask for leave for my son.B: 2. ________________________?A: He didn't feel well this morning. He has a cold.B: 3. ________________________. Is it serious?A: Not very serious. But the doctor asked him to stay in bed and have a good rest.B: Don't worry. 4. _________________________.A: Thank you, sir. Goodbye!B: Bye!补全对话二十一A: 1. __________________________?B: Come in, please. I'm in the study.A: Hi, Susan.B. Hi, James.A: 2. __________________________?B: I'm looking at the photos!A: Yes? Can you show them to me?B: 3. _________________________. Here you are.A: Oh, what photos! Where did you take them?B: Don't you see the Palace Museum?A: Oh, you've been to China! 4. _______________?B: During our summer holidayA: Whose camera did you take them with? B: Mine. I had a digital one before I left. A: 5. ______________________?B: It cost me 300 dollars.A: Well, that's great.补全对话二十二A: Good morning, sir. 1. __________________?B: I'd like to buy a white shirt. Do you have any white shirts?A: Yes. 2. ____________________?B: I want Size M.A: Here you are.B: Can I try it on?A: Sure. Is it all right?B: Yes. I like it very much. 3. _________________?A: 296 yuan.B: That's a bit expensive. Do you have any other kind? I want a cheaper one.A: What about this one? It is only 108 yuan. B: OK. 4. _________________. Here is the money.A: 5. ___________________.Goodbye, sir. 补全对话二十三A: Summer holiday is coming. 1. ______________?B: Yes, I'm going to my hometown.A: 2. _________________________?B: For about a month. 3. ____________________?A: I want to travel to Hainan Island. It's a beautiful place of interest.B: 4. _________________________. But I have to visit my grandparents in my hometown.A: It doesn't matter. If you stay in your hometown for fewer days, you'll have enough time to go traveling.B: 5. _______________. Then I will go to my hometown as soon as the holiday begins. A: OK! I will wait for you until you come back.B. That's a deal! Thank you.补全对话二十四(Jim=J Lin Tao=L)J: Hi, Lin Tao! I called you yesterday morning, but you were not in.L: 1. ___________________. I went to see my grandparents with my father and mother. J: Don't your grandparents live with you? L: No. 2. _______________. It's not far from here.J: A village? Is it beautiful?L: Yeah, it's very beautiful. There's a river around it. Trees and flowers are everywhere. And my grandparents have a big farm.J: Great! What's on the farm?L: Orange trees. Grandpa wants me to go back to pick oranges this autumn. Well, 3._____________?J: I'd love to. And we can eat oranges while picking them, can't we?L: Of course. Oh, 4. ________________________?J: Er, I called you to go hiking with me. But it doesn't matter. I asked Mike and Sam instead.L: 5. _________________________?J: Yes, we enjoyed ourselves very much.补全对话二十五A: The museum is still closed. We came here early.B: 1. ___________________________? A: At nine o'clock.B: We have to wait for about 10 minutes. 2. ___________ ?A: Yes, several times.B: Are there any interesting things?A: 3. ___________________________. You can even see some old guns.B: 4. ___________________________.A: I think they can make you think of the history of our country. And you will have more love for our country.B: Yes, oh, it's already 9:10. 5. ________________?A: Ah...., let me see. I'm sorry I forgot. There is something wrong with the front door. The side door is used as the entrance. Let's go to the side door.补全对话二十六A: Where were you between 6 and 11 p.m. last night?B: 1. ____________________________, Andrew.A: 2. ____________________________? B: We met at the Underground station at 5:30 p.m.A: 3. ____________________________? B: We went to the Ocean in Parkhill by bus. A: 4. _____________________________? B: It was quite full.A: 5. _____________________________? B: We saw a film called "The Great Train Robber." It was a detective film.补全对话二十七(Jack=J Susan=S)S: It's Sara's birthday the day after tomorrow.1. ______ _ ?J: Does she like reading? 2. __________________.S: Well she has had lots of books already. Besides, her birthday present last year was also a book.J: 3. _______________________________? S: No, she doesn't like basketball, but she likes football.J: Get her a football, then?S: 4. _______________________________?J: I have no idea, about 20 dollars, maybe. S: I have only 6 dollars. 5. ___________________?J: I have eight. Why not go and ask John if he would like to join us?S: That's really a good idea. Let's do that right away.补全对话二十八(Policeman=P Lily=L)P: What happened?L: My bike hit a car.P: 1. __________________________?L: Luckily I am not.P: 2. ______________________?L: It is not broken.P: That's good. 3. ________________________?L: About ten minutes ago.P: And where?L: Around the corner near my school.P: 4. ____________________________? L: Perhaps I rode too fast when I saw a car coming to me. I tried to stop, but my bike still hit the car.P: Well, 5. ____________________.L: Thanks a lot. I will.P: OK. Goodbye!L: Bye!补全对话二十九(Tim=T Mum=M)T: Mum, mum! M: 1. ___________________________? T: Tomorrow I'm going to take part in a sports meeting, but my sports shoes are worn out. I must buy a new pair.M: 2. __________________________?T: No. Look! There is a big hole in this one, and the other one is broken, too. I think nobody can mend them well.M: Yeah, that's true. Well. 3. ________________?T: Mum, I'm wearing size 8 now, but they're too tight. Size 9 are just right, I think. But when shall we go shopping?M: 4. _______________________?T: Tomorrow? Tomorrow is too late. Shall we go after school this afternoon?M: 5. ________________________. I'll meet you at the school gate.T: Thanks, mum. Oh, I must go to school now. See you then. Bye.M: Bye.补全对话三十(John=J Robert=R)J: Hello, Robert. I'm sorry, but I have to tell you some bad news?R: 1. ______________________?J: Jane fell off her bike and hurt herself on the way home yesterday.R: 2. _______________________?J: She's in hospital.3._______________________.R: Why didn't you send her to hospital at once?J: 4. __________________________. But this morning her leg hurt a lot. She couldn't walk by herself.R: That's too bad. 5. _____________________?J: Jane asked us not to worry and wanted us to go for the picnic without her.补全对话三十一A: Excuse me, 1. ______________________? I haven't seen him for weeks.B: Jim's gone to England.A: Really? 2. _____________________? B: He went there last week.A: 3. __________________________?B: Yes. He had lived there for 15 years before he came to China.A: 4. ___________________________? B: He traveled with his friends.A: 5. ___________________________? B: He'll be away for about two weeks.A: Oh, thank you. I'll phone him this evening.补全对话三十二A: Hi, Sue. It's Mario.B: Oh, hi. 1. ______________________. A: Fine. Look, I was wondering if you are free on Saturday evening. I've got some tickets for a concert. Would you like to come? B: Oh, well, 2. ___________________________. But, em, I am studying for my exams at the moment, and well,I'm sorry I can't.A: OK. Don't worry. Some other time then, I suppose.B: Oh, Yeah. Sure. But 3. ___________________? I think she's free at the weekend.A: Diana? Good idea! But could you tell me her telephone number?B: 4. _____________________________. Just a moment, please. It's 68906133.A: 68906133. Thank you.B: You're welcome. And 5. __________________.A: The same to you! Bye!B: Bye补全对话三十三A: Hello. 1. ___________________.B: Me, too.A: But you look worried. 2. __________________?B: I got a "C" in the English exam.A: 3. ______________________!B: I think English is too difficult for me. I don't understand why we Chinese studentshave to learn it.A: You know, 4. _____________________. B: You're right. Though it's very useful, it's too hard.A: It's hard, but it's important. 5. ______________.B: Really? It's very kind of you. I'll try harder.补全对话三十四A: 1. ______________________?B: It will be held on November 1oth.A: 2. _______________________?B: There are seven events in the school sports meeting.A: 3. ________________________?B: I certainly will. You know, I'm the best runner in my class.A: Really? 4. ___________________?B: I'll take part in 400 meters race.A: Oh, that's good. 5. __________________. B: It's very kind of you to say so.补全对话三十五A: 1. _____________________, Dad ?B: I'm learning English on TV.A: 2. ________________________? You're only a taxi driver, not a student. 3. __________________?B: Yes. As we know, the Olympic Games will be held in Beijing in 2008. When the day comes, 4. ______________________. I'll drive my taxi to welcome and help friends all over the world.A: Oh, You're really great.B: And what's more, we are a member of the WTO.5. ________________________________. Let's try our best to learn English well. OK? A: Good idea!补全对话三十六(Sue=S Ken=K)S: Hello, Ken! Could you give me a lift? K: 1.____________________________, I don't have a car right nowS: Oh, that's too bad! I want to go to the Central Hospital.K: Why? 2______________________________?S: No, I'm all right. My English teacher is there. She is ill now and is to leave the hospital today.K: I see. 3. ____________________________?S: I've already got some flowers from my mother's garden.K: Well, well. 4. ___________________________.S: But, what a pity! I can't see Linda now. No car and no driver.K: Wrong. You have a good driver here. 5. ___________________________.S: Really? That's great. It's very kind of you,Ken.K: It's my pleasure.补全对话三十七(Robert=R Jack=J)J: Hello, Robert. Are you free on Saturday morning?R: Yes. 1.___________________________? J: There is a basketball match at the Sports Center. Do you want to watch it?R: Sure. 2. _________________________? J: Our school Vs No. 1 Middle School.R: 3. __________________________! Let's go to cheer for our team.J: Yeah. No.1 Middle School Team is not easy to beat.R: So the match will be exciting. 4. _______________?J: 8:30. Do you think you can get up on time? R: Of course. 5. __________________________.J: OK. There will be three school buses waiting for us in front of the library. Let's meet there at 8:30.R: All right. See you then.中考英语总复习50套补全对话答案(1)1. Have you taken your temperature?2. How long have you been like this?3. You've got a cold.4. Is it serious?5. How often do I have to take it? (2)1.What are you talking about?2. No, I didn't.3.what a pity!4 Can we watch it on TV?5 Work must come first.(3)1 Have you finished your homework?2 I'll help you.3 Here you are.4 By the way5 Where is she?(4)1 She may have one.2 Here you are.3 Would you like to come?4 What time will it begin?5 I must finish my homework first. (5)1 I' really sorry.2 Are you ill?3 Why not take some flowers with you?4 That's wonderful.5 I can borrow a car and take you there.(6)1 Thank you for meeting me.2 Here is my card.3 It was OK.4 Where is the hotel?5 What time does it begin?(7)1 What's up\Why?2 Between which teams?3 Great!4 What time does it start?5 I'd like to watch the game very much.(8)1 Which path would you like to choose?2 Which hotel do you want to live in?3 It's not expensive.4 Will you please fill in this form?5 Sure\certainly \ Yes, it's quite all right.(9)1 What is it ?2 Who told you about it?3 I was the winner.4 Where shall we go?5 See you later.(10)1 I was ill.2 How are you now \Are you better now3 Have you seen the doctor4 Why don't you stay at home today5 I can help you with your lessons (11)1 How are you \ How's everything going2 You look so nice in the new skirt3 I bought it in Hangzhou4 When did you go there5 He has gone to England(12)1 Where have you been2 What were you doing3 How about now4 It seems you borrowed all of them5 Sam must spend all of his money on music (13)1 Did you watch the football match last night2 What a pity3 What was the score \result4 Was it an exciting game5 Soon our team kicked another two goals.\ And in the last minute our team got one more.\But after that our team still played very well.\And the American team got no more......(14)1 This is Mei Ya speaking2 Not yet, and you3 Really4 Would you like to go with me5 How about walking\riding a bike(15)1 How about going on a trip2 Where to go\where do you plan to go3 We can go there by bike4 Who else would you like to go with\Why not ask someone else to join us5 We can just lie on the grass having a good rest\we can have a picnic there\we can do anything we like......(16)1 I have to look after my mother\my mother is ill in hospital2 She has got a bad cold\cough...3 How is she feeling now4 Can I do anything to help5 See you(17)1 Have you done this kind of work before2 Why are interested in it3 What was your last job4 Why did you leave5 What was the arguments about(18)1 I'm sorry I don't know2 Is there a hotel near here3 How far is it4 How can I get there5 Thank you(19)1 What's up\what happened\what's wrong with you2 I missed the early bus3 You must be late, weren't you\were you late for school4 They went to the playground to see a basketball match....5 Did you find them at last\did you go to look for them(20)1 Which is the way to the Children's Hospital2 How far is it3 Can I take a bus4 Go along this road5 Thank you(21)1 What are you doing\where are you2 Let me do it by myself\Let me help you (22)1 Would you like to go with us\would you like to listen to it2 Who is going to give the talk3 When is going to start4 Where shall we meet(23)1 Can I speak to Mr. White2 What's wrong with him3 I'm sorry to hear that4 I hope he will be all right soon(24)1 May I come in\is anyone in2 What are you doing3 Sure4 When did you go there5 How much did it cost(25)1 Can I help you2 What size do you want3 How much is it4 I'll take it5 Here you are(26)1 Do you have any plans for it2 How long will you stay there3 What about you4 I'd like to travel, too5 That's a good idea(27)1 Do you like cooking2 Why will you cook this evening3 Who often cooks in your family4 What will you cook5 Enjoy your noodles(28)1 I'm very sorry2 They live in a village3 Would you like to go with me4 Why did you call me5 Did you have a good time(29)1 When does it open2 Have you ever been here3 Of course, there are4 They were only used in old days \but now they are useless except for show5 What's the matter \Why is it still closed (30)1 I went to the cinema with my friend2 When did you meet him3 Which cinema did you go to4 Was the cinema full or empty5 What film did you see(31)1 What shall we buy for her birthday2 We can buy her a book3 How about a basketball4 Do you know how much a football costs5 How much do you have(32)1 Are you badly hurt2 What about your bike3 When did it happen4 How did it happen5 Be careful next time(33)1 Yes2 Can't they be mended3 What size do you wear4 What about tomorrow5 All right(34)1 What happened2 Where is she now3 We sent her there this morning4 Because she said nothing serious5 What about our picnic。

