辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末联考地理试题
辽宁省沈阳市东北育才双语学校2013-2014学年高一下学期期中考试数学试题 Word版含答案
辽宁省沈阳市东北育才双语学校2013-2014学年高一下学期期中考试数学试题第Ⅰ卷一.选择题(本大题共12小题,每小题5分,在每小题给出的四个选项中,只有一项是符合题目要求的)1. 在ABC ∆中,内角A B 、、C 的对边分别为a b c 、、,︒=135A ,︒=30B ,2=a ,则b 等于( )A.1B.2C. 3D.2 2. 已知a b a <<,则以下不等式中恒成立的是( )A. b a <-B. 0ab >C. 0ab <D. a b <3.在ABC D中,若22sin 53,sin 2C b a ac A =-=,则cos B 的值为( ) A. 13 B. 12 C. 15 D. 144. 已知等差数列{}n a 的前n 项和n S ,若4518a a =-,则8S =( ) A.72 B. 68C. 54D. 905.若a b 、、c d x y 、、、是正实数,且P Q ==,则( ) A .P Q = B .P Q ³ C .P Q £ D .P Q >6.已知1230a a a >>>,则使得2(1)1(1,2,3)i a x i -<=都成立的x 的取值范围是( ) A. 11(0,)a B. 12(0,)a C. 31(0,)a D. 32(0,)a 7. 等比数列{}n a 中,若2a 、6a 是方程221180x x ++=的两根,则4a 的值为( ) A.2 B.2±D. 2-8. 设ABC ∆的内角,,A B C 所对的边分别为,,a b c ,若cos cos sin b C c B a A +=,则ABC ∆的形状为( )A .锐角三角形B . 直角三角形C .钝角三角形D .等腰三角形 9. 等差数列{}n a 的前n 项和n S ,满足2040S S =,则下列结论中正确的是( ) A .30S 是n S 中的最大值 B .30S 是n S 中的最小值C .300S =D .600S =11.若数列{}n a 满足*111(,n nd n N d a a +-= 为常数),则称数列{}n a 为“调和数列”,若正项数列1{}nb 为“调和数列”,且12990b b b +++=,则46b b 的最大值是( )A .10B .100C .200D .40012.已知0,0,x y x a b y >>、、、成等差数列x c d y 、、、、成等比数列,则2()a b cd+的最小的值是( )A .0B .1C .2D .4第Ⅱ卷二.填空题(本大题共4小题,每小题5分)13.在ABC ∆中,角B 所对的边长6b =,面积为15,外接圆的半径为5,则ABC ∆的周长为14.在ABC ∆中,A B C 、、的对边分别为a b c 、、,且b a c =+2,则B 的取值范围是________.15.数列{}n a 满足*12211131,333n n a a a n n N +++=+∈,则=n a .16.定义在(,0)(0,)-? 上的函数()f x ,如果对于任意给定的等比数列{}n a ,有(){}n a f 仍是等比数列,则称()f x 为“保等比数列函数”.现有定义在(,0)(0,)-? 上的如下函数:①()f x =2x ; ②()f x =x2; ③()x x f =; ④()f x =ln |x |,则其中是“保等比数列函数”的()f x 的序号为三.解答题(解答应写出文字说明,证明过程或验算步骤)18.已知正项数列{}n a 的前n 项和为n S ,且2*1(1)().4n n S a n N =+∈ (1)求1a 、2a ;(2)求证:数列{}n a 是等差数列;(3)令19n n b a =-,问数列{}n b 的前多少项的和最小?最小值是多少?19.解关于x 的不等式22(1)40()ax a x a R -++>∈.20.关于x 的方程220x ax b ++=的两根分别在区间(0,1)与(1,2)内,求21b a --的取值范围.21.如图,公园要把一块边长为2a 的等边三角形ABC 的边角地修成草坪,DE 把草坪分成面积相等的两部分,D 在AB 上,E 在AC 上.(1)设()AD x x a = ,DE y =,试用x 表示函数y ;(2)如果DE 是灌溉水管,希望它最短,D E 、的位置应该在哪里?22. 若数列{}n A 满足21n n A A +=,则称数列{}n A 为“平方递推数列”.已知数列{}n a 中,19a =,点1(,)n n a a +在函数2()2f x x x =+的图象上,其中n 为正整数.(1)证明数列{}1n a +是“平方递推数列”,且数列{}lg(1)n a +为等比数列; (2)设(1)中“平方递推数列”的前n 项积为n T ,即12(1)(1)(1)n n T a a a =+++,求lg n T ; (3)在(2)的条件下,记lg lg(1)nn n T b a =+,求数列{}n b 的前n 项和n S ,并求使4026n S >的n 的最小值.答题时间:120分钟 满分:150分 命题人:高一数学组 校对人:高一数学组 一. 选择题1-5 AADAC 6-10 BDBDD 11-12 BD 二. 填空题13. 14. (0,π3] 15. 112 13 1n n n a n +ì=ï=í>ïî16. ①③三.解答题17. 解:(1)由已知得到2sin sin A B B =,且(0,)sin 0sin 2B B A π∈∴≠∴=,且(0,)23A A ππ∈∴=; ……5分(2)由(1)知1cos 2A =,由已知得到222128362()3366433623b c bc b c bc bc bc =+-⨯⇒+-=⇒-=⇒=所以12823ABCS=⨯⨯=10分 18. 解:(1)由已知条件得:21111(1). 1.4a a a =+∴= 又有22122221(1).-2304a a a a a +=+-=即,解得221()=3a a =-舍或 (2)由21(1)4n n S a =+得2-1-112(1)4n n n S a ≥=+时:所以数列{}n a 是公差为2的等差数列。
辽宁省东北育才学校、省实验中学、大连(新疆部)三校2013-2014学年高一下学期期末联考生物试题【解析版】
【知识点】细胞中的元素。 【答案解析】D 解析:组成生物体的元素大体相同,不同生物体内各种化学元素含量差异较 大。 【思路点拨】理解生物体化学元素的统一性与差异性。 6.关于生物体内氨基酸的叙述错误的是( A.构成蛋白质的氨基酸分子的结构通式是 B.人体内氨基酸的分解代谢终产物是水、二氧化碳和尿素 C.人体内所有氨基酸均可以互相转化 D.两个氨基酸通过脱水缩合形成二肽 【知识点】细胞中的化合物。 【答案解析】C 解析:氨基酸根据是否在体内合成分为必需氨基酸和非必需氨基酸,其中 8 种必需氨基酸不能在体内合成,它们是亮氨酸、异亮氨酸、色氨酸、苏氨酸、苯丙氨酸、缬 氨酸、甲硫氨酸、赖氨酸。 【思路点拨】注意必需氨基酸与非必需氨基酸的区别。 7.细胞内结合水的生理作用是( ) )
辽宁省东北育才学校、省实验中学、大连二十高(新疆部) 三校 2013-2014 学年高一下学期期末联考生物试题
一、单选题(1-20 题,每题 1 分,21-40,每题 2 分,共 60 分) 1. 下列各组性状中,属于相对性状的是 ( A.兔的长毛和短毛 C.鸡的长腿和毛腿 B.玉米的黄粒与圆粒 D.马的白毛和羊的黑毛 )
【知识点】DNA 的分子结构。 【答案解析】A 解:在 DNA 结构中 A 与 T 配对,C 与 G 配对,一条链的 A 为 17%,C 为 22%, 另一条链的的 T 为 17%,G 为 22%,故 G+T=17%+22%=39%。 【思路点拨】理解碱基之间的配对关系。 22.下列各图,能正确表示显微镜下观察到的紫色洋葱表皮细胞质壁分离现象的是( )
【知识点】DNA 的分子结构。 【答案解析】C 解:病毒只有一种核酸 DNA 或 RNA,所以碱基数和核苷酸种类都为 4。 【思路点拨】理解病毒的核酸特点。 13.ATP 转化为 ADP 可表示如下:式中 X 代表( )
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二数学下学期期末联考理试题新人教A 版考试时间:120分钟 试题分数:150分卷I一、选择题(本大题共12小题,每小题5分,满分60分,每题四个选项中只有一项是符合题目要求的)1.3i 等于( ) A. -3i B .-32 i C . i D .-i2.用数学归纳法证明1+a +2a +…+1n a +=-211n a a+--(a ≠1,n ∈N *),在验证n =1成立时,左边的项是( )A .1B .1+aC .1+a +2a D .1+a +2a +4a3 在验证吸烟与否与患肺炎与否有关的统计中,根据计算结果,认为这两件事情无关的可能性不足1%,那么2K 的一个可能取值为( )A .6.635B .5.024C .7.897D .3.8414 在极坐标系中,以极点为坐标原点,极轴为x 轴正半轴,建立直角坐标系,点M (2,6π)的直角坐标是( )A .(2,1)B .(3,1)C .(1,3)D .(1,2)5.在一个投掷硬币的游戏中,把一枚硬币连续抛两次,记“第一次出现正面”为事件A ,“第二次出现正面”为事件B ,则P (B |A )等于( )A.12B.14C.16D.18 6.如图,阴影部分的面积是( )A .2 3B .2- 3 C.323 D.3537 我国第一艘航母“辽宁舰”在某次舰载机起降飞行训练中,有5架歼-15飞机准备着舰.如果甲、乙两机必须相邻着舰,而丙、丁两机不能相邻着舰,那么不同的着舰方法有( )A .12种B .18种C .24种D .48种8.81(3)x x+(n ∈N +)的展开式中含有常数项为第( )项A .4B .5C .6D .79. 口袋中有n (n ∈N *)个白球,3个红球.依次从口袋中任取一球,如果取到红球,那么继续取球,且取出的红球不放回;如果取到白球,就停止取球.记取球的次数为X .若P (X =2)=730,则n 的值为( )A .5B .6C .7D .810 有四辆不同特警车准备进驻四个编号为1,2,3,4的人群聚集地,其中有一个地方没有特警车的方法共________种.A .144 B.182 C.106 D.17011直线的参数方程为0sin 501cos50x t y t ⎧=-⎪⎨=-⎪⎩ (t 为参数),则直线的倾斜角为( ) A .040 B .050 C .0140 D .0130 12. 已知函数()f x =2xx ⋅,则下列结论正确的是( )A .当x =1ln2时()f x 取最大值B .当x =1ln2时()f x 取最小值C .当x =-1ln2时()f x 取最大值D .当x =-1ln2时()f x 取最小值卷II二、填空题 (本大题共4小题,每小题5分,共20分)13 在某项测量中,测量结果ξ服从正态分布N (1,σ2)(σ>0).若ξ在(0,1)内取值的概率为0.4,则ξ在(0,2)内取值的概率为________.14 复数z 满足方程(1)z i --+=4,那么复数z 在复平面内对应的点P 的轨迹方程____________ 15下列五个命题①任何两个变量都具有相关关系 ②圆的周长与该圆的半径具有相关关系 ③某商品的需求量与该商品的价格是一种非确定性关系 ④根据散点图求得的回归直线方程可能是没有意义的⑤两个变量间的相关关系可以通过回归直线,把非确定性问题转化为确定性问题进行研究 正确命题的序号为____________.16 古希腊毕达哥拉斯学派的数学家研究过各种多边形数。
东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二下学期期末联考语文试卷及答案
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二下学期期末联考考试时间:150分钟考试分数:150分卷Ⅰ阅读题一、现代文阅读(9分,每小题3分)阅读下面的文字,完成1-3题。
莫把汉学当国学慕朵生日前,美国著名汉学家史景迁携带《曹寅与康熙》等新书来华举办首发式,并在多所高校进行讲座,在学界和媒体引发新一轮“汉学热”。
但笔者以为,“汉学”当热,然不可将之混同为“国学”。
汉学是外国尤其是欧美国家学者研究和介绍中华文化的学问,历经游记性汉学、传教士汉学、学院派汉学,以及侧重研究中国现实问题的“中国学”等几大阶段,至今已有600多年历史。
面对中国浩瀚的文化和复杂的现实,汉学家们皓首穷经,著书立说,既促进了中华文化的海外传播,也带动了中外文化的交流融合,甚至改写了世界的文明进程。
比如,欧洲“启蒙运动”就深受来华传教士介绍的儒学的启迪。
不过.中国学界对汉学的追踪和介绍仅有100多年的历史,且忽冷忽热,不成系统。
其中,上个世纪二三十年代和八九十年代,国内曾分别兴起一股“汉学热”,原因是这两个时段中国社会变动剧烈。
思想争鸣活跃,国人迫切希望通过汉学来了解外国人是如何看待中国以及中华文化的。
此次史景迁访华引发的新一轮“汉学热”,则是在经济全球化和文化多样化时代背景下,国人试图借助汉学对自己国家崛起和文化复兴进行的一种心理上的印证和调适。
不难看出,汉学不仅是中华文化走向世界的桥梁,还是中华文化反观自身的镜子。
通过汉学,中华文化既能发现自己的优缺点、长短处,也能了解自己在世界文化生态中的方位和价值。
然而,汉学虽有重要价值,但亦不可无限拔高。
因为,汉学在本质上是一种“西学”,是西方人用西方价值观念、学术范式来研究中华文化的学问。
对汉学家而言,中华文化仅仅是学术研究的客观对象,就像实验室的试验品或博物馆的展览品一样,很难内在于自己的生命,灌注以自己的情感,更很少自有弘扬和光大的责任感。
但是,中国人注定做不了中华文化的旁观者。
东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末政治试题带答案
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末一、单项选择题(每题3分,共75分)1.国家是阶级矛盾不可调和的产物,由此可见国家的根本属性是A.主权性 B.阶级性 C.社会性 D.全民性2.我国是人民民主专政的社会主义国家,其本质是A.公民当家作主 B.人民当家作主C.无产阶级当家作主 D.农民阶级当家作主3.新一届人大代表选举即将开始,在我国公民选举所需经费均由政府开支;在选举期间,国家掌握的报刊、电视、广播等都为选举活动服务。
这一事实说明我国人民当家作主的权利有 A.制度的保障 B.法律的保障 C.物质的保障 D.政策的保障4.我国人民对台独分子的言论进行批判,这主要是在履行A.维护国家统一的义务 B.言论自由C.维护国家安全、荣誉和利益的义务 D.维护民族团结的义务5.在我国,是公民基本的民主权利,行使这个权利是公民参与管理国家和管理社会的基础和标志。
A. 选举权和被选举权B.政治自由C. 监督权D.言论权6.我国公民有权参与政治生活,但在参与政治生活时必须遵循①坚持公民在法律面前一律平等的原则②坚持权利与义务统一的原则③坚持民主集中制原则④坚持个人利益与集体利益、国家利益相结合的原则A.①②③ B.①②④ C.②③④ D.①③④7.结合右图,某乡在人大换届选举中,个别人用“小恩小惠”拉选票的行为,这会①危害社会主义民主政治建设②妨碍选民正确行使民主权利③破坏了国家统一和民族团结④违反选举法的有关规定A.①②③ B.①②④C.②③④ D.①③④8. “树和绿是城市的生命线,”原省委常委、南京市委书记朱善璐强调,重要决策一定要尊重民意。
公开征求社会意见,各界人士通过各种渠道发表意见建议210多万条,信件14000多封。
南京市政府这样做有利于A. 公民平等地参与国家管理B. 维护公民的提案权C. 引导公民积极参与民主选举D. 提高决策的科学性9.下列属于基层民主中公民直接参与的政治生活的重要形式的是①基层人民代表大会②村民自治③居民自治④基层政治协商会议A.①② B.①③ C.②③ D.①④10. 根据宪法规定,对于国家机关和工作人员的违法失职行为,公民行使的监督权的对象是A、政府及其工作人员 B、广大党员 C、政协委员 D、村委会组成人员11.专家学者利用自己掌握的专业知识、相关信息等,对专业性、技术性较强的重大事项进行分析论证,这是公民通过_____参与民主决策A.社情民意反映制度 B.专家咨询制度C.重大事项社会公示制度 D.社会听证制度12.我国政府的性质从根本上看是由决定的。
辽宁省实验中学分校2013-2014学年高一6月月考数学试题 Word版含答案
一、选择题:(每题5分,共计60分)
1.下列说法正确的是()
A.第二象限的角是钝角B.第三象限的角必大于第二象限的角
C.是第二象限的角D.
2.如果 ,,,那么 =()
A.B.C.D.
3.若 ,且 ,则 可以表示成()
A. B. C. D.
