三桩承台计算书

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NL
=
1 3

FN
=
2250

kN
桩对承台冲切验算 = "满足GB50007-2011第8.5.19-2-2条" if NL ≤ min(NLc1 , NLc2)
"不满足GB50007-2011第8.5.19-2-2条,增加承台高" otherwise 桩对承台冲切验算 = "满足GB50007-2011第8.5.19-2-2条"
=
⎡⎢⎣1 −
0.5 ⋅ ⎛⎜⎝1 −
b01 b02
⎞⎟⎠⎤⎥⎦
⋅ b02 =
Leabharlann Baidu
1.69 m
承台截面的斜截面抗剪承载力: Vca = βhs ⋅ β ⋅ ft ⋅ b0 ⋅ h0 = 4260.418 ⋅ kN
承台截面 = "满足GB50007-2011第8.5.21条" if V ≤ Vca "不满足GB50007-2011第8.5.21条,增加承台高或提高混凝土强度 "
桩边距: c = 1D = 600 ⋅ mm
长桩距与短桩距之比
αc
=
S1 S2
=1
单桩承载力特征值: Ra = 1800kN 桩顶伸入承台内尺寸: cc = 50mm
柱截面尺寸: hc = 600mm
hb = 600mm
承台截面参数: 承台高:h = 1500mm
承台边夹角: α
=
1 3

π
初步假定分布筋直径:dv0 = 10mm
底桩内边至承台边线交点的距离: c1 = 0.5 ⋅ b01 ⋅ tan(α) = 1.247m
顶桩内边至承台边线交点的距 离:
c2
=
c
+
0.5a

tan⎛⎝
α⎞ 2⎠
tan⎛⎝
α 2
⎞ ⎠
= 1.279m
底桩内边至柱边的距离:
a11 = ax = 360 ⋅ mm
顶桩内边至柱边的距离:
a12 = ay ⋅ sin(α) = 432.346 ⋅ mm
三桩承台
CT − 3
一、计算方法及使用的国家规范:
以单桩承载力特征值为依据,反推上部荷载标准值及设计值 ,三桩等腰承台按受弯板带计算 抗
弯、抗剪承载力和正常使用阶段的 裂缝,裂缝按永久荷载作用计算。
设计中使用的国家规范:
《混凝土结构设计规范》(GB50010 − 2010)
《建筑地基基础设计规范》(GB50007 − 2011)
冲垮比: λ11 =
0.25
if
a11 h0

0.25 =
0.252
1
if
a11 h0

1
a11 h0
otherwise
λ12 =
0.25
if
a12 h0

0.25 =
0.303
1
if
a12 h0

1
a12 h0
otherwise
冲切系数:
α11
=
0.56 λ11 + 0.2
=
1.238
α12 =
0.56 λ12 + 0.2
otherwise
承台截面 = "满足GB50007-2011第8.5.21条"
3.冲切计算:
1)柱对承台的冲切计算:(按GB50007 − 2011中8.5.19条计算)
柱短边至桩内边的距离: ax = 0.5(S2 − hb − a) = 360 ⋅ mm
冲切锥体底部计算边长: a0x = min(ax , h0) = 0.36m
1
if
a0x h0

1
a0x h0
otherwise
λ0y =
0.25
if
a0y h0

0.25 =
0.35
1
if
a0y h0

1
a0y h0
otherwise
冲切系数:
α0x
=
0.84 λ0x + 0.2
=
1.858
α0y =
0.84 λ0y + 0.2
=
1.528
承台截面抗冲切承载力计算:
FLc = 2 ⋅ ⎡⎣α0x ⋅ (hb + a0x) + α0y ⋅ (hc + a0y)⎤⎦ ⋅ βhp ⋅ ft ⋅ h0 = 14659.581 ⋅ kN
最大弯矩设计值:
M=
1 3
FN 3

