人教版必修5小题练习

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人教版高二数学必修5期末综合测试题及答案

必修5综合测试题（2010.11）班级姓名一、选择题1. 数列1，3，6，10，…的一个通项公式是（）A. a n =n 2-(n-1) B . a n =n 2-1 C. a n =2)1(+n n D. a n =2)1(-n n 2. 2b ac =是a,b,c 成等比数列的（）A 、充分非必要条件B 、必要非充分条件C 、充要条件D 、既不充分也非必要条件 3．已知等差数列{a n }的公差d ≠0,若a 5、a 9、a 15成等比数列,那么公比为 ( )A ．B ．C ．D ．4. 等差数列{a n }共有2n+1项，其中奇数项之和为4，偶数项之和为3，则n 的值是( )A.3B.5C.7D.9 5．△ABC 中，cos cos A aB b=，则△ABC 一定是( ) A ．等腰三角形 B ．直角三角形C ．等腰直角三角形D ．等边三角形6．已知△ABC 中，a ＝4，b ＝43，∠A ＝30°，则∠B 等于( )A ．30°B ．30°或150°C ．60°D ．60°或120°7. 在△ABC 中，∠A =60°,a =6,b =4,满足条件的△ABC( )(A )无解 (B )有解 (C )有两解 (D )不能确定 8．若110a b<<，则下列不等式中，正确的不等式有 ( ) ①a b ab +< ②a b > ③a b < ④2b aa b+>A .1个B .2个C .3个D .4个 9．下列不等式中，对任意x ∈R 都成立的是 ( )A ．2111x <+ B ．x 2+1>2x C ．lg(x 2+1)≥lg2x D ．244xx +≤110. 下列不等式的解集是空集的是( )A.x 2-x+1>0B.-2x 2+x+1>0C.2x -x 2>5D.x 2+x>211．不等式组 (5)()0,03x y x y x -++≥⎧⎨≤≤⎩表示的平面区域是（）A 。

人教版高中数学必修5第一章解三角形测试题及答案

必修五第一章解三角形测试(总分150)一、选择题(每题5分，共50分)1、在△ABC 中，a ＝3，b ＝7，c ＝2，那么B 等于（）A ． 30°B ．45°C ．60°D ．120°2、在△ABC 中，a ＝10，B=60°,C=45°,则c 等于（）A ．310+B ．()1310-C ．13+D ．3103、在△ABC 中，a ＝32，b ＝22，B ＝45°，则A 等于（）A ．30°B ．60°C ．30°或120°D ． 30°或150°4、在△ABC 中，3=AB ,1=AC ,∠A ＝30°，则△ABC 面积为（）A ．23 B ．43 C ．23或3 D ．43 或23 5、在△ABC 中，已知bc c b a ++=222，则角A 为（）A ．3πB ．6πC ．32πD ． 3π或32π6、在△ABC 中,面积22()Sa b c =--,则sin A 等于（）A ．1517B ．817C ．1315D ．13177、已知△ABC 中三个内角为A 、B 、C 所对的三边分别为a 、b 、c ，设向量(,)p a c b =+ ，(,)q b a c a =-- .若//p q，则角C 的大小为（）A ．6π B ．3π C ．2π D ．23π8、已知锐角三角形的边长分别为1，3，a ，则a 的范围是（）A ．()10,8B ．()10,8C ．()10,8D ．()8,109、在△ABC 中，已知C B A sin cos sin 2=,那么△ABC 一定是 ( )A ．直角三角形B ．等腰三角形C ．等腰直角三角形D ．正三角形 10、在△ABC 中,3,4ABBC AC ===,则AC 上的高为（）A ．BC ．32D ．二、填空题（每小题5分，共20分）11、在△ABC 中，若∠A:∠B:∠C=1:2:3,则=c b a :: 12、已知三角形两边长为11，则第三边长为13、若三角形两边长为1和3，第三边上的中线长为1，则三角形的外接圆半径为 14、在△ABC 中BC=1，3Bπ=，当△ABC tan C =三、解答题（本大题共小题6小题，共80分）15、（本小题14分）在△ABC 中，已知210=AB ，A ＝45°，在BC 边的长分别为20，3320，5的情况下，求相应角C 。

人教版新课标高中英语必修五Unit 1 Great scientists 单元测试含答案详解

Unit 1Great scientists本套试卷分为第Ⅰ卷和第Ⅱ卷两部分。

总分120分。

考试时间100分钟。

第Ⅰ卷Ⅰ.阅读理解(共两节,满分35分)第一节(共10小题;每小题2.5分,满分25分)阅读下列短文,从每题所给的A、B、C和D四个选项中,选出最佳选项。

AMy senior year of high school was a very hectic one, to say the least. If I wasn´t studying or worrying about my grades, I was working on after-class activities. It seemed as if my life had turned into one crazy cloud of confusion and I hoped to find some sort of direction.Finally, I got a part-time job at the local coffee shop. I had thought it would be easy and, for the most part, stress-free. I pictured myself pouring coffee and becoming close friends with my customers.What I hadn´t expected were the people with so many orders. There were moments when I was very angry simply because I couldn´t seem to please anyone. There was always too much sugar, too little ice, or not enough skim milk. However, I kept at it.One day, one of my customers came in, depressed. Before he left, I handed him a bag along with his iced coffee. He looked at me questioningly because he hadn´t ordered anything but the coffee. He opened the bag and saw his favourite doughnut (甜甜圈) I had given him. He smiled and thanked me before heading out into the rain.The next evening, he came. Instead of ordering something, he handed me a single pink rose and a note.“Thanks for being so sweet and thoughtful yesterday. It is so nice to meet someone who´s warm and unselfish. Please don´t change your ways because I truly believe that you will do better. Have a great day!”As time went on, I did come across some customers really particular. But anytime I felt depressed, I thought of that man and his kindness. Then I would smile, hold my head up high, clear my throat and ask politely, “How can I help you?”1.What does the underlined word “hectic” in Paragraph 1 mean?A. Glad.B. Interesting.C. Productive.D. Busy.2.What can we know about the author´s part-time job?A. It is easy and stress-free.B. It is quite busy and challenging.C . It doesn´t need special skills. D. It gives the author a feeling of freshness.3.What´s the message the author wants to convey?A. Kind words are worth much but cost little.B. It is impossible to satisfy everyone in our life.C. A small act of kindness can make a big difference.D. Our attitude determines our suffering or our freedom.BAn idea that started in Seattle´s public library has spread throughout America and beyond. The idea is simple: help to build a sense of community in a city by getting everyone to read the same book at the same time.In addition to encouraging reading as a pursuit(爱好) to be enjoyed by all, theprogramme allows strangers to communicate by discussing the book on the bus, as well as promoting reading as an experience to be shared in families and schools. The idea came from Seattle librarian Nancy Pearl who launched (发起)the “If All of Seattle Read the Same Book” project in 1998. Her original programme used author visits, study guides and book discussion groups to bring people together with a book, but the idea has since expanded to many other American cities, and even to Hong Kong.In Chicago, the mayor appeared on television to announce the choice of To Kill a Mockingbird as the first book in the “One Book, One Chicago” programme. As a result, reading clubs and neighbourhood groups sprang up around the city. Across the US, stories emerged of parents and children reading to each other at night and strangers chatting away on the bus about plot and characters.The only problem arose in New York, where local readers could not decide on one book to represent the huge and diverse population. This may show that the idea works best in medium-sized cities or large towns, where a greater sense of unity(一致)can be achieved.Or it may show that New Yorkers rather missed the point, putting all their energy and passion into the choice of the book rather than discussion about a book itself.As Nancy points out, the level of success is not measured by how many people read a book, but by how many people are enriched by the process or have enjoyed speaking to someone with whom they would not otherwise have shared a word.4.What is the purpose of the project launched by Nancy?A.To invite authors to guide readers.B.To encourage people to read and share.C.To involve people in community services.D.To promote the friendship betweencities.5.Why was it difficult for New Yorkers to carry out the project?A.They had little interest in reading.B.They were too busy to read a book.C.They came from many different backgrounds.D.They lacked support from the local government.6.The underlined words “shared a word” in Paragraph 5 probably mean .A.exchanged ideas with each otherB.discussed the meaning of a wordC.gained life experienceed the same languageCScientific experiments can sometimes go wrong and when they do, the results may range from the disastrous (灾难性的) to the troubling. One such experiment took place in South America about fifty years ago. Whether its final consequences will cause serious damage or nothing more than a small trouble still remains to be seen.The story began in 1956 when an American scientist working in Brazil decided to solve the problem of increasing the productivity of that country´s bees. He imported a very active type of African bee from Tanzania and mated (交配) it with the more easy-going native variety to produce a new kind of bees. The new bees worked harder and produced twice as much honey. It seemed that Professor Kerr, which was the scientist´s name, had a total success on his hands.Then things began to go wrong. For some reason as yet unseen, but perhaps as a result of something in their environment, the new bees began to develop extremely attacking personalities. They became bad-tempered and easy to be angry. They attacked the native bees and drove them from their living places.But worse was to follow. Having taken over the countryside, the new bees, with their dangerous stings (刺), began to attack their neighbours—cats, dogs, horses, chickens and finally man himself. A long period of terror began that has so far killed a great number of animals and about 150 human beings.This would have been bad enough if the bees had stayed in Brazil. But now they are on the move, heading northwards in countless millions towards Central and North America, and moving at the alarming speed of 200 miles a year. The countries that lie in their path are naturally worried because it looks as if nothing can be done to stop them.7. The results of the South American experiment .A.are not importantB.are not yet certainC.have caused a serious troubleD.have proved to be wrong8. The experiment mentioned in this passage was designed to .A.make African bees less activeB.increase the number of bees in BrazilC.make Brazilian bees more easy-goingD.increase the amount of honey in Brazil9. Which of the following may be the cause of the new bees´ attacking personalities?A.Their bad temper.B.Their hard work.C.Their production of honey.D.Their living environment.10. The last paragraph implies that .A.the bees prefer to live in BrazilB.the bees must be stopped from moving northC.the bees may bring about trouble in more countriesD.the bees have been driven to Central and North America第二节阅读七选五(共5小题;每小题2分,满分10分)根据短文内容,从短文后的选项中选出能填入空白处的最佳选项。

