江西省上高二中2010届高三年级第二次月考
江西省上高二中2015届高三上学期第二次月考数学(理)试卷及答案
xDCB A 江西省上高二中2015届高三上学期第二次月考数学(理)试题龠题人:黄友泰一、选择题:本大题共10个小题,每小题5分,共50分.在每小题给出的四 个选项中,只有一项是符合题目要求的.1.已知全集U=R ,集合A={x||x ﹣2|<1},B={x|y=},则A∩B=( )A .(1,2)B . (2,3)C . [2,3)D .(1,2] 2、在下列四个命题中,其中为真命题的是( )A. 命题“若42=x ,则22-==x x 或”的逆否命题是“若22-≠≠x x 或,则42≠x ” B. 若命题p:所有幂函数的图像不过第四象限,命题q:所有抛物线的离心率为1,则命题p 且q 为真 C. 若命题p:032,2>+-∈∀x x R x ,则032,:2<+-∈∃⌝x x R x pD. 若b a >,则)(+∈>N n b a nn3、设11,2450.50.9,log 0.3,a b c ===则a ,b ,c 的大小关系是( ) A.a c >>bB.a b >>cC.c a >>bD.b a >>c4.函数()sin ln f x x x =⋅的 部分图象为 ( )5.若函数321(02)3x y x x =-+<<的图象上任意点处切线的倾斜角为α,则α的最小值是( ) A.4π B. 6πC. 34πD.56π6.已知[x]表示不超过实数x 的最大整数,例如[1.3]=1,[-2.6]=-3,][)(x x g =为取整函数, 已知x 0是函数f(x)=lnx-x2的零点,则)(0x g 等于( )A .1B .2C .3D .47若点(,)P a b 在函数23ln y x x =-+的图像上,点(,)Q c d 在函数2y x =+的图像上,则22()()a c b d -+-的最小值为( ) (A (B ) 2 (C ) (D )88.定义在R 上的可导函数)(x f ,当),1(+∞∈x 时,0)1)(()()1(''>--⋅-x x f x f x 恒成立,若)2(f a =, )3(21f b =, )2(121f c -=,则c b a ,,的大小关系是( ) A .b a c << B .c b a << C .c a b << D .b c a <<9函数)51(cos 2)21()(2≤≤-+=-x x x f x π的所有零点之和等于( ) (A )4 (B )8 (C )12 (D )1610.设函数x x x f )41(log )(4-=,xx x g ⎪⎭⎫⎝⎛-=41log )(41的零点分别为21x x 、,则( )A . 121=x xB .1021<<x xC .2121<<x xD . 21x x 2≥二、填空题(本大题共5小题,每小题5分,共25分。
倒装
倒装下列情况句子需要全部倒装(1>表示方位地副词(如there,here,up,down,out,in,away等>位于句首,句子谓语是go,come,run等表示位置地动词,可将谓语动词全部置于主语之前.There goes phone again.It’s not stopping ringing all morning.电话铃又响了.整个上午都响个不停.There remains the possibility that mistakes have been made.仍然有可能出了差错.Here comes the train to Beijing.去北京地火车来了.There goes the bell.铃响了.Down came the rain.下雨了.但主语是人称代词时,主语仍置于动词之前.Here he comes.他来了.Here it comes.它来了.(2>由一些表示方位地介词短语引起.In the middle of the mountain lies a temple.山里有座庙.Inside the temple live many monks.庙里有很多和尚.(3>一些作表语地形容词放在句首.Seated in the lecture hall are hundreds of students.演讲大厅里坐着数百名学生.Present at the conference were many famous people.出席会谈地是很多著名人士.下列情况需要部分倒装(1>句子以never,seldom,rarely,little,hardly,scarcely等否定意义地副词以及by no means,not until,not a word,not a single等否定词开头地词组一般都用部分倒装语序. Never in all my life have I felt so humiliated.我这辈子从未感到如此受辱.Seldom in my life have I met so determined a person.一生中我很少见到如此果断地人.Not a word did he say at the last meeting.在上次会议上他一句话都没说.(2>hardly...when,no sooner...than,not only...but also引导两个分句时,将前一个分句中地主谓作部分倒装,后一个分句中地主谓语序不变.Hardly had he began to speak when his father stopped him.他刚开口发言就被父亲制止了.No sooner had I left my house than it began to rain.我刚刚离开家就下雨了.(3>当句子用so,nor,neither开头,来说明前面一句话中谓语表示地情况,也适用于另外一些人或物时,主语和谓语部分倒装,这时谓语只是用助动词、情态动词或系动词来表示.其常见句型是:so/neither/nor+be (have/do等助动词或情态动词>+主语.Frank adores dogs and so does his wife.弗兰克非常爱狗,他妻子也一样.She couldn’t work out the answer,and nor could I.她算不出答案,我也算不出.(4>当only所修饰地副词、介词短语或状语从句位于句首时,采用部分倒装形式.Only then did I realize the importance.只有那时我才意识到重要性.Only when I see it with my only eyes do I believe it.只有亲眼见到,我才相信.(5>在so...that引导地结果状语从句中,当为了强调把so提到句首时,主谓要倒装.So moved was she that she could not say a word.她激动得一句话也说不出来.So loudly did he speak that even the people in the next room could hear him.他地声音那么大,连隔壁屋子里地人都听得见.So fast does light travel that it is difficult for us to imagine its speed.光速如此之快,我们很难想像.So frightened is he in the darkness that he dare not say a word.他在黑暗中十分害怕,一句话都不敢说.(6>as引导让步状语从句时句子要用倒装语序,即要将从句中地表语、状语或从句中地动词提到as地前面.在as引导地让步状语从句中,作表语地单数可数名词前不用任何冠词.Try as she might,Sue couldn’t get the door open.无论苏怎么努力,她都打不开门.Popular as he is,the President hasn’t always managed to have his own way.尽管总统很受人欢迎,但他也并非总按自己地方式办事.(7>在省略if地条件状语从句中,were,had或should要提到句首构成倒装.Had you come a few minutes earlier,you would have seen him.如果你早来几分钟,你会见到他.Should he be here next week,he would help us.如果他下周来这儿,他就帮助我们.1.(2009年上海卷>Hearing the dog barking fiercely,away________.A.fleeing the thief B.was fleeing the thiefC.the thief was fleeing D.fled the thief【解读】句意为:听到狗地狂叫声,小偷逃掉了.本题考查了全部倒装句.表地点方位地副词away放句首时,句子要全部倒装.正常地语序是:The thief fled away.【答案】 D2.(2009年全国卷Ⅰ>The computer was used in teaching.As a result,not only________,but students became more interested in the lessons.A.saved was teachers’ energyB.was teachers’ energy savedC.teachers’ energy was savedD.was saved teachers’ energy【解读】句意为:电脑被应用于教学中.结果,不仅节省了老师地精力,学生也对课堂更感兴趣了.此题考查not only用于句首时地倒装结构,not only用于句首时后面地句子必须用部分倒装.【答案】 B3.(2009年重庆卷>Unsatisfied________with the payment,he took the job just to get some work experience.A.though was he B.though he wasC.he was though D.was he though【解读】句意为:尽管对工资不满意,但为了获得工作经验,他还是接受了这份工作.本题考查though引导状语从句可用倒装地形式,即从句中地表语、状语或动词原形置于句首,但主谓顺序不变.though引导地从句也可以不倒装,前半句可写为:Though he was unsatisfied with the payment.【答案】 B4.(2009年山东卷>So sudden________that the enemy had no time to escape.A.did the attack B.the attack didC.was the attack D.the attack was【解读】句意为:这次袭击非常突然以至于敌人没有时间逃跑.so+adj.放于句首时,主句倒装.sudden是形容词,在句中作表语,故应用was.【答案】 C5.(2009年福建卷>For a moment nothing happened.Then________all shouting together. A.voices had come B.came voicesC.voices would come D.did voices come【解读】句意为:那会儿,什么都没发生.之后大家一起欢呼起来.本题考查倒装句型,副词then,away,out,in 等置于句首,且主语是名词时,主谓要全部倒装.【答案】 B6.(2009年江苏卷>Distinguished guests and friends,welcome to our school.________the ceremony of the 50th Anniversary this morning are our alumni (校友> from home and abroad. A.Attend B.To attendC.Attending D.Having attended【解读】句意为:尊敬地来宾朋友们,欢迎莅临我校.今天早上参加50周年庆典地是来自国内外地校友.本句为倒装句,正常地语序应该是:Our alumni from home and abroad are attending the ceremony of the 50th Anniversary this morning.【答案】 C7.(2009年四川卷>Not until I came home last night________to bed.A.Mum did go B.did Mum goC.went Mum D.Mum went【解读】句意为:昨晚妈妈直到我回家才上床睡觉.not until引导状语从句且提前置于句首需要部分倒装,又因为时态是过去时(从came可知>,所以要将助动词did提前.【答案】 B8.(2008年上海卷>So much of interest________that most visitors simply run out of time before seeing it all.A.offers Beijing B.Beijing offersC.does Beijing offer D.Beijing does offer【解读】so much置于句首,后面地句子应用部分倒装,即将助动词、情态动词提到主语前面.【答案】 C9.(2008年陕西卷>Not until the motorbike looked almost new________repairing and cleaning it.A.he stopped B.did he stopC.stopped he D.he did stop【解读】句意为:他把摩托车擦洗和修补得像新地一样才停止下来.not until引导地状语(或状语从句>放在句首,主句部分需部分倒装,所以只有B符合题意.【答案】 B10.(2007年安徽卷>Little________that we were watching his every move,so he seemed to be going his own way in this business.A.he realized B.he didn’t realizeC.didn’t he realize D.did he realize【解读】本题考查倒装结构.否定词little位于句首时句子要部分倒装.【答案】 D1.