2014年高中语文新课标第二轮总复习限时训练(1-4) 专题一 语言文字运用

2014年高中语文新课标第二轮总复习限时训练(1-4) 专题一 语言文字运用

2014年高中语文新课标第二轮总复习专题一语言文字运用限时训练卷(1)限时:20分钟满分:38分一、语言文字运用(12分,每小题3分。

限时6分钟)1.下列句子的字形和加点字的读音全都正确的一项是()A.窗外,雨滴滴哒哒的下个不停。

雨声一滴一滴,雨情一幕一幕,那些被雨淋过的花儿,绽.(zhàn)放着嫣.(yān)红的色泽。

B.灌木丛新生的叶子贪婪地吮.(yǔn)吸着露珠,柳树摇摆着纤.(qiān)细的腰肢,摇曳着柔美的枝条,“绿”占领了人们的眼睛。

C.风儿抚摸着大地沟壑纵横的年轮,月光孤独地梳理着它高高低低的心思,大地的呢喃,氤氲..(yīnyūn)成一片,空灵幽远,扶摇汉霄。

D.一抹乌云掠.(lüè)过,山坡上松树林立,郁郁葱葱.(chōng),层层梯田挂在山腰,雾气蒙蒙,山粱上几棵松树在雨中越发显得妩媚。

2.下列句子中加点的成语运用正确的一项是()A.“文革”时评价一个人先认定你是反革命还是革命一派,再找证据,总能得出罪行。

在古代这就叫诛心之论....,做了什么事不要紧,关键是怀的什么心。

B.每值樱花盛开的季节,这个城市常常是十室九空....,人们举家玩赏樱花,到那时,这里就如同一个浪漫、梦幻的世界,处处花朵簇拥,人流如织。

C.费力地从车门里钻出来的某著名女演员,虽然浓妆淡抹....,穿着入时,但是神色十分憔悴,完全没有了平时在镜头前的精神和气质。

D.城市建设既要考虑未来发展的长远方向,也要考虑历史形成的客观事实,因此实际推进过程中要实事求是,量力而行....地去做。

3.下列加点的词必须删除的一项是()在.①拉丁美洲地区,塞万提斯国际艺术节享有极高的知名度和很大的影响力。

每年秋季,来自几十个国家的数千名艺术家都.②齐聚墨西哥历史文化名城瓜纳华托,进行演出、展示和交流。

同时,来自世界各地的艺术爱好者也.③蜂拥而至,将艺术节变成了狂欢节。

如今,塞万提斯国际艺术节已经成为了.④世界上最重要的艺术节之一。

2014大学无机化学考试总复习

2014大学无机化学考试总复习
(已知Fe(OH)3的Ksp=2.79×10-39)
分步沉淀
例:含0.1mol/L的Cl-及I-溶液中加入Ag+,问 哪种沉淀先析出,可否实现分步沉淀。
已知:AgCl的Ksp=1.56×10-10; AgI的Ksp=1.5×10-16)
解 Ksp(AgCl)=1.77×10-10, Ksp(AgI)=8.52×10-17 AgCl开始沉淀时,
(B) 4.5 10-10
(C) 4.5 10-8
(D) 4.5 10-4
〔OH-〕= Kbc碱
Ka Kb KW
7
二元弱酸、弱碱溶液
在实际计算[H+] 时,通常忽略二级离解,从 而把二元弱酸、弱碱当作一元弱酸、弱碱近 似处理。
二元弱酸第二步质子传递平衡所得的共轭碱 的浓度近似等于Ka2,与酸的浓度关系不大。
[Ag ]
Ksp (AgI) [I ]
8.52 10 17 0.0100
mol
L1
8.52 10 15 mol
L1
AgI开始沉淀时,
[Ag ]
Ksp (AgCl) [Cl ]
1.77 10 10 0.0100
mol
L1
1.77 10 8 mol
L1
所以AgI先沉淀。
AgCl开始沉淀时,
(A)11.25 (C) 9.25
(B) 4.75 (D) 4.25
在实际应用中还可采用酸碱反应的生成物与剩余的反
应物组成缓冲体系:
[OH- ]=Kb
c碱 c共轭酸
30
pH = 9.56的NH4Cl和NH3·H2O的混合溶液中 NH4Cl和NH3·H2O的物质的量浓度比是______。
( NH3·H2O 的pKb = 4.74 ) 答案:1:2

2014届高考第一轮总复习:直线与平面平行的判定课件

2014届高考第一轮总复习:直线与平面平行的判定课件

4.三角形中位线定理:三角形的中位线平行于第三边, 且等于第三边长的 一半. 5.梯形中位线定理:梯形的中位线平行于两底边,且等 于两底边和的 一半. 6 .经过直线外一点有 且只有一 行; 条直线与已知直线平
经过直线外一点有 无数 个平面与已知直线平行; 经过平面外一点有 无数 条直线与已知平面平行; 经过平面下一点 且只有一 平面与已知平面平行; 经过两条异面直线中的一条有 且只有一 个平面与另一 条直线平行.
[例 2]
如下图所示,两个全等的正方形 ABCD 和 ABEF
所在平面相交于 AB,M∈AC,N∈FB,且 AM=FN.求证:MN
∥平面 BCE.
[分析]
解答本题可先在面 BCE 中找一条线与 MN 平行,
再判定出 MN∥面 BCE.
[证明]
方法一:作 MP∥AB 交 BC 于 P,NQ∥AB 交 BE
[分析]
欲证 MN∥平面 PBC,根据判定定理,关键是在
PM BN 平面 PBC 内找到一条直线与 MN 平行, 而所给条件为MA=ND, 比例式自然会和平行产生联想,但 PA 与 BD 为异面直线,无 法直接利用此条件,于是想怎样做才能化异为共,使问题得到 解决,很自然的一个想法就是直线 PB 与两异面直线均相交, 且 PB⊂平面 PBC 内,只要在 PB 上取点 E,符合上述比例关 PE PM 系,产生平行线即可解决,于是在 PB 上取 E,使 = ,则 EB MA ME∥AB∥CD,只须再过 N 作 NF∥CD,∴ME∥NF.
思路方法技巧
直线与平面平行的判定定理
学法指导 1.应用判定定理证明线面平行的步骤
上面的第一步“找”是证题的关键,其常用方法有:利 用三角形、梯形中位线的性质;利用平行四边形的性质;利 用平行线分线段成比例定理.