【金牌学案】2022秋英语人教版必修5练习：Unit 5 First aid 3 Word版含答案

课时训练Ⅲ基础夯实Ⅰ.单词拼写Of all the people who a for the job,he was the youngest.t think I was fairly t on that matter.that they don’t know much about the subject and are determined to work harder.This wet ground is not f enough to walk on.The shoes are too t for me and I want to change for a bigger pair.(抢救车) waiting for the patients.(喉咙) and begins to talk.t give too much (压力) to those students.That can only make them feel more worried.(英勇) in the war.(仪式) on May Day.Ⅱ.选词填空English.what he has achieved in study.foreign students in my school.from outside because of the snowstorm.We are very busy.the scandal.this treatment cancer...Ⅲ.完成句子1.He(刚要开头试验这时) the door opened and his wife came(她能够找到的).3.毫无疑问是他的持之以恒使他最终取得了成功。

4.在那个欢快的时刻,他的同学们向他赠送了鲜花和卡片。

His students him beautiful flowers and cards on that happy occasion.5.近几年他向那所学校捐助了大量的图书。

高中数学必修5复习题及答案(A组)免费范文

篇一：高中数学必修5课后习题答案人教版高中数学必修5课后习题解答第一章解三角形1．1两角和与差的正弦、余弦和正切公式练习（P4） 1、（1）a?14，b?19，B?105?；（2）a?18cm，b?15cm，C?75?. 2、（1）A?65?，C?85?，c?22；或A?115?，C?35?，c?13；（2）B?41?，A?24?，a?24. 练习（P8） 1、（1）A?39.6?,B?58.2?,c?4.2 cm；（2）B?55.8?,C?81.9?,a?10.5 cm. 2、（1）A?43.5?,B?100.3?,C?36.2?；（2）A?24.7?,B?44.9?,C?110.4?. 习题1.1 A组（P10） 1、（1）a?38cm,b?39cm,B?80?；（2）a?38cm,b?56cm,C?90? 2、（1）A?114?,B?43?,a?35cm;A?20?,B?137?,a?13cm（2）B?35?,C?85?,c?17cm；（3）A?97?,B?58?,a?47cm;A?33?,B?122?,a?26cm； 3、（1）A?49?,B?24?,c?62cm；（2）A?59?,C?55?,b?62cm；（3）B?36?,C?38?,a?62cm；4、（1）A?36?,B?40?,C?104?；（2）A?48?,B?93?,C?39?；习题1.1 A组（P10）1、证明：如图1，设?ABC的外接圆的半径是R，①当?ABC时直角三角形时，?C?90?时，?ABC的外接圆的圆心O在Rt?ABC的斜边AB上.BCAC在Rt?ABC中，?sinA，?sinBABABab即?sinA，?sinB 2R2R所以a?2RsinA，b?2RsinB 又c?2R?2R?sin902RsinC （第1题图1）所以a?2RsinA, b?2RsinB, c?2RsinC②当?ABC时锐角三角形时，它的外接圆的圆心O在三角形内（图2），作过O、B的直径A1B，连接AC， 1?90?，?BACBAC则?A1BC直角三角形，?ACB. 11在Rt?A1BC中，即BC?sin?BAC1， A1Ba?sin?BAC?sinA， 12R所以a?2RsinA，同理：b?2RsinB，c?2RsinC③当?ABC时钝角三角形时，不妨假设?A为钝角，它的外接圆的圆心O 在?ABC外（图3）（第1题图2）作过O、B的直径A1B，连接AC.1则?A1BC直角三角形，且?ACB?90?，?BAC?180?11在Rt?A1BC中，BC?2Rsin?BAC， 1即a?2Rsin(180?BAC)即a?2RsinA同理：b?2RsinB，c?2RsinC综上，对任意三角形?ABC，如果它的外接圆半径等于则a?2RsinA,b?2RsinB, c?2RsinC2、因为acosA?bcosB，所以sinAcosA?sinBcosB，即sin2A?sin2B 因为0?2A,2B?2?，（第1题图3）所以2A?2B，或2A?2B，或2A?22B. 即A?B或A?B?所以，三角形是等腰三角形，或是直角三角形.在得到sin2A?sin2B后，也可以化为sin2A?sin2B?0 所以cos(A?B)sin(A?B)?0 A?B??2.?2，或A?B?0即A?B??2，或A?B，得到问题的结论.1．2应用举例练习（P13）1、在?ABS中，AB?32.2?0.5?16.1 n mile，?ABS?115?，根据正弦定理，得AS?ASAB?sin?ABSsin(6520?)?AB?sin?ABS16.1?sin115sin(6520?)∴S到直线AB的距离是d?AS?sin2016.1?sin115sin207.06（cm）. ∴这艘船可以继续沿正北方向航行. 2、顶杆约长1.89 m. 练习（P15）1、在?ABP中，?ABP?180?，?BPA?180(?)ABP?180(?)?(180?)在?ABP中，根据正弦定理，APAB?sin?ABPsin?APBAPa?sin(180?)sin(?)a?sin(?)AP?sin(?)asin?sin(?)所以，山高为h?APsinsin(?)2、在?ABC中，AC?65.3m，?BAC?25?2517?387?47??ABC?909025?2564?35?ACBC?sin?ABCsin?BAC?747AC?sin?BAC65.?3?sinBC?m 9.8?sin?ABCsin?6435井架的高约9.8m.200?sin38?sin29?3、山的高度为?382msin9?练习（P16） 1、约63.77?. 练习（P18） 1、（1）约168.52 cm2；（2）约121.75 cm2；（3）约425.39 cm2. 2、约4476.40 m2a2?b2?c2a2?c2?b2?c?3、右边?bcosC?ccosB?b?2ab2aca2?b2?c2a2?c2?b22a2?a左边? 【类似可以证明另外两个等式】 ?2a2a2a习题1.2 A组（P19）1、在?ABC中，BC?35?0.5?17.5 n mile，?ABC?14812622?根据正弦定理，14?8)?，1BAC?1801102248ACB?78(180ACBC?sin?ABCsin?BACBC?sin?ABC17.?5s?in22AC?8.8 2n milesin?BACsin?48货轮到达C点时与灯塔的距离是约8.82 n mile. 2、70 n mile.3、在?BCD中，?BCD?301040?，?BDC?180?ADB?1804510125?1CD?3010 n mile3CDBD根据正弦定理， ?sin?CBDsin?BCD10BD?sin?(18040125?)sin40?根据正弦定理，10?sin?40sin1?5在?ABD中，?ADB?451055?，?BAD?1806010110??ABD?1801105515?ADBDABADBDAB根据正弦定理，，即sin?ABDsin?BADsin?ADBsin15?sin110?sin55?10?sin?40?sin1?5BD?sin1?5?10s?in40?6.8 4n mile AD?sin1?10si?n110?sin70BD?sin5?5?10sin40?sin55n mile 21.6 5sin1?10sin15?sin70如果一切正常，此船从C开始到B所需要的时间为：AD?AB6.8?421.6520?min ?6?01?0?60 86.983030即约1小时26分59秒. 所以此船约在11时27分到达B岛. 4、约5821.71 m5、在?ABD中，AB?700 km，?ACB?1802135124?700ACBC根据正弦定理，sin124?sin35?sin21?700?sin?35700?sin21?AC?，BC?sin1?24sin124?700?sin?357?00s?in21AC?BC7?86.89 kmsin1?24si?n124所以路程比原来远了约86.89 km.6、飞机离A处探照灯的距离是4801.53 m，飞机离B处探照灯的距离是4704.21 m，飞机的高度是约4574.23 m.1507、飞机在150秒内飞行的距离是d?1000?1000? m3600dx? 根据正弦定理，sin(8118.5?)sin18.5?这里x是飞机看到山顶的俯角为81?时飞机与山顶的距离.d?sin18.5??tan8114721.64 m 飞机与山顶的海拔的差是：x?tan81sin(8118.5?)山顶的海拔是20250?14721.64?5528 m8、在?ABT中，?ATB?21.418.62.8?，?ABT?9018.6?，AB?15 mABAT15?cos18.6?根据正弦定理，，即AT? ?sin2.8?cos18.6?sin2.8?15?cos18.6?塔的高度为AT?sin21.4?sin21.4106.19 msin2.8?326?189、AE97.8 km 60在?ACD中，根据余弦定理：AB?AC??101.235 根据正弦定理，（第9题）?sin?ACDsin?ADCAD?sin?ADC5?7si?n66sin 44?ACD?0.51AC101.2356?ACD?30.9??ACB?13330.9?6?10 2?在?ABC中，根据余弦定理：AB?245.93222AB?AC?B2C245.9?3101?.22352204sBAC?0.58co? 472?AB?AC2?245.?93101.235?BAC?54.21?在?ACE中，根据余弦定理：CE?90.75222AE2?EC?A2C97.8?90.?751012.235sAEC?0.42co? 542?AE?EC2?97?.890.75?AEC?64.82?0AEC?(1?8?0?7?5?)?7564.8?2 18?所以，飞机应该以南偏西10.18?的方向飞行，飞行距离约90.75 km.10、如图，在?ABCAC??37515.44 km222AB?AC?B2C6400?37515?2.44422200?0.692 ?BAC? 42?AB?AC2?640?037515.448，2 ?BAC?9043.?8 ?BAC?133.? 2所以，仰角为43.82?1111、（1）S?acsinB28?33?sin45326.68 cm222aca36（2）根据正弦定理：，c?sinCsin66.5?sinAsinCsinAsin32.8?11sin66.5?S?acsinB362sin(32.866.5?)?1082.58 cm222sin32.8?2（3）约为1597.94 cm122?12、nRsin.2na2?c2?b213、根据余弦定理：cosB?2acaa2所以ma?()2?c2?2c?cosB22a2a2?c2?b22?()?c?a?c? B22ac12212?()2[a2?4c2?2(a?c?2b)]?()[2(b?c2)?a2]222（第13题）篇二：人教版高中数学必修5期末测试题及其详细答案数学必修5试题一．选择题（本大题共10小题，每小题5分，共50分）1.由a1?1，d?3确定的等差数列?an?，当an?298时，序号n等于（）Ａ．99Ｂ．100Ｃ．96Ｄ．1012.?ABC中，若a?1,c?2,B?60?，则?ABC的面积为（） A．12B．2 C.1 D.3.在数列{an}中，a1=1，an?1?an?2，则a51的值为（）A．99 B．49 C．102 D． 101 4.已知x?0，函数y?4x?x的最小值是（） A．5 B．4C．8 D．6 5.在等比数列中，a11?2，q?12，a1n?32，则项数n为（） A. 3B. 4C. 5D. 66.不等式ax2?bx?c?0(a?0)的解集为R，那么（）A. a?0,0B. a?0,0C. a?0,0D. a?0,0?x?y?17.设x,y满足约束条件??y?x,则z?3x?y的最大值为（）y2A． 5B. 3C. 7 D. -88.在?ABC中,a?80,b?100,A?45?,则此三角形解的情况是（）A.一解 B.两解 C.一解或两解 D.无解9.在△ABC中，如果sinA:sinB:sinC?2:3:4，那么cosC等于（）A.23 B.-2113 C.-3D.-410.一个等比数列{an}的前n项和为48，前2n项和为60，则前3n项和为（ A、63B、108 C、75 D、83）二、填空题（本题共4小题，每小题5分，共20分） 11.在?ABC中，B?450,c?b?A＝_____________; 12.已知等差数列?an?的前三项为a?1,a?1,2a?3，则此数列的通项公式为______三、解答题 (本大题共6个小题，共80分；解答应写出文字说明、证明过程或演算步骤) 15(12分) 已知等比数列?an?中，a1?a3?10,a4?a6?16(14分)(1) 求不等式的解集：?x(2)求函数的定义域：y?17 (14分)在△ABC中，BC＝a，AC＝b，a，b是方程x2?0的两个根，且2cos(A?B)?1。