4.在△ABC中,已知 ,则此三角形的解的情况是( )
17.(1) (5分)(2) (10分)
18.(Ⅰ)在△ABC中,根据正弦定理, ,于是AB=
(Ⅱ)在△ABC中,根据余弦定理,得cosA=
于是sinA= 从而sin2A=2sinAcosA= ,cos2A=cos2A-sin2A=
所以sin(2A- )=sin2Acos -cos2Asin =
16.若 , , ,求
三、解答题:(共70分)
18.(满分12分)在△ABC中,BC= ,AC=3, .
(1)求AB的值;(2)求 的值。
19.(满分12分)
(1) 的周期为 ,求 的单调递增区间;
(2)若 的图像的一条对称轴为 ,求 的值。
21.(满分12分)已知△ABC的角A, B, C所对的边分别为 ,且 .
C.向左平移 个单位D.向右平移 个单位
9.已知 , ,则 ( )
A. B. C. D.
10.下列函数中,最小正周期是 的函数是( )
A. B.
C. D.
11.在△ABC中, ,(a,b,c分别为角A,B,C的对应边),则△ABC的形状为()
A.正三角形B.直角三角形C.等腰直角三角形D.等腰三角形
A.有一解B.有两解C.无解D.有解但解的个数不确定
东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末化学试题及答案联考
高一下学期期末联考化学试题考试时间:90分钟 试题分数:100分 命题人:廉丽丽Ⅰ卷一、 选择题(每题只有一个选项符合题意,每题2分,共10分 )1.下列对化学反应的认识错误的是( )A .会引起化学键的变化B .会产生新的物质C .必然引起物质状态的变化D .必然伴随着能量的变化2.下列有关化学用语使用正确的是 ( )A .硫原子的原子结构示意图:B .NH 4Cl 的电子式:C .原子核内有10个中子的氧原子:O 188D .乙烯的结构式为:CH 2=CH 23.一定量的锌粉和6mol ·L —1的过量盐酸反应,当向其中加入少量的下物质:①石墨 ②CuO ③铜粉 ④锌粒 ⑤浓盐酸 ⑥无水乙酸 ⑦KNO 3溶液 ⑧CuCl 2时,能够加快反应速率,又不响产生H 2总量的是 ( ) A.①③④ B.①③⑤ C.②④⑧ D.①⑤⑦4.XY 2是由短周期元素形成的化合物,Y -比X 2+多一个电子层,且与氩原子的电子层结构相 同。
下列有关叙述不正确的是( )A .X 是第二周期元素B .Y 是第ⅦA 族元素C .Y -与X 2+的最外层电子数相同 D .化合物XY 2的化学键为离子键 5.下列关于苯的性质的叙述中,不正确的是( ) A .苯是无色带有特殊气味的液体B .常温下苯是一种不溶于水且密度小于水的液体C .苯在一定条件下能与溴发生取代反应D .苯不具有典型的双键结构,故不可能发生加成反应二、 选择题(每题只有一个选项符合题意,每题3分,共54分 ) 6.关于元素周期表,下列叙述中不正确的是 ( )A .在金属元素与非金属元素的分界线附近可以寻找制备半导体材料的元素B .在过渡元素中可以寻找制备催化剂及耐高温和耐腐蚀的元素C .在非金属元素区域可以寻找制备新型农药材料的元素D .在地球上元素的含量的分布和它们在元素周期表中的位置有密切关系 7.下列有关电池的说法不正确的是 ( )A.手机上用的锂离子电池属于二次电池B.铜锌原电池工作时,电子沿外电路从铜电极流向锌电极C.甲醇燃料电池可把化学能转化为电能D.锌锰干电池中,锌电极是负极8.某烷烃的相对分子质量为86,与氯气反应生成的一氯代物只有两种,其结构简式是()A.CH3(CH2)4CH3B.(CH3)2CHCH(CH3)2C.(C2H5)2CHCH3D.C2H5C(CH3)39.下列除杂方法(括号内为杂质)操作正确的是()A.乙醇(水) 加新制的生石灰,过滤B.乙烷(乙烯) 通过溴的四氯化碳溶液,洗气C.溴苯(苯) 加水,振荡静置后分液D.乙酸乙酯(乙酸) 加饱和NaHCO3溶液,振荡静置后分液10.把下列四种X溶液分别加入四个盛有10mL 2mol·L-1盐酸的烧杯中,均加水稀释到50mL,此时X和盐酸缓缓地进行反应.其中反应速率最大的是( )A.20mL3mol·L-1的X溶液B.20mL2mol·L-1的X溶液C.10mL4mol·L-1的X溶液D.10mL2mol·L-1的X溶液11.在一定条件下的密闭容器中,一定能说明反应A(g)+3B(g) 2C(g)+2D(g)达到平衡状态的是()A.反应体系的总压恒定 B.B的浓度不变C.C(A):C(B)=1 : 3 D.每生成3mol的B同时生成1mol的A12.下列事实不能..作为实验判断依据的是()A.钠和镁分别与冷水反应,判断金属活动性强弱B.在MgCl2与AlCl3溶液中分别加入过量的氨水,判断镁与铝的金属活动性强弱C.硫酸与碳酸的酸性比较,判断硫与碳的非金属活动性强弱D.Br2与I2分别与足量的H2反应,判断溴与碘的非金属活动性强弱13.根据下表信息,判断以下叙述正确的是()A.氢化物的沸点为H 2T<H 2RB.单质与盐酸反应的速率为L<QC.M 与T 形成的化合物具有两性D.L 2+与R 2-的核外电子数相等14.阿波罗宇宙飞船上使用的是氢-氧燃料电池,其电极总反应式为:2H 2+O 2=2H 2O ;电解质溶液为KOH 溶液,下列叙述正确的是 ( )A . 此电池能见到浅蓝色火焰B . H 2为正极,O 2为负极C .工作时电解液的pH 不断增大D .电极反应为: 正极 O 2+2H 2O +4e -=4OH -15. 关于氢键的说法,下列不正确的是( )A. HF 的沸点比HCl 的沸点高,是由于HF 分子间存在氢键作用B. H 2O 加热到很高温度都难以分解,是因为水分子间有氢键作用C. 水在结冰时体积膨胀,是由于水分子间存在氢键作用D.在氨水中水分子和氨分子之间也存在着氢键16.某有机物的结构简式如右下图, 该有机物不.可能具有的性质是( ) A .能与溴水发生氧化反应,使溴水褪色 B .能使酸性KMnO 4溶液褪色 C .能发生聚合反应 D .能发生酯化反应17.已知苯与一卤代烷在催化剂作用下可生成苯的同系物:在催化剂存在下,由苯和下列各组物质合成乙苯最好应选用的是 ( )A .CH 3CH 3 和l 2B .CH 2=CH 2和HClC .CH 2=CH 2和Cl 2D .CH 3CH 3和HCl18.山梨酸是一种常见的食物添加剂,它是一种无色针状晶体或白色粉末,它的结构简式为 CH 3—CH=CH —CH=CH —COOH 。
辽宁省东北育才学校、省实验中学、大连二十高新疆部三校最新高二下学期期末联考生物试题
卷I一.单项选择题(本题共40小题,1—20每题1分,21—40每题2分,共60分)1.黄曲霉毒素是毒性极强的致癌物质。
有关研究发现它能引起细胞中的核糖体不断从内质网上脱落下来。
这一结果直接导致( )A.染色体被破坏 B.高尔基体被破坏C. 中心体被破坏 D.分泌蛋白的合成受到影响2.植物细胞发生质壁分离的原因有( )①外界溶液浓度大于细胞液浓度②细胞液浓度大于外界溶液浓度③细胞壁的伸缩性大于原生质层的伸缩性④原生质层的伸缩性大于细胞壁的伸缩性A. ②④ B.①④ C.②③ D. ③④3。
在人体细胞中除了细胞核外,以下哪个结构里还含有DNA( )A.线粒体 B. 叶绿体 C. 核糖体 D. 液泡4.下列选项中,属于动植物细胞共有的糖类是( )A.葡萄糖、核糖、脱氧核糖 B. 麦芽糖、糖原和果糖C. 淀粉、脱氧核糖、纤维素D. 麦芽糖、果糖、乳糖5.在处理污水时,人们设计出一种膜结构,将有毒重金属离子阻挡在膜的一侧,以降低有毒重金属对水的污染,这是模拟了生物膜的()A. 单纯扩散功能B. 流动性C.主动运输功能D. 选择透过性6。
下列有关组成生物体化学元素的论述,正确的是( )A.组成生物体和组成无机自然界的化学元素中,碳元素的含量最多B. 人、动物与植物所含的化学元素的种类差异很大C. 组成生物体的化学元素在无机自然界都可以找到D. 不同生物体内各种化学元素的含量比例基本相似7. 代谢旺盛的细胞中,下列哪一项不会上升( )A.线粒体数量B.细胞核内DNA含量 C.蛋白质的合成量 D.核糖体数量8. 关于细胞生理过程的描述,正确的是()A.活细胞在高浓度溶液中都会发生质壁分离B.蓝藻因没有叶绿体,所以不进行光合作用C. 人的红细胞成熟后,仍继续合成蛋白质D.核孔实现核质之间的物质交换和信息交流9。
用呼吸抑制剂处理红细胞,其对下列物质吸收量显著减少的是( )A. 乙醇和苯B. O2和H2OC. K+和氨基酸D. CO2和O210。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末联考英语试题
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末联考英语试题考试时间:120分钟试题分数:150分第I卷(选择题,共85分)第二部分阅读理解(共两节,满分40分)第一节阅读理解(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出一个最佳选项。
AChildren are our future, and i t’s up to us to arm them with the tools to succeed. Sadly, today’s children are being armed with more dangerous tools like weapons (武器), drugs and gangs. Once a relatively peaceful environment, many schoolyards of today are becoming unsafe for both students and teachers.Home schools are available to give you choices. Home schooling provides top-quality education, flexibility, and freedom to create your own schedule (日程表). At Heritage Home School we believe the choice should be yours.Thanks in part to modern technology, home schooling information is becoming readily available across our nation. A recent study by the ITBS(Iowa Tests of Basic Skills)and TAP (Tests of Achievement and Proficiency)shows us that students of home schools do particularly well when compared with the nationwide average. In every subject at every grade level, students of home schooling scored obviously higher than those in public and private schools.If you’re new to home schooling, you may be asking yourself, “Will home schools real ly work for my children? ”Fact: A nationwide study using a random(任意)selection of 1,516 families found students of home schooling to be scoring, on average, at or above the 80th percentile in all areas on standardized achievement test.Note: The national average on standardized achievement tests is the 50th percentile.Collectively, the staff(全体职员)at Heritage Home School brings 65 years of experience in home schooling curriculum(全部课程). We’ve placed students in the top 2% of the nation in math and many are successfully moving on to college.One study found that of the home schooled adults, 2% were unemployed, 2% were on welfare(福利)and 94% said home education prepared them to be independent persons.For more home schooling information, call us today toll free at 1(877)532-7665.1. We can learn from the first paragraph that _______.A. many schools armed their students with weaponsB. violence and crime exist in many schoolyardsC. students use weapons to defend their schoolyardsD. weapons are more dangerous than drugs2. All of the following are true of home schools EXCEPT that _______.A.students are free to choose their coursesB. students do well in important national testsC. they help students find jobsD. they help students to be independent3. What is the purpose of the text?A. To give information about different schools.B. To compare home schools with other schools.C. To suggest a new method of school education.D. To persuade people to choose home schools.4. The advertisement is mainly aimed at _______.A. studentsB. parentsC. teachersD. adults5. Students of home schooling get higher scores than those in public and private schools____ .A. in some subjects at every grade levelB. in part subjects at every grade levelC. in few subjects at every grade levelD. in all subjects at every grade levelBInvention of TV began in 1922 in Rigby, Idaho, the hometown of Philo. At the age of 16, Philo was a very shy boy. Only his teacher, Justin Tolman, realized that Philo was a special person.One day after school Mr Tolman found Philo in the schoolroom. The boy was making drawings on the blackboard.“What are you doing?” Mr Tolman asked with interest. “What are these drawings?”