【步步高】2014届高三化学一轮总复习 第三章 金属及其化合物 专题讲座二 无机化工流程题复习策略与

【步步高】2014届高三化学一轮总复习 第三章 金属及其化合物 专题讲座二 无机化工流程题复习策略与
(1)滤渣主要成分有___M__g__(O__H__)_2___和__C__a_S__O__4 ___以及未溶杂卤石。
(2) 用 化 学 平 衡 移 动 原 理 解 释 Ca(OH)2 溶 液 能 溶 解 杂 卤 石 浸 出 K + 的 原 因 :
_加__入___C_a__(O__H__)_2_溶__液__,___M__g_2_+__与__O__H__-_结___合__生___成__M__g_(_O__H__)_2沉___淀__,___M__g_2_+_浓___ 度___减__小___,__平__衡___正__向___移__动__,___K__+_增___多__。 (3)“除杂”环节中,先加入K__2_C_O__3__溶液,经搅拌等操作后,过滤,再加入__H_2_S__O_4__
专题讲座二 无机化工流程题复习策略与解题 方法指导
一、解题策略
化工流程中常见的操作与名词
化工流程题目在流程上一般分为3个过程:
原料处理 ―→ 分离提纯 ―→ 获得产品
(1)原料处理阶段的常见考点与常见名词 ①加快反应速率 ②溶解:通常用酸溶。如用硫酸、盐酸、浓硫酸等 水浸:与水接触反应或溶解 浸出:固体加水(酸)溶解得到离子 浸出率:固体溶解后,离子在溶液中含量的多少(更多转化) 酸浸:在酸溶液中反应使可溶性金属离子进入溶液,不溶 物通过过滤除去的溶解过程
(4)其他常见考点 ①化学方程式 ②实验仪器 ③计算 ④信息
二、热点题型探究 热点1 碱金属及其矿物的开发利用
【例 1】 (2012·广东理综,32)难溶性杂卤石(K2SO4·MgSO4·2CaSO4·2H2O)属于“呆 矿”,在水中存在如下平衡: K2SO4·MgSO4·2CaSO4·2H2O(s) 2Ca2++2K++Mg2++4SO24-+2H2O 为能充分利用钾资源,用饱和 Ca(OH)2 溶液溶浸杂卤石制备硫酸钾,工艺流程如下:

2014项目管理学(总复习)

2014项目管理学(总复习)

文化产业项目管理学复习题(2014)一、名词解释(本大题共4题,每小题5分,共20分)1、项目管理:就是把相关的知识、技能、工具和技术应用于项目各项工作之中,以满足或超过项目利益相关者对项目的要求和期望。

2、矩阵式组织形式:指在矩阵型组织形式中既存在适合于项目日常运用的职能型组织形式,又有适合于完成专门项目任务的项目型组织形式,适用于多项目企业,项目之间的差别较大,项目的技术比较复杂。

根据职能型组织形式和项目型组织形式的混合程度不同,又可以分为:弱矩阵式组织形式、平衡矩阵式组织形式和强矩阵式组织形式。

3、关键路径法(CPM):是一种运用特点的、有顺序的网络逻辑和估算出的项目活动工期(2分),确定项目每项活动的最早和最晚开始和结束时间(2分),并做出项目工期网络计划的方法(1分)。

(关键路径法关注的核心是项目活动网络中关键路径的确定和关键路径总工期的计算,其目的是使项目工期能够达到最短)。

4、项目的生命周期:是由一个项目经历的各分析阶段组成的序列。

项目各阶段划分的原则是从某种交付结果的完成为标志,大多数项目的生命周期大致可划分为概念阶段、设计阶段、实施阶段、和终止阶段四个阶段。

项目:是一个组织为实现的目标(1分),在一定的时间、人员和其他资源的约束条件下(2分),所开展的一种有一定独特性的一次性的工作(2分)。

5、项目网络图:是表示项目工作逻辑关系的图示标示法,为了反映项目的年度序列关系,网络图总是从左向右绘制。

网络图的表现形式有两种:一种是节点式网络图,另一种是箭线式网络图。

6、可交付成果:是为了完成项目而必须做出的可以衡量的有形的,并可验证的事项(3分),一般指向外部交付的成果(1分),这种成果需要由项目发起人或客户事先批准(1分)。

7、工作分解结构(WBS ):是一个以项目产品或服务为中心的子项目组成的项目“家族树”,它规定了项目的全部范围。

为方便管理和控制而将项目按等级分解成易于识别和管理的子项目,再将子项目分解成更小的工作单元,直至最后分解成具体的工作(或工作包)的系统方法,是项目范围规划的重要工具和技术之一8、项目相关者:又叫项目的干系人,或项目利益相关者,或项目的受益者,他们是在项目的全过程中与项目有某种利害关系的人或组织(2.5分),他们还会对项目的目标和可交付结果施加影响(2.5分)。

2014年五年级语文上学期读音总复习练习题(新人教版)

2014年五年级语文上学期读音总复习练习题(新人教版)