【高中英语基础过关】必修5 U5 First aid 人教版英语基础练习题

B5U5 First aid满分：120分得分：__________第一步：单词拼写（根据汉语提示，写出该单词的正确形式。

每小题1分，满分20分）1. Foreign __________ (援助) from many countries poured into the flooded area.2. I’m living with my parents, but it’s only __________ (临时的).3. Janet slipped on the stairs and twisted her __________ (踝关节).4. Put your bowls back in the __________ (橱柜).5. Her __________ (皮肤) was as smooth as ever, her teeth as perfect.6. It is __________ (本质的) that our pilots (should) be given the best possible training.7. The mountains form a natural __________ (屏障) between the two countries.8. Hatred is a __________ (毒药) that will destroy your life.9. China was a __________ (复合体) of different societies.10. Human __________ (生物组织) is made up of cells.11. Never put a finger or __________ (剪刀) into an electric socket.12. We should protect the __________ (盆地) by keeping water levels and water quality.13. He wrapped a __________ (绷带) around his injured arm.14. A fever is a __________ (症状) of illness.15. She filled the __________ (水壶) and switched it on.16. The injured __________ (手腕) was swollen up with infection.17. He suffered a lot because a fishbone stuck in his __________ (咽喉).18. They insisted that he (should) be present at the __________ (典礼).19. This is to be my __________ (招待), so I'll pay for everything.20. The wounded man was rushed to the hospital by __________ (救护车).（以上习题，填了空格就是完整的句子，填，念，用。

人教版高中数学必修5《数列》练习题(有答案)

必修5 数列2．等差数列{}n a 中，()46810129111120,3a a a a a a a ++++=-则的值为A ．14B ．15C ．16D ．173．等差数列{}n a 中，12910S S a =>，，则前项的和最大．解：0912129=-=S S S S ， 10111211111030,00a a a a a a ∴++=∴=∴=>，，又4．已知等差数列{}n a 的前10项和为100，前100项和为10，则前110项和为．解：∵ ，，，，，1001102030102010S S S S S S S ---成等差数列，公差为D 其首项为10010=S ，6．设等差数列{}n a 的前n 项和为n S ，已知001213123<>=S S a ，，．①求出公差d 的范围；②指出1221S S S ，，，中哪一个值最大，并说明理由．解：①)(6)(610312112a aa a S +=+=36(27)0a d =+>②12671377666()013000S a a S a a a S =+>=<∴<>∴，最大。

