2014年普通高等学校招生全国统一考试(四川卷)

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2014年高考理综四川卷(含详细答案)

理科综合能力测试试卷第1页（共48页）理科综合能力测试试卷第2页（共48页）绝密★启用前 2014年普通高等学校招生全国统一考试（四川卷）理科综合 • 物理理科综合考试时间共150分钟，满分300分。

其中，物理110分，化学100分，生物90分。

物理试题卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）。

第Ⅰ卷1至3页，第Ⅱ卷4至6页，共6页。

考生作答时，须将答案答在答题卡上，在本试题卷、草稿纸上答题无效。

考试结束后，将本试题卷和答题卡一并交回。

第Ⅰ卷（选择题共42分）注意事项：必须使用2B 铅笔在答题卡上将所选答案对应的标号涂黑。

第Ⅰ卷共7题，每题6分。

每题给出的四个选项中，有的只有一个选项、有的有多个选项符合题目要求，全部选对的得6分，选对但不全的得3分，有选错和不选的得0分。

1. 如图所示，甲是远距离输电线路的示意图，乙是发电机输出电压随时间变化的图象，则（）A. 用户用电器上交流电的频率是100 HzB. 发电机输出交流电的电压有效值是500 VC. 输电线的电流只由降压变压器原、副线圈的匝数比决定D. 当用户用电器的总电阻增大时，输电线上损失功率减小2. 电磁波已广泛运用于很多领域，下列关于电磁波的说法符合实际的是（）A. 电磁波不能产生衍射现象B. 常用的摇控器通过发出紫外线脉冲信号来摇控电视机C. 根据多普勒效应可以判断遥远天体相对于地球的运动速度D. 光在真空中运动的速度在不同惯性系中测得的数值可能不同3. 如图所示，口径较大、充满水的薄壁圆柱形浅玻璃缸底有一发光小球，则（）A. 小球必须位于缸底中心才能从侧面看到小球B. 小球所发的光能从水面任何区域射出C. 小球所发的光从水中进入空气后频率变大D. 小球所发的光从水中进入空气后传播速度变大4. 有一条两岸平直、河水均匀流动、流速恒为v 的大河。

小明驾着小船渡河，去程时船头指向始终与河岸垂直，回程时行驶路线与河岸垂直。

去程与回程所用时间的比值为k ，船在静水中的速度大小相同，则小船在静水中的速度大小为（）A.B.C.D.5. 如图所示，甲为 1 s t =时某横波的波形图象，乙为该波传播方向上某一质点的振动图象，距该质点0.5 m x ∆=处质点的振动图象可能是（）A. B.C. D.-------------在--------------------此--------------------卷--------------------上--------------------答--------------------题--------------------无--------------------效----------------姓名________________ 准考证号_____________理科综合能力测试试卷第3页（共48页）理科综合能力测试试卷第4页（共48页）6. 如图所示，不计电阻的光滑U 形金属框水平放置，光滑、竖直玻璃挡板H 、P 固定在框上，H 、P 的间距很小。

张厦2014年普通高等学校招生全国统一考试英语试题(四川卷,解析版)

2014年四川省高考英语试题本试题分第I卷（选择题）和第II卷（非选择题）。

第I卷1至8页，第II卷9至10页，共10页。

考生作答时，须将答案答在答题卡上，在本试题卷、草稿纸上答题无效。

满分150分。

考试时间120分钟。

考试结束后，将本试题卷和答题卡一并交回。

第I卷（选择题共100分）注意事项：1. 必须使用2B铅笔在答题卡上将所先答案对应的标号涂黑。

2. 第I卷共两部分，共计100分。

第二部分英语知识运用（共两节，共40分）第一节完形填空（共20小题，每小题2分，共40分）阅读下面短文，从短文后各题所给的四个选项（A、B、C、D）中，选出可以填入空白处的最佳选项，并在答题卡上将该项涂黑。

My husband, Tom, has always been good with animals, but I was still amazed when he befriended a female grouse (松鸡). It's 11 for a grouse to have any contact (接触) with people. In fact, they're hard to spot, 12 they usually fly off when they hear humans approaching. This grouse came into our lives in 13 . Tom was working out in the field when he 14 her walking around at the edge of the field. She was 15 unafraid and seemed to be 16 about what he was doing. Tom saw the 17 bird several times, and she got more comfortable around him. We quickly grew 18 of the bird and decided to call her Mildred. One day, as Tom was working, Mildred came within a few feet of him to watch. Tom 19 he didn't see her and kept working to see what she would do next. Apparently, she didn't like to be 20 . She'd run up and peck (啄) at Tom's hands, then 21 off to see what he would do. This went on for about 20 minutes, until Mildred became tired of the 22 and left. As spring went and summer came, Mildred started to 23 more and more often. 24 Mildred felt comfortable enough to jump up on Tom's leg and stay long enough for me to get a 25 of the two of them together. This friendly grouse soon felt 26 not just with our family, but with anybody who walked or drove by. When hunting season opened, we put a 27 at the end of our driveway asking 28 not to shoot our pet grouse. My father, who lived down the road, 29 warned people not to shoot her. 30 , hunters would stop and take pictures, because they had never seen anything like her.11. A. interesting B. reasonable C. impossible D. unusual12. A. though B. because C. unless D. until13. A. spring B. summer C. autumn D. winter14. A. got B. kept C. noticed D. imagined15. A. naturally B. certainly C. normally D. surprisingly16. A. crazy B. curious C. concerned D. cautious17. A. shy B. awkward C. friendly D. elegant18. A. careful B. tired C. fond D. sick19. A. supposed B. realized C. hoped D. pretended20. A. ignored B. observed C. amazed D. disturbed21. A. put B. back C. set D. take22. A. game B. work C. place D. man23. A. give up B. come out C. turn over D. fly by24. A. Eventually B. Suddenly C. Constantly D. Presently25. A. chance B. dream C. picture D. sense26. A. comfortable B. guilty C. anxious D. familiar27. A. lantern B. sign C. gun D. loudspeaker28. A. drivers B. farmers C. hunters D. tourists29. A. just B. yet C. thus D. also30. A. In fact B. For long C. On the contrary D. By the way第二节阅读下列短文，从每题所给的四个选项（A、B、C、D）中，选出最佳选项，并在答题卡上将该项涂黑。

2014年普通高等学校招生全国统一考试(四川卷)

2014年普通高等学校招生全国统一考试(四川卷)D【答案】A【解析】从甲图可以得到波长为2 m，从乙图可以得到周期为2 s，即波速为1 m/s；由乙图的振动图像可以找到t＝1 s时，该质点位移为负，并且向下运动，距该质点Δx＝0.5 m处的质点与该质点的振动情况相差T4，即将乙图中的图像向左或右平移14周期即可得到距该质点Δx＝0.5 m处质点的振动图像，故只有A正确。

6．如图所示，一不计电阻的光滑U形金属框水平放置，光滑、竖直玻璃挡板H、P固定在框上，H、P的间距很小。

质量为0.2kg的细金属杆CD恰好无挤压地放在两挡板之间，与金属框接触良好并围成边长为1m的正方形，其有效电阻为0.1Ω．此时在整个空间加方向与水平面成300角且与金属杆垂直的匀强磁场，磁感应强度随时间变化规律是B＝(0.4－0.2 t) T，图示磁场方向为正方向。

框、档板和杆不计形变。

则A．t=ls时，金属杆中感应电流方向从C到DB．t=3s时，金属杆中感应电流方向从D到CC．t =1s时，金属杆对挡板P的压力大小为0.1ND．t=3s时，金属杆对挡板H的压力大小为0.2N 【答案】AC【解析】由于B＝(0.4－0.2 t) T，在t＝1 s时穿过平面的磁通量向下并减少，则根据楞次定律可以判断，金属杆中感应电流方向从C到D，A正确．在t ＝3 s时穿过平面的磁通量向上并增加，则根据楞次定律可以判断，金属杆中感应电流方向仍然是从C到D，B错误．由法拉第电磁感应定律得E＝ΔΦΔt＝ΔBΔt S sin 30°＝0.1 V，由闭合电路的欧姆定律得电路电流I＝ER＝1 A，在t＝1 s时，B＝0.2 T，方向斜向下，电流方向从C到D，金属杆对挡板P的压力水平向右，大小为F P＝BIL sin 30°＝0.1 N，C正确．同理，在t＝3 s时，金属杆对挡板H的压力水平向左，大小为F H＝BIL sin 30°＝0.1 N，D 错误．7．如右图所示，水平传送带以速度V1匀速运动，小物体P、Q由通过定滑轮且不可伸长的轻绳相连，t=0时刻P在传送带左端具有速度V2，P与定滑轮间的绳水平，t=t0时刻P离开传送带。

2014高考(四川卷)

2014年普通高等学校招生全国统一考试(四川卷)全卷满分150分,考试时间150分钟。

第Ⅰ卷(单项选择题共27分)一、(12分,每小题3分)1.下列词语中加点的字,读音全部正确的一项是()A.眼睑．(jiǎn) 哺．育(bǔ) 扎．辫子(zā) 亘．古未有(gèn)B.嫩．绿(nèn) 铲．除(chǎn) 紧箍．咒(kū) 一蹴．而就(cù)C.抽噎．(yē) 迸．裂(bèng) 户口簿．(bù) 不屈不挠．(láo)D.愤懑．(mèn) 要挟．(xiá) 绊．脚石(bàn) 恃．才傲物(shì)1.A本题考查识记现代汉语普通话常用字的字音的能力。