(2010届重庆一中期中测试>Not until he called the secretary three times________that the manager went to an important meeting.A.did he tell B.he toldC.was he told D.he was told【解读】否定词not置于句首时,句子要用部分倒装,加之he与tell为动宾关系,故主句应用被动语态;所以选C.【答案】 C2.(2010届福建部分重点中学联考>Only under special circumstances________to take make-up tests.A.are freshmen permittedB.permitted are freshmenC.freshmen are permittedD.are permitted freshmen【解读】only后面跟状语位于句首时,句子要部分倒装,故答案为A.【答案】 A3.(2010届江西高安中学月考>—Did you see who the driver was?—No,so quickly________that I couldn’t get a good look at his face.A.does the car speed by B.the car sped byC.did the car speed by D.the car speeds by【解读】考查倒装句.句型so...that...中so与其后形容词或副词置于句首时,主句部分采用部分倒装结构;此句时态为一般过去时,借助于助动词did构成倒装句.【答案】 C4.(2010届江西上高二中月考>________he is,________he can do something that grown-ups do.A.A boy as;but B.A boy though;yetC.Boy as;yet D.Boy as;but【解读】考查特殊句式.句意为:虽然他只是一个孩子,但是他可以做一些成年人做地事情.前半句是as引导地让步状语从句,表语前置;此处表语为名词,其前不加冠词.此结构可以和yet,still等连用,但不可与but连用.【答案】 C5.(2010届九江地区联考>Hardly________the phone________I was told that the hotel had been booked full.A.I had picked up;whenB.had I picked up;thenC.had I picked up;whenD.I had picked up;then【解读】考查倒装句和固定句式.本句使用了“hardly...when...”句式,表示“刚一……就……”;当否定副词hardly放在句首时,主句要用倒装结构,因此选C.近年高考试题地单项填空部分有不少试题都呈现“复合型”,一个试题中考查两个或多个语法知识.【答案】 C6.(2010届抚州地区联考>Only when class began________that he had left his book at home. A.will he realize B.he did realizeC.did he realize D.should he realize【解读】考查倒装句,当only+状语位于句首时,主句要用部分倒装形式.【答案】 C7.(2010年皖南八校第二次联考>Little________about H1N1 so far,so there is no doubt that many people are afraid when talking about the disease.A.did scientists knownB.scientists have knownC.have scientists knownD.had scientists known【解读】本题考查时态和倒装.根据关键词so far,可以确定用现在完成时,故排除A、D 两项;little表示否定,放句首要倒装.【答案】 C8.(2009年福州检测>“By no means,” declared the captain.“________give way to disappointment.”A.we would B.we willC.might we D.shall we【解读】考查倒装句型.by no means位于句首句子要倒装,根据句意应该用shall we.【答案】 D9.(2009年南昌二模>Not until he called the secretary three times________that the manager went to an important meeting.A.did he tell B.he toldC.was he told D.he was told【解读】考查倒装.not until 置于句首,句子要部分倒装;he 与tell之间存在着动宾关系,要用被动语态,所以答案为C.【答案】 C10.(2009年绵阳市第三次诊断>________,she talks a lot about her favorite singers after she went home.A.A quiet student as she may beB.Quiet as she may be a studentC.Be a quiet student as she mayD.Quiet student as she may be【解读】考查倒装结构.句意为:尽管她是个寡言地学生,但回家后关于她喜欢地歌手她也谈了很多.该倒装结构为:adj.+n.(单数>+as+主语+谓语.【答案】 D11.(2009年西安八校联考二>By the side of the Bird’s Nest________,completed in 2008. A.there standing the Water CubeB.does the Water Cube standC.the Water Cube standsD.stands the Water Cube【解读】考查倒装.由于地点状语前置,句子应采用全部倒装语序,即把整个谓语放在主语之前.语境为:鸟巢地旁边就是2008年建成地水立方.【答案】 D12.(2009年福州检测>Many people agree that never in history________a more splendid opening ceremony than that of the Beijing Olympics.A.there were B.has there beenC.there has been D.were there【解读】考查倒装结构.在从句中,否定副词never置于句首,所以要用部分倒装.【答案】 B13.(2009年苏州模拟>Not a single word________when he left home and joined the army in 1941.A.did he leave B.left heC.did leave he D.he left【解读】考查倒装语序.not a single word位于句首时,句子地主语与谓语应该使用部分倒装语序.【答案】 A14.(2009年南通三模>We must apply what we have learned to our daily work because in no case________from practice.A.should theory separateB.should theory be separatedC.theory should separateD.theory should be separated【解读】考查倒装结构.从in no case可知,后面地句子应用部分倒装,同时theory和separate为动宾关系,应用被动结构,故选B项.【答案】 B15.(2009年东北三校联考>—Can I smoke here?—No.In no circumstances________in the library.A.smoking permitsB.smoking is permittedC.does smoking permitD.is smoking permitted【解读】考查倒装句.in no circumstances 表示否定,意思是“决不,在任何情况下都不”,放在句首时,句子要倒装,由此排除A、B两项;根据句意可知,permit应该用于被动语态,所以D项正确.【答案】 D申明:所有资料为本人收集整理,仅限个人学习使用,勿做商业用途.。
江西省上高二中2011-2012学年高一下学期第二次月考 数学
1高一年级下学期第二次月考数学试卷一、选择题1、等比数列{}n a 中,1a =32,q=21-,则6a =( )A.-1B.1C.2D.212、等差数列{}n a 中,2a =3,8a =9,则前9项和9S =( ) A .45 B.54 C.52 D.1083、在△ABC 中,a =2, b=6,C=60°,则三角形的面积S=( ) A .63 B.23C. D.64、向量(3,1),*||5,a x x N a a =-∈=且则与垂直的单位向量是( )A .43(,)55-B .43(,)55-C .4343(,)(,)5555-或 D .43(,)55-或43(,)55-5、在ΔABC 中,222,a b c ab C +-=∠则=( ) A .1200B .600C .450D .3006、若数列{}n a 的前n 项和11357(1)(21)n n S n -=-+-++-- ,则10714S S S +-为( )A .-2B .11C .17D .217、若数列{}n a 中满足11201012,1,n na a a a +==-则=( ) A .2 B .1 C .12D .-18、等差数列{}n a 中,18a =-,它的前16项的平均值是7,若从中抽取一项,余下的15项的平均值是7.2则抽取的是( ) A .第7项 B .第8项 C .第15项 D .第16项9、知||1,|2,0O A O O A O B =⋅= ,点C 在∠AOB 内且∠AOC=450,设(,),mO C m O A n O B m n R n=⋅+⋅∈ 则=( ) A .12B.2CD .310、数列{}n a 满足111291111,,,2n n n n n n a a a a a a a a a -+-+--===则为( ) A .912B .12C .19D .9二、填空题11、公差不为零的等差数列{}n a 中,1416,,a a a 成等比数列,则123456a a a a a a ++++=12、数列20091{},,,(1)n n n n a a S S n n =+前项和为中则=13、各项均为正数的等比数列{}n a 中,若5621222108,log log log a a a a a ⋅=+++ 则=14、已知点A(1,-2),若向量(2,3),||AB a AB ==与同向B 坐标为。
江西省上高二中2011届高三第二次月考(数学文)
2011届高三年级第二次月考数学试卷(文科)卷参考公式:1()'ln ,(log )'(01)ln x x xa a a a a a x a==>≠且一、选择题(5×10=50分)1、已知集合{},{},A B A B ==⋂直线集合圆则中元素个数为( ) A .2个B .1个C .0个D .以上都不对2、函数1()lg(1)f x x=-定义域是( )A .(-∞,1)B .[0,+∞]C .(0,1)D .(1,+∞)3、命题“若22x y >则x y >”的逆否命题是( ) A .若22x y <则x y < B .若x y >则22x y > C .若x y ≤则22x y ≤D .若22x y x y ≥>则4、已知命题2:[1,2],0P x x a ∀∈-≥,命题2:,220q x R x a x a ∃∈++-=,若命题“p q 且”是真命题,则实数a 的取值范围是( )A .21a a ≤-=或B .212a a ≤-≤≤或C .2a ≤-D .21a -≤≤5、已知函数()f x =10023,0,()1,log ,0x xx f x x x +⎧≤⎪≥⎨>⎪⎩若则的取值范围是( ) A .[2,)+∞ B .[1,0]-C .[1,0][2,)-⋃+∞D .(,1](0,2]-∞-⋃6、“a=0”是函数2()y x x a =-为奇函数的( )A .充要条件B .必要不充分条件C .充分不必要条件D .既不充分也不必要条件7、已知函数()f x 满足112()()||f x f x x -=,则()f x 的最小值是( )A .2B. C .23D.38、已知函数228()log ,(4,8),()()xf x x y f x f x =∈=+则函数的值域为( )A .[8,10)B .26(,10)3C .26[8,)3D .25(,10)39、设集合1,11[0,),[,1],()2222(1),x x A A B f x x x B⎧+∈⎪===⎨⎪-∈⎩函数, 若(())m A f f m A ∈∈且,则实数m 的取值范围是( )A .11(,)42B .11(,]42C .1(0,]4D .3[0,]810、已知函数212()log [(1)2]f x ax a x =---的值域为R ,且()f x 在(2,5)上是减函数,则实数a 的取值范围是( )A .0a >B .0a ≥C .02a ≤≤D .942a -≤≤-二、填空题(4×6=24分)11、已知幂函数21()(1)m f x m m x -=--在(0,)+∞上是增函数,则实数m=12、若23log 1,44x xx -=+则的值为。
江西省高中,2015届高三上学期,第二次月考化学试题
江西省上高二中2015届高三上学期第二次月考化学试题本试卷可能用到的相对原子质量有:H:1 C:12 N:14 O:16 S:32 Se:79 Cl:35.5I:127 Na:23 Mg:24 Al:27 K:39 Mn:55 Fe:56 Cu:64一、选择题(每小题3分,共48分)1.相同质量的钠在下列情况下产生氢气最多的是()A.放在足量水中B.放在足量盐酸中C.放在足量CuSO4溶液中D.用刺有小孔的铝,包好放入足量水底中2.下列各物质的学名是:Na2S2O3叫硫代硫酸钠;CaS x叫多硫化钙;Na2O2叫过氧化钠;KO2叫超氧化钾。