2014年五年级语文上学期读音总复习练习题(新人教版)2014鐗堬級璇婚煶缁冧範棰?涓€銆佸悓闊冲瓧 1.m霉锛?锛夎壊闄嶄复寮€锛?锛?缇★紙锛?鍧燂紙锛?鐖憋紙锛?2.f霉锛?锛変範锛?锛?锛夐挶杈滐紙锛?濂旓紙锛?3. y谩锛?锛夊埛璞嗭紙锛?锛?澶╋紙锛夋捣瑙?4. y矛锛?锛夊姏锛?锛夌珛锛?锛変箟锛?锛? 5.xi谩ng 瀹夛紙锛?鍚夛紙锛?鎱堬紙锛?锛?锛夌粏缈憋紙锛?6.ni菙鐢碉紙锛?锛?锛夋墸锛?锛夌害锛?锛夊姩7.z脿o 骞诧紙锛?锛?鎬ワ紙锛?锛?锛夊姩鏆达紙锛?鍒讹紙锛?8.zh矛锛?锛夊矕锛?锛夊笢锛?锛夌洏锛?锛夋€?锛?锛夊疄锛?锛夊叺浜屻€侀€夋嫨1?锛夈€?A. 娑熸吉(y墨锛?鑵艰厗(di菐n) 鐔?sh贸u)缁?缈曪紙x墨锛夊姩 B. 纾?m贸)缁?鑹版订锛坰h猫锛?l煤n锛夊悶鏋?娌?q墨)鑼?C. h墨锛?鐭虫Υ锛坙iu锛?鍜?锛坺膩锛夊槾鐪稿瓙锛坢贸u锛?D.鍧狅紙zhu矛锛夎惤渚匡紙pi谩n锛夊疁钁辫審(l贸ng) 鍥涙暎锛坰脿n锛夋父寮€ 2. 涓嬪垪甯︾偣瀛椾腑璇婚煶瀹屽叏姝g‘鐨勪竴缁勶紙锛夈€?A. 椹?b贸)鏉?骞叉陡(h茅) 娲ユ触鏈夊懗(j墨ng) 闄勮繎(f霉) B. 婊氱摐鐑傜啛(sh煤) 娼烘胶(ch谩n) 鍝轰钩(p菙) 濠€濞?nu贸) C. 纾ㄩ毦锛坣脿n 锛?绋€缃曪紙h脿n锛?浣庡ご鎶樿妭(zh茅) 鍓婂急(xu膿) D. 鍛?菕u)蹇冩播琛€(j菒) 鍋滄硦锛坆贸锛?鐜茬彂鍓旈€?t墨) 3. 涓嬪垪甯︾偣瀛楃殑璇婚煶瀹屽叏姝g‘鐨勪竴缁勬槸锛?锛夈€?A.浼伴噺锛坙i谩n锟芥簝锟?楠ㄩ珦锛坰u铆锛?鐟板疂(gu墨) di菐n锛夎捣鑴氬皷 B.鍙嬭皧(y铆) 鍚屼粐鏁屽烤(k脿i) 闂撮殧(ji脿n ) 娌夌潃(zhu贸) C.鎮勭劧(qi菐o) 纾ㄧ洏(m貌) 鍒归偅(ch脿) 韪?ch贸u)韬?zh煤) D.鐏扮儸(j矛n) 缁疯劯(b臎ng) 鎷栨矒锛坱脿锛?娴佸厜婧㈠僵锛坹矛锛?4.锛?锛夈€?A. 娣凤紙h霉n锛変贡涓嶅眻涓嶆尃(n谩o) 鍩嬫€?m谩i) 鑻旇棑(xi菐n) B. 鑸€姘达紙y菐o锛?鍠嬪枊涓嶄紤锛坉i茅锛?鎶?ju茅)鎷?鍜?z膩)鍢?C. 鐡︾牼锛坙矛锛?涓€骞?f煤) 鍗筹紙j铆锛変娇韪夎笁璺勮穭(qi脿n锟斤拷) D. 瑾?t茅ng)鍐??s艒u) 鏆傦紙z脿n锛夋椂鐭?ji菐o)鍋?5. 涓?锛夈€?A. (f猫n) 楠ㄦ皵(g煤) 绉夋€?b菒ng) n锛?B.鐐圭紑(zhu矛) 鐪?ju脿n)鎭?绮?zh膩n )璐?鐜锋薄锛坉i脿n锛?C.鐜锋薄(di脿n) 绗?ti谩o)甯?濂旇荡锛坆猫n锛?zhu菐n锛夊集 D.澶т箟鍑涳紙l菒n)鐒?n锛?涓?d菒)鏌?纾呯ご锛坆贸锛?6.勬槸锛?锛夈€?A.鏁o紙s菐n锛夊皠鍒?hu谩)鐮?灏?j菒n)绠?鍙?k貌u)闂?B.鎹?b菙)鎹?灏藉揩(j菒n) 鎷?f煤)鏅? C.鎸f墡(zh谩) 棰ゆ姈(ch 脿n) (j铆) 绨哥畷(b貌ji) D.鎸?ti菐o)鎷?鎷?n菒)瀹?鎷樻潫(sh霉) 婀栨硦锛坧艒锛?7.?A.鏄旓紙x墨锛夋棩B.鏆傛椂锛坺h脿n 锛?C.琛€锛坸i臎锛夋穻娣?D.hu脿n锛?( ) A.渚电暐锛坙眉猫锛?B.閰?xi脿o)姣?C.鍊熼壌(ji脿n) D.婕嗭紙q墨锛夐粦( ) A.鎶?m菕)鍑€ B.濠€濞滐紙膿锛?C. 涓€闃?qu猫) D.鍞卞拰锛坔猫锛?( ) A.鐨?ji菐o)娲?B.榫燂紙j 奴n C.娈嬬柧(j铆) D. 鎺掑北鍊掓捣锛坉脿o锛?( ) 8.涓嬪垪姣忕粍璇嶈€?A.缁?鑵?(m矛) B. 鍝轰钩(b菙) C.灏樺焹锛埬乮锛?D.浠嶇劧(r茅ng) ( ) A.鍕夊己锛坬i谩ng锛?B .澶逛笣缃戯紙ji膩锛?C.鍊炬枩锛坬墨n锟芥簝锟?D.澶勭悊(ch 霉) ( ) A.n锛?B. 濂囪抗(j矛) C.鑻旇棑锛坱谩i锛?D.娼滃叆(qi菐n) ( ) A.闄峰叆锛坸i脿n 锛?B.杩囨护锛坙霉锛?C.鍓婂急锛坸u膿锛?D.鐪嬪畧(k膩n) ( ) 9.勶紝鎶婂畠閫夊嚭鏉ャ€?A. h菕u锛?B.鏁拌惤锛坰h菙luo锛?C. 浼?s矛)涔?D. 鍥伴毦锛坣脿n 锛?( ) A. 涓€瓒?t脿n锟斤拷) B.鍝庡摕锛坹艒u 锛?C. 浼翠荆锛坙菤锛?D. 寮€鑺辩粨锛坖i膿锛夋灉( ) A. 鍏?x矛ng)濂?B. 鏇?q奴)绾?C.缁欙紙j菒锛変簣D. l谩锛?( ) A. 鎿庣潃锛坬铆n锟芥簝锟?B. 渚涘簲(锟芥嫭锟絥锟斤拷) C.蹇界暐(l眉猫) D.閫讹紙w膿墨锛夎郡锛坹铆锛? ) 10.璇婚煶涓庘€滀腑闂粹€濈殑鈥滈棿鈥濅笉鍚岀殑涓€椤癸紙锛夈€?A锛庝竴姘撮棿 B.鎴块棿 C.杞﹂棿 D.11.鏈変竴缁勮瘝璇婚煶鐩稿悓鐨勬槸锛?锛夈€?A锛?澶勭悊澶勬柟澶勭綒锛?锛?B锛庤皟鑺?璋冩暣鍗曡皟璋冨姩锛?锛?C锛庢棩鏅?鏅曡溅鏅曞€?鏅曡埞锛?锛?D?濂旇荡濂旇窇?锛?涓夈€佺敤鈥淺鈥?鏀ョ潃锛坺u脿n zhu脿n锛?鍐锋紶锛坢貌m猫锛?澶勭悊锛坈h霉ch菙g膿ng g猫ng锛?棰ゆ姈锛坺h脿n ch脿n锛?濂旇荡锛坒奴f霉锛?閾告垚锛坺h霉z霉锛?鑻旇棑(xi膩n xi菐n) 缇庡樊锛坈h膩i ch脿锛?ch膩i ch脿锛?锛坙菙l菤锛?寰滃緣锛坱菐ng ch谩ng锛?娈夎亴锛坸霉n x奴n 锛?浼肩殑锛坰h矛s矛锛?鎷у紑锛坣菒n锟斤拷n铆n锟芥簝锟?鎷ф瘺宸撅紙n菒n锟斤拷n铆n?b贸p艒) 绔嬪嵆锛坖矛j铆锛?鍕夊己锛坬i谩ng qi菐ng锛夋按娴掍紶锛?chu谩n zhu脿n锛?鍥涖€佺粰鍔犵偣瀛楅€夋嫨姝g?鎴胯垗锛坰h臎sh猫锛変拱绉?zh菕ng zh貌ng) 鍨傝敁(m脿n w脿n) 绌?k艒ng k貌ng )鍦?(d矛de)鍦?琛€锛坸i臎xu猫锛変笣zhu菐n zhu脿n鐭崇⒕(zh 菐n ni菐n) 缁匡紙l菧l霉锛夋灄姝э紙q铆q菒锛夐€?鏁伴噸锛坈h贸n 锟斤拷zh貌n锟芥簝鈹ワ拷鎰忎竾閲嶏紙ch贸n锟斤拷zh貌n锟芥簝锟?鏈?ch谩o zh膩o)鏅?y脿n y猫锛?鍛滃捊锛坹脿n y猫锛?褰?d膩ng d脿ng)浣?。