B项“紧箍咒”的“箍”应读gū。

C 项“不屈不挠”的“挠”应读náo。

D项“要挟”的“挟”应读xié。

2.下列词语中,没有错别字的一项是()A.打蜡顷刻生死攸关口干舌噪B.飙升印证贻养天年扶摇直上C.巨擘清彻历久弥新所向披靡D.皱褶荧屏风生水起精简机构2.D本题考查识记现代汉语常用字的字形的能力。

A项“口干舌噪”应为“口干舌燥”。

B项“贻养天年”应为“颐养天年”。

C项“清彻”应为“清澈”。

3.下列各句中,加点词语使用恰当的一项是()A.李劼人偏爱用四川方言写作,这和他从小生活在成都分不开,他爱到茶馆听评书,评书艺人生动幽默的话语,就成了他今后．．文章中的语言。

B.生态走廊如果建立得当,能够在不影响人类居住区域的前提下将隔离的栖息地连接起来,从而．．将大大提升野生动物种群的稳定性。

C.熊猫饮水,颇似酒徒贪杯,它总是喝得肚皮隆起,而后安之若素．．．．地拖着笨拙的身躯,一摇一摆地向远处的箭竹林走去。

D.随着科技的进步和社会的发展,弹棉花、补锅钉碗等许多曾与人们生活息息相关．．．．的老行业正逐渐从我们的视线中消失。

3.D本题考查正确使用词语的能力。

2014年普通高等学校招生全国统一考试数学理试题(四川卷,含答案)

2014年普通高等学校招生全国统一考试理科（四川卷）一．选择题：本大题共10小题，每小题5分，共50分．在每小题给出的四个选项中，只有一个是符合题目要求的。

1．已知集合2{|20}A x x x =--≤，集合B 为整数集，则A B ⋂= A ．{1,0,1,2}- B ．{2,1,0,1}-- C ．{0,1} D ．{1,0}- 【答案】A【解析】{|12}A x x =-≤≤，B Z =，故A B ⋂={1,0,1,2}- 2．在6(1)x x +的展开式中，含3x 项的系数为 A ．30 B ．20 C ．15 D ．10 【答案】C【解析】含3x 项为24236(1)15x C x x ⋅=3．为了得到函数sin(21)y x =+的图象，只需把函数sin 2y x =的图象上所有的点 A ．向左平行移动12个单位长度 B ．向右平行移动12个单位长度 C ．向左平行移动1个单位长度 D ．向右平行移动1个单位长度【答案】A【解析】因为1sin(21)sin[2()]2y x x =+=+，故可由函数sin 2y x =的图象上所有的点向左平行移动12个单位长度得到4．若0a b >>，0c d <<，则一定有 A ．a b c d > B ．a b c d < C ．a b d c > D ．a b d c< 【答案】D【解析】由1100c d d c<<⇒->->，又0a b >>，由不等式性质知：0a b d c ->->，所以a bd c< 5．执行如图1所示的程序框图，如果输入的,x y R ∈，则输出的S 的最大值为A ．0B ．1C ．2D ．3 【答案】C【解析】当001x y x y ≥⎧⎪≥⎨⎪+≤⎩时，函数2S x y =+的最大值为2.6．六个人从左至右排成一行，最左端只能排甲或乙，最右端不能排甲，则不同的排法共有 A ．192种 B ．216种 C ．240种 D ．288种【答案】B【解析】当最左端为甲时，不同的排法共有55A 种；当最左端为乙时，不同的排法共有14C 44A 种。

2014年普通高等学校招生全国统一考试(四川卷)