试综合上述命名规律,分析回答:Na2CS3应读做()A.硫代碳酸钠B.多硫碳酸钠C.过硫碳酸钠D.超硫碳酸钠3.纯碱和小苏打是厨房中两种常见用品,下列区分它们的做法正确的是()A.分别用炒锅加热两种样品,全部分解挥发,没有残留物的是小苏打B.用洁净铁丝蘸取两种样品在煤气灯火焰上灼烧,火焰颜色发生明显变化的是小苏打C.先将两样品配成溶液,分别加入石灰水,无白色沉淀生成的是小苏打D.用两只玻璃杯分别加入少量的两种样品,再加入等量的食醋,产生气泡速度快的是小苏打4、下列各化学反应的离子方程式中,有错误的是()A.铝与氢氧化钠反应:2Al+2OH-+2H2O=2AlO2-+3 H2↑B.氧化铝溶于氢氧化钠溶液:Al2O3+2OH-=2AlO2-+H2OC.碘化亚铁溶液中滴入足量溴水:2Fe2++2I-+2Br2=I2+2Fe3++4Br-D.碳酸氢镁溶液中加过量澄清石灰水Mg2++2HCO3-+2Ca2++4OH-=2CaCO3↓+2H2O+Mg(OH)2↓5.下列有关实验的叙述正确的是()A.可用碱式滴定管量取12.85 mL KMnO4溶液B.实验室蒸馏石油可用如图甲所示实验装置C.取用金属钠或钾时,没用完的钠或钾要放回原瓶D.配制500 mL 0.4 mol·L-1 NaCl溶液,必要的仪器如图乙所示6与I2的氧化性强弱D 用NH4Cl固体和Ca(OH)2固体制备并收集NH3酒精灯、烧杯、导管、集气瓶正确的是( )A.分散系的分类:B.AlCl3和NaOH溶液反应后铝元素的存在形式:C.常温下甲基橙的变色范围:D.CO2与NaOH溶液反应的产物:8.下列有关实验操作、现象和解释或结论都正确的()选项实验操作现象解释或结论①过量的Fe粉中加入稀3HNO,充分反应后,滴入KSCN溶液溶液呈红色稀3HNO将Fe氧化为3Fe+②AgI沉淀中滴入稀KCl溶液有白色沉淀出现AgCl比AgI更难溶③Al箔插入稀3HNO中无现象Al箔表面被3HNO氧化,形成致密的氧化膜④用玻璃棒蘸取浓氨水点到红色石蕊试纸上试纸变蓝色浓氨水呈碱性⑤将浓硫酸滴到蔗糖表面固体变黑膨胀浓硫酸有脱水性和强氧化性⑥将足量的22H O溶液滴入4KMnO溶液中4KMnO溶液褪色2MnO4-+7H2O2+6H+=2Mn2++6O2↑+10H2O⑦将一小块Na放入无水乙醇中产生气泡Na能置换出醇羟基中的氢⑧将水蒸气通过灼热的铁粉粉末变红铁与水在高温下反应9、下列说法正确的是()A.铁是位于第四周期第ⅧB族元素, 是一种重要的过渡元素B.四氧化三铁是氧化铁和氧化亚铁组成的混合物C.14克铁粉和7克硫粉混合后高温下充分反应能生成21克硫化亚铁D.铁在溴蒸气中点燃可生成FeBr310.下列各组中的两种物质相互反应时,无论哪种过量,都可以用同一个离子方程式表示的是()①碳酸钠溶液与盐酸 ②偏铝酸钠溶液与盐酸 ③二氧化碳与氢氧化钠溶液 ④硝酸银溶液和氨水 ⑤氯化铝与氨水⑥碳酸氢钠溶液与澄清石灰水 A .③⑤B .①③⑥C .仅有⑤D .②④11.下列制取、检验、提纯或保存物质的方法可行的是( ) ①向某溶液中加入KSCN 溶液,检验该溶液是否含有Fe 3+②用植物油、NaOH 溶液制取肥皂 ③向FeCl 3饱和溶液中滴加NaOH 溶液制取Fe(OH)3胶体 ④用焰色反应检验K +时需透过蓝色钴玻璃观察 ⑤少量液溴用水液封后密封保存在棕色试剂瓶中 ⑥向混有乙酸的乙酸乙酯中加入NaOH 溶液后再分液,提纯乙酸乙酯 A .①③⑤⑥ B .②④⑤⑥ C .①②④⑤ D .①③④⑥12.下列各组物质中,W 为主体物质,X 为杂质,Y 为除杂试剂,Z 是除杂方法,其中正确选用了试剂和处理方法的是( )13.无色溶液可能由K 2CO 3、MgCl 2、NaHCO 3、BaCl 2溶液中的一种或几种组成。
江西省上高二中2013-2014学年高一下学期第二次月考 英语试题
江西省上高二中2013-2014学年高一下学期第二次月考英语试题一.听力:(共30分,每小题1.5分)第一节听下面5段对话, 每段对话后有一个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
听完每段对话后, 你都有10秒钟的时间回答有关小题和阅读下一小题。
每段对话仅读一遍。
1. Why can’t the man tell the woman the way?A. He’s lost.B. He doesn’t want to help her.C. He is not familiar with the area.2. How does the man feel about the play?A. It’s very good.B. It’s very terrible.C. It’s the best one he has ever seen.3. What is the time now?A. 830.B. 820.C. 800.4. What are the speakers talking about?A. Their hobbies.B. The players.C. The games.5. What color is the shirt?A. Yellow.B. Green.C. Blue.第二节听下面5段对话或独白, 每段对话或独白后有几个小题, 从题中所给的A、B、C三个选项中选出最佳选项, 并标在试卷的相应位置。
听每段对话或独白前, 你将有时间阅读各个小题, 每小题5秒钟;听完后, 各小题将给出5秒钟的作答时间。
每段对话或独白读两遍。
听下面一段对话, 回答第6和第7两个小题。
6. What is the woman?A. A librarian.B. A shop assistant.C. A teacher.7. What is the woman’s suggestion?A. Buying some books on computers.B. Borrowing some magazines.C. Asking some experts for advice.听下面一段对话, 回答第8和第9两个小题。
江西省上高二中2014-2015学年高一上学期第二次月考试题 化学
江西省上高二中2014-2015学年高一上学期第二次月考试题化学可能用到的相对原子质量:H=1 S=32 Cl35.5 O=16 C=12 Na=23一、选择题(每题3分,共18题,48分)1.下列实验能达到目的的是()A.加稀盐酸后过滤,除去混在铜粉中的少量镁粉和铁粉B.将蒸发皿放置在铁架台的铁圈上,并加垫石棉网加热C.用玻璃棒搅拌漏斗中的液体以加快过滤的速度D.加入盐酸以除去硫酸钠中的少量碳酸钠杂质2.下列叙述正确的是()A.1 mol H2O的质量为18 g/molB.CH4的摩尔质量为16 gC.2 mol NaOH溶于1 L水中配成溶液的浓度为2 mol·L―1D.3.01×1023个SO2分子的质量为32 g3.在标准状况下,所占体积最大的是()A.6 g H2B.6.02×1023个N2分子C.44.8 L HCl D.98 g H2SO44.下列有关0.1 mol·L-1NaOH溶液的叙述正确的是( )。
A.0.1L该溶液中含有NaOH 4.0gB.从1L该溶液中取出100mL,所取出的NaOH溶液的浓度为0.01 mol·L-1C.100 mL该溶液中含有OH- 0.01molD.在1 L水中溶解4g NaOH即可配制得0.1 mol·L-1 NaOH溶液5.在物质分类中,前者包括后者的是( )。
A.化合物、电解质B.氯化物、化合物C.溶液、胶体D.溶液、分散系6.在强酸性无色透明溶液中,下列各组离子能大量共存的是()A.Fe3+、K+、Cl-、NO3- B.Ag+、Na+、NO3-、Cl-C.Zn2+、Al3+、SO42-、Cl- D.Ba2+、NH4+、Cl-、HCO3-7.除去下列溶液中的杂质(括号内是杂质)所用试剂不正确...的是( )。
A.KOH溶液[K2CO3]:用Ca(OH)2溶液B.NaOH溶液[Ba(OH)2]:用Na2SO4溶液C.HNO3溶液[HCl]:用AgNO3溶液D.NaCl溶液[Na2SO4]:用Ba(NO3)2溶液8.下列离子方程式书写正确的是( )。
江西上高二中高三年级第二次月考地理试题
上高二中高三年级第二次月考地理试题命题人:刘建军一、选择题(25×2=50分)读我国南方某地等高线地形,回答1~2题1.图中最大高差可能是()A. 320米B. 397米C. 412米D.506米2.关于图示地区说法可信的是 ( )A. 在N地看不到甲村B. 该地地势西北高、东南低,地形以山地为主C. 该地可能位于四川盆地D. 如陡崖M在甲村正南方,则乙村处的河段自北向南流右图为我国某地形图。
读图回答3,4题。
3.某图中四地中②地森林生长最旺盛,其原因最可能是()A.因地势较低,热量远优于其他三地B.因处于山脊,地势高,光照条件最好C.因地势较为平坦,土层深厚,水源充足D.因受地形影响,降水较其他地区丰富4.③地森林比①地长势较好的原因可能是()A.③地日照较强,太阳辐射收入多于①地B.③地蒸发较少,土壤水分条件比①地好C.③地气温较①地高,且日变化大D.③地降水较多,水源比①地充足读右图,回答5,6问题5.若图示为两条纬线,P点昼长小于Q 点昼长,那么该图所在位置和月份分别为()A.北半球、6月B.南半球、6月C.北半球、12月D.南半球、4月6、若图所示是地球侧视图,PQO为赤道,图示部分既是西半球又是夜半球,且北京正午人影将越来越短,则此时北京时间为( )A.3月21日3:20B.3月21日15:20C.9月23日3:20 D.9月23日15:20右图为不同纬度四地正午太阳高度季节变化玫瑰图,读图回答7、8题。
7.图示四地纬度由高到低的顺序是()A.①③④②B. ②①③④C.④②①③.D.③④②①8.冬至日图中四地白昼时间由长到短依次是()A.①④③②B.②①④③C.④③②①D.③②①④王教授于北京时间10:20从杭州(1200E、30o N)出发去夏威夷群岛进行野外考察,飞机飞行了4小时40分钟到达该地,当地时间为20:00。
下图为考察的某岛等高线地形图,读图回答9、10、题9、王教授所考察的岛屿的经度位置是()A.1650EB.1800C.1650WD.1600W10、右图是王教授在图中④处考察拍摄的太阳照片,拍摄时当地时间最有可能是()A.5:30B.6:30C.17:30D.18:30右图为某河段示意图,箭头表示河流流向。
江西省宜春市上高县上高二中2024-2025学年高二上学期10月月考英语试题
江西省宜春市上高县上高二中2024-2025学年高二上学期10月月考英语试题一、阅读理解Discover exciting optional courses at our school and join us to explore your interests and develop new skills!Podcasting 101Dive into the active world of podcasting (播客) and improve your speaking and technical skills. This course offers hands-on training in making interesting videos on topics of your choice.A perfect stage to express yourself and learn the ropes of digital storytelling.·Schedule: Fridays, 4:30 PM — 5:15 PM·Requirements: Please bring a USB stick Easy CarpentryRelease your creativity and manual skills with our Easy Carpentry (木工) workshop. Learn the basics of carpentry, including the safe use of tools, as you create functional and decorative items like tables, birdhouses and musical boxes.·Schedule: Mondays, 3:30 PM — 4:30 PM·Requirements: Safety glasses required Show ChoirExplore the art of singing performance and dance routines in our Show Choir program. Take part in singing and dancing to a variety of lively songs. Work together with other members to stage an impressive end-of-term performance. This program is a fantastic opportunity to make new friends.·Schedule: Thursdays, 1:00 PM — 1:45 PM·Requirements: No items necessary Yoga and Y ouStart a journey of self-discovery and relaxation with our Yoga and You class. Practice standing and balancing like trees and mountains to become more flexible and feel happier. Yoga promotes better sleep and a healthier figure.