“I want to invent things,” Philo answered, “and these are the dra wings of one of my first inventions. I have an idea for a way of sending pictures through the air. Please, just let me tell you about it. You are the only person who can understand what I have done.” In the school library Philo had read about a man who had worked on an idea for TV, but had failed. Philo was sure that his idea was better and that he could succeed.Mr Tolman was not sure and asked Philo many questions about the drawings. Giving facts and figures, Philo answered every question.In 1926, Philo sent his drawings to Washington, along with a letter asking for patent (专利)rights on TV. Since then, television has become an important business all over the world.6. When he lived in his hometown, Philo was _____________.A. quite different from othersB. an activity boyC. an inventorD. a hard-working boy7. When Philo said “ You are the only person who can understand what I have done.”, hismood(情绪)was_________.A. discouragedB. guilty (内疚的)C. trustingD. hopeless8. It took Philo ________ to invent the television.A. 2 yearsB. 4 yearsC. 6 yearsD. 8 years9. Philo ________ after he invented television.A. asked for the patent rights on televisionB. sent his drawings to Mr TolmanC. answ ered Mr Tolman’s questionsD. gave facts and figures to Mr Tolman10. When Mr Tolman saw Philo’s dra wings, he ______________.A. did not believe it was Philo’s inventionB. believed Philo could succeedC. did not believe Philo could succeedD. believed Philo was a special personC“It hurts me more than you,” and “This is for your own good.” These are the statements my mother used to make years ago when I had to learn Latin, clean my room, stay home and do homework..That was before we entered the permissive period in education in which we decided it was all right not to push our children to achieve their best in school.The schools and the educators made it easy on us. They taught that it was all right to be parents who take a let-alone policy. We stopped making our children do homework. We gave them calculators(计算器), turned on the television, left the teaching to the teachers and went on vacation.Now teachers, faced with children who have been developing at their pace for the past 15 years, are realizing we’ve made a terrible mistake. One such teacher is Sharon Klompus who says of her students ----- “so passive” ----- and wonders what happened. Nothing was demanded of them, she believes. Television, says Klompus, contributes to chil dren’s passivity; “We’re not training kids to work any more.” says Klompus. “We’re talking about a generation of kids who’ve never been hurt or hungry. They have learned somebody will always do it for them. Instead of saying go look it up, you tell them th e answer. It takes greater energy to say no to a kid.”Yes, it does. It takes energy and it takes work. It’s time for parents to end their vacation and come back to work. It’s time to take the car away, to turn the TV off, to tell them it hurts you more than them but it’s for their own good, It’s ti me start telling them no again.11. By “permissive period of education” the author means an age ______.A. when children are allowed to do what they wish to.B. when everything can be taught in schoolsC. when every child can be educated.D. when children are permitted to receive education.12. We learn from the passage that th e author’s mother used to connect importance with _____A. learning LatinB. natural developmentC. disciplineD. school education13 According to the passage, children are growing inactive in study mainly because _____.A. they watch TV too oftenB. their parents leave them aloneC. their teachers are strict with themD. they take on too many duties14.To today’s kids as described in this passage,_____.A. it is easier to give a negative(否定的)reply than to give a positive(肯定的) replyB. it is easier to give a positive reply than to give a negative replyC. neither is easy —to say yes or to say noD. neither is no easy job —to say yes or to say no15.The main idea of this passage is that _____.A. parents should set a good example for their kidsB. kids should have more activities outside campus(校园)C. educators should not he so permissiveD. it is time to be strict with our children第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项,并在答题卡上将该项涂黑。
2013-2014学年辽宁省东北育才学校、省实验中学、大连二十中(新疆部)三校联考高二(下)期末数学试卷(文
2013-2014学年辽宁省东北育才学校、省实验中学、大连二十中(新疆部)三校联考高二(下)期末数学试卷(文科)一、选择题:(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.(5分)已知集合A={0,1,2,3},B={x|x2﹣x=0},则集合A∩B=()A.{0}B.{1,2,3}C.{0,1}D.{1}2.(5分)“x=2”是“log2|x|=1”的()A.充分不必要条件 B.必要不充分条件C.充分必要条件D.既不充分也不必要条件3.(5分)函数y=的定义域为()A.(﹣∞,2)B.(2,+∞)C.(2,3)∪(3,+∞)D.(2,4)∪(4,+∞)4.(5分)下列函数中,既是偶函数又在区间(0,+∞)上单调递减的是()A.B.y=e﹣x C.y=lg|x|D.y=﹣x2+15.(5分)命题“对任意x∈R,都有x2≥0”的否定为()A.对任意x∈R,都有x2<0 B.不存在x∈R,都有x2<0C.存在x0∈R,使得x02≥0 D.存在x0∈R,使得x02<06.(5分)曲线(t为参数)与坐标轴的交点是()A.(0,)、(,0)B.(0,)、(,0)C.(0,﹣4)、(8,0)D.(0,)、(8,0)7.(5分)已知函数f(x)为奇函数,且当x>0时,f(x)=x2+,则f(﹣1)=()A.2 B.1 C.0 D.﹣28.(5分)点P的直角坐标为(1,﹣),则点P的极坐标为()A.(2,)B.(2,)C.(2,﹣) D.(﹣2,﹣)9.(5分)如图,PA是⊙O的切线,A为切点,PC是⊙O的割线,且PB=BC,则等于()A.2 B.C.1 D.10.(5分)方程log2(x+4)=2x的根的情况是()A.仅有一根B.有两个正根C.有一正根和一个负根D.有两个负根11.(5分)函数f(x)=ln(x2+1)的图象大致是()A.B.C.D.12.(5分)已知函数f(x)是定义在R上的偶函数,且在区间[0,+∞)上单调递增,若实数a满足f(log 2a)+f(a)≤2f(1),则a的取值范围是()A. B.[1,2]C. D.(0,2]二、填空题(共10小题,满分90分)13.(5分)已知f(x)=,则f(f(f(﹣2)))的值为.14.(5分)在平面直角坐标系xOy中,若直线(s为参数)和直线(t为参数)平行,则常数a的值为.15.(5分)函数f(x)=()的单调递减区间为.16.(5分)计算:=.17.(10分)如图,EB、EC是圆O的两条切线,B、C是切点,A、D是圆上两点,如果∠E=46°,∠DCF=32°,求∠A的度数.18.(12分)设集合M={x|ax2﹣2x+2=0,x∈R}至多有一个元素,求实数a的取值范围.19.(12分)已知函数f(x)=b•a x(其中a,b为常量且a>0,a≠1)的图象经过点A (1,6),B(3,24).(1)试确定f(x).(2)若不等式()x+()x﹣m≥0在x∈(﹣∞,1]时恒成立,求实数m的取值范围.20.(12分)设f(x)=log a(1+x)+log a(3﹣x)(a>0,a≠1),且f(1)=2.(1)求a的值及f(x)的定义域.(2)求f(x)在区间[0,]上的最大值.21.(12分)已知曲线C1的参数方程为(t为参数),以坐标原点为极点,x轴的正半轴为极轴建立极坐标系,曲线C2的极坐标方程为ρ=2sinθ.(1)把C1的参数方程化为极坐标方程;(2)求C1与C2交点的极坐标(ρ≥0,0≤θ<2π).22.(12分)已知定义域为R的函数f(x)=是奇函数.(1)求a,b的值;(2)用定义域证明f(x)在(﹣∞,+∞)上为减函数;(3)若对于t∈R,不等式f(t2﹣2t)+f(2t2﹣k)<0恒成立,求k的范围.2013-2014学年辽宁省东北育才学校、省实验中学、大连二十中(新疆部)三校联考高二(下)期末数学试卷(文科)参考答案与试题解析一、选择题:(本大题共12小题,每小题5分,共60分.在每小题给出的四个选项中,只有一项是符合题目要求的)1.(5分)已知集合A={0,1,2,3},B={x|x2﹣x=0},则集合A∩B=()A.{0}B.{1,2,3}C.{0,1}D.{1}【解答】解:∵集合A={0,1,2,3},B={x|x2﹣x=0}={0,1},∴集合A∩B={0,1}.故选:C.2.(5分)“x=2”是“log2|x|=1”的()A.充分不必要条件 B.必要不充分条件C.充分必要条件D.既不充分也不必要条件【解答】解:当x=2时,log2|x|=1成立,即充分性成立,若log2|x|=1,则x=±2,即必要性不成立.故“x=2”是“log2|x|=1”的充分不必要条件,故选:A.3.(5分)函数y=的定义域为()A.(﹣∞,2)B.(2,+∞)C.(2,3)∪(3,+∞)D.(2,4)∪(4,+∞)【解答】解:要使原函数有意义,则,解得:2<x<3,或x>3所以原函数的定义域为(2,3)∪(3,+∞).故选C.4.(5分)下列函数中,既是偶函数又在区间(0,+∞)上单调递减的是()A.B.y=e﹣x C.y=lg|x|D.y=﹣x2+1【解答】解:A中,y=为奇函数,故排除A;B中,y=e﹣x为非奇非偶函数,故排除B;C中,y=lg|x|为偶函数,在x∈(0,1)时,单调递减,在x∈(1,+∞)时,单调递增,所以y=lg|x|在(0,+∞)上不单调,故排除C;D中,y=﹣x2+1的图象关于y轴对称,故为偶函数,且在(0,+∞)上单调递减,故选D.5.(5分)命题“对任意x∈R,都有x2≥0”的否定为()A.对任意x∈R,都有x2<0 B.不存在x∈R,都有x2<0C.存在x0∈R,使得x02≥0 D.存在x0∈R,使得x02<0【解答】解:因为全称命题的否定是特称命题,所以命题“对任意x∈R,都有x2≥0”的否定为.存在x0∈R,使得x02<0.故选D.6.(5分)曲线(t为参数)与坐标轴的交点是()A.(0,)、(,0)B.(0,)、(,0)C.(0,﹣4)、(8,0)D.(0,)、(8,0)【解答】解:当x=0时,t=,而y=1﹣2t,即y=,得与y轴交点为(0,);当y=0时,t=,而x=﹣2+5t,即x=,得与x轴的交点为(,0).故选B.7.(5分)已知函数f(x)为奇函数,且当x>0时,f(x)=x2+,则f(﹣1)=()A.2 B.1 C.0 D.﹣2【解答】解:∵已知函数f(x)为奇函数,且当x>0时,f(x)=x2+,则f(﹣1)=﹣f(1)=﹣(1+1)=﹣2,故选D.8.(5分)点P的直角坐标为(1,﹣),则点P的极坐标为()A.(2,)B.(2,)C.(2,﹣) D.(﹣2,﹣)【解答】解:∵点P的直角坐标为(1,﹣),∴ρ==2,再由1=ρcosθ,﹣=ρsinθ,可得θ=﹣,故点P的极坐标为(2,﹣),故选C.9.(5分)如图,PA是⊙O的切线,A为切点,PC是⊙O的割线,且PB=BC,则等于()A.2 B.C.1 D.【解答】解:设PB=x,则BC=2x,PC=PB+BC=3x,根据圆的切割线定理,得到PA2=PB•PC即PA2=x•3x=3x2,∴PA=x,∴=.故选D.10.(5分)方程log2(x+4)=2x的根的情况是()A.仅有一根B.有两个正根C.有一正根和一个负根D.有两个负根【解答】解:采用数形结合的办法,画图:y1=log2(x+4),y2=2x的图象,画出图象就知,该方程有有一正根和一个负根,故选C.11.