2014年普通高等学校招生全国统一考试(四川卷)数学(理工类)第Ⅰ卷(选择题共50分)注意事项：必须使用2B 铅笔在答题卡上将所选答案对应的标号涂黑．一、选择题．1．已知集合A ＝{x |x 2－x －2≤0}，集合B 为整数集，则A ∩B ＝( ) A ．{－1,0,1,2} B ．{－2，－1,0,1} C ．{0,1} D ．{－1,0}2．在x (1＋x )6的展开式中，含x 3项的系数为( ) A ．30 B ．20 C ．15 D ．103．为了得到函数y ＝sin(2x ＋1)的图象，只需把函数y ＝sin 2x 的图象上所有的点( ) A ．向左平行移动12 个单位长度B ．向右平行移动12 个单位长度C ．向左平行移动1个单位长度D ．向右平行移动1个单位长度4．若a >b >0，c <d <0，则一定有( ) A.a c >b d B.a c <b d C.a d >b c D.a d <b c5．执行如图所示的程序框图，如果输入的x ，y ∈R ，那么输出的S 的最大值为( )A ．0B ．1C ．2D ．36．六个人从左至右排成一行，最左端只能排甲或乙，最右端不能排甲，则不同的排法共有( )A ．192种B ．216种C ．240种D ．288种7．平面向量a ＝(1,2)，b ＝(4,2)，c ＝m a ＋b (m ∈R )，且c 与a 的夹角等于c 与b 的夹角，则m ＝( )A ．－2B ．－1C ．1D ．28.如图，在正方体ABCD -A 1B 1C 1D 1中，点O 为线段BD 的中点，设点P 在线段CC 1上，直线OP 与平面A 1BD 所成的角为α，则sin α的取值范围是( )A.⎣⎡⎦⎤33，1B.⎣⎡⎦⎤63，1C.⎣⎡⎦⎤63，223 D.⎣⎡⎦⎤223，19．已知f (x )＝ln(1＋x )－ln(1－x )，x ∈(－1,1)，现有下列命题：①f (－x )＝－f (x )；②f ⎝⎛⎭⎫2x1＋x 2＝2f (x )；③|f (x )|≥2|x |.其中的所有正确命题的序号是( )A ．①②③B ．②③C ．①③D ．①②10．已知F 为抛物线y 2＝x 的焦点，点A ，B 在该抛物线上且位于x 轴的两侧，＝2(其中O 为坐标原点)，则△ABO 与△AFO 面积之和的最小值是( )A ．2B ．3 C.1728 D.10第Ⅱ卷 (非选择题共100分)二、填空题．11．复数2－2i1＋i ＝________.12．设f (x )是定义在R 上的周期为2的函数，当x ∈[－1,1)时， f (x )＝⎩⎪⎨⎪⎧－4x 2＋2，－1≤x <0x ， 0≤x <1，则f ⎝⎛⎭⎫32＝________.13.如图，从气球A 上测得正前方的河流的两岸B ，C 的俯角分别为67°，30°，此时气球的高是46 m ，则河流的宽度BC 约等于________m ．(用四舍五入法将结果精确到个位．参考数据：sin 67°≈0.92，cos 67°≈0.39，sin 37°≈0.60，cos 37°≈0.80，3≈1.73)14．设m ∈R ，过定点A 的动直线x ＋my ＝0和过定点B 的动直线mx －y －m ＋3＝0交于点P (x ，y )，则|P A |·|PB |的最大值是________．15．以A 表示值域为R 的函数组成的集合，B 表示具有如下性质的函数φ(x )组成的集合：对于函数φ(x )，存在一个正数M ，使得函数φ(x )的值域包含于区间[－M ，M ]．例如，当φ1(x )＝x 3，φ2(x )＝sin x 时，φ1(x )∈A ，φ2(x )∈B .现有如下命题：①设函数f (x )的定义域为D ，则“f (x )∈A ”的充要条件是“∀b ∈R ，∃a ∈D ，f (a )＝b ”； ②函数f (x )∈B 的充要条件是f (x )有最大值和最小值；③若函数f (x )，g (x )的定义域相同，且f (x )∈A ，g (x )∈B ，则f (x )＋g (x )∉B ； ④若函数f (x )＝a ln(x ＋2)＋xx 2＋1(x >－2，a ∈R )有最大值，则f (x )∈B .其中的真命题有________．(写出所有真命题的序号)三、解答题．16．(本小题满分12分) 已知函数f (x )＝sin ⎝⎛⎭⎫3x ＋π4. (1)求f (x )的单调递增区间；(2)若α是第二象限角，f ⎝⎛⎭⎫α3＝45cos ⎝⎛⎭⎫α＋π4cos 2α，求cos α－sin α的值．17．(本小题满分12分)一款击鼓小游戏的规则如下：每盘游戏都需击鼓三次，每次击鼓要么出现一次音乐，要么不出现音乐；每盘游戏击鼓三次后，出现一次音乐获得10分，出现两次音乐获得20分，出现三次音乐获得100分，没有出现音乐则扣除200分(即获得－200分)．设每次击鼓出现音乐的概率为12，且各次击鼓出现音乐相互独立．(1)设每盘游戏获得的分数为X ，求X 的分布列； (2)玩三盘游戏，至少有一盘出现音乐的概率是多少？(3)玩过这款游戏的许多人都发现，若干盘游戏后，与最初的分数相比，分数没有增加反而减少了．请运用概率统计的相关知识分析分数减少的原因．18．(本小题满分12分)三棱锥A -BCD 及其侧视图、俯视图如图所示．设M ，N 分别为线段AD ，AB 的中点，P 为线段BC 上的点，且MN ⊥NP .(1)证明：P 是线段BC 的中点； (2)求二面角A -NP -M 的余弦值．19．(本小题满分12分)设等差数列{a n }的公差为d ，点(a n ，b n )在函数f (x )＝2x 的图象上(n ∈N *)． (1)若a 1＝－2，点(a 8,4b 7)在函数f (x )的图象上，求数列{a n }的前n 项和S n ；(2)若a 1＝1，函数f (x )的图象在点(a 2，b 2)处的切线在x 轴上的截距为2－1ln 2，求数列⎩⎨⎧⎭⎬⎫a nb n 的前n 项和T n .20．(本小题满分13分)已知椭圆C ：x 2a 2＋y 2b 2＝1(a >b >0)的焦距为4，其短轴的两个端点与长轴的一个端点构成正三角形．(1)求椭圆C 的标准方程；(2)设F 为椭圆C 的左焦点，T 为直线x ＝－3上任意一点，过F 作TF 的垂线交椭圆C 于点P ，Q .①证明：OT 平分线段PQ (其中O 为坐标原点)； ②当|TF ||PQ |最小时，求点T 的坐标．21．(本小题满分14分)已知函数f (x )＝e x －ax 2－bx －1，其中a ，b ∈R ，e ＝2.718 28…为自然对数的底数． (1)设g (x )是函数f (x )的导函数，求函数g (x )在区间[0,1] 上的最小值； (2)若f (1)＝0，函数f (x )在区间(0,1)内有零点，求a 的取值范围．答案第Ⅰ卷(选择题共50分)注意事项：必须使用2B 铅笔在答题卡上将所选答案对应的标号涂黑．一、选择题．1．解析：选A 因为A ＝{x |－1≤x ≤2}，B ＝Z ，故A ∩B ＝{－1,0,1,2}．2．解析：选C 只需求(1＋x )6的展开式中含x 2项的系数即可，而含x 2项的系数为C 26＝15，故选C.3．解析：选A 因为y ＝sin(2x ＋1)＝sin ⎣⎡⎦⎤2⎝⎛⎭⎫x ＋12，故可由函数y ＝sin 2x 的图象上所有的点向左平行移动12个单位长度得到，选A.4．解析：选D 由c <d <0⇒－1d >－1c >0，又a >b >0，故由不等式性质，得－a d >－bc >0，所以a d <bc，选D. 5．解析：选C 当⎩⎪⎨⎪⎧x ≥0，y ≥0，x ＋y ≤1时，由线性规划的图解法知，目标函数S ＝2x ＋y 的最大值为2，否则，S 的值为1.所以输出的S 的最大值为2.6．解析：选B 当最左端排甲时，不同的排法共有A 55种；当最左端排乙时，甲只能排在中间四个位置之一，则不同的排法共有C 14A 44种．故不同的排法共有A 55＋C 14A 44＝9×24＝216种．7．解析：选D 解法一由已知得c ＝(m ＋4,2m ＋2)，因为cos 〈c ，a 〉＝c ·a|c |·|a |，cos 〈c ，b 〉＝c ·b |c |·|b |，所以c ·a |c |·|a |＝c ·b|c |·|b |，又由已知得|b |＝2|a |，所以2c ·a ＝c ·b ，即2[(m ＋4)＋2(2m ＋2)]＝4(m ＋4)＋2(2m ＋2)，解得m ＝2.解法二易知c 是以m a ，b 为邻边的平行四边形的对角线向量，因为c 与a 的夹角等于c 与b 的夹角，所以该平行四边形为菱形，又由已知得|b |＝2|a |，故m ＝2.8.解析：选B 易证AC 1⊥平面A 1BD ，当点P 在线段CC 1上从C 运动到C 1时，直线OP 与平面A 1BD 所成的角α的变化情况：∠AOA 1→π2→∠C 1OA 1点P 为线段CC 1的中点时，α＝π2，由于sin ∠AOA 1＝63，sin ∠C 1OA 1＝223>63，sin π2＝1，所以sin α的取值范围是⎣⎡⎦⎤63，1. 9．解析：选A f (－x )＝ln(1－x )－ln(1＋x )＝－f (x )，故①正确；因为f (x )＝ln(1＋x )－ln(1－x )＝ln 1＋x 1－x ，又当x ∈(－1,1)时，2x 1＋x 2∈(－1,1)，所以f ⎝⎛⎭⎫2x 1＋x 2＝ln 1＋2x1＋x 21－2x 1＋x 2＝ln ⎝ ⎛⎭⎪⎫1＋x 1－x 2＝2ln 1＋x 1－x ＝2f (x )，故②正确；当x ∈[0,1)时，|f (x )|≥2|x |⇔f (x )－2x ≥0，令g (x )＝f (x )－2x ＝ln(1＋x )－ln(1－x )－2x (x ∈[0,1))，因为g ′(x )＝11＋x ＋11－x －2＝2x 21－x 2>0，所以g (x )在区间[0,1)上单调递增，g (x )＝f (x )－2x ≥g (0)＝0，即f (x )≥2x ，又f (x )与y ＝2x 都为奇函数，所以|f (x )|≥2|x |成立，故③正确，故选A.10．解析：选B 设点A (x 1，y 1)，B (x 2，y 2)(不妨假设y 1>0，y 2<0)，直线AB 的方程为x＝ty ＋m ，且直线AB 与x 轴的交点为M (m,0)．由⎩⎪⎨⎪⎧x ＝ty ＋my 2＝x 消去x ，得y 2－ty －m ＝0，所以y 1y 2＝－m .又＝2，所以x 1x 2＋y 1y 2＝2，(y 1y 2)2＋y 1y 2－2＝0，因为点A ，B 在抛物线上且位于x 轴的两侧，所以y 1y 2＝－2，故m ＝2.又F ⎝⎛⎭⎫14，0，于是S △ABO ＋S △AFO ＝12×2×(y 1－y 2)＋12×14×y 1＝98y 1＋2y 1≥298y 1×2y 1＝3，当且仅当98y 1＝2y 1，即y 1＝43时取“＝”，所以△ABO 与△AFO 面积之和的最小值是3.第Ⅱ卷 (非选择题共100分)二、填空题．11．解析：2－2i 1＋i ＝2(1－i )2(1＋i )(1－i )＝(1－i)2＝－2i.答案：－2i12．解析：f ⎝⎛⎭⎫32＝f ⎝⎛⎭⎫2－12＝f ⎝⎛⎭⎫－12＝－4×⎝⎛⎭⎫－122＋2＝1. 答案：113. 解析：过A 作BC 边上的高AD ，D 为垂足．在Rt △ACD 中，AC ＝92，在△ABC 中，由正弦定理，得BC ＝AC sin ∠ABC×sin ∠BAC ＝92sin 67°×sin 37°≈920.92×0.60＝60(m)．答案：6014．解析：易求定点A (0,0)，B (1,3)．当P 与A 和B 均不重合时，不难验证P A ⊥PB ，所以|P A |2＋|PB |2＝|AB |2＝10，所以|P A |·|PB |≤|P A |2＋|PB |22＝5(当且仅当|P A |＝|PB |＝5时，等号成立)，当P 与A 或B 重合时，|P A |·|PB |＝0，故|P A |·|PB |的最大值是5.答案：515．