·Schedule: Wednesdays, 4:00 PM — 5:00 PM·Requirements: Please bring a towel and a yoga mat1.What skill will students develop in Podcasting 101?A.Performing first aid.B.Giving speeches on stage.C.Creating short films.D.Debating on heated topics.2.When can a student learn to make a hand-made decoration?A.Fridays, 4:30 PM—5:15 PM.B.Mondays, 3:30 PM—4:30 PM.C.Thursdays, 1:00 PM—1:45 PM.D.Wednesdays, 4:00 PM—5:00 PM. 3.Which course suits those who enjoy both physical activity and teamwork?A.Podcasting 101.B.Easy Carpentry.C.Show Choir.D.Yoga and You.Chinese food is well received by the world. Who doesn’t long for a favorite Chinese dish? But there is one interesting concept concerning Chinese food which is almost unheard of in the West, and which is becoming increasingly ignored by the youth of the East — the ancient custom of “tonic (滋补) food”.Tonic food is food which is consumed to improve one’s well-being or avoid sickness. For instance, it was once the custom for new mothers to eat a sesame oil (麻油) hot pot every day for the first month after giving birth. It was believed that this dish would benefit the muscles, reduce pain, improve circulation, stimulate sweating, and warm the body. Some foods, such as goat meat and spinach, are seen as “hot”, while others, such as Chinese cabbage and radishes, are seen as “cold”. One should be careful not to eat too much of either “hot” or “cold” food. However, how much “hot” or “cold” food one should eat depends on the time of the year, how the food is prepared and what it is prepared with, and the individual’s health.The custom of employing tonic food for a healthier life also influences the catering industry. Chinese herbal medicines, such as wolfberry (枸杞), can be found on many a restaurant menu, either added to fruit tea or as a beneficial addition to a dish. These herbs attract customers, such as overworked office staff, in need of a modest pick-me-up.So, whether you need to boost your strength with a large helping of chicken soup, or increase your mental powers with a serving of fish soup, you may find that this ancient Chinese custom could be just the tonic you were looking for.4.What is the present situation of tonic food?A.It is catching less attention.B.It is enjoyed by many young people.C.It is well-known worldwide.D.It is becoming increasingly popular.5.What is believed to benefit new mothers?A.Chinese cabbage.B.Fruit tea.C.Fish soup.D.Sesame oil hot pot.6.Which of the following best explains “catering” underlined in Paragraph 3?A.Medicine.B.Restaurant.C.Manufacture.D.Agriculture.7.What can be a suitable title for the text?A.The Charm of Chinese CuisineB.The Popularity of Tonic FoodC.An Introduction of Chinese Tonic FoodD.Differences Between Hot Food and Cold FoodIn 1983, Howard Blatt, an electrical engineer at MIT and a married father, collapsed in his kitchen due to a stroke (中风). This left him with a paralyzed arm and leg and severe aphasia.Aphasia does not affect intellect, so some aphasia sufferers liken it to living in a prison within their own brain; their minds work, yet they are unable to express themselves or understand spoken or written language. The condition can prevent them from speaking, reading, writing or comprehending, sometimes a combination of those, sometimes all of them. At least 2 million people in the U. S. have aphasia, commonly as a result of stroke.Describing his condition, Blatt said: “No talking — zip. Speech — zip. One incident. Changed life.” Blatt adapted to his physical disabilities but never fully recovered. Discovering aid networks for people with aphasia were a rarity in the early 1980s, he co-founded the Aphasia Community Group in 1990 with his wife and others. It’s one of the oldest and largest support groups for aphasia patients and their families, offering services like concerts, book groups, health information, and companionship.Mary Borelli, a stroke survivor, described the group as a lifesaver, providing understanding and a sense of belonging. The group helps break the isolation. Jerry Kaplan, a co-founder and Boston University speech-language pathologist, noted that newcomers often express relief at finding others who share their struggles. Thousands have attended since its founding, finding a safe, comfortable space to connect.Blatt focused on regaining function. He moved from a wheelchair to a leg brace, re-camed his driver’s license, and documented cross-country trips. He also pursued sculpting, house restorations, and created a newsletter called The Aphasia Advocate. Within the Group, he was a role model of adaptability and determination.The Aphasia Community Group, which will celebrate its 35th anniversary next year, remains one of Blatt’s enduring legacies. Kaplan emphasized Blatt’s determination, saying “Though given a tough break in midlife, with young children, at the top of his game in his profession, and his communication gifts were largely wiped out, he did not give in to this for 40-plus years. And not only did he survive; he thrived.”8.What is the second paragraph mainly about?A.The consequences of a stroke.B.The huge aphasia sufferers.C.The causes of a stroke.D.The symptoms of aphasia.9.Why did they set up the Aphasia Community Group?A.To provides companionship for lonely people.B.To address the lack of support for aphasia sufferers.C.To work on a medical cure for aphasia.D.To answer the call of MIT.10.According to the members, what is the significance of the Aphasia Community Group?A.It offers them financial assistance.B.It helps them regain their speech completely.C.It creates a caring community for them.D.It conducts extensive research on their conditions.11.Which saying effectively highlights Howard Blatt’s life story?A.Turn lemons into lemonade.B.Let nature take its course.C.As you sow, so shall you reap.D.Nothing ventured, nothing gained.Do you have a brain for math? New research indicates that levels of two key neurotransmitters (脑神经传递素)—— glutamate (谷氨酸) and gamma-aminobutyric acid(GABA) can predict mathematical abilities, suggesting brain chemistry may be playing a role in those who find math easy.The new study, published in the journal PLOS Biology, recruited 255 subjects (实验对象) extending a range of six- year-olds in primary school to university students. The research focused on glutamate and GABA, known to play a role in brain plasticity and learning. Based on prior research, the focus was on two brain regions linked with mathematical abilities—— the left intraparietal sulcus(IPS 顶叶内沟) and the left middle frontal gyrus (MFG 脑额中回).The results were interestingly different. In the youngest subjects high GABA levels and low glutamate levels in the left IPS were consistently associated with high math skills. But in the older university group