(5分)函数f(x)=ln(x2+1)的图象大致是()A.B.C.D.【解答】解:∵x2+1≥1,又y=lnx在(0,+∞)单调递增,∴y=ln(x2+1)≥ln1=0,∴函数的图象应在x轴的上方,又f(0)=ln(0+1)=ln1=0,∴图象过原点,综上只有A符合.故选:A12.(5分)已知函数f(x)是定义在R上的偶函数,且在区间[0,+∞)上单调递增,若实数a满足f(log 2a)+f(a)≤2f(1),则a的取值范围是()A. B.[1,2]C. D.(0,2]【解答】解:因为函数f(x)是定义在R上的偶函数,所以f(a)=f(﹣log 2a)=f(log2a),则f(log 2a)+f(a)≤2f(1)为:f(log2a)≤f(1),因为函数f(x)在区间[0,+∞)上单调递增,所以|log2a|≤1,解得≤a≤2,则a的取值范围是[,2],故选:A.二、填空题(共10小题,满分90分)13.(5分)已知f(x)=,则f(f(f(﹣2)))的值为4.【解答】解:根据题意,∵f(x)=,∴f(﹣2)=0;f(0)=2,f(2)=22=4;∴f(f(f(﹣2)))=4.故答案为:4.14.(5分)在平面直角坐标系xOy中,若直线(s为参数)和直线(t为参数)平行,则常数a的值为4.【解答】解:直线l1的参数方程为(s为参数),消去s得普通方程为x﹣2y﹣1=0,直线l2的参数方程为(t为参数),消去t得普通方程为2x﹣ay﹣a=0,∵l1∥l2,x﹣2y﹣1=0的斜率为k1=,∴2x﹣ay﹣a=0的斜率k2==,解得:a=4.故答案为:4.15.(5分)函数f(x)=()的单调递减区间为(﹣∞,﹣2] .【解答】解:设t=﹣x2﹣4x+3,则y=()t,为减函数,则要求函数f(x)的单调减区间,则只需求t=﹣x2﹣4x+3的增区间,∵二次函数的对称轴x=,∴t=﹣x2﹣4x+3的增区间为(﹣∞,﹣2],故答案为:(﹣∞,﹣2].16.(5分)计算:=1.【解答】解::==2﹣3++=1.故答案为1.17.(10分)如图,EB、EC是圆O的两条切线,B、C是切点,A、D是圆上两点,如果∠E=46°,∠DCF=32°,求∠A的度数.【解答】解:∵EB、EC是圆O的两条切线,∴EB=EC又∵∠E=46°,∴∠ECB=∠EBC=67°又∵∠DCF=32°∴∠BCD=81°又由圆内接四边形对角互补∴∠A=180°﹣81°=99°18.(12分)设集合M={x|ax2﹣2x+2=0,x∈R}至多有一个元素,求实数a的取值范围.【解答】解:①当a=0时,﹣2x+2=0,解得:x=1,即M={1},成立.②当a≠0时,△≤0,即4﹣8a≤0,a≥.综上所述:a=0或a.19.(12分)已知函数f(x)=b•a x(其中a,b为常量且a>0,a≠1)的图象经过点A (1,6),B(3,24).(1)试确定f(x).(2)若不等式()x+()x﹣m≥0在x∈(﹣∞,1]时恒成立,求实数m的取值范围.【解答】解:(1)将A(1,6),B(3,24)代入f(x)=b•a x得6=ab,24=ba3,解得a=2,b=3.(2)∵()x+()x﹣m≥0在x∈(﹣∞,1]时恒成立,∴m≤()x+()x在x∈(﹣∞,1]时恒成立,∴m≤[()x+()x]min x∈(﹣∞,1],令f(x)=()x+()x x∈(﹣∞,1],任取x1<x2≤1,则f(x1)﹣f(x2)=①∵在R上是减函数,∴,(,∴①式>0,∴f(x1)>f(x2)∴f(x)在(﹣∞,1]上是减函数,f(x)min=f(1)=,∴m≤.20.(12分)设f(x)=log a(1+x)+log a(3﹣x)(a>0,a≠1),且f(1)=2.(1)求a的值及f(x)的定义域.(2)求f(x)在区间[0,]上的最大值.【解答】解:(1)∵f(x)=log a(1+x)+log a(3﹣x)(a>0,a≠1),∴f(1)=log a2+log a2=2log a2=2,∴a=2;∴f(x)=log2(1+x)+log2(3﹣x),∴,解得﹣1<x<3;∴f(x)的定义域是(﹣1,3).(2)∵f(x)=log2(1+x)+log2(3﹣x)=log2(1+x)(3﹣x)=log2[﹣(x﹣1)2+4],且x∈(﹣1,3);∴当x=1时,f(x)在区间[0,]上取得最大值,是log24=2.21.(12分)已知曲线C1的参数方程为(t为参数),以坐标原点为极点,x轴的正半轴为极轴建立极坐标系,曲线C2的极坐标方程为ρ=2sinθ.(1)把C1的参数方程化为极坐标方程;(2)求C1与C2交点的极坐标(ρ≥0,0≤θ<2π).【解答】解:(1)将,消去参数t,化为普通方程(x﹣4)2+(y﹣5)2=25,即C1:x2+y2﹣8x﹣10y+16=0,将代入x2+y2﹣8x﹣10y+16=0,得ρ2﹣8ρcosθ﹣10ρsinθ+16=0.∴C1的极坐标方程为ρ2﹣8ρcosθ﹣10ρsinθ+16=0.(2)∵曲线C2的极坐标方程为ρ=2sinθ.∴曲线C2的直角坐标方程为x2+y2﹣2y=0,联立,解得或,∴C1与C2交点的极坐标为()和(2,).22.(12分)已知定义域为R的函数f(x)=是奇函数.(1)求a,b的值;(2)用定义域证明f(x)在(﹣∞,+∞)上为减函数;(3)若对于t∈R,不等式f(t2﹣2t)+f(2t2﹣k)<0恒成立,求k的范围.【解答】解:(1)∵函数f(x)=是奇函数,∴f(﹣x)=﹣f(x)恒成立,即f(﹣x)===﹣=恒成立,即恒成立,∴a=b=1.(2)证明:任取x1<x2,则f(x1)﹣f(x2)==①,∵函数y=2x在R内是增函数,且x1<x2,∴,∴,又,>0,∴①式>0,∴f(x1)﹣f(x2)>0∴f(x1)>f(x2),∴函数f(x)=在(﹣∞,+∞)上为减函数.(3)f(t2﹣2t)+f(2t2﹣k)<0可化为f(t2﹣2t)<﹣f(2t2﹣k),∵f(x)是奇函数,∴f(t2﹣2t)<f(﹣2t2+k),又∵在R上f(x)是减函数,∴t2﹣2t>﹣2t2+k恒成立,即k<3t2﹣2t,t∈R恒成立,只需k<(3())min=,∴k的取值范围是().。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校高一历史下学期期末联考试题新人教版
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一历史下学期期末联考试题新人教版考试时间:90分钟试题分数:100分卷Ⅰ一. 选择题(每小题2分,共60分,答案涂在答题卡上)1.就说明“至迟到春秋末期,我国已经开始用牛耕地”而言,下列论据中说服力最小的是A.春秋时期的典籍中出现的“牛”与“耕”结合在一起的人的名字B.考古发现的春秋时期反映牛耕的文物C.战国初期的典籍中关于春秋时期“宗庙之牲(祭祀用的牛)为畎亩之勤”的记载D.成书于战国时期的《山海经》中关于叔均(传说中的人物)是“始作牛耕”的人物2. “锄禾日当午,汗滴禾下土。
谁知盘中餐,粒粒皆辛苦。
”此诗是我国封建社会劳动人民生活的真实写照,它所反映的我国传统农业的主要耕作方式是A.刀耕火种 B.耜耕 C.石器锄耕 D.铁器牛耕3. 明朝后期,土地高度集中,太湖流域90%的土地都在官僚和地主手中。
造成这一现象根本上是因为A.太湖流域是农业中心 B. 明朝中后期政治腐败C.统治者“不抑兼并” D.土地私有制的发展4. 在我国古代,“社稷”是国家的代称。
其中,“社”是土地之神,“稷”是主管五谷之神。
关于国家的这种理解,反映了我国古代A.非常重视祭祀 B. 农业与土地的关系C.以农业为立国之本 D.小农经济的突出特点5. “今棉之为用,可以御寒,可以生暖,盖老少贵贱无不赖之。
其衣被天下后世,为功殆过于蚕桑也。
”这句话反映的现象是A.棉布柔软结实,取代了丝织品的地位 B.棉布适用范围广C.棉布保暖性好,可以御寒 D.棉布功劳大于丝织品6. 据《东京梦华录》等记载,宋代都城多见“当街列床凳,堆垛冰雪”出售凉席和专向客商出租铺席宅舍等现象。
这反映了A.城市商业功能增强 B.经商方式不受限制C.官府鼓励经商 D.生活习俗改变③政府财政收入越来越倚仗于非农业税④重农抑商政策已经不再实施A. ①②B. ②③C. ①④D.③④8. 明朝丝织业中出现的“机房”被认为是中国出现资本主义萌芽的标志,其主要依据是A.使用机器生产且有一定规模 B.分工精细,生产有序C.生产的目的是为了交换生活用品 D.“机户出资,机工出力,计日受值”9. 下列历史现象中,最能体现明清时期符合世界发展趋势的是A.玉米、甘薯等作物传入我国,并在一些地区广泛种植B.苏州丝织业“小户听大户呼织”“计日受值”C.“湖广熟,天下足”取代了“苏湖熟,天下足”D.金属货币广泛应用,白银成为普遍流通的货币10. 最早开辟新航路的迪亚士曾经说过,他航行的目的是“为了像所有男子汉都欲做到的那样,为上帝和陛下服务,将光明带给那些尚处于黑暗中的人们。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)
高一下学期期末联考数学试题考试时间:120分钟 试题分数:150分 命题人:孙咏霞 校对人:王琪卷Ⅰ一、选择题(本大题共12个小题,每小题5分,共60分,每小题有4个选项,其中有且仅有一个是正确的,把正确的选项填在答题卡中) 1.与角-6π终边相同的角是( )A .56π B. 3π C. 116π D. 23π 2.某扇形的半径为1cm ,它的弧长为2cm ,那么该扇形的圆心角为( ) A .2° B. 4rad C. 4° D. 2rad 3.已知平面向量a =(3,1),b =(x,-3),且a ⊥b ,则x 等于( )A .3 B.1 C.-1 D.-34.某单位有职工750人,其中青年职工350人,中年职工250人,老年职工150人,为了了解该单位职工的健康情况,用分层抽样的方法从中抽取样本.若样本中的青年职工为7人,则样本容量为( )A .7B .25C .15D .35 5.在[0,2π]内,满足sinx >cosx 的x 的取值范围是( )A.6.如图1,在正六边形ABCDEF 中,BA CD EF ++=( )A.0B.BEC.ADD.CF图1 图27.某时段内共有100辆汽车经过某一雷达地区,时速频率分布直方图如图2所示,则时速超过60km/h 的汽车数量为( )A .38辆B .28辆C .10辆D .5辆 8.已知MP ,OM ,AT 分别为角θ()42ππθ<<的正弦线、余弦线、正切线,则一定有( )A.MP OM AT <<B.OM MP AT<<C.AT OM MP <<D.OM AT MP <<9.利用计算机产生0~1之间的均匀随机数a ,则使关于x 的一元二次方程x 2-x+a=0无实根的概率为( ) A .12 B.14 C.34 D.23a =(2,-1b =(1,1),c =(-5,1()a kb +∥c ,则卷Ⅱ二、填空题(本大题共4个小题,每空5分,共20分,把正确答案填在题中横线上) 13.已知1,2,,60,2a b a b a b ==<>=+=则14. 若α为锐角,且sin ⎝⎛⎭⎫α-π6=13,则sin α的值为________.π三、解答题(本大题共6个大题,共70分,解答应写出文字说明,证明过程或演算步骤)17.(本小题满分10分(1)化简()f α;(2)若α是第三象限角,且cos(32πα-)=18. (本小题满分12分)如图,某中学甲、乙两班共有25名学生报名参加了一项 测试.这25位学生的考分编成的茎叶图,其中有一个数据因电脑操作员不小心删掉了(这里暂用x 来表示),但他清楚地记得两班学生成绩的中位数相同. (1)求这两个班学生成绩的中位数及x 的值;(2)如果将这些成绩分为“优秀”(得分在175分以上,包括175分)和“过关”,若学校再从这两个班获得“优秀”成绩的考生中选出3名代表学校参加比赛,求这3人中甲班至多有一人入选的概率.19. (本小题满分12分) 已知函数f (x )=2sin x 4cos x 4+3cos x2.(1)求函数f (x )的最小正周期及最值;(2)令g (x )=f ⎝⎛⎭⎪⎫x +π3,判断函数g (x )的奇偶性,并说明理由.20.(本小题满分12分) 在△ABC 中,中线长AM =2.(1)若OA →=-2OM →,求证:OA →+OB →+OC →=0;(2)若P 为中线AM 上的一个动点,求P A →·(PB →+PC →)的最小值.21. (本小题满分12分)在△ABC 中,a ,b ,c 分别为内角A ,B ,C 的对边,且2asinA=(2b+c )sinB+(2c+b )sinC . (1)求A 的大小;(2)求sinB+sinC 的最大值.22. (本小题满分12分)设函数f (x )=sin(2x +φ)(-π<φ<0),y =f (x )图象的一条对称轴是直线x =π8.(1)求φ;(2) 求函数y =f (x )的单调增区间;(3)画出函数y =f (x )在区间[0,π]上的图象.高一数学下学期期末考试答案:二、填空题:13.14.15. 16.三、解答题:17.解:...............5分=157.....................................2分乙班学生成绩的中位数正好是150+x=157,故x=7;........................................2分(Ⅱ)用A表示事件“甲班至多有1人入选”.设甲班两位优生为A,B,乙班三位优生为1,2,3.则从5人中选出3人的所有方法种数为:(A,B,1),(A,B,2),(A,B,3),(A,1,2),(A,1,3),(A,2,3),(B,1,2),(B ,1,3),(B ,2,3),(1,2,3)共10种情况,..........................3分 其中至多1名甲班同学的情况共(A ,1,2),(A ,1,3),(A ,2,3), (B ,1,2),(B ,1,3),(B ,2,3),(1,2,3)7种......................3分 (1)(x)sinf =(2)g (x )是偶函数.理由如下:.................................................................................1分 ∴函数g (x )是偶函数. ......................................................................................... ...1分 20. 解:(1)证明:∵M 是BC 的中点,∴OM →=12(OB →+OC →).....................................................................................................3分代入OA →=-2OM →,得OA →=-OB →-OC →,.................................................................2分 即OA →+OB →+OC →=0........................................................................................................1分 (2)设|AP →|=x ,则|PM →|=2-x (0≤x ≤2).....................................................................1分 ∵M 是BC 的中点,∴PB →+PC →=2PM →................................................................................................................2分∴PA→·(PB→+PC→)=2PA→·AM→=-2|PA→||PM→|=-2x(2-x)=2(x2-2x)=2(x-1)2-2,...................................................................2分当=1时,取最小值-2.................................................................................................1分则a=2RsinA,b=2RsinB,c=2RsinC................................................................................2分∵2asinA=(2b+c)sinB+(2c+b)sinC方程两边同乘以2R∴2a2=(2b+c)b+(2c+b)c...........................................................................................2分整理得a2=b2+c2+bc............................................................................................................1分∵由余弦定理得a2=b2+c2-2bccosA..................................................................................1分(Ⅱ)由(Ⅰ)得:sinB+sinC=sinB+sin(60°-B)....................................................1分sin(60B)+ (2)故当B=30°时,sinB+sinC取得最大值1......................................................................1分故函数y=f(x)在区间[0,π]上的图象是.................................................2分。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二下学期期末联考英语试题