解析：对于①，根据题中定义，f (x )∈A ⇔函数y ＝f (x )，x ∈D 的值域为R ，由函数值域的概念知，函数y ＝f (x )，x ∈D 的值域为R ⇔∀b ∈R ，∃a ∈D ，f (a )＝b ，所以①正确；对于②，例如函数f (x )＝⎝⎛⎭⎫12|x |的值域(0,1]包含于区间[－1,1]，所以f (x )∈B ，但f (x )有最大值1，没有最小值，所以②错误；对于③，若f (x )＋g (x )∈B ，则存在一个正数M 1，使得函数f (x )＋g (x )的值域包含于区间[－M 1，M 1]，所以－M 1≤f (x )＋g (x )≤M 1，由g (x )∈B 知，存在一个正数M 2，使得函数g (x )的值域包含于区间[－M 2，M 2]，所以－M 2≤g (x )≤M 2，亦有－M 2≤－g (x )≤M 2，两式相加得－(M 1＋M 2)≤f (x )≤M 1＋M 2，于是f (x )∈B ，与已知“f (x )∈A ”矛盾，故f (x )＋g (x )∉B ，即③正确；对于④，如果a >0，那么x →＋∞，f (x )→＋∞，如果a <0，那么x →－2，f (x )→＋∞，所以f (x )有最大值，必须a ＝0，此时f (x )＝xx 2＋1在区间(－2，＋∞)上，有－12≤f (x )≤12，所以f (x )∈B ，即④正确，故填①③④.答案：①③④ 三、解答题．16．解：(1)因为函数y ＝sin x 的单调递增区间为－π2＋2k π，π2＋2k π，k ∈Z ，由－π2＋2k π≤3x ＋π4≤π2＋2k π，k ∈Z ，得－π4＋2k π3≤x ≤π12＋2k π3，k ∈Z .所以，函数f (x )的单调递增区间为－π4＋2k π3，π12＋2k π3，k ∈Z .(2)由已知，有sin ⎝⎛⎭⎫α＋π4＝45cos ⎝⎛⎭⎫α＋π4(cos 2α－sin 2α)，所以sin αcos π4＋cos αsin π4＝45cos αcos π4－sin α·sin π4(cos 2α－sin 2α)，即sin α＋cos α＝45(cos α－sin α)2(sin α＋cos α)．当sin α＋cos α＝0时，由α是第二象限角，知α＝3π4＋2k π，k ∈Z .此时，cos α－sin α＝－ 2.当sin α＋cos α≠0时，有(cos α－sin α)2＝54.由α是第二象限角，知cos α－sin α<0，此时cos α－sin α＝－52. 综上所述，cos α－sin α＝－2或－52. 17．解：(1)X 可能的取值为：10,20,100，－200.根据题意，有P (X ＝10)＝C 13×⎝⎛⎭⎫121×⎝⎛⎭⎫1－122＝38， P (X ＝20)＝C 23×⎝⎛⎭⎫122×⎝⎛⎭⎫1－121＝38， P (X ＝100)＝C 33×⎝⎛⎭⎫123×⎝⎛⎭⎫1－120＝18，P (X ＝－200)＝C 03×⎝⎛⎭⎫120×⎝⎛⎭⎫1－123＝18. 所以X 的分布列为(2)设“第i 盘游戏没有出现音乐”为事件A i (i ＝1,2,3)，则P (A 1)＝P (A 2)＝P (A 3)＝P (X ＝－200)＝18.所以，“三盘游戏中至少有一次出现音乐”的概率为1－P (A 1A 2A 3)＝1－⎝⎛⎭⎫183＝1－1512＝511512. 因此，玩三盘游戏至少有一盘出现音乐的概率是511512.(3)X 的数学期望为EX ＝10×38＋20×38＋100×18－200×18＝－54.这表明，获得分数X 的均值为负，因此，多次游戏之后分数减少的可能性更大． 18．解：(1)如图，取BD 中点O ，连接AO ，CO .由侧视图及俯视图知，△ABD ，△BCD 均为正三角形，因此AO ⊥BD ，OC ⊥BD .因为AO ，OC ⊂平面AOC ，且AO ∩OC ＝O ，所以BD ⊥平面AOC .又因为AC ⊂平面AOC ，所以BD ⊥AC . 取BO 的中点H ，连接NH ，PH .又M ，N 分别为线段AD ，AB 的中点，所以NH ∥AO ，MN ∥BD . 因为AO ⊥BD ，所以NH ⊥BD . 因为MN ⊥NP ，所以NP ⊥BD .因为NH ，NP ⊂平面NHP ，且NH ∩NP ＝N ，所以BD ⊥平面NHP . 又因为HP ⊂平面NHP ，所以BD ⊥HP .又OC ⊥BD ，HP ⊂平面BCD ，OC ⊂平面BCD ，所以HP ∥OC . 因为H 为BO 中点，故P 为BC 中点．(2)法一：如图，作NQ ⊥AC 于Q ，连接MQ .由(1)知，NP ∥AC ，所以NQ ⊥NP .因为MN ⊥NP ，所以∠MNQ 为二面角A -NP -M 的一个平面角．由(1)知，△ABD ，△BCD 为边长为2的正三角形，所以AO ＝OC ＝ 3. 由俯视图可知，AO ⊥平面BCD .因为OC ⊂平面BCD ，所以AO ⊥OC ，因此在等腰Rt △AOC 中，AC ＝6，作BR ⊥AC 于R .在△ABC 中，AB ＝BC ，所以BR ＝AB 2－⎝⎛⎭⎫AC 22＝102. 因为在平面ABC 内，NQ ⊥AC ，BR ⊥AC ，所以NQ ∥BR . 又因为N 为AB 的中点，所以Q 为AR 的中点，因此NQ ＝BR 2＝104.同理，可得MQ ＝104.所以在等腰△MNQ 中，cos ∠MNQ ＝MN 2NQ ＝BD 4NQ ＝105.故二面角A -NP -M 的余弦值是105. 法二：由俯视图及(1)可知，AO ⊥平面BCD .因为OC ，OB ⊂平面BCD ，所以AO ⊥OC ，AO ⊥OB . 又OC ⊥OB ，所以直线OA ，OB ，OC 两两垂直．如图，以O 为坐标原点，以的方向为x 轴，y 轴，z 轴的正方向，建立空间直角坐标系O -xyz .则A (0,0，3)，B (1,0,0)，C (0，3，0)，D (－1,0,0)．因为M ，N 分别为线段AD ，AB 的中点，又由(1)知，P 为线段BC 的中点，所以M ⎝⎛⎭⎫－12，0，32，N ⎝⎛⎭⎫12，0，32，P ⎝⎛⎭⎫12，32，0.从而⎩⎪⎨⎪⎧x 2＝0，32y 2－32z 2＝0. 取z 2＝1，所以n 2＝(0,1,1)．设二面角A -NP -M 的大小为θ.则cos θ＝⎪⎪⎪⎪n 1·n 2|n 1|·|n 2|＝⎪⎪⎪⎪⎪⎪(3，1，1)·(0，1，1)5×2＝105. 故二面角A -NP -M 的余弦值是105. 19．解：(1)由已知，b 7＝2a 7，b 8＝2a 8＝4b 7，有2a 8＝4×2a 7＝2a 7＋2，解得d ＝a 8－a 7＝2.所以，S n ＝na 1＋n (n －1)2d ＝－2n ＋n (n －1)＝n 2－3n .(2)函数f (x )＝2x 在(a 2，b 2)处的切线方程为y －2a 2＝(2a 2ln 2)(x －a 2)，它在x 轴上的截距为a 2－1ln 2.由题意知，a 2－1ln 2＝2－1ln 2，解得a 2＝2.所以，d ＝a 2－a 1＝1.从而a n ＝n ，b n ＝2n ，所以T n ＝12＋222＋323＋…＋n －12n －1＋n 2n ， 2T n ＝11＋22＋322＋…＋n 2n －1. 因此，2T n －T n ＝1＋12＋122＋…＋12n －1－n 2n ＝2－12n －1－n 2n ＝2n ＋1－n －22n . 所以，T n ＝2n ＋1－n －22n . 20．解：(1)由已知可得⎩⎨⎧ a 2＋b 2＝2b ，2c ＝2a 2－b 2＝4，解得a 2＝6，b 2＝2，所以椭圆C 的标准方程是x 26＋y 22＝1. (2)①由(1)可得，F 的坐标是(－2,0)，设T 点的坐标为(－3，m )，则直线TF 的斜率k TF ＝m －0－3－(－2)＝－m . 当m ≠0时，直线PQ 的斜率k PQ ＝1m，直线PQ 的方程是x ＝my －2. 当m ＝0时，直线PQ 的方程是x ＝－2，也符合x ＝my －2的形式．设P (x 1，y 1)，Q (x 2，y 2)，将直线PQ 的方程与椭圆C 的方程联立，得⎩⎪⎨⎪⎧ x ＝my －2，x 26＋y 22＝1，消去x ，得(m 2＋3)y 2－4my －2＝0，其判别式Δ＝16m 2＋8(m 2＋3)>0.所以y 1＋y 2＝4m m 2＋3，y 1y 2＝－2m 2＋3， x 1＋x 2＝m (y 1＋y 2)－4＝－12m 2＋3. 所以PQ 的中点M 的坐标为⎝ ⎛⎭⎪⎫－6m 2＋3，2m m 2＋3，所以直线OM 的斜率k OM ＝－m 3. 又直线OT 的斜率k OT ＝－m 3，所以点M 在直线OT 上，因此OT 平分线段PQ .②由①可得，|TF |＝m 2＋1，|PQ |＝(x 1－x 2)2＋(y 1－y 2)2＝(m 2＋1)[(y 1＋y 2)2－4y 1y 2] ＝(m 2＋1)⎣⎢⎡⎦⎥⎤⎝⎛⎭⎫4m m 2＋32－4·－2m 2＋3＝24(m 2＋1)m 2＋3.所以|TF ||PQ |＝124·(m 2＋3)2m 2＋1＝124·⎝⎛⎭⎫m 2＋1＋4m 2＋1＋4≥124·(4＋4)＝33. 当且仅当m 2＋1＝4m 2＋1，即m ＝±1时，等号成立，此时|TF ||PQ |取得最小值．所以当|TF ||PQ |最小时，T 点的坐标是(－3,1)或(－3，－1)． 21．解：(1)由f (x )＝e x －ax 2－bx －1，有g (x )＝f ′(x )＝e x －2ax －b ，所以g ′(x )＝e x －2a .因此，当x ∈[0,1]时，g ′(x )∈[1－2a ，e －2a ]．当a ≤12时，g ′(x )≥0，所以g (x )在[0,1]上单调递增．因此g (x )在[0,1]上的最小值是g (0)＝1－b ；当a ≥e 2时，g ′(x )≤0，所以g (x )在[0,1]上单调递减，因此g (x )在[0,1]上的最小值是g (1)＝e －2a －b ；当12<a <e 2时，令g ′(x )＝0，得x ＝ln(2a )∈(0,1)．所以函数g (x )在区间[0，ln(2a )]上单调递减，在区间(ln(2a )，1]上单调递增．于是，g (x )在[0,1]上的最小值是g (ln(2a ))＝2a －2a ln(2a )－b .综上所述，当a ≤12时，g (x )在[0,1]上的最小值是g (0)＝1－b ；当12<a <e 2时，g (x )在[0,1]上的最小值是g (ln(2a ))＝2a －2a ln(2a )－b ；当a ≥e 2时，g (x )在[0,1]上的最小值是g (1)＝e －2a －b . (2)设x 0为f (x )在区间(0,1)内的一个零点，则由f (0)＝f (x 0)＝0可知，f (x )在区间(0，x 0)上不可能单调递增，也不可能单调递减．则g (x )不可能恒为正，也不可能恒为负．故g (x )在区间(0，x 0)内存在零点x 1.同理g (x )在区间(x 0,1)内存在零点x 2.所以g (x )在区间(0,1)内至少有两个零点．由(1)知，当a ≤12时，g (x )在[0,1]上单调递增，故g (x )在(0,1)内至多有一个零点．当a ≥e 2时，g (x )在[0,1]上单调递减，故g (x )在(0,1)内至多有一个零点．所以12<a <e 2. 此时g (x )在区间[0，ln(2a )]上单调递减，在区间(ln(2a )，1]上单调递增．因此x 1∈(0，ln(2a )]，x 2∈(ln(2a )，1)，必有g (0)＝1－b >0，g (1)＝e －2a －b >0. 由f (1)＝0有a ＋b ＝e －1<2，有g (0)＝1－b ＝a －e ＋2>0，g (1)＝e －2a －b ＝1－a >0.解得e －2<a <1.当e －2<a <1时，g (x )在区间[0,1]内有最小值g (ln(2a ))．若g (ln(2a ))≥0，则g (x )≥0(x ∈[0,1])，从而f(x)在区间[0,1]上单调递增，这与f(0)＝f(1)＝0矛盾，所以g(ln(2a))<0.又g(0)＝a－e＋2>0，g(1)＝1－a>0，故此时g(x)在(0，ln(2a))和(ln(2a)，1)内各只有一个零点x1和x2.由此可知f(x)在[0，x1]上单调递增，在(x1，x2)上单调递减，在[x2,1]上单调递增．所以f(x1)>f(0)＝0，f(x2)<f(1)＝0，故f(x)在(x1，x2)内有零点．综上可知，a的取值范围是(e－2,1)．。