the exact opposite was seen: low GABA and high glutamate were linked with strong mathematical abilities. Levels of both neurotransmitters in the MFG did not associate with math skills.The group was tested twice over 18 months, allowing the researchers to see if these neurotransmitter levels could predict mathematical ability into the future. And it worked, with neurotransmitter levels effectively predicting one’s success on math tests completed a year and a half later.Another recent study from the same research team looked specifically at GABA levels in MFG of 14 to 18 year-olds. That research indicated MFG GABA levels could effectively predict whether a student was still studying maths or had stopped that subject years prior.Cohen Kadosh, one of the researchers working on the study, says this may indicate math education can help stimulate the development of key brain regions. Further research will work on whether certain learning interventions (干预) can help those children less interested in math so these brain regions still get the developmental workout they need.“ Not every adolescent enjoys maths so we need to investigate possible alternatives, such as training in logic and reasoning that engage the same brain area as maths.” says Cohen Kadosh. 12.What is the new study aimed at?A.Revealing the structure of brain.B.Testing the link between brain regions.C.Exploring mathematical abilities of the subjects.D.Finding the tie between brain chemistry and math.13.What can be learned from paragraph 3 and 4?A.The levels of GABA decide one’s math skills.B.Low MFG glutamate means poor math ability.C.Neurotransmitter levels can predict mathematical ability into the future.D.The levels of Neurotransmitters in the MFG will affect math skills.14.How can math education be improved according to Cohen Kadosh?A.By training key relevant brain areas.B.By tracking slow learners’ early learning.C.By teaching math learners individually.D.By improving the levels of GABA.15.What can be the best title of the text?A.Ways to Promote Math SkillsB.Factors Affecting Math EducationC.Brain Activities Involved in Math StudyD.Neurotransmitters Predicting Math AbilityMore mainstream sources of news such as newspapers, radio and IV aren’t gone yet, but the Internet is growing and entrenching itself as the preferred source. Here are some of the reasons why the Internet is now the best source of news people hive.Online news is faster and more convenient while on the go. Soon after a major story occurs, it takes a few hours for news channels to report it live on cable. 16Social media makes news more relevant. Social media platforms are not just limited to sharing pictures and posting updates about our daily routines. 17 For example, when there is breaking news on the Internet, people can make comments and post their thoughts regarding the event. As a result, they get into a dialogue where different opinions are presented and debated.18 On the other hand, if you get news from cable TV,you have very limited options to discuss.You can get news directly from its source. Many newsmakers are already active on the Internet. Since all these newsmakers have an online presence. People can get news directly from the concerned source, public figures, and newsmakers. 19 . Their social media presence is verified (证实的) and it is easier to trust information coming from them.20 For generation Z, cable TV is limited to sports and movie channels. They don'tsit in front of the TV to watch a news bulletin. There primary source of information is the Internet. This is how they have grown up. It's unlikely they'll move away from digital anytime soon. And since this younger generation is the future, digital or Internet news is too.A.The future is digital.B.Traditional journalism still holds great value.C.That is, news doesn't have to be reported to you.D.This makes everyday news quite relevant for a while.E.The Internet is quick to judge and demand an apology.F.However, people can get news faster through social media.G.More importantly, it is a great way to understand the public’s perspective on certain issues.二、完形填空At just 14 years old, Heman Bekele from Virginia stood out as the winner of the 2023 Young Scientist Challenge. Among the ten finalists he 21 the title of “ America’s Top Young Scientist” with his 22 creation known as the Skin Cancer Treating Soap (SCTS), a bar of soap created for the very first time at a low cost to treat melanoma, the most common kind of skin cancer.Rather than a cure, Bekele’s brilliant idea 23 the development of a soap that aims to help the patient’s cells stay active while fighting melanoma. He always has endless passion for biology and technology, and the Young Scientist Challenge just 24 him with the perfect platform to display his ideas. Reflecting on his 25 , Bekele shared that his childhood experience had played a crucial role in 26 his innovative thinking. “Having witnessed people work tirelessly under the sun, I wanted to raise people’s awareness of 27 related to constant sun exposure.”“I wanted to make my idea accessible to a broad audience.” Bekele remarked during an interview with the media. Bekele also passionately expressed his 28 of turning the soap into a world where skin cancer treatment is within 29 for all.” He was grateful that he had received invaluable 30 from a product engineering specialist, who connected him with other scientists to 31 him to reach his ambitious plans.While similar methods are available for skin cancer treatments, his solution is a more 32 option. In the future, Bekele longs to 33 his invention by trial and error and establish a nonprofit organization 34 to providing fair skin cancer treatment to as many people as possible, bringing 35 in the battle against skin cancer.21.A.kept B.desired C.defended D.secured 22.A.groundbreaking B.instant C.far- reachingD.common23.A.focuses on B.relies on C.carries on D.agrees on 24.A.armed B.satisfied C.provided D.assisted 25.A.profession B.inspiration C.determination D.imagination 26.A.shaping B.showing C.quitting D.obeying 27.A.challenges B.crises C.risks D.advantages 28.A.fear B.doubt C.dream D.surprise 29.A.distance B.reach C.limit D.space 30.A.guidance B.welcome C.praise D.invitation 31.A.require B.remind C.press D.aid 