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二下学期期末联考英语试题考试时间:100分钟试题分数:150分第二部分阅读理解(共两节,满分40分)第一节(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出最佳选项,并在答题卡上将该项涂黑。
AMy brother Ron joined the US army a few years ago. Most girls, especially those who are my age, are thrilled by anything that has to do with the “army”. It’s a novelty to them to shoot a gun, jump out of a plane, and wear uniform.Now I know you’re thinking that I must find it really cool to know a solider, who’s my brother. That’s wrong, before I found out that my brother joined the army, I was crazy about the army. Firstly, I wanted to go to college, knew that joining the army was probably the only way I could get it as my parents couldn’t afford it. Additionally there were all the other points of the army that grabbed my heart. I wanted the challenge, I wanted the discipline and I wanted the feeling that I would be doing something beyond the ability of average citizen.But as soon as my brother joined the army, all those things fell away. All I saw were dead people, guns shooting, tanks turning into a ball of fire, tents burning, and lots of blood. It was so horrible. When Ron went to Iraq, I freaked out whenever I didn’t hear from him for more than a week. I kept up with the news, reading the latest newspaper and listening to the hourly reports. And every time I heard that an American solider was killed, I prayed, it’ wasn’t Ron.I’m proud of my brother for serving our country, and his willingness to devote his life to something he finds important. It’s great to see how discipline and mature he’s got, and I’m glad he has his college paid for. But although I am proud, I gladly give up the “coolness”of having a brother in the army. I would be perfectly all right if I had never seen that uniform on him, and he was just a plain old “boring” brother.I love my brother, and I’m proud of him, but I want him back home!21. What did the writer think of the army before Ron joined?A. Joining the army was more beneficial than going to college.B. Joining the army was a good choice for those who couldn’t afford college education.C. Joining the army was meant risking one’s life for something important,D. Joining the army did more harm than good.22. After Ron joined the army, the writer .A. decide to join the army one dayB. became afraid of seeing soldiersC. often showed off Ron in front of friendsD. became aware of the danger of joining the army23. What would be the best title for the passage?A. Peace or war?B. Life in the armyC. Having a soldier in the familyD. A choice between your life and your dreamBThe greatest recent social changes have been in the lives of women. During the twentieth century there has been a remarkable shortening of the proportion of a woman's life spent in caring for the children. A woman marrying at the end of the nineteenth century would probably have been in her middle twenties, and would be likely to have seven or eight children, four or five of whom lived till they were five years old. By the time the youngest was fifteen, the mother would have been in her early fifties and would expect to live a further twenty years, during which health made it unusual for her to get paid work. Today women marry younger and have fewer children. Usually a woman's youngest child will be fifteen when she is forty-five years and can be expected to live another thirty-five years and is likely to take paid work until retirement at sixty. Even while she has to take care of children, her work is lightened by modern living conditions.This important change in women's life-patterns has only recently begun to have its full effect on women's economic position. Even a few years ago most girls took a full-time job after they left school. However, when they married, they usually left work at once and never returned to it. Today the school- leaving age is sixteen; many girls stay at school after that age, and though women usually marry older, more married women stay at work at least until shortly before their first child is born. Many more afterwards return to full-or-part-time work. Such changes have led to a new relationship in marriage, with the husband accepting a greater share of the duties and satisfactions of family life, and with both husband and wife sharing more equally in providing the money, and running the home, according to the abilities and interests of each of them.24. At what age did most women marry around the 1890 according to the passage?A. At about twenty-fiveB. In their earl fiftiesC. At the age of fifteenD. At any age from fifteen to forty-five25. Many girls, the passage claims, are now likely to_______.A. give up their jobs for good after they are marriedB. leave school as soon as they canC. marry so that they can get a jobD. continue working until they are going to have a baby26. When she was over fifty, a late nineteenth-century mother ______.A. was usually expected to die fairly soonB. would expect to work until she diedC. would be healthy enough to take up paid jobsD. was less likely to find a job even if she wanted to27. Nowadays, a husband tends to_______.A. play a greater part in looking after the childrenB. help his wife by doing much of the houseworkC. feel dissatisfied with his role in the familyD. take a part-time job so that he can help in the homeCThe best example of something is often called the "gold standard." It sets the standard against which other things are measured. In economics, the term describes how major trading nations once used gold to set currency values and exchange rates. Many nations continued to use the gold standard until the last century.In the United States, people could exchange paper money for gold from the eighteen seventies until nineteen thirty-three. Then-President Richard Nixon finally disconnected the dollar from the value of gold in nineteen seventy-one. From time to time, some politicians call for a return to the gold standard.In 1978, the International Monetary Fund ended an official gold price. The IMF also ended the required use of gold in transactions with its member countries. Since that time, gold prices have grown and continued to be high. But people keep buying. Some people are "gold bugs." These are investors who say people should buy gold to protect against inflation(通货膨胀).People have valued gold for thousands of years. The soft, dense metal polishes to a bright yellow shine and resists most chemical reactions. It makes a good material for money, political power -- and, more recently, electrical power. If you own a device like a mobile phone or a computer, you might own a little gold in the wiring.The gold standard was the subject of one of the best-known speeches in