⎛⎜⎝S1

0.75hc 4 − αc
⎞⎟⎠
=
1155.144

kN

m
最大剪力设计值:
V=
1 3
FN
=
2250

kN
永久荷载作用最大弯矩标准值 :
Mqk
=
1 3
FNqk 3

⎛⎜⎝S1

0.75hc 4 − αc
⎞⎟⎠
=
721.965 ⋅
kN

m
2.承台截面的斜截面抗剪承载力
1.1 − 0.65 ⋅ ftk
otherwise
ρte ⋅ σsk
= 0.2
最外层受拉钢筋外边缘至混凝 土受拉区底边的距离:
cs = 20 ⋅ mm if cc + dv0 < 20 ⋅ mm
= 60 ⋅ mm
otherwise
65 ⋅ mm if cc + dv0 ≥ 65 ⋅ mm
cc + dv0 otherwise
=
1.114
承台截面抗冲切承载力计算:
底桩:
NLc1
=
α11 ⋅
(2 ⋅
c1
+
a11)

tan⎛⎝
α 2
⎞ ⎠

βhp ⋅
ft ⋅
h0
=
4319.41 ⋅
kN
顶桩:
NLc2
=
α12 ⋅
(2 ⋅
c2
+
a12)

tan⎛⎝
π 2

α⎞⎠
⋅ βhp ⋅ ft ⋅
h0 =
4070.056 ⋅ kN
桩平均净反力设计值:
ξ
=
x h0
= 0.038
相对界限受压区高度ζb按规范GB50010 − 2010式6.2.7 − 1计算
if(ξ < ξb , "满足要求" , "请重新计算") = "满足要求"
ξb = 0.518
5.配筋计算:
按规范GB50010 − 2010中式6.2.10 − 2和GB50007 − 2011中式8.2.12计算
a0y = min(ay , h0) = 0.499m
受冲切截面高度影响系数:βhp =
1 if h ≤ 800mm
0.9 if h ≥ 2000mm
0.9
+
(1

0.9)
2m 2m −
−h 0.8m
otherwise
= 0.942
冲垮比: λ0x =
0.25
if
a0x h0

0.25 =
0.252
混凝土弹性模量: 箍筋抗拉强度设计值: 计算参数 α1 = 1
钢筋混凝土保护层厚度: asv = 50mm
Ec = 31334 ⋅ N ⋅ mm− 2 fyv = 360 ⋅ N ⋅ mm− 2
β1 = 0.8 βc = 1
桩参数: 桩径: D = 600mm 腰桩中心间距: S1 = 1800mm 底桩中心间距: S2 = 1800mm
实配钢筋 8ϕ25 n = 8 d = 25mm
Asd
=

d2 4
=
3927 ⋅
mm2
ρsd
=
Asd ba ⋅ h
=
0.291 ⋅
%
底部实配钢筋 = "满足要求" if Asd ≥ max(As , Amin) = "满足要求"
"钢筋不足,重新选筋" otherwise
纵筋布置间距 =
"满足要求"
初步假定底部纵筋直径:ds0 = 25mm
承台计算高度: h0 = h − cc − dv0 − 0.5 ⋅ ds0 = 1427.5 ⋅ mm
3.荷载:
荷载综合分项系数: γk = 1.35 (荷载标准值计算用) γqk = 1.60 (荷载永久值计算用)
γ = 1.25 (荷载设计值计算用) 单桩承载力利用率: ρg = 1
if
ba − asv n− 1
≥ 100mm ∧
ba − asv n− 1
≤ 200mm
"不满足要求,重新选筋" otherwise
纵筋布置间距 = "满足要求"
四、裂缝计算
裂缝按GB50010 − 2010中7.1.2 − 1式计算
1.裂缝计算参数:
构件受力特征系数: αcr = 1.9 钢筋的相对粘接系数: vi = 1.0
裂缝计算 = "满足GB50010-2010中3.4.5条"
五、结果汇总
承台高: h = 1.5m
承台底面纵向钢筋: 8ϕ25
配筋率:
承台底面裂缝: ωmax = 0.088 ⋅ mm
ρsd = 0.291 ⋅ %
As
=
max⎛⎜⎝ α1 ⋅
fc ⋅ b01 ⋅ fy
x
,
M 0.9 ⋅ fy ⋅
h0 ⎞⎟⎠
=
3666.9 ⋅
mm2
最小配筋率按GB50010 − 2010中8.5.1条计算取值
ρmin =
0.2%
if
45
ft 100fy
< 0.2%
45
ft 100fy
otherwise
= 0.2 ⋅ %
Amin = ρmin ⋅ (ba ⋅ h) = 2700 ⋅ mm2
0.01
if
Asd Ate
<
0.01
Asd Ate
otherwise
= 0.01
受拉钢筋应力:
σsk
=
Mqk 0.87 ⋅ h0Asd
= 148.034 ⋅
N mm2
裂缝间受拉钢筋间距不均匀系 数:
ψ=
0.2 if 1.1 − 0.65 ⋅ ftk < 0.2 ρte ⋅ σsk
otherwise 1 if 1.1 − 0.65 ⋅ ftk > 1 ρte ⋅ σsk
柱对承台冲切验算 = "满足GB50007-2011第8.5.19-1式" if FN ≤ FLc "不满足GB50007-2011第8.5.19-1式,增加承台高" otherwise
柱对承台冲切验算 = "满足GB50007-2011第8.5.19-1式"
2)桩对承台的冲切计算:(按GB50007 − 2011中8.5.19条计算)
《建筑桩基技术规范》(JGJ94 − 2008)
《建筑抗震设计规范》(GB50011 − 2010)
二、 设计资料
1.材料: 混凝土强度度等级
纵向钢筋强度等级
箍筋强度等级
构造措施抗震等级
材料参数程序
钢筋弹性模量: 纵筋抗拉强度设计值: 混凝土强度设计值: 环境类别: 二a类 2.基本参数:
Es = ⋅ N ⋅ mm− 2 fy = 360 ⋅ N ⋅ mm− 2 fc = 16.72 ⋅ N ⋅ mm− 2
λa =
受剪切截面高度影响系数:βhs =
0.25
if
ay h0