2014年四川高考英语(完整试题+解析)

2014年普通高等学校招生全国统一考试（四川卷）英语本卷满分150分答题时间120分钟第一部分：听力（共两节，满分30分）第一节(共5小题；每小题1.5分，满分7.5分)听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. How is the man going to school today?A. By bus.B. By bike.C. By taxi.2. What does the woman say?A. English is the official language in the UK.B. The majority of UK citizens speak only English.C. There are five native languages in the UK.3. Who probably are the speakers?A. Tom’s teac hers.B. Tom’s parents.C. Tom’s friends.4. What’s the weather like in Beijing these days?A. Cold and sunny.B. Hot and sunny.C. Rainy.5. How long will the man stay at the hotel in total?A. Two nights.B. Three nights.C. One night.第二节（共15小题：每小题1.5分，满分22.5分）请听下面5段对话。

每段对话后有几个小题，从题中所给出的A、B、C三个选项种选出最佳选项，并标在试卷的相应位置。

听每段对话前，你将有时间阅读各个小题。

，每小题5秒钟；听完后，各小题给出5秒钟的作答时间。

2014年高考英语试题及答案(四川卷).doc

2014年普通高等到学校招生全国统一考试（四川卷）英语第I卷（选择题共90分）第一节单项填空1. ---She’d lived in London and Manchester, but she liked ______ and moved to Cambridge.A. bothB. neitherC. noneD. either2. Grandma pointed to the hospital and said, “That’s ______ I was born.”A. whenB. howC. whyD. where3. Was it because Jack came late for school _______ Mr. Smith got angry?A. whyB. whoC. whereD. that4. Until now, we have raised 50,000 pounds for the poor children, _______ is quite unexpected.A. thatB. whichC. whoD. it5. The manager was satisfied to see many new products _______ after great effort.A. having developedB. to developC. developedD. develop6. I still remember my happy childhood when my mother _______ take me to Disneyland at weekends.A. mightB. mustC. wouldD. should7.—I hope to take the computer course.—Good idea. ________ more about it, visit this website.A. To find outB. Finding outC. To be finding outD. Having found out8. I’ll be out for some time. _______ anything important happens, call me up immediately.A. In caseB. As ifC. Even thoughD. Now that9. She _______ someone, so I nodded to her and went away.A. phonedB. had phonedC. was phoningD. has phoned10. --How about dinner tonight? It’s on me.--_________.A. You are welcomeB. Oh, I’d like toC. Well, I’m afraid soD. That’s all right第二节：完形填空（共20小题；每小题1.5分，共30分）My husband, Tom, has always been good with animals, but I was still amazed when he befriended a female grouse（松鸡）. It’s 11 for a grouse to have any contact（接触）with p eople. In fact, they’re hard to spot, 12 they usually fly off when they hear humans approaching.This grouse came into our lives in 13 . Tom was working out in the field when he 14 her walking around at the edge of the field. She was 15 unafraid and seemed to be 16 about what he was doing.Tom saw the 17 bird several times, and she got more comfortable around him. We quickly grew18 of the bird and decided to call her Mildred.One day, as Tom was working, Mildred came within a few feet of him to watch. Tom 19 he didn’t see her and kept working to see what she would do next.Apparently, she didn’t like to be 20 . She’d run up and peck（啄）at Tom’s hands, then 21 off to see what he would do. This went on for about 20 minutes, until Mildred became tired of the 22 and left.As spring went and summer came, Mildred started to 23 more and more often. 24 Mildred felt comfortable enough to jump up on Tom’s leg and stay long enough for me to get a 25 of the two of them together. This friendly grouse soon felt 26 not just with our family, but with anybody who walked or drove by.When hunting season opened, we put a 27 at the end of our driveway asking 28 not to shoot our pet grouse. My father, who lived down the road, 29 warned people not to shoot her. 30 , hunters would stop and take pictures, because they had never seen anything like her.11. A. interesting B. reasonable C. impossible D. unusual12. A. though B. because C. unless D. until13. A. spring B. summer C. autumn D. winter14. A. got B. kept C. noticed D. imagined15. A. naturally B. certainly C. normally D. surprisingly16. A. crazy B. curious C. concerned D. cautious17. A. shy B. awkward C. friendly D. elegant18. A. careful B. tired C. fond D. sick19. A. supposed B. realized C. hoped D. pretended20. A. ignored B. observed C. amazed D. disturbed21. A. put B. back C. set D. take22. A. game B. work C. place D. man23. A. give up B. come out C. turn over D. fly by24. A. Eventually B. Suddenly C. Constantly D. Presently25. A. chance B. dream C. picture D. sense26. A. comfortable B. guilty C. anxious D. familiar27. A. lantern B. sign C. gun D. Loudspeaker28. A. drivers B. farmers C. hunters D. tourists29. A. just B. yet C. thus D. also30. A. In fact B. For long C. On the contrary D. By the way第二节：补全对话Mary: Mike, how do I look in these blue jeans?Mike: ______51_____ They really suit you, Mary!Mary: Thanks, you know, these kinds of jeans are in style now.Mike: 52Mary: I mean… they are very popular these days; everyone is wearing them!Mike: You are great at keeping up with fashions.Mary: Well, 53Mike: Perhaps you can help me pick out a pair of jeans now, since you are an expert.Mary: 54 I would be happy to help you with your fashion change!Mike: 55A. Wow, great!B. No problem!C. See you then.D. Any suggestions?E. I am a girl after all.F. What do you mean?G. Thank you so much!第II卷（非选择题共60分）第三部分写作（共三节，共60分）第一节阅读表达（共5小题；每小题2分，共10分）阅读下面短文，并用英语回答问题，请注意题后的词数要求。

2014年普通高等学校招生全国统一考试(四川文综卷)

2014年普通高等学校招生全国统一考试（四川卷）文科综合·地理文科综合考试时间共150分钟，满分300分。

政治、历史、地理各100分。

地理试题卷分第Ⅰ卷（选择题）和第Ⅱ卷（非选择题）。

第Ⅰ卷9至11页，第Ⅱ卷12至12页，共4页。

考生作答时，须将答案答在答题卡上，在本试题卷、草稿纸答题无效。

考试结束后，将本试题卷和答题卡一并交回。

第Ⅰ卷（选择题共48分）注意事项：必须使用2B铅笔在答题卡上将所选答案对应的标点涂黑。

第Ⅰ卷共12题，每题4分。

在每题给出的四个选项中，只有一项是最符合题目要求的。

（2014四川·1～2）我国嫦娥三号月球探测器于北京时间2013年12月2日1时30分，在四川西昌卫星发射中心成功发射。

据此回答1～2题。

（2014四川·1）1.发射时刻的国际标准时间（世界时）是2013年12月（）A.1日17时30分B.1日21时30分C.2日1时30分D.2日9时30分（2014四川·2）2.发射时，发射场及其周围地区最可能处于（）A.冷锋过境时B.暖锋过境时C.低压控制下D.高压控制下（2014四川·3～4）图1为高速铁路和甲运输方式两者间客运市场占有率随运距变化图。

读图回答3～4题。

图1（2014四川·3）3.图中两种运输方式的市场占有率变化幅度最大在（）A.700～900kmB.600～800kmC.500～700kmD.400～600km（2014四川·4）4.甲运输方式应该是（）A.高速公路B.普通铁路C.航空D.水路（2014四川·5～6）风功率密度等级可以反映风能资源丰富程度，等级数越大风能资源越丰富。