American political history. William Bryan wanted the country to use both gold and silver as money. The idea was to devalue the dollar and make it easier for farmers to pay their debts. So he delivered a speech, which made him famous. He was a presidential candidate three times. But he never won.28. The underlined word “transactions” probably means “”A. warsB. tradeC. meetingsD. conflict29. After the IMF ended the official gold price, the gold prices .A. stayed the sameB. began to dropC. increasedD. increased a little at first and kept drop30. What’s the fourth paragraph mainly about?A. The reason for valuing goldB. The history of the use of goldC. New function of goldD. How to obtain gold31. We can learn from the last paragraph that William Bryan .A. was once a farmerB. loved to collect goldC. was a famous political figureD. was a good at giving speechesDEdward Wilson is America's, if not the world's, leading naturalist. In The Future of Life, he takes us on a tour of the world's natural resources. How are they used? What has been lost? What remains and is it able to continue with the present speed of use? Wilson also points out the need to understand fully the biodiversity(生物多样性)of our earth.Wilson begins with an open letter to the pioneer in environment protection, Henry David Thoreau. He compares today's Walden Pond with that of Thoreau's day. Wilson will use such comparisons for the rest of the book. The problem is clear: man has done great damage to his home over the years. Can the earth, with human help, be made to return to biodiversity levels that will be able to support us in the future?Biodiversity, Wilson argues, is the key to settling many problems the earth faces today. Even our agricultural crops can gain advantages from it. A mere hundred species(物种) are the basis of our food supply, of which but twenty carry the load. Wilson suggests changing this situation bylooking into ten thousand species that could be made use of, which will be a way to reduce the clearing of the natural homes of plants and animals to enlarge farming areas.At the end of the book, Wilson discusses the importance of human values in considering the environment. If you are to continue to live on the earth, you may as well read and act on the ideas in this book.32. We learn from the text that Wilson cares most about .A. the environment for plantsB. the biodiversity of our earthC. the waste of natural resourcesD. the importance of human values33. How many species are most important to our present food supply?A. TwentyB. EightyC. One hundredD. Ten thousand34. Wilson suggests that one way to keep biodiversity is to .A. learn how to farm scientificallyB. builds homes for some dying speciesC. makes it clear what to eatD. use more species for food35. We can infer that the text isA. description of natural resourcesB. a research reportC. a book reviewD. an introduction to a scientist第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二下学期期末联考历史试题
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高二下学期期末联考历史试题(试卷分第Ⅰ卷和第Ⅱ卷两部分,考试时间90分钟,满分100分)第Ⅰ卷选择题(60分,每小题2分,共30题)1.成语“当仁不让”的典故出自于《论语·卫灵公》,孔子在给学生讲学时提出“当仁,不让于师”,意在A.倡导学生自主学习B.鞭策学生承担社会责任C.鼓励学生要超过老师D.提倡学生独立思考2.清代学者钱大昕说:“孟子言性善,欲使人尽性而乐于善;荀子言性恶,欲使人化性而勉于善。
立言虽说殊,其教人以善则一也。
”由此可知,性善论和性恶论A.发扬了孔子的思想B.都主张人性是善的C.为各国统治者采用D.仅为教化百姓向善3.班固在《汉书·艺文志》里说:“诸子十家,其可观者九家而已。
皆起于王道既微,诸侯力政,时君世主,好恶殊方,是以九家之说蜂出并作,各引一端,崇其所善,以此驰说,取合诸侯。
”班固认为“百家争鸣”局面出现主要是A.诸子要改变礼崩乐坏的局面B.诸子为迎合统治者争霸需要C.诸侯为了争霸战争求贤若渴D.学术环境宽松并且学术下移4.朱熹说:“宇宙之间,一理而已。
天得之而为天,地得之而为地,凡生于天地之间者,又各得之以为性;其张之为三纲,其纪之为五常,盖皆此理之流行,无所适而不在。
”对此理解准确的是A.仍然属于董仲舒的“天人感应”理论范畴B.“三纲”、“五常”是宇宙万物奉行的准则C.“理”推动人类社会道德规范的广泛传播D.“理”使社会伦理化,伦理道德天理化5.对朱熹“格物致知”与王阳明“致良知在格物”两种思想主张解读合理的是A.二者思想没有区别B.“知”的本质是儒家伦理C.二者思想完全对立D.格物是致知的根本途径6.我国古代的一位儒学大师认为,“天子受命于天,诸侯受命于天子,子受命于父,妻妾受命于夫。
诸所受命者,其尊皆天也,虽谓受命于天亦可。
”这位儒学大师是7.2012年北京诚轩秋季拍卖会钱币专场中,一枚正面刻着“下匕阝(qǔ)阳”,背面刻着“十七•两”的青铜古钱(见右图)以人民币368万元成交,一举刷新中国古钱拍卖价格的最高记录。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校高一英语下学期期末联考试题新人教版
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一英语下学期期末联考试题新人教版第I卷(选择题,共85分)第二部分阅读理解(共两节,满分40分)第一节阅读理解(共15小题;每小题2分,满分30分)阅读下列短文,从每题所给的四个选项(A、B、C和D)中,选出一个最佳选项。
AChildren are our future, and it’s up to us to arm them wi th the tools to succeed. Sadly, today’s children are being armed with more dangerous tools like weapons (武器), drugs and gangs. Once a relatively peaceful environment, many schoolyards of today are becoming unsafe for both students and teachers.Home schools are available to give you choices. Home schooling provides top-quality education, flexibility, and freedom to create your own schedule (日程表). At Heritage Home School we believe the choice should be yours.Thanks in part to modern technology, home schooling information is becoming readily available across our nation. A recent study by the ITBS(Iowa Tests of Basic Skills)and TAP(Tests of Achievement and Proficiency)shows us that students of home schools do particularly well when compared with the nationwide average. In every subject at every grade level, students of home schooling scored obviously higher than those in public and private schools.If you’re new to home schooling, you may be asking yourself, “Will home schools really work for my children? ”Fact: A nationwide study using a random(任意)selection of 1,516 families found students of home schooling to be scoring, on average, at or above the 80th percentile in all areas on standardized achievement test.Note: The national average on standardized achievement tests is the 50th percentile.Collectively, the staff(全体职员)at Heritage Home School brings 65 years of experience in home schooling curriculum(全部课程). We’ve placed students in the top 2% of the nation in math and many are successfully moving on to college.One study found that of the home schooled adults, 2% were unemployed, 2% were on welfare(福利)and 94% said home education prepared them to be independent persons.For more home schooling information, call us today toll free at 1(877)532-7665.1. We can learn from the first paragraph that _______.A. many schools armed their students with weaponsB. violence and crime exist in many schoolyardsC. students use weapons to defend their schoolyardsD. weapons are more dangerous than drugs2. All of the following are true of home schools EXCEPT that _______.A.students are free to choose their coursesB. students do well in important national testsC. they help students find jobsD. they help students to be independent3. What is the purpose of the text?A. To give information about different schools.B. To compare home schools with other schools.C. To suggest a new method of school education.D. To persuade people to choose home schools.4. The advertisement is mainly aimed at _______.A. studentsB. parentsC. teachersD. adults5. Students of home schooling get higher scores than those in public and privateschools ____ .A. in some subjects at every grade levelB. in part subjects at every grade levelC. in few subjects at every grade levelD. in all subjects at every grade levelBInvention of TV began in 1922 in Rigby, Idaho, the hometown of Philo. At the age of 16, Philo was a very shy boy. Only his teacher, Justin Tolman, realized that Philo was a special person.One day after school Mr Tolman found Philo in the schoolroom. The boy was making drawings on the blackboard.“What are you doing?” Mr Tolman asked with interest. “What are these drawings?”