32.A.fashionable B.affordable C.adaptable D.capable 33.A.picture B.clear C.control D.perfect 34.A.used B.addicted C.committed D.opposed 35.A.recognition B.hope C.comfort D.impact三、语法填空语法填空Fireworks began in ancient China before spreading West. The thinking goes 36 someone living in China around the first century B.C.37 (throw) a piece of bamboo on a fire and it exploded with a bang. Bamboo stalks (节) contain air pockets that can expand and blow up in extreme heat. Chinese travelers would carry bamboo on journeys in case they needed to create 38 loud noise to scare away wild animals.The next major development came around the ninth century, when gunpowder was invented.Chinese producers loaded up bamboo stalks with gunpowder 39 (create) perhaps the world’s first manufactured fireworks, and later began using paper tubes as well. These were employed to ward off evil spirits and celebrate births and weddings. By the 12th century, fireworks were being lit 40 entertainment purposes in China’s imperial court. Around the 14th century, primitive fireworks then made their way to Europe, 41 Italian artists constructed displays like theatrical sets called “machines” and set off fireworks inside them.Fireworks became far 42 (complex) thanks to advances in chemistry. The 19th century saw potassium chlorate (a chemical) 43 (use) to bring out brilliant colors in fireworks, such as red and green, and enhance their44 (bright).Over the years, innovations in technology led to some curious suggestions for 45 fireworks could help solve modern problems. Whalers experimented with rocket-powered harpoons (鱼叉) in the late 1800s, and inventor Gerhard Zucker attempted to use pyrotechnic rockets to deliver mail in the 1930s.Now pyrotechnic amusements have become a global phenomenon and almost the accepted way big events are celebrated.四、书信写作46.假如你是李华,是学校英文报“Advice”栏目的编辑。
江西省宜春市上高二中2014届高三上学期第二次月考 语文 Word版含答案
2014届高三年级第二次月语文试卷命题:龚慧明审校:陈颂群本次试卷分第Ⅰ卷(选择题)、第Ⅱ卷(非选择题)两部分,满分150分,测试时间150分钟。
答题时,请将答案直接写在答题卷相应的位置上。
第Ⅰ卷(选择题共36分)本卷共12小题,每小题3分,共36分。
在每小题给出的四个选项中,只有一项符合题目要求。
一、(18分,每小题3分)1.下列词语中加点的字,读音正确的一项是()A.桀骜.( áo) 噩.耗(è) 肯綮.(qìng) 不省所怙.(hù)B.譬.如(pì) 冠.冕(g uān)嫡.亲(dí) 休戚.相关(qì)C.琵琶.(pá) 洿.池(wū) 侘.傺(chà) 暴虎冯.河(píng)D.翌.年(yì) 戕.害(qiān g) 囊.括(náng) 量.体裁衣(liāng)2.下列词语中,没有..错别字的一组是()A. 哂笑聒噪险衅故弄悬虚B.萃取纂夺赍发山清水秀C.广袤瞥见阑珊再所不惜D.弭谤饿殍婆娑牙牙学语3.依次填入下列各句横线处的词语,最恰当的一组是()(1)一辆运载盐酸的货车在高速公路上发生了侧翻事故,交通、消防等部门的人员迅速赶赴出事现场,并做出了紧急。
(2)这次你有困难,我一定相助。
(3)社会进步了,生活水平提高了,我们虽已不用过那箪食瓢饮的日子,但那种的“豪爽”也是我们应该唾弃的。
A.处治鼎力一掷千金B.处置大力一掷千金C.处治鼎力一饭千金D.处置大力一饭千金4.下列各句中,标点符号使用正确的一项是()A. 杏鲍菇是近年来开发栽培成功的集食用、药用于一体的珍稀食用菌新品种,其菌肉肥厚、质地脆嫰、菌柄比菌盖更脆滑、爽口。
B.最近几年,“草鞋书记杨善洲”“雷锋传人郭明义”“最美妈妈吴菊萍”等时代先锋不断涌现,他们的事迹打动人心。
C.加减乘除,算不尽您作出的奉献!诗词歌赋,颂不完对您的崇敬!您用知识甘露,浇开我们理想的花朵,您用心灵清泉,滋润我们情操的美果。
江西省上高二中2015届高三上学期第二次月考地理试卷(解析版)
江西省上高二中2015届高三上学期第二次月考地理试卷(解析版)一、选择题人们可用观测日影的方法测量所在地的纬度。
如图甲所示,OL为当地一竖立直杆,OP和OQ 是某日不同时刻OL的日影。
图乙中两条曲线分别示意某两地3月份到7月份的昼长变化。
完成下列各题。
1.直杆所在地的纬度()A.80°SB.80°NC.75°SD.65°N2.观测当日①、②两地昼长分别约为()A.8小时 14小时30分B.10小时 13小时30分C.16小时 9小时30分D.17小时 10小时30分【答案】1.A2.C【解析】试题分析:1.读图甲,根据OL杆影的方向,分别是正南和正北方向,说明该地位于高纬地区,有极昼现象。
OP、OQ分别是一日中最大、最小太阳高度,即正午太阳高度和子夜时太阳高度。
根据太阳高度的差值可以判断该日的太阳直射点纬度为(25°+5°)/2=15°S,该地正午时日影朝南,说明位于南半球,所以该地纬度是80°S,A对。
2.读图乙,①地6月21日昼长最短,约7小时,说明位于南半球,②地6月21日左右昼长为15小时左右,应在北半球。
结合前面分析,观测当日太阳直射纬度约是15°S,南半球各地应昼长夜短, A、B错。
太阳直射点从赤道移到南回归线用三个月的时间移动23.5°,则移动15°约用两个月时间,即该日为11月21日左右。
图中5月21日①、②两地的昼长分别为8小时和14小时30分,其昼夜长短情况与11月21日正好相反,C对。
考点:太阳直射点移动规律,正午太阳高度计算。
读“大别山山麓与山顶太阳辐射强度及其垂直变化率折线图”,完成下列各题。
3.有关该地太阳辐射强度的叙述,正确的是( )A.山麓始终大于山顶B.山顶始终大于山麓C.1~8月山麓一直增大D.9~12月山顶一直减小4.关于该地太阳辐射垂直变化的叙述,正确的是( )A.7月最大 B.12月最大C.6月随高度递增 D.11月随高度递减5.该地太阳辐射最大的月份不是6月,而是8月,其主要原因可能为8月( )A.太阳高度大 B.白昼长 C.晴天多 D.阴雨天多【答案】3.C4.A5.C【解析】试题分析:3.读图,根据图例判断,山麓只在夏季太阳辐射强度大于山顶,A、B错。
2010届高三最新月考试题分类汇编(1) 大气
2010届高三最新月考试题分类汇编(1):大气(福建省漳州三中2010届高三第一次月考)读“天气系统图”,回答 1-2 题。
1.左图的天气系统剖面是沿右图中( ) A ① 线绘制的 B ② 线绘制的 C ③线绘制的 D ④ 线绘制的 2.右图所示天气系统( ) A 为南半球的锋面气旋 B . P 处气温高于 Q 处气温 C 多出现在副热带地区 D 多出现在海洋上,陆地一般不会出现答案 1.D 2.B3.(江西省上高二中2010届高三上学期第一次周练)气象谚语有“露重见晴天”的说法。
就此现象,下列叙述正确的是( )A .天空云量少,大气保温作用强B .地面辐射强,地表降温慢C .空气中水汽少,地表降温慢D .大气逆辐射弱,地表降温快 答案 D(福建省才溪中学2010届高三摸底测试)气象部门用五天平均气温的高低(简称候平均气温)作为划分四季的指标:低于10摄氏度的时间段为冬季,高于22摄氏度的为夏季,10-22度之间的分别为春秋两季。
读图9“2008年11月7日(立冬)我国大陆部分各地季节状况”,回答4-5题。
4.形成图中我国各地在同一天出现三种季节的主要原因是( )A.海陆热力性质差异 B.地形地貌地区差异 C.各地纬度差异大 D.各地经度差异大图9图3 5.若此时从西南到长江以南地区形成大范围降雨( )A.降雨形成原因可能是受副热带高压控制B.锋面在附近活动,并可能诱发西南地区泥石流灾害 C. 台风登陆造成该地区大范围降雨D. 在这种天气系统控制下西南地区可能诱发地震 答案 4.C 5.B(湖南省长沙二中2009届高三上学期第一次质量检测)读我国东部某地的等高线示意图和该地区的气候资料表,图中等高线所示高度分别为100m 、200m 、300m 、400m 。
综合分析后,完成6—8题。
6.下列判断正确的是 ( )A .从图中的H 地看不到G 地B .图中海拔高度G 处100m ,H 处为400mC .该地典型植被为热带雨林D .该地河段最主要的补给类型为雨水 7.图中城镇与H 地相对高度的最大值为h ,则h 为 ( ) A .199<h <200 B .289<h <290 C .299<h <300 D .300<h <301 8.图中地区适宜发展的经济作物为 ( ) A .棉花 B .苹果 C .甘蔗 D .甜菜 答案 6.D 7.C 8.C9.(广东省佛山市2009届高三第一次质量检测)图3为某区域传统民居的建筑示意图,据图分析该区域所属气候类型最有可能是( )A .热带沙漠气候B .亚热带季风气候C .热带雨林气候D .温带海洋性气候答案 A(四川省成都市2010届高三摸底测试)读世界某区域气候分布图,回答10-14题。
江西省宜春市上高二中2024-2025学年高三上学期9月月考数学试题
江西省宜春市上高二中2024-2025学年高三上学期9月月考数学试题一、单选题1.如图,已知全集U =R ,集合()(){}2310A x x x =-⋅+≤,{}0B x x =>,则图中阴影部分表示的集合为( )A .{}1x x ≤-B .{}1x x <-C .3{|0}2x x x ≤>或D .3{|0}2x x x <>或2.若幂函数()()2231m f m x m x -=--在()0,∞+上单调递增,则实数m 的值为( )A .2B .1C .1-D .2-3.若函数()31,4,,4x a x x f x x a x -⎧+-≥⎪=⎨⎪<⎩在R 上单调递增,则实数a 的取值范围是( )A .()0,1B .(]1,4C .(]1,8D .(]1,164.函数22sin 1()e ex xx x f x --+=-的部分图象大致为( ). A . B .C .D .5.冰箱空调等家用电器使用了氟化物,氟化物的释放破坏了大气上层的臭氧层,使臭氧量Q 呈指数函数型变化.当氟化物排放量维持在某种水平时,臭氧量满足关系式0.00250e tQ Q -=⋅,其中0Q 是臭氧的初始量,e 是自然对数的底数,t 是时间,以年为单位.若按照关系式0.00250e t Q Q -=⋅推算,经过0t 年臭氧量还保留初始量的四分之一,则0t 的值约为(ln 20.693≈)( ) A .584年B .574年C .564年D .554年6.已知函数()e sin 1ex xa f x x a -=⋅+,则“函数()f x 的图象关于y 轴对称”是“1a =”的( ) A .充分不必要条件 B .必要不充分条件 C .充要条件D .既不充分也不必要条件7.斐波那契数列因数学家斐波那契以兔子繁殖为例而引入,又称“兔子数列”. 这一数列如下定义:设{}n a 为斐波那契数列,()*12121,1,3,N n n n a a a a a n n --===+≥∈,其通项公式为n nn a ⎡⎤⎥-⎥⎝⎭⎝⎭⎦,设n是2log 1(14(x x x ⎡⎤⎣⎦-<+的正整数解,则n 的最大值为( ) A .5B .6C .7D .88.已知π10e a =,9π1sin 10b =+,61.1c =,则a ,b ,c 的大小关系为( ) A .a b c >>B .a c b >>C .c a b >>D .c b a >>二、多选题9.下列说法正确的是( ) A .若a b >,则22ac bc >B .命题“R x ∃∈,()12f x <≤”的否定是“R x ∀∈,()1f x ≤或()2f x >”C .若R x ∈,则函数y = 2D .当R x ∈时,不等式210kx kx -+>恒成立,则k 的取值范围是[)0,4 10.已知,x y 为正实数,2x y +=,则( )A .xy 的最大值为1B .2y x y+的最小值3 C .2212x y x y +++的最小值为56D .2211()()55x y ++的最小值为212511.已知函数()f x 是定义在R 上的可导函数,其导函数为()(),2g x f x +和()1g x +都是奇函数,()11f =,则下列说法正确的是( )A .()g x 关于点()1,0对称B .()()0f x f x +-=C .