1．已知等差数列{}n a 中，12497116a a a a ，则，===+等于( ) A ．15 B ．30 C ．31 D ．64794121215a a a a a +=+∴= A2．设n S 为等差数列{}n a 的前n 项和，971043014S S S S ，则，=-== ．543．已知等差数列{}n a 的前n 项和为n S ，若=+++=118521221a a a a S ，则． 4．等差数列{}n a 的前n 项和记为n S ，已知50302010==a a ，． ①求通项n a ；②若n S =242，求n ．解：d n a a n )1(1-+=111020193012305021019502n a d a a a a n a d d +==⎧⎧==∴∴=+⎨⎨+==⎩⎩，解方程组5．甲、乙两物体分别从相距70m 的两处同时相向运动，甲第一分钟走2m ，以后每分钟比前一分钟多走1m ，乙每分钟走5m ，①甲、乙开始运动后几分钟相遇? ②如果甲乙到对方起点后立即折返，甲继续每分钟比前一分钟多走1m ，乙继续每分钟走5m ，那么，开始运动几分钟后第二次相遇?故第一次相遇是在开始运动后7分钟．故第二次相遇是在开始运动后15分钟 10．已知数列{}n a 中，，31=a 前n 和1)1)(1(21-++=n n a n S ． ①求证：数列{}n a 是等差数列； ②求数列{}n a 的通项公式； ③设数列⎭⎬⎫⎩⎨⎧+11n n a a 的前n 项和为n T ，是否存在实数M ，使得M T n ≤对一切正整数n 都成立? 若存在，求M 的最小值，若不存在，试说明理由．12122(1)(1)()2n n n n n n n a n a a a a a ++++∴+=++∴=+ ∴数列{}n a 为等差数列．②1)1(311-+==+n n a n na a ，{}212121522n a a a a a ∴=-=∴-=即等差数列的公差为1(1)3(1)221n a a n d n n ∴=+-=+-⋅=+121n +++，要使得T n n 都成立，三、等比数列知识要点1. 定义：如果一个数列从第二项起，每一项与它的前一项的比等于同一个常数，那么这个数列叫做等比数列，这个常数叫做等比数列的公比，记为()0q q ≠，．2. 递推关系与通项公式mn m n n n n n q a a q a a qa a --+⋅=⋅==推广：通项公式：递推关系：111 3. 等比中项：若三个数c b a ,,成等比数列，则称b 为a 与c 的等比中项，且ac b ac b =±=2，注：是成等比数列的必要而不充分条件． 4. 前n 项和公式)1(11)1()1(111≠⎪⎩⎪⎨⎧--=--==q q qa a q q a q na S n n n5. 等比数列的基本性质，),,,(*∈N q p n m 其中①q p n m a a a a q p n m ⋅=⋅+=+，则若，反之不成立！ ②)(2*+--∈⋅==N n a a a a a qm n m n n mn mn ， ③{}n a 为等比数列，则下标成等差数列的对应项成等比数列．④若项数为()*2n n N ∈，则S q S =偶奇．⑤nn m n m S S q S +=+⋅．⑥ ，，，时，n n n n n S S S S S q 2321---≠仍成等比数列． 6. 等比数列与等比数列的转化 ①{}n a 是等差数列⇔{})10(≠>c c cna ，是等比数列；②{}n a 是正项等比数列⇔{})10(log ≠>c c a n c ，是等差数列；③{}n a 既是等差数列又是等比数列⇔{}n a 是各项不为零的常数列． 7. 等比数列的判定法 ①定义法：⇒=+（常数）q a a nn 1{}n a 为等比数列； ②中项法：⇒≠⋅=++)0(221n n n n a a a a {}n a 为等比数列；③通项公式法：⇒⋅=为常数）q k q k a nn ,({}n a 为等比数列； ④前n 项和法：⇒-=为常数）（q k q k S nn ,)1({}n a 为等比数列．性质运用1．103107422222)(++++++=n n f 设()()()n N f n *∈，则等于1342222(81)(81)(81)(81)7777n n n n A B C D +++----．．．．D2．已知数列{}n a 是等比数列，且===m m m S S S 323010，则，．3．⑴在等比数列{}n a 中，143613233+>==+n n a a a a a a ，，． ①求n a ，②若n n n T a a a T 求,lg lg lg 21+++= ．⑵在等比数列{}n a 中，若015=a ，则有等式n n a a a a a a -+++=+++292121)29(*∈<N n n ，成立，类比上述性质，相应的在等比数列{}n b 中，若119=b ，则有等式成立．解：⑴①由等比数列的性质可知：16341616163233321a a a a a a a a a a ⋅=⋅=+=>==又，解得，②由等比数列的性质可知，{}n a lg 是等差数列，因为⑵由题设可知，如果0=m a 在等差数列中有n m n a a a a a a --+++=+++122121)12(*∈-<N n m n ，成立，我们知道，如果q p n m a a a a q p n m +=++=+，则若，而对于等比数列{}n b ，则有q p n m a a a a q p n m ⋅=⋅+=+，则若所以可以得出结论，若n m n m b b b b b b b --==1221211 ，则有)12(*∈-<N n m n ，成立，在本题中 n n b b b b b b -=372121 则有)37(*∈<N n n ，1．{a n }是等比数列，下面四个命题中真命题的个数为 ( ) ①{a n 2}也是等比数列；②{ca n }(c ≠0)也是等比数列；③{na 1}也是等比数列；④{ln a n }也是等比数列． A ．4 B ．3C ．2D ．12．等比数列{a n }中，已知a 9 =－2，则此数列前17项之积为 ( ) A ．216 B ．－216 C ．217 D ．－2173．等比数列｛a n ｝中，a 3=7，前3项之和S 3=21，则公比q 的值为 ( )A ．1B ．－21 C ．1或－1 D ．－1或214．在等比数列{a n }中，如果a 6=6，a 9=9，那么a 3等于 ( )A ．4B ．23 C ．916 D ．25．若两数的等差中项为6，等比中项为5，则以这两数为两根的一元二次方程为 ( )A ．x 2－6x ＋25=0B ．x 2＋12x ＋25=0C ．x 2＋6x －25=0D ．x 2－12x ＋25=06．某工厂去年总产a ，计划今后5年内每一年比上一年增长10%，这5年的最后一年该厂的总产值是 ( )A ．1.1 4 aB ．1.1 5 aC ．1.1 6 aD ．(1＋1.1 5)a7．等比数列{a n }中，a 9＋a 10=a (a ≠0)，a 19＋a 20=b ，则a 99＋a 100等于 ( ) A ．89abB ．(ab )9C ．910abD ．(ab )108．已知各项为正的等比数列的前5项之和为3，前15项之和为39，则该数列的前10项之和为( )A ．32B ．313C ．12D ．159．某厂2001年12月份产值计划为当年1月份产值的n 倍，则该厂2001年度产值的月平均增长率为 ( ) A ．11n B ．11n C ．112-n D ．111-n10．已知等比数列{}n a 中，公比2q =，且30123302a a a a ⋅⋅⋅⋅=，那么36930a a a a ⋅⋅⋅⋅等于 ( )A ．102 B ．202 C ．162 D ．15211．等比数列的前n 项和S n =k ·3n ＋1，则k 的值为 ( )A ．全体实数B ．－1C ．1D ．312．某地每年消耗木材约20万3m ，每3m 价240元，为了减少木材消耗，决定按%t 征收木材税，这样每年的木材消耗量减少t 25万3m ，为了既减少木材消耗又保证税金收入每年不少于90万元，则t 的范围是 ( )A ．[1，3]B ．[2，4]C ．[3，5]D ．[4，6]一、选择题： BDCAD BACDB BC13．在等比数列{a n }中，已知a 1=23，a 4=12，则q =_____ ____，a n =____ ____．14．在等比数列{a n }中，a n ＞0，且a n ＋2=a n ＋a n ＋1，则该数列的公比q =___ ___．15．在等比数列｛a n ｝中，已知a 4a 7＝－512，a 3＋a 8＝124，且公比为整数，求a 10＝．16．数列｛n a ｝中，31=a 且n a a n n (21=+是正整数)，则数列的通项公式=n a ．二、填空题：13.2， 3·2n －2． 14.251+．15.512 ．16.123-n ． 17．已知数列满足a 1=1，a n ＋1=2a n ＋1 (n ∈N *)．(1)求证数列{a n ＋1}是等比数列；(2)求{a n }的通项公式． (1)证明由a n ＋1=2a n ＋1得a n ＋1＋1=2(a n ＋1)又a n ＋1≠0 ∴111+++n n a a =2即{a n ＋1}为等比数列．(2)解析：由(1)知a n ＋1=(a 1＋1)q n－1即a n =(a 1＋1)q n －1－1=2·2n －1－1=2n －118．在等比数列｛a n ｝中，已知对n ∈N *，a 1＋a 2＋…＋a n ＝2n －1，求a 12＋a 22＋…＋a n 2．解析：由a 1＋a 2＋…＋a n ＝2n －1 ① n ∈N *，知a 1＝1且a 1＋a 2＋…＋a n －1＝2n －1－1 ②由①－②得a n ＝2n －1，n ≥2 又a 1＝1，∴a n ＝2n －1，n ∈N *212221)2()2(-+=n n nn a a ＝4 即｛a n 2｝为公比为4的等比数列 ∴a 12＋a 22＋…＋a n 2＝)14(3141)41(21-=--nn a 19．在等比数列｛a n ｝中，已知S n ＝48，S 2n ＝60，求S 3n ．解析一： ∵S 2n ≠2S n ，∴q ≠1 根据已知条件121(1)481(1)601n na q qa q q ⎧-=⎪-⎪⎨-=⎪⎪-⎩①②②÷①得：1＋q n ＝45即q n ＝41 ③ ③代入①得q a -11＝64 ④解析二：∵｛a n｝为等比数列∴(S2n－S n)2＝S n(S3n－S2n)20．求和：S n＝1＋3x＋5x2＋7x3＋…＋(2n－1)x n－1 (x≠0)．解析：当x=1时，S n=1＋3＋5＋…＋(2n－1)=n2当x≠1时，∵S n=1＋3x＋5x2＋7x3＋…＋(2n－1)x n－1，①等式两边同乘以x得：xS n=x＋3x2＋5x3＋7x4＋…＋(2n－1)x n．②21．在等比数列｛a n｝中，a1＋a n=66，a2·a n－1=128，且前n项和S n=126，求n及公比q．解析：∵a1a n=a2a n－1=128，又a1＋a n=66，∴a1、a n是方程x2－66x＋128=0的两根，解方程得x1=2，x2=64，∴a1=2，a n=64或a1=64，a n=2，显然q≠1．22．某城市1990年底人口为50万，人均住房面积为16 m2，如果该市每年人口平均增长率为1%，每年平均新增住房面积为30万m2，求2000年底该市人均住房的面积数．(已知1.015≈1.05，精确到0.01 m2)解析：依题意，每年年底的人口数组成一个等比数列{a n}：a1=50，q=1＋1%=1．01，n=11 则a11=50×1．0110=50×(1．015)2≈55.125(万)，又每年年底的住房面积数组成一个等差数列{b n}：b1=16×50=800，d=30，n=11∴b11=800＋10×30=1100(万米2)因此2000年底人均住房面积为：1100÷55.125≈19．95(m2)。