【精品一轮 特效提高】2014高考总复习(理数)-题库:8.6 空间向量及其运算

【精品一轮 特效提高】2014高考总复习(理数)-题库:8.6 空间向量及其运算

8.6 空间向量及其运算一、选择题1.若{a ,b ,c }为空间的一组基底,则下列各项中,能构成基底的一组向量是( ).A .{a ,a +b ,a -b }B .{b ,a +b ,a -b }C .{c ,a +b ,a -b }D .{a +b ,a -b ,a +2b }解析 若c 、a +b 、a -b 共面,则c =λ(a +b )+m (a -b )=(λ+m )a +(λ-m )b ,则a 、b 、c 为共面向量,此与{a ,b ,c }为空间向量的一组基底矛盾,故c ,a +b ,a -b 可构成空间向量的一组基底. 答案 C2.以下四个命题中正确的是( ).A .空间的任何一个向量都可用其他三个向量表示B .若{a ,b ,c }为空间向量的一组基底,则{a +b ,b +c ,c +a }构成空间向量的另一组基底C .△ABC 为直角三角形的充要条件是AB →·AC →=0 D .任何三个不共线的向量都可构成空间向量的一组基底解析 若a +b 、b +c 、c +a 为共面向量,则a +b =λ(b +c )+μ(c +a ),(1-μ)a =(λ-1)b +(λ+μ)c ,λ,μ不可能同时为1,设μ≠1,则a =λ-11-μb+λ+μ1-μc ,则a 、b 、c 为共面向量,此与{a ,b ,c }为空间向量基底矛盾. 答案 B 3.有下列命题:①若p =x a +y b ,则p 与a ,b 共面; ②若p 与a ,b 共面,则p =x a +y b .③若MP →=xMA →+yMB →,则P ,M ,A 、B 共面;④若P ,M ,A ,B 共面,则MP →=xMA →+yMB →. 其中真命题的个数是( ).A .1B .2C .3D .4 解析 其中①③为正确命题. 答案 B4. 如图,在底面ABCD 为平行四边形的四棱柱ABCD -A 1B 1C 1D 1中,M 是AC 与BD的交点,若AB =a ,11A D =b ,1A A =c 则下列向量中与1B M 相等的向量是( ) A .-12a +12b +c B.12a +12b +cC.12a -12b +c D .-12a -12b +c 解析 1B M =1B A +AM =1B B +BA +AM =-12a +12b +c .答案 A5.如图所示,已知空间四边形OABC ,OB =OC ,且∠AOB =∠AOC =π3,则cos 〈OA →,BC →〉的值为( ).A .0 B.12C.32 D.22解析 设OA →=a ,OB →=b ,OC →=c由已知条件〈a ,b 〉=〈a ,c 〉=π3,且|b |=|c |,OA →·BC →=a ·(c -b )=a·c -a·b=12|a||c |-12|a||b|=0,∴cos 〈OA →,BC →〉=0. 答案 A6.如图,在大小为45°的二面角A -EF -D 中,四边形ABFE ,CDEF 都是边长为1的正方形,则B ,D 两点间的距离是( )A. 3B. 2 C .1 D.3- 2解析 ∵BD →=BF →+FE →+ED →,∴|BD →|2=|BF →|2+|FE →|2+|ED →|2+2BF →·FE →+2FE →·ED →+2BF →·ED →=1+1+1-2=3-2,故|BD →|=3- 2. 答案 D 7.下列命题中①若a ∥b ,b ∥c ,则a ∥c ;②不等式|a +b |<|a |+|b |的充要条件是a 与b 不共线;③若非零向量c 垂直于不共线的向量a 和b ,d =λa +μb (λ、μ∈R ,且λμ≠0),则c ⊥d . 正确命题的个数是( ).A .0B .1C .2D .3 解析 只有命题③是正确命题. 答案 B 二、填空题8.如图所示,已知空间四边形OABC ,其对角线为OB 、AC ,M 、N 分别为OA 、BC的中点,点G 在线段MN 上,且MG →=2GN →,若OG →=xOA →+yOB →+zOC →,则x ,y ,z 的值分别为________________.解析 ∵OG →=OM →+MG →=12OA →+23MN →=12OA →+23(ON →-OM →)=12OA →+23ON →-23OM → =12OA →+23×12(OB →+OC →)-23×12OA → =16OA →+13OB →+13OC → ∴x ,y ,z 的值分别为16,13,13.答案16,13,139. 设,x y ∈R ,向量()()()4,2,,1,1,-===c y b x a ,且c b c a //,⊥,则_______=+b a解析 2402,//(3,1)10242x x a c b c a b y y -==⎧⎧⊥⇔⇔⇒+=-=⎨⎨=-=-⎩⎩. 答案 1010.在平行六面体(即六个面都是平行四边形的四棱柱)ABCD -A′B′C′D′中,AB =1,AD =2,AA′=3,∠BAD =90°,∠BAA′=∠DAA′=60°,则AC′的长为________.解析 如图,AC′→=AB →+BC →+CC′→=AB →+AD →+AA′→,所以|AC′|=|AC′→|=|AB →+AD →+AA′→| =AB →2+AD →2+AA′→2+2AB →·AD →+AB →·AA′→+AD →·AA ′→=1+4+9+21×3×cos60°+2×3×cos60°=23.答案 2311.已知ABCD -A 1B 1C 1D 1为正方体,①(11A A +11A D +11A B )2=311A B 2;②1A C ·(11A B -11A A )=0;③向量1AD 与向量1A B 的夹角是60°;④正方体ABCD -A 1B 1C 1D 1的体积为|AB ·1AA ·AD |.其中正确命题的序号是________. 解析 由1AA ⊥11A D ,1AA ⊥11A B ,11A D ⊥11A B ⊥11A B ,得(1A A +11A D +11A B )2=3(11A B )2,故①正确;②中11A B -1A A =1AB ,由于AB 1⊥A 1C ,故②正确;③中A 1B 与AD 1两异面直线所成角为60°,但1AD 与1A B 的夹角为120°,故③不正确;④中|AB ·1AA ·AD |=0.故④也不正确. 答案 ①②12.如图,空间四边形OABC 中,OA =8,AB =6,AC =4,BC =5,∠OAC =45°,∠OAB =60°,则OA 与BC 所成角的余弦值等于________.X解析 设OA →=a ,OB →=b ,OC →=c .OA 与BC 所成的角为θ, OA →·BC →=a (c -b )=a ·c -a ·b =a ·(a +AC →)-a ·(a +AB →)=a 2+a ·AC →-a 2-a ·AB →=24-16 2.∴cos θ=|OA →·BC →||OA →|·|BC →|=24-1628×5=3-225.答案3-225三、解答题13.已知非零向量e 1,e 2不共线,如果AB =e 1+e 2,AC =2e 1+8e 2,AD =3e 1-3e 2,求证:A 、B 、C 、D 共面.证明 令λ(e 1+e 2)+μ(2e 1+8e 2)+v (3e 1-3e 2)=0. 则(λ+2μ+3v )e 1+(λ+8μ-3v )e 2=0. ∵e 1,e 2不共线,∴⎩⎨⎧λ+2μ+3v =0,λ+8μ-3v =0.易知⎩⎨⎧λ=-5,μ=1,v =1,是其中一组解,则-5AB +AC +AD =0. ∴A 、B 、C 、D 共面.14.如右图,在棱长为a 的正方体ABCD ­A 1B 1C 1D 1中,G 为△BC 1D 的重心, (1)试证A 1、G 、C 三点共线; (2)试证A 1C ⊥平面BC 1D ; (3)求点C 到平面BC 1D 的距离.解析 (1)证明 CA 1→=CB →+BA →+AA 1→=CB →+CD →+CC 1→,可以证明:CG →=13(CB →+CD →+CC 1→)=13CA 1→,∴CG →∥CA 1→即A 1、G 、C 三点共线.(2)证明 设CB →=a ,CD →=b ,CC 1→=c ,则|a |=|b |=|c |=a , 且a·b =b·c =c·a =0, ∵CA 1→=a +b +c ,BC 1→=c -a ,∴CA 1→·BC 1→=(a +b +c )·(c -a )=c 2-a 2=0, ∴CA 1→⊥BC 1→,即CA 1⊥BC 1,同理可证:CA 1→⊥BD →, 因此A 1C ⊥平面BC 1D .(3) ∵CA 1→=a +b +c ,∴CA 1→2=a 2+b 2+c 2=3a 2,即|CA 1→|=3a ,因此|CG →|=33a .即C 到平面BC 1D 的距离为33a .15.把边长为a 的正方形ABCD 沿对角线AC 折起成直二面角,点E 、F 分别是AD 、BC 的中点,点O 是原正方形的中心,求: (1)EF 的长;(2)折起后∠EOF 的大小.解析 如图,以O 点为原点建立空间直角坐标系O -xyz ,则A (0,-22a,0), B (22a,0,0),C (0,22a,0),D (0,0,22a ),E (0,-24a ,24a ),F (24a ,24a,0).(1)|EF →|2=⎝ ⎛⎭⎪⎫24a -02+⎝ ⎛⎭⎪⎫24a +24a 2+⎝ ⎛⎭⎪⎫0-24a 2=34a 2,∴|EF |=32a .(2)OE →=⎝ ⎛⎭⎪⎫0,-24a ,24a ,OF →=⎝ ⎛⎭⎪⎫24a ,24a ,0,OE →·OF →=0×24a +⎝ ⎛⎭⎪⎫-24a ×⎝ ⎛⎭⎪⎫24a +24a ×0=-a 28,|OE →|=a 2,|OF →|=a2,cos 〈OE →,OF →〉=OE →·OF→|OE →||OF →|=-12,∴∠EOF =120°.16.如图所示,已知空间四边形ABCD 的每条边和对角线长都等于1,点E ,F ,G 分别是AB 、AD 、CD 的中点,计算:(1)EF →·BA →; (2)EF →·DC →;(3)EG 的长; (4)异面直线AG 与CE 所成角的余弦值. 解析 设AB →=a ,AC →=b ,AD →=c . 则|a |=|b |=|c |=1,〈a ,b 〉=〈b ,c 〉=〈c ,a 〉=60°, (1)EF →=12BD →=12c -12a ,BA →=-a ,DC →=b -c , (2)EF →·BA →=⎝ ⎛⎭⎪⎫12c -12a ·(-a )=12a 2-12a·c =14,EF →·DC →=12(c -a )·(b -c )=12(b·c -a ·b -c 2+a·c )=-14;(3)EG →=EB →+BC →+CG →=12a +b -a +12c -12b=-12a +12b +12c ,|EG →|2=14a 2+14b 2+14c 2-12a·b +12b·c -12c·a=12,则|EG →|=22. (4)AG →=12b +12c ,CE →=CA →+AE →=-b +12a ,cos 〈AG →,CE →〉=AG →·CE→|AG →||CE →|=-23, 由于异面直线所成角的范围是(0°,90°],所以异面直线AG 与CE 所成角的余弦值为23.。

2014高考总复习物理力学经典习题精选(二)(含答案) (9)

2014高考总复习物理力学经典习题精选(二)(含答案) (9)

2014高考物理总复习力学经典习题精选(二)王鹏大连市物理名师工作室门贵宝1. 如图,A、B两物体用轻绳相连后跨过无摩擦的定滑轮,A物体在Q位置时处于静止状态。

若将A物体移到P位置仍处于静止状态,A物体由Q移到P后,作用于A物体上的力中增大的是( C )2、如下图所示,一定质量的物块用两根轻绳悬在空中,其中绳OA固定不动,绳OB在竖直平面内由水平方向向上转动,则在绳OB由水平转至竖直的过程中,绳OB的张力的大小将(B)A.一直变大 B.一直变小C.先变大后变小D.先变小后变大3.一轻杆BO,其O端用光滑铰链铰于固定竖直杆AO上,B端挂一重物,且系一细绳,细绳跨过杆顶A处的光滑小滑轮,用力F拉住,如图所示.现将细绳缓慢往左拉,使杆BO与杆AO间的夹角θ逐渐减小,则拉力F及杆BO所受压力FN的大小变化情况是( BD )4.如图所示,滑轮本身的质量可忽略不计,滑轮轴O安在一根轻木杆B上,一根轻绳AC绕过滑轮,A端固定在墙上,且绳保持水平,C端挂一重物,BO与竖直方向夹角θ=45°,系统保持平衡.若保持滑轮的位置不变,改变θ的大小,则滑轮受到木杆作用力大小变化情况是( D )5、如图所示,由物体A和B组成的系统处于静止状态.A、B的质量分别为mA和mB,且mA>mB.滑轮的质量和一切摩擦可不计。