()20251g =D .20240()0k f k ==∑三、填空题12.已知函数()()2lg 1f x x ax =++在区间(),2-∞-上单调递减,则a 的取值范围为.13.我国南宋数学家秦九韶在《数书九章》中记述了“三斜求积术”,即在ABC V 中,角,,A B C所对的边分别为,,a b c ,则ABC V 的面积S =3a =,且22cos cos 3c b C c B -=,则ABC V 面积的最大值为. 14.设()f x 是定义在R 上的偶函数,对任意的x ∈R ,都有(2)(2)f x f x -=+,且当[2,0]x ∈-时,1()12xf x ⎛⎫=- ⎪⎝⎭.若关于x 的方程()log (2)0(1)a f x x a -+=>在区间(2,6]-内恰有三个不同实根,则实数a 的取值范围是四、解答题15.已知函数()()ln R mf x x m x=+∈. (1)讨论函数()f x 的单调性;(2)当1m =时,证明:当1x ≥时,()e e 0xxf x x --+≤.16.某学校共有1200人,其中高一年级、高二年级、高三年级的人数比为3:4:5,为落实立德树人根本任务,坚持五育并举,全面推进素质教育,拟举行乒乓球比赛,从三个年级中采用分层抽样的方式选出参加乒乓球比赛的12名队员.本次决赛的比赛赛制采取单循环方式,每场比赛都采取5局3胜制,最后根据积分选出最后的冠军,亚军和季军积分规则如下:每场比赛5局中以3:0或3:1获胜的队员积3分,落败的队员积0分;而每场比赛5局中以3:2获胜的队员积2分,落败的队员积1分.已知最后一场比赛两位选手是甲和乙,如果甲每局比赛的获胜概率为23(1)三个年级参赛人数各为多少?(2)在最后一场比赛甲获胜的条件下,求其前2局获胜的概率(3)记最后一场比赛中甲所得积分为X ,求X 的概率分布及数学期望()E X17.如图,在四棱锥P ABCD -中,//AB CD ,4AB =,2CD =,2BC =,3PC PD ==,平面PCD ⊥平面ABCD ,PD BC ⊥.(1)证明:⊥BC 平面PCD ;(2)若点Q 是线段PC 的中点,M 是直线AQ 上的一点,N 是直线PD 上的一点,是否存在点M ,N 使得MN =请说明理由. 18.已知椭圆22122:1(0)x y C a b a b+=>>,左、右焦点分别为12,F F ,短轴的其中一个端点为1B ,长轴端点为12,A A ,且112B F F △.(1)求椭圆1C 的方程及离心率;(2)若双曲线2C 以12,A A 为焦点,以12,F F 为顶点,点Q 为椭圆1C 与双曲线2C 的一个交点,求12QA A △的面积;(3)如图,直线:l y kx m =+与椭圆1C 有唯一的公共点M ,过点M 且与l 垂直的直线分别交x 轴,y 轴于()(),0,0,A x B y 两点.当点M 运动时,求点P x ,y 的轨迹方程.19.基本不等式:对于2个正数12,a a ,它们的算术平均数不小于它们的几何平均数,即122a a +≥12a a =时,等号成立.可以推广到一般的情形:对于n 个正数12,,,n a a a L ,它们的算术平均数不小于它们的几何平均数,12n na a a +++L 当且仅当12n a a a ===L 时,等号成立.若无穷正项数列 a n 同时满足下列两个性质:①0,n M a M ∃><;② a n 为单调数列,则称数列 a n 具有性质P .(1)若327n a n n =+;求数列 a n 的最小项; (2)若数列 b n 的前n 项和为1,31n n nS b =-,判断数列{}n S 是否具有性质P ,并说明理由; (3)若11nn c n ⎛⎫=+ ⎪⎝⎭,求证:数列{}n c 具有性质P .。
2022-2023学年江西省宜春市上高二中高二下学期第二次月考(期中) 化学试题
2022-2023学年江西省宜春市上高二中高二下学期第二次月考(期中)化学试题1.化学与人类生活、生产和社会可持续发展密切相关,下列说法正确的是A.采取“静电除尘”、“燃煤固硫”、“汽车尾气催化净化”等方法,可提高空气质量B.为测定熔融氢氧化钠的导电性,可将氢氧化钠固体放在石英坩埚中加热熔化C.黏胶纤维中的长纤维一般称为人造丝,短纤维称为人造棉,都可用于纺织工业都是人工合成高分子材料D.二氧化硅是良好的半导体材料,能将太阳能转化为电能2.关于“冰墩墩”“雪容融”的制作材料,下列说法不正确...的是A.PVC( )的单体为氯乙烯B.PC( )中所有原子均可共平面C.ABS的单体之一苯乙烯( )能使溴水褪色D.亚克力( )可通过加聚反应制备3.将乙炔通入银氨溶液,产生白色沉淀,通过该实验可以区分乙炔和乙烯。
化学方程式为:HC≡CH+2[Ag(NH3)2]+→AgC≡CAg↓+2NH4++2NH3。
乙炔银遇酸可放出乙炔。
下列分析或推测不正确...的是A.乙炔与银氨溶液的反应不是氧化还原反应B.乙炔中C-H键的活性比乙烯中C-H键的活性强C.乙炔通入AgNO 3溶液中也能发生类似反应D.2-丁炔不能与银氨溶液发生类似反应4.下列“类比”或“对比”合理的是A.Mg在CO 2中点燃反应生成MgO和C,则Zn在CO 2中点燃反应生成ZnO和CB.Na 3 N与盐酸反应生成NaCl和NH 4 Cl,则Mg 3 N 2与盐酸反应生成MgCl 2和NH 4 ClC.NaClO溶液与少量CO 2反应生成NaHCO 3和HClO,则Ca(ClO) 2溶液与少量CO 2反应生成Ca(HCO 3 ) 2和HClOD.NaOH溶液与少量AgNO 3溶液反应生成Ag 2 O和NaNO 3,则氨水与少量AgNO 3溶液反应最终生成Ag 2 O和NH 4 NO 35.设为阿伏加德罗常数的值,下列说法不正确...的是A.100g质量分数为34%H 2 O 2水溶液中含H-O键数为2N AB.和的混合物1.1g,含有的质子数为C.晶体中含有的阳离子总数目为3N AD.向的溶液中通入适量氯气,当有被氧化时,该反应转移的电子数至少为6.由下列实验操作、现象得出的结论正确的是水解能力: CO> HCO当其他条件不变7.能正确..表示下列反应的离子方程式是A.溶液与过量溶液反应:B.电解水溶液:C.NaClO溶液中通少量:D.溶液中滴加稀氨水:8.下列说法正确的是A.蛋白质及其水解产物都具有两性B.淀粉和油脂都是可水解的高分子化合物C.鸡蛋清溶液中加入饱和Na 2 SO 4溶液有沉淀生成是因为蛋白质变性D.在酸性条件下,CH 3 CO 18 OC 2 H 5的水解产物是CH 3 CO 18 OH和C 2 H 5 OH9.下列实验能获得成功的是A.苯和浓溴水混合,加入铁作催化剂制溴苯B.除去乙烷中的乙烯,将混合气体通过盛有酸性KMnO 4溶液的洗气瓶C.向蔗糖水解后的液体中加入新制的Cu(OH) 2悬浊液,加热至沸腾,验证水解产物为葡萄糖D.用NaHCO 3溶液鉴别乙醇和乙酸10.植物光合作用和动物体内食物氧化分解提供的能量,可使ADP与磷酸重新反应合成ATP。
江西省上高二中2015届高三上学期第二次月考 生物
江西省上高二中2015届高三上学期第二次月考生物试题命题人:熊小红一、选择题(1-10每个1分,11-30每个2分,共50分)1.“达菲”(又名磷酸奥司他韦),是目前人们公认的抵抗甲型H1N1流感病毒的有效药物之一。
该药具有能抑制流感病毒表面的一种蛋白质——神经胺酶的作用,从而使流感病毒不能从宿主细胞中释放出来。
下列判断正确的是()A.“达菲”能阻止甲型H1N1流感病毒在人体细胞内的繁殖B.“达菲”能阻止甲型H1N1流感病毒在人体细胞间扩散C.“达菲”能使甲型H1N1流感病毒丧失对人体细胞的识别能力D.“达菲”能使甲型H1N1流感病毒中控制神经胺酶的基因发生突变2.观察细胞结构时,下列说法正确的是()A.低倍镜下物像清晰,换高倍镜后视野变暗,应首先调节细准焦螺旋B.用光学显微镜观察神经细胞,可以观察到核糖体,以及突触小体等结构C.视野中有异物,转动物镜发现异物不动,移动装片也不动,则异物在目镜上D.制作口腔上皮细胞装片时为防止产生气泡,首先在载玻片上滴加1~2滴清水,然后再盖载玻片3.下列关于生物体中元素或离子的说法不.正确的是()A.缺P会影响动植物细胞的呼吸作用B.细胞吸收无机盐离子都需要细胞膜上蛋白质的协助C.HCO-3和HPO2-4不是维持组织液pH稳定的缓冲物质D.人体血钙过低会引起肌肉抽搐,缺铁则易患贫血4.实验测得小麦、大豆、花生三种生物干种子中三大类有机物含量如右图,有关叙述正确的是()A.选用花生检验细胞中有脂肪存在时需要使用显微镜B.向小麦种子的研磨滤液中加入斐林试剂,就会呈砖红色C.用双缩脲试剂检验大豆组织样液中存在蛋白质加热呈蓝色D.萌发时相同质量的三种种子需要的O2量基本相同5.下列有机物的鉴定实验中,导致实验失败的操作是()①脂肪鉴定时,花生子叶染色后,没有用酒精洗去浮色②蛋白质鉴定时,把A、B液混合后再加入蛋白质样液中③还原糖鉴定时,用60℃水浴加热④淀粉鉴定时,直接把碘液滴加到淀粉样液中⑤鉴定酵母菌是否产生酒精的实验中,直接把重铬酸钾加入到酵母菌培养液的滤液中A.①②⑤B.②④⑤C.③④⑤D.①②④6.在生物组织中还原糖、脂肪、蛋白质的鉴定实验中,对实验材料的选择,下列叙述错误的是()A.可用斐林试剂甲液和乙液、蒸馏水来鉴定葡萄糖和尿液中的蛋白质B.花生种子含脂肪多且子叶肥厚,是用于脂肪鉴定的理想材料C.食用花生油最好选用苏丹Ⅳ染液来鉴定,而一般不选用苏丹Ⅲ染液来鉴定D.甘蔗茎的薄壁组织、甜菜的块根等,都含有较多糖且近于白色,因此可以用于还原糖的鉴定7.环孢素(CsA)是从土壤霉菌中分离出来的含有11个氨基酸的环形多肽,该物质能选择性地抑制辅助性T淋巴细胞分泌白细胞介素-2和其他细胞因子,因而是一种强效免疫抑制剂,下列有关CsA的叙述正确的是()A.该物质的天然合成过程需要拟核DNA上基因的控制B.如果氨基酸的平均相对分子量为128,则它的相对分子量为1228C.可以用来开发移植器官后抗排斥反应的药物D.只有在受到抗原刺激后霉菌才合成该细胞因子8.与生物膜的功能直接相关的一组是()①水的光解②神经纤维的兴奋③胰岛素调节血糖④受精作用⑤氨基酸脱水缩合⑥乳酸菌分解丙酮酸A.①②③④B.②③④⑤C.⑤⑥D.②④⑥9.下列关于细胞器的叙述中,正确的一组是()(1)线粒体(2)叶绿体(3)高尔基体(4)核糖体(5)内质网(6)中心体①上述所有细胞器都含有蛋白质②与分泌蛋白形成有关的细胞器只有(3)(5)③含单层膜的细胞器只有(3)(5)④含RNA的细胞器只有(1)(2)A.①③B.①④C.②③D.②④10.下列关于酶特性实验设计的叙述中,正确的是()A.验证酶的专一性时,自变量一定是酶的种类B.验证酶的高效性时,自变量是酶的浓度C.探究温度对酶活性的影响时,自变量是温度D.探究酶催化作用的最适pH时,应设置过酸、过碱、中性三组11.某一细胞通过细胞膜从环境中吸收Q物质,进行实验得到下列结果,其中能作为判断主动运输的依据是()①当细胞中Q浓度高于溶液中Q浓度时,也会发生Q的吸收②只有在氧气存在时才会发生Q的吸收③Q的吸收存在最大值,且吸收结束时膜两侧存在Q浓度差④Q的吸收随温度变化而变化,且有一定的最适温度A.①③④B.①③C.①②D.①②③12.下图甲表示四种不同的物质在一个动物细胞内外的相对浓度差异。
江西省上高二中2013-2014学年高一下学期第二次月考 语文试题
江西省上高二中2013-2014学年高一下学期第二次月考语文试题第I卷(选择题共36分)一、(6小题,每小题3分)1.下列各组词语中,加点字注音全都正确的一组是()A.琵琶.(pá) 模.(mú)样臭.(xiù)迹斗转参.(shēn)移B.佣.(yòng)金旋.(xuán)涡广袤.(máo ) 强.(qiǎng)颜欢笑C.晕.(yùn)眩句读.(.dòu ) 孝悌.(tì) 度长絜.(xié)大D.鳏.(gān)夫中.(zhòng)肯笑靥.(yè)人才济济.(jǐ)2.下列各组中,错别字最少的一组是()A.一暴十寒年纪青青饿殍粘液B.拖沓烦琐穿流不息诡秘撕打C.瓮牖绳枢璀灿夺目堙没内闱D.众说纷芸撒手人寰欣享白蓬船3.下列各句中,划横线的成语使用不恰当的一项是()A. 爸爸工资不高,妈妈没有稳定的工作,生活拮据,但他们兄弟二人都很懂事,让枣推梨,关系融洽,很受邻居们喜爱。
B. 他潜心于文字学研究,身居书斋十多年,焚膏继晷,颇下了一番“头悬梁锥刺股”的功夫,终于取得了令人瞩目的成就。
C. 小李考虑问题总是出于公心,勇担责任,从不患得患失,所以在这个有着十年奋斗历程的团队中威望很高。
D. 我攀过陡峭的崖壁,历尽艰辛,登上绝顶,放眼望去,天无涯际,顿觉自己渺小,登高自卑之感油然而生。
4.下列句子中,没有语病的一项是()A.中国科学院最近研究发现,喜马拉雅山冰川退缩,湖泊的面积扩张,冰湖溃决危险性增大,引起了研究者的广泛关注。
B.长江中的江豚被誉为“水中大熊猫”,是国家二级保护动物,也是《华盛顿公约》确定的全球濒危物种之一,再不加以保护,15年后将会灭绝。
C.专家认为,我国人均饮茶量每天不足10克,加之大部分农药不溶于水,茶叶中即使有少量的农药残留,泡出的茶汤中也会农药含量极低,对人体健康影响不大。
江西省上高二中2013-2014学年高一下学期第二次月考 数学试题