新课标人教版高中数学必修5综合检测试题

人教版高中数学必修5 综合检测试题一选做题:1．如果33log log 4m n +=，那么n m +的最小值是（）A ．4B ．34C ．9D ．182、数列{}n a 的通项为n a =12-n ，*N n ∈，其前n 项和为n S ，则使n S >48成立的n 的最小值为（）A ．7B ．8C ．9D ．103、若不等式897x +<和不等式022>-+bx ax 的解集相同，则a 、b 的值为（） A ．a =﹣8 b =﹣10 B ．a =﹣4 b =﹣9 C ．a =﹣1 b =9D ．a =﹣1 b =24、△ABC 中，若2cos c a B =，则△ABC 的形状为（）A ．直角三角形B ．等腰三角形C ．等边三角形D ．锐角三角形5、在首项为21，公比为12的等比数列中，最接近1的项是（） A ．第三项 B ．第四项 C ．第五项 D ．第六项6、在等比数列{}n a 中，117a a ⋅=6，144a a +=5，则1020a a 等于（） A ．32 B ．23C ．23或32D ．﹣32或﹣237、△ABC 中，已知()()a b c b c a bc +++-=，则A 的度数等于（） A ．120B ．60C ．150D ．308、数列{}n a 中，1a =15，2331-=+n n a a （*N n ∈），则该数列中相邻两项的乘积是负数的是（）A ．2221a aB ．2322a aC ．2423a aD ．2524a a9、某厂去年的产值记为1，计划在今后五年内每年的产值比上年增长10%，则从今年起到第五年，这个厂的总产值为（）A ．41.1 B ．51.1 C ．610(1.11)⨯- D ． 511(1.11)⨯-10、已知钝角△ABC 的最长边为2，其余两边的长为a 、b ，则集合{}b y a x y x P ===,|),(所表示的平面图形面积等于（）A ．2B ．2-πC ．4D ．24-π二填空题:11、在△ABC 中，已知BC=12，A=60°，B=45°，则AC=12．函数2lg(12)y x x =+-的定义域是13．数列{}n a 的前n 项和*23()n n s a n N =-∈，则5a =14、设变量x 、y 满足约束条件⎪⎩⎪⎨⎧≥+-≥-≤-1122y x y x y x ，则y x z 32+=的最大值为15、《莱因德纸草书》(Rhind Papyrus)是世界上最古老的数学著作之一。

【高中英语基础过关】必修5 U3 Life in the future 人教版英语基础练习题

B5U3 Life in the future满分：120分得分：__________第一步：单词拼写（根据汉语提示，写出该单词的正确形式。

每小题1分，满分20分）1. Things take on a new__________ (方面). (万象更新)2. They walked out of the thick forest with the help of a local __________ (向导).3. The foreign coach has special knowledge and __________ (专门技术).4. It costs £45.50 including __________ (运费).5. He asked several hard questions at the __________ (新闻) conference.6. We can drive a car forwards or backwards, but not __________ (向侧面).7. Hard work can often make up for a __________ (缺乏) of intelligence. (勤能补拙)8. There was a __________ (闪光) of lightning a moment ago.9. Cut the wire and attach its free ends to a __________ (开关).10. The railway __________ (时刻表) shows the times when the trains arrive and depart.11. We are __________ (乐观的) about the future of Sino-US relations.12. Don't be so __________ (悲观的). Don’t always look at the dark side of things.13. New cities grow up in the __________ (沙漠).14. We need our schools to teach students to be good __________ (公民).15. You will need to know the full address and __________ (邮编) for your hotel.16. Press this __________ (按钮) to start the engine.17. The __________ (瞬间) I saw him, I knew he was the man from the restaurant.18. He is on the wing gathering __________ (原料) for his novels.19. The address of the __________ (制造) is usually provided.20. All the __________ (商品) in the supermarket are clearly priced.（以上习题，填了空格就是完整的句子，填，念，用。

人教版高中英语必修五Unit4Makingthenews单元练习

高中英语人教新课标必修5Unit4 Making the news单元练习一、听力(听力)（共20小题；共20分）听力理解（共两节，满分30分）第一节（共5小题；每小题1.5分，满分7.5分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. What is the man?A. A student.B. A pianist.C. A teacher.2. What happened to Amanda?A. She failed to go to the beach.B. She was caught in a fire.C. She got sunburn.3. Where does the conversation probably take place?A. In a hospital.B. In the woman's house.C. In the woman's office.4. What is the man doing?A. Signing for a box.B. Collecting the woman's information.C. Filling out a form (填表).5. What will the man do tomorrow?A. Meet the manager.B. Look for a new job.C. Introduce a job to the woman.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项中选出最佳选项，并标在试卷的相应位置。

听完每段对话或独白前，你将有时间阅读各个小题，每小题5秒钟；听完后，各小题将给出5秒钟的做答时间。

2019秋高二年级英语新人教版必修5练习：Unit4《Makingthenews》课时训练Ⅰ(含答案

Unit 4 Making the news课时训练I基础夯实I •单词拼写1. Although he is an a _ chess player,David' s skills are no worse tha n a professi on al ' s.答案：amateur2. There is only one day before the d _ so you really should make full use of your time.答案：deadli ne3. We now face a d _ : Should we stay or go?答案：dilemma4.1 often feel g __ about not being able to look after my parents.5.Ann has mastered English grammar and a __ a large vocabulary without the help of a teacher. 答案：acquired6.1' m ___ (怀疑的)about the team ' s chanee of winning.答案：sceptical7. We must __ (更新)our information sources constantly in today ' s society.8. The discussion is just meant to _ (评估)the strengths and weaknesses of other players.9. He is one of my p friends in the school.答案：pers onal10. The tall man was a of killing the millionaire.答案：accusedH .用括号内所给单词的适当形式填空2.1 am ___ (delight) to find that most of the students can speak English fluently now.答案：delighted3. To our surprise,the result of the event is quite ______ (usual) compared with similar ones in the past.答案：unu sual4. If you thi nk you have a medical problem,seek __ (professi on) help from your family doctor.答案：professi onal5. Catherine is a talented musician as well as a __ (photograph).答案：photographer6. Lucy couldn' t attend the meeting so her ___ (assist) took her place.答案：assista nt7. He shook his head slowly and __ (deliberate).答案：deliberately8. If Mr.Dewey had been present,he would have offered any possible ______ (assist) to the people there.答案：assista nee9. Please send us all the __ (inform) that you have about the can didate for the positi on.答案：n formati on10. The police __ (accuse) him of robbing and put him into prison.答案:~ ccused川•翻译句子1. 你能把收音机音量关小点儿吗？我不能集中注意力做功课。

(完整word版)高中数学人教版必修5课后习题答案[电子档]