“I want to invent things,” Philo answered, “and these a re the drawings of one of my first inventions. I have an idea for a way of sending pictures through the air. Please, just let me tell you about it. You are the only person who can understand what I have done.” In the school library Philo had read about a man who had worked on an idea for TV, but had failed. Philo was sure that his idea was better and that he could succeed.Mr Tolman was not sure and asked Philo many questions about the drawings. Giving facts and figures, Philo answered every question.In 1926, Philo sent his drawings to Washington, along with a letter asking for patent (专利)rights on TV. Since then, television has become an important business all over the world.6. When he lived in his hometown, Philo was _____________.A. quite different from othersB. an activity boyC. an inventorD. a hard-working boy7. When Philo said “ You are the only person who can understand what I have done.”,his mood(情绪) was_________.A. discouragedB. guilty (内疚的)C. trustingD. hopeless8. It took Philo ________ to invent the television.A. 2 yearsB. 4 yearsC. 6 yearsD. 8 years9. Philo ________ after he invented television.A. asked for the patent rights on televisionB. sent his drawings to Mr TolmanC. answered Mr Tolman’s questionsD. gave facts and figures to Mr Tolman10. When Mr Tolman saw Philo’s drawings, he ______________.A. did not believe it was Philo’s inventionB. believed Philo could succeedC. did not believe Philo could succeedD. believed Philo was a special personC“It hurts me more than you,” and “This is for your own good.” These are the statements my mother used to make years ago when I had to learn Latin, clean my room, stay home and do homework..That was before we entered the permissive period in education in which we decided it was all right not to push our children to achieve their best in school.The schools and the educators made it easy on us. They taught that it was all right to be parents who take a let-alone policy. We stopped making our children do homework. We gave them calculators(计算器), turned on the television, left the teaching to the teachers and went on vacation.Now teachers, faced with children who have been developing at their pace for the past 15 years, are realizing we’ve made a terrible mistake. One such teacher is Sharon Klompus who says of her students ----- “so passive” ----- and wonders what happened. Nothing was demanded of them, she believes. Television, says Klompus, contributes to children’s passivity; “We’re not training kids to work any more.” says Klompus. “We’re talking about a generation of kids who’ve never been hurt or hungry. They have learned somebody will always do it for them. Instead of saying go look it up, you tell them the answer. It takes greater energy to say no t o a kid.”Yes, it does. It takes energy and it takes work. It’s time for parents to end their vacation and come back to work. It’s time to take the car away, to turn the TV off, to tell them it hurts you more than them but it’s for their own good, It’s t ime start telling them no again.11. By “permissive period of education” the author means an age ______.A. when children are allowed to do what they wish to.B. when everything can be taught in schoolsC. when every child can be educated.D. when children are permitted to receive education.12. We learn from the passage that the author’s mother used to connect importance with _____A. learning LatinB. natural developmentC. disciplineD. school education13 According to the passage, children are growing inactive in study mainly because _____.A. they watch TV too oftenB. their parents leave them aloneC. their teachers are strict with themD. they take on too many duties14.To today’s kids as described in this pass age,_____.A. it is easier to give a negative(否定的)reply than to give a positive(肯定的) replyB. it is easier to give a positive reply than to give a negative replyC. neither is easy — to say yes or to say noD. neither is no easy job — to say yes or to say no15.The main idea of this passage is that _____.A. parents should set a good example for their kidsB. kids should have more activities outside campus(校园)C. educators should not he so permissiveD. it is time to be strict with our children第二节(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项,并在答题卡上将该项涂黑。
辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一数学下学期期末联考
某某省东北育才学校、省实验中学、某某二十高(某某部)三校2013-2014学年高一数学下学期期末联考试题新人教A 版考试时间:120分钟 试题分数:150分卷Ⅰ一、选择题(本大题共12个小题,每小题5分,共60分,每小题有4个选项,其中有且仅有一个是正确的,把正确的选项填在答题卡中)1.与角-6π终边相同的角是( ) A .56π B.3π C.116π D.23π 2.某扇形的半径为1cm ,它的弧长为2cm ,那么该扇形的圆心角为( )A .2° B. 4rad C. 4° D. 2rad3.已知平面向量a =(3,1),b =(x,-3),且a ⊥b ,则x 等于( )A .3 B.1 C.-1 D.-34.某单位有职工750人,其中青年职工350人,中年职工250人,老年职工150人,为了了解该单位职工的健康情况,用分层抽样的方法从中抽取样本.若样本中的青年职工为7人,则样本容量为( )A .7B .25C .15D .355.在[0,2π]内,满足sinx >cosx 的x 的取值X 围是( )A.(4π,34π)B.(4π,54π) C.(34π,54π) D.(54π,74π) 6.如图1,在正六边形ABCDEF 中,BA CD EF ++=( )A.0B.BEC.ADD.CF图1 图27.某时段内共有100辆汽车经过某一雷达地区,时速频率分布直方图如图2所示,则时速超过60km/h 的汽车数量为( )A .38辆B .28辆C .10辆D .5辆8.已知MP ,OM ,AT 分别为角θ()42ππθ<<的正弦线、余弦线、正切线,则一定有( ) A.MP OM AT << B.OM MP AT << C.AT OM MP << D.OM AT MP <<9.利用计算机产生0~1之间的均匀随机数a ,则使关于x 的一元二次方程x 2-x+a=0无实根的概率为( )A .12 B.14 C.34 D.23 10.已知平面向量a =(2,-1),b =(1,1),c =(-5,1),若()a kb +∥c ,则实数k 的值为( )A .2 B.12 C.114 D.114-11.要得到y =sin ⎝⎛⎭⎫x 2+π3的图象,需将函数y =sin x 2的图象至少向左平移( )个单位. A.23π B.3π C.34π D.4π12.阅读程序框图,当输入x 的值为-25时,输出x 的值为( )A .-1B .1C .3D .9卷Ⅱ二、填空题(本大题共4个小题,每空5分,共20分,把正确答案填在题中横线上)13.已知1,2,,60,2a b a b a b ==<>=+=则14. 若α为锐角,且sin ⎝⎛⎭⎫α-π6=13,则sinα的值为________. 15.在△ABC 中,已知∠BAC=60°,∠ABC=45°,BC=3,则AC=16.定义在R 上的偶函数f(x)是最小正周期为π的周期函数,且当[0,]2x π∈时,(x)sinx f = ,则5()3f π的值是三、解答题(本大题共6个大题,共70分,解答应写出文字说明,证明过程或演算步骤)17.(本小题满分10分)已知sin()cos(2)tan()()tan()sin()f παπααπαπαπα---+=-----(1)化简()f α; (2)若α是第三象限角,且cos(32πα-)=15,求()f α的值.18. (本小题满分12分)如图,某中学甲、乙两班共有25名学生报名参加了一项 测试.这25位学生的考分编成的茎叶图,其中有一个数据因电脑操作员不小心删掉了(这里暂用x 来表示),但他清楚地记得两班学生成绩的中位数相同.(1)求这两个班学生成绩的中位数及x 的值;(2)如果将这些成绩分为“优秀”(得分在175分以上,包括175分)和“过关”,若学校再从这两个班获得“优秀”成绩的考生中选出3名代表学校参加比赛,求这3人中甲班至多有一人入选的概率.19. (本小题满分12分) 已知函数f(x)=2sin x 4cos x 4+3cos x 2.(1)求函数f(x)的最小正周期及最值;(2)令g(x)=f ⎝⎛⎭⎫x +π3,判断函数g(x)的奇偶性,并说明理由.20.(本小题满分12分)在△ABC 中,中线长AM =2.(1)若OA →=-2OM →,求证:OA →+OB →+OC →=0;(2)若P 为中线AM 上的一个动点,求PA →·(PB →+PC →)的最小值.21. (本小题满分12分)在△ABC 中,a ,b ,c 分别为内角A ,B ,C 的对边,且2asinA=(2b+c )sinB+(2c+b )sinC .(1)求A 的大小;(2)求sinB+sinC 的最大值.22. (本小题满分12分)设函数f(x)=sin(2x +φ)(-π<φ<0),y =f(x)图象的一条对称轴是直线x =π8.(1)求φ;(2) 求函数y =f(x)的单调增区间;(3)画出函数y =f(x)在区间[0,π]上的图象.高一数学下学期期末考试答案:二、填空题: 13.3322+23 三、解答题:17.解: (1)sin()cos(2)tan()sin cos (tan )()cos tan()sin()tan sin f παπααπααααααππααα---+-===------...............5分 (2)∵α为第三象限角,且31cos()sin 25παα-=-=....................................2分21sin 526cos 1sin ααα∴=-∴=-=. ...........................................................2分 则26()cos 5f αα=-=............................................................1分18. 解(Ⅰ)甲班学生成绩的中位数为12(154+160)=157.....................................2分 乙班学生成绩的中位数正好是150+x=157,故x=7;........................................2分(Ⅱ)用A 表示事件“甲班至多有1人入选”.设甲班两位优生为A ,B ,乙班三位优生为1,2,3.