江西省上高二中2013-2014学年高一下学期第二次月考 数学试题一、选择题(10×5=50分) 1.函数cos(2)4y x π=+的图象的一条对称轴方程是( )A .2π-=x B. 4π-=x C. 8π-=x D. π=x2.已知向量a =(1,2),b =(1,0),c =(3,4).若λ为实数, (a +λb )∥c,则λ=( )A.14B.12C .1D .23.下列命题中:①//a b ⇔存在唯一的实数,R b a λλ∈= 使得 ②e 为单位向量,且//,||a e a a e =±⋅ 则③3||||a a a a ⋅⋅= ④a 与b 共线,b 与c 共线,则a 与c 共线⑤若0,a b b c b a c ⋅=⋅≠=且则,其中正确命题序号是( )A .①⑤B .②③C .②③④D .①④⑤4.在ΔABC 中,若2AB AB AC BA BC CA CB =⋅+⋅+⋅,则ΔABC 是( )A .等边三角形B .锐角三角形C .直角三角形D .钝角三角形5.设(1,2),(1,1),a b a a b λ==+且与的夹角为锐角,则实数λ的取值范围是( ) A .5(,0)(0,)3-⋃+∞B .5(,)3-+∞C .5[,0)(0,)3-⋃+∞D .5(,0)3-6.若ΔABC 的内角A 、B 、C 所对的边a 、b 、c 满足22()4,60a b c C +-==且,则ab 的值为( )A .43B.8-C .1D .237.设ΔABC 的三个内角为A 、B 、C,,sin ),(cos ),m A B n B A ==1cos()m n A B ⋅=++若,则角C 等于( )A .6πB .3πC .23πD .56π 8.已知|a |=2|b |≠0,且关于x 的方程x 2+|a |x +a ·b =0有实根,则a 与b 的夹角的取值范围是( )A .[0,π6]B .[π3,π]C .[π3,2π3]D .[π6,π]9.已知O 是平面上一定点,A 、B 、C 是平面上不共线的三个点,动点P 满足()(0)||sin ||sin AB ACOP OA AB B AC Cλλ=++≥,则P 点的轨迹一定通过ΔABC 的( ) A .重心B .垂心C .内心D .外心10.已知||1,||,120OA OB k AOB ==∠=,点C 在ΔAOB 内部,,2,||OC OA OC m OA m OB OC ⊥=⋅+⋅=若,则k 等于( )A .1B .2CD .4二、填空题(5×5=25分)11.函数)32cos(π--=x y 的单调递增区间是____________. 12.已知tan =2α,则22sin 1sin 2αα+= .13.在△ABC 中,BC =3,AB =2,且sin 21)sin 5C B =+,则A = .14.在△ABC 中,C =π2,AC =1,BC =2,则f (λ)=|2λCA →+(1-λ)CB →|的最小值是________.15.在实数集R 中,我们定义的大小关系“>”为全体实数排了一个“序”.类似的,我们在平面向量集D={a |a(,),R,R x y x y =∈∈}上也可以定义一个称为“序”的关系,记为“ ”.定义如下:对于任意两个向量a 1=(x 1,y 1),a 2=(x 2,y 2),a 1 a2,当且仅当“12x x >”或“12x x =且12y y >”.按上述定义的关系“ ”,给出如下四个命题:①若e 1=(1,0),e 2=(0,1),0 =(0,0),则e 1 e 2 0 ; ②a 1 a 2, a 2 a 3,则a 1 a 3;③若a 1 a 2,则对于任意a ∈D,( a 1+a ) (a 2+a );④对于任意向量a 0 ,0 =(0,0),若a 1 a 2,则a a 1>a a2.其中真命题的序号为 .2016届高一下学期第二次月考数学试卷答题卡一、选择题(10×5=50分) 题号 1 2 3 4 5 6 7 8 9 10 答案二、填空题11、 12、 13、 14、 15、 三、解答题 16.(12分)在平面直角坐标系xoy 中,点(1,2),(2,3),(2,1)A B C ----。
江西省宜春市上高二中高二下学期第二次月考试题生物
2024届高二年级下学期第二次月考生物试卷出题人:晏家伟一、单选题(共20小题,每小题2分,共40分。
在每小题给出的四个选项中,只有一项正确) 1.单向性集团内捕食作用是指不同天敌共享同一猎物,而一种天敌捕食共同猎物的同时还捕食另一种天敌,被称为集团内捕食者,另一种天敌被称为集团内猎物。
某生态系统中瓢虫与寄生蜂、蚜虫三者之间存在单向性集团内捕食作用,其中寄生蜂既是猎物又是捕食者,蚜虫吸取植物汁液为生。
下列说法错误的是()A.瓢虫通过寄生蜂获得的能量要比蚜虫多B.瓢虫与寄生蜂之间存在种间竞争和捕食关系C.题中所述食物网中,瓢虫占据第三、四营养级D.瓢虫属于集团内捕食者,寄生蜂属于集团内猎物2.下列图1为某草原生态系统的部分碳循环示意图,甲~丁为生态系统的组成成分;图2为该生态系统的部分能量流动示意图(不考虑未利用的能量)。
下列叙述中正确的是()A.图1中碳元素进入无机环境的途径是②③④,进入生物群落的途径是①⑤B.图2中B表示兔的同化量,C表示兔流向分解者的能量C.在该生态系统中,狼和兔种群数量保持相对稳定的调节机制属于负反馈调节机制D.过度放牧会导致该生态系统在逐渐向荒漠生态系统演替,此过程中,生产者固定的CO2量与生物群落排出的CO2量相等3.下列关于生态系统相关的说法,正确的有几项()①食物网中某生物的位置不能被其他生物取代②当天气干旱时,草原生态系统中的动植物种类和数量一般不会有太大变化,这一事例属于恢复力稳定性③组成生物体的C、H、O、N、P、S 等元素,不断在无机环境和生物群落之间进行循环的过程,叫生态系统的物质循环④任何生态系统都需要不断得到来自系统外的能量补充,以便维持生态系统的正常功能⑤植物生长素对植物生长的调节属于生态系统的信息传递中的化学信息⑥信息传递对于个体、种群、群落、生态系统的稳定都有重要作用A.一项B.两项C.三项D.四项4.某同学画出3幅表示生态系统部分碳循环示意图,下列分析错误的是()A.3幅图中生产者都是AB.图1中C能促进生态系统的物质循环和能量流动C.图2中A、B、D、E构成群落,碳在其中流动的形式是有机物D.若使图1、图2、图3完整表示碳循环,需补充化石燃料燃烧产生CO25.南宋诗人辛弃疾在《西江月》中写到,“稻花香里说丰年,听取蛙声一片”,描绘了稻田群落的繁荣景象。
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江西省上高二中2010届高三年级第二次月考物理试卷一、选择题(48分)1.如图所示,A、B两叠放在一起的长方体木块,A的质量m,B的质量2m,它们之间的摩擦因数为μ,B与水平地面间的动摩擦因数也为μ,现对A施加一个水平向右的拉力F,可使A向右、B向左都做匀速直线运动,若滑轮处的摩擦不计,连接A、B的细绳水平,则F的大小等于()A.2μmgB.3μmgC.4μmgD.5μmg2.如图所示,轻绳两端分别系有质量为m1和m2的两个小球,m1沿半球形光滑碗面下滑到P点处于平衡,O为球心,C处光滑,∠COP等于60,碗对m1的支持力为F N,绳对m2的拉力为F T,则下列各式中正确的是()A.F N>F TB.F N=F TC.F N= m2gD.m1= 23.让甲物体从楼顶自由落下,同时在楼底正对甲将乙物体以初速度v竖直上抛,在空中两物体不相碰撞,结果它们同时落地,那么楼房高为()A.22vgB.2vgC.24vgD.22vg4.如图所示,A、B并排紧贴着放在光滑的水平面上,用水平力F1、F2同时推A、B,如F1=10N,F2=6.0N,m A<m B,则A、B间的压力可能为()A.9.0NB.7.0NC.6.0ND.4.0N5.如图所示,某一小球以υ0=10m/s的速度水平抛出,在落地之前经过空中A、B两点,在A点小球的速度方向与水平方向的夹角为45°,在B点小球速度方向与水平方向的夹角为60(空气阻力忽略不计,g取10m/s2)。
以下判断正确的是()A.小球经过A、B两点间的时间t=1)SB.小球经过A、B两点间的时间C.A、B两点间的高度差h=10mD.A、B两点间的高度差h=15m 6.如图,质量为m的物块,沿着半径为R大小为υ,若物体与球壳之间的摩擦因数为μ,则物体在最低点时,下列说法正确的是()vA .受到向心力为mg +m 2v RB .受到的摩擦力为μm 2v RC .受到的摩擦力为μmgD .受到的合力方向斜向左上方7.如图所示,水平地面上放置一左边固定有竖直挡板的长木板,在长木板上放一小块木块,它们之间用一轻弹簧相连,现用大小为F 的水平恒力向右推长木板,当它们达到相对静止且保持相同的加速度一起加速运动时撤去水平力F 。
已知长木板的质量为M ,小木板的质量为m ,所有接触面不计摩擦,则刚撤去水平力F 瞬间关于两物体的加速度大小和方向下列说法中正确的是( )A .长木板的加速度大小为F/(M +m ),方向向左B .长木板的加速度大小为F/M ,方向向左C .小木块的加速度大小为F/m ,方向向右D .小木块的加速度大小为F/(M +m ),方向向右8.a 、bA .物体a 的加速度大于物体b 的加速度B .20s 时,a 、b 两物体相距最远C .60s 时,物体a 在物体b 的前方D .40s 时,a 、b两物体速度相等,相距200m9.一根质量分布均匀的长绳AB ,在水平外力F 的作用下,沿光滑水平面做直线运动,如图甲所示,绳内距A 端χ处的张力T 与χ的关系如图乙所示,由图可知( )A .水平外力F=6NB .绳子的质量m=3kgC .绳子的长度ι=2mD .绳子的加速度a=2m/s 210.如图所示,一质量为M 、倾角为θ的斜面体在水平地面上,质量为m 的小木块(可视为质点)放在斜面上,现用一平行于斜面的、大小恒定的拉力F 作用于小木块,,拉力在斜面所在平面内绕小木块旋转一周的过程中,斜面体和木块始终保持静止状态,下列说法中正确的是( )A .小木块受到斜面的最大摩擦力为B .小木块受到斜面的最大摩擦力为F -mgsinθC .斜面体受到地面的最大摩擦力为FD .斜面体受到地面的最大摩擦力为Fcosθ11.如图所示,物体A 和B 的质量均为m ,且分别用轻绳连接跨过定滑轮(不计绳子与滑轮、滑轮与轴之间的摩擦)。
当用水平变力F 拉物体B 沿水平方向向右做匀速直线运动的过程中( )A .物体A 也做匀速直线运动F甲 乙B .绳子拉力始终大于物体A 所受的重力C .物体A 的速度小于物体B 的速度D .地面对物体B 的支持力逐渐增大12.如图所示,OO′为竖直轴,MN 为固定在OO′上的水平光滑杆,有两个质量相同的金属球A 、B 套在水平杆上,AC 和BC 为抗拉能力相同的两根细线,C 端固定在转轴OO′上。
当绳拉直时,A 、B 两球转动半径之比恒为2:1,当转轴的角速度逐渐增大时( )A .AC 先断B .BC 先断 C .两线同时断D .不能确定哪段线先断二、实验题(18分,第13题12分,第14题6分)13.某研究性学习小组探究平抛运动的规律,他们在水平桌面上用练习本做成一个斜面,使一个钢球(可视为质点)从斜面上某一位置滚下,用数码相机拍摄钢球从桌面水平飞出后做平抛运动的几张连续照片,然后用方格纸做背景,根据照片上小球的位置在方格纸上画出小球的平抛运动轨迹。
已知所用的数码相机每秒钟拍摄10帧照片,现用刻度尺测得桌边离地高度为90.0cm ,重力加速度取g=10m/s 2。
试回答下列问题:(1)该组同学一次实验最多可以得到几帧小球正在空中运动的连续照片( ) A .1帧 B .5帧 C .15帧 D .100帧(2)如图所示,是该组同学得到的小球在空中运动的三张连续照片的局部图,由图所示可判断小球做平抛运动时,在水平方向上的运动特点是 。
(3)由图可以计算出小球离开桌边时的初速度大小为 。
14.利用如图所示的装置,用自由落体做“测定重力加速度”的实验中,在纸带上取得连续清晰的7个点,如图所示,并且测得第2到第5点的距离为s 1=20.4cm ,第4到第7点间的距离s 1=22.7cm ,设打点计时哭所用电源的频率f 为50H Z ,则重力加速度的计算式为三、计算题(54分) 15、(10分)如图所示,质量M=400g 的劈形木块B 上叠放一木块A ,A 的质量为m=200g 。
A 、B 一起放在斜面上,斜面倾角θ=37°,B 的上表面呈水平,B 与斜面之间及 B 与A 之间的动摩擦因数均为μ=0.2。
当B 受到一个F=5.76N 的沿斜面向上 的作用力时,A 相对B 静止,并一起 沿斜面向上运动。
求:(1)B 的加速度大小;(2)A 受到的摩擦力及A 对B 的压力大小(sin37°=0.6,cos=0.8,g=10m/s 2)。
16.(10分)如图所示,用固定档板P 将质量为m 的小球挡在斜面体上处于静止状态,已知斜面体质量为M ,倾角为θ,斜面体与水平面间的动摩擦因数为μ,则至少以多大的水平恒力向右拉动斜面体时,小球才能做自由落体运动到地面。
17.(10分)飞机在h 米高处以水平速度υ0向地面轰炸飞行,求瞄准角(瞄准器到目标的视线与铅直方向的夹角)多大时就应投弹?18.(12分)如图是一种电动夯的结构为:在固定于夯上的电动机的转轴上固定一杆,杆的另一端固定一铁块,工作时电动机带动杆与铁块在竖直平面内匀速转动,则当铁块转至最低点时,夯对地面将产生很大的压力而夯实地面。
设夯的总质量为M ,铁块质量为m ,杆的质量不计。
电动机的转速可以调节,为了安全,夯在工作中不离开地面,则此夯能对地面产生的最大压力为多少?19.(12分)一质量为m的均匀立方体木块沿倾斜的直角槽AB从顶端滑到底部,AB棱的倾角θ,长度为L,两槽面和过AB 棱的竖直平面夹角相等,如图所示,若立方体木块与直角槽间的滑动摩擦系数皆为μ,试求木块下滑时间。
高三第二次月考物理试题参考答案一、选择题(48分)二、实验题(18分,第13题12分,第14题6分)13、(1)B (2)匀速直线运动 (3)1m/s 14、(1)2216S S f - (2)9.58 三、计算题(54分)15、(10分)解:(1)1sin ()f F G F M m a θ--=+ 2分 11f N F F Gcos μμθ==以上三式联立解得B 的加速度为:22/a m s = 2分(2)竖直方向:2sin N A F G ma θ-= 2分 水平方向:2cos f F ma θ=2分代入数据得:2 2.24N F N = 20.32f F N= 由牛顿第三定律,A 对B 的压力的大小等于B 对A 的持力,所以A 对B 的压力为2.24N2分a116、(10分)解:对于F Mg Ma μ-= ① 2分21c o t 2h a t θ=②3分 对于小球 212h gt = ③ 2分联立①②③得cot F Mg Mg μθ=+ 3分 17、(10分)解:建立如图所示坐标,炸弹离开分机后做平抛运动,要刚好落到目标点,位移S 与竖直方向的夹角Ψ就是瞄准角。
即有:0s v t = 2分212h gt =2分 tan xhψ= 2分解之,得:tan ψ=ψ= 4分 18、(12分)解析 设杆长为L,由题意可知,当铁块转至最高点时,由牛顿第二定律得2T v F mg m L+= ① 2分又由题意得()T F M m g =- ② 2分当铁块转至最低点时有2T v F mg m L'-= ③ 2分则夯对地面的最大压力为()N T F M m g F '=-+ ④ 2分由①、②、③、④式解得2N F Mg = 4分19、(12分)解析 先画出AB 棱的正面图,如图所示,将重力G 沿平行于AB 和垂直于AB 的方向分解,求得两个分力:1sin F mg θ=,2cos F mg θ= 2分v甲 乙再画出过F 2且垂直于两槽面的平面图(此平面不是竖直平面),如图乙所示,将F2沿垂直两槽面的方向分解,两分力122cos45N N F ==︒ 2分两槽面对木块的滑动摩擦力大小相等,有122cos cos45f f F mg μμθ===︒,方向相同且平行于AB 棱斜向上方。
木块沿BA 棱方向加速下滑,由牛顿第二定律得112F f f ma --= 2分把1f 、2f 、1F 代入此式可得(sin cos )a g θθ=根据运动学公式212s at =2分可得t == 4分。