高中数学必修 5 课后习题答案[ 人教版]高中数学必修5 课后习题答案第1页共34 页2.1 数列的概念与简单表示法练习（P31）2、前5项分别是：1,0, 1,0, 1.I*(n 2m,m N )3、例 1(1)a n n1 *(n 2m 1,m N )说明：此题是通项公式不唯一的题目, 能的通项公式表达形式不唯一的例子.习题2.1 A 组(P33)1、 ( 1)2,3,5,7,11,13,17,19;(2) 2, .6,2、2,3, .10,2 •.3, . 14, . 15,4,3、2 ;(3) 1,1.7,1.73,1.732，…1.732050; 2,1.8,1.74,1.733，…,1.732051.1111 2、 (1) 1,1,1,1,1 ；(2) 2, 5,10, 17,26.4 9 16 253、 (1) (1), 4, 9, ( 16 ), 25, ( 36) , 49;a . ( 1)n 1 n 2 ;(2) 1,运,U3 ), 2, , U6 ),万; a n 蘇.4、 (1) ^,3,13,53,213 ;(2) 丄,5,4,丄,5.24545、对应的答案分别是:(1) 16,21; a n 5n 4 ; (2) 10,13;可 3n 2 (3) 24,35; a . n 26、 15,21,28;a n a . 1 n .习题2.1 B 组(P34)1、前 5 项是 1,9,73,585,4681.第二章数列(2) a n2(n 2m,m N *)*0(n 2m 1,m N )鼓励学生14'(1)an丹 Z)；⑵a n£(n(3) a nL (n2n .a 3 10 (1 0.72 罚3 10.217559 ;2 3 5 8 13厶， 55 52 3 5 82.2 等差数列练习（P39）1、表格第一行依次应填：0.5，15.5，3.75；表格第二行依次应填：15， 11， 24.2、 a n 15 2（n 1） 2n 13， a 10 33.3、c n 4n4、（ 1）是，首项是a m 1a 1md ，公差不变，仍为d ；（2）是，首项是耳，公差2d ；（3）仍然是等差数列；首项是a 7色6d ;公差为7d . 5、（ 1）因为a 5 a 3 a 7a 5，所以2a 5a 3 a 7.同理有2a 5aa 9也成立；（2）2a n a . 1 a . 1（n 1）成立；2a . a n k a . k （n k 0）也成立.习题2.2 A 组（P40）1、( 1) a n 29 ； (2)n 10 ； (3) d 3 ； (4) a ! 10. 2、略. 3、60 .4、2C ；11C ； 37 C .5、( 1) s 9.8t ；(2) 588 cm ， 5 s习题2.2 B 组（P40）1、（ 1）从表中的数据看，基本上是一个等差数列，公差约为2000，a 2010 a 2002 8 d 0.26 105再加上原有的沙化面积9 105，答案为9.26 105 ；（2） 2021年底，沙化面积开始小于8 105 hm 2. 2、略.该数列的递推公式是： 8“ 1a n 1 1 8a n ,印1.通项公式是：a n a 2 10 (1 0.72 罚2 10.144518;2、a 110 (1 0.72 罚 10.072 ; a n 10 (1 0.72 罚n .3、(1) 123,5,8;(2)2.3 等差数列的前n 项和1、(1) 88 ；59,n 2、a n126n !练习（P45） (2) 604.5.1125,n 13、元素个数是30,元素和为900.习题2.3 A 组（P46） 1、（ 1） n(n 1）；（2）n （3）180 个，和为 98550；（4）900个，和为 494550.2、（ 1） 20,a n 54,S n999代入 S n n(a1 an) 并解得 27 ； 20,a n 54,n 27代入a n d (n 1)d 并解得(2)1 —,n 3 37,S n 629代入a n 印 (n 1)d S n n(a 1 17 13 . a n )a 1a n 得 37(a ,212 a n );解这个方程组，得 629a 1 11,a n 23. (3) 将a 1 将a t5,d6 5訐i ,Sn 1 6，n5代入S n 15代入a na 1 (n (4)2,n15,a n10代入a n(n 将a 138,a n 10, n 15 代入 S n43、4.55 1 04m.4、4.n （n 1）d ，并解得1)d 1)d n(an 15 ；得a n并解得 an)，得S n25、这些数的通项公式：7（n 1） 2，项数是14,和为665. 习题2.3 B 组（P46）1、 ................................ 每个月的维修费实际上是呈等 ................. 共的维修费，即再加上购买费，除以天数即可 .2、本题的解法有很多，可以直接代入公式化简, 现提供2个证明方法供参考.38；360.6、1472.等差数列的.代入等差数列前答案：292元. 但是这种比较繁琐 n 项和公式，求出 5年内的总(1)由 S 6 6a t 15d ， S 2 12a t 66d ，S 18 1可得S (S 18S12) 2(S 2 S 6). ⑵S 12 （印a 2 L a 12) (a 1 a 2 La 6)a 7 a 8 La12（印6d) (a 2 6d) L 包6d)（印a 2 La 6) 36d153dS 6 36d同样可得：S 18$2 S 6 72d ，因此 S 6 (S i8 02)2(S 2 閒•3、( 1)首先求出最后一辆车出发的时间 4时20分；所以到下午6时，最后一辆车行驶了 1小时40分.(2)先求出15辆车总共的行驶时间，第一辆车共行驶 4小时，以后车辆行驶时间依次递减，最后一辆行驶1小时40分.各辆车的行驶时间呈等差数列分布，代入前n 项和公式，这乘以车速60 km/h ，得行驶总路程为2550 km.4、数列1 的通项公式为 a n 1 1 1 n(n n(n 1) n n 11)所以S n(11111 -)( )(-1) .1 1 .. 1 n L() 1-1 22 3 3 4n n 1n 1 n 1类似地，我们可以求出通项公式为 a n11 (11)的数列的前n 项和n(n k) k n n k2.4 等比数列练习(P52)2、由题意可知，每一轮被感染的计算机台数构成一个首项为印80，公比为q 20的等比数列，则第5轮被感染的计算机台数a 5为a 5 a ,q 4 80 204 1.28 107.3、 ( 1)将数列a n 中的前k 项去掉，剩余的数列为3「忌2丄.令b a —i 1,2丄，则数列 a k 1,a k 2,L 可视为 ddL .因为Lq(i > 1)，所以，b n 是等比数列，即丄是等比数列.b ia k i(2) a n 中的所有奇数列是a !,a 3,a 5,L ，则邑邑LL q 2(k > 1).a1a3a2k 1所以，数列q,a 3，a 5，L 是以耳为首项，q 2为公比的等比数列.个车队所有车的行驶时间为121585h.(3)a n中每隔10项取出一项组成的数列是a1,a12，a23丄，则空屯L电！L q11(k > 1)a i a12a11k 10所以，数列Q,a12,a23丄是以3为首项，q11为公比的等比数列.猜想：在数列a n中每隔m ( m是一个正整数)取出一项，组成一个新的数列，这个数列是以a1为首项，q m1为公比的等比数列.4、( 1)设a n 的公比为q，则a；(aq4)2a：q8，而a3 a? aq2ag6 a：q8所以a；a3 a?,同理a f 印a?(2)用上面的方法不难证明a2 a n 1 a n,n 1).由此得出，a.是a n 1和a n 1的等比中项• 同理：可证明，a：a n k a. k(n k 0).由此得出，a.是a. k和a. k的等比中项(n k 0).5、( 1)设n年后这辆车的价值为a.，则a. 13.5(1 10型.(2) a413.5(1 10写488573 (元).用满4年后卖掉这辆车，能得到约88573元.习题2.4 A 组(P53)2高中数学必修5课后习题答案［人教版］4，解得61、(1)可由 a 4a/，得a 11， a 7a 1q 6 ( 1) (3)6 729. 也可由a 76a 1q， a4a 1q，得a73a 4q27 3)3729⑵由ae 3ae188，解得8 27 2 327 2 3还可由a 5,a 7,a 9也成等比数列，即a 5a 9，得 a 92a7a57 9.(4)由4ag 3aga 15L L ① a 1q 6L L ②(3)由4 ae 6ae高中数学必修5课后习题答案［人教版］①的两边分别除以②的两边，得-，由此解得q -或q 2.q 22当 q -时，d 16.此时 a 3 a^q 24.当 q 2 时，a 1.此时 a 3 a^2 4.2、设n 年后，需退耕a n ，贝V a n 是一个等比数列，其中d 8(1 10罚,q 0.1. 那么2005年需退耕a 5 a(1 q)5 8(1 10写5 13 (万公顷)3、若a n 是各项均为正数的等比数列，则首项印和公比q 都是正数.n 11由 a n aq n 1，得..a ?..町.可 2,a ?(q 2)(n 1).1那么数列a n 是以、..乳为首项，q 2为公比的等比数列.4、这张报纸的厚度为0.05 mm ,对折一次后厚度为0.05X 2 mm ,再对折后厚度为0.05X 22 mm ，再对折后厚度为0.05X 23 mm.设a 。

高中数学必修5课后习题答案(共10篇)

高中数学必修5课后习题答案(共10篇)高中数学必修5课后习题答案（一）: 人教版高一数学必修5课后习题答案课本必修5,P91练习2,P93习题A组3和B组3,全部都是线性规划问题, 生产甲乙两种适销产品，每件销售收入分别为3000元，2023元。

甲乙产品都需要A、B两种设备上加工，每台A、B设备上加工1件甲设备工时分别为1h，2h，加工乙设备工时2h,1h，A、B两种设备每月有效使用台时数分别为400h和500h，如何安排生产可使收入最大？2.电视台应某企业之约播放两套电视剧，其中，连续剧甲每次播放时间为80分钟，其中广告时间为1分钟，收视观众为60万；连续剧乙每次播放时间为40分钟，广告时间1分钟，收视观众20万。