0.25
=
0.35
3
if
ay h0

3
ay h0
otherwise
1 if h0 ≤ 800mm
0.7952 if h0 ≥ 2000mm
⎛ 800mm ⎞0.25 ⎝ h0 ⎠
otherwise
= 0.865
剪切系数:
β
=
1.75 λa + 1.0
2.裂缝计算
ωmax
=
αcr ⋅
ψ

σsk Es

⎛⎜⎝1.9cs
+
0.08 ⋅
de ρte
⎞⎟⎠
=
0.088 ⋅
mm
按三级二a类环境允许裂缝: ωlin = 0.2mm
裂缝计算 = "满足GB50010-2010中3.4.5条" if ωmax ≤ ωlin "不满足GB50010-2010中3.4.5条,增加配筋量" otherwise
= 1.297
承台计算端头最小宽度: b01 = 2c + a ⋅ cos(α) = 1.44m
承台计算截面处宽度: b02 = 2⎡⎣c + (ay + 0.5 ⋅ a) ⋅ cos(α)⎤⎦ = 1.939m
承台受剪截面计算宽度,参GB50007 − 2011中附录U.0.2 − 1式近似计算
b0
上部荷载设计值等效于:FN = 3ρg ⋅ γ ⋅ Ra = 6750 ⋅ kN
上部荷载标准值等效于: FNk
=
3γ γk
⋅ ρg ⋅ Ra = 5000 ⋅ kN
上部荷载永久值等效于: FNqk
=
3γ γqk

ρg

Ra
=
4219

kN
三、承载力计算
1.内力计算(弯矩按GB50007 − 2011中8.5.18条计算)
根据GB50007 − 2011中8.5.20条,按GB50007 − 2011式8.5.21 − 1计算桩边和柱边连线的抗剪
承载力:
圆桩等效方桩截面边长: a = 0.8 ⋅ D = 480 ⋅ mm
桩边至柱边的最大距离:
ay =
2 3

S1

sin(α)

0.5(a
+
hc)
=
499.23

mm
计算截面剪跨比:
4.截面相对受压区高度
不考虑受压钢筋作用,根据GB50010 − 2010中式6.2.10 − 1,计算混凝土等效受压区高度:
三向板带受弯计算宽度近似取: ba = 1.5D = 900 ⋅ mm
x = h0 ⋅ ⎛⎜1 − ⎝
1−
α1

2M fc ⋅ ba

h02
⎞⎟ ⎠
=
54.828 ⋅ mm
混凝土相对受压区高度:
有效受拉混凝土截面面积: Ate = 0.5ba ⋅ h = 675000 ⋅ mm2
实配受拉钢筋面积 HRB400 8ϕ25 di = d = 25 ⋅ mm
受拉钢筋等效直径:
de
=
di vi
= 25 ⋅ mm
按有效受拉混凝土截面计算受 拉钢筋配筋率:
Asd = 3926.991 ⋅ mm2
ρte =
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