图2为南海全年风功率密度等级图。

读图回答5～6题。

图2（2014四川·5）5.结合南海风功率密度等级冬季高于夏季判断，对该海域风能资源总量形成作用最大的风是（）A.东北风B.东南风C.西南风D.西北风（2014四川·6）6.从资源利用角度考虑，目前在下列四地建大型风力发电站最合理的是（）A.①地B.②地C.③地D.④地（2014四川·7～8）图3所示区域受西风影响，年降水量多在50～300毫米。

2014年普通高等学校招生全国统一考试四川卷

2014年普通高等学校招生全国统一考试（江西卷）语文一、（18分，每小题3分）1.下列加点的字注音全部正确的一组是A．翌．（yì）日贲．（bèn）张黑魆．(yuè)魆沆瀣．（xiè）一气B. 倜．（tì）傥和．（huó）面角．（jiǎo）斗士莞．（wǎn）尔一笑C. 魑．（chī）魅伛偻．（lǔ）入场券．（quàn）心广体胖．（pàng）D. 笑靥．（yè）圭臬．（nìè）打擂．（lèi）台绿．（lù）林好汉2. 下列词语中，没有错别字的一组是（）A. 弭乱国粹泊来品入不敷出B. 伺候斐声煞风景得鱼忘筌C. 日晷陨落挖墙脚纵横捭阖 D．萦回撺掇黑黢黢入目三分3. 依次填入下列词句横线处的词语，最恰当的一组是（1）时下，概括中国教育病症最流行的______莫过于“应试教育”。

（2）你们这样对待远道而来的客人，________太不礼貌了吧。

（3）外交部发言人表示中国海监船进入钓鱼岛海域活动_______。

A．词语不免无可厚非 B 词汇不免无可厚非C．词汇未免无可非议 D. 词语未免无可非议4.下列各句中，没有语病的一项是A．中心思想是针对文章的整体内容而言的，要求具有较高的分析概括能力和准确的语言表达能力。

B．虽然有国家资源作支撑，但面临重重困难，国有企业能取得现在这样的成绩，确实可说堪称不易。

C．大庆石化总公司的老少直供们同台竞赛，年轻职工积极踊跃，老年职工更是不让须眉。

D．通过捐款、创办公益基金的方式回馈会，不是企业家的法定义务，可提倡而不宜强制。

5.依次填入下列一段文字划线处的语句，衔接最恰当一组是：瓦尔登湖“波平如镜”，，或许，一只燕子飞掠在水面上，低得碰到了湖水。

，，。

①或许，还会有一只鸭子在整理自己的羽毛。

②其是，只有一些掠水虫，隔开了同等的距离，分散在全部的湖面。

2014年四川英语高考试卷word版附答案 2014年普通高等学校招生全国统一考试英语(四川卷)