已知和电视台协议，要求电视台每周至少播放6分钟广告，二电视台每周只能为该企业提供不多于320分钟的节目时间。

如果你是电视台制片人，电视台每周应播映两套连续剧各多少次，才能获得更高的收视率？P91练习 2 答案：解设每月生产甲商品x件,生产乙商品y件,每月收入z元,目标函数z=3X+2y,需要满足的条件是：x+2y≤400 2X+y≤500 x≥0 y≥0作图略作直线z=3x+2y,当直线经过A点时,z 取最大值解方程组{x+2y=400 2x+y=500 可取点A 《200,100》所以z的最大值为800高中数学必修5课后习题答案（二）: 高一人教版数学必修5课后习题答案知道下列各项·写出同项公式1,√2/2,1/2,√2/4 1/4关于数列问题1,√2/2=1*√2/2,1/2=1*（√2/2）^2,√2/4=1*(√2/2)^31/4=1*(√2/2)^4……所以是以首项为1,公比为√2/2的等比数列An=(√2/2)^（n-1）高中数学必修5课后习题答案（三）: 高中数学必修5课后习题1.1A组第一第二题答案要有步骤解三角形A=70° B=30° c=20cm b=26cm c=15cm C=23° a=15cm，b=10cm，A=60° b=40cm，c=20cm，C=25°1.180°--70° --30° =80°所以角C=80°然后用正弦定理2.还是正弦定理3.还是正弦定理4.还是正弦定理很简单的正弦定理a比上sinA=b比上sinB=c比上sinCa是边长,A是角高中数学必修5课后习题答案（四）: 数学必修五课后习题答案数学必修五第五页（也可能是第四页）课后习题答案,要有解题过程,大神们呐,帮帮我吧参考书里没有解题过程!2在三角形ABC中，已知下列条件，解三角形(1)a=20cm,b=11cm,B=30°(2)c=54cm,b=39cm,C=115°画图题2个题做法基本一样比如第1小题,先根据已知角度画出已知角B,然后以角点B为圆心,以20为半径画圆弧,和B的某一线相交一点C,再以该点为圆心,以11cm为半径画圆弧,和B角的另一角边相交,这样得到A点,到此,三角形就画好了.高中数学必修5课后习题答案（五）: 数学必修5练习x^2-(2m+1)x+m^2+m分析x -(2m+1)x+m +m高中数学必修5课后习题答案（六）: 高一数学必修5解三角形正弦定理课后练习B组第一题(1) a=2RsinA,b=2RsinB,c=2RsinC; (2) sinA :sinB :sinC = a :b :c;高中数学必修5课后习题答案（七）: 高二数学必修5答案,人民教育出版社的,习题2—3A的练习题,P51页,急用,我的同学瞧不起我,我非要做个全对不可,可我数学一点都不好,我不想就这样被同学踩在脚底下,希望谁有答案,帮忙写一下,拜托了,我先拿30分,不够的话,再说.看看这个,参考参考.高中数学必修5课后习题答案（八）: 高中数学必修5第三章不等式复习参考题答案【高中数学必修5课后习题答案】有本书叫《中学教材全解》,是陕西出版社的金星教育那上面有详细的解答准确度很高同时发几个网址,看有没有你需要的高中数学必修5复习题及答案（A组）人教版高中数学必修模块（1-5）全部精品课件集高中数学必修5课后习题答案（九）: 高一数学作业本必修5的题目..11.(1)已知x＞0,y>0．且(1/x)+(9/y)=1.求x+y的最大值．（2）已知x【高中数学必修5课后习题答案】11.(1) (1/x+1/y)*(x+y)=1+9+9x/y+y/x=10+9x/y+y/x9x/y+y/x>=2√9x/y*y/x1/x+9/y>=16(2)y=4x-5+1/(4x-5)+3>=2√(4x-5)*1/(4x-5）+3>=5(3)跟第一题是一样的,就是除以xy,答案是18高中数学必修5课后习题答案（十）: 人教版数学必修5习题2.2B组1答案求高中数学必修5的40页B组第一题的答案.（1）从表看出,基本是一个等差数列,d=2023,a2023=a2023+8d=0.26x10^5,在加上原有的9x10^5,答案为：9.26x10^5.(2)2023年底,小于8x10^5hm略。

高中数学人教版必修5课时练习：第二章数列2-3 等差数列的前n项和

＝－1，所以当 n＝20 时 Sn 最大．故选 B．
3.3×1 5＋5×1 7＋7×1 9＋…＋13×1 15＝(
)
A．145
B．125
C．1145
D．175
[答案] B
[解析] 原式＝12(31－15)＋12(51－17)＋…＋12(113－115)＝12(13－115)＝125，故选 B．
4．已知等差数列{an}的前 n 项和为 Sn，a5＝5，S5＝15，则数列{ana1n＋1}的前 100 项和为(
∴数列{Snn}是等差数列，其首项为－2，公差为21，
∴Tn＝14n2－94n.
第 2 课时
一、选择题
1．记等差数列{an}的前 n 项和为 Sn.若 d＝3，S4＝20，则 S6＝( )
A．16
B．24
C．36
D．48
[答案] D
[解析] 由 S4＝20,4a1＋6d＝20，解得 a1＝12⇒S6＝6a1＋6×2 5×3＝48.
7．设 Sn 是等差数列{an}(n∈N*)的前 n 项和，且 a1＝1，a4＝7，则 S5＝________. [答案] 25
[解析]
由a1＝1 得a1＝1 ， a4＝7 d＝2
∴S5＝5a1＋5×2 4×d＝25.
8．(2014·北京理，12)若等差数列{an}满足 a7＋a8＋a9>0，a7＋a10<0，则当 n＝________
高中数学人教版必修 5 课时练习第二章 2.3 等差数列的前 n 项和
一、选择题
1．设 Sn 为等差数列{an}的前 n 项和，S8＝4a3，a7＝－2，则 a9＝( )
A．－6
B．－4
C．－2
D．2
[答案] A

【高中英语基础过关】必修5 U1 Great scientists 人教版英语基础练习题(

B5U1A Great scientists满分：120分得分：__________第一步：单词拼写（根据汉语提示，写出该单词的正确形式。

每小题1分，满分20分）1. The _________ (特征) I like best in him is his cheerfulness.2. There is still no __________ (疗法) for AIDS.3. The area was struck by an __________ (爆发) of cholera.4. Two __________ (嫌疑犯) were arrested today in connection with the robbery.5. Many charities sent money to help the __________ (受害者) of the earthquake.6. Thank you for your __________ (询问) about my health.7. The story that he has adopted a son is being whispered about the __________ (邻里).8. No __________ (线索) to his whereabouts has been found until now.9. The __________ (水泵) doesn’t work and we have no running water.10. She seemed to be placing most of the __________ (责备) on her mother for the serious mistake.11. I turned the __________ (把手) and found the door was open.12. Her parents were still __________ (负责的) for her because she was under age.13. The __________ (图标) hanging on the wall shows an uptrend of meat prices this year.14. Li Hua is a sunny boy and he has a __________ (肯定的) attitude towards life.15. If there is to be revolution, there must be a __________ (革命的) army.16. Because of his long illness, he is __________ (后退的) in his studies.17. If we take a wheel, and__________ (旋转) it in empty space, it will go the same way forever.18. I am an __________ (热情的) supporter of the project, and my wife and I contribute to it annually.19. We all look forward to the day when the scientists can discover more secrets of the __________ (宇宙).20. He was doing his best to be __________ (合作的) with you.第二步：单句语法填空（在空白处填入一个适当的单词或括号内单词的正确形式；每小题1分，满分20分）1. When the investigation __________ (conclude), the results will be sent to the US Attorney’s office.2. The cause and effect of this event should __________ (analyze) carefully to make it known to the public.3. Eggs known to __________ (infect) with salmonella (沙门氏菌) were allowed to go on sale.4. They hoped to win the match but actually they __________ (defeat) by 3 goals to 2 in the game.5. I am the first child in my family __________ (attend) college.6. No one wants __________ (expose) themselves and lay their innermost feelings bare.7. You should keep it in mind that diet __________ (cure) more than the doctor.8. This kind of writing usually requires careful reading and thinking and __________ (challenge) the mind to work at a higher level.9. The clever boy __________ (absorb) all the knowledge that his teachers could give him.10. The naughty student __________ (suspect) of telling a lie last week.11. Listen! The pump __________ (pump) water from the well.12. It is hard __________ (foresee) what will happen in the next minute. Just wait and see.13. The FBI has been called in __________ (investigate) the question.14. Who is __________ (blame) for the accident?15. The __________ (pollute) river is getting cleaner and you can find some fish in it.16. Meat, improperly __________ (handle), is a dangerous carrier of bacteria.17. Great attention must be paid to __________ (link) theory with practice.18. There are plans __________ (construct) a new road bridge across the river.19. You give shares to someone who is __________ (contribute) to the enterprise.20. The candidate got a high score but he __________ (reject) by the famous university.（以上习题，填了空格就是完整的句子，填，念，用。

2021人教版高中英语必修五Unit1Greatscientistsword单元练习

Unit1 Great scientists单元练习一、听力(听力)（共20小题；共20分）第一节（共5 小题；每小题1.5 分，满分7.5 分）听下面5段对话。

每段对话后有一个小题，从题中所给的A、B、C三个选项当选出最佳选项。

听完每段对话后，你都有10秒钟的时间来回答有关小题和阅读下一小题。

每段对话仅读一遍。

1. Where does the conversation probably take place?A. At a restaurant.B. At the doctor's.C. In a coffee shop.2. What time is it now?A. 9:15 p.m.B. 9:30 p.m.C. 9:45 p.m.3. Why can't the woman meet the man this evening?A. The man will visit his friend.B. She will go to visit her friend.C. Her friend will come to see her.4. What does Billy mean?A. His brother never forgets his own birthday.B. His brother will give him a birthday present.C. His brother is coming to celebrate his birthday.5. What does the woman suggest the man do?A. Order a new book.B. Read another book.C. Search the shelf again.第二节（共15小题；每小题1.5分，满分22.5分）听下面5段对话或独白。