使悬绳的悬点由P点向右移动一小段距离到Q点,系统再次达到静止状态。

当移动悬点后系统再次平衡时,B物体的位置( B )6、如图所示,物体用轻绳通过轻小且不计摩擦的滑轮悬挂起来,物体静止。

现将B点稍向左移一点,物体仍静止,则此时与原来相比(B )A.绳子拉力变大B.绳子拉力变小C.两侧绳子对滑轮的合力变大D.两侧绳子对滑轮的合力变小7、如图所示,一半球状物体在粗糙的水平面上,一只甲虫(可视为质点)从半球面的最高点开始缓慢往下爬行,在爬行过程中( BC )A.球面对甲虫的支持力变大B.球面对甲虫的摩擦力变大C.球面对甲虫的作用力不变D.地面对半球体的摩擦力变大8、如图所示,一物体放在斜面上处于静止状止状态。

2014届高考数学总复习(考点引领+技巧点拨)第三章 三角函数、三角恒等变换及解三角形第3课时三角函数图象

2014届高考数学总复习(考点引领+技巧点拨)第三章 三角函数、三角恒等变换及解三角形第3课时三角函数图象

《最高考系列 高考总复习》2014届高考数学总复习(考点引领+技巧点拨)第三章 三角函数、三角恒等变换及解三角形第3课时三角函数的图象和性质1. (必修4P 25练习2改编)函数f(x)=3sin ⎝ ⎛⎭⎪⎫x 2-π4,x ∈R 的最小正周期为________. 答案:4π解析:函数f(x)=3sin ⎝ ⎛⎭⎪⎫x 2-π4的最小正周期为T =2π12=4π. 2. (必修4P 39第2题改编)将函数y =sinx 的图象上所有的点向右平行移动 π10个单位长度,再把所得各点的横坐标伸长到原来的2倍(纵坐标不变),所得图象的函数解析式是____________________.答案:y =sin ⎝ ⎛⎭⎪⎫12x -π10 解析:∵ 向右平移π10个单位,∴ 用x -π10代替y =sinx 中的x ;∵ 各点横坐标伸长到原来的2倍,∴ 用12x 代替y =sin ⎝ ⎛⎭⎪⎫x -π10中的x ,∴ y =sin ⎝ ⎛⎭⎪⎫12x -π10.3. (必修4P 45第9题改编)如图,它表示电流I =Asin(ωt +φ)(A>0,ω>0)在一个周期内的图象,则I =Asin(ωt +φ)的解析式为________________.答案:I =3sin ⎝⎛⎭⎪⎫100π3t +π3解析:由图可知A =3,ω=100π3.代入⎝ ⎛⎭⎪⎫150,0和⎝ ⎛⎭⎪⎫120,0,解得φ=π3,于是I =3sin ⎝⎛⎭⎪⎫100π3t +π3.4. (必修4P 32练习6改编)函数y =cos ⎝ ⎛⎭⎪⎫2x -π4的单调递增区间是________.答案:⎣⎢⎡⎦⎥⎤-3π8+k π,π8+k π(k∈Z )解析:-π+2k π≤2x -π4≤2k π,即-3π8+k π≤x ≤π8+k π(k∈Z ),所求单调递增区间是⎣⎢⎡⎦⎥⎤-3π8+k π,π8+k π(k∈Z ).5. (必修4P 32第5题改编)函数y =2sinx ⎝ ⎛⎭⎪⎫π6≤x ≤2π3的值域是________.答案:[1,2]解析:根据正弦函数图象,可知x =π6时,函数取到最小值1;x =π2时,函数取到最大值2.1. 周期函数的定义周期函数的概念:对于函数y =f(x),如果存在一个不为零的常数T ,使得当x 取定义域内的每一个值时,f(x +T)=f(x)都成立,则称y =f(x)为周期函数;函数y =Asin(ωx +φ)和y =Acos(ωx +φ)的周期均为T =2π|ω|;函数y =Atan(ωx +φ)的周期为T =π|ω|2. 三角函数的图象和性质“五点法”作图原理:在确定正弦函数y =sinx 在[0,2π]上的图象形状时,起关键作用的五个点是(0,0)、 ⎛⎭⎪⎫π2,1、(π,0)、 ⎛⎭⎪⎫3π2,-1、 (2π,0).余弦函数呢?4. 函数 y =Asin(ωx +φ)的特征若函数y =Asin(ωx +φ) (A >0,ω>0,x ∈(-∞,+∞))表示一个振动量时,则A 叫做振幅,T =2πω叫做周期,f =1T叫做频率,ωx +φ叫做相位,φ叫做初相.[备课札记]题型1 依据三角函数的图象求解析式例1 (2013·南京三模)已知函数f(x)=2sin(ωx +φ)(ω>0)的部分图象如图所示,则ω=________.答案:23解析:由图象可知函数的四分之三周期为15π8-⎝ ⎛⎭⎪⎫-3π8=34T ,T =3π,ω=2π3π=23.变式训练已知函数y =Asin(ωx +φ)(A >0,ω>0,|φ|<π2)的部分图象如图所示,则ω=________.答案:3解析:由图知,A =2,将(0,2)、⎝ ⎛⎭⎪⎫π12,2代入函数,得⎩⎪⎨⎪⎧2sin ⎝ ⎛⎭⎪⎫π12w +φ=2,2sin φ=2,∴ ⎩⎪⎨⎪⎧φ=π4,ω=3.题型2 三角函数的图象变换例2 为了得到函数y =2sin ⎝ ⎛⎭⎪⎫x 3+π6(x∈R )的图象,只需把函数y =2sinx (x∈R )的图象上所有的点经过怎样的变换得到?解:y =2sinx 用6x p +代替x ,左移 6p个单位 y =2sin ⎝ ⎛⎭⎪⎫x +π6再用3p 代替x ,各点横坐标伸长到原来的3倍。

2014高考人民版历史总复习课件:专题7近代以来科学技术的辉煌

2014高考人民版历史总复习课件:专题7近代以来科学技术的辉煌

察与分类,研究生物的群体,故选 B 项。其他 A、C、D 都是 哈维的研究路线,只不过换个说法而已。 [答案] B
3. 用事实证明了人类不是上帝创造的,而是由古代的猿一 步步进化而来的科学家是 A.达尔文 C.拉马克 B.巴斯德 D.赫胥黎 ( )
[解析]
达尔文提出了人类起源于古猿的观点,但没有找
学的发展。
拉马克 。
(2)理论:生物是从低级向 高级 发展进化的,肯定环境对 物种变化的影响。 (3)意义:为达尔文创立 进化论 奠定了重要基础。
2.创立 (1)人物: 达尔文 (2)过程 ①经常参加讨论 。
拉马克
的进化思想的活动。
②1831 年,参加了“贝格尔”号军舰的环球考察,沿着
林耐 研究生物群体的方向前进,但得出了不同结论。
专题七 近代以来科学技术的辉煌
一、专题概术 本专题主要讲述世界近代以来影响世界发展的科学技术的 辉煌成就,主要内容有: 1. 近代物理学的奠基人和革命者, 是指牛顿和他的力学理 论,普朗克等人的量子理论、爱因斯坦及他的相对论。 2.人类追寻生命的起源,包括各种人类起源传说,近代生 命科学的成果,特别是达尔文的进化论,科学与宗教的分歧。
[解析] 哈维着重研究生物个体,运用解剖和实验的方法, 发现了血液循环理论,故选 B 项。
[答案] B
2.(名师原创)英国生物学家达尔文研究生物进化是沿着哪 条路线进行的 A.重视研究个体 C.运用解剖和实验 B.运用观察和分类 D.沿着哈维的路线 ( )
[解析]
达尔文是沿着林耐的路线进行研究的,主要用观
②施莱登提出 细胞 是一切植物结构的最基本单位。 ③施旺把施莱登的理论扩展到动物界,指出生命的共性是 细胞。二者共同创立了 细胞 和胚胎学奠定了基础。 学说。为比较解剖学、生理学

2014·新课标高考总复习·数学2-2函数的定义域和值域

2014·新课标高考总复习·数学2-2函数的定义域和值域

2.(2013 年唐山模拟)函数 y= 1-lgx+2的定义域为( A.(0,8] C.(-2,8] B.(2,8] D.[8,+∞)
)
解析:由题意可知,1-lg(x+2)≥0,整理得:lg(x+2)≤lg 10,∴
x+2≤10, 解得-2<x≤8,故函数 y= 1-lgx+2的定义域为(- x+2>0,
解析:根据解析式有意义的条件求解. 1 由题意,需 1-2x>0,解得 x<2.
1 故 f(x)的定义域为-∞,2.
1 答案:-∞,2
菜 单
隐 藏
2014 ·新课标高考总复习 ·数学(B ·理)
抓主干 双基知 能优化
研考向 要点知 识探究 悟真题 透析解 题策略 提素能 高效题 组训练
2 . y = ax2 + bx + c(a≠0) 的 值 域 是 : 当 a>0 时 , 值 域 为 ;当a<0时,值域为
3.y=(k≠0)的值域是 {y|y≠0} . 4.y=ax(a>0且a≠1)的值域是 {y|y>0} . 5.y=logax(a>0且a≠1)的值域是 R .
6.y=sin x,y=cos x的值域是 [-1,1] .
菜 单
隐 藏
2014 ·新课标高考总复习 ·数学(B ·理)
抓主干 双基知 能优化
研考向 要点知 识探究 悟真题 透析解 题策略 提素能 高效题 组训练
考向二 求已知函数的值域 [例 2] 求下列函数的值域. 1-x2 4 (1)y= ;(2)y=x+x (x<0); 1+x2 (3)f(x)=x- 1-2x .
2-x≥0, 2-x 解析: 要使函数 y= 有意义, 则 解得 x≤2 且 x≠1, x-1 x-1≠0,