2014年四川省高考英语试题第一节单项选择1. She'd lived in London and Manchester, but she liked ______ and moved to Cambridge.A. bothB. neitherC. noneD. either2. Grandma pointed to the hospital and said, "That's ______ I was born."A. whenB. howC. whyD. where3. Was it because Jack came late for school ______ Mr. Smith got angry?A. whyB. whoC. whereD. that4. I now, we have raised 50.000 pounds for the poor children. ______ is quite unexpected.A. thatB. whichC. whoD. it5. The manager was satisfied to see many new products ______ after great effort.A. having developedB. to developC. developedD. develop6. I still remember my happy childhood when my mother ______ take me to Disneyland at weekends.A. mightB. mustC. wouldD. should7. —I hope to take the computer course.—Good idea. ____ more about it, visit this website.A. To find outB. Finding outC. To be finding outD. Having found out8. I'll be out for some time. ______ anything important happens, call me up immediately.A. In caseB. As ifC. Even thoughD. Now that9. She ______ someone, so I nodded to her and went away.A. phonedB. had phonedC. was phoningD. has phoned10. — How about dinner tonight? It's on me.— ______ .A. You are welcome C. Well, I'm afraid soB. Oh, I'd like to D. That's all right第二节完形填空My husband, Tom, has always been good with animals, but I was still amazed when he befriended a female grouse (松鸡). It's 11 for a grouse to have any contact (接触) with people. In fact, they're hard to spot, 12 they usually fly off when they hear humans approaching.This grouse came into our lives in 13 Tom was working out in the field when he 14her walking around at the edge of the field. She was 15 unafraid and seemed to be 16about what he was doing.Tom saw the 17 bird several times, and site got more comfortable around him. We quickly grew 18 of the bird and decided to call her Mildred.One day, as Tom was working, Mildred camc within a few feet of him to watch. Tom 19he didn't see her and kept working to see what she would do next.Apparently, she didn't like to be 20 . She'd run up and peck (啄) at Tom's hands, then21 off to see what he would do. This went on for about 20 minutes, until Mildred became tired of the 22 and left.As spring went and summer came, Mildred started to 23 more and more often. 24Mildred felt comfortable enough to jump up on Tom's leg and stay long enough for me to get a25 of the two of them together. This friendly grouse soon felt 26 not just with our family, but with anybody who walked or drove by.When hunting season opened, we put a 27 at the end of our driveway asking 28not to shoot our pet grouse. My father, who lived down the road, 29 warned people not to shoot her. 30 . hunters would stop and take pictures, because they had never seen anything like her.11. A. interesting B. reasonable C. impossible D. unusual12. A. though B. because C. unless D. until13. A. spring B. summer C. autumn D. winter14. A. got B. kept C. noticed D. imagined15. A. naturally B. certainly C. normally D. surprisingly16. A. crazy B. curious C. concerned D. cautious17. A. shy B. awkward C. friendly D. elegant18. A. careful B. tired C. fond D. sick19. A. supposed B. realized C. hoped D. pretended20. A. ignored B. observed C. amazed D. disturbed21. A. put B. back C. set D. take22. A. game B. work C. place D. man23. A. give up B. come out C. turn over D. fly by24. A. Eventually B. Suddenly C. Constantly D. Presently25. A. chance B. dream C. picture D. sense26. A. comfortable B. guilty C. anxious D. familiar27. A. lantern B. sign C. gun D. loudspeaker28. A. drivers B. farmers C. hunters D. tourists29. A. just B. yet C. thus D. also30. A. In fact B. For long C. On the contrary D. By the way第二部分第一节阅读理解ADo you want to get home from work knowing you have made a real difference in someone's life? If yes. don't care about sex or age! Come and join us, then you'll make it!Position: Volunteer Social Care Assistant(No Pay with Free Meals)Place: Manchester Hours: Part TimeWe arc now looking for volunteers to support people with learning disabilities to live active lives! Only 4 days left. Don't miss the chance of lending your warm hands to help others!Role:You will provide people with learning disabilities with all aspects of their daily lives. You will help them to develop new skills. You will help them to protect their rights and their safety. But your primary concern is to let them know they are valued.Skills and Experience Required:You will have the right values and great listening skills. You will be honest and patient. You will have the ability to drive a car and to communicate in fluent written and spoken English since you'll have to help those people with different learning disabilities. Previous care-related experience will be a great advantage for you.31. The text is meant to ______ .A. leave a noteB. send an invitationC. present a documentD. carry an advertisement32. What docs the underlined part mean?A. You'll make others' lives more meaningful with this job.B. You'll arrive home just in time from this job.C. You'll earn a good salary from this job.D. You'll succccd in getting this job.33. The volunteers' primary responsibility is to help people with learning disabilities ______ .A. to get some financial supportB. to properly protect themselvesC. to leam some new living skillsD. to realize their own importance34. Which of the following can first be chosen as a volunteer?A. The one who can drive a car.B. The one who has done similar work before.C. The one who has patience to listen to others.D. The one who can use English to communicate.BIn 1943, when I was 4, my parents moved from Coeur d'Alene, Idaho, to Fairbanks, Alaska, where adventure was never very far away.We arrived in the summer, just in time to enjoy the midnight sun. All that sunlight was fantastic for Mom's vegetable garden. Working in the garden at midnight tended to throw her timing off, so she didn't care much about my bedtime.Dad was a Railway Express agent and Mom was his clerk. That left me in a mess. I usually managed to find some trouble to get into. Once I had a little Are going in the dirt basement of a hotel. I had tried to light a barrel（桶）of paint but couldn't really get a good fire going. The smoke got pretty bad, though, and when 1 made my exit, a crowd and the police were there to greet me. The policemen took my matches and drove meMom and Dad were occupied in thegarden and Dad told the police to keep me, and they did! I had a tour of the prison before Mom rescued me. 1 hadn't turned 5 yet.As I entered kindergarten, the serious cold began to set in. Would it surprise you to know that I soon left part of my tongue on a metal handrail at school?As for Leonhard Seppala, famous as a dog sledder (驾雪橇者), I think I knew him well because I was taken for a ride with his white dog team one Sunday. At the time I didn't realize what a superstar he was, but I do remember the ride well.I was wrapped (包裹) heavily and well sheltered from the freezing and blowing weather.In 1950, we moved back to Coeur d'Alene, but we got one more Alaskan adventure when Leonhard invited us eight years later by paying a visit to Idaho to attend a gathering of former neighbors of Alaska.35. What can be inferred about the author's family?A. His father was a cruel man.B. His parents didn't love him.C. His parents used to be very busy.D. His mother didn't have any jobs.36. What happened when the author was 4?A. He learned to smoke.B. He was locked in a basement.C. He was arrested by the police.D. He nearly caused a fire accident.37. Which of the following is true?A. Leonhard was good at driving dog sleds.B. The author spent his whole childhood in Alaska.C. Leonhard often visited the author's family after 1950.D. The author suffered a lot while taking the dog sled in Alaska.38. What is the author's purpose of writing the text?A. To look back on his childhood with adventures.B. To describe the extreme weather of Alaska.C. To express how much he misses Leonhard.D. To show off his pride in making trouble.CA schoolgirl saved her father's life by kicking him in the chest after he suffered a serious allergic (过敏的) reaction which stopped his heart.Izzy, nine, restarted father Colm's heart by stamping (踩) on his chest after he fell down at home and stopped breathing.Izzy's mother, Debbie, immediately called 999 but Izzy knew doctors would never arrive in time to save her father, so decided to use CPR.However, she quickly discovered her arms weren't strong enough, so she stamped on her father's chestDebbie then took over with some more conventional chest compressions (按压) until the ambulanceIzzy, who has been given a bravery award by her school, said: "I just kicked him really hard. My mum taught me CPR but I knew I wasn't strong enough to use hands. I was quite scared. The doctor said I might as well be a doctor or a nurse. My mum said that Dad was going to hospital with a big footprint on his"She's a little star," said Debbie, "i was really upset but Izzy just took over. I just can't believe what she did. I really think all children should be taught first aid. Izzy did CPR then the doctor turned up. Colm had to have more treatment on the way to the hospital and we've got to see an expert."Truck driver Colm, 35, suffered a mystery allergic reaction on Saturday and was taken to hospital, but was sent home only for it to happen again the next day. The second attack was so serious that his airway swelled, preventing him from breathing, his blood pressure dropped suddenly, and his heart stopped for a moment.He has now made a full recovery from his suffering.39. Izzy kicked her father in the chest ______ .A. to express her helplessnessB. to practise CPR on himC. to keep him awakeD. to restart his heart40. What's the right order of the events?○1Izzy kicked Colm.○2Debbie called 999.○3Izzy learned CPR.○4Colm's heart stopped.A. ○3○1○2○4B. ○4○2○3○1C. ○3○4○2○1D. ○4○3○1○241. What does Paragraph 8 mainly talk about?A. What Colm suffered.B. Colm's present condition.C. What caused Colm's allergy.D. Symptoms of Colm's allergic reaction.42. Why does the author write the news?A. To describe a serious accident.B. To prove the importance of CPR.C. To report a 9-year-old girl's brave act.D. To call people's attention to allergic reaction.DWilli around 100 students scheduled to be in that 9 am Monday morning lecture, it is no surprise that almost 20 people actually make it to the class and only 10 of them arc still awake after the first IS minutes; it is not even a surprise that most of them are still in their pyjamas (睡衣). Obviously, students are terrible at adjusting their sleep cycles to their daily schedule.All human beings possess a body clock. Along with other alerting (警报) systems, this governs the sleep/wake cycle and is therefore one of the main processes which govern sleep behaviour. Typically, the preferred sleep/wake cycle is delayed in adolescents, which leads to many students not feeling sleepy until much later in the evenings. This typical sleep pattern is usually referred to as the "night owl" schedule ofThis is opposed to the "early bird" schedule, and is a kind of disorder where the individual tends to stay up much past midnight. Such a person has great difficulty in waking up in the mornings. Research suggests that night owls feel most alert and function best in the evenings and at night. Research findings have shown that about 20 percent of peoplecan be classified as "night owls" and only 10 percent can be classified as "early birds" - the other 70 percent are in the middle. Although this is clearly not true for all students, for the ones who are true night owls this gives them an excellent excuse for missing their lectures which unfortunately fall before midday.43. What docs the author stress in Paragraph I?A. Many students are absent from class.B. Students are very tired on Monday mornings.C. Students do not adjust their sleep patterns well.D. Students are not well prepared for class on Mondays.44. Which of the following is true according to Paragraph 2?A. Most students prefer to get up late in the morning.B. Students don't sleep well because of alerting systems.C. One's body clock governs the sleep/wake cycle independently.D. Adolescents' delayed sleep/wake cycle isn't the preferred pattern.45. Which of the following is closest in meaning to the underlined word "classified"?A. Criticised.B. Grouped.C. Organised.D. Named.46. What docs the text mainly talk about?A. Functions of the body clock.B. The "night owl" phenomenon.C. Human beings' sleep behaviour.D. The school schedule of "early birds".EWomen are friendly. But men are more competitive. Why? Researchers have found it's all down to the hormone oxytocin (荷尔蒙催生素). Although known as the love hormone, it affects the sexes differently."Women tend to be social in their behavior. They often share with others. But men lend to be competitive. They are trying to improve their social status," said Professor Ryan.Generally, people believe that the hormone oxytocin is let out in our body in various social situations and our body creates a large amount of it during positive social interactions (互动) such as falling in love or giving birth.But in a previous experiment Professor Ryan found that the hormone is also let out in our body during negative social interactions such as envy.Further researches showed that in men the hormone oxytocin improves the ability to recognize competitive relationships, but in women it raises the ability to recognize friendship. Professor Ryan's recent experiment used 62 men and women aged 20 to 37. Half of the participants（参与者）received oxytocin. The other half received placebo (安慰剂).After a week, the two groups switched with participants. They went tlirough the same procedure with the other material.Following each treatment, they were shown some video pictures with different social interactions. Then they were asked to analyze the relationships by answering some questions. The questions were about telling friendship from competition. And their answers should be based on gestures, body language and facial expressions.The results indicated that, after treatment with oxytocin, men's ability to correctly recognize competitive relationships improved, but in women it was the ability to correctly recognize friendship that got better.Professor Ryan thus concluded: "Our experiment proves that the hormone oxytocin can raise people's abilities to better distinguish different social interactions. And the behavior differences between men and women are caused by biological factors (因素) that are mainly hormonal."47. What causes men and women to behave differently according to the text?A. Placebo.B. Oxytocin.C. The gesture.D. The social status.48. What can we learn from Professor Ryan's previous experiment?A. Oxytocin affects our behavior in a different way.B. Our body lets out oxytocin when we are deep in love.C. Our body produces oxytocin when we feel unhappy about others' success.D. Oxytocin improves our abilities to understand people's behavior differences.49. Why did Professor Ryan conduct the recent experiment?A. To test the effect of oxytocin on the ability to recognize social interactions.B. To know the differences between friendship and competition.C. To know people's different abilities to answer questions.D. To test people's understanding of body language.50. The author develops the text by______.A. explaining people's behaviorsB. describing his own experiencesC. distinguishing sexual differencesD. discussing research experiments第二节补全对话Mary: Mike, how do I look in these blue jeans?Mike: 51 They really suit you, Mary!Mary: Thanks, you know, these kinds of jeans are in style now.Mike: 52Mary: I mean...they are very popular these days; everyone is wearing them!Mike: You are great at keeping up with fashions.Mary: Well, 53Mike: Perhaps you can help me pick out a pair of jeans now, since you are an expert.Mary: 54 I would be happy to help you with your fashion change!A. Wow, great!B. No problem!C. See you then.D. Any suggestions?E. I am a girl after all.F. What do you mean?G. Thank you so much!第二卷第一节阅读表达When my father was celebrating a milestone (里程碑) birthday, I pulled together a surprise gift that he would never forget.As he was approaching 60,1 had a fim idea: What if I could get the memories people had of him, put each one into an envelope - 60 in total - and have him open them, one by one, on his birthday? So I wrote an e-mail to family and friends, explaining my idea.I sent the e-mail and waited. And then the replies started coming in and I was very, very surprised. There were so many memories, and they were all so lovely. They came from the '50s, '60s, '70s, from every decade（十年）between now and the day my dad was bom. They came from my mother, my siblings, my grandma, my dad's friends from high school, his sister, my dad's first boss, a colleague at his first job, from people who hadn't seen my dad in 40 years, from people I myself hadn't even informed. They typed them and handwrote them. They mailed them and e-mailed them.The night before Dad's birthday, my sister and 1 stayed up late, putting everything together with someThe next morning, after breakfast and presents and cake, we gave the pile of envelopes to him. "Just one more thing for you," we said.It took him a long time to open them and read. Each one was a brief ticket to another time, a leap (跳跃) backward over years and decades. There was a lot of laughter and a few tears, too.I was kind of sad when the project was over because it was great fun to collect these memories. It gave me a different picture of my dad.56. When did the author give her father a surprise gift? (no more than 4 words)57. Who sent the mails? (no more than 6 words)58. Why did the author and her sister stay up late the night before their father's birthday? (no more than 9 words)59. How did the author's father most probably feel when he read (he mails? (no more than 3 words)60.What was the surprise gift? (no more than 6 words)第二节短文改错Hello, boys and girls! Today, I am going to talk with what you should do when a fire alarm go off. If you hear the alarm, stand in line at the door and wait your teacher to lead you outside. Stay close to your teacher and classmate. Don't panic or get out of line, and trying to remain quiet and calmly. Soon the firefighters will come and put out a fire. If it's a false alarm and there is no fire, your teacher will lead us back to the classroom. If you notice that when someone is missing and hurt, tell your teacher immediately.第三节书面表达笫三节书面表达（共35分）假设你是李夏I你的美国笔友Sam来信关心你参加商考的情况，请根据以下要点回信告知。

2014年普通高等学校招生全国统一考试(四川卷)