则从5人中选出3人的所有方法种数为:(A ,B ,1),(A ,B ,2),(A ,B ,3),(A ,1,2),(A ,1,3),(A ,2,3),(B ,1,2),(B ,1,3),(B ,2,3),(1,2,3)共10种情况,..........................3分其中至多1名甲班同学的情况共(A ,1,2),(A ,1,3),(A ,2,3),(B ,1,2),(B ,1,3),(B ,2,3),(1,2,3)7种......................3分由古典概型概率计算公式可得P (A )=710.............................................................2分 19. (1)(x)sin 32sin()2223x x x f π=+=+.......................................................2分∴f (x )的最小正周期T=212π=4π......................................................................1分当sin()123x π+=-时,f (x )取得最小值-2;..............................................................1分当sin()123x π+=时,f (x )取得最大值2...................................................................1分(2)g (x )是偶函数.理由如下:.................................................................................1分 由(1)知(x)2sin()23x f π=+ 又g (x )f(x )3π=+ ∴g (x )=12sin[(x )]2sin()2cos 233222x x πππ++=+=...........................................3..分 ∵g (-x )=2cos()2cos 22x x -==g (x ),....................................................................2分∴函数g (x )是偶函数.......................................................................................... ...1分20. 解:(1)证明:∵M 是BC 的中点,∴OM →=12(OB →+OC →).....................................................................................................3分代入OA →=-2OM →,得OA →=-OB →-OC →,.................................................................2分即OA →+OB →+OC →=0........................................................................................................1分(2)设|AP →|=x ,则|PM →|=2-x(0≤x≤2).....................................................................1分∵M 是BC 的中点,∴PB →+PC →=2PM →................................................................................................................2分 ∴PA →·(PB →+PC →)=2PA →·AM →=-2|PA →||PM →|=-2x(2-x)=2(x2-2x)=2(x -1)2-2,...................................................................2分当x =1时,取最小值-2.................................................................................................1分 21. (Ⅰ)设sin sin sin a b c A B C ==2R则a=2RsinA ,b=2RsinB ,c=2RsinC................................................................................2分 ∵2asinA=(2b+c )sinB+(2c+b )sinC方程两边同乘以2R∴2a2=(2b+c )b+(2c+b )c...........................................................................................2分 整理得a2=b2+c2+bc............................................................................................................1分 ∵由余弦定理得a2=b2+c2-2bccosA..................................................................................1分故cosA=-12,A=120°........................................................................................................2分 (Ⅱ)由(Ⅰ)得:sinB+sinC=sinB+sin (60°-B )....................................................1分 =31cosB sin sin(60B)22B +=+...................................................................................2分 故当B=30°时,sinB+sinC 取得最大值1......................................................................1分22. 解:(1)因为x =8π是函数y=f (x )的图象的对称轴,所以sin(2×8π+ϕ)=±1,即4π+ϕ=kπ+2π,k ∈Z ...............................2分因为-π<φ<0,所以ϕ=−34π.............................................................2分(2)由(1)知ϕ=−34π,因此y =sin(2x−34π).由题意得2kπ−2π≤2x−34π≤2kπ+2π,k ∈Z ,.......................................2分 所以函数y =sin(2x−34π)的单调区间为[kπ+8π,kπ+58π],k ∈Z........2分(3)由y =sin(2x−34π)知:.................................................................2分 x 0 π8 3π 8 5π 8 7π 8 π.y 22- -1 0 1 0 22-分。
【免费下载】辽宁省实验中学分校2013-2014学年高二(新疆班)下学期期末考试数学试题 Word版含答案(新人教A版
考试时间:120 分钟 试题分数:150 分
卷I
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辽宁省东北育才学校、省实验中学、大连二十高(新疆部)三校2013-2014学年高一下学期期末联考地理试题考试时间:50分钟试题分数:100分卷Ⅰ一、单项选择题(共70分)下列各题均有四个选项,其中只有一项是符合题意要求的。
(每小题2分,多选、错选、漏选该小题均不得分。
)1、下列各大洲中,人口的自然增长率最低的是()A、大洋洲B、亚洲C、非洲D、欧洲2、近期我国将采取渐进、微调、各省不同步的方式推开单独二胎政策,可能带来的影响有()A、缓解目前我国劳动力短缺状况B、加快城市化速度C、增加我国的环境人口容量D、缓解我国人口老龄化现象3、为了缓和人口压力,我国应采取下图人口增长模式中的:()4、人口增长模式决定于()A、出生率、死亡率、人口总数B、出生率、死亡率、自然增长率C、出生率、死亡率、社会生产力D、出生率、人口总数、社会生产力5、人口增长的快慢,归根结底取决于()A、生产力发展水平B、人口出生率的大小C、人口死亡率的高低D、人口自然增长率的大小6、改革开放后,我国东南沿海地区出现“民工潮”的主要原因有()①城市和沿海地区经济的迅速发展②东南部地区劳动力不足③我国农村出现大量剩余劳动力④我国农村人口密度大A、①②B、②③C、③④D、①③7、下列表示影响人口迁移的推力因素的是()A矿产资源丰富B文化教育发达 C 土地荒漠化 D 经济发达8、环境人口容量由小到大排序正确的是()A、原始社会—农业社会—现代社会—工业社会B、农业社会—原始社会—工业社会—现代社会C、工业社会—原始社会—农业社会—现代社会D、原始社会—农业社会—工业社会—现代社会9、人口的合理容量与()A、自然资源状况无关B、自然资源状况成负相关C、科技水平成正相关D、文化生活消费水平成正相关10、制约环境承载力的首要因素是()A、科技发展水平B、资源状况C、人口的文化水平D、人口生活消费水平11、读某工业部门在某城市及其附近地区土地、运输和劳动力等成本曲线图,其中土地成本和运费都只与距城市中心的远近、交通通达度有关。
完成下题。
综合考虑土地、运输、劳动力等成本,该工业部门应布局在()A、①地B、②地C、③地D、④地12、下列各区与其特色优势、功能搭配正确的是()A、矿区---交通优势B、旅游区---自然景观或人文景观特色C、中心商务区---艺术特色D、文化区----商业功能13、影响城市内部空间结构的主要因素是()A、自然因素B、历史因素C、经济因素D、社会因素14、城市中最为广泛的土地利用方式是:()A、工业区B、商业区C、住宅区D、行政区15、下列叙述,正确的是()A、城市等级越高,数目越多B、城市等级越高,数目越少C、城市等级越低,服务范围越大D、城市等级越低,服务功能越多16、衡量城市化水平最重要的指标是()A、城市人口数量B、城市人口占总人口的百分之比C、城市面积的大小D、城市职能的重要性17、城市热岛效应出现的主要原因是()A、纬度因素影响B、地形因素影响C、人类活动影响D、海陆因素影响18、有人戏称北京为“首堵”,其交通拥挤的根本原因是()A、城市面积的不断扩大B、城市人口的迅猛增加C、城市化水平较低D、城市经济发展水平低下19、城市化对城市水循环产生了重要影响,下列叙述正确的是()A、不透水面积增加,使地表径流增加B、地表植被减少,使下渗量增加C、城市热岛效应,使降水量减少D、建筑物增加,使地表径流量减少20、城市化起步最早和最早出现逆城市化的国家是()A、德国B、英国C、日本D、美国21、随着商品房价格上升,城市中住宅区的付租能力也在提高,右图中住宅区的付租能力由实线变为虚线,若只考虑这一种因素,住宅区的界线A、B将()A、A、B点都向C方向移B、A点向O方向移、B点向C方向移C、A、B点都向O方向移D、A点不动,仅B点向C方向移22、图9为“2013春节期间深圳某大街‘空城’一角示意图”,造成深圳某大街2013年春节期间“空城现象”的最主要原因是()A、逆城市化加速B、务工人员返乡C、人口老龄化加剧D、旅游人数增多23、世界上某些城市实行“公交优先”的规定,其主要目的是()A、扶持国有大中型企业B、控制出租车的发展C、改善城市交通拥挤状况D、提高公交公司的效益24、“东北大米”质优畅销,其主要优势是()A、热量充足,生长快B、冬季昼夜温差大,利于有机质积累C、机械化程度高,亩产高D、少用农药,绿色环保25、新疆生长的水果特别甜,原因是()A、云量多,光照弱,利于作物的光合作用B、降水少,瓜果水分含量少,糖分含量高C、昼夜温差大,营养物质消耗少,糖分积累多D、晴天多,云量少,温差不大,有利于植物生长26、下列既有商品谷物农业,又有大牧场放牧业的国家是()A、南非B、加拿大C、新西兰D、澳大利亚27、白兰瓜,又名“兰州蜜瓜”,享有“香如桂花,甜似蜂蜜”之誉。
兰州为显著提高白兰瓜的产量、质量在原有土地上增铺砂砾层(如下图)。
下列有关砂砾层作用描述正确的是( )①减少了水分的蒸发②增大土壤日温差③便于采摘白兰瓜④减少风沙等造成的土壤养分流失⑤提高土壤温度⑥便于灌溉A、①②③B、①④⑤C、①②④D、③④⑤28、新疆南部种植棉花的有利条件()A、光照充足B、土壤为肥沃的黑土C、降水丰富D、地块小,利于机械化的实现29、我国珠江三角洲的基塘生产,其农业地域类型属于()A、商品谷物农业B、大种植园农业C、粗放农业D、混合农业30、我国内蒙古、新疆地区适合发展的农业地域类型是( )A、大牧场放牧业B、商品谷物农业C、乳畜业D、季风水田农业31、有关阿根廷牧牛业的叙述,正确的是( )①横穿潘帕斯草原大铁路的修建,促进了牧牛业的发展;②种植饲料作物等措施弥补了天然草场的不足;③这里所产的牛肉大量供应美国市场;④粗放的经营方式降低了生产成本A、①②B、②③C、③④D、①④32、乳畜业在我国主要分布在( )A、内蒙古牧区B、新疆牧区C、西藏牧区D、大城市周围33、有关商品谷物农业的叙述,正确的是:()A、主要分布在美国、加拿大、印度等国B、商品谷物农场都是家庭经营方式C、我国东北和西北地区也有商品谷物农场D、商品谷物农业主要包括水稻种植业读“木桶效应(组成木桶的木板如果长短不齐,那么这只木桶的盛水量,不取决于最长的那一块木板,而是取决于最短的那一块)图”,完成34~35题。
34、某地以耕地、森林、淡水、矿产测得的各自所能供养的人口数量分别为8 000、6 000、4 500、10 000,则该地的环境承载力取决于()A、耕地B、森林C、淡水D、矿产35、下列影响我国不同省区人口合理容量的因素中相当于木桶短板的是()A、四川—水力资源B、山东—气候资源C、黑龙江—矿产资源D、福建—耕地资源卷Ⅱ二、综合题(共30分)36、读图填充(12分)1、伦敦在城市发展过程中,______________规模和_____________规模不断扩大,使中心区环境质量下降,主要表现为_____________、_____________、_______________和__________。
(6分)2、1950年伦敦发生震惊世界的酸雾事件,其产生的主要原因是________________________________________________________.。
(2分)3、20世纪70年代后,伦敦城市人口有所下降,大量人口迁往卫星成,其原因是____________ _____________________________________________。
(2分)4、从图中观察,伦敦在保护和改善城市环境方面采取了哪些措施?(2分)37、读图填充题(18分)1、写出亚洲季风水田农业主要分布地区的名称:A_____________B、___________C、_____________。
(3分)2、上述地区主要的气候类型有:______________、_______________和_____________。
(3分)3、在水稻的生长季节,这几种气候共同的特征是__________________________.。
(2分)4、从地形和水源条件看,亚洲季风水田农业和分布区的共同之处是____________________. _________________________________________.(2分)5、亚洲水稻种植区不利的气候因素是______________________。
为了减少这种危害,亚洲各国都十分重视_______________建设(2分)6、从社会经济条件分析,亚洲水稻种植业的优势有_____________________,同时这又会存在______________________等问题。
(3分)7、亚洲水稻种植业的基本特征是_________________、_____________、________________.(3分)2013—2014学年度下学期期末考试高一地理试卷参考答案一、选择题二、综合题36、读图填空(12分)1、人口用地(或城市用地)大气污染水污染噪声污染固体废弃物污染(每空1分共计6分)2、生产和生活大量燃烧煤、石油等矿物燃料,排放出大量酸性气体(2分)3、人们对环境质量要求提高,以及乡村和小城镇基础设施逐步完善。
(2分)4、建设卫星城,开发新城区;扩大绿化面积。
(2分)37、读图填空(18分)1、中国南方地区印度东部(主要在恒河流域)朝鲜半岛(3分)2、亚热带季风气候热带季风气候温带季风气候(3分)3、高温多雨,雨热同期(2分)。