学生-劳动经济学 (总复习2014)

学生-劳动经济学 (总复习2014)

第0章绪论一、名词解释1、劳动2、劳动力或劳动能力3、劳动经济学二、填空1、劳动经济学的研究对象是( )A.劳动资源的利用问题B.劳动资源的配置问题C.劳动资源的产生问题D.劳动资源的稀缺问题2、在市场经济中,劳动资源稀缺性的本质表现是()A.消费劳动资源的支付能力、支付手段的稀缺性B.劳动资源的相对稀缺性C.劳动资源的绝对稀缺性D.劳动资源的普遍稀缺性3、马克思认为,劳动力是存在于人体中的一种功能,体现为()A.每当人生产某种价值时就运用的体力和智力的总和B.每当人生产某种使用价值时就运用的体力和智力的总和C.每当人生产某种价值时就运用的情绪和思维的总和D.每当人生产某种使用价值时就运用的情绪和思维的总和三、判断1、劳动力是人所特有的一种能力。

()2、劳动力是存在于活的人体中的能力。

()3、劳动力是人在劳动中所运用的能力。

()4、劳动力是人在劳动中运用的体力和智力的总和。

()5、实证方法:解决“是什么”的方法,描述事物本来的面貌。

规范方法:解决“应该是什么问题”的方法,带有一定的价值判断。

价值尺度:互惠原则。

()6、劳动经济学与普通经济学有所不同,前者将问题的注意力投向了人们工作的范围,后者学主要是将人从消费者的角度加以观察和认识的。

()四、简答1、劳动经济学研究特点是什么?2、劳动经济学研究应注意的问题五、论述1、联系实际分析劳动经济学的重要性。

第一章劳动力需求一.名词解释1.劳动力2.劳动力需求3.短期劳动力需求4.长期劳动力需求5.劳动力需求弹性二.单项选择1.在其他生产要素不变时,由劳动投入增加引起的产量的变动可以分为()阶段。

A.一个B.两个C.三个D.四个2.工资上升对劳动力需求产生的影响可分解为替代效应和()。

A需求效应B派生效应C收入效应D规模效应3.在资本与劳动的比率既定的条件下,劳动的边际生产力与资本的边际生产力同比例上升,这样的技术进步称为()。

A.希克斯技术进步B.资本密集型技术进步C.劳动密集型技术进步D.要素密集型技术进步4.当劳动力的需求弹性大于1时,劳动力需求变动的百分比()工资变动的百分比。

2014C级注册验船师题库精华版资料

2014C级注册验船师题库精华版资料

注册验船师资格考试复习题C级科目1(法律法规)单选题1、海事管理机构在实施船舶安全检查过程中发现船舶技术状况存在重大缺陷且经安全检查人员初步判定认为与船舶检验质量有关的,所在直属海事局应在检查结束后()内将船舶安全检查通知书以传真或电子邮件方式抄送船籍港所在地直属海事局或船检管理处(由地方海事局登记的船舶)。

C、48小时2、对船舶检验质量的调查可采取哪些方式进行?A、实地调查或函件调查或两者结合进行3、哪些负责在本辖区内对船舶检验质量实施监督管理?D、各船检管理处、各直属海事局4、下列船舶在内河航行,可不向引航机构申请引航?B、500至1000总吨的海上机动船舶5、下列中国籍船舶,哪些可不向中国船级社申请入级检验?C、载重量500至1000吨的油船6、船舶进行下列活动,1、进行残油、含油污水、污染危害性货物残留物的接收作业,或者进行装载油类、污染危害性货物船舱的清洗作业;2、进行散装液体污染危害性货物的过驳作业;3、进行船舶水上拆解、打捞或者其他水上、水下船舶施工作业。

应当编制作业方案,采取有效的安全和防污染措施,并报作业地哪个机构批准?A、海事机构7、下列哪些情形的,可以注册验船师?C8、符合《暂行规定》第十条规定的基本要求,并具备相应级别报名条件的人员,均可参加相应类别注册验船师资格的考试。

下列哪些条件可报考C级验船师?C、取得工学类、理学类专业本科学历,从事船舶检验及其相关工作满1年。

9、《中华人民共和国行政许可法》规定除可以当场作出行政许可决定的外,行政机关应当自受理行政许可申请之日起()内作出行政许可决定。

这个期限内不能作出决定的,经本行政机关负责人批准,可以延长十日,并应当将延长期限的理由告知申请人。

但是,法律、法规另有规定的,依照其规定C、二十日10、哪级政府对行政法规设定的有关经济事务的行政许可,根据本行政区域经济和社会发展情况,认为通过本法第十三条所列方式能够解决的,报国务院批准后,可以在本行政区域内停止实施该行政许可。

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一、选择题1、C++对C语言作了很多改进,下列描述中()使得C语言发生了质变,从面向过程变成了面向对象。

A、增加了一些新的运算符;B、允许函数重载,并允许设置缺省参数;C、规定函数说明必须用原型;D、引进了类和对象的概念;2. 如果一个类X只有一个构造函数X(int),以下对象声明哪一个正确?( )a. X x;b.X x[5];c. X x(5);d. <X> x(5);3. 若一个类中定义成员,但没有显式规定其访问权限,其默认的权限是()。

A、privateB、publicC、protectedD、都不对4. 类的成员函数能够直接访问所在类中定义的成员为()。

A、只是数据成员B、只是函数成员C、数据成员和函数成员D、都不能5 有关构造函数说法不正确的是()A构造函数的名字和类的名字一样。

B 在创建对象时,系统自动调用构造函数C 构造函数无任何函数返回类型D构造函数有且只有一个6. 对于任意一个类,析构函函数的个数最多为()个。

A 0B 1C 2D 37()不是构造函数的特征。

A、构造函数应声明为公有函数,但它不能象其他成员函数被显示地调用.B、构造函数可以重载;C、构造函数可以设置缺省参数;D、构造函数必须指定返回类型说明。

8、下列关于析构函数说法不正确的是( )A、当撤销对象时,编译系统会自动调用析构函数B、析构函数的名字必须是类名前面加上一个波浪号~C、析构函数没有参数,也没有返回值,而且不能重载,因此一个类中只能有一个析构函数。

D、一个类必须定义析构函数,不能缺省。

9.下列静态数据成员的特性中,()是错误的。

A、说明静态数据成员时前边要加修饰符static;B、静态数据成员要在类体外进行初始化;C、静态数据成员不是所有对象所共用的;D、引用静态数据成员时,要在其名称前加<类名>和作用域运算符;10、关于new运算符的下列描述中,()是错误的。

A、它可以用来动态创建对象和对象数组;B、使用它创建的对象或对象数组可以使用运算符delete删除;C、使用它创建对象时要调用构造函数;D、使用它创建对象数组时必须指定初始值;11、派生类的对象对它的基类成员中()是可以访问的。

A、公有继承的公有成员;B、公有继承的私有成员;C、公有继承的保护成员;D、私有继承的公有成员;12、设置虚基类的目的是()。

A、简化程序;B、消除二义性;C、提高运行效率;D、减少目标代码;13、下列描述中,正确的是()A、虚函数是一个static 类型的成员函数;B、虚函数是一个非成员函数;C、抽象类是指具有纯虚函数的类;D、抽象类可以说明其对象;14、如果在基类中将show声明为不带返回值的纯虚函数,正确的写法是()A.virtual show()=0;B.virtual void show();C. virtual void show()=0;D.void show=0 virtual;15、下列关于纯虚函数与抽象类的描述中,错误的是()A.纯虚函数是一种特殊的函数,它允许没有具体的实现。

B.抽象类是指具有纯虚函数的类。

C.一个基类的说明中有纯虚函数,该基类的派生类一定不再是抽象类。

D.抽象类只能作为基类来使用,其纯虚函数的实现由派生类给出。

16、有关运算符重载正确的描述是()A.C++语言允许在重载运算符时改变运算符的操作个数B. C++语言允许在重载运算符时改变运算符优先级C. C++语言允许在重载运算符时改变运算符的结合性D. C++语言允许在重载运算符时改变运算符原来的功能17、能用友元函数重载的运算符是()A.+B.=C.[]D.->18、下列函数支持this指针的是( )A.类的构造函数与析构函数B.类中的友元函数C.类中的静态数据成员D.main()函数19、假设定义了模板template<class T>T max(T x,T y){return (x>y)?x:y;}并定义了int i;char c;错误的调用语句是():A.max(i,i);B. max(c,c);C. max((int)c,i);D. max(i,c);20、模板的使用是为了()A.提高代码的可重用性B.提高代码的运行效率C.加强类的封装性D.实现多态性21、基类A,派生类B私有继承了A,在B类中如要将A类的成员函数void print()访问声明为公有,则下列写法正确的是A.public: void A::print;B.public: A::print();C.public:void A::print();D.public:A::print;22、假设定义了模板template<class T>T max(T x,T y){return (x>y)?x:y;}并定义了int i;char c;错误的调用语句是():A.”max(i,i)”;B.”max(c,c);”;C. “max((int)c,i)”;D.”max(i,c)”;23、模板的使用是为了()A.提高代码的可重用性B.提高代码的运行效率C.加强类的封装性D.实现多态性二、判断下列描述的正确性,正确填T,错误填F。