2014年成人高考数学模拟试题第Ⅰ卷（共60分）一、选择题：本大题共12个小题,每小题5分,共60分.在每小题给出的四个选项中，只有一项是符合题目要求的.1. 设集合{1,2,4,6,8},{1,2,3,5,6,7}M N ==，则M N I 中元素的个数为（）A ．2B ．3C ．5D ．72. 已知角α的终边经过点(4,3)-，则cos α=（）A ．45B ．35C ．35-D ．45- 3. 不等式组(2)0||1x x x +>⎧⎨<⎩的解集为（）A ．{|21}x x -<<-B ．{|10}x x -<<C ．{|01}x x <<D ．{|1}x x > 4. 已知正四面体ABCD 中，E 是AB 的中点，则异面直线CE 与BD 所成角的余弦值为（）A ．16B ．6 C ．13D ．35. 函数1)(1)y x =>-的反函数是（）A ．3(1)(1)x y e x =->- B ．3(1)(1)xy e x =->- C ．3(1)()x y e x R =-∈ D ．3(1)()xy e x R =-∈6. 已知a b r r 、为单位向量，其夹角为060，则(2)a b b -•=r r r （） A ．-1 B ．0 C ．1 D ．27. 有6名男医生、5名女医生，从中选出2名男医生、1名女医生组成一个医疗小组，则不同的选法共有（）A ．60种B ．70种C ．75种D ．150种8. 设等比数列{}n a 的前n 项和为n S ，若243,15,S S ==则6S =（）A ．31B ．32C ．63D ．649. 已知椭圆C ：22221x y a b+=(0)a b >>的左、右焦点为1F 、2F，过2F 的直线l 交C 于A 、B 两点，若1AF B ∆的周长为C 的方程为（）A ．22132x y +=B ．2213x y += C ．221128x y += D ．221124x y += 10. 正四棱锥的顶点都在同一球面上，若该棱锥的高位4，底面边长为2，则该球的表面积为（）A ．814π B ．16π C ．9π D ．274π11. 双曲线C ：22221(0,0)x y a b a b-=>>的离心率为2，，则C 的焦距等于（）A ．2 B． C ．4 D．12. 奇函数()f x 的定义域为R ，若(2)f x +为偶函数，且(1)1f =，则(8)(9)f f +=（）A ．-2B ．-1C ．0D ．1第Ⅱ卷（共90分）二、填空题（每题5分，满分20分，将答案填在答题纸上） 13. 6(2)x -的展开式中3x 的系数为 .（用数字作答） 14. 函数cos 22sin y x x =+的最大值为 .15. 设x 、y 满足约束条件02321x y x y x y -≥⎧⎪+≤⎨⎪-≤⎩，则4z x y =+的最大值为 .16. 直线1l 和2l 是圆222x y +=的两条切线，若1l 与2l 的交点为（1,3），则1l 与2l 的夹角的正切值等于 .三、解答题（本大题共6小题. 解答应写出文字说明、证明过程或演算步骤.） 17. （本小题满分10分）数列{}n a 满足12212,2,22n n n a a a a a ++===-+.（1）设1n n n b a a +=-，证明{}n b 是等差数列；（2）求{}n a 的通项公式. 18. （本小题满分12分）ABC ∆的内角A 、B 、C 的对边分别为a 、b 、c ，已知13cos 2cos ,tan 3a C c A A ==，求B.19. （本小题满分12分）如图，三棱柱111ABC A B C -中，点1A 在平面ABC 内的射影D 在AC 上，090ACB ∠=，11,2BC AC CC ===.（1）证明：11AC A B ⊥；（2）设直线1AA 与平面11BCC B 1A AB C --的大小. 20.（本小题满分12分）设每个工作日甲、乙、丙、丁4人需使用某种设备的概率分别是0.6，0.5,0.5,0.4，各人是否使用设备相互独立，（1）求同一工作日至少3人需使用设备的概率；（2）实验室计划购买k 台设备供甲、乙、丙、丁使用，若要求“同一工作日需使用设备的人数大于k ”的概率小于0.1，求k 的最小值.21. （本小题满分12分）函数32()33(0)f x ax x x a =++≠.（1）讨论函数()f x 的单调性；（2）若函数()f x 在区间（1，2）是增函数，求a 的取值范围. 22. （本小题满分12分）已知抛物线C:22(0)y px p =>的焦点为F ，直线4y =与y 轴的交点为P ，与C 的交点为Q ，且54QF PQ =. （1）求抛物线C 的方程；（2）过F 的直线l 与C 相交于A,B 两点，若AB 的垂直平分线l '与C 相交于M,N 两点，且A,M,B,N四点在同一个圆上，求直线l 的方程.2014年成人高考数学模拟试题答案3一、选择题1.B2.D3.C4.B5.D6.B7.C8.C9.A10.A11.C12.D二、填空题13. -16014.3215. 5 16.43三、解答题：解答应写出文字说明，证明过程或演算步骤。

2014年高考语文四川卷-答案

2014年普通高等学校招生全国统一考试（四川卷）语文答案解析第Ⅰ卷一、选择题1.【答案】A【解析】B“箍”应读ɡū；C.“挠”应读náo；D.“挟”应读xié2.【答案】D【解析】A.口干舌噪—口干舌燥；B.贻养天年—颐养天年；C.清彻—清澈。

3.【答案】D【解析】息息相关：呼吸相关联，形容关系密切。

A.今后：从今以后根据语境，可改为“以后”。

B.从而：连词，表示上文是原因、方法等，不用于表示假设关系。

C.安之若素：表示对反常现象或不顺利的情况视若平常，毫不在意，也指对错误言论或事物不闻不问，听之任之。

不合语境。

4.【答案】B【解析】A.搭配不当，“提高”与“特色”不搭配，可将“提高”改为“展现”等。

C.语序不当，应将“所有”与“中国”互换位置。

D.句式杂糅，“艺术形式”“娱乐性”既是“具有”的宾语，又是“使”的主语，显然不正确，应在“使”前加“这”。

5.【答案】C【解析】A.“直接催生了大数据教育”于文无据。

B选项说的是大数据与传统的数据相比的特点，原文大数据教育的特点是“弹性学制、个性化辅导、社区和家庭学习、每个人的成功”。

D.“第二门实实在在的实证科学”错误，原文第三段结尾一句仅说明教育是“继经济学之后”的“一门实实在在的实证科学”6.【答案】C【解析】题干是“将给教育带来的变化”，选项表述的是目前存在的在线教育模式。

7.【答案】D【解析】“教师需求量将大为减少”于文无据。

8.【答案】B【解析】优：居丧。

也叫“丁优”“丁艰”“守孝”9.【答案】B【解析】均为副词，于是，就，A.介词，因为/动词，做。

C代词，他/代同，它的。

D.代词，这，这些/结构助词，的。

第Ⅱ卷二、非选择题10.【答案】（1）尚书令沈约，是当时的文坛宗师每当看到主筠的文章，赞叹吟诵玩味，认为（自己）赶不上（王筠）。

（2）王筠天性宽弘敦厚，不因有技艺才能面自视高人一等，而且年轻时就有才华名望，在当时和刘孝绰一起被（世人）看重。

2014年普通高等学校招生全国统一考试(四川卷)

第I卷（选择题共42分）相对原子质量（原子量）：H－1 C－12 N－14 O－16 Na－23 S－32一、选择题（本大题共7小题，每小题6分，共42分。

在每小题给出的四个备选项中，只有一项符合题目要求）1．化学与生活密切相关。

下列说法不正确．．．的是（）A．乙烯可作水果的催熟剂B．硅胶可作袋装食品的干燥剂C．福尔马林可作食品的保鲜剂D．氢氧化铝可作胃酸的中和剂【答案】C【考点地位】本题主要是考查化学与生活的有关判断。

【名师点晴】本题主要是以化学在生活中的应用为载体，涉及乙烯、硅胶、甲醛和氢氧化铝的性质与用途，意在提高学生关注化学在生活中的广泛应用，提高学生的科学素养。

本题难度不大，平时注意相关基础知识的理解掌握和积累。

2．下列关于物质分类的说法正确的是（）A．金刚石、白磷都属于单质B．漂白粉、石英都属于纯净物C．氯化铵、次氯酸都属于强电解质D．葡萄糖、蛋白质都属于高分子化合物【答案】A的化合物是强电解质，不能完全电离，存在电离平衡的是弱电解质。

氯化铵是强电解质，次氯酸是弱电解质，C不正确；D、蛋白质是高分子化合物，而葡萄糖是单糖，不是高分子化合物，D不正确，答案选A。

【考点地位】本题主要是考查物质分类的有关判断【名师点晴】本题属于基础性试题的考查，题目难度不大，明确有关概念与含义以及判断依据是答题的关键，有利于巩固学生的基础，提高学生的应试能力。

注意单质、纯净物、强电解质以及高分子化合物的含义，注意有关基础知识的理解掌握。

3．能正确表示下列反应的离子方程式是（）A．Cl2通入NaOH溶液：Cl2＋OH－=Cl－＋ClO－＋H2OB．NaHCO3溶液中加入稀HCl：CO32－＋2H＋=CO2↑＋H2OC．AlCl3溶液中加入过量稀氨水：Al3＋＋4NH3·H2O=AlO2－＋4NH4＋＋2H2OD．Cu溶于稀HNO3：3Cu＋8H＋＋2NO3－=3Cu2＋＋2NO↑＋4H2O【答案】D【考点地位】本题主要是考查离子方程式的正误判断【名师点晴】本题属于中等难度试题的考查，明确反应原理是答题的关键。