每段对话或独白后有几个小题，从题中所给的A、B、C三个选项当选出最佳选项。

人教版高中英语必修五Unit3 Life in the future单元练习.docx

高中英语学习材料***鼎尚图文理制作***Unit3 Life in the future单元练习一、听力(听力)（共20小题；共20分）Listening Comprehension (30 marks)Section A (22.5 marks) Directions: In this section, you will hear six conversations between two speakers. For each conversation, there are several questions and each question is followed by three choices marked A, B and C. Listen carefully and then choose the best answer for each question.You will hear each conversation TWICE.Conversation 11. What did the man buy yesterday?A. A shirt.B. Some shoes.C. Some pants.2. Where does the man work?A. At a post office.B. At a clothing store.C. At a bank.Conversation 23. Who will take the woman to work this week?A. Matt.B. The man.C. She will drive herself.4. What kind of car does Matt have now?A. A BMW.B. An Audi.C. A Mercedes-Benz.Conversation 35. What time was the man's appointment?A. 11:15.B. 11:30.C. 12:00.6. What happened earlier this morning?A. The doctor was late.B. The power went out.C. The Internet had some problems.Conversation 47. How long will it take to get to Paris?A. An hour.B. An hour and ten minutes.C. Two hours.8. How will the man get to the city center in Paris?A. By bus.B. By car.C. By air.9. How much will the man pay for the tickets?A. 60 pounds.B. 100 pounds.C. 300 pounds.Conversation 510. Which apartment do the speakers give up first?A. The one on 68th Street.B. The one on 72nd Street.C. The one on 80th Street.11. What does the woman think of the apartment on 80th Street?A. It has a better view.B. It has good parking.C. It has much space.12. What do the speakers agree to do in the end?A. Buy a new sofa.B. Put the desk in the living room.C. Buy the apartment on 72nd Street.Conversation 613. What is not necessary for working at home?A. A printer.B. A TV set.C. A phone.14. What will happen in the future?A. People won't have to work at all.B. People can cook dinner with their computers.C. People can work at home for companies in different countries.15. How does the woman feel about technology?A. Confident.B. Worried.C. Disappointed.Section B (7.5 marks) Directions: In this section, you will hear a short passage. Listen carefully and then Jill in the numbered blanks with the information you have heard. Fill in each blank with NO MORE THAN THREE WORDS. You will hear the short passage TWICE.News item 1 At least 16. people died in a serious accident on theM6 motorway in Lancashire early this morning.News item 2 Prime Minister and 17. have agreed to work togetherto find ways of combating inflation (抗击通货膨胀) andreducing the present level of unemployment in 18. .News item 3 A national bus strike will start on 19. .News item 4 Police in Manchester continue their 20. the murdererof 71-year-old Jane Simpkins.16.17.18.19.20.二、单词拼写(单句首字母填空)（共15小题；共15分）21. --- How do you like the new employee?--- His loyalty to the company has made a good i on me.22. Tom is a promising student. I'm sure that with his c effort, he will realize his dream.23. Along with the elapsing of year, this book will be more p .24. G by the kind-hearted old man, we had no difficulty in walking through the forest.25. He was not employed by the company because he l the qualifications for the post.26. Don't lose heart. You should be o , then everything will be all right.27. He spent a year on the d island and made a living on wild fruits.28. The strikers have reached a s with the employers.29. Dealing with people is one of the most important a of my work.30. The school can't t such bad behavior.31. We've had to make some a to our original calculations.32. We take all the old bottles to be r .33. If you drink some water, it will make the pills easier to s (吞咽).34. F your seat belts, please! The plane is going to take off.35. The g boy ate so many cakes that he fell ill.三、单词拼写(根据中文提示拼写单词)（共15小题；共15分）36. I regret that a p (先前的) engagement prevents me from accepting your kind invitation.37. We'll be travelling by camel with local (导游), camping in tents and sleeping on the ground in our thick sleeping bags.38. People in Germany put their garbage into different bags and then r (重新利用) it.39. We should be (乐观) and always keep a positive attitude towards life.40. Though he (缺乏) in experience he makes up for it in enthusiasm.41. The girl had a strong (动机) to learn crosstalk as a child, but soon he quitted his dream.42. Iris plays the piano very well. Her (不间断的) practice has helped her to win many prizes.43. They have planned a tight (日程安排表) of travel.44. Dear, put the pills in your mouth and (咽下) them.45. Knowing good manners will help make a good (印象).46. He made several (调整) to the plan.47. He is a (贪婪的) man. Nothing can stop his (贪婪) for money.48. You should consider other (方面) of the matter before making a decision.49. How can you (忍受) all that noise while you are working?50. He (系) the rope to the tree and went away.四、翻译(根据中文提示完成句子)（共10小题；共20分）51. 如果误服, 有些药物可以致命, 所以在服用药物的时候要小心。

2019学年高中语文人教版必修5习题：单元综合习题(第二单元)含答案

单元综合测评(第二单元)(时间：120分钟，分值：120分)一、基础巩固(18分，每小题3分)1．下列句子中，没有通假字的一项是( )A ．乃瞻衡宇云销雨霁B ．北冥有鱼汤之问棘也是已C ．非臣陨首所能上报沐浴清化D ．夙遭闵凶零丁孤苦【解析】 A 项，“销”通“消”。

B 项，“冥”通“溟”。

D 项，“闵”通“悯”，“零丁”通“伶仃”。

【答案】 C2．下列句子中，加点词的解释不正确的一项是( )A ．既自以心为形役．役：奴役 B ．都督阎公之雅．望雅：崇高 C ．而莫之夭阏．．者夭阏：阻塞 D ．臣具．表以闻具：准备【解析】 D 项，具：详尽。

【答案】 D3．下列各组句子中，加点词的意义和用法相同的一组是( )A.⎩⎪⎨⎪⎧公田之．利，足以为酒悟已往之．不谏 B.⎩⎪⎨⎪⎧襟三江而．带五湖控蛮荆而．引瓯越 C.⎩⎪⎨⎪⎧且．举世誉之而不加劝彼且．恶乎待哉 D.⎩⎪⎨⎪⎧急于．星火海运则将徙于．南冥【解析】 B 项，均为连词，表并列。

A 项，助词，“的”；助词，用于主谓之间，取消句子的独立性。

C 项，况且；还要。

D 项，介词“比”；介词，“到”。

【答案】 B4．下列句子中，加点词的意义与现代汉语相同的一项是( )A ．将有事．．于西畴 B ．阮籍猖狂．．C ．蟪蛄不知春秋．．D ．翱翔．．蓬蒿之间，此亦飞之至也【解析】 A 项：古义指耕种之事；今义指有事情。

B 项，古义指狂放、不拘礼法；今义指狂妄而放肆。

C项，古义指四季；今义指春天和秋天，历史上的一个时代。

【答案】 D5．下列各句中，加点词的用法分类正确的一项是( )①策．扶老以流憩②或棹．孤舟③雄州雾．列，俊采星．驰④而后乃今将图南．⑤则刘病日．笃⑥臣不胜犬马．．怖惧之情A．①②③/④⑤⑥B．①③④/②⑤⑥C．②④⑤/①③⑥D．①②④/③⑤⑥【解析】①策：名词作动词，拄着；②棹：名词作动词，用桨划；③雾、星：名词作状语，像雾一样，像星星一样；④南：名词作动词，向南飞；⑤日：名词作状语，一天天地；⑥犬马：名词作状语，像犬马一样。

高中语文人教版必修5习题：第2单元学业分层习题(六) 逍遥游含答案

学业分层测评(六) 逍遥游[基础巩固层]1．下列各句中都有通假字的一项是( )①小知不及大知②此小大之辩也③举世非之而不加沮④而御六气之辩⑤彼且奚适也⑥而征一国者⑦北冥有鱼⑧而莫之夭阏者A．①②⑥⑦B．②④⑤⑧C．①③⑤⑦D．③④⑥⑧【解析】③⑤⑧没有。

①“知”通“智”，②“辩”通“辨”，④“辩”通“变”，⑥“而”通“能”，⑦“冥”通“溟”。

【答案】 A2．下列各句中加点词语的解释，不．正确的一项是( )A．众人匹．之，不亦悲乎匹：比B．去．以六月息者也去：离开C．绝．云气，负青天绝：直上穿过D．而控．于地而已矣控：遥控【解析】D项，控：投，落下。

【答案】 D3．下列句中加点词的意义和用法，判断正确的一项是( )①虽．然，犹有未树也②此虽．免乎行，犹有所待者也③且．举世誉之而不加劝，举世非之而不加沮④彼且．恶乎待哉A．①②不同，③④不同。

B．①②不同，③④不同。

C．①②相同，③④不同。

D．①②相同，③④相同。

【解析】虽，都解释为“虽然”。

且，前者为“况且”，表递进；后者为“还”，助词。

【答案】 C4．下列各句中，没有词类活用现象的一项是( )A．水击三千里B．其视下也，亦若是则已矣C．而后乃今将图南D．举世非之而不加沮【解析】A项，水，在水面上，名词作状语；C项，南，向南飞，名词用作动词；D项，非，形容词的意动用法，以……为非。

【答案】 B5．与“《齐谐》者，志怪者也”句式相同的一项是( )A．而莫之夭阏者B．覆杯水于坳堂之上C．石之铿然有声者，所在皆是也D．野马也，尘埃也，生物之以息相吹也【解析】D项与题干均为判断句。

A项，宾语前置句；B项，状语后置句；C项，定语后置句。

【答案】 D[阅读提升层]阅读下面的文言文，完成6～9题。

昔赵文王喜剑，剑士夹门而客三千余人，日夜相击于前，死伤者岁百余人，好之不厌。

如是三年，国衰，诸侯谋之。

太子悝患之，募左右曰：“孰能说王之意止剑士者，赐之千金。

”左右曰：“庄子当能。