1、C++中标识符内的大小写字母是没有区别的。

()2、使用关键字class定义的类中缺省的访问权限是私有(private)的。

()3、类的私有成员只能被类中的成员函数访问,任何类以外的函数对它们的访问都是非法的。

()4、多继承情况下,派生类的构造函数的执行顺序取决于成员初始化列表中的顺序。

()5、在公有继承中,基类中的公有成员和私有成员在派生类中都是可见的。

()6、在私有继承中,基类中所有成员对派生类都是不可见的。

()7、构造函数可以声明为虚函数。

()8、类(AA)中的友元类(BB)的所有成员函数可以存取或修改该类(AA)中的公有成员,不能存取或修改该类(AA)中的私有成员。

()9、对象、指向对象的指针及对象的引用都可以作函数参数,但使用对象引用作函数参数更普遍些。

()10、多重继承中处于同一层次的各个基类构造函数的执行顺序,取决于成员初始化列表的顺序而与声明派生类时所指定的各个基类的顺序无关。

( )11、构造函数不能是虚函数,但析构函数可以是虚函数。

( )12、基类的构造函数和析构函数不能被继承。

( )13、抽象类即可以建立普通对象,又可以建立抽象类的指针或引用,此指针可以指向它的派生类。

()14、若抽象类的派生类中没有重新说明纯虚函数,则这个派生类也是一个抽象类。

()三、填空题1.和C语言相比,C++是面向程序设计语言。

将数据和操纵数据的函数封装在一起的数据类型称作。

2. 非成员函数应声明为类的才能访问这个类的private成员。

3. c++中,表示公有的关键字是,表示保护的关键字是。

4. 在说明类的一个对象时,系统自动调用其。

5. 定义重载函数时,应在函数形参中的或有所不同。

6、假定AB为一个类,则执行“AB a[10];”语句时,系统自动调用该类的构造函数的次数为。

7、假定类AB中有一个私有属性的静态(static)数据成员int bb,在类外为其附初值为0的写法是。

8、A类私有继承B类的写法是。

9.含有纯虚函数的类称为。

10、是指用一个名字定义不同的函数,这些函数执行不同但又有类似的操作,即用同样的接口访问功能不同的函数,从而实现“一个接口,多种方法”。

11、函数实现了函数参数的通用性,作为一种代码的重用机制,可以大幅度地提高设计的效率。

12、类模板不代表一个具体的,实际的类,而代表着一类类。

四、程序完型1. 在下面的横线处填上适当的语句,使其输出结果为25,10。

using namespace std;class location{int X,Y;public:_void init(int k,int t);int getX(){return X;}int getY(){return Y;}};void location::init(int k,int t){X=k;Y=t;}void main(){location a;a.init(25,10);_cout<<a.getX()<<”,”<<a.getY()<<endl__; //输出对象a的数据成员X和Y的值}例2:在横线处填写合适的语句,完成类模板对平面上的点的初始化.template < class Type>class cpoint{private:Type x,y;public:void setpoint(Type a ,Type b );void show(){cout<<"x="<<x<<" y="<<y;} };template < class Type>void cpoint<Type>::setpoint(Type a,Type b ) {`x=a;y=b;}void main(){ int a=2,b=3;cpoint<int>op1;op1.setpoint(a,b);float p=2.2,q=3.3;cpoint <float> op2;op2.setpoint(p,q);}五、程序分析例1class Sample{public:int x,y;Sample(){x=y=0;}Sample(int a,int b){x=a;y=b;}void disp(){cout<<"x="<<x<<",y="<<y<<endl;}};void main(){Sample s1(2,3);s1.disp();}例2class A {public:int n;};class B: public A{};void main(){A a;B b;a.n=20;b.n=10;cout<< b.n <<","<< a.n<<endl;}例3class E{ int x;static int y;public:E(int a){x=a;y+=x;}void show() {cout<<x<<’,’<<y<<’\n’;} };int E::y=100;void main(){E e1(10),e2(50);e1.show();}A.50,160 B10,160 C50,110 D.10,110 例4以下程序的数据结果是( ){ static int i;public:void set(int x){i=x;}Sample(int i){this->i+=i;}static disp(){cout<< i;}};int Sample::i=100;void main(){ Sample s(10);Sample::disp();}A.20B.10C.120D.110例5以下程序输出结果是()#include “iostream.h”class A{ int x;public:static void setx(int a){x+=a;}A(int a){x=a;}void disp(){cout<<x;}};void main(){A a(10),b(20);A::setx(100);a.disp();}A.100B.110C.10D.程序有错误,不能编译例6以下程序执行的输出结果是(){ int A;static int B;public:Sample(int a){A=a;B+=a;}static void func(Sample &s);};void Sample::func(Sample &s){cout<<"A="<<s.A<<",B="<<B<<endl;} int Sample::B=0;void main(){Sample s1(2),s2(5);Sample::func(s1);Sample::func(s2);}例7以下程序执行的输出结果是()#include"iostream.h"class Sample{ int n;public: Sample(int i){n=i;}friend int add(Sample &s1,Sample &s2); };int add(Sample &s1,Sample &s2){return s1.n+s2.n;}void main(){Sample s1(10),s2(20);cout<<add(s1,s2)<<endl;}例8以下程序执行的输出结果是()#include"iostream.h"class A;class B{ int i;public: B(int x){i=x;}friend A;};class A{ int i;public: int set(B&);int get(){return i;}A(int x){i=++x;}};int A::set(B &b){return i+=b.i;}void main(){A a(1);B b(2);a.set(b);cout<<a.get()<<endl;}例9以下程序执行的输出结果是()#include"iostream.h"class B;class A{ int i;friend B;void disp(){cout<<i<<endl;}};class B{public: void set(int n) {A a;a.i=n;a.disp();}};void main(){B b;b.set(2);}例10class Appointment{public:Appointment() {}Appointment( char *b, int y, int m, int d );~Appointment();void display();private:char *what;int year, month, day;};Appointment::Appointment( char *b, int y, int m, int d ): year(y), month(m), day(d) { what= new char[50];strcpy(what, b);cout<<"constructor is called."<< endl;}Appointment::~Appointment(){ delete [] what;cout<<"destructor is called."<< endl;}void Appointment::display(){ cout<<what<< endl;cout<<year<<","<<month<<","<<day<< endl;}void main(){ Appointment jack("Good morning!" ,2005, 7, 6);jack.display();}例11class base {int n;public:base(){};base (int a) {cout << "constructing base class" << endl;n=a;cout << "n=" << n << endl; }~base() { cout << "destructing base class" << endl; } };class subs : public base{int m;public:subs(int a, int b) : base(a){ cout << "constructing sub class" << endl;m=b;cout << "m=" << m << endl;}~subs() { cout << "destructing sub class" << endl; } };void main (){ subs s(1,2); }例12class Food{ public: void eaten(){cout<<"can be eaten"<<endl;}};class rice:public Food{public: void eaten(){cout<<"rice can be cooked"<<endl;} };class flour:public Food{public: void eaten(){cout<<"flour can be toasted"<<endl;} };void show(Food *f){f->eaten();}void main(){ Food *ff;rice r1;flour f1;ff=&r1;show(&f1);show(ff);}flour can be toastedrice can be cooked例13class A{public:A() {cout<<"A's con."<<endl;}~A(){cout<<"A's des."<<endl; }};class B{public:B() {cout<<"B's con."<<endl;}~B(){cout<<"B's des."<<endl; }};class C:public A,public B{public:C():B(),A() {cout<<"C's con."<<endl;}~C(){cout<<"C's des."<<endl; }};void main(){C obj;}例14class Sample{int n;public:Sample(){}Sample (int m){n=m;}friend void square(Sample &s){s.n=s.n*s.n;}void disp(){cout<<"n="<<n<<endl;}};void main(){Sample a(10);square(a);a.disp();}例16class TStudent{ private: static int sc;public:TStudent(){ sc++;cout<<"Default constructor..."<<sc<<endl;}TStudent(TStudent &obj){ sc++;cout<<"Initialize copy constructor..."<<sc<<endl;} static int Sfun(){return sc;}~TStudent(){ sc--;cout<<"Destructor..."<<sc<<endl;}};int TStudent::sc=0;void main(){TStudent obj1;TStudent obj2(obj1);cout<<TStudent::Sfun()<<endl;}例17:下面的程序中虚函数被重新定义的方法正确么?为什么?class base{public:virtual int f(int a)=0;};class derived:public base{public:int f(int a,int b){return a*b;}}例18:程序运行结果:#include "iostream.h"class X{private:int xi;public:X(int i){xi=i;}X(){xi=0;}friend X operator++(X a);friend X operator--(X &a);void print(){cout<<xi<<endl;}X operator++(X a){++a.xi; return a;}X operator--(X &a){--a.xi; return a;}int main(){X I(7);(++I);I.print();--I;I.print();}例19、程序运行结果class base{protected:int a;public:base(int sa) {a=2;}};class base1:virtual public base{ public:base1(int sa):base(sa){a=a+5;}};class base2:virtual public base{ public:base2(int sa):base(sa){a=a+10;}};class derived:public base1,public base2 {public:derived(int sa):base(sa),base1(sa),base2(sa){cout<<base1::a<<endl;cout<<base2::a<<endl;}};int main(){ derived obj(2);}例20、程序运行结果template <class Type1,class Type2> class myclass{public:myclass(Type1 a,Type2 b){i=a;j=b;}void show(){cout<<i<<' '<<j<<'\n';} private:Type1 i;Type2 j;void main(){ myclass <int,double> ob1(10,0.23); myclass <char,char*> ob2('X',"This is a test"); ob1.show();ob2.show();}例21指出程序中的错误,说明原因template <class T>class Stack{public:Stack(int sz){}~Stack(){}void push(T x){}T pop(){}private:T *v;T *p;int size;};void main(){Stack aSt(5);aSt.push(10);}。

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